help-27

[olive snow]

do you agree that PS = PQ + QS ?

and so what is PQ equal and QS ?

[languid field]

what sorry i dont understand

could you please elaborate

[olive snow]

do you agree with my first question ?

[languid field]

yeag

[olive snow]

so what is PQ and QS in terms of a and b ?

[languid field]

do you need me to send you the notes

so that tou can understand

[olive snow]

no

i understand what you have to do dw

[languid field]

yeah but i dont understand all ur questions

in fact i dont understand the WHOLE lesson

[olive snow]

ok

i can explain

no problem

[languid field]

ok thank you sO mych

[olive snow]

so

[restive river]

heh

[olive snow]

if you have 3 points

[restive river]

hi

[olive snow]

A, B and C

are three points

then you have AC = AB + BC

[languid field]

ok and then

[olive snow]

it's useful to decompose some unknown vectors in vectors that you know

that's what they want you to do here

[languid field]

ahhh ok

so whats the answer

and the solution

[languid field]

this is an example by the way

thats what i need to do

but i dont understand anything

[olive snow]

ok but answer my question

[languid field]

whats tquestion

[olive snow]

this

[languid field]

thats the question im tryna ask

[olive snow]

the answer is in the statement of the exercice

[languid field]

ok

and then

[olive snow]

and then its done

?

[languid field]

??????????

[olive snow]

you have the answer for question a)

[languid field]

yeah but i need the whole answer

like the thing in the whiteboard i sent

something like thaT

[olive snow]

no need that here

the exercice is easier than what's on the board

[green river]

i mean it says in the question that ||PQ = a|| so that's probably something

[languid field]

then why dont you help

[olive snow]

?

i told you what to do

[languid field]

what again

[olive snow]

PS = PQ + QS and then replace value

given in the statement of the exercice

and same for the second one

same method

i won't do the whole exercice

that's not the point of helping

the method is the same

apply for the second question

How can you write PT ?

[languid field]

do i have to do something with the drawing

[olive snow]

it can help to have idea yeah

[languid field]

but what i do

[green river]

i mean this question looks more like juggling symbols around tbh

you can probably do it without the drawing

[languid field]

ah ok so what do i do

guys i know the answer but not the solution

chatgpt helped me with the answer help me with the solution now

[green river]

maybe i show u 1/2 and then you complete the other 1/2? using ur pattern recognition

[languid field]

yeah ok thanks do that please

[green river]

PS
= PQ + QS (as we agreed earlier)
= a + QS (because the question says PQ = a)
= ...

the other equations from the question are
QT = (-1/2) QR
QS = (1/4) QR
QR = b

so which one can you apply

[languid field]

wow thanks

ummmmmmm

[languid field]

apply what agin

sorry

[green river]

by apply i mean substitute
use one of the equations to substitute

[languid field]

what equations

[green river]

the ones the question gave us

since it gave us these equalities

PQ = a
QT = (-1/2) QR
QS = (1/4) QR
QR = b

right?

[languid field]

oh yeah so what do i do next

[green river]

well

take a guess first and i'll tell you after

[languid field]

is the one u gave me already there or did u answer that for me

[green river]

i haven't given you any puzzle pieces the question didn't give you

this is just the working so far

PS
= PQ + QS (as we agreed earlier)
= a + QS (because the question says PQ = a)
= ...

so what do you think the next step is

[languid field]

sorry what can you use basic english i dont understand what you been saying this whole time

[green river]

[languid field]

haha sorry i really just dont understand everything

very sorry

[green river]

which parts are you having trouble understanding? only the math, or also the english?

what is your native language

[languid field]

only the math

[languid field]

im flippino

[green river]

i see

okay

to summarize how we got to this point

[languid field]

i know the final answer but i need the solution anf my teacher needs us to do something on the illustration for each question

like the thing i sent

the white board

[green river]

okay

let me think

btw what is the final answer

[languid field]

ok thabk you so much i appreciate your help

[languid field]

this is the final answrr i just need the solution and the illustration

[green river]

how come chatgpt didn't tell you the solution

[languid field]

similar to the one on the whiteboard

[languid field]

it did but it not the same as the one on the whiteboar

and the illustration

[green river]

[languid field]

ar you still gonna help

[green river]

give me a second

writing things down

[languid field]

okayyy

[green river]

so basically this is what we've said so far

does it help to put it in this format...

[languid field]

bro i feel bad you did all that and i still dont understand anything

[green river]

okay

we take one step further backk

can you tell me what is a vector

[languid field]

i dont know

sorry

[green river]

no worries

it just means your teacher is bad at teaching

[languid field]

nah i dont think so

im really bad at math

like really really bad

it would take me so long to understand a topic

[green river]

everyone learns differently

anyway

when you draw a shape like a square or hexagon

it has corners, and it has lines connecting the corners

[languid field]

sorry why are we talking about that

[green river]

when we have a line that connects two points, that is a vector

makes sense?

