#help-27

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rain coral
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how to make the circle equation

devout snowBOT
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@rain coral Has your question been resolved?

rain coral
#

.close

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kindred mauve
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can someone explain to me how i'd know where these lines inrersect?

kindred mauve
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without using a graphing calculator

mystic scarab
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By solving x² = 1/x

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No more no less

kindred mauve
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ah okay so

mystic scarab
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Yep

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That's something you should already know

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The concept of find the intersection points between two functions

kindred mauve
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thanks

#

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violet sparrow
#

can anyone explain this? why it is sin(theta) = sin(180-theta)?

candid maple
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have you learnt about the unit circle?

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and also how circular/trigonometric functions are represented on the unit circle?

violet sparrow
candid maple
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I will then assume you know the basics of representing circular functions on the unit circle.
in that case, take a look at this diagram.

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does this directly answer your question?

violet sparrow
candid maple
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because an angle of theta is made from the other side (the negative x-axis). what do you recall about two angles that lie on a straight line? what must they sum to?

violet sparrow
candid maple
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exactly so. now, if you make an angle of theta from one side, what must its supplement be?

violet sparrow
candid maple
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why is there a 'maybe'? is there any other situation where the linear pair of an angle marked theta is not 180-theta?

violet sparrow
candid maple
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well then, I will tell you that it is correct (but I am also interested what made you doubt that).

violet sparrow
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because you have to minus from 180 to get the other side

violet sparrow
candid maple
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but do you need to assume?

violet sparrow
candid maple
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theta and 180-theta form a linear pair, and because they are a linear pair, they are supplementary. it's not a baseless assumption.

violet sparrow
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but have you heard about projectile motion? specifically horizontal formula?

candid maple
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there's a difference if you merely guessed the answer, but you even gave me the correct reasoning. what's there to assume if you've substantiated your claim?

candid maple
violet sparrow
candid maple
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well I will need you to cite that formula then.

violet sparrow
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here it is

candid maple
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I don't see where the 180 degrees is, though I do see a sin 2theta.

violet sparrow
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i was trying to understand this question here:

  1. A Batang Pinoy athlete from your school throws a javelin, always at the same speed, at four different angles (30, 40, 60, and 80) above the horizontal. Which two throws cause the javelin to land the same distance? A) 30 and 80 B) 40 and 80 C) 30 and 60 D) 40 and 60
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the explaination is from ChatGPT

candid maple
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I knew the explanation was from ChatGPT (which I highly do not recommend if you have no way to verify its output).

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but one way you can think about this problem in particular is to recall that you get maximum range at 45 degrees.
this is because you get the best of both worlds - you get the largest possible air time and horizontal range combination.

violet sparrow
candid maple
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that advice applies to any question.

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anyway...

violet sparrow
candid maple
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now, if you move away from 45 degrees, the effects change almost symmetrically (in ideal conditions - in the real world, there's air resistance and all the other good jazz to think about). if you go 5 degrees more than 45 degrees (that is, you aim at 50 degrees), you get slightly more air time, at the cost of slightly less horizontal range, because the vertical component of your initial velocity is now more than the horizontal component (you can check by drawing the triangle formed by the velocity vector and its components).
however, if you dip 5 degrees under (that is, you aim at 40 degrees), your projectile has a faster horizontal speed (because you're aiming at a more horizontal angle), at the cost of less air time.

as mentioned in the first sentence though, these two effects more or less cancel each other out symmetrically.

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as such, under ideal conditions, a projectile being thrown at 40 degrees has roughly the same effective range as the same projectile thrown at 50 degrees (of course, assuming same force, etc.).

violet sparrow
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so what does imply?

candid maple
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notice the angles add up to 90 degrees. that is not a coincidence.

violet sparrow
candid maple
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for any angle theta, throwing the same projectile with the same force at an angle 90-theta yields roughly the same effective range, provided theta is NOT 0 degrees.

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if theta is 0 degrees, you still get that relationship only if you interpret throwing at 0 degrees meaning 0 air time and thus 0 range. otherwise, if you give a horizontally-thrown projectile any air time at all, you will definitely get a further range out of that projectile over a projectile thrown 90 degrees; that is, thrown straight up and back down.

violet sparrow
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so these two angles produce the same effective range and then also these two add up to 90. So that means any angles that add up 90 (i.e. 60 and 30) then each of those would produce the same effective range?

candid maple
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exactly so.

violet sparrow
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i also thought of pythgorean theorem (and the right triangles and stuff)

candid maple
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it has something to do with the 180 degrees and the unit circle. the unit circle is how you (intuitively) derive the relationship containing the 180 degrees to begin with, and it's the 180 degrees together with the fact that you are taking the sine of 2(theta), NOT just theta, that makes this whole thing work.

violet sparrow
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but you just need to know the fact that any two angles that sum up to 90 is the answer?

candid maple
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intuitively you can reason that way, but using that property of sine is the more rigorous method.

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and it's not that any two angles sum to 90, it's that any two distinct angles at which a projectile achieves the same effective range sum to 90.

violet sparrow
candid maple
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then you may need to revisit the unit circle and how the circular formulas are derived from it.

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anyway, if you think about it, it kinda makes sense why you would need that 180. the angle of projection is theta, which ranges from 0 to 90, but you are dealing with the sine of 2(theta), so the range of the argument of that sine is 2(0) to 2(90) = 0 to 180. and that's why the relationship is with 180, not 90.

violet sparrow
candid maple
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what is physics if not models created using math to describe reality?

violet sparrow
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but you said ChatGPT is not recommended

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what can you recommend for me?

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i mainly use ChatGPT for studying basic math problems, studying biological stuffs and physics and chemistry

candid maple
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human tutors.

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or books.

