#help-27
1 messages · Page 441 of 1
Ty man
dw both are correct ;3 i am alas but a planet ;3
Bro friend?
Now we could use ur thing
I'll catch onto it again later
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Task 11. (0–2)
For a performance in a certain theater, tickets were sold according to the following price list.
A total of 200 tickets were sold for this performance.
After paying the costs related to organizing the performance, amounting to 25% of the ticket sales revenue, the organizers had 4665 zł left.
Calculate the number of reduced-price tickets sold for this performance. Show your calculations.
well then, as always, for future helpers, what have you tried and where are you stuck?
Result:
5831.25
So they earned 5831,25 zł in sales
Are you sure it's ×1.25
Yes cause it’s 85% and we’re missing 25%
Let's say I lost 99% of my money and I only got 1 dollar left
How much did I originally had
100
Ok so how did you calculate that?
Idk
Also where are you getting 0.85 from
What?
Result:
6997.5
200(x+y)=6220 zł??
What are we calling x and y
IOQM 2022
@maiden cloud Has your question been resolved?
x regular and y discounted
Leave me alone
<@&286206848099549185>
Chop chop
how many tickets were there?
200
suppose x tickets were of regular
that means how many reduced ones?
200-x
what money do you get from selling regular tickets
Money
yeah. what's the price of one regular?
6220-x(35)=y
huh?
Please be kind, I am just trying to help you.
i am asking ya price of one regular ticket
Almost! I think 6220-x(35)=y(25) is closer
!volunteers
Helpers are just people volunteering their time to help you. Be polite and patient.
Okay, so you correctly figured out the full price of the tickets, 6220.
You also know that if we have x as the number of regular tickets, and y is discounted tickets, then we have:
x+y=200
And that
6220=35x+25y
Do you think you can solve this now?
Your behavior is unacceptable, OP.
No
Idk how to eliminate x and y
To have one variable
Try rearanging the first equation
Ok like ppl have said
Let x = number of reduced price tickets and y = number of regular price tickets
Total: x+y=200 so y = 200-x
The revenue is obviously 25x+35y
Sub y in then then ull get ur revenue in x and then the cost was 25% this imples the organizer kepts 75% so 0.75(revenue in x) = 4665 fill in the blanks to solve it
No x for regular and y for reduced
Once you rearange, you should have x=200-y, which you can then substitute into the second equation, does this make sense?
Dawg it doesnt make a difference keep x as reduced we want reduced
Why solve for y when its irrelevant
6220-x(35)=200-x(25)
602 regular were bought
Almost! In this case we want 6220=35(substitute here)+25y
We want to get rid of x so we can solve for y
,calc 602*35
Result:
21070
Chop chop read what i sent takes 2 seconds
Remember how the question said only 200 tickets were bought? 602 can't be correct. Try again
Can you solve this?
Can you do it?
People do not work for you.
Your behaviour is unacceptable for twice.
!noans
The purpose of this server is to help you learn; please don't ask for direct answers. Ask for guidance, explanations, or feedback instead.
Remember, helpers are volunteers, do not assume people do for you freely.
Bring the attitude down.
Sorry, but no, all this is coming from you telling someone else to "chop chop"; that's on you
Bring yours down.
Further, as has been stated before, the purpose of this server is to assist you in your work, not to do your work for you.
Number one - where did 85 percent come from here?
@maiden cloud Has your question been resolved?
To know what’s the real amount
Mathematically speaking, what did you do to get 85?
Because that's nowhere in the question you've posted
@maiden cloud
please post your ENTIRE thought process
@gloomy aurora I mean...
updated suitably.
gang this is still not solved 😭
@maiden cloud is the problem solved?
@maiden cloud Has your question been resolved?
@maiden cloud, you're gonna have to do better than just answering ❌ to the bot - you've still not responded to this question I've put to you here ^
or to Annie's request to show your entire process
I don’t know what now
what is your question still.
if your question has not been answered, what is your question?
