#help-27

1 messages · Page 451 of 1

copper mango
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yes.

limpid lantern
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-10/7

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i used a calculator to get that lol, Was making sure i did it right

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Thanks, Sorry i made you lose braincells

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copper mango
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and per your original question, yes -10/7 is rational

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sour needle
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Does anyone know how to do b of this?

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robust apex
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First one is 90-75=15 so m=90+15=105

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Second one 180=121+x+32

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You’re basically in this case
And the orange angles in the pic are the same

sour needle
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ohh

robust apex
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Just make the x axis longer and you’ll see it

sour needle
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yeah i get it now

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thanks

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fair crescent
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fair crescent
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In the part where they substitute x with 0 why did they use y=2x+1

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Coz theres also a y=-2x+1

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narrow plank
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Both yield the same point

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You could have probably picked either one

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Given that it looks like you’re solving a system of two linear equations

fair crescent
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Oh yeah tru

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But in what im doing

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The asymptotes are y=x-6 and y=-x+6

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Then x=6

fair crescent
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Nvm i got confused mb

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It would turn out as 0=0 just like the example

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tribal portal
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hey guys can you explain me cancelation law by addition or a+c = b+c is a=b

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queen flame
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@tribal portal a+c = b+c
a = b + c - c
c cancels eachother out
a = b

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is this what you're looking for?

tribal portal
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ok im seeing

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rose wyvern
#

Can you give a dynamic (that uses rotations) offline (knows the future) binary search tree scheme that supports the following search requests in O(1) amortized time? The search requests sequence is: 1, n/2, 2, n/2 + 1, 3, n/2 + 2, . . .

Assume that the universe is 1, 2, . . . , n (where n is a large integer). You
can assume an overhead cost of O(n^2) for inserting all these elements (i.e.,
1, 2, . . . , n) into a binary search tree first. The number of search requests m ≥ n.

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rose wyvern
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<@&286206848099549185>

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rose wyvern
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.close

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restive river
#

Sonia works at a bakery. The function f(x) represents the amount of money Sonia earns per loaf, where x is the number of loaves she makes. The function g(x) represents the number of bread loaves Sonia bakes per hour, where x is the number of hours she works. Show all work to find f(g(x)), and explain what f(g(x)) represents.

f(x) = 9x2 + 1
g of x equals the square root of the quantity 2 x cubed

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restive river
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<@&286206848099549185>

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im only confused on this part

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explain what f(g(x)) represents.

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restive river
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I don't know how to get arc AB measure

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restive river
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cry

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I tried using the other arc measures to figure it out but im not sure what to do

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cry

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restive river
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<@&286206848099549185>

restive river
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is anyone able to help

final laurel
restive river
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ok

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oh I just realized that DB was the diameter

restive river
final laurel
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For this arc?

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oops

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yep

restive river
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ok tysm

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real patrol
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How do you tell wether to add or subtract these? <@&286206848099549185>

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real patrol
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<@&286206848099549185>

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Help

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cunning pelican
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how do i find the limit of f(x) 😭😭

cunning pelican
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<@&286206848099549185>

signal pond
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do you have f(x)?

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oh nbm

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nvm*

cunning pelican
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no

signal pond
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If that goes to -infinity, then you can say a few things

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about what 2f(x)-1 and 5f(x) + 2 must go to

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or could go to

cunning pelican
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so the denominator is 0

winter patrol
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how do i find the limit of f(x)
do you mean the limit as x approaches 1 of f(x)?

cunning pelican
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and the numerator negative

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yes sorry

signal pond
cunning pelican
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if the numerator is 0 then what now

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denom*

signal pond
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well you know the limit of 1/x as x -> 0

cunning pelican
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ya

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+inf

signal pond
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Yes

cunning pelican
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oh so 2f(x) -1 < 0

signal pond
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Yes

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But to make sure you are accounting for all possible cases

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perhaps split the fraction up into 2

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And then find all the ways a limit could make - infinity

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Then ask what does that say about f(x) as x->1

cunning pelican
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how should i split the fraction

signal pond
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But I think on your initial idea -> 5f(x) + 2 -> 0 is correct

signal pond
cunning pelican
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aah

signal pond
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Because you might ask why doesnt 2f(x) go to -infinity on it's own

cunning pelican
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hm

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but how do i find the limit of f(x) rhat way

signal pond
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Well there might be a better way, but what I'm proposing is to look at what you have

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split it up, why not

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And then ask how can this equal -infinity

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as you said

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we can get an infinity if 5f(x)+2 goes to 0

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And that can be negative if 2f(x)-1 is negative

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when 5f(x)+2 goes to 0

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the only other way to get a negative infinity would be to have 2f(x)-1 go to negative infinity on its own

