help-28

[hot herald]

can you identify which colour the hypotenuse is

[light scaffold]

15.1?

[hot herald]

colour

[light scaffold]

green

[hot herald]

yes, and its length is 15.1 (that was going to be my next question)

[light scaffold]

so this means this is correct? 15.1^2 = 12.8^2 + b^2

[hot herald]

noone said it wasn't

and it was implied that it was correct

your identification of what b represented was incorrect

you implied that you knew the length of the red leg was 12.8
your b represent the length of the third side of that right triangle highlighted in blue

[light scaffold]

so 12.8 is not b?

[hot herald]

in your initial equation no

[light scaffold]

why?

[hot herald]

because its what you wrote

in your equation

15.1^2 = 12.8^2 + b^2
you were using a to represent the length of the red side which is 12.8
which led to the approximation of b to be 8.01
there was no issue with any of that

and as mentioned earlier

swapping a,b doesn't really matter if you're being consistent
a represents one leg of your right triangle and
b the other

[light scaffold]

but it does not matter right?

[light scaffold]

ohh okay

[hot herald]

not if youre being consistent

you could've started with
15.1^2 = 12.8^2 + a^2
just instead of b representing the initially unkown side,
a would represent that

[light scaffold]

ohhhh

so i am just wrong with the placement?

[hot herald]

that's what i've been saying this whole time

[light scaffold]

okayy tysm

but is x really 8.01?

thats correct?

[hot herald]

no

i never said x is 8.01

i confirmed that the b in your original equation you set up was approximately 8.01

that b is a side of your right triangle

(x is NOT a side of that triangle)
applying pythag doesn't immediately give you x

your b represents the length of the third side of that right triangle highlighted in blue

[light scaffold]

ohhhh

so 8.01 is just the initial value?

[hot herald]

8.01 is the (approximate) length of the blue side in my colour coded diagram

[light scaffold]

but how do i get x?

[hot herald]

apply properties of radii

and apply (segment) addition/subtraction

note that the segment you highlighted at the very start (now coded in purple) was actually a radius of the circle (which is given)

[light scaffold]

ohh so x is the whole radius?

[devout valley]

Not quite...

What's the value of the radius?

[light scaffold]

8.01 + 8.01 = 16.02

[light scaffold]

16.02

[hot herald]

no

[devout valley]

Hint: you should be able to just read it off

[light scaffold]

why?

[hot herald]

things that look around the same or even the same might not be the same

[light scaffold]

12.1?

[hot herald]

no

[light scaffold]

8

12.8

[hot herald]

no

no

stop guessing

[light scaffold]

i am getting confuse now

[hot herald]

recall the definition of radius

[devout valley]

Why did you say 12.1?

[light scaffold]

typo

[light scaffold]

radius is any line from the center extending to any point in the circle

[devout valley]

On the diagram, do you have any such line?

[light scaffold]

yes

[light scaffold]

this one the violet

[devout valley]

...do you have another one?

[light scaffold]

yes the 15.1

[devout valley]

There we go!

[devout valley]

With that, can you tell me a relationship between b and x from this?

[light scaffold]

b and x are segments of the radius?

[devout valley]

Well, that wasn't what I was looking for...

Using the fact that the radius is 15.1, can you tell me what x is now?

[light scaffold]

ohh so 15.1-8.01?

so its 7

[devout valley]

That's what I was looking for 😉

[hot herald]

15.1 - 8.01 isn't quite 7

[light scaffold]

7.09 or 7.1 to be exact

thank you

.close

[full forum]

Channel closed

Closed by @light scaffold

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[next basalt]

s = Vo * t + at^2/2

[next basalt]

How would i solve out "a" in this case

In my head it would be fine to multiple Right side with 2 and the same with left side to move the /2

But my teacher moves the Vo * t first

Is there a reason to why that is?

[sharp flame]

Doesn't matter you'll get the same result at the end

[next basalt]

That's the problem

i'm not

Let me show you, one moment

,rotate

[next basalt]

I must have done something wrong because i'm not getting the answer that i'm looking for.

Is it because the *2 should be with every term on the left side?

[full forum]

@next basalt Has your question been resolved?

[next basalt]

wdym?

[devout valley]

That's where you went wrong, do you see why?

[next basalt]

no

[devout valley]

Don't you think that should be 2v_0?

[full forum]

@next basalt Has your question been resolved?

Channel closed

Closed by @next basalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

https://cdn.discordapp.com/attachments/486844875632017408/1051457053916405810/image.png

[torn jolt]

how do you rewrite the entire equation in terms of ln(x)

[spice orchid]

change of base formula

[onyx glen]

log_a(x) = log_a(b) * log_b(x)

[torn jolt]

yeah i just don't understand what it means to write the entire equation in terms of ln(x)

[spice orchid]

write log x as an expression involving lnx

[torn jolt]

how would that look like not worked out

[spice orchid]

not worked out?

