#help-27
1 messages · Page 276 of 1
jag är inte den bästa på dessa
Min hjärna orkar tyvärr inte tänka 😭
Fattar, klockan är ju nästan 11
Jag får alltid hjärnsläpp på lektionerna
Jaha. Eftersom det finns chans för både 5 och 6 är det 4/47+4/47=8/47
Då fattar jag...
Om du får en god natts sömn kommer du förmodligen lösa problemet, sömn löser nästan allt!
Ah
När jag kodade spel brukade jag alltid tänka på problem jättelänge, men sedan under maten kom jag på de.
Matte 1c är dock jobbigt, eftersom vi går igenom en ny grej varje lektion
Fysik är nog svårast dock
Jo det är mycket man måste lära sig utan en kanske djupare förståelse
Ifall du väljer att plugga vidare till matematik vid universitetet
Men alltså på fysiken gick vi igenom kinetisk energi, sedan friktion nästa lektion
Så kanske det kan komma som en chock hur annorlunda man lär sig
Då är det väl bara föreläsningar?
Det är oftast uppdelat på liknade sätt, föreläsning, sen räkneövning
Men skillnaden är i materialet
Vi fick typ 30 minuters pluggtid efter kinetisk energi
Sedan gick vi igenom friktion
Oj
Personligen föredrar jag hur man lär sig i universitet, men många jag känner som tyckte om matten vid gymnasiet blev lite chockade när dem fick reda på skillnaden
Ja.. Men det finns matte spec och matte 5 här också
Då lär man sig komplexa tal
Så ifall du redan nu tycker att du inte får en så djup förståelse så kommer du att föredra universitet
Det är väl en ganska bra övergång?
Typ..
Många av dem gick det också, och det var fortfarande inte representativt
Vid gymnasiet är det mindre fokus på varför saker funkar, men snarare någon typ av metod eller formel (detta är väldigt grovt sagt)
Under vilka förutsättningar? Att härleda något med symboler ger egentligen väldigt lite och är inte så djupt
Det är skillnaden vid universitet
Symboler?
Dvs. en algebraisk härledning ger inte en djup förståelse av något, det bara faller ut från en beräkning
Och sen är detta under vissa förutsättningar som man gömmer
Detta är mera sagt bara en grov jämförelse
Från vad du kan förvänta dig vid universitetet
Inget illa menat, men bara en reflektionen; då många studenter får denna chock
Men hur förklarar de på universitetet?
Det är istället mindre fokus på en metod eller formel, oftast får du istället lära dig saker på en mycket mer djupare nivå
Men alltså hur exakt?
Ska jag tipsa min lärare om något?
Det är helt enkelt högre krav på att tänka själv och inte förlita dig på metoder.
Just det, man lär sig mer genom att testa själv
Inte riktigt? Det är mer av en konsekvens av att inte alla vill fördjupa sig på den nivån
Ett bra tips om man vill få ett smakprov av universitet är att gå någon typ av basårs kurs på ett universitet
Men läraren brukar ge exempeluppgifter som vi diskuterar med klasskamraten bredvid, sedan går han igenom hur man löser
Basår? Det kan jag väl göra när jag har tagit studenten?
Jo som sagt jag försökte bara ge en grov uppskattning av vad jag har lagt märkte till i de första gymnasium; detta måste inte sjävklart alltid stämma
Jaha, okej.
Men vad menar du med basår?
Jo ville precis nämna problemet att det är just efter du är klar med gymnasiet du kan söka till dessa.
Men kan vara bekvämare oftast om man gör på detta sätt, även om ämnena i sig är behörigheter för kurser från gymnasiet, så är dem på djupare nivå och i en miljö som faktiskt speglar livet i universitet
Jag tror dock du kommer klara dig utmärkt utan dessa
Mer av ett tips för elever i allmänt
Ialla fall
Jaa men jag fick bara C på fysikprovet
Var ganska krångligt
Oj :(
Jag fick F på matte1B i tre år vid gymnasiet
Men sen sista året klicka allting plötsligt
I tre år? Du pluggade matte 1b i tre år?
Japp!
Gick du 4 år?
Hatade matematik
Gymnasieingenjör?
Lyckades få C sista terminen innan studenten
Bra
Estet!
