#help-28

1 messages · Page 29 of 1

neon mulch
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$E(X) = \int ^{\infty} _{-\infty} x f(x) dx$
why is $E(Y) = \int ^{\infty} _{-\infty} x^2 f(x) dx$

glossy valveBOT
#

manaclo

mighty ridge
#

that's not it

neon mulch
#

but in the solution they use $E(Y) = \int ^{\infty} {-\infty} x^2 f(x) dx$

glossy valveBOT
#

manaclo

mighty ridge
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nope

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well, yes

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that works too

neon mulch
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i dont get why it works

mighty ridge
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I'm looking at what's the name of the theorem for that, I don't know it in english

neon mulch
#

can you send the name anyway?

mighty ridge
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in french it's called théorème de transfert

neon mulch
#

thanks ill do some reading

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merry pecan
#

I've been given the values for AE and GK. AE = 20.3, GK = 9.1. How do I find the volume of the tank, starting with all the lengths. All I've been able to work out is the length of lines ED and CA.

merry pecan
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<@&286206848099549185>

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@merry pecan Has your question been resolved?

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@merry pecan Has your question been resolved?

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@merry pecan Has your question been resolved?

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dark seal
#

I am not able to to this right?

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eager violet
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Yeah, that's fine

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I mean, you'd have to simplify the right hand side

dark seal
#

thanks another time, and do you know if this is right?

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I think yes, but I am not pretty sure

eager violet
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Looks right

dark seal
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thank you 🙂

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iron vapor
#

i think we can think like a.e /c

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dense edge
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sharp vine
#

,w how many terms x(x+1)

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@dense edge Has your question been resolved?

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vapid steeple
#

can some one help me figure this out? my dumbass cant figure out how to get 45 degrees +60k at all

raw turret
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sin(270)=-1

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(270+360k)/6

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@vapid steeple

vapid steeple
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oh damn.. nice thank you

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torn jolt
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@torn jolt Has your question been resolved?

torn jolt
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.close\

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fading cargo
#

7th exercise, are the steps here alright?

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fading cargo
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inland turret
#

Linear Equations - Algebra

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inland turret
#

anyone can explin this?

balmy peak
#

khan academy

torn jolt
inland turret
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anyone can teach?

torn jolt
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explain what a linear equation is ?

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ok

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what specifically do you need to know about linear equations ?

inland turret
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everything

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i forgot how to do it

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alr lemme read

torn jolt
inland turret
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alright thanks

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The value of y from 6(y + 5) = 2(-2y - 5) is

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from last test

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loud haven
#

someone here with a lot of experience with block matrices and order of operations?

loud haven
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x^+ is a vector with (1,0) as its entries (its dirac stuff, dont ask 😂 ), while

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sigma_y is this

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sigma * p =

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how would i have to do the order of operations? Can one evalaute block matrices directly? Do i need to make everything in its 4 dimensional form? Do i need to calculate (sigma * p) * x^+ before anything?

fiery dove
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mensional form? Do i need to calculate (sigma * p) * x^+ before anything?

loud haven
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<@&286206848099549185> anyone?

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loud haven
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plucky parrot
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plucky parrot
#

using ti-Nspire software, can't solve that? Claims its missing an "("

onyx glen
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what even is this

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did you mean $\frac{\pi \cdot 3 \cdot \pi^2}{7 \cdot \pi \cdot \pi^2}$?

glossy valveBOT
plucky parrot
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no

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$\frac{\pi \cdot 3 \cdot \n^2}{7 \cdot \pi \cdot \n^2}$

glossy valveBOT
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offline
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plucky parrot
#

how do i put that to Nspire

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$\frac{\pi \cdot 3 \cdot \x^2}{7 \cdot \pi \cdot \x^2}$

glossy valveBOT
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offline
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plucky parrot
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not working

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well it is my attempt at solving big circle area/small circles combined area

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$\frac{\pi3a^2}{7\pi a^2}

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\frac{\pi 3a^2}{7\pi a^2}$

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$\frac{\pi 3a^2}{7\pi a^2}3$

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nono

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$\frac{\pi 3a^2}{7\pi a^2}$

glossy valveBOT
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offline

plucky parrot
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yeah

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wouldn't that work?

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if a=r

glossy valveBOT
#

Reacquired

plucky parrot
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thanks

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lethal jolt
#

How does one prove that pi/4 = arctan(3/5) + arctan(1/4) ?

brisk obsidian
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$\tan^{-1}{x} + \tan^{-1}{y} = \tan^{-1}{\left(\frac{x+y}{1-xy}\right)}$

glossy valveBOT
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Kookiemon

torn jolt
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kookiemon back to the rescue

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🙏🏻

lethal jolt
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Sorry, I don't follow. Is that result derived from compound angle? If it is I'm not seeing it 😩

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(And I don't think I'm allowed to quote it, I have to be able to derive)

lethal jolt
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Could you please derive it from something else?

brisk obsidian
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You aren't learning about identities?

lethal jolt
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Nah this is high school work. And I've never learnt about inverse trig identities

brisk obsidian
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There is no pretty way of proving that it equals pi/4. The given values do not lend themselves to easy angle measures.

lethal jolt
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Then can you explain how the identity was derived? And thus I might apply it without needing to quote it

brisk obsidian
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That proof requires using a Maclaurin Series which I think is beyond what you are capable of.

