#help-27

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dark sable
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fun fact, half the people there got less than 1 question correct

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out of 30

sand quarry
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so like

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everybody failed?

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crazy

dark sable
sand quarry
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i mean it isn't really difficult but having you do the computations in 90 seconds is rough

dark sable
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ok what if

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Let a and b be positive real numbers, and X, Y be random variables such that Y=aX+b. If E[X]=2ab, E[X^2]=5a^2b^2, Var[X]=6a, Var[Y]=48. Determine E[aY^2-bY+ab]

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60 seconds ๐Ÿ˜ญ

sand quarry
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cringe

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again not really hard

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but its a lot of computations

dark sable
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if I'm mkinag any sense

sand quarry
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like

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,, \lm \Var[Y] = \Var[aX+b] = a^2\Var[X]

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is that your quesiton

woven radishBOT
dark sable
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why is i a^2Var[X]

sand quarry
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but you can prove it

dark sable
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ok so I assume i express Y as a function of X so

dark sable
sand quarry
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you dont assume

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its given to you

dark sable
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um

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is it

sand quarry
dark sable
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E[a^3X^2+2a^2bX+ab^2-abX-b^2+ab^2]=E[a^3X^2+(2a^2b-ab)X+2ab^2-b^2]=

sand quarry
#

that sure is a chungus

dark sable
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is it 5a^5b^2+2a^3b^2-2a^2b^2+2ab^2-b^2

sand quarry
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idk what you are doing rn

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like

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what i'd do is like

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1- evaluate Var[X] from Var[X] = E[X^2] - E^2[X} and Var[X] = 6a in terms of a and b
2- Recover a from Var[Y] = Var[aX+b] = a^2Var[X]
3- Recover b from the equation resulting from step 1
4- find E[X], E[Y], and E[Y^2] now that you know a and b
5- use the fact that E[aY^2 - by + ab] = aE[Y^2] - bE[Y] + ab to calculate the lhs

dark sable
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kk thanks is this still in the same book

sand quarry
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yes everythign is there

dark sable
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6a=5a^2b^2-4a^2b^2 => 6=ab^2
a=2
b=sqrt3
E[X]=4sqrt3, E[Y]=E[aX+b]=aE[X]+b=9sqrt3, E[Y^2]=a^2E[X^2]+2abE[X]+b^2,=240+48+3=291
582-27+2sqrt3=555+2sqrt3

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am I right

dark sable
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555+2sqrt 3

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crazy

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ok what if

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Given a random variable X is normally distributed with mean 28 and variance 6, what is E[X^3]-E[X]^3

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is this kurtosis

sand quarry
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i need to go really bending_skull but you should propbably open up a new help chnanel

dark sable
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aw

dark sable
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.close

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#
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idle citrus
#

im kinda confused, is this how u do this?

devout snowBOT
dull parrot
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so you expand it normally

idle citrus
pure flower
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yes

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multiplication is commutative (for real numbers)

hardy trail
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In other words, no; the order does not matter :)

idle citrus
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so 4x^2 - 5xy - 21y^2

pure flower
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me trying to phrase it in the least 'assumes you know what i mean' way possible

pure flower
hardy trail
idle citrus
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okay ty i wouldve def got that wrong

pure flower
idle citrus
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i did say can it be 7xy lasy so i assumed yes was for that xD

pure flower
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but yes order doesnt matter

idle citrus
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alright tysm!

pure flower
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and i guess (7x)y = 7(xy) is associativity

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so yes multiplication is associative as well (for real numbers)

idle citrus
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.close

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lament cradle
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How do i do b

devout snowBOT
lament cradle
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Vectors gen wanna make me like

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๐Ÿ’”

devout snowBOT
#
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7. None of the above
lament cradle
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1

willow helm
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I assume we begin with a)

lament cradle
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Ys

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That one i got

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4b-2a

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With the weird lines underneith

willow helm
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Weird lines underneath?

lament cradle
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Yk how

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U put those dashes

willow helm
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Oh, above

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$\vec{a}$

lament cradle
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Ya

woven radishBOT
lament cradle
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Ya those

somber trout
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Any genius

willow helm
# lament cradle Ya those

Eh, I don't have reliable internet anymore. Imma let someone else take over instead of you waiting on me every time for 5 minutes. Good luck and sorry!

verbal wharf
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i can take over if needed

undone egret
# verbal wharf i can take over if needed

Not hopping in to help but how are you undergrad & this smart bnuuy (im just hoppping between help channels to see what people are doing to procrastinate)

MORE MORE JUMP SPOTTED SO PEAK

verbal wharf
undone egret
verbal wharf
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THATS OKAYYY

