#help-27

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fervent jewel
steel sage
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And you did correctly

torn vessel
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looks good

fervent jewel
#

๐Ÿฅณ

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ty

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vague obsidian
#

Quick question: why do I get a different answers when I multiply the whole equation by 9 and when I just simplify 5/9 and 18?

main gull
#

Because if you multiply the right side by 9, you also have to do it on the left side

vague obsidian
#

Oh

main gull
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So you'd end up with 9c = 5 * 18

vague obsidian
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wait is not 9c = 5 * (18*9)

main gull
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No

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Because 5/9 * 18 * 9, the 9s cancel

vague obsidian
#

OHHHHHHH

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that make sense

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thank you

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analog trellis
#

I'm stuck on finding the Mobius map...could anyone help? In class we showed how to construct a mobius map that takes three points to another three points, but how to do this problem?

analog trellis
#

<@&286206848099549185>

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pls

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๐Ÿฅบ

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river trout
#

yo g's need help with a question:
2 ร— โˆš3 ร— (sin(2x))=3 ; 0<x<2pi
Need to determine all the possible solutions

magic galleon
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,tex $2 $\sqrt{3} \sin 2x = 3, 0<x<2 \pi$

river trout
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uhm not quite

pallid vector
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$2 \sqrt{3} \cdot sin(2x) = 3 ; 0 < x < 2\pi$

woven radishBOT
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Si Arya

river trout
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๐Ÿ‘

magic galleon
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so what have you done?

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pls show us your working

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or any thoughts

river trout
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aight

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so

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2 ร— (sin(2x))= 3 x 3^2
(sin(2x))= 27/2
(sin(2x)) = 13.5

magic galleon
river trout
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uhm cause it was โˆš3 so it goes to the other side yk and now its power of 2 instead of square root

river trout
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nah chill

magic galleon
river trout
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ong thats what i remember

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so what would it be then?

magic galleon
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3^-1/2

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not 3^2

woven radishBOT
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||๐“š๐“ช๐“ผ๐“น๐“ฎ๐“ป||

magic galleon
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@river trout

river trout
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ahhhh

magic galleon
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just treat sqrt(3)

river trout
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that makes more sense

magic galleon
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as a regular number

river trout
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alr cool

magic galleon
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cool so can we continue

river trout
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yessir

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this is non calc, let me do the calculation rq

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1 sec

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so 1/โˆš3 x 3 = โˆš3

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so then sin(2x) = โˆš3/2

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and i know what to do from here

woven radishBOT
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||๐“š๐“ช๐“ผ๐“น๐“ฎ๐“ป||

river trout
#

nah that aint right

magic galleon
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why?

magic galleon
river trout
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its โˆš3/2

charred bolt
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same thing lol

magic galleon
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yea

pallid vector
magic galleon
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if you do the rationalise

river trout
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nah but idk why you do it like that

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when it clearer when its โˆš3/2

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as โˆš3/2 is a clear sin value of 60

magic galleon
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fine

river trout
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anyways thats all

magic galleon
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but you skipped the step bro

river trout
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thanks for the help ๐Ÿ‘

#

ik what to do

magic galleon
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I'm just doing division

river trout
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trust

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yeh ik only thing i was having trouble with was rearranging it

magic galleon
#

Yea if that's what you want

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I respect your opinions

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restive river
#

Hello! I'd like to compute this beauty. Does anyone have an idea ? I guess it is impossible to find an analytic solution

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near shoal
#

help

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near shoal
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i dont get why (f f)=(0,4)

supple trench
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because order of elements doesn't matter in a set

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i.e. {0,4} = {4,0}

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but $(0,4) \ne (4,0)$

woven radishBOT
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vin100

near shoal
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is this like

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graph coordinates?

supple trench
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i would say graph coordinates use this $(?,?,?,\dots)$ structure

woven radishBOT
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vin100

supple trench
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because each axis is supposed to have a different role to play\

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say in the 2D case, using the Cartesian coordinates

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the $x$-axis and the $y$-axis are the independent and dependent variables respectively.

woven radishBOT
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vin100

near shoal
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so why is range the of (f f) = set {0,4}?

winter patrol
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the range of f is {-2,0,2,4}
if you plug those values into f again, it'll come out as 0 or 4

near shoal
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ah

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im stupid

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didnt notice that

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thanks for the help

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amber dock
#

help

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amber dock
#

Im Confused on the median and mode

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@amber dock Has your question been resolved?

amber dock
#

<@&286206848099549185>

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amber dock
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worn crystal
#

i need to find the height of the container, i dont know how. any help?

small field
#

I think it wants you to assume you got a right angle

worn crystal
#

im sorry i dont understand ๐Ÿ˜ฆ

small field
worn crystal
worn crystal
small field
worn crystal
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but i need to write how i got the answer ๐Ÿ™‚

sonic spruce
#

ah yes

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h =โˆš(250ยฒ-150ยฒ)

worn crystal
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ah ty

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small field
#

my g doesn't know trig

worn crystal
#

look i hate math okay๐Ÿ˜‚

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craggy quiver
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craggy quiver
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why doesn't order matter?

