help-28

[empty sapphire]

you take the outer - inner

[torn jolt]

14

[empty sapphire]

yep!

[torn jolt]

And that’s 9

[empty sapphire]

since we have 2 sides we need to multiply that by 2

[torn jolt]

So do I add 9

And multiply by 2 (9)

So I do 2(9)

Plus everything else

[empty sapphire]

yep! so we have (outer perim) + (inner perim) + 2(9)

[torn jolt]

Okay

[empty sapphire]

then round to the 2nd decimal place 🙂

[torn jolt]

Wait after this can you still help me

👀

The stress

[empty sapphire]

depends. I'll do what I can. 🙂

[torn jolt]

Okay thanks

Leme get the answer now

Mellow

Would my answer be 96.96

[empty sapphire]

one sec lemme check lol

[torn jolt]

Okay

[empty sapphire]

yep that's what I got too

[torn jolt]

Yes!

Wait it’s wrong

Cries

[empty sapphire]

uhhhh

okay one moment

[torn jolt]

Okay

[empty sapphire]

umm

I guess try 96.95

maybe it was a rounding error

[torn jolt]

It was wrong lol

But the question changed numbers

Lemme quickly send the pikc and do it myself and tell u my answer

[empty sapphire]

oh crap

my bad

I didn't check the simple calculation

25-14 is 11, not 9

[torn jolt]

I..

It’s fine

[empty sapphire]

lol

okay same process

[torn jolt]

Dw

So 113/360x2pix15?

Or 24

Would it be 25 for inner

And 15 for outer

[empty sapphire]

reverse

wait no

24 is outer, 15 is inner

their diff is 24 - 15

[torn jolt]

Ohhhh

Sorry

[empty sapphire]

no worries!

[torn jolt]

I am so tried

Okay so can you give me the substitution equations and I can do them in my calculator with the answer

[empty sapphire]

it's the same as before, just scroll up! lol. But instead of 25 do 24 and instead of 14 do 15 🙂

[torn jolt]

OH

So would I do 113/360x2pix15

Then 113/360x2pix24

[empty sapphire]

very good

[torn jolt]

Then add them together then also add

2(9) since there are two sides

[empty sapphire]

yep! in this case 24 - 15 is indeed 9 lol

yep you got it

[torn jolt]

Lol

[empty sapphire]

I have the answer ready so let me know what you get

[torn jolt]

94.92?

Oh it’s wrong

[empty sapphire]

that's what I got

no way

[torn jolt]

YES

[empty sapphire]

I don't believe you

[torn jolt]

UESSS

it’s right

Okay can u help me some more?

[empty sapphire]

wait what changed? lol

how did it go from wrong to right? 😮

sure I can do 1 more problem

[torn jolt]

I thought I got it wrong

[empty sapphire]

ah

[torn jolt]

Wait

Can you wait for like 20 minutes

And I’ll ping u when I’m ready again

[empty sapphire]

I might not be here

so I reccommend .close this thread

and re-opening

[torn jolt]

Oh

Well wait one second

[empty sapphire]

if I'm around still I"ll look for you 🙂

[torn jolt]

I just wanna say thanks for the help and ik we might never see eachother again but I wish you the best of luck from the bottom of my heart thank you

Wait done accept my friend request just kept it there so incase I ever need your help I can hopefully ask if it doesn’t bother u

?close

How do I close

Lol

[empty sapphire]

sorry I was helping someone else

[torn jolt]

It’s fine

[empty sapphire]

yeah of course, glad I could help!

and you close with .close with the period 🙂

[torn jolt]

Oh

Bye

.close

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[empty sapphire]

bye!!

[torn jolt]

Byeee

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[wraith oriole]

if a 4x4 matrix has a det of -2

[wraith oriole]

what would det 2a be?

[torn jolt]

wait, so det(A) = -2, and you want to know det(2A)?

[wraith oriole]

yea

[torn jolt]

well in general if A is n x n, then

det(p*A) = p^n*det(A)

[wraith oriole]

ohhhhh

i was confused with what n was

but its size of matrix so i get it now

thank you

[wraith oriole]

so if

det A = 3

and

det B = -6

then what is det(AB^-1 A)

so is it 1/-18 * A?

[torn jolt]

first of all

det(A*B) = det(A)*det(B)

and det(A^-1) = 1/det(A)

you want to know

$\det(A \cdot B^{-1} \cdot A)$

[glossy valve]

rbit ✨

[torn jolt]

?