[languid field]

yeah

so like what do i do bro

[green river]

slow down a bit

if u dont understand the solution and i just write it out then u learned nothing

[languid field]

i dont know if im able to slow down i got some other thigns to do i feel so very pressured right jow

[languid field]

ok continue

[green river]

ok u tell me if i go too slow or too fast

so

in the question the line between points P and Q is given its own name

it is a

PQ = a

[languid field]

are you filipino or american

[green river]

neither

[languid field]

oh

ok continue

[green river]

and similarly QR = b

ok we also know that QS = (1/4) QR. we don't have a name for QS, but because we know that QS = (1/4) QR we can subs QR => b and write QS = (1/4) b

in other words

the line QS is 1/4 the length of the line QR, and in the same direction
the line QR has its own name which is b
so the line QS is 1/4 of b

[languid field]

hey bro

[green river]

does this looks right

[languid field]

maybe

[green river]

yeah?

[languid field]

i dont remember my teacher doing that

[languid field]

i appreciate your help and all

but teaching me all this isnt really gonna do anything because i dont understand what ur sauing

but what im sayin f is that can you send the answer

and illustration

i mean the solution cause i alrewdy know the answer

[green river]

have u considered asking your teacher for help after school ends

[languid field]

no

[green river]

maybe you should

[languid field]

yeah maybe

but you dont wanna send the solution? hehe

just the solution

[green river]

hence a + (1/4) b

ok i've said enough

[languid field]

is that answer?

thank you still

for your effort

[green river]

its illustration

[languid field]

ohh for the ps right

[green river]

yes

ok i go now wish u good luck with the part (b)

[languid field]

ok thank you bro tysm for helping me i really appreciate it

have a nice day

[devout snow]

@languid field Has your question been resolved?

[languid field]

is this mfor my question

[steady onyx]

no it was when the bot was broken

i thought that you were done so i used your channel

[languid field]

thou lumpish gorbeilled onion eyed flap dragon pls help me with letter b

[steady onyx]

have you found the answer yourself or

[languid field]

i mean i know the final answer but i need the solution and illustration

[steady onyx]

what is the original question

[devout snow]

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[languid field]

hold in

on

@steady onyx

[steady onyx]

im going to assume that T is outside of the image

[languid field]

what

[steady onyx]

where is 'T'

[languid field]

hold on

i thi nk below

[steady onyx]

k

[languid field]

bro what you mean k???

[steady onyx]

okay

im thinking

[languid field]

ok

actually

yeah i was right it is belo

here

[steady onyx]

isnt answer a just 1/4ab ?

[devout snow]

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[astral stump]

hey yall, isnt this solution just completely wrong becuase it implies you could get the same card twice

[winter torrent]

well no

that's what C(52, 5) means

[astral stump]

waut

wait

im so dumb

holy shit

thanks for your services

.close

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[cerulean wharf]

Hello

[cerulean wharf]

Suppose I pick a uniformly random number x from Z_p, multiply it by a small constant c and take c*x mod p mod q, with q < sqrt(p), will the result be uniformly random too?

[violet wind]

What is a "small" constant

[cerulean wharf]

Can be q or smaller for example

[violet wind]

If it's not divisible by p then the first step won't change the distribution

second step will cause slightly higher probability for whichever values are less than p mod q

[winter torrent]

this feels like crypto. is this crypto?

[cerulean wharf]

Yesss, I am looking for ntru

[winter torrent]

nice

[cerulean wharf]

So c has to be coprime with p

Thank you!!

[winter torrent]

hmm even if q < √p you'll still see boundary effects

as a small example if p = 5 and q = 2, then 1 will be a fair bit more likely than 0 i think?

[cerulean wharf]

q prob need to be way smaller than p to keep uniform or close to it

All tests I do give a very non uniform answer 😔

Oh actually it did now with q very small and p very big

[devout snow]

@cerulean wharf Has your question been resolved?

[devout snow]

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[ebon cloud]

How do i find the radius?

You are standing at point C as shown in the figure, about 8 feet away from a circularnfountain

[ebon cloud]

from you to the point if tangency is 20 ft

[opaque willow]

So O is the center of the circle right?

[ebon cloud]

yes

[opaque willow]

You spotted the right angle right here, so we have a right triangle

What property do you know about right triangles?

[ebon cloud]

like the hypotnuse and legs?

[opaque willow]

ye

what's the name of the theorem?

[ebon cloud]

pythagorean theorem

i think

[opaque willow]

yes

[ebon cloud]

im confused on what i need to solve for here

[opaque willow]

You want to find the radius

Call it x

[fossil locust]

the radius, you want to find the radius

[ebon cloud]

and where is x located tho

[opaque willow]

It is the radius of your circle

Where is it located?

