#help-28

1 messages · Page 10 of 1

rapid laurel
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art of solving problem

wise widget
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Can’t you put the function and the inequality together into an inequality equation and simplify or something?

rapid laurel
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this question is supposed to use the CS inequality,,

wise widget
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What’s that?

rapid laurel
wise widget
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Woahhhhwwhaat the

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What’s Cs stand for?

rapid laurel
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its really just like(a^2+b^2)(c^2+d^2) is greater and equal to (ab+b*d)^2

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as an example

wise widget
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Ahhh

torn jolt
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And there’s the vector form of it too which is confusing

rapid laurel
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^

wise widget
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Ooh La la sounds interesting

torn jolt
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Is it proven by Fibonacci thing?

rapid laurel
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hmmmmm

deft zodiac
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oh no fairylog

rapid laurel
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what happened to her😭

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i miss her

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we were gonna play apex together, but she just left me

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so suddenly

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@torn jolt Has your question been resolved?

torn jolt
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.clode

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.close

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untold lance
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@karmic zinc here would be better, just so we dont get in the way of the other person

untold lance
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oop

karmic zinc
untold lance
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well I'll explain it here

karmic zinc
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Alright

untold lance
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so, what sort of triangle has 2 sides of equal length?

karmic zinc
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Isoceles triangle?

untold lance
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can you not?

untold lance
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so, what else does that mean about the triangle? Isosceles triangles have congruent sides and...

karmic zinc
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Equal angles

untold lance
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on the two base angles, yep

untold lance
karmic zinc
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180

untold lance
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so, the rest of the angle on that line ACD would be shown by the difference of what?

karmic zinc
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109?

untold lance
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yep

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good job

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was that your only question or do you have any more?

karmic zinc
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It didn’t work…

untold lance
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hm... you put in m<BCD = 109 right?

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seems like theres a box for BCD as well

sour mauve
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that should be right

untold lance
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yeah

karmic zinc
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Yup

untold lance
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and you selected a reason right?

karmic zinc
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Is the reason base angle of an isosceles triangle?

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Correct?

untold lance
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yep

karmic zinc
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Yeah I put that

untold lance
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wierd

karmic zinc
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It says

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BCD is not a base angle of any isosceles triangle

untold lance
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for reason, is there anything about subtraction of angles or straight angles?

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it could be that

karmic zinc
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I think we have to show the steps on how we got the answer for BCD

untold lance
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oh I see. so say first how you know what BCA is, then what BCD is based off of that. didn't realize it was a geometric proof

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😅

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anyways, hope that helps you but I have to head to sleep, I won't be getting any sleep at this rate. Have a good night, good luck

karmic zinc
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Appreciate it

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bleak haven
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I am trying to write an equation for this graph. I think this has to be a piece wise function (please let me know if there's another way to write this out without using a piecewise function). I have attached what I have so far but I couldn't get the middle part.

bleak haven
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<@&286206848099549185>

wise widget
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Looks like an absolute value combines with the absolute value of a radical

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Oh it looks like the absolute value of a radical, exactly!

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Except shifted some

bleak haven
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I tried this but it's not curving the right way

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I also tried this which looks the closest but its not hitting (3,0) and (5,0) exactly like in the problem

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I think my slope of 1/12 is wrong but idk how to find the right one

wise widget
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The graph u showed me look a lot like a radical with two sides. That tells me that even though a radical is normally just one sided, an absolute value inside the radical will allow it to be double sided, going both left and right

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Secondly the radicals in the graph get reflected upwards when they touch the x axis, as if they were reflected over the x axis from the negative region underneath. It tells me that there should be a absolute value over everything

bleak haven
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I think i got it?

wise widget
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Negate the entire expression, put over everything an absolute value, and does it work?

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Actually just put an absolute value over everything is fine too

bleak haven
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which expression are you talking about? the third one?

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does what I have not work?

wise widget
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Yeah the third one

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If u absolute value your third equation, you won’t need the first or second

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Just a single equation that can draw cool stuff

bleak haven
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thank you!!

wise widget
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Beautiful [insert chefs kiss]

bleak haven
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would this be a radical as well?

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someone told me to try piecewise functions but i wasn't sure if there was a way to do this in a single equation

wise widget
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Hmm what if it seems linear? Can u check that for me?

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Damn ok I think it could be another darn radical with an absolute

bleak haven
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I was just thinking how it looks like one side of the first problem

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how do i make it so only one side is showing?

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would i just note it as x≤3 ?

wise widget
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Um remove the absolute value in the radical

bleak haven
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it removed the side of the graph i needed

wise widget
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Hmm

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Do you know how to flip a function over the x axis?

bleak haven
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yes

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got it

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thank you!

wise widget
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No problem!

bleak haven
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torn jolt
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@torn jolt Has your question been resolved?

rose rain
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Have you tried drawing a diagram?

torn jolt
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yes

tall juniper
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Since a full circle's 360° and there's four faces, the angles at the top should be 90° each, right?

torn jolt
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i think so

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unkempt coral
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unkempt coral
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can someone help me with this?