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i thought because theres 6 possible answers that are wrong and your choosing 3

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you would multiply that by 5C3

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but you dont?? why?

weak tundra
craggy quiver
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i did this x 5c3

weak tundra
craggy quiver
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yh and p=0 is probability they choose all 3 incorrect answers, right?

weak tundra
# craggy quiver

The 5 wrong answers are fixed. You can't change the 3 correct answers to the question

craggy quiver
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i dont understand what fixed means

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you cant answer them in a different order?

weak tundra
# craggy quiver i dont understand what fixed means

Fixed means doesn't change.
You just have to choose 3 answers.

Say the question had options:
1 2 3 4 5 6 7 8
and 2,3,4 are correct. [This is fixed. Suppose the question was "Please choose 2,3,4". The correct answers are 2,3,4 and 2,3,4 only. This is fixed, because the question is fixed. Fixed means doesn't change.]
Then the probability of getting none correct is choosing something out of 1,5,6,7,8. There are 5C3 choices you can make out of a total of 8C3, so 5C3/8C3 is the ans.
Or 5/8 * blabla as ms did

craggy quiver
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i dont understand how there are 5c3 choices you can make out of 8c3

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can we do it in terms of probabilities first?

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ok so 12345678, 234 are correct

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which means probability of someone picking 167 is 5/28? yes or no?

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ohhh wait a second

craggy quiver
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i think i just realized fixed

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your saying

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order dont matter

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123 is same as 231 because they are all picked at once?

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i understand the 5c3 now

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however i dont understand why 8c3 is total

weak tundra
weak tundra
craggy quiver
#

hmmmmmm i thiiink i get it maybe

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yes, yes i get it.

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now i just need to make sure it sticks.

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ahh, ok thanks for the help appreciate it

#

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agile narwhal
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agile narwhal
#

Is this correct

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?

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restive river
#

I'm supposed to prove this identity

I've tried multiplying the right side's first term with 1 + tanA/1 + tanA

restive river
#

I've also tried doing something similar with the right side's second term
but I can never get them to make sin A + cos A

turbid locust
restive river
#

would I get sinA.cosA/ 1 - cos A?

turbid locust
#

uhm i dont think so

restive river
turbid locust
#

$$\frac{\cos A}{1-\frac{\sin A}{\cos A}} - \frac{\sin^2 A}{\cos A - \sin A}$$

woven radishBOT
#

Nathan_

turbid locust
#

them multiply the left fraction by cos/cos

restive river
#

wouldn't the sin A at the bottom multiply with the cos A?

turbid locust
#

$$\frac{\cos^2 A}{\cos A -\sin A} - \frac{\sin^2 A}{\cos A - \sin A}$$

woven radishBOT
#

Nathan_

restive river
#

I mean wouldn't the sinA that's underneath the cosA go to the top?

turbid locust
#

there is no sin A underneath a cos A
tan = sin/cos so its the cos that is underneath

restive river
#

it's a random example
just checking if my math is right
I understand how to prove the identity tho thks

#

this is what I meant

turbid locust
#

where have you got that from though?

restive river
turbid locust
#

oh right lol

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1/(1+tan) = cos/(cos+sin)

restive river
#

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turbid locust
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stoic crystal
#

What is the complement of the intersection between two sets when the sets are disjoint

distant harbor
#

U

stoic crystal
#

$(P\cap Q)'$

woven radishBOT
#

JUGisMUG

stoic crystal
#

P and Q are disjoint

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Oh wait

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The universal?

distant harbor
#

ye

stoic crystal
#

Ok so a set being disjoint does not affect anything about (P int Q)'

#

Thanks

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dreamy pine
#

how do I do c. ii?

devout snowBOT
dreamy pine
#

cuz theres no values so I dunno if area is possible

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@dreamy pine Has your question been resolved?

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@dreamy pine Has your question been resolved?

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@dreamy pine Has your question been resolved?