[torn jolt]

without change of base done

[spice orchid]

well change of base is exactly how you do it, so im not sure what you mean

[torn jolt]

i don't really understand tbh

like is it log(x) = ln(x)?

[spice orchid]

you need to look at and understand the change of base formula

ln is log base e

[torn jolt]

yes

and log is log base 10

ok, question

is it

f(lnx) = log(x)

is that what we're doing

cause i don't even understand how ln(x) is being involved here

that's my problem

[spice orchid]

you want it to look like y = (something involving lnx)

[torn jolt]

okay yeah

[spice orchid]

and you do this by using the change of base formula to write logx in terms of lnx

[torn jolt]

if i want to involve ln(x) then do i have to multiply it or plug it in to a variable or

what exactly

[spice orchid]

is there a reason you're not looking at the change of base formula?

[torn jolt]

i know what the formula is

can you show me how to apply it

to this question

maybe i'll understand then

[spice orchid]

if you know the formula, then make one of the bases 10, and one of the bases e

you should be able to then write logx in terms of lnx

[torn jolt]

yeah i don't really understand still

[torn jolt]

i told you ik the formula that's not the issue

i just genuinely don't understand how to apply it still lmao

[spice orchid]

what is the new base we want

[torn jolt]

for log(x)?

ln i'd assume

[spice orchid]

base

[torn jolt]

yes base e

[spice orchid]

okay so b=e in the picture above

x is still x

and our old base a=10

[torn jolt]

alright

[spice orchid]

plug in

[torn jolt]

ln(x)/ln(10)

is that what you mean

[spice orchid]

yes

that is equal to logx

so you've written logx in terms of lnx

in particular, as (a constant)*lnx

[torn jolt]

alright i see

so you just wanna involve ln(x)

but then i don't understand

this already has the same base

but it's (1/x) instead of x

to make it the same you'd have to multiply it by *-1

so it becomes log(x)

but idk if that's right

[spice orchid]

try using some other log rules you know

well

actually

you are basically right

you are saying log(1/x) = -log(x) ?

[torn jolt]

yes

[spice orchid]

then yep just substitute that

[torn jolt]

oh

[spice orchid]

i was doing to say to use the quotient rule log(1/x) = log1 - logx, but it gives you the same

[torn jolt]

so it's just about finding what it's equal to

that's in the form of log(x)

alright last one then this would be

log(1) - 2log(x)

so it's -2log(x)?

[spice orchid]

indeed!

[torn jolt]

alright got it then

tysm

really did take me a while to understand it lol

[spice orchid]

no worries, well done

[torn jolt]

yep ty ty

.close

[full forum]

Channel closed

Closed by @serene falcon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz quail]

Find the quaratic rule that relates the number of balls to the term number (n) in the following pattern. If 66 balls are in the pattern, what tern number is it?

[quartz quail]

the pattern goes:

N = 1, balls = 1

N = 2, Balls = 3

N = 3, Balls = 6

N = 4, Balls = 10

I see a pattern

but idk how to write it

as a quadratic

Pattern I see:

For instance

N = 2

and balls = 1

for N =1

if you add them

N = 2

balls = 3

another is

Balls = 3

In N =2

and N = 3

3 + 3 = 6

N = 3 = 6 balls

but i cannot graph this

someone help pls

[fast peak]

can you find a quadratic given three points on the graph?

[quartz quail]

Should I graph this 1st?

uhh

N = 2

N = 1 has 1 ball

and 1 + 1 = 2

(1 as in N = 1 and the other 1 is the balls in n = 1)

but that doesnt work for the others

Pls help

[quartz quail]

hello

[fast peak]

say you have a quadratic f(x)=ax^2+bx+c and you know that f(1)=1, f(2)=3 and f(3)=6

do you know how to get the coefficients a,b and c from that information?

[quartz quail]

yes

of course

I mean

[fast peak]

good. that's exactly what the question is asking

[quartz quail]

perhaps?!

actually I dont know for all 3

but I can for one

like one at a time

[quartz quail]

how do you do it for all 3

at the same time

hm

[fast peak]

ok then maybe they don't want you to solve it like that

[quartz quail]

yes

[quartz quail]

can u walk me thru it

please

[fast peak]

https://i.imgur.com/6LsQ9YE.png

ok so this is the pattern, right?

[quartz quail]

ye

n = 4

[fast peak]

yes and you want to know the total amount of balls

[quartz quail]

hmm

yes

wait

[fast peak]

https://i.imgur.com/Ec74bMG.png

[quartz quail]

n^2

in this case 4

yes!

