#help-27

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drifting sierra
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.reopen

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drifting sierra
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@proven oriole I forgot to tie it back to the first step I made you do

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This

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You found both solutions, 1 and 3, but you need to check whether they satisfy those preliminary conditions

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In this case, they obviously do, both x=1 and x=3 satisfy x >= -1/8, but in the future you might encounter exercises where it gets slightly more complicated

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Anyway, that's pretty much it

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chrome gyro
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@fast garden

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channel closed

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pseudo basin
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@chrome gyro do you have a math question to ask right now

chrome gyro
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yes

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we were
Mid conversation

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the channel closed

fast garden
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?

chrome gyro
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I do

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how would I do this in the triangle method rather than the parrelolgram

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@fast garden

fast garden
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np

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so you find out "how much" force you have in 2 perpendicular directions

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that way you can result them in 2 different directions

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as a result, you have 1 final triangle

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and from there you can work out the total force and angle

chrome gyro
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Can you draw it

fast garden
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yh give me a few min, i just finished cooking dinner

fast garden
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something like this

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does it make sense?

chrome gyro
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noooo

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I meant how can I do it as a scale diagram

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like this

fast garden
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oh i see

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this is basically just the same as the parallelogram but with just one side

chrome gyro
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How would I draw it in this case

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Can you do it and show me

fast garden
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just imagine moving one of the arrows you drea earlier to the tip of the other

chrome gyro
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How would I do it becuase it goes left

fast garden
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there is not much more to it

chrome gyro
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But I can’t

fast garden
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why?

chrome gyro
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becuase one triangle is facing left whole other is down

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could you show me what you mean please

fast garden
chrome gyro
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oh woahhhhh

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now I connect the line starting from 20?

fast garden
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yes

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stiff karma
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Does this give us intersection with y axis?

faint gorge
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it can give intersection with the two lines or none if they parallel

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and not identical

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you would have to try x=0 to really see if they intersect at the y-axis

civic umbra
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What's the question? what language is it?

stiff karma
dusky parrot
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-x + 2 = -2x + 1
-x +2x = -2 + 1
x = -1

stiff karma
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@dusky parrot

ocean gale
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!nosol

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Ahh why won’t it work

stiff karma
dusky parrot
stiff karma
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It’s not a statement for this specific

civic umbra
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If it means the y coordinate of the solution of both of these equations, then 3

stiff karma
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Situation

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But like overall

dusky parrot
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y = 3

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x = -1

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Intersection Point is
(-1, 3)

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the equation is not giving the y axis answer

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but the x axis answer

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and from the x axis we can get the y axis

stiff karma
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system of equations is basically a function?

dusky parrot
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wdym

stiff karma
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What does it give us?

dusky parrot
civic umbra
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There should be something wrong with the question. Maybe because of the translating in other another language??

dusky parrot
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Can you send image of the whole question? @stiff karma

stiff karma
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It’s basically not a question

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I just want to understand what systems are

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@dusky parrot

dusky parrot
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ok so a system of equations is a collection of two (or more) equations that share the same variables the goal is to find a single set of values for those variables that makes every equation in the system true at the same time

dusky parrot
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ok

stiff karma
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When I can create it into an systems

lunar sandal
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hi guys

dusky parrot
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ok

stiff karma
dusky parrot
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so if we have

willow helm
dusky parrot
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y = x + 1
y = -x + 2

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!nosols

devout snowBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

stiff karma
lunar sandal
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who do you guys watch on youtube that explains domains and ranges well pls

dusky parrot
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wait

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im typing

fossil locust
willow helm
lunar sandal
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idk if im overcomplicating it or my teacher didnt explain it well

ocean gale
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!nosols

devout snowBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

lunar sandal
ocean gale
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Ohhhhhhh

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M

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K

stiff karma
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!nosols

devout snowBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

willow helm
lunar sandal
willow helm
fossil locust
stiff karma
dusky parrot
#

if we have a system like that:
y = -x + 2
y = -2x + 1
the x must be -1
because if we put it in the system equations we will get
1 + 2 = 3
and
2 + 1 = 3

lunar sandal
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i didnt understand now i do

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sorry

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thank you

dusky parrot
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but the x cant be 1 because it will not fit in the system equations

dusky parrot
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in a graph

stiff karma
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Show me example when you use it

willow helm
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Otherwise you construct your own

stiff karma
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And when you change it to system

willow helm
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For all kinds of things

stiff karma
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That’s the point

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Don’t need to show me how to solve it cause I know

dusky parrot
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ok

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you need to first identify your unkowns

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like x or anything else

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or y

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and define the relationships

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and then assemble the system

stiff karma
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Ok

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Do it

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So I understand

civic umbra
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For basics, what a system of equations represents: if you take two equations that have their own sets of solutions for each value of Y at X, and both equations are part of a system. Then the solution for the system of equations will be the intersection of both sets (solution of both equations).

stiff karma
#

.close

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minor junco
#

guys is dy²/dx² same as minimum and maximum?

minor junco
willow helm
woven radishBOT
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USS-Enterprise

willow helm
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d^2y, not dy^2

fossil locust
minor junco
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so the 2nd why do I use it?