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the problem with LLMs is that they sound confident, even when they are wrong, and some mistakes are so subtle you won't even notice it unless you are purposely out to catch it making that mistake. as a learner, though, are you?

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plus, I find that LLMs cannot adapt to human learning styles at the speed a good human tutor can. a good human tutor can adapt to your learning and emotional needs. not an LLM. they are designed to feed you wall after wall of text regardless of whether you're ready, and they cannot quickly mix intuition and formalism together.

violet sparrow
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like I say I have difficulties in understanding

candid maple
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that's why communities like these exist, no?

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what do you think we are doing at the moment?

violet sparrow
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but its anxious

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maybe you dont get replies

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depends on the question

candid maple
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I mean, I don't know about you. but if I ask a question and get no replies, I'd probably just bookmark that question and ask again later. or I'd go find a personal tutor to ask them. or I'd ask my teacher. or if I am really that desperate I'd email a teacher, tutor or professor (I haven't had to do this though).

candid maple
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unless I am very confident I can verify the LLM's output and that I am prepared to work through what it says, I would probably be cautious about using an LLM.

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I mean, your confusion right now? it's caused by the explanation from an LLM!

violet sparrow
violet sparrow
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In fact most of our school repotings/presentations are based on AI research/explaination. Thats why I dont trust with the reportings and stuffs

candid maple
# violet sparrow What I trust with these LLMs is that when I see a difficult passage or a stanza ...

so you trust large language models with language, which is exactly what they are designed to do, and thus I do not see a problem with that because that's what they're good at. they're not perfect, but they get the job done in language and linguistics far better than anything requiring reasoning (i.e., STEM).
of course, that is not to say current LLM models are bad - the latest thinking models are honestly scary in their abilities, but at their core they are still kinda language-based. also, note that a lot of the time, if it starts thinking, the answer that comes out is less likely to be explained unless you ask it to, but if you ask it to and it doesn't think, then it may introduce mistakes where it didn't originally. I have been hit by that twice during GPT-5, thankfully both times with people who can catch the output.

violet sparrow
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I appreciate your knowledge about AIs and LLMs

candid maple
# violet sparrow they sometimes inaccurate

and that is exactly what I mean! they're not perfect. neither are humans, but humans (at least good human teachers and tutors) would be more willing to reassess their stance given evidence and you can assess their confidence in their answers by their language, tone, and body expressions. not so for an LLM - they sound confident no matter what random (and I'm sorry for swearing here, but) bullshit they happen to be peddling at you at that time.

violet sparrow
candid maple
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nowadays I really only use GPT as a glorified screen reader because some people send problems that I cannot read with my poor eyesight.

violet sparrow
candid maple
violet sparrow
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im just curious

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but yeah thanks for answering my math/physics question

candid maple
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it's alright to be curious. but right place, right time, right topic.

violet sparrow
candid maple
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you too! you can ⁨.close⁩ the channel if you're done with it, or send your next question if you have another one.

violet sparrow
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wait

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couldn't we just do dm?

candid maple
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for most purposes I do not prefer to DM, unless you state up front what you want to talk to me about (which again, is not a topic for this channel).
if you want to DM me, perhaps close this channel first, notify me in #serious-discussion about what you want to discuss, then I'll let you know if I am comfortable discussing with you.

violet sparrow
#

.close

devout snowBOT
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viral lynx
pearl grove
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am I doing something wrong?

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I put the exercise on desmos and only the roots are correct

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but the rest of the graph just isn't

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are the channels not working

devout snowBOT
pearl grove
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anyone knows if nel is online

devout snowBOT
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@pearl grove Has your question been resolved?

pearl grove
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No

tired surge
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who’s nel

devout snowBOT
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@pearl grove Has your question been resolved?

native gyro
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whos channel is this

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did the bot just bug?

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should we call mods?

devout snowBOT
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lilac vortex
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mellow willow
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Can anybody help me with this one I’m stuck on what to do next

mellow willow
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And for this one I don’t even know how to start

tired surge
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allie is back

mellow willow
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lol

tired surge
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welcome back

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no robo_17 to ragequit on you this time

mellow willow
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that’s good then

tired surge
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both terms have sin x

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$$\sec x \cdot \sin x + \sin x = 0$$

woven radishBOT
tired surge
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$$\sin x(\sec x + 1) = 0$$

woven radishBOT
tired surge
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then set each factor equal to 0

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can you do that?

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or do you need more breaking down and babysitting with this

mellow willow
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How would I find secx=-1? I think it’s going to be one of those four points on the unit circle but the fact that it is sec and not cos is screwing me up

tired surge
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remember what sec means

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so your first line

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$$\sec x = \frac{1}{\cos x}$$

woven radishBOT
mellow willow
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Yea irs radius / x

tired surge
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so if

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$$\sec x = -1$$

woven radishBOT
tired surge
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then

mellow willow
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So if I flipped the fraction -1/1 would it just be 1/-1 so -1

tired surge
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$$\cos x = -1$$

woven radishBOT
mellow willow
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I don’t think I wrote my answers down correctly

upper schooner
tired surge
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you wrote both 0 + 2pik and pi +2pik

mellow willow
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Wait how

tired surge
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but pik already covers both

upper schooner
mellow willow
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Ah ok that’s good

upper schooner
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But note that sin(x) = 0 gives you both of these, whereas cos(x) = -1 gives you the bottom one catokay

mellow willow
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Kk

tired surge
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so final answer

mellow willow
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isn’t that the final answer?

tired surge
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clean it up clean it up

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it's correct i guess

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no need to go further if your professor isn't nitpicky about it

upper schooner
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(yea depending on how you get marked, and if there's "give as condensed as possible" instructions given to you catThink)

mellow willow
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ahh ok

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I don’t think she is to picky tbh because it’s precalc

upper schooner
devout snowBOT
#

@mellow willow Has your question been resolved?

