help-28

[deft zodiac]

b is fk+1

r is fk

hm

they didnt ask for q

but q is trivially 1

[full forum]

@calm field Has your question been resolved?

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[wraith river]

How do i do this

[manic sedge]

how do you get from 5 to 8 to 11

[glass crystal]

do you notice any pattern?

[wraith river]

You add 3

Okay but how do you state this mathematically

i see these subscripts n they confuse me

[manic sedge]

$a_n=a_{n-1}+3$

[glossy valve]

Splash

[manic sedge]

n is the one you are at right now

[wraith river]

What do the n's and n-1's mean ?

[manic sedge]

since you are at the second one (8)

n is 2

so the second in the sequence is 8

so 8 = 5+3

[wraith river]

Oh okay

[manic sedge]

so how do you get from 38 to 27 to 16

[wraith river]

Hmm

minus 11

What does subtracting 1 do ?

[glass crystal]

this kind of formula is used to describe the sequence at any step n, it simply means that $a_n$ the value at step number n can be expressed as some formula (recurrence formula) that involves the value at the previous step (so step number n-1) which we denote $a_{n-1}$

[glossy valve]

Benjamin

[wraith river]

Ohhh ok that explains it thank u

[glass crystal]

you should understand it as

"how to get to one step from the previous one"

[glass crystal]

and here the way is to add 3 to the previous one

as you can see reading the formula

[wraith river]

My teacher also did this thing

Where he put n > 2 or something like that

what does he mean by that?

[glass crystal]

it means that the formula works for the steps bigger than 2

and doesnt for step 1

since step 1 is the first you cant get it from a previous one

[wraith river]

Ohhh

[glass crystal]

so you must state the value explicitely

[wraith river]

Thank you

[glass crystal]

so the full answer for a) should be

$a_1 = 5$

[glossy valve]

Benjamin

[glass crystal]

$\forall n \geq 2, a_n = a_{n-1} +3$

[glossy valve]

Benjamin

[wraith river]

?

[glass crystal]

it reads as "for all"

[wraith river]

Oh okay

[glass crystal]

"for all n bigger than 2 , the formula is true"

[manic sedge]

or just say $a_0=5$

[glossy valve]

Splash

[manic sedge]

and then state the eq

[glass crystal]

it doesnt change anything

just you would have n>=1

instead of n>=2

[wraith river]

My teachers answer for the question he did

t1 = 5

[manic sedge]

yep

[wraith river]

tn = tn-1 + 3, n > 2

[glass crystal]

probably $\geq$

[glossy valve]

Benjamin

[glass crystal]

not >

[wraith river]

yeah

sry i dont know how to do that on computer

[glass crystal]

dw

usually you can write >=

people will understand

[wraith river]

oo okay thank you

I understand now so i will close this channel thank you guys

.close

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[pearl timber]

Whats the domain of this

[pearl timber]

k= sqrt(3)

[clear lily]

when is the inside positive?

[brave blaze]

$y = \sqrt{\cos(x) + \sqrt{3} \sin(x)}$

[glossy valve]

Ｈｅｒｅｌｓ

[brave blaze]

we can rearrange this thing to make things easier

$y = \sqrt{2\left(\frac{1}{2} \cos(x) + \frac{\sqrt{3}}{2} \sin(x) \right)} = \sqrt{2} \sqrt{\sin(\frac{\pi}{6}) \cos(x) + \cos(\frac{\pi}{6}) \sin(x)} = \sqrt{2} \sqrt{\sin(x+\frac{\pi}{6})}$

[glossy valve]

Ｈｅｒｅｌｓ

[brave blaze]

now its easier to find the domain

[pearl timber]

Got it thank you

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[late tinsel]

Question: Calculate sqrt(1.1) with an error less than 10^−4 using the Taylor expansion of the function f(x) = sqrt(x + 1) in a setting of a = 0.
To calculate such error, we know that is will be equal to:

[late tinsel]

now, how do I find an upperbound of the n+1 derivative?

[fast peak]

Well how do you find the maximum of a function

[late tinsel]

finding where derivative == 0

but we can't use this cz its the n+1 derivative

[fast peak]

Well calculate enough derivatives until the error is smaller than 1e-4

[late tinsel]

or evaluating the extremes of the intervals

[late tinsel]

is there any way to know beforehand how many derivatives i'll have to compute?

[fast peak]

I doubt it

But this function is nice so it shouldn't be that bad

[late tinsel]

cz, if f(x) was sin(X), then i could just upperbound the function to 1

[fast peak]

Yes sqrt is not that easy sadly

[late tinsel]

okey

[fast peak]

But still not too bad

[late tinsel]

thx tho

:)

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[brisk sorrel]

Now consider this case where 4 1 2 are the value of f level curve, now the one intersecting the curve has maximum value whereas the one touching it has neither maxima nor minima, now here won't the logic of lagrange gets defeated?

[full forum]

@brisk sorrel Has your question been resolved?

[brisk sorrel]

, rotate

[brisk sorrel]

<@&286206848099549185>

Please help with this

[rotund scroll]

What is your question precisely, @brisk sorrel ?

[fossil stump]

That doesn’t help anyone help you. You can’t just expect people to know what you’re asking

Was the above still your question?