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@unkempt coral Has your question been resolved?

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@unkempt coral Has your question been resolved?

rough plaza
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hello! @unkempt coral
which part of the question are you stuck on?

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@unkempt coral Has your question been resolved?

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dense arrow
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Quick question do I divide sin42 by 120 to get answer

warm abyss
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120/sin 42

dense arrow
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Oh ok

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Thank you

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upbeat haven
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upbeat haven
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Sorry for same question again, but how are both maps going from $$R^s -> R^m$$

glossy valveBOT
brave blaze
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h is map from R^s to R^r
g is a map from R^r to R^n
f is a map from R^n to R^m

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so (f o g) o h is a map from R^s to R^m

upbeat haven
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(f o g) o h = h(f(g))?

brave blaze
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hell nah

upbeat haven
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okay good haha

brave blaze
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they basically told you what it is equal too

upbeat haven
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OOO

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I see

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And how does this answer the law that (AB)C = A(BC)?

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Like i see that the ending size is the same

brave blaze
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did you study abstract algebra ?

upbeat haven
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nah fam

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this from computer science math

grand yacht
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if you do don't learn it from dummit and foote

upbeat haven
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what

grand yacht
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aa

brave blaze
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Well i dont know how to explain in it to you, but associative property for an operation * is like this :
(x*y)*z = x*(y*z)

upbeat haven
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yea makes sense for regular numbers

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and we showed that the size of the resulting matrix will be the same from 3.20 right?

brave blaze
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the operation sign for applications is o

upbeat haven
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but how do i know that the result is the same

brave blaze
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well matrices represent applications

upbeat haven
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wdym by that

brave blaze
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kinda hard to explain it without talking about vector spaces

upbeat haven
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welp lemme read up on that then?

brave blaze
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if you can understand everything, then good

upbeat haven
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thanks man

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spare tiger
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how many permutations of the letters of the word JUMPER do not start with a J?

grand yacht
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how many permutations in total?

warm abyss
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Maybe try: How many permutations are there in general - how many are there with J first

spare tiger
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the ones that do not start with letter j

grand yacht
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how many permutations are there without any conditions?

spare tiger
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how do i do find the number of permutations with j first

grand yacht
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do you agree that the starting letter could be anything with equal likelyhood?

spare tiger
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how

grand yacht
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just fix j to be the first letter

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and construct the rest of it

spare tiger
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6!-5!?

grand yacht
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👍

warm abyss
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Yes

spare tiger
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ah

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thank u

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empty sapphire
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Abstract Algebra proof check. This seems wrong or a stretch, but thought?

empty sapphire
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nvm I see how it's wrong

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spring pelican
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Given that y(1)=1 I'm supposed to find y'(1). I'm havent really done much derivation like this, am I supposed to see something with y(1)=1 or just derivate it somehow?

deft zodiac
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hii

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um is y(x) like

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y is a func of x

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or y * x

spring pelican
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function of x

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I think atleast...

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yeah it doesnt make sense if its y * x

deft zodiac
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,w derivative of y^y

deft zodiac
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take the derivative to try to find dydx

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dy/dx

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which is

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y'

spring pelican
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but y^y didnt get me y'? or do I need to do it again with log(y)?

deft zodiac
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e^ln(y^y) = y^y

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yea?

spring pelican
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yeah

deft zodiac
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e^(ylny) = y^y

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u can just use ur um

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diff rules on that i think

spring pelican
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ohhhh I think I see what you mean the core rule or idk what its called in english

deft zodiac
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well

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i havent done diff in v long as well

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hahhaa

spring pelican
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that will be quite complicated though, maybe theres a shortcut or something smart I dont see

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I'll try it though and come back if I cant figure it out hahah, thanks for the help

deft zodiac
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d/dy e^(ylny) = (lny + 1) e^(ylny)

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just cuz

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d/dy ylny = lny + 1

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yea

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then i think u can do it from there

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then ud get some expression with

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dy/dx = stuff in x and y

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then sub in x=1 n ud get

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1 = 1 + stuff in y

spring pelican
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I also have the 5 in y^5y, I'm so rusty with derivation hahah but yeah the explination makes sense I just have to get the derivation right, again thanks

deft zodiac
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ayy

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glad prairie
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I wander how to solve that

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glad prairie
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I think it's something about linearized an expression but idk

torn jolt
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perhaps you could you trig identities like double angular formula?