[fast peak]

what if I add more balls like this

[quartz quail]

that was what i was thinking

[quartz quail]

then its 16

balls

[fast peak]

not n^2 but close

[quartz quail]

oh yea

lol

this is 20

balls

[fast peak]

what are the sidelengths of the rectangle

[quartz quail]

Length = 5

Width = 4

[fast peak]

what if for example n=13?

what would be the sidelengths?

[quartz quail]

uh

width = 13

length = 14?

[fast peak]

yes

[quartz quail]

oh damn

[fast peak]

so n and n+1

[quartz quail]

yes

sir

[fast peak]

so how many total balls are there

[quartz quail]

in n = 13?

[fast peak]

in general

[quartz quail]

uh

there is n^2 + 1?

I mean

n^2 + n

perhaps

[fast peak]

yes

[quartz quail]

yessir!

[fast peak]

n(n+1)

and how many black balls are there?

[quartz quail]

in general?

[fast peak]

yes

[quartz quail]

half of that

[fast peak]

yes

[quartz quail]

yes

(n^2 + n)/2

[fast peak]

yes

[quartz quail]

is that it

[fast peak]

well now we know the formula

[quartz quail]

yes

[fast peak]

f(n)=(n^2+n)/2

[quartz quail]

n = 66

in the question

f(n)

(66^2 + 66)/2

[quartz quail]

I mean

no

there are 66 balls

[fast peak]

are you asking you for f(66) or f(n)=66

[quartz quail]

I am asking for n

if there are

66

[fast peak]

ok

[quartz quail]

balls

66 = n^2 + n/2

[fast peak]

brackets

[quartz quail]

132 = n^2 + n

[fast peak]

on second thought this would be easier to just continue the pattern by hand tho

[quartz quail]

ok

n^2 + n = 132

[fast peak]

cause 66 is still pretty small

[quartz quail]

I mean

n^2 + n - 132

[quartz quail]

is this right

[quartz quail]

yea

but i have to do it

thru quadratics

[fast peak]

n^2+n-132=0 but yes

[quartz quail]

yesssss

what factors of -132

add to 1

hmm

I got a website for that

cuz im too lazy

-11 and 12

the answer would be 12

I mean 11

x - 11 = 0

x + 12 = 0

[quartz quail]

since the balls cant be negative

as that is illogical

[fast peak]

well n-11=0 or n+12=0 but yes

dont switch the variable

[quartz quail]

Ok!

that is it right

[fast peak]

yes

correct

[quartz quail]

thank you for this great explanation

the visual representation of the equation really helps

[fast peak]

yes. visual representations are often very helpful

[quartz quail]

yea

[fast peak]

always try drawing some stuff

[quartz quail]

usually people in this server over complicate some things

especially with explanations

[fast peak]

even if it doesn't help, drawing it doesnt hurt

[quartz quail]

righteo

is that how you got advanced?

[fast peak]

do you mean the advanced role I have?

[quartz quail]

yes

[fast peak]

that's self assigned to be able to see certain channels on here

[quartz quail]

oh

i didnt know that lol

[fast peak]

doesn't really mean anything

but drawing some stuff when in doubt is definitely one of the tricks in my toolbox

always helps to try to visually represent some things

[quartz quail]

can u

tell me

all the tricks

in ur toolbox

[fast peak]

uhm

no I don't really have them in like an organized "list" or something

[quartz quail]

lol

damn

alr thanks

.close

[full forum]

Channel closed

Closed by @quartz quail

Use .reopen if this was a mistake.

[fast peak]

but with more practice etc you'll see some tricks for certain types of problems

that often help

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

how do I approach this problem

I tried using cosine law to set the x's to each other but I got a long equation that got me more confused

is there a more elegant solution

[onyx glen]

ABD is isosceles; drop an altitude from A onto BD and call its foot H

then DH = x/2

[torn jolt]

hmm okay I'll try to solve it with this new info

thanks

.close

[full forum]

Channel closed

Closed by @full adder

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

Can someone help me with these 3 questions?

Starting with 11

Looking for the length of the segment QR

QR and GF are congruent correct?

[north warren]

do you know what it means for 2 triangles to be congruent?

[torn jolt]

The same

Right?

[north warren]

yes, but side length wise

[torn jolt]

Equal

[north warren]

and note the order the triangle letters are written in

yes

meaning pq = ?