[brisk sorrel]

Did you read this and still didn't understand my doubt

Much more clearer diagram

<@&286206848099549185> please respond, i ll even restate my doubt, what i am saying is in the picture above, look at the dffrnt points where g meets f and for the gvn constraint g the 4 one looks like a maxima but still according to the lagrange multiplier only 2 is selected as candidate point, so it defeats our purpose of finding the best candidate point to find maxima and minima along the g curve

[brisk sorrel]

<@&286206848099549185>

I restated my problem

[brisk sorrel]

<@&286206848099549185>

[hollow glacier]

sorry

but this is not on my level

[heavy jasper]

@brisk sorrel I would suggest asking in #multivariable-calculus

[brisk sorrel]

Ok

[heavy jasper]

oh I see you asked there already

feel free to .close this channel

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[alpine girder]

suppers

[alpine girder]

a

[slow gulch]

oh which part?

[alpine girder]

a bruh i said it above

[slow gulch]

ohh sorry I didn’t see that haha

[alpine girder]

np

[slow gulch]

maybe you can try $\frac13 \int{sec^{n}3x (3sec(3x)tan(3x))}dx$ and go from there

[glossy valve]

Polipoli ❤

[slow gulch]

oh that’s messy in my latex haha

can you read it?

[alpine girder]

AH

alr one sec gonna try

[slow gulch]

okay!

[alpine girder]

noice got it

how about b?

[worthy tree]

u-substitution :
put u = 2x +1

[alpine girder]

AH

after that?

[worthy tree]

u = 2x + 1
du = 2 dx <=> dx = du/2

when x = 0 , u = 1
when x = 1 , u = 3

[glossy valve]

Mehdi_Moulati

$\int^1_0 \frac{1}{(2x+1)² + 3} dx = \int^{3}_{1} \frac{1}{u² + 1} \* \frac{1}{2} \* du$

[alpine girder]

ah

alr so

[glossy valve]

Mehdi_Moulati

[alpine girder]

what i get after ?

what should i get after integrate

never done this question before

[slow gulch]

$\begin{bmatrix}
\frac{1}{2\sqrt3} \tan^{-1}{\frac{2x+1}{\sqrt3}}
\end{bmatrix}^{1}_{0}$

[glossy valve]

Polipoli ❤

[slow gulch]

I think you should get this

[glossy valve]

Mehdi_Moulati

[alpine girder]

nice

thx gonna try

[slow gulch]

yep! do what mehdi said :D

[glossy valve]

Mehdi_Moulati

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[hollow zenith]

Is there a mathematical operator that removes units

[hollow zenith]

like meters or seconds so i only have the number

[clear lily]

you can divide by meters per second

lol

[hollow zenith]

I want to calculate the escape velocity of a mass from the Uranus

Im already done but I am not given a mass so my answer is just

2,279 x 10^8 x mass (in kg) x m^2/s^2

I would like to have an operator so that I can split the mass of the satellite or whatever in the skalar and in kg

[hollow zenith]

.

because the answer should be in Newton * meter

[clear lily]

that is newton * meter

$1 N = 1 \frac{kg \cdot m}{s^2}$

[hollow zenith]

yeah but then I split the mass in kg and the skalar

[glossy valve]

Gijs

[hollow zenith]

dont I need an operator for that

[clear lily]

if your answer should be in N * meter then you are already done

and your answer is 2,279 * 10^6

[hollow zenith]

times the skalar of the mass

whatever

.close

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[void widget]

How can I write a equation

It goes like

[frosty geyser]

hey, could this be an exam question?

[void widget]

Nah

[frosty geyser]

this seems suspicious

[void widget]

Somebody give me

[twilit leaf]

yeah

[void widget]

Gave

[brave blaze]

5-7-9-11...

[void widget]

,ti

[glossy valve]

The current time for 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛 is 03:50 AM (IST) on Wed, 04/01/2023.

[kind jay]

[void widget]

I know

[kind jay]

#help-3

[void widget]

Exam at 4am?@frosty geyser

[kind jay]

#help-5

[frosty geyser]

vpn

[void widget]

Really

[light sonnet]

Also you are asking someone else's question

[frosty geyser]

well anyway, someone kindly gave you the first differences, so the rule is obvious now?

[void widget]

I know

[tulip beacon]

??

[void widget]

Cause I am stuck at this

I am curious 🥲

[kind jay]

https://www.youtube.com/watch?v=5NY6CpB2Mog&ab_channel=RadfordMathematics

[void widget]

5,7,9,11 we Just add odd number starting from 5 to the constant

But how can we write it

[frosty geyser]

so every step is +2 more than last time

[void widget]

Yes

[frosty geyser]

something like... 2n right?

[void widget]

2n+1?

[frosty geyser]

well, for n=1 you must get 5

[stable plover]

hint: subtract 8 from each element in the list

[void widget]

2n+3

[stable plover]

you will see the pattern immediately

[frosty geyser]

not yet

[frosty geyser]

lets take it slow

[frosty geyser]

yes

thats the difference

[void widget]

Ohhh

[frosty geyser]

now you need to apply it to the bases

[void widget]

How

[frosty geyser]

https://cdn.discordapp.com/attachments/903486480985489478/1059959167705698375/image-31.png

you start with 12

you know your formula looks like a+2n

for n=1 you get 12

[light sonnet]

I still don't really know why you are asking someone else's question.