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upper schooner
#

Can you believe it, I'm asking a question SCshocked
[Don't mind me, just trying to clear the channel naming Hehe]

upper schooner
#

.close

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arctic field
upper schooner
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I tried nothing, just give me the answer sky_kekegirlOwO

arctic field
uncut crow
devout snowBOT
upper schooner
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.Why do I not have the "this is irreversible" sticker sadcat

upper schooner
arctic field
#

you are simply reversible

cold haven
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😭

upper schooner
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.istg if the bot closes the channel but keeps it with my name instead, imma scream catscream

heavy current
#

cat bit help channel hmmcatfone

devout snowBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

rare kernel
#

!da2a

devout snowBOT
#

Asking the actual question right away is more likely to get responses.

Asking "Can I ask...?" or "Does anyone know about...?" doesn't give people enough information to decide whether they can help, and answering can feel like a promise to help with the actual question, which they might find themselves unable to.

upper schooner
heavy current
#

I blew the @devout snow up kannafire

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that should answer your question catthink

upper schooner
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.One of these days, probably sooner rather than later, I'll actually ask a question happycat

upper schooner
heavy current
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sorry, I'll give it a headpat instead of blowing it up next time catsnuggle

rare kernel
#

Charbit r u a boy or a girl

upper schooner
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I am also a bot bot

rare kernel
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O then close it urself

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Simply asking for my help

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😡

heavy current
upper schooner
#

.it don't work that way, we aren't the same type of bot SCshocked

devout snowBOT
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Available help channel!

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severe surge
devout snowBOT
severe surge
#

this confuses me

#

im sure its simple

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but why is f(-3)= to x

woven vale
#

this x is different to f(x), it's just representing an unknown quantity which you need to solve for

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you can write $f(-3)=y$ or $f(-3)=a$ or $f(-3)=\blacksquare$ if that helps you

woven radishBOT
#

حسیب ♥

versed juniper
severe surge
#

my teacher did this

woven vale
#

personally, why they want to do it that way makes no sense and this seems needlessly complicated. if you can read the value off the graph or off the equation, you are set

severe surge
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EVERYONE

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IN THIS MANS CLAS

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SAYS

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he overcomplicates stuff

severe surge
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what is the point of that

woven vale
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no idea! KEK

severe surge
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so on my test

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if i wrote

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f(-3)= -2

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it would be wrong

woven vale
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i mean, if you don't know what f is exactly, then you work with f(-3) = x as an unknown symbol. so maybe he's trying to get you used to this

severe surge
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but we do know what f is

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this is so confusing

woven vale
severe surge
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also what does it mean "determine the value of x such that f(x) = 2"

woven vale
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here you are given the y-value of the co-ordinate, i.e. y=2

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so when the function has a y-value of 2, what's the corresponding x-value?

severe surge
woven vale
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well we have the graph

severe surge
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It clicked

woven vale
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we can go to a specific y-value, like y=2, find when the function is exactly that high, and then read off the related x-value

severe surge
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because

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x = 4

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hits y =2

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okok

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im good now thanks he writes these weird 😭

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takes a bit of time to get

woven vale
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yeah, i would say "the function hits the line y=2 when x=4"

severe surge
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thanks so much

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thats all

woven vale
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!done

devout snowBOT
#

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severe surge
devout snowBOT
severe surge
#

I’m confused on A and B I don’t know where to start

supple knot
#

,rotate

woven radishBOT
severe surge
#

Domain and range without a graph sucks for me for some reason

autumn girder
# woven radish

Look at a, does there exist any value of x for which you can't evaluate f(x)?

devout snowBOT
#

@severe surge Has your question been resolved?

severe surge
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cant you use any value

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for x

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couldnt i do 4

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4wai

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wait

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seven is the vertex

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right @autumn girder

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so i just

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draw the vertex

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and see where it hits

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on the y axis

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and the vertex is h+k

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so

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it would be 2,7

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so domain is {xer} and range is {yer | y >= 7}

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okok

#

a makes sense

#

b

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.close

devout snowBOT
#
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devout snowBOT
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Available help channel!

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Remember:
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Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pale pecan
#

I need a function with the following properties(for personal curiosity on desmos graphing calculator):

  • Variables "x" and "n"
  • I guess function f(x,n)?
  • Domain: [0,100]
  • as n -> infinity, f(100,n) -> infinity
  • as x -> 0, f(x,n) -> 0
  • as n -> Infinity, median of y values -> 0
  • The mean of y values should remain consistent regardless of the value n, and preferably be able to be controlled by a variable if possible?
devout snowBOT
#

@pale pecan Has your question been resolved?

pale pecan
#

<@&286206848099549185>

solar goblet
hollow ice
#

does y = (x/75)^n work?

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oh I totally overlooked the last point mb

pale pecan
pale pecan
solar goblet
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maybe two normal distributions could do?

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make this into a piecewise, tweak the domains and stuff

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this is just a rough sketch on the graph shape

pale pecan
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Also yeah normal distributions make perfect sense here haha

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I'm not super math-y I just got this idea for a silly dice game 😭

solar goblet
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the blue graph is just a horizontal shift of the red graph

solar goblet
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as n goes to up, the (for lack of better word) base of the graph goes up

pale pecan
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Mhmmm...

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Sorta?

