ah ok great
#help-27
past moat
restive river
and i just figured out this discord server
restive river
ok wait
past moat
do u=3x^5
is that part clear?
restive river
ye ig
past moat
u can set u to whatever u want
restive river
like..
past moat
so here we set it to that
restive river
so the same thing
restive river
whats p??
restive river
ahh
restive river
why is it not loading for me
past moat
click the image to load it faster
restive river
no
past moat
u can put them in the brackets
restive river
ohh
past moat
just replace
restive river
oh
past moat
what did u set u equal to?
what did u set p = to?
since there equal u can replace them
restive river
3x to the power of 5
past moat
exactly
so like this
u see how much nicer it looks
now u can expand it easily right?
restive river
what abt the y to the power of 3
past moat
we did p = y^3
past moat
now expand this
restive river
wdym
past moat
u should not be struggling this much 😭
past moat
nah its fine
restive river
and this work is so dumb
restive river
ye
restive river
lemme see
past moat
how are ur friends doing are they also struggling w this?
restive river
i guess its fine
restive river
is that fine?
.
past moat
i guess its fine
get atleast 1 friend frfr
restive river
hmm
restive river
wait
past moat
the dot between u and p is a times
restive river
alr
the first u has a power of 2 on top
what would i do
@past moat
and how would i do that
past moat
the first u has a power of 2 on top
bracket it
past moat
(3x^5)^2
restive river
ok
past moat
if greater can help u its fine
past moat
okay
restive river
(3x^5)^2 - 2(3x^5)(y^3)+(y^3)^2 @past moat
past moat
(x²)² = x power 2 times 2
restive river
okay
restive river
oh ok
restive river
ill save this
past moat
Deal
past moat
Deal means okay
restive river
oh ok
now did i finish this question?
or is there more
@past moat
uhh
@past moat ?
.
.
.
.
past moat
Sorry back
past moat
or is there more
More
restive river
its ok
restive river
9
past moat
What does the rule say
past moat
(3x^5)^2 - 2(3x^5)(y^3)+(y^3)^2 <@525637392754016258>
Do ( y³)²
past moat
So whats the full equation now
past moat
past moat
3x^5)^2 - 2(3x^5)(y^3)+(y^6) <@525637392754016258>
9x¹⁰
restive river
wdym
past moat
First one
restive river
oh
restive river
oh really?
thank you
thank you
very much
can i friend you on discord @past moat
or do you not allow it
restive river
thanks
past moat
Np
restive river
wait
restive river
what are ur like help hours
restive river
Is there mor
yes but i dont have time to ask today srry
past moat
what are ur like help hours
Idk just dm me if im free i respond
past moat
yes but i dont have time to ask today srry
All good take A screen shot tho i am curious
restive river
All good take A screen shot tho i am curious
alr
i will
thanks thats all i had
@past moat
do i close this
or will you?
restive river
.close
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stark shuttle
Hello
valid vector
I'm confused on why it is drawn like this
$0\le x\le 1$, and the circle bounds too.
woven radishBOT
mathisfun
stark shuttle
And also I thought √(1-x^2) was a semi circle
valid vector
And also I thought √(1-x^2) was a semi circle
It is.
stark shuttle
$0\le x\le 1$, and the circle bounds too.
Isn't that radius?
valid vector
Did you read the first line of the solution?
valid vector
Isn't that radius?
No. Those are the bounds on x.
Look, $y=\pm\sqrt{1-x^2}\implies x^2+y^2=1$.
woven radishBOT
mathisfun
valid vector
Obviously, this is a unit circle.
stark shuttle
I get that
valid vector
We have the bounds $0\le x\le 1$, so...?
woven radishBOT
mathisfun
stark shuttle
Then why is the left half of the circle missing?
Oh
OH
I realized we haven't converted into polar yet lol
valid vector
Then why is the left half of the circle missing?
Because of the bounds...
valid vector
I realized we haven't converted into polar yet lol
Ok.
stark shuttle
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vocal wren
soccer she won 1/3 out of 3, could have won: 3 won: 1
basketball she won 1/2 out of 2, could have won: 2 won: 1
in total she could have won: 5
vocal wren
other options should be fine too, but is 5 a valid answer also ?
valid vector
other options should be fine too, but is 5 a valid answer also ?