[ebon cloud]

ah i mistook the radius for the whole circumference

my bad

[restive river]

you can use this equation:

and then you can solve for r

[restive river]

Since we don't have angles, we can't apply trignometry and derive the value of x

[opaque willow]

That's just spoon-feeding the answers

[restive river]

still requires thinking on their end 😉

[opaque willow]

I mean, nobody doubts that you can do this yourself, but writing the equation is like 80% of the thinking

[restive river]

I'll remove it

You have a good point

My apologies

[fossil locust]

yeah I've been corrected like that in the past

to not give away the question

[restive river]

Perhaps a nice annotation could help them

[fossil locust]

they clearly can do it cause they mentioned Pythagoras and they drew the diagrm

[opaque willow]

This is promising

[fossil locust]

mhm

[restive river]

however they are yet to show that they have understood the idea that the hypotenuese is 8 + x

[ebon cloud]

i have no idea what is even happening rn

[opaque willow]

Essentially 3 helpers arguing

Anyway

The diagram is a good start

Now you need to find the hypotenuese in terms of x

[restive river]

I'll let brainducker continue...I think that they would do a good job explaining

ciao

[ebon cloud]

wait this may take a while

[opaque willow]

Really?

On the first figure

[ebon cloud]

so uh

leg a is x

leg b is 20 ft

from what i wrote

to find the hypotnuse, i used
c² = a²+b²

then

c² = x² + 20²

c² = x² + 400

then i got lost

i think a √ should be used?

[ebon cloud]

yuh

[opaque willow]

Hm

Well, the sketch was not correct in fact

The hypotenuse is 20 ft

[ebon cloud]

ah

sh

oh wait how

[ebon cloud]

leg b is 20 ft,

[opaque willow]

No, 20ft that would be c, the hypotenuse

[ebon cloud]

can u try to remix this

cuz

from my understanding

its like this

the hypotnuse is the side that is directly across the right angle

[devout snow]

@ebon cloud Has your question been resolved?

[devout snow]

@ebon cloud Has your question been resolved?

[devout snow]

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[native thistle]

pls tell me where im doing wrong im so confused abt eular

[devout snow]

@native thistle Has your question been resolved?

[native thistle]

<@&286206848099549185>

[native thistle]

Pls anyone..

[supple knot]

Are you trying to use L'Hopital?

[native thistle]

L hopital is. Basically derivattive right?

Until it's no longer the 1st form?

[supple knot]

That doesn't answer my question

And no

[native thistle]

Then what is itt

[supple knot]

https://tutorial.math.lamar.edu/Classes/CalcI/LHospitalsRule.aspx

Blue box in the middle of the page

[native thistle]

uh..differentiation?

[native thistle]

also yes? since its like indeterminate

but i dont rlly know how the flow works

[native thistle]

<@&286206848099549185>

[restive river]

hi, @native thistle

I think i can help you

if you know about Taylor, you can use that

understand?

@native thistle , are you there?

your result is wrong

🔒

[supple knot]

Read the examples in the link

[devout snow]

@native thistle Has your question been resolved?

[devout snow]

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[carmine orbit]

how do i solve it

[idle swift]

0<=sin^2(x)<=1

[carmine orbit]

?

[ocean pendant]

sin^2(x) will always be bounded between 0 and 1

x^2+1 increases much faster than sin^2(x)

meaning that as x approaches infinity, the function exponentially decays towards 0

[carmine orbit]

how tho

how does it decay towards 0

[ocean pendant]

because you are dividing by an increasingly larger number

e.g. 1/2, 1/10, 1/26, ...

[carmine orbit]

im kinda confused how is sin^2x bigger than the denominator

[ocean pendant]

it isn't

thats why we can say that the function will approach 0

the denominator grows MUCH faster than the numerator

[carmine orbit]

exactly

ohhh

i got it now

[ocean pendant]

sin^2(x) will never be greater than 1

[carmine orbit]

thing is i have to look for these graphs in desmos but if im in the exam how do i know how the graphs look

[ocean pendant]

whereas (x^2+1) will approach infinity as x approaches infinity

[carmine orbit]

yeah i got it

[ocean pendant]

wdym u have to look for them

[carmine orbit]

idk how sin^2x looks in a graph i have to go to desmos and see

[ocean pendant]

why do you need to know that on an exam

do you have to draw it yourself or something

[carmine orbit]

because how would i know that x^2+1 gets bigger

[ocean pendant]

like why does it increase faster than sin^2(x)

?

[carmine orbit]

yes

[ocean pendant]

because it's an exponential

different functions will increase at differring speeds relative to one another

take 2x and (x+2)^2 for example

which one do u think will grow faster

[carmine orbit]

dumb question but what does this mean

[ocean pendant]

exponential functions are those which are multipled some number of times by itself

[carmine orbit]

oh ok

[ocean pendant]

so like

x^2 is the same as x times x

[carmine orbit]

but sin^2 is multiplied some number of times by itself no?

