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In this proof for proving the supremum, why can we say that M > 0?
Like what if epsilon is like 100, then M would be less than 0
pretty much just convention to assume epsilon is less than 1 in most cases
bring up the error and ask your teacher to correct it if you haven't been taught the convention
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Please
first combine the x's in individual terms if there is any square root
like write x*sqrt(x) as x^(3/2)
then use power rule
why tho
see i cant remember the rules we learned
like its just not clicking
do you have any yt vids you recommend?
so you can directly use power rule
$x\sqrt{x} = (\sqrt{x})^3$
Samuel
Only be careful to write the 3 outside because inside is not always true
$x\sqrt{x} \neq \sqrt{x^3}$
Samuel
Okay, i get that but what is that for?
the 5x sqrt x?
huh
What
oh nvm you did mention it is not true for every case
So, if i am solving the first problem, whats the first step i should take?
sry i did not notice
do this
but which part is that for lmao
it remains as the coefficients
isnt it 1
2
square ROOT
uh i got no clue
1/2
oh right
?
,rotate
thats pretty fkn dope ngl
Yes, $x\cdot\sqrt{x} = x^1 \cdot x^{\frac{1}{2}} = x^{1 + \frac{1}{2}} = x^{\frac{3}{2}}$
Alberto Z.
ok this might be a dumb question but how does 1+1/2 become 3/2
when u add fractions doesn't the denominator need to be the same?
Yes, you can write 1 as 2/2
I would highly recommend you to revise (very) basic stuff on fractions operation before studying derivatives (and later integrals)...
okay so, for 3x^5, what would be the process?
I know 3 * 5x^4 = 15x^4
im confused on how he gets 15x^4
What's 3*5?
its 15
but where is the 3 and the 5 coming from
3 is the coefficient right?
and 5 is the power
Alberto Z.
i give up
how does he make it seem so easy
like in class i feel like i understand
when i actually practice i cant
It is that easy, just need practice and you'll see it'll become almost a piece of cake
I don't have particular videos, I think that whatever video you find on YouTube by searching "power rule derivatives" or similar it will be fine
okay i got it now
lol that was much easier than i thought
makes more sense now
would this be over dx?
wait nvm my professor has 5 * 3/2x^3/2-1
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hi, im a little new to writing pde solvers, and i was just wondering if it's common to have loads of oscillation when solving the advection equation using crank-nicolson + gauss-seidel. i've read that cn should be unconditionally stable for advection, but for large enough time step or fine enough special discretization my simulation blows up. are there better schemes for advection, or is a smaller time step/ more diffusion the best solutions?
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no worries. pretty typical for harder questions like this to get cross posted and or posted on math stack exchange /overflow
fsfs
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I have a parameterization of a hyperbola and I need to rewrite this in some form that is recognizable as a hyperbola [i presume this would be X_n = acosh(alpha)-bcosh(beta)] but im not entirely sure how to go about it.
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I need help in these two questions
Part (b) for this one
LicensedDumbass
For the second one, I got 0 idea considering this homework is about induction and not combinatorics
I tried normal induction but that doesn't seem to go anywhere
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Using the distance formula, if I get sq rt( (300^2) + (160^2) )
Instead of actually doing 300x300 and 160x160, cant i just do 300+160 because im finding the root of them anyway
not in this case
since they aren't equivalent
think about a case like sqrt(2^2+2^2)
that would be sqrt(4+4)=sqrt(8)
if you square rooted both though
it would be sqrt(2+2)=sqrt(4)=2
$\sqrt{a^2 + b^2} \neq a + b$
knief
got it, thanks all
sorry if that was a dumb question i havent done math in a year lol
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is it asking me to write the answer as x=4, x=-4 or x=4,-4
maybe try "how to enter you answer"
i would guess
x=4, x=-4
or
x=4,x=-4
okay thanks
not sure if anyone could know though 🤷🏻♀️
if its wrong imma email cause they gotta be more clear
I'm "highly confident" it's these, as those are the equations 
4 points
you could plug in 1, 2, 3,4
probs easiest to find x ints and y int
and just one random
plug that in for x
x = 1 , x = -1 are also some good ones
x ints and y ints are going to be the easiest
then you just need one more
and it can be any number besides x=7/2
any point (x,y) that satisfies the function is an ordered pair
ye thats right
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im a bit confused on d) here, checking my old notes it should be 2^8 but i don't remember why
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@lucid swift Has your question been resolved?
d is definitely not 2^8
d should depend on n
okay idk why the answer key says 2^8 thank you
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applied linear alg, supposed to determine only by examination whether the set is linearly dependent or independent
just not really sure what im missing
can a linear combination of two of them combine to be the third?
if we have a set of vectors {v1, v2, v3} then k1v1 + k2v2 + k3v3 = 0 must mean that all 3 coefficients k1, k2, and k3 if they are linearly independent
ohhh because theres the 0 vector it can just be 0(3, 5, -1) + 1(0, 0, 0) + 0(-6, 5, 4) right
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yo
Ah
Add c to both sides
9+c+c = 15-c+c
The c and the -c cancel out
Then you subtract 9 from both sides
mmmmmmmm
fs gng
Bet
thanks gng
Anytime
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No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
if you plug in a certain value of x
the denominator/numerator goes zero
find that value
It says denominator must not equal zero
x+1 ≠0
x ≠ -1
I gave you a hint for the second one
no
show your work
show what you have done
yea but they need x≠ smth
that was for the first question
bro
!nososl
!nosol
.nosol
fuckj
this server has no solution policy
if you don't understand its always gonna be a problem
but the answer is not 1
just equate the algebraic expression you get to zero
in both numerator and denominator
no
nobody used chat gpt for math
for the second one
You have enough time to solve this before midnight without asking for someone else to give you the answers
You don't have to simplify?
thats the division problem
yea bc I don't know how to type in latex
(x+5) or (4x+20) ≠0
buddy
I was talking about x≠ part
calm down
how did you get the x neq 1
I told him its wrong
oh
just equate the algebraic part here to zero
yea
yep
huh
I'm talking about part A
no, bc you get 0/0 at a certain value of x
find that value of x
its negative
no
show your work
@wise compass Has your question been resolved?