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But then you would have a -infinity/-infinity in a sense

cunning pelican
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ohh

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i get it

signal pond
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Okay so what can we say about what f(x) goes to?

cunning pelican
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can we?😭

signal pond
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Okay so we decided that the only way we can get negative infinity

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is if

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5f(x)+2 goes to 0

cunning pelican
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num < 0

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denom = 0

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yes

signal pond
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Yes

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Okay

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So what can we say if the denom goes to 0?=

cunning pelican
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idk😭

signal pond
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Like literally

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What do we say

cunning pelican
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that f(x)+2 = 0

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5f

signal pond
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yes

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But with limits that says that

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lim x -> 1 5f(x) + 2 = 0

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right?

cunning pelican
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oh yes

signal pond
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So can we re-arrange that to get f(x)?

cunning pelican
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cant we use a different function

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like a g(x) = 5f + 2 with lim x-> 1 g = 0

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ok nvm

signal pond
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And give me lim x->1 f(x) on one side

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After all this is what we want right?

cunning pelican
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can we just rearrange the 2 and the 5

signal pond
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giving?

cunning pelican
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like

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can we put 2 to the other side

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i never do that when i work with limits

signal pond
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but it's okay

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because 2 isnt dependent on x is it?

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so 2 is just a 2 on it's own

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lim x->1 2 = 2

cunning pelican
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yes

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so what now

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so we can move it to the other side?

signal pond
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What do you think?>

cunning pelican
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i mean probably

signal pond
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if i told you to re-arrange

cunning pelican
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not much left to do

signal pond
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5f(x) + 2 = 0, to get f(x) what would you do?

cunning pelican
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id just move the 2 and divide by 5

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so -2/5

signal pond
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okay so we get f(x) = ?

cunning pelican
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-2/5

signal pond
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yes

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Now if we include a limit

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well the 2 doesnt matter does it?

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so we get

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lim x->1 5f(x) = ?

cunning pelican
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-2

signal pond
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yes

cunning pelican
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and divide by 5 cuz its a constant

signal pond
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yes

cunning pelican
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kk

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thxx

signal pond
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So the limit as x->1 of f(x) /?

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But be careful

cunning pelican
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-2/5

signal pond
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check to make sure 2f(x) -1 is negative

cunning pelican
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oh ur eight

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right

signal pond
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And also make sure you think about why 2f(x) -1 cannot go to negative infinity, for the whole limit to go to negative infinity

cunning pelican
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kk thank u

signal pond
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np

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empty ingot
#

Find the value of x and y

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fallen swallow
empty ingot
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yes

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im looking

fallen swallow
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all the angles of the triangle are equal

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which is marked by the red arc

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so, 8y = 40

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y = ?

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@empty ingot

fallen swallow
empty ingot
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5

empty ingot
fallen swallow
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I think the question is irrelevant with the figure

empty ingot
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y=5

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whats x?

fallen swallow
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X is an angle or side?

magic chasm
empty ingot
#

TY

magic chasm
empty ingot
#

.close

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empty ingot
#

find the perimeter

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fallen swallow
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I don't understand

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what is*** "in."***?

copper mango
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Inches

fallen swallow
copper mango
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The side lengths...

magic chasm
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All of them is equals to each other because each side is 5 ball long. But question must say each ball is same lol

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x is simply 8

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potent rover
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potent rover
#

how do i find this sum

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i simplified it to [(-1)^(n-1) * 3^(n-1)] / 8^n

flint schooner
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I assumed it’s d but I’m not to sure

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I meant k

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Not d

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<@&286206848099549185>

timber pebble
timber pebble
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but im not sure how to move forward from there

potent rover
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hm

timber pebble
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oh

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yea i do

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lol

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so

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youll want to simplify it a bit more

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we also want it to start at 0

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the idea is to use this

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$\sum _{k=0} ^{\infty} (-1)^k x^k = \frac{1}{1+x}$

woven radishBOT
#

jan Niku

timber pebble
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there are convergence concerns with this formula in general obviously

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but your sum should converge just fine by inspection

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hint i guess is youll need to pull some stuff, do some index shifting

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i think youll need to subtract something too

potent rover
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why must you index shift?

timber pebble
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to get it into a given form

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alternatively

potent rover
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why do i need it in that form

timber pebble
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because it has a nice solution we can easily memorize

potent rover
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can i find the sum from that form

timber pebble
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yes

restive river
#

shrek math problem can u answer the same thing idk if im right yet

potent rover
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if i reindex my series to 0

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wouldnt i get

restive river
#

yo gio

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can u help me out with fun math

potent rover
#

[(-1)^(n+1) * 3^(n+1)] / 8^(n+2)

