help-28

[junior siren]

help get the answer bro

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[junior siren]

yeah bro

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[paper kelp]

can someone help me with this question thanks

[timber oriole]

there was a formula for polynomial expansion like this

but this is doable on paper though

idk, depends on the context of this question as to what you should use

[paper kelp]

for the first one (1+x)^5 i got 5x+10x^2+10x^3+5x^4+x^5

[fast peak]

Forgot the 1

[paper kelp]

oh yea +1 in the end

[fast peak]

Well at the start

[paper kelp]

so it'll be 5x+10x^2+10x^3+5x^4+x^5+1

[fast peak]

1=x^0

Also it's more symmetrical with 1 at the start

[paper kelp]

x^5+5x^4+10x^3+10x^2+5x+1

so rewrite 1 at the beginning?

[fast peak]

"ascending powers of x"

1+5x+...+x^5

[paper kelp]

x^5+5x^4+10x^3+10x^2+5x+1 can be written as 1+5x+10x^2+10x^3+5x^4+x^5 right?

so the first three terms would be 1+5x+10x^2

[fast peak]

Yes

[paper kelp]

thank you

[fast peak]

Wait no

[paper kelp]

what did i do wrong

[fast peak]

The last term should be x^5. But I hope that's just a typo

[paper kelp]

oh forgot to include that

[fast peak]

Don't include the 10x^3 twice

1+5x+10x^2+10x^3+5x^4+x^5

[paper kelp]

👍

thanks i get it now

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[torn jolt]

this

[full forum]

Please don't occupy multiple help channels.

[torn jolt]

valid

?

i want to have y clear

as well as the other function

[pliant crown]

Bro has multiple channels for multiple doubts 💀

[vast fossil]

y = sqrt((x + 5)/0.2) will be the part of the curve above x-axis and y = -sqrt((x + 5)/0.2) will be the one below x-axis

[torn jolt]

thats what i thought but there is half the curve

[vast fossil]

Yes

And -sqrt will be the other half

[torn jolt]

so there is

that?

nvm

i just noticed something else

.close

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[fringe rune]

isnt that 9?

[vast fossil]

Depends on which order did the author want the operations to be executed

[fringe rune]

mmm

if thats not defined

then what

there has to be 1 answer

there cant be 2

[brave blaze]

a good mathematician won't even write this operation in this way

[fringe rune]

6÷2 = 3 × 3 = 9

[fringe rune]

ik

its a twitter meme

[brave blaze]

so stop arguing over a meme

[fringe rune]

but i really wanna know the answer

[brave blaze]

people sure love wasting their time

[fringe rune]

cause there has to be one

[vast fossil]

That's the same as if the author wrote some statement about David

You don't know who David is, but surely there's one person the writer meant

[fringe rune]

Hm okay

lets imagine umu were in an exam

what would be ur answer

[brave blaze]

a good exam won't write this shit

[fringe rune]

thats not the question though

[vast fossil]

Or you should be allowed to ask the order of operations

[fringe rune]

.close

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[north flicker]

how u find out the centre

https://assets.sparxhomework.uk/908f0d15-f2c6-4fec-ab9b-f02ee308b513

[silver pasture]

10,6?

[north flicker]

thats for a to b i know that

but whats b to a

[silver pasture]

same

[north flicker]

but i got it wrong

[north flicker]

i put a= scale factor= 3 with centre (10,6) and
B= scale factor=1/3 with centre (10,6)

bruh

[silver pasture]

wot??

i think thats the right thing anyways that think is probly wrong

[north flicker]

oh well

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[runic spruce]

If something is projected horizontally does that mean it has no vertical component

[eager violet]

The projection doesn't, no

[knotty fossil]

unless anything else is given, no

[runic spruce]

Does that mean I can’t resolve vertically

[eager violet]

Wdym by resolve

[runic spruce]

Suvat equations for motion

[eager violet]

Show the original problem

[runic spruce]

Find the time which elapses between the instant when the stones are projected and when they collide

[eager violet]

Oh, so by projected, it means thrown

Yeah, the initial velocity has no vertical component

But of course you need to consider gravity

[runic spruce]

Yeah

Can I assume that when they collide, they just stop so final velocity is zero?

