#help-27

1 messages · Page 435 of 1

bold dock
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ye

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apples are identical

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so without order

polar chasm
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okay yeah, thats not the right way to do it

bold dock
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ye so basically why is that not the righ way?

polar chasm
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This will count 2-2-0 with the same weight as 3-1-0

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but as we saw above, when we put apples randomly into baskets, 3-1-0 is actually less likely to happen (there are 4 ways to make 3-1-0, 6 ways to make 2-2-0)

bold dock
polar chasm
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This is like saying there is 1% chance for a coin to land on heads 99 times out of 99, because there are 100 different scenarious:
99 heads, 0 tails
98 heads, 1 tail
...
0 heads, 99 tails

polar chasm
bold dock
polar chasm
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because each of the scenarios has a different chance of actually happening

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if i wanted to make it even worse:
There are 2 possibilities,
99 heads, 0 tails
Less than 99 heads

So there is 1 favorable outcome / 2 total outcomes = 50%

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this favorable outcomes / total outcomes only works if each outcome is equally likely to happen

bold dock
polar chasm
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yeah

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you need to ensure that your outcomes are all equally likely

bold dock
polar chasm
#

np

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<@&268886789983436800>

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ornate crane
#

hey i have a doubt on what are cyclic intergrals

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primal ferry
#

so from experience with these question types, i am aware that i need to make 3 cases of 90 and 95 has but 99 does not OR 90 and 99 not 95 OR 95 and 99 not 90

however, i cannot wrap my head around HOW that is possible. how can a 90 and 95 CI have it but at the same time a 99 cannot

primal ferry
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the explanation in my mind is that theyre not nested since they were computed from 3 different experiments with different computed means and variances

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but it's still hard not to fall for the trap that theyre nested and so im getting confused

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vernal stump
#

Guys

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vital sedge
#

sup

hasty cargo
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# vernal stump Guys

Asking the actual question right away is more likely to get responses.

Asking "Can I ask...?" or "Does anyone know about...?" doesn't give people enough information to decide whether they can help, and answering can feel like a promise to help with the actual question, which they might find themselves unable to.

vernal stump
#

!da2a

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Asking the actual question right away is more likely to get responses.

Asking "Can I ask...?" or "Does anyone know about...?" doesn't give people enough information to decide whether they can help, and answering can feel like a promise to help with the actual question, which they might find themselves unable to.

#

Asking the actual question right away is more likely to get responses.

Asking "Can I ask...?" or "Does anyone know about...?" doesn't give people enough information to decide whether they can help, and answering can feel like a promise to help with the actual question, which they might find themselves unable to.

hasty cargo
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...

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it isnt used like that

vernal stump
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Guys, how to use this bot...

ebon coyote
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(No, YOU don't need to type da2a every time, that's just to get the bot to display that message)

vernal stump
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I'm not usually be here

hasty cargo
#

... doesnt matter

hasty cargo
vernal stump
#

Mm, just reply to it?

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jaunty moat
#

Someone help

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jaunty moat
#

I can't for the life of me do these symmetry questions

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Can do intergration but can't do basic shit son

hasty cargo
#

like for these questions you just need to inspect lmao

jaunty moat
#

Like for rotational symmetry I can imagine them but not for these lines thing

hasty cargo
jaunty moat
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But it's not symmetrical thru that

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so it might be diagonal

hasty cargo
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who said it must be symmetrical at all

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this reminds me of a parallelogram

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which looks awfully symmetric but isnt

jaunty moat
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Idk im just really bad at imagination

hasty cargo
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then mess with the pieces

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as a last resort

lunar harbor
jaunty moat
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lol

hasty cargo
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if that shit looks like a rectangle but with decorations on opposite vertices like that it isnt symmetrical

jaunty moat
hasty cargo
#

i was taught "axis of symmetry" but whatever

jaunty moat
#

alr ty ty

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vital edge
#

<@&268886789983436800> ?

