#help-27

1 messages · Page 455 of 1

stuck field
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hmmmmmmmm

worthy quest
stuck field
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I see.

worthy quest
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doesn't jive with the wording of the problem imo

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i'm just going to report it for incorrect answer and move on

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thanks for the help catthumbsup

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soft shore
#

find b/a where 2a^2=(a+b)^2

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woven radishBOT
soft shore
#

<@&286206848099549185>

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@soft shore Has your question been resolved?

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@soft shore Has your question been resolved?

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@soft shore Has your question been resolved?

main gull
soft shore
main gull
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Expand the right side

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To be a^2 + 2ab + b^2

soft shore
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a^2=2ab+b^2

main gull
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Almost

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Set it equal to 0

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So 0 = -a^2 + 2ab + b^2

soft shore
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ohh

main gull
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Now quadratic formula

soft shore
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that makes sense lol, didn’t think of that at all

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thanks a bunch dude

main gull
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Hopefully from there, you should get it

soft shore
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yeah, the next few steps are p clear

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cheers

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delicate galleon
#

is this assumption correct?
$gcd(2a,2b) = 2 \implies gcd(a, 2b) \leq 2$

woven radishBOT
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@delicate galleon Has your question been resolved?

delicate galleon
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plucky solar
#

Can someone explain how to convert 31,680 ft and 5 in to miles? I know the answer is 6.00094696969697 but I don't know how to get there.

supple knot
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1 mile = 5280 feet

plucky solar
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thanks

supple knot
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restive river
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I sketched S but I'm stuck on the second part of the question

pseudo basin
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@restive river z2 is the point in S furthest away from the origin

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for z1, imagine an idealized, perfectly straight windshield wiper hinged at the origin and rotating counterclockwise; z1 is the first point in S that it hits.

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restive river
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restive river
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Thought of factoring 324 as 2^2 * 3^4 (since 324 is in every pair) rewrite the equation to see where's going but can't see anything

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or maybe highlight the common factors?

mild marsh
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I can only see completing the square as $324 = 18^2$

woven radishBOT
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वाह्य

restive river
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Oooooh

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I forgot about that

mild marsh
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$a^2 + b^2 = (a-b)^2 + 2ab$

woven radishBOT
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वाह्य

restive river
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oooooooooooooh

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That's enough hints, I'll try to do in a second

carmine jacinth
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search up sophie-germain identity

carmine jacinth
restive river
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But if I wanted to use sophie-garmain identity I should change 18^2 to x^4

woven radishBOT
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felipee

mild marsh
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$10^4 = (10^2)^2$

woven radishBOT
#

वाह्य

mild marsh
woven radishBOT
#

felipee
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

restive river
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still leaving 10^2

restive river
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I'm a bit confused how to use the method

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knowing that I have to transform 18^2 to x^4

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(3^2 * 2)^2

carmine jacinth
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324/4=81=3^4

restive river
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Oh....

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Sorry for that I'm dumb

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okay so I did the formula

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and so, I have to do it with the 5 pairs and simplify everything?

carmine jacinth
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uh

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I'm pretty sure almost everything cancels

restive river
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Noticed that right now

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I'll do the latex 1 minute

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Actually nevermind, too big

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1 question

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4*3^4 = (2b^2) = (2.3^2)

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or is it (3^4)^2

carmine jacinth
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Where did you get 4*3^4=(2b^2) from?

restive river
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(a^2 + 2b^2 - 2ab)

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2b^2

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(10^4 - 4.3^4)

carmine jacinth
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Right so you would want to find the b term from 4*3^4 and plug that into (a^2 + 2b^2 - 2ab)

restive river
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Yes

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the b term is 3

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but I'm confused if it's 2.3^2 or 2.(3^2)^4

carmine jacinth
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Sorry I'm not exactly sure what you're asking

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Are you asking if it's (2b)^2 vs 2(b^2)?

restive river
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${2b^{2} = 2.3^{2} or 2.(3^{4})^{2}}$

woven radishBOT
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felipee

restive river
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I'm asking if a^4 will stick to it

carmine jacinth
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oh

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it's 2(3^2)

restive river
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okay

carmine jacinth
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Remember that you set 4b^4=324 so b^4=81

restive river
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yes

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I done it, as you said, almost everything cancels

main gull
restive river
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Oh sorry

placid rover
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\cdot

restive river
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thank you

placid rover
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in latex

main gull
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or \times

restive river
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alright

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Thank you ,,,,

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I got it perfectly

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odd saddle
#

I still don’t know where I’m going wrong so I’d appreciate any help. I don’t even know what the max and min is 🤦‍♂️

mild marsh
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Maximum distance both vectors pointing in opposite directions

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min distance when both pointing in the same direction

woven radishBOT
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वाह्य

mild marsh
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correct me if I am wrong

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@odd saddle Has your question been resolved?

odd saddle
#

Thank you, but how would I even begin to answer it? Someone told me I should do the square length of v and w separately with cos

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restive river
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I choose a random integer $n$ between $1$ and $10$ inclusive. What is the probability that for the $n$ I chose, there exist no real solutions to the equation $x(x+5) = -n$? Express your answer as a common fraction.

woven radishBOT
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crabbo

restive river
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my answer is that every n will have a real solution

carmine jacinth
restive river
placid rover
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???