[torn jolt]

12

[north warren]

false

wait no

true

[torn jolt]

14**

[north warren]

lmao i read the letters wrong

[torn jolt]

Oh

[north warren]

yeah its 14

note thr fact that the order of the letters in the triangle congruence is very important

[torn jolt]

Pr= 14 tho

[north warren]

$\triangle PQR \cong \triangle EFG \Longleftrightarrow PQ \equiv EF, QR \equiv FG, PR \equiv EG$

$\triangle PQR \cong \triangle EFG \Longleftrightarrow PQ \equiv EF, QR \equiv FG, PR \equiv EG$

[glossy valve]

Kel.plush

[north warren]

along with the angle congruences

[north warren]

pr is 12

[torn jolt]

How

Pr and ef same side

Can anyone can help me?

[full forum]

@torn jolt Has your question been resolved?

[torn jolt]

no

Can anyone help me please?

Been sitting right here for 54 minutes now

[torn jolt]

A hour has passed

Qr= gf

Pq= eg

Pr=ef

Pq and eg =12

Pr and ef= 14

Now I'm stuck

https://tenor.com/view/cry-sad-gif-25488313

Almost 2 hours done passed

ima just pick another one

.close

[full forum]

Channel closed

Closed by @latent venture

Use .reopen if this was a mistake.

[torn jolt]

.closed

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

How can i simplify this boolean algebra expression?
(x & y & z) | (x & !y & !z) only using AND, OR, NOT

[torn jolt]

.close

[full forum]

Channel closed

Closed by @wooden oracle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[novel fable]

Hello could someone let me know if I am right to think that acceleration is 0 in i and ii

I think so but I wanna double check to avoid 20 minutes of confusion if its not

[atomic blade]

What's your force diagram with its components

I would let the slope be the x axis and the normal force's direction be the y axis

[novel fable]

I just need to know the acceleration

if its 0 or not

Just needed a yes or a no

nevermind i got it

.close

[full forum]

Channel closed

Closed by @novel fable

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cunning atlas]

@fast peak sorry, just one more thing, what if i want the image of an almost null sequence to be 0

[onyx glen]

may i get some context on this

[fast peak]

what is an almost null sequence supposed to be?

[cunning atlas]

yes sry.. so i need an example of group homomorphism that goes from the group of sequences with + to Z,+

[onyx glen]

real sequences?

[cunning atlas]

that sends an almost null seq to 0

sequences from N to Z

[onyx glen]

so integer sequences

[cunning atlas]

sequence with a finite number of terms

[cunning atlas]

yes

[onyx glen]

and you want just any homomorphism at all?

then why not the zero map?

[cunning atlas]

other than null

[onyx glen]

can you maybe show the entire problem exactly as stated

[cunning atlas]

its in french

[onyx glen]

i speak french

[cunning atlas]

this is the remaining part tho it doesnt matter

[onyx glen]

sure does

[cunning atlas]

ah lol

[onyx glen]

problem 2 asks to show that if a homomorphism from Z^N to Z is almost null then it is the zero map

[cunning atlas]

🤦‍♂️

i should read the whole question

thanks a lot

.close

[full forum]

Channel closed

Closed by @cunning atlas

Use .reopen if this was a mistake.

[cunning atlas]

tho

.reopen

[full forum]

✅

[cunning atlas]

any idea for teh first one

i have the sol but i want to see what your first intuition would be

i mean since its linear i could decompose the seq and id have an infinite sum of almost null sequences no?

[onyx glen]

so phi is an almost-null morphism and we want to show that any sequence of the form p^n a_n gets sent by it to 0, for a_n an integer sequence

[cunning atlas]

yeah

[onyx glen]

hm

[cunning atlas]

is there something wrong with this logic, its my first line of thought

[cunning atlas]

p prime

[onyx glen]

talking about infinite sums in this context seems fishy

[cunning atlas]

an infinite sum of 0 tho

tho i didnt use any hypothesis from the question so ofc its false

[onyx glen]

wtf

i can't seem to get any foothold

[cunning atlas]

dont forget its prime

[onyx glen]

don't quite see how that helps us.

[cunning atlas]

i still havent looked at the sol

[cunning atlas]

so this is isnt valid

[onyx glen]

ok

i think i got it

[cunning atlas]

ouf

[onyx glen]

a homomorphism is almost null iff it has the following property: for any two sequences (a_n), (b_n) that differ in only finitely many terms, phi((a_n)) = phi((b_n))

[cunning atlas]

waaaaaw

thats correct

[onyx glen]

and if a sequence is divisible by m ∈ Z (meaning all of its terms are divisible by m) then its image under any homomorphism also ought to be divisible by m

and the sequence p^n a_n is "finitely many terms away from" a sequence divisible by p, and one that's divisible by p^2, and one that's divisible by p^3, and so on.