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wispy warren
#

hello

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wispy warren
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I'm stuck

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wait

dim perch
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$$\int_0^{1/e}\frac{2x + 1}{x^3 - x^2 + x - 1} \dd x$$

woven radishBOT
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blanketism

dim perch
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for legibility

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looks like at this step, you dropped the + 1

wispy warren
#

oh

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okay one second

wispy warren
# wispy warren

this is correct but I don't know how to handle the primitive of x/x^2 + 1

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wispy warren
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yes thank you

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upper geode
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upper geode
#

How will I get evaluate the integral

supple knot
#

Try x = 3 sinh(x) or cosh

upper geode
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No sorry I already did that

supple knot
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Then show

upper geode
upper geode
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In cosh ^3 u

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Also the integral is correct I checked the answer sheet

supple knot
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Use cosh^2 = 1 - sinh^2

upper geode
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What do u mean

supple knot
supple knot
upper geode
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What do I do with this can u be more clear

supple knot
supple knot
upper geode
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So (1-sinh^2u) ^3/2

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Equals (cosh u)^3

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Ok I so get it thanks

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neon wagon
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neon wagon
#

can someone explain how the Integral function F is like that

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shouldnt the exponent be ^3

vital sedge
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do you know integration by parts?

neon wagon
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thats why we do this coefficiant comparing thing

vital sedge
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Well the handy wavy reason is because integral of e^x = e^x

neon wagon
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right

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yeah i can just memorize that i guess

vital sedge
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Maybe just learn integration by parts, instead of this

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I've never even heard of this coefficient comparing thing

neon wagon
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or

vital sedge
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After some exercises it's pretty simple to do

neon wagon
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i got my finals next week

primal ferry
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in its simplest form, yes. but it's a rigorous process the harder the questions get

primal ferry
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learning the principle is quite easy

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it's one formula and learning to use it

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it becomes hard only when the questions become hard

neon wagon
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i think ill just stick to this comparison thing

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i learned it

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muscle memory

primal ferry
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id watch an organic chemistry tutor video on it to give it a try at least

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ibp is foolproof and thats why we're recommending it

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and frankly almost certainly more useful and principled

neon wagon
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this is how it works

vital sedge
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Im sorry e^2 x ?

neon wagon
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my bad

vital sedge
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do they mean e^x or e^(2x) or xe^2

neon wagon
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poor translation

vital sedge
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Ahh okay

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I'mma be real I'd say integration by parts is much simpler than this

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ich spreche ein bisschen Deutsch

primal ferry
#

give it a try at least

ionic chasm
vital sedge
ionic chasm
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neon wagon
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neon wagon
#

did i derive A correctly?

faint gorge
#

Ja

neon wagon
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okay

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ty

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so now i could say 3 must be 3x^3 +3ax^2

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?

faint gorge
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what

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What are you even supposed to do with A'(x), can you post the original

neon wagon
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theres no original

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just the integrate function of a(x)

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wait fuck i did something wrong

faint gorge
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Ohh

neon wagon
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i wrote ax^3 in the A(x)

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i think thats wrong

near jolt
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since the degree three term "x^3" is still there after taking derivative

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it might be wise to do ax^2 instead

neon wagon
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but then if just do the same approach?

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like the final step

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how do i compare the coefficients

faint gorge
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you only compare coefficients with same powers

near jolt
neon wagon
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tf

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wait let me redo this rq

near jolt
# faint gorge you only compare coefficients with same powers

also yeah that. Your derivation makes the crucial assumption that a,b,c are constant numbers. So you need the coefficient for e^x x^3, e^x x^2,... to match (this is because they are linearly independent over R, but saying this probably makes it confusing if you dunno lin alg)

neon wagon
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so this should be correct right?

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or

near jolt
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where did your e^3x go

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it escaped the matrix after the second line

near jolt
neon wagon
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yeah

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also did i factorize correctly?

near jolt
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no need for factorizing in the end

neon wagon
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oh

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ive seen people do that tho

near jolt
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note that ax^2+bx+c=dx^2+ex+f for all x, if and only if a=d,b=e,c=f

near jolt
#

but no matter what method, you should try and find a,b,c.

neon wagon
#

yo i got

neon wagon
near jolt
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wispy warren
#

hello

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wispy warren
#

I'm struggling to solve this problem

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graph f(x) = 1/(x+1) + arctan(x)

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here's my work:

trail eagle
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It's already a good start. Are you just struggling with putting all of those together in the graph?

wispy warren
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yes

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drawing out the graph

trail eagle
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For the asymptotes, just make sure you identity them. Either have them go through a tick-mark on the axes, or write their equation next to them (x=-1 for the VA, y=... for the HAs).

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Identifying your axes would be good as well.

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The graph is pretty much on point, except you could make it a little more apparent on the graph that (0,1) is a minimum.

wispy warren
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oh okay alright

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I do have another question

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I’m required to find the values that f(x) can assume

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are we supposed to this by looking at the graph?

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or is there a different way to do this

trail eagle
#

Well looking at the graph certainly helps understanding what values you're expecting.
To have a more precise idea, you can check that, say, f is decreasing between -1 and 0 and increasing after, so using the limit you found you should be able to say what values this part of the function reaches.