My question is how to solve it
right, and someone asked you a question after that. you should answer that so the other helpers can have an easier time guiding you through it.
so I shall reiterate the question I'd asked you - why, when the organisation costs amount to 25% of the revenue generated, have you used the number 85%?
Do you expect random people on the Internet to do all your work for you and then hand it to you on a golden platter? I'm sorry, but you aren't gonna go far with that kind of mentality.
Perhaps it was a carry over error
Remember that percentage must add up to 100 here
so if the full revenue is 100%
and they spent 25%
then they have 100%-25% left over
fyi, I wanted to get him to say that
Yeah but he's confused and using the wrong number I think
It's not even that
I already pointed out that this was the first hurdle, by asking him where he got 85% from
I asked that over 4 hours ago, with no response to it
I suppose he was not very interested in answering that
Which can only mean he won't be interested in answering any other question posed to him
Yeah thats why i just put it there incase he reads it
"Coach, I'm trying to run this hurdle race, but I keep stumbling over them"
"Okay, why are you in a potato sack?"
"That isn't the problem, just help me not stumble over these hurdles"
"Get out of the sack first"
Not too dissimilar a situation to this
solution 2: roll under the hurdles
If they are in potato sack, are they potato?
If they were a human, and they became a potato does that mean humans can become potatoes
Does that mean, I am one step away from becoming peri-peri French fries

I mean, I dread to think what that extra step to become peri-peri French fries would be; but we're getting more and more off-topic
obviously bathing in a tub of peri-peri
duh
getting on-topic. close this channel bruh
-# (it's more the plural "fries" that's concerning)
But yh - @maiden cloud are you claiming that you did 100 - 25 to get 85?
@maiden cloud Has your question been resolved?
OP just going to ignore all helpers' questions and waiting for solutions.
What a waste of time and disrespectful behavior.
Should I ban OP?
There are a lot of people that do that
@maiden cloud Has your question been resolved?
@maiden cloud if you aren't going to answer the helpers' questions, we will close this channel.
FYI, you will not get answers in this server.
yes but we want OP to learn their mistakes and learn how to do the problem.
I think ik it
No stop
I’ll continue tomorrow
!done in that case.
If you are done with this channel, please mark your problem as solved by typing .close
First you need to figure out the value of how much money they had before paying the venue anf stuff
then please close this channel and make a new one when you have time/are willing to learn.
A quick note is that if this behavior is still shown tomorrow, no one will be able to help you.
just open a new channel tmr?

Thid channel never xlosed lol
odd...
@maiden cloud are you going to actually come back and use this channel?
do we ask a mod?
Im not exactly sure how teh closing logic works. I was reading the source code, and it says whoever has the manage_clopen tag can close a channel. But I'm not sure how this tag is assigned
I think only OP can close
or mod
I think it will also just time out if we ignore it
And people with the "manage_clopen" tag too. I dont think its neccessarily a mod. ill have to ask the creator of the bot
It should
helpfuls can but we tend to choose not to
since OP said "tomorrow" im willing to wait a max of 24h before i pursue
if OP is not flat out trolling or what not we have no reason to close it despite how much we may bitch about it
but you can modping if you think OP is indeed not acting in good faith
So do you have any problems? No? If no then close. Else elaborate.
Not yet
Then when?
A better explanation is needed, else I have to modpings.
Because I’m at school.
I mean I don't feel its good practice just to keep a channel open because you're at school and will come back at indeterminate time. You can as well 1) write down progress so far 2) close channel 3) open a new one
considering the amount of progress in this channel or lack thereof, might as well you close and reopen later.
with all due respect, I don't think the channel is the only thing people are mad at you for.
As observed, OP tends to leave channel opened as an act of revenge, for helpers not giving him what he wants (which is the results). Moreover, a lot of disrectful acts have been given to other helpers like: "chop chop". Once no ones give him answers, he will ultimately stop to reply to others and wait until someone lose their patients to giveaway answers.
