help-28

[willow bloom]

Thank you very much!

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[inner gull]

The options are :

can someone pls guide me through this question?

[knotty coral]

okay

so lets say the first bead was colored red

[inner gull]

then the second bead can only be colored yellow or blue?

[knotty coral]

the next bead must be either yellor or blue bc the adjacent color can't be the same

[knotty coral]

yes

so 2 is ur answer

[inner gull]

ohhh, so this is also the same for if the first bead was colored blue or yellow?

[knotty coral]

yup

just take a random example and go from there

thats the way i usually handle these problems

[inner gull]

oh, oki, Thanks

[knotty coral]

np

[inner gull]

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[weak blaze]

what's the exact formula?

[smoky wing]

Approximate by normal

You can find mean and variance using the formula np and npq

[weak blaze]

how do you do that

[smoky wing]

https://youtu.be/k9nRcadQYsU

Useful to look at

[weak blaze]

damn i forgot that meant that

thx i think i get how to do it

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[charred coral]

Can someone show me a worked solution to this please

[charred coral]

<@&286206848099549185>

[humble steppe]

Notice that $$\int_0^{2a} = \int_0^a + \int_a^{2a}$$, and $$\int_0^{-a} = -\int_0^a$$, for even functions.

[glossy valve]

jimmy1234

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@charred coral Has your question been resolved?

[charred coral]

Ah right thank you

What’s the significance of the 3 in front of the f(x)?

How does that work when adding integrals together, can I just take it out of the integral?

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@charred coral Has your question been resolved?

[charred coral]

<@&286206848099549185>

[charred coral]

elp

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[raven remnant]

help me : f ( f(x)) = f(x) + 2x

[raven remnant]

i found f(x) = -x and f(x) = 2x easily by subtituting f(x) =ax+b but i cant prove thatis the only functions

f(x)is continous

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[lime sand]

,help

[glossy valve]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

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Please don't occupy multiple help channels.

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[waxen whale]

Hi, so I'm not quite understanding when to use integration by parts vs tabular (DI) integration

[waxen whale]

Why can't we just use tabular all the time?

It seems so much easier than doing it by parts..

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[rain vapor]

Can someone explain this to me in detail? i have no idea what to do here.

[slate compass]

O

[clear canyon]

xy+xz=100, x(y + z) = 100
x(3y + 3z) = 300
x/5*(3y+3z) = 60
x/5*(3y+3z) + 10 = 70

[rain vapor]

What are we trying to do here?

like turn the first equation into the second?

[deep flint]

yes, basically

[fresh wren]

yea

[rain vapor]

What is the connection between the 2 equations tho?

[fresh wren]

multiply the first by 3

[deep flint]

it's just algebraic manipulations

[fresh wren]

factor x

divide 5

add 10

[deep flint]

meh, finger slipped, sent before i was done typing

you can also start with the second expression and go backwards untol you get to the first

[rain vapor]

How to know what to multiply or divide in the numbers with?

[subtle edge]

by looking at the equations

[rain vapor]

ok

I think i get it now

thank you guys very much

have a great day

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[torn jolt]

How does $$\frac{d.dt}(t^8(t^4+1)^4) $$not equal t^8(16t^3(t^4+1)^3+(t^4+1)^4(8t^7)

[torn jolt]

I did that wrong?

[clear lily]

$\frac{d}{dt}(t^8(t^4+1)^4) \neq t^8(16t^3(t^4+1)^3+(t^4+1)^4(8t^7)$

[torn jolt]

oh i did my frac wrong

[clear lily]

$\frac{d}{dt}(t^8(t^4+1)^4)$

what the hell

[torn jolt]

How are those not equal is what I am trying to ask.

Because first you apply the multiplication rule.

and then for

you have to use the chain rule.

which would make the derivative of that

because it is

[fast peak]

well you misplaced a bracket

there should be a bracket after (t^4+1)^3

[torn jolt]

oh yeah i see

[torn jolt]

Correction to this

Anyways I don't follow how my math is wrong.

[fast peak]

are you sure that it is?

[torn jolt]

this is the first step (i did on my own but am taking a picture from somewhere else)

the derivative of t^8 is 8t^7

and the derativative of

is

So yeah, I feel pretty confident overall. To me this seems like an easy multiplication and chain rule problem.

and the answer provided doesn't have any addition in it which further confuses me.

