#help-27
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And you did correctly
looks good
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Quick question: why do I get a different answers when I multiply the whole equation by 9 and when I just simplify 5/9 and 18?
Because if you multiply the right side by 9, you also have to do it on the left side
Oh
So you'd end up with 9c = 5 * 18
wait is not 9c = 5 * (18*9)
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I'm stuck on finding the Mobius map...could anyone help? In class we showed how to construct a mobius map that takes three points to another three points, but how to do this problem?
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yo g's need help with a question:
2 ร โ3 ร (sin(2x))=3 ; 0<x<2pi
Need to determine all the possible solutions
,tex $2 $\sqrt{3} \sin 2x = 3, 0<x<2 \pi$
uhm not quite
$2 \sqrt{3} \cdot sin(2x) = 3 ; 0 < x < 2\pi$
Si Arya
๐
why is this 3^2
uhm cause it was โ3 so it goes to the other side yk and now its power of 2 instead of square root
not really
nah chill
wdym
||๐๐ช๐ผ๐น๐ฎ๐ป||
@river trout
ahhhh
just treat sqrt(3)
that makes more sense
as a regular number
alr cool
cool so can we continue
yessir
this is non calc, let me do the calculation rq
1 sec
so 1/โ3 x 3 = โ3
so then sin(2x) = โ3/2
and i know what to do from here
||๐๐ช๐ผ๐น๐ฎ๐ป||
nah that aint right
why?
2 sqrt 3 here
its โ3/2
same thing lol
yea
It is right
if you do the rationalise
nah but idk why you do it like that
when it clearer when its โ3/2
as โ3/2 is a clear sin value of 60
fine
anyways thats all
but you skipped the step bro
I'm just doing division
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Hello! I'd like to compute this beauty. Does anyone have an idea ? I guess it is impossible to find an analytic solution
@restive river Has your question been resolved?
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help
(0,4) is different from {0,4}
the order of matters in the former, but not the later
because order of elements doesn't matter in a set
i.e. {0,4} = {4,0}
but $(0,4) \ne (4,0)$
vin100
i would say graph coordinates use this $(?,?,?,\dots)$ structure
vin100
because each axis is supposed to have a different role to play\
say in the 2D case, using the Cartesian coordinates
the $x$-axis and the $y$-axis are the independent and dependent variables respectively.
vin100
so why is range the of (f f) = set {0,4}?
the range of f is {-2,0,2,4}
if you plug those values into f again, it'll come out as 0 or 4
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help
@amber dock Has your question been resolved?
<@&286206848099549185>
@amber dock Has your question been resolved?
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i need to find the height of the container, i dont know how. any help?
I think it wants you to assume you got a right angle
im sorry i dont understand ๐ฆ
do you know what trig is
200cm
h=200cm ..
no lol
ty

but i need to write how i got the answer ๐
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my g doesn't know trig
look i hate math okay๐
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why doesn't order matter?
i thought because theres 6 possible answers that are wrong and your choosing 3
you would multiply that by 5C3
but you dont?? why?
The answers which are correct are fixed. There are exactly 5 wrong answers. So it's 5C3/8C3 oe MS method
i dont understand
i did this x 5c3
6 possible wrong ans
No. There are 5 wrong answers. The question has 3 fixed correct answers.
yh and p=0 is probability they choose all 3 incorrect answers, right?
The 5 wrong answers are fixed. You can't change the 3 correct answers to the question
Yes
Fixed means doesn't change.
You just have to choose 3 answers.
Say the question had options:
1 2 3 4 5 6 7 8
and 2,3,4 are correct. [This is fixed. Suppose the question was "Please choose 2,3,4". The correct answers are 2,3,4 and 2,3,4 only. This is fixed, because the question is fixed. Fixed means doesn't change.]
Then the probability of getting none correct is choosing something out of 1,5,6,7,8. There are 5C3 choices you can make out of a total of 8C3, so 5C3/8C3 is the ans.