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or use half angle formula

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convert them to tanx

glad prairie
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hum

glass crystal
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it looks like youd have to linearize this

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its long though

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like use the def of cos and sin from exponential

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and developp everything

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join as much terms together

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and integrate each

glad prairie
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i think before doing that there's a way to simplify the expression

glass crystal
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maybe there is a smarter way

sharp vine
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you can use Pythagorean Identity and then sin/cos reduction formula but it also takes a long time

glass crystal
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teah its the same process one is doing it directly

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and one is using the formulas that are obtained doing this

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like the cos^2 to cos2x formula is directly a linearization of cos^2

glad prairie
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if i remember it correctly then : cos(2x) = 2sin^2 - 1

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glad prairie
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pearl dirge
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Hello I need help calculating this figure area and perimeter

modern sentinel
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not enough information

glass crystal
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yeah we need more about how this is constructed

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its not clear as it is

pearl dirge
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Well im pretty sure the figure is made from square which is 2 * 2 and two circles which radius are 2

glass crystal
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oh ok

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i think i can get it

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maybe try to do a clear drawing involving everything first

pearl dirge
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im thiking the peremeter should be 2+2+3/4 * 2 * pi * r

glass crystal
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yeah

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replace r and simplify then

pearl dirge
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k, thx buddy

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really glad found this server, bcz learning hard stuff atm

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trigonometry and etc ;D

glass crystal
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for the area there is a trick

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if you make a good drawing of the situation you will find it

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its not that hard

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compact wasp
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Given that P is a projector, how would I prove that $\parallel P \parallel_2 \ge 1 with equality iff P is an orthogonal projector based on the format \frac{\parallel Px \parallel_2}{\parallel x \parallel_2}$?

glossy valveBOT
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Maxerature

compact wasp
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Given that P is a projector, how would I prove that

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$\parallel P \parallel_2 \ge 1$

glossy valveBOT
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Maxerature

compact wasp
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with equality iff P is an orthogonal projector based on the format

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$\frac{\parallel Px \parallel_2}{\parallel x \parallel_2}$

glossy valveBOT
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Maxerature

compact wasp
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I can get to $\parallel x - (I-P)x \parallel_2 \ge \parallel Px + (I-P)x \parallel_2$

glossy valveBOT
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Maxerature

compact wasp
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But I'm stuck from there

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@compact wasp Has your question been resolved?

compact wasp
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<@&286206848099549185>

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@compact wasp Has your question been resolved?

compact wasp
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<@&286206848099549185>

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@compact wasp Has your question been resolved?

gritty rose
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glass trench
#

Hey all

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glass trench
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I am suuuuuuper lost

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I understand the pigeonhole principal. But honestly, this solution is not super intuitive

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Something something binary string?

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Okay... I might be starting to get it...

ivory cairn
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It’s not binary strings. It’s residue classes

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Each of 2^k must be in a residue class. Since there are only m of those, at least two of 2^k must be in the same class.

glass trench
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Yes — so I've managed to figure that out

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And I checked modulus arithematic properties (I'm a little rusty) and I can see how the last step produces something along the lines of 2^(k-l) == 0 mod m

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Which means that 2^(k-l) divides m. Where does the -1 fit in

ivory cairn
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check your arithmetic again

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$2^k-2^l = 2^l(2^{k-l}-1)$

glossy valveBOT
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Zybikron

glass trench
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Oh good christ

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XD

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And because it can be written in the form ca=b where c=2^l, a=2^(k-l) - 1, and b=m

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The statement is proved

ivory cairn
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not quite.

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ca = 0 mod m, So ca | m

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er, no

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so you need to argue why m doesn't divide 2^l, and it's 2^(k-l)-1

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for example, 9*4 is 0 mod 6, but 6 doesn't divide 9 or 4. So why do you know m divides 2^(k-l)-1

glass trench
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Okay, one thing I want to clear up

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I'm trying to divide into m

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Right?

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So I want ca=m

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Not cm = b

ivory cairn
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You have ca= 0 mod m. Which implies that ca is a multiple of m, or that m divides ca.

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You’re trying to show that m divides something

glass trench
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The division algorithm: b = ca + r. If r is zero, then a divides b perfectly.

ivory cairn
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Yes. But b is not (necessarily) equal to m. The best you can say is that it’s a multiple of m

glass trench
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XD I'm going to circle back in on this

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My brain is too fuzzy right now for all of these variables

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I get it — I just can't quite put it into words

ivory cairn
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And again, you’re trying to show b divides a, not the other way around

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(Using your variables)

glass trench
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Thanks bud 🙂

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modest flume
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What is the meaning of R^n? Someone said it is n vector basis, someone said n dimension. Is n-dimension same as n vector-basis?

Thank you.

torn gust
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if the n vectors are all linearly independent yea, it's the same

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@modest flume Has your question been resolved?

modest flume
torn gust
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yea, those are different things

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R->R4 vs. R2->R4

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gonna be different sized matricies etc.

modest flume
torn gust
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like this sorry

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the space on the left there means "the input is 1 real variable"

modest flume
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In my understanding LHS is describing the parameter of the function

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But why we care about R-> R4 ? not just look at input and output dimensionality each of the time? @torn gust

torn gust
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not sure what you mean, we care that it's 1 dimension of inputs and 4 dimensions of outputs

modest flume
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We care about dimensionality of the input, also care about the dimensionality of the output,
Do we need to care about dimensionality of them in a pair?