[fast peak]

well you can factor out some stuff

the 8t^7 and (t^4+1)^3

[torn jolt]

as in I should multiply those?

because they have different powers.

oh

or

I could factor out (t^4+1)^3

and t^7 could be factored out

and then i guess some things could be multiplied in

and then added together

and then further multiplied out

Oh

Thats the answer

I am sorry for taking your time, thank you @fast peak.

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[fast peak]

dw about it

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[zenith pecan]

What would be the eigenvectors here?

[zenith pecan]

Its a weird matrix right? 1 row of 2 and a row of 1?

[onyx glen]

$M = \bmqty{0.5 & 0 \ 0 & 2}$

[glossy valve]

Ann

[onyx glen]

but also, with a list like this, it is easy to tell which of these vectors are eigenvectors or not

just compute Mv for each v in the list and see if you get back a scalar multiple of v...

[zenith pecan]

hmm, but shouldnt the question then be posed with [[0.5,0.0],[0.0,0.2]]

Is it a mistake in the question?

Oh sorry, I am reading it wrong

[onyx glen]

...i just retyped the matrix in a more familiar format, but go off

[zenith pecan]

Yeah I just misread the question

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[karmic silo]

What is the coordinate of l and m

[proud willow]

don’t need to actually find the coordinates

it isn’t in the question

[torn jolt]

I guess he'll use it for solving it in his way.

[proud willow]

you can use m1m2 = -1

[karmic silo]

So can u guys write the equation of al and bm that would help me a lot

[proud willow]

did you answer the part I

[karmic silo]

Yes

[proud willow]

what was the answer

[karmic silo]

-3

[proud willow]

okay

that’s the gradient of BC yes

AL is perpendicular to bc

and since perpendicular

if you multiply gradient of AL and gradient BC you get -1

so AL x -3 = -1

what is AL

[karmic silo]

1/3

[proud willow]

yes

that is gradient of AL

[karmic silo]

So whats the equation

[proud willow]

so now you know $y= \frac{1}{3}x + c$

[glossy valve]

duckiescute!

[karmic silo]

Yes

[proud willow]

how would you solve for c

[karmic silo]

3y -x = 3c ?

[proud willow]

okay sure yes

but how to find c

[karmic silo]

hmm idk

[proud willow]

okay

we need to plug a coordinate that is on AL

what coordinate do we know that is on AL

[karmic silo]

A (-2,1)

[proud willow]

yes

plug that inside

and solve for c

[karmic silo]

Whats the formula

[proud willow]

no formula

[proud willow]

what is the x coordinate of A

[karmic silo]

-2

[proud willow]

and what is y coordinate of A

[karmic silo]

1

[proud willow]

yes so plug in x = -2 and y=1 herw

and find c

[karmic silo]

C= 5/3

[proud willow]

okay

so now the equation is

what is it

[karmic silo]

idk

[proud willow]

look here

this is the equation of AL

now that we found c

plug c inside and that’s our equation

[karmic silo]

Y = 1/3x + 5/3 ?

[proud willow]

yes

[karmic silo]

But how will that give us the coordinate of l

[proud willow]

no need

they don’t want coordinates of l

they want equation of AL

[karmic silo]

answer is x-3y+5 = 0

[proud willow]

yea

same thing

you can write it this way or my way

[karmic silo]

So what is x and y of l just curious

[proud willow]

they are coordinates

so any point on line AL

[karmic silo]

its 4,3 but its impossible

[proud willow]

what do you mean 4,3?

[karmic silo]

x for 4 y for 3

[proud willow]

is 4,3 on AL

[karmic silo]

its the coordinate of l

[proud willow]

how

did you find that

question doesn’t want you to find coordinates of L

[karmic silo]

x-3y = -5 substitute x for 4 and y for 3

But the problem is its impossible for x to be 4

[proud willow]

^

and also

how did you find L

[karmic silo]

Yes i know that but x cant be 4

i just subsituted

[proud willow]

that means you found L wrongly

[karmic silo]

Can u find l plsss

[proud willow]

but why

you don’t need to hahaha

[karmic silo]

im very curious

[proud willow]

solve simultaneous

[karmic silo]

The question is false if its x 4

[proud willow]

let L(p,q)

plug into eqn of BC

and eqn AL

and solve simultaneous

for coordinates of L

[karmic silo]

Thanks a lot

i was being so dumb

[proud willow]

no prob!

