#help-28

1 messages · Page 11 of 1

fast peak
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yeah the question is badly written

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lets assume that $x=(x_1, x_2, \ldots, x_d)$ and $0<m\leq n\leq d$

glossy valveBOT
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Denascite

visual topaz
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alright

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does that get us anywhere?

fast peak
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well now we can start

visual topaz
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hmm lets say we plug those in

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by saying that m > 0 , n>0 basicly always yields in positive right/

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no matter what x1 or x2 are

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plus we are taking absolute value of the elements

fast peak
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ok. so the first axiom is satisfied

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what about the next

visual topaz
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scalar multiplication

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this one might be tricky , but same logic i guess

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alright ill try to work something out, thanks for the help

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solemn ice
#

How do I tell which way the inequality sign goes

wide sundial
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What’s the question

torn jolt
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why square function is equal to linear

solemn ice
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Question d

wide sundial
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,rotate

glossy valveBOT
wide sundial
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You should also lay out what answers which question

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For example, have i) for the graph

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Then ii) shows the intersection points if any

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Then iii) solves the inequality

solemn ice
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How do I find points of intersection is it simultaneous equations

wide sundial
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Yep

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Points of intersection is where the x and y values of both equations are the same

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Which is why simultaneous equations work

solemn ice
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?

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That correct

wide sundial
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What

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The 2 equations equal each other

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Your 2 equations are:
y = 3 - x²
y = 2x - 12

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@solemn ice Has your question been resolved?

solemn ice
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How do I solve that simulatineously

wide sundial
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Equate the y’s

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So 3 - x² = 2x - 12

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@solemn ice Has your question been resolved?

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edgy cypress
#

<@&268886789983436800>

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primal mica
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Hello, I would like to ask for help in mathematical analysis, I'm struggling with integration

pine wasp
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good to know

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do you have a question?

primal mica
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this is my homework, i already solved 11-14

pine wasp
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which tequniques have you learnt

primal mica
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currently we are supposed to use substitution

pine wasp
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which question do you need help in?

primal mica
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i would like to solve 15

pine wasp
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integrate it?

primal mica
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yes

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"integrate the following functions"

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but i didnt send the text, because its in my first language

pine wasp
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thats ok i speak all languages you can think of

primal mica
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haha

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hungarian?

pine wasp
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all languages apart from that

primal mica
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:))

pine wasp
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you sure its to inegrate and not differenciate it?

primal mica
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yes, 100% sure

pine wasp
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is this calulator or non calc?

primal mica
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im not sure what that means

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im confused because the previous problems were a lot easier to integrate, this one i cant think of a way to do it

cedar heart
pine wasp
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yes this one is a bit digusting

cedar heart
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Cause this one is disgusting

primal mica
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idk how to type the syntax

cedar heart
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Is it disgusting

primal mica
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it has a 5th root

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and stuff

cedar heart
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Ah I see

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So yes

pine wasp
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$\sqrt[5]{x}$

glossy valveBOT
pine wasp
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thats the syntax

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inline math goes in $ and functions have a \ before them

primal mica
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you know what, im already tired as fck

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im gonna ask the teacher tomorrow

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if its a mistake in the book or something

pine wasp
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maybe

primal mica
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i just thought i might be overlooking something

pine wasp
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the answer i got was

primal mica
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thats why i came here

primal mica
pine wasp
primal mica
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whaaaaaaaaaa

pine wasp
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well this is what an online calculator got...

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its a bit ugly

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however it would be fun to differenciate

primal mica
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i just wanna pass math

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😰

pine wasp
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oh you will

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if you enjoy calculus then you will

primal mica
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im trying to

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but i mean 🤠

pine wasp
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watch 3blue one browns series on it

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it gives a good intuition

cedar heart
primal mica
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alright, thank you

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obtuse hatch
#

how many anagrams we can compose from the word "TIZI OUZOU" such That two similar letters are not adjacent to each other?

obtuse hatch
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@zenith kernel

zenith kernel
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Which two letters?

obtuse hatch
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any two similar letters

zenith kernel
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Inclusion-exclusion principle

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(4)(8C1)(7!/2^3)-(4)(3)(7C2)(5!/2^2)+(4)(3)(2)(6C3)(3!/2)-(4!)(5C4)

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Oh not this directly

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9!/2^4 minus what I typed

zenith kernel
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Np

obtuse hatch
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native briar
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The questions is just about using limit laws. Should the final answer not be 8, not 7?

native briar
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Want to make sure I'm not missing something here.

rose blaze
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What is f(x) and g(x)?

dim wolf
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^

full marsh
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Depends on what f(x) and g(x) approach

native briar
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f(x) = 4
g(x) = 9

I see using these numbers how you would get the answer in the book. I thought that when you had lim as x-->a that you set the value of f(x) to a. This is evidently false.

full marsh
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4 + 1/3 * 9 = 7

native briar
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lim x->a C = C

full marsh
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They already tell you f(x) approaches 4, and g(x) approaches 9. In other words:

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$\lim_{x \to 6} f(x) = 4$

glossy valveBOT
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RedstonePlayz09

full marsh
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$\lim_{x \to 6} g(x) = 9$

glossy valveBOT
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RedstonePlayz09

full marsh
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You might want to revise what limit means.