Actually I don’t think that’s useful ugh

[eager violet]

No, you can't say that

Because the equations aren't gonna know when they collide, so it won't give you a 0 velocity

They'll collide when they have the same x and y position

[runic spruce]

Surely there isn’t enough info 😭for A to find an equation and equate to b

Oh wait nvm

[limber flicker]

u have enough

[runic spruce]

Ok thanks

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[dusk torrent]

how do i prove the archimedean property of R from the definition that it is a complete ordered field?

[dusk torrent]

nvm i did it

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[trim comet]

Hi ineed help

[astral sinew]

don't we all?

[tulip beacon]

Fr

[tame goblet]

what do you need help with

[trim comet]

Ididnt undrstand the exercice

[knotty quartz]

,rotate

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@trim comet Has your question been resolved?

[trim comet]

No

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@trim comet Has your question been resolved?

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[valid path]

anyone can help me with connverting the percent to a fraction?

percent to fraction

[worthy tree]

what do you what to convert ?

from fraction to percentage => multiply by 100

from percentage to fraction => divide by 100

[glossy valve]

Mehdi_Moulati

[worthy tree]

,calcul 303/400

[glossy valve]

Result:

0.7575 ul

Mehdi_Moulati

[worthy tree]

@valid path is it clear how ?

to convert from (fraction or decimal ) to percentage : multiply by 100
to convert from percentage to (fraction or decimal) : divide by 100

[worthy tree]

like this one

we convert it from the fraction to percentage

From percentage to fraction we divide it by 100

3/8% is a percentage

so $\frac{\frac{3}{8}}{100} = \frac{3}{8} * \frac{1}{100} = \frac{3}{800}$

[glossy valve]

Mehdi_Moulati

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[faint yew]

Iknow the graph one

How do i find the c in this

And the table values

[torn jolt]

the value of c is 0

becauase c is the y intercept

and

because their isnt a c'

the ertex form

vertex

is -b/2a

[faint yew]

Ty so much

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@faint yew Has your question been resolved?

[faint yew]

Can anyone help me find the table of values

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@faint yew Has your question been resolved?

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@faint yew Has your question been resolved?

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@faint yew Has your question been resolved?

[iron vapor]

don't know is it clear but

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[cursive badger]

Hi just want to confirm if I did this correct

For divisible by 7

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[cursive badger]

For (c)

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@little helm Has your question been resolved?

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[mortal rose]

help

[left crypt]

Which method should be used for this data structure? Red-black tree? Or what tree?

You can sort nodes, and leaf nodes can also be sorted

[mortal rose]

i dont know data structure yet

):\

<@&286206848099549185>

[undone summit]

excuse me

[mortal rose]

just nvm iam dumb

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@junior geyser Has your question been resolved?

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[gloomy warren]

What am I supposed to do here

[gloomy verge]

get helped?

[gloomy warren]

Second one cuz help forum isn't working

[gloomy verge]

calculus dayum

[gloomy warren]

Yea

Number 2

I can't solve integration for now

[gloomy verge]

i just started learning integration

;-;

[gloomy warren]

Same

I'm not good at it

Which one

I tried solving all those questions but I stopped midway

I'm confused

For example this is first one

Do u have any clue about 9 1/x(x+3)

Oh man

Deleted message or was I hallucinating

[echo bison]

I deleted because i dont know wich one you need help on

If it is tan(x) you can think as sin(x)/cos(x)

[gloomy warren]

I'm solving the whole page

But I'm currently one number 2

So basically turn y=tan 0 to sin/cos

[echo bison]

Shit i didnt saw y=sec

[gloomy warren]

Lemme resend it for u

Do I get derivative of both

Then put it on each other

Or just get y which is dy/dx

My mind

Is confused

<@&286206848099549185>

Is this correct

[fossil stump]

That looks good to me @gloomy warren

You can always check using wolfram alpha

using the ,w integrate feature here

,w integrate 4 sin(2x) e^(cos(2x))

At least it should work

[gloomy warren]

Is that an app

[gloomy warren]

So is it correct

[fossil stump]

It's a website you can access

[gloomy warren]

Oh

[fossil stump]

Looks good to me

[gloomy warren]

Wait

[gloomy warren]

What does that mean

[fossil stump]

You can also google integral calculator

[gloomy warren]

My brain is almost dying

[fossil stump]

Your answer looks good to me

[gloomy warren]

But is it good to others

[fossil stump]

Idk, I'm not others

[gloomy warren]

How about this

[fossil stump]

You can check this result online

In fact you can check all integrals online

[gloomy warren]

Wolfram alpha or integral calculator

[fossil stump]

Both actually

[gloomy warren]

I really don't know how to do

Last one using integral calculator

[gloomy warren]

.