[void widget]

Ummm

[light sonnet]

It's not your question. That person who asked could be in a higher level math, meaning that you could be lacking the prior knowledge you need

[void widget]

Well sometimes I can't solve some problems so I just want to clear it like that

[light sonnet]

So it's best to learn that

[light sonnet]

This video helps

[void widget]

Ohk

[light sonnet]

It demonstrates how to find the first and second difference, then what to do after

[void widget]

Thanks for clearing it @light sonnet

@frosty geyser

.close

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[tardy lotus]

A small section of a graph is shown below. Evaluate the shaded area enclosed between the implicit curve, the x-axis and the y-axis correct to five decimal places.

[gritty rose]

what techniques are you supposed to use

[tardy lotus]

Any

[gritty rose]

no you're not

what are you learning in class

[tardy lotus]

I am learning calculus

[hot wadi]

[gritty rose]

are you supposed to use a programming language?

[tardy lotus]

Nope

[onyx glen]

uh wtf

you're not supposed to do this by hand, are you???

[dapper bane]

is it on rad or degrees?

[gritty rose]

or a graphing calculator?

[tardy lotus]

I don't know but we can build intuitions

[tardy lotus]

Rad?

[onyx glen]

...

rad stands for radians.

but still...

[gritty rose]

the intuition is to use a graphing calculator or programming language

[tardy lotus]

Yeah i know

[onyx glen]

did this problem come from a worksheet?

[tardy lotus]

No I got this from a math forum

[dapper bane]

so the answer doesn't have to be exact correct?

[onyx glen]

give us the link, if you would?

[tardy lotus]

I think this could be done by hand I don't know...

[dapper bane]

how tho

[tardy lotus]

https://www.facebook.com/groups/1730747267167812/permalink/3296960153879841/?app=fbl

[onyx glen]

this group is private

screenshot the entire post, with all accompanying text and instructions.

[gritty rose]

YOU think that or someone else says you can do this by hand?

[tardy lotus]

Oh I forgot that

[tardy lotus]

You are supposed to this by hand because otherwise they wouldn’t give it

[gritty rose]

who's "they"

[onyx glen]

screenshot the entire post, with all accompanying text and instructions.

we CANNOT proceed unless you comply.

[onyx glen]

so nothing about this says you're supposed to do it by hand.

[tardy lotus]

Idk

[gritty rose]

so you made this up?

[tardy lotus]

I never found any math in that group which can't be done by hand and It's also not allowed to post such maths there

[light sonnet]

If it's possible to do by hand, doesn't necessarily mean that all the problems have to be done by hand

[fast peak]

and no one would ever post something not allowed somewhere

and read all the rules before posting

[onyx glen]

has anybody posted any comments on this post?

[tardy lotus]

I know but can you explain why it is not possible?

[tardy lotus]

No

[onyx glen]

it's not that it's impossible -- you could, in principle, reproduce any computer's calculations given enough time and paper -- it's just painful.

[fast peak]

and you might die before you are done

[tardy lotus]

I see 😅

[tardy lotus]

What's the approach to solve this though

[onyx glen]

i havent a fucking clue to be honest

[fast peak]

probably use newton to get your function y(x) and then numerically integrate as usual?

[dapper bane]

the graph ressembles a triangle so maybe you gotta use the formula A=bh/2

i know that it isn't exact but

[onyx glen]

it's nowhere near enough precision, is it

[tardy lotus]

I haven't learnt multi variable yet so I have to know about the approach

[tardy lotus]

Multi variable calculus*

[fast peak]

have to? lol

[tardy lotus]

Why can't we use direct integral?

[fast peak]

on what function

we dont have a function f(x) to integrate

not explicitly anyway

and I very much doubt that you can solve that equation for y

[tardy lotus]

I guess limit series expansion could help

[fast peak]

I doubt it but feel free to try

[tardy lotus]

Sin(u)= u-u^3/3!+u^5/5!-...

[fast peak]

well yes

and?

how does that help

(1+x^y) - (1+x^y)^3/6 + (1+x^y)^5/120...

[tardy lotus]

Multiply with the denominator of the R.H.S

Then we get a polynomial equation

[fast peak]

no

how is this a polynomial

y in the exponent and it's a series

[dapper bane]

this is getting wild, we got a series with a y as exponent in every term

[tardy lotus]

Yeah u are right

[dapper bane]

there's no way we could calculate by hand without the help of computers

what did the guys over at facebook say?

did they find an answer to this mess?

[tardy lotus]

Nope

[fast peak]

its been up for an hour

really not that surprising

[tardy lotus]

Should I close it?

[dapper bane]

eh we can atleasr approximate it

[fast peak]

up to you. I doubt you'll get other answers from here which will say something other than "throw a computer at it"

[full forum]

@tardy lotus Has your question been resolved?

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[tribal gust]

An equation in r and theta can represent a curve in the plane with respect to polar coordinates. The straight line 2x-3y = 5 has a polar counterpart r(2costheta-3sintheta) = 5. How does that represent a line since theta is a fixed value so is r no? meaning that equation represents a point [r,theta]

[gritty rose]

no, r and theta are not fixed values

just like how x and y aren't fixed values

[tribal gust]

but a line always has the same angle with the polar axis no?

[gritty rose]

don't confuse lines with rays

in this case, theta is fixed to 2 values

even so, theta and r are independent of each other

[tribal gust]

Can you perhaps construct a few points of the line using the polar equation? Maybe that way i'll understand

[gritty rose]

a few good examples here
https://math.libretexts.org/Bookshelves/Algebra/Book%3A_Algebra_and_Trigonometry_(OpenStax)/10%3A_Further_Applications_of_Trigonometry/10.03%3A_Polar_Coordinates

[tribal gust]

I'll give it a read thanks!

