#help-27

1 messages · Page 276 of 1

versed wyvern
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Vet du det?

cold bough
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jag är inte den bästa på dessa

versed wyvern
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Samma

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Hatar sannolikhet

iron sun
versed wyvern
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Fattar, klockan är ju nästan 11

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Jag får alltid hjärnsläpp på lektionerna

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Jaha. Eftersom det finns chans för både 5 och 6 är det 4/47+4/47=8/47

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Då fattar jag...

iron sun
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Om du får en god natts sömn kommer du förmodligen lösa problemet, sömn löser nästan allt!

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Ah

versed wyvern
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Matte 1c är dock jobbigt, eftersom vi går igenom en ny grej varje lektion

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Fysik är nog svårast dock

iron sun
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Jo det är mycket man måste lära sig utan en kanske djupare förståelse

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Ifall du väljer att plugga vidare till matematik vid universitetet

versed wyvern
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Men alltså på fysiken gick vi igenom kinetisk energi, sedan friktion nästa lektion

iron sun
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Så kanske det kan komma som en chock hur annorlunda man lär sig

versed wyvern
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Då är det väl bara föreläsningar?

iron sun
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Det är oftast uppdelat på liknade sätt, föreläsning, sen räkneövning

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Men skillnaden är i materialet

versed wyvern
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Sedan gick vi igenom friktion

iron sun
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Oj

versed wyvern
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😭

iron sun
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Personligen föredrar jag hur man lär sig i universitet, men många jag känner som tyckte om matten vid gymnasiet blev lite chockade när dem fick reda på skillnaden

versed wyvern
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Då lär man sig komplexa tal

iron sun
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Så ifall du redan nu tycker att du inte får en så djup förståelse så kommer du att föredra universitet

versed wyvern
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Det är väl en ganska bra övergång?

iron sun
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Typ..

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Många av dem gick det också, och det var fortfarande inte representativt

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Vid gymnasiet är det mindre fokus på varför saker funkar, men snarare någon typ av metod eller formel (detta är väldigt grovt sagt)

versed wyvern
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Det är väl så du menar?

iron sun
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Under vilka förutsättningar? Att härleda något med symboler ger egentligen väldigt lite och är inte så djupt

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Det är skillnaden vid universitet

iron sun
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Dvs. en algebraisk härledning ger inte en djup förståelse av något, det bara faller ut från en beräkning

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Och sen är detta under vissa förutsättningar som man gömmer

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Detta är mera sagt bara en grov jämförelse

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Från vad du kan förvänta dig vid universitetet

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Inget illa menat, men bara en reflektionen; då många studenter får denna chock

versed wyvern
iron sun
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Det är istället mindre fokus på en metod eller formel, oftast får du istället lära dig saker på en mycket mer djupare nivå

versed wyvern
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Ska jag tipsa min lärare om något?

iron sun
versed wyvern
iron sun
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Ett bra tips om man vill få ett smakprov av universitet är att gå någon typ av basårs kurs på ett universitet

versed wyvern
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Men läraren brukar ge exempeluppgifter som vi diskuterar med klasskamraten bredvid, sedan går han igenom hur man löser

versed wyvern
iron sun
versed wyvern
#

Men vad menar du med basår?

iron sun
# versed wyvern Basår? Det kan jag väl göra när jag har tagit studenten?

Jo ville precis nämna problemet att det är just efter du är klar med gymnasiet du kan söka till dessa.

Men kan vara bekvämare oftast om man gör på detta sätt, även om ämnena i sig är behörigheter för kurser från gymnasiet, så är dem på djupare nivå och i en miljö som faktiskt speglar livet i universitet

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Jag tror dock du kommer klara dig utmärkt utan dessa

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Mer av ett tips för elever i allmänt

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Ialla fall

versed wyvern
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Var ganska krångligt

iron sun
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Oj :(

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Jag fick F på matte1B i tre år vid gymnasiet

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Men sen sista året klicka allting plötsligt

versed wyvern
iron sun
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Japp!

versed wyvern
iron sun
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Hatade matematik

versed wyvern
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Gymnasieingenjör?

iron sun
versed wyvern
iron sun
versed wyvern
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I min linje behöver man inte göra matte i 3an

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Men jag kommer nog göra det

iron sun
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Men nu går jag Matematik programmet i universitet, även om jag trodde jag hatade matematik

versed wyvern
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I alla fall, klockan är jätte mycket och måste gå upp innan 7 imorn

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Tack så mycket igen för det intressanta snacket

iron sun
versed wyvern
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Jag var orolig att jag inte skulle få det

versed wyvern
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Tack! Och god natt igen, på riktigt den här gången 😂

iron sun
iron sun
versed wyvern
#

.close

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violet umbra
#

Hey guys!
If i have a linear system of ODE's in the form of x'=Ax+b. A (n by n matrix) and b (n-dim vector) are both complex. How do i find a particular solution?

violet umbra
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We had something really similar were A and b were both with real Numbers. Can i just do the same?