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i finished college here and just looking for a university atm

lament cradle
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a

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i m back

undone egret
verbal wharf
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TYYYY AND YOU TOOO

verbal wharf
lament cradle
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A

lament cradle
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Im so stuck

dark sable
# lament cradle

I'm gonna be making this intentionally harder since it doesn't make sense
wow whoever made this question hates you, I don't even think a is answerable and expressable as just a and b ๐Ÿฅ€, since no angles are given on a technicality(one can assume but do we really want to assume)

winged hearth
lament cradle
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ya

verbal wharf
lament cradle
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Yes i did that

lament cradle
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Legit the vectors i did in class is like NOTHING

lament cradle
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Since like

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No value for P

dark sable
# lament cradle

express OP and BC as a line, Q is the point at which they intersect, find the point at which they intersect
2AP=3PC => AP=3PC/2 => 5PC/2=AC=5AP/3 => PC=2AC/5, AP=3AC/5,
now what we can do is do
with respect to O as the origin,
OP can be expressed as y=tanPOAx I think, then you have BC
similar concept, except it's raised up by a bit, how much?
you can do (y-y1)=m(x-x1) where x1 is the x component of OB and y1 is the y component of OB and m is the slope of BC(or tangent of the angle BC would form against a line parallel to OA, or simply put OBC-(108-BOA)) to which you can then do y= and x= and approximate the values from there(not really approximate)
the issue is expressing it as unit vectors, there is probably a geometry theorem out there that would help you find the sides but here I can only assume from point B to C you have to figure out how much x changes to 2a+b and translate it to the x value you get for CQ

now of course, this is all speculation and you should ask your teacher to specify since it's virtually a "why are we doing this" question

dark sable
lament cradle
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Shld i sen the ms

dark sable
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I mean by the x and y thing is that your units are 2a+b
for a specific x amount you calculate in the question, your hypotenuse is 2a+b or something, if you find the ratio from x:2a+b, then you can apply it to other x vals and y vals to find how to express the vectors as a and b

dark sable
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also is there more to the question

lament cradle
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Mark scheme

dark sable
lament cradle
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If u wanna deciper this go ahead but i genuinely gave u

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Up

verbal wharf
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do you understand how to find P first?

lament cradle
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No

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Wait

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Yes

dark sable
verbal wharf
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i got the same end answers though ๐Ÿค”

dark sable
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why do you randomly have mew and k and the angular torsion symbol

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and gamma

verbal wharf
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that is what they are doing

dark sable
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it said in terms of a and b, adding another constant or anything like that would ruin the point of expressing it as solely a and b

verbal wharf
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these arent constants though

dark sable
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if constants are allowed qa=fb=w(a+b)
where q f and w are constants that allow for the above to be true!!!

dark sable
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they also are constants

verbal wharf
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they are just a variable being multiplied to (a+b) acting as scalars

dark sable
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it's multiplied by a factor of say k representing CQ or PQ, where since they are collinear with BC and OP respectively, can be expressed as a constant multiplied to the vector quantities of BC and OP respectively plus OB+BC or OP

dark sable
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my wording ain't right prolly

verbal wharf
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multiplying is okay

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adding wouldnt be

dark sable
#

you following this OP? the questions don't make sense at least not in conventions I know

devout snowBOT
#

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steep agate
#

What do the z, x, u, o, and n looking symbols mean? I totally forgot

shy osprey
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Is this related to statistics?

steep agate
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yes

shy osprey
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right x bar is mean

lethal wraith
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z means z in this case

shy osprey
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mu is the mean deviation
sigma is variance
n is number of observarioms

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i think

wheat pawn
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z means z
we could never guess that

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z is the value after tipification of the variable

shy osprey
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oh well regional differnece ig

wheat pawn
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no, that's phi(z), which is the value of the normal

shy osprey
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OH right

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-# i hate stats

wheat pawn
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z is the entry value, phi(z) is the exit value

shy osprey
steep agate
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ok I will see if I get a reasonable answer then I will close

shy osprey
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Sure

wheat pawn
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i mean, we already gave you the answer for each of the letters

steep agate
#

yes but the answer for what I needed the letters for

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thank you

#

.close

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#
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wheat pawn
#

.thats... not what you asked tho?

steep agate
#

I couldve asked for more help

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cold topaz
#

How do i get this?

devout snowBOT
cold topaz
supple knot
#

you pick convenient values for x in the range and plug them into the function

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e.g. x = -5 < -4 and (-5 - 4)(-5 + 4)/(-5 + 2)^2 = some positive number

rain summit
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And then the rest is sign work

cold topaz
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x = -3 should be negative

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?