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indigo abyss
#

can someone please explain how to solve this?

supple trench
#

symmetry is great sosad u cant use that

west pulsar
#

3*Pi/2 is the only number thats coming to me rn

supple trench
#

think about the period of $r(\theta)$

woven radishBOT
#

vin100

supple trench
#

when 1 is added to $\sin(\theta)$, what are the roots of $r(\theta) = 0$?

woven radishBOT
#

vin100

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tawny horizon
#

yo

devout snowBOT
#

Please don't occupy multiple help channels.

main gull
# tawny horizon yo

Someone was literally helping you in your other channel you had, and asked for your work, if you are still doing that problem

tawny horizon
#

i know how to solve it but how is answer 79.6

tawny horizon
#

thats the problem

main gull
#

Show your work on what you did

#

Write it out

#

Paint or something

tawny horizon
#

okay

restive river
#

Or @woven radish

tawny horizon
#

i will

#

so

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16400 x 4/100 x 3 /100

main gull
tawny horizon
#

=19.68 + 16400

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and compound interest

main gull
tawny horizon
#

16400(1 + 4/100)to the power of 3

#
  • 16400
#

how is the answer 79.6

pseudo basin
pseudo basin
#

did the investment only last 0.03 years, i.e. eleven or so days?

tawny horizon
#

no

pseudo basin
#

no, of course not. it lasted 3 years and your calculation should reflect that.

tawny horizon
#

its a fraction

#

it lasted 3 years

pseudo basin
#

yes, but there is no reason to divide the duration by 100.

tawny horizon
pseudo basin
#

also, you calculated the total for one plan, but only the interest for the other. so of course you get bullshit if you try to subtract them.

tawny horizon
#

i was doing without adding and subtracting but the ms was telling me otherwise

#

@pseudo basin

pseudo basin
#

??

tawny horizon
#

you just disappeared

pseudo basin
#

wym disappeared

tawny horizon
#

are you a helper

pseudo basin
#

i never went anywhere

tawny horizon
#

?

pseudo basin
#

no, i don't have the helper role

#

will you now tell me to fuck off on those grounds?

tawny horizon
#

nah

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can you help

pseudo basin
tawny horizon
#

lol

#

if you dont mind

pseudo basin
#

both because you are being cryptic in showing your work and because i haven't seen your mark scheme

tawny horizon
#

okay i will solve again

#

one sec

#

how do you even draw the answers out on paint

#

can you solve it

#

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obtuse slate
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obtuse slate
lilac heath
#

it resembles your pfp

obtuse slate
#

wdym

wooden zodiac
#

egg

lilac heath
#

oh did i offend you

obtuse slate
#

oh you mean my profile picture?

#

i didn't know what pfp means

#

lol

#

ellipses = egg

#

<@&286206848099549185>

buoyant coyote
#

you might have calculated something wrong

obtuse slate
#

the major vertices = 4
the minor vertices = 6
Center = (-3,2)

#

is this right?

buoyant coyote
obtuse slate
#

did i miscount on the graph?

buoyant coyote
#

perhaps

#

count again

buoyant coyote
obtuse slate
#

i think the minor vertices is 12.

#

Is the minor vertices the entire length of the ellipse or just the center to the end?

buoyant coyote
obtuse slate
#

yes but they are ___ amount of spaces away from the center

#

im pretty sure I did not miscount

buoyant coyote
#

then try graphing your answer

obtuse slate
#

It looks shorter than the graph given

#

.close

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devout snowBOT
#

@peak lark Has your question been resolved?

weak tundra
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@peak lark Has your question been resolved?

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@peak lark Has your question been resolved?

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restive river
devout snowBOT
restive river
#

can someone explain this solution

#

for a!=0

#

how do they say that b/a = 0

torn vessel
#

Once you have 1 in the bottom right, do roe operations to make the top right =0

torn vessel
torn vessel
#

-b/a*R_2 + R_1 โ€”> R_1

restive river
#

whats R_2

#

and R_1

torn vessel
#

row 2

#

row 1

restive river
#

so its

torn vessel
#

multiply the second row by -b/a

#

add it to the first row

restive river
#

why is it

#

-b*a

#

b/a

torn vessel
#

to get 0 in the top right

restive river
#

im so confused

#

if you multiply the second row by -b/a

#

wouldn't u get

#

0, -b/a

torn vessel
#

yes

#

now add that to the first row

restive river
#

but then

#

the second row is still

#

0, -b/a

torn vessel
#

so multiply it by -a/b

restive river
#

oh ok

#

its clicking

#

man thanks a lot

#

u've helped me with at least like 10 problems so far I think

#

much appreciated

#

.close

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mystic dew
#

how would you get started with this?

devout snowBOT
mystic dew
#

so far I have pulled the n out and make it (2^p/3)^n but I'm not sure what to do from there

crystal rune
#

Maybe some case work

#

p=0, p=1, 0 < p < 1, p > 1

#

(I think)

mystic dew
#

oh so would it just be sort of guess and check?

crystal rune
#

Not really, we're considering all values that p could take

#

Once you do the positive cases, you can do the negative ones similarly

mystic dew
#

ok i'll try that out, ty :)

#

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devout snowBOT
orchid sierra
#

What is your question?

#

Do you not know what equation to use?

#

Are you unable to explain your choice?

#

Are you having trouble using the equation?

#

The function takes horizontal distance, d, as an input
And outputs height

#

d is distance from the ramp

#

All stated in the problem, I am just repeating

#

Yes, but use d instead of x

#

Ok. Why did you pick that equation?