[cunning atlas]

waaaaaw

youre incredible

so it's divisible by all powers of that prime

[onyx glen]

yes

and $\bigcap p^n \bZ = {0}$

[cunning atlas]

whats that

$\bigcap p^n \bZ = {0}$

[onyx glen]

the intersection of the sets pZ, p^2 Z, p^3 Z, ... is {0}

[cunning atlas]

the infinite intersection?

but i still fail to understand why my reasoning wasnt valid

[cunning atlas]

this one

[fast peak]

well you have an infinite sum

and want to use linearity on that

but linearity only works for finite sums

[full forum]

@cunning atlas Has your question been resolved?

[cunning atlas]

Ah

okay

thank you

[full forum]

Channel closed

Closed by @cunning atlas

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner solstice]

is there a faster way to workout what x is

instead of substituting numbers till its right?

[runic bloom]

in the first step, minus 42 from both side

so that you can factor

and find the roots

[stark geyser]

you can do it with delta after

[void widget]

There are two different ways that you could try substracting 42 in both sides and you could factor it

And the second way is
Use the quadratic formula and take out the values for x and sift the value where cx=0 ( where c is a constant) cause there will be 2 value of x you will get the answer

[inner solstice]

thank you

that app looks helpful

thanks

[void widget]

Wolfram alpha it's a website

[void widget]

When you are using quadratic just sift the RHS values to LHS is x is at LHS and Keep RHS = 0 by this you will get two values

[void widget]

Here it will be (x+9)(x-4)

[inner solstice]

ye

ive done that

[void widget]

Yes

[void widget]

5x-36??

[inner solstice]

is that not right

[void widget]

Where did the x² goes?

[inner solstice]

ill show you what i did

[void widget]

No you have written it wrong

[inner solstice]

i was rushing

one sec

[void widget]

Oh ok

[void widget]

Yeah but process?

You have to factor it by mid term

Using mid term*

You know how to factor quadratic polynomial?

[inner solstice]

nope my class have just started learning this

[void widget]

you have to use middle term factorisation

[storm sky]

x^2-4x+9x-36
x(x-4)+9(x-4)
(x+9)(x-4)

[void widget]

Like is its
x²+5x-36
Then it will be
x²-4x+9x-36

https://youtu.be/nJrEUZkDNpI

Watch this

[inner solstice]

i will

but what would x be

[void widget]

Well x has two values

Which are

[storm sky]

-9 & +4

[void widget]

x=-9
And x=4

[inner solstice]

the answer only has 1 value

it just says 4

[void widget]

It's not possible

[inner solstice]

no -9

but i understand what you mean -9

[storm sky]

it has 2 values but it must be saying only 1

[inner solstice]

is it because both brackets have equal to 0

both sides

[storm sky]

ye

[void widget]

(x+9)(x-4)=0 then check by putting the values

[void widget]

Yes

[inner solstice]

but x could be one value if u do it this way

[void widget]

If you put x=4 you will get 0 if you put x=-9 then you will get 0 that's my both are correct

[void widget]

@glossy valve

,w (-9+2)(-9+3)=42

[glossy valve]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[void widget]

It's correct too

,w (-9+2)(-9+3)

[glossy valve]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[inner solstice]

oh yeah

ill show u the answer sheet because it only says x=4

[void widget]

That's why x=-9 is true

[void widget]

Bruh

You should send the Actual question first you know

[inner solstice]

would -9 not work for this question

[void widget]

Cause a side you could not be = any negative

In geometrical figure

-9 is correct in the algebraic way

But in rectangle

You could see that

If you put

x=-9

Then one side will be -6cm and other will be -7 cm

[inner solstice]

ohhhhhhhhhhh my bad

[void widget]

And side couldn't be negative

[inner solstice]

sides cant be negative

[void widget]

That's why only 4 is correct only in this question

[inner solstice]

i see thank you

i forget things like that

[void widget]

Welcome

[inner solstice]

.close

[full forum]

Channel closed

Closed by @inner solstice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ocean plinth]

Can somone care to explain how this works because i really dont get it

[storm sky]

since it is square we have to multiply it 2 times
(x+y)(x+y)
now multiply x iwth the 2 nd equation and also mulyiply y with the 2nd equation and add em up
x(x+y) + y(x+y)
x^2+xy+yx+y^2
x^2+2xy+y^2

[glossy valve]

♡LexQa♡

[torn jolt]

Oh yeah what they wrote basically

[ocean plinth]

Im stupid thank you tho

.close

[full forum]

Channel closed

Closed by @ocean plinth

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar moth]

Can someone please help me with these Geometry questions

I want to know how to do these

[narrow granite]

the two angles of the base of an isoceles triangle/trapezoid are equal

so (BA,BC)=(CB,CD)

[cedar moth]

So it's gonna be 7x+16=x2+x

Right?