I'll keep the channel open

Ohhhhh

so r = equation for all theta

i was thinking of r as a vector instead of a coordinate

so i imagined r changing while theta stays constant but r changes with inputs theta

okeyy polar coordinates make way more sense now

[tribal gust]

thanks alot!

.close

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[tribal gust]

.reopen

[full forum]

✅

[tribal gust]

Would it be fair to say r is a function r: [0,2pi] --> R: theta --> r(theta)

[gritty rose]

nope

[tribal gust]

why not

[gritty rose]

not always at least.

[tribal gust]

ooh yeah not a function but a map, or well just a relation not bounded by "for every x there exisys only one y" stuff

[gritty rose]

it's probably better to just keep them independent of each other

[tribal gust]

For class i will but out of curiosity i'd still like to know the details haha

[gritty rose]

sure, but i don't know how that benefits you

[tribal gust]

Makes more sense to me idk

• its fun to have your 'insights' verified, as small as they may be haha

Anyway thanks again!

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[slow gulch]

hi!

[fallen loom]

hi

[slow gulch]

I tried this but am not able to get the form they want

can someone try to see where I went wrong?

I colour coded so it might be a little more clear

[dapper bane]

i cannot find the mistake

[viral jasper]

Respect for showing what you tried and making it look nice

What is a chord to an ellipse?

Just any line that goes through it not being tangent?

[dapper bane]

also if d has a ² in the ym coordinate doesn't the d in the xm also need a ²

but i have been looking at your drawings for a full 10 minutes and i couldn't find a mistake, so i came to the conclusion that it is probably a typo made by them. idk

[marble halo]

the cord of ellipse will satisfy the two equations at two points

don't know why I said it
they already have solved it

[jolly patio]

what language is that lol

[dapper bane]

english?

[jolly patio]

at the top

looks like alien language

[dapper bane]

looks like the georgian scipt

[marble halo]

printing error

tbh

[jolly patio]

lmaooo

[jolly patio]

ayo wtf that looks like what OP wrote lol

[full forum]

@slow gulch Has your question been resolved?

[slow gulch]

hi!

[slow gulch]

oh okay! ty! I also couldn’t find any careless mistake haha

[dapper bane]

don't take me as fact

[slow gulch]

ohh it’s Burmese sorry! I forgot to crop it out

[dapper bane]

i just couldn't find the answer

[slow gulch]

ohh I see

I’ll clarify with my teacher about the question :D ty!

[viral jasper]

Asking again, @slow gulch, is a chord just a line through an ellipse?

[marble halo]

I'm 90% sure
the answer is yes

*95%

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[viral jasper]

.reopen

[full forum]

✅

[viral jasper]

@slow gulch is this part right?

ah nvm, it is

Nope, your work is perfect

.close

[full forum]

Channel closed

Closed by @viral jasper

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gritty rose]

,rotate

[full forum]

@torn jolt Has your question been resolved?

Channel closed

Closed by @low quarry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frank stump]

I don’t really know the rules of how to solve these types of problems because my math teacher speaks in moon runes, can somebody dumb down the process for me a bit? Like rules and basics that can get me through this

[torn jolt]

Well let's start with 12th, okay ? @frank stump

[trim field]

you understand the principles of rearranging

[frank stump]

The knowledge I have to go off of is how to factor something like x^2+10x-5=0

[trim field]

I can show you something called the diamond method

[light sonnet]

Lol moon runes

[frank stump]

Alright

[trim field]

That is quite reasonably easy to understand

[silent furnace]

hey guys, can i get some assistant with something?

[full forum]

Please read #❓how-to-get-help

[silent furnace]

Three positive integers are equally spaced on a number line. The middle number is 15, and the
largest number is 4 times the smallest number. What is the smallest of these three numbers?

[light sonnet]

Read #❓how-to-get-help

[trim field]

So do you know the factoring rules

[silent furnace]

so basically, the spacing is equal

what do you mean

[frank stump]

Yeah

[trim field]

@frank stump lets start with question 12

[light sonnet]

This channel is occupied by someone else, you need to open your own channel

[frank stump]

I’m a tad slow but yes

[trim field]

12/t + t -8 = 0

[light sonnet]

Read #❓how-to-get-help to figure that out

[frank stump]

Yep

Where would I start

[silent furnace]

done i opened a forum

[trim field]

so you would want to get it into a straight line equation

or you can have everything have a common denominator

[light sonnet]

Or don't do any of that, because that makes it complicated

[trim field]

hmmm fine you'd rearrange first

the equation

[light sonnet]

You have a fraction, the first and easiest step is to clear fractions

[light sonnet]

No

[trim field]

thats rearranging it

:I

[frank stump]

Well dont argue now I’m open to hearing multiple methods

[light sonnet]

You can multiply all the terms by the lcm

[light sonnet]

No it's not

[frank stump]

I can keep track of yall talking over eachother

Just dont fight for who is right

[light sonnet]

Rearranging is moving terms around

[trim field]

lmao you'd want to get a straight line equation

[light sonnet]

That's not what I'm doing

[frank stump]

Just say what to do don’t worry about arguing

[trim field]

So you have a fraction with the denominator of t, how do you get rid of it

[frank stump]

Multiply by t

[trim field]

what would you multiply by t

[light sonnet]

.