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Like the idea is uhh

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A dice game, where you can pick a die of any number of faces

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Dice with less faces have a lower maximum payout

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But the same average as a die with more faces

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The idea is the payout is never lower than 0 either*?*

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If you don't have an answer that's fine it's a really random question

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Thank you for your effort either way

devout snowBOT
#

@pale pecan Has your question been resolved?

craggy dagger
pale pecan
craggy dagger
#

if the mean is 5.5, the die cannot have less than 6 faces

pale pecan
craggy dagger
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Other than that there is a lot of flexibility in the problem

craggy dagger
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If all possibilities are < 5.5 you can never get a mean of 5.5

pale pecan
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Ohhh

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The mean in this hypothetical function isn't correlated to the actual value assigned to the faces

pale pecan
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Thank you for your help !!!!

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As in the function would create coordinates that would describe the percent out of the whole of the faces of dice

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And what value to assign them

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To make the dice have the same average value when rolled while making them varied in median

craggy dagger
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So how likely each option is and what value each option has

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Not necessaily 1 to 5

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If the mean is x, the median can't be larger than 2x (assuming all options are nonnegative)

pale pecan
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I think we're both confused😭

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It's not about how likely each option is I'm just tryna use this graph in a weird way

craggy dagger
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If the mean is 5.5, the median can't be bigger than 11?

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You want to produce physical dice?

pale pecan
pale pecan
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The idea is like plinko kinda?

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Like a function to make a graph, 1-100

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The dice analogy doesn't really matter 😭✌🏽

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Its hard to explain

pale pecan
craggy dagger
pale pecan
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Which I suppose could be done as a domain restriction/peice wise

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And the other 2 things I don't understand, as I said I'm not very math-y I'm only in precalc 🥲

craggy dagger
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Is the intention that y is uniformly distributed to form a random variable f(y, n)?

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Oh hmm looks like at some point i confused x for y

devout snowBOT
#

@pale pecan Has your question been resolved?

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lapis raft
#

z = x + iy
where x = a
a=5

(\omega ) = ln(z)

is this plot of the line z = 5 + iy correct?

woven radishBOT
lapis raft
#

where the red lines are ln(z)

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lapis raft
#

no

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lapis raft
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.reopen

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lost laurel
devout snowBOT
lost laurel
#

oh, nvm, missed the first sentence 😔

#

.clsoe

#

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lost laurel
#

.reopen

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lost laurel
lost laurel
#

I feel like I'm missing something here

#

the cdf is t^{n+1}; 0<t<1

#

so surely it converges to 0

uncut crow
#

each Z_n’s cdf looks like t^{n+1} + C for some C

lost laurel
#

the +C is because t isn't defnite?

lost laurel
#

but how would we know what C is

uncut crow
#

actually ignore me

#

C is just 0 here anyway

lost laurel
uncut crow
#

0 for what?

lost laurel
#

$\lim_{n \to \infty} t^{n+1}; 0<t<1$

woven radishBOT
uncut crow
#

i don’t see what the problem is

lost laurel
#

I have to show {Z_n} converges in dist to Z=1

uncut crow
#

yep

lost laurel
#

the the dist is the derivative of the cdf

uncut crow
#

yea i agree now. maybe this question is sus. Z’s cdf is the identity function (well on [0,1])

lost laurel
#

yea

#

okay, so I guess it;s wrong

#

wait, lemme see if there;s a soln

#

@uncut crow

#

this is what the book says

uncut crow
lost laurel
uncut crow
#

nothing they wrote there is wrong, but concluding Z_n converges to Z from that is. hence the ducky_skull

lost laurel
#

cool

#

thanks

#

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drowsy thicket
#

Can someone explain the alternating series test to me?

pseudo basin
#

are you looking for an explanation of why it's true or just how to apply it?

drowsy thicket
pseudo basin
#

ok, do you have a particular series you're struggling to apply it on

drowsy thicket
pseudo basin
#

ok, do you know what an alternating series is in the first place

drowsy thicket
pseudo basin
#

the (-1)^n encodes the sign alternation yes

#

but if you just write $\sum (-1)^n$ you'll end up adding and subtracting specifically 1's

woven radishBOT
drowsy thicket
#

Yeah, like there should be an a sub n after that

#

right

pseudo basin
#

a_n yes

#

$\sum_{n=0}^{\infty} (-1)^n a_n$, with the $a_n$ themselves being positive

woven radishBOT
pseudo basin
#

to apply the alternating series test you:

  • check whether the sequence {a_n} (without the (-1)^n) is monotone decreasing, or at least eventually so
  • work out the limit of a_n, expecting to get 0
#

if both of these checks pass then the series is convergent

#

thats the "execute application of AST" part

#

maybe you could link one of those formal things you saw online but could not understand?

drowsy thicket
pseudo basin
#

i... would not say you are "disregarding the alternating part" exactly

#

rather you are putting it out of the way

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silver breach
#

uhmm i forgot what my prof said in class about the havel-hakimi theorm... how do i draw a graph from it xD I got my numbers but yeah- this is the only example i got

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kindred mauve
devout snowBOT
kindred mauve
#

how do we know what the values in yellow are?

scarlet sequoia
#

those from above

#

at the top of the paper

kindred mauve
#

and these

#

becuase the values are different

scarlet sequoia
#

These are well-known formulas, they can be derived, but also simply memorized

#

Or do you mean which function is f and g?

kindred mauve
scarlet sequoia
#

for 1 < x < 2 you have 2x + 3 > -x, so f(x) = 2x + 3 ("higher one") and g(x) = - x ("lower one")

kindred mauve
#

thanks

#

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kindred mauve
#

.reopen

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kindred mauve
#

is f(x) always the higher one?

lilac patio
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potent yew
#

I need help for 14iii

devout snowBOT
potent yew
dry oak
fair juniper
#

you already did a major portion of the progress in part ii

dry oak
#

What did you do in the question before?

potent yew
potent yew
dry oak
fair juniper
#

use your progress from part ii and solve for theta

#

then plug theta back in

potent yew
#

But no restriction of range

#

What value do i write

fair juniper
#

because they say give your answer to 3 decimal places, you are expected to use a calculator

