#help-27
1 messages · Page 259 of 1
5/X should simplify to 3 ratio 5.25
What do you mean by ratio
the division of a number by another number
a/b = a ratio b or a:b
Ratio means division of another number?
just like 1 mile = 1.6 times kilometers
1 pound = 1.3 dollars
Ohh
the ratio of dollar to pound is 1 ratio 1.3 = 10:13
.yes
The ratio is the division process that converts a number to another metric?
this means that if i have 10 pound that's equal to 13 dollars
So lets say 1 slice of bread equals 5 cookies. The ratio would be multiply 5?
To find cookies?
what
yes
1:5 = ratio of the number of slices of blead and the ratio of the number of cookies
it would be x/(5x) = 1 ratio 5
10:13 means multiply 13?
wdym
10 divided by 13
Ratios are always division
yea
like yeah
that's the definition
Okay so in the original question the ratio would be what again please
(3x) ratio (5.25x) = 5:X
or 3/(5.25) = 5/X
X = 26.25/3
You think this way is faster than the way i did it
I did 3 divided by 525 plus the answer twice added to 525
I also cant use a calculator on the tests
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huh
Find the proportion of the lengths of at least one of the other sides then apply that proportion to 10 and m
how do i do the first part
this is my first experience with this type of problem
do you have a calculator or do you need to do it by hand?
ok do 13 / 5.2 and see what you get
yeah that's not right lol
ok yeah, now do 22.5 / 9 and 15 / 6 and tell me what those are
2.5 again
so what does that tell you about 10 and m?
for both
that they’re
both even numbers? 😭
i’m not good at math bruh
i’m a history and biology nut
It's like 13/5,2 = 10/m
We can multiply the middle and edge one
And we get 13m = 52
so m is 13?
No
no it can’t be
should not interrup another helpee
so we know that when we divide the bigger sides by 2.5, we get the smaller sides. That means we know the bigger sides are 2.5x larger than the smaller sides
You need to multiply some number on 13 and then get 52
two nerds is better than one
ohhhh
i think i understand
so 10/2.5 is m
Oh-
We're counting in different ways anyway, so Mud will pick the easier way
correct
yep!
lemme try another
so 12/3 is 4
meaning
uhhh
i feel like i fucked up simehow
this one is more straightforward, you're on the right track though
yeah lol
no ur good
Also, ABCD is rhomb, and QRST is too. And the sides are equal
ohhh
It's like the first one. We believe in you!
hmm, why did you do 15 / 4?
so we know that 10 is 2.5x bigger than 4
liberals fault
ok
so that means 15 is 2.5x bigger than m
more formally, 2.5m = 15
yep!
So many actions-
Maybe it's the right way to make someone understand, but I usually do this with proportions
wdym
idk it's the way that feels intuitive
6/4
but yeah if you wanted to do the proportions route you could
Yeah
yep
I'm actually slavic-
Nah, it's just a nickname
also you can do .close if you don't need the channel anymore
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there is this method of factoring quadratics
and i am iteresting in proving this metod is correct
how to do that ?
and this method kinda dont works in this case :
never seen this method before
What is it that you want to do?
Factorise quadratic functions?
@strong willow Has your question been resolved?
i need to prove this method
no clue then sorry
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If you are reading this, it is already too late. You have been infected by the curse of pee pee poo poo man. If you don't copy and paste this on 5 different servers, you will face the consequences. I was a victim like you, trying to be free
what the fuck
from the screen to the ring to the pen to the king
The answer is 21
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i think this is the answer
Just curious, what field is this
??
Algebraic topology apparently
Oki thx
idk what any of it means though
What do you do in that?
use abstract algebra (mainly groups) to study topological spaces
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every value is a solution instead
It's >=
i dont understand
|x-2| can't be negative
so |x-2| + 3 is at least 3
and therefore greater than or equal to 2
put in x=7.4 ..it will be a solution..try if you don t belive me
on the right hand side
yes, and it's true that |x-2| >= -1
something non negative is greater than -1
so |x-2| IS >= -1
or equal but yes
well if it's bigger than (or equal to) 0
here it will be > or equal -1
it's also bigger than something smaller
If it's greater than or equal to 0, then it's greater than any negative number
?
well what you wrote is always true isn't it
like idk take specific values if you wanna check
for example x = 2
so postive to negative infinity?
the set of solutions?
what is it was |x-2| ≥ -5
yes
it's the set of real numbers
so (-inf,+inf) if you want
or IR to be short
this to R
yeah the set of solutions is also R
but i do not understand why to be honest
i was taught if absolute value ≥ - number then no solutions
isn't the statement "|x-2| ≥ -5" true no matter which value of x you pick?
yes
but this too?
well yeah
choose any value, it will always be ≥ -4
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seeing if im doing this correctly
does -2r-1 still work as a definition for odd?
