#help-27
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okay yeah, thats not the right way to do it
ye so basically why is that not the righ way?
This will count 2-2-0 with the same weight as 3-1-0
but as we saw above, when we put apples randomly into baskets, 3-1-0 is actually less likely to happen (there are 4 ways to make 3-1-0, 6 ways to make 2-2-0)
but doesnt it like account for it by saying there are 3! to get 3-1-0 and 3 combination to get 2-2-0, doesnt that give different weight?
This is like saying there is 1% chance for a coin to land on heads 99 times out of 99, because there are 100 different scenarious:
99 heads, 0 tails
98 heads, 1 tail
...
0 heads, 99 tails
well, you dont account for that in the unordered approach
oh wait but this is obviously not true
because each of the scenarios has a different chance of actually happening
if i wanted to make it even worse:
There are 2 possibilities,
99 heads, 0 tails
Less than 99 heads
So there is 1 favorable outcome / 2 total outcomes = 50%
this favorable outcomes / total outcomes only works if each outcome is equally likely to happen
oh I see, so I can only use the unordered approach if each otucome is equally likely, otherwise the ordered approach is the way to go>
hmm I see, I appreciate ur time and knowledge thanks for helping
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hey i have a doubt on what are cyclic intergrals
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so from experience with these question types, i am aware that i need to make 3 cases of 90 and 95 has but 99 does not OR 90 and 99 not 95 OR 95 and 99 not 90
however, i cannot wrap my head around HOW that is possible. how can a 90 and 95 CI have it but at the same time a 99 cannot
the explanation in my mind is that theyre not nested since they were computed from 3 different experiments with different computed means and variances
but it's still hard not to fall for the trap that theyre nested and so im getting confused
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Guys
sup
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Guys, how to use this bot...
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I'm not usually be here
... doesnt matter
just ask the question, nothing else okay
Mm, just reply to it?
I see
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Someone help
I can't for the life of me do these symmetry questions
Can do intergration but can't do basic shit 
what have you tried
like for these questions you just need to inspect lmao
Drawing lines
Like for rotational symmetry I can imagine them but not for these lines thing
try common symmetry lines like diagonal and vertical
I did that
But it's not symmetrical thru that
so it might be diagonal
who said it must be symmetrical at all
this reminds me of a parallelogram
which looks awfully symmetric but isnt
Idk im just really bad at imagination
if you cant figure it out go into a image editor and chop it up
then mess with the pieces
as a last resort
... ok here is a heuristic
if that shit looks like a rectangle but with decorations on opposite vertices like that it isnt symmetrical
okay so it has 0 lines of symmetry?
i was taught "axis of symmetry" but whatever
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<@&268886789983436800> ?
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hello
$$\int_0^{1/e}\frac{2x + 1}{x^3 - x^2 + x - 1} \dd x$$
blanketism
for legibility
looks like at this step, you dropped the + 1
this is correct but I don't know how to handle the primitive of x/x^2 + 1
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yes thank you
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How will I get evaluate the integral
Try x = 3 sinh(x) or cosh
No sorry I already did that
Then show
How do I put arcsinh 2 in to the integral
In cosh ^3 u
Also the integral is correct I checked the answer sheet
Use cosh^2 = 1 - sinh^2
What do u mean
.
You used the same identity in the integrand
What do I do with this can u be more clear
You have a cosh here
Use this to write it in terms of sinh
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can someone explain how the Integral function F is like that
shouldnt the exponent be ^3
do you know integration by parts?
no we didnt learn that
thats why we do this coefficiant comparing thing
Well the handy wavy reason is because integral of e^x = e^x
oh
right
yeah i can just memorize that i guess
Maybe just learn integration by parts, instead of this
I've never even heard of this coefficient comparing thing
is it learnable fast
or
After some exercises it's pretty simple to do
i got my finals next week
in its simplest form, yes. but it's a rigorous process the harder the questions get
true
learning the principle is quite easy
it's one formula and learning to use it
it becomes hard only when the questions become hard
id watch an organic chemistry tutor video on it to give it a try at least
ibp is foolproof and thats why we're recommending it
and frankly almost certainly more useful and principled
this is how it works
Im sorry e^2 x ?
do they mean e^x or e^(2x) or xe^2
Ahh okay
I'mma be real I'd say integration by parts is much simpler than this
ich spreche ein bisschen Deutsch
give it a try at least
would you say fractions are easy compared to this
or prime factorization or integars
Not sure what you mean, but If you have a question you can open your own help channel! :)
oh, it was just a silly joke.. and yes i have opened my own help channel, just waiting for someone..