Lack of elaboration and cooperation also counted here, waiting for people to solve for him, no thanks, no appreciations, just silently take all the results, what he wanted. Then close, the next day, things repeated again.
if you think so, just modping or modmail
Yes, I will do it now.
<@&268886789983436800> Please take a look at this channel.
I think people with the helpful role can close a help channel
That is against the server rules unless other circumstances.
Actually?
Re-read the rules, only close if necessary.
Giving you the benefit of the doubt here, even if you're just joking, it really is worth being quite careful with what you say to people who aren't familiar with you, because they may not interpret it as humourously as you.
(if you're actually demanding your helper to hurry up, then that's not cool - remember that people are volunteering to help you, and that there's no obligation for anyone to help you with anything)
just because we can does not mean we (always) should.
(grrrr I was already here
)
My favourite cat 
Yea in general, you shouldn't close the help channel, and let us know
)
You are my fellow cat too Lute, even if I don't know you (Maybe I left for too long) 
I... don't know who you are, sorry.
I don't think we should chat here anyway, but last message before I leave: I don't think I will know you if none of my friends here know you.
i am SOOOOO tempted to but ik i shouldntt-
No worries, I just join to help random people for recess.
If someone is free so they can come to my help channel
i mean the amount of messages here, this channel as well may be closed
As was mentioned, you are probably going to have a better time getting a new channel, but I do want to remind you that we are not here to do problems for you, but to guide you in how to solve what you're working on. (Us moderators may also get a bit annoyed at people who give you solutions too!)
As I feel it would be better if the channel starts off fresh, I shall close this one, and in your own time, you can open another one. Please do bear in mind to explain, as clearly as possible, what you've tried 
no, on top of some other stuff you probably should not engage in as a helper.
You could closse it and reopen it
!noads, please.
Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, so advertising can quickly turn into spam.
If you do, I'll bite you 
Anyways-
.close
Closed by @upper schooner
Use .reopen if this was a mistake.
you took away the opportunity from me to close it 
-# oh i was /j sorry-
sameeee 
on this sure. but perhaps some other stuff as well.
(also, it will time out at some point)
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Pls help
The midpoints are different
How is D -2,-6 when you defined that as A?
I think you got the wrong value of D
Oh
Once you fix that you'll fret the right answer
Also check 2 with an updated value of D
But is my method right?
Method for what?
Confused about what?
For b
Are you confused about how to find the value of D?
Yh
The way I like to do it is that you know that the opposite sides are parallel right?
Yh
So CD||AB
starting from B, last say it moves y units down and x units left to get to A. Then, since the two lines are parallel, to get to D from C, you have to move the same y units down and x units left
So tou can compare it to find the x and y coordinates
1 min I'll make a diagram
I missed the equal part before
It's because the lines are PARALLEL and EQUAL
Hmm. I'm not the best explainer. It's really just breaking down of vectors
To get from B to A, you move left by x and down by y. Since CD is parallel, equal and the same segment orientation, the exact same movement takes you from C to D.
That's fine
This is the best explanation I can give
Oki wait
How do you do it in class? Like what did your teacher tell you?
A formula
Which is?
I don’t remember it’s the equation one or midpoint
What do you mean
To find coordinates
Did you write it down? Also is it for midpoint cords or the cords for D?
Because I'm asking for the coords of D
Im trying to find that
Ok no problem. Take your time
The formula will be something like:
A(a1,a2), B(b1,b2), C(c1,c2), D(d1,d2)
b1-a1=c1-d1
b2-a2=c2-d2
This is just an implementation of what I was saying before
Did you find the formula your teacher gave you?
Hmm. I'm a really bad teacher
<@&286206848099549185> could someone try explaining it better?
what's the problem here
I'm trying to explain this
This is the best explanation I could give
well. ABCD is a ||gm
And this is the formula I gave
No. No. I'm explaining how to find D if A, B, and C are given
the x coordinate of the midpoint will be same of BD
ok wait lemme see
what you explained
gang
you made it very complex
i dont think that was even needed
@potent compass do you see that this is a ||gm ?
