#help-27

1 messages · Page 315 of 1

muted mural
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You're welcome

somber mulch
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i will try and see if i can fix it now

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rocky marlin
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I need help with b

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rocky marlin
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<@&286206848099549185>

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<@&286206848099549185>

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Bro can someone help ive been sitting here for so long wasting time that could be spent doing something fun in my life

cinder nova
pure kelp
rocky marlin
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Ik which is 7.5 but it need to be coordinate form

pure kelp
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you'll need to use that here

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assume the point you want the coordinates of to be (x,y)

rocky marlin
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k

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lapis mirage
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lapis mirage
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I don’t get number 5

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?

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(Sorry I don’t mean to rush I just texted the ? To show am still here and didn’t leave)

lunar eagle
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@lapis mirage Has your question been resolved?

lapis mirage
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What

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Nvm

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How is x 43.2

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Oh you use sin^-1

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zenith fable
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if $||x||^{2}_{c^-1} = x^t C^{-1} x$ then would the square root of this would be the similar but then would be $\sqrt(||x||^2{c^-1}) =\sqrt(x^t C^{-1} x)$ right?

woven radishBOT
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RealTek

stone stump
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well the latex is fucked up

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but if two things are equal then you can take the root on both sides, sure

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modulo dealing with positive/negative but thats not a problem here

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zenith fable
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because im able to make a simpflicatin in my code that cuts down run time from like 5 minutes to seconds

zenith fable
stone stump
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just taking roots should not speed up your code that much

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zenith fable
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and i am writing up my thesis right now, and i saw a way to take it further

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from scipy.sparse import identity
#e_j = identity(66049, format="csr")
result = (C_op @ fwd.T) @ (np.linalg.solve((fwd @ (C_op @ fwd.T)) ,fwd @ U))

this was a lagranian process i ran.

Then i took the norm of this

w = np.zeros(result.shape[1])

for j in tqdm(range(len(w)), desc="Processing columns"):
w[j] = np.sqrt(result[:, j] @ (C_inv_op @ result[:, j].T))

however, i had an idea and it reduced the code to this here

w = np.sqrt(np.diag(U.T @ fwd.T @ np.linalg.solve(fwd @ (C_op @ fwd.T), fwd @ U)))

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so its much much faster'

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but im asking about this because i want to make sure i got my head screwed on before coming to my supervisor with this idea '

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im more of a comp sci guy, and i fail with the math so i just wanted to make sure

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thank you 🙂

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halcyon solar
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Let F(t) be a parametric curve whose domain is an interval I ,
such that F′(t) = 0 for every t ∈ I . Show that F(t) is
constant.

this is very intuitive, yes but how am i supposed to write the proof?

pseudo basin
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show each of its coordinates is constant

halcyon solar
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so just f(t)=[c1, c2, c3] with d/dt=[0,0,0]

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thats it, thanks

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gentle flume
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gentle flume
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Hi I need help with Integrals

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weary arch
#

If i may ask a math related coding question: in python, given two numpy arrays of shapes (a, b, c, ..., 2) and (x, y, z, ..., 2), is there a way to add them along the last axis to give something like (a,b,c,...,x,y,z,...,2)? e.g. a.shape == (4,3,2) and b.shape == (8,6,2), then i want a+b to be (4,3,8,6,2) if that makes sense. If there is a builtin way of doing something like this it'd be great! Doing b[:, None, None, :] works but only for a specific case

wispy oyster
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so merging two arrays with last index being 2?

weary arch
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two arrays with their last dimension being 2

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or any number really

wispy oyster
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remind me, is python 0-indexed again

weary arch
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yes

wispy oyster
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okay you could loop from 0 to (number of elements of the array two -1) and access each element of array 2. I dont use python much but i think theres an append function which you can use it to add it to array one on index after the first n-1 elements

weary arch
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both arrays are higher dimension arrays (from 1 to 4 in practise), i dont think this is it...

wispy oyster
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oh its not a 1 dimensional array?

weary arch
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like a = [[[2,3], [4,5], [6,7]], [[1,2], [3,4], [5,6]]] for example

wispy oyster
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ah i see

weary arch
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then a.shape == (2,3,2) i believe

wispy oyster
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what does the shape function do

weary arch
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shape returns the dimensions of the array

wispy oyster
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ahh

weary arch
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Like (M, N) would be your usual M by N matrix

wispy oyster
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im not too equipped with python to figure this out, hope someone else can help here

weary arch
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nw, thanks anyways!

sullen island
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Doing b[:, None, None, :] works but only for a specific case
wdym by specific case here ?

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@weary arch

weary arch
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and thanks for the tip, though not sure how to apply it here

sullen island
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well I ain't exactly sure what you're trying to do here

weary arch
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For now i think I'll just add the maximum number of newaxis everytime and reduce from there

sullen island
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could you try and give a simple example of what you want ?

weary arch
sullen island
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say (n, 2) and (m, 2) to (n,m,2)

weary arch
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yes!

sullen island
weary arch
weary arch
weary arch
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(the context here is a simple integral along a straight line segment in 2d, but i want to vectorise the code to take in multiple positions (two or three dimensional r) at once as well as integrate over multiple line segments at once (two dimensional a and b, but then theres a linspace in there), anyways this is getting annoying...)