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Having an intuitive understanding of it might help

native briar
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So if I had something like $\lim_{x \to 6} x = ?$ then I would be able to set the ? value to 6?

glossy valveBOT
full marsh
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Yes

rapid bay
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not always

full marsh
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But what about $\lim_{x \to 6} 2x$

glossy valveBOT
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RedstonePlayz09

full marsh
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x is continuous

native briar
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Okay, need to remember to keep f(x) and x as separate ideas. (I understand how they are, just a slip of the brain)

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2 lim(6)?

full marsh
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that limit is just equal to 2 * 6 which is 12

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you could take the 2 out, but no reason to do that. just plug x = 6 in

native briar
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Sounds good. I was just told we need to 'understand why we can just plug it in' which is why I was writing out one of the laws.

full marsh
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of course, you will soon encounter limits where you can't just plug in the value.

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For example, limits as x approaches infinity, or where the function is undefined

rapid bay
native briar
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Think I've got it. Thanks.

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fallow kayak
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scenic wren
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p has a point at 0.0 therefore p(0)=0

vast fossil
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And p'(0) = 0 follows from the definition of a turning point

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Let's say p(x) = a_nx^n + ... + a_1x + a_0, using this information you can deduce that a_0 = a_1 = 0

scenic wren
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huh

vast fossil
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So p(x) = a_nx^n + ... + a_2x^2, therefore p(x) = x^2(a_nx^(n-2) + ... + a_2) = x^2q(x)

eager violet
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Don't just give answers

scenic wren
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interesting in germany we have different terms
a turning point would translate to wendepunkt which is where p' changes sign

vast fossil
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Ye, so it's 0 there (the derivative)

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As long as the derivative is continuous

fallow kayak
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thanks a lot

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torn jolt
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Got a quick one, why take negative here when integrating?

modern sentinel
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derivative of a^2-x^2=-2x

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and -(-)=+

torn jolt
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Ahhh I see, thanks man!

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wise ridge
#

How do you do the second part

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modern sentinel
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on differentiating it would be
-sin(y)*dy/dx=1/2sqrtx, so you'll get dy/dx

wise ridge
#

Oh I get it

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muted flicker
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Hi, can someone explain to me this example?

brave blaze
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which lines are you failing to understand ?

muted flicker
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How the negative square root was used

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Don't really see the connection even having the TB giving a brief explanation

brave blaze
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when x approaches -oo, that means x is negative right ?
when we factor by x^2 in the sqrt, we have : sqrt(x^2 (4 + 3/x^2)) = sqrt(x^2)*sqrt(4+3/x^2)

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and we all know that sqrt(x^2) = |x|

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we know too that
|x| = x when x > 0 and -x when its negative

muted flicker
#

Understand it much 🙏

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past trail
#

How to factor 81z^2+36z+4 and 4z^2-20z+25? They are squared but when I try to factor by grouping I get 9z(z+2)+2(9z+2) when the answer is (9z+2)(9z+2)

regal gust
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Which one are you trying to factor

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For $4z^2-20z+25$ you can do what multiplies to 100 and adds to -20

glossy valveBOT
past trail
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for $4z^2-20z+25$ I got 2z(z-5)-5(2z-5)

glossy valveBOT
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EliteFriedRice

regal gust
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So factoring by grouping usually is reserved for polynomials with 4 terms from my understanding

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Cause you’d group the first 2 and last 2

past trail
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oh

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i thought grouping was for when coeffiecient wasn't 1 and couldn't be factored

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because then the equation would be
4z^2-10z-10z+25
because -10-10=-20 and -10*-10=100 100=25*4(coeffec)

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NVM

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i redid it and I was wrong, it was 2z(2z-5) and -5(2z-5)

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sorry

regal gust
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Gotcha I was trying to see what was going Wrong but you found it haha

past trail
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for 55 when grouping i got (9z)(z+2)+(2)(9z+2), how would i get (9z+2)^2

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original equation was 81z^2+36z+4

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nevermind

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i just made a small mistake lol

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topaz juniper
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topaz juniper
#

Probably a stupid question, but what is here meant by maximum?