#

Since the assignment asks

#

You would do that in both equations

#

But do you mean to say

#

The first two terms become zero immediately and you just read off the third constant term?

#

goo

#

~

#

Ok, what has you stuck though, you were gonna say something

devout snowBOT
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solemn onyx
#

The sum of the sides of two squares is 21 cm and the sum of their areas is 225 cm2.
Find the length of a side of the smaller square.

winter patrol
#

what ahve you tried

solemn onyx
#

idk how to form an equation

restive river
#

did u draw

solemn onyx
#

o wait i got it

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oak forum
devout snowBOT
oak forum
#

this is what i've done so far

#

I'm still confused how to manipulate what I've got into the RHS

patent tartan
#

try also writing the RHS in sin/cos form

oak forum
#

ahh okay is the reason I'm struggling because I'm approaching it from the more difficult side?

patent tartan
#

nah looks solid so far

#

one way to prove this is to manipulate both LHS and RHS into their basic parts consisting only of sin and cos and then trying to manipulate the resulting fractions

#

so leave the LHS as is right now and play around with the RHS

near fern
#

Whats on the LHS side

#

@oak forum

oak forum
#

then I've manipulated it

near fern
#

as in whats the question a the paper thing

oak forum
near fern
#

can u take a photo?

oak forum
# near fern can u take a photo?

why the question is in the 1st image, besides theres load of other questions in the booklet on that page that would complicate it.

near fern
#

oh found it k

patent tartan
#

@oak forum did you solve?

oak forum
patent tartan
#

Write the RHS as
$$\frac{\frac{\sin A}{\cos A} + \frac{\sin B}{\cos B}}{1 - \frac{\sin A}{\cos A} \cdot \frac{\sin B}{\cos B}}$$

woven radishBOT
patent tartan
#

Now you only need to multiply and divide the fraction by a specific term to get exactly the LHS

oak forum
patent tartan
#

Hint: You want to clear the nested fractions

#

What would you need to multiply the numerator with to clear the nested fractions?

#

if you have something like 1/x + 2/y = 0 what would multiply that equation with to make the denominators disappear?

oak forum
#

am I simply just flipping the nest fraction (denominator) and multiplying the numerator (top fractions ?

devout snowBOT
#

@oak forum Has your question been resolved?

oak forum
#

@patent tartan is this correct ?

#

<@&286206848099549185>

patent tartan
#

Multiply both numerator and denominator by cos(A)cos(B)

#

@oak forum

oak forum
#

is my most recent image i sent wrong

oak forum
#

@nvx I've finally done it, sorry my severely handicapped brain wasted your time lol

patent tartan
#

@oak forum gj!

devout snowBOT
#

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#
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silk hull
#

two questions

devout snowBOT
silk hull
#

firstly

#

e^(3lnx) can be simplified to x^3

#

but e^(3lnx) cannot take some values that x^3 can

#

how does that work

#

secondly

#

i am having trouble rearranging x=(3y-5)/(y+1) to get y

tiny carbon
silk hull
#

-1

tiny carbon
#

-1^(3 * ln(-1)) = -1

silk hull
#

you cant ln a negative

#

or am wrong

magic thicket
#

The constraints stay, so x > 0

silk hull
#

what constraints

silk hull
magic thicket
#

That ln must be defined. As assuming you're studying a function for instance

silk hull
#

so when dealing with lns there must be a domain?

#

and yes this has to do with functions but i was asking about this as an independent equation

#

how does that work when its impossible to have a natural log take a negative value?

tiny carbon
#

It's not impossible..?

silk hull
#

it should be undefined no?

tiny carbon
#

It's just a complex solution

silk hull
#

like dividing by zero?

tiny carbon
#

It is just pi * i

#

I believe

silk hull
#

but i is imaginary

tiny carbon
#

So?

#

That doesn't make it impossible

silk hull
#

im talking about real answers

magic thicket
silk hull
#

x^3 will have a real answer but the e wont

tiny carbon
#

$e^{3 * ln(x)}$

woven radishBOT
#

Breeziboi

silk hull
#

e^(3ln-1) has a real value?

tiny carbon
#

Plug in -1

#

Yes

silk hull
#

my calculator wont compute it

#

says math error

tiny carbon
silk hull
#

it wont compute anything to do with lns that have negative values

tiny carbon
#

Or something

silk hull
#

but thats imaginary i mean

#

-1^3 will have a real answer

#

and thats just a simplification of the original right

tiny carbon
#

3 * ln(-1) = 3pi * i

silk hull
#

how come they give two different answers for the same value

#

if x^3 is just the original equation simplified

tiny carbon
tiny carbon
silk hull
#

no -1^3 is -1

#

real answer

tiny carbon
#

e^ln(x) = x

silk hull
#

e^(3ln-1) has an imaginary answer right

tiny carbon
#

Use exponent laws

#

Since there is a 3 in the exponent

#

Just take it out like so:

silk hull
#

natural logs cannot take negative values and give real answers

#

what am i missing here

tiny carbon
silk hull
#

but what i dont understand is

#

how come the answer for the same input (-1) is different depending on whether u input it into the simplified equation or the original one

