#help-27

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pulsar trellis
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yeah but i get a different answer 😅

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Wait I think I understand lol

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sorry

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I forgot that it can't be a negative when square rooting

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pure stone
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Given A and B are real, n x n matrices that satisfy AB = BA. Prove det(A^2 + B^2) >= 0

royal hatch
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what have u tried ??

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@pure stone Has your question been resolved?

shell igloo
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zenith lion
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Hello helpers

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zenith lion
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why is the output vector and input vector on the same plane?

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its just for intuition right?

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because 2d input vector and 2d output vector would be 4 dimensional

pseudo basin
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if you were to graph a function R^2 -> R^2 in the literal same way as we do R -> R then yes that would require 4 dimensions

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here though visuals-wise the output vector is attached to its corresponding input

zenith lion
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right so if I just took two different 2d planes, what would the resulting output vector look like

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would it also start at 0,0 ?

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or at the input vectors coordinates

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Im trying to understand where the output vector actually begins and ends

zenith lion
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on its own 2d plane it would begin at (0,0) right?

pseudo basin
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it doesnt 'actually' begin/end anywhere at all

zenith lion
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So its generally normal to be confusing

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because I always get it wrong considering this way

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whatever not worth digging into it

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the visualization is good

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thanks ann

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fair raft
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could someone help me with this problem?

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fair raft
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anyone?

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@fair raft Has your question been resolved?

carmine veldt
# fair raft anyone?

I think we could apply the definition of ρ-length on the equality given for ρ-length being invariant for mobius transformations of H

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once we subtract both integrals, we shd get somethings like integral from a to b of (ρ(γ(σ(t)))∣γ′(σ(t))∣−ρ(σ(t)))∣σ′(t)∣ dt = 0

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setting f(z)=ρ(γ(z))∣γ′(z)∣−ρ(z) should immediately give you the answer after applying the thing given in the hint

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Correct me if I'm wrong tho, idk what those transformations and all mean 😭

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dusky belfry
# fair raft anyone?

I am not gonna be too much of a helper but after no one responds for 15 minutes

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I read it on the rules

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it's safe to ping them at @ helpers

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once

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only once

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merry ivy
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Is this the right method

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surreal zenith
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when price is 700 + 100 * 0, number of occupied rooms is 72 - 2 * 0
when price is 700 + 100 * 1, number of occupied rooms is 72 - 2 * 1
when price is 700 + 100 * 2, number of occupied rooms is 72 - 2 * 2
....
when price is 700 + 100 * n, number of occupied rooms is 72 - 2 * n

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daily income is (700 + 100 * n) (72 - 2 * n)

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and x = 700 + 100 * n

merry ivy
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merry ivy
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<@&286206848099549185>

merry ivy
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<@&286206848099549185>

merry ivy
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<@&286206848099549185>

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errant tapir
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hello

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I am taking algebra 2 this summer

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should I get any textbooks

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or rely on the normal curriculum work

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unique crown
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I need help learning elimination and substution

unique crown
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ill send a problem one sec

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ping me when seen if possible

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silk rock
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unique crown
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unique crown
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Had dnd on

upbeat forge
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so do you know what you need in both equations to use elimination?

unique crown
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Subtract

upbeat forge
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before you do, you need to make sure you have a term in each equation that will cancel itself out when added to or subtracted from the second equation.

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that's why the whole process is called elimination - you're eliminating one variable from consideration.

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as of now, though, using your question, there's no direct elimination possible. a naive subtraction here will still see both x and y.

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to start using elimination in a situation like this, you should first match the coefficient of one variable in one of the two equations to its coefficient in the other one by multiplying.
in this case, the x terms are easy to match here.

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hint: multiply the second equation by a number to get the x coefficient to the same as the one in the first.

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can you do this step first?

upbeat forge
unique crown
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Appreciate it

strange vale
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yall know about quadratic equations like finding roots and vertex??

upbeat forge
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unique crown
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What number do I multiply though?

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Does it matter?

upbeat forge
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it does.

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you want the 5x to turn into 15x so that when you subtract the two equations, the 15x from the first equation and the 15x from the second cancel each other out.

upbeat forge
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that's the whole idea behind matching coefficients: multiply one of the two equations by a specific number to get either the x/y-cofficient to match that of the other equation's, then add or subtract them to eliminate that variable.

upbeat forge
unique crown
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So 75x + 75y = 300

upbeat forge
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how did that happen?

unique crown
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I multiplied 15 by the bottom equation

upbeat forge
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15 is overkill.

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you want the 5x to turn into 15x, not multiply the whole thing by 15.

unique crown
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The 3 is negative though

upbeat forge
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we're eliminating x, not y. if you want to eliminate y, you'd have to scale both equations.

unique crown
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Would it be easier to use substitution?

upbeat forge
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for this one, using elimination kills the problem right away.

unique crown
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So its 3?

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And i just plug that in again to get y

upbeat forge
unique crown
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x=3?

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5 x 3 =15

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5 x 3 =15

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20 x 3 =60

upbeat forge
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ok, hang on a second.

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you're multiplying equation 2 by 3, correct?

unique crown
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Yes

crystal dawn
upbeat forge
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in that case, write the entire equation after you've multiplied by 3.