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Then you can argue similarly for the part in the third quadrant

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wispy warren
#

thank you 😄

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neon wagon
#

hello so im trying to find out the integrate function but im confused on this one, like

neon wagon
#

IS it supposed to be E(x) = (ax^2 - c) e^1/3x

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do we just leave the bx out?

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(im doing the compare coefficient method)

neon wagon
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yes

faint gorge
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Formansatz should be ax²+bx+c a full quadratic polynomial, it might be that some coefficients end up 0 anyway

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The important part is the order

neon wagon
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yeah makes sense

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ill just do that

neon wagon
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or does it not matter

faint gorge
#

it doesn't matter

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The solutions will adjust to your choosing

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For example if b was 7 then if you chose +bx, then simply 7x, but if you chose -bx then you'd get -7 so that -(-7)x=7x yields the same

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hasty rune
#

Am I able to solve this question without theta?

hasty rune
#

Or is there an assumption I can make to solve to the best of my abilities?

lusty sapphire
#

You absolutely need the angle

neon folio
#

wow yellow swr looks so weird

hasty rune
#

Dang, this is my final. Is there really no possible way to solve it?

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Well, thank you for ensuring me I'm not an idiot.

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Was feeling real dumb not knowing how to do it

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.close

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hasty rune
#

.reopen

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hasty rune
#

I've finished the test and I don't understand how this is the correct answer. How would i get -28475.023%?

#

That's the correct answer according to my class.

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Also, here's the answer to the unsolvable question.

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frozen solar
#

how do i solve

mod(x) >= -x^2-6

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frozen solar
#

oh wait nvm i confused mod and gif

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mb gng

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.close

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barren fable
#

<@&268886789983436800>

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glass maple
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glass maple
#

How would I start this problem?

untold ravine
#

you can split up the integral based on the intervals

glass maple
#

i got 10

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civic tangle
#

can someone explain how my friend got this answer or just how to solve the question

near jolt
civic tangle
#

bc i lowk fell asleep in class

near jolt
#

its telling tou how long r is when theta grows

#

f(theta) returns the radius for angle theta

civic tangle
#

well not negative but like on the graph

near jolt
civic tangle
#

😭

near jolt
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digital hatch
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digital hatch
#

Could someone please help me with my practice test

solid perch
#

what have you tried, and where are you stuck at?

digital hatch
#

I mean i have a formula sheet

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i know 1 is L

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and 2 is K

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but i dont know the rest

solid perch
#

3 is an identity about sine. maybe test the expression in 3 with some special values of x, like pi/4, pi/2, and pi.

digital hatch
#

acc nvm i have this formula sheet im allowed to use

solid perch
#

ah, alright then.

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fickle rune
#

I'm in too much of a panic attack about not having studied for finals to focus on trying to figure out what they want from this question

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#

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fickle rune
#

<@&286206848099549185>

twilit falcon
gloomy aurora
#

well so where are you stuck?

fickle rune
#

I just don't really know where to start with this question. What do I say? I think I did something with a similar problem earlier that had a similar conclusion, cos2x to cos2x, but I don't know what from it can help me here

fickle rune
fickle rune
# gloomy aurora well so where are you stuck?

I don't know how to approach this problem. I can never get a good enough understanding of anything to say how this Maclaurian series converges to f(x) just because it's less than n, or between 1 and 0

#

Like, it works for sin! somehow.

#

no, cos

#

Well, I guess it'd work for both

#

Is it involving some quirk of 1 or 0 over (n!) always results in R=(-infinity,infinity)?

twilit falcon
#

Here is part of proof not sure if it is correct or not but to me it makes since i am not done yet

#

Hy this is the proof

#

i short some of the thing not in paper but if you confused refer to my writing lastly if you confused with something let me know

lunar harbor
#

<@&268886789983436800> AI

fickle rune
#

Yeah I'm thinkin its more of a conceptual problem than something you solve for, and I've never heard squeeze theorem used in the context of any of this before

#

Well, if that last post was AI, how do I solve this?

#

and whoever was telling me to... I think find the radius? Deleted their comment. was it wrong or something?

twilit falcon
#

if you have never seen something being used it does not mean it is wrong the real question is is it used correctly

twilit falcon
#

that individual mentioned radius of converges

spiral raptor
#

Squeeze theorem seems to work. Also, if this is about proving that a Maclauren series works then I think there is a proof using differentiation

twilit falcon
#

In this case since a=0 u centered at 0 and radius of convenges informs you about in a nutshell for what x from ranges from 0 either sides (depends on question) so it tells you where does the series converge not does it converge to f(x)

spiral raptor
#

How what? Like the proof of a maclauren series?