No.
What is 5/3?
And 5/2?
The point is, it is 1/3 of her total trophies
and 1/2 of her total trophies
vocal wren
I dont think thats what the text says
vocal wren
and 1/2 of her *total* trophies
1/2 od her total trophies in basketball
so not her total trophies
valid vector
How can she win a half of a trophy??
valid vector
"She won half of her trophies for soccer"
She physically cannot win half of her trophies.
vocal wren
"She won half of her trophies for soccer"
She *physically* cannot win half of he...
I thought that the text said that she won 1/2 of basketball trophies
not that half of her trophies are from basketball
valid vector
I thought that the text said that she won 1/2 of basketball trophies
No
Like I said, physically impossible.
vocal wren
then yeah its not correct
valid vector
This is a very badly worded question.
vocal wren
This is a very badly worded question.
what would happen if the question was:
she won 1/2 of all basketball trophies
she also won 1/3 of all soccer trophies
how many trophies could grace have won ?
would this be true ?
soccer she won 1/3 out of 3, could have won: 3 won: 1
basketball she won 1/2 out of 2, could have won: 2 won: 1
in total she could have won: 5
valid vector
what would happen if the question was:
she won 1/2 of all basketball trophies
sh...
If trophies was an object, yes.
vocal wren
got it, thanks for the help
sonic parrot
got it, thanks for the help
Ibwould say the answers is miltiples of 6
potent tusk
Ibwould say the answers is miltiples of 6
Ib?
vocal wren
Ibwould say the answers is miltiples of 6
To the original problem? Yeah, I just read it wrong
sonic parrot
To the original problem? Yeah, I just read it wrong
Ic
vocal wren
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mortal aspen
uhmm how to find the minimum points to this type of graph?
devout snowBOT
uhmm how to find the minimum points to this type of graph?
mortal aspen
this si the full question if needed
devout snowBOT
@mortal aspen Has your question been resolved?
supple trench
this si the full question if needed
you can apply the fundamental theorem of linear programming
https://en.wikipedia.org/wiki/Fundamental_theorem_of_linear_programming
mortal aspen
uhmm how to find the minimum points to this type of graph?
uhmmm but the corner points its showing as incorrect
thnkk u
.close
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queen ravine
why im i not getting zero
devout snowBOT
why im i not getting zero
queen ravine
since
faint zinc
Because of floating point error
queen ravine
what is that?
faint zinc
Computers store real numbers in an approximate form
young spade
numbers in computers arent the actual number but just a really close aproximations
sooo, instead of 0, you get like: 0.0000000000000008
faint zinc
Yes, a general real number takes an infinite amount of data to specify
queen ravine
oh wow
young spade
is it impossible for computers to store real numbers?
yeah, kinda, they just use really precise aproximates, but sometimes it leads to this kind of things, just assume that its equal to 0
faint zinc
A computer can exactly store some real numbers, everything else gets rounded to one of them
queen ravine
yeah, kinda, they just use really precise aproximates, but sometimes it leads to...
so the integral is just equal to zero
young spade
desmos has the bad tendency of not doing the rounding on these kind of problem for some reason
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marsh bane
.reopen
faint zinc
Why?
marsh bane
Cause I need help
faint zinc
marsh bane
I alr did
faint zinc
Then wait there please
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restive river
I need help at Calculate limit limes,
devout snowBOT
I need help at Calculate limit limes,
restive river
<@&286206848099549185>
young spade
!status
devout snowBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
ill guess those symbols mean taking the limit from x to +infinty and x to -infinity
restive river
Yes
young spade
How do I get the dominant if there are brackets
$\left( a+b \right)\left( c+d \right)=ac+ad+bc+bd$
woven radishBOT
zzz0nnn
restive river
If u want I can send you the original paper
young spade
If u want I can send you the original paper
yeah, prob useful
restive river
The 1b
young spade
How do I get the dominant if there are brackets
you have to evaluate the multiplication in this case, if you are quick, you will eventually find you get x^4 as the biggest term related with x
still, try to do the full multiplication of terms
restive river
Mhhh
I get it, im confused bcs look at 1a the dominant is x^4
And at 1b I just read it like the first one or must I add the one x3 with the other x so I get x4
young spade
you could also evaluate by solving both
i guess you already figured that for +infinity its just +infinity
-infinity . -infinity would also lead you to the same answer anyways
young spade
And at 1b I just read it like the first one or must I add the one x3 with the ot...