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@weary arch Has your question been resolved?

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@weary arch Has your question been resolved?

faint zinc
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sorry, retracted.

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I saw you already answered the question a little bit higher, my bad

weary arch
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nw!

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@weary arch Has your question been resolved?

weary arch
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Actually I think something like b[..., *(None,)*len(a.shape), :] works, although a bit ugly..

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Enjoy some beautiful point sources together

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tulip pendant
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How do I get the upper bound for the integral

tulip pendant
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Lower bound solved to be one using basels

weary arch
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Consider the taylor series of sine/cosine!

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(it should be one of them i believe)

tulip pendant
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Cosine looks like

tulip pendant
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sonic hill
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can anyone explain why the set {1, 1/2, 1/3,...} is Jordan Mesurable

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@sonic hill Has your question been resolved?

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sonic wadi
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sonic wadi
#

<@&286206848099549185>

pseudo basin
#

@sonic wadi stick to one channel. i have closed your other two.

sonic wadi
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alright

pseudo basin
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so... you just want somebody to tell you how much you scored on this test?

tranquil bloom
#

You got them all wrong

sonic wadi
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as an asian

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if it is true

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this will the last time you will hear from me

pseudo basin
tranquil bloom
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Because you ticked every answer, which is diabolical

pseudo basin
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i can see at least question 38 seems to be right? on the first pic?

pseudo basin
tranquil bloom
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Seems you got most right though

sonic wadi
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in india it is allowed to write on the test

tranquil bloom
pseudo basin
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...

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anyway ok

tranquil bloom
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All though I guess an answer sheet was there

pseudo basin
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let me go through it all, i guess...

sonic wadi
tranquil bloom
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And this was just the paper which doesn’t matter

sonic wadi
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in india

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a single sheet of paper decides your entire future

tranquil bloom
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What test is this even

sonic wadi
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if you will be kept in the family or not

tranquil bloom
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That seems more of a socio-cultural issue

sonic wadi
mystic scarab
sonic wadi
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it is reality

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for us

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that is why many people after getting marks which doesn't meet there parnets requirements

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take their own life

tranquil bloom
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A grade 5 level test determining your life sounds harsh

pseudo basin
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@sonic wadi do the questions in sections B, C and D carry any partial marks

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or is it just get full marks on right answers and 0 otherwise

sonic wadi
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they carry

pseudo basin
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(im still going through section A, mind you)

sonic wadi
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ok

pseudo basin
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where did you write your answers to questions 19 and 20?

sonic wadi
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i wrote

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19 is b

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and 20 is a

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a

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Q21. K=-3, Q23 and Q24 are right (i was able to prove)

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Q27,Q28,Q29 i was able to do

pseudo basin
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should i just take your word for 23 and 24

sonic wadi
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yes

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Q33 and Q34 (a) part i was able to do

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Q35. slant height=26

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Q36. C answer is 10

tranquil bloom
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Someone check 26

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From headsolving, I get a different answer but it’s a high chance my mental maths is wrong

pseudo basin
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26 looks correct to me.

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i am on section D rn

sonic wadi
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Q26 was a bit challenging at first

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but if you use (x+y+z)^2 identity

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you can get the answer

tranquil bloom
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Yeah it’s 124

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I thought it was 2124 and was like no way the answer is that big

pseudo basin
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ok

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i think i have calculated all of it

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and the total comes to 72 marks

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90%

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but i had to take your word for 23 of these marks so be careful

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@sonic wadi

sonic wadi
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where was i worng

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wrong

sonic wadi
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but still where i am wrong

sonic wadi
sonic wadi
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where have you gone @pseudo basin

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hello

pseudo basin
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18, 36bc, 37c is where you lost marks

sonic wadi
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ok

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hey 18 is right

pseudo basin
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unfortunately i cannot do anything about the family who are about to commit literal murder on you or even worse abandon you to suffer forever

pseudo basin
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i see you ticked 7

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the correct answer for the UPPER boundary is 13

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so nope

sonic wadi
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ok

pseudo basin
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how old are you and why is your family putting you through such harsh testing

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it's very fucked up of them

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#
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sonic wadi
#

Q36. C answer

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kind flame
#

these are my notes from lecture, I understand that everything up until 5/9N < 1/N but i'm not sure why we can just equate 1/N to epsilon

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kind flame
#

someone pelase help sobbing

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supple trench
#

we equate 1 / N to ε cuz we want ε on the RHS of the inequality, so that it matches the (RHS of the) inequality

|f(x) − L| < ε
in the definition

kind flame
#

tysm

#

❤️

#

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dusty sigil
#

hi

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dusty sigil
iron kindle
#

whats your question

dusty sigil
#

how do i solve this?

supple trench
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iron kindle
devout snowBOT
# dusty sigil

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

faint gorge
# dusty sigil

Doesn't seem doable that way, I suggest to change the order of integration.