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ik the 1st to get the gradient

fossil locust
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the 2nd derivative tells you the concavity, so whether the function looks like a smiley face (+) or a frowny face (-)

minor junco
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tysm

fossil locust
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no worries!!

fossil locust
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rustic jetty
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Rewrite as an expression without a fraction $$\frac{\csc(x)}{1-\sin(x)}$$

woven radishBOT
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dork9399

rustic jetty
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I'm not sure if this is possible

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or i might js be blind

fossil locust
rustic jetty
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yeah i did that

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that gives (csc+1)/cos^2

fossil locust
rustic jetty
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oh

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.close

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keen wind
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lucid rock
#

doees anyone know how to apply lagrangian operators for solving a linear SVM using DUAL mode?

lucid rock
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I am absolutelylost

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I know only primal mode

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@lucid rock Has your question been resolved?

small inlet
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<@&268886789983436800> is it concerning that this person's server tag is suspicious

lucid rock
lucid rock
upper schooner
lucid rock
upper schooner
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jagged heron
#

Can someone help me find the ARIMA of this ACP and PACF

jagged heron
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I know has d above 1

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since the acf is all 1's practically

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jagged heron
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<@&286206848099549185>

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@jagged heron Has your question been resolved?

jagged heron
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nope

uncut crow
jagged heron
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@jagged heron Has your question been resolved?

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quiet jackal
#

Can someone explain for me why the underlined portion =0?

quiet jackal
#

From what I can tell, the fourth term should be omega subscript y, is a typo

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Never mind, was specified in the question that those commute to 0

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pseudo basin
#

have you done riemann sums before

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severe prairie
devout snowBOT
severe prairie
#

how wld yalldo this

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do i deadass have to differentaite arsech(x+1/2)

fossil locust
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this should be in your formula booklet though

fossil locust
severe prairie
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i found

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this

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sry

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i think i got tha tpart

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but i got another enquiry

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for b

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so like

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im finding y(0) rn

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and turned it into coshy(2)

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and i moved it to e^x nd got 2+-sqrt3

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but theyre both positive

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so how dik which to pic

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aa nm

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nvm

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the - gives a - ln

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for a i got

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coshy is (x+1/2)^-1

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and sinhydy/dx is that

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so like

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how do i use that

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is 1st derivative the coshy

devout snowBOT
#

@severe prairie Has your question been resolved?

severe prairie
#

<@&286206848099549185>

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sm1 please help me

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im deadass tweaking

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how do i find y’(0)

steel sage
#

x+1/2=sech(y)
derivative both sides
1=sech’(y) y’(x)

severe prairie
#

it turns into this no

steel sage
#

Yeah, you said you wanted y’(0), now you have it

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severe prairie
devout snowBOT
severe prairie
#

how do i have it

steel sage
#

y’(x)=1/sech’(y(x))

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lost laurel
#

This notation is kind of confusing me

devout snowBOT
lost laurel
#

$\mathcal{O}= \mathcal{O_{\Q(\sqrt{D})}}$?

woven radishBOT
stone stump
#

so much for one more problem

fast garden
#

just your ring of integers of Q(\sqrt D) and they wanted to write it shorthand as \mathcal O

lost laurel
#

noted

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thanks

#

.close

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fierce matrix
devout snowBOT
fierce matrix
#

∀A,(x:1→A,f:A→A)
⇒ ∃! h:N→A s.t. h∘o=x ∧ h∘s=f∘h.

A=N′
⇒ h:N→N′, symmetric k:N′→N.

unicity
⇒ k∘h=id_N ∧ h∘k=id_N′ ⇒ iso

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tribal void
#

In statistics and probability, why are proofs and definitions often multiple equalities at once? Should I read it as "these are all basically the same" or should I read it as a left to right break down of reducing the equation? Example is attached.

vital edge
#

In this specific case, the idea is that it's symmetric

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A ∩ B is the same as B ∩ A

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So the order doesn't matter

tribal void
#

Omg thank you, I was so confused

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Thanks!

rain summit
#

!done

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tribal void
#

.close

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devout glen
#

hey need some help on this problem!

devout snowBOT
devout glen
#

for finding the derivative? i understand you make the exponent 1/2

#

but would it look like

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$\frac{2h^(1/2)}{|g|}$

woven radishBOT
sand quarry
#

No, it would not be

devout glen
#

oh gosh it looks bad

sand quarry
#

the square root applies for the entire term

devout glen
#

ohh okay

sand quarry
#

with what you wrote, you are only applying it to the h variable

devout glen
#

ohh so they would all have the exponent 1/2?

#

so like

sand quarry
#

,, T(h) = \3{\4{2h}{\abs g}} = \8{\4{2h}{\abs g}}^{1/2}

woven radishBOT
devout glen
#

ohh

#

ok

#

then how would i go from there?