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@timber pebble

timber pebble
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hmm i made a mistake somewhere

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lemme see

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dang

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keep getting weird errors

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I have idea where theyre getting 11

potent rover
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hm

timber pebble
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lemme code it

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@potent rover

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theres an error in the problem

potent rover
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how so

timber pebble
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total = 0;

for i = 1:10
    numerator = (-3)^(i-1);
    denominator = 2^(3*i);
    term = numerator / denominator;

    total = total + term;
    
    if mod(i,2) == 0
    (1/11) - total        
    end


end```
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converges to 1/11 but only if it starts at 1

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the sum if it begins at 2 is negative

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since the first term is negative and each successive term is smaller in magnitude

potent rover
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oh

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so how do you solve it

timber pebble
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converges really fast

potent rover
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or can it not be

timber pebble
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it exhausts machine precision in 40~ terms

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you can solve it, just start it at 1 instead

potent rover
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so then do i have to reindex it

timber pebble
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if you want

potent rover
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what about this

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im comparing with the series i know for sin(x)

timber pebble
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dang i wish i knew how to calculate though

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still getting the wrong answer

potent rover
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she might have made an error

potent rover
#

that series starts at 0

potent rover
# potent rover

so i say that that series equals the first two terms of this series plus the series itself

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x - [x^3 / 3!] + series from 2 to inf [(-1)^n / (2n+1)!]

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i can see that that series looks like sin(1)

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what do i do with those first two terms?

timber pebble
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you mean like if you want to reindex

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you can just add them and subtract them

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if im understanding you right

potent rover
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i wasnt reindexing actually

timber pebble
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$\sum _2 ^\infty n = (\sum _2 ^\infty n) + 0 + 1 - 0 - 1 = \sum _0 ^\infty n - 0 - 1$

woven radishBOT
#

jan Niku

timber pebble
#

oh flonshed

potent rover
#

i was just writing out the first 2 terms of the series for sin(x)

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and then adding the series in question

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since it starts at n = 2

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main sluice
#

How do I do the integral of (ln(x)) / x^n dx

main sluice
#

Im not used to the variable "n" power

magic chasm
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you can just a put a random number, then replace it with "n" when you solve

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or you can just:

main sluice
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um is that "loptu"? What's that

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on top right

magic chasm
# main sluice um is that "loptu"? What's that

It is for me to remember easily

LAPTÜ
L=logarithm
A=arc
P=Polynomial
T=Trigonmetry
Ü=üstel (Exponential) (in turkish)

if there are two of these in an integral, you call the left one u, and everything else equals dv

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Like this for example

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It goes from left to right

storm gyro
#

uh i think you integrated x^n wrong

magic chasm
#

It is possible sadcat

storm gyro
#

if x^ndx=dv, v=x^(n+1)/(n+1)

main sluice
#

Thanks guys

#

$close

#

.close

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eager elm
devout snowBOT
eager elm
#

Arctan 2 + arctan 3 = ?

magic chasm
#

arctan2+arctan3=x

tan(arctan2+arctan3)=tanx

tan(arctan2) + tan(arctan3) / 1-(tanarctan(2) x tanarctan3) = tanx

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2+3 / 1- 2x3 = tanx
5/-5 = tanx
-1 = tanx

eager elm
#

To use this formula AB<1

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But here AB =6

magic chasm
#

The rule applies to sin and cos, not tan

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tan may be bigger than 1

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tan60 for example, it is sqrt3

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rare lichen
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rare lichen
#

in the simplest way possible, how would you describe the symmetries of an equilateral triangle?

#

pls help 😦

#

oh wait

#

since I'm assuming each symmetry is under the dihedral group

#

do I just need to describe the rotations, reflections, and stuff like that?

rare lichen
#

I see

#

thank you very much!

#

also, I learned that dihedral groups aren't commutative, but there are some cases where some elements composed with each other are commutative right?

#

It's just not all elements composed with one another are commutative

#

which makes dihedral groups non-abelian

#

right?

#

like if you composed a rotation A with another rotation B, that would be the same as composing the rotation B with the rotation A

#

however

#

if you tried composing a rotation A with a reflection R, it wouldn't be the same as composing the reflection R with the rotation A

#

@copper mango

copper mango
#

I don't actually know group theory, I just know the symmetries of an equilateral triangle sully

rare lichen
#

oh

#

that's fine

#

😄

#

thanks for the help

#

I do have another question for anybody else who understands group theory

#

oh wait

#

yeah

#

I'm quite curious

#

are all cayley tables the same for all dihedral groups?