Or 5/8 * blabla as ms did
i dont understand how there are 5c3 choices you can make out of 8c3
can we do it in terms of probabilities first?
ok so 12345678, 234 are correct
which means probability of someone picking 167 is 5/28? yes or no?
ohhh wait a second
i think i just realized fixed
your saying
order dont matter
123 is same as 231 because they are all picked at once?
i understand the 5c3 now
however i dont understand why 8c3 is total
Yes. Both give X=2.
8 numbers. Choose 3.
hmmmmmm i thiiink i get it maybe
yes, yes i get it.
now i just need to make sure it sticks.
ahh, ok thanks for the help appreciate it
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Closed by @agile narwhal
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I'm supposed to prove this identity
I've tried multiplying the right side's first term with 1 + tanA/1 + tanA
I've also tried doing something similar with the right side's second term
but I can never get them to make sin A + cos A
try expressing tan on the RHS as sin/cos and then getting rid of the /cos
would I get sinA.cosA/ 1 - cos A?
uhm i dont think so
$$\frac{\cos A}{1-\frac{\sin A}{\cos A}} - \frac{\sin^2 A}{\cos A - \sin A}$$
Nathan_
them multiply the left fraction by cos/cos
wouldn't the sin A at the bottom multiply with the cos A?
$$\frac{\cos^2 A}{\cos A -\sin A} - \frac{\sin^2 A}{\cos A - \sin A}$$
Nathan_
wdym?
I mean wouldn't the sinA that's underneath the cosA go to the top?
there is no sin A underneath a cos A
tan = sin/cos so its the cos that is underneath
it's a random example
just checking if my math is right
I understand how to prove the identity tho thks
this is what I meant
where have you got that from though?
sorry
I edited a message instead of replying
so what I did is completely wrong ye?
thks
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uhm ye...
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What is the complement of the intersection between two sets when the sets are disjoint
U
$(P\cap Q)'$
JUGisMUG
ye
Ok so a set being disjoint does not affect anything about (P int Q)'
Thanks
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how do I do c. ii?
cuz theres no values so I dunno if area is possible
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@dreamy pine Has your question been resolved?
@dreamy pine Has your question been resolved?
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can someone please explain how to solve this?
symmetry is great sosad u cant use that
3*Pi/2 is the only number thats coming to me rn
think about the period of $r(\theta)$
vin100
when 1 is added to $\sin(\theta)$, what are the roots of $r(\theta) = 0$?
vin100
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yo
Someone was literally helping you in your other channel you had, and asked for your work, if you are still doing that problem
i know how to solve it but how is answer 79.6
my phone aint with me
thats the problem
okay
Or @woven radish
Not a lot of users know latex, but if the OP does, that'll be good
Horribly formatting, need parentheses
use ^ for exponents
why 3/100?
did the investment only last 0.03 years, i.e. eleven or so days?
no
no, of course not. it lasted 3 years and your calculation should reflect that.
yes, but there is no reason to divide the duration by 100.
yea forgot ^ ^
also, you calculated the total for one plan, but only the interest for the other. so of course you get bullshit if you try to subtract them.
i was doing without adding and subtracting but the ms was telling me otherwise
@pseudo basin
??
you just disappeared
wym disappeared
are you a helper
i never went anywhere
?
no, i don't have the helper role
will you now tell me to fuck off on those grounds?
i don't know what you mean by this
both because you are being cryptic in showing your work and because i haven't seen your mark scheme
okay i will solve again
one sec
how do you even draw the answers out on paint
can you solve it
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it resembles your pfp
wdym
egg
oh did i offend you
oh you mean my profile picture?
i didn't know what pfp means
lol
ellipses = egg
<@&286206848099549185>
your answer is off by a number
you might have calculated something wrong
somethings off
did i miscount on the graph?
or you can try graphing your answer and see whats off
i think the minor vertices is 12.
Is the minor vertices the entire length of the ellipse or just the center to the end?
pretty sure vertices are points
yes but they are ___ amount of spaces away from the center
im pretty sure I did not miscount
then try graphing your answer
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@peak lark Has your question been resolved?
โข Ask your math question in a clear, concise manner.
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@peak lark Has your question been resolved?
@peak lark Has your question been resolved?
