#help-28

1 messages · Page 26 of 1

reef sparrow
#

if you keep dividing 1 by increasingly "large" negative numbers, what happens?

#

1/-1, 1/-2, 1/-3, 1/-4...

stiff swan
#

we get closer to 0?

reef sparrow
#

correct

#

so 1/ln(x) goes to 0 as x → 0⁺

stiff swan
#

oh

reef sparrow
#

so this limit is equal to cosh(0), which is...

stiff swan
#

1

reef sparrow
#

right.

stiff swan
#

lets gooo

#

Is there a way to easily remember graphs

#

I think the graphs are very useful here

#

specially the inverse

#

I can't memorize those

#

guess I just gotta do it

full forumBOT
#

@stiff swan Has your question been resolved?

full forumBOT
#

@stiff swan Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed due to the original message being deleted

deft zodiac
#

hi

#

post again elsewhere

exotic cloud
#

why is the 1/3 here?

deft zodiac
#

eh

#

what u found is the direction

#

uve to normalise it

#

like /magnitude

#

in this case its

#

sqrt[(-2)^2 + 1^2 + 2^2]

#

= sqrt(4+1+4) = sqrt9 = 3

#

so when u divide by that u get

#

1/3

#

unit vector always has length 1

exotic cloud
#

so that 1/3 is direction or magnitude?

#

this applies for all when we find through this ijk right?

deft zodiac
#

um

#

1/3 is the magnitude

#

direction is

exotic cloud
deft zodiac
#

go to

#

the other

#

o u got it alr?

exotic cloud
#

thank you so mcuhhhhhh

#

yes

deft zodiac
#

np

#

just

#

dont delete ur original msg next time

#

itll close the channel in some time

#

even if ppl r in it

#

anyway

exotic cloud
#

i send the wrong picture

deft zodiac
#

💕

#

yea just

exotic cloud
#

thank youuuu!!

deft zodiac
#

repost it in another channel

#

np

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

void arch
#

Struggling to understand the intuition of dedekind cuts

void arch
#

For any x in the real numbers you can partition the rational numbers into two sets

#

Take for example root2 and root3 and it has the dedekind cuts a and b respectively

#

Would you then say that a is a subset of b?

#

And that the union of all dedekind cuts defines the real numbers?

fast peak
#

so we have two dedekind cuts a and b. one represents the number sqrt(2) and the other the number sqrt(3). we can then define what it means that sqrt(2) < sqrt(3), namely that a is a subset of b

void arch
#

Why did you use the inequality sign to denote subset?

fast peak
#

well we wanna think about sqrt(2) and sqrt(3) as numbers and not as sets

#

so as numbers they are smaller if the corresponding sets are subsets

full forumBOT
#

@void arch Has your question been resolved?

void arch
#

How does this imply they are the same dedekind cuts?

fast peak
#

usually A isn't allowed to have a greatest element

#

or at least the definitions I have seen

void arch
#

The question is to give an example of dedekind cuts where B1 is a subset of A1 and alpha is not strictly larger than beta

fast peak
#

proper subset or just subset

void arch
#

Proper

fast peak
#

can you give the definition of dedekind cuts you are using?

void arch
#

It has no maxima element in A, it’s not the empty set and finally if a is in A and b<a then b is in A aswell

#

Another thing I’m confused about

#

Do Dedekind define all real numbers, so rationals and irrationals by choosing what supremum you use as the maxima

fast peak
#

very informally, yes

#

assuming I understand correctly what you mean

#

so you want two dedekind cuts alpha and beta, so that alpha=beta but A_1 is not the same as B_1 ?

#

that doesn't work. dedekind cuts are unique

full forumBOT
#

@void arch Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed due to the original message being deleted

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

broken rain
#

Why the answer is 448? I interpret like 9 x 8 x 7 = 504, I don't understand why is 448

ivory cairn
#

there aren't 9 options for the first digit

sharp zenith
#

^

#

since it’s a 3 digit number, you don’t have 0 as a choice and you don’t have 5 as a choice

#

so for the hundreds, there’s 8 options

#

for the tens, you can’t have 5 or the number from the hundreds so there’d be 8 options again

#

and for the units, you can’t have 5, the number for the hundreds, and the number for the tens

#

so 7 options

#

8 x 8 x 7 choices

full forumBOT
#

@broken rain Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pulsar grail
full forumBOT
#

@pulsar grail Has your question been resolved?

full forumBOT
#

@pulsar grail Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torn jolt
full forumBOT
torn jolt
#

I've tried substituting the x and y coordinates into y = f(1/3x) but I got confused when I saw that I have been left to work out for f

#

I don't get what I should do

#

<@&286206848099549185>

#

man

#

.close

full forumBOT
#
Channel closed

Closed by @polar veldt

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

charred ivy
#

hi can someone help me with this

full forumBOT
torn jolt
#

hello im new can anyone help me learn?

charred ivy
#

this is precalc but my my teacher showed us how to evaluate the limit

rocky vale
#

Precalc?