#

Its a standard proof

twilit falcon
spiral raptor
#

Yes that's what I meant by work. It means that its a solution

twilit falcon
#

So how do you differentiation to show it works

spiral raptor
devout snowBOT
#

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fickle rune
#

I don't know. I think I'll just try to solve it myself.

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proud gull
#

I'm trying to prove that if a linear transformation f: U -> V has an inverse, then dim U = dim V. I have proved that dim U cannot be greater than dim V, and if so f cannot be one-to-one. I next plan to prove that if dim U < dim V, that f cannot be onto. However, can I not apply the criteria proven for injectivity to f^-1 to also prove that dim U cannot be less than dim V, or that invalid in some way?

lost laurel
#

However, can I not apply the criteria proven for injectivity to f^-1 to also prove that dim U cannot be less than dim V,
Because this is what you'd essentially be doing right

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lament cradle
devout snowBOT
lament cradle
#

Did i differentiate this correctly?

runic prawn
#

d(what?)/dx

lament cradle
#

I gen dont know how to do differentiation when theres fractions but i quickly saw a vid and it was someting similar

#

dy/dx

#

oops soz if my handwringis bad

runic prawn
#

it is

lament cradle
#

O

#

So its right?

runic prawn
#

d/dx (16/x) = -16/x^2 yes

#

but you wrote it poorly

#

y = 16/x

#

then you find dy/dx

#

not dy/dx (16/x)

lament cradle
#

okkok

#

Thank u

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vague gyro
#

Does anyone know if I can get a call to ask questions? Like a tutor call?

vague gyro
#

Can I?

sonic smelt
#

There are no public vcs on the server if that's what you are asking, you'd need to move into dms

sturdy fiber
willow helm
#

So I'd just give it a shot

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harsh stream
#

<@&268886789983436800>

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@harsh stream Has your question been resolved?

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@harsh stream Has your question been resolved?

harsh stream
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<@&286206848099549185>

rose trellis
#

Hi

gloomy aurora
#

i would say post in an advanced channel if no helper replies in the next 30 mins

hasty cargo
rose trellis
#

I want a talk

#

I’m having a panick attak pls

rose trellis
gloomy aurora
devout snowBOT
hasty cargo
rose trellis
#

Pls can u play Roblox

gloomy aurora
#

!redir

devout snowBOT
#

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

rose trellis
#

It will calm. Me down plssssssss

gloomy aurora
#

I've already warned you twice.

hasty cargo
rain summit
devout snowBOT
rose trellis
#

HELLP

#

PLS

#

PLS

#

PLS

#

OKS

#

PLS I SONT USETSYNF IM

harsh stream
harsh stream
harsh stream
#

I dont wanna seem like im asking on diff channels for a help channel...

gloomy aurora
#

and post it there, or you may forward

#

either works

harsh stream
#

Ill leave it open

gloomy aurora
#

but since your thing is spread across three messages

harsh stream
#

Yea 😭

gloomy aurora
#

better to type it out

#

instead of forwarding

harsh stream
#

.close

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distant ibex
#

I've been given an assignment to prove lehmer's totient conjecture right using a system of given inequalities and equalities, by showing that they lead to a contradiction. I've tried 3 or 4 different ways, and none seem to work. I've found proof for the conjecture online, but it didn't use the system I was given. I'm beginning to feel like it isn't really possible to show a contradiction in the system, and maybe thats the conclusion our professor wants us to get to (?) idk I'm desperate

sacred sedge
#

<@&268886789983436800>

distant ibex
#

<@&286206848099549185>

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#

@distant ibex Has your question been resolved?

uncut crow
#

ts problem is open last i knew

#

who wrote this ducky_skull

distant ibex
#

my discrete math prof :D

#

or the TA

uncut crow
#

lol

#

i'm like 99% sure it's an open problem

distant ibex
#

yeah, it is

uncut crow
#

the 'proof' you found is probably not valid (there are 'proofs' you can find of every open problem that has a name)

#

and the formatting of the question looks like ai slop honestly

faint gorge
#

Why would someone give you an open problem

distant ibex
uncut crow
#

In mathematics, Lehmer's totient problem asks whether there is any composite number n such that Euler's totient function φ(n) divides n − 1. This is an unsolved problem.
It is known that φ(n) = n − 1 if and only if n is prime. So for every prime number n, we have φ(n) = n − 1 and thus in particular φ(n) divides n − 1. D. H. Lehmer ...