[fossil stump]

You can combine the two into one integral

[gloomy warren]

It shows me stuff I didn't learn

[fossil stump]

Are you integrating a product or is there a plus sign? It looks like there should be a + sign between the two integrals

For that, combine the two and there's a common factor

[gloomy warren]

There is

A plus sign

The main function is 6x+9/x²+3x

I split it into 2 jntegrals

And solved first

Wolfram ain't working

Is this correct

.rotate

How does the bot work

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[wet prairie]

I tried this for 2 h now, pls with solution

[torn jolt]

hi

[wet prairie]

Hey there

[torn jolt]

factor 2

[wet prairie]

I always get 0,25 as Solution but the correct answer is 0,5 i don´t get it

[onyx glen]

can you show your work

maybe we can point out a mistake you made

with 2 hours of work surely you have something you could show us?

[torn jolt]

1 / x(x+2) = 1 /(x^2 +1)
x^2 +1 = x^2 +2x

right?

[onyx glen]

x^2 + 1 ≠ (x+1)^2, so no.

[torn jolt]

ok

oK?

2x = 1

[wet prairie]

Its so hard to write this on paint

[torn jolt]

x = 0.5

1/x^2+2x = 1/x^2 + 1

[onyx glen]

then write it on paper.

[wet prairie]

Cant make a photo with my pc

[onyx glen]

hm.

[wet prairie]

wait I try tippin here

[onyx glen]

well, you can type equations in desmos and take a screenshot.

plaintext might be a tad hard to read.

[torn jolt]

i'm solved it

!!!!

x^2 +1 = x^2 +2x

2x = 1

x= 0.5

right?

@onyx glen

[onyx glen]

yes...

[torn jolt]

understand??

[wet prairie]

Wait no

How did u make 2^2+1=x^2 +2x?

[torn jolt]

@wet prairie ?

1/x^2+2x = 1/x^2 +1

(x^2 +1)(1) = (x^2+2x)(1)

[torn jolt]

false

[wet prairie]

yeah obviously 😦

[torn jolt]

see my solve

first factor 2

and simply it

then make multiplication that

and simply

understand?

[wet prairie]

trying my best english is not my first language

[torn jolt]

what is your first language

??

[wet prairie]

german

[torn jolt]

ok please a minet

@wet prairie

understand ???

[wet prairie]

omg i think so

I didn´t knew that you could make the left side /2 without doing so with the other side

[torn jolt]

hhh

now are you understand?

[wet prairie]

Yes THANK YOU so much, I really got it

[torn jolt]

you can send me other problem i'm happy to solve that

[wet prairie]

haha ty but rn I don´t have any more problems ty!

[torn jolt]

.close

type it if haven't any problem

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[brittle monolith]

why does cos x give this

and not only Bcosx?

why the C sin x too?

some formulas^

[fossil stump]

In general for problems like these you include a linear combination of both cos x and sin x because they play with each other well

Especially in e^x

@brittle monolith

[brittle monolith]

what if it said 34/3sin x instead?

I bring cos x and sinx still?

both of them

[fossil stump]

I don't see why not

It's ideal to test the most general case

[brittle monolith]

okay

is the right side equal to y? @fossil stump

[fossil stump]

Not necessarily

[brittle monolith]

then why do we derivate the right side particular solution

and insert in left side

[fossil stump]

I don't think we're taking the derivative of the RHS

[brittle monolith]

what?

[fossil stump]

I'm saying we are not doing this

[brittle monolith]

isnt it this

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@brittle monolith Has your question been resolved?

[fossil stump]

That's not the RHS

That's your guess for y_p

[brittle monolith]

yes

so we derivate that?

and insert in left side?

[fossil stump]

Yes, you need y' and y'' given your arbitrary guess for y

*y_p

Yes

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[strange compass]

hi

[strange compass]

How do i enter a phisic discord?

physic

[void widget]

https://discord.gg/physics

[strange compass]

Thank u

End.