[wraith oriole]

yea thats right

ohhhh

i know how to do it

its b inverse

not ab inverse

so i times 3 by 1/-6

then times by 3 again

last question

B^t?

does that mean if its transposed?

its the same right

[torn jolt]

$\det(A^t) = \det(A)$

[glossy valve]

rbit ✨

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[torn jolt]

hey

[torn jolt]

whats the fastest way

I can solve this

h(x) btw

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[static kite]

is it ok

[full forum]

Please don't occupy multiple help channels.

[stiff musk]

did you try calculating both?

the first one is 17 times 11

the second one is 5 times 3

are those the same?

[static kite]

not exactly..

so you cant destroy them?

[stiff musk]

no, you can't just cancel random factors from a product

you might be thinking of a quotient (division)

moreover, note that 5 isn't actually a factor

it's (5 times 3) plus 2, not 5 times (3 plus 2)

[static kite]

hmm i think its the key answer

what is a factor

[compact mauve]

5 isn't a factor becaasuse there is ssstill a 2 after 5*3

and even if yuo factor you have to takae the 5 out and stilll you canan't caancel

[static kite]

what does factor mean @compact mauve

[compact mauve]

idk the exact defe=inition

I would saya a number that if multiplied by another whole number can get the desired number

but look it up

[static kite]

its hard to understand that description..

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@static kite Has your question been resolved?

[desert elk]

"a number or quantity that when multiplied with another produces a given number or expression "

That is a factor

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[hexed canopy]

i don’t understand nothing

[brittle steeple]

first one use log properties

log(a*b)=log(a)+log(b)

, rotate

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[wicked agate]

.close

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[shy pilot]

I need help with linear programing, specifically finding x and y values, constraints, equations, and just overall helping me understand how to get the hang of it.

[full forum]

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[shy pilot]

<@&286206848099549185>

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[shy pilot]

I need help with linear programing, specifically finding x and y values, constraints, equations, and just overall helping me understand how to get the hang of it.

[shy pilot]

<@&286206848099549185>

.close

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[stray wraith]

What is f(a) + f'(a)*h=c? Is this another formula for f(a)+f'(a)(x-a)? How would I go about solving this

[glass crystal]

this kind of approximation uses the fact that you know the exact value at point a

and you want to compute the value at point a+h

with h somewhat small

so what would h and a be here?

since we already know that h+a= 4pi/13

since h+a is what you want to know about

[stray wraith]

Is a 4pi/13?

[glass crystal]

no

4pi/13 is h+a

[stray wraith]

oh

[glass crystal]

you dont know whats sin(4pi/13) do you

[stray wraith]

nope

[glass crystal]

you have to chose a

close to 4pi/13

but for a value where you know what sin(a) is equal to

[stray wraith]

I have no idea what value would be close to 4pi/13 while at the same time knowing the value'

[glass crystal]

4pi/12

=pi/3

so what is h

the difference between the two points

you should have a+h = 4pi/13

[stray wraith]

so a is 4pi/12 and h is the difference between the two points?

[glass crystal]

yeah

but do you understand what is the approximation we are doing?

[stray wraith]

i'm not exactly sure how it works, for example what would i then do with f(a)? And it says f'(a)*h so how does a+h play a role into that?

[glass crystal]

its the approximation of the tangent

like the tangent is a good approximation of a curve around the point at which the tangent line touches the curve

so we say

if a is this point

f(a+h) ~= T(a+h)

and T(a+h) = f(a)+h*f'(a)

[stray wraith]

I'm sorry for not understanding this at all. Are you able to list the steps I should generally follow to solve a problem like this? For instance, you told me to choose a value for "a" that is close to 4pi/13, I fail to comprehend how to use this information

[glass crystal]

do you see what this means?

[stray wraith]

yes, do i need to solve for tan?

[glass crystal]

no you dont see then

it has nothing to do with tangent the trig funciton

[stray wraith]

oh

[glass crystal]

its this

so since "close to a"

f= Ta roughly

f(a+h) = f(a)+f'(a)*h

roughly aswell

and the smaller h (meaning the closer a+h is to a)

the better the approximation

[stray wraith]

Do I not need to solve for anything then

[glass crystal]

no

you have to understand whats going on

then you apply the approximation

to some a

and some x=a+h close to a

[stray wraith]

So basically f(a+h) is approximately equal to the tangent line which is T(a+h) and the tangent line is equal to the original formula f(a)+f'(a)*h

[glass crystal]

yeah

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[stray wraith]

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[sly kelp]

hello

for this question

why cant we just make the 2ln|7-8| a 0

since ln(1) = 0

for the left side

so at the end it would be 22-2ln(3)

[humble steppe]

You can, but notice that by doing so, your final value will become $$22 + 2\ln 3$$

[glossy valve]

jimmy1234

[sly kelp]

oh

i see

thank u so much

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[stuck vessel]

hi, could someone pls explain what happened here?