#

quotient rule?

sand quarry
#

no

celest frigate
#

Separate the constants

devout glen
#

how so

sand quarry
#

use the property [
\3{ab} = \3a\2\3b
]

woven radishBOT
devout glen
#

sorry! how do i do that

sand quarry
#

in [
\8{\4{\0b2h}{\0b{\abs g}}}^{1/2}
]
you can notice that the highlighted terms are constants, yes?

woven radishBOT
devout glen
#

ok yeah

sand quarry
# woven radish

your goal is to separate the square root into two, using this identity, such that the constants are all in one square root and the variable, h, is in the other

devout glen
#

oh like

#

$\frac{2^{1/2}}{|g|^{1/2}} * h^{1/2}$

woven radishBOT
devout glen
#

oh yess i got it

sand quarry
#

nailed it

#

so

#

what is [
\dv x(a\3x)
]
where $a$ is a constant

slate peak
woven radishBOT
devout glen
#

wouldnt i use chain rule or something?

sand quarry
#

you would not

devout glen
#

idk! sorry

pseudo basin
#

which is to say, no

devout glen
#

lmao!

pseudo basin
#

if you know how to differentiate 5x^3 then you also know this one

sand quarry
#

use the property of derivatives where [
\dv x (af(x)) =a\2\dv x(f(x))
]

woven radishBOT
devout glen
#

well 5x^3 is 15x^2

sand quarry
#

where, again, a is a constant

pseudo basin
devout glen
#

oh yeah

pseudo basin
#

anyway,

#

power rule

devout glen
#

ohhh

pseudo basin
#

constant multipliers stay intact always

devout glen
pseudo basin
#

task failed successfully

#

product rule is mega overkill

devout glen
#

ohh sorry i mized up power and product rule

pseudo basin
#

read what lex said, read what i said...

devout glen
#

would it turn into

#

$\frac{1^{\frac{-1}{2}}}{|\frac{1}{2}g|^{\frac{-1}{2}}} * \frac{1}{2}h^{\frac{-1}{2}}$

fiery cape
woven radishBOT
#

Weaboo Jones

mystic scarab
woven radishBOT
devout glen
devout glen
mystic scarab
faint zinc
#

$\dv{x}(\sqrt{x}) = \frac{1}{2 \sqrt{x}}$

woven radishBOT
#

OmnipotentEntity

faint zinc
#

for clarity

devout glen
#

im soo sorry, im not processing it

#

yes yes

faint zinc
devout glen
#

no like how would i use that for my problem?

#

im truly so lost in this class, so for some formulas imma need some extra assistance 😭

faint zinc
#

\begin{align*}
\qty(\frac{2h}{|g|})^{1/2} &= \qty(\frac{2}{|g|})^{1/2} \sqrt{h} \
&= a \sqrt{h}
\end{align*}

woven radishBOT
#

OmnipotentEntity

devout glen
#

how come h turned into a square root?

faint zinc
#

\begin{align*}
\qty(\frac{2h}{|g|})^{1/2} &= \qty(\frac{2}{|g|} h)^{1/2} \
&= \qty(\frac{2}{|g|})^{1/2} h^{1/2} \
&= \qty(\frac{2}{|g|})^{1/2} \sqrt{h} \
\end{align*}

woven radishBOT
#

OmnipotentEntity

faint zinc
#

@devout glen does the above make sense?

devout glen
#

ohh

#

ok

#

ohhh wait, i didnt know equations to the power of one half become square root

#

okay i now know that

#

thank you!

faint zinc
#

you're welcome!

devout glen
#

ok how do i go forward

fiery cape
#

Do you see why g is treated as a constant and so you don't have to use the product rule or anything with it?

sand pumice
devout glen
#

mmmm okpandahmm

#

thank you!

faint zinc
devout glen
faint zinc
#

can you walk me through it?

devout glen
#

the first part?

faint zinc
devout glen
#

ohh mkay like 2?

faint zinc
#

part A. Find the derivative of T(h), T'(h).

faint zinc
devout glen
#

ok

fiery cape
devout glen
#

okay so from square root 2h over |g|, it becomes 2h over |g| to the power of 1/2, i take out constantsnand im left w/

#

$\frac{2^{1/2}}{|g|^{1/2}} * \sqrt{h}$

woven radishBOT
devout glen
#

yeah?

fiery cape
#

looks good

devout glen
#

then thats it?

#

thats the answer to a?

mystic scarab
#

This is only the original function, isn't it?

#

You still need to find the derivative

devout glen
#

oh okay

#

do i use power rule for everything? or like quotient rule for the fraction and power rule for h?

mystic scarab
#

The fraction √(2/g) is just a constant...

#

You can take it out

mystic scarab
#

You only have to differentiate √h

devout glen
#

then im just left with

#

$\frac{1}{2}h^{-\frac{1}{2}}$?

woven radishBOT
fiery cape
# woven radish **evan**

Yes, that is how you differentiate the h part, but the constant part is still multiplied to that. For example, think about differentiating 3x^2. You don't just get rid of the 3, it stays multiplied to the derivative of x^2, i.e. 3 * (2x) = 6x.