/end

end.

[fossil stump]

here

[onyx glen]

it's .close

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[brittle monolith]

how do you find the roots on the right side?

[smoky wing]

roots?

are we solving for y

[brittle monolith]

it isnt mentioned

[smoky wing]

it lierally says y=f(x) at the end

what part of the solution are you confused about

[brittle monolith]

i figured

when it's just a number

like 1 or 8

then the root is just 0

so particular solution is just A?

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[elfin mica]

Not sure if I can do what I did in the circled step

Like it's legal

[hot herald]

ugh

it's quite hard to follow since some xs look like ys

and probably dodgy notation too

were you trying to differentiate both sides

[elfin mica]

Yes

[hot herald]

then firstly you should be apply the derivative operator
d/dx
(and not be multiplying by dy/dx)

after the first application of chain rule
d/dx (4 + sin(xy)) would be cos(xy) d/dx (xy)

the derivative of the left is wrong too for other reasons

[elfin mica]

Ok thanks

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[weak plaza]

hello

[weak plaza]

my question wasnt answered so i try again

#help-19 message

this is what i wrote... 😦

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.reopen

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✅

[weak plaza]

<@&286206848099549185>

arithmetic mean is obvious, but not sure when harmonic mean is appropriate to use yet

[steel cove]

i don't rly understand harmonic mean

but geometric mean is basically "Imagine you have an n-dimensional rectangle. Calculate the area, then find what side lengths would turn the n-d rectangle into a n-d cube, while keeping the same area"

so for 2 items, let's say 3 and 5

it would be "make a rectangle with sides 3 and 5. Find the area, which in this case is 15. Now find what side length of a square would also have the same area, which is just sqrt(x), which in this case is sqrt(15)"

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[glossy valve]

CalicoJackRackham

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[weary cedar]

Assume that a sample is used to estimate a population mean μ . Find the 99.9% confidence interval for a sample of size 57 with a mean of 22.6 and a standard deviation of 12.3. Enter your answer as an open-interval (i.e., parentheses) accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).

99.9% C.I. =

Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

[weary cedar]

Can't understand this can someone sway me in the right direction with this question?

I want to use my Ti-84 for this

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[weary cedar]

<@&286206848099549185>

<@&286206848099549185>

[hexed rock]

Use the normal distribution

[weary cedar]

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[weary cedar]

thanks!

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[terse cliff]

hi can someone point me to what is wrong in the computation of ak?

the result should be 4/pik^2

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[west sapphire]

Hello, im working on deriving a wheel for an inverted cyloid curve and ive found something which should help me but I dont understand where they're getting these numbers from, can anyone help me decipher what they mean and how they got them.

[west sapphire]

I can provide the entire paper if that would help: https://web.mst.edu/~lmhall/Personal/RoadsWheels/RoadsWheels.pdf

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<@&286206848099549185>

[west sapphire]

<@&286206848099549185>

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[west sapphire]

close.

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[torn jolt]

describe the proportion between these relations:
A) kinetic energy as a function of velocity
B) velocity as a function of time
C) gravitational potential energy as a function of height
use proper notation to signify each answer

[shrewd hamlet]

KE = 0.5mv^2

[torn jolt]

thats a quadratic right if mass is constant

what would i say for my proportion tho

[torn jolt]

i got K_e ∝v^2, v ∝t^-1, GPE ∝h for my answers

is that right

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[strange haven]

Hello! I'm having alot of issues with this equation since , we didn't fully learn how to do it like this, im from a different country but the subject is called "Partial Equations" with using D(f) and stuff. Would appreciate help :)

[strange haven]

nvm actually pretty easy , just missed small detail

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[cloud shore]

a) show that f is continuous on [-1,1] and differentiable on (-1,1)

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[terse cliff]

$$z=\frac{1}{(1+i)^2}$$

[glossy valve]

Umma.Gumma

[terse cliff]

hi, how do I convert this number to exponential form? (i.e. z = re^itheta)?

[astral sinew]

1/z = (1+i)²
z^(-1) = exp(2log(1+i))
z = exp(-2log(1+i))

Just find the log of 1+i

[terse cliff]

any solution that does not involve the use of log?

