#help-28

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fierce stirrup
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Hello, I'm solving exercise 4.15 from "quantum computation and information" by Nielsen/Chuang, but I'm kinda confused about the minus sign on the second equation before the cross product term, this minus sign does not appear on other places like here https://math.stackexchange.com/questions/382760/composition-of-two-axis-angle-rotations . Which is correct?

fierce stirrup
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This is my work to solve the exercise, also no minus sign in the answer, but maybe some sign got messed up (X, Y, Z are the Pauli matrices)

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@fierce stirrup Has your question been resolved?

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@fierce stirrup Has your question been resolved?

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zinc steeple
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zinc steeple
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i have one of these wrong

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i am pretty sure it must be one of the g

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but not sure which one and why

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i think it must be 5

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oh nvm it should be line for 5

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tawny pond
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is gradient the derivative at a specific point or is derivative the gradient at a specific point

flint kraken
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unless you are using the word gradient in another way than i am used to the convention is that the gradient is the derrivative in all "directions" at a specific point

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so they are interchangeable definitions in R^2 but not in higher dimensions

tawny pond
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im so confused but that helps thanks

flint kraken
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what confuses you?

pure basin
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the derivative is a function which helps you to find the gradient at any point

tawny pond
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in straight lines the gradient is equal at all points but isnt the derivative same at all points

pure basin
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in a straight line, the gradient is equal yes

tawny pond
pure basin
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therefore, the derivative is the same at all points

tawny pond
flint kraken
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in straight lines the gradient is equal at all points
gradient of what exactly? Gradient is a concept that is (in my experience) mostly used to describe multidimensional fields, I am unsure why you are making a distinction between gradient and derrivative for this. But if everything is clear now thats good

pure basin
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for any curve/line

tawny pond
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wait what else does gradient mean

flint kraken
pure basin
tawny pond
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oh ok

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thanks

flint kraken
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be happy that you dont have to worry about that^^

tawny pond
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yes i am very hapopy

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scenic yarrow
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scenic yarrow
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<@&286206848099549185>

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vague solstice
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Quick question:

Am i allowed to do this am i using the rules correctly ?

pure basin
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yes as long as they are the same base

vague solstice
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well if its ln isntthe base e ?

pure basin
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oh yes its ln

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my bad

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yea

vague solstice
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yeah alright

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TY

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unreal spoke
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im too dumb for this

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unreal spoke
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its homework

gritty rose
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$x = 0.034\overline{78}$. what's $1000x = ?$

glossy valveBOT
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riemann

unreal spoke
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1000 x 0.034(78)???

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idk

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idk how to do that

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<@&286206848099549185>

sweet void
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do you understand what the line represents

unreal spoke
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yes

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recurring

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like 0.034787878787878787878787878

sweet void
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Yes

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so what’s 1000(x)

unreal spoke
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34.78?

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idk

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how do u times the line thing

slate hemlock
unreal spoke
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ohhhh

slate hemlock
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it just repeats forever

unreal spoke
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how do i turn that into a fraction then

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34 78/99

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?

slate hemlock
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Basically you have $\frac{3478-34}{99}=\frac{3444}{99}$

glossy valveBOT
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Andrea276

unreal spoke
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so 3444/99 is the answer?

slate hemlock
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yes

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,w 3444/99

glossy valveBOT
slate hemlock
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no wait

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that's not what the question was asking for

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it was asking to express 0.03478787878.... as a fraction, not 34.7878787...

unreal spoke
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yea..

slate hemlock
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well divide the fraction by a 1000 then

unreal spoke
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3.444/99?

slate hemlock
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you can't use decimals in fractions

unreal spoke
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right

slate hemlock
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$\frac{\frac{3444}{99}}{1000}=\frac{3444}{99\times1000}=\frac{3444}{99000}$

glossy valveBOT
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Andrea276

slate hemlock
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,w 3444/99000

glossy valveBOT
slate hemlock
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that's the answer you're looking for

unreal spoke
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alright thank you so much

slate hemlock
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yw

unreal spoke
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what does the exact result mean

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simplified?

slate hemlock
unreal spoke
slate hemlock
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oh it's just simplified, yes

unreal spoke
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alr

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torn jolt
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doesnt {s_n} = E since all finite sequences in R converge to their last term and for each [x is a member of {s_n}], we can construct a finite subsequence of {s_n} (lets call it A) with x being the sup of A and hence x being what A converges to.
also implies that limsup and lim are equivalent functions

nova basin
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First, you can't have a sequence be equal to a set, because one ordered and one is not.
Second, they may not even have the same cardinality: for sn = sin n, E = [-1, 1]
Thirdly, we never talk about limits of finite sequences

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nova basin
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Btw it's called the set of limit points of the sequence

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viscid moon
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My friends and I are trying to figure out what the equation would be for the column on the right, as all the columns are related by some pattern.
We were coming up with equations for the first, middle, and right but are stuck on the last column on the right.
Does anyone know what type of mathematics this is called so that I may do further research?

viscid moon
rare dock
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+55, +60, +65, +70?

