By hamilton on A^2021
#help-28
summer jacinth
So that would mean $A^2 - trace(A)A = 0$ so either A is the zero vector or the trace of A is zero. Either one would mean the other is also true.
glossy valveBOT
NoahN
summer jacinth
well i guess you could have the matrix $\begin{bmatrix} 1 & 0\ 0 & 0\end{bmatrix}$
glossy valveBOT
NoahN
summer jacinth
I'm sorry man this has me stumped
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remote nest
I have this set {1,2,3,4} and the relation from the set R={(4,4),(3,3),(1,4)}
So, the problem is to determine if the relation is symmetric, asymmetric, or antisymmetric.
The answer was antisymmetric which is I understood why but it should also be asymmetric too since (1,4) is an elemnt in the relation but (4,1) is not.
remote nest
am i missing something?
remote nest
I have this set {1,2,3,4} and the relation from the set R={(4,4),(3,3),(1,4)}
So...
the answer was only antisymmetric but i just dont understand why it is not asymmetric
lament rock
You are correct that the given relation is both antisymmetric and asymmetric. A relation is antisymmetric if it satisfies the property that for all elements a and b in the set, if (a,b) is in the relation, then (b,a) is not in the relation. In this case, the relation contains the pairs (4,4), (3,3), and (1,4), and it does not contain the pair (4,1). Therefore, the relation satisfies the antisymmetry property.
A relation is asymmetric if it satisfies the property that for all elements a and b in the set, if (a,b) is in the relation, then (b,a) is not in the relation, and (a,a) is not in the relation. In this case, the relation contains the pairs (4,4) and (1,4), but it does not contain the pair (4,1), and it does not contain any pairs of the form (a,a). Therefore, the relation also satisfies the asymmetry property.
Therefore, the given relation is both antisymmetric and asymmetric. It is possible for a relation to be both of these types at the same time, because the definitions of antisymmetry and asymmetry are not mutually exclusive.
torn jolt
Translation
Make a separate drawing for each question.
6p 4 In parallel projection, draw a tetrahedron with edges of 6 cm.
4p 5 Draw a second tetrahedron at 4 such that all corners of the bases form a regular hexagon.
Due to corona I have lacked a large amount of education, especially at maths, and I have zero clue how to do this. I managed to draw the tetrahedron, but I have no clue how to do the rest. the picture of the tetrahedron I sent is how my teacher told me to draw it, but I cannot find how to connect that with a second tetrahedron it can make a regular hexagon.. help would be dearly appreciated!
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**Translation**
Make a separate drawing for each question.
6p 4 In parallel proj...
@torn jolt Has your question been resolved?
torn jolt
<@&286206848099549185>
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torn jolt
..
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sharp seal
i feel like im super close to getting this but i just dont know what to do about the 3 under the du
stiff minnow
Find an equation of the line perpendicular to y=2/3x+5 that passes through the point (7.-10) If possible, write the equation in slope-intercept form.
hollow herald
i feel like im super close to getting this but i just dont know what to do about...
you can take the constants outside the integral
or add/subtract... whatever you wanna do
as long as it doesn't have a relation with the variable you're integrating with respect to(in this case "u")
stiff minnow
as long as it doesn't have a relation with the variable you're integrating with ...
Find an equation of the line perpendicular to y=2/3x+5 that passes through the point (7.-10) If possible, write the equation in slope-intercept form.
sharp seal
so like could i take the 3 outside the integral like
hollow herald
yes good job!
slender surge
hello
slender surge
does marginal dependencies work when P[(A & B) ^ C] = P(A & B) x P(C)
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leaden roost
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leaden roost
Can anyone help me how to figure these?
jade lynx
hi
leaden roost
Hello
hollow wharf
What part are you stuck on?
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brisk obsidian
Can anyone help me how to figure these?
Look at the "points" on the graph and map it to each axis.
leaden roost
Look at the "points" on the graph and map it to each axis.
So its 3 and positive 1?
brisk obsidian
One moment, I'm making a graph that will hopefully explain it better.
Where the graph exists on the x-axis will be the domain.