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-7 . 1 / 1

supple knot
supple knot
flat ibex
#

The work is wrong then right

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Should be + - - +?

rain summit
cold topaz
#

ok thanks everyone

#

.close

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pure skiff
#

Hello so I don't have specific type of question about math, but I got an exam/test coming up tomorrow all about integrals. So can someone teach me all about integrals like ranging from neper's number integration up to X and Y-axis integration

pure skiff
#

I would be appreciate it if someone could give valuable youtube video about integration perhaps

gloomy aurora
#

khan academy

pure skiff
gloomy aurora
#

!done

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pure skiff
#

I guess

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opal olive
#

hey

devout snowBOT
trail eagle
#

What is your question?
Also avoid opening duplicate help channels.

twilit comet
#

have a question?

trail eagle
#

I'll close this one since OP posted their problem in the other channel.

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.close

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worthy phoenix
#

how to find the equation of circle if I have 3 points that are in the same circle

trail eagle
#

!xy

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winter patrol
#

perp bisector theorem twice to get the centre
then distance formula for the radius

worthy phoenix
#

<@&286206848099549185>

crude niche
#

!15m

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#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

crude niche
#

do you have the original problem

worthy phoenix
crude niche
#

try and find the midpoint

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of every point

worthy phoenix
#

after that?

crude niche
#

of each segment of points

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and then find the perpendicular bisector

worthy phoenix
#

yes

worthy phoenix
#

its the perp segment of a segment?

crude niche
#

create 90 deg

worthy phoenix
#

yes

crude niche
#

basically the slope is opposite

worthy phoenix
#

ahh I see

crude niche
#

eg 3 is slope

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so the perp is -1/3

worthy phoenix
#

yes

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what should I do after?

crude niche
#

then you find the center

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also i might be so wrong so idk ๐Ÿ˜ญ

lunar harbor
#

(In the future, please make the first message you send the actual question since that's what the bot pins. This saves us the effort of having to change the pin manually.)

worthy phoenix
#

found the intersection between the segments

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now how do I calc the distance for radius

tribal leaf
#

Hey

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So the circle equation is

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X^2+y^2+2gx+2fy+c=0

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Which is S=0

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Now

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U substitute the points in the equation

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You will be 3 equations and 3 variables

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solve them you will get g,f,c values

worthy phoenix
tribal leaf
#

S is the equation of circle

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we denote it that way

worthy phoenix
#

I see

worthy phoenix
tribal leaf
#

Do you want me to solve it?

worthy phoenix
#

if u can

tribal leaf
#

Okay give me few min

winter patrol
thick lotus
worthy phoenix
#

thank you

winter patrol
#

I prefer this method compared to the system of 3 equations above

worthy phoenix
tribal leaf
tribal leaf
winter patrol
#

As in the length of the radius?

tribal leaf
#

Nah

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r = \sqrt{g^2 + f^2 - c}

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so the center would be (-g,-f)

tribal leaf
#

instead of h and k u get f and g

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it's only the change in variables rest is same

winter patrol
#

It's pretty different

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applying different properties/ideas

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#

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worthy phoenix
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@worthy phoenix Has your question been resolved?

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light plover
#

is the 1/4 applied to all of the numbers including both the numerator and denominator? or only the numerator/denominator or there is some sequence

supple knot
#

both numerator and denominator

#

$\lp\frac ab\rp^x = \frac{a^x}{b^x}$

woven radishBOT
#

pi_day

light plover
supple knot
#

,tex .exp rules

woven radishBOT
#

pi_day

supple knot
light plover
#

thanks

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severe ice
devout snowBOT
severe ice
#

can someone help me with the bottom 2? the shapes are rhombi

woven radishBOT
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@severe ice Has your question been resolved?

winter patrol
#

What have you tried?

severe ice
#

.close

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cold badger
#

can someone help me how to answer this?

devout snowBOT
rose granite
#

What kind of answer would u need?

#

One with a solution?

#

Or just the answer.

marsh trail
devout snowBOT
# cold badger can someone help me how to answer this?
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
rose granite
#

@cold badger ?

small geyser
#

!nosols, I don't think we should provide a full solution from the get-go?
(if you were not planning to provide a full solution or just the answer, then please ignore this, and I'm sorry for entering.)

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#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

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hollow agate
#

i honestly have no clue where to start, i don't see a way in that has any meaningful way to break this question.

hollow agate
#

nvm i have a start

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serene forge
#

Helloo im kinda struggling here

The farthest i got was 2(โˆš5+โˆš3)

But the answer's not on the options

serene forge
#

,rotate 180

woven radishBOT
serene forge
#

<@&286206848099549185>

zealous ledge
serene forge
zealous ledge
#

Honestly, i think the answer is a
The power of the denominator is greater than that of the numerator

#

So you end up with something like this (gimme a sec im writing this down)

serene forge
#

Okie

zealous ledge
serene forge
zealous ledge
#

Its always been there

#

Not that it affects the answer

serene forge
#

Oh

#

So i just ignore that 1/4

#

?