#

So, you haven't learned about derivatives?

full forumBOT
#

@charred ivy Has your question been resolved?

charred ivy
#

@rocky vale no

#

only know functions and algebra

supple flume
#

this is what it looks like

#

and you take the limit as h goes to 0

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lone flint
#

Vector A = (1,2,-4), vector B = (1,1,k-1), ||A + B|| = 7
Find k

lone flint
#

It looks easy but I don't get how to solve it

torn jolt
#

whats the question

lone flint
#

Find k

torn jolt
#

easy

#

use the length rule

#

you have everything except k

lone flint
#

Length rule?

#

Norm you mean?

torn jolt
#

its been 3years since vectors

lone flint
#

Look here is my board

torn jolt
#

i think idk

lone flint
#

Idk why I got a weird equation at the end

torn jolt
#

seems good i think
now separate the K from the numbers each one to side and find k

lone flint
#

How

#

<@&286206848099549185> ayo mind checking the solution above

full forumBOT
#

@lone flint Has your question been resolved?

full forumBOT
#

@lone flint Has your question been resolved?

#
Channel closed

Closed by @lone flint

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wheat garden
#

hi

full forumBOT
wheat garden
#

did i do this right

heavy wolf
#

,rotate

glossy valveBOT
wheat garden
#

idk if what i used works

#

i used like the conjugate of the complex zero

#

.close

full forumBOT
#
Channel closed

Closed by @wheat garden

Use .reopen if this was a mistake.

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

outer charm
#

For the first question, unsure where teeter is.
For the second question, Not sure how to manipulate the equation further, or if I even manipulated it right to begin with. Cannot tell where does m come into play for this equation, and hence unable to continue to answer this question.
O, P and Q = 2. R and S = 4. T = 1. U = 3, V = 2. W=1, X = 2, Y = 3, Z =4.
For the third question, Have quite a weak foundation in trigonometry... Just stuck for the entirety of this question... unable to answer them at all.

full forumBOT
#

@outer charm Has your question been resolved?

full forumBOT
#

@outer charm Has your question been resolved?

outer charm
#

<@&286206848099549185> please do help out if you are able to. Thank you so much!

full forumBOT
#

@outer charm Has your question been resolved?

full forumBOT
#

@outer charm Has your question been resolved?

azure aurora
#

lol i have no idea how to do that, nor do I have the desire to read 8 pages

outer charm
#

Thank you for providing valuable insight to this. I will take note that perhaps I should not ask too many questions in 1 channel for future questions.

full forumBOT
#

@outer charm Has your question been resolved?

outer charm
#

hello all, i will be heading to sleep now but the questions have yet to be answered. please do not close the thread, thank you!

#

Upon further reading of the statement above made by Christopher I also would like to clarify, it is NOT 8 pages, but a page split into 2 due to feedback from before that if I were to post the question page by page, it would be unclear. Hence I have opted to split some questions into 2 or 3 shots to make it clearer 🙂

full forumBOT
#

@outer charm Has your question been resolved?

silver drift
#

For 2, use the length of ac and the sin value given to work out ah. Very direct.

#

For 1, use the ah you got before in the classic triangle area formula 1/2 b*h

#

In the future, ask a specific question, not "here's the assignment sheet, i don't get it."

#

I see now I answered questions you already got the solution to.

#

For part 3 of question 1, you can form a triangle with OAH. You know the length of all 3 sides. Theta is in the corner of H. The rest should be straightforward, like part 1 and 2 were.

#

You may need the formula vol=1/3 height * area for pyramids.

outer charm
silver drift
#

OAH is in the third dimenson. H is between B and C, as seen in parts a and b.

outer charm
#

uk what nvm i tink i will never get it at this rate thanks anws

#

.close

full forumBOT
#
Channel closed

Closed by @outer charm

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fathom saddle
#

Factor top and bottom

#

So you factored, and didn't notice anything weird?

#

Factor top and bottom

full forumBOT
#
Channel closed

Closed due to the original message being deleted

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

full forumBOT
#
Channel closed

Closed due to the original message being deleted

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shadow nimbus
#

Solve by “Trial and Error”.) Below is a floor plan of an art gallery.
IS it possible to take a stroll that passes through EVERY doorway WITHOUT going through the same doorway twice? HOW?

shadow nimbus
scenic wren
#

i dont think it is possible

#

nevermind

#

i counted wrong

#

think about what to do with the rooms with three doors

#

they are the problem here and also the key to a solution

wild sleet
#

there are many solutions

spice orchid
#

Its a graph with doors as vertices and edges if two doors share a room

#

Then you can use degree of vertex argument to say if it's possible or not

wild sleet
#

you can solve it by trial and error, just pick a new room as a start every time

full forumBOT
#

@shadow nimbus Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torn jolt
#

(6) If the angles of a triangle are 2a, a + 20 and a + 24, the value of a is:

torn jolt
#

How do we do this sum can anyone help pls

split yacht
#

Sum of angles in a triangle is 180 right?

torn jolt
#

yes

split yacht
#

So? It gives you the 3 angles

torn jolt
#

yes

split yacht
#

Which gives an equation for a?

torn jolt
#

idk

#

.close

full forumBOT
#
Channel closed

Closed by @graceful arrow

Use .reopen if this was a mistake.

split yacht
#

Uh, ok

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

full wave
#

someone help me w this rational equation 🥲

full wave
#

i somehow ended up with this

#

idk what to do further 💀

scenic wren
#

try to rewrite the fractions

#

to get the same denominator

full wave
#

which is 12x^2 - 12 (i guess)

scenic wren
full wave
#

ohhhh

#

okay so i messed up with that first part i see

#

thank you!