Men nu går jag Matematik programmet i universitet, även om jag trodde jag hatade matematik
I alla fall, klockan är jätte mycket och måste gå upp innan 7 imorn
Tack så mycket igen för det intressanta snacket
Har även fått VG (A betyg) i alla kurser än så länge, så betygen du har just nu spelar absolut ingen roll för din förmåga som jag märker du har väldigt gott av :)
Vad bra, jag fick A på matteprovet även fast jag råkade skippa en 3 poängare 😅 (jag såg inte frågan)
Jag var orolig att jag inte skulle få det
Bra jobbat!
Tack! Och god natt igen, på riktigt den här gången 😂
Så fort man inte förväntar något betyg har jag märkt att det är just då jag gör bra av mig, dem kan vara frestande när man lyckats få dem innan
God natt nu på riktigt!
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Hey guys!
If i have a linear system of ODE's in the form of x'=Ax+b. A (n by n matrix) and b (n-dim vector) are both complex. How do i find a particular solution?
We had something really similar were A and b were both with real Numbers. Can i just do the same?
We had this in another exercise even tho i dont know how the Integral would be defined on complex functions, we definitely never had such things so i dont think this is a solution too
@violet umbra Has your question been resolved?
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x = e^At + bt
Mhhhm, have to think about this
what part
nvm this may be wrong
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Could someone help me with descriptive geometry?
what will the cube look like?
on the top left is the right side
on the top right is the front
and on the bottom right is the top
<@&286206848099549185>
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Why am I getting a different answer here? Im using the correct formula
(Image 1 + 2): Formula I used
(Image 3 + 4): The answer my prof got
this is like the original question for this
shouldnt I be getting the same answer as prof
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if an integer sequence ,for example a_n,is in between some ranges for all n, does this mean a_n,repeats?
what does repeats mean?
it's not obvious if it has or doesn't have to be periodic
there are only so many integers in the range. if you have more elements than that (which you do in an infinite sequence), there must be a repeat
i see
i was doing an imo problem and didnt know where to go next, thanks guys
yeah ok even with just 2 possible integers, it doesn't have to be
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just a lil bit of help on this one
was sick for class and couldnt attend
and they gave homework
i do not understand that one guy on youtube with a black background
so if possible, with solution please
nah bruv
thats fck up
i think i will solve a few cases then u solve the rest
hows that
u gonna learn it the hard way
like how i was raised
like an asian
yes
i was sick for class today
alr bet
did not attend school at all
"The intersecting secants theorem states that when two secants intersect at an exterior point, the product of the one whole secant segment and its external segment is equal to the product of the other whole secant segment and its external segment. This is also known as the secant theorem or the secant power theorem."
just wikipedia it tho
i see
dunno anything about the lesson
bet
ill check
do you have the notes from ur friend or sth?
i think you should take a look at it tho
be4 i solve ur problem
waa
i dont have a single shit
mb i responded late
i was lookin at the theorem ands tuff
alr bet
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How to solve standard deviation?
..
How this work bruh
How to solve standard deviation
What the sigma
Ohh now i get it
I need a clear explanation about how to solve variance and Standard deviation
And also the meanings of the symbols
for variance:
- add all the numbers up then divide by the total number of numbers, to get the mean
- for each number, subtract the mean
- square all the numbers you have after doing step 2
- add all the numbers you have in step 3
- divide by the number of numbers
for standard deviation:
6) all of the above, but square root your answer in step 5
also, this gives you the population variance and population s.d
for sample variance and s.d you need to divide by (n - 1) instead of n in step 5
Step 3 is where i get confused
I dont know about how to square the numbers
say if I want to do step 3 on the numbers 3, 4, and 11 for example
their mean is
,calc (3 + 4 + 11)/3
Result:
6
so you do (3 - 6)^2 + (4 - 6)^2 + (11 - 6)^2
I've jumped ahead and added all the squares, so we have done step 4 actually
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how do i find these points for the second part
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i need help with this problem
try taking ln
Already and this is where i stuck
try using the Maclaurin series $\tan u \approx u + u^3/3$
then sub in $u = \pi x /2$
wait
no sorry you need the series around x = 1 arrghh
at least you know that $\ln(2 - x) \approx 1 - x$
cause $\ln(1 + u) \approx u$ and now sub in $u = 1 - x$
it's the tan part that is annoying
,w tan(pi x/2) taylor series at x = 1
But not workin tho
yeah the vertical asymptote screws it up
ah I think I might know
rewrite $\tan(\pi x/2) = \cot(\pi - \pi x/2) = \cot(\pi/2 \cdot (1 - x))$
southlander!