[proud willow]

hahha noo it happens don’t wry

did you get L

coordinates

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[bitter stone]

Negate the following propositions, pushing the negation past all quantifiers (∀, ∃) and logical
connectives (“and”, “or”, ”implies”), and determine which of the original or negated proposition is
true, with a short explanation.

[bitter stone]

Do my answers make sense?

[ivory cairn]

no

the negation $\forall x\in \mathbb R$ is $\exists x\in \mathbb R$

[glossy valve]

Zybikron

[bitter stone]

read direction

it says to push past quatifiers in R

[ivory cairn]

yeah

the negation of 'for all x in R' is 'there exists x in R' not 'for all x not in R'

[bitter stone]

So

ok

pushing past means

like change those?

[ivory cairn]

yes

otherwise 'negate the statements $\forall x\in A, \exists y\in B, P(x,y)$' could be written as $\neg(\forall x\in A, \exists y\in B, P(x,y))$ and be technically correct

[glossy valve]

Zybikron

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[warm vale]

This is just part of a larger question but i have to integrate 1/(v^2 + 1) and I got -2v/(v^2 + 1)^2 +c but on the answer booklet it says arctan + c and I am confused. what is arctan and am i wrong?

[warm vale]

excuse my awful handwriting

[next sail]

you're wrong, yes

you differentiated, you didn't integrate it looks like

@warm vale

try integrating instead

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@warm vale Has your question been resolved?

[warm vale]

thats my bad thanks.
Still confused on what arctan is and why intergrating that gets arctan

hmm, i watched this [https://www.youtube.com/watch?v=b7kePAuqU3I] video on it and i get what arctan is now. I dont understand why you decide to make x=tan(u) specifically; why not x=cos(u)?

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[zenith sequoia]

no clue what this is asking tbh

[fast peak]

chain rule

g(x) = h(3x^2+4x)

what is g'(x) ?

[zenith sequoia]

so h'(x)(6x+4)

[fast peak]

yes

[zenith sequoia]

thanks

weird cuz this wasnt chain rule section it was first derivative test

so idk how that coorelated

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[fast peak]

well still the question screams chain rule

dont rely on sections to tell you what to do

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[vestal crescent]

Tor, Tom and Georg will share a pizza. Thor eats 35% of the pizza, and Tom eats 2/5. how much does georg get?

[fallow widget]

what have you done so far?

[vestal crescent]

i literally dont know where to start, i suck at math. 1st reason why im here

[fallow widget]

ok so do you know how to transform from % to fraction?

[vestal crescent]

nope

how?

[fallow widget]

$\frac{number}{HowManyDigitsHasTheNumber+0}$

[glossy valve]

Hero472

[fallow widget]

you can search on google, a lot of people on youtube explain that

[vestal crescent]

okay

[fallow widget]

so the 35% = 35/100

[vestal crescent]

yea

[fallow widget]

you know why?

[vestal crescent]

bc prerecentagr is out of 100

and he ate 35% of the pizza

[fallow widget]

ok so if one person eats 35/100 and another 2/5

how many pizza is left?

[vestal crescent]

u see

[fallow widget]

you can simplify 35/100 i recommend to do it

[vestal crescent]

i dont know

😭😭

what simplify mean? english not my first language

[fallow widget]

35/100 to the simplest fraction

[fallow widget]

which is?

[vestal crescent]

which is what

[fallow widget]

youre native language? i speak spanish btw

[vestal crescent]

norwegian

i dont speak spanish

[fallow widget]

ok

so back to the exercise

if i drink half of a bottle of water, and my friend drinks the other half, how much water is in the bottle?

[vestal crescent]

0

no?

[fallow widget]

ok so if now if i refill with water until is half full and my friend drinks half of what i fill

[fallow widget]

yes

[vestal crescent]

25?

[fallow widget]

yes

[vestal crescent]

okay

[fallow widget]

so if now i fill 25% of the bottle and my friend does the same (25%) how much water there is in the bottle?

[vestal crescent]

50

[fallow widget]

ok and how much is left to fill it?

[vestal crescent]

50

[fallow widget]

now i think you can do your question

[vestal crescent]

oaky hold on

[fallow widget]

if thor eats 35% and tom 2/5

[vestal crescent]

is 2/5 like

[fallow widget]

like?

[vestal crescent]

is it 40%

?