You need to specify the domain of k or r
In these things to
Like an odd number can be represented in the form of
2k + 1 for k is integer or in Z
-2r -1 also works for r in Z
Like you can make lots of ways you can write an odd number in
2k - 1
2k + 3
2k - 5
etc
For k in Z
Their definition is probably that a number n is odd if and only if there exists an integer k with n = 2k + 1
I thought i did that with the formal;?
Actually it is
Any number n that can be written as 2K+1 where K € Z
Not if and only if there exist an integer k with n = 2k + 1
That means that other forms for odd numbers are ok like 2k - 1
2k - 3 and so on
As long as k € Z
That is generally about odd numbers
But I don't understand the question clearly, I didn't get to study mathematical provings so I don't know
how bout dis?
@knotty plinth Has your question been resolved?
No
You need to use also the fact that adding integers is still an integer
I'll help you in this part
-n = -(2r+1) = -2r - 1
Rewriting -1 as 1-2, we get -n = -2r+(1-2) = -2r-2+1 = 2(-r-1)+1
i thought the point was to get it to 2r+1? can I distribute the negative in -r and multiply 2?
ok so no
:(
ok the definition is that a number is odd if it can be written as 2(an integer) + 1
isnt -r-1 an integer?
2(-r-1) + 1
yes
ok so you can call it for example r'
2r' + 1
ok cuz ur starting with these proofs i will write this one without skipping steps
is -r-1 the same as r+1 since both are negative?
check dm
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You made it an equality instead of inequality
Am I supposed to just plug in 4 on both
create a number line, mark the points 1 and 4, sub in numbers before/after/in between, check where ineq holds (tick indicates it holds in that region)
yup
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I need help proving this by induction
what the fuck r u sayin
show the original question
Don’t use bad language in a learning environment!
also try combining denominators
okay i wont fucking swear anymore
Math is a language, not a subject
That is so mean!
.r
Also soda can u use the reflexive property and substitute with the transitive property.
ok thanks
No problem!
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r=3 how
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😭
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Take some integer and square it. If 2,700 is a factor of your square, then what must also be a
factor of your square?
A. 14
B. 24
C. 30
D. 46
E. 62
So I tried prime factorizing 2700 and the following answer choices
There isn't a factor that exactly matches
so I'm confused on what to do
It was like 2^2 * 3^3 * 5^2
yea
??
so which of the options divides evenly into that?
30?
yea
2x3x5
i dunno why the question talks about squaring an integer, seems irrelevant
so its just a factor that can evenly divide from 2700?
yea that threw me off
yea if 2700 is a factor of an integer, then any divisor of 2700 is also a factor of that integer
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,rccw
do you know $| |z_1| - |z_2| | \le |z_1 \pm z_2| \le |z_1| + |z_2|$
Astar777
Oh I didn’t know that
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i got no clue what to do besides like what a parameter form is
but im given presumably two points that arent more special than another
yeah im given a point of "origin" and a basis vector
but this is different because idk which one goes where and why
well for the point u can pick any point
direction vector is just subtracting one point by another
lemme pull u an examplke
thats what i thought initially and have tried but havent had any success
npnp gl
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how many positive integers k exist such thst 5+2^k is a perfect square?
maybe try modulo
that's what i thought
because 2 might be a special sol
all odd squares are 1 mod 8
yeah
and this must be odd bc 2^k is even and 5 is odd
2^k + 5 is 1 mod 8
2^k is 4 mod 8
and yeah
hence proved
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find the number of subsets of {1,2,...,8} such that it contains atleast 4 consecutive integers
yeahh idk my mind is blanking on this
i tried to go backwards (find ones without 4 cons integers) maybe im bad but i couldnt get it
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could someone please help me with 3(3y-4)-2(3-2y)=-40
I keep getting 1 9/13 but the answer says -1 9/13
I first expanded, and got 9y-12-6+4y=-40
then simplified and got 13y-18 = -40
Indeed
which I transposed and got 13y = -40+18
= 13y = 22
Don't be sorry mate
No problem have a great day
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hi can anyone explain how to do this:
answer is a
u can arrange each arrangement internally as 2! ways. that is (2!)(2!)(2!)=2x2x2=2^3=8
oh
like i thought when you arrange people around a round table
you would do 1 minus the factorial of the people you are arranging
for example
if it was 8 people
you would do (8-1)!