[glass crystal]

they put x-y +C on the right side

all the ln

on the left side

using ln rules

they group it under one ln

then they apply exponential on both sides

and they call e^c = c1

[stuck vessel]

is this right?

[glass crystal]

yeah but it was y+3 and x+4

[stuck vessel]

oh yeah that was the example

thanks for the explanation

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[desert moat]

Q.2 please explain

[woven snow]

,rcw

[woven snow]

how many electrons there in Na?

[desert moat]

11

[woven snow]

okay cool

[desert moat]

1s32s32p33s3

Like this right?

[woven snow]

so 1s^3 2s^3 2p^5

no

1 orbitals = 3 electrons

[desert moat]

How 5 in p orbital

[woven snow]

p has 3 orbitals correct?

px py pz

each can have 3 electrons instead of 2

uhh do you get it?

[desert moat]

I didnt understand

[woven snow]

well do you get p has 3 orbitals?

px py pz

[desert moat]

Yes

[woven snow]

good

earlier we could only have 2 electrons each in px py pz

but now we can have 3

so in total now

p can accommodate 9 electrons

correct?

earlier it was 6

because 1 orbital could accommodate only 2 electrons

uhh does it make sense?

[desert moat]

So now p can have 9 elecron right

[woven snow]

yes

,rccw

[woven snow]

so u can have something like this

[desert moat]

If asked then could have 15 electrons?

[woven snow]

uhh?

[desert moat]

D*

[woven snow]

yes

[desert moat]

I mean d subshell could have 15 e-

[woven snow]

yes

because 3*5

[desert moat]

Yes yes i understood

Thankyou

[woven snow]

np

[desert moat]

@woven snow

Is answer for q 20 is correct?

[woven snow]

,rcw

[desert moat]

?

[woven snow]

uhh not sure

its been so long

maybe try chem server in #old-network

[desert moat]

The answer given back is C

Oh okay thankyou

[woven snow]

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[pearl shuttle]

need help for question (iii)

[mossy roost]

5+4(n-1)

[pearl shuttle]

huh?

i need to understand how to do it

bc i have a test tmrw

not the answer

[vernal ice]

Start with the common difference of matchsticks as you add 1 to the shape number

so the sequence goes 5,9,13,17 etc. To find the expression you first have to know the "rate" of increase

[pearl shuttle]

ok

the rate of increase is 4

[vernal ice]

yeah, so that means it's following the same rate of increase as the 4 times table if that makes sense. So you have 4n as the first part of your equation. but if you do 4n you get 4, 8, 12 which is not what the number of matchsticks is, so you have to add or subtract something to get your 5, 9 , 13 etc.

[pearl shuttle]

is there an equation?

is it like finding the nth term?

[vernal ice]

yeah it is

basically finding the nth term

[pearl shuttle]

so its Tn=a+(n-1)(d)

and a is T1

and d is 1st dif

[vernal ice]

yeah that's what the other person did

the alternative way is to find which times table the increase is closest to then add the difference between each term

[pearl shuttle]

but the formula works anyways right?

so the formula that i just said would work for questions that are asking for the nth and n term?

[vernal ice]

yeah it would, but you should probably multiply it out to get 4n+1

just for when you use it later

[pearl shuttle]

what do you mean?

[vernal ice]

as in it's simpler to write it as 4n + 1 instead of 5 + (n-1)4

[pearl shuttle]

how did u get 4n +1

[vernal ice]

multiply out the brackets

5 + 4n - 4

= 4n +1

[pearl shuttle]

bruh this is just confusing me now

if i use the formula

wouldent that be better because when i get to a different type of question i can just use the formula

[vernal ice]

yeah you can use it, but for n^2 sequences it's different. If you ever have to find them then the method i was going to describe is the way to find them

But the formula works for all sequences with n

[pearl shuttle]

i dont think i have n2 sequences on this test

ngl

🙂

[vernal ice]

well then i guess you can just use the formula

[vernal ice]

yeah the formula works but it's always good to know the other way for later on

like for the sequence in a(iii)
common difference is 2, so nth term is 2n
but there's a difference of -7 between 2n and -5,-3,-1,1 etc.

so the nth term equation is 2n - 7

which you could've done doing the formula:
a = -5, d = 2
-5 + (n-1)2 is the same as 2n - 7

[pearl shuttle]

ok

i think he wants us to write down the formual

formula

so we earn extra marks

bc if u have formul correct and ans wrong still get marks

for knowing how to do the question

[vernal ice]

yeah i think for your exam now use the formula, for later learn this way since it's pretty useful for the n^2 sequences

[pearl shuttle]

ok

moving to the n2 sequences now

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[dense saffron]

A is a matrix, b and c are real numbers, I is the identity matrix
Assume A^2 = bI + cA. Find a formula for A^-1
can someone give me some hint how to solve it?

