#help-27
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I see.
doesn't jive with the wording of the problem imo

i'm just going to report it for incorrect answer and move on
thanks for the help 
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find b/a where 2a^2=(a+b)^2
<@&286206848099549185>
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@soft shore Has your question been resolved?
FYI, I can help you with this

a^2=2ab+b^2
ohh
Now quadratic formula
Hopefully from there, you should get it
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is this assumption correct?
$gcd(2a,2b) = 2 \implies gcd(a, 2b) \leq 2$
Crown
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Can someone explain how to convert 31,680 ft and 5 in to miles? I know the answer is 6.00094696969697 but I don't know how to get there.
1 mile = 5280 feet
thanks
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I sketched S but I'm stuck on the second part of the question
@restive river z2 is the point in S furthest away from the origin
for z1, imagine an idealized, perfectly straight windshield wiper hinged at the origin and rotating counterclockwise; z1 is the first point in S that it hits.
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Thought of factoring 324 as 2^2 * 3^4 (since 324 is in every pair) rewrite the equation to see where's going but can't see anything
or maybe highlight the common factors?
I can only see completing the square as $324 = 18^2$
वाह्य
$a^2 + b^2 = (a-b)^2 + 2ab$
वाह्य
search up sophie-germain identity
If this doesn't work
But if I wanted to use sophie-garmain identity I should change 18^2 to x^4
felipee
$10^4 = (10^2)^2$
वाह्य
I think you need this tbh
felipee
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
still leaving 10^2
okay
I'm a bit confused how to use the method
knowing that I have to transform 18^2 to x^4
(3^2 * 2)^2
324/4=81=3^4
Oh....
Sorry for that I'm dumb
okay so I did the formula
and so, I have to do it with the 5 pairs and simplify everything?
Noticed that right now
I'll do the latex 1 minute
Actually nevermind, too big
1 question
4*3^4 = (2b^2) = (2.3^2)
or is it (3^4)^2
Where did you get 4*3^4=(2b^2) from?
Right so you would want to find the b term from 4*3^4 and plug that into (a^2 + 2b^2 - 2ab)
Sorry I'm not exactly sure what you're asking
Are you asking if it's (2b)^2 vs 2(b^2)?
${2b^{2} = 2.3^{2} or 2.(3^{4})^{2}}$
felipee
I'm asking if a^4 will stick to it
okay
Remember that you set 4b^4=324 so b^4=81
Are you using . as multiplication? Because I suggest not to do that, because that looks like a decimal
Oh sorry
\cdot
thank you
in latex
or \times
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I still don’t know where I’m going wrong so I’d appreciate any help. I don’t even know what the max and min is 🤦♂️
Maximum distance both vectors pointing in opposite directions
min distance when both pointing in the same direction
वाह्य
correct me if I am wrong
@odd saddle Has your question been resolved?
Thank you, but how would I even begin to answer it? Someone told me I should do the square length of v and w separately with cos
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I choose a random integer $n$ between $1$ and $10$ inclusive. What is the probability that for the $n$ I chose, there exist no real solutions to the equation $x(x+5) = -n$? Express your answer as a common fraction.
crabbo
my answer is that every n will have a real solution
and your reasoning for this?
thats sortof my answer
???
Well ok, and I tell you I'm not convinced at all by your reasoning.
There is none.
Reason in a way that would leave me with no doubts there are real solutions no matter what n is.
Brute force, logic, whatever.
@restive river what is the probability of an event that is guaranteed to happen?
actually wait
i think you may have screwed up since the last time you came here w/ this problem and none of us noticed
you calculated the discriminant of x(x+5) = -n, yes?
...ping me when/if you reply
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@restive river when does a quadratic have no real solutions?
Hint: It has to do with the discriminant of a quadratic
they already calculated the discriminant earlier
but i think they did so incorrectly and so i'm asking them to restate what they got
just to be sure
but crabbo is intentionally refusing to provide
shock
f
?
shock they're not posting their working / answering the question(s)
genuine shock or sarcastic shock?
latter
Thought the \s was implied from the crossout.
I mean that's how I parsed it
right
@restive river Has your question been resolved?