I'm a really bad teacher if I'm to physically with the other person with a pen and paper
no problem man
i will try to explain it to them
I know, but skittles got the value of D wrong. I was trying to explain how to get D
Please do
Yes
Yes
My WiFi is bad rn
do you know that the diagonals bisect each other
oh ok
@potent compass Has your question been resolved?
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lemme translate
- provethat for every natural number Un+1 = ...
2 . count the first 5 limits
3 . study the deplacment if Un while -<=Un<=0
- lets say Vn=...
-
Prove that ( (v_n) ) is an arithmetic sequence, and determine its common difference and first term.
-
Write the expression of ( (v_n) ) in terms of ( n ), then deduce the expression of ( u_n ) in terms of ( n ).
i hate thoes type of exercise
What have you tried
Try 1 it’s relatively easy
ive tried
but its still
anynomous for me
plz help
Hint:||fraction addition or synthetic division||
still didnt work out
Hmmmm, how about we put it this way:
Consider the fraction
[ \frac{x - 1}{x + 3} ]
Is there a way to split it into one whole number another another fraction?
Average Maths Student
I wonder how we can get the expression "x + 3" on the numerator...
are questioning me or its too stupid that i couldnt solve it?
uhhhh it's a hint for you
You can also just plug u_(n+1)=(u_n-1)/(u_n+3) into the equation in 1.
@deft furnace Has your question been resolved?
no
Do you even want to be helped or just handed out the solutions
jst want the solution
cuz tbh i am tiered
Well then you should close the channel, it's against the rules and you aren't really considering anything of what other helpers suggested
i di
what helper suggested
Have you tried this?
yh
Did it work out or did you get stuck
What's the rest, 2, 3, 4?
Like we can't read your mind what you're attempting
2 . count the first 5 limits
is weirdly translated, are you sure that's it?
its literly what the question is saying
Well it doesn't make sense
that why i asked help
Only thing I can think of is the first 5 terms
no it limits not terms\
As well for
3 . study the deplacment if Un while -<=Un<=0
Study the monotonicity or something
That's just how this server works, it's against its philosophy
If you had 1-4/(x+3) then how could this behave on [-1,0]
wym
oh
i usealy count the derivitive
and see the signes of (when postive negative equal zero bla bla)
-# If it helps, I guess
Either way, if you found that out then you can prove it directly with the respective definition of increasing/decreasing
It's just the definition of an arithmetic sequence, nothing to do right now with what we do
bruh
my brain is not braining
i guess its going down
cuz its smaller than zero
Can you support your claim
what
wait i got idea
.
how abt i count U0 U1 U2
and then see wich bigger than the other
Great idea
.
This is why you should have done 2 first
and the opsit
Write down the first 5 terms ffs
no the behavior
No
If the next term is larger than the previous then it obviously goes up
if U0<U1<U2
this is not next term smaller
see
this is next term larger
.\
hey btw i had never studied math in english so please if sometimes u say something basic that i dont know
that means i didnt understand
I don't understand
\prpl Arithmetic sequence:
[ a_n=a_1+(n-1)d ]
Geometric sequence:
[ a_n=a_1 r^{n-1} ]
This is a geometric sum
exactly
that what i was looking for
and hiow abt the arithmetic sum?
cuz there is an exersise next to it i wana solve it alone just need the laws
if u are wondring
\prpl Arithmetic sum:
[ S_n = frac{n}{2} cdot (a_1+a_n) ]
r u sure its this one?
i remembred its something else
What do you remember
It's more general
does it going to work everytime?