then you're just looking for $\lim_{u \to 0} \cot(\pi/2 \cdot u) \cdot u$
southlander!
now applying the limit of (tan u)/u as u goes to 0
this equals 1/(pi/2) = 2/pi
so the original limit must equal e^(2/pi)
I've checked on Desms
Yea
Ikr
yeah this should be a typo then
Wait but why $\cot(\pi-\pi x/2) = \cot(\pi/2 \cdot (1 - x))$
danto
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,w 1/x^2-2x-3 taylor series at x = 4
,w 1/(x^2-2x-3) taylor series at x = 4
Do you got the original question? Or is your question asking for Taylor series for the function when n=4?
Hmm interesting
nah bro just to make sure im correct tho
still have to do these shit manually tmr
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Could someone explain to me why the DFT of a signal x[n] is real if the magnitude of the DFT is even and its argument is odd?
I dont think I conceptually get this
For context: I don't quite understand the real and even reasonings
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by evaluating the integral using part two of the fundamental theorem of calculus and then differentiating
g'(x) =
I turned it into 5t - cost | 1 -> x
but when I tried to F(a) - F(b) I get some weirdness and I think I did something wrong
because I get cos(1)
are you purposefully not using ftc p1
oh so you solve the integral with both methods
why is it 1 to x
Oh
Why did I write 1, wtf
I think that was from the previous problem, okay let me fix that
yep
$[5x - cos(x)] - [5(0) - cos(0)]$
Xbye
Idk what the vocabulary is for this but I got that, but cos(0) is -1 let me see where this goes
$g(x) = 5x-cos(x)+1$
Xbye
So then I have to find the derivative of that?
yep
Okay, so cos = -sin
which makes me get back to the same as the FTC1 then
I got it, thank you. I'll probably be back in another channel with harder ones 🤣
np lol
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"Divisible by 5" = the last digit must be a 0 or 5
Of the 720 possibilities, how many end in a 5?
yea hes right, you could just count the ones that are devisible by 5 since theres not a lot. You could also use combinations but thats a bit more advanced
You wouldn't have to list them out and literally count
Just try to compute the number of strings like - - - - 5 and subtract from 720
ohh
complementary counting yeah
Yes
okkkk
sorry wifi problems
what about thisss
i dealt with questions that say
it has to be even and greater than so so number
but not with this
this is a constructive counting question i believe
last number always has to be a 2 or 4
then case work on 1 digit, 2 digit, and 3 digit cases
only thing to be careful of is that 5 isn’t the first number on the 3 digit case
last number?
not first?
oh right even
yes even
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"If three normal dice are thrown, what is the probability, P(C), that the the last C will be equal to the sum of the two first dices"?
I started by noting that for the first two dices, there are 6^2 = 36 combinations. Out of these 36, by drawing a multiplication table and only counting where the sum is equal to or less than 6, I get 15 such entries
The possibilities that I get those sums is therefore 15/36
The last dice can't be 1, as there is no way to get that sum
so there are 5/6 possibilities for the first dice
my answer is therefore P(C) = 5*15/6^3
but the correct answer is 15/6^3
yeah i believe it should be multiplying by 1/6 not 5/6 because after you throw the first 2 dice, only one of the 6 faces will complete the problem
(one of the six faces on the last dice)
wait wait
is it because the sum... can only be expressed by one of the faces?
But the first face is invalid, i.e when it is 1
wouldn't that leave us with 5 valid ones?
ohh nonono
,w expand (x+x^2+x^3+x^4+x^5+x^6)^2
if that logic you would multiply by 1/5, but you can still roll a 1 so you need to factor that into the probability
Yeah
I mixed up the valid cases vs the total possible cases
yeah all good
so for each selection from the table of 36 values, there's only 1 throw of the third die that will match.
so the chance of this occurring is 1/6
which is why it is 15/6^3 not 5*15/6^3
(for instance, if you throw a 1, 1, 2 that fits, but any of 1, 1, 3, or 1, 1, 4, etc will not.)
chance of rolling a sum <= 6 is 15/36, then your chance of rolling whatever the sum was is 1/6
yes
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\textbf{Exercise 4.} It is known that for a certain ( \alpha \in (\pi, \frac{3\pi}{2}) ), ( \sin(\alpha) = -\frac{1}{5} ). \textbf{Without using a calculator}, calculate ( f(\alpha) ) for the function
[
f(x) = \tan(x) + \tan(2x).