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don't do anything else with it yet - just write out the equation as a whole.

unique crown
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15x + 15y = 60

upbeat forge
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right side?

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there we go.

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now, we see that we have a 15x in this new equation and a 15x in the first equation.

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at this step, you can now subtract the two equations. the order doesn't matter.

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(by the two equations, I mean the original first equation and the new second equation, by the way. don't use the original second equation for this.)

unique crown
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Ohhhh

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18y = 80

upbeat forge
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18y?

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at most a 3 and a 5 makes 8. did you mistype something somewhere?

unique crown
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Its 15?

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I have 15x and 15y = 60

upbeat forge
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ok see, let me line up the two equations top to bottom.

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15x -  3y = -30
15x + 15y =  60
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oh, wait, never mind then. your 18y is correct, but not your right side.

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a 60 and a 30 don't make an 80.

unique crown
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-30-60=90

upbeat forge
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yeah, and you wrote 80 there.

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it should really be a 90.

upbeat forge
# unique crown 18y = 80

after fixing this mistake, you're now on the right track to getting the value of y.
one minor tidbit though: if this was a free-response section, ensure you say which way you're doing the subtraction to result in this new equation.

unique crown
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So i plug 5 into y

upbeat forge
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why do that though?

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I know y = 5 fits, but if you didn't know that, you're going to have to show how you got it.

unique crown
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Thats the answer

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90/18

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Plug it in then solve so I can get x

upbeat forge
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in this case, yes, you can solve for x now, but the question didn't really ask for the value of x.

unique crown
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Oh wait I realize that now

upbeat forge
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is there anything else you'd need help with?

unique crown
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Nope, thank you

lost tide
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Are u in grade 9

unique crown
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8th

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Im taking algebra 1 honors and ive been absent for 1 week and now we have a quiz 😭

crystal dawn
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so is there anything OP still wants to ask?

unique crown
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Not as of right now no

upbeat forge
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!done, if you're done then.

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unique crown
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!done

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unique crown
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.xlose

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.closoe

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.close

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granite fractal
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i'm confused on how to get the vertex with -b/2a

supple knot
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which line in there is confusing

granite fractal
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how do i get the y

supple knot
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f(3)

granite fractal
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oh

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so like put 3 in for x

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into the og equation

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okok

supple knot
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yes that's what f(3) means

granite fractal
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sorry brain farting rn thank you 😭

supple knot
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all good

granite fractal
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blissful gorge
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hi im a little confused where did the -e^-x come from?

blissful gorge
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this is my teachers asnwer key

heavy current
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if that's what you mean, then it's because the derivative of e^-x is -e^-x

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and the reason we're getting that is because of the product rule

heavy current
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chain rule!

blissful gorge
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i know that the derivative of e^x is e^x

blissful gorge
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i need to be applying that more

heavy current
blissful gorge
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hee hee okay cool

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thank you higher!

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heavy current
blissful gorge
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.reopen

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blissful gorge
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okay so i fear im still confused

blissful gorge
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its breaking me

heavy current
woven radishBOT
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higher!

heavy current
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what is it's derivative? the chain rule says that it's $f'(g(x))g'(x)$

woven radishBOT
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higher!

heavy current
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f'(x) is just e^x

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and g'(x) is -1

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so f'(g(x))g(x) is e^{-x} * -1

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i.e. -e^-x

blissful gorge
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okay got it

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wait hold on

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so why is f(x) e^x?

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the -x isnt outside of the ^x, is it?

novel python
# blissful gorge so why is f(x) e^x?

as in, why is f(x) e^x?
that is given in the question, the essence of doing f(g(x)) is putting the expression g(x) as the term for x

anothher example for constants would be f(3), this means you evaluate as x=3 in the equation, or if you do f(x^2) then you replace x with x^2, similarly this means that for composite f(g(x)) it just indicates that the x term in your f(x) now becomes whatever g(x) is

blissful gorge
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i see

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i fear im still a little foggy but i have a basic understanding and i gotta keep pushing through

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thank you!

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heavy current
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ebon saddle
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I don't get this. Why both of them are = to x.
Here is my evaluation,
For the first one, f-1(x)=x(domain), then f(x)=y(range)
For the second one, f(x)=y(range), then f-1(y)=x(domain)

novel python
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do you mean the expression? or do you mean the range and domain

because correct me if im wrong, the doman and range of f operated on f^-1 and the method of f^-1 operated on f is diffferent

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with regards to expression

you can think of f^-1 as an undo button, essentially if i have the result of f(x), doing f inverse takes the output of f(x) and gives you the original value

the undo button f inverse is similar to f^-1(y) =x and therefore i will explain it as such
since f(x) =y, then applying f^-1f(x) is essentially conducting f^-1(y) which returns x

ebon saddle
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for the first one, if i use f-1(x), i can get the x in the f(x) right? then, i plug the x into f, that just f(x), so it equals to y. That's what i think of.....

novel python
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okay... let me think of an intuitive way to understand this yeah

long pasture
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My first thought is that x is a dummy variable.
The x in first line belongs to the range, while the x in the 2nd line belongs to the domain.

if you doesn't feel safe about both using x, you can rewrite the x's in the first line into y's

ebon saddle
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so, they are not the same thing? 😨

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The problem is, when I apply to the inverse+composite function, i feel weird....