#

In other words, the derivative of a constant c multiplied by function of x f(x) is just c multiplied by the derivative of that function

#

$\dv x (af(x)) =a\2\dv x(f(x))$

woven radishBOT
#

Weaboo Jones

$\dv x (af(x)) =a\2\dv x(f(x))$
```Compilation error:```! Undefined control sequence.
l.49 $\dv x (af(x)) =a\2
                        \dv x(f(x))$
The control sequence at the end of the top line
of your error message was never \def'ed. If you have
misspelled it (e.g., `\hobx'), type `I' and the correct
spelling (e.g., `I\hbox'). Otherwise just continue,
and I'll forget about whatever was undefined.

Preview: Tightpage -1310720 -1310720 1310720 1310720
[1{/usr/local/texlive/2023/texmf-var/fonts/map/pdftex/updmap/pdftex.map}{/usr/l```
devout glen
#

wait so how do i apply this to my equation?

#

so i multiply my h with the fraction?

devout glen
fiery cape
#

Yeah the formatting is a little weird

devout glen
#

like how would i know to use this formula?

fiery cape
fiery cape
#

I'll clear it up in a second

devout glen
#

$\frac{1^{-\frac{1}{2}}}{\frac{1}{2}|g|^{-\frac{1}{2}}}$

woven radishBOT
devout glen
#

?

devout glen
#

like how

fiery cape
#

We got to this part right?

#

Sorry wrong pic

toxic rain
#

Can sm reply to the og question?

fiery cape
toxic rain
devout glen
#

ok yeah

fiery cape
#

The left part (2/g) is a constant, and the right is a dependent on h

#

So the derivative looks like this

#

Because the derivative of a constant times a function of h is just the constant times the derivative of that function of h

devout glen
#

oh? okay so i just put a variable for the fraction?

fiery cape
#

Now you can replace c with what it was originally

#

I used c just to clarify that its a constant part

devout glen
fiery cape
#

This is your final answer. And yes, its different because the h part is differentiated

devout glen
#

$\frac{2^{1/2}}{|g|^{1/2}} * \frac{1}{2}h^{-\frac{1}{2}} $

#

ohh okay

#

thank you

#

and i could just leave it like that?

fiery cape
#

You could make it a bit nicer just with some algebra

devout glen
#

how so

fiery cape
#

For example, switch the ^1/2 back to square roots

#

Put the 1/2 in front of the equation instead of just before the h

#

I dont think its necessary though, since you arent really using the equation for the rest of the problem

#

Aside from plugging numbers in for h

devout glen
#

ohh ok

devout glen
fiery cape
#

First of all, what are the units of T?

devout glen
#

seconds

fiery cape
#

And what happens to the units when you differentiate with respect to some other unit?

For example, if I take a displacement (in meters), and differentiate with respect to time (in seconds), what are the units then?

devout glen
#

im sorry i have no idea

lilac moat
#

$$\dfrac{\mathrm dy}{\mathrm dx} = \lim_{\Delta x \to 0}\frac{\Delta y}{\Delta x}$$

devout glen
#

instant slope

woven radishBOT
#

gfauxpas

lilac moat
#

seen this before?

devout glen
#

umm im pretty sure but i cant explain it to you

lilac moat
#

$$\frac{\Delta y}{\Delta x}$$ is slope

woven radishBOT
#

gfauxpas

lilac moat
#

rise/run

#

when you look at it instantaneously, it still has the same units

#

the units of slope

devout glen
#

okay im sorry, this has gone a lot longer than i expected and i still need to study for my other exam, ill have to come back for this questin

#

okay yeah slope

lilac moat
#

so

#

"per (whatever unit x is in)"

#

function of x, per x

#

function of time, per time

devout glen
#

so meters over seocnds?

#

seconds over time?

fiery cape
# devout glen im sorry i have no idea

Basically, if if you take a function in one unit, and differentiate it by another, you "divide" them. I.e., meters differentiated by time becomes meters/seconds

devout glen
#

oh okay so its meters over seconds?

fiery cape
#

The reverse, because our original unit is time, and its being differentiated by h which is in meters

#

So seconds/meters

devout glen
#

okay

#

alright thank you!!

#

.close

devout snowBOT
#
Channel closed

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devout snowBOT
#
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fading sundial
#

I have $$\lim_{n \to \infty} (\frac{n^2}{\sqrt{n^3 + 4n}})$$ and I want someone to check my work

woven radishBOT
fading sundial
#

wait its uploading hold on

ionic harness
#

Looks good to me, I know some textbooks would have 1/0 as lim = infinity and some use 1/0 as lim = DNE

tender cobalt
woven radishBOT
crimson tundra
fading sundial
#

thanks guys :) i think the more correct answer should be infinity though so ill use that instead

#

.close

devout snowBOT
#
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quartz nova
#

Can someone check my work

devout snowBOT
deep abyss
#

Ques?

quartz nova
#

solving for lambda and theta

#

in terms of x and y

#

i didnt plug in a and h for the sake of simplicity/neatness

devout snowBOT
#

@quartz nova Has your question been resolved?

mint cairn
#

Where is the original question?

quartz nova
#

I mean ill just try to recite it to the best of my ability. Its an inverse kinematics question if it helps. You have limbs l1, l2, l3 that are lengths 79, 25, 77, respectively. L1 is anchored to (0,0) and the end effector is at point (x,y). You know that l3 and l2 are at a fixed 90 degree angle. Find the angle between l1 and the "floor" (x axis) and the angle between l1 and l2 - 90 degrees

#

@mint cairn

mint cairn
#

You got a picture?

#

Or is it worded?

quartz nova
#

well its my diagram

#

i drew in my photo

mint cairn
quartz nova
#

Ye

#

but uhh i drew the diagram

#

above if it helps

mint cairn
#

Okay.

quartz nova
#

Ye it isnt

mint cairn
#

Sorry.

quartz nova
#

hmm?

mint cairn
#

I just saw the l3...

quartz nova
#

ohh no thats mb

#

i accidently wrote it wrong

#

but ye

mint cairn
#

Let me visualise it myself then.

quartz nova
#

I just decomposed it into a 2 limb problem

#

Ok thx

mint cairn
#

So.

#

l2 and l3 are perpendicular to each other...

#

At where?

#

The end effector of l1?

quartz nova
#

So they're all connect at the ends of the limbs

#

l1 connects to l2 which connects to l3

#

basically image a line segment that has 2 points on it

#

that divide it into 77 25 and 79

#

segments

#

each of those points allow the segments to rotate

#

but you know that 77 (l3) and 25 (l2) "joint" is fixed at 90 degrees

#

sorry for the poor wording

#

from memory so

mint cairn
#

So basically it should look like this right?

#

l1 touches (0,0)

#

l2 touches end of l1 with length 25.

#

And l3 joins perpendicularly at the end of l2 with length 79.

quartz nova
#

Yes

#

wait

#

but l3 is 77

#

and l1 is 79

mint cairn
#

Oh typo.

#

It is 77.

#

My brain.

#

So what are we solving for again?

#

Angle between l1 and x axis.

quartz nova
#

2 things

#

angle between l1 and x axis

#

and angle between l1 and l2

#

subtract 90 degrees

mint cairn
quartz nova
#

uhh ye it is

#

its like the problem isnt exactly that

#

but like it boils down to that

mint cairn
quartz nova
#

Yes

mint cairn
#

Like this?

quartz nova
#

Umm yes assuming that that point is 77 away from the l2l3 joint

mint cairn
#

I hide the circles to make it less confusing.