#

youre not done when you solve for theta

#

remember, we want x

#

so you plug theta back in, and your multiple values disappear

potent yew
#

Yeah do i only write the calculator solution for theta?

fair juniper
#

your infinite values*

fair juniper
potent yew
#

Why did i get only one value

#

I got x = 0.322

dry oak
#

How many values for theta did you write?

potent yew
#

1

dry oak
#

You can write more

fair juniper
#

dont forget to plug the value back in to be sure you got a good value

dry oak
#

Remember the unit circle

potent yew
#

But they equal the same thing

fair juniper
#

sin(3theta) equals the same thing for all of them, but sin(theta) is different

potent yew
#

Oh

#

How am i supposed to know how many values of theta to wrote

#

Write

dry oak
potent yew
#

But

#

Some angles add to 180 so they are equal

dry oak
potent yew
#

After

dry oak
fair juniper
#

solving for sin(3theta)=3/4 looks like this:
3theta = asin(3/4) + 2*k*pi
theta = asin(3/4) + (2/3)*k*pi

#

k is an integer

#

notice how when you pick two k's which differ by 3, you get theta which differs by 2pi

potent yew
fair juniper
#

those are the same (coterminal) angles

potent yew
#

Can i just say

fair juniper
#

oh lol i forgot about the second solution

potent yew
#

That a polynomial degree of 3 means it has 3 roots so i test until i find 3 roots?

fair juniper
#

once you find one, you can use polynomial division to get a quadratic, and quadratics are easy

potent yew
#

O

dry oak
dry oak
# potent yew

Bit yeah this is good just check they satisfy the original equation

fair juniper
#

i wasnt sure if the sin gives all solutions, so thats what i would go with

potent yew
#

Is the working fine

dry oak
dry oak
potent yew
#

Ok

#

Thanks

#

🙏

#

.close

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lost laurel
devout snowBOT
lost laurel
#

I'm interested in E(X^2)

#

So I first need the marginal, $P_X(x)$

woven radishBOT
pseudo basin
#

you don't rly need the marginal as such no

#

or are you forbidden from using the law of the unconscious statistician?

lost laurel
#

well , I can

pseudo basin
#

$E[g(X,Y)] = \sum_{(x,y)} g(x,y) p_{X,Y}(x,y)$

woven radishBOT
lost laurel
#

I can, but If I need E(X) , I'll want to restrict it no?

pseudo basin
#

this law works perfectly fine with g(X,Y) = X

lost laurel
#

okay, so just $\sum_{(x,y)} x^2 p_{X,Y}(x,y)$

pseudo basin
#

lowercase p and also you're gonna sum over the entire support of p_X,Y

#

putting down $\sum_{(x)}$ will make no sense

woven radishBOT
lost laurel
pseudo basin
#

no

lost laurel
#

so $4 \cdot \left [ p(2,10)+p(2,12)+p(2,14) \right] +49 \cdot \left [p(-7,10)+p(-7,12)+p(-7,14) \right]$

woven radishBOT
pseudo basin
#

so it seems, yes

lost laurel
#

Thanks!

#

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grizzled iris
#

Question about translation and translation vector

grizzled iris
#

When applied to a equation y = f(x)
the vector (a b) would change the equation like y = f(x -a) + b or y = f(x+a) + b?

#

Because in this lesson I was doing exercises but I messed up the order, but it marked it as correct, but the theory states otherwise, what is the correct way?

crystal dawn
#

gods why are they bringing in vectors right now

grizzled iris
#

Because they literally give me this in the theory lesson

#

OH wait

#

YOu aren't blaming me

#

I thought you are

crystal dawn
#

I have no incentive to blame a learner over a syllabus

grizzled iris
#

Ok so what are they trying to do here, because they are contradicting themselves

#

It's IB material by the way, official one

crystal dawn
#

the super simplified gist of it is that if a function is translated by (a, b), its graph is shifted by (a, b) (where positive x and y represent right and up respectively), and the translated function is represented by f(x - a) + b

#

these two are two of the four transformations I mentioned in our DMs

grizzled iris
#

Ok I understand this

#

But How do I apply vector transformation to cordinates?

#

lul

crystal dawn
#

if a point (a, b) is translated by (c, d), then the new coordinates are simply (a+c, b+d)

grizzled iris
crystal dawn
#

translation is literally just adding coordinates (or subtracting if you have a negative)

grizzled iris
#

I know

crystal dawn
grizzled iris
#

Ok so for cordinates it works normally

#

But for function input it is inverted?

crystal dawn
#

suppose I have f(x) = something

#

let's notate that something as a

#

so f(x) = a

#

eh wait sorry

#

f(0) = a

#

but the general formula is f(x)

#

now, suppose I rewrite f(x) as f(x - 3)

grizzled iris
#

Then it moves to the right

crystal dawn
#

in the original function, substituting x = 0 gives us f(0), which is a

#

but now, if we substitute x = 0 into our new function, we find that we get f(0 - 3) = f(-3)

#

so to compensate, we have to increase the value of x, aka moving right

grizzled iris
#

Holy quacks what

crystal dawn
#

in this case, right by 3 gives us x = 3, and indeed, f(3 - 3) = f(0) = a

grizzled iris
#

Uh, Me is confused

crystal dawn
#

which part

crystal dawn
#

so now suppose we want to know which value of f(x) gives a

grizzled iris
#

inverse function?

crystal dawn
#

we know that f(0) = a; keep this in mind

#

we don't care about inverses since we know key values already

#

so given the original function f(x), what must x be for f(x) to equal a?

grizzled iris
#

I don't know I am lost

crystal dawn
#

I will remind you, f(0) = a.

grizzled iris
#

x =0

crystal dawn
#

there we go

#

but now, consider f(x - 3)

#

what must x be here for f(x - 3) = a?

grizzled iris
#

3

crystal dawn
#

good

#

now, originally, the point (x, a) was at (0, a).