[frank stump]

12/t

[trim field]

no

everything

in the equation

[frank stump]

Ah

[trim field]

so if you multiplied 12/t + t - 8

[frank stump]

Oh, so it would become t^2+4

[trim field]

what would it look like after

[frank stump]

?

[trim field]

not quite

[frank stump]

My bad

[trim field]

we dont know what t is

[frank stump]

t^2-8t+12

[light sonnet]

You need the = 0 part too

Because that's what makes it an equation

[frank stump]

Well look it’s self explanatory

I definitely dont forget to put it on my answers and get marked down for it

[light sonnet]

There is a difference between expression and equation, what you have typed is an expression

[trim field]

You hhave to remember you also have to times the left hand side which in this case is 0 by t

[light sonnet]

Meaning you don't "solve" for anything with an expression

When you have = 0, that denotes as an equation

[frank stump]

It would still be 0 tho

[trim field]

yes but im saying for other equations you cant forget to

[frank stump]

Ah, thank you

[trim field]

okay so now we know 12 + t^2 -8t = 0 whats the next step

[frank stump]

Oh so now I just do it normally

[trim field]

which would be doing what to the equation

[frank stump]

To get -8 from factors of 12, -6 and -2 should work, meaning x=6 and 2 right?

[trim field]

yeah

[frank stump]

Sweet

[trim field]

tho

you have to write down

you factorising it

[frank stump]

(t-2)(t-6)=0

[trim field]

so as you said but you'd have to write (t -6)(t-2)

yeah

exactly

to get full marks

[frank stump]

Sick

Thanks

[trim field]

lets do another

do 14

[light sonnet]

No because you're not done

12 isn't completed yet

[trim field]

he did it

[frank stump]

Mannnnn get this guy out the chat

[light sonnet]

First, this is wrong because there is no x

[frank stump]

No I did that

[frank stump]

Variable

t

[trim field]

he said t = 2 and 6

[light sonnet]

And second, if this is what you have, you did not solve the equation yet

[lapis basin]

oh yes sorry I onyl saw the () one oops

[light sonnet]

No they did not, they said x = 2 and 6 which is wrong

[frank stump]

I’m not gonna argue to validate the fact I answered a math equation

[trim field]

alr 2/y+2 + 3/y = -y/y+2

[frank stump]

So I’m going to ignore you indefinitely

[light sonnet]

And I'm gonna argue the fact that it should be done properly

[trim field]

we have to get it into a a straight line

whats the common factor with all of them

[frank stump]

Multiply by Y, get /2 for the other two

[light sonnet]

Because if there is miscommunication, people aren't going to understand what you mean

[frank stump]

2/2+3=-y/2

[light sonnet]

If you decided to write x instead of t, on a test, it could be marked wrong because you threw in a letter that never existed

[frank stump]

Which is 1+3

4

4=-y/2

Multiply by 2

8=-y

[light sonnet]

And no, this is wrong

[trim field]

im back

[light sonnet]

You don't multiply by y

[trim field]

okay so we want to completley get rid of them

[frank stump]

-8=y

[trim field]

with one multiplication

[light sonnet]

You multiply by the lcm of the denominators

[frank stump]

That is what I got

[light sonnet]

And the lcm is not y

[frank stump]

I have completed the problem

I think

[frank stump]

?

[light sonnet]

.

[trim field]

so i dont think its right

[frank stump]

Damn

[trim field]

ill do it rn

see what i get

[frank stump]

Alright

[light sonnet]

You multiply by the lcm of the denominators

[trim field]

no you're right

well done

[light sonnet]

And the lcm is not y

[frank stump]

YOOOOO

[trim field]

y = -8

[frank stump]

IM SMART NOW

lol

[trim field]

alr lets do 16

[trim field]

doesnt have to be lcm can just be a common multiple

alr what first

[frank stump]

Multiply by b

[trim field]

what we get

[frank stump]

Get 1=3

So

[trim field]

and does that seem correct

[frank stump]

New approach

Lol

[frank stump]

Not exactly

[trim field]

yeah okay so a new way

[frank stump]

There is no b in the numerator so I gotta do something else

[light sonnet]

That is wrong

[trim field]

so

[light sonnet]

You are teaching absolutely wrong

[trim field]

right

so

i times everything by y+2

got -y = 8

[frank stump]

I’m surprised this man is marked ‘helpful’

[light sonnet]

This isn't correct

,w 2/(y +2) +3/y = -y/(y+2) solve for y

[glossy valve]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dldh06#2659

[light sonnet]

y = -3

So it's wrong

And I'm trying to show you the proper method

[frank stump]

Well you are being quite obnoxious doing it

[light sonnet]

So you can either listen to lima and be wrong every time or I can help you

[frank stump]

No if you talk to me like that

[light sonnet]

Because I know how to approach these problems properly

[stable crow]

whats going on here

[frank stump]

Idk at this point

[trim field]

tbf i did forget a part its 3(y+2)/ y

so it gives

3y + 6

[light sonnet]

The obnoxious part is because as mentioned, if you write x instead of t on tests, you will get points off

[stable crow]

yea y does = -3

[light sonnet]

If you don't present properly, you will get points off

[frank stump]

I will resume ignoring you indefinitely

So I will backtrack to figure out what I did wrong

[light sonnet]

Fine, listen to the people who gave you wrong answers

[frank stump]

Lemme write this down rq

[light sonnet]

You multiply by the lcm of the denominators

Telling you what to do there

[quartz relic]

Because you have (b+1) and (b+2), you wqant to multiply everything by (b+1)(b+2)

[trim field]

yeah ikik

and then for the y equation y(y+2)

ik i was just having somefun

knows its wrong dw

whatd you get for 16 ryan

[frank stump]

Why tho

[trim field]

bc

its the lcm

of the denominators

[light sonnet]

If you know it's wrong, don't teach people the wrong thing

[frank stump]

What is lcm

[trim field]

you know what the LCM is?