[astral sinew]

Lol

[torn jolt]

yes

find $(1 + i)^2$ as re^itheta

[glossy valve]

45
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[vast fossil]

z = 1/(1 + i)^2 = 1/(2i) = -i/2, much quicker, no?

Ah wait I just read the question nvm

[torn jolt]

In the formula $re^{i\theta}$ for some complex number $z = a + bi$, $r = \sqrt{a^2 + b^2}$ and $\theta = \arctan\left(\frac{b}{a}\right)$. You know $r = \sqrt{1^2+1^2}$ and now you have to calculate $\arctan{\frac{1}{1}}$.

[glossy valve]

45

[torn jolt]

does that make sense?

[vast fossil]

Actually this still helps though

[terse cliff]

yes that is the procedure I would follow in any other circumstance @torn jolt

[torn jolt]

why would you not follow it in this circumstance?

what's stopping you

[terse cliff]

correct me if I'm wrong but I get r=1/2 and Arg=pi/2 here

my prof result: 1/2 e^i3/2pi

[vast fossil]

Arg = -pi/2

[terse cliff]

why is that? a is 0 and b is 2

[torn jolt]

Alternatively, you can do the following:
$$z = \frac{1}{(1 + i)^2} = \frac{1}{(1 + i)^2} \cdot \frac{(1-i)^2}{(1-i)^2}$ to leverage difference of squares.

[terse cliff]

so I would expect to have pi/2 as theta

[glossy valve]

45
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[torn jolt]

So then we have $z = \frac{(1-i)^2}{4}$

[glossy valve]

45

[terse cliff]

I would stick to the other method you mentioned

why would Arg be -pi/2 and not pi/2?

this makes sense with the 3/2pi of my professor

[torn jolt]

because $-\pi \leq \theta \leq \pi$

[glossy valve]

45

[torn jolt]

why?

[terse cliff]

because I am more used to it to be honest

[terse cliff]

..still not getting it

[torn jolt]

okay look

let's take a look at 1 + i on its own

what is the polar representation for 1 + i?

[terse cliff]

in that case the exp form would be

$$\sqrt{2}e^{i\frac{\pi}{4}}$$

[glossy valve]

Umma.Gumma

[torn jolt]

yes, correct

now take this to the -2nd power

what do we obtain?

I can tell you, we have $\frac{e^{-i\frac{\pi}{2}}}{4}$

[terse cliff]

$$2^{-1}e^{-i\frac{\pi}{2}}$$

[torn jolt]

no

you are taking this to the 2nd power

I asked you to take this to the -2nd power

that is how we obtain that theta is -pi/2

[terse cliff]

oh right just a sec

[torn jolt]

Hence $r = \frac{1}{2}$ and $\theta = -\frac{\pi}{2}$

[glossy valve]

Umma.Gumma

[torn jolt]

yes

[glossy valve]

45

[terse cliff]

and given that -pi/2 is basically equivalent to 3/2 pi

that other solution is acceptable

[torn jolt]

yes because sin and cos are 2pi-periodic and geometrically they are equivalent

yes

do you understand everything now?

[terse cliff]

yes it is conceptually clear now

thanks a lot for your time

really appreciated

[torn jolt]

no worries

[terse cliff]

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[umbral plinth]

Hello, how to proove that :

[umbral plinth]

M —> PMP^-1 is continuous

(P \in GL3(K))

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[fast peak]

I mean do you know that matrix multiplication is continuous?

[umbral plinth]

i didnt knew

can we proove it ?

[fast peak]

you can break it down to each individual coordinate

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[umbral plinth]

don't understand

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[remote bronze]

quick question

[remote bronze]

How do I find the inverse of x^3+x-3

or how do i apply that inverse derivative equation to this

cause im super confused

[woven sand]

$y = x^3 + x - 3$

[glossy valve]

lexitorius

[woven sand]

Swap the y's and x's, then solve for y again and you'll get the inverse

[remote bronze]

im stuck

I get x+3= y^3+y

Then Idk how to isolate just 1 y

[woven sand]

I just hit it with wolfram and it's a really beefy answer

I'm not quite sure how to get to it either lol

[remote bronze]

Is there any other way I can get the derivative of the inverse of this

if you cant solve it its not looking good for me

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[sand stone]

@remote bronze rather than solving for y you can just swap the x and y and then implicitly differentiate

[remote bronze]

thats genius

never would have thought of that

i just solved for y and it somehow worked in the 1/f'(f^-1(x) equation

[sand stone]

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[round moth]

find domain : f(x) = (x-0.5) / (x+0.5)

[round moth]

helppp

[eager violet]

What have you tried

[round moth]

i dont know how to form a written answer for this

i just know that i cant use -0.5 since it would result in a 0 for the denominator

otherwise all real numbers should work

[eager violet]

Do you know what form you need the domain in? Like, set builder notation? Interval notation?