#

🤔

modest dagger
#

Cayley tables like the group multiplication tables?

rare lichen
#

yeah

modest dagger
#

Then no

rare lichen
#

so a cayley table of a dihedral group order 8 wouldn't be the same as a cayley table of order 6?

modest dagger
#

The different dihedral groups at the very least don't always have the same numbers of elts.

#

So they can't have the same cayley tables.

rare lichen
#

I see

#

damn

modest dagger
#

Maybe I could be mixing this up?

#

I haven't touched dihedral groups in a minute

#

But you can just google dihedral groups and check a couple of the tables to verify.

rare lichen
#

yeah

#

thanks tho

#

😄

modest dagger
#

Or like consider a triangle vs some regular polygon with a ton of sides.

rare lichen
#

mhm

modest dagger
#

The triangle might have way less elts in its corresponding dihedral group compared to the dihedral group corresponding to the big ugly regular polygon you might pick.

rare lichen
#

what do you mean by "elts"

modest dagger
#

Sorry I mean elements. At the very least you can pick n large enough that there are more rotations for your big ugly polygons dihedral group than there are elts of the dihedral group for the triangle.

rare lichen
#

so more sides = more elements

modest dagger
#

Yep.

rare lichen
#

I see

#

luckily I'm only dealing with $D_4$

modest dagger
#

Think about it, how many elts correspond to rotations for the dihedral group of a triangle? Now compare that to a regular 17-gon.

woven radishBOT
#

ChubbyMuffins

rare lichen
#

😅

modest dagger
#

Yeah, you generally deal with small examples because big ones blow up in ur face lol.

rare lichen
#

oops

#

I meant D_3

modest dagger
#

Small examples are good for building intuition.

rare lichen
#

what would be an example of the elements for a 17 gon then?

#

like there's 8 elements in a dihedral group of order 6

#

or just a 3-gon

modest dagger
#

So for ex you would have a rotation by some amount of degrees (360/17 maybe? I forget basic geometry lmao).

#

You'd also have flips about certain lines of symmetry and junk.

rare lichen
#

ohhhhhhhhhhh

modest dagger
#

The basic elts you would come up with the same way as in other dihedral groups.

rare lichen
#

I think I've been thinking too much on angles of rotation..

#

I wish my book made this more clearer

#

r just means 1 rotation

#

r^2 means 2 rotations

modest dagger
#

Yep exactly

rare lichen
#

now I get what you're talking about

#

tysm bro

modest dagger
#

No problem. Dihedral groups are neat but sort of weird to think about at first

rare lichen
#

if it's ok, you don't have to but I got 1 more question

#

wtf is this problem

uneven elk
#

damn idk

rare lichen
#

I mean

#

I kind of understand the first diagram

#

when you reflect the graph you get the second graph

uneven elk
#

$FR^1=R^{(-1)}$

#

?

woven radishBOT
uneven elk
#

second one is if you rotate counterclockwise and flip

rare lichen
#

F composed with 1 rotation is the same as the inverse of R?

uneven elk
#

I very minimal understanding of group theory I am not equipped to answer you I just think this makes sense to me

#

@modest dagger

rare lichen
#

this is chapter 1 of my abstract algebra book 😰

#

well

#

chapter 2 specifically

uneven elk
#

looks like group theory but I think I am wrong

uneven elk
rare lichen
#

I see

uneven elk
#

wait no it doesn't

#

its so wrong one sec

modest dagger
#

Yeah idk if ur identity is right vrang but the top is just explaining what happens after doing a flip then rotate

#

Bottom is showing rotate then flip

#

I'm not sure I understand what they want us to conclude

#

I think I see something it proves.

uneven elk
#

$FR^1=RFR^2$

woven radishBOT
uneven elk
#

or

#

$F = RFR$

woven radishBOT
modest dagger
#

What happens if n=5? What does that tell u about whether or not fr=rf?

#

^this is what I'm thinking.

uneven elk
#

but idk if thats like already known for all transformations

rare lichen
#

oh wait

minor pebble
uneven elk
modest dagger
#

n is just one of the corner numbers.

rare lichen
#

yeah..

#

true

modest dagger
#

For ex in dihedral group of triangle n is 1,2,3.

uneven elk
#

both the same thing

#

right?

minor pebble
#

how do i get help?

modest dagger
#

So pick an n, do f and r commute according to the diagram?

uneven elk
modest dagger
#

Maybe they have a different idea in mind.

#

But that diagram def tells u whether f,r commute or not.