zealous ledge
#

You dont ignore it

#

But this limit, according to me, evaluates to zero

solemn gorge
#

hey freinds needed help for explaination

serene forge
verbal wharf
devout snowBOT
serene forge
zealous ledge
#

Use what?

serene forge
zealous ledge
#

Brother

solemn gorge
zealous ledge
serene forge
#

Or whenever there's a number at the bottom

Like something something but it's root
Denominator is 8x
you write 1/8?

serene forge
zealous ledge
#

I mean you dont have to, i did it for clarity

serene forge
serene forge
solemn gorge
zealous ledge
#

I thought you meant whered i get the 4 from ๐Ÿ˜ญ

serene forge
#

Its ok ๐Ÿ˜‚

solemn gorge
serene forge
#

He just taught us

#

Use the x with the highest exponent

#

Like

#

In the question its xยณ

#

So 3xยณ/xยณ -> 3
5-> 5/xยณ ->5/0-> 0

#

And so on

#

Is it correct tho?

zealous ledge
solemn gorge
#

6

serene forge
#

Ghis is the notes qwq

solemn gorge
zealous ledge
serene forge
#

Oh ok thankss

serene forge
#

Why'd it become 4ยฒ?

solemn gorge
zealous ledge
#

So if the denominator has more power, all the finite terms get divided by infinity and so its zero

serene forge
zealous ledge
zealous ledge
#

I dont even blame you, its my handwriting

#

But yeah thats an x

zealous ledge
#

Whats your answer?

lunar harbor
serene forge
#

Okie thanks holdon

serene forge
zealous ledge
#

Lemme write that step by step

serene forge
zealous ledge
#

Theyre both x's

#

Youre getting firsthand experience on why my classmates prefer not to take notes from me

serene forge
zealous ledge
#

I honestly dont know what you mean by that

serene forge
#

Just realized i say wait alot

zealous ledge
#

I circled all the 4s for you

#

Anyways, i should go get lunch

last parrot
#

number 4 slowly transforms into 3 or 5

serene forge
serene forge
serene forge
last parrot
#

i was being sarcastic with the handwriting

serene forge
thick lotus
#

do you need help

devout snowBOT
#

@serene forge Has your question been resolved?

serene forge
zealous ledge
#

Amything else?

serene forge
#

Uhm

#

I'll try to proses that ine rq

serene forge
zealous ledge
#

10 shouldnt be zero imo, lemme try it

zealous ledge
#

Are you familiar with the concept of binomial approximation?

zealous ledge
zealous ledge
#

BRO

#

You evaluated it for limit x tends to 0

zealous ledge
serene forge
#

I forgot how to do it lowkey

zealous ledge
#

I think you need to revise your concepts first ๐Ÿ’€

serene forge
#

Ye ๐Ÿ˜ญ

zealous ledge
#

Do you remember the expansion for (1+x)โฟ

#

I could walk you through it, but if you dont, id honestly recommend you to review your notes first

serene forge
#

Thank you :'

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#

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summer harbor
#

hello again

devout snowBOT
summer harbor
#

is the potential graph correct? im unsure about a decreasing function yet concave up

summer harbor
#

i dont have a graphing notebook either

tribal leaf
#

there's one website

summer harbor
#

LOL

tribal leaf
#

ill send it (if I get it)

summer harbor
#

but is the graph correct based on the

#

table?

tribal leaf
#

It's worng

summer harbor
#

i see.. which ones in the table did i get it wrong?

tribal leaf
#

I plotted the graph

summer harbor
#

damn

tribal leaf
# summer harbor i see.. which ones in the table did i get it wrong?

$1. At x = 0: wrong nature of point

Given: f'(0) = 0, f''(0) = 0
So, (0,0) is a stationary point of inflection

Error: Graph shows a slanted straight crossing
Correction: Curve must have a horizontal tangent (flat touch) at (0,0)

  1. Concavity change not clearly shown at x = -1 and x = 1

Given: inflection points at (-1,1) and (1,-1)
Error: Curve looks almost straight โ†’ no visible change in bending

Correction:
At x = -1: concave down โ†’ concave up
At x = 1: concave up โ†’ concave down
โ†’ Show clear change in curvature

  1. Segment near origin drawn almost linear

From table, curvature keeps changing
Error: Middle portion looks like a straight line

Correction: Curve must be smoothly curved throughout, not linear$

woven radishBOT
#

แแ•แฆแฐ
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

tribal leaf
#

These are the mistakes

summer harbor
#

thanks

tribal leaf
#

I might have gotten wrong, like double derivative, in the graph*, just change those ig,

devout snowBOT
#

@summer harbor Has your question been resolved?

summer harbor
#

i cant draw ts ๐Ÿ˜ญ

devout snowBOT
#
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#
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viral kernel
#