[fallow widget]

nope

sum those fractions

[vestal crescent]

😭😭

20

bro gave up on me😭😭😭

u there?

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[iron patrol]

hi

[iron patrol]

https://gyazo.com/ba79acc8a27c48622a82ef7e27c8431b

so i kind of understand how the 4 looks and the x^2 will go up, but

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[torn jolt]

can someone explain this

I dont understand why its 20,22 either

1-9 is a increase

right how is that running away

and why is t=11 greatest speed?

[eager violet]

The table is showing values for J'(t)

Not J(t)

[torn jolt]

so the derivative basically but I dont understand how its (4,7) and (20,22)

how would i come to that

using the information given

[eager violet]

Because the derivative is positive at least once on those intervals

And if the derivative is positive, the position J(t) is increasing

[torn jolt]

ok

so for the speed is the greatest

how is that t=11

would graphing this help?

i still dont understand it fully

j'(t)

[eager violet]

Speed is the absolute value of velocity

And J'(t) is velocity

[torn jolt]

but

why is (8,11)

not an answer its decreasing and she could be running away

from her owner

[eager violet]

It's not guaranteed J'(t) is positive on that interval

If J'(t) is negative, then J(t) is decreasing

[torn jolt]

so th en

if (7,8)

interval was an answer choice would that be correct?

[eager violet]

Yes

[torn jolt]

kk so basically because its negative it means that its decreasing

so it would not be possible for her to be running away

because the distance would be increasing from the owner not decreasing

[eager violet]

Yes. Increasing means she's running away

[torn jolt]

but is it not increasing from

(1,9)

or

(20,22) i mean

[eager violet]

The derivative is positive, yes

Which means J(t) is increasing

Which means Judy is running away

[torn jolt]

ok this sounds stupid but how do u know the derivative is positive there

at those points

[eager violet]

Because the derivative is between 1 and 9 on there

And both 1 and 9 are positive last I checked

[torn jolt]

ohhhhh

so if we were given as well

(17,20)

would that work

as answer because the derivative is positive

there

[eager violet]

Yes

[torn jolt]

kk thanks also i dont understand the second part at all

why is it t=11

is it cause it has the greatest decline

like the slope

its steep

?

[eager violet]

.

Which given value of J'(t) has the largest absolute value?

[torn jolt]

ohhhh

12

-12 absolute value is 12

I see

I just get confused because derivative graphs are very differnt than like normal ones

can I ask one more question im still confused about

if you want to answer ofc

[eager violet]

Sure

[torn jolt]

for the first one [5,6]

ik its constant but

why not [0,1]

thats also constant

straight

and [11,12]

[eager violet]

The graph is of C'(t), not C(t)

[torn jolt]

kk so its the derivative of c(t) but i dont really understand still

why are those not constant

[eager violet]

What does it mean for a function to be constant in terms of its slope?

[torn jolt]

like it has one output for an input

right

[eager violet]

y = x gives one output for any input

Is it constant?

[torn jolt]

so bascially every output has an input can u explain it in this context

still kinda confused sorry

[eager violet]

Can you give an example of a constant function

[torn jolt]

like

f(x)=4

[eager violet]

What's the derivative of any constant function?

[torn jolt]

0

righ

[eager violet]

Is C'(t) = 0 on [0, 1]?

[torn jolt]

ngl im confused how would i know that mathematically

like what would I do to check that

[eager violet]

You're given the function y = C'(t)

Just see when it's 0

[torn jolt]

oh

lol

which is [5,6]

ah

so

anywhere y=0

its constant?

[eager violet]

Yep

[torn jolt]

or t i meant

kk

i see

so

if it said

[7]

would that be correct?

just 7

as interval

[eager violet]

x = 7 is constant yes

Or, t = 7

It'd be weird to write that as an interval

[torn jolt]

thank you so much

can u explain for the second part why [3,4] is nto decreasing

i know its c'(t) not c(t)

but how does that make a difference

is it just

anywhere negative its decreasing?

[eager violet]

Yes

[torn jolt]

so if its negative its decreasing

for derivative

[eager violet]

Yes

[torn jolt]

if its positive

its increasing?