#

Do you see what I'm seeing?

rare lichen
#

ohhhh

modest dagger
#

You see it?

rare lichen
#

I think I kinda get what you're saying

#

but

#

the thing is

#

dihedral groups aren't commutative

modest dagger
#

Yes that's what I'm getting at lol

#

It just shows that f and r can't commute

#

If they could u would get those vertices to match in the pic

rare lichen
#

ohhhhhhhhh

#

that makes a lot of sense

modest dagger
#

Or something vaguely like that at least

rare lichen
#

both starting graphs were the same, but the ending graphs were different

modest dagger
#

Yes, that is what i was seeing. Granted, they could mean something else too.

rare lichen
#

so it's just a way to geometrically show that FR is not the same as RF

#

damnnnn

modest dagger
#

Vrang might not be wrong or anything tho

#

They could have a different property in mind and there could be other properties we could find from that pic I suppose.

rare lichen
#

I see

#

yeah group theory isn't easy ig 😂

#

and it'll probably get harder as I progress forward

modest dagger
#

You get used to it.

#

The parts that are hard later are a different kind of hard.

rare lichen
#

I see

modest dagger
#

I found it easier to work with the later kind of hard.

rare lichen
#

thanks a lot!

#

I think I can do the rest by myself now

#

😄

modest dagger
#

Np

uneven elk
#

nah dootdooter's property makes much more sense

#

learn something new everyday and today it was basic group theory

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#

@rare lichen Has your question been resolved?

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viscid goblet
#

write in the form of y=a(x-h)^2+k

y=x^2-2x+7

my answer was y=(x-1)^2+8
is it correct

winter patrol
#

no

viscid goblet
#

can you explain why

main gull
#

How did you get to that answer?

#

Show your work and we can tell you which part went wrong

viscid goblet
#

y=(x^2-2x+1^2)+7-1^2

#

@main gull

winter patrol
#

thats ok so far

viscid goblet
#

and then i did y=(x^2-1)^2+8

winter patrol
#

how are you getting that

main gull
#

Because I think you are doing y=(x^2-2x+1^2)+7+(-1)^2

viscid goblet
#

but 1 moved from lhs

#

wait

#

am confused

winter patrol
#

how are you getting from
7-1^2 to 8

viscid goblet
#

-1^2= 1

winter patrol
#

no

#

its not

#

recall your exponent laws

viscid goblet
#

wait so its 7-1

main gull
#

It's 7-(1^2), not 7+(-1)^2

viscid goblet
#

oh 7-(1^2)

#

i see

#

so the answer should be y=(x^2-1)^2+6

#

@main gull

winter patrol
#

no

viscid goblet
#

wait what

winter patrol
#

double check what you've written

viscid goblet
#

y=(x^2-2x+1^2)+7-(1^2)

#

@winter patrol

winter patrol
#

thats ok so far

viscid goblet
#

y=(x^2-1)^2+6

#

then it should be this

winter patrol
#

is not correct

viscid goblet
#

where is the problem which area

winter patrol
#

how are you getting from
(x^2-2x+1^2) to (x^2-1)^2

#

more specifically why do you have (x**^2**-1)^2

viscid goblet
#

oh

#

i see

#

yeah

#

its should be (A+B)^2

#

my bad

#

thanks @winter patrol

#

.close

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restive river
#

.open

snow python
#

how do i begin to solve this

devout snowBOT
snow python
#

i genuenly have no idea

#

<@&286206848099549185>

devout snowBOT
#

@snow python Has your question been resolved?

snow python
#

pls just a tip or somethin i genuenly dont knwo

random lintel
#

Try and use a+b≥2ab

#

And cycle through for a+c≥2ac and b+c≥2bc @snow python

#

then see if you can continue from here

#

Sorry it should be root 2ab and root 2bc etc.

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#

@snow python Has your question been resolved?

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worldly jewel
#

why isnt the minimum value of |z+1| 1? because even if |z| is 0, you still have to add 1 to it right?

winter patrol
#

what is z = -1

worldly jewel
#

what?

winter patrol
#

if z=-1, |z+1| = |-1+1| = |0| = 0

#

|z+1| isn't the same as |z| + |1|

worldly jewel
#

ohh

#

so the 1 can get cancelled out

#

.close

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untold sky
#

how do we solve this?

devout snowBOT
copper mango
#

C has the same dimensions as A and B

#

since you need to add A and B

untold sky
#

i don't understand. please explain more clearly

copper mango
#

do you know how to add matrices Y or N?

untold sky
#

yes

copper mango
#

so then... 5A and 3B need to have the same dimensions.

untold sky
#

yeah

copper mango
#

and C will have the same dimension as those

#

so C has the same dimensions as A and B.

untold sky
#

so the answer should be 3 x 5?

copper mango
#

yes

untold sky
#

okay thanks 🙂

#

.close

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north sail
#

If the solution set of (3a-1)x+6=5x+3 is empty then find the value of a.