[ocean pendant]

you're right

but what is the highest that sin x could ever be?

what is the greatest value that sin(x) could possibly take

[carmine orbit]

1

[ocean pendant]

right

so what is 1 * 1

[carmine orbit]

ok got it

[carmine orbit]

so to answer this the second one will grow faster

[ocean pendant]

the denominator will grow much faster than the numerator

so the function will decay towards 0 as x approaches infinity

[carmine orbit]

yes

ok what if it was the other way around @ocean pendant

the denominator for example was (sin^2)x

[ocean pendant]

hmm

that I do not know

because sin^2(x) at different intervals of x will approach 0

so the function on those intervals will "blow up"

someone else would have to answer than lol

[carmine orbit]

ok

one last question regarding smth else

[ocean pendant]

actually I think the function will still approach infinity

[carmine orbit]

in this one

why do we multiply with the the numerator

but +5

[ocean pendant]

to get rid of the square root

[carmine orbit]

oh

[ocean pendant]

you treat the numerator as a-b, where a is sqrt(x^2+9) and b is 5. if you do (a-b)(a+b), you are left with a^2-b^2

[carmine orbit]

yeah i got it

[ocean pendant]

just make sure you multiply the denominator by the same thing

[carmine orbit]

yes i know

i just didnt know why we did that

alright thanks for everything

.close

[devout snow]

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[devout snow]

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[wind elm]

Hello

[wind elm]

I’m going back to a similar mistake I made from a differential equation

with this in mind, I didn’t want to forget the (-)

But here:

I made a mistake where this problem in particular does not have a (-)

just wanted to get clarification if it is because our value “y” is not a constant and therefore cannot result in (-)

[misty crest]

y is the independent variable here

and the coefficient of y is 1

if it was a-y then yes

it would have the -1 as before

[wind elm]

how does that make it different from the other problem we went over not long ago

[misty crest]

because it’s y-a

not a-y

we’re integrating dy not da

a is the constant here

before it was constant - L

[wind elm]

so because its derivative y-a is with respect to y, then its simply 1?

meaning, we dont need any additional adjustments to our problem

[devout snow]

@wind elm Has your question been resolved?

[devout snow]

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[haughty badger]

how can I sovle this, by paper and pen?

[haughty badger]

[x/(-1/2)], I want to learn how to solve the -1/2 in the equation above,

[plain lily]

Multiply both sides by -0.5?

[hollow pulsar]

woah, the arabic version of my name

[haughty badger]

thank you

[haughty badger]

Woah, you are the English version of يوسف

.close

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[devout snow]

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[stable nymph]

i need help

[stable nymph]

on

optimisation

[devout snow]

@stable nymph Has your question been resolved?

[stable nymph]

<@&286206848099549185>

[devout snow]

@stable nymph Has your question been resolved?

[devout snow]

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[unborn atlas]

Question 3, equation 5 is at the top

[unborn atlas]

I know the answer is sin(4x) and I get why but I don’t see how to get that using equation 5

I just get a very confusing integra

[wicked turtle]

confusing because the denominator is unreadable? 😁

[unborn atlas]

$cos^2(4x)$

[woven radish]

Nathan

[misty crest]

$\cos \gamma \psi 0)$

[woven radish]

knief

[unborn atlas]

Ok it’s not that bad 😭

Just help please

[misty crest]

nah it is

[unborn atlas]

Okay well how do I do it

[misty crest]

what’s the cos(4x) outside

is it supposed to be in the integral?

[unborn atlas]

Nope

It’s outside

Look at equation 5 at the top

[misty crest]

ahh ok

so

$\int \frac{e^{-16x}}{\cos^2(4x)} dx$

[woven radish]

knief

[misty crest]

have you tried ibp

[unborn atlas]

I don’t know what that is

Oh

Parts

Yes

It doesn’t work

[misty crest]

hmm yea no it won’t

is this even possible

you probably made a mistake somewhere

[unborn atlas]

The answer is sin4x

It says use that equation

Putting two and two together it must be

[misty crest]

,w \int \frac{e^{-16x}}{\cos^2(4x)} dx

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
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Requested by c.knief

[unborn atlas]

Nope

[misty crest]

yep definitely not

[unborn atlas]

So then what’s up

[misty crest]

go back in your work then

you made a mistake somewhere

[unborn atlas]

Look at the question

I didn’t

Look at 5 and just sub on cos(4x)

[misty crest]

number 5?

you mean 3?

[unborn atlas]

No

The equation

Is number 5 at the top of the page

The derived formula for the second fundamental solution

3 is the question

[misty crest]

oh

well

what’s your P(x)

how did you get -16x

[unborn atlas]

Because P is 16

?