]
\textbf{Note:} It is not required to find ( \alpha ).
Renato Chavez
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Write everything in terms of $\sin\alpha$ and $\cos\alpha$
SWR
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?
u-sub
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the cyrrilc does not matter. i am so confused what the point of having a defenition of a subset
the defention of a subset by defeniotn must make it equal.
whats the point of having a convulted defeniton if it just means equal?
,rotate
pay more attention to the definition
A is a subset of B: Every element in A is also in B.
A is a Proper subset of B: Also, A is not B.
right, subset means that every element of A cant be found in B but by def proper subset says that if there is another element in B that is not in A then it is a proper subset
the only way for something to be just a subset is to have them equal then no?
im confused on what you mean by A is not B
the set A is not the same set (aka does not contain the exact same elements) as set B
for example. Let B={1, 2, 3}
A={1, 2, 3} would be a subset.
A'={1} would be a subset, and a proper subset
right, so A and B are equal
so whats the point of calling it a subset
if it just means equal
for proofs, basically
to prove that two sets are equal, very often you prove that A is a subset of B, AND B is a subset of A, thus A=B
thats is so stupid and convulted for a introduction to sets imo
not really
definitions simply need to be precise
because if they arent, Bad Things happen
but then why not define it as equal in the first place
i already did. A={1}
wait wait wait
so a set can be considered a subset and proper subset?
it breaks the def of a subset tho
no it doesnt
let's use my example
is every element in A also in B? yes, because 1, which is the only element of A, is in B. Thus, A is a subset of B
but B contains 2 and 3 which are not in A tho, def says if B contains elements that are not in A, then A is called a proper subset of B
like can a set basically be considered both in that case?
like as long as it fits the criteria it gets the title subset and proper subset?
yes
sometimes the distinction is important
when it isnt, you go by the more relaxed "subset"
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hi can someone help with proofs i cant do this 😔
What can you say about AED and BEC being congruent
um idk.. 😭
okay nvm
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help
If you have a question, you can ask it, and if anyone can help, we will 
I'll close the other one for you 
thanks
How comes you want to DM me? I may not be able to help with your question, after all 
Awwww, that's fine, you can ask anything here (and we're all [or at least mostly!] understanding and friendly here) 
tysm
Did you like have a worksheet or anything? 
no sadly
Awwww
that's fairs 
im in winter break 😦
I'm not super great with helping in general unless I have something to like reference personally 
Ah that's fair, was there anything from before you went on break you were working on?
Yep, if you can find something (and then ping me if you get anything!) 
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helo
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this doesn't have a maximum
but, how can I tell wheter it has a maximum minimun or not
You can find a maximum or minimum by taking the derivative of the function and solving for the values where x=0
As a max or min will look like a mountain or a U, where the peak or valley has slope 0
yeah but like
not, what do you see.
How can we make this x=0?
WE CANT
so, what do we do in cases like this.
the max/min can be at critical points
and critical points are where the first derivative is 0 or undefined
Sorry I forgot that part^
Okay, now
What do we do next
one would use second derivative
use the first or second derivative test to see if it’s actually a maximum or minimum
and/or*
we cannot replace x with 1
So, what happens in that case?
Secons derivative is not possible, so far.
to begin with x=1 isnt in the domain of m
and therefore the function has no critical points
and no possible extrema
critical points are in the interior of the functions domain
What?
But aren't critical points points where derivative doesn't exist?
Such derivative doesn't exist hehehe.
to be exact
A critical point of a function f is the point in the interior domain of f at which the graph of f has a horizontal tangent (first derivative = 0) or where f is not differentiable (first derivative undefined)
so
if the funcion is not defined in the first place
no critical point, right?
yes
@hexed berry Has your question been resolved?