north sail
#

I have no idea where to start

frozen elm
#

An easy way to get a no solution set is to just make it so the two x's cancel out

#

Or the coefficients are equal on both sides of the equation

devout snowBOT
#

@north sail Has your question been resolved?

north sail
#

Okay I’ll try that

#

I’m still confused could I get some more help

#

How do I do that?

devout snowBOT
#

@north sail Has your question been resolved?

north sail
#

.close

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latent hill
#

It looks like wolfram alpha gives the wrong output here

latent hill
#

Can someone maybe validate me?

devout snowBOT
#

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fervent hamlet
#

,tex 8² - (-3)² = 64 - 9 = 55

devout snowBOT
woven radishBOT
#

randomystery

exotic stump
#

ok lol

woven radishBOT
#

randomystery

fervent hamlet
#

good 👍

exotic stump
#

uh no

woven radishBOT
#

Euclid31415

fervent hamlet
#

Ah

#

Its a test bro

torpid cairn
#

Testing latex?

fervent hamlet
#

Nop

#

This wrong algebra is a test i know the result

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#

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wanton fulcrum
#

H

devout snowBOT
wanton fulcrum
#

Help

wanton fulcrum
wispy reef
#

Anyone knows how to solve identities

copper mango
wispy reef
#

Thanks

devout snowBOT
#

@wanton fulcrum Has your question been resolved?

wanton fulcrum
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@wanton fulcrum Has your question been resolved?

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@wanton fulcrum Has your question been resolved?

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little escarp
#

i understand that $A$ is hermitian $\implies$ its eigenvalues are real, but is the converse true?

woven radishBOT
little escarp
#

As in

#

Eigenvalues of $A$ are real $\implies$ A is hermitian

woven radishBOT
little escarp
#

.close

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whole patio
#

So like

devout snowBOT
whole patio
#

could someone explain me, mathematically speaking

#

what's the difference between recursion and iteration in general

#

For iteration, I usually just think about something like as described in https://en.wikipedia.org/wiki/Iterated_function

In mathematics, an iterated function is a function X → X (that is, a function from some set X to itself) which is obtained by composing another function f : X → X with itself a certain number of times. The process of repeatedly applying the same function is called iteration. In this process, starting from some initial number, the result of appl...

#

In mathematics, an iterated function is a function X → X (that is, a function from some set X to itself) which is obtained by composing another function f : X → X with itself a certain number of times.

#

As for recursion, here goes a formal definition

#

In mathematics and computer science, a class of objects or methods exhibits recursive behavior when it can be defined by two properties:

A simple base case (or cases) — a terminating scenario that does not use recursion to produce an answer
A recursive step — a set of rules that reduces all successive cases toward the base case.

#

So, this idea of having a base case is also present in the context of iterated functions, it corresponds to that

#

and the idea of a recursive steps seems to also be present in that composition of functions

frozen elm
whole patio
#

so how could recursion and iteration be differentiated from a mathematical standpoint?

#

Perhaps I should just refer to https://en.wikipedia.org/wiki/Iteration instead of speaking about iterated function

Iteration is the repetition of a process in order to generate a (possibly unbounded) sequence of outcomes. Each repetition of the process is a single iteration, and the outcome of each iteration is then the starting point of the next iteration.
In mathematics and computer science, iteration (along with the related technique of recursion) is a s...

#

Since in programming recursion is actually seen as function calling itself and possibly providing itself as an input

#

Oh

#

Oh,

#

that makes sense

#

In algorithmic situations, recursion and iteration can be employed to the same effect. The primary difference is that recursion can be employed as a solution without prior knowledge as to how many times the action will have to repeat, while a successful iteration requires that foreknowledge.

#

So that's the reason

#

we're able to find solutions for recurrences like Fibonacci

#

or more generally speaking any kind of recurrence, whether it only has a homogeneous solution or even a particular one

#

while only having prior knowledge to the initial terms which are really representative of the degree hm

frozen elm
#

Reasonable

#

Also hi

#

(Scf moment)

devout snowBOT
#

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robust thistle
devout snowBOT
robust thistle
#

How do you do question 2

#

<@&286206848099549185>

shy wing
#

it means find where the slope is 0

robust thistle
#

how would you do that

shy wing
#

find where the derivative is 0

robust thistle
#

we havent done that

shy wing
#

yes you have

#

the slope of the tangent line is the derivative

#

so you obviously have

#

since those exact words are on the paper

robust thistle
#

the word derivative has never been mentioned so i dont rlly know what it means

shy wing
#

the derivative is the slope of the tangent line

robust thistle
#

ok so first step is find the slope

#

ill do that and see what i get

shy wing
#

@robust thistle oh wait i was looking at question 3

#

ignore the 0 part of what i said

#

do you know what f’(x) means?