btw i'll come back later after my class

long pasture
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But what if A=B?
then x in A also means x in B, therefore we can use x (in A)
to say g(f(x))=x
and we can use x (in B)
to say f(g(x))=x

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sharp laurel
#

Hey guys, I have a question about how i start with matthematics I am now in 11t grade and my knowledge of math is pretty poor: fuctions, basic logarithm's ect... But i want to learn way more math and i really want to learn and understand everything well but i searched about how i should start with math online and there where so many different ways and fields that i came to the conclusion that i really just need someone that has some decent expirience to talk with them about it, so if anyone wants to start a little conversation with me about the most efficient ways on starting math im all ears! (sorry for bad english its not my main language).

late scaffold
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I'd say that the first move is to find a syllabus to structure your learning from this point forward
one sample syllabus I like to use is in the Bookshelves of Math LibreTexts, which covers you all the way to abstract algebra adequately

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then, instead of focusing entirely on just reading, always do practice problems! you are only as good in math as the problems you understand and can solve, so consider spending some time trying out some problems after each topic

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also, don't hesitate to ask when stuck! it would be nice if you tried the problems at least as much as you could first, but if you're stuck, someone could give you a tiny hint that could be enough for you to make progress.
and sometimes, while waiting for an answer (or even when voicing out the question for your helpers/teachers/tutors) you hit upon an idea you've never thought of

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the last tip I can offer is to understand why formulas are what they are (i.e.: understand where they come from, why they work and how they apply)

sharp laurel
late scaffold
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https://math.libretexts.org/Bookshelves
if you go to this part of the site specifically, notice that each field is laid in order

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the fields start at Arithmetic, then Pre-Algebra, then Algebra, Geometry, Precalc/Trig, Calculus, etc.

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up to and including calculus, this is more or less the suggested study order for most people

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after that, you can sort of jump around depending on what field you plan to major in

sharp laurel
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Ah ok its like a road map for the basics?

late scaffold
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yes!

sharp laurel
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And do you suggest that i learn all of them?

late scaffold
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not necessarily, but if you are going into pure math, you will see a lot of them

sharp laurel
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Alright thank you so much you are wonderfull

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I finially have some good structure now

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Thanks

late scaffold
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no problem, glad to help

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anything else you would like to ask?

sharp laurel
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No that was all for now, i will close this channel

late scaffold
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aight, see you around, and welcome to the server!

sharp laurel
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🙂

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cold haven
sharp laurel
#

Hey i am now learning my math trough math libretexts but as i am going trough the excercises i just can't seem to find any solutions to the excercises so i can't know 100% if my answer is right or not. Is it just like that or does the Solutionpage stand anywhere that i can't seem to find?

late scaffold
#

the channel is closed btw. if you want to ask your question, please grab another channel

sharp laurel
#

Oh ok

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humble siren
#

prove that x=2 is the only solution

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gloomy aurora
#

what are your steps so far? where have you reached?

humble siren
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I found that a=0 and x=2 is a solution

gloomy aurora
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what is a here?

gloomy aurora
humble siren
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the full statement is find a then find all solutions (all x)

gloomy aurora
pure stone
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so a^2 <= 0 and so a = 0

humble siren
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yes

pure stone
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when does the equality in AM-GM happen

humble siren
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when the two terms are equal

pure stone
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when the terms are equal right?

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so use it to prove that the equality only happens when x = 2

humble siren
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Nice thank you

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lunar locust
#

shouldnt this function have a jump discontinuity at x = pi/2

lunar locust
#

floor of sin(90)=1 is 1 right?

pseudo basin
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yes, it's just a removable jump discont and desmos cant really show these well

lunar locust
pseudo basin
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yes

lunar locust
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jade owl
devout snowBOT
jade owl
#

Pls help me I'm stuck here i wanted someone to explain me

pseudo basin
jade owl
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Yea it would be 225/100 i.e. umm 9/4

pseudo basin
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yes 9/4.

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ok, next: do you know log laws?

jade owl
#

Ohh i seee , I see something like loga-logb

pseudo basin
#

that's half of one law

jade owl
#

We have log2 and log3 , 9/4 is square of 3 and 2 right

pseudo basin
#

this "and" is doing a lot of heavy lifting.

#

9/4 = 3^2 / 2^2, sure.

jade owl
#

Sorry my bad

jade owl
pseudo basin
#

ok, do you have paper on you

jade owl
#

Yes lemme try real quick

#

Did I do correctly?

jade owl
coarse flume
jade owl
#

Ty for correction @coarse flume

#

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lunar locust
#

if LHL and RHL limits both are +infinity then can I say that the limit exists at that point

lunar locust
#

and the limit is +infinity

lunar locust
#

wat if im solving continuity questions

#

still no?

carmine veldt
#

no

#

normally we define it for the limit to exist as some finite real number

cold haven
#

<@&268886789983436800> troll.

pseudo basin
copper harbor
#

Limits taking infinite values are a lot trickier than limits taking finite values

lunar locust
#

is this dude even alive

carmine veldt
copper harbor
#

What Ann means is that you can define a notion of limit existing if f goes to infinity, it depends on if the text you're reading uses that

lunar locust
#

(at -3)

copper harbor
#

Personally I'd say that's infinite but it depends on your curriculum

lunar locust
#

do i say limit of -3 infinit

copper harbor
#

this thing doesn't have a universal answer

lunar locust
#

not undefined

copper harbor
#

it depends on what curriculum you're following, go read your textbook to find out