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Once you have 1 in the bottom right, do roe operations to make the top right =0
Basically, they donโt say b/a = 0, they do row operations to get 0 in that position
what how
what row operation
-b/a*R_2 + R_1 โ> R_1
to get 0 in the top right
im so confused
if you multiply the second row by -b/a
wouldn't u get
0, -b/a
so multiply it by -a/b
oh ok
its clicking
man thanks a lot
u've helped me with at least like 10 problems so far I think
much appreciated
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how would you get started with this?
so far I have pulled the n out and make it (2^p/3)^n but I'm not sure what to do from there
oh so would it just be sort of guess and check?
Not really, we're considering all values that p could take
Once you do the positive cases, you can do the negative ones similarly
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What is your question?
Do you not know what equation to use?
Are you unable to explain your choice?
Are you having trouble using the equation?
The function takes horizontal distance, d, as an input
And outputs height
d is distance from the ramp
All stated in the problem, I am just repeating
Yes, but use d instead of x
Ok. Why did you pick that equation?
Since the assignment asks
You would do that in both equations
But do you mean to say
The first two terms become zero immediately and you just read off the third constant term?
goo
~
Ok, what has you stuck though, you were gonna say something
Closed by @warped sluice
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The sum of the sides of two squares is 21 cm and the sum of their areas is 225 cm2.
Find the length of a side of the smaller square.
what ahve you tried
idk how to form an equation
did u draw
o wait i got it
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this is what i've done so far
I'm still confused how to manipulate what I've got into the RHS
try also writing the RHS in sin/cos form
ahh okay is the reason I'm struggling because I'm approaching it from the more difficult side?
nah looks solid so far
one way to prove this is to manipulate both LHS and RHS into their basic parts consisting only of sin and cos and then trying to manipulate the resulting fractions
so leave the LHS as is right now and play around with the RHS
as in whats the question a the paper thing
the question is in a booklet, i wrote the question down in the 1st image
can u take a photo?
why the question is in the 1st image, besides theres load of other questions in the booklet on that page that would complicate it.
oh found it k
@oak forum did you solve?
nahh i'm still crunching. I think I've hit a brick wall
Write the RHS as
$$\frac{\frac{\sin A}{\cos A} + \frac{\sin B}{\cos B}}{1 - \frac{\sin A}{\cos A} \cdot \frac{\sin B}{\cos B}}$$
nvx
Now you only need to multiply and divide the fraction by a specific term to get exactly the LHS
I've got to that stage but my brains not working to get over the final hurdle
Hint: You want to clear the nested fractions
What would you need to multiply the numerator with to clear the nested fractions?
if you have something like 1/x + 2/y = 0 what would multiply that equation with to make the denominators disappear?
am I simply just flipping the nest fraction (denominator) and multiplying the numerator (top fractions ?
@oak forum Has your question been resolved?
am i multiplying by the denominator ?
@patent tartan is this correct ?
<@&286206848099549185>
I still don't understand
is my most recent image i sent wrong
is it at this step I multiply both the numerator and denominator by cos(A)cos(B) ?
@nvx I've finally done it, sorry my severely handicapped brain wasted your time lol
@oak forum gj!
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two questions
firstly
e^(3lnx) can be simplified to x^3
but e^(3lnx) cannot take some values that x^3 can
how does that work
secondly
i am having trouble rearranging x=(3y-5)/(y+1) to get y
Give an example of a value
-1
-1^(3 * ln(-1)) = -1
The constraints stay, so x > 0
what constraints
it shouldnt be -1 to the power of it should be e
That ln must be defined. As assuming you're studying a function for instance
so when dealing with lns there must be a domain?
and yes this has to do with functions but i was asking about this as an independent equation
how does that work when its impossible to have a natural log take a negative value?
It's not impossible..?
it should be undefined no?