robust thistle
#

yes

shy wing
#

the equation of the tangent line to f(x) at (a,f(a)) is defined as y = f’(a)(x-a)+f(a)

robust thistle
#

what do i do with that info

shy wing
#

you’re literally asked to find the equation of the tangent line at a = 2

robust thistle
#

so is this what id do

shy wing
#

f’(x) = 6x^2 - 4, f’(2) = 20

#

wrong

robust thistle
#

how is f(2) 20

shy wing
#

find f’(2)(x-2)+f(2)

#

f’(2) = 20

#

f(2) doesn’t

#

you said you knew what f’(x) meant

#

didn’t you

robust thistle
#

i didnt notice the '

shy wing
#

well another way of writing it is $y = m(x-x_1)+y_1$

woven radishBOT
#

quantum

shy wing
#

but m is the derivative

#

so that doesn’t help actually

#

oh darn, thanks

#

f’(x) = 9x^2 - 4, f’(2) = 32

robust thistle
#

there are answers in the pic i took

#

so first step would be to find m when x=2?

shy wing
#

yes

robust thistle
#

@shy wing i got a slope of 40

shy wing
#

it’s 32

robust thistle
#

oh i see what i did

#

so whats the next step

shy wing
#

y = 32(x-2)+f(2)

#

just find f(2)

#

and you’re done

robust thistle
#

oh okay i got it

shy wing
#

although afterwards simplify the equation

robust thistle
#

can you explain why we do this

shy wing
#

what do you mean

robust thistle
#

sorry i mean why we use that formaula

shy wing
#

because it’s the formula for a tangent line

robust thistle
shy wing
#

it’s a rewrite of the slope formula

robust thistle
#

ahhh

#

thank you

#

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full gulch
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full gulch
#

I used vf=vi+ at but I couldn't get any of these answers, whar am I doing wrong?

#

So vf is 3m/s and acceleration is equal to
3m/s divided by 4sec should be.75m/s2 but why is this not correct?

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scarlet copper
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#

@scarlet copper Has your question been resolved?

merry urchin
#

you could start by making the assumptions mentioned, so you have numbers to work with

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@scarlet copper Has your question been resolved?

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@scarlet copper Has your question been resolved?

wooden stirrup
#

@scarlet copper

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restive river
#

|𝑥−3| + |𝑥+4| ≥ 7

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thick oxide
#

Hi, may I send my question here.

devout snowBOT
thick oxide
#

?

cosmic jacinth
thick oxide
#

g(x)=x^3 + x f(g(x)) = (x^2(1-x))/4-x

#

solve for f(-2)

cosmic jacinth
#

is your question this:

thick oxide
#

3

cosmic jacinth
#

$g(x)=x^{3}+x$

$f(g(x)) = \frac{x^{2}(1-x)}{4-x}$

Solve for
$f(-2)$

woven radishBOT
#

Muhammad Hussaini

thick oxide
#

yes, thanks!

cosmic jacinth
#

Oh, let me see

#

Well let me show you

#

The way

#

Did you try it

#

By yourself

#

@thick oxide

thick oxide
#

One second.

#

I tried substituting g(x) by a

cosmic jacinth
#

Well, I'll give you a hint

#

Try finding g^-1(x)

#

And substituting it in fog(x) to get f(x)

#

Then find f(-2)

thick oxide
#

I'll give it a try

cosmic jacinth
#

Sure

#

Well, I think inverses for cubes are difficult to find

thick oxide
#

exactly,

#

how do you solve x = y^3 + y

#

Could you tell me?

#

@cosmic jacinth

copper mango
thick oxide
#

solve to y =

copper mango
#

isolate

thick oxide
#

I'm sorry?

copper mango
#

and there's no way to do that unless you somehow know the cubic formula

thick oxide
#

@copper mango How would you solve the original problem?

thick oxide
copper mango
#

find x such that g(x)=-2

thick oxide
#

-1

copper mango
#

yes

#

so just... evaluate f(g(x)) at x=-1.

thick oxide
#

I'm not taught maths in english, I assume you mean filling in x for -1? Then I get zer

#

zero

copper mango
#

you do not

#

1-(-1) is not 0

thick oxide
#

2/5

copper mango
#

yes.

thick oxide
#

so that's the answer?

copper mango
#

yes.

thick oxide
#

Ow, thank you! May I perhabs ask one more question, I've got my exams tomorrow

#

Prove: a^b log c = c ^ b log a

#

@copper mango, if you've got the time

#

Actually, <@&286206848099549185>

#

.close

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restive river
#

hey can i post a paper picture?

devout snowBOT
restive river
#

i need help with these

copper mango
#

<@&268886789983436800> Test.

restive river
#

?