#

or, what is the domain for this topic? I am still very confusing, so might have to study these concepts all at once for completeness.

torn gust
#

the domain is the left side, R

modest flume
torn gust
#

lool

#

linear algebra

#

for stuff like vectors and vector functions of R^n spaces

modest flume
#

I could have (x,y) (2 dimensional) coordinates, but could have, eg, R^4 vector space if g(x,y, xy,1)

#

That's quite weird to count the constant "1" as one dimensionality 😂

torn gust
#

it's basically the same yea

#

for that picture, 1 is in the x-axis, x is in the y-axis, x^2 is in the z-axis, and x^3 is in the w-axis

modest flume
torn gust
#

the parameters or "phase space" is 2D yea, but when you draw it out it'll probably be in more dimensions than 2

#

like instead of a 2d plane it might be some wavy surface in 3D

#

this study area could also be differential geometry

modest flume
#

reading

#

@torn gust which chapter? thank you

torn gust
#

uh probably just 1.1 in that book

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torn jolt
#

how do you parameterize an equation by itself, such as 3x-5y-4z=0?

torn jolt
#

I know how to do it if given as equality statements like x+2=y-1=-z

#

but not as a normal equation

#

I have no work but this isnt a homework question

woven snow
#

you should look up parametric equation of planes

torn jolt
#

okay

woven snow
#

i’ve forgotten most of it

#

but that should help you

torn jolt
#

it already has, i didnt know what to google and my other searches gave bad results

#

thank you again

woven snow
torn jolt
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woven snow
#

no problem SCgoodjob2

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pale ermine
#

for a rational function, how can you tell the if the domain and range will lead to all real numbers or to infinity?

sleek apex
#

as long as it doesn't vertically asymptote

#

You can then determine it goes to infinity, infinitely

pale ermine
#

do you mean by using the vertical line test?

sleek apex
#

huh

#

What is the vertical line test

pale ermine
#

what do you mean by it doesn't vertically asumptote

sleek apex
#

do you know what an asymptote is

pale ermine
#

it's an invisible line that doesn't get touched

deft zodiac
#

to test if a fn is onto

#

one to one

#

1 to 1

sleek apex
deft zodiac
#

is for inverses

#

bit diff

sleek apex
deft zodiac
#

yes pengu

sleek apex
#

if a function asymptotes its domain will stop there

#

Not going into infinity

#

Unless its like the function 1/x

#

Where its just an essential discontinuity

#

but then the domain is not all real numbers

pale ermine
#

any other scenarios where it'll lead to infinity?

sleek apex
#

where it won't?

pale ermine
#

for hw problems, I need to additionally label the domain and range as all real numbers or infinity

sleek apex
#

square root graphs

#

sideways parabolas

#

circles

#

many many many things

#

domain restrictions

pale ermine
#

so what u just said will NOT lead to infinity but all real numbers correct

sleek apex
#

It has to lead to infinity to be all real numbers

#

But leading to infinity doesn't necessarily mean all real numbers

pale ermine
sleek apex
#

you can have discontinuities in the graph

#

so while it does indeed lead to infinity, its not all real numbers

#

Let's say 1/x

#

All real numbers except 0

#

since 1/0 is undefined

pale ermine
#

i see

#

when you say discontinuities you were referring to like sideway parabolas and square root graphs correct>

sleek apex
#

nope

#

That's something different

#

@pale ermine

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zenith pecan
#

The derivative of this should be fx/dx = (x+dx)^2 - (x)^2 / dx right?

zenith pecan
#

So then I would get x^2 + 2(x)dx) + dx^2 - x^2 where dx^2 -> 0

#

Divided by dx

#

And then I would be left with 2(x)?

rapid rain
zenith pecan
#

So then I am wondering

#

When I am looking for the derivative f'(x) where f(x) = x^3

rapid rain
#

yes, you apply the same formula

zenith pecan
#

Right

#

But what are the algebra steps exactly

rapid rain
#

[f(x+dx)-f(x)]/dx = [(x+dx)^3 - x^3]/dx

zenith pecan
#

Because I see I should get this

rapid rain
#

develop (x+dx)^3

zenith pecan
#

x^3 + 3(x)^2dx + 3(x)dx^2 + (dx)^3 - x^3

#

So then I would be left with 3(x)^2dx / dx

#

Would that then cancel to 3(x)?