$|z|=|a+ib|\leq|a|+|ib|\leq|a|+|i|\cdot|b|\leq|a|+1\cdot|b|\leq|a|+|b|\to|z|\leq|a|+|b|$

woven radishBOT
#

Mr. Penguin

viral kernel
#

is it correct?

trail eagle
#

Yes

viral kernel
#

๐Ÿ‘

#

thanks

#

.close

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#
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devout snowBOT
#
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frozen solar
#

question 7

devout snowBOT
frozen solar
#

max value is obvious

it would come at x=6

hidden torrent
#

diffrentiate

#

and equate to 0

frozen solar
#

haven't don't differentiation yet

#

done*

hidden torrent
#

hmm u know to plot graphs ?

frozen solar
hearty yoke
#

if you havent done differentiation try substitution x+2.5 = t

#

the function will look easier to understand

hidden torrent
#

maybe i think

frozen solar
#

but what do we get from it?

do i hv to open brackets in the end?

hearty yoke
#

fuck around and find out

hidden torrent
#

we can pair up x+1 and x+4 & x+2 and x+3
then t = x^2 + 5x + 5

frozen solar
hidden torrent
frozen solar
#

I've heard shi like that

#

but not in maths

hearty yoke
#

you wont build intuition if you just ask for everything, try different things you'll get what works

frozen solar
frozen solar
#

but I was hoping to not have to open the brackets

#

i alr know the way to open these brackets

#

take pair with constant sum same

#

well if that's all that's coming in you all's mind then ig I'll jus make quadratics

#

kk min value iz 4

#

at x=-5

#

thanks and adios

hidden torrent
#

well

#

1+2+3+4/4 =2.5

#

and minima is at x=2.5

frozen solar
#

eh

hidden torrent
#

a coincidence

#

i think not

frozen solar
#

oh it's at t=5

#

not x=5

#

for x you get q quadratic which I don't need to solve

frozen solar
#

.close

devout snowBOT
#
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frozen solar
#

<@&268886789983436800>

devout snowBOT
#
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#

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candid mica
#

In our book we have the numerator of the correlation coefficient simplified as on the attached picture. How do we get to the last part where only xi*yi is inside the sum

lunar harbor
#

So
$$\sum (-x_i \bar{y}-y_i \bar{x}+\bar{x} \bar{y})=-\bar{y} \sum x_i-\bar{x} \sum y_i+n \bar{x} \bar{y}$$

woven radishBOT
#

Civil Service Pigeon

faint gorge
#

typo?

lunar harbor
woven radishBOT
#

Civil Service Pigeon

lunar harbor
#

$$=-n \bar{x} \bar{y}$$

woven radishBOT
#

Civil Service Pigeon

lunar harbor
#

$$=-\sum \bar{x} \bar{y}$$

woven radishBOT
#

Civil Service Pigeon

lunar harbor
#

@candid mica

candid mica
lunar harbor
#

\begin{align*}
\sum (-x_i \bar{y}-y_i \bar{x}+\bar{x} \bar{y}) &= \sum (-x_i \bar{y})+\sum (-y_i \bar{x})+\sum \bar{x} \bar{y} \
&= -\bar{x} \sum y_i-\bar{y} \sum x_i+\bar{x} \bar{y} \sum 1 \
&= -\bar{y} \sum x_i-\bar{x} \sum y_i+n \bar{x} \bar{y}
\end{align*}

woven radishBOT
#

Civil Service Pigeon

lunar harbor
#

Hello?

candid mica
#

ye gimme a sec, im checking on paper

candid mica
#

thats not correct is it?

#

o wait im stupid

lunar harbor
woven radishBOT
#

Civil Service Pigeon

candid mica
lunar harbor
# candid mica ye forgot that one, but is that really the same result as they give in the book?...

ye forgot that one, but is that really the same result as they give in the book?
Yes, see what I said [above](#help-27 message).
shouldnt the product of the two means be inside the sum aswell? in the book it is outside (because no parenthesis)
Observe what I did [here](#help-27 message) (same as the attached image) and/or the last line of [this](#help-27 message).

If you're asking something else, you need to clarify because I don't follow then.

candid mica
#

oh i see where the problem was, i forgot to multiply the leftover sums by 1/n, now it makes sense

lunar harbor
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#

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candid mica
#

.close

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raven swift
#

Help? is Y also 1?

devout snowBOT
supple knot
#

1 is the horizontal line right above the point A

raven swift
supple knot
#

AB is 1 yes. AC is the vertical length from the x axis to point A on the circle

raven swift
#

If i dont know the angles, how do i even work this out

supple knot
#

you eyeball it and guestimate

raven swift
#

Would B be false?