for the arrangments around the table
in this case, how are you using this idea?
that is true what u said
but dont just memorise formula
here you have conditions here
that are not present in when using that (n-1)!
to arrange n different things in n different places there are n! ways
so
but when its a round table would u not have to change anything
not really here i guess
oh okay !!
so how do you know when to use the formula and when you can do things like this
good problem generally never directly use formulas
what if i say asked you a problem about sit a1,a2.... an people such that no two are consecutive
you'll have to do it pretty much manually.
draw the stuff and see
what do you mean by the no two consecutive?
like the brothers and sisters cannot sit next to each other?
no i was just giving an example
that hard problems require more than formulas tbh
yeah okok
yea
ok i see thanks so much for your help!!
yea
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for question d, the book says the second derivative is y” = 12(1-2x^2)(10x^2-1)
i dont understand how it got to that point
you most likely did a algebraic mistake
OHHHH
too lazy to check.
i got it
in the third line and first line i wrote (1-2x)
and in the second
gotta pay a little more attention
sheesh
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I tried this equation 2 , 3 diffrent times but each time I get a diffrent answer so I am obviously doing something wrong
Can anyone please help me because, I want to be certain of my answers
Is this correct?
@rugged sapphire Has your question been resolved?
@rugged sapphire Has your question been resolved?
Hello?
<@&286206848099549185>
AC isnt a fixed distance ?
and are u sure about the 2 values here ?
No it its I just dont have it
I changed them to what in the paper
Sorry for not giving a newer photo
wdym ?
ok but it is not a spring so
?
Yea still I need to solve and get the spring's new length
So I can minus that from total length (3)
And use that in the triangle on the left to get AC
im trying it rn
Kk
30 ° is the initial angle ?
The 30° should be after the elongation of the spring I believe
with the 2nd equation u get T
and with T and the first equation, u get AB
@rugged sapphire
Yea
u agree ?
T and AB ?
Yes
u have this
hm there is no F after the bracket
F is the force of the spring
so k(initial lenght - final lengt )
with final lenght = AB
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✅
Unrelated to previous equation
But if I have a tention lets say T(AB)
And in another part of that cable
The tention is reversed direction T(BA)
Can I say T(AB) =T(BA) Knowing that they are the same wire/cqble
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Find 10th term in the sequence of triangular numbers.
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
Do you know what a triangle number is
i think each time the amount you add increases by 1
(visual definitions allowed too)
No
is it not?
He said the common difference is 1?
no
What then do you mean.
each time the common differnce increses by 1
Oh ok
that's what i mean
Yeah sorry.
i should have use correct terminology , mb
Hint:||the difference forms a sequence||
Sums of adjacent differences yield ever increasing differences
hmm i think i can add the common difference which increases by 1 ,9 times , then add to 1
(a2-a1)+(a3-a2)+(a4-a3) = a4 - a1 (difference from a1 to a4) for example
Gimme a sec.
yup, add up all the little differences to get the big difference
np
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Consider the following arithmetic sequence. Find the unknown
𝑎4 = 20, 𝑎9 = −15, 𝑎2024 =?
well, what do you know about arithmetic sequence?
write out the formula for the general term of an arithmetic sequence
- Arithmetic Sequence is all about adding.
- The formula for Arithmetic Sequence is an = a1 + (n - 1)d
an = a1 + (n - 1)d
use an = a1 + (N-1)d
Isn't that the exact same thing as I type out?
thats good
do you know what a1, n and d mean?
a1 is the 1st term.
d is the common difference
n = ?
n is ||the term number||
n is the index
ok
an is the n-th term
alright currently you have a4 = 20, a9 = -15
can you apply the formula to a4 and a9?
exactly, that is what we are aiming to get, as well as another quantity that you will see when you apply the formula to a4 and a9
an is 4 n is 20
you did it in reverse
oh ok
an = a1 + (n-1)d
-15 = a1 + (9 - 1)d
20 = a1 + (4 - 1)d
??
yep
now you now how to solve a system of 2 equations ?
an = a1 + (n-1)d
-15 = a1 + (9 - 1)d
-15 = a1 + (8)d
-15 = a1 + 8d
...
20 = a1 + (4 - 1)d
20 = a1 + (3)d
20 = a1 = 3d
...