You can't force someone to learn 🤷
The public education system tries hard enough as it is
they came here to get help
it's disrespectful on their part to completely ignore ppl trying to hep them
I wonder whether they wanted help or solutions
We'll never know for sure I guess
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I am confuse confused understanding frequency distribution and understanding contingency table
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I need help with this (I will translate if needed)
so.. you're looking for the amount of value gained?
The percentage of value gained
I will be doing other questions so please ping me if u have anything I really need help with this one
<@&286206848099549185>
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so here's the problem, I gotta turn into a + bi
I used euler's formular twice
to get this for a
and this for b
my question is if I messed up the calculation or if the conceptual idea is wrong
I did euler's to the upper exponential
to get 7(cos(pi/3) + isin(pi/3))
then separated my new one into two exponentials being multiplied by each other
and did euler's again
realizing now I forgot to distribute the seven to b
cool
that'll do it
you know sometimes all I need is someone to talk out my answer to
so thanks for existing, server
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there are four married couples at a party, how many ways can they sit around a circular table where the couples cannot sit next to each other? i know that the amount of ways they can sit around the table without restrictions is 5040, but how do i put it where the couples cannot sit next to each other when everyone in the party as a spouse? i cannot find a way to figure it out
Use the compliment. Figure out how many ways at least one couple is sitting together and take that away from the total number of ways they can sit
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@tight crypt Has your question been resolved?
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<@&286206848099549185>
You have to wait at least 15 minutes before pinging
Also, you pinged before even asking anything
sorry im very confused on the ssytem
can you help me tho
how can i solve this im stuck on it
h(x) = x^4-x^3+2x^2-4x-8
i got -1,0,-2,6
as the zeros
but that isnt right
i tried doing it like with quadratic formula
and it wasnt working
it keeps giving me these numbers
Can you provide your work?
You see that expression at the end, after doing synthetic division? The x^3 - 2x^2...
Apply factor by grouping
i havent been taught that
what is that
my goal is to get it into that little like criss cross thingy
that happend on nuimhber 1
but idk how
I'm pretty sure that you've been taught it, it's a factoring method for cubics
bro im being so serious idek wat cubics is
im in alg 2
my teacher doenst teach like "normal" he teaches his own way but idk how to do it
Cubics is the name of an expression that has power of 3
oh okay
This algebra video tutorial explains how to factor by grouping when you have a polynomial with 4 terms. It provides plenty of examples and practice problems showing you how to factor quadratic and cubic polynomial expressions by factoring completely.
I suggest viewing this
Yes
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I have a few math questions that need to be done... if anyone is free can you help? (pls ping me @quasi wind )
Dont ask to ask.
Solution set
find the solutions to that system
then give them the largest y value.
So just solve for x?
yes.
Ok
then find the largest y value.
is this a multiple choice question
What do they mean by "y" though...
they are trying to say y(x) = highest value
so solve for the equation set
what x solutions did you get
the y value of the points of intersection..
y-intercept?
nowhere did I say intercept, so no.
oh, so 3.782
why do you think it's correct?
I graphed the equations in desmos
Yeah but the actual point of intersection clearly isn't useful
cause they don't ask about anything quantitative
what does the point of intersection represent here?
what happens when revenue=expense?
No profit.
yes.
The graph is constant
No
(a perfect line)
Still no
Wha
That picture has no meaning whatsoever
Oh
Nor, should you be graphing anything.
revenue = expense at the POI as I said already
so they break even at the POI.
So yeah, I get this. The more the revenue goes past the expense, the higher the earnings.
But what does that mean?