#

shouldnt both give the same answers since theyre just the same equation one is just simplified?

tiny carbon
silk hull
#

no one gives a complex the other gives a real answer

#

thats not the same?

tiny carbon
silk hull
#

but -1^3 is just -1

tiny carbon
silk hull
#

is the exponent not part of the answer?

magic thicket
silk hull
#

no it isnt

#

wait

#

how

tiny carbon
#

Theres a proof

#

Somewhere

silk hull
#

how is e^pi i equal to minus 1

tiny carbon
#

for e^(pi * i) = -1

silk hull
#

are you sure?

tiny carbon
#

Yes

silk hull
#

wtf

magic thicket
#

ln -1 = i pi (1+2n) for any n. You can take any n because they're all valid

silk hull
#

is that just something youre supposed to know?

magic thicket
tiny carbon
silk hull
magic thicket
#

Because x -> e^ix is 2pi periodic

silk hull
#

what does periodic mean

magic thicket
#

f is T periodic iff for all x in its domain, x+T is also in the domain and f(x) = f(x+T)

silk hull
#

ok

#

now on to my second question

#

should be less theoretical im just stuck on rearranging an equation

#

i am having trouble rearranging x=(3y-5)/(y+1) to get y

#

i brought y+1 to the left side

#

so now i have x(y+1) = 3y-5

#

but im stuck with ys on both sides

magic thicket
#

y depends on x, that's to be expected

silk hull
#

i need to isolate y tho

#

and i dunno how to get rid of the xy and 3y

#

to get just y

#

ive literally been staring at xy+x = 3y-5 for ten minutes

#

all ive done in ten minutes is expand x(y+1) and im not sure thats brought me any closer

silk hull
#

my problem is the xy and the 3y

magic thicket
#

Then you can write (x-3)y and there is only one y

silk hull
#

where did you get (x-3)y from

magic thicket
#

Just move the 3y to the other side and factor y out

tiny carbon
silk hull
#

ill watch that

#

trying to figure out (x-3)y tho even if u move it to the other sid

#

side*

#

u still have an x

#

u didnt account for

#

did u move that too

magic thicket
silk hull
#

u moved the lone x to the right hand side right?

#

the x that was on the left side of the equation

magic thicket
#

Yes of course

silk hull
#

and then divided by the (x-3)

#

ok i see

#

didnt see it before

#

might be braindead

#

thanks for the help

magic thicket
#

Just consider both x and y as constants. It's a little extra abstraction but the math is the same

silk hull
#

got it

silk hull
#

i think u missed a minus

magic thicket
#

Yes

silk hull
#

ok thank you

devout snowBOT
#

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devout snowBOT
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restive river
#

<@&286206848099549185>

devout snowBOT
restive river
#

could it be 10km/h + 2km/h = 12 km/h, t= s/v= 18/12= 1,5 - answer for the 2nd one?

cold bough
#

yes you got it

restive river
#

thank you so much!

cold bough
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#

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runic turtle
#

ive got a question

devout snowBOT
runic turtle
#

how would you solve this

magic thicket
#

this is not an equation, what do you mean by "solve"

runic turtle
#

it says write equation in simplest form

restive river
#

make them both have the same denom

solid vapor
#

multiply top and bottom by 4 - root 3

runic turtle
#

oh mb i found it already

#

.close

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#
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pliant gyro
#

Hi there

devout snowBOT
pliant gyro
#

I am asking about (b)

#

I am first considering the absolute value of it and I get that it is equal to sum (1 / |a^ln(n)|)
Can I just say here that it is like 1/q^n which converges?
or is it different because ln(n) tends to inf slower than n?

pseudo basin
#

a^ln(n) is not exponential in n so yes your argument falls apart

#

in fact it is equal to n^ln(a)

pliant gyro
#

I see

pliant gyro
pseudo basin
#

$a^{\ln(n)} = e^{\ln(a)\ln(n)} = e^{\ln(n)\ln(a)} = n^{\ln(a)}$

woven radishBOT
pliant gyro
#

hmmm

#

e^ln

#

yeah

#

that's a good trick.

#

Thanks Ann

pliant gyro
pseudo basin
#

yes

pliant gyro
#

But that does not help right?