[light sonnet]

Lowest common mulitple

[stable crow]

than fractions are gone

[trim field]

lowest common multiple

[quartz relic]

You're trying to eliminate the fractions

[frank stump]

Alright so is it just

[light sonnet]

The easiest method to finding the lcm of the denominators is just multiply all the denominators together

[frank stump]

All the different denominators side by side

[stable crow]

in Q14 LCM y(y+2)

[frank stump]

I’m stubborn and spiteful so I am going to not acknowledge that dld answered my question

Despite the fact I just did

[trim field]

so the only way to eliminate b+2 is to times it by b+2 but that dont get rid of b+1 so you have to multiple (b+2){to get rid of the 2 b+2 denominators}(b+1){to get rid of the b+1 denominator}

[frank stump]

Ahhh okay

[lapis basin]

just real quick number 16 you already have common denominator

[trim field]

he's doing 16 rn

[frank stump]

I’ll come back in a second when i have an answer

[quartz relic]

You're kinda doing 2 steps in 1

[lapis basin]

yeah like I plugged in just to double check but the equation in desmos 1/x+2 + 1/x+2 = 2/x+2

[light sonnet]

And the fact that I am giving proper help then saying

ik i was just having somefun
knows its wrong dw

[lapis basin]

so you can just start 16 with 2/b+2=3/b+1

[frank stump]

I have blocked him I am no longer bothered

[lapis basin]

2/(b+2) it's hard typing math lol

and 3/(b+1)

[stable crow]

i think theres a bot for that

but idek how to use it lol

[trim field]

nah that bot takes too much effort

could just search google and copy and paste it

[light sonnet]

It really doesn't and I would help but the OP doesn't care for my help

Latex is simple

[trim field]

but google hardly works when you type in equations

[light sonnet]

Once you get the idea

[frank stump]

I got -4=b

[trim field]

thats wrong

[stable crow]

right on

[stable crow]

huh

[trim field]

its a joke dw

[stable crow]

u sure

[frank stump]

Yeah no

[trim field]

yes im sure he's right i got it dwdw

[trim field]

ehehehhehe

[stable crow]

oh

[frank stump]

Dont feed my bad habits Lima

It isn’t a joke I think you just struggle a bit as well

[lapis basin]

-4 is correct

[frank stump]

Or are trolling idk

[trim field]

do 17

[frank stump]

Thats a lot to type into my calculator

Welp brb

[trim field]

you're not wrong

i hate lines

never does.

[clear lily]

17 is fairly doable

[kind jay]

All are

Reee

[clear lily]

lmao true

[stable crow]

ryan u familiar with the quadratic eqn

[trim field]

i done 17

[clear lily]

im starting to understand why people hate maths lmao

[kind jay]

I have done 42 😎

[clear lily]

if this is all youre forced to do i wouldnt like it much either

[trim field]

EEEEEE

[kind jay]

Nothing beats doing 100 fourier series

[gritty rose]

a/sqrt(2pi) * exp(-x^2 / 2) for a = 1, 2, ..., 100

[trim field]

gul did you do it

[stable crow]

what 17

yea

[trim field]

yh

okok

[kind jay]

For a=1 e^(-x^2/2)/sqrt(2pi). QED

[trim field]

agreed

@frank stump you done it

[frank stump]

I’n here

For 17

[trim field]

yes\

[frank stump]

A = 3/2 and -1

[trim field]

@stable crow just checking u get same

[stable crow]

messed up a little

[frank stump]

No wait

[trim field]

i didnt... i got

a = 3

[frank stump]

Yeah

[trim field]

a = -1/2

shwo your working

[stable crow]

yea lima thats the ans

[frank stump]

A = 3/2 and -1/4

[trim field]

heh

idk how youve gotten thta

[frank stump]

That is what I got

[trim field]

show your working

[stable crow]

ryan did u factor out 3 and 4

[stable crow]

in the denominators

[frank stump]

This is what I did

First move was lcm

[trim field]

right i see what you did wrong

lemme take a pic of my workings and explain

[light sonnet]

Or you can point out where they messed up

[trim field]

you multiplied wrong on thhe fractions

[frank stump]

Just tell me where I went wrong

That is true man I have blocked

[trim field]

so when you tried multiplying

its better in these type of 3 different denominator questions

to transform them

factorise the denominator

rather than just multiplying them all together against everything and making a mess

[frank stump]

Alright

But that doesnt explain what I did wrong

Yea I did it the long way but did I mess up on it?

[trim field]

bc your multiplication was wrong

[frank stump]

Cuz if I did my calculator is of concern

[stable crow]

how exactly

[trim field]

doing equations like this is very

hard thing to do on calculator

better to do it on paper following methods

[light sonnet]

What was your lcm?

[frank stump]

I typed each section out separately and multiplied it by the lcm

[trim field]

what would the LCM be

[stable crow]

(a-1)(a+1)?