And because there is an empty circle at (4,-4), that means x=4 is not inclusive in the domain.
So the domain exists from [-4, 4) as indicated by the vertical orange lines.
For 1), to determine the Domain, imagine vertical lines that intersect the x-axis. Where they intersect will be the domain.
To determine the Range, imagine horizontal lines that intersect the y-axis Where they intersect will be the range.
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native wolf
“Bill bought 38 1/2 feet of wire fencing to put around his blueberry plants. He cut the wire into several pieces, each one measuring 5 1/2 feet. How many pieces of wire did he have after making the cuts?”
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“Bill bought 38 1/2 feet of wire fencing to put around his blueberry plants. He ...
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fresh cypress
What is the reason of these coefficients in the general formulae for dirichlett regularization of a summation?
fresh cypress
So, Basically
I've been trying to find the general formulae for the dirichlett regularizations of various summations
These are all the formulae
My question is, where do we derive the coefficients and constants we get here?
They must have a source from somewhere
and where do we get these from?
It would help me out a lot
thank you
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fresh cypress
<@&286206848099549185> Can one of you help me out perhaps?
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torn jolt
guys i have an assumption that a matrix that has 2 linear dependent columns already has a determinant of 0 ? am i correct?
fast peak
yes
torn jolt
yes
also here at this matrix which clearly has rank 4 it asks me what dimension does the solution space have?
flint moon
fast peak
also here at this matrix which clearly has rank 4 it asks me what dimension does...
remember rank nullity theorem
or just explicitly calculate the solution space
torn jolt
i don't even know what that is, i am a cs freshmen
fast peak
rank(A) + dim(ker(A))=n
potent acorn
stop hijacking help lobbies
torn jolt
rank(A) + dim(ker(A))=n
nxn is the the matrix right? rank (n) in our case so + dim(ker(A)) what i need to find out?
torn jolt
no
fast peak
ker(A) = {x: Ax=0}
is the solution space of Ax=0
and the solution space of any system Ax=b always has the same dimension as the kernel ker(A)
torn jolt
and the solution space of any system Ax=b always has the same dimension as the k...
is this the solution space?
the solution space of Ax=b
fast peak
if anything that's a solution
the solution space is a set
which in this case only contains this vector
torn jolt
so what do i need to do to get the kernal and the dimension
fast peak
if a set only contains one vector then it has dimension 0
otherwise like I said, rank-nullity
you know rank(A)=4
and n=4
so dim(ker(A))=0
torn jolt
so dim(ker(A))=0
if it had only 3 ranks despite being 4x4 would the dimension be 1?
fast peak
yes
fast peak
dimension of solution space, yes
you can also word it as dim(column space) + dim(solution space) = n
cause the first part is exactly what the rank is
torn jolt
ah ok nice thx
slender pond
Can someone help me with question 4c please
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Can someone help me with question 4c please
wide sundial
slender pond
Not really I think my school taught how to answer this question differently
I’m supposed to use sin^2X + cos^2X = 0
Or sinX/cosX= tanX
But I’m not sure how I can use it to answer this
Trig identities
This is what I have done
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idle crow
I'm trying to solve for all real solutions to the D.E below. I get that the roots of the charistic equaiton are $r = \pm 2i$, which should hten give me that the homogenous solution is $y_h = A\cos(2x)+Bi\sin(2x)$, however, this includes complex solutions as well
glossy valveBOT
Chippotle Maths
idle crow
The answer for the homogenous part is $y_h = A\cos(2x)+B\sin(2x)$
glossy valveBOT
Chippotle Maths
spice orchid
because of identities like $\cos (\theta) = \frac{e^{i\theta} + e^{-i\theta}}{2}$
glossy valveBOT
ΣAC
idle crow
Ahh, ocmpletly forgot about those! I'll try it again with the identities instead of just answering with the standard form
spice orchid
https://www.mathsisfun.com/calculus/differential-equations-second-order.html scroll down to "complex roots" for a reminder
idle crow
Will read that as well
Thank you, ΣAC!