#

Okay.

#

Let me try now.

quartz nova
#

ight

devout snowBOT
#

@quartz nova Has your question been resolved?

mint cairn
#

Alright...

#

I actually don't think you can express it in terms of x and y only...

#

Like the whole system is not even unique...

mint cairn
quartz nova
#

Ok thx

quartz nova
#

Well alright

#

.close

devout snowBOT
#
Channel closed

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devout snowBOT
#
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cerulean violet
#

Can someone help with this?

devout snowBOT
cerulean violet
#

I just can't figure out how to solve from the very starting, I can only find out the general term

rough nova
#

With this kind of problem, you want the "coefficients" (n²+1) to be expressed in terms of (n-1) and (n+1) so that the adjacent terms cancel each other out

#

Can you do that?

devout snowBOT
#

@cerulean violet Has your question been resolved?

#
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devout snowBOT
#
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agile garnet
#

im tryna plot thomae function

devout snowBOT
agile garnet
#

when i tried to confirm online

#

i was wrong

#

so now i wanna understand the graph

sand pumice
agile garnet
#

yeah but why s it tending to 0 at 1

#

oh

#

nvm

#

ohh

#

i got it thx

#

.close

devout snowBOT
#
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devout snowBOT
#
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agile owl
#

Any hint for 59

devout snowBOT
agile owl
cold haven
#

,rccw

woven radishBOT
cold haven
#

!status

devout snowBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vale swallow
#

help

dense raft
#

l

devout snowBOT
# vale swallow

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

cold haven
agile owl
#

Is it rlly the only option

#

😢

cold haven
#

IBP is not the only option, but any other effective method is really equivalent to IBP or more cumbersome…

#

@agile owl

agile owl
#

Will try it then

cold haven
devout snowBOT
#

@agile owl Has your question been resolved?

#
Channel closed

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#
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warped beacon
#

How do I find the probability of something not happening?

My question is if there are 5 white marbles and 20 non white marbles, what are the chances of pulling at least 1 white marble when picking 5 randomly.
I know that I need to find the probability of finding no white marbles and then reverse it, but I’ve forgotten how to do that.

So far all I’ve done was make a combination of (25, 5) to get a total of 53,130.

lilac crescent
#

How do I find the probability of something not happening
i mean if its not happening , then its probability is 0
||didnt read the rest of the question||

rare kernel
warped beacon
#

Yee

urban harbor
onyx torrent
warped beacon
#

If not that’s fine, I’ve been overthinking it a lot

urban harbor
#

well its easier to see where the formula comes from when you do the multiplications together, yes you can write it in terms of some factorials

#

but those fractions make immediate intuitive sense right? see if you can write out the multiplications and consider how you'd write it in terms of factorials for the general case

warped beacon
#

Yee

rare kernel
#

x=number of successes

#

n=number of attempts

#

and p = probability of success

warped beacon
warped beacon
#

I don’t recognize it at all either…

rare kernel
#

ok take 1-p = q where q is probability of failure

#

then the expression that u see there is

#

general term of (p+q)^n

#

if u know binomial theorem

warped beacon
#

I don’t think I do

rare kernel
#

then i cant help u

#

but u asked for a formula

#

and there it is

warped beacon
#

Shit KleeTired

#

Well thank you for trying, I appreciate it

daring mesa
#

The formula... well, it seems overkill for the problem we're asking to solve.

warped beacon
#

Do you know of a simpler option HoVCookie

daring mesa
#

We're trying to find the probability we pull at least one white marble, right? As you noted, it's probably easier to relate this with another probability, that being that we pull no white marbles.

warped beacon
#

Yee RazorCrown_Devonxy

daring mesa
#

How would we calculate that second probability? How would that help us find the probability we're asking for?

warped beacon
#

Well it would be the probability of finding no white marbles -1

#

Or

#

1-no white marbles

#

And then we would have the probability of at least 1

#

I just don’t know how to find the probability of no white marbles

daring mesa
#

Is there a combinatorical way we could think about finding that probability? That is, can we count the number of 'favored outcomes' vs. the number of 'total outcomes'?

warped beacon
#

Well I know the total outcomes are 53,130

#

But I’m yet to find out the number of favored outcomes

daring mesa
#

How did we compute the number of total outcomes? Why so?

warped beacon
#

Combination of (25,5)

#

And I did it because I knew I’d have to compare total outcomes to desired outcomes

daring mesa
#

What does a favored outcome look like?

warped beacon
#

No white marbles

daring mesa
#

If we have no white marbles, then what else would be true for any given outcome?

warped beacon
#

All non white marbles.
I’m sorry but is this going anywhere?

daring mesa
#

Yes. How many ways can we pick all non-white marbles? (It'll be similar to the way we computed the ways we can pick any kind of marbles)

warped beacon
#

Ok I feel like you’re hinting at a combination but it’s not clicking in my head how that’ll work

#

There’s no way it’s just (20,5) right???

daring mesa
#

Why not? We have 20 black marbles, and we're picking 5 black marbles from them, right?

warped beacon
#

… well shit

#

So I just do that

#

Which hold on lemme get what that is

daring mesa
#

I suspect you have a good path from here catthumbsup

strong cypress
ionic harness
#

!occupied

devout snowBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

strong cypress
#

Oh sorry

warped beacon
#

So if I’m doing this correctly, the probability of finding at least one white marble is 37626/53130

ionic harness
#

,calc 37626/33130

woven radishBOT
#

Result:

1.1357078176879
dull parrot
#

also since it's greater then 1, the probability doesn't make sense

warped beacon
#

Wait

#

53130

#

Typo sorry

ionic harness
#

,calc 37626/53130

woven radishBOT
#

Result:

0.7081874647092
ionic harness
#

Yep that's what I got too

#

Probability of choosing at least 1 white marble when picking 5 randomly =
probability of choosing 1 white marble on the first + prob of choosing 1 white marble on the second (and non white on the first) + prob of choosing 1 white marble on the 3rd (and non white on the first and second) + ...

= 5/25 + (20/25)(5/24) + (20/25)(19/24)(5/23) + (20/25)(19/24)(18/23)(5/22) + (20/25)(19/24)(18/23)(17/22)(5/21)
= 0.7082

warped beacon
#

Yippee

#

Thanks fellas RazorCrown_Devonxy

#

.close

devout snowBOT
#
Channel closed

Closed by @warped beacon

Use .reopen if this was a mistake.

rare kernel
#

,calc 1-(4/5)^5

woven radishBOT
#

Result:

0.67232
rare kernel
#

huh

rare kernel
#

my bad

knotty salmon