Integrate is 16x with the negative in front

[misty crest]

am i mistaken or is the P(x) supposed to be the coefficient of y’

16 is the coefficient of y

not y’

[unborn atlas]

It is

And I am stupid indeed

[misty crest]

yep

sin(4x) is correct then

because it’s just the integral of sec^2

[unborn atlas]

Yeah I’ll take it front here yeah thanks

[misty crest]

which is tan

[unborn atlas]

Yep

Silly mistake heh

[misty crest]

and tan * cos is sin

[unborn atlas]

.close

[devout snow]

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[devout snow]

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• Show your work, and if possible, explain where you are stuck.
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[hardy sonnet]

Hi!

I’m working on C

[misty crest]

factor 3 + b

[hardy sonnet]

I’ve been doing well on most of these questions but I can’t seem to find out this

Why am I tricking over this question

[solar goblet]

dennis ritchie is that you?

[hardy sonnet]

I don’t understand why it turns out to be (1+b)

[hardy sonnet]

When factored

[misty crest]

they also factored the 5

[hardy sonnet]

Why tho

Why is it 1+b

I don’t get it

[maiden pecan]

They factored out the 5 after

[agile elbow]

just factor out 5(3+b) as given

and don't rely on chat gpt

for math

[solar goblet]

!nogpt

[devout snow]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[hardy sonnet]

Oh

My fault

I guess I’m just adding 1 in every equation wtf

Connor!

[supple pike]

Don't utilize artificial intelligence for algebraic expressions, when it ventures outside the domain of simple arirthmetic and other operations, it's quite innacurate. However, could I assist you?

[supple pike]

What?

[hardy sonnet]

Yes please!

Help meeee

[supple pike]

Alright, what's the exact equation/statement you need solved?

[hardy sonnet]

Wait

[supple pike]

Alright

[hardy sonnet]

Chat gpt is wrong

WOW HHAHAH

[supple pike]

That's what I suspected..

[hardy sonnet]

It was right many times before I swear

[supple pike]

It's just innacurate, sometimes it can fail with simple arithmetic operations, it really just depends on your luck

[hardy sonnet]

The answer key is (3+b)(5+5b)

I can’t understand how to factor that

[supple pike]

For what statement?

[maiden pecan]

It’s not wrong

You can still factor out 5 from (5+5b)

That’s how ChatGPT got its answer

[hardy sonnet]

Oh

[hardy sonnet]

This is the equation

C

[supple pike]

Alright, it seems quite easy

[hardy sonnet]

Yes

I did all the hard stuff and stuck on easy stuff lmao

[supple pike]

First, I've noticed that the common factor would be (3 + b) for it

[hardy sonnet]

yes

so i keep 1 of them

[supple pike]

Alright, I know, so let's see

Alright, so you would need to factor 5(3+b) out of 5(3+b) + 5b(3+b), resulting in the answer, 5(3 + b)(1 + b)

@hardy sonnet

[hardy sonnet]

how come its 1+b sir

is there any chance u an give me step by step instead of saying u need to factor

im starting to forget how the whole thing works tbh

[maiden pecan]

Start by factoring (3+b)

[supple pike]

Sure, I'll show you my work

[maiden pecan]

What do you get after that

[supple pike]

Or he could just share his if taht works

[misty crest]

factor 5(3+b)

[supple pike]

that*

[hardy sonnet]

how do i factor

[maiden pecan]

You did it in the last question

[misty crest]

5(3+b) is common to both

[supple pike]

Factor by the common factor, (3 + b)

5(3+b)*

[fallen hull]

[supple pike]

Here's a further explanation: When you first factor 5(3+b) from the first statement, you'll be left with 1, and when you do the same with the second statement, you're left with b; therefore, you'll yield 5(3+b)(1+b), which would be equivalent to 5(3+b) + 5b(3+b)

[hardy sonnet]

thanks so much

i understand now

have a good day!

.close

[devout snow]

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[misty crest]

you as well

[supple pike]

You as well!

[devout snow]

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[reef frost]

Can someone please show me how to do this and explain it to me

[woven radish]

𝔸dωn𝓲²s

[faint gorge]

So basically you first solve Ly = b then Ux = y

[restive river]

Bacc?

[devout snow]

@reef frost Has your question been resolved?

[devout snow]

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[restive river]

HI CAN ANYBODY HELP ME, I'M IN NEED OF HELP RN

[soft umbra]

Where’s your question?