I consulted my textbook as well as the website above. I still do not understand why one can simply do this. In my textbook they did the following manipulation
Where $B = i(C_1-C_2)$. This means that $B$ is complex unless $C_1 - C_2 = -i$ (its conjugate, think that's the name in English)
glossy valveBOT
Chippotle Maths
idle crow
I tried using some of Euler's identities for cos and sine as well but can't really seem how to derive a formula where the answer is $Acos(2x)+Bsin(2x)$ where both $A$ and $B$ are real
glossy valveBOT
Chippotle Maths
idle crow
I fully understand the textbook's derivation of the formula... but that formula is only correct when B is complex... or am I mistaken?
idle crow
Where $B = i(C_1-C_2)$. This means that $B$ is complex unless $C_1 - C_2 = -i$ (...
or do we have some initial conditions for C_1 and C_2 so this is true? I'll try again to derive the formulas where A and B are real using ΣAC's tips.
ahh now it clicked.... really tired so it didn't even cross my mind that B can be complex with Im(B) = 0, oopsie!
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white willow
can someone help me understand this question? we never learned this in class at all.
white willow
wild sleet
like there's a red box and a blue box
and it asks the proportion of numbers in a box
signal osprey
signal osprey
how do I do these three bc im clueless
atomic blade
Use your trig identities and then factor
signal osprey
if you do them for me ill give you ten bucks
signal osprey
twenty?????
atomic blade
I ain't doing them for you
atomic blade
Refer to your unit circle
atomic blade
signal osprey
so how do i do that
atomic blade
(cosine, sine)
Each coordinate point
Find which points have the x-value of -sqrt(3)/2
signal osprey
so i just plug each one in
atomic blade
Well you have to look at the angles each point corresponds
signal osprey
yes what about them
atomic blade
You can google what arc stuff first
atomic blade
I'll leave you this with:
Google to do to arcsine, arccosine, arctangent
Learn u-sub
Look at your trig identities
If you excuse me I have to eat
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verbal musk
$$T = \Bigg{ \begin{pmatrix} x \ y\z\end{pmatrix} : -y \le x \le y\Bigg} $$
verbal musk
is this a subspace????
glossy valveBOT
please request a new nickname
verbal musk
hint is that T is a cone in R3
outer moth
Is it not?
verbal musk
idk man
verbal musk
i did all the addition and stuff but i cant even visualize it
vague kayak
Precisely
minor gazelle
Need help
slate zenith
then ask for it
light sonnet
• Show your work, and if possible, explain where you are stuck.```
waxen cloud
true, true, false
minor gazelle
Thx
waxen cloud
well I think so...
waxen cloud
yeah yeah, you do 400 times 6 hours
and it equals 2400
so they will make 2400 bicycles in 6 hours
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gentle smelt
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gentle smelt
I could use some help with this
waxen cloud
so you put E0 which is 10^4,4 at the bottom and E which is 3,4*10^14 at the top
gentle smelt
If so how did you get it
waxen cloud
using a calculator
gentle smelt
Oh that’s simple
waxen cloud
can you use one or you can't use one for this exercise
gentle smelt
I don’t have a graphing calculator so it doesn’t give me a similar answer
gentle smelt
can you use one or you can't use one for this exercise
I can
waxen cloud
no you don't need a graphic calculator
gentle smelt
Did you get 67,543
waxen cloud
gentle smelt
Oh I see
waxen cloud
yeah?
waxen cloud
well E means Exp which is like doing (3,4*10^14)
gentle smelt
Oh ok
waxen cloud
good job
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torn jolt
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glossy valveBOT
hibyehibye
glossy valveBOT
hibyehibye
torn jolt
so i got
hearty prairie
no
torn jolt
$\int_{0}^{8} 9800\pi (4-\frac{x}{2})^2 x dx$
glossy valveBOT
hibyehibye
torn jolt
I'm going top down
could anyone help me see where I went wrong
I calculated r by doing
$\frac{4}{8} = \frac{r}{8-x}$
glossy valveBOT
hibyehibye
glossy valveBOT
glossy valveBOT
hibyehibye
torn jolt
$\frac{32-4x)}{8} = r$
glossy valveBOT
hibyehibye
torn jolt
$4 - \frac{x}{2}= r$
glossy valveBOT
hibyehibye
glossy valveBOT
torn jolt
**hibyehibye**
where did I go wrong simplifying this im so dumb
,w is (4(8-x)/8) = 4-(x/2)
glossy valveBOT
torn jolt
wat
torn jolt
,w integral from 0 to 8 of 9800pi(4-x/2)^2x dx
why are these different answers then
torn jolt
,w integral from 0 to 8 of 9800pi((4(8-x))/(8))^2x dx
.