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did i derive A correctly?
Ja
yk formansatz
theres no original
just the integrate function of a(x)
wait fuck i did something wrong
Ohh
yeah because that gives u a=0
since the degree three term "x^3" is still there after taking derivative
it might be wise to do ax^2 instead
so
but then if just do the same approach?
like the final step
how do i compare the coefficients
you only compare coefficients with same powers
u find out a=0 and you plug in a=0, then you note that A'(x), no matter b and c, will never equal to a(x)
also yeah that. Your derivation makes the crucial assumption that a,b,c are constant numbers. So you need the coefficient for e^x x^3, e^x x^2,... to match (this is because they are linearly independent over R, but saying this probably makes it confusing if you dunno lin alg)
ignoring this typo it seems to be correct
oh shit
yeah
also did i factorize correctly?
no need for factorizing in the end
note that ax^2+bx+c=dx^2+ex+f for all x, if and only if a=d,b=e,c=f
so using this its best to group them by degree on x
but no matter what method, you should try and find a,b,c.
yo i got
a = 1
b = 2
c = 5
seems right, you should double check by taking derivative tho
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hello
I'm struggling to solve this problem
graph f(x) = 1/(x+1) + arctan(x)
here's my work:
It's already a good start. Are you just struggling with putting all of those together in the graph?
For the asymptotes, just make sure you identity them. Either have them go through a tick-mark on the axes, or write their equation next to them (x=-1 for the VA, y=... for the HAs).
Identifying your axes would be good as well.
The graph is pretty much on point, except you could make it a little more apparent on the graph that (0,1) is a minimum.
oh okay alright
I do have another question
I’m required to find the values that f(x) can assume
are we supposed to this by looking at the graph?
or is there a different way to do this
Well looking at the graph certainly helps understanding what values you're expecting.
To have a more precise idea, you can check that, say, f is decreasing between -1 and 0 and increasing after, so using the limit you found you should be able to say what values this part of the function reaches.
Then you can argue similarly for the part in the third quadrant
@wispy warren Has your question been resolved?
thank you 😄
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hello so im trying to find out the integrate function but im confused on this one, like
IS it supposed to be E(x) = (ax^2 - c) e^1/3x
do we just leave the bx out?
(im doing the compare coefficient method)
Formansatz again?
yes
Formansatz should be ax²+bx+c a full quadratic polynomial, it might be that some coefficients end up 0 anyway
The important part is the order
hmm
yeah makes sense
ill just do that
yo but how do i know if its -bx or +bx
or does it not matter
it doesn't matter
The solutions will adjust to your choosing
For example if b was 7 then if you chose +bx, then simply 7x, but if you chose -bx then you'd get -7 so that -(-7)x=7x yields the same
@neon wagon Has your question been resolved?
yeah
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Am I able to solve this question without theta?
Or is there an assumption I can make to solve to the best of my abilities?
You absolutely need the angle
wow yellow swr looks so weird
Dang, this is my final. Is there really no possible way to solve it?
Well, thank you for ensuring me I'm not an idiot.
Was feeling real dumb not knowing how to do it
.close
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✅ Original question: #help-27 message
I've finished the test and I don't understand how this is the correct answer. How would i get -28475.023%?
That's the correct answer according to my class.
Also, here's the answer to the unsolvable question.
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how do i solve
mod(x) >= -x^2-6
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How would I start this problem?
you can split up the integral based on the intervals
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can someone explain how my friend got this answer or just how to solve the question
ur friend picked D when it is stated that b<2pi

oh well can u explain how to solve
bc i lowk fell asleep in class
u can kinda draw the graph using the graph of the function
its telling tou how long r is when theta grows
f(theta) returns the radius for angle theta
is there a pattern or something the petals should form bc how will i know if its in q3 or q4 if im just checking for a negative
well not negative but like on the graph
try drawing the function out and I think that will give u some intuition on when pedals form
😭
try graphing it out for theta from 0 to pi/2
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Could someone please help me with my practice test
what have you tried, and where are you stuck at?
I mean i have a formula sheet
i know 1 is L
and 2 is K
but i dont know the rest
3 is an identity about sine. maybe test the expression in 3 with some special values of x, like pi/4, pi/2, and pi.
acc nvm i have this formula sheet im allowed to use
ah, alright then.
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I'm in too much of a panic attack about not having studied for finals to focus on trying to figure out what they want from this question
@fickle rune Has your question been resolved?