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We had this in another exercise even tho i dont know how the Integral would be defined on complex functions, we definitely never had such things so i dont think this is a solution too

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violet umbra
#

<@&286206848099549185>

violet umbra
#

Mhhhm, have to think about this

runic prawn
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what part

runic prawn
violet umbra
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I dont know

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Seems okay tho

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ebon mist
#

Could someone help me with descriptive geometry?

ebon mist
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what will the cube look like?

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on the top left is the right side
on the top right is the front
and on the bottom right is the top

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<@&286206848099549185>

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@ebon mist Has your question been resolved?

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@ebon mist Has your question been resolved?

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scenic surge
#

Why am I getting a different answer here? Im using the correct formula

(Image 1 + 2): Formula I used
(Image 3 + 4): The answer my prof got

scenic surge
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this is like the original question for this

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shouldnt I be getting the same answer as prof

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scenic surge
#

bruh

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🙏

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@scenic surge Has your question been resolved?

scenic surge
#

<@&286206848099549185>

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dapper fable
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if an integer sequence ,for example a_n,is in between some ranges for all n, does this mean a_n,repeats?

uncut crow
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what does repeats mean?

dapper fable
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like a_1 = c, and a_k = c for some k

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but not periodic

uncut crow
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then yes

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pigeonhole principle

dapper fable
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oh

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whats the reason😭 ive never really used pigeonhole before

topaz axle
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it's not obvious if it has or doesn't have to be periodic

uncut crow
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there are only so many integers in the range. if you have more elements than that (which you do in an infinite sequence), there must be a repeat

dapper fable
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i was doing an imo problem and didnt know where to go next, thanks guys

topaz axle
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yeah ok even with just 2 possible integers, it doesn't have to be

dapper fable
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oh

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grave ermine
#

just a lil bit of help on this one

devout snowBOT
grave ermine
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was sick for class and couldnt attend

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and they gave homework

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i do not understand that one guy on youtube with a black background

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so if possible, with solution please

fierce lagoon
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so

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which one tho

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or everything

grave ermine
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everything 😭

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what one day of no school does:

fierce lagoon
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nah bruv

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thats fck up

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i think i will solve a few cases then u solve the rest

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hows that

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u gonna learn it the hard way

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like how i was raised

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like an asian

grave ermine
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solve like one in each sure

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ill get it

fierce lagoon
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okay

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so this case

grave ermine
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yes

fierce lagoon
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do you know the

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Intersecting Secants Theorem?

grave ermine
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i was sick for class today

fierce lagoon
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alr bet

grave ermine
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did not attend school at all

fierce lagoon
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"The intersecting secants theorem states that when two secants intersect at an exterior point, the product of the one whole secant segment and its external segment is equal to the product of the other whole secant segment and its external segment. This is also known as the secant theorem or the secant power theorem."

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just wikipedia it tho

grave ermine
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i see

fierce lagoon
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uhmm

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the problems not really clear tho

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but nvm

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im gonna assume tho

grave ermine
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dunno anything about the lesson

fierce lagoon
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bet

grave ermine
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ill check

fierce lagoon
#

do you have the notes from ur friend or sth?

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i think you should take a look at it tho

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be4 i solve ur problem

grave ermine
#

waa

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i dont have a single shit

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mb i responded late

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i was lookin at the theorem ands tuff

fierce lagoon
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stuck locust
#

How to solve standard deviation?

devout snowBOT
stuck locust
#

..

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How this work bruh

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How to solve standard deviation

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What the sigma

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Ohh now i get it

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I need a clear explanation about how to solve variance and Standard deviation

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And also the meanings of the symbols

fossil locust
# stuck locust How to solve standard deviation?

for variance:

  1. add all the numbers up then divide by the total number of numbers, to get the mean
  2. for each number, subtract the mean
  3. square all the numbers you have after doing step 2
  4. add all the numbers you have in step 3
  5. divide by the number of numbers

for standard deviation:
6) all of the above, but square root your answer in step 5

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also, this gives you the population variance and population s.d

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for sample variance and s.d you need to divide by (n - 1) instead of n in step 5

stuck locust
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I dont know about how to square the numbers

fossil locust
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their mean is

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,calc (3 + 4 + 11)/3

woven radishBOT
#

Result:

6
fossil locust
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so you do (3 - 6)^2 + (4 - 6)^2 + (11 - 6)^2

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I've jumped ahead and added all the squares, so we have done step 4 actually

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young aurora
#

how do i find these points for the second part

young aurora
#

.close

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fierce lagoon
devout snowBOT
fierce lagoon
#

i need help with this problem

fossil locust
fierce lagoon
#

Here is my current solution

fierce lagoon
fossil locust
#

then sub in $u = \pi x /2$

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wait

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no sorry you need the series around x = 1 arrghh

fierce lagoon
#

Sound legit

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The answer should be e^pi/2

fossil locust
#

at least you know that $\ln(2 - x) \approx 1 - x$

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cause $\ln(1 + u) \approx u$ and now sub in $u = 1 - x$

woven radishBOT
#

southlander!