im actually so lost
,w is (4(8-x))/8 = 4-(x/2)
glossy valveBOT
torn jolt
,w integral from 0 to 8 of 9800pi((4(8-x))/(8))^2x dx
glossy valveBOT
torn jolt
,w integral from 0 to 8 of 9800pi(4-x/2)^2x dx
glossy valveBOT
torn jolt
,w integral from 0 to 8 of 9800pi((4(8-x))/(8))^2x dx
why are these integrals different is my updated question ^
,w expand (4-x/2)^2
,w expand ((4(8-x))/(8))^2
torn jolt
ok im even more confused now
torn jolt
why are these integrals different is my updated question ^
anyone?
spice pond
why is this wrong
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why is this wrong
spice pond
this is the answer so i assume i missed a 1/2 somewhere but idk where
gritty rose
3rd line from top
You're missing a factor of 2 from one of the squared substitution identities
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worthy dock
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deft zodiac
,rcw
glossy valveBOT
deft zodiac
hi
worthy dock
hi
deft zodiac
what dont u get
worthy dock
whats the question mean i dont get what to do
deft zodiac
,w graph y=x^3
glossy valveBOT
deft zodiac
so
P moves along that at some rate
aka
dx/dt=5
u want to find
dy/dt
when x=1
for b u wanna find
(dy/dx)/dt
ok im heading off to buy stuff
rich mesa
How many subsets of {1, 2, . . . , n} have no two successive numbers?
rich mesa
Why is the answer n-k+1 above k
indigo ore
Well, this is not the answer, k means nothing here
deft zodiac
:0
torn jolt
;0
topaz valley
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native wolf
“Joyce is making cookies. The recipe calls for 1.25 cups of sugar to make one dozen cookies. How many cups of sugar will she need to make three dozen cookies?”
native wolf
Then they just give me this, “1.25/3 = x/3”
torn jolt
Weird are you sure it's not 1.25 = x/3 or sth
Or in that case it means 1.25=x so find 3x=
native wolf
Weird are you sure it's not 1.25 = x/3 or sth
Oh wait you’re right it’s 1.25/1.
My bad.
So it’s 1.25/1 = x/3.
native wolf
Find x and you're done
How do i start?
torn jolt
You can multiply by 3 each side and it's basically done
deft zodiac
amaze
native wolf
So 1.25 times 3?
torn jolt
Yeah
torn jolt
Yeah that's the answer i mean it makes sens with your question right
She need 3 times more ingredients for 3 times the result
native wolf
Yeah that's the answer i mean it makes sens with your question right
Okay thankyou!
.close
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crystal leaf
Help
sacred fog
what do you need help with
sacred fog
don't expect us to put more time into helping you than you spent at asking your question
"I need help with this" isn't gonna cut it. you have to tell us what part you're struggling with / have trouble understanding for us to be able to help you >.<
crystal leaf
I don't know hot to even start this two tasks that why i need help
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slate shell
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onyx glen
@slate shell which of these best describes your confusion?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
2
I expanded and got 4x-3xi-y-6yi-3=0
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rocky vale
I expanded and got 4x-3xi-y-6yi-3=0
From here, try gathering the real terms and imaginary terms together
slate shell
From here, try gathering the real terms and imaginary terms together
re = 4x-y-3 and Im=-3x-6y
rocky vale
and the entire complex number is equal to 0
which means the real and imaginary parts are both equal to 0
slate shell
so then do I solve both equations simultaneously?
rocky vale
That should work
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tall tendon
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tall tendon
I got 11149 to be the most reasonable but it's wrong
I don't know what I am missing since I logically eliminate smaller options
onyx glen
,w 20 smallest primes greater than 10000
hollow herald
hollow herald
I got 11149 to be the most reasonable but it's wrong
I believe you can reasonably get lower though, (a - b) can't be even so 10000s isn't an option
onyx glen
clearly we must have a-b make up the first two digits and a+b the last three
or actually maybe it's one and four but that would require c to be at least 11000
actually. hm.