#

Because the power is on the 3(x) not on the dx

rapid rain
#

3x^2

zenith pecan
#

Ah I see

#

So the notation is df/dx where f(x) = x^n, = nx^n-1

#

Ok that makes sense now

rapid rain
#

yes

zenith pecan
#

Thank you

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slate relic
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slate relic
#

How do I find the odd one

hybrid geyser
#

find the gradient of each line

#

since there’s 2 pairs of perp lines

#

u can use $m1m2=-1$ to help

glossy valveBOT
#

swaggofishballs

slate relic
#

Yeah

deep flint
#

i'm guessing what they mean by "odd one out" is that two of those equations specify one line, two specify another line (perpendicular to the first one) and the last, the "odd one", specifies a third line

#

oh, no, not quite, each of those is a distinct line, but two of them are parallel to each other, two more are parallel to each other and each perpendicular to the first two, and the fifth stands alone, like a cheese

slate relic
#

??

hybrid geyser
#

basically u have 2 lines perp to each other

deep flint
#

i agree with swaggofishballs, you should find the slope of each line

hybrid geyser
#

and another 2 perp to each other

#

one isn’t

slate relic
#

Yes

deep flint
#

two of them will have one slope, two will have another that is perpenculiar, and the fifth will be "different"

slate relic
#

But I can just make the line perpendicular by using the m1xm2 method

hybrid geyser
#

m1m2 doesn’t MAKE the lines perp

deep flint
#

for a line in the form Ax + By = C the slope is -A/B

hybrid geyser
#

ya basically just rearrange ur eqns in the form $y=mx+c$

glossy valveBOT
#

swaggofishballs

slate relic
#

Yeah

deep flint
#

you don't need to do that, though, if you just use that above formula

hybrid geyser
#

I can go thru one w u if u want

hybrid geyser
deep flint
#

so like for the first one, a, A = 3 and B = 5, so tjhe slope is -A/B or -3/5

hybrid geyser
#

if u don’t wanna memorise

slate relic
hybrid geyser
#

omg cute handwriting!

#

ya seems fine

#

where’s the last one?

#

oh I see it

slate relic
#

Yeah

deep flint
#

note that some of the equations are "backwards" , with y before x

slate relic
#

Yeah

deep flint
#

which is a dirty little trick

slate relic
#

True

hybrid geyser
#

hehehhee

#

okie so do u know which is the odd one out

deep flint
#

it'll be the one whose slope is unlike any of the others

slate relic
#

b ig? Since its different

deep flint
#

a and c are a pair

#

b and e are a pair

#

wait, i may have messed up

slate relic
#

Wait how is it a pair for b and e

deep flint
#

i'm doing these in my head and i might have flipped a sign

slate relic
#

Yea

hybrid geyser
#

ya it’s confusing dng it in my head HAHAHA

#

i have no energy to grab paper

deep flint
#

yup, i did sorry

slate relic
#

A and c is a pair since -3/5 and 5/3

#

D and e is a pair since 2x and -0.5

deep flint
#

d and e are a pair

#

that leaves b standing alone

slate relic
#

And reciprocal stuffs

#

Yeah

hybrid geyser
#

🤩

slate relic
#

Oh wow

#

I've mistaken the question

deep flint
#

frankly it's a bad question so i don't blame you

slate relic
#

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torn jolt
#

Hi. I need help calculating how many points I have. My average grade is 6.1, but it's not listed on the table. Could you figure out how many points I have?

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torn jolt
hearty lynx
#

Oh you need about 100 points

torn jolt
#

7 starts with 80 points and 4 starts with 46 poiints

hearty lynx
#

70-100 points

torn jolt
#

@hearty lynx thank you

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atomic delta
#

How would you prove by contradiction: There is no smallest irrational number.

What I have tried so far is: Suppose on the contrary that there is a smallest irrational number, call it x. Then x/2 is a smaller number, and so must be rational. This means that x/2 = m/n for some integers m, n, where n != 0. But then we get x = 2m/n, where 2m and n are integers, so x is rational and we get a contradiction.

atomic delta
#

Is this proof correct and does it account for it not stating: There is no smallest POSITIVE irrational number

sweet ingot
#

Say x=-pi

#

Is x/2 then smaller than x?

atomic delta
#

no its not

#

so how would i reword it

#

would I just do absolute value?

sweet ingot
#

No you can’t just use abs value

#

Either split up in cases if positive or negative

#

Or say you know -pi is irrational and negative

#

So the lowest irrational number must be negative

atomic delta
#

does it also account for if it is 0 since it does not state positive or negative irrational numbers

sweet ingot
#

0 isn’t irrational is it

atomic delta
#

haha no its rational since any number can be divided by 0 and still equal 0 lol

#

my bad lol

#

but would you rephrase my proof above

#

how would*

sweet ingot
#

Either of the two ways I said

atomic delta
#

okay thanks

#

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mortal owl
#

i’m confused when it states find f(a), and f(a+3) on my homework LOL how would i find f(a)? attached is what i have so far, and that’s when i solved for f(-2). thank you so much:)))

toxic elbow
#

why are you dividing by -2 ?

#

in the 2nd photo

#

and in the first photo

mortal owl
#

to be completely honest i do not know LOL i plugged and chugged

#

math is not my strong suit

toxic elbow
#

well with functions

#

when you are said to evaluate smth like f(-2)

#

u did the right thing by subbing in the x as -2

#

but f(-2) is a value itself, you aren't multiply f by -2

#

you know how f(x) is the same thing as y?

mortal owl
#

yes!

toxic elbow
#

and when u sub in an x val to find y

#

you dont multiply y with anything

#

?

mortal owl
#

yes

toxic elbow
#

it's the same idea here

#

f(-2) is the same thing as y when x=-2

mortal owl
#

so i would just sub in -2 and solve for f(x)=2?