#

this will be explained somewhere

lunar locust
#

i thought math was supposed to be objective

copper harbor
#

it is objective in the sense that once you fix your definitions everything has exactly one answer

#

but fixing those definitions is subjective

mystic scarab
#

I think that in this case the answer is +∞

lunar locust
#

then what should i conclude abt the limit

#

does it exist or not

mystic scarab
copper harbor
#

As I said

#

it depends

#

read your textbook and see what it says

lunar locust
copper harbor
#

reading is an important life skill joia

lunar locust
carmine veldt
#

read his textbook 💀

lusty sapphire
copper harbor
#

I would check which one will not make me lose marks by reading my textbook

lunar locust
lunar locust
#

ok here

#

damn chartbit is here

copper harbor
# lunar locust ok here

you didn't need to go straight to the answers, usually your textbook will explain the content to you in the pages before the problems, you should read those pages when you're stuck

copper harbor
#

but then you don't learn

#

and you do badly on your exams

lunar locust
lunar locust
#

1 sec

#

it says does not exist

#

but why did it write +inf in the answers then

#

just write dne

acoustic leaf
#

we write +infinity for these limits because it is more informative than just saying "DNE"

#

even if "DNE" is technically true it's less helpful

lunar locust
acoustic leaf
#

well you should just get into the habit of writing 'infinity' where it applies and then just remember that also implies it DNE

lusty sapphire
#

Which is basically what the book said. It's just a convenience to convey the f grows without bound

lunar locust
#

are undef & dne the same

devout snowBOT
#

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stiff karma
#

Why is x^-1 = 1/x^1

devout snowBOT
thin inlet
#

well

#

it preserves our exponent properties!

#

it's an extension

polar chasm
#

x^3 = x * x * x
x^2 = x * x (we divided by x)
x^1 = x (we divided by x)
x^0 = 1 (we divided by x)
x^-1 = 1/x (we divided by x)

it's defined this way because it preserves many nice properties and patterns

thin inlet
#

that exponent property being...

$x^{a+b}=x^{a}x^{b}$

woven radishBOT
#

🫎 Moosey 🫎

thin inlet
#

and it works nicely with the other exponent properties as well

#

$x^{(ab)}=\left(x^{{(a)\right)}^{b}}$

stiff karma
#

also why is x^0 = 1?

woven radishBOT
#

🫎 Moosey 🫎
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

thin inlet
#

you know x^(a+b)=x^a x^b

#

if you have x^2 * x^3 then that's equal to x^5

#

2^2 * 2^3=2^5

#

2^0*2^1=2^1, it only makes sense for 2^0 to be 1 in this circumstance

stiff karma
#

but we don't have to add 1^1 to 1^0...

thin inlet
#

well yeah because 1^x is just going to be 1

#

its the same reason why we define square root as x^(1/2) as well

#

an nth root as x^(1/n), because when we take the n-th power, we get back to x (atleast for odd powers)

#

(x^n)^1/n=x (for even n its |x|, because even root functions don't account for negative signs)

mystic scarab
stiff karma
#

,calc (4a)^2

woven radishBOT
#

The following error occured while calculating:
Error: Undefined symbol a

stiff karma
#

,w (4a)^2

devout snowBOT
#

@stiff karma Has your question been resolved?

devout snowBOT
#

@stiff karma Has your question been resolved?

supple knot
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#

@stiff karma Has your question been resolved?

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loud lynx
#

nvm

#

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gray geyser
#

I have to test this equation for x-axis, y-axis, and origin symmetry. x = 2y^4 - 9y^2

gray geyser
#

First I was doing y-axis

#

I know that you gotta substitute x for -x

#

But now I am confused

#

Would I make the negative x back to positive?

#

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royal laurel
devout snowBOT
royal laurel
#

I cannot really see how it went to 2 from 1

#

Can someone explain

hollow ice
#

its an identity

hollow ice
# hollow ice

its pretty easy to see if you try to achieve the LHS by expanding the RHS in this

devout snowBOT
#

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mellow willow
#

Am I crazy or does this not have a gcf

devout snowBOT
cyan surge
#

I think what you need to do is to find lowest power of variables and coefficients that appear in all terms
i.e. 2x^2 + 4x= (2 * x * x) + (2 * 2 * x).
You could see that only 2x is common in both the terms

mellow willow
#

I have no idea how to do that

flat ibex
fossil locust
#

there's no constant term

fossil locust
#

so it's not about the numbers 3, 8, 5, 44 (their gcd = 1, of course)

#

but it's about...

mellow willow
#

?