[eager violet]

Yep

[torn jolt]

regardless if it goes straight down

kk

can u explain the last one the tempature being highest

at 7

why not 2.5

ish

[eager violet]

Because it's still increasing past 2.5

[torn jolt]

ohhh

i see

lol

because the second it becomes negative

it starts decreasing

right

so the last highest increasing positive value

is 7

since 7 is the last value before decreasing

[eager violet]

Yes

[torn jolt]

bro taught me more than my teacher in 1 month

[eager violet]

This only works cuz it doesn't start increasing after

[torn jolt]

lol

[eager violet]

If it starting increasing again later it'd be much more complicated

[torn jolt]

if it started increasing after it would be the point last show on the graph

?

like hte highest

x value?

or t

so if it came back above the x axis at like

x=14 then stopped

it would be x=14?

[eager violet]

We'd need to find some way to find the integral of the function

It wouldn't be guaranteed to be the last point

[torn jolt]

this is liek our first exam and we havent went into like intergrals yet so i dont think that will be asked

hopefully

lol

math is like my worst but im trying

can i keep the ticket open if i have more like soon or should i close

thanks btw

[eager violet]

Probably close. You can always open it again if you find another problem you're stuck on

[torn jolt]

kk thanks

!

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[dark oar]

i need help finding the zeros in the quadratic function

[dark oar]

y = 3(x-5)(x+4)

[torn jolt]

You mean roots?

[dark oar]

im not sure ill take a picture of the question rq

[torn jolt]

I mean

[dark oar]

oml my phone just died

[torn jolt]

This form already shows all answers

Try to put -4 in there

[dark oar]

well the question is asking what are the zeros of the quadratic function

[torn jolt]

Then it's 3 * something * 0

Which is 0

Actually it's 3 * (-9) * 0 but

Doesn't matter since it equals 0

also try to put 5 in there, it should be y=0 as well

[dark oar]

when you say try to put a number in there what do you mean?

[torn jolt]

All quadratic functions can be displayed as $ \lambda(x - \alpha ) ( x - \beta ) $ form

why no work

$$ \lambda(x - \alpha ) ( x - \beta ) $$

[glossy valve]

Seminaire

[torn jolt]

k

[dark oar]

im so confused this is the first time ive done this

[torn jolt]

And this means $$ x = \alpha , \beta $$

[glossy valve]

Seminaire

[torn jolt]

Ohhh

[atomic blade]

Essentially set each factor equal to 0

[dark oar]

like set the 5 to zero set the 4 to zero?

[atomic blade]

So:
3 = 0
x-5 = 0
x+4 = 0

Now obviously 3 cannot be 0 so we can ignore that top line

But x-5 = 0, and x+4 = 0 both have solutions

[dark oar]

im just not understanding the question it says "What are the zeros of the quadratic function."

[atomic blade]

Zeroes are the x-intercepts

The values of x that makes y = 0

[dark oar]

OHHHHHH

so wait

(x-5) x=5 right?

@atomic blade

[atomic blade]

yeah

So 5 is one of the zeroes

There's another one

[dark oar]

(x+4) x=-4?

@atomic blade

[atomic blade]

Yea

[atomic blade]

,rotate

[dark oar]

so the answer would be x=5 and x=-4

[atomic blade]

Yes

[dark oar]

thanks

.close

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[little heron]

Can i get help?

[little heron]

bot

[light sonnet]

Concept of supplementary angles

[little heron]

ye

[light sonnet]

Do you know how to apply that?

[little heron]

Wdym?

[light sonnet]

Do you know how to apply supplementary angles

[little heron]

yes

But this one is giving me problems

[light sonnet]

What does supplementary angles mean?

[little heron]

180

Degress

Angle

[light sonnet]

So the sum of angles equals 180, right?

[little heron]

yes

[light sonnet]

Can you make an equation based on that info?

[little heron]

yes

Lemme try

2s+2+3s-2=90

That’s correct I think

[light sonnet]

Yes

Solve for s

[little heron]

5s=90

[light sonnet]

So s equals?

[little heron]

18

[light sonnet]

There you go

[little heron]

That was

Way easier

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[daring prawn]

does anyone know why this is wrong?

isnt y this

<@&286206848099549185>

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[fluid robin]

yo

[fluid robin]

Yo what are the steps to remove the - from y

[noble field]

Multiply both sides by -1

[fluid robin]

wait u not dividing?

thats where im getting confused at im not sure if u multiply or divide in that scenario cuz its in the numerator

[light sonnet]

You can if you want to

[noble field]

U could if u want

[fluid robin]

oh ok so its better to multiply i see

[light sonnet]

Technically since it's in the numerator, you should divide

[fluid robin]

okay i get that i have to multiply but what do i multiply specifcally

[light sonnet]

If you have -x = 3, how do you find x?