10xxx is ruled out. bc this way a-b is even (being 10), so a+b is even and c will be even too
so that's no good
11003 works, doesn't it?
a-b=1, a+b=1003
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tall tendon
oh :o makes sense... well, that's that then: 11003
Can't start with 0
hollow herald
a-b=1, a+b=1003
Ann explained how it's 11003
tall tendon
Oh actually yeah I got it
hollow herald
oh, sorry Ann, didn't mean to ping
onyx glen
it's fine
tall tendon
Thank you
glacial tiger
Hello...
glacial tiger
I need some help on a few math problems.
gritty rose
glacial tiger
fallen bone
What does it mean to be an x-intercept?
glacial tiger
The x-intercept is where a line crosses the x-axis.
fallen bone
Where does the line cross the x-axis in the diagram drawn?
stray schooner
You need in the first equation to define x proportionally to y ( you need to have x = ...y)
Then on the second equation you change the value of x with the value that you found earlier and now there is only one unknow so you can solve the equation normally
glacial tiger
But x proportionally to y is going to be x/2 - 7, right?
stray schooner
I don't quite understand where you get x/2 -7 but what I'll do is
x + 2y = 7
x = 7 -2y
glacial tiger
Oh, yeah. Sorry, I divided by 2 then subtracted by 7.
So, now we know that x = 7 - 2y, how would we find the second equation?
stray schooner
Now you change the value of x with what you just found so with the example you will get:
2(7-2y) + 2y = 13
Then you just solve the equation
glacial tiger
Oh, ok. Though I do have another question before I close this...
How do you become a helper?
stray schooner
I don't exactly remember exactly where it is but in the first salon ( in the introduction category) there is somewhere a bot that let you chose what role do you want
And you can choose helper
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glacial tiger
.reopen
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torn jolt
integral of sin^3(x) cos^2(x)
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integral of sin^3(x) cos^2(x)
finite bluff
anyone familiar with inertia moments
finite bluff
Ixx?
errant lion
hello
errant lion
anyone familiar with inertia moments
yep, what do you need help with?
errant lion
let me check
errant lion
yeah
finite bluff
im asked to find Ixx for each section
so Ab and EF have no y or z
so its Ixx is zero
errant lion
yep
finite bluff
im confused by
errant lion
what?
finite bluff
as y remains constant
errant lion
true
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old sapphire
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old sapphire
im trying to find the sum using this table
it looks like e^x where x=5 but i dont know how to account for the (n+1)! if that was the case
stable heart
you can change it to $\sum_{n=1}^\infty\frac{5^n}{n!}$ and adding the first term
glossy valveBOT
Duh Hello
stable heart
or, subtracting it in this case
$\sum_{n=1}^\infty\frac{5^n}{n!}=\sum_{n=0}^\infty\frac{5^n}{n!}-\frac{5^0}{0!}$
glossy valveBOT
Duh Hello
old sapphire
so that would be e^5-1?
stable heart
yea
hollow badger
Hey
dense arrow
i was wrong because i said this does not have a hole, how does this have a hole at (0, 15/2) if there is no same term at the numeriator and denominator?
fathom terrace
Did I draw #30 correctly?
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Did I draw #30 correctly?
glossy valveBOT
wise knot
Need help
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fathom terrace
not to scale so sure
Yeah ik I just mean, do I have to do add anything?
Like does it need to be cut by a diagonal r smth
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hot mango
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brisk obsidian
Are you using a website?