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this isn't really a type of mathematics

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I guess you could call it inductive reasoning

viscid moon
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Ah okay, thanks for the help

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high gale
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high gale
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Ik this is basic but getting confused any help

torn jolt
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Circle itself will answer you now

deft zodiac
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take the area of a quarter of a circle minus the area of an isosoles triangle of lengths 2.5

torn jolt
# high gale

A = πr²
area of tow circles is
A = (3.14)(2.5)² = 19.6 cm²
so the two shaded is a half circle area A/2 = 19.6/2 = 9.8 cm²

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if they was two quarters

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but i think they are creating quarter circle like what circle said so A/4 = 4.9 cm²

spark shell
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you cant just assume that the circle is being divided into a quarter

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im thinking about it

torn jolt
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True

deft zodiac
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i mean u can show its a quarter and it isnt too hard but it requires a bit of work and normally u dont really show that

torn jolt
# spark shell im thinking about it

if we move the top one and remove the bottom one. to create a complete circle against the white circle. we will see that shaded circle is half of the complete colored circle. or at least some of half complete circle

deft zodiac
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unless the question is specifically about that

high gale
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Thank for the help but they not quarters

torn jolt
high gale
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Oh thank you

torn jolt
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nope

deft zodiac
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wait how did that show

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how did that show anything

high gale
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But I told my teacher that I was struggling and she said they are not quarters

deft zodiac
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ok the easiest way is

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these red points are the centre, the purple bits are all the radius of the circles, so they are all length 2.5cm

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so we get a square and we can thus see that it is 90 degrees aka quarter of a circle

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@high gale

high gale
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But there is still that green left over

torn jolt
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Can i know if you are trying to know the area of white circle or the shaded parts ?

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Because

deft zodiac
torn jolt
high gale
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My one smart friend said the answer is 12 cm2 but won't tell me the answer

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*the method

deft zodiac
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area 1 and area 2 is a quarter of a circle,
area 4 is half a circle,
so area 3 is the answer, 2.5*5=12.5

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alternatively u can calculate area 1 + area 2 + area 3 - area 4

high gale
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That's the answer

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My friend said he got it wrong

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Thank you so so much

deft zodiac
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yes

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btw that quarter of a circle thing is if u wanna calculate the parts individually, which u normally do u dont do it here i guess as theres the shortcut

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magic canyon
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magic canyon
spice orchid
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What is the range, in general?

magic canyon
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-2 to 3?

spice orchid
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Well yeah you got it

magic canyon
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maybe i typed it wrong in interval notation

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i did typed it but it was wrong

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i put (-2.3] or (-2,3)

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<@&286206848099549185>

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earnest harness
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A B and C are going to split on 12.000 SEK, A gets 2x more than B and C gets 50% more than A, how much does C get?

hot bone
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did you try anything so far ?

earnest harness
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honestly ive tried to make equations but i didnt get far

hardy elm
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uh

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hey

earnest harness
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X + 2X + 2X ^0.5 = 12.000?

hot bone
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x in this case is the amount of money B gets ?

earnest harness
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yes

hot bone
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can you explain why 2x^0.5 ?

deft zodiac
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the last one, 50% more means * 1.5, not ^ .5

hardy elm
earnest harness
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oh very true

hardy elm
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wait does anyone know how to do polynomials

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alg II

deft zodiac
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u shld go to another chat that isnt used..

hot bone
hardy elm
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ok ok

earnest harness
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X + 2X + 2X ^1.5 = 12.000?
or is the equation wrong

hot bone
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It doesn't need to be a power of 1.5

deft zodiac
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sry, ^ mean to the power of, use *

hot bone
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only multiplied by 1.5

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but yea your general approach is correct

earnest harness
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how should the equation look?

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a bit confused sorru

hot bone
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x+2x+2x*1.5

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do you understand why we multiply by 1.5 ?

earnest harness
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since its 50% more than 1, yes

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that leaves us with 5x*1.5 = 12000

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12.000 / 5*1.5 = 1073?

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X = 1073?

hot bone
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you need to multiply by 1.5 before you perform addition

earnest harness
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ahh i mixed up * and ^

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5x * 1.5 = 7.5x

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12.000 / 7.5 = 1600

hot bone
earnest harness
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x + 2x + 2x*1.5

hot bone
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okay thats the original expression

earnest harness
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u prolly do the multiplication first right

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x + 2x + 3x

hot bone
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What do you get if you simplify it following the rules of operations ?

earnest harness
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6x = 12000?

hot bone
earnest harness
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2000kr

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is that for x?

hot bone
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yep

earnest harness
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A gets 4000

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and C gets 6000

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thank you very much

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now i understand!

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❤️

hot bone
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awesome

earnest harness
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vast forum
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I tried to solve this and got stuck at x^2 - 2x - 1 =< 0.

modern sentinel
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x^2 - 2x - 1 <=0, (x-1)^2 <= 2

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can u proceed further?

vast forum
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(x-1)^2 <= 2
Then maybe like x^2 - 2x + 1^2 <= 2

floral bobcat
vast forum
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Where did 2 come from

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If bring everything to left side then we get x^2 - 2x - 1 =< 0.

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Then we can do smth like (x^2 - 2x + 4) -3 =< 0.