#

.close

full forumBOT
#
Channel closed

Closed by @full wave

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stuck lichen
#

i am indeed a dumbass

full forumBOT
stuck lichen
#

where everyone starebleak

smoky wing
#

For the LCM, What will the degree of 2 and 3 be

stuck lichen
#

uh

#

what

smoky wing
#

Do you know what the lowest common multiple is?

stuck lichen
#

yeah

#

A is basically 45000

#

and the first common multiple to has with b is given

smoky wing
#

Right so the LCM must contain 2^3 x 3^3 and 5^m

stuck lichen
#

ye

smoky wing
#

We’re given that the lcm is 3375000

#

$2^3 \times 3^3 \times 5^m = 3375000$

stuck lichen
#

mhm

glossy valveBOT
smoky wing
#

$5^m = 15625$

stuck lichen
#

how to find a variable exponent.

glossy valveBOT
smoky wing
#

Are you allowed a calculator

stuck lichen
#

ye

smoky wing
#

Then do log base 5 of 15625

stuck lichen
#

ight

smoky wing
#

Or simply recognise that 125 x 125 = 15625

stuck lichen
#

i got 6

smoky wing
#

Yea

stuck lichen
#

so i assume thats the ans?

smoky wing
#

Yeah n must be 6

stuck lichen
#

right

#

thanks a lot mate

smoky wing
stuck lichen
#

.close

full forumBOT
#
Channel closed

Closed by @stuck lichen

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

uncut vine
full forumBOT
uncut vine
#

I got this so far

#

Sorry for my bad hand writing

ivory cairn
#

i'm pretty sure there's a typo in this question. There's no need to do all of this

#

lim 3x is infinite
lim root(9x^2-x) is infinite
add them together.....

torn jolt
#

Because you can still get indeterminate forms where you can transform to do l'hopital

ivory cairn
#

i mean... infinity + infinity is not indeterminate

spice orchid
uncut vine
thin flint
#

why would there be a typo?

#

if it's a negative then it's extremely easy

spice orchid
#

?

torn jolt
uncut vine
#

So will it be

thin flint
#

i don't see how it should be - sqrt()

spice orchid
#

Well the point is that inf+inf isn't indeterminate but inf-inf is

uncut vine
#

So answer is 1/6?

spice orchid
#

Yes

uncut vine
#

All that writing for nothing

ivory cairn
spice orchid
#

Well your method was still valid just had to flip some signs

#

Clarify with your teacher which they meant though

thin flint
uncut vine
#

So just submit just this to my teacher?

uncut vine
spice orchid
#

Oh me and zyb have been thinking it's +inf

thin flint
#

no you shouldn't

#

you should find it yourself because otherwise you don't learn

#

but i am confused as to why there would be a typo

#

so i used wolfram alpha

#

to check if it results in indeterminate form

spice orchid
#

I thought it was x-->inf

#

As I suspect Zyb did too

torn jolt
#

It should be 1/6

#

Yeah

uncut vine
torn jolt
#

Also I will repeat this over and over, if you get something of the form infinity - infinity that's NOT 0 @uncut vine

thin flint
#

with explanation yes

#

for the submit

#

from the start

#

😄

full forumBOT
#

@uncut vine Has your question been resolved?

#
Channel closed

Closed by @uncut vine

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mortal forum
full forumBOT
mortal forum
#

Wondering how to get the right number since the solution is ~29.7

atomic notch
#

gotta inverse cos it

#

@mortal forum

void widget
#

,w cos x=(10^2+8^2-5^2)/(2×10×8)

atomic notch
#

10^2 + 8^2 not -

void widget
#

Oh yeahhh

mortal forum
#

which button is that on the calculator

atomic notch
#

shift cos

#

faking hell

glossy valveBOT
mortal forum
#

dont know if i have it

atomic notch
#

i see it above ur cos

void widget
mortal forum
#

yeah but it does nothing when i press it

atomic notch
#

maybe click 2nd f then cos

mortal forum
#

ill try

#

dont think anything happend

void widget
#

How could you use this one

#

After getting the cos sign

mortal forum
#

what do you mean

void widget
# void widget Here

After typing cos could you use that button that I've marked by any type of function

mortal forum
#

i juts did cos-1

#

it says still 0.960506

void widget
#

cos^(-1) or cos -1

mortal forum
#

cos-1

#

and pressed it again gave me 16.1

void widget
#

How do you put 2^(-1) in that calculator?

mortal forum
#

the button yx

#

bracket -1

void widget
#

So
Type cos and do that same thing maybe it will be good
Tap
Cos
Button yx
Bracket -1
Then (139÷160)

mortal forum
#

ya dont think this calculators gonna work

void widget
#

Use mobile

#

And nothin 😂

mortal forum
#

k

#

.close

full forumBOT
#
Channel closed

Closed by @mortal forum

Use .reopen if this was a mistake.