It's possible you may have exceeded the required precision.
light sonnet
Put it in exact form, aka fraction
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hot mango
Put it in exact form, aka fraction
mk
verbal silo
verbal silo
<@&286206848099549185>
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dense jungle
Ok so in essence your question is saying you've got a bottle of x percentage wine and y percentage wine how can we get to z percentage wine
As long as z is between x and y it's reasonable that this is possible
So let's set the values to something simple
We've got 0% and 100%, how many litres of each to get to 50%?
verbal silo
500ML !!!!
dense jungle
Ok now how did you get there
verbal silo
i don't understnad how to really set up the algebra for it
dense jungle
I'll give you a hint, you used the average when you just found that value
Can you think of how to write that in terms of x y and z in the example i just gave you?
verbal silo
don't know
dense jungle
So you've got 0% and 100%
Let's assume we use one part of each
The formula for an average is the sum of your values divided by the total amount of values
When you got 50% you essentially did 0 + 100 / 2
verbal silo
yes?
dense jungle
So now let's say we mix 2 parts 100% and 1 part 0%
verbal silo
maybe x+y/2 = z?
dense jungle
maybe x+y/2 = z?
Yes when we have equal parts that's the formula
But you usually don't have equal parts
dense jungle
So now let's say we mix 2 parts 100% and 1 part 0%
What percentage does this create
verbal silo
50%
dense jungle
Imagine you are mixing paint
If you are mixing white and black 2 parts white 1 part black will be lighter than 1 part white 2 parts black
verbal silo
mhm
dense jungle
So the proportion when you are mixing matters
Do you have a different answer to the percentage of 2 parts 100% and 1 part 0% mixture now?
verbal silo
ohh 66%?
verbal silo
100 + 100 +0 / 3 = 66?
dense jungle
Yes
Ok now let's say i have 75% solution, how many parts 0% and how many parts 100% do i need to get there?
dense jungle
3 parts 100% one part 0%
Yea, can you come up with a way to mathematically explain this answer?
verbal silo
let y=0%, x=100% , z = 75%
3x + y / 2 = z?
dense jungle
Yes, now that you understand the problem I'll explain what your teacher wants you to be doing
You set the sum of solution 1 and solution 2 to the total amount of liquid
And then make a second equation involving the percentages
And solve because you've got two equations now
Make sure you don't rely too hard on formulas though, a strong intuition is far more useful than being able to spew xs and ys
verbal silo
yeah sorry still don't have a clue
all i've tried so far is
Wine = x, Water = y
A=2xy
B=5yx
dense jungle
X and y are the liquid volume from each bottle
Not distinguishing between water and wine
Set up your equations to be something like this
%1 X + %2Y = %3V
X + Y = V
verbal silo
Set up your equations to be something like this
%1 X + %2Y = %3V
X + Y = V
can send me your work solutions of this question and i'll just analyse it and ask questions thanks
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sinful raven
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hollow herald
so? what's the issue?
sinful raven
im not sure how they get from step 2 to 3
hollow herald
you don't know the integral for cosec x?
sinful raven
oh thats how they got there
woven snow
sinful raven
alr thank you forgot about those lol
hollow herald
the 4th one is particularly sketchy
sinful raven
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woven snow
severe basin
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torn jolt
Hello i need help out the steps to solve the sqrt(a^6) * sqrt (a^6)
shrewd cargo
√(a÷6) × (√a÷6) right?
spice orchid
√(a÷6) × (√a÷6) right?
Where are you getting division from
torn jolt
can you help out with the steps to follow inorder to find out the solution
shrewd cargo
It's just a a^6
Unless I'm missing something
When you times a square root by it's self you just get rid of the square root
torn jolt
i know the answer is sqrt a^6 but what idk is the steps on how we get the answer
shrewd cargo
What's √4?
torn jolt
2
shrewd cargo
What's 2 × 2?
torn jolt
4
shrewd cargo
The square root of something is finding out what needs to be times together to find the number
So √(a^6) × √(a^6) is just a**6
torn jolt
I understand that but how do we solv a question like this for example: sqrt (a^6) * sqrt (a^4)
shrewd cargo
You're not doing imaginary numbers right?
torn jolt
yeah, what i need is just method that is used to solve questions like these
shrewd cargo
The answer is a**5
Just halve both powers and add them together
Since when you times you add the powers
And when you square root you'll divide the power by 2
torn jolt
I understand that but how do we solv a question like this for example: sqrt (a^6...
how to do we solv a question like this
torn jolt
What's halve of 6?