[fluid robin]

i get that like you can divide -1

or multiply

and get x = -3 but im not sure how it works

in a fraction like abovee

[light sonnet]

For example -x = 1/2 + y
We're dividing by -1 again, so -x/-1 = (1/2 + y)/(-1)

And the concept of fractions $\frac{-a}{b} = \frac{a}{-b}$

[glossy valve]

dldh06

[fluid robin]

so for fractions

[light sonnet]

So (1/2 + y)/(-1) is the same as -(1/2 + y)/1

[fluid robin]

only the denoms inherit the

negative?

[light sonnet]

No

[light sonnet]

.

[fluid robin]

wait

i get that you divide -1 to the other side now

which one of these inherit the negative

@light sonnet

or out of all of them

[light sonnet]

All of them

$$-x = \frac{1}{2}+ y$$
$$x = \frac{\left(\frac{1}{2} + y\right)}{-1}$$

[glossy valve]

dldh06

[light sonnet]

That's my simple example

$$x = \frac{-\left(\frac{1}{2} + y\right)}{1}$$

[glossy valve]

dldh06

[fluid robin]

answer/

[light sonnet]

No

[fluid robin]

oh wait -2*

thats the answer right

when its a -2 miswrote

?

@light sonnet

?

[light sonnet]

No that's wrong

Apply the concept of the example I provided above

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[torn jolt]

How many trailing zeroes does 100! have when converted to base 6?

[torn jolt]

<@&286206848099549185>

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[static creek]

proof that

Prove that ¬(A ↔ B) ↔ (A ⊕ B):
using tautology

[static creek]

I'm largely lost on the first step that I should do here. I've done a few of these problems in class, but they used and, not if and only if

[simple totem]

is $\oplus$ xor?

[glossy valve]

maximo

[static creek]

yeah

I'm pretty sure i could solve this if I knew where to start / that

that's what I want to do

cause I want to learn it

I solved it with a truth table already

[simple totem]

when in doubt go back to basic ands, ors, and nots

[static creek]

but how?

[simple totem]

i believe you can also use $\lnot(A \iff B)\equiv \lnot A \oplus \lnot B$, but i’m not 100% on that

[glossy valve]

maximo

[static creek]

like is there an equivlance for turning xor and if and only if into ands/ors?

[simple totem]

yes

$A\iff B\equiv (A\implies B)\land(B\implies A)$

[glossy valve]

maximo

[static creek]

oh

that makes sense

[simple totem]

and $A\implies B\equiv (\lnot A) \lor B$

[static creek]

thanks man

[glossy valve]

maximo

[static creek]

from here I got it

[simple totem]

ok

[static creek]

pretty sure

I'll leave this open till I'm 100% done

[simple totem]

oh well obviously $\lnot(A\iff B)\equiv A\oplus B$

[glossy valve]

maximo

[simple totem]

but i guess the point of the exercise is to prove that

[static creek]

yeah. that's the main point

@simple totem if you don't mind me asking what's the one for xor?
is it $A \oplus B\equiv (A\lor B)\land \lnot(A\land B)$

[glossy valve]

Arjun132

[simple totem]

looks about right

[static creek]

alright. thanks

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[torn jolt]

don't test them

.close

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[severe frigate]

how do i find all three? i know how to do it when its only Y and X but now its Z?

[brave blaze]

Gauss elimination
Row reduction
Cramer determinant

There are a lot of methods to solve things like this

[severe frigate]

i dont know any of those, i'm not good with english terms in math

[brave blaze]

you can google them

[severe frigate]

so i cant get help here?

[brave blaze]

I mean, if you don't know any methods to solve a system of 3 equations, try it yourself first and if you are stuck I can help you

I gave you 3 methods of solving

I don't want to give a full course here tho

[severe frigate]

i know wht to do with only x and y

i find X and Y alone, then i insert X into the Y formula and once i have the Y i put that into the other formula

[brave blaze]

thats the way when there is only 2 variables

you have 3 variables here

[severe frigate]

i have no idea what to do now

yes

[brave blaze]

3 methods, when dealing with 3 variables, now go on the internet, there are many courses about them

[severe frigate]

great help thanks

"google it"

[brave blaze]

you don't even know the methods, how would I help, I don't want to give a full course here

[severe frigate]

i'm not asking for a full course, i'm just asking for guidance inthe right direction, not "google it"

whatever

[brave blaze]

and the guidance is, look at each method

try to understand them first

and come back if you are struggling with one of them

[severe frigate]

Thanks for nothing

[brave blaze]

np

[severe frigate]

Close

[brave blaze]

idk if you wanted me to solve it for ya, but whatever

[severe frigate]

No bro i wanted you to atleast try to help me instead of saying google it

I am familiar with the method with 2 equations

Can anyone else please help me?