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

trail oasis
#

$\frac{a}{b}$ = $\frac{1}{\frac{b}{a}}$

glossy valveBOT
#

ByShaDowZ

full forumBOT
#
Channel closed

Closed by @simple plinth

Use .reopen if this was a mistake.

#

trail oasis
#

$\frac{n+1}{n}$ = $\frac{n}{n}$ + $\frac{1}{n}$

glossy valveBOT
#

ByShaDowZ

full forumBOT
#
Channel closed

Closed by @simple plinth

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

astral brook
#

how do i proof that $\frac{\log _2\left(2 \sqrt{10}\right)}{\log _4(5)+\log {10}(5)} = \log{5}{10}$

glossy valveBOT
#

Impractical

hoary cliff
#

God

onyx glen
#

convert everything to natural logs and do some algebraic fuckery

#

gonna be some moderately nasty expression in terms of log(2) and log(5)

astral brook
#

well thats kind of ugly i was hoping there was a shortcut

onyx glen
#

i mean ok like

#

$\log_2(2\sqrt{10}) = \frac32 + \frac12 \log_2(5)$

glossy valveBOT
onyx glen
#

bc sqrt(10) = 2^(1/2) * 5^(1/2) of course

astral brook
#

mhm

hoary cliff
#

im bad at logarithms

#

😦

onyx glen
#

@hoary cliff with all due respect, if you don't want to or can't help, then please do not intrude in this channel.

hoary cliff
#

Okk

onyx glen
#

@astral brook idt we can avoid some nested-fraction nonsense here

#

like the log_4(5) + log_10(5) at the bottom

astral brook
#

i should probably ask a simpler question, whats $\frac{\log _2\left(2 \sqrt{10}\right)}{\log _5(40)}$

glossy valveBOT
#

Impractical

astral brook
#

thats all i need to simplify the above

onyx glen
#

wait what

astral brook
#

yeah

onyx glen
#

log_4(5) + log_10(5) ≠ log_5(40) thonk

astral brook
#

no

onyx glen
#

i mean like ok hold on

astral brook
#

i manipulated the expression to be $\frac{\log _2\left(2 \sqrt{10}\right) \log _5(4) \log _5(10)}{\log _5(40)}$

glossy valveBOT
#

Impractical

onyx glen
#

right

#

ok

astral brook
#

if we can somehow proof that $\frac{\log _2\left(2 \sqrt{10}\right)}{\log _5(40)} = \log _4(5)$ then its a breeze

glossy valveBOT
#

Impractical

onyx glen
#

so $\frac{\log_2(2\sqrt{10})}{\log_5(40)} = \frac{\frac32 + \frac12 \log_2(5)}{1 + 3 \log_5(2)}$

glossy valveBOT
onyx glen
#

let $t := \log_2(5)$ then our expression is $\frac{(3+t)/2}{1 + \frac{3}{t}}$

glossy valveBOT
onyx glen
#

$\frac{\frac12(3+t)}{1 + \frac{3}{t}} = \frac12 \cdot \frac{t}{t+3} \cdot (3+t)$

glossy valveBOT
onyx glen
#

= t/2

#

and $t = \log_2(5)$ therefore $\log_4(5) = \frac12 t$

glossy valveBOT
astral brook
#

okay so what

onyx glen
#

aren't we done

astral brook
#

im kinda confused could u put them in one place

#

Nvm i figured it out

#

Thanks

#

.close

full forumBOT
#
Channel closed

Closed by @astral brook

Use .reopen if this was a mistake.

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

errant stone
#

I want help

full forumBOT
errant stone
#

bro y u pin me 😭😭😭😭😭

#

uhh

#

me became pro now

vast fossil
#

That's how the bot works

#

Just post the question

errant stone
#

I just don't know how to divide

#

help me I don't know how to divide

errant stone
#

u not work bruh

onyx glen
errant stone
#

google gave me false information

onyx glen
#

as in, google gave you some information about division of whole numbers, and you know this information to be false?

errant stone
#

no

onyx glen
#

ok so you're full of shit then

errant stone
#

thx

onyx glen
#

...say, how old are you?

errant stone
#

NO U YOU'LL NEVER GET ME KICKED OUT

#

AM LEAVING THE SERVER

onyx glen
#

bye

errant stone
onyx glen
#

weren't you going to leave the server?

errant stone
#

No

silver pasture
#

damn u just deleted that?

onyx glen
errant stone
silver pasture
#

"mom said i better learn division or else"