[round moth]

nope its just this question without any details

the solution at the back of the book says R \ {-0.5}

[eager violet]

That's another way

[round moth]

What does the backslash means?

i dont get it

[eager violet]

It basically means you remove that element from the set

It's all ℝ, but you remove the element -0.5

[round moth]

how do you type that R?

[eager violet]

You can also write it {x | x ≠ -0.5}

[round moth]

aaah

alright

[eager violet]

Or (-∞, -0.5)U(-0.5, ∞)

[eager violet]

I have a bunch of symbols saved under shortcuts on my phone

[round moth]

perfect, thank you

[round moth]

yeah, that's the one I use generally

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[round moth]

how do i find domain of f(x) = x+5/x^2+x-6

??

i am not sure how to do it

[torn jolt]

Don't ping people like that (unless you know they're fine with it).

[round moth]

okay

[eager violet]

What have you tried

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[torn jolt]

First, figure for which values of $x$ is $\frac{x+5}{x^2+x-6}$ indefinite.

[eager violet]

I think the denominator is x² + x - 6

[round moth]

yes

[glossy valve]

3317

[torn jolt]

You know that, for instance, fractions cannot have 0 as their denominator.

[round moth]

but wont that take a lot of time?

yes

ik that

[torn jolt]

Then, solve $x^2+x-6=0$ and you'll have the values $x$ cannot take.

[glossy valve]

3317

[torn jolt]

Welcome to mathematics.

[round moth]

haha

[torn jolt]

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$.

[glossy valve]

3317

[torn jolt]

Now what is $a$, $b$ and $c$?

[glossy valve]

3317

[round moth]

got it

a = 1 b = 1 and c = -6

[eager violet]

You can factor

[round moth]

the final ans 2,-3

[torn jolt]

Wonderful, so the domain is $\mathbb{R}/{2,-3}$.

[glossy valve]

3317

[round moth]

okay, thank you

[torn jolt]

Glad to help.

[round moth]

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[amber shuttle]

Can someone help me like not solve it but what I have to do to solve it?

[amber shuttle]

Anyone tell me what I have to do to solve this?

I don’t need like full answers just need like a explanation (I’m just trying to go ahead for I can fully understand it before my classmates)

<@&286206848099549185>

Anyone?

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@amber shuttle Has your question been resolved?

[torpid estuary]

Hi @amber shuttle , to me it looks like a bit of intersection and algebra substitution, is there a specific concept that you are after?

[amber shuttle]

No just need in of a explanation

sorry it’s my first time here

[amber shuttle]

But if you can give me like a good explanation or example

[torpid estuary]

Assuming you know what variables are. Most of the times these question types would involve you using two variables, and then form 2 types of equations, which you would then use to find the values of both variables.

Through equating them together.

Hope this helps.

[amber shuttle]

Oh alright

Thanks man

Thanks for helping a youngster out

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[lilac pine]

hi

[lilac pine]

pls can someone help

i don’t get what it’s asking

i know if it’s inside the bracket

then it affects x axis and it does the opposite

so divides by 2

but what does it mean by solution of the equation

[sacred zodiac]

So you're looking for f(2x) = 0 i.e. y = 0. Where is there a point where y = 0?

[lilac pine]

at (5,0)

oh is it (5/2, 0) then

[sacred zodiac]

yes so f(5) is 0 so 2x = 5 so x = 5/2

[lilac pine]

thanks

[sacred zodiac]

5/2 yes but (5/2, 0) isn't on the graph

no worries!