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Well ok, and I tell you I'm not convinced at all by your reasoning.

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There is none.

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Reason in a way that would leave me with no doubts there are real solutions no matter what n is.

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Brute force, logic, whatever.

pseudo basin
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@restive river what is the probability of an event that is guaranteed to happen?

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actually wait
i think you may have screwed up since the last time you came here w/ this problem and none of us noticed

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you calculated the discriminant of x(x+5) = -n, yes?

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...ping me when/if you reply

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pseudo basin
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pseudo basin
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.reopen

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slender mirage
oak harness
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Hint: It has to do with the discriminant of a quadratic

pseudo basin
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they already calculated the discriminant earlier

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but i think they did so incorrectly and so i'm asking them to restate what they got

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just to be sure

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but crabbo is intentionally refusing to provide

copper mango
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shock

oak harness
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f

pseudo basin
copper mango
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shock they're not posting their working / answering the question(s)

pseudo basin
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genuine shock or sarcastic shock?

oak harness
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sarcastic

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Hence it was struck out

copper mango
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Thought the \s was implied from the crossout.

oak harness
pseudo basin
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right

devout snowBOT
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@restive river Has your question been resolved?

pseudo basin
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and they are still ignoring us all.

oak harness
#

You can't force someone to learn 🤷

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The public education system tries hard enough as it is

pseudo basin
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they came here to get help

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it's disrespectful on their part to completely ignore ppl trying to hep them

oak harness
#

We'll never know for sure I guess

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iron cedar
#

I am confuse confused understanding frequency distribution and understanding contingency table

iron cedar
#

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crisp plume
#

I need help with this (I will translate if needed)

gaunt quiver
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so.. you're looking for the amount of value gained?

crisp plume
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The percentage of value gained

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I will be doing other questions so please ping me if u have anything I really need help with this one

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<@&286206848099549185>

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crisp plume
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.reopen

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@crisp plume Has your question been resolved?

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fresh cairn
#

so here's the problem, I gotta turn into a + bi

fresh cairn
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I used euler's formular twice

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to get this for a

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and this for b

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my question is if I messed up the calculation or if the conceptual idea is wrong

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I did euler's to the upper exponential

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to get 7(cos(pi/3) + isin(pi/3))

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then separated my new one into two exponentials being multiplied by each other

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and did euler's again

fresh cairn
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cool

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that'll do it

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you know sometimes all I need is someone to talk out my answer to

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so thanks for existing, server

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half bolt
#

there are four married couples at a party, how many ways can they sit around a circular table where the couples cannot sit next to each other? i know that the amount of ways they can sit around the table without restrictions is 5040, but how do i put it where the couples cannot sit next to each other when everyone in the party as a spouse? i cannot find a way to figure it out

torn vessel
#

Use the compliment. Figure out how many ways at least one couple is sitting together and take that away from the total number of ways they can sit

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tight crypt
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tight crypt
#

Not sure on how to do this question, nor what its asking

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<@&286206848099549185>

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tight crypt
#

<@&286206848099549185>

#

is no one gonna help lol?

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tight crypt
#

.reopen

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restive river
#

<@&286206848099549185>

devout snowBOT
restive river
#

hellos

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I need help finding imaginary zeros

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i have a few problems

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3

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of them

main gull
restive river
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can you help me tho

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how can i solve this im stuck on it

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h(x) = x^4-x^3+2x^2-4x-8

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i got -1,0,-2,6

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as the zeros

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but that isnt right

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i tried doing it like with quadratic formula

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and it wasnt working

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it keeps giving me these numbers

main gull
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Can you provide your work?

restive river
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yes

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i have to correct

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2-4

main gull
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You see that expression at the end, after doing synthetic division? The x^3 - 2x^2...

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Apply factor by grouping

restive river
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i havent been taught that

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what is that

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my goal is to get it into that little like criss cross thingy

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that happend on nuimhber 1

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but idk how

main gull
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I'm pretty sure that you've been taught it, it's a factoring method for cubics

restive river
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im in alg 2

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my teacher doenst teach like "normal" he teaches his own way but idk how to do it

main gull
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Cubics is the name of an expression that has power of 3

restive river
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oh okay

main gull
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I suggest viewing this

restive river
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hmm

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ok ig

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@main gull is

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x=2,−1,2i,−2i

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correct

main gull
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Yes

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quasi wind
#

I have a few math questions that need to be done... if anyone is free can you help? (pls ping me @quasi wind )

quasi wind
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What

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Anyways

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I dont understand at all...