[narrow granite]

or 7x+16 = -(x² + x)

[cedar moth]

Thank you

.close

[full forum]

Channel closed

Closed by @cedar moth

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[willow fiber]

What method do I use to for this expression

[willow fiber]

10^102+10^100

---

10^100

[narrow granite]

take apart the fraction

[willow fiber]

How would I go about doing it

[narrow granite]

(a+b)/c = a/c + b/c

you're going to notice something immediately once you do that

[willow fiber]

Alright Ill write it down

[void widget]

What's your question?
(100¹⁰²+100¹⁰⁰)/100¹⁰⁰

[willow fiber]

Yeah

I can send a pic

[onyx glen]

better to send a pic if you don't know how to type your thing properly

[willow fiber]

Bots broken so had to improvise

[void widget]

100¹⁰²/100¹⁰⁰+100¹⁰⁰/100¹⁰⁰

[void widget]

Yeah

$\frac{10^{102}}{10^{100}}+\frac{10^{100}}{10^{100}}$

[onyx glen]

the bases are 10, not 100.

you could at least not actively distort the question

[glossy valve]

Arnab Pal

[void widget]

Yes that's why I was editing it

[willow fiber]

Yea I got to this point

[void widget]

Yes

Now just simplify and solve it

[willow fiber]

Can I simplify with / 10^100?

10^2 would be what I have left?

[void widget]

10²+1

[willow fiber]

Indeed

[void widget]

101

[willow fiber]

Thank you man

Understand the process too now

[void widget]

Yes welcome 🫂

[willow fiber]

.close

[full forum]

Channel closed

Closed by @willow fiber

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dire flame]

I tried the first one

I cant find a good video for the M thingie

My textbook has 1 example which doesnt even cover this

[fathom saddle]

M2,2 are "2x2 matricies"

[dire flame]

I know

Did i do the first one right?

[fathom saddle]

The M thingy?

[dire flame]

Lol my bad

[fathom saddle]

T takes matricies and produces real numbers

You've written down that you want to compute T(u) and T(cu) but I don't see that computation anywhere on the page

[dire flame]

you would just put it into the form a - b - c - d right?

[fathom saddle]

T(a b) = a - b - c - d
(c d)

[dire flame]

yeah

but since both matricies are equivalent

it should hold true no?

[fathom saddle]

u and cu are not the same matrix

However, yes cT(u) = T(cu)

[dire flame]

wait one sec

The left is cT(u) and the right it T(cu)

I think

I hate this class

[fathom saddle]

I really like that second last line

I'm realizing now we're using c to mean two different things whoops lol

[dire flame]

yeah i tried making one bigger to show it's different

so i cant rewrite the stuff inside the bracket on the left to T?

[fathom saddle]

I think you get how this works, let's make it concrete. I'll use m as the scalar.

Let's compute mT(u):
= m(a - b - c - d)
= ma - mb - mc - md

Let's compute T(mu):
= T(ma mb)
(mc md)
= ma - mb - mc - md

Whoa, they simplify to the same thing. So, mT(u) = T(mu)

[dire flame]

okay that makes sense ty

[fathom saddle]

And that's half the work done. The other half is T(u + v) and T(u) + T(v) which is done the same way

[dire flame]

okay thank you

do you understand the second one?

[dire flame]

the bottom question

Im just not sure how to approach it

[fathom saddle]

Also the same. Note this T is a function that takes a matrix as input, and produces a matrix as output

[dire flame]

would i be like u + v = that matrix?

[fathom saddle]

So for example, let's compute:
T(0 0 0)
(0 0 0)
(3 0 0)

= (0 0 1) (0 0 0)
(0 1 0) (0 0 0)
(1 0 0) (3 0 0)

= (3 0 0)
(0 0 0)
(0 0 0)

[dire flame]

ah okay that makes sense

[fathom saddle]

T acts on your matrix by multiplying it by another matrix

Matrix algebra is always linear!

No need to check the axioms for this, which I think would be very difficult haha

[dire flame]

oh alrighht

thank you very much

have a good day!

.close

[full forum]

Channel closed

Closed by @dire flame

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[narrow rose]

how do i work out e if 0.5e^4 = e^12

[torn jolt]

Is e here

Euler's number or some variable

[narrow rose]

some variable

[torn jolt]

Okay multiply both sides by 2 first

[narrow rose]

e^4 = 2e^12

[torn jolt]

Take the right term to the left

[narrow rose]

e^-8 = 2?