<@&286206848099549185>

[manic meteor]

Use elimination method

[severe frigate]

this group is ass

[brave blaze]

you didn't listen me

have fun struggling I guess

[gusty elbow]

equation 3: 3z=x-y+1

u can sub that into equation 1 and 2, so u only hv a pair of equations in x,y only which u know how to solve, then afterwards u can find z by putting back the x,y values u find

[severe frigate]

ok let me try this one sec

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[magic laurel]

i need help

[magic laurel]

<@&286206848099549185>

.close

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[grand nimbus]

Can someone help pls

[fleet cedar]

https://www.khanacademy.org/math/geometry/xff63fac4:hs-geo-conic-sections/xff63fac4:hs-geo-parabola/a/parabola-focus-directrix-review

not so fast champ

[grand nimbus]

?

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[torn jolt]

How do I do this or even start it ? Please

[torn jolt]

Or if I could suggest a video that would help explain it

[graceful ether]

its asking you to make it into 1 fraction and simplify it. Do you know how to make it into a single fraction?

[torn jolt]

No

[graceful ether]

each term needs to have a common denominator

then you can add them together

[torn jolt]

I also don’t know what the numbers in the right are

[graceful ether]

those are mostly unimportant

its just saying that x is a real number and does not equal -4 or 2

if it were to equal -4 or 2 then the function would be undefined because the denominator would have a zero

do you know how to make each term have a common denominator?

[torn jolt]

No

[graceful ether]

see what happens when you multiply 2/(x+4) by (x-2)/(x-2)

since (x-2)/(x-2) = 1, it is still the same expression but now with a common denominator

[torn jolt]

Where did u get (x-2)/(x-2) from

[graceful ether]

it equals 1

its just multiplying by 1

n*1=n

so when you multiply the second term by (x-2)/(x-2) you end up with (x+4)(x-2) in the denominator which is the same as the denominator for the 3rd term

https://www.youtube.com/watch?v=1KGVwaUhR-s

[torn jolt]

Thanks

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[sonic hatch]

i have a question about differential calculus
how to calculate the extremes so highpoint and lowpoint without the pq formula cuz i cant use it when the x has an exponent of more than 2
eg
3x^4+2x^3+x^2

[torn jolt]

factor out x^2

[sonic hatch]

3x^5+2x^3+x^2

[sonic hatch]

what if its like that?

[torn jolt]

hope that you are lucky because in general, its hard to factor polys with degree >2

,w factor 3x^3+2x+1

[glossy valve]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Toby#2275

[torn jolt]

irreducible here

[sonic hatch]

i dont understand what to do if i simply cannot use the pq-formula

cuz normally i factor the x with the lowest exponent out and solve x^smth and then use the pq-formula to solve the brackets

[torn jolt]

there is no "normal" when the degree is bigger than 2

(unless you want to learn the cubic/quartic formula)

[sonic hatch]

sounds.. complicated

so what do i do then?

[torn jolt]

cry /hj

normally, first verify with a computer (eg wa) to check if its got integer roots

(or use rational root thm)

then use poly division for them

[sonic hatch]

i didnt understand half of that sentence bro

i should buy a computer? 😭

[torn jolt]

wolframalpha is a website

rational root is this https://en.wikipedia.org/wiki/Rational_root_theorem

[sonic hatch]

oh i thought u meant whats app

u know what.. i think im just using the most noblest and simplest of acts. Praying to god that this isnt gonna come on the exam 🙂

[safe trench]

What is the meaning of hj?

[torn jolt]

half joking https://toneindicators.carrd.co/

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[gaunt fulcrum]

Any helps pls

[gaunt fulcrum]

How do I evaluate f(x) for some large values of x without a calculator

[graceful ether]

a*ln(b) = ln(a^b)

knowing that, does (1+1/x)^x as x approaches infinity remind you of anything?

its a pretty famous limit

[gaunt fulcrum]

e?