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Where are they getting the "y value"

copper mango
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Solution set

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find the solutions to that system

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then give them the largest y value.

quasi wind
copper mango
#

yes.

quasi wind
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Ok

copper mango
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then find the largest y value.

quasi wind
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Thats what I don't understand...

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Where are they getting "y" from...

warped crest
#

is this a multiple choice question

quasi wind
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Yes

quasi wind
polar oyster
#

lmao

#

that question makes no sense

quasi wind
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Yeah

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Thats the problem

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And I thought that it was just me...

warped crest
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they are trying to say y(x) = highest value

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so solve for the equation set

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what x solutions did you get

copper mango
polar oyster
#

y-intercept?

copper mango
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nowhere did I say intercept, so no.

polar oyster
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oh, so 3.782

quasi wind
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Huh

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Ok.... I will just go with that....

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This should be correct right?

copper mango
quasi wind
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I graphed the equations in desmos

copper mango
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Yeah but the actual point of intersection clearly isn't useful

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cause they don't ask about anything quantitative

quasi wind
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Oh yeah...

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Could you explain how to do this?

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Hello?

copper mango
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what does the point of intersection represent here?

quasi wind
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The profit?

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I think...

copper mango
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what happens when revenue=expense?

quasi wind
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No profit.

copper mango
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yes.

quasi wind
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The graph is constant

copper mango
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No

quasi wind
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(a perfect line)

copper mango
#

Still no

quasi wind
#

Wha

copper mango
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There's no profit was correct, then you spoke nonsense

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ie they broke even.

quasi wind
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Sorry, its hard writing with mouse lol

copper mango
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That picture has no meaning whatsoever

quasi wind
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Wait

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Sorry

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Wrong one

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Like that?

copper mango
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Yeah no

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It's not a constant as I said

quasi wind
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Oh

copper mango
#

Nor, should you be graphing anything.

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revenue = expense at the POI as I said already

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so they break even at the POI.

quasi wind
quasi wind
copper mango
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Breaking even means Revenue=Expense

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ie Profit = 0.

quasi wind
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Ohh

copper mango
#

You made back exactly how much you spent.

quasi wind
#

yes

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So that's the correct answer right?

copper mango
#

yes

quasi wind
#

Ok

devout snowBOT
#

@quasi wind Has your question been resolved?

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reef pebble
#

hello

devout snowBOT
reef pebble
#

so im given the function and have to find the derivative and then the value when x = 2pi/3

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$$f(x)=\frac{sin(2x)}{cos(x)}$$

woven radishBOT
reef pebble
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i start buy doing quotient rule

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$$f'(x) =\frac{cos(x)*(cos(2x) * 2 - sin(2x)*sin(x)}{cos^{2}(x)}$$

woven radishBOT
reef pebble
#

i think plug in 2pi/3 and got -1/2 / (1/4) which is not correct

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so i was wondering if my calc was right and just the angles i was incorrect with

slender mirage
#

.

old plank
slender mirage
#

ahh

reef pebble
#

oh i didn't simplify i just plugged in 2pi/3 since it seemed like stuff would cancel

slender mirage
#

I see... You've mistaken the derivative of cos x as sin x

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It should've been -sin x

reef pebble
#

ah so it should be

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$$f'(x) =\frac{cos(x)*-(cos(2x) * 2 - sin(2x)*sin(x)}{cos^{2}(x)}$$

woven radishBOT
slender mirage
#

ehhh?

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no

old plank
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no

reef pebble
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oh wait

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no

slender mirage
#

cos times derivative of (sin 2x) - sin(2x) times derivative of (cos x)

reef pebble
#

im sorry

slender mirage
#

in numerator

old plank
#

$$f'(x) =\frac{cos(x)*(cos(2x) * 2 + sin(2x)*sin(x)}{cos^{2}(x)}$$

woven radishBOT
#

gog IGGa

reef pebble
#

the last sin in numerator should be negative

slender mirage
#

yes

reef pebble
#

$$f'(x) =\frac{cos(x)(cos(2x) * 2 - sin(2x)-sin(x)}{cos^{2}(x)}$$

slender mirage
#

not the -cos 2x

old plank
#

what

slender mirage
#

ehhh

woven radishBOT
reef pebble
#

i copied and pasted my previous line i forgot to take the mistake out

old plank
#

no it should all be positive

reef pebble
#

wdym I think this equation is right cause if i plug in 2pi/3 in all the x

#

i get 4/(1/4) or -1

#

which on my guide says is correct

old plank
#

nvm

#

the two negatives cancel

reef pebble
#

yeah and then the denominator gives me the negative to get -1 so all is well :D

#

ty for the help tonight

#

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candid sierra
#

Can someone explain why these are not the same...

candid sierra
#

<@&286206848099549185>

main gull
candid sierra
#

mb

placid rover
#

that k should be +1 or -1 or something?