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It's kind of the reason why we have identities in the first place. Someone did the work so you don't have to.

brisk obsidian
lethal jolt
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trigonometry

lethal jolt
brisk obsidian
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One alternative would be this.

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Hmm, but that would still involve a rotation of the point C and F that requires knowing the angle BAC.

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#

@lethal jolt Has your question been resolved?

lethal jolt
# brisk obsidian

Got it! Used complex numbers to represent the vector AC, then multiply i/4 to represent the opposite side of the 1/4 triangle. Add the two together and the argument is pi/4. Thanks for helping

brisk obsidian
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Interesting method. 🙂

lethal jolt
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Yeah your graph and comment about rotation made it click

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dull thicket
#

An Area is bounded by the graph of the function f(x) = e^(-x^2), the x-axis and the 2 straight lines x = a x=3a, a>0. Find "a" where the area is biggest?

dull thicket
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so i been trying this for a bit and i assume i make some integral and somehow get the answer

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but i have really know where to start this problem

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I would be happy to elaborate if anyone needs it

torn jolt
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Hmm sketching it will give you some sort of hilltop looking curve

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It will have a maximum at x = 0, and then starts growing slower and slower from both ends as it approaches 0

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I think knowing that should give you an idea of what a should be thinkies

torn jolt
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No, maximum

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It is $e^{-x^2}$ correct?

glossy valveBOT
#

♡LexQa♡

dull thicket
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yeah i just noticed i mistyped the graph T_T

torn jolt
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Oh what

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what is it

dull thicket
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in my graphing software not here

torn jolt
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Ah i see

dull thicket
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instead of a hilltop it was "U" shaped

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this makes it slightly easier

torn jolt
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Yeah. So anyways, I suppose you would have the "biggest" area maximising the area under that hilltop before it goes to infinity and minus infinity

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Since I assume a is some constant here

dull thicket
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yup its supposed be

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my first instinct here would be to take the antiderivative but we get hint that says we should not do that

torn jolt
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Yeah not taking the derivative means not doing any of what we just did lmfao

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Because you can only really figure out what it looks like using the derivative

dull thicket
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i made a very important typo

torn jolt
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Oh what is it

dull thicket
torn jolt
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Ah okay

dull thicket
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sorry about that

torn jolt
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Then our approach is suddenly alright

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Lmao

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Anyways, now figuring out what the 'a' needs to be is the hard part

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The 3a is the problem I think

dull thicket
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its a multiple choice question btw

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i can show the answers if that would help

torn jolt
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Nah it's fine, we can bullshit our way through it without the choices

dull thicket
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okay xd

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how would we go about finding the area of the graph without integral/antiderivatives tho?

torn jolt
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Also they said to not do the anti derivative because you wouldn't find one no matter how you try anyways

torn jolt
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fun times with erf(x) ig

dull thicket
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that should work i think but, we also shouldn't have to as its not part of this courses curriculum

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we have learnt taylor polynomials but not series

torn jolt
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i am really clueless as to how you could ascertain a value for a

dull thicket
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maybe i should just post the multiple choices and we can trial and error it?

brisk obsidian
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$\frac{\partial}{\partial x} \int_{a}^{b} f(x) dx = f(b) - f(a)$

dull thicket
glossy valveBOT
#

Kookiemon

dull thicket
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Dont mind the text parts

torn jolt
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oh partial derivative, did not think of that

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good idea kookiemon

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did u even learn partial derivatives? @dull thicket

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thats like calc 3 and taylor series is calc 2

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so i assume no

dull thicket
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yes, i passed calc 3 and 2 but not one bc i was sick twice on exams

torn jolt
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what is this question for?

dull thicket
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calc 1

torn jolt
dull thicket
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so technically its not on the curriculum

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i know xd

torn jolt
dull thicket
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yuuuuuup

torn jolt
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yeah i am pretty clueless, sorry

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will continue thinking about it though

dull thicket
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This task is pain

nocturne creek
brisk obsidian
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It's not my question, but it is an optimization problem to find the largest are under a curve with the boundaries defined as a and 3a, solve for a.

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y = e^(-x^2)

dull thicket
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<@&286206848099549185>

brisk obsidian
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I know what the answer is but I'm not exactly sure how to solve for it.

dull thicket
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how did you arrive at an answer?

brisk obsidian
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So going back to this being an optimization problem of the area under the curve of f(x). You take the derivative of the integral of f(x) from x=a to 3a.

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Given that f(x) = e^(-x^2), the derivative of the area function should equal f(3a) - f(a).

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Or

a'(x) = e^(-9a^2) - e^(-a^2)

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Which should allow you to solve for a but it doesn't work so there is some fault with my reasoning.

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I made a graph in Geogebra where I plugged in each of the optional answers you gave and found it is 6 though.