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,rccw
im confused about this whole section
im trying to answer 3a
but
im confused
the only one that looks parralel is plane JKL
OK, what does parallel mean?
its means they are going the same direction or is simalair i understand what it means but not how to explain it
same direction for a line
but im unsure for a plan
For lines in the same plane, the lines don't intersect.
For planes, the planes don't intersect.
yup
The idea is that they stay the same distance apart and so they can't cross each other.
so wouldnt plane JKL be the answer
Yes.
Yes.
Right.
OK, skew means there's no plane that has both of them, they're not parallel, and they don't intersect.
OK, is there a plane that has both of them?
yes
OK, so that can't be it.
then HG can be the answer
Is there a plane that has both of them?
yup
What plane?
OK, are they parallel?
no
Do they intersect?
no
OK, so that's correct.
OK, do you have something that defines the properties?
what do you mean
Like that just lists the properties on the right.
Do you have anything that tells you what each property means?
no i dont have any notes
but is the first one reflexive property?
because i think i remember doing this
No.
oh
Reflexive is like AB = BA, but that's not what you have there.
That defines them.
ah
wait
im confused again Symmetric Property of Equality: If m∠A=m∠B
, then m∠B=m∠A
Yes, it is.
and i beleive then next one is either transative property or substitution
its transativ
?
transative property for the 2nd one
and last one is reflexive
Note that the last one has the ms disappearing.
Reflexive means you have a = a, same thing on both sides (it's like a reflection).
ok
What book is this from?
the third one is it definition of midpoint
What is a midpoint?
a point that is in the middle of a line
It's a point that's halfway between two other points.
yes
But we don't know if S is halfway between them.
oh ok
It could be somewhere else between them.
ok
Yes, that's right.
is the next one substition property?
In geometry, the segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC. This is related to the triangle inequality, which states that AB + BC
≥
{\displaystyle \geq }
AC...
oh so its wrong
Maybe, maybe not.
i see now
But substitution is like if b = c, then a + b = a + c.
But you kind of have the reverse.
If a + b = a + c, then b = c.
but would it still not be substition?
So, the substitution property won't be it.
No, when you say "if then", it's a one directional thing.
The 'if' being true makes the 'then' true.
But you're going the other way.
You're saying that the 'then' is true, so the 'if' must be true.
ok
You start with JK + KL = MN + KL.
yes
How can you change that to JK = MN?
meaning JK+2KL
Sorry?
What do you add?
Sorry, how did you get that from JK + KL = MN + KL?
well oh wait
i mixed it up
i read it wrong
i saw this seciton by itself
JK + KL = MN
Oh, OK.
it can be substition or relfexive
What is equal to itself?
it cant*
No.
what
It's not doing anything.
It's an equation.
You need to manipulate the equation to get the second equation.
well they are equal to eachother
No, you can't.
what
You're starting with JK + KL = MN + KL.
That's all you know.
You don't know anything else.
You don't know that JK = MN.
oh ok
You're trying to prove JK = MN, not start out knowing it.
No, definition of congruence is where two things that have the same measure are congruent.
ok
Like if two angles have the same number of degrees, they're congruent.
ok
Or if two segments are the same length, they're congruent.
ok
How would you go from JK + KL = MN + KL to JK = MN using algebra?
subtraction get rid of both KL
Right, so which rule is that?
property of subtraction
Right.
What are you substituting?
OK, that's a good guess, but there's a better rule.
No, there are no congruence symbols.
OK, so the reflexive property means a = a (same thing on both sides). The symmetric property means that a = b leads to b = a (you switch the sides). The transitive property means that a = b and b = c leads to a = c.
so it is transitive?
but we already used it?
Which problem did we use it in?
That's like the fourth problem.
is it addition property?
Oh, never mind.
what do you mean
It's not like the fourth problem.
oh
so its substition
Right.
that was my second guess
Transitive also works, but you have to use the symmetric property to flip one of the equations.
So, it would be more than one rule.
ah okay
VW + WY = ZY and VW + WY = XZ
VW + WY = ZY and XZ = VW + WY
XZ = VW + WY and VW + WY = ZY
XZ = ZY
Hey,
could anyone help me draw x²-|x| 's chart?
To use transitive, yes.
See #❓how-to-get-help for how to get help.
ok
But substitution is much easier.
OK, which rule is that?
No.