dusty sigil
faint gorge
#

your y bounds are wrong

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ln(1) and ln(2) are the y bounds

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and your x bounds should be from e^y to 2

dusty sigil
faint gorge
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this precisely

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you are now integrating along the y-axis so you need to look at it vertically

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so in order to capture still the same region (the red one)

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it is bounded by the line x = 2 and curve x = e^y

dusty sigil
#

this is the original ya?

faint gorge
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ye

dusty sigil
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isnt it 0 to ln2?

faint gorge
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and what is ln(1)?

dusty sigil
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OMG

dusty sigil
faint gorge
dusty sigil
#

okay wait im back to square

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its looks like integrating the thing originally

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before flip

faint gorge
#

it should been from e^y to 2 but tbh it doesnt look very promising

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faint gorge
dusty sigil
#

my friend sent me the answer its like this

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just a simple u sub xD

faint gorge
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i am so dumb

dusty sigil
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nah its my fault

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i messed up the upper and lower bound

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so its harder to see the

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pattern

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but thansk so much i learn much from the flip (which is the the main point)

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🙏

#

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mellow willow
#

I am confused what my teacher met by “ opposite inputs produce the same outputs” and opposite inputs have opposite outputs “

mystic scarab
#

Do you know what opposite means?

lament plover
#

on the upper one whether u give +x or -x u get +y
but in the lower if u give +x u get +y, if -x u get -y

fierce matrix
#

If y axis is a road, and (1,4) is a shop, opposite the shop there is a laundrette, at (-1,4)?

lament plover
#

well i can see the teacher clearly cooked with the wording

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it only makes sense 4 the second one

fierce matrix
#

If you fold the first graph along the y axis, you get the same graph, the graph is symmetric to the y axis, in other words even. x values on opposite sides of the x axis, where the origin is the middle, are mapped to the same y values, or outputs.

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For the second one if you fold the along the y axis and then along the x the curves match, I think.

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A value and its additive inverse as inputs are both mapped to the same output, that's the even function, the parabola.

fierce matrix
mellow willow
lament plover
little totem
#

a simpler way to say this, since it looks like you know functions already from the worksheet

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even functions: f(x) = f(-x)

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odd functions: -f(x) = f(-x)

fierce matrix
#

I didn't know the names odd and even came from the powers of x.

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#

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thick schooner
#

i vaguely remember lol!

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toxic kernel
#

The final project involves examining and analyzing statistical data. The project can be completed in pairs or individually.

Those working in pairs must document their work and submit a brief text along with the project, describing how the collaboration went and what each person contributed.

Distance learners must also keep track of their work on the project and submit it with the final deliverables. This can be done through short journal entries or a brief report (no more than one page).

1)

The first step is to find a dataset or research topic (in consultation with the teacher) that you are interested in analyzing based on what you have learned in the course. You can search for data online, such as on the Statistics Iceland website or the Eurostat website. Both sites offer a variety of datasets that can be downloaded in Excel format for analysis. Once you have found a dataset(s) of interest, you must contact the teacher to confirm that the data is suitable for the project.

2)

Next, you will conduct a simple study by analyzing your data using the statistical knowledge gained in the course. The analysis will vary depending on the topic and datasets, so use creativity and focus on what best suits your research goals. Use descriptive statistics to present numerical information and graphs. Interpret the results in your own words and relate them to the data.

(Concepts covered in the course that you might explore include: descriptive statistics, measures of central tendency (mean, median, mode), distribution (range, mean deviation, standard deviation), correlation, significance, normal distribution, binomial formula, etc.)

toxic kernel
#

3)

You will present your findings to the teacher and classmates on the assessment days at the end of the term. The presentation format can vary (e.g., slideshow, video, brochure, or poster).

The presentation should include:

  • Introduction: Overview of the topic and objectives.
  • Methodology: Description of methods and statistical processing.
  • Results: Explanation of findings with tables and graphs.
  • Conclusions: Summary of results and interpretation of their significance.

Presentations will take place on Teams on Monday, March 3rd, between 10:00-12:00. Both distance and on-campus students are expected to attend. Note that the presentation accounts for 30% of the project grade.

4)

In this submission area, you must submit:

  • Your presentation materials.
  • The Excel files used for the project (work documents).
  • If the project was done in pairs, each student must submit a short text discussing the collaboration and their individual contributions.
  • Distance learners must also submit their report on their work for the project.
#

I chose unemployment rate.

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restive river
devout snowBOT
restive river
#

for the part b

#

is that gonna be like i make a secant from p to q1

#

then p to q2 then q3 q4

#

getting closer to the p

#

that would be the tangent

#

i suppose?

