#help-27
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You're welcome
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the question is asking to find the dimensions of a rectangle of the largest area inscribed in a circle with radius 4. I am not getting the right length and I am not able to understand why
oh I think I get it. I got the length for only half the Rectangle?
i got to multiply it by 2?
yes
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can anybody calculate H here as i got really messed up in calculations
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Can someone explain to me the how to get the answer for the the last two questions. This is homework and it's like the 2nd day of school and i understand to some extent but like this stumped me 😓😓 (btw for question 16 it says the end of the 10 years and question 17 it says interest rates for the given period. Srry for the cut off)
.rotate
.rotate
caca
Do u want me to rotate for u?? 😭
.rccw
,rotate
thank you
What's rhe * for?
Ah okay ty
Okay wait I tried to do that formula and I got like 0.2 and then I scrolled to the answers
I'm lowk so confused 😭
,rccw
what have you tried
show your work
So basically for the questions 17 a) I did what rhe other dude said and did (5/100) multiply 4 and I got 0.2 on the calc but it doesn't match w the andwe
Answer*
that formula is not correct ig neither is (5/100)^4 =(5/100)*4
this is the one for compound interest
equating that with simple interest should give you the rate
What is the nt for? Also for question 17 I don't think I was given a P
n is the number of periods, here n=1 as the interest is compounded annually
dw P will cancel out as P is same for both compound and simple interest
So is P is just not in the equation anymore?
for CI = $P((1+r_{c})^t - 1)$ \
SI = $P(r_{s}t)$
Hi
it is, equate SI = CI you will see it cancels out
Whete did the s some from?? And I'm still a bit confused on what t is supposed to be?
mb mb I dont know a single thing about economy shi
Dw nor do I that's y I'm here in the first place
$r_{c}$ = rate for compound interest \
$r_{s}$ = rate for simple interest \
t = time period which is number of years her
🥀 we all bad at economics here
Hi
economy != math
Wait so if there isn't a P in the question how do I substitute the P in the formula or smth
I feel like I'm js making u repeat urself 💔
if you have a(b) = a(c) , you can divide both sides by a so a cancels out because a is common
Similarly CI = SI \
$\implies P((1+r_{c})^t - 1) =P(r_{s}t)$ (P cancels) \
$\implies (1+r_{c})^t - 1 = r_{s}t$
Hi
Ah okay
sometimes you dont need to substitue you can just work with P as P
Ty bro 🥹🫰
Question could u write out the formula but replace the letters w rhe numbers from the question
which formula
This one
Wait what?? 😓
?
here for 17a
Yes that one
you are given r_c which is rate of compound interest, and t is given as well
just subtitute that
,rccw
,calc (105/100)^4 -1
Result:
0.21550625
yh
this = r_s * t
0.215 = 4r_s
,calc 0.215/4
Result:
0.05375
so you have r_s = 0.05375
now r_s is in the form rate/100
so your rate will be r_s *100 = 5.375
,calc 0.21550625/4
Result:
0.0538765625
hm.. it is closer to 5.39
Okay wrote ts all down ty sm for being so paitent 😌
np
if you have any more doubts you can post else close this channel by typing .close
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Im a truck driver, i need to figure out some trip planning stuff. I have to drive 1050 miles, averaging 55 mph, i need to be at my destination by Tuesday at 8am. I need to take a 10 hour break after 600 miles. When should i leave to start the trip?
,calc 1050/55
Result:
19.090909090909
30 hours
30 hours before
Okay thank you
Monday 2 am
anything else you would like to ask?
Yes theres another aspect
sure. what would it be?
Driving time = Distance / Speed (use miles and mph)
Total time = Driving time + Break time
This is the general formula you can use next time
Actually no im good, i just figured it out, thank you guys
realistically though for the original travel time you'd want to add a couple of hours extra in case of traffic or something.
oh alright, you may .close the channel, and see you around1
Yeah im gonna add 5 hours of buffer so ill leave Sunday at 9 pm
Safe travels
all the best OP!