#

@rare kernel If your question have been resolved please close this channel

rare kernel
knotty salmon
#

it says it's occupied

rare kernel
knotty salmon
#

well I think I'm stupid

devout snowBOT
#
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lilac briar
#

.help

devout snowBOT
#

Commands:

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Type .help <command name> for more info on a command.

lilac briar
#

.help math

devout snowBOT
#

No command called "math" found.

granite bough
#

hello

devout snowBOT
granite bough
#

i dont understand vectors

#

i am learning about vector spaces

#

and how you can express a vector in different basis

#

in a vector space i need a basis to reach all the points in the space

olive snow
granite bough
#

but then i can look at some other vector outside that basis, and i can see how i have to manipulate the vectors that make up the basis to reach that other vector

olive snow
#

Mostly computing

granite bough
#

is that what people mean by change of basis, im so very confused about this

#

im talking about the same vector but expressing it in different ways

olive snow
granite bough
#

one way is just the "standard basis" way of just saying, oh, that's (1,0)

#

and another one might be

#

"oh, i need 1 of this vector x and -1 of this vector y to reach that same point"

#

and that basis would be like [x,y]_(name of basis) or something

#

idk what the notation is

olive snow
#

B_smth := (span)

#

Depends lectures actually

granite bough
#

also what is a kernel, someone explained it to me as it being the space where things have been turned to the 0 vector

#

or are the 0 vector?

#

so if someone gives me this equation x + y + z = 0, then is (1,1,0) a part of its kernel?

#

sry i meant

#

(1,-1,0)

olive snow
#

Given a linear application f, the set of vectors v such that f(v) = 0

#

Thats what ker(f) is

#

{v \in vector space, f(v) = 0}

granite bough
#

and f(v) means i feed the function f a vector v

#

like could my f be x + y + z = 0

#

or am i misunderstanding what f is

olive snow
granite bough
#

ah okay, and then when i feed f(x,y,z) the vector v=(1,-1,0), then it is part of the kernel because f(v)=0?

granite bough
#

why do i care about the guys who got turned to 0

olive snow
granite bough
#

im very happy with how you have explained it so far i didnt understand for sure that this is what the kernel was

olive snow
#

If f is linear and if you can show that f(v) = 0 => v = 0

#

Then f is injectiv

granite bough
#

but yeah i dont understand the significance of the kernel yet

#

damn i forgot what injective means

olive snow
ionic harness
#

Since when did we learn math because it was significant 🏃‍♂️ I think once I reached university all the significance went out the window

granite bough
#

and f is a function/linear transformation/square matrix?

olive snow
#

Linear transformation

granite bough
#

so if a linear transformation turns something into the 0 vector it is part of the kernel, how is this useful for problem solving i dont quite understand

#

im terrible at problem solving so im probably missing something obvious

granite bough
olive snow
#

If ker(f) is reduced to {0} then f is injective

#

It turns out that if the starting set of f has a finite dimension then f is bijective

ionic harness
granite bough
#

is injective that the input leads to one output, and bijective that the input leads to one output, and the output leads to one input?

wicked rover
#

injective = different inputs have different outputs

granite bough
#

ah im sorry i will revise

#

on what injective and bijective means later

#

and what it means

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and relates to this

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but

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if im given just a vector, any vector some vector v

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is it expressed in a basis

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or not

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like, do i have to define some vector space

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before i can say i am expressing it in a basis

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or rather do i have to define a basis

wicked rover
#

talking about a vector assumes you already have a vector space in mind

granite bough
#

that makes sense

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someone told me otherwise so that confused me

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and if not explicitly written, i assume the basis is the standard basis?

wicked rover
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but you can talk about a vector space without knowing a basis

granite bough
#

maybe i just dont know the basis okay

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there has to be a basis otherwise talking about my vector wouldnt make any sense

wicked rover
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the set of functions from an interval to R is a vector space without an easily describable basis

granite bough
#

okay, but there could be/is definitely a basis for it

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even if it isnt easily describable

wicked rover
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every vector space has a basis if you accept axiom of choice

granite bough
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okay i had to google that

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but i can definitely accept that!

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:)))

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hmmm

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do i dare ask what span is

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like if im in R^3

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and i have 3 vectors linearly independent of one another

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and make a base that way

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they are linear too

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then, that's a basis

wicked rover
#

knowing what basis means requires you to know what span means

granite bough
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oh no uhm

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yeah i definitely dont know what span is but i feel like i know what a basis is

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to some degree

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what is a span

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do i have a span of a vector or span of a vector space

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or span of a basis

wicked rover
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how do you define basis if you dont know what span means?

granite bough
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i am not rigorous so i cant describe how i define it, i think of it as 3 linearly independent whatzadootzitzs, meaning if scaled or added to one another, they cant create one another, and if i have 3 or 4 of these whatzadootzits they can reach all the points in some space of certain dimensions