#

check the formula - it aint this.

candid sierra
#

i jsut plugged it here

#

nvm i see it

#

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leaden aurora
#

,rotate

woven radishBOT
leaden aurora
#

Write it as $ax^2+bx^2+c=0$

woven radishBOT
#

azeem321

leaden aurora
#

yh

#

so you can apply the discriminat

#

Yes

#

For the $x^2$ terms you can write it as $(1+m^2)x^2$

woven radishBOT
#

azeem321

leaden aurora
#

good

#

now apply discriminant

#

and set equal to 0

#

set =0

#

and solve for m

slender mirage
#

which question we doing btw (@_@;)

leaden aurora
#

if you get imaginary solutions, it means you went wrong in your workings somewhere

#

last part

woven radishBOT
leaden aurora
#

,w 100m^4-4(m^2+1)(100m^2-20)=0

woven radishBOT
slender mirage
#

Write the line eqn. m = y/(x-10) = -x/y and x^2 + y^2 = 20

leaden aurora
placid rover
#

Nothing.

leaden aurora
#

oh

slender mirage
#

,w solve 100m^2 = 20(1+m^2)

slender mirage
#

that's the solution lol

#

I think devastation

leaden aurora
#

yh i got the above too on my calculator

#

It seems you went wrong somewhere with $x^2+(m(x-10))^2=20$

woven radishBOT
#

azeem321

slender mirage
#

for starters, y^2 = -x(x-10) would give away the x coordinates of the tangent anyways.. plug, get y, get m

devout snowBOT
#

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slow bronze
#

Hello!

devout snowBOT
slow bronze
#

How do I check that a sequence converges or diverges?

supple knot
#

is this your first calculus class?

slow bronze
#

I'm good at other areas of calculus

#

Just not series and sequences

#

Sorry guys 😦

twin flint
#

Thinking about how a sine wave behaves is probably the best first intuition to have

#

Its y values are bounded between -1 and 1 for all infinity, and the limit as sin goes to infinity is undefined

supple knot
slow bronze
#

No it's okay

#

When it comes to learning maths, I have no ego... lol

#

Can we take a step back and talk about what converge and diverge actually means for a sequence?

supple knot
#

great question

#

do you have a definition in your book?

#

or is it assumed by your instructor you already know it

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languid ocean
#

no help on tests!

#

the format seems sus

#

anyways

#

probably P(k1-k2) then

#

huh
weird

#

or maybe they want P as an exponential

#

in which case the "Use P for P(t)" doesn't make much sense

#

write "the rate as which the innovation spreads" as dx/dt, and definition of joint proportionality?

#

what's that even for

#

i thought you needed dx/dt?

#

so where's y from?

#

that's x

#

x is the variable

#

dx/dt is the rate

#

seems right

#

nah

#

initially there's 1 person

#

nah

#

well

#

initially, there's one person

#

initially = at time t=0

#

so x(0) = what?

#

is the initial condition related to the derivatives by any chance?

#

oops misleading question

#

i mean

#

x(0) doesn't depend on the derivative of x

#

it's already given

#

x(t) = the number of people with the invention at time t
at time t=0, the number of ppl with the invention is 1
so x(0) = what?

#

yea

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glad cypress
#

What am I doing wrong here?

devout snowBOT
glad cypress
#

is the right side not the inverse??

#

I just went over the calculations one more time and I don't see an error

leaden aurora
#

Is this the only method you've been taught to find inverse matrices?

glad cypress
leaden aurora
#

top right

glad cypress
#

yeah we haven't done that in this section yet :/

leaden aurora
#

ok

glad cypress
#

I mean if you think I'm doing it the right way I'm just gonna use some tool to get it done, I just wanna know I can do it on exams, I'm tired

leaden aurora
#

Multiply this by this. If you don't get $I$, then they are not inverse

woven radishBOT
#

azeem321

glad cypress
#

so that means I messed up my calculations

leaden aurora
#

Shouldn't this be zero?

glad cypress
#

but that doesn't affect the right side

leaden aurora
#

everything in this row is fine

#

except for the cross

glad cypress
#

is there a specific order I need to do this in?