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That answer does not coincide with a'(x) above which you can visually see in the graph.

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I'm trying to figure out what I'm doing wrong.

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\begin{align*}
Area &= \int_{a}^{3a} e^{-x^{2}} dx \
Area' &= \frac{d}{dx} \int_{a}^{3a} e^{-x^{2}} dx\
Area' &= e^{-x^{2}} |_{a}^{3a}\
Area' &= e^{-9a^{2}} - e^{-a^{2}}
\end{align*}

glossy valveBOT
#

Kookiemon

brisk obsidian
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In my mind, this should have worked but it doesn't.

dull thicket
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i have no idea tbh

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im still stuck trying to find a calc 1 way of actually being able to actually try begin to get an answer

brisk obsidian
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The method I showed is Fundamental Theorem of Calculus (Part 1) which you would learn about in Calc 1.

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$\frac{d}{dx} \int_{a}^{b} f(x) dx = f(b) - f(a)$

glossy valveBOT
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Kookiemon

dull thicket
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im aware

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might have phrased my sentence a bit odd

brisk obsidian
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And the optimization should be fairly straightforward but I do not get the correct the answer and I'm trying to figure out what I'm doing wrong.

nocturne creek
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Okay i think i got it

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😈

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As in

brisk obsidian
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👀

nocturne creek
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I might say a lot of weird stuff cuz im still learning this

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But to find the maxima

dull thicket
nocturne creek
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We need to put the derivative =0?

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And if you do that you actually do get

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Option 6

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Now if you want to check if its maxima or minima, i think you need to find the second derivative and see there(?), Which you find out depending on the sign

nocturne creek
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Absolutely not sure if this is correct or not tho

brisk obsidian
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Gahh, I forget to use the Chain Rule. 😛

dull thicket
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sooooo

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if you use the correct derivative and FTC we will get the answer now right?

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which should be six

brisk obsidian
nocturne creek
# nocturne creek

In order to check whether a= that is maxima or minima, do we need to find out the 2nd derivative and input this there?, Also is my derivative correct 😭

nocturne creek
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But a>0

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So a=0+?

dull thicket
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sorry i was away for a couple of min

dull thicket
dull thicket
nocturne creek
dull thicket
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fair enough

brisk obsidian
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Well, there are only two solutions for a and only one of them is greater than zero.

dull thicket
brisk obsidian
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That's a 2, his 2's just happen to look like an L.

dull thicket
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okay then im stupid 🙏

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not stupid

nocturne creek
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Okay since x=a

dull thicket
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aaaaaaa

nocturne creek
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da/dx =1

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Would that be correct?

nocturne creek
dull thicket
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i suffer the same skill issue 😔

dull thicket
nocturne creek
dull thicket
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wait we know the answer is 6 right and 6) is 1/2 sqrt(ln3/2)

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right

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and you have at the third last sentence 8a^2 = ln3

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solving for "a" would give us sqrt(ln3)/2

torn jolt
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Hello

dull thicket
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right?

torn jolt
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What's happening @nocturne creek

dull thicket
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hi

torn jolt
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Give me a run down

nocturne creek
torn jolt
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How did u make it e^a

nocturne creek
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That is from the ftc i think

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Or as my teacher made me learn, a case of leibnitz rule🗿

torn jolt
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Also I don't think it makes sense, that's just a definite integral that should be 0 no?

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When u are taking its derivative

nocturne creek
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The reason i thought itd be 0 is cuz a and 3a are constants

torn jolt
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Yes

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Exactly

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Either you inadvertently did something in a similar way to how it should be done, or u just did something I have no idea about

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Maybe @nocturne creek

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Integrating from a to x

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Might be an idea

nocturne creek
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Integrating what

torn jolt
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You might as well say that you don't know what 3a is

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Also shit with erf(x) is just big no-no territory I don't want to get into

brisk obsidian
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$Area(a) = \int_{a}^{3a} e^{-x^{2}} dx$

glossy valveBOT
#

Kookiemon

torn jolt
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Isn't that hard

brisk obsidian
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So when you do the Chain Rule, it's just d(3a)/da

nocturne creek
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Was it supposed to be like this?

brisk obsidian
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You don't need the + and everything after that.

nocturne creek
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The reason i did that cuz i found this in my notes

dull thicket
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sorry i was gone for 10 min what has happened

brisk obsidian
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Just ironing out the fine details of how to solve the problem. In particular, it was how the Chain Rule should be applied.

dull thicket
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aaaaa its so close

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@dull thicket Has your question been resolved?

dull thicket
#

im not making any progress tbh and im just considering closing this and working on another task

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.close

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torn jolt
#

I need to find $\Im((a+bi)^2)$ and $\Re((a+bi)^2)$. Expanding $(a+bi)^2$ gives $a^2+2abi-b^2$, is that right?

glossy valveBOT
torn jolt
#

In this case $\Im$ will be $2ab$, but what's $\Re$?

glossy valveBOT
torn jolt
#

$a^2-b^2$?

glossy valveBOT
forest widget
#

you got it

torn jolt
#

Thanks a lot.