It's just a complex solution
like dividing by zero?
but i is imaginary
im talking about real answers
The function you're studying has a predetermined domain, and your stick to it normally
x^3 will have a real answer but the e wont
Breeziboi
e^(3ln-1) has a real value?
it wont compute anything to do with lns that have negative values
You might have imaginary disabled
Or something
but thats imaginary i mean
-1^3 will have a real answer
and thats just a simplification of the original right
3 * ln(-1) = 3pi * i
how come they give two different answers for the same value
if x^3 is just the original equation simplified
I just said... they have the same answer
It is
e^ln(x) = x
e^(3ln-1) has an imaginary answer right
natural logs cannot take negative values and give real answers
what am i missing here
Complex is not the same as undefined
but what i dont understand is
how come the answer for the same input (-1) is different depending on whether u input it into the simplified equation or the original one
shouldnt both give the same answers since theyre just the same equation one is just simplified?
I don't think you understand, they give the exact same answers
Complex exponent, the answer is real
but -1^3 is just -1
So is e^(3ln(-1))
is the exponent not part of the answer?
e^(3ln(-1)) = e^3(i pi) = e^pi i = -1
how is e^pi i equal to minus 1
for e^(pi * i) = -1
are you sure?
Yes
wtf
ln -1 = i pi (1+2n) for any n. You can take any n because they're all valid
is that just something youre supposed to know?
That's basic complex numbers
It's one of the more famous things in math I guess
so no matter what n is the answer will always be -1?
Because x -> e^ix is 2pi periodic
what does periodic mean
f is T periodic iff for all x in its domain, x+T is also in the domain and f(x) = f(x+T)
ok
now on to my second question
should be less theoretical im just stuck on rearranging an equation
i am having trouble rearranging x=(3y-5)/(y+1) to get y
i brought y+1 to the left side
so now i have x(y+1) = 3y-5
but im stuck with ys on both sides
y depends on x, that's to be expected
i need to isolate y tho
and i dunno how to get rid of the xy and 3y
to get just y
ive literally been staring at xy+x = 3y-5 for ten minutes
all ive done in ten minutes is expand x(y+1) and im not sure thats brought me any closer
It has
my problem is the xy and the 3y
Then you can write (x-3)y and there is only one y
where did you get (x-3)y from
Just move the 3y to the other side and factor y out
Euler's formula about e to the i pi, explained with velocities to positions.
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Not familiar with the calculus referenced in this video? Try takin...
ill watch that
trying to figure out (x-3)y tho even if u move it to the other sid
side*
u still have an x
u didnt account for
did u move that too
xy-3y = 5-x
(x-3)y = 5-x
y = (5-x)/(x-3)
u moved the lone x to the right hand side right?
the x that was on the left side of the equation
Yes of course
and then divided by the (x-3)
ok i see
didnt see it before
might be braindead
thanks for the help
Just consider both x and y as constants. It's a little extra abstraction but the math is the same
got it
its y=(-5-x)/(x-3) right?
i think u missed a minus
Yes
ok thank you
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could it be 10km/h + 2km/h = 12 km/h, t= s/v= 18/12= 1,5 - answer for the 2nd one?
yes you got it
thank you so much!
no problem
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ive got a question
this is not an equation, what do you mean by "solve"
it says write equation in simplest form
make them both have the same denom
multiply top and bottom by 4 - root 3
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Hi there
I am asking about (b)
I am first considering the absolute value of it and I get that it is equal to sum (1 / |a^ln(n)|)
Can I just say here that it is like 1/q^n which converges?
or is it different because ln(n) tends to inf slower than n?
a^ln(n) is not exponential in n so yes your argument falls apart
in fact it is equal to n^ln(a)
I see
How do you get there exactly?
$a^{\ln(n)} = e^{\ln(a)\ln(n)} = e^{\ln(n)\ln(a)} = n^{\ln(a)}$
Ann
In that case, using the fact than a > 1 we can see that ln(a) > 0
yes
it does
but does not say if it converges or not
since we don't know if it is smaller than 1 or bigger
well you have absolute convergence for a>e
which is 1 yeah
But if a < e it does not
So in that case I need to split into cases?
you have an alternating series
and the sequence 1/n^ln(a) goes to 0, and monotonically at that, no matter what a is (so long as it's above 1)
But you can not assure it is above 1
We already learned in class that for a exponent > 1 it converges.
a>1 is given
and a being above 1 is what i was referring to
As you said before, it depends if a > e of not
Is that correct?