#

this is so time consuming

leaden aurora
#

Does your teacher want you to use the above method?

glad cypress
#

we've done it today

#

I can do LU factorization with that too?

leaden aurora
#

For the determinant method, you just swap the a and d, turn the b and c negative and the multiply each element of the matrix by $\frac{1}{ad-bc}$

woven radishBOT
#

azeem321

glad cypress
#

but I can't do LU factorization with that can I

leaden aurora
#

LU factorization?

glad cypress
#

where you have lower triangular matrix times upper triangular one

#

I'm just gonna drop this class

leaden aurora
#

no

#

dont quit

glad cypress
#

no like I'm done

leaden aurora
#

just learn the content from youtube

glad cypress
#

I've been working on math for 5 hours, again until midnight

#

2 math classes at once was a dumb idea

#

why is this wrong

slender mirage
# glad cypress

consider multiplying L and U... you'll get a different value for a_(21) from LU

glad cypress
#

so what am I supposed to do to find LU

#

I don't know what to do anymore

glad cypress
#

my calculations?

#

I'm even following a youtube tutorial and getting the same thing

slender mirage
#

the 1 in L_(21) should be -1

glad cypress
#

why?

slender mirage
#

it's probably just a minor miscalculation somewhere

glad cypress
#

I didn't subtract it

#

but I added it

#

or do I write the inverse actions in that matrix?

slender mirage
#

idk what tutorial you're following (@_@;) I can only point out it should be -1 there, figure how/why

glad cypress
#

no I figured it out

#

to get back to my original matrix, I need to use inverse operations

slender mirage
#

Good job!

glad cypress
#

mhm

#

so how does that help me get x_1 and x_2 then

#

can't I just solve the system of equations as it was before?

#

I can

#

what was the point of this?

slender mirage
#

calculating inverse of triangular matrices is easier? zoomEyes

#

maybe devastation

#

x = U^-1( L^-1 ( b ))

glad cypress
#

so I'd need to find the inverse of U and L?

#

lol what

#

got it

#

.close

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fervent maple
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steep sable
#

reopen first

#

you closed channel

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jade phoenix
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pseudo basin
#

@jade phoenix have you made any progress on this or are you stuck not knowing how to begin?

soft shore
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#

@jade phoenix Has your question been resolved?

harsh inlet
oak harness
pseudo basin
#

@harsh inlet do not give out answers or do people's work for them.

oak harness
#

Oh, I just assumed it was a help request

#

Not that someone just actually posted the solution

harsh inlet
#

Oh Am I not supposed to help them?

pseudo basin
#

what you did is not helping

#

i thought i was clear in what i told you not to do

harsh inlet
#

Oh do I just have to give hints?

oak harness
#

No, you help them to learn how to solve it

#

so they can do it themselves

wicked rover
#

guide to an answer thru conversation instead of just giving it

oak harness
#

sometimes they need hints

#

sometimes more

harsh inlet
#

Oh sorry it's my first time

#

I'll be careful next time

wicked rover
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restive river
devout snowBOT
slender mirage
#

Uh

#

Did you try the question?

restive river
#

yes

#

@slender mirage

slender mirage
#

What's your approach?

#

Do you have a gist of it? any insight? any simplifications of the problem?

restive river
#

please just give me the ans @slender mirage i beg u

slender mirage
#

Sorry, we're not supposed to provide answers.

#

It's a help channel, as you can see

oak harness
#

As I like to say, we are not a glorified calculator

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restive river
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restive river
#

Can anyone help pls

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heady coral
#

Hi, I'm studying analytics geometry. I don't know how to continuous the following proof: "Let A = <a , b> and B = <c , d> vectors on the plane. A and B are linear dependence ⇔ ad - bc = 0" ; so, because it's a bi-conditional, I have proof in both directions, I already proof that "A and B are LD → ad - bc = 0", now, here it's where I don't know, I have to prove that "ad - bc = 0 → A and B are LD", I have both cases when d ≠ 0 and when d = 0, I don't know how to prove when d = 0

devout snowBOT
#

@heady coral Has your question been resolved?

placid rover
#

If d = 0

#

Then either b or c must be 0

#

In either case, you are done.

heady coral
#

thanks you, I was think it but I don't feel sure about it, thanks you

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rugged panther
devout snowBOT
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rugged panther
#

.

#

.close

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umbral bolt
#

I just want to confirm... how would HA be determined here

umbral bolt
#

would it just be the LC of the x in the numerator/ LC of x in the denominator

#

which is 1

#

and then multiplied by k value (3) and a value (2) and then add 1

#

to get 7?

vagrant comet
#

My english is not enough to understand this.do you want to draw a line in coordinate system with this equation or smt else?

umbral bolt
#

no im trying to determine the horizontal asymptote

#

which is essentially an imaginary straight horizontal line where the graph will never though that value

#

okay nvm i got it

#

.close

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golden dirge
devout snowBOT
golden dirge
#

Not sure how to do these two questions

supple knot
#

looks like an exam

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#

@golden dirge Has your question been resolved?

golden dirge
#

Just practice problems

main gull
golden dirge
#

Thanks

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formal pecan
#

Course: Applied Real Analysis

I'm given this problem (attached).