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southlander!

fossil locust
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it's the tan part that is annoying

fierce lagoon
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I know right

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I tried to turn tan into sin/cos

fossil locust
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,w tan(pi x/2) taylor series at x = 1

fierce lagoon
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But not workin tho

fossil locust
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yeah the vertical asymptote screws it up

fierce lagoon
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Lol wish i could use these stuf

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We dont do computer around here

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Typical asian

fossil locust
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ah I think I might know

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rewrite $\tan(\pi x/2) = \cot(\pi - \pi x/2) = \cot(\pi/2 \cdot (1 - x))$

woven radishBOT
#

southlander!

fossil locust
#

then you're just looking for $\lim_{u \to 0} \cot(\pi/2 \cdot u) \cdot u$

woven radishBOT
#

southlander!

fossil locust
#

now applying the limit of (tan u)/u as u goes to 0

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this equals 1/(pi/2) = 2/pi

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so the original limit must equal e^(2/pi)

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I've checked on Desms

fierce lagoon
#

Yea

fierce lagoon
fossil locust
fierce lagoon
#

Ah yes

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Typo

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My bad

fierce lagoon
woven radishBOT
fierce lagoon
#

nvm

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got it tho

#

.close

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fierce lagoon
#

,w 1/x^2-2x-3 taylor series at x = 4

devout snowBOT
fierce lagoon
#

,w 1/(x^2-2x-3) taylor series at x = 4

lavish nimbus
#

Do you got the original question? Or is your question asking for Taylor series for the function when n=4?

restive river
#

Hmm interesting

fierce lagoon
#

nah

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im just messing around with wolfalpha

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sorry

fierce lagoon
#

still have to do these shit manually tmr

#

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sand quarry
#

Could someone explain to me why the DFT of a signal x[n] is real if the magnitude of the DFT is even and its argument is odd?

sand quarry
#

I dont think I conceptually get this

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For context: I don't quite understand the real and even reasonings

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hollow shoal
#

by evaluating the integral using part two of the fundamental theorem of calculus and then differentiating

g'(x) =

hollow shoal
#

I turned it into 5t - cost | 1 -> x

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but when I tried to F(a) - F(b) I get some weirdness and I think I did something wrong

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because I get cos(1)

river knot
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are you purposefully not using ftc p1

hollow shoal
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Part A uses FTC1

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Part B wants me to (practice) FTC2

river knot
#

oh so you solve the integral with both methods

river knot
hollow shoal
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Oh

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Why did I write 1, wtf

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I think that was from the previous problem, okay let me fix that

river knot
#

yep

hollow shoal
#

$[5x - cos(x)] - [5(0) - cos(0)]$

woven radishBOT
hollow shoal
#

Idk what the vocabulary is for this but I got that, but cos(0) is -1 let me see where this goes

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$g(x) = 5x-cos(x)+1$

woven radishBOT
hollow shoal
#

So then I have to find the derivative of that?

river knot
#

yep

hollow shoal
#

Okay, so cos = -sin

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which makes me get back to the same as the FTC1 then

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I got it, thank you. I'll probably be back in another channel with harder ones 🤣

river knot
#

np lol

hollow shoal
#

.close

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marsh obsidian
devout snowBOT
marsh obsidian
#

can someone help me solve this

#

i have been facing a hard time to understand

restive river
#

"Divisible by 5" = the last digit must be a 0 or 5

Of the 720 possibilities, how many end in a 5?

floral barn
restive river
#

You wouldn't have to list them out and literally count

Just try to compute the number of strings like - - - - 5 and subtract from 720

marsh obsidian
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so i find which are divisble by 5

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and sub from the whole thing?

restive river
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Yes

marsh obsidian
#

okkkk

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sorry wifi problems

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what about thisss

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i dealt with questions that say

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it has to be even and greater than so so number

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but not with this

verbal vector
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last number always has to be a 2 or 4

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then case work on 1 digit, 2 digit, and 3 digit cases

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only thing to be careful of is that 5 isn’t the first number on the 3 digit case

marsh obsidian
#

not first?

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oh right even

verbal vector
marsh obsidian
#

alright thank youuuu

#

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floral lodge
#

"If three normal dice are thrown, what is the probability, P(C), that the the last C will be equal to the sum of the two first dices"?

floral lodge
#

I started by noting that for the first two dices, there are 6^2 = 36 combinations. Out of these 36, by drawing a multiplication table and only counting where the sum is equal to or less than 6, I get 15 such entries

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The possibilities that I get those sums is therefore 15/36

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The last dice can't be 1, as there is no way to get that sum

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so there are 5/6 possibilities for the first dice

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my answer is therefore P(C) = 5*15/6^3

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but the correct answer is 15/6^3

verbal vector
#

yeah i believe it should be multiplying by 1/6 not 5/6 because after you throw the first 2 dice, only one of the 6 faces will complete the problem

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(one of the six faces on the last dice)

floral lodge
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wait wait

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is it because the sum... can only be expressed by one of the faces?