Say your first term was indeed a_1 then p=1 and you get the same
Your formula works for arbitrary first term a_p
so look i found another one
?
this is another exersise that i am just stuck here
Then say so, this help channel was focused on this
Usually one opens a new channel so helpers are not confused
oh ok
its ok mb
elmme returne to the old one ig
i got one final question i skipped it
so lemme not
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I am in severe need of help with someone explaining to me how Rudin derived that q
(see equation 3)
p^2-2/(p+2) gives us polynomial whose root is the square root of 2( if it exists)
the p-(p-√2)=√2 again if √2 exists
which is the motivation for chosing it
( I think?)
Closed by @bitter garnet
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[
\text{The range of the function } f(x)=\left[9^x-3^x+1\right]
]
[
\text{where } [x]\text{ denotes the greatest integer function, is}
]
[
\text{(a) } {, r \mid r \in \mathbb{N} ,}
]
[
\text{(b) } {, r \mid r \in \mathbb{W} ,}
]
[
\text{(c) } {, r \mid r \in \mathbb{N}\cup{0} ,}
]
[
\text{(d) } {, r \mid r \in \mathbb{N},\ r\ge 2 ,}
]
BlackidoZΣ
I solved it and got (a) as my answer but the given is (b) & (c)
my logic is that:
let 3^x = a
f(x) = [a^2 - a + 1] & let a^2 - a + 1 = m
since a >0 and D< 0 => m>0 for all real
it means (m) inside GIF is always positive and positive GIF is the number itself
therefore, f(x) = a^2 - a + 1 = 3^2x - 3^x + 1
now exponential function are defined for x > 0 and x not eqal 1.
so x >0 there its range should be r E N
can you tell me where is the fault in my logic
What is D here
discriminant
Ok so first of all do you know what the greatest integer function is?
yes
Assuming you know then what is [x] if 0<x<1?
it gives x if x is integer and it gives a number left to x if x isnot integer
= 0
This is not how you use Latex btw
So if there exists a value 9^x-3^x+1 between 0 and 1 of the function your answer is already wrong
Because remember the natural number set
alright now we need to take cases right?
cases to give gif definition for given function
Well I think we only need to find the range of the original function and apply the floor function to it if that makes sense
% Just for your reference
% Although do note you need the enumitem package in your preamble for this to work
The range of the function, $f(x)=\left[9^x-3^x+1\right]$, where $[x]$ denotes the greatest integer function, is:
\begin{enumerate}[label=(\alph*)]
\item ${r\mid r \in \mathbb N}$
\item ${r\mid r \in \mathbb W}$
\item ${r\mid r \in \mathbb N \cup {0}}$
\item ${r\mid r \in \mathbb N, r \ge 2}$
\end{enumerate}
how do we solve this now
Do we know the range of the non floored function?
@normal bolt Has your question been resolved?
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Pls I need help with question b
do you not know how to start with it or
I don’t know how to start
Can I use the midpoint
To find the coordinates of d
don't need coordinates of D for part b)
consider that you can get the equation of a line using point and slope
Wha
you have the point C
and you can get the slope of CD (without knowing the coordinates of point D)
by applying properties of a parallelogram and slopes of parallel lines
Idk the properties
Then when do I use M
worry about that later,
you don't need it yet,
that's in the next part where you'll apply a different property
Ok
If you don't know the properties it would also be a good idea to look them up
I am
I’m still learning
Did you look up the properties
specifically the ones that mentions sides being parallel?
Yeah but I’m still doing tht
Cd is parallel and equal to ab
Do I use gradient
Bc their parallel
Do I use gradient
slope, gradient
don't need the gradient equation for CD, just apply that CD has the same gradient as AB
I’ll have to go soon
You now know that CD has a slope of 1
and passes through the point C
and the gradient
Closed by @fresh jetty
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,rccw
Ig using vieta would result in some manipulation
A picture of the original question would help.
???
.
well that is the original question
^
have you not learnt the propert for common roots?
AH nevermind, I forgot to scroll up.
Ah Idk I might've forgotten
check your notes again if you cant find it search up online
Since d,e,f are in G.P., then aren't $e^2=df$?
Mercury (ヤフォダ)
pretty famous property for your QE in you grade i think
Then I guess you could just find the determinant.