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The area of 2 circles are in ratio 16:25. Find the ratio of their corresponding circumference.
Plz help with it. I'm struggling a lot and sorry if it was too easy.
have you tried anything yet?
I can't solve it
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
Nah
so you don't know where to start.
3
oh?
can you show your answer and working then?
(that's not the same as no progress!)
My phone's camera is broken
can you rewrite it in MS Paint or whatever drawing app, or type it here?
try microsoft whiteboard
Wait
ש?
ישראלי?
I know the handwriting is a lil trash
Also it took long since my phone is laggy and I'm not familiar with ms whiteboard
If anyone is not answering I'm closing it by 9:30
I don't think you can semplify r1 with r2, since those are different varables
C=2πr, therefore 2πr1/2πr2 should be the ratio you need
You can simplify 2π and you Just gotta find r1/r2
Since you have the area πr² you have πr1²/πr2²=16/25
Semplify π you got (r1/r2)²=16/25
might wanna check in with OP to see if he knows why
Square rooth both sides ratio should end up 4/5
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
@green delta Has your question been resolved?
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Im doing number 2 and just a quick question, i got that there arent any points of inflexion since concavity doesnt change at x=0 even with y''(0)=0. Now im doing 2b and i dont know whether i should include x=0 within the interval where y is concave up
Alright, thanks!
So just in general, even if the second derative of a point is 0, if it isnt an inflexion point then it also has a concavity?
I think it can be an inflection point and still have concavity
I believe f is concave up iff f" >= 0
Convexity/concavity can be strict
So should my answer be that y is concave up through (-inf;0)U(0;inf) or (-inf;inf)?
All of R should be correct, but you may want to review the definition of "concave up" that you've been given
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Damn, that definition conflicts with pretty much every definition I can find online
@tranquil marlin if the subject interests you, you could have an argument with your teacher about it 
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How do I go on to solve this?
hmm
you should probably rearrange the equation so that the sine is left standing alone on the left first.
jus plot the graph
you would need arcsin here
The answers are so ugly.
yh assume they use calculator
,calc 3pi
Result:
9.4247779607694
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Hi, I am confused with the second part of the question. I did the first half pretty easily but the second half my proof seems very weak, im wondering if I can just make a set with 4-5 elements and show that it has an inverse and identity element but I dont know how that would apply for all.
do you know what $\bZ_4^\times$ is?
generating function shill
i think? its multiplying elements in Z mod 4?
i imagine it is the elements in {0,1,2,3} that are relatively prime to 4
oh is it? i thought it was a quick way to write mod 4
The identity element isn't 0 btw
Thats for addition
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I think youre better off drawing a Cayley table btw
The set is so small
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Good afternoon, I am teaching myself python with a text book. I am struggling with the following commands. I am getting a unique graph for each command that only shows the most recent step. For example plt.xlabel('x') displayes a graph with nothing but the xlabel labelled. The show() command is showing nothing.
<@&268886789983436800>
Keep it sfw
That includes code output
@blissful hound Has your question been resolved?
This isn't a math question
Go join a python server
dont know if someones gonna say !NOAI but chatgpt is pretty good with coding
ohk then try it on a different system
or use a different compiler online
like thonny or smth
Yes python discord server has people
Again this ain't a math question
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how do i find the maximum area of this cuboid if the 2nd derivative was positive (concave up)?
it is possible that there is no max
ok but how do i prove that then?
you only had one solution to d/dx SA = 0
one stationary point,
second derivative indicates that's a local min
(probably also shouldn't mention for maximum surface area that early)
1 divided by 0 equals Infinity
Yeah but then i disproved it by checking with the 2nd derivative
better to mention for stationary points
wait they never taught me this, what does 0^+ mean?
x approaches 0 from the positive side
so numbers like 0.01, 0.001, 0.0001 etc?