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That's bascially (x-2)^2 - 3 <= 0

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Ok how do I solve it

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I've never used quadratic formula before. That sounds complicated

vast forum
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uneven bronze
#

My daughter is in 8th grade and is doing these simplify problems. I’m just trying to check one thing so I know how they’re wanting her to do them. So like for numbers 1, 3, and 4, is she supposed to just multiply the actual numbers together since they are multiplication problems? She was saying that in class they were just adding them together but my wife and I were thinking that she was remembering wrong because for number 3 she wrote 11 but we were thinking it’d be 24. As for number 1, she had another problem where they just added exponents for numbers that were the same. For example she had a problem that was 2x2x5x5x5 and the answer was 2^2 5^3 and that was written in pen by her teacher. So I assumed number 1 on this sheet would just simply be 3^9

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torn jolt
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You are right. She is supposed to multiply.

uneven bronze
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But what about when the numbers are the same like on number 1?

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Would she just add an extra exponent to it since it’s the same number. So make it 3^9 rather than 9^8

torn jolt
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3^9 - you are right too

uneven bronze
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Alright. Awesome. Thank you.

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torn jolt
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Help pls

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torn jolt
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@torn jolt Has your question been resolved?

torn jolt
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<@&286206848099549185> ?

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@torn jolt Has your question been resolved?

calm nacelle
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yo

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lemme see

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okay it's kinda hard to read your work, but what did you get as the rectangular form for w?

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okay I see it now

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why did you take arctan(2pi/5)?

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that's not right

torn jolt
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Isnt argz=tan^-1(2pi/5)=b/a

calm nacelle
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No

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you're confusing some things

torn jolt
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Oh maybe that's why

calm nacelle
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arg z = 2pi / 5 here

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not b/a

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remember that tangent is opposite over adjacent

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so tan(2pi/5) gives you y/x

torn jolt
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Ahhh ofc

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No wonder

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So how exactly would I solve this?

torn jolt
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And continue with what I was doing before

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Just fixing the mistakes I made

calm nacelle
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if I'm reading what you wrote correctly then yea

torn jolt
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Awesome ty, I'll come back if I get it wrong

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Also why doesn't arg z start from the origin?

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@calm nacelle

calm nacelle
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it just starts from wherever the start of the arrow is

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where you begin the arrow is somewhat arbitrary

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it's just the length and angle that matter

torn jolt
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Ahh alr alr

torn jolt
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@calm nacelle thanks it worked

calm nacelle
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np!!

torn jolt
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dry steppe
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decisions to stop at any of the tourist attractions in an independent event

dry steppe
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how do i answer this

torn jolt
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take the opposite of it

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at most 14

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means p(the total) - p(15 stops) - p(16 stops)

dry steppe
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gotcha

torn jolt
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oh p(the total) is just 1

stiff musk
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the last sentence was cut off but i assume it's something like "assume decisions to stop at each site are independent of the others"?

stiff musk
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ah i see

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good, that makes it easy to calculate P(15 stops) and P(16 stops)

dry steppe
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what number is represented by the 16 and 15 stops

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it is 1 - p(16) - p(15)

torn jolt
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huh

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yup

dry steppe
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i know but how do i find that answer

stiff musk
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this is where the independence comes in

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P(stop at all 16 stops) = P(stop at one stop)^16

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due to independence

dry steppe
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so P(stop at 16 stops) = 0.87 ^ 16?

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stiff musk
dry steppe
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ok i will do that now

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15 stops is 0.87 ^ 15 which equals 0.123819

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16 stops is 0.87^16 which equals 0.107723

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total equals 1

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so 1 - 0.123819 - 0.107723 = 0.768458

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therefore p(at most 14) = 0.768458 ?

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is that correct

fleet cedar
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there are 16 spots that could be chosen as the one to skip

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and theres a 1-0.87 chance you skip it

dry steppe
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wait so how do i do that?

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1-0.87 is 0.13

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do i subtract that from my final answer?

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deft zodiac
deft zodiac
#

15 times where u stop at an attraction and 1 times that u dont, and also there is 16 ways to arrange the attraction u visit/dont visit

dry steppe
deft zodiac
#

yep

dry steppe
#

okay i got 0.63473259221

deft zodiac
#

yep

dry steppe
#

that is correct?

deft zodiac
#

i think so yes

dry steppe
#

perfect thankyou

deft zodiac
#

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modern sentinel
#

what's the meaning of exhaustive set, does it mean domain of the function

amber sapphire
#

in sets

rare dock
#

it just means all

amber sapphire
#

exhaustive means the union of all results in the super set

#

ya basically all soltuions

modern sentinel
#

so it means range?

amber sapphire
#

i don't really think you can use those terms here

amber sapphire
#

it is basically what you meant dw

modern sentinel
rare dock
#

what does that have to do with this

#

it's asking for all real numbers $x$ that make $\log_{|x|}(x^2+x+1)\geq 0$ a true sentence

glossy valveBOT
#

layla💜

modern sentinel
#

oh

rare dock
#

for example, $\log_{10}(111)\geq 0$, so 10 is one of values of $x$ that satisfy that

glossy valveBOT
#

layla💜

modern sentinel
#

okay ill try solving

#

@rare dock did u do it? im getting d as the answer

#

but i dont have the ans key to verify

#

anyways ty

#

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rare dock
#

I haven't done it but I can take a look if you want

modern sentinel
#

okay thnks

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manic nacelle
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modern sentinel
#

write tan square as sin square/ cos square

manic nacelle
#

Sin square + 1 over cos square

#

The first fraction?