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i feel like the basis is like a weird handle

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and you can find a bunch of different basis

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by just grabbing that handle

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and twisting it

wicked rover
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"reach all points" is close to the idea of span. have you heard of how to formalize that?

granite bough
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even if the handle is four dimensional or in some abstract polynomial space

granite bough
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c would be the ting that scales the vector

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and the yeah you just add some arbitrary amount of them

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and depending on what c you choose and as long as the vectors arent parallell to eachother

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you can reach some point in your more or less abstract space

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sorry yeah no i have no clue how to formalize it

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and i dont even know if im thinking of it right but i hope so

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i definitely dont know what a span is though like

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like maybe i have a vector named "Bridge"

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in the English basis

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but in the Swedish basis maybe it is called "Brygga"

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but idk what span is

wicked rover
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lets say we know some vectors $v_1,\dots,v_n$. we define a linear combination of these vectors to be another vector of the form $c_1v_1+\dots+c_nv_n$ where $c_1,\dots,c_n$ are some scalars

granite bough
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sorry does it say and are a linear combination of those vectors?

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sorry i dont understand the text you wrote :(((

woven radishBOT
#

ロケット・ジャンプ

wicked rover
#

does that help

granite bough
#

okay yeah and a linear combination is just like alpha v_1 + beta v_2 and so on?

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and yeah i think that helped

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thank you!

wicked rover
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now there are two slightly different usages of the word span. heres the first

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the span of vectors $v_1,\dots,v_n$ is denoted $\Span(v_1,\dots,v_n)$. we define it as the set of ALL linear combinations of $v_1,\dots,v_n$

woven radishBOT
#

ロケット・ジャンプ

wicked rover
#

heres the second

granite bough
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is this what it is meant with linear combination: $c_1v_1+\dots+c_nv_n$?

woven radishBOT
wicked rover
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yes but we must take ALL linear combinations to get the span

granite bough
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yeah yeah, and the one i asked about is just one linear combination

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so there might be a different linear combination but it is like $c_(11)v_(11)+\dots+c_nv_n$

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oops

woven radishBOT
granite bough
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eww

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yeah idk how to use that

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im trying to jus tname them something else XD

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but not just 2, because i get 2 will be the next one in that same linear combination

wicked rover
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taking ALL linear combinations means varying all the scalars and collecting the combinations they produce

granite bough
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like i can scale a vector by SOMETHING, add it to another one that is also scaled by SOMETHING, but i could also do that same process, but just scaled by SOMETHING different

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and then it would be different linear combinations

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then i take all those different linear combinations

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okay so upon collecting them

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is that when i reach all the points, or is it greater than that, and not only do i reach all the poitns in my space, i also reach all of the points in all of the ways i can reach them?

wicked rover
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the span may or may not equal the whole vector space

granite bough
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hmm okay that doesnt make sense to me i would have definitiely guessed it equalled all of it

wicked rover
#

that leads me to the second usage of the word span

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we say that vectors $v_1,\dots,v_n$ span a space $V$ if $V=\Span(v_1,\dots,v_n)$

woven radishBOT
#

ロケット・ジャンプ

granite bough
#

damn i feel like im not following it

wicked rover
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the first usage of span is as a noun, the second usage as a verb

granite bough
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because i feel like if we have all the ways we can reach a point in a space

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then there is nothing else to say, like it would just be every way to reach every point and it would be reaching every point

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so i think im misunderstanding

wicked rover
#

not every set of vectors will span your vector space

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easy example, let v=(1,0). does it span R^2?

granite bough
#

okay so say c_1 = 1 and c_2=1, all the other c = 0, then i dont span the entire space

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i just span... what?

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v_1 and v_2?

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can i say that? idk

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im sorry :<

wicked rover
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i only gave u one vector v

granite bough
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oh sorry let me look at ur example

wicked rover
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so its span is the set of all cv, c is a scalar

granite bough
#

i was trying to come with an example of my own sry

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let me read it

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okay so c=1 for v, and all the other c equal 0?