3
torn jolt
a^3 × a^2 = a^5
So the answer will basically be sqrt of a^5
shrewd cargo
Yeah
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acoustic pebble
Helo
tardy verge
onyx glen
Does the diagonals of an isosceled trapezium bisect each other?
no, not necessarily.
(in fact they only do that if your trapezoid is a rectangle, or so it appears to me at first glance.
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mighty torrent
valid stump
it's all about being able to spot these things isn't it
I'll practice more, thank you
I won't close this just yet, I still want to solve it
thanks
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vernal haven
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torn jolt
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torn jolt
we're asked to solve for theta
I got 31.4
wouldn't there be a second solution of 148.6?
on the ans key though they say only 31.4 degrees
why is 148.6 not a second solution? It's under 180 degrees
calm kite
Bro 148.6 + 38 is more than 180
Show your working, I'm not professional but probably i can help
calm kite
It's given in ques that one angle is 38, so if you take any other angle as 148.6 then it's not possible to make triangle
thick phoenix
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thick phoenix
Hi i am unsure on how to do this question
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thick phoenix
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gritty rose
wtf
khan has videos on almost all of these. a single help channel can't teach you a whole month's+ worth of knowledge
pick one topic at a time to learn and add "khan academy" to your search topic
past month
help channels are meant for specific problems, typically exercises from books
you either need a tutor or just be disciplined enough to watch khan academy videos of all your subjects
eternal quiver
depends on your skill, but yeah overnight study doesnt work for mathematics
torn jolt
khan has videos on almost all of these. a single help channel can't teach you a ...
Riemann... Time to start tutoring
Your time has come
Explain one month of study content in a day
I believe in you champ
gritty rose
eternal quiver
https://www.khanacademy.org/
riemann my G you can just get some smoov money out of it instead of giving around links for free
nevermind math students are usually broke
gritty rose
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void arch
I’m not really understanding the idea of continuity of the probability measure
void arch
In the proof they considered increasing and decreasing sets to be A?
But how do you know there exists these montonical sets to become A?
void arch
My bad, I didn’t even read the theorem that we’re trying to prove
spice orchid
Lmao
void arch
I mean now it makes sense
spice orchid
Yeah reading everything usually helps things make sense lol
void arch
Why is right continuity analogous with monotonically non-increasing sets?
Actually I think I do see it now I think? it’s coming from the right since the nested sets are x1=>x2=>…?
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random pollen
More of a techy question about Maple:
I have a 4000*2 matrix, left row represents years, right row represents something else irrelevant. Important thing is that each year appears many times.
How do I extract all values in the right row that correspond with a certain year in the left row?
I'm on Maple BTW
limber flicker
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hollow herald
first write down what it means for the two vectors to be orthogonal
then wonder how you can come to |u| = |v|
limber flicker
should it not be there
gritty rose
You'll only have: (u + v) . (u - v) = 0
it's only like 1 more line after this
restive hawk
could someone explain to me how i do these kinds of questions?
dense edge
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dense edge
Is this second line I highlighted correct?
sharp vine
no
untold gulch
Hi
untold gulch
Im stuck on part (ii) of this question
I found from (i) the mean = 38.19
variance = 668.9139
sd = 25.86
how would i approach each department/the question itself?
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waxen cloud
For the question 3) a) i), I need to develop with the MAClaurin method but I don’t understand why the last term has the exponent 2n +1 and is at the bottom (2nd photo bottom right)
waxen cloud
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quasi dust
I have 2 values, Value A, and Value B, both worth the exact same.
I have 3000 of value A, and 4500 of Value B. I have to split these 2 values with a group of 8 people, with each person having different preferences as to what value they'd like to receive, as well as each person getting a different cut (as in, % of the values combined, so 7500). Value B can be turned into Value A at the same rate, but, Value A can't be turned into Value B.