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I know what the maximum of a function is, but you're not given a function here 🤔

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I was trying to help someone with this but was confused by this wording

nimble current
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you want to find the real numbers a,b such that a + 2b = 24 and ab is as big as possible

topaz juniper
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Okay

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" ab is as big as possible"

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That's what I was missing

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Thanks

nimble current
#

np

topaz juniper
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ashen quail
#

i need help understanding piecewise functions

deft zodiac
#

what about e,m

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red oracle
#

what is the use of rational expression in daily life

violet ridge
#

passing a test

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rigid mist
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how do i do this

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i know normal DA

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@torn jolt sorry for the ping but you were able to help me a lot on the other question so could i get a little more help here

gleaming coral
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so uh yeah

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lets refer to these units as X, Y

rigid mist
#

okay

gleaming coral
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and the numbers as A,B

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so a x^3 = b y^3

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You know 'a'

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and you can calculate y/x

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A x^3 * (y/x)^3 = b y^3

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Does that make sense so far

rigid mist
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i lost you at the last part

gleaming coral
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Hmmmm

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What is confusing about the last part

rigid mist
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like im trying to visualize it with DA

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but then i get confused

gleaming coral
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I'm not sure what DA is

rigid mist
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dimensional analysis

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This is what I had been doing so far for normal questions

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Now I got to ones asking for cubed units

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I don’t get that

gleaming coral
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That's a really long way of doing it but it makes sense

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so in essence, a x^3 = b y^3

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You get the conversion y/x, and basically do $a x^3 \frac yx \frac yx \frac yx = b y^3$

glossy valveBOT
#

KurtDee

gleaming coral
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I'm not sure how to explain the intuition

rigid mist
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yea I’m getting confused by that example

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Sorry

gleaming coral
#

Well I suppose you could either think of it two different ways

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you're either 1. eliminating one part of the cubed unit at a time

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or 2. you're calculating the conversion between cubes first

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as to HOW it's done, you need to find "Xierons/Kygenes" first

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And then you get the ratio of "cubic Xierons /cubic Kygenes" by raising to the third power

rigid mist
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is it possible for you to like write down on paper the first few steps?

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im better at visualizing stuff

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or draw on an app

gleaming coral
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I can solve a different problem

rigid mist
#

yes thatll help too

gleaming coral
#

Lets say I want to solve 20 sq feet to sq meters

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$1 ft \approx 0.3m$

glossy valveBOT
#

KurtDee

gleaming coral
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so we need m/ft, which is $\frac1 {0.3} \approx 3.28$

glossy valveBOT
#

KurtDee

rigid mist
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yes

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i understand that

gleaming coral
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$\frac {m^2}{ft ^2} = 10.76$

glossy valveBOT
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KurtDee

gleaming coral
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so actually we need to put this on the other side, $\frac{m^2}{ft^2} \frac 1 {10.76} = 1$

glossy valveBOT
#

KurtDee

gleaming coral
#

I should have done it like that to start with

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finally, $20 ft^2 * \frac 1 {10.76} \frac{m^2}{ft^2} = 1.86 m^2$

glossy valveBOT
#

KurtDee

gleaming coral
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You can also think of it like $m^2 = 10.76 ft^2$

glossy valveBOT
#

KurtDee

gleaming coral
#

in that case, you would still divide by 10.76 to get m^2

rigid mist
#

im trying to understand this but i just cant for some reason

gleaming coral
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which part

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i did invert it twice by accident

rigid mist
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so

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i tried my best to solve the problem

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this is what i ended up wit

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for this

gleaming coral
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looks right to me

rigid mist
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thanks

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now i have to do it with square

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instead of cubed

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is it similar?

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or the same

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but doing square instead of cube

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oh it looks like it is

#

can you confirm

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torn jolt
#

this is stupid:

λd: 400÷410nm

the symbol between 400 and 410 (for some reasons discord can't display one futher one), is used as to denote a rage between 400 and 410 (nm)?

brave blaze
#

what

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its a division symbol right ?

hot herald
#

one futher one
?

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torn jolt
#

but in that context makes no sense

brave blaze
#

why

torn jolt
#

so I suppose it's used to indicate a rage

brave blaze
#

what is a rage

torn jolt
torn jolt
brave blaze
#

and its about wavelength ?

torn jolt
#

for rage I meant range
I'm sorry autocorrection

brave blaze
#

well I dont know what that notation means, but maybe try to understand the whole context

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dense edge
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dense edge
#

This is the first time polynomials have been explained to me like this… is this true what I have written near the bottom?

#

If so, what would a polynomial be called if it contains complex numbers or asymptotes?

#

This is from Professor Leonard btw

sour mauve
#

a/x would give asymptotes?

#

elaborate

dense edge
#

Well, i wrote that but I could be wrong.. he was saying negative exponents

sour mauve
#

well if you mean that having a term a/x could lead to asymptotes then you're right

#

everything else is correct

dense edge
#

The a/x was mine. I will adjust that

sour mauve
#

everything else is good

dense edge
#

Wow

#

This is the first time I have learned this..