Ohh
You made back exactly how much you spent.
yes
Ok
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hello
so im given the function and have to find the derivative and then the value when x = 2pi/3
$$f(x)=\frac{sin(2x)}{cos(x)}$$
heep
i start buy doing quotient rule
$$f'(x) =\frac{cos(x)*(cos(2x) * 2 - sin(2x)*sin(x)}{cos^{2}(x)}$$
heep
i think plug in 2pi/3 and got -1/2 / (1/4) which is not correct
so i was wondering if my calc was right and just the angles i was incorrect with
.
you should prob simplify that
ahh
oh i didn't simplify i just plugged in 2pi/3 since it seemed like stuff would cancel
I see... You've mistaken the derivative of cos x as sin x
It should've been -sin x
ah so it should be
$$f'(x) =\frac{cos(x)*-(cos(2x) * 2 - sin(2x)*sin(x)}{cos^{2}(x)}$$
heep
no
cos times derivative of (sin 2x) - sin(2x) times derivative of (cos x)
im sorry
in numerator
$$f'(x) =\frac{cos(x)*(cos(2x) * 2 + sin(2x)*sin(x)}{cos^{2}(x)}$$
gog IGGa
the last sin in numerator should be negative
yes
$$f'(x) =\frac{cos(x)(cos(2x) * 2 - sin(2x)-sin(x)}{cos^{2}(x)}$$
not the -cos 2x
what
ehhh
heep
i copied and pasted my previous line i forgot to take the mistake out
no it should all be positive
wdym I think this equation is right cause if i plug in 2pi/3 in all the x
i get 4/(1/4) or -1
which on my guide says is correct
yeah and then the denominator gives me the negative to get -1 so all is well :D
ty for the help tonight
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Can someone explain why these are not the same...
<@&286206848099549185>
You have to wait at least 15 minutes before pinging helpers
mb
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,rotate
Write it as $ax^2+bx^2+c=0$
azeem321
yh
so you can apply the discriminat
Yes
For the $x^2$ terms you can write it as $(1+m^2)x^2$
azeem321
which question we doing btw (@_@;)
if you get imaginary solutions, it means you went wrong in your workings somewhere
last part
,w 100m^4-4(m^2+1)(100m^2-20)=0
🤔
Write the line eqn. m = y/(x-10) = -x/y and x^2 + y^2 = 20
whats wrong?
Nothing.
oh
,w solve 100m^2 = 20(1+m^2)
yh i got the above too on my calculator
It seems you went wrong somewhere with $x^2+(m(x-10))^2=20$
azeem321
for starters, y^2 = -x(x-10) would give away the x coordinates of the tangent anyways.. plug, get y, get m
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Hello!
How do I check that a sequence converges or diverges?
is this your first calculus class?
Thinking about how a sine wave behaves is probably the best first intuition to have
Its y values are bounded between -1 and 1 for all infinity, and the limit as sin goes to infinity is undefined
no worries. it's best to give an answer that suits your background, hence why i ask. not to be condescending
No it's okay
When it comes to learning maths, I have no ego... lol
Can we take a step back and talk about what converge and diverge actually means for a sequence?
great question
do you have a definition in your book?
or is it assumed by your instructor you already know it
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no help on tests!
the format seems sus
anyways
probably P(k1-k2) then
huh
weird
or maybe they want P as an exponential
in which case the "Use P for P(t)" doesn't make much sense
write "the rate as which the innovation spreads" as dx/dt, and definition of joint proportionality?
what's that even for
i thought you needed dx/dt?
so where's y from?
that's x
x is the variable
dx/dt is the rate
seems right
nah
initially there's 1 person
nah
well
initially, there's one person
initially = at time t=0
so x(0) = what?
is the initial condition related to the derivatives by any chance?
oops misleading question
i mean
x(0) doesn't depend on the derivative of x
it's already given
x(t) = the number of people with the invention at time t
at time t=0, the number of ppl with the invention is 1
so x(0) = what?
yea
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What am I doing wrong here?
is the right side not the inverse??
I just went over the calculations one more time and I don't see an error
Is this the only method you've been taught to find inverse matrices?
what is the other one? afaik yes
yeah we haven't done that in this section yet :/
ok
I mean if you think I'm doing it the right way I'm just gonna use some tool to get it done, I just wanna know I can do it on exams, I'm tired
Multiply this by this. If you don't get $I$, then they are not inverse
azeem321
so that means I messed up my calculations
but that doesn't affect the right side
It really is. Have you not been exposed to the determinant method
Does your teacher want you to use the above method?