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in that case i think i would say it does not span R^2

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or is it important that c may vary

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if i let c vary it can reach a line

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but not R^2

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but now i feel like im talking about a basis again and not a span

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but then again i dont know what a span is

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cv=(c,0), then (c,0) can reach every point along a line if c is a member of the real numbers

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like every point along the x axis if we are working in the standard basis

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but does that mean it spans the x-axis?

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im sorry ty for the help but i have to go my campus is closing in 10 minutes

wicked rover
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i have to go too

granite bough
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and merry christmas to you and also happy new year if i dont get to message you again before then

wicked rover
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ur right that v spans the x axis but not R^2

granite bough
#

okay thank you for confirming that

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that actually helps a little

wicked rover
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so thats an easy example of not spanning our vector space

granite bough
#

yes that helps

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i still have some confusion but that is actually very good for me

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now i understand much more thank you

wicked rover
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np glad it helped, have a good day

granite bough
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bye!!!

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.close

devout snowBOT
#
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Use .reopen if this was a mistake.

devout snowBOT
#
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visual stone
devout snowBOT
visual stone
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how can i find the norm of this vector

acoustic leaf
#

can you give more context?

visual stone
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and the orientaiton of that ? vector is 28

acoustic leaf
#

is there any relationship between them?

visual stone
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whats a relationship

acoustic leaf
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like anything connecting them

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because it seems like you just have two random vectors next to each other right now

visual stone
#

well it said the vector with 400 N has an angle of 34

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and it said that ? vector has an orientation of 28

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so i thought 34 was the orientation of that vector so i put it on top of it

hardy trail
#

So that's why we need some additional context.

hardy trail
visual stone
#

if i can remember

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it said that angle for 400 N was 34

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with no other thing explaining it then it said one angle has a orientation of 28

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and it told me to find the norm of that vector with an orientation of 28

hardy trail
#

🤷

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The background context is too vague to give any sort of reasonable answer.

visual stone
#

oh alright

hardy trail
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If you're basing this off memory, I can only assume that you got this problem in class or during an exam. Might want to ask your teacher for some clarification on that problem.

visual stone
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im trying to remember

hardy trail
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oof

visual stone
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that i was working on but that number i understood 0

hardy trail
#

Maybe you could ask a classmate if they have a copy?

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Idk perhaps if you get the original context, that might help you solve the problem lol

visual stone
hardy trail
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Rip

visual stone
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also i got another question

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but this one is very difficult

hardy trail
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o

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What's up?

visual stone
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it said Adam throws a ball at beatrice with (35,20) components

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then it said Beatrice throws one to Charles with (8,-3) components

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then Charles throws to Diana (-40,-20)

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find the norm of the vector of Diana to Adam

hardy trail
#

Hmmm, well - what are your thoughts on this problem so far?

visual stone
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well i know where the vectors are in which quadrant

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like adam to beatrice is in the 1st quadrant beatrice to charles is in the 4th and charles to diana is in the 3rd

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so adam to beatrice is AB

hardy trail
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Any other thoughts?

visual stone
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i thought that AB + BC + CD = DA

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but wheni drew it

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it didnt lok like that

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ill show you why

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ill draw it again

hardy trail
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What do you think AB + BC + CD is equal to then?

visual stone
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not sure

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also i think htis problem gave a norm for one of them but i forgot

hardy trail
#

If you just drew the vectors AB + BC + CD, what would that look like?

visual stone
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a paralelogram

hardy trail
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Hmm, well, draw it for me :)

visual stone
hardy trail
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Yep.

hardy trail
visual stone
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the thing is i dont know how to draw this

hardy trail
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Wait,