#

No my brains broken

thick crown
#

tan x = sin x / cos x
sin² x + cos² x = 1

The rest is just algebra.

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hasty pagoda
#

.reopen

mellow kettle
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mellow kettle
#

How to justify that these functions are infinitely continuous

#

Like that the first derivate is continuous

#

The second too

#

Until the n-th one

#

Sorry if unclear , i can try to explain more

opaque helm
#

Oh it's in french

mellow kettle
#

Can you speak French ?

opaque helm
#

Du coup pour f tu peux déjà dire que f est C^1 par le théorème fondamental de l'analyse. Ensuite sa dérivée est le quotient de fonctions C^inf dont le dénominateur ne s'annule pas sur R_+^*

#

Euh d'ailleurs c'est $[1,+\infty)$ l'intervalle que tu regardes, ou $(0,+\infty)$ ?

glossy valveBOT
#

Twenty

mellow kettle
#

On peut en discuter en privé ? Jsp si on peut parler fr ici NervousSweat

opaque helm
#

Je pense que si, je l'ai déjà fait 😇 et on peut switch back in english si besoin

mellow kettle
#

Okay

#

Donc avant cette question y’en a une autre vraiment bateau mais j’ai peur de mal justifier

#

Faut justifier que les deux fonctions que j’ai envoyé sont définies sur R+*

#

La fonction g c’est évident

#

Et f est définie sur R non ?

opaque helm
#

Ok, alors la fonction f n'est pas définie en 0

#

$t \mapsto \frac{1}{t}$ n'est pas intégrable en 0

glossy valveBOT
#

Twenty

mellow kettle
#

D’acc elle est pas intégrable en 0 mais def pourquoi ?

opaque helm
#

(ni en +inf d'ailleurs)

mellow kettle
#

On peut intégrer de 0 à 1 en mettant un moins

opaque helm
#

Alors oui mais non ^^ oui on peut faire ça quand la fonction qui est à l'intérieur (l'intégrande) est intégrable, mais pas ici

mellow kettle
#

Oh ok

opaque helm
#

Ici exp(t) s'approche de 1 en t->0

#

Donc ton intégrande ressemble à 1/t lorsque tu t'approches de 0 (c'est un développement limité ou un équivalent si tu veux justifier ça proprement)

#

ça va jusque là ?

mellow kettle
#

On est d’accord sur la fait que l’intégrande est pas intégrable à cause du t au dénominateur ?

#

En 0

opaque helm
#

Ouaip

mellow kettle
#

Ok

opaque helm
#

Du coup, quand on se place sur R_+^*

#

(je veux dire x>0)

#

Il se passe quoi ? ^^

mellow kettle
#

La fonction (l’integrande) est intégrable

#

Donc l’intégrale existe

#

Pour tout x > 0

opaque helm
mellow kettle
#

e^t/t est continue sur le segment [ 1;x] où x appartient à R*?

opaque helm
#

👍

#

continue + segment
Ce sont les 2 mots clés

mellow kettle
#

Ok !

#

Pour g c’est évident avec le ln

opaque helm
mellow kettle
#

On peut justifier par «  definie sur R+*par différence de telles fonctions »?

opaque helm
#

Ouais

mellow kettle
#

Ok, je dois après calculer les dérivées premières et secondes de ces fonctions

#

Pour f j’ai envie de dire qu’on retombe sur e^t /t quand on dérive mais je sais que c’est faux x(

opaque helm
#

C'est pas faux ^^

mellow kettle
#

Ça me paraissait bizarre parce qu’on dérive en fonction de x

#

Et on va se retrouver avec du t à la fin , le x ayant disparu

opaque helm
#

Ah, ok j'ai mal lu

#

Mais "enlever l'intégrale" c'est l'idée

#

C'est juste que en effet ça va être du x à la fin

#

C'est encore un coup du théorème fondamental de l'analyse

#

Comme c'est marqué, t c'est une variable muette. Elle "existe" pas en dehors de l'intégrale

mellow kettle
#

Donc à la fin on aura du x à la place du t

opaque helm
#

Ouais

mellow kettle
#

Merci beaucoup ! Je pourrais t’envoyer un mp si je rencontre d’autres soucis par la suite ?

#

Ton aide a refait ma journée

opaque helm
#

De rien ^^

opaque helm
#

(si tu as fini tu peux .close le salon)

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tawny pond
#

how do I prove that if a pair of opposite sides of a convex quadrilateral are equal and parallel, then it is a parallelogram

faint dock
#

Write down the formal definitions of all the things you are working with and go from there

tawny pond
#

i know that the oppposite sides and angles in a parrellogram are ueqal

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grizzled halo
#

yes, your proof is simply saying that because 2 sides are parallel and equal, the other 2 sides to complete the quadrilateral will also be parallel and equal

#

What the helpers said find your defintions, define them, then prove the the next 2 sides must also be parallel and equal, then by the definition of parallegram we have the answer.