#

.close

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#
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icy acorn
#

Determine all extremum points of this function and classify them!

so normally I would take the 1. derivation of the function, set equals 0, 2. derivation, form the Hesse matrix and the determinant and then classify. Is there a quicker way to find the solution cause this is lowkey time consuming

sonic wolf
#

hello im not rly sure how to use this discord server but i need help with any tips on factorizing and simplifying in grade 9 maths

icy acorn
icy acorn
#

this is occupied

#

by me

#

hi hi

sonic wolf
#

oh sorry i dont rly know how to use this server

icy acorn
#

read how to get help

#

<@&286206848099549185>

supple knot
icy acorn
#

oke

#

.close

devout snowBOT
#
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finite briar
#

HELLO

devout snowBOT
finite briar
#

what why is that in caps

#

uhh

#

whatever

iron kindle
#

!da2a

devout snowBOT
#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

finite briar
#

integration time (source: mqnic)

#

$-\frac{1}{4}\int_{0}^{\infty}\frac{1}{te^{t}}\sum_{n=1}^{\infty}\frac{1}{n\left(-t\right)^{n}}\left(\int_{0}^{t}x^{\frac{n-1}{2}}e^{-x}dx\right)^{2}dt$

woven radishBOT
#

rak³en

finite briar
#

alrighty

iron kindle
#

yuck

finite briar
#

right off the bat, the squared term is the lower incomplete gamma function

#

iirc theres a recurrence relation between the s+1 and s terms

finite briar
#

found it

#

from here I should be able to get a result in terms of the error function (gamma(1/2, t)) and a e(-x)(finite GP)

#

or something like that

#

but the square term scares me :\

finite briar
#

but I have to check convergence before hand

#

which reminds me does this converge as written at all?

devout snowBOT
#

@finite briar Has your question been resolved?

finite briar
#

<@&286206848099549185>

devout snowBOT
#

@finite briar Has your question been resolved?

raw bear
# sonic wolf oh sorry i dont rly know how to use this server

Pick any channel that has the word "help" in its name WITHOUT the "|" and the name of someone behind (the person who occupied the channel).

But your question is too broad,
so i think the math-discussion channel should be fine,
the help channels are for specific problems
@sonic wolf

finite briar
#

<@&286206848099549185>

#

@dense lynx

#

where did u bring this nightmare from

dense lynx
#

this probably is not solvable

dense lynx
#

$\int_0^1 \int_0^1 \frac{\ln(1 + xy)}{1 + x^2 + y^2}, \mathrm{d}x, \mathrm{d}y$

woven radishBOT
#

Mqnic_

finite briar
#

thank you for giving me the original integral

finite briar
dense lynx
#

no

#

this is a gpt integral btw

#

so most likely (and i think) it is utter nonsense

finite briar
#

💀

#

looks interesting

#

I wanna know if this converges tho

dense lynx
#

it does

finite briar
#

How did you test a double integral?

dense lynx
#

to about 0.1111415849

#

you check it numerically using like matlab or wolfram

#

well ig that’s not necessary here

finite briar
#

I see

dense lynx
#

this function has no poles where integrated and it’s integrated over a finite region so it’s not like it’s going to diverge anyway

finite briar
#

oh right good point

finite briar
#

.close

devout snowBOT
#
Channel closed

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empty flame
#

still obsessed with integrals as usual sotrue

devout snowBOT
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long panther
#

can someone explain the derivative of a^x to me without any circular reasoning

crude spruce
woven radishBOT
#

kizzyyy

long panther
#

yea

#

i swear to god if you use the derivative of e^x or logarithms im actually gonna jump out my window

misty crest
#

bruh

#

i mean the alternative is limit definition lmao

long panther
#

let me guess

#

then we use lhoptial

iron kindle
woven radishBOT
feral agate
misty crest
long panther
feral agate
#

$\dv{}{x} \left(a^x\right)=\lim_{h\to 0}\frac{a^{x+h}-a^x}{h}=a^x\cdot\lim_{h\to 0}\frac{a^h-1}{h}$

#

e is defined as the value of a for which that second limit is 1

#

wtf

woven radishBOT
#

kheerii

long panther
#

let me guess then that limit is equal to lna

misty crest
#

and?

long panther
#

thanks for 0 circular reasoning

feral agate
#

dude...

misty crest
#

you’re insufferable

#

he derives the derivative of e^x using this

#

using the definition of e^x

feral agate
#

define $e^x$ as the taylor series $1+x+\frac{x^2}{2!}+...$ and prove everything from there

woven radishBOT
#

kheerii

long panther
misty crest
#

nothing is circular smart guy

misty crest
#

cry more

long panther
spring salmon
#

taylor series is calc 2

#

lol

feral agate
#

you have to start from some definition of an exponential

#

it could be the limit or the series

misty crest
#

it’s literally just a definition

long panther
misty crest
#

you don’t know what circular means

#

stop using words you don’t understand

iron kindle
long panther
#

im talking about how youd show the derivbbative of ax^b

misty crest
#

🤔

spring salmon
#

did you watch the video

#

in full

misty crest
#

obviously not

feral agate
#

are you trolling

misty crest
#

has to be

long panther
#

thanks

spring salmon
#

np

long panther
#

.close

devout snowBOT
#
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deft scaffold
#

(ignore that some of the numbers are different between the two images, but im struggling to understand why in the first image the (12-y) is not squared?

pseudo basin
#

they are doing it with the shell method

#

neither the 12-y nor the y^2 are supposed to be raised to the second power here

#

it's just that their shells enclose the x-axis rather than the y as is usual

deft scaffold
#

ah

#

that'd do it

#

definitely did NOT forget about shell method (whoops)

devout snowBOT
#

@deft scaffold Has your question been resolved?