#

I mean it does

pseudo basin
#

it does

pliant gyro
#

but does not say if it converges or not

#

since we don't know if it is smaller than 1 or bigger

pseudo basin
#

well you have absolute convergence for a>e

pliant gyro
#

which is 1 yeah

#

But if a < e it does not

#

So in that case I need to split into cases?

pseudo basin
#

you have an alternating series

#

and the sequence 1/n^ln(a) goes to 0, and monotonically at that, no matter what a is (so long as it's above 1)

pliant gyro
#

But you can not assure it is above 1

#

We already learned in class that for a exponent > 1 it converges.

pseudo basin
#

and a being above 1 is what i was referring to

pliant gyro
#

I think I do understand what you're saying

#

Let me send something

pliant gyro
#

Is that correct?

pseudo basin
#

...................

#

the ratio of adjacent terms tends to 1 regardless of the value of a

#

and the limit of b_n is 0 for all a > 1 regardless of whether or not a > e

pliant gyro
pliant gyro
#

But we learned that the sequence must be decreasing

pseudo basin
#

$1/n^p$ is a decreasing sequence for all positive $p$

woven radishBOT
pseudo basin
#

yes even when 0<p<1

#

ive repeated this like three times already

pliant gyro
#

Oh yeah

#

it decreases anyways.

#

Sorry... my bad here..

#

To sum it up:
The series is converging absolutely if a > e and converging conditionally if a <= e?

pseudo basin
#

yes

#

and my energy has converged to zero

pliant gyro
#

Then I am done asking you for today

#

cya tomorrow ๐Ÿ™‚

#

Thanks for the help

#

.clsoe

#

.close

devout snowBOT
#
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tall dawn
#

hi, can aynone tell me what how to solve this

tall dawn
#

which role

mighty harness
tall dawn
#

you mean this. no i don't

woven radishBOT
#

GUNILLA62

mighty harness
#

Sure but the expression is always negative for negative h

tall dawn
#

they gave us hint. wait a sec

#

Determine the limit value by first simplifying and then extending the rational expression so that you can use the conjugate rule.

mighty harness
#

Sorry I got a sign wrong

#

Dont mind me

tall dawn
#

ok, but how

#

ok

hybrid snow
#

When in doubt with an indeterminate form, use L'Hopital

tall dawn
#

oooh, the picture disappeared

devout snowBOT
#

@tall dawn Has your question been resolved?

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nimble narwhal
#

A restaurant receives 8 cartons of milk daily. On a random day, the number of cartons with a defective screw cap among them is equal to 2. One of the employees picks up 2 cartons.
a) What is the probability that the employee receives more than 1 milk carton with the defect?
b) What is the probability that the employee receives exactly 0 defective milk cartons if the employee receives 1 or fewer milk cartons with the defect?
c) What is the expected number of cartons with the defect?
d) Calculate the variance of the number of defective milk cartons.

nimble narwhal
#

No idea how to come any closer to the answer. previous task asked about the p of 0 defected cartons, I got it correct, 0,536

devout snowBOT
#

@nimble narwhal Has your question been resolved?

nimble narwhal
#

<@&286206848099549185>

marsh linden
marsh linden
#

b) for n = 1
itโ€™s 2/8 * 6/7 = 3/14 = 6/28
for n = 0
itโ€™s 6/8 * 5/7 = 15/28
so total probability of clause is 21/28 = 3/4
answer is 15/28 divided by 3/4 (bayes theorem)

#

c) 1/4 * 2 + 3/14 * 1 = 5/7 . so almost 1

#

d)use your calc or the formula for variance

#

@nimble narwhal

mighty harness
marsh linden
#

but I feel like expansions for 0/0 or infinite /infinite limits are a bit of an overkill

#

but hey, if it works, it works

nimble narwhal
#

I didn't really got c. b is also saying wrong (it is a homework where I get if the answer is correct right away)

nimble narwhal
#

@marsh linden

#

<@&286206848099549185>

tiny carbon
#

.close

devout snowBOT
#
Channel closed

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tiny carbon
#

You have a much more recent channel

devout snowBOT
#
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wooden veldt
#

Take the standard parameterization of a cone

#

And mess with it to get it to look like the one you want

devout snowBOT
#

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dense trout
#

I have a question, does the converse of the power rule true for all natural numbers n?

dense trout
#

<@&286206848099549185>

#

.close

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#
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normal sleet
#

Could someone check if itโ€™s right

devout snowBOT
normal sleet
#

Just rough sketch

#

Donโ€™t mind the extra lines

twin flame
#

This looks good, I would just mark on the maximum turning point coordinates and the point at x=4 where it has a root

normal sleet
#

Ok tysm

#

.close

devout snowBOT
#
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#
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mighty harness
devout snowBOT
#

@mighty harness Has your question been resolved?

devout snowBOT
#
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craggy quiver
devout snowBOT
craggy quiver
#

if cos(x) = cos(-x)

#

why does cos(a-x) not equal cos(a+x)

green inlet
#

I think it might be because the cos(a-x) starts at a minus going to a plus while cos(a+x) starts with a plus going to a minus