Maybe start with the second equation?
wouldn't that be the longer route
Nah, by substitution of e^2 =df.
It could cut the length down, I guess.
Why don't you give it a try?
well what i did was since it's given that they're in GP I just assumed they could be consecutive terms
and let x be common difference and d first term
Interesting. Looks fine though.
common differnece?
ahh geometric difference or whatever you call it.
Dude that property doesn't seem to work imo I'm not able to manipulate it
common difference?
wdym
@stuck reef Has your question been resolved?
Closed by @stuck reef
Use .reopen if this was a mistake.
jojo
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Why did they make it round brackets (a,b)
it is a technicality
a limit, by definition, must be approached from both sides
but at the endpoint you dont know what is happening outside of that interval
you cant 'see' what the function is doing outside of [a,b]
Yes but even if u use round brackets
U can’t see whats happening outside this interval too
if you say it is differentiable on [a,b] you are making assumptions about what is happening outside that interval
if you say it is differentiable on (a,b) you are not making assumptions about what is happening outside that interval
Closed by @keen sundial
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How can I easily tell which side is opposite and which side is adjacent in a triangle? I keep mixing them up and want an easy way to recognize them
ignore the longest side. is the side right next to your angle? if yes, that's the adjacent one. otherwise it's the opposite.
If Which side is right next to which angle sorry i didn’t understand
the adjacent and opposite sides are always in reference to one of the two non-right angles of your right triangle
now, the word adjacent means next to
so if the side (not the longest side, we don't care abt that as it's always the hypotenuse) is next to the angle of interest, then it's the adjacent side
otherwise it's the opposite side
Oh yes i understand thank you but what if its not given because my teacher just give a plain triangle with only the 90 degree side and she wants us to state which side is adj and which is opp
then you have to choose one of the two angles to mark as a reference angle.
well in this case your angle of interest is angle A
if your followup question is "how do you determine the angle of interest", the answer is "it depends on the question/situation"
Ohhhhhhhhh so they’ll always give it to us???
if they do not then you will have to determine from context
and what about them?
like, what are you asking about these types of questions?
how to determine angle of interest?
Yes
Ohhhhhh i get it so they’ll always mark it for us right?
so we can tell which one is opp and which is adj
always is a stretch. again, if it is not marked, then you will have to determine from context
but usually even if it is not marked the question will tell you what the angle of interest is. then you'll just have to draw it
yo, take over for me, need to go do some stuff
So for example if the question says whats the measure of angle o the angel interest is o right?
yes.
Wait omg i get it thank you so much guys
nice! anything else?
No thats it thank you
alright, then you may .close the channel (type that text in boxes, including the .). all the best!
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In 1) why did my teacher put 1/b but most sources use bx?
I understood all but I mean what’s the difference
Why are these function in b all 1/b?
,rccw
if b is the period of the sinusoidal function, then 1/b is the frequency. (if you've studied physics you may have heard of the term angular frequency , this is the same concept.)
so I guess 1/b is more used because it allows the period to be expressed as a transformation of the function sin(x) or cos(x).
So b in this case represents the frequency?
no, in the textbook, b is the period, it looks like. you might want to read further - the text should introduce what b is.
It only shows examples of how to solve
Or the period 2pi|b|
Same thing on the internet the equation is 2pi/|b|
For period
then yeah, looks like your text is using b as the period.
I was trying to solve a question to prepare for my exams and I couldn’t since I didn’t know how to app,y the value of b which in my case equaled to 3pi into the function 1/b x
I put 1/3pi x
Basically f(x)sin(1/3pi x)
But Gemini said otherwise
It said sin(3pi x)
I'm not sure if I can continue answering this, but I would encourage you to show the question.
(and your working too.)
,rccw
I would easily solve this question in the form (bx) but 1/b x is confusing
Or did I do it correct
,rccw
okay, so what's your final answer?