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mystic bloom
devout snowBOT
mystic bloom
#

Idk how to do binomials

devout snowBOT
#

@mystic bloom Has your question been resolved?

devout snowBOT
#

@mystic bloom Has your question been resolved?

devout snowBOT
#

@mystic bloom Has your question been resolved?

tawny pewter
devout snowBOT
mystic bloom
#

Idk how to do it

tawny pewter
#

what do you know about the binomial dist

#

In probability theory and statistics, the binomial distribution with parameters n and p is the discrete probability distribution of the number of successes in a sequence of n independent experiments, each asking a yes–no question, and each with its own Boolean-valued outcome: success (with probability p) or failure (with probability q = 1 − p). ...

mystic bloom
#

Idek wat a binomial is

tawny pewter
#

if you pick one american what's the probability he lives in a city with 100k+ people in it?

tawny pewter
# mystic bloom Idek wat a binomial is

it's a random variable representing the number of success after n trials, in your cases the "successes" are people living in a city with 100k+ population and the number of trials is 30.

tawny pewter
# mystic bloom Idek wat a binomial is

ok let's make this simpler, if you pick one person, he has 7/10 chances/probability to be in a city with 100k+ pop (and 3/10 chance not to) it's a binomial n = 1, p=7/10, if you pick 2 person, both can be in such a city, none of the 2 and 1 of the 2 so the number of people in a city with 100k+ pop in your sample of 2 people (let's call it X) is a binomial with n=2 and p = 7/10 with the probabilities P(X=0) = (3/10)^2 P(X=1)=2 * (3/10) * 7/10 and P(X=2) = (7/10)^2

#

does this make any sense?

tawny pewter
mystic bloom
#

Oh

#

7/10

tawny pewter
#

that's the p parameter in the binomial distribution

#

ok now for a) let's make it simpler, if you had 3 American instead of 30 what's the chances that exactly 2 of them are in a city with 100k+ pop in it?

tawny pewter
mystic bloom
#

idrk wat p() means in stats

tawny pewter
#

It's a shorthand for the probability the chance that a random variable takes a certain value

#

so for one people the probability that exactly 1 guy lives in a city with 100k+pop is P(X=1) = 7/10

tawny pewter
mystic bloom
tawny pewter
tawny pewter
#

This video provides an introduction to probability. It explains how to calculate the probability of an event occurring in addition to determining the sample space of an event using tree diagrams.

Probability - Free Formula Sheet: https://www.video-tutor.net/formula-sheets.html

Statistics - Video Lessons:
https://www.video-tutor.net/statis...

▶ Play video
devout snowBOT
#

@mystic bloom Has your question been resolved?

mystic bloom
#

ill try tmrrw idk

devout snowBOT
#

@mystic bloom Has your question been resolved?

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#
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inner ibex
devout snowBOT
inner ibex
#

how do they know the domain

#

i only know the range

lost laurel
#

huh, domain of 1/(9-x), right

inner ibex
#

how do i know the domain for that..

wispy oyster
#

domain of the inverse function is the range of the original function

inner ibex
#

how is the range -infinity

#

,0

wispy oyster
#

the denominator is always negative for x>9

#

so from -inf to 0

#

0 not included since that is the horizontal asymptote

inner ibex
#

wow this is hard 😢

inner ibex
#

wait that ones easy

#

ok so the range of the inverse function is

#

(1,infinity)

#

and the domain is

#

idk..

#

is it

#

2^2 - 1 bcoz x is greater than 1 but not 1... so u sub in 2 to find the smallest value..

#

(3, infinity)

wispy oyster
#

finding range can be tough by just looking at the function

#

advice:
find inverse, look at the domain of the inverse

#

that is the range of the original function

inner ibex
#

dom of inverse is

#

[-1, infinity)...

wispy oyster
#

yes that is correct but notice how they have the x>1 requirement

inner ibex
#

yea

#

what can i do about that

wispy oyster
#

f(x) = x^2 - 1
range are all possible outputs, if x>1 then the minimum value would be something around x~1, plugging that in yields
f(1.000000001) = 0. So the range is from 0 to inf

#

for quadratics, u can find the range by finding the max or min

inner ibex
#

in the thing

#

x>1

#

im havign trouble finding da domain

wispy oyster
#

thats the domain, x>1

inner ibex
#

oh

#

ok othewr way round

#

im having trouble finding the range of the function

wispy oyster
#

thats 0 to inf

inner ibex
#

oh

#

im having trouble finding the domain

#

wai tisnt the domain

#

(1,inf)

wispy oyster
#

yes

#

which also means x>1

inner ibex
#

howw it 0

wispy oyster
#

look at this graph

inner ibex
#

yes

wispy oyster
#

since we restrict domain to x>1

#

we start at around x=1

#

notice how it is 0 at x = 1

#

but 0 is not included since the initial condition was x>1 so it is (0, inf)

inner ibex
#

if we restrict the domain to x>1 dont we have to start at x=2

wispy oyster
#

is 1.0000001 not a number?