[frank stump]

(3a+3)(4a-4)(2a+2)

[trim field]

thats

[light sonnet]

Fyi if you aren't the OP, you should really be giving answers

[stable crow]

sry bout tht

[light sonnet]

It's easier to factor out, so then you can clearly see the lcm

If it overlaps, meaning repeats in other denominators, then you just need it once

[trim field]

you dont wanna be multiplying big LCM's you wanna make them as simple as possible

[trim field]

^^

[frank stump]

I get that, but I do multiply big things

[trim field]

thats why you got it wrong

so factorise all the denominators

[frank stump]

Where did i go wrong in my multiplication

That is my concern

[light sonnet]

Like 1/2 and 1/4, a possible denominator is 8 because multiplied all the denominators together, but a better denoominator is 4

[frank stump]

Because a calculator did it

[frank stump]

?

[light sonnet]

In my opinion, hard to tell since you just went straight to that line

[trim field]

okay im gonna try do what you did and see if i get the same as the calculator

it wont be

[frank stump]

Alright, I’m gonna trace back and figure it out

[trim field]

or scrap that method and do it as factorising to get the simplest LCM

[light sonnet]

What exactly did you do here?

[trim field]

writte

[light sonnet]

You skipped a lot of math so it's hard to understand the process that occurred

[frank stump]

I wrote each thing into the calculator times the lcm

[trim field]

well i just did 7a(3a+3)(4a-4)(2a+2) and i got -14a^4 + 182a^2 + 168

so off of that ik it wont work

[light sonnet]

Fyi people can do it their way if they want, you don't need to force a certain method, if ryan wants to do lcm, they can

[frank stump]

As in (7a/3a+3)•((3a+3)(4a-4)blah blah blah that was the just of it

But the right numbers

Then i stuck them all together

[trim field]

yeah just divided the 3a+3 rn and i got -14^3 + 42a^2 + 56a

[light sonnet]

(7a)(3a+3)•((3a+3)(4a-4)
If that was what you used as the lcm, can you explain where (x - 1) and (x + 1) came from?

[trim field]

he did say. he just copied the calculator

[light sonnet]

I wasn't asking you

[trim field]

i mean we've asked abt 6 times same response

[light sonnet]

I am trying to understand what the OP did step by step

[trim field]

dont think much gonna change

[frank stump]

Stop being a dick

Hes right

But I’m getting nowhere here

I’ll try again on my own

[trim field]

Okay so this time

try factorising the denominators

[light sonnet]

What exactly did you type into the calculator?

[frank stump]

I have been told nothing about how to do that

[trim field]

so

[frank stump]

.

[trim field]

its like factorising

normal stuff

factorise 3a+3

[frank stump]

3(x+1)

[trim field]

well 3(a+1)

[frank stump]

Yeah yeah

[trim field]

try keep the algebriac expressions the same as the question

[frank stump]

That seems like desimplifing

[trim field]

well you just factorised the first denominator

so

write

7a/3(a+1)

[frank stump]

Ill figure it out from here

[stable crow]

there is a different way u could have found it

[trim field]

and then factor the rest of the denominators

[trim field]

what way did you do

[stable crow]

idk what its called

its like using common division

wait ill see if i can google it

[frank stump]

24(x-1)(x+1)^2

[trim field]

what

wheres that come from

[frank stump]

Factored

[trim field]

whats that

the factor of

[frank stump]

Okay

[trim field]

you only factor 3a+3

4a-4

and 2a + 2

[frank stump]

Yeah i did that all

[trim field]

okay show me the equation

[stable crow]

looks something like this

[frank stump]

4(a-1)

2(a+1)

[trim field]

right okay

[frank stump]

Put them all together

[trim field]

stop

you're rushing

[frank stump]

Mostly because I’ve spent half of my day doing this math and im tired

[trim field]

you want to reduce now

[light sonnet]

Alright how about we all calm down, because the work you have is good, I know where it went wrong

So you can either reset and do lima's method or I can tell you what went wrong

[frank stump]

Tell me

[light sonnet]

It was this part right here

You divided by 2 for some reason

If you didn't you would have gotten a = 3 and a = -1/2

[trim field]

tbf if you didnt the answer woudl be right

[frank stump]

O

[trim field]

but the only thing is these questions will appear in non calculator exams

[frank stump]

Well that was simple

[frank stump]

Dont have those

[trim field]

so its good to know how to do it without one aswell

[trim field]

do you not????

[frank stump]

Nope

[trim field]

where you from??

[frank stump]

America

For better or for worse

[trim field]

see now why do they not do non calculator exams there

thats mad

never knew that

[frank stump]

My teachers are the type that say ‘look if I’m going to compare prices at a grocery store I’m not pulling out a notebook I’m using my phone, so I will be teaching you how to use your phone calculator like a god’

[stable crow]

is q 17 resolved

[trim field]

mental maths more satisfying tho

[light sonnet]

Yes

[frank stump]

Yes

[stable crow]

nice

[trim field]

yeah he divided it by 20 and thought he only done it by 10 so did it by 2 again

[frank stump]

Well my mental sorrows leave no room for math

Aka

My brain is tiny and it hurts without paper

Or calculator

[trim field]

fair enough

i factorised and just went off that

then reduced by x the top of all fractions by 12(a+1)(a-1)

[frank stump]

Well I got my answer

I’m getting food

[light sonnet]

Tbh in the real would, nothing is mental. Like you will always have a calculator on you, internet, so on. Like teachers making you memorize is both good and bad, good so you can understand an apply it but bad since in the real world you'll have resources to use