x.x^3, = x^4
young spade
you could also follow this route
since x and x^3 have odd exponent, you retain the negative sign
restive river
Ah I might have the solution
Hear me out
Look at first bracket the highest exponent it’s x^1 why 1 bcs if there is a variable with no exponent it’s 1, so and now look a the second bracket the highest exponent is x^3 so if you multiply them with 5 u get 5x^4.
Why 5 bcs with the five u can decide wether + infinity ♾️ or - infinity ♾️
I think so it’s right
Lemme ask gpt
Now I get it Bro thx for your help
@young spade
If I got another problem I let u know
regal berry
$1,(4)\sqrt{75} * (-2,4\sqrt{50}) * (-1/{26} \sqrt{18})$
devout snowBOT
$1,(4)\sqrt{75} * (-2,4\sqrt{50}) * (-1/{26} \sqrt{18})$
woven radishBOT
Simon
regal berry
i kept trying this problem and i keep getting it wrong for some reason
$\frac{4}{9} * 5\sqrt{3} * (\frac{24}{10}* 5\sqrt{2}) * (1/26 *3\sqrt{2})$
woven radishBOT
Simon
winter patrol
4/9 would be 0.4444...
not 1.444....
devout snowBOT
@regal berry Has your question been resolved?
valid vector
@regal berry I am confused, what are you trying to do?
broken pivot
yeah, im a little stuck on this, tried making the equations for x1 x2 x3 and x4 but it just confused me, as x3 has an x2 value in its equation
devout snowBOT
yeah, im a little stuck on this, tried making the equations for x1 x2 x3 and x4 ...
devout snowBOT
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dusk pilot
Minor question. could someone explain this to me, I'm not sure exactly whats being asked of me. I dont "remember" 
devout snowBOT
Minor question. could someone explain this to me, I'm not sure exactly whats bei...
jagged harbor
if this is instructor feedback on your submitted work, I think they're just saying to put the "for all (...)" junk before the rest of the statement
although, by the comment, it almost sounds like the instructor didn't see that you did include the quantifiers, just after the statement
because like, you did repeat the quantifiers
dusk pilot
i thought so, I just wanted to make sure to avoid doing something wrong again
jagged harbor
maybe they mean to repeat the quantifiers exactly? idk
jagged harbor
in practice, you don't need to explicitly state the contrapositive in a proof, but it certainly helps for legibility
e.g. "Let a,b,c be integers. It suffices to demonstrate the contrapositive, i.e. that if a | b or a | c, then a | bc" and then proceed
dusk pilot
my prof is really hard about this stuff for a discrete 1 class 
appreciate your help tho, u can close it if you'd like
jagged harbor
you know, after seeing the wacky things students do with proofs, I get it
you do have to genuinely know how to identify what's logically correct before allowing yourself to bend the rules to help the writing style
otherwise you tend to sound like a loon lol
"too handwavy" etc
jagged harbor
it'll pass
after your first proofs class, the instructors assume you can write a proof
and the content will shift away from the proofwriting itself, although it's still definitely important
it's like knowing how to cite your sources before taking a literature class I guess?
dusk pilot
i transferred credits from a uni a few years ago and they somehow gave me discrete 2 credits and not discrete 1 credits. I've never taken a discrete 2 class in my life
jagged harbor
there's a chance your equivalent counted for both
someone in my "discrete math" class transferred into a uni that splits the two in their CS program, and he got credits for both
dusk pilot
I checked with my advisor and it didnt, thats why i gotta take this class after forgetting everything already
jagged harbor
oh word
dusk pilot
should've waited for an online summer course and speedran 
jagged harbor
eh it's whatever
the hard stuff is good for you
plus if you do well, you can be elitist about it and critique other peoples' proofs in the same way lmao
oh but seriously, if you're in math the proofwriting is obviously very important, but if you're in cs, if you come up with a new algorithm or encryption protocol etc., you can write an accompanying math paper to prove its efficiency and efficacy
dusk pilot
man, i wanna finish this course and never think about this again. I spend so long going to math labs and whatnot to try and finish hw and portfolios and still dont understand a single thing to retain it but enough to get the work done
jagged harbor
the vibe seems to be that discrete math is just the vessel through which proofwriting and logic is taught to students who have previously never been asked to prove anything, ever
dusk pilot
i understand how proofs works, its just discrete math vocab if that is the right term is just so tedious, it flies over my head for some reason
jagged harbor
that's all vocab honestly
dusk pilot
anyway, i should get back to finishing this stuff. thank you for the help again
jagged harbor
no problem, have fun
small whale
have I done something wrong? how do I continue from here?