?
Ugh <@&268886789983436800> send him to the shadower realm
if x was 0.01, 0.001 etc
Sorry for interrupting anyways 0+ means you go from 0.01 to 0.001 to 0.001 etc. until it approaches/is 0
Wait a minute your eqn is wrong
Try doing 2nd derivative again, you've made a differentiation mistake there
ok lemme check again
oh wait the denominator should be a 3x^3
Also I think the questions wrong, there shouldn't be a maximum surface area
Think about it: you can stretch a cuboid to be infinitely long, so the surface area is infinite, but the volume can still be the same
@gaunt oyster Has your question been resolved?
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Hello I need help with this
How do i find out obtuse ABC?
hey this channel is occupied
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
I m really sry
ah thank u
anything else you would like to ask?
nope, thank you
alright, then you may close the channel with .close. welcome to the server and see you around!
.close
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heads-up: your asterisks are missing.
\* for *
do you intend to italicize the parts of the messages that are currently italicized or do you mean to put *s there?
if you intend to italicize whatever is italicized right now then my message does not apply and I apologize.
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How do you guys make math studying enjoyable? I found that normall studying just doesn't work for me and internal brain processes get in the way (I won't discuss that) and I need to engineer the process so that studying becomes more comfortable and stimulating.
relate it to everyday life, find uses for the math you learnt, and teach/share it to others.
Ok something more specific can I ask?
sure.
I personally love puzzel so I kinda like combinatorics, other than that you can try doing somewhat of mid-easy problems first to boost your mood
it also kinda depends on what mode of learning you prefer.
99% of people who tried to learn math memorizes the rules, but instead, you should understand why it works
Yes that's what I am trying to achieve
different people learn differently, so some people find physical activities more conducive to learning. some people learn better by seeing, some learn better by reading, etc.
yep, relate to real life like nicole said
Well currently, the only way I study math is I am getting to my worksheet set of problems, and I solve them one by one
find what works best for you and apply it.
That's what I am trying to d
so for instance
mm. this process will be an experiment though, so don't be discouraged if the first few methods you try don't work out too well.
do you know why $a = a$ for any $a$?
1 divided by 0 equals Infinity
Because equality sign?
do we really want to get into the analysis derivation of equality in this help channel...
Equality is used when 2 sides have the same value
No please im in 11 grade don't shoot me with calculus yet
anyway, you said you have something more specific to ask. what is it?
You have to admit that going everyday, to the same worksheet of problems, and just solving them one by one, occasionally asking questions here to learn something more or gooling something isn't super intersting
that's the process you have to go through
not only do I admit and agree with you, this is the reason I skip around some problems.
but I only do so if I can fully motivate and oneshot any remaining questions in the same section.
But this is the reason I avoid doing it so much
The discomfort of sitting with this stupid black white question paper and doing it one by one is super boring
im shooting to calculus as a 9th grader here
This is not how I am going to get good with math
welp, here comes the calculus despite OP not wanting it. I'll excuse myself before this turns into a shitshow then.
it's because i wanted to
No it's fine
So how you do it?
i just keep on doing it and submit the homework
If you are shooting calculus at 9th grade you possibly didn't find the worksheets as boring as me
and avoid punishment
uhh, i shoot up to calculus because i wanted to and i feel confident about my algebra skills
i do worksheets and textbooks like you do
and i hop into help channels like yours here
to improve my skills
:)
?
You do it differently/better than I do
?
So for you it's "i do worksheets and textbooks like you do"
But psychologically you are going through completely different thing than I
ngl i also do advanced class
Can you go deeper into "i do worksheets and textbooks like you do"
Add more details
💀
Infinity, I don't think you can assume everyone has the same motivation you do...