...................
the ratio of adjacent terms tends to 1 regardless of the value of a
and the limit of b_n is 0 for all a > 1 regardless of whether or not a > e
I meant to write > 1 or < 1, mb
Yeah I know
But we learned that the sequence must be decreasing
$1/n^p$ is a decreasing sequence for all positive $p$
Ann
Oh yeah
it decreases anyways.
Sorry... my bad here..
To sum it up:
The series is converging absolutely if a > e and converging conditionally if a <= e?
lol
Then I am done asking you for today
cya tomorrow ๐
Thanks for the help
.clsoe
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hi, can aynone tell me what how to solve this
which role
Feels like overkill with L'hospital. Just note that the numerator is larger than $\sqrt{ h}$ for positive $h$
you mean this. no i don't
GUNILLA62
Sure but the expression is always negative for negative h
they gave us hint. wait a sec
Determine the limit value by first simplifying and then extending the rational expression so that you can use the conjugate rule.
When in doubt with an indeterminate form, use L'Hopital
oooh, the picture disappeared
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A restaurant receives 8 cartons of milk daily. On a random day, the number of cartons with a defective screw cap among them is equal to 2. One of the employees picks up 2 cartons.
a) What is the probability that the employee receives more than 1 milk carton with the defect?
b) What is the probability that the employee receives exactly 0 defective milk cartons if the employee receives 1 or fewer milk cartons with the defect?
c) What is the expected number of cartons with the defect?
d) Calculate the variance of the number of defective milk cartons.
No idea how to come any closer to the answer. previous task asked about the p of 0 defected cartons, I got it correct, 0,536
@nimble narwhal Has your question been resolved?
<@&286206848099549185>
lhopitals. itโs a 0/0 situation.
youโll get -1/2 I think
so for n = 2
itโs 2/8 * 1/7
b) for n = 1
itโs 2/8 * 6/7 = 3/14 = 6/28
for n = 0
itโs 6/8 * 5/7 = 15/28
so total probability of clause is 21/28 = 3/4
answer is 15/28 divided by 3/4 (bayes theorem)
c) 1/4 * 2 + 3/14 * 1 = 5/7 . so almost 1
d)use your calc or the formula for variance
@nimble narwhal
Yeah that works. A first degree Taylor expansion of sqrt(2+x) works as well
did you mean mac expansion (taylor expansion with fn(0) ) ?
but I feel like expansions for 0/0 or infinite /infinite limits are a bit of an overkill
but hey, if it works, it works
I didn't really got c. b is also saying wrong (it is a homework where I get if the answer is correct right away)
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Take the standard parameterization of a cone
And mess with it to get it to look like the one you want
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I have a question, does the converse of the power rule true for all natural numbers n?
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Could someone check if itโs right
This looks good, I would just mark on the maximum turning point coordinates and the point at x=4 where it has a root
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Didn't think I would need to specify it since there is no other natural choice of point to do the expansion around. I personally prefer using Taylor over l'hopitals when I can since Taylor expansions are more useful in other parts of analysis
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uh
I think it might be because the cos(a-x) starts at a minus going to a plus while cos(a+x) starts with a plus going to a minus
Or vice versa
-(a-x) isn't a+x
Let $a - x = s$
$cos(s) = cos(-s)$
Substitite back
Pluton
oh whops
how did i mess that up lol
thank
s
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subtract 8 7/8 from 23 1/4
Provide work
15
1/4 - 7/8
5/8
Alright look
okay so break 1 off 23
to get 4/4
it would be 22 4/4+1/4
22 5/4
now you go from there
22 5/4 - 8 7/8
now 22 - 8
14
now you do 5/4 - 7/8
Don't do the work for people
This was sufficient
he already tried it himself and i think he knows 22-8
That's what I got
WhT
Yes
so why this 8 7/8 - 23 1/4
Wdym why this
is this your old work?
sure
Right
so you need to take one from 23
So other way around
no
Okay
you need to take one from 23
Ye
so does 1/4 belong to 23 or 8
23 ig
22
that 1 just equals 4/4 now okay
so give me the full equation now
with the 22 and 4/4
22 4/4 - 8 7/8
whered the 1/4 go
1 = 4/4 correct
Yes
but we started with 23 1/4
now should be (22 1/4 + 4/4) - (8 7/8)
you cant just get rid of the 1/4 understand?