[torn jolt]

Nah just
[
e^4 = 2e^12
]
[
e^4 - 2e^12 = 0
]

[narrow rose]

oh

[torn jolt]

$h$

God dammit this bot breaks every day

Sigh

Anyways from e^4 -2e^12 = 0 factor out e^4

[narrow rose]

e^4(1-2e^3) = 0

[torn jolt]

no

Divide e^12 by e^4 what do u get

[narrow rose]

e^8

[torn jolt]

Yes

So not e^3

[narrow rose]

so e^4(1-2e^8) = 0?

[torn jolt]

Yes

U have two cases here

e^4 = 0
1-2e^8 = 0

[narrow rose]

ok

[torn jolt]

First one is just when e = 0, what's the second

[narrow rose]

e^8 = 0.5 but im not sure how to get rid of the ^8

[torn jolt]

Take the 8th square root of both sides

[narrow rose]

0.917

[torn jolt]

It's an even polynomial

It will have two solutions

[narrow rose]

and 0

[torn jolt]

±

[narrow rose]

oh

ok ty for the help

.close

[full forum]

Channel closed

Closed by @narrow rose

Use .reopen if this was a mistake.

[torn jolt]

±0.917 and 0 ig

[torn jolt]

Aighty

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wild fable]

hi, can someone help w this?

[devout valley]

Can you relate $f(x)$ being increasing to a statement about $f'(x)$?

[glossy valve]

chartbit

[wild fable]

it increases when f'(x) is positive

[devout valley]

Yea, so try and find where that is...?

[full forum]

@wild fable Has your question been resolved?

Channel closed

Closed by @wild fable

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

do you guys know by any chance how one could start with this ?

[brittle frost]

What is the question you need help with? Please provide more details so that we can better assist you.

[warm abyss]

Substitution u = sqrt(x)

[torn jolt]

integrating it

[torn jolt]

ah

ill try that brb

@warm abyss

do both sqrt x become u ?

or only one is chosen?

[north warren]

yeah both

[torn jolt]

ok

[north warren]

youre changing the variable to differentiate on from x to u, which changes it everywhere in the integral

[torn jolt]

ok it worked

thanks

.close

[full forum]

Channel closed

Closed by @signal quiver

Use .reopen if this was a mistake.

[warm abyss]

The sqrt(x) in the numerator becomes u. The one in the denominator disappears because du/dx = 1/(2sqrt x)

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heavy geyser]

how do they go from 2nd to 3rd line

[brittle frost]

The third line of the equation is derived from the second line through algebraic manipulation. To go from the second line to the third line, you need to divide each side of the equation by the coefficient of x, which is -3 in this case. After doing this, you should be left with the third line of the equation.

[heavy geyser]

the coefficient of x is -3?

how so

isnt it npi/2 or n/2

what

the n are integer multiples

this is fourier series

here was the question for more context

i see it now

.close

[full forum]

Channel closed

Closed by @heavy geyser

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glass trench]

Hey math people

[glass trench]

The question, the teacher's answer, and then my answer

I know the first term in my answer is functionally equivalent to the first term in his answer

But I'm not sure what's going on with the second term

[ivory cairn]

pretty sure they're also the same

m-k+1 = (m+1) - k

[glass trench]

Derp

Are you a robot, Churnos? Or are you a human?

I think the details of my question are pretty apparent, though implicit

[spice orchid]

very suspicious

[glass trench]

Hey, Churnos

Quick turing test

What is love?

[gritty rose]

baby don't hurt me

[glass trench]

I am Bender, please insert gerder

.close

[full forum]

Channel closed

Closed by @glass trench

Use .reopen if this was a mistake.

[torn jolt]

Hi there! How can I help you? @gritty rose

[gritty rose]

hey LexQa. quick turing test

what is hate

[torn jolt]

I'm not sure what you mean by that.

[spice orchid]

It's definitely a tough one!

[ivory cairn]

true or false: This sentence is false.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limber flicker]

oop

.close

[full forum]

Channel closed

Closed by @limber flicker

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pale shadow]

Hello

[pale shadow]

so some basic math here I think

so after a raise which was 750$

a worker is now getting paid 2282$

[brave blaze]

let him finish

[pale shadow]

how do I calculate how much percent

It increased

[gritty rose]

typing the question

[torn jolt]

It's a bot @brave blaze

Don't mind it

Come on guys 😭

[brave blaze]

[pale shadow]

shahahahah

[spice orchid]

okay if you're gonna be a bot/pretend to be a bot, atleast dont straight up give out answers

[pale shadow]

oh okey so I got it right

nvm

but 2282 isn't the original

it's the after

[torn jolt]

[pale shadow]

is it still correct ?

[gritty rose]

did you even read what sigma said?