No that's serious question
you can take over
im not a specialist in this
Yes that's true
(or is that the right word to say)
I mean as a teacher I've met students who are at different levels in learning, but many of them are outliers in that they do bring their own motivation
still, I have seen some that don't find worksheets particularly interesting, at least not alone
and to be fair, I understand. I used to be subject to boring worksheets all the time too
Yes that's what I want to do
The reason is that they are going through different mental processes compared to the worse students
you're not wrong indeed.
That's the reason they can practice math for 5 hours per day and enjoy it
Because I am not, I know this because I had to research up psychology before coming here
-# oh lord, didn't expect that coming
ok, I did not expect that answer, but sure
Well, this shit is really threatening me and my future so I had to do something about it
either way, I find myself intrinsically motivated in a way that is extremely difficult to explain
Yes that's what I want to achieve
so in the interests of not speaking on behalf of those who can bring their own motivation in concrete ways, if you want to hear a better answer I'll defer to one of my students
because if you want to see my motivation
#1430149350931173417
#1463931680594329655
I am not hesitant to just rambo into fields like those knowing absolutely nothing and getting cooked by the books and the seniors in this server
as for why, I just love STEM, which is a disingenuous answer. as such I cannot promise you this answer from a student's pov
@twilit field get back here
I will say my way of motivating myself will not apply to everyone, because I already have a higher field in mind (namely, geometric measure theory and fractal geometry).
but as my bio implies, I love fractals independently of math.
the reason i think some ppl enjoy doing maths is cuz they have a strong foundations. They dont get stuck in simple things like solving a quadratic, doing some algebraic manipulations etc. And when you get good in these basic things you remove the hard part. Now you can come up with a blueprint of the solution in just your brain without writing anything.
this has led to me trying to investigate fractals intuitively first, and then when I found out that there are literal fields that do low-level research of fractals, I build a pathway to those fields.
but while working my way there, I try to think of the relationships between any exercise I do and my end goal of understanding fractals.
So Hanako is a teacher
indeed I am
You have paid extra lessons?
It would be useful to always ask "What problem was this trying to solve" whenever you are given a definition. This gives motivation to look at examples, and a sense as to why you'd care about this.
no. I teach STEM more or less for free, with asterisks.
I find math interesting as to why and for what purpose it is used
But when it comes to details to solving equations and memorizing stuff that's when it becomes little too costly
Damn everyone is having somewhat of pretty cool motivations
I wish I could have one
I have found little need to memorize most stuff actively.
What point is a set of tools if they're unable to be used?
I genuinely just do things because I can't bear being worse than my friend in Math
maybe a few key details here and there, but almost always you can reason things out from the foundational details.
at first I was like this.
Fair enough haha
then I got to know one particular person from a nearby school (I think she's a Helpful here)..
I am still like that lol
after knowing her the hope of being the best amongst my contacts in math got shattered in a way that I don't mind.
at least now I get friends to talk cool stuff with.
this could be a motivation in itself!
was it the fox
yes. 
that's fair
people are are crazy also
now I'll wait for OP before continuing.
don't want OP to come back to a huge wall of text.
take your time!
what level do you tech 
from absolute basics to whatever I know atm.
oh, ic ty
But it's impossible, the fact that I am not able to sit down on my ass and just do it and all of you guys can
There are multiple factors and underlying reasons why is this happening
I don't sit down all the time.
sometimes I'll be drawing at the whiteboard, sometimes I'd be 3D printing some fractal-related stuff, etc.
math is as much of a science than it is raging lunatics sitting and furiously penning away at proofs and reading papers.
which means you can experiment with some of the more concrete stuff in math.
doesn't apply to all of math, esp. the more abstract fields (infinite-dimensional stuff, anyone?), of course, but for most of early math this method works.
Ok so I knew nothing before joining, and i know more nothing after I am leaving

Counterintuitive interpretation of knowledge
?
I sympathize with you, but I don't know what else to say, sorry.
do you have any other questions for the channel though?