Got it
so subtract the constants now and tell me what you get
when I say constants i mean non fraction numbers
10/8 - 7/8 = 3/8
๐๐๐
well yes that is correct for the fractions
thats correct now do the whole numbers
22-8 = 14
now combine those two solutions
14 3/8
there it is
do you understand it though
you need to take one away from the constants because you cannot find a negative fraction without having negative rope as well
Yeah so
yes any further qs?
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Tysm
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I'm trying to find the coefficient of x^5 in the expansion of (1 + x + x^2)^8 and I think I've reduced it to finding the number of natural number solutions to y_0 + 2y_1 + 3y_2 = 13, but I'm not sure how to do that. Could someone give me a hint?
Well id treat it as binom
$$(x^2 + (1 + x))^8$$
So we get
$$x^{16} + {8 \choose 1}x^{14}(1 + x) + {8 \choose 2}x^{12}(1 + x)^2 ... + (1 + x)^8$$
Pluton
Maybe it helped maybe it didnt
if i'm right you can consider the polynom f(x) = 1 + x + x^2 as a 3-vector (1,1,1), let A be (1,1,1) then we can consider the vector associated with f(x)^2 as the convolution between A and A.
So the vector associated with f(x)^8 would be foundd by making A = convolution(A,A) 3 times in a row (because 8 = 2^3) then the sixth value of the final vector A would be the coefficient of x^5 in the expanded polynom
it's been only 24 hour i know what is a convulotion so maybe i'm wrong though xd
We ignore first few so we focus only on
$$(1 + x)^8 + {8 \choose 1}x^2(1 + x)^7 + {8 \choose 2}x^4(1 + x)^6$$
Pluton
$$(1 + x)^8$$ has coefficient of $x^5$ as ${8 \choose 5}$
Now just calculate for other ones
Pluton
@dull flax Has your question been resolved?
>>> import numpy as np
>>> a = np.array([1,1,1])
>>> for i in range(3) :
... a = np.convolve(a,a)
>>> print(a)
[ 1 8 36 112 266 504 784 1016 1107 1016 784 504 266 112
36 8 1]```
well i guess that works
i'm responding to the guy that want a way to calculate the coefficient of x^5 :(
so sorry
fairs
@dull flax Has your question been resolved?
@dull flax Has your question been resolved?
<@&286206848099549185>
this is the question
@dull flax Has your question been resolved?
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oops
Closed due to the original message being deleted
ok
this
didnโt mean to send the second pic, only the frost
anyways i thought that you just do the integral from 2 to 6, which gives you choice A
but thatโs wrong, and the right answer is C and iโm confused why
<@&286206848099549185>
dont @ helpers until no one responds for 15 mins
itโs 11:17 at night
So
nobodyโs on
The integral from 2 to 6 seems right conceptually. Maybe double check your work?
Total difference takes into account the negative area as well.
that doesnt mean you can do that, theres rules for a reason
itโs a calculator question
then use symbolab lol
Are you using radians
yes
Doing the integral from 2 to 6 is wrong yes.
Because there are roots in between 2 to 6
wait idk what this means
i see but how does that
Take the absolute value
of
Ohhhh distance and not displacement
yes
I get it now
total distance
wait iโm not like
The velocity is changing from negative to positive to negative to positive so the displacement will be around 0. Hence why you got a small number for A
When you graph the velocity of an object, the area is considered the amount of distance traveled. Seeing as he is moving right to left, -
yes what he said.
ohhh i understand
So to get total distance you need to do absolute value so the negative adds to the distance instead of subtract
ok ok ima do that
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hiya, the problem is finding the extrema of $$f(x,y,z)=\abs{2x+y+z-2}$$ subject to the constraints $$y^2-xz=1$$ and $$z^2-xy=1$$ using lagrange multipliers
dino
I thought to consider when 2x + y + z - 2 is non-negative first