Right.
can we use addition property here
Yes.
so it would be addition property
Right.
Right, it's reflexive.
can it not be congruence?
Reflexive is like reflecting, where it's the same thing on both sides.
Definition of congruence takes numbers like angles in degrees or lengths.
Then it says that if the numbers are equal, the things are congruent.
well it says measure meaning the number is the same
Right, but we're not converting an equation to a congruence.
That's the kind of thing it's used for.
ah ok
Equal numbers means you have a congruence.
ok
But this is reflexive, so we can just use that.
next one has to be multiplcation right?
Right.
The "x property of equality" ones are algebra rules.
Like do the same thing to both sides kind of thing.
ah
ok
this next one has to be
congruence because its the only one that justifies the statment
You're welcome.
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$(n): ; 0 + 1 + 2 + \dots + n = \frac{n(n+1)}{2}.&$
Benjamin Libet
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Benjamin Libet
How do we get on $n = \frac{n(n+1)}{2}.$
Benjamin Libet
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How many different ways are there to write A in the form A=L+U where L is a lower triangular matrix and U isan upper triangular matrix?
this is a homework question and i wanna solve it but i dont have a single idea how
now ik that there r infinite ways to write it but idk how did we even get to that and idk how to get to the example thing
cuz i also have to give example of L and U
so can someone just guide me through this ?
@queen tapir Has your question been resolved?
you need to have knowledge of fundamental principle of multiplication
it is pretty simple after that u make cases according to your conditions
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Q. Prove that x^2 congruent to 1 (mod p) implies that x is congruent to +-1 (mod p).
x ≡ y(mod p)
so,
x² ≡ y²(mod p)
so, y² =1
=> y = +1 or -1
=> x ≡ -1 or +1 (mod p)
Why is this not correct?
Why is y^2 necessarily 1? Which set are you taking y from
x^2 ≡ 1 (mod p) (given)
x^2 ≡ y^2 (mod p)
y^2 = 1
Can you give an example to show why this may be wrong?
3^2 = 1 mod 2
3^2 = 3^2 mod 2
3^2 =/= 1
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For what do you use sin, cos, tan?
Like to find what?
It's used for many purposes.
a lot of things actually :
in geometry it links the angle to the sides of a triangle
in physics, to study waves and other things
@nova abyss Has your question been resolved?
But like what does it show?
What do you mean what does it 'show'?
it shows your coordinates as you move around a circle
when you're at the bottom, your y corrdinate is −1 and it changes slowly
your x coordinate is changing fast
like the middle of the circle is 0 and the radius is 1
sin is y and cos is x, the graph is a wave
@nova abyss Has your question been resolved?
I don’t understand
if this circle has radius 1 you can roughly guess the coordinates of the point i marked
@nova abyss Has your question been resolved?
How?
.close
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Any convex optimization experts?
@inner mango Has your question been resolved?
<@&286206848099549185>
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I have to calculate the sum of this series and i have no idea how. Anyone can help?
?
i asked chatgpt and it showed me smth totally nowhere that
fuck chat gpt
@polar chasm telescopical series?
my teacher said smth about that but i don't understand shit
there is a e
but i don't understand why i have to do whatever u say
ye
i completely forgot i could do that
what do i do afterwards tho
how do i like, calculate the rest?
where are you going w this
do you know it or not
nope
i'm dead honest, the math i did in highschool was very basic
now i'm a clueless year 1 student
welp
god damn wtf
how about this one
did i solve it right?
my teacher solved one similar to this
cant understand the q
the q?
oh
it was just to calculate the sum of the series
just like i asked on the exercise before
that's why i am so confused about the way you solved it
cause it's nowhere near how i did this one
both the questions are related as they're just inf series summations
but the second one is geometric progression
while the first is not
yeah the second one looks right
isn't it a telescopic progression?
telescopic is different
in telescopic terms actually cancel out
here theres no canceling
this is a polynomial
you'll learn slowly
youtube
there are so many good channels
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f is continuous / for all x€ R f(x)=f(2x) I should show that f is constant
Hint: Show that for any x we have f(x) = f(0)
Écoute notre ami error
Oui oui
This is french night kekw
J'ai déjà vu beaucoup des personnes aujourd hui qui parlent francais. Malheureusement, je ne peux pas lire tous les question