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But the first face is invalid, i.e when it is 1

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wouldn't that leave us with 5 valid ones?

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ohh nonono

uncut crow
#

,w expand (x+x^2+x^3+x^4+x^5+x^6)^2

verbal vector
floral lodge
#

I mixed up the valid cases vs the total possible cases

verbal vector
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yeah all good

faint zinc
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so for each selection from the table of 36 values, there's only 1 throw of the third die that will match.

#

so the chance of this occurring is 1/6

#

which is why it is 15/6^3 not 5*15/6^3

#

(for instance, if you throw a 1, 1, 2 that fits, but any of 1, 1, 3, or 1, 1, 4, etc will not.)

floral lodge
#

yup

#

I was sloppy, should've been a tad more thoughtful xD

uncut crow
#

chance of rolling a sum <= 6 is 15/36, then your chance of rolling whatever the sum was is 1/6

floral lodge
#

yes

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spring oasis
#

\textbf{Exercise 4.} It is known that for a certain ( \alpha \in (\pi, \frac{3\pi}{2}) ), ( \sin(\alpha) = -\frac{1}{5} ). \textbf{Without using a calculator}, calculate ( f(\alpha) ) for the function
[
f(x) = \tan(x) + \tan(2x).
]

\textbf{Note:} It is not required to find ( \alpha ).

woven radishBOT
#

Renato Chavez

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#

@spring oasis Has your question been resolved?

spring oasis
#

<@&286206848099549185>

lusty sapphire
woven radishBOT
devout snowBOT
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@spring oasis Has your question been resolved?

spring oasis
#

.solved

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stone thorn
devout snowBOT
river knot
olive snow
#

4 = 2²

#

4^x = (2^x)^2

eager nova
#

Or replace x with 1

stone thorn
#

.close

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signal mountain
#

the cyrrilc does not matter. i am so confused what the point of having a defenition of a subset

signal mountain
#

the defention of a subset by defeniotn must make it equal.

#

whats the point of having a convulted defeniton if it just means equal?

wheat pawn
#

,rotate

woven radishBOT
wheat pawn
#

pay more attention to the definition

#

A is a subset of B: Every element in A is also in B.
A is a Proper subset of B: Also, A is not B.

signal mountain
#

right, subset means that every element of A cant be found in B but by def proper subset says that if there is another element in B that is not in A then it is a proper subset

#

the only way for something to be just a subset is to have them equal then no?

#

im confused on what you mean by A is not B

wheat pawn
#

the set A is not the same set (aka does not contain the exact same elements) as set B

#

for example. Let B={1, 2, 3}

#

A={1, 2, 3} would be a subset.
A'={1} would be a subset, and a proper subset

signal mountain
#

right, so A and B are equal

#

so whats the point of calling it a subset

#

if it just means equal

wheat pawn
#

for proofs, basically

#

to prove that two sets are equal, very often you prove that A is a subset of B, AND B is a subset of A, thus A=B

signal mountain
#

thats is so stupid and convulted for a introduction to sets imo

wheat pawn
#

not really

#

definitions simply need to be precise

#

because if they arent, Bad Things happen

signal mountain
#

but then why not define it as equal in the first place

wheat pawn
#

because they arent

#

being a subset doesnt mean that they are equal

signal mountain
#

can you show a subset that isisnt equal then?

#

by def it is no?

wheat pawn
#

i already did. A={1}

signal mountain
#

wait wait wait

#

so a set can be considered a subset and proper subset?

#

it breaks the def of a subset tho

wheat pawn
#

every proper subset is also a subset

#

proper subsets are a subset of subsets

wheat pawn
#

let's use my example

#

is every element in A also in B? yes, because 1, which is the only element of A, is in B. Thus, A is a subset of B

signal mountain
#

but B contains 2 and 3 which are not in A tho, def says if B contains elements that are not in A, then A is called a proper subset of B

#

like can a set basically be considered both in that case?