#

Or vice versa

winter patrol
#

-(a-x) isn't a+x

placid narwhal
#

Let $a - x = s$
$cos(s) = cos(-s)$
Substitite back

woven radishBOT
#

Pluton

craggy quiver
#

how did i mess that up lol

#

thank

#

s

#

.close

devout snowBOT
#
Channel closed

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bitter night
#

Hello I need help

devout snowBOT
bitter night
#

I got

#

32 1/8 as my answer

#

But it says A is the answer

shrewd dock
#

subtract 8 7/8 from 23 1/4

bitter night
#

Sir I did

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I got 257/8

shrewd dock
#

start with whole numbers first

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23-8

main gull
bitter night
#

15

shrewd dock
#

1/4 - 7/8

bitter night
#

5/8

bitter night
shrewd dock
#

okay so break 1 off 23

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to get 4/4

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it would be 22 4/4+1/4

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22 5/4

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now you go from there

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22 5/4 - 8 7/8

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now 22 - 8

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14

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now you do 5/4 - 7/8

main gull
main gull
bitter night
#

Welp

#

8 7/8 - 23 1/4 = 71/8 -182/8= 13 7/8

shrewd dock
#

he already tried it himself and i think he knows 22-8

bitter night
#

That's what I got

bitter night
#

But it's 23

shrewd dock
#

no

#

you're subtracting 8 from 23

#

not 23 from 8

#

its 23 1/4 - 8 7/8

bitter night
#

WhT

bitter night
shrewd dock
#

so why this 8 7/8 - 23 1/4

bitter night
#

Wdym why this

shrewd dock
#

is this your old work?

bitter night
#

No

#

I look

#

I solved the mixed numbers

#

Then

#

Found a LCM

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And subtracted them

shrewd dock
#

do constants first

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then fractions

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dont mix right away

bitter night
#

Hmmm

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So

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1/4 - 7/8

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First

shrewd dock
#

sure

bitter night
#

?

#

Alright

#

So

shrewd dock
#

but you dont want a negative

#

because you cant have negative rope

bitter night
#

Right

shrewd dock
#

so you need to take one from 23

bitter night
#

So other way around

shrewd dock
#

no

bitter night
#

Okay

shrewd dock
#

you need to take one from 23

bitter night
#

One from 23

#

Then

shrewd dock
#

1/4

#

so

#

4/4 = 1 yes

#

?

bitter night
#

Ye

shrewd dock
#

so does 1/4 belong to 23 or 8

bitter night
#

23 ig

shrewd dock
#

yep

#

so take one from 23

#

23-1

bitter night
#

22

shrewd dock
#

that 1 just equals 4/4 now okay

#

so give me the full equation now

#

with the 22 and 4/4

bitter night
#

22 4/4 - 8 7/8

shrewd dock
#

whered the 1/4 go

bitter night
#

Wha

#

You said 4/4

shrewd dock
#

1 = 4/4 correct

bitter night
#

Yes

shrewd dock
#

but we started with 23 1/4

bitter night
#

Right

#

Alright

#

23 1/4 - 8 7/8

shrewd dock
#

now should be (22 1/4 + 4/4) - (8 7/8)

bitter night
#

Alright

#

So

shrewd dock
#

you cant just get rid of the 1/4 understand?

bitter night
#

Got it

shrewd dock
#

so subtract the constants now and tell me what you get

#

when I say constants i mean non fraction numbers

bitter night
#

10/8 - 7/8 = 3/8

bitter night
shrewd dock
#

well yes that is correct for the fractions

bitter night
#

Welp

#

My bad

shrewd dock
#

thats correct now do the whole numbers

bitter night
#

22-8 = 14

shrewd dock
#

now combine those two solutions

bitter night
#

14 3/8

shrewd dock
#

there it is

bitter night
#

Wow

#

We got A

shrewd dock
#

do you understand it though

bitter night
#

Kind off

#

One thing I didn't understood is

shrewd dock
#

you need to take one away from the constants because you cannot find a negative fraction without having negative rope as well

bitter night
#

Why did we take One from 23

#

And how the whole 4/4

shrewd dock
#

because 4 divided by 4 equals 1

#

4/4 = 1

bitter night
#

Yeah so

shrewd dock
#

so we turn one into its fraction form

#

we are given its fraction form with 1/4

bitter night
#

Hmmm

#

I see

#

Tysm

shrewd dock
#

yes any further qs?

bitter night
#

Nah that's it

#

You can close this channel now

shrewd dock
#

okay best of luck with the rest

#

.close

devout snowBOT
#
Channel closed

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bitter night
#

Tysm

devout snowBOT
#
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dull flax
#