devout snowBOT
have I done something wrong? how do I continue from here?
shadow brook
have I done something wrong? how do I continue from here?
A tan appears to have disappeared.
When you got rid of the square root you removed a tan.
shadow brook
There’s another tan x in that expression.
So you really have tan squared when the dust settles.
shadow brook
Where are you stuck this time?
shadow brook
To be honest, this is still hard to integrate.
I was hoping to change the integral to 16(sec^2 - 1)sec^2
You then have to integrate sec^3 which will require some IBP.
small whale
book doesn’t integrate so that means I shouldn’t right‼️
shadow brook
I assumed the point of the problem was an integration exercise!
Umm… did the book just leave it there
shadow brook
You then have to integrate sec^3 which will require some IBP.
If you wanted to complete the integration you would have to do this. ^
small whale
I don’t think I wanna 😭😫
shadow brook
But maybe it’s just trying to show you the situations in which you should think of a trigonometric substitution?
small whale
perchance
These are the rest
maybe I WILL get an answer at some point
but thank u for the help
shadow brook
If you know about hyperbolic functions, a hyperbolic substitution is much easier.
small whale
as a matter of fact I do not know hyperbolic functions
shadow brook
Ah. Essentially, these functions are versions of sine and cosine but they parametrise ‘hyperbolas’ instead of circles. If you don’t know about them, then I guess you do only have one way to do it
small whale
I’ve given up with actual answers and I think I’m just gonna leave them as integrals
shadow brook
I do believe that is probably the intention
small whale
I done some before
and in those I was actually getting answers
but they are a little different
and just to check
that answer is correct right…
mortal tinsel
I am proving that if a function is entire, then there exists a function F such that F'(z) = f(z).
I begin by defining $F(z) = \int_0^z f(z) dz$
Then taking the derivative we get
$$F'(z) = \lim_{h \rightarrow 0} \frac{1}{h}[F(z+h) - F(z)]$$
$$ = \lim_{h \rightarrow 0} \int_z^{z+h} f(z) dz$$
Which by the MVT for integrals is
$$f(c)(z+h-z) = hf(c)$$
So the h's cancel and you get
F'(z) = f(c) for some $c$ in that range, however how do I conclude that its eqal to f(z)? Do I just use the fact that the h in the bound approaches 0? Then I can't use MVT
devout snowBOT
I am proving that if a function is entire, then there exists a function F such t...
woven radishBOT
Bean Man
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mortal tinsel
<@&286206848099549185> please
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thin crest
F(x)= 1/(x-6)^2 How would i go about getting the derivative of this
acoustic leaf
chain rule
thin crest
How is that done i forget the names of the formulas
devout yarrow
the reduction formula isnt something ive learnt; how can I integrate (tan^2x)/(cosx); and if it's a u sub of sec^2 or tan how would i know generally what one to make?
tropic skiff
the reduction formula isnt something ive learnt; how can I integrate ***(tan^2x...
You can rewrite $\frac{\tan^2(x)}{\cos(x)} = \tan^2(x) \sec(x)$
woven radishBOT
King Leo
tropic skiff
Then use $u = \tan(x)$
woven radishBOT
King Leo
tropic skiff
when i get to integ[u^2*sqrt(1+u^2)]?
This looks like integration by parts, but you dont need that
devout yarrow
what do i do next?
tropic skiff
what do i do next?