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[dense saffron]

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[main monolith]

What do you call this kind of equation?

[spice orchid]

you could call it a "trigonometric identity"

[main monolith]

is that a generalization or would i only find stuff that would look like the picture

im only asking cause im lacking on my math class i dont mean to be mean lol

[spice orchid]

its not a generalization, trig identities are equations involving trig functions that are true for any x

this specific equation at the top is the "pythagorean trig identity" and then each equation below is another identity that is a consequence of the first

[main monolith]

Ah I see

[spice orchid]

trig identity/ trig equation will cover everything

[main monolith]

Thank you

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[wild lantern]

I thought I understood the product rule. I had this question on my WebAssign:

https://i.gyazo.com/85d9dd3caafdcea8cba6ab5af623eef8.png

[wild lantern]

So, This looks like f(x) * g(x). But I got the correct answer using the product rule and by multiplying out first and taking the derivative. So, my question is: How do I know when I need to use the power rule?

[buoyant tinsel]

You can use either for this question, if it's possible and more convenient to use power rule, then you should use it. Provided that the question doesn't explicitly say "use the product rule" like it does here

[wild lantern]

How will I know when I run into a problem where I MUST use the product rule over the power rule?

[full marsh]

If you have some multiplication between 2 functions that you can't "expand"

not all functions are polynomials

[wild lantern]

so if I needed to take the derivative of somthing like Sin(x) * Cos(x), since I cant expand it, I would need to use the product rule?

[full marsh]

Yes, you would

Well in this case there is a different way

$\sin(x)\cos(x) = \frac{1}{2}\sin(2x)$

[glossy valve]

RedstonePlayz09

[full marsh]

And you could use the chain rule here

But that's not the point

When you have multiplication, it's probably best to use the product rule.

Since expanding things out can be harder.

[wild lantern]

I see, thank you for the explanation!

[full marsh]

No problem!

[wild lantern]

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[rancid notch]

How do you find the nth term of a fraction

[full marsh]

1/(n+1)?

[gritty rose]

what do the rows below the harmonic sequence mean?

different problems?

[rancid notch]

Shit I rubbed them out, I multiplied by 6 then by 4 to get whole numbers

[rancid notch]

Yo howd u figure that out

Just common sense?

[full marsh]

Yeah.

[rancid notch]

Aw bruh

[gritty rose]

it helps to find patterns for numerator and denominator separately

numerator: 1,1,1,1,1

[rancid notch]

Yea

And then

[gritty rose]

.

[rancid notch]

Ah well now that I’ve seen the answer I can’t unsee it and it makes sense

Thanks tho .close

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[eternal portal]

i don’t understand exactly the steps to get to the answer. can someone simplify what they’re trying to tell me to do?

[eternal portal]

i just need help for C btw

[full marsh]

Isolate x from y = 6x + 11

Or..

Are they asking for a different function?

[eternal portal]

oh wait i got it

thank u

it’s the first option u said

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[sharp torrent]

What is the derivative of e^(-x) . im confused on how to get there, ik that the derivative of e^(x) = e^(x), but does the same result work for -x?

[full marsh]

Chain rule

[sharp torrent]

how do i apply the chain rule if theres only this function, dont I need two functions to do that?

[full marsh]

It's the function e^x

When plugging in -x

[sharp torrent]

wait so is f(x) = -x and g(x) = e^x?

[full marsh]

Another way (but more complicated) is to write 1/e^x instead of e^(-x) and use quotient rule.

[full marsh]

Yes, and find the derivative of g(f(x))

[sharp torrent]

ah okay, thanks

[full marsh]

No problem!