#

like as long as it fits the criteria it gets the title subset and proper subset?

wheat pawn
#

yes

#

sometimes the distinction is important

#

when it isnt, you go by the more relaxed "subset"

signal mountain
#

hm

#

ok

#

i think that makes sense

#

thank you for your help

#

.resolve

#

.close

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rigid fern
#

hi can someone help with proofs i cant do this 😔

still zephyr
rigid fern
#

okay nvm

#

.close

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pure sapphire
#

help

devout snowBOT
#

Please don't occupy multiple help channels.

pure sapphire
#

im sorry

#

anyways may i get help

upper schooner
#

If you have a question, you can ask it, and if anyone can help, we will SCgoodjob2

#

I'll close the other one for you catlove

pure sapphire
#

but

#

can i dm u

upper schooner
#

How comes you want to DM me? I may not be able to help with your question, after all sadCatThumbsUp

pure sapphire
#

this may seem crazy

#

but i need help with ratios in stupid

upper schooner
#

Awwww, that's fine, you can ask anything here (and we're all [or at least mostly!] understanding and friendly here) LanLove

pure sapphire
#

tysm

upper schooner
#

Did you like have a worksheet or anything? catThink

pure sapphire
#

no sadly

upper schooner
#

Awwww sadcat that's fairs sadCatThumbsUp

pure sapphire
#

im in winter break 😦

upper schooner
#

I'm not super great with helping in general unless I have something to like reference personally SCGhugkitty

upper schooner
pure sapphire
#

no 😦

#

i can search

upper schooner
devout snowBOT
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lost laurel
#

hint please

devout snowBOT
lost laurel
#

I want to use a u -sub

#

.close

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lost laurel
#

nvm

#

have an idea

autumn fjord
#

helo

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hexed berry
#

okay

devout snowBOT
hexed berry
#

this doesn't have a maximum

#

but, how can I tell wheter it has a maximum minimun or not

vital hinge
#

You can find a maximum or minimum by taking the derivative of the function and solving for the values where x=0

#

As a max or min will look like a mountain or a U, where the peak or valley has slope 0

vital hinge
#

But like what

#

@hexed berry

hexed berry
#

look at this

hexed berry
#

not, what do you see.

#

How can we make this x=0?

#

WE CANT

#

so, what do we do in cases like this.

river knot
#

and critical points are where the first derivative is 0 or undefined

vital hinge
#

Sorry I forgot that part^

hexed berry
#

What do we do next

#

one would use second derivative

river knot
#

use the first or second derivative test to see if it’s actually a maximum or minimum

hexed berry
#

but like, we cannot really do that, can we?

#

since, again

hexed berry
#

we cannot replace x with 1

#

So, what happens in that case?

#

Secons derivative is not possible, so far.

river knot
#

to begin with x=1 isnt in the domain of m

#

and therefore the function has no critical points

#

and no possible extrema

#

critical points are in the interior of the functions domain

hexed berry
#

But aren't critical points points where derivative doesn't exist?

#

Such derivative doesn't exist hehehe.

river knot
#

to be exact

#

A critical point of a function f is the point in the interior domain of f at which the graph of f has a horizontal tangent (first derivative = 0) or where f is not differentiable (first derivative undefined)

hexed berry
#

if the funcion is not defined in the first place

#

no critical point, right?

river knot
#

yes

devout snowBOT
#

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@void knot Has your question been resolved?

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lone skiff
devout snowBOT
frozen aurora
#

,rccw

woven radishBOT
lone skiff
#

im confused about this whole section

#

im trying to answer 3a

#

but

#

im confused

#

the only one that looks parralel is plane JKL

strange nimbus
#

OK, what does parallel mean?

lone skiff
#

its means they are going the same direction or is simalair i understand what it means but not how to explain it

#

same direction for a line

#

but im unsure for a plan

strange nimbus
#

For lines in the same plane, the lines don't intersect.

#

For planes, the planes don't intersect.

lone skiff
#

yup

strange nimbus
#

The idea is that they stay the same distance apart and so they can't cross each other.

lone skiff
#

so wouldnt plane JKL be the answer

strange nimbus
#

Yes.

lone skiff
#

and for question b

#

EJ Fk would work right?

strange nimbus
#

Yes.

lone skiff
#

for c

#

it would be dh

strange nimbus
#

Right.

lone skiff
#

but im confused for d.

#

i dont understand skew

strange nimbus
#

OK, skew means there's no plane that has both of them, they're not parallel, and they don't intersect.

lone skiff
#

oh

#

what about jk?

strange nimbus
#

OK, is there a plane that has both of them?

lone skiff
#

yes

strange nimbus
#

OK, so that can't be it.

lone skiff
#

then HG can be the answer

strange nimbus
#

Is there a plane that has both of them?

lone skiff
#

yup

strange nimbus
#

What plane?

lone skiff
#

wait nvm

#

that one just had e

strange nimbus
#

OK, are they parallel?

lone skiff
#

no

strange nimbus
#

Do they intersect?

lone skiff
#

no

strange nimbus
#

OK, so that's correct.

lone skiff
#

ok for question 4

#

the organization one

#

i dont understand the properties

strange nimbus
#

OK, do you have something that defines the properties?

lone skiff
#

what do you mean

strange nimbus
#

Like that just lists the properties on the right.

#

Do you have anything that tells you what each property means?

lone skiff
#

no i dont have any notes

#

but is the first one reflexive property?