<@&286206848099549185>
how can i help you
well so where are you stuck?
I just don't really know where to start with this question. What do I say? I think I did something with a similar problem earlier that had a similar conclusion, cos2x to cos2x, but I don't know what from it can help me here
I don't know how to approach this problem. I can never get a good enough understanding of anything to say how this Maclaurian series converges to f(x) just because it's less than n, or between 1 and 0
Like, it works for sin! somehow.
no, cos
Well, I guess it'd work for both
Is it involving some quirk of 1 or 0 over (n!) always results in R=(-infinity,infinity)?
Here is part of proof not sure if it is correct or not but to me it makes since i am not done yet
Hy this is the proof
i short some of the thing not in paper but if you confused refer to my writing lastly if you confused with something let me know
<@&268886789983436800> AI
Yeah I'm thinkin its more of a conceptual problem than something you solve for, and I've never heard squeeze theorem used in the context of any of this before
Well, if that last post was AI, how do I solve this?
and whoever was telling me to... I think find the radius? Deleted their comment. was it wrong or something?
The question is is it mathematically valid
if you have never seen something being used it does not mean it is wrong the real question is is it used correctly
It wont work if you use it
that individual mentioned radius of converges
Squeeze theorem seems to work. Also, if this is about proving that a Maclauren series works then I think there is a proof using differentiation
In this case since a=0 u centered at 0 and radius of convenges informs you about in a nutshell for what x from ranges from 0 either sides (depends on question) so it tells you where does the series converge not does it converge to f(x)
How?
Proof that it works not sure what you really meant by works on my side that is it converges to f(x)
Yes that's what I meant by work. It means that its a solution
So how do you differentiation to show it works
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I'm trying to prove that if a linear transformation f: U -> V has an inverse, then dim U = dim V. I have proved that dim U cannot be greater than dim V, and if so f cannot be one-to-one. I next plan to prove that if dim U < dim V, that f cannot be onto. However, can I not apply the criteria proven for injectivity to f^-1 to also prove that dim U cannot be less than dim V, or that invalid in some way?
if you prove there's a one one function from V to U you're done if you can use thsi
However, can I not apply the criteria proven for injectivity to f^-1 to also prove that dim U cannot be less than dim V,
Because this is what you'd essentially be doing right
@proud gull Has your question been resolved?
What I'm trying to solve is a problem in a book I'm following. I shouldn't use theorems outside of the book. I was more of asking if there was anything incorrect with it perhaps logic-wise.
hmmm ok.
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Did i differentiate this correctly?
d(what?)/dx
I gen dont know how to do differentiation when theres fractions but i quickly saw a vid and it was someting similar
dy/dx
oops soz if my handwringis bad
it is
d/dx (16/x) = -16/x^2 yes
but you wrote it poorly
y = 16/x
then you find dy/dx
not dy/dx (16/x)
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Does anyone know if I can get a call to ask questions? Like a tutor call?
?
Can I?
There are no public vcs on the server if that's what you are asking, you'd need to move into dms
read chartbit's message in #discussion
Honestly, I'd say most problems can be resolved via messages no problem
So I'd just give it a shot
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<@&268886789983436800>
@harsh stream Has your question been resolved?
@harsh stream Has your question been resolved?
@harsh stream Has your question been resolved?
<@&286206848099549185>
Hi
i would say post in an advanced channel if no helper replies in the next 30 mins
why did you say hi to him? 
Can u play Roblox pls
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
?????
Pls can u play Roblox
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
It will calm. Me down plssssssss
I've already warned you twice.
no off topic.
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
What channel should i post it in
Thank you
Is it ok if i just forward it into that
I dont wanna seem like im asking on diff channels for a help channel...
its fine you may close this
and post it there, or you may forward
either works
Ill leave it open
but since your thing is spread across three messages
Yea 😭
.close
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I've been given an assignment to prove lehmer's totient conjecture right using a system of given inequalities and equalities, by showing that they lead to a contradiction. I've tried 3 or 4 different ways, and none seem to work. I've found proof for the conjecture online, but it didn't use the system I was given. I'm beginning to feel like it isn't really possible to show a contradiction in the system, and maybe thats the conclusion our professor wants us to get to (?) idk I'm desperate
<@&268886789983436800>
<@&286206848099549185>
@distant ibex Has your question been resolved?
yeah, it is
the 'proof' you found is probably not valid (there are 'proofs' you can find of every open problem that has a name)
and the formatting of the question looks like ai slop honestly
Why would someone give you an open problem
Yeah I wouldn't be surprised if he used it lol
In mathematics, Lehmer's totient problem asks whether there is any composite number n such that Euler's totient function φ(n) divides n − 1. This is an unsolved problem.