[sharp vine]

find 3 divisors and that's it

[teal kindle]

#❓how-to-get-help

anyways, it's even so you know it's divisible by 2

[sharp vine]

two divisors are 1 and 23 452

no, because there are also other numbers that divide it

these two divisors (1 and number itself) divide any number

[teal kindle]

look up what it means to be prime, I think that would help more

[sharp vine]

2 is even and it's prime, but this is only one case like that

that's true

I guess it represents divisors of the number, I'd rather just write it in words

generally, we say that number is composite, you can use this term

I don't think you should do it that way, just write
23 452 isn't a prime number since it has more than two divisors
it follows from the definition

[full forum]

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[umbral solar]

it should be -44 right?

ping me if you're gonna answer me bc ill be in another tab

[hot herald]

@umbral solar show work

[umbral solar]

there is no work

[hot herald]

then no

[umbral solar]

?

no like

if f(-2)=-11, then the remainder when divided by (x+2) is -11

same goes for f(1), (x-4)

so if you divide by both of them

remainder is -44

right?

[hot herald]

no

[umbral solar]

huh

4x-11

[hot herald]

don't attempt shortcuts and/or make assumptions because they feel easy

follow remainder theorem

[umbral solar]

i did

if f(-2)=-11

then f(x)/(x+2)=-11

[hot herald]

apply remainder theorem for dividing by a polynomial

what's will be the form of the remainder when dividing by a quadratic

[umbral solar]

it didnt specify tho

it says polynomial

[hot herald]

yeh

generally when you divide a polynomial by a quadratic polynomial,
why kind of remainder would you expect?

[umbral solar]

idrk, its not in our curriculum, im just checking a higher level of remainder theorem and factor theorem questions online

cubic function divided by a linear factor to get quadratic factor is as far as we go

[hot herald]

have you done polynomial long division before?

[umbral solar]

yeah

[hot herald]

when do you stop the division iterations/algorithm when doing that

[umbral solar]

when i subtract under the division and i end up w 0

[hot herald]

what if the divisor isn't a factor

[umbral solar]

not in our curriculum, idk tbh

[hot herald]

(and you'll never end up with 0)

[umbral solar]

hmmm

[hot herald]

well you won't really realise whether you'll end up with a reminder of 0 until you actually do it right?

the idea is knowing when to stop

[umbral solar]

so remainder of dividing by (x+2)(x-1) is a linear expression?

[hot herald]

yes

generally when dividing by a quadratic the remainder will be at most linear

[umbral solar]

sooo

f(x)/(x^2+x-2)= px+q?

[hot herald]

no

this is one of the quotient remainder forms:
$$f(x) = Q(x)D(x)+ R(x)$$

[glossy valve]

ℝamonov

[hot herald]

$$f(x) = Q(x)(x+2)(x-1)+ \underbrace{ax + b}_{R(x)}$$

[glossy valve]

ℝamonov

[umbral solar]

hmm

is there like

a simultaneous equation for ax+b

[hot herald]

yes

[umbral solar]

our only given is

wait

when x=-2

Q(x)D(x) is 0

so ax+b=-11

[hot herald]

yes

no

[umbral solar]

and when x=1

huh

[hot herald]

you didn't sub your value into the x in ax

[umbral solar]

OH

[hot herald]

a * -2 + b = -11

[umbral solar]

yeah sorry mb

and also

a+b=4

[hot herald]

yes

[umbral solar]

easy simultaneous equation

1 sec

lemme solve

a=3

b=-5

[hot herald]

nope

3-5 isn't 4

[umbral solar]

oh lmao

OH OOPS

a=5

for some reason my brain went 15/3=3

b=-1

[hot herald]

yes

[umbral solar]

so when divided by (x^2+x-2)

x=-2*1

which is -2

wait

im noit sure

[hot herald]

you're overthinking

note that the remainder was at most linear and expressed as
ax + b
right?

[umbral solar]

mhm

[hot herald]

and you've determined the values of a and b

[umbral solar]

yeah

[hot herald]

so just chuck those values of a and b into ax + b and that's it

[umbral solar]

5x-1?

[hot herald]

yes

[umbral solar]

that's the remainder?

[hot herald]

yes

[umbral solar]

YO I THINK I UNDERSTAND

tysm for ur tim

time

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[whole thicket]

for part b) would normal distribution be appropiate for this problem

[whole thicket]

also if anyone can explain to me the difference between binomail and normal distribution, i would appreciate it

[sweet ingot]

you are likely given a rule for when you can use normal distribution approximation for binomial

and they aren't similar at all? One is discrete the other is continious for one

[whole thicket]

I see. The only thing i understand from it is binomial works for any finite value, while normal works for infinite values. So does that mean binomial problem must show a given number? Also for normal distribution if we're not given a mean or standard deviation, we can assume its 0 and 1?