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sinful onyx
#

"write a quadratic equation with whole-number coefficients, where one solution is x1 = sqrt(3) + 1 / sqrt(3) - 1"

torn jolt
#

What do you think

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How should this be done?

sinful onyx
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move the solution to the left so its x1 - solution = 0, then square it?

silver pasture
torn jolt
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Lets see

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Can we subtract 2√3 from x1 to get x2?

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Firstly

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Have you rationalized?

sinful onyx
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i have not

torn jolt
sinful onyx
#

2 + sqrt(3)

torn jolt
#

Since we need whole number coefficients

#

We will need such a number that can be added to 2+√3 so that only the whole remains and multiplied to 2+√3 such that only the whole remains

#

The other number should be?

#

I mean

#

The other zero will be?

sinful onyx
#

2 - sqrt(3)?

torn jolt
#

It will be the rationalizing factor

#

Whenever they ask for whole number coefficient

#

Take the other zero as the rationalizing factor of the first zero

#

Now try formation of polynomial using the sum and product rule

ivory cairn
#

after you rationalize, you can also just move the 2 over and square everything
(x-2)^2 = (root 3)^2

sinful onyx
#

we didnt learn that

torn jolt
sinful onyx
#

nope

torn jolt
torn jolt
#

Basically

#

To make a polynomial based on its zeros

#

Assuming ß and ∂ to be the zeros

#

K(X^2 - (ß ∂)x + (ß+∂))

sinful onyx
#

i see

#

thank you

#

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torn jolt
#

K is a constant just in case there is a fraction in the x2 term, you can multiply the whole polynomial by the denominator

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silver valve
#

What is the value of this because if it is 10 then shoudnt you square the exponent?

torn jolt
#

Value?

silver valve
#

The value of the box

atomic blade
#

But wdym square the exponent

silver valve
#

Like square the 10

atomic blade
#

No why would you

#

That would be raising to 100 which would make the equality false

silver valve
#

?

atomic blade
#

It's just 10

#

Why would you square the 10? That makes no sense

silver valve
#

then if you were to simplify this equation would you not power it to the exponent

#

or square it to the exponent

#

take the numerator

#

for example the first numbers

#

you wouldnt square it?

atomic blade
#

The numerator would become -12x^5y^7

#

The denominator is 4x^4y^4

#

Overall it's just gonna be -3xy^3

#

You have to use exponent laws

#

$$(a^b)^c = a^{bc}$$

#

@glossy valve boy you dead

silver valve
#

hm ok

#

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dull thicket
#

hi so i need a bit off help im using the trapezoidal rule to calculate the definte integral of e^x^2 from 0 to 1

dull thicket
#

1,4 and its a bit perhaps a but to much

#

well 1,4806

#

i was wondering how much its usually is off?

#

its probably off by like 0.03

#

is that to much?

balmy peak
#

depends how many trapezoids you are using to approximate

dull thicket
#

i used 5

#

plus endpoints

balmy peak
#

so your n = 5?

#

yeah ur answer should be 1.48065

#

is ur question about the error bound of the trapezoid rule ?

dull thicket
#

no

balmy peak
#

what specifically then? ur answers correct

dull thicket
#

Calculate the volume of the body that appears when the area between the graphs of cos(x) for x in [0,1] and e^x^2 for x in [0,1]

balmy peak
#

u have to use trapezoid rule for this?

dull thicket
#

and rotates around the y-axis

#

you cant integrate e^x^2

atomic blade
#

Bruh moment

balmy peak
#

just plug into ur calculator

dull thicket
#

and i couldnt find anything else

atomic blade
#

Yeah no e^x^2 is ass

dull thicket
#

first one

balmy peak
dull thicket
#

yeah

#

i gotta find the triangle ish area bordering y = 1

balmy peak
#

theres no area between them

#

ohhh

#

yeah ic

dull thicket
#

i think atleast ?

balmy peak
#

yeayea

#

im dumb

dull thicket
#

cuz the functions only defined from 0 to 1

#

i have now found an estimate of the area which 0,6342

#

and now i gotta rotate it

#

which i really dont understand how to do

balmy peak
#

nvm im lost i dont see an area between them

#

maybe someone else can help sorry

dull thicket
#

Shitty pic

#

Aaaaa

balmy peak
#

rotated around the y axis?

dull thicket
#

just type y = 1

#

into geogebra

balmy peak
#

so ur using shell method

#

?

dull thicket
#

what method is that

#

my book rarely uses names for the method only describtions

#

T_T

balmy peak
#

2pi * integral from a to b of R(x)H(x)dx

#

or r u doing this using washer but in the y world?

#

actually that seems way harder

#

so im assuming shell

dull thicket
#

i was gonna use washer method but wtf is the difference

balmy peak
#

ur rotating around y axis no?

dull thicket
#

yeah

#

and i found the area but i couldnt really do the full integral

#

so im assuming i just add 2pi to the area

#

?