#

because i think i remember doing this

strange nimbus
#

No.

lone skiff
#

oh

strange nimbus
#

Reflexive is like AB = BA, but that's not what you have there.

#

That defines them.

lone skiff
#

ah

#

wait

#

im confused again Symmetric Property of Equality: If m∠A=m∠B
, then m∠B=m∠A

strange nimbus
lone skiff
#

yes

#

the symmetric property is the correct one then ?

strange nimbus
#

Yes, it is.

lone skiff
#

and i beleive then next one is either transative property or substitution

#

its transativ

#

?

#

transative property for the 2nd one

#

and last one is reflexive

strange nimbus
#

Yes, that looks right.

#

What do you mean by the last one?

#

The m<LMN one?

lone skiff
#

yes

#

?

#

hello?

strange nimbus
#

Note that the last one has the ms disappearing.

lone skiff
#

ah

#

so it cant be refkexive

strange nimbus
#

Reflexive means you have a = a, same thing on both sides (it's like a reflection).

lone skiff
#

ok

strange nimbus
#

What book is this from?

lone skiff
#

i have no idea

#

is my exam study guide

#

?

strange nimbus
lone skiff
#

the third one is it definition of midpoint

strange nimbus
#

What is a midpoint?

lone skiff
#

a point that is in the middle of a line

strange nimbus
#

It's a point that's halfway between two other points.

lone skiff
#

yes

strange nimbus
#

But we don't know if S is halfway between them.

lone skiff
#

oh ok

strange nimbus
#

It could be somewhere else between them.

lone skiff
#

ok

lone skiff
#

i was thinking on segment addition postulate

#

?

strange nimbus
#

Yes, that's right.

lone skiff
#

is the next one substition property?

strange nimbus
lone skiff
#

hm

#

im still kinda confused

#

wait no i understand

strange nimbus
#

What are you substituting there?

#

That link was for the previous problem.

lone skiff
#

oh so its wrong

strange nimbus
#

Maybe, maybe not.

lone skiff
#

i see now

strange nimbus
#

But substitution is like if b = c, then a + b = a + c.

#

But you kind of have the reverse.

#

If a + b = a + c, then b = c.

lone skiff
#

but would it still not be substition?

strange nimbus
#

So, the substitution property won't be it.

lone skiff
#

oh wait

#

i see what i missed

strange nimbus
#

No, when you say "if then", it's a one directional thing.

#

The 'if' being true makes the 'then' true.

#

But you're going the other way.

#

You're saying that the 'then' is true, so the 'if' must be true.

lone skiff
#

ok

strange nimbus
#

You start with JK + KL = MN + KL.

lone skiff
#

yes

strange nimbus
#

How can you change that to JK = MN?

lone skiff
#

meaning JK+2KL

strange nimbus
#

Sorry?

lone skiff
#

wait

#

im confused now

#

i add

#

Kl to JK to make it MN

strange nimbus
#

What do you add?

lone skiff
#

meaning JK+2KL

#

or

#

JK + KL+ KL

strange nimbus
#

Sorry, how did you get that from JK + KL = MN + KL?

lone skiff
#

well oh wait

#

i mixed it up

#

i read it wrong

#

i saw this seciton by itself

#

JK + KL = MN

strange nimbus
#

Oh, OK.

lone skiff
#

it can be substition or relfexive

strange nimbus
#

What is equal to itself?

lone skiff
#

it cant*

strange nimbus
#

Oh.

#

OK, you're starting with JK + KL = MN + KL. How do you get to JK = MN?

lone skiff
#

wait

#

uhh

#

is just replacing Jk with Mn

#

meaning it is subsitioin

strange nimbus
#

No.

lone skiff
#

what

strange nimbus
#

It's not doing anything.

#

It's an equation.

#

You need to manipulate the equation to get the second equation.

lone skiff
#

well they are equal to eachother

strange nimbus
#

What things are equal to each other?

#

There are two equations there.

lone skiff
#

Mn and Jk

#

meaning we can subtract both

#

to get KL by itself

strange nimbus
#

No, you can't.

lone skiff
#

what

strange nimbus
#

You're starting with JK + KL = MN + KL.

#

That's all you know.

#

You don't know anything else.

#

You don't know that JK = MN.

lone skiff
#

oh ok

strange nimbus
#

You're trying to prove JK = MN, not start out knowing it.

lone skiff
#

ah

#

so its defintion of congruence?

strange nimbus
#

No, definition of congruence is where two things that have the same measure are congruent.

lone skiff
#

ok

strange nimbus
#

Like if two angles have the same number of degrees, they're congruent.

lone skiff
#

ok

strange nimbus
#

Or if two segments are the same length, they're congruent.

lone skiff
#

ok

strange nimbus
#

How would you go from JK + KL = MN + KL to JK = MN using algebra?

lone skiff
#

subtraction get rid of both KL

strange nimbus
#

Right, so which rule is that?

lone skiff
#

property of subtraction

strange nimbus
#

Right.

lone skiff
#

ok

#

this next one has to be substition

strange nimbus
#

What are you substituting?

lone skiff
#

m of angle d in to c

#

wait

strange nimbus
#

OK, that's a good guess, but there's a better rule.

lone skiff
#

its congruence right?