What I did so far:

I wrote out acos(ct)+bsin(ct)=Acos(ct-p) which is given

I've changed A to sqrt(a^2+b^2) to get acos(ct)+bsin(ct)=sqrt(a^2+b^2)*cos(ct-p)

I then used the hint by changing cos(ct-p) into ((cosctcosp)+(sinctsinp))

The equation I have now is acos(ct)+bsin(ct)=sqrt(a^2+b^2)((cosctcosp)+(sinct*sinp))

What I need help with: I would like to know if I'm on the right track.

magic thicket
#

"(cosctcosp)+(sinctsinp)" doesn't ring a bell ?

formal pecan
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odd dagger
#

Hey! Can someone hlpe me solve this problem; f(x) = e^x + tx, solve for x

woven radishBOT
#

OurBelovedBungo

slender mirage
#

can you share the original question please? writing "x" in terms of f(x) here, is a bit ...

#

questionable

wicked turtle
woven radishBOT
#

OurBelovedBungo

deft wagon
#

Go newton method😩

slender mirage
#

does it though? can you find x in terms of y?

#

,w inverse of e^x + x

wicked turtle
#

Maybe not with an explicit formula, but $x \mapsto e^x + tx$ is injective (assuming $t \neq 0$), so an inverse function exists on a suitable domain.

odd dagger
slender mirage
#

yup I saw that 👀

woven radishBOT
#

OurBelovedBungo

slender mirage
#

Ah okay, Lambert W function at work here

devout snowBOT
#

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@odd dagger Has your question been resolved?

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harsh marlin
#

i just wanted an explanation on the dotted line, im not sure what it is for

umbral cargo
#

It is used to help indicate that that is where y=1

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late rivet
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late rivet
#

hello i need help with this exercise. this exercise is part of my exam that i had in winter. i have alot of questions and if you need more information just ask

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#

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late rivet
#

my question has been resolved

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#

if your question is resolved, close the channel with .close

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wise quartz
#

hi! how would I got about solving this?

devout snowBOT
wise quartz
#

don't even know where to begin tbh

#

.close

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wise quartz
#

.reopen

devout snowBOT
#

wise quartz
#

yeah nevermind thought I got it but didn't. they are similar triangle? but don't know where to go from there

#

would that be right?

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restive river
#

hello guys my profesor (introductory number theory) asks in practice sheet in special question (question for advancend) this:

if 2^n and 3^n are integers, does n have to be an integer?

i dont know how to approach this. any help is appreciate.

thank u in advance for looking at my inquiry

jan sona pona

placid rover
#

Hmmm

#

Let x = 2^n

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I will now tell you x = 10.

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What do you think ? 🤔 (not sure how else to give hints sry)

restive river
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hmm

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n is log 2 of 10 but n^3 is not integer, correct?

placid rover
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n^3, wut?

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n = log2 10, yes

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And isn't an integer.

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Does that help answer the question?

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OHHHHHHHH

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misread

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🤦

restive river
#

my question is if: 2^n, 3^n integers => n integer

restive river
placid rover
#

In any case, I would still consider the same method perhaps

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Let a = 2^n

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b = 3^n

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And assume a and b are integers

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If you can find a contradiction you're done

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but hmmm

restive river
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yes i try this

placid rover
#

By the way, do you have any sort of idea what answer you will expect?

restive river
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all day yesterday 😦

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i think its true, but i dont know how to proof it

placid rover
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Huh ok 🤔

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My intuition says false

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I'm not sure how to prove it either though

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Contrapositive

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no no

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For me, I am thinking about hunting for a non-integer n

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whch makes both integer

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It feels to me you can do it.

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Or maybe you can't --- in any case, I think I prefer this approach

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Suppose 2^n is an integer. Prove 3^n isn't an integer (or find an example).

restive river
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2^n and 3^n are integers by definition

placid rover
#

There are multiple ways you can go about the proof.

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If you show 2^n integer => 3^n isn't an integer and 3^n integer => 2^n isn't an integer. That is one way to prove what you want, I think?

lunar crane
#

let 2^n = 4, then 3^n = 9 and vice versa 🤔

placid rover
#

Right.