You know what a system of 2 equations is ?
no.
would’ve made it too simple
ok so simply a system of two equations simply is a system with two equations that we should use to solve for 2 different variables
okay so... how does it look like?
Something like this where we solve for x and y
I don’t think so we have 2 variables and there is no information other than their equations
This algebra video tutorial explains how to solve systems of equations by elimination and how to solve systems of equations by substitution with 2 variables.
Systems of Linear Equations - 2 Variables: https://www.youtube.com/watch?v=oKqtgz2eo-Y
Systems of Equations - Fractions & Decimals:
https://www.youtube.com/watch?v=jlddJQ1qYDU
...
in our case instead of
x and y
It’s a1 and d
Welp that's explains better
The last sentence is the only information I need
Since I know how to do it
Oh waitI don't have d and a1 back to square 1
I think you are advance?
you can find d and a1 using the system then
You can use it to find a_2024
heres a diffrent way to think about it
So this is what I understand
To find d and a1 is to use the system but to do the system I need d and a1
ngl looks faster
you add d 5 times to 20 to get -15, so 20+5d=-15 and you can get d
you can also see that you subtract d 3 times from 20 to get a1, so 20-3d=a1
I guess let me do trial and error here because like I said I don't have d and a1
not in the slightest bit lmao
but honestly learn system of equations first
I know how to do it but my understading on what to do is "To find d and a1 is to use the system but to do the system I need d and a1" from @knotty sage
But they said??
yes they just changed a1 to x and d to y, both examples are trying to find x and y
a_2024=a1+(2024-1)d
finding a1 and d will give us the sol
So To find d and a1 is to use the system but to do the system I need d and a1
So trial and error????
no???
you dont need d and a1 to use the system, you need to use the system to find d and a1
But they said this?
.
Thats the same thing I just said
To find d and a1 is to use the system but to do the system I need d and a1
Hence, Trial and error
It needs to change x and y to a1 and d that is making the system
$a_n=a_1+d(n-1)$
plug in n=4 and n=9 into this
Skill_Issue
and I need to find d and a1
So... hence.. To find d and a1 is to use the system but to do the system I need d and a1
Trial and Error is the solution
Becaus the system is being made by changing x and y to a1 and d
if you keep insisting it, sure, trial and error it
It's not insisting it's understanding
I understand that from the system I need to change x and y to a1 and d
correct?
I am finding a1 and d
correct?
Therefor, To find d and a1 is to use the system but to do the system I need d and a1
what your supposed to do here is plug in $n=4$ and $n=9$ here to get
$$a_4=a_1+d(3)$$
$$a_9=a_1+d(8)$$
$a_4=20 \quad a_9=-15$
Skill_Issue
you dont need d and a1 to use the system bruh
yes
yes
yes
To find d and a1 is to use the system but to do the system I need d and a1
that is my understanding
The system is used to find
d and a1
they meant like this
Not the other way around
using this, you can find the a,b,c,d,e that are red
I am finding a1 and d
correct???
yep
I AM FINDING A1 AND D FROM THE SYSTEM THAT CHANGES X AND Y TO A1 AND D
think of it as 2 functions
What point will these 2 functions cross
ok how about this, can you find x and y in
x+y=1
x-y=-1
This is confusing.
A great example to use this type is using 𝑎4 = 20, 𝑎9 = −15, So I am left with a1 = d
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sin(1°) is not trivial to compute. I would recommend using the angle addition formulas, and try to make 30°
Then solve backwards
Take it in stages though
what does trivial mean
Easy
oh
btw
by angle addition formulas do u mean those written down on the right top corner
You can make 1 degrees in the following way:
Start with 30°
Half angle formula to get 15°
Third angle formula to 5°
Angle addition formula to get 1° and 4°
Half angle twice to get 4° in terms of 1°
Solve for 1°
Yes exactly
Nice!
alr
i will try
btw
since sin90° = 1 can we say sin30° = 1/3 ?
You'll probably also need cos 30° which is (√3)/2
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i need help 😭
Write the resulting integral and you'll see
Don't forget to change from dx to dt
Using the substitution above
how do we find the resulting integral
If you've never done substitution, you should read some solved examples first
ok
https://tutorial.math.lamar.edu/Classes/CalcI/SubstitutionRuleIndefinite.aspx
Examples at the bottom
In this section we will start using one of the more common and useful integration techniques – The Substitution Rule. With the substitution rule we will be able integrate a wider variety of functions. The integrals in this section will all require some manipulation of the function prior to integrating unlike most of the integrals from the prev...