It is known that φ(n) = n − 1 if and only if n is prime. So for every prime number n, we have φ(n) = n − 1 and thus in particular φ(n) divides n − 1. D. H. Lehmer ...
Ohh
Its kinda vague, I didn't get whether I needed to do both things
Bryh
bruh lol
or just one of them
no way you're supposed to prove it
oh wait hold on
@versed juniper ur frog farm
don't bother mommy for this
no frogs were harmed
i was going to suggest maybe you are supposed to show the 'system' does lead to a contradiction but that doesn't actually prove the conjecture because the issue is in the system itself
but i don't know
that technically is what we're supposed to do
just show that it leads to a contradiction
can't seem to do that tho
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Man the bots are out in force recently
agree
Cant we just like ban these mrbeast images or is there no feature to scan images and ban them?
code one up to read image matadata 
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i dont get the argument for A+C>0. can someone explain it to me
this higher dimension stuff is really confusing D:
I think the second image is the solution to the question posed in the first.
oh i see mb
huh
the user above you thought you asked two questions in the same channel.
oh
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Part c
Maybe it would be helpful to also add a coordinate system to the sketch
It could help for visualization
Like a scale for x, y axes?
Like the origin O(0,0) and the x and y axes
Ok but we can solve it without
Ok look
DE and DC are both tangents from D
Right
Can I say the left and right side of the kite or symmetrical, because D lies exactly above the center B, meaning that the horizontal distance from B to C is same as from B to E
Yes
Yes this is correct
And E and C lie on the same y coordinate because DB (a vertical line) and EC are perpendicular, meaning EC is a horizontal line
Because EBCD is a kite
Yes
Ty
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How do you do these question tho
brain
Like don't give me the answer 
well i thought you could deduce that observation yourself
can you produce logic for why it would be true
Idk I've never learnt these questions
the hcf is 28 so we know 28 is a factor of both numbers
nothing stops you from using 28 as one of the numbers
28 would be the smallest number
that has a factor of 28
Yeah
ok
so then we need another number such that the lcm of it and 28 is a multiple of 35
how do you find the lcm of two numbers
You take the highest power primes and multiply them together
Multiple of 35, it doesn't say 35
oh my bad misread what angel said
Hm ok so then let's try to represent what we want to find
a multiple of 35 means the lcm is something like 5 * 7 * x
we know 28 is 4 * 7
so we have the 7 already
we need to get a 5 in there in order to have a multiple of 35
so you do exactly that
28 * 5 = 140
and it happens that the x we had earlier for the lcm is 4, from the 28
the lowest common multiple of 140 and 28 is 140
well, if the gcf is 28, both must be a multiple of 28 but not 56
when you're lacking ideas, you can always write stuff for simplification
like if gcd(x, y) = 28, you have 28gcd(a, b) = 28 by dividing x and y by 28, and gcd(a, b) = 1
choosing a minimum pair (x, y) is choosing a minimum pair (a, b)
since their lcm has a 5, exactly one of them has to be divisible by 5, and without other conditions the smallest pair that works is (1, 5), giving (28, 140)
kinda more obvious if you factor out the gcd sometimes
the other way around works too, if gcd = 28, it divides lcm = 35k, so 4 divides k and lcm = 140k'
and the smallest pair you can take is (28, 140) for a lcm of 140
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what's 1+1 guys?
please don’t troll in the help channels 
if you have a real question, please ask it!!
otherwise, you can close the channel 
okay thanks
what is the average mass of an instertaller Black Hole or What is the size of an black hole that has the same mass as our sun
those are 2 different questions
i think its between 2 and 150 times of the sun
for the latter use schwarzchild radius
the for the former.. what do you mean by average exactly?
yeah lmao
you cant average one single number
this is probably a troll question
well yeah
like he was trying to go super easy then super hard
i think he just
thought of the most difficult question he could think of
what
$R_s=\frac{2GM}{c^2}$ is thes schwarzschild radius which is the radius corresponding to the event horizon, so you can just plug in the numbers to find it
lyric
ppl in this server are deadass talented enough to calculate that. be careful what you say 😭
...
im just asking random questions im just curious about science/math
you did not need to confess that but alr
but genuinely, the radius of a black hole is something you are able to calculate easily
its a fascinating result with how simple it is
if you have the measurements yeah
yes
how would you measure it though
measure what?