#

credit @errant stone

#

🤧

errant stone
#

I just want help from division

silver pasture
#

if u type ".close" and go to khan acad to study

errant stone
#

😭😭😭😭

silver pasture
#

only ask questions here

errant stone
#

ohh ok

silver pasture
errant stone
#

yo how do I use long division like 500 divided by 5

#

that's a question

silver pasture
#

it does not have a mathematical answer so sorry no

errant stone
#

there

spice orchid
#

You google long division and use the numerous resources there

errant stone
#

" You google long division and use the numerous resources there "
My reply: thx me appriciate it

errant stone
silver pasture
spice orchid
#

That's literally what Google does

sterile jungle
#

Lightning Bolt, one sec

onyx glen
#

can we please stop all this

errant stone
#

nahh bro am leaving am scared

sterile jungle
#

I'll just transfer my knowledge to you through telekinesis

onyx glen
#

nobodys keeping you here

sterile jungle
#

You don't need to spend any effort my guy

#

I got you

onyx glen
#

besides you screamed "YOU'LL NEVER GET ME KICKED OUT" when asked about your age

#

kind of suspicious

#

OP is to be presumed underage until further notice

tidal reef
#

that is the most dramatic line i've ever seen

full forumBOT
#

@errant stone Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

flat lion
full forumBOT
flat lion
#

I thought sinxcosx = 2sin2x

#

but they put (1/2)sinxcosx(r^2) = z

raw turret
#

2sinxcosx=sin2x

mortal forum
#

i need help

flat lion
#

oh

#

alright thank you

#

.close

full forumBOT
#
Channel closed

Closed by @flat lion

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

misty harness
#

how is d(df) proportional to $dx^2$?

full forumBOT
glossy valveBOT
#

LichBaw_GT

full forumBOT
#

@misty harness Has your question been resolved?

misty harness
#

.close

full forumBOT
#
Channel closed

Closed by @misty harness

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

raw solar
#

Before I punch this in! Is this correct? Differential equations

raw solar
#

question

#

Accurately, separable differential equations

torn jolt
#

what have you tried?

raw solar
#

Am scared to try cause each incorrect try I lose points and get precisely zero feedback on what went wrong.

#

So I'd prefer feedback here first. I'm greedy, yes.

torn jolt
#

well, since this is assessed I can't help you

#

it's against policy

#

I can give you a hint though

raw solar
#

Sure, a hint would be nice

raw turret
#

Write y’ as dy/dx

#

And rearrange

raw solar
#

but that's what I did

full forumBOT
#

@raw solar Has your question been resolved?

#
Channel closed

Closed by @raw solar

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wooden rover
full forumBOT
wooden rover
#

how do I approach this

static bramble
#

How do you normally find the tangent line at a point?

wooden rover
#

ive kinda forgot but is it something to do with the gradient being negative reciprocal from the centre to the point

static bramble
#

Not quite

#

The tangent line shares the gradient at that point

wooden rover
#

oh

#

idk what I should try and do at first tho

#

the centre is (-2, 2) right

#

oh do i find the gradient to the point

static bramble
#

The tangent line at a point passes through that point, and has the same slope at that point as the parent equation

static bramble
wooden rover
#

i think ive got it

#

ty

#

.close

full forumBOT
#
Channel closed

Closed by @wooden rover

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

prime saffron
#

Hi

full forumBOT
prime saffron
#

I have a question with 4b

#

Why is corner E1 = corner A

#

Wait is it because ABC is similar with ECD

torn jolt
#

angles ADE = EDC

prime saffron
#

And E1 in ECD is similar to A in ABC

prime saffron
#

How do I write that down

#

Wait

#

A sec

torn jolt
#

use the fact that the angles of a triangle add up to 180

prime saffron
#

Yeah I got it

#

I wrote it down like this

#

Triangle ABC is similar with Triangle EDC
Corner C = corner C ( same corner )
Corner D1 = corner B ( 90°)
Therefore corner A = E1 ( angle sum triangle )

#

Is that correct

torn jolt
#

yup

prime saffron
#

Okay

#

Is there any other way of writing down

#

Angle C = Angle C ( same corner )

#

Instead of same corner is there other reasoning

torn jolt
#

no, what've you've said is correct

#

the angles are the same because its the same corner

prime saffron
#

Okay

#

Thanks!

torn jolt
#

yw :D

prime saffron
#

.close

full forumBOT
#
Channel closed

Closed by @prime saffron

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

heavy wagon
full forumBOT
heavy wagon
#

I have done the first part, showing that it satisfies laplaces equation

#

i dont know how to do the second one

#

I am a first year, so i havent done complex analysis yet

#

.clos

#

.close

full forumBOT
#
Channel closed

Closed by @heavy wagon

Use .reopen if this was a mistake.