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Need to be more precise with what I was thinking

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Maybe unusable idea

lunar crane
#

if n is not an integer and 2^n is an integer => 3^n isnt an integer would be one way

restive river
#

so if a, b are integers, a = 2^n, b = 3^n, we need to maybe make equation for n

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$n = log_2(a) = log_3(b)$

woven radishBOT
#

jan sona pona

placid rover
#

Is n specified to be real? (think complex might hack this q)

restive river
#

no, the question ask whether n is always integer

placid rover
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2^n = 2^(a + bi) = (2^a)2^(bi) = (2^a)2^(i(b + 2pi))

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Or something similar if I might a slight error, lol

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I probably need to convert to base e first, and then back

restive river
#

hm yeah this looks good

placid rover
#

Are you serious?

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This question is uninteresting if we allow this =.....=

restive river
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i mean

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its good way to solve, not solution XD

placid rover
#

I feel like n is restricted to be real

restive river
#

hm its not specified

placid rover
#

Is this number theory?

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Or what course

restive river
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yes

placid rover
#

Yes, n is real ok.

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lmao.

restive river
#

we dont often use complex numbers, yes 😃 (in this course)

lunar crane
#

we can take that $b = 3^{log_2 a}$

#

ty

woven radishBOT
#

Ftefan

lunar crane
#

âccording to wolframalpha

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where a and b are integers

placid rover
#

I have an idea

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$$pd = 2^n$$
$$qd = 3^n$$

woven radishBOT
#

Shuri2060

placid rover
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Suppose d divides both a and b.

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And now I'm thinking it is a useless idea

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😵

lunar crane
#

💀

restive river
#

🤔

placid rover
#

a = b = 0, n = -\infty

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This is hard 😂

#

Since this is number theory, something about factorisation/modulo arithmetic ?

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Might be the approach

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Or induction somehow?????

restive river
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ive tried induction but it didnt work

placid rover
#

How deep is this number theory

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Just want to know what tools you have

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Rings, fields or no?

restive river
#

yes we did all that

placid rover
#

Oh, this proof might go quite deep then

#

Perhaps you want to consider this statement over the rationals first

devout snowBOT
#

@restive river Has your question been resolved?

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restive river
#

why is the absolute value of an integral from a to b the area of a fuction from a to b?

supple knot
#

are you trying to prove that's true?

restive river
#

i might said it wrong sorry but im not familiar with integrals

#

I am trying to find proof of $a->bf(x)dx = F(b) - F(a)

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and why if f(x) is continues and f(x)>=0 this is equal to the area of f

supple knot
#

you're saying a lot of things

#

focus on one specific thing and one specific goal

supple knot
#

do you want to prove the fundamental theorem of calculus?

#

what's the definition of area of $f$ ?

woven radishBOT
#

riemann

restive river
#

yes i just dont understand why that is equal to F(b)-F(a)

#

why does antiderivative and area has connection

devout snowBOT
#

@restive river Has your question been resolved?

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thin rune
devout snowBOT
restive river
#

Can you post a screenshot?

vagrant comet
#

Can you send ss

thin rune
vagrant comet
#

What did you try

thin rune
#

I tried 1/2 ab sin c

vagrant comet
#

You are trying to use trigs for a easy questions think simpler

thin rune
#

1/2 base * height

vagrant comet
#

Yes

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What is base

thin rune
#

BC-BD

#

@vagrant comet

vagrant comet
#

Sorry

#

Im back

#

Base is 6+2sqrt7 right

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We dont know height so ill call it x

thin rune
#

doesnt 1/2 base * height only work for right angle triangles

vagrant comet
#

No

#

It works at every single one

thin rune
#

ok

vagrant comet
#

6+2sqrt7*1/2 is 3+sqrt7 right?

#

3+sqrt7*x=13+3sqrt7

thin rune
#

ok

#

is there any way i can attempt the question, then get the answer checked

vagrant comet
#

Idk

#

But i have to go

#

So sorry

#

I cant help you rn

thin rune
#

ok

#

how do i leave the channel

#

.close

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#
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digital egret
#

Is the second symbol phi?

devout snowBOT
digital egret
#

what is that

#

.close

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upper bloom
#

hey guys so i need help with this work that I am tryna review over for the exams next week. and I need help determining whether my proof is right:
1.) suppose m = even; n = odd
2.) by definition of even, m = 2k; and odd, n = 2k + 1
3.) therefore, m - n = -2k + 2k + 1 = 1
4.) therefore, the difference of any odd and even integers = odd

upper bloom
#

is my proof correct?

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did i like mess up somewhere?