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Whats the difference between
" For any "
"For each"
"For every " .
"There exists some number n"
"There exists a number n"
"There exist at least one n "
none
When we write "there exist some number n" or any other in that part
it means ∃n but in natural language
Do we mean one specific number that exists ,
Or we mean there are some numbers
That satisfy that
"there exists some number n" doesn't mean there's only one such n i.e. there's no uniqueness implied
Usually we can pick one at random and then do stuff with it, but it doesn't mean the one we pick is special
What about "there exists 'a' number n"
it's just one of the possibly many who verifies [insert property]
again, uniqueness is not meant
if ever you want to say unique then you have to say "unique" or "exactly one" or something like that
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That is what I am trying to solve, but let's not disrupt another OP's help channel
That was posted when this was your help channel
I know,
Since that channel is closed/solved;
For the most part, you're building a set of tools with which to solve problems right?
Yes
please refrain from chatting in closed channels, as they may lock or become available without warning.
Knowing when/why those tools are used allows you to use them without having to memorise
Thanks^
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why does the textbook need to prove that $$e^{z + w} =e^z \cdot e^w$$? Isn't this true for any numbers? like $$x^{a+b} = x^a \cdot x^b$$?
LXDL
we dont know that yet at this juncture
e^z is just a formal symbol
it might as well be just a function exp(z) that we havent proved shit about yet
but here they use ht efact that e^{x+s} = e^x e^s
hence why am kinda confused
because they are assuming what they are trying to prove basically
yeah with x and s real
the goal here is trying to extend it to complex values
ohhhwait, you are syaing we only know that the formual $$x^{a+b} = x^a x^b$$ holds only when $a, b \in \mathbb{R}$?
LXDL
but here $a, b \in \mathbb{C}$? Hence need to proce separlety
LXDL
yes
LXDL
is that something that is proven, or just follows from defn?
because i have seen "proof" that use the taylor sereis of cosx and sinx
it's the definition of exponential above applied to z = ix
i see alr, so not some sort of theroem that can be derived?
it all depends on what arbitrary choice you make for your starting pt
If your starting point is the definition above, then no, it's just the definition
if your starting point is e^z = 1 + z + z^2/2 + ...
then yes it is a "theorem" that e^(ix) = cos(x) + isin(x)
In the sense that it's not trivial and has to be proven
ohh i see okay, because i know there are equivalnet defn/charactiriaiton for e^x when x is real, just wanst sure for when x is not real
ah okay, but then we can derive that e^z = 1 + z + z^2/2 .... if we use the starting point as the defn i gave (from the book)
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so they're using the inverse tan function
Technically yeah
pretty much yeah
Ditril
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but what you said is correct
and how does this give me 2tanu
when you substitute x by 2tan u
the integral simplifies to $\int du$
Ditril
what did you do
i subbed in u
do you know how you went from the first integral to 1/a arctan(x/a)?
No
do you understand integration by parts first?
1/(x+1^2)
Yes
are you sure?
i mean x^2+1
yesss
okay so how can you get the derivative of arctan from 1/x²+a²?
as in come back to something similar to it
yes
wdym yes 😭😭
oh you mean show you how
yess
For the choice as to why they chose x = 2tan(u) it really comes to practice with calculus and noticing the fact the integrand (what's inside the integral) reminds you of arctan so a substitution with tangent could lead you somewhere
wait howd they pull out $-ln(x^2 +4)/x$
Cowking
thats not the right latex but ok
integration by parts
ahh okok
you integrate 1/x and differentiate ln
I didnt notice the first step was IBP
gulp
it is probably easier to the second step without the trig sub
i know
no reason to substitute like that when we know arctan
but it works even if it complicates it
where did the 2sec^2(u) go
sec is 1/cos right
sec^2 = 1/cos^2 = 1 + tan^2
oh right
yuh
so $$\int 1 du$$
InterGalactic
oh welp
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bro
U gotta post ur question
factor out (x+3) first and then go from there
I lowkey forgot how to do the division ngl
It’s been a while
bro js help me
Since there’s only one possible answer where it’s (x+3)(factored poly)
lol we can’t just give u the answer
Do this ^ or long division it doesn’t matter I’m pretty sure
how would you change 27
idk
whats 3x3
9
how bout 3x3x3
27
its 3^3
so change x^3+3^3
and see the formulas
check if each is right
i see only one right
ok
how do i change x^3+3^3
wait
Can you organize the four equations
wdym
k
yes
put it in the equation
is 1³+3³=(1+3)²(1-3)
this is the first equation
ok
is it right?