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tawny pond
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prisma tusk
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prisma tusk
#

Im learning the ratio test

#

this is my steps, but its not the right answer

nocturne creek
prisma tusk
#

yeah basically

nocturne creek
#

Is the answer 1

prisma tusk
#

yeah

#

what did i do wrong?

nocturne creek
#

Everything upto your second step is correct

#

Do you know what (n+1)! Is?

prisma tusk
#

yeah i thought its (n+1)*n!

nocturne creek
#

Right

#

And do you know what (n+8)! Is

prisma tusk
#

so (8+n)! must be (8+n)*n!

nocturne creek
#

No no

prisma tusk
#

ah

nocturne creek
#

(n+1)!= 1.2.3....n.(n+1)

#

(n+2)!=1.2.3...n.(n+1)(n+2)

#

Do you see what (n+8)! will be now

prisma tusk
#

yeah

#

(n+8)! = 1.2.3...n.(n+1)(n+2)(n+3)(n+4)(n+5)(n+6)(n+7)(n+8)

nocturne creek
#

So now you can do it

prisma tusk
#

wait but whats the simplified version

#

oh wait i get it

#

give me a second

#

oh i seee

#

(8+n)/(n+1)

#

= 1

#

limit as n approaches inifnity

#

thank you very much!

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mellow kettle
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mellow kettle
#

I have to prove the circled formula by induction

gritty rose
#

looks like integration by parts

mellow kettle
#

For the integral yeah

gritty rose
#

did you try?

mellow kettle
#

Yeah I got t^2n+2 in the new integral

#

But I’m looking for t^n+2 right

gritty rose
#

i don't see how you get t^(2n) instead of t^n unless you just integrated by parts too many times, in which case the two sums won't be correct either

mellow kettle
#

I’m gonna send what I did

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@gritty rose

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torn jolt
#

I used (83)(80)+(20)(x)=80 for the equation and got 68%. Is this correct or incorrect?

topaz valley
#

it is correct

torn jolt
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weak tusk
#

Can you guys help me with question 3a f.g

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weak tusk
#

I had done this for a

#

Is this correct for a

slate hemlock
#

g-f is going to be a subset of g with the elements that are in g but not in f

slate hemlock
weak tusk
#

Oh

#

How would the correct solution look

slate hemlock
#

Try to find it

#

I'll tell you if it's correct

weak tusk
#

Like this?

slate hemlock
#

Nope, don't think about (-4,4) as 2 elements but as just 1

weak tusk
#

I’m still confused

#

Am I unhelpable yes I know I am dumb

slate hemlock
#

For example, you shouldn't split (-4,2) in two parts, but leave it as it is. If (-4,2), which is in g, is not in f, then it's going to be part of the set g-f you're looking for

weak tusk
#

Is there a way you can show me I’m kinda a visual learner

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@weak tusk Has your question been resolved?

weak tusk
#

So

#

In brackets I should put the stuff that’s not pairs from f and g?

#

@slate hemlock

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cursive badger
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cursive badger
#

what do you do after you get a/b + b/a =-74/5

#

<@&286206848099549185>

torn jolt
#

after you find the values of $\alpha$ and $\beta$, just expand $(x-\frac{\alpha}{\beta})(x-\frac{\beta}{\alpha})$ and you'll get the equation you want

glossy valveBOT
#

R00tKiT

torn jolt
#

$\alpha$ and $\beta$ should not be equal to 0 though

glossy valveBOT
#

R00tKiT

cursive badger
#

why would you expand this

#

where does the x come from

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strong steeple
#

Hey all, I've been trying to adapt this sub-linear time approach for calculating the divisor summatory function for squares to work for $$d(2n^2)$$ instead. Any suggestions on how I could go about doing that?

glossy valveBOT
#

Grandmaster Shadow Morgue

strong steeple
#

I can see that $$d(2n^2) = d(2)d(n^2)$$ for odd numbers but still somewhat stumped on how I could tweak everything to give me a sub-linear method for calculating $$D(N) = \sum_{n=1}^{N} d(2n^{2})$$ overall

glossy valveBOT
#

Grandmaster Shadow Morgue

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@strong steeple Has your question been resolved?

strong steeple
#

<@&286206848099549185>

strong steeple
nimble fable
strong steeple
#

ok, thanks. I'll try the number theory channel

#

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nova basin
#

Let $(U, V) \in \mathbb{M}_{p, 1}(\mathbb{R})^2 \setminus {(0, 0)}$, show there exists $A \in \mathbb{M}_p(\mathbb{R})$ such that

$\begin{vmatrix}
A & U \
^t V & 0
\end{vmatrix} \neq 0$

glossy valveBOT
#

themateo713

nova basin
#

I thought of taking inspiration from the proof that $GL_n(\mathbb{R})$ is dense in $\mathbb{M}_p(\mathbb{R})$ to show that writing the determinant as a polynomial of p² indeterminates shows it can't always be 0, but I don't know how to actually show the polynomial can't be constant equal to 0

glossy valveBOT
#

themateo713

nova basin
#

It ought to be, but I don't know how to prove it

nova basin
gritty rose
#

what's $\mbb{M}{p,1}$ and $\mbb{M}{p}$ here?

glossy valveBOT
#

riemann (eric tao for honorable)

nova basin
#

px1 matrices and pxp matrices

#

U, V are vectors, A a square matrix

#

so the determinant is that of a p+1 square matrix

#

written in block notation

gritty rose
#

Nonzero vectors right?