#

OH HOLD ON.. are the variables for m and n supposed to be different? (the variable k)

spare crypt
#

yeah they're supposed to be different

upper bloom
spare crypt
#

1.) should probably say "without loss of generality" and 2.) should say that k and whatever other variable you choose there is an integer

upper bloom
#

need help with another 1 ^^

#

1.) suppose m = even; n = odd
2.) since m * n = even, therefore m * n = 2r where r is an integer
3.) since m = even, m = 2k
4.) since n = odd, n = 2p + 1
5.) therefore, m * n = 2k * 2p + 1 = 2r, and by definition, m * n is even

spare crypt
#

2.) shouldn't be there because that's what you're trying to prove

#

for 5.) you'll have to show that 2k*(2p+1) is a multiple of 2

upper bloom
#

i overlooked that part

spare crypt
#

circular reasoning

upper bloom
#

ohh okay! thank you so much ❤️

#

.close

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tacit sorrel
#

i need help with the christofides algorithm how to use it

tardy smelt
#

hello!

tacit sorrel
#

hi

copper mango
#

clearly not your channel

tacit sorrel
#

yo mos

#

mosh

#

are you familiar with the travellig salesman problem or christofides algorithm?

#

@spark widget hey

#

u familiar with christofides algorithm? minimum cost perfect match

copper mango
#

However if your question is "How to use this algorithm?", you can just google that

tacit sorrel
#

ive watched videos but theres a step i cant understand

devout snowBOT
#

@tacit sorrel Has your question been resolved?

tacit sorrel
#

<@&286206848099549185> help

#

this is the graph im using

devout snowBOT
#

@tacit sorrel Has your question been resolved?

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tacit sorrel
#

fucking useless

devout snowBOT
placid rover
#

Well I'm sorry for not knowing that very specific algorithm you were asking about.

main gull
#

Maybe your question is too complex to be answered?

placid rover
#

Since I didn't do graph theory

#

lmao left.

main gull
#

@supple knot Noticed you were on, want to close this channel since user apparently left because we're "useless"

placid rover
#

Need an unhelper role

devout snowBOT
#

@tacit sorrel Has your question been resolved?

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delicate quarry
#

Im trying to find any point that is orthogonal to the coordinate Q=(-1,-2,0) in the three dimensional plane
x-2y+z-3=0.
I know the process of doing so when you have a coordinate and want to calculate where the orthogonal line intersects the plane.
I tried doing the process backwards but that did not work.
I asked previously and got a reply but it turned out it didnt work.

delicate quarry
#

I have two three-dimensional planes that intersects. on these planes i have marked a coordinate Q=(-1,-2,0) now i need to find any coordinate that is perpendicular to the coordinate Q which lay on the plane x-2y+z-3=0.

#

I previously got the reply that any coordinate (0,0,z) would work but when i enter that into matlab with any given z it doesnt show the point as being perpendicular.

#

Might be hard to see but im trying to find a point that is othogonal to the blue dot (Q)

#

<@&286206848099549185>

copper fossil
charred zodiac
delicate quarry
#

I wish to find a point P that is perpendicular to Q that lays on the plane x-2y+z-3=0

charred zodiac
#

A point is not perpendicular to a point. A line, segment, vector etc. can be perpendicular to another one or to a surface

charred zodiac
delicate quarry
#

The full problem is. "Calculate a point P so that Q is the orthogonal projection of P on the plane x-2y+z-3=0"

charred zodiac
#

Ok, now I can see

delicate quarry
#

Since the point Q is a determined point on a set plane it would be possible to have vertical line running through the point

#

and any point on that line would answer my problem

charred zodiac
delicate quarry
#

oh, im sorry

charred zodiac
#

Well you only need the normal vector of the plane

#

which you can get with the coefficients of the plane's equation

delicate quarry
#

the normal vector would be 1 -2 +1 right?

charred zodiac
#

that vector would be the direction vector of a line that passes through point P

#

then any point on that line would satisfy what you want

charred zodiac
delicate quarry
#

but how do i find a coordinate on that line?

#

i have the vector (1, -2, 1) and then what

charred zodiac
#

Do you know how to get the equation of a line using the direction vector and a point?

delicate quarry
#

ye but i think i tried that already and i plotted the point i got but it was not orthogonal to Q

charred zodiac
#

mmm it should be, I mean PQ must be orthogonal to the plane because we are using the normal vector

delicate quarry
#

hold on.
When finding the equation of the line you do the end value minus the start value?

#

hmm this might be too difficult explaining over text

charred zodiac
#

the perpendicular line is (-1,-2,0) + (1,-2,1)t

#

for any real number t

delicate quarry
#

let me check my notes real quick

#

thats what i did and then i set t=1 to get "any" point but when i plotted the point in matlab if didnt look orthogonal

#

because if i set t=1 i would get the cordinate (0,-4,1)

#

Here's what it looks like

#

No matter what i have come much further than before. I am very thankful for the help you gave me @charred zodiac have a nice evening

#

.close

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restive river