[graceful ether]

yes

so what is ln(e)

im just gonna assume you know its 1

[gaunt fulcrum]

Ahh right

[graceful ether]

just remember this formula when u see something times an ln

its a common trick

[gaunt fulcrum]

Do you think I will have to show the proof for this in my working out or nah

[graceful ether]

not sure

i dont think you would have to prove an identity but it probably depends on your professor

[gaunt fulcrum]

Okay thanks a lot

[graceful ether]

do .close if u dont need any more help

[gaunt fulcrum]

.close

[full forum]

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[torn jolt]

Help me please

[empty sapphire]

hi what's the question?

[gritty rose]

^

[torn jolt]

Hi

Sorry for the delay

It’s really confusing

So would I do 116/360x2pi x(25+14)

And then add 116/360 x2pi x9

[empty sapphire]

you're really close!!

okay so what's the arc length of the outer perimeter?

[torn jolt]

Sorry

I had to do smt

[empty sapphire]

no worries

[torn jolt]

Okay so am@I close right

[empty sapphire]

you're close

but let's break it down one by one

[torn jolt]

Okay waht did I do wrong

[torn jolt]

Yep

[empty sapphire]

okay so what is the arc length of the outer perimeter of the segment?

[torn jolt]

Would it be central angle x circumference

Central angle /360

X circumference

[empty sapphire]

yep! So we can say something like $s= 2 \pi r \times (\frac{\theta}{360})$ right?

[glossy valve]

MellowDramaLlama

[torn jolt]

Yes

So what would I substitute

[empty sapphire]

okay so the outer and inner perimeter have the same angle at 116

so that's our theta

[torn jolt]

Yes

We just need to do outer minus inner right

Mellow

[empty sapphire]

well we're looking for perimeter

so we need to add all 4 sides

[torn jolt]

Ohhhhhhhhhh

I was confused

So we add everything

[empty sapphire]

yep!

outer perim + inner perim

• 2 * sides

and the sides here are just the difference in the outer - inner radius 🙂

[torn jolt]

Okay so how would I find inner would it be 116/360x2pix14

Or x25

That’s what makes me confused

[empty sapphire]

14. Inner here refers to the arc that's closer to the center

[torn jolt]

Would I times by 14 or 25

[empty sapphire]

no don't jump the gun

let's work on this one step at a time

[torn jolt]

Okay

[empty sapphire]

so let's just start with the outer perimeter

which is the furthest arc from the center

what's the radius there?

[torn jolt]

Would the radius be ...

I’m done for

[empty sapphire]

lol

you have 2 choices

if the outer perimeter is the furthest away

would its radius be 14 or 25

hint: pick the bigger number

[torn jolt]

25

[empty sapphire]

bingo

[torn jolt]

Yes

!

So we would do 116/360x2pix25

[empty sapphire]

so $s_{outer} = 2 \pi (25) \times \frac{116}{360}$

[glossy valve]

MellowDramaLlama

[empty sapphire]

yep exactly

[torn jolt]

Wait so.£9

How bout the other part

[empty sapphire]

okay so that's the outer radius

's perimeter

what about the inner radius' perimeter

?

[torn jolt]

Would this be 50.61454831

[empty sapphire]

sure. However your teacher wants the answer to be

[torn jolt]

So would the second part be 116/360x2pix?

[empty sapphire]

well your missing your radius there

[torn jolt]

Oh

14

Right

[empty sapphire]

yep!

so then you follow the same logic as r = 25

[torn jolt]

So would my inner be 28.34414705

[empty sapphire]

perfect!

so we have the outer and the inner radius

[torn jolt]

Okay so would I add them together

Plus 25 and 14

[empty sapphire]

but we still need to account for the sides

[empty sapphire]

wait where is that coming from?

[torn jolt]

The sides

[empty sapphire]

well the sides are equal

[torn jolt]

lol

Oop

[empty sapphire]

how can they be 25 and 14? 😛

[torn jolt]

Sorry

[empty sapphire]

no worries!

[torn jolt]

Waht would it be

25 and 25

[empty sapphire]

okay so lets say for example that I measured out 30 feet

and I took away 12 ft

[torn jolt]

Yes

[empty sapphire]

how many ft would I have left?

[torn jolt]

18

[empty sapphire]

good!

same principle here

[torn jolt]

Oh

25