[whole thicket]

So for part b), it would not be approiate to use normal distribution then?

[full forum]

@whole thicket Has your question been resolved?

[sweet ingot]

what?

[sweet ingot]

where did I say that?

[whole thicket]

isn't binomial used for finite vlues and normal used for infinite values

[whole thicket]

oh no I was just asking if that is correct or not?

[sweet ingot]

Wdym finite values and infinite values?

[sweet ingot]

Try checking what c) is asking should give you a clue what the answer for b) is

[sweet ingot]

But this

[whole thicket]

ok

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[silent idol]

How do i go about solving this?

[silent idol]

I was going to substitute x for 2

but once they brought up the fractions I just couldn't

[misty topaz]

start by factoring out the partsw

[silent idol]

with x = 2?

[misty topaz]

where did the 2 come from

[silent idol]

^

[misty topaz]

you dont need to subsitue

subsitute

[silent idol]

thats how i did it before

just the fractions confuse me

[misty topaz]

for that one you could have just foiled

[silent idol]

I just used the way my teacher showed us

[misty topaz]

your teacher showed you a weird way lol

[silent idol]

lmao ig

this is SAT Prep

he said this way is quicker

[misty topaz]

with the sat you need to go fast yeah?

[silent idol]

Yes

[misty topaz]

This method is way faster

[silent idol]

Is that foiling?

[misty topaz]

yeah, where you multiply the first term in the first part, by both terms in the second part

[silent idol]

so 7n * n and 7n * 4

[misty topaz]

Yeah

[silent idol]

Final answer being 5n+20?

[misty topaz]

nah, you add those two parts together

[silent idol]

Where did that 33n come from

[misty topaz]

28n+5n

[silent idol]

oh

Ah

I see

That is much quicker indeed

[misty topaz]

https://www.youtube.com/watch?v=nyk3UGwCAms&ab_channel=TheOrganicChemistryTutor

here is a video you can watch to solidify it

back to the original question

you can factor out an x

[silent idol]

But some times plugging in a 0 is much quicker too

but not always the best solution

[misty topaz]

sometimes, but honestly it is better to have 1 method than having to decide which to use each time

[silent idol]

Your right

[misty topaz]

turning $\frac{3x^3+2x^2+4x}{10x^3}$

[glossy valve]

InfinityMango

[misty topaz]

into $\frac{x(3x^2+2x+4)}{10x^3}$

[glossy valve]

InfinityMango

[silent idol]

Confused

[misty topaz]

then you can divide it into $\frac{(3x^2+2x+4)}{10x^2}$

[glossy valve]

InfinityMango

[misty topaz]

about what part

[silent idol]

ohhh

sorry I was confused with ur wording for the bot lmao

this is my first time here

didnt know that was for me

[misty topaz]

yeah, look at the bots post lol

https://wysc.us.to/docs/assets/texit_cheatsheet_1.pdf here is a cheatsheet if you want to learn how to use the bot

[silent idol]

Why did you add that x on the outside?

[misty topaz]

if there is a x in every term in the polynomial

you can factor out an x

the same way that if there is a multiple of 2 in every term, you can factor out the 2

https://www.youtube.com/watch?v=U6FndtdgpcA&ab_channel=TheOrganicChemistryTutor

here is another video to watch

but next you can turn it into $\frac{3x^2}{10x^2}+\frac{2x}{10x^2}+\frac{4}{10x^2}$

[glossy valve]

InfinityMango

[misty topaz]

then you can cancel out the xs

to get $\frac{3}{10}+\frac{2}{10x}+\frac{4}{10x^2}$

[glossy valve]

InfinityMango

[misty topaz]

then you can divide the constants

[silent idol]

I got that exact thing doing something else

[misty topaz]

to get $\frac{3}{10}+\frac{1}{5x}+\frac{2}{5x^2}$

[glossy valve]

InfinityMango

[misty topaz]

and that should be your final answer

watch the videos about factoring and foiling

you will use those methods forever in math

[silent idol]

Im confused how you went from this

[silent idol]

to this

[misty topaz]

2/10 is the same as 1/5th right?