distant ibex
#

thats the whole page

#

I already found the error in the LLM's solution

faint gorge
#

Ohh

distant ibex
#

Its kinda vague, I didn't get whether I needed to do both things

faint gorge
#

Bryh

uncut crow
#

bruh lol

distant ibex
#

or just one of them

uncut crow
#

no way you're supposed to prove it

distant ibex
#

alrighty then, thanks :)

uncut crow
#

oh wait hold on

faint gorge
uncut crow
versed juniper
uncut crow
# uncut crow oh wait hold on

i was going to suggest maybe you are supposed to show the 'system' does lead to a contradiction but that doesn't actually prove the conjecture because the issue is in the system itself

#

but i don't know

distant ibex
#

just show that it leads to a contradiction

#

can't seem to do that tho

chrome salmon
#

shit

#

wrong channel

#

my apologies

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#

Please don't occupy multiple help channels.

crude niche
#

<@&268886789983436800>

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vital edge
#

Man the bots are out in force recently

tall linden
#

agree

hasty cargo
vital edge
#

I don't believe there is, no

#

Not a reliable one at least

hard shoal
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solid osprey
devout snowBOT
solid osprey
#

i dont get the argument for A+C>0. can someone explain it to me

#

this higher dimension stuff is really confusing D:

gloomy aurora
solid perch
#

I think the second image is the solution to the question posed in the first.

hollow vine
#

oh i see mb

solid perch
solid osprey
#

oh

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#

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swift badge
devout snowBOT
swift badge
#

how is dx = 3cosudu

#

oh

#

nvm..

#

.close

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barren dune
#

Part c

devout snowBOT
barren dune
#

How do I find the coordinates of E

#

I know why my method was wrong

neon folio
#

Maybe it would be helpful to also add a coordinate system to the sketch

#

It could help for visualization

barren dune
neon folio
#

Like the origin O(0,0) and the x and y axes

#

Ok but we can solve it without

#

Ok look

#

DE and DC are both tangents from D

#

Right

barren dune
# barren dune

Can I say the left and right side of the kite or symmetrical, because D lies exactly above the center B, meaning that the horizontal distance from B to C is same as from B to E

barren dune
barren dune
neon folio
#

Yes

barren dune
neon folio
#

Np

#

!done

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#

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jaunty moat
devout snowBOT
versed juniper
#

probably going to be 28 and some other number

#

right?

jaunty moat
versed juniper
#

brain

jaunty moat
#

Like don't give me the answer son

jaunty moat
#

WOW

#

I didn't know

#

I needed a brain

versed juniper
#

well i thought you could deduce that observation yourself

#

can you produce logic for why it would be true

jaunty moat
versed juniper
#

ok

#

well you know what hcf and lcm is right

jaunty moat
#

Yeah

#

HCF you times the common and lowest power prime factors

#

and so on

versed juniper
#

the hcf is 28 so we know 28 is a factor of both numbers

versed juniper
#

nothing stops you from using 28 as one of the numbers

#

28 would be the smallest number

#

that has a factor of 28

jaunty moat
#

Yeah

versed juniper
#

ok

#

so then we need another number such that the lcm of it and 28 is a multiple of 35

#

how do you find the lcm of two numbers

jaunty moat
#

Multiple of 35, it doesn't say 35

dapper tiger
#

oh my bad misread what angel said

versed juniper
#

a multiple of 35 means the lcm is something like 5 * 7 * x

#

we know 28 is 4 * 7

#

so we have the 7 already

#

we need to get a 5 in there in order to have a multiple of 35

#

so you do exactly that

#

28 * 5 = 140
and it happens that the x we had earlier for the lcm is 4, from the 28

#

the lowest common multiple of 140 and 28 is 140

jaunty moat
#

Ohhhhh

#

I'm so dumb

#

Okay tyty

celest gyro
#

well, if the gcf is 28, both must be a multiple of 28 but not 56

dapper tiger
#

when you're lacking ideas, you can always write stuff for simplification
like if gcd(x, y) = 28, you have 28gcd(a, b) = 28 by dividing x and y by 28, and gcd(a, b) = 1
choosing a minimum pair (x, y) is choosing a minimum pair (a, b)
since their lcm has a 5, exactly one of them has to be divisible by 5, and without other conditions the smallest pair that works is (1, 5), giving (28, 140)

#

kinda more obvious if you factor out the gcd sometimes

#

the other way around works too, if gcd = 28, it divides lcm = 35k, so 4 divides k and lcm = 140k'

#

and the smallest pair you can take is (28, 140) for a lcm of 140

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dim path
#

what's 1+1 guys?