#

What did I do wrong

fossil locust
cyan surge
fossil locust
woven radishBOT
mellow willow
fossil locust
mellow willow
#

So I’m trhing the other one but the answer doesn’t seem rigjt

mellow willow
fossil locust
woven radishBOT
mellow willow
#

Yes

#

I understand that part but I don’t know what to do with the • X outside the ()

flat ibex
#

you dont do anything with it

#

you leave it there lol

mellow willow
#

But you need to solve the equation

flat ibex
#

it implies one of the roots is 0

fossil locust
woven radishBOT
flat ibex
#

and you can factor inside the parenthsis

mellow willow
#

But there’s four of them so now you just have to x^4

#

But then your just where you started?

mellow willow
#

Do you have to factor out the gcf or can you just solve it by doing long devisition twice

fossil locust
#

the gcf is x

cyan surge
mellow willow
#

I don’t know how to do long deviation with an extra x on the outside …

fossil locust
#

can you long divide (3x^3 - 8x^2 - 5x - 44) by (x - 4)?

mellow willow
#

Yes

fossil locust
#

to make a simpler example, imagine I have $x(x^2 - 3x + 2) = 0$

I factor $x^2 - 3x + 2 = (x - 1)(x - 2)$

subbing that back into the equation, $x (x - 1)(x - 2) = 0$

woven radishBOT
mellow willow
#

I kinda understanding factoring out X but I don’t know how to do long devision with just the value X on the outside

fossil locust
#

you get $x(x - 4)(\text{some quadratic}) = 0$

woven radishBOT
mellow willow
#

But why don’t we divide the X?

fossil locust
#

so dividing by 0 would be undefined

mellow willow
#

Sorry I’m very confused

#

But I’ve done long deviation before with 1x or 1x^2

fossil locust
mellow willow
#

No I understand us getting (X-4)( quadrant ) if we where just using 3x^3-8x^2-5x-44

fossil locust
#

I know you know how (polynomial) long division works

mellow willow
#

I mean techinally only polynomial long division I can’t do normal

fossil locust
mellow willow
#

How is it equal to zero and how the X value is there and was not in the long deviation

fossil locust
#

do you agree?

#

I'm giving you a new question which is to find the roots of $x(x^2 - 3x + 2)$

woven radishBOT
mellow willow
#

Are the roots the zeros?

fossil locust
mellow willow
#

I don’t do that then I use the box or quadratic formula

fossil locust
#

yes, I know you don't need polynomial long division here

fossil locust
woven radishBOT
mellow willow
#

But it says to use long divisiton

lost tide
#

This is easy

#

Bruh

tall linden
#

,rcw

fossil locust
woven radishBOT
mellow willow
lost tide
fossil locust
mellow willow
fossil locust
lost tide
#

@mellow willow what are u stuck at

woven radishBOT
mellow willow
#

Wdym on both sides

fossil locust
#

you've lost a solution: you've lost x = 0

mellow willow
#

Wait

lost tide
#

look

#

X=1
X=2

mellow willow
#

(X-0)?

lost tide
fossil locust
#

so 0 is also a root!

mellow willow
#

I’m saying is that a zero?

fossil locust
lost tide
#

@fossil locust

lost tide
mellow willow
#

So could I just do long devision twice one time with (X+4) and then with (X-0)

lost tide
#

💔

fossil locust
#

you just divide every single term by x

mellow willow
#

I just don’t know that way

fossil locust
#

but then yes, you then divide that cubic with (x + 4)

fossil locust
lost tide
#

@mellow willow write the work that u are stuck at

fossil locust
#

$\frac{x^2 + 2x}{x} = \frac{x^2}{x} + \frac{2x}{x} = \cdots$?

woven radishBOT
fossil locust
mellow willow
fossil locust
flat ibex
#

im with obama on this one

fossil locust
woven radishBOT
flat ibex
mellow willow
fossil locust
#

when we split the fraction, those two things are equal

mellow willow
#

I just don’t get how this relates

fossil locust
fossil locust
mellow willow
#

I don’t really understand how to decide by just X tho

devout grotto
woven radishBOT
#

Mirror

fossil locust
mellow willow
#

2x?

#

I dont understand how that can be X but 2/1 is 2

fossil locust
#

$\frac{2 \cancel{x}}{\cancel{x}}$

woven radishBOT
fossil locust
#

oh yeah and when you cancel, that becomes (2 * 1) / (1)

devout grotto
#

(South, if I'm not being helpful feel free to tell me to stop!)

mellow willow
#

I never take the gcf out in general which is why it’s even more confusing

#

Like I cant remember me doing that ever

devout grotto
#

Can I back us up a step?

lost tide
#

@mellow willow are u in grade 9?

mellow willow
#

I’m a senior -_-

#

Precalc

lost tide
#

Isn’t quadratic equation for grade 9

mellow willow
#

See I’m not good at math bht some how get A’s

devout grotto
mellow willow
lost tide
#

Ahh

devout grotto
#

Allie, backing us up a step: $f(x) = x({3x}^{3}-{8x}^{2}-5x-44)$ is what we're starting with

woven radishBOT
#

Mirror

mellow willow
#

Tea

#

Yea

devout grotto
#

so if f(x) = 0 what does that mean?

pure stone
mellow willow
#

X intercept?

devout grotto
#

yes, that's related. if i were to tell you that $a \cross b = 0$ can you deduce anything about a and/or b?

woven radishBOT
#

Mirror

mellow willow
#

No

#

Well one woukd be zero

devout grotto
#

Right! That's the idea here.