How do I make a formula or equation (for repeat use with different cuts, preferences and total A/B values) to split this as fairly as possible based on each persons' preferences, while making everyone as happy as possible?
Sorry if this is a mess, I can elaborate on anything if needed.
Example;
Person 1 gets a 20% cut (1500 total value), and prefers Value B
Person 2 gets a 10% cut (750 total value), and prefers Value A
Person 3 gets a 5% cut (375 total value), and prefers Value A
Person 4 gets a 5% cut (375 total value), and prefers Value B
Person 5 gets a 10% cut (750 total value), and prefers Value B
Person 6 gets a 15% cut (1125 total value), and prefers Value A
Person 7 gets a 15% cut (1125 total value), and prefers Value B
Person 8 gets a 20% cut (1500 total value), and prefers Value B
People would still be content/satisfied if all of Value B is distributed, and the "owed" amount given in Value A, but only if the people who want Value A get their fair cut.
Important: People who prefer Value A are unable to receive Value B.
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I have 2 values, Value A, and Value B, both worth the exact same.
I have 3000 o...
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quasi dust
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wicked condor
I have 2 values, Value A, and Value B, both worth the exact same.
I have 3000 o...
give all the value A to people who prefer value A first
then just distrubute the rest blindly
quasi dust
then just distrubute the rest blindly
What do you mean blindly?
wicked condor
like for the rest it doesnt matter if you know its A or B
wait what if
the people want like
not all the A
what if the total preffered for A is less than 3000
what do you do with the extra A
wicked condor
I have 2 values, Value A, and Value B, both worth the exact same.
I have 3000 o...
wait what does People who prefer Value A are unable to receive Value B.
if you have value B, cant you just make it value A and give it to them
marsh ibex
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marsh ibex
My final points should be right
but they dont align on desmos
they are sligtly off
did i do something wrong at the start ?
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honest bane
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honest bane
I'm having a little trouble understanding the concept of a proper divisor of 0
so from Z5 if i take a = 3 and b = 1
vague kayak
So 2≠(congruent)≠ 0mod4 but 2•2=0mod4
honest bane
ignoring those in the row/columns of 0
ohhh that makes so much more sense
deft zodiac
💕
honest bane
than just trying everything in Z5 to see if there's a proper divisor
deft zodiac
well
generally for some
Z/nZ
if n is prime theres no 0 divisors
if n is composite there is
deft zodiac
of what
honest bane
oh like inverse of 11 mod 47
deft zodiac
er idk im lost
honest bane
if the two of them are relatively prim then there's an inverse ?
deft zodiac
sry
honest bane
oh i think it's unrelated
i've just been doing over modular arithmetic
but thank you i get the residue tables
echo gale
Hey, I’m not sure where to go from this
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Hey, I’m not sure where to go from this
echo gale
Do I use the quadratic formula?
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vivid aurora
Do I use the quadratic formula?
no
vivid aurora
its easy
take x+2 and divide the cubic with it
cubic equation with it
you will get the quadratic eq
solve it using factorisation
you will get roots
if you wanna know solution dm me
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vivid aurora
.reopen
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torn jolt
If f(x) = p(x)+q, where p and q are integers ,
f(-1) = 5, and f(3) = 3 then p and q are equal to :
torn jolt
is the answer -0.5 and 4.5?
vast fossil
I got 2 and 7
onyx glen
@torn jolt well -0.5 and 4.5 aren't integers, so
probably not
unless it so happens that the problem itself is fucked up
which it may well be
ok yeah like. are you sure you copied the problem correctly?
p = -1/2 and q = 9/2 does match up with the problem data, except that these numbers are not integers so the "p and q are integers" stipulation is violated
torn jolt
ok yeah like. are you sure you copied the problem correctly?
yeah
onyx glen
ok then the problem is screwed up.
sacred sequoia
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sacred sequoia
pls help
torn jolt
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forest widget
it's just ratios i guess
how many degrees are there in a circle
and what proportion of people selected tennis