inner ibex
#

oh

#

1.0000000000000000000000000001

#

wow thats cheating because then wont the range thing be off by a few 0.00000000000000120121391293

wispy oyster
#

u have infinite real numbers between any two points a and b no matter how close a and b are as long as |a-b| ≠ 0

#

there are infinite real numbers between 0.0000000000001 and 0.0000000000000000001

inner ibex
#

oh

#

ok

#

what is it was x>=1

#

would the range be da same

#

wait ok let me try again with my new found knowledge

inner ibex
#

he makes the subject x

wispy oyster
#

yes

inner ibex
#

ohhh okok

inner ibex
wispy oyster
#

its not cheating

#

if you use ≥, it means inclusive

wispy oyster
#

the range would be [0, inf)

#

notice the square bracket

#

it means 0 is a possible value that the output can take

inner ibex
#

how tf do i make x the subject

inner ibex
#

..

#

z:C

wispy oyster
#

,w quadratic equation

wispy oyster
#

,quadratic equation in terms of a,b,c

#

,w quadratic equation in terms of a,b,c

wispy oyster
#

use the quadratic equation to isolate x

devout snowBOT
#

@inner ibex Has your question been resolved?

inner ibex
#

cant u jus tcomplet ethe square much easier

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#
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stone juniper
#

$$In the arithmetic progression (a_n): a_{1} = - 4 , a_{5} = a_{4} + 3; Determine the (a_1_0) of this progression.$$

woven radishBOT
#

www.
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

wide ember
#

what is common diffrence

#

an - a(n-1)

#

you are given that in question try to find it

devout snowBOT
#

@stone juniper Has your question been resolved?

stone juniper
#

i dont understand

#

$a_n - a(n-1)$

woven radishBOT
wide ember
#

no

#

bro

#

ur given

#

a5 = a4 + 3

#

right?

#

then how will you find common diff from this info?

#

think about it

stone juniper
#

i can express $a_5$

woven radishBOT
stone juniper
#

$a_5 = -4 +3d +3$

woven radishBOT
wide ember
#

no how else

#

try moving a4 to the other side

#

what do you get?

#

$a_5 - a_4 = 3$

woven radishBOT
#

lizzie250

stone juniper
#

yes

wide ember
#

and this is equal to?

stone juniper
#

-4

wide ember
#

bro what?

stone juniper
#

$a_5 - a_4 = a_1 = -4$

woven radishBOT
wide ember
#

no

#

what is the formula of common diff?

stone juniper
#

$d = a_2 -a_1$

woven radishBOT
stone juniper
#

oH ITS DIFF

wide ember
#

yessss

stone juniper
#

we got diff 3

wide ember
#

and you now know the diff

#

yesss

#

so a10 is?

stone juniper
#

23

#

-4 + 27

wide ember
#

yes

stone juniper
#

craftily task

wide ember
#

lol

stone juniper
#

thank you

wide ember
#

np

stone juniper
#

.close

devout snowBOT
#
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finite briar
#

time to open a help channel

devout snowBOT
olive snow
#

Never a bad time to

finite briar
#

how to convert this into polar coordinates

#

and more generally any rectangular polygon into polar coordinates

jaunty mantle
#

That looks hard

lost laurel
jaunty mantle
#

That doesn’t look very nice to polar coordinates

lost laurel
#

if so that would help

#

but it won't be pretty

finite briar
jaunty mantle
#

Especially ones that aren’t centred

finite briar
olive snow
#

Like

finite briar
jaunty mantle
#

Like your r both the top and bottom limit needs to change wrt θ i

finite briar
#

i think of r like the minute hand of a clock

jaunty mantle
#

I have this

#

Hate

finite briar
jaunty mantle
#

Yeah

#

Cos you need to cut out the bottom

#

Your r isn’t starting from the origin

#

Or any nice circular line

finite briar
#

ur photo btw

#

it had two regions

#

was it because i also had the bounds flipped

#

for the 2 variables

jaunty mantle
#

And your question had 2 integrals added together

#

Yes

finite briar
jaunty mantle
#

It’s 2 times 1 of the parts

#

Now

#

Have you considered

#

Doing the square or triangle

#

And subtracting the extra bits

finite briar
#

no

#

because i came here from a square

#

if u remember gpt integral is over a unit square

jaunty mantle
#

Like do this bits?

finite briar
#

wait 🤯

jaunty mantle
#

Like do the big square

#

The minus the small square and the medium square

#

Idk just a thought

#

They seem a bit nicerly aligned for polar coords

finite briar
#

maybe let me see

#

i think i'll worry abt this one later

#

thx for the idea

#

the reason i split it is because if $|x|,|y| < \frac{1}{\sqrt{2}}$ then i can expand $\frac{1}{1+x^2+y^2} = \sum_{n \geq 0} (x^2+y^2)^n$

woven radishBOT
#

rak³en

finite briar
#

right??

jaunty mantle
#

I don’t know and I’m too tired atm

finite briar
#

.close

devout snowBOT
#
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wide ember
#

help

devout snowBOT
wide ember
crude spruce
#

33 + 57 = 90

#

69 + 21 = 90

#

that should give you some ideas

#

hopefully

wide ember
#

convert to sin^2 theta?

wicked turtle
#

also 69-21 =48 and 57-33 = 24 = 48/2, might be useful(?)

wide ember
#

i converted the numerator to sin^theta

pseudo basin
#

do not miss the two

wide ember
#

yeaaa..but now i am stuck

pseudo basin
#

hang on a minute

#

this is sus

wide ember
#

??