#

but after this translation we find that the point has moved to (3, a) (assuming we want to find a point with the same y-coordinate, namely a)

#

this is a movement to the right by 3 units

grizzled iris
#

so to have a still in the output, we had to add 3 units to the x axis?

crystal dawn
#

yes.

grizzled iris
#

Ok Im still confused

crystal dawn
#

not 3 units to the x-axis

#

but 3 units to the x-coordinate of the original point

grizzled iris
#

To input

#

I am still lost

crystal dawn
#

alternatively you can also directly see the point here

grizzled iris
#

Ok so why it's inversed?

crystal dawn
#

say you have a fuel tank in a car that's good for some number of miles when full

#

now, I empty out, say, 40% of the tank. I now ask you this: what is the amount you need to add or remove back for the tank to achieve the same number of miles as a full tank?

grizzled iris
#

60?

#

I mean 40%

crystal dawn
#

didn't know 60% + 60% = 100%

#

there we go

grizzled iris
crystal dawn
#

now notice that if the input was decreased, you will need to increase it back to reachieve a given output

#

that's the key behind why this whole "direction reversing" thing happens

grizzled iris
#

It still doesn't make sense

crystal dawn
#

similarly, if I overfilled the tank by 10% and asked you the same question, your answer would have been to throw the extra 10% away

crystal dawn
grizzled iris
#

I don't know

crystal dawn
#

or maybe a symbolic approach would help you here

#

well I don't quite appreciate random gifs in the middle of a help session

#

tell me when you're ready to proceed

grizzled iris
#

I am

crystal dawn
#

cool

grizzled iris
#

Im sorry im barely holding my anger

crystal dawn
#

then consider taking a break

grizzled iris
#

I can't

#

I have to get this

#

It's a must

crystal dawn
#

how sure are you you can get it with your current mindset? I'm not judging you or anything but I will note I have experience with learning while angry and teaching students who do that

#

and I will say neither are pretty

grizzled iris
#

Ok so I will get back in 5 minutes

crystal dawn
#

in that time one of my contacts may step in

#

just a heads-up

grizzled iris
#

No problem

crystal dawn
#

or if someone else gets to this channel before she does then listen to them Ig

grizzled iris
#

I should be beaten physically because of the amount of help I am gettgin here from random people

crystal dawn
#

there's nothing wrong with that and we would really rather not have too much self-depreciation when learning

candid maple
#

I'll park myself here for when you're ready then.

grizzled iris
#

Ok im back

candid maple
#

so as mentioned by Hanako, we can try a symbolic approach.
do you agree that for any point with an x-coordinate of x, its y-coordinate is f(x)?

grizzled iris
#

Yes

candid maple
#

so keep the point (x_0, f(x_0)) in mind.
now, consider a function g(x), defined as g(x) = f(x - a).

we know that (x_0, f(x_0)) lies on the graph of f. but this point doesn't lie on the graph of g because g has been shifted relative to f. at this point, we don't care how it has been shifted (though we will find out soon how), we just know it has been shifted.

suppose, then, we want to find the point on g such that g(x) = f(x_0).
substituting x = x_0 into g yields g(x_0) = f(x_0 - a), which gives the point (x_0, f(x_0 - a)). this is of not much use to us. but since the function f has been shifted by -a to get g, we know that we can remove this from consideration by instead substituting x = (x_0 + a). why? because then:

g(x_0 + a) = f([x_0 + a] - a) = f(x_0)

so we find that the corresponding point on g(x) is (x_0 + a, f(x_0)), and that's why the shift in input has to be opposite the direction that a is in.

grizzled iris
#

What is x_0?

candid maple
#

a random specific value of x.

grizzled iris
#

so x is x or 0

candid maple
#

x_0 is a single variable.

grizzled iris
#

Ok

candid maple
#

you can replace it with m if you want to.

#

another intuition for the same situation is this.

grizzled iris
#

substituting x = x_0 into g yields g(x_0) = f(x_0 - a), I lost it here

candid maple
#

consider a machine that converts water to, say, food. don't care how it's done, just know that this machine does it.

now, you are told that 50 liters of water produces 80 kg of food.
so if 50 liters go into the machine, then you expect to see 80kg of food out.

but now suppose I have a rule that any time you want to put water into the machine, you have to pay a "water tax" - 20 liters will be removed from what you have before it goes into the machine.

how many liters of water do you need to bring to get 80kg of food under this rule?

grizzled iris
#

70

candid maple
#

and why do you say so?

grizzled iris
#

Because it will cost you 50 Liters for the conversion, and 20 Liters for tax

#

To get 80KG

candid maple
#

what if the tax was higher, say, 35 liters taken away before it goes into the machine?

grizzled iris
#

85Liters?

candid maple
#

absolutely. now, let's get a little general.
if the tax was m liters, how much water do you need to bring, and compared to some specific value of m, do you expect to increase or decrease the amount of water you need to bring if m was increased?

grizzled iris
#

m+35

candid maple
#

(assuming you want the same output of food.)

candid maple
#

careful.

grizzled iris
#

Tax is now 35, so I need to add 35 liters anywhere if I want to get 80KG of food for 50 liters

candid maple
grizzled iris
#

Then m+50

candid maple
#

great job. now, suppose m increases. do you then expect to have to bring more or less water for the same amount of food?

grizzled iris
#

More

#

But it's getting too copmlicated I am already lost a bit

candid maple
#

good.
now, let's formalize this.

suppose the function governing the amount of food for any given amount of water x is f(x) = y.
changing f(x) to f(x - m) is introducing this "water tax". this tax reduces the amount of water going into the machine f(x), so to get back the same amount of food, we need to compensate by adding back m liters of water to the input to counteract the tax.

grizzled iris
#

It's too complicated

#

Im lost

#

Working memory overload

candid maple
#

then either consider a longer break, or consulting a personal tutor, or even playing around with some graphs in Geogebra or Desmos.
in the meantime, if you want to verify what you do and/or do not understand with me, I'm all ears.

grizzled iris
#

Ok im gonna close this ticket, copy the last explanation and sit around with it for a while, if I will have more questions I will reopen

candid maple
#

sure thing. all the best.

grizzled iris
#

Thank you

#

Im sorry

candid maple
#

you don't have to apologize. you owe us nothing.