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ocean copper
#

What is the probability that a regimental student is also in an engineering program?

ocean copper
#

I said 75% someone else working on this problem said 60% we don't have an answer key

#

I arrange this in tree diagram starting with Engineer or non-engineer

wild sleet
#

it's not 75% or 60%

#

suppose there's 100 students

#

means you pick one of 75 at random

ocean copper
#

but we arent picking at random we know the student is in the regiment

wild sleet
#

you are picking at random among those 75

ocean copper
#

ok

wild sleet
#

there are 15 engineers that you couldn't have picked

#

45 engineers that you could have picked

#

they are somewhere in those 75

ocean copper
wild sleet
#

ok, that's 60%

#

i miscalculated

ocean copper
#

So its 60%?

wild sleet
#

yeah

ocean copper
#

how?

wild sleet
#

,calc 0.45/0.75

glossy valveBOT
#

Result:

0.6
ocean copper
#

Im going to fail stats because I can't interpret questions

#

I am passing partial diff eq's and failing stats

ocean copper
wild sleet
#

the other way around

ocean copper
wild sleet
#

P(E given R)
probability that it's an engineer in a world where they are in the regiment

ocean copper
ocean copper
#

.close

full forumBOT
#
Channel closed

Closed by @ocean copper

Use .reopen if this was a mistake.

ocean copper
#

@wild sleet ty

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torn jolt
full forumBOT
torn jolt
#

I'm not sure how do to partial fraction decomposition with square roots. could anyone provide some advice? thanks

#

Partial fractions decomposition?

#

Why

#

its a telescoping series

#

gotta use PFD

#

It is already decomposed

#

i am goofy

#

.close

full forumBOT
#
Channel closed

Closed by @tulip shadow

Use .reopen if this was a mistake.

torn jolt
#

.reopen

full forumBOT
#

torn jolt
#

i still do not really understand this then

#

because each portion of the limit would go to 0

#

so itd be 0 - 0 but that is wrong

#

(infinity)^(-1/2) is 0

#

and (infinity + 1)^(-1/2) is also 0

full forumBOT
#

@torn jolt Has your question been resolved?

full forumBOT
#

@torn jolt Has your question been resolved?

full forumBOT
#

@torn jolt Has your question been resolved?

torn jolt
#

no

full forumBOT
#

@torn jolt Has your question been resolved?

sly cove
glossy valveBOT
#

FLORIDA MAN

sly cove
#

Every term after the first gets canceled by the next

torn jolt
#

.close

full forumBOT
#
Channel closed

Closed by @tulip shadow

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

strong pawn
full forumBOT
strong pawn
#

how to l'hopital rule when its not a fraction? do i just do / 1?

#

no but if i do that it's divide by 0

sly cove
#

$2\sin(7t)\ln(7t) = \frac{2\sin(7t)}{\frac{1}{\ln(7t)}}$

glossy valveBOT
#

FLORIDA MAN

sly cove
full forumBOT
#

@strong pawn Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fickle path
#

help

full forumBOT
fickle path
#

i have to make it so that the line mathches the crack in teh ground

#

i have to make a sinusoidal sunction

#

i just cant get it to be perfect

#

when its matches the middle and left part the right one isnt matched

#

and when i match the middle with the right the left one isnt

#

.close

full forumBOT
#
Channel closed

Closed by @fickle path

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shadow halo
#

tried 13!/4!(13-4)! and tried 13!/(13-4)!

full forumBOT
#

@shadow halo Has your question been resolved?

honest bane
#

bc they're are 6 ways to chose the 1st colour

#

bc repeptitions are permitted then they're still 6 ways to chose the 2nd

#

i think i'm not sure

shadow halo
#

damn !

#

i think you are right

#

at least that gets me to a possible answer

#

but i gotta admit im still not understanding how you got there? like 6 pos. colors but ... head scratch

honest bane
#

my thought process was

#

we have 6 colours

#

and 4 "spots" to fill them with

#

so if i am picking a colour for the 1st spot i have 6 colours to chose from

#

bc repetitions are allowed

#

if am picking a colour for the 2nd spot i have still 6 colours to chose from

#

again i'm not sure if this is correct

shadow halo
#

ok i see the thought process. and its the only option that has given me an answer thats available so im going to run with this !

#

thank you!!

#

.close

full forumBOT
#
Channel closed

Closed by @shadow halo

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mighty bone
#

Can someone explain to me how to do this or least tell me what I am doing wrong.

full forumBOT
#

@mighty bone Has your question been resolved?

mighty bone
#

<@&286206848099549185>

full forumBOT
#

@mighty bone Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torn jolt
full forumBOT
torn jolt
#

this possible?

#

i mean, can i delete the x^2 even though its (2+x^2)?

eager violet
#

No

#

(a + b)/(a + c) ≠ b/c

gritty rose
#

Also don't write integrals in terms of two different variables.