#

it is trigo ratios of compund angles

pseudo basin
#

what do you have on the numerator exactly

#

in full

#

just to check that we have not both gone off track

wide ember
#

sin^2 57 - sin^2 33 / sin^2 (21/2) - sin^2 (69/2)

#

all in degree

pseudo basin
#

ok so i asked you for only the numerator

wide ember
#

sorry

pseudo basin
#

but if you were gonna give the entire fraction then you would have to wrap the numerator and the denominator in parentheses

#

anyway

#

it is actually better to convert only ONE of the things on top to a sine

#

so cos^2(33) - sin^2(33)

#

this is cos(2*33)

wide ember
#

soryyyyy

pseudo basin
#

the bottom is sin^2(10.5°) - sin^2(34.5°)...

wide ember
#

yes

pseudo basin
#

wait so you've learned the compound angle formulas right

wide ember
#

not in school but on my own yes

#

ohhh

#

ok

#

nvm

pseudo basin
#

then you also know that sin^2(x) = (1 - cos(2x))/2 yes?

wide ember
#

thxx

#

thank you sooo muchh

#

.close

devout snowBOT
#
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versed ledge
devout snowBOT
hexed fractal
# versed ledge

what's the general equation of a circle? do you think you can work your way around convert this?

versed ledge
#

Its ok i got now for b

#

Use discriminant

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#

@versed ledge Has your question been resolved?

versed ledge
#

Yes

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feral skiff
#

A tower stands on level ground. From a point P on the ground, the angle of elevation of the top of the tower is 26 degrees. point q is 3m vertically above p and from this point the angle of elevation of the top of the tower is 21 degrees. Find the height of the tower. This is in the sine cosine rule chapter btw.

rose rock
#

Start by drawing a diagram

feral skiff
#

this is what I thought it was trying to describe

#

i then tried 90-26 = 64 degrees

#

Is that allowed?

#

I then did 180 - 26 - 64 = 90

rose rock
#

Think that 23 should be 21 and it should be from a line parallel to the base

feral skiff
#

the answer is 14.1

#

I used the sine rule to try get this line, but it came out to 1.2 which is way off

rose rock
#

That 23 is not the angle there

feral skiff
#

ok

#

could you draw it?

rose rock
#

Yeah gimme a moment

#

That's where your 23 is

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feral skiff
#

ohhh

#

nvm I still dont get it

#

is this right? where do I go from here?

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feral skiff
#

.reopen

devout snowBOT
#

wintry flare
#

do you know which trig function would you use here

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feral skiff
#

.reopen

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#

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wintry flare
# feral skiff nope

based on the picture you drew and the value youre trying to find (height) it would be cosine

#

wait

#

lemme actually solve the problem first, im lowk talkin crazy

#

@feral skiff okay sorry, you'd be using tangent lol

feral skiff
#

can you explain what im supposed to do im completely lost

wintry flare
#

so it give you two angles, 21 degrees and 26 degrees

#

you can make a relationship between the height using tangent for both

#

tangent = adjacent/opposite

#

so, for point q, you know tan(21)=h/x

#

does this make sense so far ^

feral skiff
#

yeea

wintry flare
#

now try the same for point p

feral skiff
#

yea i dont get it lol

#

a worked solution would honestly be the best thing imo

wintry flare
feral skiff
#

i just dont get it

#

i dont see how you apply tan to this

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@feral skiff Has your question been resolved?

wintry flare
valid vector
#

@feral skiff Can you show the original question you need help with?

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#

@feral skiff Has your question been resolved?

feral skiff
feral skiff
valid vector
# feral skiff is this right? where do I go from here?

That is a correct diagram. Now, let us denote h to be the height of the tower, and x to be the distance from point P to the tower. Note that $\sin(23^{\circ})=\frac{h-3}{x}$, and $\sin(26^{\circ})=\frac{h}{x}$. Do you see why?

woven radishBOT
#

mathisfun

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coral cosmos
#

How do I find the area of triangle ABC

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winter patrol
#

what have you tried

coral cosmos
#

NVM I figured it out

#

sry

#

.close

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coral cosmos
#

Need help writing the equation to solve this

winter patrol
#

what have you tried?

jovial current
coral cosmos
#

.close

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dark siren
#

What does this upside-down triangle notation mean?

wicked turtle
#

probably gradient but maybe depends on the context?

dark siren
wicked turtle
# dark siren Idk if this helps

not really, i'm not familiar with linear transport theory
but if the context is physics then i would be very surprised if this means anything other than "the gradient of L at the point (x,omega)":

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#

@dark siren Has your question been resolved?

dark siren
wicked turtle
#

almost certainly it's the dot product of omega with the gradient of L

#

(since both are vectors)

#

geometrically speaking, it's the directional derivative of L in the direction of omega, time the magnitude of omega

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frail igloo
#

please explain to me, like i'm a stupid idiot, why the position of C, if the square is free to roll is described by r(x,y) = <(r+b)sintheta +rthetacostheta, (r+b)costheta + rthetasintheta>

frail igloo
#

i just don't understand where the second additional costheta and sinetheta terms appear in the x and y components

#

i know why the product is rtheta but idk why it's opposite trig functions.