#

Tan cant be greater than 1 right since only AB is 1

thick lotus
raven swift
supple knot
#

keep going assuming that's true

raven swift
#

How about C

#

Sin of B would be

#

So if BC is .375

#

AC would be .927

#

Sin = opp/hyp

#

So is D false?

#

C is true

thick lotus
#

yes

raven swift
#

Thanks

#

Wait D seems true

#

No

#

Sorry

tribal leaf
#

D is false

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#

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pale gull
#

How can I slove the piecewise function

devout snowBOT
trail eagle
#

!xy

devout snowBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

pale gull
#

Actually there is no original problem but I dont speak English enough to understand the YouTube so asked here in chating

#

There should be a problem?

lunar harbor
#

piecewise function catthumbsup

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#

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stark spruce
#

what is my constraint function here?

devout snowBOT
versed juniper
stark spruce
#

i did

#

i only have the volume function rn, which is the objective im p sure

#

V(x) = (16-2x)(7-2x)x

#

i guess the constraint can be represented as an inequality, but we haven't been taught how to solve inequalities yet

#

is there any other form that it can take?

junior flax
#

what is x in this scenario?

devout snowBOT
#

@stark spruce Has your question been resolved?

stark spruce
devout snowBOT
#

@stark spruce Has your question been resolved?

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#

@stark spruce Has your question been resolved?

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#

@stark spruce Has your question been resolved?

rich sluice
steady night
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#

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#
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#
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patent jay
#

if the dot product is commutative, how come $\vec{\nabla} \cdot \vec{F} \neq \vec{F} \cdot \vec{\nabla}$? I understand nabla isn't exactly a vector, and is just an operator, but if we treat it as a vector in operations, why is this the case?

woven radishBOT
pure flower
#

the latter is just notation iirc

#

nabla really isnt a vector

#

it's just convenient enough to think of as a vector

sand dove
woven radishBOT
#

Rafilouyear2026

pure flower
patent jay
patent jay
#

L notation though

pure flower
#

yeah i found it weird too but its convenient

sand dove
#

I do use it a lot though, because it's good enough and convenient

pure flower
#

until i realised its just notation

patent jay
#

also

#

in hs I would have just manipulated one side to get to the other

#

but genuinely i dont even know how to work to that

#

is it fine for me to get them both to a point where they equal each other?

pure flower
#

sure

pure flower
# patent jay

yeah this was the thing i was tripping up on too lol

patent jay
#

stewart right

pure flower
#

there's a thing written for it in griffiths

#

and i just didnt get it

patent jay
#

ah ic

#

whatever

pure flower
#

well i was doing physics not calculus KEK

#

so i was happy enough to just leave it at 'ok notation'

patent jay
#

uni forces us to take calc III in second sem of uni

#

got my exam in like a week

patent jay
#

thanks guys though

#

.solved

devout snowBOT
#
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patent jay
#

europe

smoky gyro
#

oh ok

patent jay
#

i mean its also one thing if its like a math course but im an engineering student who has to do 5 other courses at the same time </3

devout snowBOT
#
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robust bobcat
#

So I don't see how c can be any constant. Shouldn't it be f'(1). Also can someone explain why bโ‰ 1

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#

@robust bobcat Has your question been resolved?

robust bobcat
#

<@&286206848099549185>

quaint creek
#

which in this f(x) since its log(x)/log(b) b should not be equal to 1 since it makes the function tend to infinity

#

and hence we remove 1 from b's domain

#

and also b > 0

devout snowBOT
#

@robust bobcat Has your question been resolved?

robust bobcat
#

Ok thank you

#

.close

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#
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inner zenith
devout snowBOT
modern blade
#

Follow PEMDAS

#
  1. Parentheses
  2. Exponents
  3. Multiplication
  4. Division
  5. Addition
  6. Subtraction
inner zenith
#

and what now

#

9?

faint gorge
verbal wharf
inner zenith
#

oh

verbal wharf
faint gorge
verbal wharf
#

flip a coin

modern blade
#

what if today is April 1?

hearty yoke
#

What if math?

glass canopy
#

What math

hearty yoke
#

Math math

glass canopy
#

what what

hearty yoke
#

Math what

verbal wharf
glass canopy
#

if

hearty yoke
#

What

glass canopy
#

hat

inner zenith
#

at

hearty yoke
#

t

glass canopy
glass canopy
#

|| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| |||| ||

gleaming topaz
hearty yoke
inner zenith
glass canopy
#

the answer is some number, one can assume that much

inner zenith
hearty yoke
#

Black magic

glass canopy
verbal wharf
#

67

summer summit
#

67

gleaming topaz
#

67

glass canopy
#

67

inner zenith
#

67

hearty yoke
#

67

summer summit
#

jesus this generation is so cooked

glass canopy
#

can't even do a simple abuse of notation problem??? smh

verbal wharf
summer summit
glass canopy
verbal wharf
#

didnt know that

#

tyty

glass canopy
#

np:)