no
no
idk what pemdas is sorry
yeah
what is 1²
1
what is 1×3 then
3
what is 3²
9
(1-3+9)
7
yeap
no
?
(1+3)(1-3+9)=?
got it?
ye
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✅ Original question: #help-27 message
how many zeros total
4
wait
whats a double zero
2 zeros?
im in 6th grade btw
which is why this hard for me
wait how can this be answered? there could be irreducible factors
ye
how old are you, if I may ask?
im in alg 2
2 things. how old are u. is this conclusive information
you don't have to send the question twice
this is kinda ambiguous
??
if there are no other zeroes and no irrediucibles, then the number of zeroes is the degree of the polynomial
quadratic factors with no real roots
as I see it, yes.
again, assuming those two conditions
i think so too
what have you learnt about complex conjugates?
then you might wanna revise the material before attempting the quiz...?
thats what im doing now
I mean, you can't review what you haven't studied, but I digress
yea im just tryna get help rly
a complex conjugate of a complex number a + bi is the same number with the sign of the imaginary part flipped
so a + bi becomes a - bi
ok
normally it's more productive to learn the material, then come here if you don't understand the material, cuz teaching is a rather tall task for a text help session
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Hello, i translated the question and hope it still makes sense and is correct
I think got the solution for the determine how many black balls needs to be added which is 13 i think
but im not quite sure
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heyy can someone help me out with this please
i really dont even know how to read a question like this, so 1 i dont even know how to start
- says something like "give one value of x such that x = g^-1(1)"
do you mind explaining how to read it like that please?
im so sorry you might need to gently teach this to me
"give one value x..." tells you what you're ultimately looking for
"x = g..." is the thing you're solving
ohhh ok
they could've used more words I guess, but what they have is reasonable enough
then what is that long line with the subscript mean
"evaluated at"
i dont understand why its g inverse yknow? like what does that mean and how do i use that for g(x)
i'm not sure how to answer "why"
mm like i dont see g inverse on the graph, or i dont understand how to see it
they haven't drawn the inverse, but you don't need its graph
what you need is to answer this question
you can at least solve q2
im truly sorry and i hope you're not getting frustrated but i genuinely dont know how to tackle this question, like i really need extra supprt
so idk how to solve q2
oh we didn't finish q1 yet oops
you know that g(x) = 1, so you should find such an x
look at the graph, it's easier than you think
0.136
haha okay thank you
oh its 1
how to do 3?
oh nvm
its just findn slope
wait but of which values
??
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<@&286206848099549185>
no worries! im confused on how to read 3?
like i think the first value is the coordinate (1, -7.925)? but idk
okay so do you know the inverse derivative formula
no...
right lol
if a point (a, b) is on the y = g(x), then (b, a) is on the y = g^ -1 (x)
and if the slope of g at ( a, b) is m,
then the slope of g ^ -1 at (b, a ) is 1/m
so you apply these things
to your graph
you see the red point
(0.136, 1) on g(x) will be (1, 0.136) on g^ -1 (x)
um no the the slope
so when you see g prime of 0.136 equals 5.968 its the derivative of g
from the blue curve
so when you look at the blue graph at x= 0.136, you see the point (0.136, 5.968)
that's what this is saying
okay yeah, then how do i apply that to question?