[silent idol]

Yes

[misty topaz]

and 4/10 is the same as 2/5ths

if you are multiplying the terms, you can divide like that

[silent idol]

oh you just simplified

[misty topaz]

yeah

[silent idol]

Got it

hold on let me try it my self now

[misty topaz]

fs

[silent idol]

ok I'm stuck on this one

[misty topaz]

when dividing exponents

x/x^3

is the same as $\frac{x}{xxx}$

[glossy valve]

InfinityMango

[misty topaz]

and you can cancel out an x on the top and an x on the bottom

giving you $\frac{1}{x*x}$

[glossy valve]

InfinityMango

[misty topaz]

or $\frac{1}{x^2}$

[glossy valve]

InfinityMango

[silent idol]

ah

I see

[misty topaz]

so a more general equation is $\frac{x^n}{x^m}=x^{n-m}$

[glossy valve]

InfinityMango

[silent idol]

Sorry for the sloppy hand writing its hard drawing with a mouse 😭

But

I think I get it

its much easier than the method my teacher showed

[misty topaz]

yup, just review algebra basics

[silent idol]

its been a while

Im assuming I can apply the same logic to this?

[misty topaz]

yeah

[silent idol]

Alright, let me attempt it rq

I cant factor away a p

since the denominator doesn't have an exponent

[misty topaz]

you can factor a 3 though

[silent idol]

wym?

[misty topaz]

from the top and bottom

[silent idol]

oh

how would that look?

lemme try this bot rq lol

[misty topaz]

3p^5-24p^4+21p^3-9p+3

$3(p^5−8p^4+7p^3−3p+1)$

[glossy valve]

InfinityMango

[silent idol]

so this $\frac{3p^5-24p^4+21p^3-9p+3}{3p+3}$

[glossy valve]

Keif

[misty topaz]

for this one you will need to use polynomial division though

[silent idol]

into

$\frac{3p^5-24p^4+21p^3-9p}{3p}$

[glossy valve]

Keif

[silent idol]

?

[misty topaz]

https://www.youtube.com/watch?v=_FSXJmESFmQ&ab_channel=TheOrganicChemistryTutor

watch this video

[silent idol]

god I despise math

[silent idol]

alr

hold on

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[silent idol]

.reopen

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✅

[misty topaz]

?

[silent idol]

Alr I think I got it down

i have no clue how ima preform that question fast on the SAT

[misty topaz]

hopefuly not too many show up lol

[silent idol]

is this possible on a graphing calculator

[misty topaz]

depends on the calculator

I know the TI nspire cas can do it, but I dont know if you can use it on the sat

[vocal monolith]

polynomial long divi gets super easy thru practice

just do a ton of prac and you'll be able to do it really fast

also tip if its linear divisor just use synthetic

its a lot faster

[silent idol]

oh ye they limit you

[silent idol]

?

[vocal monolith]

do you know what synthetic division is?

[misty topaz]

https://www.youtube.com/watch?v=FxHWoUOq2iQ&ab_channel=TheOrganicChemistryTutor

[vocal monolith]

its significantly faster if the divisor is linear

[misty topaz]

kinda confusing ngl, but, good luck

[vocal monolith]

im pre sure u can do it even if its not but normal poly division would be easier

[silent idol]

haha

i'll be good

[silent idol]

faster but more complicated?

[vocal monolith]

no

if its linear

synthetic is so fast and so easy

[silent idol]

wym if its linear

how do I tell

[vocal monolith]

for example

if the divisor is

(x-2)

thats linear

if its (2x+1) it aint linear anymore

u can still use synthetic division even if its not linear but its more complicated than just doing it with long division]

[silent idol]

ah

[vocal monolith]

ye

also if ur doing sat

some graphing calcs arent allowed

so go thru the official list

[silent idol]

i looked it up

[vocal monolith]

ur exact model?

[vocal monolith]

ye

if ur model is there then u can use it

but yeah synth div >>>>> when divisor is linear

if its not linear

long div >>>>> synth

[silent idol]

so its better if I learn both

[vocal monolith]

definitely worth ur time

i mean synth is simple anyways

pretty much all u do is

grab the opposite sign of ur factor

and then write the coefficients of ur polynomial

ok yknow what i'll do an example qusetion on paint

and ill show u

[silent idol]

The video shows it pretty simple

[vocal monolith]

ye

takes like 10 seconds

it works with multiple factors too

[silent idol]

You write much neater with a mouse than i can

[vocal monolith]

lol ty

[silent idol]

ima save this

for future refernce

[vocal monolith]

ye just remember

multiply and then add to next

and btwe

the last number is remainder

so if its 0 that means the divisor is a factor

also make sure the divisors sign is opposite from factor

so if its (x-1)

divide by 1

not -1

:)

[silent idol]

I have a lot to learn

[vocal monolith]

dw man im here with u

im doing it rn too but the hardest for me rn is finite differences

[silent idol]

Ive just recently started preparing for the SAT

[vocal monolith]

ah

u in 12th grade? or

wait actually i prob shouldnt ask that its prob against rules right

[silent idol]

I havent taken an algebra course since covid times, and that was online too

[vocal monolith]

ah

[silent idol]

nah its not, I'm in 11th

[vocal monolith]

oh damn

[silent idol]

u?