F(x)=sin(1/3pi x)
you've correctly found b, and it is 3pi.
then no. it's sin(3pi x).
if you want to use sin((1/b) x), then your period is 2pi b, not 2pi / b.
I heard that somewhere
Could you explain further?
Please
Oh wait I think I got it basically when we use (bx) we use 2pi/b but when we use 1/b x we use 2pi b
Right?
the general rule is for $y = \sin(Bx)$, the period is always $\frac{2 \pi}{|B|}$.
go maximax or go home (Chiaki)
So basically this right?
now, if your B happens to be fractional, don't care - apply it in the period formula anyway.
I don't like splitting this into cases.
I'd much prefer applying this general rule.
but I guess yeah, that is what the cases look like.
No ty
!done then, if not. all the best!
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Hey can anyone help me with γ)? I feel like I'm doing something horribly wrong
for x>0 solve the equation xd
i am disgusted by how ugly it looks and im almost certain its wrong 🙏
Ln(e^2x-1)-ln(e^x) should be ln((e^2x-1)/e^x), not what you wrote
where is this 😭 im lost xd
oh
wtf was i thinking 🙏 thank you guys 100 times btw
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in any case, you would get a form of
$$[\ln(e^{2x} - 1) - 2x] - [\ln(e^x - 1) - x] = \ln(e^{2x} - 1) - x$$
notice that $\ln(e^{2x} - 1)$ and -x appear on both sides, so much faster, youd get $$\ln(e^x - 1) = 0$$
reze ♡
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I need help in 3rd question
,rccw
First of all I had my assumption that in parallelogram opp angles have only 1 same angle bisector .
But I got to know its wrong
have you tried drawing a figure?
But y and how is my assumption is wrong ?
?
I didn't look at your question, sorry. I just rotated your image for future helpers.
Oh k
<@&286206848099549185>
have you drawn a figure?
the hint is
that a triangle will be formed
with one angle 90 degree
then using vertical angle property you will find that one of the angles of the shape that is constructed by joining the angle bisectors is also 90 degree
Yes but I didn't understand logic
share the figure first of all
No triangle is formed
ok. do you see the figure in middle?
mark it's vertices
and then send the figure again
Its rectangle
yeah. mark it's edges. name then WXYZ
or smth
then send the figure again
But I have doubt before that
?
How is 2nd pic right nt 1st ?
Okay
Which question you currently on?
3
Than your figure is too wrong
Howwww
No rght one is
Rectangle is a parallelogram right ?
um. no i meant the left one where you wrote "how will rectangle come here". that abcd is more like a rectangle
yeah but ||gm is not a rectangle
It's my 2nd diagram ?
Ya did
Yeah
so. what's the doubt here?
After diagram how to solve ?
Wowwwww
S?
um. in degrees
180
then what's the sum of SAD and SDA
mind you the SAD and SDA are angle bisectors
that is half
90
let them answer
Yes
so? what's the sum of SDA and SAD?
Ohhh
90
now notice RSP is vertically opposite to ASD. so RSP = 90 as well. can you now find all the angles
of the figure in middle?
Yeashhh
So all angles is 90
which means?
Of rec
well. first of all your diagram should be correct. you were dropping angle bisectors of a rectangle, not a ||gm. after that you needed to prove that the figure in middle is a rectangle. for which you can either approach
- one of the angles is 90 degree
- Diagonals are equal in length
now. you can't really do much with diagonals here
it's quite evident
so you need to figure out a way to prove angles are 90
How 2nd ?
1 I got it . But how do ik I should do th3 step u did
wdym 2nd?
do you need to understand why diagonals make the figure rectangle?
2nd approach
Yes y ?
um equal diagonals make one of the interior angles 90, which prove that it is a rectangle
i am gonna go eat dinner
Rec interior angle or paragram interior angle?
rec
Ohk
i am here
of course
Indian ?
in questions without diagram
first try to make a diagram as neat as possible
ye
Ok
after the diagram
in this question you have to go through angles to prove
its a rectangle
Yes then
How would Ik that
the diagram?