#

rather than just trying to plug and chug

toxic elbow
#

no

#

here take this example

#

f(x)=4x+2

#

what is f(-2)

#

what is the first step ur doing btw

mortal owl
#

i’m putting 4(-2)+2

toxic elbow
#

yeah and then simplify

mortal owl
#

got it

#

so -6?

toxic elbow
#

yes

#

so now do that

#

with the functions given in the photos

mortal owl
#

got it

#

9

#

so f(-2)=9?

toxic elbow
#

mmm

#

what is a negative number squared always?

mortal owl
#

a positive?

toxic elbow
#

yes

mortal owl
#

so for that second one it’d be positive rather than negative

toxic elbow
#

it should be all positive numbers

#

being added

mortal owl
#

aaaa

#

17!

#

no no

#

give me

#

one second

#

ok so a negative number squared would be a positive so it’d end up being 2+4, which would be 6?

#

on that second one

#

wait

#

jk

#

i’m having a big blonde moment

toxic elbow
#

he doesn't know that 17 is correct NervousSweat

#

have some confidence

#

4+8+5

mortal owl
#

okay okay, so f(-2)=17!

toxic elbow
#

well it's 17, pro tip in math, never use exclamation mark, that's a factorial symbol

mortal owl
#

LOL thank you

toxic elbow
#

17! would be 17 time 16 times 15 all the way to 1

mortal owl
#

so would 17 be my f(a)?

toxic elbow
#

f(a)

#

is basically

#

same concept

#

but you replace x with a

mortal owl
#

got it!

toxic elbow
#

if they havent given some value or way to find a

#

and x is replaced by a+3 for the other one

#

f(whatever goes in here) basically means to replace x by "whatever goes in here"

mortal owl
#

got it

#

so i wouldn’t be able to simplify the f(a) further than a^2-4a+5

toxic elbow
#

should be unless there is some given method to getting a, but the problem doesnt say anything so i would just leave it at that

mortal owl
#

perfect! and then the next part of that segment would be a+3^2-4a+3+5

toxic elbow
#

yeah, be careful with expanding (a+3)^2 tho

#

it is NOT a^2+3^2

mortal owl
#

yes, would it only be 3^2?

#

therefore the answer would result in a+9-4a+8?

toxic elbow
#

mm

#

no

#

remember the x^2 becomes (a+3)^2

#

so you have to expand that properly

mortal owl
#

aaaa

#

got it

#

a^2+6a+9 (?)

toxic elbow
#

yeah

#

that's (a+3)^2

#

and now u need to finish simplifying with rest of equation

mortal owl
#

therefore, a^2+6a+9-4a-12+5

toxic elbow
#

should be

mortal owl
#

fr it!

#

got**

#

i’ll attempt the next one and show my work

toxic elbow
#

i gtg, if you want me to check your work just dm it with the original problem and i'll check when I can

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rigid wagon
#

So I have a number (-91) and I need to find out what makes that number an integer? I'm trying to find the definition of integer but online all I can find is whole number and -91 isn't a whole number.

fair pulsar
#

certain sources say whole numbers are natural and 0 but i've always learned its the same as a whole number and on most sites it says that

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tulip marlin
tulip marlin
#

I don't get why as the price gets large, it's more likely the option will be exercised

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prime furnace
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prime furnace
#

can someone explain to me why the answr is B?

robust slate
#

b/c the only elements shared with that options and the first set is pi

prime furnace
#

ah okay

#

thank you

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tribal iris
#

My question: If E and F are independent events with P(E) = 0.25 and P(F) = 0.29 then what is P(E’ u F)

tribal iris
#

I’m stuck with not knowing the formula for P(E’ u F)

rocky vale
#

Is it just the complement that's throwing you off?

#

The E' ?

tribal iris
#

Yes

rocky vale
#

E' means E does not happen

#

So if P(E) is 0.25, P(E') is 0.75

#

That's all

tribal iris
#

Right I understand that

#

But in the union

#

I’m unsure how to calculate it

#

It’s not .75+.29

rocky vale
#

Right

#

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

glossy valveBOT
#

tatpoj

rocky vale
#

Are you familiar with this?

tribal iris
#

Hmm I thought AuB was just A+B

rocky vale
#

Well

#

A∩B is A and B. As in, they both happen

tribal iris
#

AnB= A*B right?

rocky vale
#

yes

tribal iris
#

Yesss

rocky vale
#

That is a simpler case you may have studied first

tribal iris
#

Hmmm

#

Interesting

#

I didn’t learn that

#

I cannot find anything about A’uB anywhere online

#

Driving me crazy

#

@rocky vale lmfao

rocky vale
#

You don't need a formula specifically for A' U B

#

Since you know E, you know E'. Just plug that in instead

tribal iris
#

Hmm

#

So a’ + b - AnB?