#

April fools!!!!!! haha tricked you

verbal wharf
#

:(

glass canopy
#

*or did i?*

verbal wharf
#

mods reading this channel:

gleaming topaz
verbal wharf
#

Yes

summer summit
#

yes (i have no clue what this game is)

glass canopy
gleaming topaz
inner zenith
#

what the answer is

glass canopy
#

he said woof

summer summit
#

$wo^2f$

woven radishBOT
summer summit
#

gotta simplify

glass canopy
#

ah of course

inner zenith
#

whats his name

glass canopy
#

Rutherford

verbal wharf
#

Hi Rutherford

#

<@&268886789983436800>

glass canopy
#

<@&268886789983436800>

verbal wharf
#

the icon is sakurako oomuro from yuruyuri btw

inner zenith
#

dont invite them there

#

shhh

glass canopy
inner zenith
glass canopy
#

He's not as fluffy as he used to be

inner zenith
#

why

#

he had a haircut?

glass canopy
#

Yeah :(

#

He's very huggable though

#

literally never even growled at a person

verbal wharf
glass canopy
inner zenith
#

he mor estylish now tho

glass canopy
inner zenith
glass canopy
#

like... he's caught those cubes from a room away

inner zenith
#

woah thats crazy

jaunty mantle
#

So this is a help channel not for discussing random stuff

inner zenith
#

i am getting help

jaunty mantle
#

Thereโ€™s #chill if you want to yap

inner zenith
#

we still dont know what the answer is

glass canopy
#

the dog was helping

inner zenith
#

yes

summer summit
#

in all seriousness, might wanna close this channel now

inner zenith
#

sure thing

#

bye Rutherford was nice meeting you

#

.close

devout snowBOT
#
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unreal crow
devout snowBOT
unreal crow
#

Iโ€™m having difficulty determining dv/dt when there are two unknowns dr/dt

#

And dv/dt

#

How do I relate this back to the waterโ€™s change in volume with respect to time, based on the given information?

woven vale
#

<@&268886789983436800>

graceful cosmos
#

You do have dr/dt! It can be related to dh/dt.

unreal crow
#

Is this to do with triangles?

graceful cosmos
#

That's actually a great strategy. Similar triangles can get it

unreal crow
#

Ok, uhh lemme try and look back at lecture notes

#

This is what I kinda looked over, and then I plug back into the volume possibly of the cone

#

Am I on the right track or did I make any mistakes?

muted sapphire
#

which is 0.05

unreal crow
#

Yes

#

The work on the left is the problem and this is what I ended up with

muted sapphire
unreal crow
#

Thank you

muted sapphire
unreal crow
#

Was there another way to solve it without using similar triangle ratios?

#

Iโ€™m curious, cuz I wasnโ€™t like told about that

#

With the given information

muted sapphire
#

you can write everything in terms of h\

#

and solve it

unreal crow
#

If so, is there a video/guide to that?

#

Just h?

muted sapphire
unreal crow
#

Got it

muted sapphire
#

and substitute back, the ratio is basically the same, geometric facts

unreal crow
#

Ah. Alright

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devout snowBOT
small geyser
#

<@&268886789983436800> discussion of banned topic as per #changelog + using images to evade possible filters.

delicate dust
#

take a day to read #changelog. also, dont post nonsense in help channels.

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dapper fable
#

Determine the smallest $n$ such that for all subsets $S$ of ${1,2,...,30}$ where $|S| =n$, there is atleast two elements of $S$ that are coprime

woven radishBOT
#

Copter

dapper fable
#

the original question was n = 16, but that was pretty trivial so i was curious to what the lower bound could be

worthy raft
#

Well for {1,2,...,30} it can't be 15 or lower, because for those numbers there will be a set of only even numbers

dapper fable
#

oh right

#

then its 16

worthy raft
#

Do you know it's 16? I only know that it's more than 15 right now

dapper fable
#

yes

#

split {1,2,..,30} into {n,n+1} by pigeonhole they must contain atleast one of {i,i+1}

#

what if S were subsets of {1,2,...,m} tho what would that look like

#

same thing?

tribal patio
#

probably

#

You might have to do a bit more on the case where m is odd I think

dapper fable
#

floor(m/2) + 1 or something

vital edge
#

Yeah that should be it

dapper fable
#

so the answer is floor(m/2) +1 for all m

#

thats cool

#

.close

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#
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tardy carbon
devout snowBOT
tardy carbon
#

mainly confused on part a

frozen aurora
restive river
#

the index is in the function argument

tardy carbon
#

you wpuld get an alternating parttern

frozen aurora
#

you'll notice a pattern

frozen aurora
tardy carbon
#

so when r is od its negative

#

then when even its positive

frozen aurora
#

yes

#

which is what the RHS is talking about

tardy carbon
#

im just not sure how u would explain it in the question

frozen aurora
#

if r is an integer then 2r is even and 2r-1 is odd

frozen aurora
woven radishBOT
#

artemetra

frozen aurora
#

this is sufficient catthumbsup

tardy carbon
#

so would this be fine?