#

$x({3x}^{3}-{8x}^{2}-5x-44) = 0$ means that $x = 0$ or ${3x}^{3}-{8x}^{2}-5x-44 = 0$, are you with me so far?

woven radishBOT
#

Mirror

mellow willow
#

Uh

devout grotto
#

it looks long and complicated but it's just our a x b example from before

mellow willow
#

No I think it’s just not showing up for me

devout grotto
#

(Think x = a and The Big Scary Function = b, does that help?)

#

bc it doesn't matter what we multiply by once we multiply by zero

mellow willow
#

But I just don’t know how to do long divisiton witu x(the quadratic )

devout grotto
#

We don't have to! Let's break it up.

#

We know that if x = 0 the function equals zero, so let's set that off to the side and remember it later.

#

Now our big function is ${3x}^{3}-{8x}^{2}-5x-44$ and we're looking for when that function is zero.

woven radishBOT
#

Mirror

devout grotto
#

We also know that x=4 is an intercept, so what does that mean?

fossil locust
#

thanks for helping Mirror

#

you're doing brilliantly!

mellow willow
#

Wait so do we just divide the quadratic and not the x

devout grotto
devout grotto
#

(What are we dividing by what?)

mellow willow
devout grotto
#

There we go! Can you tell me why you're dividing by $x-4$?

woven radishBOT
#

Mirror

mellow willow
devout grotto
#

(It's the right move here, by the way: just want to make sure you understand why!)

devout grotto
#

Next step here is the long division, which (as far as I understand) you can do?

#

So do that and report back if you encounter some more trouble!

#

(Broader picture, by the way:
${3x}^{4}-{8x}^{3}-{5x}^{2}-44x) = 0$ if $x = 0$ OR $({3x}^{3}-{8x}^{2}-5x-44) = 0$ \newline
$({3x}^{3}-{8x}^{2}-5x-44) = 0$ IF ($ x-4 = 0$ OR <some other function> = 0)

woven radishBOT
#

Mirror

mellow willow
#

I’m not sure how to continue because I need to write smth witu i but I don’t know how since it’s not a perfect square

unreal edge
#

this is pre-cal?

devout grotto
#

Let me double-check that long division

mellow willow
devout grotto
#

Long division is correct mikuyay

fossil locust
#

,w (3x^3-8x^2-5x-44)/(x-4) quotient and remainder

devout grotto
#

oh we can do that??

#

fantastic

mellow willow
#

I haven’t done get before

devout grotto
#

the Wolfram i mean

mellow willow
#

For c would I leave it as is

mellow willow
devout grotto
#

I'm inclined to agree that we leave it as is since there are no real solutions to $3x^2 + 4x + 11 = 0$

woven radishBOT
#

Mirror

devout grotto
#

,w sqrt(-116)

devout grotto
#

Do you have any other questions, Allie?

mellow willow
#

I know I have to do the quadratic formula since it’s a step and it’s a little similar to a class problem but it’s not a perfect square

fossil locust
#

,calc (4)^2 - 4(3)(11)

woven radishBOT
#

Result:

-116
fossil locust
#

< 0, so no real roots

devout grotto
mellow willow
#

Yea but I need to write it with i some how

fossil locust
#

ah, of course cause your class wants the complex zeroes

#

then yes you need the quadratic formula

devout grotto
#

you can substitute $\sqrt{-116}$ into $i\sqrt{116}$ and keep crunching!

mellow willow
#

Ohh ok

woven radishBOT
#

Mirror

mellow willow
devout grotto
#

that is technically correct but i think you can clean it up a lil more

mellow willow
#

My teacher did say in clas it’s fine to not simplify but how would I?

devout grotto
#

since you're at a stage where the answer is complete i will just tell you!

#

since $4 \cross 29 = 116$, $\sqrt{116} = 2\sqrt{29}$

woven radishBOT
#

Mirror

mellow willow
#

Ohhh kk

#

One more question for another problem I’m trying to do the box but I don’t know if 7 would be positive or negative

devout grotto
#

It'll be negative in both. A great way to approach is to work from the innermost set of parentheses outward

#

so before you even start distributing turn $(x-[7+3i])$ into $(x-3i-7)$

woven radishBOT
#

Mirror

mellow willow
#

This doesn’t seem right

upper schooner
#

,rccw

woven radishBOT
devout grotto
#

,w (x-3i-7)(x+3i-7) simplify

#

You forgot a term!

upper schooner
#

(one thing I will say is that for this, I would personally be tempted to write what we're expanding as ((x - 7) - 3i)((x - 7) + 3i), from which it becomes a tiny bit easier as you can difference of two squares to begin with)

mellow willow
#

I’m not supposed to have I left I’m very confused

#

Ohhh I see

devout snowBOT
#

@mellow willow Has your question been resolved?

devout snowBOT
#
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devout snowBOT
#
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lost laurel
#

Are there any nice propeties for fin-dim vector spaces that neatly carry into the inf -dim case

lost laurel
#

That don't trivially extend via a double inclusion

#

.close

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flat ember
#

Here for example, is it x y^-2?

devout snowBOT
hollow ice
#

nope

#

maybe show your work so its easy to identify mistakes

flat ember
#

hollow ice
#

well, what more do you want?

flat ember
#

Well I’ll come back later

#

With this.