#

because they all have the same measure

strange nimbus
#

No, there are no congruence symbols.

lone skiff
#

oh ok

#

i want to say transative but we already used it

strange nimbus
#

OK, so the reflexive property means a = a (same thing on both sides). The symmetric property means that a = b leads to b = a (you switch the sides). The transitive property means that a = b and b = c leads to a = c.

lone skiff
#

so it is transitive?

strange nimbus
#

Reflexive is like its own reflection.

#

Yes, it is.

lone skiff
#

but we already used it?

strange nimbus
#

Which problem did we use it in?

lone skiff
#

the second one

#

but now looking at it

#

it looks wrong

strange nimbus
#

That's like the fourth problem.

lone skiff
#

is it addition property?

strange nimbus
#

Oh, never mind.

lone skiff
#

what do you mean

strange nimbus
#

It's not like the fourth problem.

lone skiff
#

oh

lone skiff
#

so its substition

strange nimbus
#

Right.

lone skiff
#

that was my second guess

strange nimbus
#

Transitive also works, but you have to use the symmetric property to flip one of the equations.

#

So, it would be more than one rule.

lone skiff
#

ah okay

strange nimbus
#

VW + WY = ZY and VW + WY = XZ
VW + WY = ZY and XZ = VW + WY
XZ = VW + WY and VW + WY = ZY
XZ = ZY

lone skiff
#

so. i would need a fulle statment and reasoning chart

#

to

#

prove that one

urban fulcrum
#

Hey,
could anyone help me draw x²-|x| 's chart?

strange nimbus
#

To use transitive, yes.

strange nimbus
lone skiff
#

ok

strange nimbus
#

But substitution is much easier.

lone skiff
#

ook

#

now we are onto the If PQ=QT, then PQ+RS+ST=RT

strange nimbus
#

OK, which rule is that?

lone skiff
#

im not very sure

#

is it one we already used?

strange nimbus
#

No.

lone skiff
#

its no congruence

#

not

strange nimbus
#

Right.

lone skiff
#

can we use addition property here

strange nimbus
#

Yes.

lone skiff
#

so it would be addition property

strange nimbus
#

Right.

lone skiff
#

next one i beleive to be is congruence

#

or reflexive

strange nimbus
#

Right, it's reflexive.

lone skiff
#

can it not be congruence?

strange nimbus
#

Reflexive is like reflecting, where it's the same thing on both sides.

#

Definition of congruence takes numbers like angles in degrees or lengths.

#

Then it says that if the numbers are equal, the things are congruent.

lone skiff
#

well it says measure meaning the number is the same

strange nimbus
#

Right, but we're not converting an equation to a congruence.

#

That's the kind of thing it's used for.

lone skiff
#

ah ok

strange nimbus
#

Equal numbers means you have a congruence.

lone skiff
#

ok

strange nimbus
#

But this is reflexive, so we can just use that.

lone skiff
#

next one has to be multiplcation right?

strange nimbus
#

Right.

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The "x property of equality" ones are algebra rules.

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Like do the same thing to both sides kind of thing.

lone skiff
#

ah

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ok

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this next one has to be

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congruence because its the only one that justifies the statment

strange nimbus
#

Right.

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It turns an equality into a congruence.

lone skiff
#

yep

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thank you so much for helping me

strange nimbus
#

You're welcome.

lone skiff
#

goodbye

#

.close

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strange nimbus
#

Have a good one.

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violet rampart
#

$(n): ; 0 + 1 + 2 + \dots + n = \frac{n(n+1)}{2}.&$

woven radishBOT
#

Benjamin Libet
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violet rampart
#

Help

#

$P(n): ; 0 + 1 + 2 + \dots + n = \frac{n(n+1)}{2}.$

woven radishBOT
#

Benjamin Libet

violet rampart
#

How do we get on $n = \frac{n(n+1)}{2}.$

woven radishBOT
#

Benjamin Libet

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queen tapir
#

How many different ways are there to write A in the form A=L+U where L is a lower triangular matrix and U isan upper triangular matrix?

queen tapir
#

this is a homework question and i wanna solve it but i dont have a single idea how

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now ik that there r infinite ways to write it but idk how did we even get to that and idk how to get to the example thing

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cuz i also have to give example of L and U

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so can someone just guide me through this ?