#

DOES THIS EVEN MAKE SENSE IN THE WAY THAT IM EXPLAINING IT

frail igloo
#

i love you.

#

thank you.

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frigid mantle
#

Can someone help me with 21 and how the answer is 2 pie/3 and 5 pie/3 ion get it😭💔

wide ember
#

do you know the quadrants it may lie on?

frigid mantle
wide ember
#

since the value is negative

#

where is tan theta negative

#

in which quadrants

#

it is in quad 2 and 4

frigid mantle
#

Why tho ion get quadrants

wide ember
#

since tan theta = perpendicular / base

frigid mantle
#

Oh okay what about QIII they both negatives 🤣🤣

wide ember
#

they cancel out no

frigid mantle
#

Okay they cancel out I get it

#

Then it be the same for cot right

wide ember
#

when you divide the negative perpendicukar and negative base

wide ember
frigid mantle
#

Okay thx

#

I get that part now

#

😁

wide ember
#

alright

#

next step

#

tan theta = - root3/1

#

you get thi?

frigid mantle
#

What is theta

#

I never seen that term

#

Data?

#

OH

#

My bad

wide ember
#

sryy

#

it is the angle

frigid mantle
#

Yes 👍

#

Sorry I looked it up I thought it was data

#

😁

wide ember
#

it is fine

#

so you can say that $y/x = -root 3/1 or root3/-1$

woven radishBOT
#

lizzie250

wide ember
#

do you agree?

frigid mantle
#

Yes

#

👍

wide ember
#

alright

#

now if y = root 3, x = -1

#

plot that in your circle

frigid mantle
#

Where I put in the quadrant thing

pseudo basin
woven radishBOT
pseudo basin
#

if you're gonna use latex, use latex properly!

wide ember
#

sorry idk the fucntions yet

#

$\frac{y}{x} = \frac{-\sqrt{3}}{1}$

woven radishBOT
#

lizzie250

wide ember
#

yes

wide ember
pseudo basin
pseudo basin
#

\frac{TOP}{BOTTOM} makes fractions and \sqrt{stuff} makes square roots

wide ember
frigid mantle
#

👍

wide ember
#

$(-\sqrt{3} , 1)$

#

this is the coordinate for quad 4

frigid mantle
#

Ok

wide ember
#

$(1, -\sqrt{3})$

winter patrol
#

you're mixing up the x and y coordinates

wide ember
#

oh yea sorry

#

$(-1,\sqrt{3})$

woven radishBOT
#

lizzie250

wide ember
#

for quad 2

frigid mantle
#

👍

woven radishBOT
#

lizzie250

wide ember
#

for quad 4

frigid mantle
#

👍

wide ember
#

now you know the angle that will be formed between the triangle

frigid mantle
#

👍

#

So cuz in quad II 2 pie/3 got like square root of 3 and it also got like -1 on top of that shi and then for quad IV there’s like a 1 and like a negative square root of 3 which is like it’s 5 pie/3?

#

Am I thinking right

#

😈😈

wide ember
#

yes

#

120 and 300

#

that's correct

frigid mantle
#

WOW! THX! 😁

wide ember
#

np

frigid mantle
#

/done

wide ember
#

but in theory you won't do that

frigid mantle
#

Oh

wide ember
#

i watched a video on it once i will find and share

frigid mantle
#

OKAY!

wide ember
#

lmao just found the exact question

frigid mantle
#

OH WOW THX

#

.close

devout snowBOT
#
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devout snowBOT
remote elbow
#

can someone help me out with projecting vectors i dont get the concept

#

mb

amber mantle
#

idk how this works ngl u good 😭

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dense lynx
#

Here is a reputable question for you to solve @hoary sierra :

Let X be a finite set of points. Let M be a collection of subsets of X.

We say that M is satisfactory if each of the points of X can be colored either red or blue in such a way that no set of M has all points red or all points blue.

Suppose that each set of M has exactly 5 points. What is the smallest number of sets in a collection M that is not satisfactory?

dense lynx
#

.close

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silver folio
devout snowBOT
pseudo basin
#

,rccw

woven radishBOT
silver folio
#

i had calculated before and my ans is 3

#

But schema give me 1.2

pseudo basin
#

show your calculation

silver folio
#

,rccw

woven radishBOT
pseudo basin
#

how do you get from 12 = 4.2 * (4+R)/(4R) to R=10

silver folio
#

Sorry I write wrong is 4r/4+r

pseudo basin
#

little r or big R?

silver folio