[torn bane]

https://dontasktoask.com/

[restive river]

Note also that the volume of segment of a sphere of altitude h and radii a and b is equal to the volume of a sphere of radius h/2 plus the sum of the volumes of two cylinders whose altitudes are h/2 and whose radii are a and b, respectively.

my prof asked us to prove this BUT I DIDN'T GET TO CATCH UP ON HIS ONLINE CLASS😭

my internet sucks and he's giving us a chance 12 noon it's 11:05 now

subject: Solid Mensuration 1st year college

HELLP

[torn bane]

im a bit confused, what is a segment of a sphere of altitude h and radii a and b

[restive river]

this is my drawing i just draw what i read and understand but i didn't really get to catch the discussion

[torn bane]

so is b the radius of the sphere and a the radius of the circle above the equator

[restive river]

this js the module

[restive river]

b the radius of the sphere the is in the segment ig, since a segment is formed by 2 planes cutting the sphere in parallel

[torn bane]

wait according to this diagram, it seems like R is the radius of the sphere, b is the radius of one slice, and a is the radius of another slice

and you want to find the volume of the region in between the two slices

[restive river]

OHH

yeah, well our prof tasked us to defend this statement and prove that it is a spherical:

Note also that the volume of segment of a sphere of altitude h and radii a and b is equal to the volume of a sphere of radius h/2 plus the sum of the volumes of two cylinders whose altitudes are h/2 and whose radii are a and b, respectively.

[torn bane]

alright so what are you confused about

[restive river]

like how do you prove this

[torn bane]

well what is the volume of the segment of the sphere

[restive river]

and is my illustration wrong?

[torn bane]

i think it's right

[torn bane]

_ _

[restive river]

i also don't know

all i know is that is to prove that statement and idk too😭😭

[torn bane]

the volume is written on one of the pictures you sent

,, V = \frac{\pi}{6} h (3a^2+3b^2+h^2)

[woven radish]

Bair

[restive river]

so that's the answer?

[torn bane]

you want to prove something right?

[restive river]

YES

oh wait so was this correct?

this was my answer when i tried

[torn bane]

im confused what you mean by "answer"

your answer should be a proof, not a formula

[restive river]

oh right

[torn bane]

do you understand what you are being asked to show

[restive river]

nope

wait i just noticed 2 cylinders

[torn bane]

that the volume of this region between the two slices is equal to the volume of a sphere plus the volumes of two cylinders

i would do this by finding the volume of the region between slices, which we've done already, and then finding the volume of the sphere and two cylinders

and then showing that they are equal

[restive river]

ohh okay

wait do you know howw??

[torn bane]

what's the volume of a sphere

[restive river]

i also don't know

[torn bane]

it's a common formula, it's 4/3 pi r^3

and what's the formula of a cylinder

[restive river]

is this correct???

[torn bane]

seems good to me

[restive river]

oo thankyou

then wait

how do i prove this in a sentence??

[restive river]

this??

[torn bane]

yeah pretty much

[restive river]

ok

thankyou

[torn bane]

👍

[restive river]

so am i good now?? was it correct or was i wrong??

[torn bane]

about what

[restive river]

my answers, solutions and the proving part

[torn bane]

i think i agreed with you already

[torn bane]

im not sure where exactly this came from, considering you didn't know the volume of a sphere, but this is correct

[devout snow]

@restive river Has your question been resolved?

[devout snow]

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[tight wave]

Can someone help me solve this inequality

[tight wave]

If I need to clear anything up in my writing I can do that

Idk if what I've done so far is right and if it is idk what to do from here

Also the reason why there's random spots where the letter t is super dark is bc I wrote x out of habit and was too lazy to erase them

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@tight wave Has your question been resolved?

[tight wave]

.close

[devout snow]

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[forest mason]

What do I do if I have theories? I contacted a college and they ignored me.

[rare merlin]

u invented a theorem?

[forest mason]

Yeah I got theories

[stray spade]

do you have proof of your theories?

[forest mason]

Yeah I got true theories

[stray spade]

please don't use the help channels for trolling 🙏

ive seen the meme

[forest mason]

Um

What meme lol

[stray spade]

just close the channel

type .close

[forest mason]

.close

[devout snow]

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[vital sorrel]

Just want to know how to do this so I am ready for my test later today

[quick dome]

Hello @vital sorrel

Solve this you should get your answer

[vital sorrel]

Do I just cross multiply and then solve

[quick dome]

Yup

[vital sorrel]

1.25 right

[quick dome]

Perfect

5/4

1.25

[vital sorrel]

Alright thank you for the help just wanted to check

[quick dome]

👍

[vital sorrel]

Is there a rep thing I can do or do I just close this

[restive river]

Thankyouu, i get to submit it now

[quick dome]

Nope just close

[vital sorrel]

.close

[devout snow]

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[stray flame]

Hi. I know that this is a math server but could anyone please just explain the derivation of the shrodinger wave equation (the one independent of time). Thank you.