#

Either the whole integral in terms of x or all of it in terms of u

torn jolt
# torn jolt

You should simplify this first by factoring the x inside the square foot

#

Square ROOT

#

Not foot smh autocorrect

eager violet
#

Try writing 3x² + 6 in terms of 2 + x²

torn jolt
#

Well, plus extra steps I guess

full forumBOT
#

@torn jolt Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

eternal solstice
#

If possible, could someone check to see if I did any errors

eternal solstice
#

First time applying Double angle identities and idk if I did this right

full forumBOT
#

@eternal solstice Has your question been resolved?

eternal solstice
#

.close

full forumBOT
#
Channel closed

Closed by @eternal solstice

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torn jolt
#

hello

full forumBOT
#

Please don't occupy multiple help channels.

torn jolt
#

can someone please solve these for me? i’m having a lot of trouble

#

<@&286206848099549185>

#

.skip

#

.close

full forumBOT
#
Channel closed

Closed by @jade sail

Use .reopen if this was a mistake.

full forumBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

steady shuttle
#

The CM ray intersects the parallel planes α and β at points M1 and M2, and the CR ray at points P1 and P2, respectively. It is known that M1P1: M2 P2=2:3. Calculate the length of segment M1M2, if KM1 = 8 cm.

full forumBOT
#

@steady shuttle Has your question been resolved?

full forumBOT
#

@steady shuttle Has your question been resolved?

steady shuttle
#

.close

full forumBOT
#
Channel closed

Closed by @steady shuttle

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gaunt orchid
#

Can someone explain me how to solve questions like “Determine all values of x that have the same given Trigonometry ratio” with cos 225degree?

atomic blade
#

Find coterminal angles

gaunt orchid
#

Usually there will only be one extra value or multiple?

#

Cos 225 coterminal angle is 135

#

Is this the only answer for this

atomic blade
#

There's an infinite number of coterminal angles

full forumBOT
#

@gaunt orchid Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

clear juniper
#

Hey can someone help me with this problem.

solid totem
#

Yousef

solid totem
torpid stag
full forumBOT
#

@clear juniper Has your question been resolved?

clear juniper
#

.close

full forumBOT
#
Channel closed

Closed by @clear juniper

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torn jolt
full forumBOT
torn jolt
#

I don t understand

#

how did he decide to be that t

#

And x

#

And dx

full forumBOT
#

@torn jolt Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

flint geyser
#

Hey, I need to solve the exact values of constant a. How would I go about doing that and have I done right till this point?

full forumBOT
#

@flint geyser Has your question been resolved?

flint geyser
#

What kind of expression do I make next?

old edge
flint geyser
#

the ones with additional constants like a in this case are so hard for me

#

so it says

#

a) Check with applet, with which values of a the function f(x) value at x coordinate -3 is 6
b) Solve the constant a:s exact values

#

applet is just a simple "game" or simulation with x and y axis

#

u don't have to worry about that

flint geyser
#

!close

#

burh

#

I solved it

#

Wasn't easy

#

How do I close this

gritty rose
gritty rose
flint geyser
#

ty

#

.close

full forumBOT
#
Channel closed

Closed by @flint geyser

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sudden nova
#

Does this answer seem right?

full forumBOT
sudden nova
#

of drug users is very low, and hitting a false positive or false negative on them is quite low too, so 99.99... sounds about right - intuitively.

full forumBOT
#

@sudden nova Has your question been resolved?

full forumBOT
#

@sudden nova Has your question been resolved?

full forumBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

signal thorn
full forumBOT
signal thorn
#

where am i going wrong?

tender rain
#

$\frac{1}{x} = \frac{c}{1} - \frac{b}{a}$

signal thorn
#

hmm?

cloud shore
signal thorn
#

i have these as correct answers

deft zodiac
#

how did u

signal thorn
#

im sorry im quite confused

deft zodiac
signal thorn
#

i might mess up stuff but 1/x is -x

#

or do i have a brainfreeze atm

deft zodiac
#

um

#

what step did u take

#

how did u get from the previous to this

halcyon tree
#

I got D

deft zodiac
#

can u not

#

just throw in answers

halcyon tree
#

Huh?

#

Oh

deft zodiac
#

ask them what they did or guide them on how to

halcyon tree
#

Thow the b/a to the other side

deft zodiac
halcyon tree
#

Wait no, D is weong

#

I think

deft zodiac
signal thorn
#

yea i messed up

#

i wanna swap 1/x to x

deft zodiac
#

mhm

#

and what did u do

signal thorn
#

so to make it positive i have to swap other side also

halcyon tree
#

Yes

deft zodiac
#

no

#

uve to do some steps

#

idk what u are doing

signal thorn
#

idk before i was able to solve these for some reason im stuck here again

deft zodiac
#

where did a neg even appear from

halcyon tree
#

U only need 1 step to get x to tbe other side

deft zodiac
#

and what steps are u doing

#

im so confused

halcyon tree
#

Wait, what neg

deft zodiac
#

the person was saying neg x n stuff

halcyon tree
#

Oh

deft zodiac
#

i assumed u understood something

halcyon tree
#

Theg are talking about the c-b/a i think

deft zodiac
#

ive no idea what is being done rn

#

lol

#

just realised thats an a

#

i thought its a q

#

like

#

lol

signal thorn
#

uhm

torn jolt
signal thorn
#

damn i am really stuck now 😂

halcyon tree
#

Right now the equation is

#

1/x = c - b/a

signal thorn
#

yea

halcyon tree
#

And u want to get rid of the x from tbe bottom of the fraction

#

Because that is causi mg problems

signal thorn
#

true

halcyon tree
#

So how do u do that

signal thorn
#

multiply by negative 1?