#

its a pratice i printed out

#

gogle it you can print it

#

how do i do polynomail division

#

ok

#

thankyou

#

thats it thankyou so much

mental garden
#

has anyone here done fourier transformations for functions? im suppose to test it out...with a linear function. how much terms does a linear function need? im getting upwards of 30 terms.

#

the difference is suppose to be <0.1

#

no i think the web app is just fucked up actually

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#

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bright magnet
#

<@&286206848099549185>

devout snowBOT
bright magnet
#

<@&286206848099549185>

wheat warren
#

put l in form y=mx+c to get m

devout snowBOT
#

@bright magnet Has your question been resolved?

bright magnet
#

yh ik how to get m

#

but how to do i solve the rest

#

to find a line that passes through A

#

@wheat warren

wheat warren
#

what do you know about the relationship between the gradients of perpendicular lines

bright magnet
#

they are

#

negative

#

reciprocals

#

so if one line is 1

#

the other is -1/2

wheat warren
#

so if u know m

#

the gradient of the line ur looking for is -1/m

bright magnet
#

so the answer would be -0.75

#

or -3/4

wheat warren
#

yes

#

so line is y=-3/4x+c

#

then use the coordinates they give u as y and x

bright magnet
#

so -5=(-3/4)*(3)+c

#

-5=-2.25+c

#

so c=-2.75

wheat warren
#

no

bright magnet
#

oh

wheat warren
#

negative

bright magnet
#

oh sorry i meant negative

wheat warren
#

yep then

bright magnet
#

so i make the equation?

wheat warren
#

yes

bright magnet
#

so that would be y=-3/4 -2.75

#

?

wheat warren
#

no

#

y=-3/4x-11/4

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bright magnet
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bright magnet
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.close

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blazing charm
#

Let’s say I have a quadrilateral with two right angles at the base. You also have the dimensions of the two sides and base (in the green). I was wondering what mathematical equation will get you any of the heights from the base to the top of you choose a number from 0-16.

blazing charm
#

It’s definitely an easy question I would assume and I knew it before I just can’t remember what it was.

graceful cosmos
#

Similar triangles is what you're looking for

blazing charm
#

Wdym?

graceful cosmos
#

So is the base 16 units long?

blazing charm
#

Yes

graceful cosmos
#

Another way to do it, is to turn the top into a function.

#

Slope = (11-4)/16
m = 7/16

#

So the top line is given by:
y = (7/16)x + 4

#

Then, whatever red line you want to find the height of, plug that in for x

blazing charm
#

Ahhh ok thank you

#

Just to make sure tho, you’re saying that it would be ((Heighest-Lowest)/Base)*(Any number between 0-Base Length)+(Lowest)?

#

For any quadrilateral with two right angles?

graceful cosmos
#

I'm saying it would be y = mx + b

#

Where I'm letting x = 0 be the left end of the quadrilateral

#

m = slope, b = y-intercept

blazing charm
#

Ahhh ok

#

Alright thanks a lot!

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cursive aspen
#

without calculating the determinant, show justifiably that

suggestion, make operations on the columns

cursive aspen
#

i understand its a vandermonde matrice, but it says, without calculating the determinant

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#

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@cursive aspen Has your question been resolved?

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analog pollen
#

Hi, could I get any help here with a physics question I m having trouble with?😅

analog pollen
#

no problem man

stray olive
#

Nicko

#

did u try to ask in physics server?

analog pollen
#

I only found one physics server but no one answered me

stray olive
#

sadge

analog pollen
#

do u know some server?

stray olive
#

nope

analog pollen
#

😦

#

thanks though

#

.close

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wet fox
#

i need help starting the integral

#

can i get help?

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wet fox
devout snowBOT
wet fox
#

can i get help starting the integral plz

devout snowBOT
#

@wet fox Has your question been resolved?

copper mango
#

where you want to write the integral in spherical

shy wing
#

you can just do \iiint if you forgot

copper mango
#

cant forget something I didn't know KEK

shy wing
#

lol

woven radishBOT
wet fox
#

What does the E represent?

copper mango
#

the region

#

so.. the planet in this case

wet fox
#

Ahh right I see

copper mango
#

so you just need your bounds on theta, phi, and r

wet fox
#

Would r^2= 4^2

copper mango
#

what's the radius of the planet?

wet fox
#

R

copper mango
#

so what are the bounds for r?

wet fox
#

4 and 1

#

?

copper mango
#

no

#

imagine you're in a sphere at the very center

How far are you from the center of the sphere?

wet fox
#

0

#

And