#

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compact hawk
devout snowBOT
compact hawk
#

Hi can someone just tell me what the question means by sum of the perimeters of region a,b,c and d

soft umbra
#

,rccw

woven radishBOT
compact hawk
#

Like does it means the entire square (basically combine a,b,c and d and the perimeter of that is 152) or is it that like if we took it apart individually perimeter a + b + c + d = 152

restive river
#

perimeter of A + perimeter of B ... = 152

#

id assume its double counting edges due to how its phrased

compact hawk
#

Oh alright ty

hollow jolt
#

If it meant perimeter of the whole thing then it would probably just state that

#

Rather than give of each region

compact hawk
#

Double edges would be counted

#

😭

#

Anyways ty

#

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sand girder
#

\begin{gather*}
2 a^2 + \sqrt{b} = 8 \
a^3 + ab - b = -34
\end{gather*}

woven radishBOT
#

Thomas

fossil locust
sand girder
#

yeah

fossil locust
#

what have you tried so far?

vital edge
#

Are we given anything else

sand girder
#

not rlly

vital edge
#

For example are they integers or smth

fossil locust
#

,w a^3 + a(8-2a^2)^2 - (8-2a^2)^2 = -34

vital edge
#

And nvm

#

Was wondering if it was cheeseable

sand girder
#

ok so there's one good solution

fossil locust
#

the other roots are all very ugly, yes

vital edge
#

It's still a quintic though

sand girder
#

so...now what?

fossil locust
sand girder
fossil locust
#

this is a terrible problem cause you can only solve it through guessing

sand girder
fossil locust
sand girder
#

i think it's a, b are real numbers

fossil locust
#

I mean, like what chapter this question comes from

#

and if there's a worked solution

sand girder
#

the chapter's called: "systems of equations"

#

just that 😭

fossil locust
#

what grade is this?

sand girder
#

Advanced grade 9

fossil locust
#

if you know that a must be a rational number, then the rational theorem gives the possible values of a as:

plusminus (factors of 30)/(factors of 4)

that's still too many possibilities to check

fossil locust
sand girder
#

okay

fossil locust
sand girder
#

.close

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empty star
#

I'm just learning this now sort of, as I understand it, D) would be DNE, but what do I put for C??? the coords for the darker point? both?

empty star
#

When I first saw c i assumed it was asking what d is asking

#

but since it's not idk what it's asking

#

i don't know what to do about the hole

proud mural
#

the darker point means its defined at x=-3 right?

empty star
#

i don't know

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i wish i knew

#

i hope so

#

operating on that assumption

hoary egret
#

isnt that just a removable discontinuity

#

therefore we have that it is discontinuous but still retains a limti

empty star
#

not at -3

#

that's a jump isn't it

#

but i guess i have the same question about m

#

or k i mean

#

since it has 2 holes at g(4)

empty star
#

my ass is not getting above 80 in this class 💀

hoary egret
empty star
hoary egret
#

yes bro it is

proud mural
hoary egret
#

Why

#

oh wait

#

im regarded

#

sorry i meant to say

#

that is a jump discontuity

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so the limit from both sides approaches diff values

empty star
#

so DNE for question d

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but what about question c

hoary egret
#

so we have discontinuity and no limit for that point

empty star
#

did you read my question

proud mural
hoary egret
#

Bro i just wrote for part D

empty star
#

i was asking about part c

proud mural
#

its just gonna be the y value of the dark point

hoary egret
#

I meant for part C

proud mural
#

because the function is defined there

hoary egret
empty star
#

and what about k

hoary egret
#

it is discontuityies

proud mural
#

we dont care about limits or continuity for just evaluating the function at a certain x value

#

we just care about what the value is

hoary egret
#

if it is discontinuous how can it have a value?

proud mural
proud mural
empty star
#

?

proud mural
#

at y=4?

hoary egret
proud mural
#

that's the point

empty star
#

okok so if it's not a hole then i put that answer right

#

on the test it'll be clearer

#

this is like bad scanning from a textbook lol

proud mural
#

whats confusing you?

hoary egret
proud mural
#

just means its not continuous

hoary egret
#

okay thanks

empty star
#

how do i find the limit at 2 from the graph

#

unless i "estimate" at 4 but i feel like we haven't estimated anything in a long time

hoary egret
#

limit at 2?

#

there is a point there

#

i mean u dont have the equation

empty star
#

wait i'm confused

hoary egret
#

so u cant evaluate the limit

proud mural
empty star
#

hs you are not helpful

hoary egret
proud mural
#

they wouldn't make it 3.99 or somethjng

#

that's dumb

empty star
#

is that the answer for all of these

proud mural
#

yeah it would be

#

since its continuous

empty star
#

okok

#

thanks so much

#

i feel like we've been doin a lot of equations and not a lot of pulling from graphs so the graphs are trippin me up

#

.close

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stark wigeon
#

Can someone check my working for biii)? \
let $P(x) = x^3 - 6x^2 + 9x - 15 = 0$; therefore $P(x+1) = x^3 - 3x^2 - 11$ thus $e_3(\alpha - 1, \beta - 1, \gamma - 1) = 11$

stark wigeon
#

i cant find the answer sheet anywhere sad

wise hamlet
#

I am not getting it plz help

stark wigeon
#

please occupy another help channel which isnt already open!

woven radishBOT
wise hamlet
faint hearth
#

,w expand (x+1)^3 - 6(x+1)^2 + 9(x+1) - 15

stark wigeon
#

the logic is fine aswell?

faint hearth
#

yeah because the roots of P(x+1) will be alpha-1, beta-1, gamma -1

stark wigeon
#

perfect thats what i supposed haha, thanks!