halcyon tree
#

Try again

#

U multiply something, but not by -1

deft zodiac
#

well

#

um

halcyon tree
#

Btw, if u multiple something on one side, u do the same on tbe other

deft zodiac
#

u can start with like making the 2 fractions 1

halcyon tree
deft zodiac
#

c - b/a

signal thorn
#

c-b/a?

deft zodiac
#

yes

signal thorn
#

okay

halcyon tree
#

Try combining the fractions

signal thorn
#

now i need to flip the nominator and denominator

halcyon tree
#

Try again

#

How do u normally add fractions

#

For example, 1/5 + 3/5

#

What would it be

signal thorn
#

4/5

halcyon tree
#

How about 1/2 + 1/4

signal thorn
#

3/4

halcyon tree
#

Good

deft zodiac
#

um

halcyon tree
#

Now how did u add them

deft zodiac
#

$\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}$

#

oh

#

did texit die

signal thorn
#

think it did

#

well by finding a commen denominator

#

so i have to do the same here

halcyon tree
#

Yes

signal thorn
#

which would be X(a)

halcyon tree
#

Right now u have c/1 - b/a

#

What’s the common denominator of the fractions

signal thorn
#

1(a)

#

?

halcyon tree
#

Yes

#

So what would it become

signal thorn
#

ca - ba idk damn its far on this exercise

halcyon tree
#

Thats incorrect, lets look at it like this

#

Write 1/2 + 1/4 in terms of the denominator 4

signal thorn
#

2/4 + 1/4

halcyon tree
#

So what did u do to the first fraction

signal thorn
#

multiply by 2 to have denominator 4

halcyon tree
#

Yes, the top and bottom

signal thorn
#

so ca/a - b/a

#

?

halcyon tree
#

Yes

signal thorn
#

okay got that part now

halcyon tree
#

So what would the equation so far be

signal thorn
#

we can write is as ca - b/a

#

X = a/ca +b

#

?

halcyon tree
#

(ca- b) / a

signal thorn
#

as we flip the denominator we have to change from neative to positive no?

#

or opposite

halcyon tree
#

Why did h flip it

signal thorn
#

or is it simple as a/ca -b

#

1/x

halcyon tree
#

That is not how h get rid of the fraction 1/x

signal thorn
#

hmm

halcyon tree
#

Just write it in terms of 1/x= …

signal thorn
#

1/x = (ca -b)/a

#

so

halcyon tree
#

Yes

#

We are making progress

#

So, how do u get rid of the x from the denominator

signal thorn
#

multiply by x would give us 1

#

so thats not whats needed

#

1/x is same as x to the negative power 1

halcyon tree
#

If u multiple by x, what would happen on both sides

signal thorn
#

1 = x (ca-b/a)

halcyon tree
#

We are getting closer

#

So how do u make x by itself

signal thorn
#

-x + 1 = (ca-b/a)

halcyon tree
#

Ni

signal thorn
#

im wrong here

halcyon tree
#

X(ca-b/a)Is a fraction

signal thorn
#

oh

#

x multiply by the fraction

halcyon tree
#

Lets make an example

signal thorn
#

sorry for this

#

i feel like once i get this i can move further 🙃

halcyon tree
#

1 = X x B

#

How do u make x the shbject

halcyon tree
signal thorn
#

1/x = b

#

oh no

halcyon tree
#

U made b the subject

signal thorn
#

1/b = x

halcyon tree
#

Yes

#

Its basically the same situation as the equation we have

signal thorn
#

x = -1 (ca-b/a)

halcyon tree
#

No

#

1 = x (ca-b/a)

#

Make x the shbject

#

We said that 1 = xb is the same as 1/b = x

signal thorn
#

1 - (ca-b/a) = x

halcyon tree
#

Try again

signal thorn
#

sorry wrong sign

#

1/(ca-b/a) = x

halcyon tree
#

Yep

#

Now

#

Thing if it like this now

signal thorn
#
  • (ca-b/a)
#

= x

halcyon tree
#

1/1 divided by ca-b/a

halcyon tree
halcyon tree
signal thorn
#

a / ca-b

#

because u multiply the nominator by the denominator from the other fraction

halcyon tree
#

Yes

#

So what would be the final equation be

signal thorn
#

x= a/ca-b

halcyon tree
#

Yes

signal thorn
#

answer A

halcyon tree
#

U got there :D

signal thorn
#

i see now

halcyon tree
#

Oh wait

#

A?

signal thorn
#

C sorry

halcyon tree
#

Yes

signal thorn
#

i didnt learn algebra at school and i am trying to learn it with udemy

#

it comes with struggles

halcyon tree
#

Ic

signal thorn
#

🙃

halcyon tree
#

School definitely gives a bit if a boost with the basics but as u progress, its mostly about your own studies imo

signal thorn
#

i will get there only doing it for 1 month now

#

yea for sure

#

i am trying to reschool myself for a new job

#

which ofc isnt easy

halcyon tree
#

Yea, i could imagine

#

Good luck