#

I imagined polynomials as including all of the above

#

Imaginary numbers, asymptotes, you name it

#

I guess I was over complicating things

sour mauve
#

polynomials don't have asymptotes

#

their domain is always all real numbers

dense edge
#

Nice

#

Easier to remember

sour mauve
#

the domain is not all real numbers only if there's a radical or fraction

#

which then introduces dividing by 0 and i

dense edge
#

What do we call functions that do have complex numbers or asymptotes, if not polynomials functions? And are structured like a polynomial with highest degree first with constant at the end

dense edge
#

Ah OK…

quick geode
#

yeap

dense edge
#

Complex function maybe?

sour mauve
#

function is good enough

quick geode
#

they dont really have a particular name

sour mauve
#

yeah

quick geode
#

u can call them anything u like

#

function is the most generic term

dense edge
#

Polynomial can refer to binomial, trinomial, and anything above right? but not monomial? Or is it one of those all encompassing terms

sour mauve
#

yeah

dense edge
#

Like square and rectangle lol

sour mauve
#

everything but monomial

dense edge
#

Rectangle can be a square and vice versa

#

Still confusing to me lol

sour mauve
#

well

#

what you have down so far is all good

quick geode
#

not vice versa

sour mauve
#

open up a ticket if you have more doubts

quick geode
#

not all rectangles are squares

#

all squares are rectangles however

dense edge
#

Right

#

Square is just a special case rectangle

quick geode
#

yea

dense edge
#

Sorry one more question to keep it on polynomials.. is it true anything above 4th power polynomial with a constant you will have a hard time using the quadratic formula?

#

Maybe even impossible to solve if 5th power with constant? Iirc it’s the constant that is the issue here, more than the power itself. Without constant it can be done?

sour mauve
#

well

#

there's a quadratic, cubic, and quartic formula

#

I'd suggest you use factoring or differentiation to solve anything above 3rd degree

dense edge
#

Oooo I have only learned quadratic so far

#

OK

sour mauve
#

tip: don't search up the quartic formula

dense edge
#

Lol

sour mauve
#

it gives me nightmares

dense edge
#

I hope I won’t need to use it for Calc 1 or 2

sour mauve
#

probably not

dense edge
#

OK good

sour mauve
#

if you do get a polynomial with a degree of 4 or higher you'll be taught a diff method of solving it

#

not the formula

dense edge
#

Got it, thanks!

sour mauve
#

np

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loud hull
#

Trying to figure out why plugging in the x value here gives me the wrong y value

loud hull
#

,w 5x-2y+3z=20, 2x-4y-3z=-9, x+6y-8z=21

glossy valveBOT
loud hull
#

So those are the correct x,y, and x values

#

$\begin{tabular}{r} 5x-2y+3z=20\ +2x-4y-3z=-9\ \hline 7x-6y=11\end{tabular}$

glossy valveBOT
#

dopediscorduser

loud hull
#

[\begin{tabular}{r} 129x+6y=669\ + 7x-6y=11\ \hline x=5\end{tabular}]

glossy valveBOT
#

dopediscorduser

loud hull
#

But when I plug x back in

#

[7(5)-6y=11]
[y=\frac{19}{6}]

glossy valveBOT
#

dopediscorduser

loud hull
#

??

tardy vapor
#

where did the 129x + 6y =669 come from?

loud hull
#

One sec

#

It came from 5x-2y+3z=20, multiplied to a lcm to cancel out the z terms

#

I’ll write it out in latex

daring citrus
glossy valveBOT
#

Alpha Kappa

loud hull
#

Common lcm 3 and 8 of 24
[8(5x-2y+3z=20)]
[3(x+6y-8z=21)]

[\begin{tabular}{r} 40x-16y+24z=160\ + 3x+18y-24z=63\ \hline 43x+2y=223\end{tabular}/]

To eliminate the y term, LCM between 2 and 6 is 6
[3(43x+2y=223)= 129x+6y=669]

[\begin{tabular}{r} 129x+6y=669\ + 7x-6y=11\ \hline x=5\end{tabular}/]

glossy valveBOT
#

dopediscorduser
Compile Error! Click the errors reaction for more information.
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loud hull
#

I guess I’m just bad at arithmetic

daring citrus
#

happens

loud hull
#

Thanks

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quasi nimbus
#

Given the following equation system:

  1. y = x^2 - 5x
  2. y = 2x - 10

Find the intersection point of the line with the parable and represent it on paper

vast fossil
#

Just solve x^2 - 5x = 2x - 10

quasi nimbus
#

x1 = 2 and x2 = 5

vast fossil
#

Now find the y values

quasi nimbus
#

Ok

#

Ok done for both points

#

p1 (2, -6) and p2 (5, 0)

vast fossil
#

Now just draw them on a plane

quasi nimbus
#

Ok

#

Done

vast fossil
#

That's it

quasi nimbus
#

What about the parable

#

I have to draw it too

vast fossil
#

It didn't ask you to draw it

#

Just the points

#

I presume

quasi nimbus
#

I'm italian so i translated that way; the teacher wants us to draw the parable too

brittle steeple
#

You know the x intercepts already

#

Where's the vertex?

quasi nimbus
#

I have to find them

brittle steeple
#

ah right for some reason I thought it was factored already

quasi nimbus
#

If u mean the interception points with the X axis

#

Do i keep y = x^2 -5x that way and solve it?

brittle steeple
#

you find where y=0

#

but yeah vertex first probably

#

well you can do it either way really

quasi nimbus
#

I dont think it comes out right

#

by setting y = 0 in the parable's equation

#

The intersection point with the X axis are 5,0 and 0,0

brittle steeple
#

what are you getting

#

yeah

#

that's right

quasi nimbus
#

Oh

#

Ok

#

So now i have to find the vertex

brittle steeple
#

yeah

#

which you can find from the x-intercepts if you eant

#

want

quasi nimbus
#

The vertex should be 5/2 and -25/4

#

Right?

brittle steeple
#

yeah

quasi nimbus
#

Ok

brittle steeple
#

then you can just draw the rest by feeling

quasi nimbus
#

Ok done

#

Thanks a lot!

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brittle steeple
#

Np

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midnight prawn
#

is there any way to solve it without using L-Hopital's rule?

vast fossil
#

How is L defined?

midnight prawn
#

It's In

vast fossil
#

So L(x) = lnx?

midnight prawn
#

Yes

hot herald
#

factor out -1/2, and you'll have a definition of the derivative

vast fossil
#

Well $\lim_{x\to{3}}\frac{L(x) - L(3)}{-2x + 6} = -\frac{1}{2}\lim_{x\to{3}}\frac{L(x) - L(3)}{x - 3} = -\frac{1}{2}L'(3)$

hot herald
#

half not third

vast fossil
#

mb

glossy valveBOT
#

A Lonely Bean

midnight prawn
#

but tysm

midnight prawn
vast fossil
#

You don't know what the derivative of ln is?

midnight prawn
#

nope

vast fossil
#

Eh you can look up a proof that it's 1/x

midnight prawn
#

The thing is that i dont know if I can give a task with tools that I have not yet given in the course

#

I mean, is there no other way to do it? (no derivatives)

vast fossil
#

Well you can use that proof to justify why L'(x) = 1/x

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#

@midnight prawn Has your question been resolved?

midnight prawn
vast fossil
#

Alright without mentioning L'(x)

#

Just go from limit of (L(x) - L(3))/(x - 3) to 1/3

#

According to the proof

midnight prawn
#

I don't know how to do it

vast fossil
#

(L(x) - L(3))/(x - 3) = L(x/3) * 1/(x - 3) = L((x/3)^(1/(x-3)))
From here you can do a substitution, t = 3/(x - 3)
So the limit now is L((1/t + 1)^(t/3))

#

Which is the same as 1/3 * L((1 + 1/t)^t) as t approaches infinity

#

Does the limit inside the L look familiar?

midnight prawn
midnight prawn
vast fossil
#

Yes, so the limit is basically 1/3 * L(e)

#

And L(e) = 1 by definition

#

So it's just 1/3

midnight prawn
vast fossil
#

log(a) * b = log(a^b)

#

That's a lot property

midnight prawn
#

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delicate idol
#

If the magnitudes of two vectors are 3 and 4, and the angle between them is 40, determine the magnitude
of their cross product.

ripe trench
#

use cross product formula 💀

delicate idol
#

why the skull?

ripe trench
#

vvell it vvas straightforvvard

delicate idol
#

thats what i thought

#

but i used cos instead of sin

quick geode
#

magnitude of cross product uses sin

#

Vector A * Vector B * sin theta

#

this is the magnitude of cross product of 2 vectors a and b

delicate idol
#

thanks!!

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torn jolt
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torn jolt
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umbral plinth
#

Hello

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umbral plinth
#

what is the dimension of F = {M \in M_n(K) | tr(M) = 0}

#

is it 1 ?

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pliant estuary
#

in this example, why do the solution steps consist of first consolidating the terms in the numerator and then subtracting the denominator from the top two terms, rather than first subtracting the denominator from the top two terms, and then consolidating them?

rose blaze
#

There's a power rule that if a power is a negative number, it becomes a fraction

#

For example, 2^-2 = 1/(2^2)

#

When you multiply numbers with the same base number (in this case, p), you add the powers

#

So in reality you can't subtract from both of them individually
I hope that answers your question

pliant estuary
#

Thank you!