devout snowBOT
raw parrot
#

uhhh

#

i think its 2

heavy current
#

if you have a real question, please ask it!!

otherwise, you can close the channel MenheraSalute1

dim path
#

what is the average mass of an instertaller Black Hole or What is the size of an black hole that has the same mass as our sun

runic prawn
raw parrot
#

i think its between 2 and 150 times of the sun

runic prawn
#

for the latter use schwarzchild radius

#

the for the former.. what do you mean by average exactly?

raw parrot
#

you cant average one single number

runic prawn
#

this is probably a troll question

raw parrot
#

well yeah

runic prawn
#

like he was trying to go super easy then super hard

raw parrot
#

i think he just

dim path
#

2 questions

raw parrot
#

thought of the most difficult question he could think of

runic prawn
#

what

fierce rune
#

$R_s=\frac{2GM}{c^2}$ is thes schwarzschild radius which is the radius corresponding to the event horizon, so you can just plug in the numbers to find it

woven radishBOT
raw parrot
dim path
#

okay bro 14 blobcry

#

im 14 LOL

raw parrot
#

...

dim path
#

im just asking random questions im just curious about science/math

raw parrot
#

you did not need to confess that but alr

fierce rune
#

but genuinely, the radius of a black hole is something you are able to calculate easily

#

its a fascinating result with how simple it is

raw parrot
raw parrot
#

how would you measure it though

fierce rune
#

measure what?

dim path
#

wrong send

raw parrot
raw parrot
fierce rune
# raw parrot how would you measure it though

if you're asking how you would observe the radius of a black hole experimentally, i believe physicists measure the degree of gravitational lensing using objects behind it to find the mass

#

since the curvature of spacetime is dependant on the mass of a body

raw parrot
fierce rune
#

what makes you think that?

#

special relativity has been a heavily researched area since einstein postulated it

dim path
#

nah y'all are to Good at math :/

raw parrot
#

well, because we can only estimate, and not know the true value

dim path
#

is being good at math can get u better in playing chess?

fierce rune
#

well true, theres always experimental error

dim path
#

Oh okay thanks man

raw parrot
dim path
#

is Reading and asking ur self , better than reading before going to go to bed?

raw parrot
dim path
#

😄

#

and sometimes just read books

raw parrot
raw parrot
dim path
raw parrot
fierce rune
raw parrot
#

🤦

dim path
#

It's measured by mass

#

i think

fierce rune
#

but there are exact ways of finding its radius

fierce rune
dim path
#

primarily classified and measured by their mass ?

fierce rune
#

mass distorts light in a specific and predictable way thanks to the einstein field equations

raw parrot
#

whatdatmean can you help me with my question

fierce rune
runic prawn
#

<@&268886789983436800>

devout snowBOT
#

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dim path
#

yoo

devout snowBOT
dim path
#

mb

runic prawn
#

.close

twilit comet
#

.close

devout snowBOT
#
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dim path
#

.close

devout snowBOT
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dim path
#

Guys is it possible for us Humans to create an Blackhole with the mass of 0.0001% solar mass

hasty cargo
#

3 <@&268886789983436800>

#

troilling

modest dagger
#

I don't think they are trolling.

dim path
#

bro im not trolling im asking 😭

hasty cargo
#

well explain this then.

hard shoal
#

Hes trolling dawg

hasty cargo
#

?

hard shoal
#

get jit outta here

modest dagger
#

How is that indicative of trolling?

hard shoal
#

bro came in n asked 1+1

dim path
#

i deleted it

#

Mb bro i was new to the server

hasty cargo
#

and not following conduct

#

for the 2nd time

modest dagger
#

"This isn't math" =/= "trolling"

hasty cargo
dim path
#

im 14 gng

modest dagger
#

Anyway, rather than accusing people with pings why not redirect them. You realize we have #old-network right?

modest dagger
#

for your physics question

coarse flume
dim path
#

3.3% of earth's mass

#

:)?

hard shoal
#

not plausible

#

we dont have anywhere near the resources to do that

dim path
modest dagger
#

"Facebook +1"

dim path
#

yea

#

LOL

modest dagger
#

This really is probably too far outside the scope of math for anybody to be particularly helpful here beyond what you'd get asking some rando on the street.

#

Also kinda general and not really a math "help" q. I'm gonna close this. Probably physics server is the best option. One of the general discussion channels might also be reasonable.