What u are you using
And what integral exactly are you trying to solve
tropic skiff
u is tan theta
Youre selling 😭
Oh wait
Im selling
No wai
Youre selling
No wait
Wtf
Im selling
,w derivative tan(x)
,w derivative sec(x)
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devout yarrow
<@&286206848099549185>
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opaque helm
We have a vehicle at (0, 0). It can take 6 movements to NSEW, but it must end up back at (0, 0). What are the total number of unique paths it can take? I was having a lot of trouble with this problem on my midterm.
devout snowBOT
We have a vehicle at (0, 0). It can take 6 movements to NSEW, but it must end up...
opaque helm
The solution I got was fixing 2 positions out of 6, then out of 4, and selecting an axis for each combination.
So I got 2nCr(6, 2) * 2nCr(4, 2) * 2nCr(2, 2). Then added for fixing 3 positions out of 6, which was 2nCr(6, 3).
So my final solution was 2nCr(6, 2) * 2nCr(4, 2) * 2nCr(2, 2) + 2nCr(6, 3).
Did I overcount when multiplying nCr(2, 2) by 2? But for these positions, there’s still two axes of movement to select.
low sentinel
The solution I got was fixing 2 positions out of 6, then out of 4, and selecting...
i would select pairs of moves instead of individual moves
opaque helm
i would select pairs of moves instead of individual moves
Yeah, I meant each fixed pair to be a NS/EW pair
But I didn’t multiply against 2! to prevent overcounting
low sentinel
ahh ok
opaque helm
Does anyone have a solution?
low sentinel
We have a vehicle at (0, 0). It can take 6 movements to NSEW, but it must end up...
i got 400
opaque helm
How??
low sentinel
3 North, 3 South: 6! / (3! * 3!) = 20
3 East, 3 West: 6! / (3! * 3!) = 20
2 North, 2 South, 1 East, 1 West: 6! / (2! * 2! * 1! * 1!) = 180
1 North, 1 South, 2 East, 2 West: 6! / (1! * 1! * 2! * 2!) = 180
opaque helm
Damn
So I only got the 6 choose 3 portion correct
Yeah I overcounted on 2nCr(2, 2) 🤦♂️
Thank you anyways
.close
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devout yarrow
i cannot comprehend the step to give 2x on top 🤦♂️
devout snowBOT
i cannot comprehend the step to give 2x on top 🤦♂️
jagged harbor
i cannot comprehend the step to give 2x on top 🤦♂️
see the 1/2 in front
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digital egret
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digital egret
I have no clue how to do this
alpine gulch
can someone help me, please?
faint gorge
can someone help me, please?
!occupied
devout snowBOT
can someone help me, please?
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
rapid merlin
Is this a name related to a text book or something
Because there is no mention of the matrix A here
digital egret
oh i can send a picture of what A is
M is
yeah maybe ill try to figure on my own idk how tis work
like this is what i have
I know the answer i just dont know how to get it
this is A
copper ibex
devout snowBOT
solar goblet
therefore DNE
copper ibex
therefore DNE
but the answer key says +oo
solar goblet
+infty is a form of DNE
copper ibex
oh ok
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quasi agate
Q1a
I believe I can use kirchoff’s current law, but I’m not sure how to progress from there
Do I use the current equation for the inductor L
Or is this more appropriate for the physics discord
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Q1a
I believe I can use kirchoff’s current law, but I’m not sure how to progres...
@quasi agate Has your question been resolved?
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quasi agate
.close
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cold rivet
Can someone explain to me how the Monty Fall problem is different to the Monty Hall problem? It seems that in both we are given that Monty opens a dud door, so where is the difference?
devout snowBOT
Can someone explain to me how the Monty Fall problem is different to the Monty H...
solar goblet
wtf is a monty fall problem
pseudo basin
i also wanna know
dark tundra
I was gonna joke that the Monty Fall problem was Monty Hall tripping down the stairs of the LMAD set
But uhh
it actually is lmao
cold rivet
It's just the Monty hall problem but he opens the door to the goat by accident
I found it from twitter: https://x.com/pli_cachete/status/1892025275346452774?t=HAvWlG1p7r6879mJMT3aEA&s=19
X
pseudo basin
ngl i also don't quite see where the difference is
cold rivet
Yes there is an argument about it
People say that if he randomly opened a door then it's no new information and you should stay with your original choice
However the problem is stated as if it's given that he opens a door with a goat
Does that affect things?