[lilac pine]

i got confused because it was a function

i didn’t know it meant for y

thx dude

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[autumn plover]

How do I answer this

[autumn plover]

Ping me when ur don

Done

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[autumn plover]

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[torn jolt]

Can someone tell me whats the diffrence between these 2,considering some interpretation

[torn jolt]

Where A is a relation

And B

[humble chasm]

Basically this can also be noted

as contained within

A is contained in B

The difference between the two is that

Y is quantified on the second quantifier

thus it must be introduced

Also For all of y is put first before all of x

note that

Both statements imply that A is contained within B

[torn jolt]

Does this matter

I mean the order of the same quantifiers

I tought that didnt matter

[torn jolt]

First row right

Sorry if im confusing a bit i get lost sometimes

Okay i think i understood

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[granite orchid]

can someone help explain this? i tried subbing 2n+1 into the summation formula for r^3 but i got a different result

[fast peak]

yeah not sure what that bot is doing there

$\sum_{r=1}^k r^3 = \frac{k^2(k+1)^2}{4}$

[glossy valve]

Denascite

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@granite orchid Has your question been resolved?

[granite orchid]

so you just substituw 2n+1 for k right?

[fast peak]

yes

[granite orchid]

alright so

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[plain summit]

Step by step, what does -(- 1/3)² become?

[hot mango]

like what it evaluates to?

[gritty rose]

use PEMDAS
https://www.cuemath.com/numbers/pemdas/

[plain summit]

Like positive or negative, and which rule am I supposed to do first?

Because of the even power and minus thing, and the - × - = + rule

Typo

[woven eagle]

-1/9

[gritty rose]

(-a)^2 = (-a) (-a)

[lunar dust]

(-1/3)^2 = (-1/3)*(-1/3) -> something positive. But then the negative sign infront makes it negative

[woven eagle]

solve brackets first

[plain summit]

Alright thanks

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[gray citrus]

Stuck on C

I replaced x with 3-w and have ended up with a cubic equation. What do I do from there or have I used the incorrect method to find the value?

the answer is 128/3 if that helps with explaining

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[gray citrus]

<@&286206848099549185>

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@gray citrus Has your question been resolved?

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@gray citrus Has your question been resolved?

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@gray citrus Has your question been resolved?

[rapid laurel]

u just plug 3 in????

u have p from the previous questions

??whats the problem

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[restive hawk]

could someone explain this question

[restive hawk]

I am a little confused on how i messed up the end

[static bramble]

What is the value of 1 + 2x^2 when x=1

[restive hawk]

3

oh so do i have to substitute those in when i make it u?

i thought we were just allowed to ignore the limits

[static bramble]

Yes you're integrating from u=a to u=b

Well you can either sub the limits, or ignore the limits and unsub after computing the integral

Both methods are equivalent but they want you to do the former for this

[restive hawk]

right so wouldnt that leave the limits unchanged?

or am i thinking about it wrong

[static bramble]

It would, but you would need to specify

[restive hawk]

i think since it is asking the limits in terms of u

id have to convery

[static bramble]

Like it would be something along the lines of $\int_{x=1}^{x=4} f(u) \dd u$

[restive hawk]

convert

[glossy valve]

Steakanator

[static bramble]

But if it just says a and b then it's in terms of u

[restive hawk]

ok

so then for the next part

my f(u) is wrong

[static bramble]

Indeed

[restive hawk]

am i just missing du or is it entirely wrong

[static bramble]

du = 4x dx, but your integrand only contains x

[restive hawk]

right

so im going to multiply by 4?

or sorry

1/4

[static bramble]

Yes

[restive hawk]

oh right because

xdx=1/4du

cool

so when i integrate

am i using the original limits

or the new ones

[static bramble]

New ones

[restive hawk]

right

since im using u

but if i converted back

i would use the original?

[static bramble]

Sure if you took the antiderivative and then reversed the sub you would use the original limits

[restive hawk]

ok

but as long as it is u i need to use the limits i found for u

because u basically represents x

which is the limits

because those are also x

[static bramble]

u is some function of x

So when you consider certain x bounds, you need to translate them to the equivalent u bounds

[restive hawk]

ok yeah

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[torn jolt]

Hello! So im having a trouble doing his equation here. I get the x and y wrong... And i cant find a solution.. X is aupposed to be - 0.5 and y is 0.5 but on x i get 1.5 and on y i get 2.5!