#

.close

devout snowBOT
#
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#
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chrome salmon
devout snowBOT
chrome salmon
#

can someone pls help

#

I got the the simplifying point

#

1/(121sec^2theta)

#

I took the 121 out so

#

out of the integral

#

so its just 1/sec^2

silk falcon
#

<@&268886789983436800>

chrome salmon
#

okay

silk falcon
#

you could take the x^2 out and it would become x^3 then you can let in terms inside the bracket be t and you have the derivative outside

chrome salmon
#

Do i convert that to cos^2

silk falcon
chrome salmon
#

oh

#

I have to use a specific method so

#

I can't do it like that

silk falcon
#

Or if you are using trigonometry, then you can let t=121tan(thete)

#

if you find it hard, think it this way, its $\int \frac{dx}{(a^{2} + x^{2})^\frac{3}{2}}$

woven radishBOT
chrome salmon
#

okay

silk falcon
#

yes

#

now you have to change x with a trigonometric function which can work like 1+ (fx)^2

chrome salmon
#

so

#

tanx

silk falcon
#

yes

chrome salmon
#

i get that

#

i did the whole process of that

silk falcon
#

ok and what did you get?

chrome salmon
#

right here

#

I just don't know how they got the derivative

#

of sin theta /121

silk falcon
#

hmm

#

see we made 11 sec^2(x) in numerator, did you get how we got there?

chrome salmon
#

yeah

#

the derivative of tan

silk falcon
#

yes

#

and how do we simplify the denominator from 121 + 121 tan^2x

chrome salmon
#

121sec^2x

silk falcon
#

yess

#

and then 3/2 to the power

chrome salmon
#

yes

silk falcon
#

so what is denom now?

chrome salmon
#

1331sec^3x

#

wait

#

that can be simplified

#

to 1/121secx

silk falcon
#

or to keep it simple, (11secx)^3

fluid blade
#

i solved... wait a sec

silk falcon
#

and then what do we do?

chrome salmon
#

okay

#

take the 1/121 out

fluid blade
chrome salmon
#

and do 1/secx =cosx

silk falcon
#

yes

#

and now its a simple integration

chrome salmon
#

right

chrome salmon
#

it does help to visualize it

silk falcon
fluid blade
chrome salmon
#

me neither 😭

#

ur good

#

ima close this

#

ty all for ur help

#

i appreciate it

#

.close

devout snowBOT
#
Channel closed

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devout snowBOT
#
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peak valley
#

hi so can someone help me with my ledging or something its buisness studies ans pretty simple but im not grasping it and i dont think i did this right

peak valley
#

I'll translate what i can

#

ping me when someones here!,

devout snowBOT
#

@peak valley Has your question been resolved?

devout snowBOT
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fleet fjord
#

Yo bot

devout snowBOT
wind mason
#

?

wind mason
fleet fjord
#

Yeah

#

Could you dumb this up? I don't quite get it

wind mason
#

ok, label layla's current age x and miya's current age y

#

what does the first sentence tell us about x and y? can you relate them?

fleet fjord
#

That x is equal to y four years ago

wind mason
#

how would you express that with just an algebraic equation

fleet fjord
#

X = y - 4

wind mason
#

yes

#

what about the second sentence?

#

take some time with that one

fleet fjord
#

Wait

#

I think I got the first sentence wrong

#

Is it x -4 = y?

wind mason
#

i don't think so

#

if layla is one years old, miya was one years old four years ago, so that must mean she's five now

#

so x=y-4

fleet fjord
#

Here's what I understand on the second sentence
X +11 = y 1/2

devout snowBOT
#

@fleet fjord Has your question been resolved?

uncut crow
devout snowBOT
#

@fleet fjord Has your question been resolved?

fleet fjord
#

No

devout snowBOT
#
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#
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fallen thistle
#

for a, im pretty sure its a trapezoid but i dont know how to prove that ab || pq, can someone please help 🙏

fallen thistle
#

the first part of the problem* not a

pearl relic
#

(tangents are perpendicular to radii)

fallen thistle
#

oh wait yeah forgot about that property, thanks! i'll try and use that

pearl relic
#

yeah

fallen thistle
#

.close

devout snowBOT
#
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devout snowBOT
#
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

robust ermine
#

i give up fighting with gemini bro hallucinating sack of shit cant listen to simple ionstructions
y is iii wrong (trying to all possiblities - even + lesst han 7000)
i got it right once by taking cases like 7/8/9 _ _ _ 2/8
but im trunna do it another way
Cus some guy on reddit told me a good way to get good at permutations and combinations is to do as many quesitons as possible and do them in as many ways as possible

robust ermine
#

YO

#

HOW DO YOU SPAWN WHENEVER THERES A PERMUTATION AND COMBINATION QUESTION BRO

#

every single time wihtout fail

uncut crow
#

i do not see much value in looking for a more complicated solution to this when there is a simple solution but whatever. you want to count how many are less than 7000 or even?