#

I'm the one who should be apologizing for failing to help you out here.

grizzled iris
#

.close

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#
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lost laurel
#

Really silly question, but here once I find c=3/16 all I do is (3/16xy^2)/(marginal pdf) right for f_{1|2} and f_{2|1}

lost laurel
#

hello

tired surge
#

not silly

#

yes you divide joint by marginal

#

also

#

$$
f_{1|2}(x_1|x_2)=f_1(x_1), \quad
f_{2|1}(x_2|x_1)=f_2(x_2)
$$

woven radishBOT
tired surge
#

notice they’re independent

lost laurel
#

yeah

#

I did notice that

#

will be useful in the last 2 problems

lost laurel
tired surge
#

yesss

lost laurel
#

cool

#

tq

#

lemme find them rq

#

$\mu_{2 \mid 1}= \int_{0}^{2} y \cdot \frac{3}{8} y^2 dy$

woven radishBOT
lost laurel
#

which is 3/2

tired surge
#

well done

#

smart

lost laurel
#

tq

#

$\mu_{1 \mid 2} = \int_{0}^{2} \frac{x^2}{2} = \frac{4}{3}$

woven radishBOT
lost laurel
#

Independence comes in clutch here

#

it allows me to say $E[X_1^nX_2^m]=E[X_1^n]E[X_2^m]$

woven radishBOT
lost laurel
#

which helps with the last but one problem

tired surge
#

very good

lost laurel
#

tysm

#

I'll close this now

#

.close

devout snowBOT
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grave idol
devout snowBOT
grave idol
#

Is my solution correct? (Do I need to find the limit of everything at the same time or I can do it step-by-step like this)

supple knot
#

no

#

you can't take the limit of different parts of the expression differently

#

you have to take the limit all at the same time together

grave idol
#

oh

#

alr thx

#

i will try to find another solution.

#

.close

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#
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grave idol
#

.reopen

devout snowBOT
grave idol
#

can someone give me a hint or 2 on where did i go wrong.

supple knot
#

you inputted [ log(1 + 1/n) ]^n to wolfram. the expression in the problem is log[ (1 + 1/n)^n ]

#

the main thing you need is
$\lim_{n \to \y} (1 + 1/n)^n = e$

woven radishBOT
#

riemann

supple knot
#

and lim[ log(stuff) ] = log[ lim (stuff) ]

reef sail
#

i miss the days of simple lim

grave idol
#

so it will become (ln(e)) = 1 right?

native gyro
#

what?

grave idol
native gyro
#

ln(x)^y != ln(x^y)

grave idol
grave idol
native gyro
#

thats why it shouldnt be ln(e)

#

or wait

#

is it (ln(1+1/n))^n or ln((1+1/n)^n)

#

coz i think its the first one

#

so ln before ^n

supple knot
grave idol
reef sail
#

its ln am blind

grave idol
#

anyways thx yall, appreciate it.

#

.close

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#
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devout snowBOT
alpine python
#

<@&268886789983436800>

wicked rover
#

looks like the ban didnt delete this

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ebon flicker
#

You put your first 50l u get 30kg then another 50l wich becomes 60kg then you add only 40l at the end so 20l/20kg get takken out(taxes) and then you are left with 30 + 30 +20 = 80kg

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charred eagle
#

can someoen explain why the normal vector of a plane is the values before the x + y + z

charred eagle
#

like lets say your trying to find point of intersection of the line r(t) = 6i -2j + k + t(i + 2j - 4k), t belongs to R, and the plane 4x + y + 2z = 6

#

how do i do this

supple knot
#

When F(x,y,z) = ax + by + cz + d, the normal to the plane is simply the gradient and that's the vector (a,b,c)

charred eagle
#

but wouldnt the gradient be on tjhe plane

charred eagle
supple knot
supple knot
charred eagle
supple knot
#

nowhere did i say that

charred eagle
supple knot
#

if it is, you should try to prove it

charred eagle
#

no im ngl

#

i have no idea wahts going on in this planes topic

#

like im trying to udnerstand

supple knot
devout snowBOT
#

@charred eagle Has your question been resolved?

#
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#
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queen mason
#

This is Calculus 1 Optimization, is this the right thought process? From here I would simplify and then derive right?

supple knot
#

,rccw

woven radishBOT
dry oak
#

Me aswell

rich barn
#

just find the global minima for the t(x) you came up with

dry oak
#

Ye and Id recommend not calling it t(x) but call it f(x) instead cause t is a mid letter

queen mason
#

Any tips on simplifying

dry oak
dry oak
queen mason
#

Oh I can do that

dry oak
#

Ye

#

I mean its already pretty simplified

#

Just maybe split thr fraction if its easier for you

#

The second one

queen mason
#

I only ask because my teacher tried simplifying more and it did not make sense but thanks

#

.close

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restive river
#

Can someone help me in factoring

devout snowBOT
timber pebble
#

factoring what?

devout snowBOT
#

Asking the actual question right away is more likely to get responses.