[stable crow]

true

[frank stump]

Yeah! They are smart to teach us how to use the tech

Just too bad they don’t know how to say things in dumby terms so my adhd can gather anything

[stable crow]

nowadays graphical calculators are allowed in highschool exams

good example of use of tech

[trim field]

BRO WHAT IS THIS

IN the uk

we get given ours at the exam

[stable crow]

yea

[trim field]

we're nota llowed our own

[stable crow]

tough

[frank stump]

All they need to say for me to understand is ‘this number’ but I hear ‘integers’ and stuff which I understand yes, but it takes my brain a minute to process and then im lost when i refocus

[light sonnet]

You understand that there are other countries besides the UK, people do things differently everywhere

[frank stump]

There’s where you went wrong /j

[frank stump]

He’s just finding out that why hes reacting like this

How do I close this btw

[stable crow]

,close

.close

[trim field]

guarantee most countries do not allow graphical calculators in finals

[trim field]

this one

[stable crow]

thouch im allowed

its to expenxive to actually get

only the rich kids has tht privlege

alr ryan u can close it now

[light sonnet]

.close

[full forum]

Channel closed

Closed by @light sonnet

Use .reopen if this was a mistake.

[light sonnet]

Lol

[light sonnet]

It's .close

[frank stump]

.close

[light sonnet]

But I already did it

[frank stump]

Ah

[light sonnet]

When you see this message, you are good

[stable crow]

how come it didnt close when tyoed it

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable crow]

typed

[light sonnet]

It takes a few minutes for the bot to close it

[light sonnet]

.close

[full forum]

Channel closed

Closed by @light sonnet

Use .reopen if this was a mistake.

[light sonnet]

You need special roles

[stable crow]

dang

its 4 am here

imma sleep

[frank stump]

Adios

Thanks for the help

[stable crow]

np

it was mainly dld anywy

.close

.close

[torn jolt]

its already closed

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still crater]

Hi, does anyone know what type of encryption this is?
TfZgmUn8N8KPZ4L+rWCqKvjGSnKogGvc609FOt/3wIX7n94+i/R4y5V5hzqYvX1kQdIrpdaZF20BEKHIcfnzqR/sbTWmMngjk01SJQyOwHurdmWAamb7jyUzjf1uiiKvzzisxd83WfGZNUZ1I+Ou8C5wOESQwbB2Ufm1gi27tXw=

[night jungle]

SHA256

jk i have no idea

[full forum]

@still crater Has your question been resolved?

[full forum]

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[silk solstice]

how is this integral equals this

[spice orchid]

Property of Dirac delta

[silk solstice]

i understand delta function but how a/2 is inside sin and
integral of sin didn't change

what about the term of sin squared

how was it integrated

[silk solstice]

isn't The integral of sin2x is x/2 - (sin2x)/4 + c .

[spice orchid]

Bottom property

[silk solstice]

alright thank you

.close

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[tribal gust]

Descartes' Folium is given by the parametric equations: see image. Find a Carthesian equation of the Folium. Make a sketch of the curve and show that the line x + y = -1 is an oblique asymptote

[tribal gust]

I honestly have no idea how to tackle this. I found the points (0,0) and (3/2,3/2) by figuring out that y=xt for t in R-1. And y=x for t = 0 and t = 1. But idk how else to identify the curve

I have yet to find a cartesian equation im just trying to sketch it first but perhaps thats the wrong approach

[sharp vine]

what's your Cartesian equation

[tribal gust]

no idea

[spice orchid]

You've solved for t in terms of x and y

Plug that into one of your equations

[tribal gust]

for a real number z can i simplify z^2/(1+z^2)?

algebra is a lil rusty

[spice orchid]

Not really no

[tribal gust]

oh lol

new approach it is

[spice orchid]

Why what went wrong

[tribal gust]

i thought maybe x^2+y^2 would give something interesting but it solves for a disc in the plane with center (0,0) and a missing ring for r = -1 = 1 (probably because i did it wrong)

so im gonna try just solving for t

[spice orchid]

You know t = y/x

Just plug that into one of your equations and you're basically done

[tribal gust]

Oh yeah, how do i proceed

do i like isolate y?

[spice orchid]

Do you think you need to?

[tribal gust]

i have no idea honestly

y = yx^2/(x^3+y^3) is not something i recognise

[spice orchid]

Well you're not being asked to recognise it

Bc obviously it's descartes folium and if you've never seen that before why would you recognise it

[tribal gust]

oh yeah ig this is a cartesian equation but i still need to sketch the curve

and show it has an oblique asymptote y = -1-x but i think i can do that with implicit differentiation

[spice orchid]

This is also wrong anyway

[tribal gust]

oh L, i'll try again

oh i solved for x

[tribal gust]

y = 3y^2x / (x^3+y^3)

anway, the sketching, im thinking just plugging in points tbh but i bet there's a more efficient method

[spice orchid]

plugging in points is probs your best bet tbh

[tribal gust]

alright

[tribal gust]

I think it'll be easier if i show that it symmetric around y=x, that way i have to plug in less points

how can i do that?

[spice orchid]

swap the places of x and y and show you get the same equation

[tribal gust]

ahh yeah thanks

[spice orchid]

just realised you can simplify the equation a bit

you can divide by y (just remember the line y=0 should be on your graph)

and rearrange to x^3+y^3 = 3xy