#

not add multiply

balmy peak
#

if ur doing washer method

#

the DE has to be perpendicular to axis of rotation

#

so if u were gonna use washer for this u'd have to do it in the y world

#

i.e. f(y)

dull thicket
#

but i can still use shell method

#

?

balmy peak
#

yeah bec ur DE is parallel to axis of rotation in shell method

#

so we can just use f(x)

dull thicket
#

DE?

balmy peak
#

differential element

#

like dy / dx

dull thicket
#

okay gotcha

#

soo since i have the area between graphs multiply it by 2 pi and get 3.9848

balmy peak
#

urm do

#

2pi * integral from a to b of (f(x) - g(x))*x dx

#

because our R(x) is just x

dull thicket
#

but i cant do the integral

balmy peak
#

can u not use a calculator for this question

dull thicket
#

bc is not possible with e^x^2

#

like literally

balmy peak
#

theres no way they want u to use trapezoid to estimate the area between the curve lol

dull thicket
#

but even so the integral by defintion is just the area under a graph

#

then what should i do?

balmy peak
#

yes but we have R(x) * h(x)

#

u cant split the integral into two

#

and multiply

balmy peak
#

if not just solve the integral normally

#

because its gonna be

#

xe^(x^2)

dull thicket
#

i can use a calculator

balmy peak
#

.......

#

So just plug it into ur calculator

dull thicket
#

im so confused

balmy peak
#

are u allowed to just plug it into ur calc ?

#

if not

#

solve normally

#

2pi * integral from a to b of (f(x) - g(x))*x

dull thicket
#

okay i plug the integral 0 to 1 for e^x^2 *cos(x)

balmy peak
#

multiply by x

#

shell method

#

If u cant use a calc then notice that we have

#

xf(x) - xg(x)

#

and we can solve the integrall

#

of

#

xe^x^2 normally

dull thicket
#

okay two sec

balmy peak
#

multiply by 2pi

dull thicket
#

And there we go?

balmy peak
#

yeah

dull thicket
#

ehm i dont find the same formula you showed me though

#

are you sure this is a valid one?

balmy peak
#

id look into it more if ur doing these types of problems

dull thicket
#

but where is the additional x

balmy peak
#

R(x)

#

our radius

#

again id watch the video

dull thicket
#

okay ill do that

balmy peak
#

you cant use washer method for these questions

#

or well you can but its gonna be hell

dull thicket
#

thanks for the help ^^ ❤️

#

i probably tbh aaaa

#

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rare elk
#

Can someone help me simplify this?

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vast fossil
#

Notice that 64 = 4^3 and x^3 - 3x^2 + 3x - 1 = (x - 1)^3

rare elk
#

O

#

Ty

#

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barren iris
#

Does inversely congruent mean that they are not congruent?

barren iris
#

This is about two triangles, that were split from 1.

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@barren iris Has your question been resolved?

barren iris
#

<@&286206848099549185>

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@barren iris Has your question been resolved?

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@barren iris Has your question been resolved?

south dirge
barren iris
south dirge
barren iris
#

But if I were to do that with non congruent triangles, you won't have another triangle

south dirge
#

Well usually congruent means that you can also rotate ABC, but not in your case i guess

barren iris
#

Okay

#

Yeah reading what I said again, I think I said that wrong

#

Immediate regret

#

Okay

#

Ty

south dirge
#

Np

barren iris
#

Are you used to geometric proofs?

#

My book has it where each proof has like a statement and then a reason. My only thought for this sort of problem is to just write out what I think is given

#

Like AB = DC where AB is from a trainlge ABC, and DC is from a triangle DCE

south dirge
#

I guess there must be 3 theorems when two triangles are congruent

#

If their sides are equal, two sides and angle between or two angles and side between or something like this

barren iris
#

So would it satisfy a proof to just write out theorems that have already been proven?

#

Or like how do you even know when you're done with a proof

#

Also, thank you for your help

south dirge
# barren iris Or like how do you even know when you're done with a proof

It should look smth like this:
Theorem: if A and B are true, then C is true.
You need to prove that C is true, for example.
Then you prove that A is true, then that B is true, and using theorem you say that C is true.
In your case you can just say that their sides or angles with sides are equal, so we can use the theorem, so they are congruent. In harder cases you will need to prove that sides are equal using something else, that is given, and only then use the theorem. That works for every proof problem in maths, not only geometry.

barren iris
#

Thank you so much

south dirge
#

No problem 🙂

barren iris
#

Where did you learn how to do proofs

south dirge
#

school, books, videos, on my own, right now I'm learning it in university 🙂
Like everyone, to be short

barren iris
south dirge
#

It's cool!

barren iris
#

It's rough for me rn but I need to learn it!