[tawny junco]

oh god

should i be able to answer a physics question here

[stray flame]

Idk

[lusty sapphire]

short answer:
https://math.libretexts.org/Bookshelves/Differential_Equations/Differential_Equations_(Chasnov)/09%3A_Partial_Differential_Equations/9.08%3A_The_Schrodinger_Equation

[stuck meadow]

The Schrödinger equation is like a recipe for figuring out how particles behave in the quantum world. The time-independent version is like a recipe for a specific type of particle that doesn't change over time

It's derived by combining classical wave equations with some key quantum mechanical ideas (like the wave-particle duality) and then using math to put it all together!

i found this online

good way to put it lol

[lusty sapphire]

longer answer but still glosses over stuff
https://www.dalalinstitute.com/wp-content/uploads/sites/2/Books/A-Textbook-of-Physical-Chemistry-Volume-1/ATOPCV1-1-2-Derivation-of-Schrodinger-Wave-Equation.pdf

[stray flame]

Yup I'm failing my physics class

Can I ask you guys questions later?

Like when I'm studying

[quick dome]

Yup

[stuck meadow]

a piece of advice i’d give is just sit down before and after your doing homework and just visualize what your doing

think of the processes like your teaching it

[stray flame]

my physics is like really bad

I feel like I'm decent when it comes to bath

Math*

[stuck meadow]

it will reinforce what you know and if you don’t remember something you’ll know to go over it more

[stray flame]

But physics even basics idk

[stray flame]

I follow this for math

If you teach it to someone

Even better

Helps you remember it

[stuck meadow]

i recommend the feynman lectures

[stray flame]

Is it on yt?

[tawny junco]

that's the best way to self study

[stuck meadow]

you should try it for all your subjects

[stray flame]

Tru

[lusty sapphire]

best answer:
https://www.amazon.com/Quantum-Theory-Fields-1/dp/0521550017?crid=5DBZA3UIT24V&dib=eyJ2IjoiMSJ9.hNQlutyZuvwEqF48psjpsrYaJlSjDJnVbKANRhQO3ShubhiltAYxHWVYKWNSvciYC8PeH3r46g_QKpejUdh2y-3OP6UprIOL8xl3hQOVvv5V_swI12MAgbNCVZFzIxDLs_SkUyl7EtnOCf2JhIWzRWNAPx7dFJYdYrkD5wJ2epG4u9dFPu-Ik8Hfzzxq56eK37kGR1QD__78LO-DdhC21Z8HKlutnLLBdCnkcebJ8Jw.1NFOg9zj7oXcne20rLL6vYswDTGdsl-tw-iVyTbg8N4&dib_tag=se&keywords=quantum+field+theory+textbook&qid=1731394546&sprefix=quantum+field+theory+textboo%2Caps%2C173&sr=8-10

[stuck meadow]

it’s really helped me over the years

[stray flame]

Libgen👍

[lusty sapphire]

even better

[stuck meadow]

https://youtube.com/playlist?list=PLyQSN7X0ro23NUN9RYBP5xdBYoiv2_5y2&si=gb_KH6KO8VK6uirX

[stray flame]

Thanks

[stuck meadow]

you can watching something else if your practicing problems but he makes some great points and explains everything in a great way

you can do .close if your done and open a help help chat when you need anything else

[devout snow]

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[true sonnet]

is the anser 14

[rare merlin]

no

[true sonnet]

its 16

how to find it

[rare merlin]

yes

triangle QOR is an isosceles triangle

so angle Q = angle R for triangle QOR

[true sonnet]

yeah i know

so 180 - 96

divide 2?

[rare merlin]

yes

[true sonnet]

thats 42

[rare merlin]

angle Q of triangle PQR is 90

yes

[true sonnet]

how can u be sure its a semicircle

bcz of the o?

[rare merlin]

didn't the question say its a semi circle

[true sonnet]

no

oh wait

nvm lol

it says diameter

mb

thanks i got it now

[rare merlin]

np

[true sonnet]

.close

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[dusty sigil]

can someone help me see why cant i get the right ans of 29.49 - j11.09 please 🙏

i have tried countless of times

[devout snow]

@dusty sigil Has your question been resolved?

[dusty sigil]

<@&286206848099549185> help please 😭

[quick dome]

Hello @dusty sigil

I really don't understand

How you got from step 2 to 3

[dusty sigil]

i input the calulator

40/(4-3j) = 6.4+4.8j

@quick dome

[quick dome]

Don't fo that @dusty sigil

Your calculator is treating j as a number

Here it's a variable

Your calculator just rationalized the expression

[dusty sigil]

j is sqrt(-1) right?

i used the complex number mode

so they give me back answer in j as variable

@quick dome

[quick dome]

Oh

So j is complex number

[dusty sigil]

yes j is i

xD

[quick dome]

I didn't know that sorry

[dusty sigil]

no my bad

[quick dome]

Isn't it

4- 3j^3

?

@dusty sigil

Wouldn't that be 4+3j

[dusty sigil]

oh yeah oka thanks lex

.solve

.solved

[devout snow]

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[minor hollow]

one of the terms of (2pi+5)^n is 288000pi^8. What's the value of n?