[spice orchid]

lol, yeah and deffo dont give out wrong answers

you're right nick you need to find out the original money

[pale shadow]

well theres no original

and the raise as I said is 750

[gritty rose]

what did he say

[spice orchid]

you know they added 750 to the original and they got 2282

you can figure out the original

[pale shadow]

but I got it just 2282 minus 750

[spice orchid]

yeah

[pale shadow]

yuh

💪💪💪

[spice orchid]

so you just want the percentage that 750 is of the original

Churnos go and do bot stuff somewhere other than the help channels

[pale shadow]

damn why yall doin bro like that💀

[gritty rose]

<@&268886789983436800> can you rid the bot please

[spice orchid]

our lord and pointed corner saviour

[full forum]

@pale shadow Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gritty hare]

knowing how to correctly solve these two questions (Factorization) would help out

[shrewd hamlet]

What’s (x-3)^2

[gritty hare]

wdym

?

[shrewd hamlet]

Look at ur first problem

[gritty hare]

yup

[shrewd hamlet]

What’s the first term

[gritty hare]

cant you zoom in?

(X-3)^2 - (x+2)(x-1)

thats the first question

[graceful vessel]

(x-3)(x-3) i think

[shrewd hamlet]

Ik what the question is

expand out (x-3)^2

That’s what I was asking

[gritty hare]

your asking me to expand it?

[graceful vessel]

Yea (x-3)(x-3)

[shrewd hamlet]

.

It’s jacks problem, let him do it

[gritty hare]

well no point of trying to solve it now

[graceful vessel]

K

[gritty hare]

he already shown it

i'll do future steps

[graceful vessel]

I mean there is 2nd prob

[gritty hare]

i'll just solve the 2nd side of the equation

be right back

X^2 + X -2

[shrewd hamlet]

Why are u continuing with the problem?

[gritty hare]

are you not supposed to

[shrewd hamlet]

And that has alrdy been provided

It asks u to find errors

We found the error alrdy

[gritty hare]

no no no theres a box below the question asking you to solve it

[shrewd hamlet]

Solve what? They’re just expressions

O correcting them?

[gritty hare]

solve what the student worked on

I wants to headlight errors then solve itself

[gritty hare]

without the mistakes the student made

[full forum]

@gritty hare Has your question been resolved?

Channel closed

Closed by @gritty hare

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glad prairie]

If I got the meaning of the Bolzano theorem then
If f continue in [a,b], c€[a,b] <=> f(c)€[f(a), f(b)]
Right?

[astral coral]

Yes, that is a correct statement of the Bolzano theorem.

[glad prairie]

Ok thx
.close

.close

[full forum]

Channel closed

Closed by @glad prairie

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[astral yew]

My math teacher was not very helpful when I requested extra help, and am still very confused 😭

[median dawn]

You have to use opposite angle theorem to fill in all the other angles and then use that a circle of angles adds up to 360

[astral yew]

Alright!

[median dawn]

So CFG is 3x by opposite or opposing angle theorem

Not sure exactly what it's called

[astral yew]

How exactly would that be written down?

[median dawn]

Statement: angleCFG is 3x
reason: opposing angle theorem with ACB

Btw

Which angle are you trying to find I might have messed up

Cuz actually angleFCG is 3x

Using proper notation

The angle opposite the 3 x angle

CFG is the angle in the lower left corner of the triangle

[astral yew]

Mhm

I’m trying to prove cfg is thirty degrees

[median dawn]

Yeah

So now we use parallel line stuff to says that CFG is 2x

I again don't remember the theorem

But basically you have a line connecting parallel lines then the opposite interior angles are equal

[astral yew]

Ok

[median dawn]

FGC is 7x by the same theorem

[astral yew]

Like it’s parallel right there?

[median dawn]

Well because DE and FG are parallel that angle is 2x both there and down at the bottom

Well it's 2 x there for sure

Anyways once you have all the angles in terms of x you just set them equal to 180° and remember that what you are looking for is 2x

If you have your text book you should be able to find the theorem I'm talking about and use it to justify

[full forum]

@astral yew Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[atomic vortex]

Do I check the regions around the vertical asymptotes aswell?

for where its concave up

?

[full forum]

@atomic vortex Has your question been resolved?

[sleek drum]

have you taken the second derivative?

[full forum]

@atomic vortex Has your question been resolved?

[atomic vortex]

yep

Thats how I got the inflection point

[full forum]

Channel closed

Closed by @atomic vortex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

when they find out -1/2 is a zero

how do they get 2x+1 from that

wouldnt it be (x+0.5)

[eager violet]

Yes, but that's the same as (1/2)(2x + 1), and we don't care about lingering constants