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compact hawk
#

A 5 x 7 rectanglebis partitioned into 1x1 squares. Then two opposite 1x1 corners squares are removed resilting in the figure. How many squares with integer lenght sides can be found using the line segments in the resulting figure

compact hawk
#

Uhhh i js did like 33 + 6+ 2

#

Which was wrong 💀

#

Answer is 75

pseudo basin
compact hawk
#

Then 6 2 by 2 squares

#

Then 2 3 by 3 squares

pseudo basin
#

hmm

#

only six 2×2 squares?

plucky marten
#

i think there might be more than 6 fr

pseudo basin
#

there are more ways to position a 2×2 square in there.

#

let me reproduce the grid, one moment

#

these are the possible locations of the southwest corner of a 2×2 square within the grid

compact hawk
#

Wut

#

Oh wait we can js overlap it

pseudo basin
#

if a 2×2 square fits in the grid, its SW corner has to be one of the green tiles.

#

this is the same but for 3×3 squares.

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and this is for 4×4.

compact hawk
#

Wha

#

💀

pseudo basin
#

just how many positions a 2×2 square could go in so that it's contained inside the grid

pseudo basin
pseudo basin
#

if a 2×2 square fits in the grid, its SW corner has to be one of the green tiles.

#

southwest as in bottom left.

compact hawk
#

Wait lemme try to process what u are saying 💀💀💀💀

plucky marten
#

i was wondering what u meant but then i realized that u were talking about the bottom left corner or southwest piece of the 2x2,3x3 and 4x4

#

like the positions they can occupy

pseudo basin
compact hawk
#

Okok i understand it now

pseudo basin
#

oh yeah

#

ok

#

you understand it after a man repeated it

#

what a coincidence huh

compact hawk
#

Then realise oh

pseudo basin
#

bottom left means bottom left... it's pretty clear, no?

#

like ↙️

compact hawk
#

When u said i thought like u meant the 2 x 2 squares can only fit onto thr green part

#

💀💀

#

Then i got confused on why the unshaded part cant be used

plucky marten
pseudo basin
#

i BOLDED the words "southwest corner".

plucky marten
#

chill

pseudo basin
compact hawk
#

😭🙏

plucky marten
#

some of us are dumb and it takes time to process

compact hawk
#

So 33 + 22 + 13 + 6

#

Wait uh

#

Oh yea

#

5 x 5

pseudo basin
#

that one 5×5 square, yes.

#

it can only go in one place

compact hawk
#

So its 33 + 22 + 13 + 6 + 1

#

Alright tyty

#

.close

devout snowBOT
#
Channel closed

Closed by @compact hawk

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plucky marten
#

just a sec

compact hawk
#

?

#

.reopen

devout snowBOT
plucky marten
#

@pseudo basin can u explain how to use combinitions to do this

pseudo basin
#

uhh what

#

are you asking how to shoehorn nCk shit in there

plucky marten
#

ye

#

basically

pseudo basin
#

no

#

there's no way that would save you any effort

compact hawk
#

💀

plucky marten
#

no like if i learnt that then i can do it for even larger ones

#

like 2025*2029 and 4x4 is removed

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from corners

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and i just got denied girlbleak

compact hawk
#

Anyways wait how do u use combinations in such questions

#

Im genuinely curious

plucky marten
#

i have seen some for like a rectangle

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but never with pieces removed

#

so i wanna know

carmine veldt
plucky marten
#

i dont rly know i js know the formula

#

like idk the proof fr

carmine veldt
#

uh ic

pseudo basin
#

for a full rectangle the limiting factor is whichever of width and height is smaller

#

or... ok not quite

#

i guess you kinda can make a formula for a rectangle of size m by n with m <= n but i honestly do not feel like writing it all out

carmine veldt
#

real 😭

#

hmm

#

@plucky marten cmere

plucky marten
#

here

carmine veldt
#

I'll js explain the steps, simplification if upto you, alr?

plucky marten
#

ite

carmine veldt
#

so to find total number of squares in a mxn grid

plucky marten
#

oh wai

carmine veldt
#

we take cases finding total number of ixi squares such that 0 < i < min(m,n) + 1

pseudo basin
#

@plucky marten @carmine veldt get your own channel

carmine veldt
#

ah alr mb

plucky marten
#

itw

pseudo basin
#

this used to be @compact hawk's channel

#

so yall need to take a new one in one of your names

#

.closw

#

.close

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#
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snow shore
#

What am I doing wrong? Everything I read tells me this is how to do it but I keep getting the wrong answer

snow shore
#

I feel like I am losing my mind and am over this

#

I've tried this 8 times

#

I keep looking for info on what I can be doing right, but all the resources avalible say this is the right way to do it

#

<@&286206848099549185>

carmine veldt
#

but you can't really do it without knowing the weight of the diver

snow shore
devout snowBOT
#

@snow shore Has your question been resolved?

snow shore
#

How should I find the weight

lunar harbor
devout snowBOT
#

@snow shore Has your question been resolved?

devout snowBOT
#

@snow shore Has your question been resolved?