[torn jolt]

So here are my solvings

Also dont look at the text on the work book-,it doesnt mean anything

[woven eagle]

x is -0.5 and y is also 0.5

[torn jolt]

Yeah but i am not sure how that happens

Also ty for helping me again

[woven eagle]

in 1st image (-1)^2019 = -1 because its power is odd

[torn jolt]

Yeah i know that

[woven eagle]

that's mistake in calculating x

[torn jolt]

And |-0.5| become 0. 5

[woven eagle]

yes

[torn jolt]

So

[woven eagle]

and calculating y is completely wrong

[torn jolt]

Uh oh

Well what can i say im bad at maths

Ok now i understand how x is 0.5

-1 +0.5= - 0.5

And on y - is it aupposed to Be 1/16 and 1/8?

Supposed*

[woven eagle]

$y = \frac{1}{2^{16}}:\frac{1}{2^{15}}$

[glossy valve]

ayushch80

[torn jolt]

Oh

And then it becomes 1/2^16 . 1/2^15

[woven eagle]

yes

[torn jolt]

And then 1:2 is 0.5

Ok tysm!

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[mighty valve]

can any one help me with probability and statics PDF problem

[sage basin]

maybe send a photo of the problem

[mighty valve]

wait sir

This problem

sir?

[woven eagle]

<@&286206848099549185>

[mighty valve]

Hi

[woven eagle]

<@&286206848099549185>

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[obsidian horizon]

Is the question "If x has uniform distribution ... find P(something something)"?

@mighty valve

[mighty valve]

Yes

[obsidian horizon]

Cool ok so what is the upper and lower bound of x here?

For |x-2| < 2

Well find the size of that interval and find the ratio between that size and the size of the entire interval

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[hot mango]

what would I put for the things with xs

[hot mango]

omg it just wanted me to switch them i cant with this

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[crisp bramble]

can someone check my answer? i don't have the answer keys so i can't check. I got 12/sqrt of 5pi for (b)

[lyric ember]

if you mean 12/sqrt(5pi), that is correct

[crisp bramble]

awesome thanks for verifying!

[lyric ember]

np!

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[open isle]

shouldnt it be 1 + 1 + (1^2)/2! ....

[light sonnet]

You're forgetting the x

It's f'(0)x

And f'(0) = 1, so 1 * x, hence x

[open isle]

ohhhhh

right

also

what am i missing here

|e^(0.01) - 1.0725072| equals that doesnt it?

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[polar estuary]

no

bye

[torn jolt]

Why

[polar estuary]

idk

ok anyways

[torn jolt]

.closed

.close

[polar estuary]

lol

[torn jolt]

.close

.reopen

[polar estuary]

it is closed lmao

[polar estuary]

see

[torn jolt]

It's still in the list

[polar estuary]

leave it

[torn jolt]

Maybe a bug

[polar estuary]

some mod will delete. channel if it is needed

[torn jolt]

I want to reopen the same question

[polar estuary]

then create new question

or new thing

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[rancid wigeon]

I'm trying to solve for c using the mean value theorem for integrals, I'm not sure where to go from the last line

[buoyant tinsel]

If we're just looking at sec^2(x) = 3/pi, there is no solution. Remember that the range for sec is (-inf, -1] U [1, inf)

But could you provide the full question? Having trouble following your work

[hollow herald]

heck .. isn't it (sec x)^2 = 4/π .. instead

[rancid wigeon]

Original question of f(x)= 2 sec^2 x, [-π/4,π/4] Finding the value of c using the mean value theorem for integrals

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[willow elk]

A group consisting of k people, is distributed along m rooms. ( k<m) Each person
randomly enters a room and, after entering they do not go to other rooms. The random
variable X is equal to the number of rooms that no one entered. Find expected value of X.

[willow elk]

so chance of 1 person entering a random room is 1/m

chance of someone not entering a room is 1 - 1/m

aand now im not sure

[forest widget]

does everyone have to go into a room

seems like yes

[willow elk]

ye

just can be that all ca go into 1, or all can go into different, or a mix

if we take chance of not entering a room

in case of 3 rooms, for 1 person thats 1 - 1/3 = 2/3

so for 2 people, thats 2/3^2

4/9

so for k people, thats 2/3^k

so for m rooms, (1 - 1/m) ^k

need some tips

if this is wrog

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[willow elk]

?