robust ermine
#

yea

uncut crow
#

your message is a little hard for me to parse

#

with run on sentences and poor notation

robust ermine
#

uhh

robust ermine
#

yeah

#

(b)(iii)

robust ermine
white elk
#

okay well you wanna think about the most forcing parts of the combinatorics

#

so if the number is greater than 7k, you can actually make cases on what the first digit can be

uncut crow
#

i believe he said he has already done that and gotten the right answer doing that

white elk
#

oh wait nvm I'm seeing your work now

#

yeah mb

robust ermine
#

im trying to do iii
my previous attempt was breaking it up into cases like this -> 7/8/9 _ _ _ 2/8 from which i got the correct answer
but im trying to do it like all possibilities - even + less than 7000
because some guy on reddit told me that a good way to uh get comfortable with permutations and combinations is to alot of questions and do them in a bunch of ways

#

more legible yes ^^ ?

uncut crow
#

2 or 8 as last digit?

robust ermine
white elk
#

it says odd

robust ermine
#

oh

#

i just

#

roughly wrote that from the top of my head without much thought lol

#

because i did that yesterday

#

but i did get it right

solid perch
#

so are you trying to complement count (sample space - unwanted events)?

uncut crow
#

well if you want to do it the other way… you would want
total arrangements - (arrangements that are even or less than 7000)

uncut crow
#

are you sure you worked with that correctly?

#

there would be some inclusion exclusion involved

robust ermine
#

damn discord markdown

robust ermine
uncut crow
#

a solution of the complementary counting variety

#

like that is roughly how i would do the problem but i thought you wanted a complementary counting solution now

#

also hi annie waves

robust ermine
#

this was when i got it correct

#

yesterday

#

oh

#

i thought

robust ermine
#

mb

uncut crow
#

lol no i was talking about complementary counting but that’s ok

robust ermine
uncut crow
#

no i don’t see a solution there. what about the 7000 part for example?

robust ermine
#

oh

#

wait

#

nvm

uncut crow
#

that’s a condition in the problem that needs to be considered but i don’t see it mentioned anywhere in your solution

uncut crow
#

we are trying to count the arrangements that are less than 7000 or even

#

the less than 7000 condition should show up somewhere in your solution

#

but it did not. that’s all i was saying

robust ermine
#

so if a solution was less than 7000
the first digit would be 2 or 3 then whatever for the next 3 digits
so 2/3 _ _ _
isnt that 2*4P3

uncut crow
#

yea

robust ermine
#

even is another

#

unwanted case

#

so

#

the last digit is either 2 or 8

#

isnt that also 2*4P3

uncut crow
#

yea

robust ermine
uncut crow
#

and still you are forgetting about something

#

which is that you have counted some arrangements twice

#

namely the ones that are even and less than 7000

robust ermine
robust ermine
#

bccause

uncut crow
#

i know and that is wrong

robust ermine
#

because

#

im

#

double counting

robust ermine
#

wait

#

2/3 _ _ _
like 2__8 could be a value here but
in my other case where i count all the numbers less than 7k 2__8 is also a possibility

#

so is it all - (less than 7k + even - less than 7k and even)

#

holy cRAO

solid perch
#

(trivia: this is called the principle of inclusion-exclusion.)

robust ermine
#

lol

#

let me write out the solution

uncut crow
#

principle of be happy with a simple solution

robust ermine
#

should i keep doing this
trying to do all the problems in different wayes

#

or just be happy with the first simple solution

uncut crow
#

i would be happy with the first simple solution and go do other problems

#

but sure, you are allowed to look for complicated solutions too

#

if that’s what you want to do then go for it

#

it’s not that looking for other solutions is bad

#

that’s a good thing

#

it’s just that like

#

complementary counting on ts problem is complicating it for no reason

robust ermine
#
2/3 _ _ 2/8

2 __ 8 4P2
3 __ 2/8 2*4P2
#

MAN

#

this markDOWN

#

so 3*4P2

#

are the cases whjere its less than 7lk and even

#

and then uh

#

5P4-4P3-3*4P2

#

tis 84

#

exatcly doubble the answer

robust ermine
uncut crow
uncut crow
robust ermine
#

yes 😭

#

all possibilites 5P4

#

oh

#

wit

#

its actually -12

uncut crow
#

lol

robust ermine
#

G[FOSJIFS

#

WAI