nova basin
#

they can't be both zero

gritty rose
#

oh one of them can be

nova basin
#

yes

gritty rose
#

but if U is zero, then the last column zero?

nova basin
#

actually

#

might be a mistake

#

because that's clearly how it's written

#

but the following questions basically make me believe they start off by having that one of U or V be zero

gritty rose
#

i interpret this as U and V are neither zero this was wrong

nova basin
#

it's the set of all pairs (U, V) except for the pair {(0, 0)} though

#

otherwise you'd write (M_(p, 1)(R) \ {0})²

nova basin
nova basin
#

instead

gritty rose
#

no wait you're right

#

yea it implies $(U, V) \neq (0, 0)$ but one of them could be. just a mistake i think by the author

glossy valveBOT
#

riemann (eric tao for honorable)

nova basin
#

but if one of them is 0 the det is 0 then ? I don't see how this couldn't hold ?

gritty rose
nova basin
#

so that's that but I'm still not sure how you'd prove it though

gritty rose
#

maybe by induction on p

#

ha for p=1 both have to be nonzero

nova basin
#

looks weird, because only 1 out of p+1 sub-matrices keeps the 0 in the bottom right

nova basin
#

that's what we said

gritty rose
#

OH right. jesus

nova basin
#

any other ideas ?

gritty rose
#

could get p+1 equations by contradiction. try assuming T is invertible. then

#

$Tx = 0$ if and only if $x$ is 0

glossy valveBOT
#

riemann (eric tao for honorable)

gritty rose
#

$T = \begin{vmatrix}
A & U
^t V & 0
\end{vmatrix}$

#

F

nova basin
#

its \\

nova basin
gritty rose
#

$T = \begin{bmatrix}
A & U \
^t V & 0
\end{bmatrix}$

glossy valveBOT
#

riemann (eric tao for honorable)

gritty rose
#

oh i mean assume $T$ is not invertible

glossy valveBOT
#

riemann (eric tao for honorable)

gritty rose
#

Then there is a nonzero $x$ that satisfies $Tx=0$

glossy valveBOT
#

riemann (eric tao for honorable)

nova basin
#

that forces V.x = 0

#

so if you choose lines of A such that (A_i U_i)x != 0 for every x orthogonal to V and U that works

#

can we have that ?

gritty rose
nova basin
gritty rose
#

oh nice that makes the math easier

nova basin
#

can we guarantee that though ?

#

I think so right ?

gritty rose
#

the only we know is x is nonzero, but some of its components can be zero. did you use that somewhere?

nova basin
gritty rose
#

suppose T is not invertible. then its rank is at most p, so suppose it's p. then the kernel has dimension 1. x and all its scalar multiples are this line

nova basin
#

" so suppose it's p" isn't WLOG though

#

the point is to say there exists such a matrix A, so I'm not sure this is the right way. The idea looks sound but somewhat off track

#

maybe more like x needs to be orthogonal to (V 0), which is a vector space of dimension p, and you choose the p lines of A such that they each eliminate a different dimension ? That looks like a good idea

#

basically choosing the line as being colinear to one of the basis vectors of the orthogonal space, with the right constant so that U works with it. The only problem is if the value of U is 0 though

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tulip lodge
#

Do you have to do distributive property if there's an expression in absolute value? ex. 4Ix+3I

torn jolt
#

Wdym

tulip lodge
ivory cairn
#

yes, the 4 would distribute to the y and the 3

tulip lodge
#

got it thanks

deft zodiac
#

i mean u can but i would say u have to.. it would depend on context

tulip lodge
#

alright I'll give you the whole equation

#

I have to solve the function

#

so if y=1

#

-4|1+3|

#

I still have to do distributive property I assume

deft zodiac
#

i dont think u can solve for just a function?

tulip lodge
#

ok

#

I got it now thanks

#

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ivory oriole
#

Good afternoon, I'm currently stuck on a U-substitution problem that I can't seem to figure out. I'm most likely unfamiliar with the technique I'm suppose to used, and that is the only problem I have.

ivory oriole
#

other sources say I should do the U-substitution on the left

#

but I'm afraid I don't quit understand how to get there

stiff musk
#

where did the u+5 come from?

#

on the rhs

ivory oriole
#

I have no clue

stiff musk
#

5-x becomes u

#

x should become 5-u, not u+5

ivory oriole
#

I the integral calculator I used does that for some reason

#

oh

#

That makes more sense

stiff musk
#

and you should have a (-du) on the rhs

#

from there it should be fairly easy, just split it into the sum of two integrals

ivory oriole
#

.close

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humble thunder
#

I can't figure out how to get the angle in radians

eager violet
#

What have you tried

humble thunder
#

theta=tan^-1(-1/4)

eager violet
#

And what do you get?

humble thunder
#

-0.2449 radians

eager violet
#

Remember that the angle has to be between 0 and 2pi

#

Also remember that you can add 2pi to any angle and get the same thing

humble thunder
#

I got the correct answer thank you

#

I don't really understand why though

eager violet
#

You added 2pi to your answer, right?

humble thunder
#

yes

eager violet
#

2pi represents a full rotation. Rotating an angle 360 degrees doesn't change the angle

humble thunder
#

So I added 2pi because I got negative radians?

eager violet
#

Yes, and the question specifically asked for an angle between 0 and 2pi

humble thunder
#

How about arctangent having to be in quadrants 1 and 4?