#

lmk if u canrt read anything

#

i just didnt add it up to n.

frozen aurora
#

huh interesting! yes that also works

#

you might need to elaborate on the bounds tho

frozen aurora
#

because the first sum is until 2n while the second one is until n

tardy carbon
frozen aurora
#

you write f(2) + f(4) + ....

#

that makes it look like an infinite sum

tardy carbon
#

ph i see

frozen aurora
#

write down the last terms using n

tardy carbon
#

so i should go on until 2n

frozen aurora
tardy carbon
#

yeah got it ๐Ÿ˜‰

#

Thanks!

#

.close

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#
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frozen aurora
#

ofc catlove

devout snowBOT
#
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keen estuary
#

I would like to resolve this
f(x) = \frac{x^3 - 3x + 1}{x^2 - 1}

lean crater
last parrot
#

$f(x) = \frac{x^3 - 3x + 1}{x^2 - 1}$

woven radishBOT
#

Minฮป

upper schooner
#

(worth asking, what do you mean by "resolve"?)

devout snowBOT
#

@keen estuary Has your question been resolved?

keen estuary
gusty sparrow
upper schooner
keen estuary
#

.close

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#
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velvet rain
#

in v=E/(B*sintheta) shouldnt the value of theta which minimizes v be -dx? this will make the denominator a very tiny negative value (based on magnitude) which after division gives a negative value with a large magnitude which is a very small number.

trail eagle
#

!xy In particular, is there a specified domain for theta or other restrictions?

devout snowBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

velvet rain
#

wait mb

#

its based on the lorentz force formula when force = 0 and so that we get E = -(v X B) and then by using a X b = absintheta and rearrangement we get the above result

#

there isnt a domain restriction for theta at least its not explicitly mentioned

velvet rain
trail eagle
#

The angle you put into a cross product is usually an angle in [0, 180], so your v should only be defined for like theta in (0, 180).

winter torrent
#

negative value with a large magnitude

what exactly are you trying to minimise here? v makes me think it's a vector (velocity?) which doesn't really have a "negative value". Are you trying to minimise the magnitude of v?

trail eagle
#

At least for magnitudes, which I assume is what we're considering

winter torrent
#

right, okay. so we're trying to minimise the magnitude of the velocity vector, right?

velvet rain
velvet rain
#

sorry mb

winter torrent
#

yes, and magnitude cannot be negative

velvet rain
#

.close

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sturdy yew
#

if B^2 + B is similar to B, and B is an nXn matrix, then what are thr permissible values of n?

frozen aurora
#

wdym by similar

#

is it $B^2 + B = \lambda B$ for some $\lambda$?

graceful cosmos
#

Means there's some invertible P such that:
P'(B^2 + B)P = B

Where I'm using ' for "inverse"

frozen aurora
#

ohh right i forgot about that one

graceful cosmos
#

Obv we can distribute but I'm not sure what to do after that

stone stump
#

eigenvalues but op doesnt know those

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#

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sturdy yew
#

.reopen

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sturdy yew
stone stump
#

i dont know much abt them tbh

#

probably not enough if you said that

lusty sapphire
#

<@&268886789983436800>

karmic flicker
lusty sapphire
devout snowBOT
#

@sturdy yew Has your question been resolved?

spiral moss
#

i think it has to be a zero matrix

#

you might want to check my notes tho

#

this is assuming rankB=n

stone stump
#

which your conclusion is immediately contradicting

lusty sapphire
woven radishBOT
spiral moss
#

oh yeah mb

lusty sapphire
#

@sturdy yew you still with us?

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#
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sturdy yew
#

.reopen

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sturdy yew
#

mb

#

so

#

the sets {v_i^2 + v_i} = {v_j}

#

from the arguement that the eigenvalues of similar matrices are equal

#

what do i do from here

#

v_i represents an eigenvalue of the matrices

#

<@&286206848099549185>

gritty terrace
sturdy yew
#

so B = 0 is rules out

gritty terrace
#

ah, i see

#

so B is real, invertible, and similar to B^2 + B

sturdy yew
#

yes

lusty sapphire
#

My gut tells me n needs to be even, but I have no proof

sturdy yew
lusty sapphire
#
  1. because n=1 doesn't work
  2. even square matrices kind of give you a way to fake imaginary numbers, but this is all instinct