#

Totally different from what I'm used to

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untold sapphire
#

A is (-2,0) B is (0,4). Find the equation of the line, which passes through A and is perpendicular to AB

shrewd hamlet
#

Do u know slope formula

untold sapphire
#

kinda

shrewd hamlet
#

Calculate the slope from those 2 points

untold sapphire
#

would the gradient be 2

shrewd hamlet
#

Yea

untold sapphire
#

oh okay

shrewd hamlet
#

Now, to get the perpendicular line, we need to make that slope of opposite sign and reciprocal

#

So what’s opposite sign reciprocal of 2

topaz valley
#

negative reciprocal a better word for it?

shrewd hamlet
#

Oh yea thx

pliant crown
#

💀

shrewd hamlet
#

1 am error 404

untold sapphire
#

im guessing postive sign

shrewd hamlet
#

So our current slope is: +2

glossy valveBOT
shrewd hamlet
#

Thx

#

So if m1 = +2, can u figure out m2? @untold sapphire

untold sapphire
#

hmmmm

#

no i wouldnt

shrewd hamlet
#

So try plugging in 2 where the m1 is

#

And see what m2 is equal to

untold sapphire
#

ohh

#

that make sense now

shrewd hamlet
#

Yep, so we just took the negative reciprocal of our slope

untold sapphire
#

would it be -2

shrewd hamlet
#

Close but no cigar

untold sapphire
#

or +2

shrewd hamlet
#

Take the reciprocal

#

Of -2

#

Well +2, is our slope

#

Do u know what reciprocal is

#

For example

#

3 is reciprocal of 1/3

#

1/4 is reciprocal of 4

#

-5/6 is reciprocal of -6/5

#

U see what’s happening?

untold sapphire
#

yeah

shrewd hamlet
#

So what’s the negative reciprocal of +2

merry carbon
untold sapphire
#

uhhh

shrewd hamlet
#

It’s -1/2

untold sapphire
#

oh nice

shrewd hamlet
#

Reciprocal of 2 is 1/2 and so negative reciprocal of 2 is -1/2

#

Now, do u know point slope form?

merry carbon
#

What is the equation for the perpendicular bisector of AB for the given points A (-2,0) and B(0,4)? was this the question or was i reading it wrong?

untold sapphire
shrewd hamlet
untold sapphire
#

by the way i dont even know what is a reciprocal

shrewd hamlet
#

Essentially it’s 1/(our number)

#

That’s all the reciprocal is

#

Reciprocal of 10 = 1/10

merry carbon
#

yeah

shrewd hamlet
#

Reciprocal of 1/15 = 1/(1/15) = 15

merry carbon
#

im good at trigonometry bad at probability haha

untold sapphire
#

and when u get the negative reciprocal do you plug in to point slope form

merry carbon
#

a reciprocal is this Multiplicative inverse

shrewd hamlet
#

Yea now that we have the slope of the perpendicular line that passes thru A, plug in point A and the slope we found into point slope form

untold sapphire
#

the answer would be y= -1/2x -1

shrewd hamlet
#

A(-2,0)

#

So y = -1/2(x+2)

#

y= -1/2 x - 1

#

Yep

#

Nice job

merry carbon
#

@untold sapphire do .close

#

so someone else can take the ticket

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#

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untold sapphire
#

.close

untold sapphire
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knotty silo
#

Question what is a integral in terms of a derivative?

warm abyss
#

The antiderivative

knotty silo
#

I look it up on internet and seems to be the opposite of a derivative which is slope but I don’t get how that makes sense

eager violet
knotty silo
woven sand
#

Not really opposite but the inverser

warm abyss
woven sand
#

If it helps, area under a graph wrt time usually represents a cumulative amount of something (cumulative distance, velocity, what have you) while the slope at a point is the rate of change

#

Yeah FTC makes that connection

knotty silo
#

Well I’ll watch the videos and articles. Thanks you

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broken rain
#

Let A be a finite set, with |A| = 8

a) How many relations of A in A exist?

b) How many relations of A in A exist that are reflexive?

I don't understand what means with relations of A in A :c

hard siren
#

I don't understand what means with relations of A in A :c

the relation whose domain and co-domain both is the set A? means defined from A --> A

torn jolt
#

or maybe just "arrows", in general, where it can, for example, map only a subset of its domain (instead of its whole domain)

broken rain
#

Something like this?

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broken rain
#

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marble whale
#

can anyone give me any ideas on how to approach this pls

scenic yew
#

Are we allowed to assume that angle abd is a right triangle?

#

@marble whale

#

Because my plan is to make angle abd, cdb, efb, efd a right triangle

#

And since ab = sin(2x), and cd = cos x, triangle abd and cdb are similar triangles since they both contain line BD

#

Oh we are allowed to, since cd = cosx, it must be that bc = 1

marble whale
#

Wait lemme draw the diagram again

marble whale
#

How did you get to that conclusion?

scenic yew
#

Oh since CD = cos x

#

Since cos x = a/h
and a = CD
But since there are no fractions, it means that h = 1

#

cause CD/1 = cos x

marble whale
#

☠️

#

How did I not think of that😭

#

OK that's one bit done

#

Also I managed to find that the angle is between 30 to 45

#

Not including 45

scenic yew
#

Oh I was about to answer 45

marble whale
scenic yew
#

Since we concluded that CD = cosx
It means that BD= sin x
And BD is part of triangle ABD
AB has sin 2x, angle adb must be 2x
Since bd = sin x, bad must be x

#

x+2x+90=180

#

3x=90

#

x=45

marble whale
#

30😭

#

Wait let me read this

scenic yew
#

@marble whale

#

Are you good now?