For the determinant method, you just swap the a and d, turn the b and c negative and the multiply each element of the matrix by $\frac{1}{ad-bc}$
azeem321
but I can't do LU factorization with that can I
LU factorization?
where you have lower triangular matrix times upper triangular one
I'm just gonna drop this class
no like I'm done
just learn the content from youtube
I've been working on math for 5 hours, again until midnight
2 math classes at once was a dumb idea
why is this wrong
consider multiplying L and U... you'll get a different value for a_(21) from LU
is my process wrong?
my calculations?
I'm even following a youtube tutorial and getting the same thing
the 1 in L_(21) should be -1
why?
it's probably just a minor miscalculation somewhere
I didn't subtract it
but I added it
or do I write the inverse actions in that matrix?
idk what tutorial you're following (@_@;) I can only point out it should be -1 there, figure how/why
no I figured it out
to get back to my original matrix, I need to use inverse operations
mhm
so how does that help me get x_1 and x_2 then
can't I just solve the system of equations as it was before?
I can
what was the point of this?
calculating inverse of triangular matrices is easier? 
maybe 
x = U^-1( L^-1 ( b ))
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@jade phoenix have you made any progress on this or are you stuck not knowing how to begin?

@jade phoenix Has your question been resolved?
@harsh inlet do not give out answers or do people's work for them.
Oh, I just assumed it was a help request
Not that someone just actually posted the solution
Oh Am I not supposed to help them?
Oh do I just have to give hints?
guide to an answer thru conversation instead of just giving it
see #❓how-to-get-help for rules on receiving/giving help
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What's your approach?
Do you have a gist of it? any insight? any simplifications of the problem?
please just give me the ans @slender mirage i beg u
Sorry, we're not supposed to provide answers.
It's a help channel, as you can see
As I like to say, we are not a glorified calculator
loooool

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Can anyone help pls
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Hi, I'm studying analytics geometry. I don't know how to continuous the following proof: "Let A = <a , b> and B = <c , d> vectors on the plane. A and B are linear dependence ⇔ ad - bc = 0" ; so, because it's a bi-conditional, I have proof in both directions, I already proof that "A and B are LD → ad - bc = 0", now, here it's where I don't know, I have to prove that "ad - bc = 0 → A and B are LD", I have both cases when d ≠ 0 and when d = 0, I don't know how to prove when d = 0
no
@heady coral Has your question been resolved?
thanks you, I was think it but I don't feel sure about it, thanks you
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=
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I just want to confirm... how would HA be determined here
would it just be the LC of the x in the numerator/ LC of x in the denominator
which is 1
and then multiplied by k value (3) and a value (2) and then add 1
to get 7?
My english is not enough to understand this.do you want to draw a line in coordinate system with this equation or smt else?
no im trying to determine the horizontal asymptote
which is essentially an imaginary straight horizontal line where the graph will never though that value
okay nvm i got it
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Not sure how to do these two questions
looks like an exam
@golden dirge Has your question been resolved?
Question 3, apply concept of the discriminant
Thanks
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Course: Applied Real Analysis
I'm given this problem (attached).
What I did so far:
I wrote out acos(ct)+bsin(ct)=Acos(ct-p) which is given
I've changed A to sqrt(a^2+b^2) to get acos(ct)+bsin(ct)=sqrt(a^2+b^2)*cos(ct-p)
I then used the hint by changing cos(ct-p) into ((cosctcosp)+(sinctsinp))
The equation I have now is acos(ct)+bsin(ct)=sqrt(a^2+b^2)((cosctcosp)+(sinct*sinp))
What I need help with: I would like to know if I'm on the right track.
"(cosctcosp)+(sinctsinp)" doesn't ring a bell ?
For clarification, is that a question for me? I have it in the equation. I got it from cos(ct-p).
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Hey! Can someone hlpe me solve this problem; f(x) = e^x + tx, solve for x
In terms of $f(x)$?
OurBelovedBungo
(@_@;) Can we do that?
can you share the original question please? writing "x" in terms of f(x) here, is a bit ...
questionable
If we interpret the question as $y = e^x + tx$, solve for $x$ as a function of $y$... that's about the only interpretation that seems to make sense.