I'm trying to find the coefficient of x^5 in the expansion of (1 + x + x^2)^8 and I think I've reduced it to finding the number of natural number solutions to y_0 + 2y_1 + 3y_2 = 13, but I'm not sure how to do that. Could someone give me a hint?

placid narwhal
#

Well id treat it as binom

#

$$(x^2 + (1 + x))^8$$
So we get
$$x^{16} + {8 \choose 1}x^{14}(1 + x) + {8 \choose 2}x^{12}(1 + x)^2 ... + (1 + x)^8$$

woven radishBOT
#

Pluton

placid narwhal
#

Maybe it helped maybe it didnt

restive river
#

if i'm right you can consider the polynom f(x) = 1 + x + x^2 as a 3-vector (1,1,1), let A be (1,1,1) then we can consider the vector associated with f(x)^2 as the convolution between A and A.
So the vector associated with f(x)^8 would be foundd by making A = convolution(A,A) 3 times in a row (because 8 = 2^3) then the sixth value of the final vector A would be the coefficient of x^5 in the expanded polynom

#

it's been only 24 hour i know what is a convulotion so maybe i'm wrong though xd

placid narwhal
#

We ignore first few so we focus only on
$$(1 + x)^8 + {8 \choose 1}x^2(1 + x)^7 + {8 \choose 2}x^4(1 + x)^6$$

woven radishBOT
#

Pluton

placid narwhal
#

$$(1 + x)^8$$ has coefficient of $x^5$ as ${8 \choose 5}$

#

Now just calculate for other ones

woven radishBOT
#

Pluton

devout snowBOT
#

@dull flax Has your question been resolved?

restive river
#
>>> import numpy as np
>>> a = np.array([1,1,1])
>>> for i in range(3) :
...     a = np.convolve(a,a)
>>> print(a)
[   1    8   36  112  266  504  784 1016 1107 1016  784  504  266  112
   36    8    1]```
restive river
#

i'm responding to the guy that want a way to calculate the coefficient of x^5 :(

#

so sorry

devout snowBOT
#

@dull flax Has your question been resolved?

devout snowBOT
#

@dull flax Has your question been resolved?

dull flax
#

<@&286206848099549185>

devout snowBOT
#

@dull flax Has your question been resolved?

devout snowBOT
#
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devout snowBOT
#
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devout snowBOT
atomic river
#

oops

devout snowBOT
#
Channel closed

Closed due to the original message being deleted

atomic river
#

ok

#

this

#

didnโ€™t mean to send the second pic, only the frost

#

anyways i thought that you just do the integral from 2 to 6, which gives you choice A

#

but thatโ€™s wrong, and the right answer is C and iโ€™m confused why

#

<@&286206848099549185>

crimson drift
#

dont @ helpers until no one responds for 15 mins

atomic river
#

itโ€™s 11:17 at night

zealous oyster
#

So

atomic river
#

nobodyโ€™s on

zealous oyster
#

The integral from 2 to 6 seems right conceptually. Maybe double check your work?

proper lark
#

Total difference takes into account the negative area as well.

crimson drift
#

that doesnt mean you can do that, theres rules for a reason

atomic river
#

itโ€™s a calculator question

crimson drift
#

then use symbolab lol

atomic river
#

wdym mmao

#

itโ€™s not abt plugging it in

#

like doing integral from 2 to 6 is wrong

zealous oyster
#

Are you using radians

atomic river
#

yes

proper lark
#

Doing the integral from 2 to 6 is wrong yes.

#

Because there are roots in between 2 to 6

atomic river
proper lark
#

that you need to account for

#

Look at the roots between 2 to 6

atomic river
#

the roots?

#

should i graph it

proper lark
#

precisely

#

From 2 to 6

#

it has 3 roots

atomic river
#

i see but how does that

proper lark
#

Take the absolute value

atomic river
#

of

zealous oyster
#

Ohhhh distance and not displacement

proper lark
#

yes

zealous oyster
#

I get it now

proper lark
#

total distance

zealous oyster
#

Right

#

Yeah listen to this guy

atomic river
#

wait iโ€™m not like

zealous oyster
#

The velocity is changing from negative to positive to negative to positive so the displacement will be around 0. Hence why you got a small number for A

proper lark
#

When you graph the velocity of an object, the area is considered the amount of distance traveled. Seeing as he is moving right to left, -

#

yes what he said.

atomic river
#

ohhh i understand

zealous oyster
#

So to get total distance you need to do absolute value so the negative adds to the distance instead of subtract

atomic river
#

ok ok ima do that

devout snowBOT
#
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gleaming grove
#

hiya, the problem is finding the extrema of $$f(x,y,z)=\abs{2x+y+z-2}$$ subject to the constraints $$y^2-xz=1$$ and $$z^2-xy=1$$ using lagrange multipliers

woven radishBOT
gleaming grove
#

I thought to consider when 2x + y + z - 2 is non-negative first

woven radishBOT