wrong send
how is gaining knowledge about the masses and sizes of black holes going to enlighten you in any way
the diameter or radius of black hole
if you're asking how you would observe the radius of a black hole experimentally, i believe physicists measure the degree of gravitational lensing using objects behind it to find the mass
since the curvature of spacetime is dependant on the mass of a body
yeah. but it could still be unfathomably incorrect
what makes you think that?
special relativity has been a heavily researched area since einstein postulated it
nah y'all are to Good at math :/
well, because we can only estimate, and not know the true value
is being good at math can get u better in playing chess?
well true, theres always experimental error
Oh okay thanks man
and since theres rarely been in any records of us calculating the radius, our technologies are way too unadvanced and wrong
is Reading and asking ur self , better than reading before going to go to bed?
ask chatgpt like u did earlier
I didn't ask chatgpt i only use Chatgpt for school purposes
😄
and sometimes just read books
no, theres 0 correlation between those 2 activities
shouldnt this be considered academic
Okay? well im bad at english and math sorry
the one thing you shouldnt use it for
not true! a black hole isnt something you can look at with a telescope and measure how wide it is
🤦
exactly!
but there are exact ways of finding its radius
yeah exactly!
primarily classified and measured by their mass ?
mass distorts light in a specific and predictable way thanks to the einstein field equations
whatdatmean can you help me with my question
and the schwarzschild is a direct result of those equations
<@&268886789983436800>
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yoo
mb
.close
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Guys is it possible for us Humans to create an Blackhole with the mass of 0.0001% solar mass
1 not with current technology
2 not the place for ts
3 <@&268886789983436800>
troilling
I don't think they are trolling.
bro im not trolling im asking 😭
well explain this then.
Hes trolling dawg
?
get jit outta here
How is that indicative of trolling?
bro came in n asked 1+1
asking obviously random questions in an absolutely inappropriate place
and not following conduct
for the 2nd time
But we do get good faith questions on topics adjacent to math.
"This isn't math" =/= "trolling"
i find this absolutely unrelated amd sounded like a 10 year old tryna sound smart
im 14 gng
Anyway, rather than accusing people with pings why not redirect them. You realize we have #old-network right?
ig
The physics server in the network channel is more appropriate
for your physics question
Ain't that heavier than earth
gng
"Facebook +1"
This really is probably too far outside the scope of math for anybody to be particularly helpful here beyond what you'd get asking some rando on the street.
Also kinda general and not really a math "help" q. I'm gonna close this. Probably physics server is the best option. One of the general discussion channels might also be reasonable.
.close
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can someone pls help
I got the the simplifying point
1/(121sec^2theta)
I took the 121 out so
out of the integral
so its just 1/sec^2
<@&268886789983436800>
okay
you could take the x^2 out and it would become x^3 then you can let in terms inside the bracket be t and you have the derivative outside
Do i convert that to cos^2
what x^2
inside the bracket, in the denominator
Or if you are using trigonometry, then you can let t=121tan(thete)
if you find it hard, think it this way, its $\int \frac{dx}{(a^{2} + x^{2})^\frac{3}{2}}$
Ankur
okay
yes
now you have to change x with a trigonometric function which can work like 1+ (fx)^2
yes
ok and what did you get?
121sec^2x
yes
so what is denom now?
or to keep it simple, (11secx)^3
i solved... wait a sec
here
and do 1/secx =cosx
right
cool
yes yes.. its a good question it took me 3 times😭 im not good at trigonometry formulas
me neither 😭
ur good
ima close this
ty all for ur help
i appreciate it
.close
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hi so can someone help me with my ledging or something its buisness studies ans pretty simple but im not grasping it and i dont think i did this right
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Yo bot
?
do you have a math question to ask for help about?
ok, label layla's current age x and miya's current age y
what does the first sentence tell us about x and y? can you relate them?