pseudo basin
actually i think i got it
the difference from the original MH is that the host weights the sub-branches for Car 2 and Car 3 differently
being 1 for the goat door and 0 for the car door
devout snowBOT
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neat solstice
I think 2 cases
- he opens our door
Car -> we win
Goat -> switch then 50/50 - he opens another door
Car -> we win
Goat -> should be as before 2/3 if we switch
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patent notch
guys i got an answer to a question but its wrong
devout snowBOT
guys i got an answer to a question but its wrong
woven radishBOT
patent notch
the approximation there is the answer my calculator gave (the 1.76 one)
but i was like .4 out
distant helm
send your work
patent notch
little totem
what is this handwriting
patent notch
LOL
distant helm
wrong
patent notch
-1
patent notch
oh
little totem
thats the bottom limit in the red circle
patent notch
then you need to learn to use better handwriting because thats your own -2
shit it is??
little totem
yes, you need to fix your own handwriting before it bites you in the ass
patent notch
its better than this in school i promise
little totem
well the point is that you need to make it a habit or else it will bite you in the ass
in math, your handwriting doesn't need to look pretty, it only needs to be perfectly legible
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marble lily
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queen onyx
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queen onyx
what after this??
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thin coyote
I tried twice but I don't get the correct result. The first part in the bracket I get 0.454, while the second is 1.999. After multiplication with 4.3 I get -6.647
devout snowBOT
I tried twice but I don't get the correct result. The first part in the bracket ...
pseudo basin
I tried twice but I don't get the correct result. The first part in the bracket ...
are those decimals exact or approximations?
thin coyote
approximations
thin coyote
I mean I calculate and take 3 numbers after the . if thats what u mean
pseudo basin
anyway, we need to see all of your work to diagnose what is wrong with it -- your answers for the two penultimate steps don't tell us much
pseudo basin
I mean I calculate and take 3 numbers after the . if thats what u mean
yeah that's exactly what you are NOT supposed to do
thin coyote
how should i approach it then? If i go with fractions and not with decimals numbers are just too big
sorry if my english is bad for math lol
pseudo basin
you need to do it with fractions, but i am pretty sure you can simplify things along the way so they never get too big.
thin coyote
I'll try with fractions rn
pseudo basin
show all your work and not only the answer
thin coyote
I'll take a picture when i finish with fractions
pseudo basin
k
sour spire
guys, how to know which method to use for this question? is it the left one or the right one?
devout snowBOT
guys, how to know which method to use for this question? is it the left one or t...
sour spire
based on the mark scheme, the correct one is the left one
sour spire
wait why is this wrong?
winter patrol
you have an extra 1/2 in the second term
versed garnet
sour spire
you have an extra 1/2 in the second term
ohhhhhhh i get it now
thank you sooo muchh guysss!
devout snowBOT
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keen dust
my answer: (including image) In measure 2, where a subsidy of s euros is given to sellers so that the price for the buyer is equal to pmax, this causes an increase in both the producer surplus and the consumer surplus, it also causes a shift downwards/to the right of the supply curve of size s, (the size of s is 20, because the subsidy applies to suppliers from q = 10 up to q = 30, 30 – 10 = 20.)
From q = 30, the new equilibrium is reached. And consumers are no longer willing to buy a house above p_max.
The deadweight loss is formed at i. These DWL represent buyers who buy a house that they normally would not have paid that much money for. The government subsidy runs from q = 0 to q = 30 with a height of 20, (pmax to pmax + s )
Consumer surplus in market equilibrium: A + B + D
Consumer surplus after subsidy: A + B + D + E + F + H
Producer surplus in market equilibrium: C + E + F
Producer surplus after p_max: C + E + F + B + D + G
Welfare: A+B+E+C + D + F + G + H - I
Deadweight loss: -i = change in welfare = -DWL
Government Costs = B + E + D + F + G +H + I
The original question:
In recent years, the price of owner-occupied homes has risen dramatically, making it a problem for
starters1 in particular to find an (affordable) owner-occupied home. The government is
therefore considering measures to accommodate starters on the housing market. Two possible
measures are: 1) setting a maximum price pmax for owner-occupied homes; 2) giving a
subsidy of s euros per home to sellers, such that the price of a home becomes equal to
pmax.
c) (4 pts.) Use the analytical framework from Chapter 9 to
analyze and compare the effects of both measures. Assume that the owner-occupied homes are all identical.