OurBelovedBungo
Go newton method😩
Maybe not with an explicit formula, but $x \mapsto e^x + tx$ is injective (assuming $t \neq 0$), so an inverse function exists on a suitable domain.
yup I saw that 👀
OurBelovedBungo
Ah okay, Lambert W function at work here
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Closed due to the original message being deleted
i just wanted an explanation on the dotted line, im not sure what it is for
It is used to help indicate that that is where y=1
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hello i need help with this exercise. this exercise is part of my exam that i had in winter. i have alot of questions and if you need more information just ask
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hi! how would I got about solving this?
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✅
yeah nevermind thought I got it but didn't. they are similar triangle? but don't know where to go from there
would that be right?
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hello guys my profesor (introductory number theory) asks in practice sheet in special question (question for advancend) this:
if 2^n and 3^n are integers, does n have to be an integer?
i dont know how to approach this. any help is appreciate.
thank u in advance for looking at my inquiry
jan sona pona
Hmmm
Let x = 2^n
I will now tell you x = 10.
What do you think ? 🤔 (not sure how else to give hints sry)
n^3, wut?
n = log2 10, yes
And isn't an integer.
Does that help answer the question?
OHHHHHHHH
misread
🤦
my question is if: 2^n, 3^n integers => n integer
ok
In any case, I would still consider the same method perhaps
Let a = 2^n
b = 3^n
And assume a and b are integers
If you can find a contradiction you're done
but hmmm
yes i try this
By the way, do you have any sort of idea what answer you will expect?
Huh ok 🤔
My intuition says false
I'm not sure how to prove it either though
Contrapositive
no no
For me, I am thinking about hunting for a non-integer n
whch makes both integer
It feels to me you can do it.
Or maybe you can't --- in any case, I think I prefer this approach
Suppose 2^n is an integer. Prove 3^n isn't an integer (or find an example).
well
2^n and 3^n are integers by definition
There are multiple ways you can go about the proof.
If you show 2^n integer => 3^n isn't an integer and 3^n integer => 2^n isn't an integer. That is one way to prove what you want, I think?
let 2^n = 4, then 3^n = 9 and vice versa 🤔
if n is not an integer and 2^n is an integer => 3^n isnt an integer would be one way
so if a, b are integers, a = 2^n, b = 3^n, we need to maybe make equation for n
$n = log_2(a) = log_3(b)$
jan sona pona
Is n specified to be real? (think complex might hack this q)
no, the question ask whether n is always integer
2^n = 2^(a + bi) = (2^a)2^(bi) = (2^a)2^(i(b + 2pi))
Or something similar if I might a slight error, lol
I probably need to convert to base e first, and then back
hm yeah this looks good
I feel like n is restricted to be real
hm its not specified
yes
we dont often use complex numbers, yes 😃 (in this course)
Ftefan
Shuri2060
💀
🤔
a = b = 0, n = -\infty
This is hard 😂
Since this is number theory, something about factorisation/modulo arithmetic ?
Might be the approach
Or induction somehow?????
ive tried induction but it didnt work
How deep is this number theory
Just want to know what tools you have
Rings, fields or no?
yes we did all that
Oh, this proof might go quite deep then
Perhaps you want to consider this statement over the rationals first
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why is the absolute value of an integral from a to b the area of a fuction from a to b?
draw a picture?
are you trying to prove that's true?
i might said it wrong sorry but im not familiar with integrals
I am trying to find proof of $a->bf(x)dx = F(b) - F(a)
and why if f(x) is continues and f(x)>=0 this is equal to the area of f
this one
do you want to prove the fundamental theorem of calculus?
what's the definition of area of $f$ ?
riemann
yes i just dont understand why that is equal to F(b)-F(a)
why does antiderivative and area has connection
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Please can someone help me with this paper
Can you post a screenshot?
Can you send ss
I tried 1/2 ab sin c
You are trying to use trigs for a easy questions think simpler
1/2 base * height
doesnt 1/2 base * height only work for right angle triangles
ok
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Is the second symbol phi?
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hey guys so i need help with this work that I am tryna review over for the exams next week. and I need help determining whether my proof is right:
1.) suppose m = even; n = odd
2.) by definition of even, m = 2k; and odd, n = 2k + 1
3.) therefore, m - n = -2k + 2k + 1 = 1
4.) therefore, the difference of any odd and even integers = odd
is my proof correct?
did i like mess up somewhere?