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@pseudo bobcat Has your question been resolved?

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subtle leaf
#

Just to be sure, this solution should have the $\mathscr{A}$ and $\mathscr{B}$ interchanged right?
(Apart from in the parentheses).

glossy valveBOT
#

CoffeeMan

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#

@subtle leaf Has your question been resolved?

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#

@subtle leaf Has your question been resolved?

fast peak
#

what is M(B) and M(A)?

#

but something about this is mixed up, yes

subtle leaf
#

The measurable functions on B and A, i.e.
$f \in M(\mathscr{B}) \iff \left( \forall X \in \mathscr{B} (\mathbb{R}) \colon f^{-1} (X) \in \mathscr{B} \right)$
where the $\mathscr{B}(\mathbb{R})$ is the borel-sigma algebra.

glossy valveBOT
#

CoffeeMan

subtle leaf
#

Anyhow, I think I just need some sleep tbh. But thanks. bye.

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worn zenith
#

Wilhelm has $84 of coins in his wallet. There is 4x as many $5 dollar coins as $1 coins. How many of each does Wilhelm have?

glossy valveBOT
#

JazzBo
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scenic wren
#

he has only coins and 5 dollar bills right?

#

we can extract some equations from this info

#

bills equal 5
coins equal 1
therefore 5b+1c=84

worn zenith
#

Well, it’s directly translated from Swedish. SEK (Swedish Crowns) whereas he has them in coins

scenic wren
#

where b and c are the numbers of bills/coins

worn zenith
#

1 and 5 SEK coins

#

Ok

scenic wren
#

next we know we have 4 times as many bills as coins

#

this means
b=4c

#

we can substitude this into the first equation

worn zenith
#

So its not 4b = 1c?

scenic wren
#

we can test this

#

lets assume we have 1 bill

#

4 times 1 equals 4

#

so we would have 4 coins

#

which is the opposite of what we want

boreal marlin
#

The amount of bills is four times the amount of coins

scenic wren
#

so we have
5b+1c=84
b=4c
setting b to 4c in the first equation we get
20c+1c=84

#

the rest should be easy

worn zenith
#

Ok thanks

worn zenith
#

What is the answer I’m getting?

#

4 can’t be the bill nor the $1 coin

scenic wren
#

20c+1c=84
21c=84
c=4
remember that c is the amount of coins

#

so we have 4 coins

#

b=4c=16

worn zenith
#

Sorry, I’m really bad at math. But how do I get this to the answer

#

Can you solve it so I can watch an example

#

Please

scenic wren
#

what exactly are you stuck on?

worn zenith
#

Getting b=4c=16 in to the total amount of each coin

scenic wren
#

we know c=4 right?

worn zenith
#

Yeah

scenic wren
#

ok

worn zenith
#

Oh wait

scenic wren
#

we know we have 4 times as many bills as coins

worn zenith
#

So I multiply both sides

scenic wren
#

so b=4c

worn zenith
#

Till it’s 84

scenic wren
#

we already got c

#

so we just put c into the equation

#

b=4c
since c=4
b=4×4
so
b=16

worn zenith
#

Alright

#

Now I get it

#

Thank you

scenic wren
#

^^

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hearty cipher
#

Can someone help me?

full forumBOT
hearty cipher
#

How would I simplify this?

regal gust
hearty cipher
#

Oh ok...How do I do that?

regal gust
#

So you’d apply it to each term to get
$2^3x^3y^{2^3}$

hearty cipher
#

Oh

regal gust
#

Bot troubles bearlain

hearty cipher
#

;o

glossy valveBOT
regal gust
#

There we go uwucat

#

The first and last term can be simplified further however

hearty cipher
#

What would the outcome be?

regal gust
#

So what’s 2^3

hearty cipher
#

I don't see your answer?

#

8

regal gust
#

Yep and now

hearty cipher
#

OH

#

I got it

regal gust
#

What’s y^{2^3}

#

Perfect

hearty cipher
#

y 8?

regal gust
#

So we know we have
8x^3y^2*3

atomic blade
#

$(y^2)^3 ≠ y^{(2^3)}$

#

Make sure you're asking correctly

regal gust
#

When we have an exponent to an exponent you multiple then

glossy valveBOT
#

Umbraleviathan

atomic blade
#

y^{2^3} isn't the same as (y^2)^3

#

Make sure you're asking the correct stuff

regal gust
#

My bad blobsweat

hearty cipher
#

My last question I need help on is this:

regal gust
#

Nvm

#

So

#

You’d start my multiplying them

hearty cipher
#

Sorry I was taking my dog out how do I multiply the problem?

#

Do I multiply the exponents to the number?

#

<@&286206848099549185>

#

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silent mango
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silent mango
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<@&286206848099549185>

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torn jolt
#

is sine or cosine better?