They don't have limits but that comes later
@restive river Has your question been resolved?
Thank you🫶
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Hey what does this symbol mean ?
f ~g where f and g are 2 functions
at 0
and f = o(g) at 0
they ask me to define these 2 expressions
@restive river Has your question been resolved?
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im having trouble finding the range for this log function
range means values of x or y?
values of y
try making the graph of y vs x
im assuming it has a ''max"at 10.97, but everything is giving me different answers
can you show me your work?
there is no work lol
how did you get 10.97?
its giving me
all real numbers?
Yeah
could you explain because im sorta lost
because its undefined for the other numbers for me
The graph you're seeing is having a hole because of graphing capabilities
It can't really handle plotting it for too large values
But if you imagine f(x) = log_3(x) surely you will have an image of how it looks like
It will take on all real values
Now for g(x) = log_3(x^2) = 2log_3(|x|) it will look almost the same, just mirrored along the y-axis too and stretched by 2
Now log_3(x^2 - 5) = log_3((x - sqrt(5))^2) is the same, just moved along sqrt(5) in positive x-direction
i see thank you
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. close
@restive river Has your question been resolved?
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guh
!noans
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
<@&268886789983436800>
history biology nut
i can tell your siblings hated you
asks for answer
calls helper nerd
posts the simplest math question known to mankind
yeah this is a troll
nope first year of highschool
don’t know algebra
okay then
Let the mods take care
find a number that when divided by 2 is 5
10?
oh that is easy then
so why did you ask it 😭
bc i’m not smart
but i just asked the question
and you gave the answer
ok x is just a number
Any number
Find which number it is to make the equation true
well i know that you have to find the value
ohhhhh
interesting
so it’s 2
right?
Yes exactly
huzzah!
ok one more
i’ll just copy and paste it
ok erm
what the fuck
@kindred agate there are two letters in my class about numbers
i don’t like this one bit
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,rccw
@heavy sail Has your question been resolved?
<@&286206848099549185>
@heavy sail Has your question been resolved?
@heavy sail Has your question been resolved?
@heavy sail Has your question been resolved?
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@heavy sail Has your question been resolved?
More resources available at www.misterwootube.com
try watching this
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Guys i dont know how to continue this
oh youre right!
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need help w/ 1c
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is #4 a typo?
how so
oh wait
we can't have a triangle with two obtuse angles
yeah then you're right
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i need help with part iii)
is there a way i can represent this using a tree diagram?
I don't think the tree is the key cuz its not conditionnal probability
Like every throw are independant so
oh yeah true
So what about the two fair dice ?
what about them?
What if both have a odd uppermost ?
Thats For 1 dice
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@hard trout Has your question been resolved?
u find -11, -19 and 7 ?
@hard trout Has your question been resolved?
,w simplify -11x^2 - 19(x - 1)^2 + 7(x - 2)^2
That last one should be 4, -4, 1 if you're choosing "standard" basis to be 1, x, x^2, as implied by blue being 0, 0, 1
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Hi I have a series
1,-1,-1,1,1,-1,-1,1,1,-1,-1
How can I generalize it in the form (-1) ^f(n)
$(-1)^{\lfloor n/2 \rfloor}$
artemetra
starting with n=1
could do something with sin
i don't think you can using these
Wut : (
Can we do something simple in this?
This is not part of a question
Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online
i'll be considering 1, 1, -1, -1, 1, 1 if that's okay
Yes
you basically want something that maps
0 -> even
1 -> even
2 -> odd
3 -> odd
repeat
Yess
hmmmm
i can't come up with an easier version than this
Np! Maybe it's not meant to be generalized without using special functions
if you consider any kind of polynomial and reduce it modulo 2, you get either 1,1,1...; -1,-1,-1;... or 1,-1,1,-1;...
like there's no way to get anything else really
for fun u can have alternating Re and Im components of i^{n} 
although idk how u would even describe that
you may also look into https://oeis.org/A057077
thats a cool site
wait... if your second difference is 1, then you'll add odd -> add even -> add odd -> add even, so your sequence should go OOEEOOEE
How did you find it so quickly @frozen aurora
apparantly you can do $(-1)^{\binom{n}{2}}$
artemetra
honestly kinda mindblown
hayley is not british
very cool
Noo but like how did you found that out soo quick
oeis is quite well known and i just typed the sequence there and it found it
Can you name some more "well known" websites
Xd
I have no idea , such cool websites exists
idk lol