Asking "Can I ask...?" or "Does anyone know about...?" doesn't give people enough information to decide whether they can help, and answering can feel like a promise to help with the actual question, which they might find themselves unable to.

restive river
#

Factoring quadratics

#

I forgot how to do it and need it for homework

timber pebble
#

can you show a problem you're having trouble with?

restive river
#

It’s many

timber pebble
#

lets start with one happy

restive river
#

Thank you a lot

#

I know this is supposed to be easy I’m just very not smart with math 🙁

timber pebble
#

do you know what you're allowed to use

#

are you supposed to just do it on paper?

restive river
#

anything but not quadratic formula

#

that’s for another question

timber pebble
#

so on the first one, do you have any ideas?

#

$x^2 + 2x - 3$

woven radishBOT
#

jan Niku

restive river
#

1st step in finding common factor and there is none so

#

idk what to do

timber pebble
#

so you know, if we can factor this, it will look like (x-a)(x-b)

#

for some a and b

#

usually when they say, factor quadratic, they mean write it like this

restive river
#

ohhhhh

timber pebble
#

(x - something) times (x - something else)

restive river
#

I did that less then a week ago but forgot

#

I’m stupid

#

How fo you do it again

timber pebble
#

this one is one we'd say uhh you'd solve by inspection

restive river
#

Like the process

timber pebble
#

what you wanna do is

#

$x^2+2x-3$

woven radishBOT
#

jan Niku

timber pebble
#

we want two numbers that multiply to 2, and add to -3

restive river
#

ohhh I remember this

#

do you do

timber pebble
#

we almost always just try small, whole numbers

#

1, 2, 3 ,5

#

things like that

#

or -1, -2, etc

restive river
#

1 x -2?

timber pebble
#

close

#

i think -1 and -2

#

since (-1) * (-2) = 2

restive river
#

Oh that makes sense

#

YES

timber pebble
#

and -1 + -2 = -3

restive river
#

thank you

timber pebble
#

do you know how to write it now?

restive river
#

And then you write it like

timber pebble
#

x^2 + 2x - 3 =

restive river
#

(X - 1) (x-2)^2

#

?

timber pebble
#

A for effort but off a little bit

timber pebble
#

we have to write it in a very specific way

#

say the numbers are a and b

#

we have to write, $(x-a)(x-b)$

woven radishBOT
#

jan Niku

timber pebble
#

here your numbers are -1 and -2

#

that means we have to write $(x - (-1)) (x - (-2))$

woven radishBOT
#

jan Niku

restive river
#

I was close

timber pebble
#

thats a lot of parens but do you get what i mean?

#

yea you were close

restive river
#

Yes

timber pebble
restive river
#

Okay so anytime you need to factor

#

with 3=0

#

you do like this?

timber pebble
#

3=0?

restive river
#

3 different coefficients

timber pebble
#

oh

#

well, we call this factoring by inspection, i htink

restive river
#

Why is there even a 0 at the end I don’t get it

timber pebble
#

this is usually the first thing you try, because its easy if it works

#

you try it by staring at the quadratic for 15 or 30 seconds and then you give up

#

and try something more complicated

#

its usually a good first thing to try no matter what

restive river
#

Should you find the common factor first tho

timber pebble
#

its a lot easier to calculate if x^2 has a coefficient of 1

#

so if you see a problem like, $6x^2 + 10x + 14$

woven radishBOT
#

jan Niku

timber pebble
#

you might not waste too much time trying to solve by inspection

#

but, a problem like $x^2 + x - 2$

woven radishBOT
#

jan Niku

restive river
#

you would want to get rid of 6

timber pebble
#

fractions are hard to deal with in your head, usually

#

wanna do your next problem?

restive river
#

It says in the book the answer is -3 and 1

timber pebble
#

oh geez sorry i bungled it

#

its been a long day sadcat

restive river
#

no worries lol I feel the same

timber pebble
#

wait no

#

-1 -3

#

it just wasnt 2

#

aoeunsh 1s

restive river
#

?

timber pebble
#

you got it

#

-3 and 1

#

bleh i thats embarassing blobsweat

restive river
#

How do you even get that answer tho I’m confused

timber pebble
#

x^2 + 2x - 3

#

we need numbers that add to 2

#

and multiply to negative 3

#

i mixed up add and multiply when i told you to do this initially

#

and then since i was reading my own post instead of the question i didnt catch your answer being off

#

you solved it correctly based on what i told you to do, though happy

restive river
#

Ohhh

timber pebble
#

add to 2

#

multiply to -3

#

3 - 1 = 2

#

3 * -1 = -3

restive river
#

so it’s 3-1

timber pebble
#

blobsweat forgive me for bungling that

restive river
#

No please don’t apologize

#

Thanks for helping me

timber pebble
#

we can look at the other one i said, if its helpful

#

$x^2 + x -2$

woven radishBOT
#

jan Niku

timber pebble
#

so we want two numbers that add to 1, and multiply to -2

restive river
#

1- + 1

timber pebble
#

but -1 * 1 = 1

lethal zinc
#

could someone help me in vc im studying calclus 1

restive river
#

obbb

#

Then

timber pebble
#

whats an easy way to make -2 using whole numbers

#

we could try, -2 * 1, or -1 * 2

#

theres only really two options

restive river
#

1- 2

timber pebble
#

so which one of them adds to 1

#

yea -1 and 2

#

since 2 - 1 = 1

#

and -1 * 2 = -2

#

so we'd write, $(x- (-1)) ( x-2) = x^2 + x - 2$

woven radishBOT
#

jan Niku

timber pebble
#

make sense?

devout snowBOT
#

@restive river Has your question been resolved?

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#
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dire hinge
#

Sketch a graph for 0 ⩽ t ⩽ 60 , labelling the endpoints