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clear lily
#

sine clearly

#

cosine is just sine in disguise

cloud shore
#

Cos is better, cos is even

#

Even is better than odd

torn jolt
#

imo sine is a bit more curvy

clear lily
#

but sin(x) = x close to 0

cloud shore
#

Engineer moment

clear lily
#

🙂

regal gust
#

Cosine obv cause it’s just sine + more ecstasy

clear lily
#

its like asking whos better, pilot or copilot

#

clearly the pilot

#

hence the copilot is a co-pilot

regal gust
#

Copilots don’t receive enough recognition

#

They have all the skills of the pilot but don’t get the fame

#

Therefore cosine is ultimately underestimated

clear lily
#

hahah

#

sine gets to do the real jobs though

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brittle zenith
#

I’m did something wrong can someone put me on the right direction

brittle zenith
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tired blade
#

is that right?

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tired blade
#

here's how it looks in a graph

twilit leaf
#

looks good

tired blade
twilit leaf
#

both of the equations are the same so yes they both work

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tranquil moat
#

i need help on Estimating Integers it's really hard and i have a quiz tomorrow think you can help me out.

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Please don't occupy multiple help channels.

deft zodiac
#

yea

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just

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stick with 1 channel

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chilly patio
#

Joe completed a trip of 503 miles in 8 hours. His speed during the day was 4 mph faster than her speed at night. She traveled 368 mi during the day and 135 mi at night. Find her speeds during the day and the night.

chilly patio
#

I'm not sure how to use the s=d/t equation to make an equation to solve for variable x.

#

sorry. youre looking at the unfilled in variable box. ignore the equations to the right

boreal marlin
#

Your unknown is the speed at night, call it x, you know the speed at day is x+4

chilly patio
#

thank you

#

im gonna solve this out quick and post my result if i could get your input

torn jolt
#

Let's see what you have

#

trip of 503 miles in 8 hours : so you can deduce the average speed

#

368 mi during the day: d for day

#

135 mi at night: d for night

#

s= d / t

#

d= ?

chilly patio
#

okay so my day speed came out to be 6.3176 and my night speed came out to 2.3176 mph..

#

that doesnt seem right

torn jolt
#

Well you can check it

chilly patio
torn jolt
#

If you do 368 mi with a speed of 6.3176 and 135 with a speed of 2.3176

#

Does it takes 8 hours to make the trip?

chilly patio
#

Here's my updated work. And I used the time equations to find the speed

#

So that wouldn't work cuz it would obviously be equal to 8

#

WAIT I'm dumb

#

Again

#

Why would time be equal to eachother

torn jolt
#

Yeah

#

why? lol

#

What is average speed with x and x+4?

chilly patio
#

63.875 i think

#

couldnt I do (308/x+4)*(135/x)=8?

#

and solve for x?

torn jolt
#

Hmm

#

It's a + but yeah

#

Total time is time day + time night

chilly patio
#

yeah i meant a plus my b

torn jolt
#

It's 368 too

chilly patio
#

?

#

what you mean

torn jolt
#

not 308

chilly patio
#

fk

torn jolt
#

just in case you wrote it 308

chilly patio
#

so uh

#

had to use quadratic equations lol

torn jolt
#

What do you find?

chilly patio
#

He doesn't want rounding. So that's what I have lol

torn jolt
#

What value is this

#

It looks wrong

chilly patio
#

the quadratic would come out to 52.65688

#

and yeah it does look wrong lol

torn jolt
#

Yeah, you can check it it's wrong

chilly patio
#

how would i check?

torn jolt
#

well (368/x+4)+(135/x)=8?

#

Try it with x = 52.66

chilly patio
#

comes out to 9

#

not 8

#

what did I do?

torn jolt
#

hmm

chilly patio
#

its correct up to the quadratic

#

hold on let me check the quadratic

torn jolt
#

yeah

chilly patio
#

MISINPUT

#

fuck

#

this is worse than coding

torn jolt
#

Not sure what you wrote

chilly patio
#

the number inside the root was wrong. I used symbolab to assist and started the problem with 308 instead of 368

torn jolt
#

Ho wait yeah

chilly patio
#

How do I get from point a to point b here?

brittle steeple
#

First, distributing

chilly patio
#

done

#

503x + 540 = 8x^2 + 32x

#

do I have to set all factors equal to zero?

brittle steeple
#

nah just get everything on one side

#

so it's in the usual quadratic form

chilly patio
#

so 8x^2 - 471x - 540 = 0

brittle steeple
#

yeah

#

then do quadratic equation, hopefully with a calculator lol

chilly patio
#

RIGHT?