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sturdy mango
#

it is pretty simple after that u make cases according to your conditions

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restive river
#

Q. Prove that x^2 congruent to 1 (mod p) implies that x is congruent to +-1 (mod p).

restive river
#

x ≡ y(mod p)
so,
x² ≡ y²(mod p)
so, y² =1
=> y = +1 or -1
=> x ≡ -1 or +1 (mod p)

Why is this not correct?

sonic smelt
#

Why is y^2 necessarily 1? Which set are you taking y from

restive river
#

x^2 ≡ 1 (mod p) (given)
x^2 ≡ y^2 (mod p)
y^2 = 1

#

Can you give an example to show why this may be wrong?

sonic smelt
#

3^2 = 1 mod 2
3^2 = 3^2 mod 2
3^2 =/= 1

restive river
#

Oh

#

Got it

#

thank you so much

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restive river
#

.reopen

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restive river
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.close

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nova abyss
#

For what do you use sin, cos, tan?

devout snowBOT
nova abyss
#

Like to find what?

restive river
#

It's used for many purposes.

zenith jacinth
#

a lot of things actually :
in geometry it links the angle to the sides of a triangle
in physics, to study waves and other things

devout snowBOT
#

@nova abyss Has your question been resolved?

restive river
#

What do you mean what does it 'show'?

nova abyss
#

Like yk

topaz axle
#

it shows your coordinates as you move around a circle

#

when you're at the bottom, your y corrdinate is −1 and it changes slowly

#

your x coordinate is changing fast

#

like the middle of the circle is 0 and the radius is 1

#

sin is y and cos is x, the graph is a wave

nova abyss
#

What-

#

It’s so hard to understand.

topaz axle
#

it's uh

#

it's not hard

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#

@nova abyss Has your question been resolved?

nova abyss
topaz axle
#

if this circle has radius 1 you can roughly guess the coordinates of the point i marked

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#

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inner mango
#

Any convex optimization experts?

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#

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inner mango
#

<@&286206848099549185>

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hearty carbon
#

I have to calculate the sum of this series and i have no idea how. Anyone can help?

supple horizon
#

yeah

#

first

#

add one and subtract one

#

in the numerator

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then simplify

#

done

hearty carbon
#

bruh what

#

😭

supple horizon
#

?

hearty carbon
#

i asked chatgpt and it showed me smth totally nowhere that

supple horizon
#

fuck chat gpt

hearty carbon
#

@polar chasm telescopical series?

supple horizon
#

it can't solve math stuff

#

do what i said

hearty carbon
#

my teacher said smth about that but i don't understand shit

supple horizon
#

you'll get the ans

#

in terms of e

hearty carbon
#

but i don't understand why i have to do whatever u say

supple horizon
#

in order to simpify

#

the expression

#

you want to remove that n from numerator

hearty carbon
#

oh what the fuck

#

okay i see

supple horizon
#

ye

hearty carbon
#

i completely forgot i could do that

supple horizon
#

you actually dont get e

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you get 1

hearty carbon
#

what do i do afterwards tho

supple horizon
#

after what

#

do you know the series of e ?

hearty carbon
#

how do i like, calculate the rest?

hearty carbon
#

i am completely new to series

supple horizon
#

do you know euler's constant

#

2.7

hearty carbon
#

where are you going w this

supple horizon
#

do you know it or not

hearty carbon
#

nope

#

i'm dead honest, the math i did in highschool was very basic

#

now i'm a clueless year 1 student

supple horizon
#

the above simplified series converges to e-1 -(e-2) = 1

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okay fine

hearty carbon
#

welp

supple horizon
#

screw that theres a better method

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if you dont know e

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so you get 1 at the end

hearty carbon
#

god damn wtf

#

how about this one

#

did i solve it right?

#

my teacher solved one similar to this

supple horizon
#

cant understand the q

hearty carbon
#

the q?

supple horizon
#

but the way you solved is correct ig

#

question

hearty carbon
#

oh

#

it was just to calculate the sum of the series

#

just like i asked on the exercise before

#

that's why i am so confused about the way you solved it

#

cause it's nowhere near how i did this one

supple horizon
#

both the questions are related as they're just inf series summations

#

but the second one is geometric progression

#

while the first is not

#

yeah the second one looks right

hearty carbon
supple horizon
#

telescopic is different

#

in telescopic terms actually cancel out

#

here theres no canceling

hearty carbon
#

oh

#

so is this one geometric as well?

supple horizon
#

this is a polynomial

hearty carbon
#

how do i even begin

#

😭

#

i wanna actually understand those

supple horizon
#

you'll learn slowly

hearty carbon
#

where can i actually learn how to solve those

#

ai is almost of no use

supple horizon
#

there are so many good channels

devout snowBOT
#

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restive river
#

f is continuous / for all x€ R f(x)=f(2x) I should show that f is constant

lone ravine
olive snow
#

Écoute notre ami error

lone ravine
#

Oui oui

olive snow
lone ravine
#

J'ai déjà vu beaucoup des personnes aujourd hui qui parlent francais. Malheureusement, je ne peux pas lire tous les question

olive snow
#

No way error speak fr

#

The goat