This is a discrete math problem(i think)

[devout snow]

@minor hollow Has your question been resolved?

[left palm]

so you'll prob want to use the binomial theorem

[woven radish]

citrusmunch

[devout snow]

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[fast sequoia]

Help

[fast sequoia]

How i can evalute this?

[devout snow]

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[normal merlin]

I dont understand what im doing wrong I'm solving for Tank A
though they A = pi(3y/7 )^2

[devout snow]

@normal merlin Has your question been resolved?

[devout snow]

@normal merlin Has your question been resolved?

[devout snow]

@normal merlin Has your question been resolved?

[devout snow]

@normal merlin Has your question been resolved?

[somber jetty]

Can someone help me here?

[devout snow]

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[heady vault]

anyone know how to do this

[heady vault]

im lost

[devout snow]

@heady vault Has your question been resolved?

[heady vault]

.close

[devout snow]

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[raven wind]

Help pleeease

[deep heath]

use KCF

change the sign into multiplication and then flip the numerator and the denominator

[devout snow]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

@raven wind Has your question been resolved?

[lone sage]

uhm I’d divide the individual fractions first

whether u want to do long or synthetic division it’s up to u

[raven wind]

Bwahhh

The answers are like

All weird tho...

[deep heath]

can you please show your work?

[raven wind]

Inna sec yah

Alright SO

[raven wind]

Should I multiply 20 by 6?

Then do the whole

Find variables thing?

[raven wind]

Ima send my work page here in a sec

Augh nvm I got it

Please help ;~;

[devout snow]

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[errant sparrow]

how do i solve these?

[topaz beacon]

do you know how to integrate

[errant sparrow]

no

we didnt learn that yet

[topaz beacon]

thats fine

integrating is basically guessing anyway

lets look at a

what has a derivative of x?

[errant sparrow]

1?

[topaz beacon]

thats the derivative of x

im looking for derivative of what equals x

[errant sparrow]

wdym?

[topaz beacon]

what is a function such that when you take the derivative of it, you get x?

[errant sparrow]

x?

[topaz beacon]

if you take the derivative of x, do you get x?

[errant sparrow]

no? you get 1?

how would i find it?

[topaz beacon]

power rule states that if you have cx^n, the derivative is cnx^(n-1) right?

[errant sparrow]

yea

[topaz beacon]

ok, so we have our derivative is cnx^(n-1) = x

what is n?

note that x = x^1

[errant sparrow]

i dont get it..

[topaz beacon]

if you have x^(n-1) = x^(1), can you find n?

[errant sparrow]

2?

[topaz beacon]

yes

so now we have cnx^(n-1) = c(2)x^(2-1) = 2cx

we want 2cx to be x

we can pick c so that 2cx = x

do you know how to find c?

[errant sparrow]

whats c?

constant?

[topaz beacon]

yes

you can find what c is using algebra

[errant sparrow]

but isnt 2 the constnt because x^2 we bring the 2 to the front 2x^1?

[topaz beacon]

no

[errant sparrow]

then where did we get c from?

[topaz beacon]

if we have some number in front of a power of x, that is your c

[errant sparrow]

1?

[topaz beacon]

for example, if you have 3x^6, your c is 3

[errant sparrow]

yes

[topaz beacon]

we currently have the equation 2cx = x

how do you solve for c?

[errant sparrow]

you divide 2x

and get 1/2?

[errant sparrow]

where did we get this equation from tho?

[topaz beacon]

from derivative of cx^n = x

derivative of cx^n = cnx^(n-1)

we found that n=2

so we plug n=2 in

you get c(2)x^(2-1)

simplifying, we get 2cx^1 or just 2cx

[errant sparrow]

we get cx^n from power rule?

[topaz beacon]

yes, we are picking c and n to make power rule work out nicely

[errant sparrow]

and then c = 1/2?

[topaz beacon]

yes

so putting that all together, we get (1/2)x^2 has a derivative of x

[errant sparrow]

got it

[topaz beacon]

if you check using power rule, thats good

now we have the next term for part a

[errant sparrow]

so we just keep doing this for each term?

[topaz beacon]

ye

[errant sparrow]

what about the f(1)=2?

[topaz beacon]

lets look at a function like f(x) = 3x+5

what is f'(x)?

[errant sparrow]

3?

[topaz beacon]

yes

notice how constant terms disappear with no evidence

[errant sparrow]

yes

[topaz beacon]

if i told you f(x) was originally 3x+7, you wouldnt know the difference

but, if i gave you f(1) = 8, then you know for sure that f(x) = 3x+5

in other words, you have a very important constant +C

[errant sparrow]

would i sub in f(1)=2 into f(x) after i find it?

[topaz beacon]

when you learn integration, this is very common to miss

yes

once you have f(x), you need to plug in 1 and add a constant to make it 2