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grim kestrel
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grim kestrel
#

why is it 1/4t^2 at end

#

i understand the constant and rest remains untouched

balmy peak
#

bec u have -1/4t^2

#

1/2t^2 - 1/4t^2

deft zodiac
grim kestrel
#

oh i was seeing it as a 7

#

not 2

#

my b

#

ty

deft zodiac
#

happens

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sly kelp
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sly kelp
#

can anyone tell me where i went wrong with this integral

#

instead of |2x|, its just x

proud willow
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covert sequoia
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covert sequoia
#

hello I don't know how to solve for most of these problems

#

the power to 1/3 is odd

deft zodiac
#

so first part first?

smoky wing
#

Are you familiar with the exponent rules/laws

covert sequoia
#

yes up til fractions and I get lost

#

like 1/3

#

the 2nd problem on that list

#

well pretty much everything except the first one, even if I had some examples of how you would solve those particular problems it would help me figure these out

smoky wing
#

So you know this law $(a^m)^n = a^{mn}$

glossy valveBOT
smoky wing
#

You can apply this for the second q

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torn jolt
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vast fossil
#

Use u-sub, let u = cosx

#

Also don't forget the dx

torn jolt
#

oh alr

#

ty

torn jolt
#

i got this but no minus sign

#

how come the answer has a minus?

vast fossil
#

du = -sinx dx, from here

torn jolt
#

ohh

torn jolt
vast fossil
#

Derivative of cos is -sin

torn jolt
#

oh my god

#

its late

#

i forgot its deriavtive n not integral

#

!close

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?close

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torn jolt
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torn jolt
#

Looking at a practice exam. What is the curly looking P?

fast peak
#

power set

#

(probably)

next sail
#

yes

torn jolt
# fast peak power set

Thank you. Forgot those existed. Going to do a couple practice problems to refresh myself.

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torn jolt
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torn jolt
#

I'm having some issues just understanding a bit of negation exercises.

#

Like why is b >=?

#

I understand where the > comes from as you're saying the opposite of a statement.

#

idk im being silly

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molten smelt
#

Say you collect all the cards that show a “5” [there should be 10 of them]. Imagine drawing 7 times,
with replacement, from this group of cards; what is the probability that you would will observe:
one set of three matching suits
two sets of two matching suits (that aren’t the same as eachother and not the same as the set of three)

molten smelt
#

“deck has 10 suits with normal 13 denominations” 130 cards total.

torn jolt
#

I only see 4 "5"

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torn jolt
ivory cairn
#

where are you stuck?

torn jolt
#

I think i got the first one now

#

,calc 0.0574010010

glossy valveBOT
#

Result:

57.4
torn jolt
#

57.4% right ?

#

@wild sleet Do you know how to programm a simulation for this?

torn jolt
#

You have to make a computer programm again for this?

#

nvm this is also like a programm for this

#

so is a good coinflip that i get 2 times the same number twice lets see

#

,w 7 random numbers between 1 and 10

torn jolt
#

,w 7 random numbers between 1 and 10

torn jolt
#

Yep

#

nah its 57% to get one number trice

#

,w 7 random numbers between 1 and 10

torn jolt
#

why dont i get it

#

,w 7 random numbers between 1 and 10

torn jolt
#

did i calculate it wrong?

#

,w 7 random numbers between 1 and 10

torn jolt
#

last roll

#

,w 7 random numbers between 1 and 10

torn jolt
#

like 10 times but no number three times

torn jolt
#

times 1000

#

,calc 0.02296*1000

glossy valveBOT
#

Result:

22.96
torn jolt
#

how do i solve b)?

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@torn jolt Has your question been resolved?

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@torn jolt Has your question been resolved?

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scarlet galleon
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scarlet galleon
#

sorry having a hard time understanding how they got U and V

#

directino vector

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@scarlet galleon Has your question been resolved?

proven jay
#

@scarlet galleon

scarlet galleon
#

ye

#

@proven jay

proven jay
#

Can you find a vector lying in the plane?

scarlet galleon
#

[-5,1,0]

#

[0,-2,1]

#

subtract it to get a vector?

scarlet galleon
#

@proven jay

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humble steppe
# scarlet galleon

Express RHS as a matrix-vector multiplication, then u and v are just s-column and t-column in the matrix.

The reason that direction vectors can be found in this way is due to the “geometric meaning” or context of the matrix 🙂

scarlet galleon
#

O

scarlet galleon
#

@humble steppe sorry one thing

#

so I can always find direction vector like this given 3 parametric equations right

humble steppe
scarlet galleon
#

i see

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merry atlas
#

Could someone help me make sense of this rational partitioning problem? Might be mistranslating that, but the problem is to rewrite this rational polynomial as the sum of two rational polynomials

deft zodiac
#

nani

#

cant u just use 0+itself

merry atlas
#

On this form, except I don't have enough constants in the rightmost rational

deft zodiac
#

oh