That x is equal to y four years ago
how would you express that with just an algebraic equation
X = y - 4
i don't think so
if layla is one years old, miya was one years old four years ago, so that must mean she's five now
so x=y-4
Here's what I understand on the second sentence
X +11 = y 1/2
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No
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for a, im pretty sure its a trapezoid but i dont know how to prove that ab || pq, can someone please help 🙏
the first part of the problem* not a
idk about a formal proof but you can use the fact that AQ and BP are each perpendicular to PQ
(tangents are perpendicular to radii)
oh wait yeah forgot about that property, thanks! i'll try and use that
yeah
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i give up fighting with gemini bro hallucinating sack of shit cant listen to simple ionstructions
y is iii wrong (trying to all possiblities - even + lesst han 7000)
i got it right once by taking cases like 7/8/9 _ _ _ 2/8
but im trunna do it another way
Cus some guy on reddit told me a good way to get good at permutations and combinations is to do as many quesitons as possible and do them in as many ways as possible
YO
HOW DO YOU SPAWN WHENEVER THERES A PERMUTATION AND COMBINATION QUESTION BRO
every single time wihtout fail
i do not see much value in looking for a more complicated solution to this when there is a simple solution but whatever. you want to count how many are less than 7000 or even?
yea
your message is a little hard for me to parse
with run on sentences and poor notation
uhh
are you trying to do 3?
let me type it out properly then i guess
okay well you wanna think about the most forcing parts of the combinatorics
so if the number is greater than 7k, you can actually make cases on what the first digit can be
i believe he said he has already done that and gotten the right answer doing that
im trying to do iii
my previous attempt was breaking it up into cases like this -> 7/8/9 _ _ _ 2/8 from which i got the correct answer
but im trying to do it like all possibilities - even + less than 7000
because some guy on reddit told me that a good way to uh get comfortable with permutations and combinations is to alot of questions and do them in a bunch of ways
more legible yes ^^ ?
2 or 8 as last digit?
yeah
it says odd
oh
i just
roughly wrote that from the top of my head without much thought lol
because i did that yesterday
but i did get it right
so are you trying to complement count (sample space - unwanted events)?
well if you want to do it the other way… you would want
total arrangements - (arrangements that are even or less than 7000)
yea
are you sure you worked with that correctly?
there would be some inclusion exclusion involved
total arrangements is 5P4
even is 2*4P3
odd is _ _ _ 2/3
2*4P3 also
so 5P4 - 4*4P3
damn discord markdown
found my working
yea i did
that.. doesn’t look like a solution of this type
a solution of the complementary counting variety
like that is roughly how i would do the problem but i thought you wanted a complementary counting solution now
also hi annie 
noo
this was when i got it correct
yesterday
oh
i thought
u were referring to like whether or not i got it correct uh the first time i did it
mb
lol no i was talking about complementary counting but that’s ok
do you understand this?
yea i think so
is uhh
is that not what i did here
no i don’t see a solution there. what about the 7000 part for example?
wdym 7000 part?
oh
wait
nvm
that’s a condition in the problem that needs to be considered but i don’t see it mentioned anywhere in your solution
uhhh wut is a 7000 part....
we are trying to count the arrangements that are less than 7000 or even
the less than 7000 condition should show up somewhere in your solution
but it did not. that’s all i was saying
so if a solution was less than 7000
the first digit would be 2 or 3 then whatever for the next 3 digits
so 2/3 _ _ _
isnt that 2*4P3
yea
yea and uh
even is another
unwanted case
so
the last digit is either 2 or 8
isnt that also 2*4P3
yea
arent those the only trwo unwanted cases i gotta cosnider
sure. but that was not expressed very well here. it still doesn’t even make sense after your recent messages
and still you are forgetting about something
which is that you have counted some arrangements twice
namely the ones that are even and less than 7000
my working was
all possibilities = 5P4
even = 2*4P3
7000 = 2*4P3
all - even + >7000 = 5P4 - 4P3
i know and that is wrong
because
wait
2/3 _ _ _
like 2__8 could be a value here but
in my other case where i count all the numbers less than 7k 2__8 is also a possibility
so is it all - (less than 7k + even - less than 7k and even)
holy cRAO
(trivia: this is called the principle of inclusion-exclusion.)
princple of frying my brain gangggggg
lol
let me write out the solution
principle of be happy with a simple solution
principle of agreement
should i keep doing this
trying to do all the problems in different wayes
or just be happy with the first simple solution
i would be happy with the first simple solution and go do other problems
but sure, you are allowed to look for complicated solutions too
if that’s what you want to do then go for it
it’s not that looking for other solutions is bad
that’s a good thing
it’s just that like
complementary counting on ts problem is complicating it for no reason
2/3 _ _ 2/8
2 __ 8 4P2
3 __ 2/8 2*4P2
MAN
this markDOWN
so 3*4P2
are the cases whjere its less than 7lk and even
and then uh
5P4-4P3-3*4P2
tis 84
exatcly doubble the answer
i learnt dis da hard way

are you sure you used this correctly?
lol