rocky vale
#

You want to find P(E' U F)

#

So take this:

#

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

glossy valveBOT
#

tatpoj

rocky vale
#

And plug in E' for A, and F for B

#

$P(E' \cup F) = P(E') + P(F) - P(E' \cap F)$

glossy valveBOT
#

tatpoj

tribal iris
#

0.8225

rocky vale
#

Yep

tribal iris
#

Tysm!

rocky vale
#

👍

#

no problem

tribal iris
#

Do I close this and ask another question or do I keep this open to ask another question?

rocky vale
#

You can ask another question here

#

Either way is fine

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outer prawn
#

Let X be a subspace of Rk and E ⊂ X be a set with the property that
every sequence of points in E has a subsequence that converges to a point
in E. Prove that E is a compact set.
Any idea how can we do this?

native flicker
#

Assume that E is not bounded.
For every n € N there exists x_n € E such that |x_n| > n

#

Consider sequence {x_n} where you let x_n_i be subsequence of x_n

#

Can u start from here

topaz valley
#

thats just the definition of a sequentially compact set thonk

#

what is there to prove thonk

native flicker
#

U want me to explain

outer prawn
#

yes please

#

I think E should be bounded

native flicker
#

Man I’m outside hol on

topaz valley
#

what is your definition of compact?

native flicker
#

Getting paper

topaz valley
#

theres

#

way too many

outer prawn
topaz valley
#

no like

#

thats just a theorem

#

what is the definition of compact

#

in your text

outer prawn
#

A subset K of a metric space X is said to be compact if every
open cover of K contains a finite subcover.

topaz valley
#

oh my

#

cover compact

#

okay so this is the proof that sequential compactness = cover compactness (in metric spaces)

outer prawn
#

Can I assume that E is closed?

topaz valley
#

no ofc not

#

do you have a theorem

outer prawn
#

if I assume E is closed and it is bounded because it contains subsequence that converges then it uses theorem 2.41 to prove it is compact

topaz valley
#

that states sequential compactness implies closed?

#

well what theorems can you use

outer prawn
#

Every bounded sequence in Rk contains a convergent subsequence.

native flicker
outer prawn
#

as E contains convergent subsequence it is bounded, can also be proved using cauchy subsequence

native flicker
#

See from here it’s not done yet

topaz valley
#

like

#

you're trying to show cover compact

#

what results do you know to imply cover compactness

native flicker
#

Therefore we have shown that E is a closed and bounded subset of R^n

By heine borel, E is compact

#

Is this what ur looking for ?

full forumBOT
#

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icy marten
#

Anyone know how to solve this correctly?

full forumBOT
torn jolt
#

,rotate

glossy valveBOT
whole marsh
icy marten
#

(8,-5) is a point on the graph before translation and I'm trying to find the corresponding point after translation.

#

<@&286206848099549185>

lofty sigil
#

whats the translation

#

oh its above nvm

torn jolt
#

What if you use X=-x+1

icy marten
#

Does the -2 effect the x or nah?

torn jolt
#

wdym

#

rewrite y with X=-x+1

lofty sigil
#

i think?

#

i havent done transformations in a while

lofty sigil
#

shift* not shit 💀

torn jolt
#

Well i don't know about transformations but you know -5=f(8) so with x=-7 you can calculate y and find the point (-7,y)

lofty sigil
#

that could also work

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#

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torn jolt
#

Can anyone check if I graphed these right

full forumBOT
torn jolt
#

,rotate

dense lake
torn jolt
#

Well what did I do wrong?

dense lake
#

maybe you included +3 in the root?

torn jolt
#

🤔

#

Wym

dense lake
#

nvm, I just checked and that graph doesn't resemble yours.

torn jolt
#

Oh lol

#

Yeah I was a bit confused 😅

#

Yeah and how would I state a function in 2 ways the question c part

dense lake
dense lake
#

and you would need to solve for x. I never been asked something like that, so it seems pretty weird to ask

torn jolt
dense lake
#

What I meant, is that it's maybe it's asking to state the equation that is equal to that

dense lake
# dense lake

since f(x)^-1 is the same as y^-1, then it's the same as g(x) here

#

basically the whole equation but with negative 1 as exponent

torn jolt
#

🤔

dense lake
#

but yeah, it seems unlikely they are asking for that

torn jolt
#

Yeah

#

<@&286206848099549185>

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#

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torn jolt
#

.close

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#
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eternal harbor
full forumBOT
#

Please don't occupy multiple help channels.

eternal harbor
#

by differentiation and combination, isolation method anf by determinants
I have tried to differentiate the given equations according to the number of arbitrary constants. but I don't know how to eliminate the arbitrary constants using algebraic manipulation.