like am i finding the slope of the blue line now?
you are just using that to figure out the slope of red line
you take the reciprocal
you think you got it now?
no im sorry its still alittle blurry
do you mind providing like the equation and what to plug in? and reciprocal?
um so you wanna find the slope of y = g^ -1 (x) at point (1, 0.136)
find the matching point on g(x): (0.136, 1), then read the slope of g there, and then take the reciprocal
idk how to explain more 😭
no but like how do i "read" the slope of g? like is there an equation to do or am i manually going to count on the graph?
like i understand i have to find the slope but the question is how, like i know how to find a slope with two coords, but its only one coord
this is pretty hard to do without the formula 😭
let me think for a minute and see if there is an equation
I think you can just interpret the graph
oh thats so weird, i assumed every problem wants you to find a slope with an equation yknow? like i would think manually reading the graph would be innacurate?
yeah you kinda have to use the inverse derivative formula but without it, we can just do it manually
and I don't think it's inaccurate
think of it like this
the inverse function is just flipped over the line y=x. So the tangent line flips too. when a line is flipped over y=x, its slope becomes the reciprocal
you understand this right
okay so one coord is the (0.136,5.968) and i look for ones that pass through a corner so like (0.5, 3)
oh okay so i just flip the slope, okay i get it
from the graph, on g: point is (0.136, 1) slope there is 5.968, so on inverse g, point is (1, 0.136), so flip the slope then it will be 1/ 5.968
you got it? nice 😊
okay 5 and 6 are the same so i just need help on 4 then ill be done
whats the diff between this and 3?
number 3 is the slope and this is asking for the whole line
tangent line
so point on g^-1 you plug them into point slope form, then you got it
this was pretty hard ngl 😭
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can anybody solve this
Expand using a2-b2
yh
!noans
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we cannot provide solutions
use the symbol ^ for exponents
Mb
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wait
not how it works you were late
so i will have to reupload
what have you tried
yeah
"what have you tried" is not a yes/no question
but i got the soln which didn,t match the options
can you show your work
ig he was about to type regarding that, that's how people tend to type sometimes
i basically applies a-b*a2+b2-ab
identity
then used cos2theta identity
hey anybody there listening
use brackets
sorry
did you miss brackets and ^ or what
yeah proceed then
or youna bot
also that is only half of the thing 
the final answer?
can you show the full form of this identity, including the "=" sign
i strongly strongly suspect you misremembered it and so may have applied it incorrectly, or maybe it is even the wrong identity to use at all
oh wait yeah
what did you do
BUT MINE IS NOT MATCHING
READ THE PREVIOUS CHATS
you never showed what you did
WHY
why what.
as an expansion of what
ye this is wrong +ab
WELL i told you my approach
and where is any cube in the original q
wdym
oh fuck mb i did 2^3
i am questioning execution, not approach
well le me try again
what
so there were 2 things wrong in your approach
- it doesnt work here
- the formula is wrong as well
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hi i need help in this. i want to find the limit of the given equation without hopital rule, just simplification. can anyone tell how?
my first instinct is to multiply by the conjugate of the denominator.
i did, but that results in complexer square roots at the numerator
but i still get 0in denominator
Some of the factors here do simplify to x^3-a^3 or x^3+a^3.
But I don’t see how this will help
btw answer is in terms of a
You don't have to expand $(\sqrt{a+x}+\sqrt{a-x})$ in the numerator
cupcake
Try multiply both num and denom by $(\sqrt{a^2+ax+x^2}+\sqrt{a^2-ax+x^2})$
cupcake
but ill get 2x in denominator, 2x=0 which is not good
Yeah the 2x in denom is indeed annoying
lemme try the other one
But this would get rid of the 2x
OH SHIIII
Just plug x=0 lol
Ty
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yea this one is solved correctly (if repletion is allowed)