In your analysis, specifically address the welfare effects for buyers of owner-occupied homes,
providers of owner-occupied homes, and the government.
devout snowBOT
my answer: (including image) In measure 2, where a subsidy of s euros is given t...
keen dust
My question is, is the subsidy rectangle right? i'm conflicted between D + F + G + H + I and B + E + D + F + G +H + I
i'm also not sure if I got the welfare effect right
Also I'm not even sure if the subsidy makes sense, here in my image, because the measure 2 is proposing a subsidy to the point it reaches p max, for each home for the seller. where (I believe) the buyer pays (up to?) pmax.
but then the subsidy would go beyond q = 30 right? so idk im stuck
devout snowBOT
@keen dust Has your question been resolved?
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@keen dust Has your question been resolved?
keen dust
<@&286206848099549185>
devout snowBOT
@keen dust Has your question been resolved?
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@keen dust Has your question been resolved?
devout snowBOT
@keen dust Has your question been resolved?
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devout cipher
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inner ibex
hii
distant helm
,w (a-bi+1)/(a+bi)
woven radishBOT
distant helm
bruh nvm
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valid gale
What is x²+y² while x+y= 5*√2 ,x*y=6?
devout snowBOT
What is x²+y² while x+y= 5*√2 ,x\*y=6?
tranquil bloom
(x+y)^2=x^2+y^2+2xy
violet umbra
Yes. 25*2=(x+y)²=x²+y²+2xy=x²+y²+12 -> x²+y²=50-12=38.
static pivot
I dont know what mistake im doing
devout snowBOT
I dont know what mistake im doing
static pivot
dont mind the bottom trig stuff
just fixed the sign mistake above, still not right
I might have figured it out?
in the process, I have to solve for dx
which is going to be du/cosx
right?
nah, it was the same thing i was doing, just explained better
help ;-;
devout snowBOT
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thin geode
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willow harbor
Hello!
I will spare you the background information, if you want it go ahead and ask and i can shortly explain it
Question:
Imagine two circles that do not have the same radius placed at constant distance from each other connected through a rod that has constant length. If you rotate the larger circle (or the smaller one, doesn't matter) how much will the smaller circle rotate?
I know that the circles can't do a full rotation but there must be some formula to describe their movement in the part of the rotation where they can move.
I have tried describing the connecting rod in terms of the known variables, R, r, D, L but I get en expression that seems a bit too convoluted
sinful fable
Hello!
I will spare you the background information, if you want it go ahead and...
?
Which is the rod in your figure?
sinful fable
Aah ok
willow harbor
Sorry hope it is clearer now
sinful fable
A relation between alpha and theta is reasonable
willow harbor
You think?
sinful fable
You can assume a coordinate plane and parametric coordinates,
Then you would technically have the equation using distance formula
It would be ugly but you would have it
Maybe a more cleaner relation between d(alpha),d(theta) is what you want?
willow harbor
Yeah i would like to specifically have a function alpha = f(theta)
sinful fable
Are alpha and theta changes/ how much they rotate by?
willow harbor
yeah i guess
willow harbor
In this picture i did alpha+ delta_alpha
So maybe saying delta_alpha = f(delta_theta) would be better
sinful fable
Im not convinced such a function would exist,i mean just intuitively, like suppose it changed by delta theta at first and then changed by it again, intuitively feel like alpha would be different
willow harbor
yeah most definitely
Right now i am doing it using numerical methods in matlab and the change in angle is not constant
But it would be nice to have an analytical solution instead, or atleast one that doesnt use guesses
willow harbor
So without any change?
sinful fable
Yeah
willow harbor
Yeah that i have figured out already
willow harbor
One last question then
sinful fable
One last question then
Whats the q tho
Btw i do think a differential equation is possible which would be satisfactory
I do*
willow harbor
Do you think the bottom expression here would give an answer if i were able to solve it?
sinful fable
Yeah seems good
willow harbor
I will try to stick it into matlab then 🙂
sinful fable
After that you can implicit differentiate to get the differential
frozen aurora
interesting, i'm trying to make a model for this in geogebra
willow harbor
interesting, i'm trying to make a model for this in geogebra
Go ahead, that would be great
frozen aurora
Hello!