OH HOLD ON.. are the variables for m and n supposed to be different? (the variable k)
yeah they're supposed to be different
gotcha.. 2 and 3 are wrong then yeah?
1.) should probably say "without loss of generality" and 2.) should say that k and whatever other variable you choose there is an integer
gotcha! thanks
need help with another 1 ^^
1.) suppose m = even; n = odd
2.) since m * n = even, therefore m * n = 2r where r is an integer
3.) since m = even, m = 2k
4.) since n = odd, n = 2p + 1
5.) therefore, m * n = 2k * 2p + 1 = 2r, and by definition, m * n is even
2.) shouldn't be there because that's what you're trying to prove
for 5.) you'll have to show that 2k*(2p+1) is a multiple of 2
ahh makes sense.. what is this issue specifically called? so i can look into it ^^
i overlooked that part
circular reasoning
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i need help with the christofides algorithm how to use it
hello!
hi
yo mos
mosh
are you familiar with the travellig salesman problem or christofides algorithm?
@spark widget hey
u familiar with christofides algorithm? minimum cost perfect match
don't ping random users, and no I don't
However if your question is "How to use this algorithm?", you can just google that
ive watched videos but theres a step i cant understand
@tacit sorrel Has your question been resolved?
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fucking useless
Well I'm sorry for not knowing that very specific algorithm you were asking about.
Maybe your question is too complex to be answered?
@supple knot Noticed you were on, want to close this channel since user apparently left because we're "useless"
Need an unhelper role
@tacit sorrel Has your question been resolved?
lol wow
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Im trying to find any point that is orthogonal to the coordinate Q=(-1,-2,0) in the three dimensional plane
x-2y+z-3=0.
I know the process of doing so when you have a coordinate and want to calculate where the orthogonal line intersects the plane.
I tried doing the process backwards but that did not work.
I asked previously and got a reply but it turned out it didnt work.
I have two three-dimensional planes that intersects. on these planes i have marked a coordinate Q=(-1,-2,0) now i need to find any coordinate that is perpendicular to the coordinate Q which lay on the plane x-2y+z-3=0.
I previously got the reply that any coordinate (0,0,z) would work but when i enter that into matlab with any given z it doesnt show the point as being perpendicular.
Might be hard to see but im trying to find a point that is othogonal to the blue dot (Q)
<@&286206848099549185>
Hello, do you want to find a point P such that PQ is perpendicular to the plane x-2y+z-3=0?
I wish to find a point P that is perpendicular to Q that lays on the plane x-2y+z-3=0
A point is not perpendicular to a point. A line, segment, vector etc. can be perpendicular to another one or to a surface
so what exactly do you mean by a point being perpendicular to another point?
The full problem is. "Calculate a point P so that Q is the orthogonal projection of P on the plane x-2y+z-3=0"
Ok, now I can see
Since the point Q is a determined point on a set plane it would be possible to have vertical line running through the point
and any point on that line would answer my problem
yes, that's what I meant by this
oh, im sorry
Well you only need the normal vector of the plane
which you can get with the coefficients of the plane's equation
the normal vector would be 1 -2 +1 right?
that vector would be the direction vector of a line that passes through point P
then any point on that line would satisfy what you want
yes
but how do i find a coordinate on that line?
i have the vector (1, -2, 1) and then what
Do you know how to get the equation of a line using the direction vector and a point?
ye but i think i tried that already and i plotted the point i got but it was not orthogonal to Q
mmm it should be, I mean PQ must be orthogonal to the plane because we are using the normal vector
hold on.
When finding the equation of the line you do the end value minus the start value?
hmm this might be too difficult explaining over text
let me check my notes real quick
thats what i did and then i set t=1 to get "any" point but when i plotted the point in matlab if didnt look orthogonal
because if i set t=1 i would get the cordinate (0,-4,1)
Here's what it looks like
No matter what i have come much further than before. I am very thankful for the help you gave me @charred zodiac have a nice evening
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