#

Cause I'm about to send a proof that AD = 2sinx

marble whale
#

Yep that's fine, thanks a lot!

scenic yew
#

Oh do you need AD's length just in case?

marble whale
#

I got 1 and 2sinx and just equated them together

#

And got x = 30

scenic yew
#

Ok, it seems we're done here

#

You may now close the channel for others

marble whale
#

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ivory moon
#

I forgot how to do this

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smoky wing
#

bruh

#

tan(theta)=sqrt(e^x -1)

ivory moon
#

Ah yes this substitution

#

K let me try again

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lean gazelle
#

How do I solve this?

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lean gazelle
#

This is my response for a)

#

and this is my response for b)

torn jolt
#

We don't see b)

lean gazelle
torn jolt
#

Or a)

lean gazelle
#

still?

torn jolt
#

The question themselves? No

lean gazelle
#

its translated from danish, so sorry if its garbage lol

#

<@&286206848099549185>

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torn jolt
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frozen lark
#

can't see the inputs of the first two gates

torn jolt
#

hold on

#

is that better

frozen lark
#

very well

torn jolt
#

thats good

frozen lark
#

so first let me say that it's good to start from the output then go back to the inputs

#

like in the finish line we've got a not gate

#

so we have a one big bar up all the equation

torn jolt
#

im just confused

frozen lark
#

?

torn jolt
#

as far as this goes and my teacher doesn't want to help me with it

#

i see it

frozen lark
#

no worries son, i'm gonna show u the way of truth

torn jolt
#

the x bar is shorter then the y bar

frozen lark
#

wait step by step

#

first we've got a huge bar in up

#

after that there's an and gate

#

*or

#

sorry mistake

#

any ways so we have a huge bar and under it there is or so it's +

#

so it's like :

#

$\overline{something + somthing}$

glossy valveBOT
#

mino65

frozen lark
#

we keep

#

the first something is an and gate

#

and of what ?

#

x and y

torn jolt
#

if you have something + something

#

you have an input of x and y correct?

frozen lark
#

remeber :
or = +
and = * (multiplication )

#

you can say that x and y is equal to x times y

#

x*y

#

but see that there is a not gate up that and gate

#

so it becomes nand gate

#

so:

torn jolt
#

the triangle?

frozen lark
#

you know the logical gates symbols no ?

torn jolt
#

yes

#

the triangle

frozen lark
#

any ways it becomes :

torn jolt
#

the one above

marsh surge
#

[(x.y)bar + (x+y)]bar

torn jolt
#

has a triangle and the one below just has a line

frozen lark
#

as long as you understand it like that

#

yes

#

but don't name a triangle in front of the teacher he'll probably laugh at you

#

say not gate or inverting gate

#

that's more accurate

torn jolt
#

my teacher is already a joke

frozen lark
torn jolt
#

i already laugh at him he dropped my grade by giving the entire class 0s

marsh surge
torn jolt
#

well

#

thats even worse

frozen lark
#

naa don't worry logical calculations are super ez you'll get them in no time

#

any ways so now we have that

#

$\overline{\overline{x\cdot y} + somthing}$

glossy valveBOT
#

mino65

frozen lark
#

don't care about that i'm used to a and b

#

the other something is what?

#

we follow the other line that goes through as an input for the final or gate

#

and what is that ?

#

it's x or y

#

so x + y

#

so our final equation well be like :

torn jolt
#

wait

frozen lark
#

$\overline{\overline{x\cdot y} + x + y}$

glossy valveBOT
#

mino65

frozen lark
#

?

torn jolt
#

i have to hand draw this

#

i dont know where to start

frozen lark
#

there is no beginning line

torn jolt
#

i got a math disability

#

i can't think mathmathically

#

when it comes to doing math in general im struggling with keeping up

frozen lark
#

then think like an engineer

#

engineers don't think of some crazy integration equation they just start from some little scraches and then make the way step by a step

torn jolt
#

is this for the top part

frozen lark
#

?

torn jolt
#

im lost

#

and confused

#

struggling

frozen lark
#

eazy brother chail

torn jolt
#

here wait i got an example

frozen lark
#

it's not like the sky will fall if you can't solve some logical stupid equation

torn jolt
frozen lark
#

sus

torn jolt
#

4th slide

frozen lark
#

McMystix you've been writing since yesterday what's there ?