I will spare you the background information, if you want it go ahead and...
i need you to explain how you construct the initial connection
in a bit more detail
if you start like this in EF then you can't move it as to rotate the circles you will need something of length more than 5
if you start out with an initial config like this, where EF is more than 5, then it seems like there's too much freedom
willow harbor
Yes
That position will never happen in my model
This is a mechanical issue to begin with and i know there are limits
willow harbor
if you start out with an initial config like this, where EF is more than 5, then...
How do you mean there are too many freedoms?
frozen aurora
like there will be many possible cases and configurations that are kinda hard to categorize
at least the way i see it rn
frozen aurora
if you start out with an initial config like this, where EF is more than 5, then...
even here, if i make the angle FAC bigger, there is no way i can move point E to keep the distance at 6 units
frozen aurora
your lines here are already of very different lengths
willow harbor
your lines here are already of very different lengths
I will record the solid edge model wait a little
frozen aurora
even here, if i make the angle FAC bigger, there is no way i can move point E to...
actually nvm it's doable
willow harbor
willow harbor
actually nvm it's doable
Here is the movie
Can i upload it as a video in discord 🤔
There we go 🙂
Is you can see it breaks on some angles
Which is completely fine, it would almost be great if that showed in the final function because then i know the measurements are incorrect
devout snowBOT
@willow harbor Has your question been resolved?
devout snowBOT
@willow harbor Has your question been resolved?
misty granite
Okay I’m just stuck on a easy trig question I’m trying to find angle c
misty granite
I mean this is easy but I haven’t done trig in ages 
iron kindle
rewrite to sin(c)=?
iron kindle
what do you get?
iron kindle
But the annoying thing is
is?
iron kindle
is your calculator on radians?
misty granite
Degrees
misty granite
iron kindle
98.65+56.75+24.6=180
misty granite
Nah but the sides
Are not suppose to exist
Isn’t the largest angle=largest side
And smallest angle=smallest side
iron kindle
yes
misty granite
So why 98.65=7 and 56.75=11
iron kindle
,w asin(11/5.475*sin(24.6 degrees)
woven radishBOT
iron kindle
,w 0.9906 radians to degrees
woven radishBOT
woven radishBOT
iron kindle
,w 0.561234 radians in degrees
woven radishBOT
misty granite
,w asin(7/5.475*sin(24.6 degrees))
Calculating angle a?
devout snowBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
misty granite
I don’t have OG, it’s:triangle abc is a non right triangle. Side c measures 11 and side a measures 7. Angle B measures 24.6 what is angle c?
iron kindle
so where did you get 5.475 from?
misty granite
Law of cos
iron kindle
,w 11/5.475*sin(24.6 degrees)
woven radishBOT
iron kindle
,w sqrt(11^2+7^2-2(7)(11)cos(24.6 degrees))
woven radishBOT
misty granite
I think I know
So after this
I realized the mistake
I think I treated this like a ssa or ass case
So I did 180-56.75
And got 123.244
And it just worked
So I think it’s just 123.244
iron kindle
okay
misty granite
I’m not certain though
Law of cos if I recall does create a ass case right
It’s been so long since I’ve done trig
Yeah I think it’s accurate
iron kindle
if it works, it works
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humble dirge
i'm confused how a square root of a square root work
devout snowBOT
i'm confused how a square root of a square root work
humble dirge
i have the question sqrt of sqrt of x^12 and it asks to "write a simplified equivalent expression using exponents"
and the answer is x^3
how does that work?
restive river
you can express a square root as 1/2
as in, square root of x = x^(1/2)
sorry if my handwriting is a little rough but there's an example
humble dirge
i see
so the square root of x^12 would be x^12(1/2) which is x^6
and then you just do it again to get x^6 to x^3
humble dirge
sweet
restive river
yes
humble dirge
thanks mr apple