#

is that why he adds pi

#

to do a half rotation and get into quadrant 1

eager violet
#

Well, there's two distinct angles that give the same tangent

#

Arctan only gives angles in the first and fourth quadrant

#

So you'll need to see if the angle your given is in the second or third quadrant

#

If it is, the other angle will be + π

#

Because tan(x + π) = tanx

humble thunder
#

Ok thanks a bunch

#

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kind grail
#

.open

#

Hey can Somone help me

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light sonnet
kind grail
#

Oh mb then

#

I’m stuck on we’re to begin

#

Here is the problem

#

So far I have (6 squared -4)- (6x-6

#

)

#

I’m in Alg 2 btw

astral sinew
#

6 squared?

kind grail
#

Yea

#

Because on the other side it’s 6x

#

So doesn’t that mean 6x is on both

#

Or is it jus 1x

eager violet
#

(f - g)(x) = f(x) - g(x)

#

Don't change f(x) for no reason

kind grail
#

Ok

#

So it’s 1x

hot herald
#

what's "it"

kind grail
#

X

hot herald
#

well x is 1x if that's what you mean...

kind grail
#

Yea

eager violet
#

f(x) is x² - 4

kind grail
#

I missed the first 2 days because I had Covid so I’m behind sry

eager violet
#

It's not 6² - 4, nor is it x - 4

humble thunder
#

Just subtract the two things

kind grail
#

So

#

1x-4=6x-6

hot herald
#

no

eager violet
#

When did an expression become an equation

kind grail
#

So it’s 1x squared - 4 -6x-6

#

Yea that

hot herald
#

no

humble thunder
#

combine like terms

eager violet
#

This is incorrect

humble thunder
#

wdm

hot herald
#

missing ()

kind grail
#

So 1x squared is 1

hot herald
#

no

humble thunder
#

you still have to combine and rearrange

eager violet
#

Parenthesis are important

kind grail
#

1x -6x = 5x

hot herald
#

no

kind grail
#

I’m confused

eager violet
#

x² is very much not the same thing as x

hot herald
#

stop going ahead when we say no, implying what you did/ currently have is wrong

kind grail
#

Mb

#

So what do you want me to do

hot herald
#

note that the whole of g(x) is being subtracted

#

so you shouldn't be only applying the - to whichever term appears first

#

after the initial step you should have
$$(f-g)(x) = f(x)-g(x) = x^2 - 4 - \red{(} 6x - 6 \red{)}$$

kind grail
#

?

hot herald
#

and then simplify

#

and do NOT change things to stuff they aren't

kind grail
#

Ok I’m confused on that part so

glossy valveBOT
#

ℝamonov

kind grail
#

Would I just plug everything in

#

And do the math from there

hot herald
#

plugging in f(x) and g(x) gets you ^

#

then simplify

humble thunder
#

You just distribute the negative to the stuff in the paranthesis 🙂

hot herald
#

x^2 is x^2, do NOT change that to x, 1, 🍎, 🍌 or whatever you feel like that isn't x^2

kind grail
#

So (x^2 -4) (X)

#

What is X where do I go from that

hot herald
#

whut

#

(x^2squared -4) (X)
where's that coming from

kind grail
#

That’s what u guys said

hot herald
#

no?

kind grail
#

F(X)

hot herald
#

that is NOT what we said

kind grail
#

Ok I’m majorly confused then

hot herald
#

where did we say
(x^2squared -4) (X)

kind grail
#

It’s confusing do you guys have a YouTube vid I can learn from here i wasn’t in class for this

kind grail
light sonnet
hot herald
#

rub it out?

kind grail
#

How do I do this then

kind grail
#

Alright

#

I give in

#

I’ll use photomath and stay after school for help

humble thunder
#

dude

kind grail
#

.close

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#
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humble thunder
#

Distribute the negative

kind grail
#

.reopen

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#

humble thunder
#

plz

kind grail
#

Bro I don’t get what you mean by that

#

This is my first time learning this unit I wasn’t here for the class

light sonnet
humble thunder
#

see the negative

#

apply it to 6x and -6

#

they become -6x and +6

#

now you have

light sonnet
humble thunder
#

now you just combine like terms

#

make sure you order it by highest powers also

kind grail
#

Ah ok

#

Thanks

humble thunder
#

Did you really get it?

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@kind grail Has your question been resolved?

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rocky kelp
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rocky kelp
#

I'm not really sure what I'm doing wrong here. What I have is close but not quite right

#

is my implicit differentiation wrong, or am I not applying algebra correctly?

zenith kernel
#

dy/dx=2xy/(y-1)->
(1-1/y)dy=2xdx
y-In|y|=x^2+C

#

No idea why you let C=1

rocky kelp
#

wait... what?

#

I didn't integrate anything, where did the C come from?