[vocal monolith]

good on u for preparing

im in 12th rn

[silent idol]

I see

[vocal monolith]

im so ass at math

[silent idol]

Better than me

[vocal monolith]

nah ur already doing better than me

i did nothing the past 2 years LOL

so now im catching up with everything

[silent idol]

Smart

I took an SAT prep course

my school offered it

[vocal monolith]

o damn

nice

[silent idol]

But this math is killing me

[vocal monolith]

im so screwed man

gotta apply for uni soon

gotta grind before it happens

[silent idol]

hold on lets take this somewhere else

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[vocal monolith]

ye

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[cosmic shoal]

how do i set limits

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@cosmic shoal Has your question been resolved?

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[cosmic shoal]

.REOPEN

.reopen

[full forum]

✅

[cosmic shoal]

<@&286206848099549185>

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@cosmic shoal Has your question been resolved?

[full forum]

@cosmic shoal Has your question been resolved?

[cosmic shoal]

<@&286206848099549185>

no body can help 😦

<@&286206848099549185>

[cosmic shoal]

.close

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[runic bloom]

I did the whole problem again and still get the same answer

where did I go wrong?

oh forgot to send this

[dull void]

I honestly don't see what you did wrong either maybe I'm braindead

[runic bloom]

I even used desmos and it seems right..?

at this point I may have misread the problem or something

but how..

[dull void]

I mean idk do you know what the intended answer was?

[runic bloom]

no

[dull void]

talk to your prof

cuz ur answer seems right to me

[runic bloom]

hmm okay thanks

<@&286206848099549185>

I’ll keep this open a bit longer in case anyone finds something

perhaps my teacher misgraded

but like that’s a major messup lol..

so many points docked for nothing

[gritty rose]

,calc (4^2 -3(4))/(4*sqrt(4^2-4))/4

[glossy valve]

Result:

0.072168783648703

[gritty rose]

,calc 1/(8sqrt(3))

[glossy valve]

Result:

0.072168783648703

[gritty rose]

Looks right

[runic bloom]

👍 thanks

now my teacher has to prove lems, riemann, and a literal calculator all wrong to be able to dock these points

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[spare basin]

Prove that permiter of a triangle is constant its area is max when it is equilateral

[woven snow]

use herons

and am-gm

am gm my beloved

[full forum]

@spare basin Has your question been resolved?

[spare basin]

@full forum no

[spare basin]

Have too use Lagrange

[woven snow]

well for lagrange you can use f(x) = (s-a)(s-b)(s-c) with constraints a+b+c=0 ig

but i’m not much used to lagrange, maybe wait for someone else to comment

[spare basin]

@woven snow , yes

[woven snow]

okay perhaps a+b+c =1

not 0

[spare basin]

You are write

But iam also not having a proper knowledge

So I need a full solution

[woven snow]

full solution is too much to ask, have you been taught lagarange’s multipliers?

[spare basin]

Some but

Not properly

Are teacher not so good

I know the basics of Lagrange

But

[woven snow]

some are ig, maybe try khan academy?

[spare basin]

Yes

[woven snow]

https://youtube.com/playlist?list=PLCg2-CTYVrQvNGLbd-FN70UxWZSeKP4wV

[spare basin]

Thanks

[woven snow]

[spare basin]

Are you insta

[woven snow]

uhh?

i’m deep

[spare basin]

Yes

You are

[glass crystal]

[woven snow]

do you mean am i on instagram?

[spare basin]

Yes

[woven snow]

no

[spare basin]

Oh

Want to deep

Want to know deep

Interesting bit

[woven snow]

u can just ask wolfram ig

,w deep

[glossy valve]

Results provided by WolframAlpha

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Requested by Deep.#0001

[woven snow]

huh

[glass crystal]

45 yo uh

on discord

didnt expect that

[spare basin]

Yes really

[woven snow]

insta cringe

[spare basin]

Hey truely not

You have use it first

[woven snow]

and cringe it later

anyways u should probably close this

[brittle steeple]

Your tag is 0001?????

have we been over this

I feel like someone's was 0025

And they were bragging about it

[woven snow]

whom are u speaking to?

[brittle steeple]

You

[woven snow]

0001 is thru power of nitro

[brittle steeple]

Oh