marsh surge
# torn jolt i dont know where to start

what you can do is divide the sequence in branches
find the equation for the top branch (the AND and NOT gate) let that be A

then find equation of bottom branch
(OR gate) let that be B

then find equation of the middle branch (OR and NOT) in terms of A and B

in the end substitute values of A and B
and you will get the final equation for the output

torn jolt
#

makes more sense

marsh surge
torn jolt
#

thank you

marsh surge
#

np

torn jolt
#

i watched the lectures

frozen lark
#

wew

torn jolt
#

and im super confused

frozen lark
#

what a splendid explanation

#

he gave them a half-adder circuit as a beginning ☻

torn jolt
#

this guys a complete joke honestly when it comes to teaching lol that is my teacher

marsh surge
torn jolt
#

thank you for this

frozen lark
#

yeah you said that you can't think mathematically but you don't need to

torn jolt
#

you dont

#

i see no math involved damn

frozen lark
#

in ma class there is a classmate that is so trash in math ... he really is but he's super powerful when comes to the logic

#

my point is

marsh surge
#

bad at math != bad at everything

torn jolt
#

basically

frozen lark
#

don't blame yourself if you can't understand it very quickly

torn jolt
marsh surge
#

watch videos on YouTube if your teacher isint good

torn jolt
#

ok that might help

#

ima just be honest with you

#

i just listened to the lectures

#

so i didn't take notes on it and i went back and watched some of it and yeah it makes sense now being able to get it explained by you guys

frozen lark
#

yeb

#

listen

#

don't worry if you can't take it

#

cuz you will

torn jolt
#

yep

marsh surge
#

practice a bunch

frozen lark
#

you just need to keep solving these gate question

#

it'll become hella ez

marsh surge
#

start with easier questions and then try to solve hard ones

#

there isint much thinking to do in these questions, just be careful to not make mistakes

frozen lark
torn jolt
#

xD

#

thats nice

frozen lark
#

and for the 2nd question i can show how to solve it but i think it'd be better if you get yourself used to the 1st question problem first

torn jolt
#

the first one

#

can i skip that one and do 2 and 3

frozen lark
#

it envolves some Factorization

torn jolt
frozen lark
#

he simply gave you a table

torn jolt
#

this is blurry af

#

geez

frozen lark
#

that table shows you when the F gets the value 1 according to the variable x, y and z

#

so we need to find the equation of F

#

look

torn jolt
#

hold on

frozen lark
#

a simple rule

torn jolt
#

idk what im doing honestly

frozen lark
#

know binary

#

?

torn jolt
#

no

#

the entire thing

marsh surge
#

welp

torn jolt
#

i hand drew the logic gate

marsh surge
#

you need to know binary to solve this

frozen lark
#

ok this seems to be a little bit hard

#

but you'll get through

#

first here's a good explanation for this weird table that's called " truth table"

#

you'll get the idea of the binary as well

marsh surge
#

better to learn binary itself first

#

not too complicated

torn jolt
#

i know how to do those

frozen lark
#

i know but the guys says that he have 0 base in all of this and a trash teacher

torn jolt
#

i dont know how to do logic circuits

frozen lark
#

it's just like yes or no

torn jolt
#

im getting really distracted i was just sending a message to my teacher

frozen lark
#

heeee

torn jolt
#

i understand what truth tables are

#

you have different symbols

#

or and

#

or is like a symbol of a wheel

frozen lark
#

how do you understand them while you don't know binary

#

?

torn jolt
#

because i learned truth tables at the beginning of this class

frozen lark
#

wtf

torn jolt
#

and it took 3 fucking months for this class to start

#

so basically he told me to just go play video games until the class started

frozen lark
#

ok ok son calm down calm down

torn jolt
#

😦 im depressed now

frozen lark
#

nooooooooooo

#

no depression

torn jolt
#

lets just focus on the topic

frozen lark
#

your not some stinky depressed 15 yo teenager

torn jolt
#

so i can understand this i've gotten no where

torn jolt
#

and no im over 18

frozen lark
#

17 me

torn jolt
#

i learned about truth tables

#

on the first week of school

marsh surge
#

without learning binary first?

torn jolt
#

yes

marsh surge
#

weird

torn jolt
#

yep

frozen lark
#

wat da hail is going on with the educational system

torn jolt
#

this class makes me wanna give up and jump off a bridge

frozen lark
#

naa don't let some 0s and 1s take your life that's kinda shame

torn jolt
#

im shocked

#

you're able to help me with this

frozen lark
#

any way it's kinda ez to get out of this situation

#

yes

#

it's not that hard

torn jolt
#

ok

frozen lark
#

just go and learn binary and everything will become bright

torn jolt
#

im 23 myself but ill stay on topic

#

i wanna try to figure out the logic gate first

frozen lark
#

dont'

#

go learn binary

torn jolt
#

for the logic gate

frozen lark
#

you see your trash teacher started with the wrong thing

#

here is the series of what you should do

torn jolt
#

ill come back after i get a bit of a better understanding

frozen lark
#

first : learn binary, hexadecimal and other numerical systems

torn jolt
#

so i dont waste your time

marsh surge
#

binary
octal
hexa
logic gates

frozen lark
#

good

torn jolt
#

i feel bad

#

for wasting your time and my time

frozen lark
#

it's not your fault that you have a trash teacher

marsh surge
#

it's 2 am and I'm bored so wasn't a waste of time lol

#

atleats for me

torn jolt
#

thats good

#

so should we close the ticket

#

ill watch youtube videos on logic gates