#

(y - ln|y| = x^2 + 1) is the implicit solution I'm trying to prove for dy/dx = 2xy/y-1

#

I'm trying to do implicit differentiation of it to verify the ODE

gritty rose
#

Finish the bottom multiplication

rocky kelp
#

wait

#

I think I get it

zenith kernel
#

You better ask your question clearly, you didn’t say what the question is, giving y-In|y|=x^2+1, to prove dy/dx=2xy/(y-1) or solve differential equation dy/dx=2xy/(y-1)

#

I assumed the latter

rocky kelp
#

but, if I multiply the right hand by Y don't I have to multiply the left hand by Y?

#

I'm trying to isolate dy/dx on the left side

#

multiplying the right by Y would make the right hand side 2xy/1-y but then it would make the left hand side y dy/dx too no?

#

actually, I think that would be wrong for the right hand too, wouldn't it make it 2xy^2/y-1?

gritty rose
rocky kelp
#

ohhhhh wow that was not obvious at all

#

multiplying everything by y in step 2 leads to a solution though, if that's what you mean't

#

thanks for the help 👍

gritty rose
#

Sure there are multiple ways to do it. Glad it works

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odd summit
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odd summit
#

How exactly do you solve this question? Thanks 🙂

nocturne creek
round gust
#

How did you get from basic trig to this

odd summit
#

I'm doing some calculus review

round gust
#

Ok

odd summit
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glass rune
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next flume
#

Make LHS a common denominator then cross multiply

next flume
#

Sorry

#

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dry mirage
#

how many millions are there in 86,953,061

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onyx glen
#

can you write the number 86,953,601 in words? the answer might become clear.

#

also please don't just .close without saying a word if your question was resolved. at least thank the person or people who responded or something.

dry mirage
#

oh

onyx glen
#

no

#

we don't do that here

dry mirage
#

oh

torn jolt
#

wanda!!

#

marry me

dry mirage
#

.close

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dry mirage
#

.reopen

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#

dry mirage
onyx glen
#

right

#

the answer to your question should now become clear

dry mirage
#

okay

#

thanks?

#

.close

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simple ridge
#

Hi

full forumBOT
simple ridge
#

Is this correct or no

#

<@&286206848099549185>

#

Also pls don't tell me that I should wait 15 mins before I use @ helpers bc I had too channels closed from waiting and this is the third

#

I made one from abt 4-5hrs and it closed so I made another at 1hr ago prob and it closed now I made this

#

Why isn't anybody answering my question

calm osprey
# simple ridge Why isn't anybody answering my question

So this discord consist of only volunteers. This means that that there might not be anyone eligible to help online depending on complexity of the question. They might not have time or any other reason. There is no one on the discord that is obliged to answer questions for better or worse.

You can only hope someone is available.

simple ridge
#

Ik but many people already have their questions answered in this time that I am trying to find someone to answer my question

#

It's ok if no body wants to answer my question but just inform me to know what to do instead of just waiting

#

Nvm I'll just close the channel

#

And sorry if my way wasnt so good forgive me

#

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torn jolt
full forumBOT
torn jolt
#

did i do something wrong

#

trying to isolate h

onyx glen
#

yes, very.

deft zodiac
#

yea u treated the first + as a *

torn jolt
#

oh i see mb

onyx glen
#

if you wanted to isolate h you could have subtracted 6x^2 then divided by 6x

torn jolt
deft zodiac
#

seems right

torn jolt
#

aight tyty, mb

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supple briar
#

why is it 0.9j shouldnt it be 9j ?

full forumBOT
deft zodiac
#

use a calculator

supple briar
rugged harbor
#

I get 0.9 too, did you forget the **0.**5?

supple briar
#

hmm ill try gain

deft zodiac
#

send a pic of what u entered in the calc along with the result

supple briar
#

nevbvermind

rugged harbor
supple briar
#

you guys fixed my calcullator

#

wow this discord is magic thanks

#

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cursive badger
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cursive badger
#

how would i show that for this question

#

i know how to normally do this type of question

#

but idk what to do with the 2

onyx glen
#

let θ = arcsin(3/5), then you know that sin(θ) = 3/5 and θ ∈ (0, π/2) [and in fact θ ∈ (0, π/4) since 3/5 < sqrt(2)/2]. find sin(2θ).

cursive badger
#

so sin2θ=3/5

#

do i just need to find sinθ

#

and ill be able to do the rest

onyx glen
#

no, that is not what i said.

#

please read what i said more carefully

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cursive badger
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torn jolt
#

try drawing the unit circle and constructing a triangle with height x

#

or u can sub x=sintheta maybe

#

in (a)

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@cursive badger Has your question been resolved?

torn jolt
#

ok

cursive badger
#

ok

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noble pelican
#

[Italian Linear Algebra]
I really need somebody to guide me here, our professor's explanation is so disjointed and minimal that its useless. I tried other sources but what he asks of us its to advanced.
I'll translate it shortly. Please I need help.

nova basin
#

V is the set of all polynomials with what that's at least 3 ?

#

I if understand correctly (cause I don't speak italian)

noble pelican
#

Question A) Prove that only one Linear Operator F: exist so that:

Ker(F) has linear system ->
F(0,...

Write the matrix of F in regards of the Standard Basis R^5, taken as a starting basis in R^5 and at {1, t, t^2, t^3} taken as a basis of arrival to T

spice orchid
#

at most degree 3 i imagine