I meant after diagram wt to doo after identifying to prove
what you alr know about the diagram
like what information you alr know
Opp angle were equal
you know angle a + d is 180
Adjacent angle equal to 180 that's it
Yes
But how am asking how will ik I should take thisss and modify it furtherrr
similarly angle CQB is 90
Yes
i also never knew this when i used to do this
How uk now ?
somethings you have to learn or discover by yourself
thats better
ye of course
but wait
did you got this
Wt
I got solution
wait
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this is legal right??
that's a log_2 btw
hmm
idk i am not really good with modulus
looks correct
sorry, what's what here?
Yes, if that's a log_2
log_2^-1
log_(2^-1)(x+1)
to be clear, since I can't read it, what you wrote is:\
$\log_{2^{-1}} (x+1) +1 < 0 \implies -\log_2(x+1)<-1$?
Annie Maqionde
At the bottom I mean
yes
Then that is correct afaik
okay perfect
that seems to be correct.
the thing is not over so bare with me for a sec
i invert the inequality right?
i wanna learn this thing first
youtube i guess
'invert' as in?
yeah
HELL YEAAAAAAAAHHHH
it's the first excercise i solve first try
i feel like god now
thanks
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Write in set builder form
$$A = {2,3,5,7,11,13}$$
should the answer be
$$A = {x \mid x \text{ is a prime number and } x < 14}$$
TheAstorPastor
or $$A = {x \mid x \text{ is a collection of prime number and } x < 14}$$
TheAstorPastor
TheAstorPastor
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
the first one
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<@&268886789983436800>
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ok in 1 min i will do it again when its 15 min
Oh sorry i didn't rwlaize you ahd already waited very very sorry
I thought this was a new thread
Wassup?
alr the image i sent I havnt done these problems in months and forgot how to do them
??
Why did you ping helpers at 12:01, then 4 minutes later?
Even if someone doesnt respond after 15 minutes only ping once please
because someone yelled at me for waiting 11 min instead of 15
so i pinged at 15 min
i was wondering if you can check my work
Bro.
,rccw
Couldn't find an attached image in the last 10 messages.
,rotate
Couldn't find an attached image in the last 10 messages.
i can resend the image
resend thepic
,rotate
You have the right idea!! You have your roots (although you should label them) And each root has an order of two, which means that the graph goes through those points in a parabolic fashion
wait so i was right about the line bouncing on the points because its squared?
Yes!!!
Of course. Because it's squared it's always positive
ok and how about describing these graphs what are the nessesary things to include?
And if it was say, an (x -1)^3, the graph would cross through the root like a cubic function
end behaviour, the x and y intercepts and the sign of the function i think
Your roots, and your y-intercept are usually enough to get a pretty good picture
That is also true
i already put end behavior and wym sign of the function?
I’d argue the “sign” is also a part of end behaviour
I wouldn’t list it as a separate thing
im confused on what this means
I would just recommend, label your freaking points. lol
um notice that everything in it is squared. so
(x+1)^2 >=0
and similarly, for all
so y>=0
@potent dirge is right here as well. it's kinda implied
yeah this works as well
What are you confused about?
i dont know what this "sign" means
they were talking about sign of function
also the y - is 0,100 right?
Yeah
and when putting the inequality for the x and y, for x would i put x is greater than or equal to - inf and les than or equal to inf?
Well, you can’t really be equal to positive, or negative infinity
so should i just say inf?
-♾️ < x < ♾️
ohhhhhh ok i get it now
Me personally, I prefer interval notation vs an inequality
x ∈ (-♾️, ♾️)
All good. This fancy e, “∈” just means, “is an element of”
So the statement, in English says, “x is an element from negative infinity to infinity”
ah ok
A round bracket means the value is not included in the interval. A square bracket means the number IS included in the interval
So, the “y” one would look like this
y ∈ [0, ♾️)
But, if your teacher taught you a specific form, use it. lol