#

<@&286206848099549185>

#

.close

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eternal harbor
#

.reopen

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steel stone
#

Help pls

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steel stone
smoky wing
#

First one: product of three same numbers equal -27

full tundra
#

sure, so what 3 numbers multiplied together equal 27?

steel stone
#

3 in the cube

smoky wing
#

Okay just put a minus there cause it’s -27

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celest quiver
#

How to integrate sin(x/2)+cos(x/2) dx?

full forumBOT
hot herald
#

chain rule

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#

@celest quiver Has your question been resolved?

torn jolt
#

split them and both are chainrule

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storm nest
full forumBOT
storm nest
#

Not sure where to start with this one

hot herald
#

were you able to do at least a) and c)?

storm nest
#

Nope

hot herald
#

do you understand basic function notation?

storm nest
#

I’ve never seen this type of question before

storm nest
hot herald
#

sry typo

storm nest
#

Depends what basic function notation is

hot herald
#

if you were given
g(x) = x^2 + 6
would you be able to find g(3)

storm nest
#

Like (3)^2+6?

hot herald
#

yes

storm nest
#

Yep

hot herald
#

it is implied that the image is a graph of y = f(x)

storm nest
#

Yeah

hot herald
#

f(-1) will simply be the y-coordinate on the graph where x=-1

storm nest
#

Ok makes sense

#

What about the f’(x) questions?

hot herald
#

that's related to the slope at that location

#

draw a rough sketch of the tangent line at the specified location

#

note that you are not required to determine the actual slope,
just whether its positive or negative which should be quite clear

storm nest
#

Is this what you mean?

hot herald
#

the position of your light is a bit off

storm nest
#

Better?

hot herald
#

you want the line tangent to the point on the curve where x=3
and NOT a tangent of the curve that intercepts the x-axis at 3

#

somehow that's worse

#

the line looks even further away from the curve and doesn't look like it has any intention of being a tangent line at all

storm nest
#

Oof

hot herald
#

you're line should be going through that red point

storm nest
#

How do I know where it should tilt towards?

hot herald
#

draw the line that just touches the curve at that point

storm nest
#

Surely this time

hot herald
#

no

storm nest
#

Absolute bruh moment

hot herald
#

i suggest looking up tangent to a curve

storm nest
#

Yeah I’ll do that

hot herald
#

you want something closer to

storm nest
#

Ohhh I see

hot herald
#

#bookruined

storm nest
#

Yeah rubbed a bit too hard

#

How does this indicate whether the value is a positive or negative?

hot herald
#

but yeh, that looks better

storm nest
#

Great

hot herald
#

is the slope of that line positive or negative

storm nest
#

Negative

hot herald
#

yes

#

the slope of the tangent at x=3 is negative,
hence f'(3) is negative

storm nest
#

Ohh makes sense

#

Thanks for the help

#

.close

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#
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#
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deep flint
#

you're supposed to wait 15 minutes before pinging for helpers

#

there's no rule that a function cannot cross its horizontal asymptotes

#

asymptotes refer to a function's behavior at very large (positive) or very small (negative) numbers. the function may cross its asymptote "near" the origin as long as, in the limit case, it approaches, but does not reach, the asymptote

#

yes, vertical asymptotes will never be crossed because the function is undefined at such points

#

but it is possible for a function to cross a horizontal asymptote

#

this is a graph of a curve that crosses its (oblique) asymptote infintiely many times

#

another example is f(x) = sin(x)/x

#

the x axis is an asymptote because the limit at infinity is 0

#

the curve crosses the x axis every 2pi

#

yes

#

well, it keeps crossing t over and over again, but it never stays there

#

it always wanders away and then back

#

for rational functions, you won't see this

#

rational functions will only cross a horizontal asymptote at most as many times as there are roots of the polynomial in the numerator

#

this is $f(x) = \frac{4x+2}{x^2+4x+5}$

glossy valveBOT
#

rome of oxtrot

deep flint
#

it crosses once, where the numerator is zero and thus f(x) = 0

#

at x = -1/2

#

exactly

#

right, only x with large absolute values

#

yw

#

i graduated in 1998

#

my degree wa sin political science, but i studied election theory which is actually somewhat math-heavy. my interest in math is personal, and i got back into studying it so i could help my kids with their schoolwork

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#

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visual topaz
#

can anyone help me with this?

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fast peak
#

what are the norm axioms?

visual topaz
#

aren't these the right axioms?

fast peak
#

they are

#

so now show those apply or not apply for the norms given in the exercise

#

or I shouldn't say norms, lets call it functions

#

the first question should really specify how long the vectors are tho

visual topaz
#

i dont get what max stends for in the first question

fast peak
#

maximum

#

$\max_{m\leq i\leq n} |x_i| = \max{|x_m|, |x_{m+1}|, \ldots, |x_n|}$

glossy valveBOT
#

Denascite

visual topaz
#

first property of the vector norm is

#

= 0 right?

#

so how im going to show that is what i dont get

#

how do show this in that problem

fast peak
#

well take any vector and show if you compute that formula it will end up >= 0

#

you can use that |y|>= 0 for all y

visual topaz
#

the elements of x vector aren't presented in the assigment