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7.e
you can torture yourself by just expanding and rearranging if you wish
Okayy lemme see
After this?
should be fairly normal process
Isn't normal😭🙏🏻
notice u have column with (c - a) and 0 and (a - c)
ye
now do row operations
ur choices are limited so do what feels natural
keep in mind the statement u are trying to prove, knowing the answer is (a + b + c)(a - c)^2 should be a hint
What's do you suggest?
@jagged flare Has your question been resolved?
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Is it right that we can get extraneous or missing solutions only when applying not injective functions? Because on the Internet I see that they need to be invertible, i.e. bijective, for that not to happen but I fail to see how them being surjective(an extra condition for bijectiveness) is related to the issue
can you provide an example?
such as applying f(x) = x^2 to both sides of an equation. It is not injective because more than 1 initial value leads to 1 result, e.g. -2 and 2 to 4. So by doing this we might introduce extraneous solutions
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@chrome nymph Has your question been resolved?
You don't often see simple surjective functions so that's why it maybe isn't too obvious but suppose you have an equation with solutions x0 = 0, x1 = 2. Then by multiplying the equation by 1/x (which is not surjective over the whole R because 1/x is never 0) we loose the x0 solution. You can imagine it as x(x-2) = 0 and multiplying by 1/x gives us x-2=0 or only the x1 solution.
It's the missing solutions part
@chrome nymph Has your question been resolved?
Okay I reviewed the topic and so far have not found any functions other than division which when applied to whole equations introduce missing solutions
Can you think of any?
@chrome nymph Has your question been resolved?
yeah if u apply an injective function on both sides of the equation that's fine
doesn't have to be surjective
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null means the x's that are true for system Ax=0
why is the picture true?
i mean if x_1 is true for Ax=0 then it's in null(A), therefore also:
A^2x_1=0 => AAx_1=0 => A*0=0 => 0=0 => True
there x_1 in null(A^2)
yes?
yes
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this is a question about multiplying polynomials; i understand how to do them but in this particular question
[(8m+1)+9b]^2, the answer is 64m^2+16m+1+144mb+18b+81b^2. the math program i use for my algebra class shows me a walkthrough, so here is a screenshot of exactly where i am getting stuck.
i do not understand where the 16m is coming from. it has me square the first term (8m+1)^2, which to my understanding would just be 64m^2+1
Bro
(a+b)^2 = a^2 + b^2 +2ab
!!!!
Not a^2 + b^2
16m comes from 2ab : 2(8m)(1) = 16m
@violet yacht
yeah but in the screenshot you can see they havent solved that section yet
they still have 2(8m+1)(9b) which is the 2ab
Its already present in above eq also
look clearly again
First eq also has 2(8m+1)(9b)
They're seperate stuff!
Look properly
@violet yacht
@violet yacht
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yeah
yeah cause they havent solved that section yet so there shouldn't be a 16m just yet, but okay
why don't you solve all of it ?
just use(a+b)² where (8m+1) is a and 9b is b
solve you'll get what you are looking for
@violet yacht
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How do you find E(X+Y | Z)
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i mean, this is a bit of a vague question
could u give an example?
by linearity, we can split it as E(X | Z) + E(Y | Z)
but then like u'll have to find the conditional prob. density of X given Z
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Did I reach the correct answer? If I did not tell me which process was incorrect
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did you do the volume integral
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Can $p$ of form $4k + 1$ divide $2^n + 1$ for odd $n$.
Pluton
I dont see a clear contradiction yet it seems like it cant
As it seems that $4 \mid ord_p (2)$
Pluton
Ok it can but it doesnt for first few n
just prove by induction lol
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I am a bit confused by what he means by Event M being the event he has six fingers on his right hand and the probability P(M|R). Isn't that probability just 1 since we know he has six fingers?
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you have to find the probability between innocent men and the acutal culprit
probability can't be 1 cause he's not a criminal yet
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Believe u can use product rule and chain rule
or logarithmic differentiation
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Hello… We are dealing with moments and center of mass in Calculus right now. Does anyone have any clue why I got the moments wrong, but the center of mass correct? From my understanding, the only difference is that the center of mass is the moment over the sum of the masses. But evidently this is wrong.
sorry for the bad screenshot by the way. No discord on my other device
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<@&286206848099549185> Sorry for ping. It's been 15 minutes, and i'm pretty sure this is what I'm supposed to do
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The extrema
what’s that?
oh right, I can create the equations by vertices
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✅
could u explain how?
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Hello, I would like to know if the is is considered as an RREF
hi 

What's the definition of RREF?
I know, I’m just making sure whether this is one or not but I think it is
Thanks! 
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.(In particular, you don’t need the next leading 1 to appear in the very second column, in case that’s what you were wondering about
)
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I have this function which tell us the position at the time
How can i find the function that tell the distance form 0 to t?
can you be more specific on distance
Like integral of 0 to t but it's point idk how to solve it
?
sounds like you should post the original question
I dont have the original question
thats a shame
My brain question me
your brain is coming up with this question?
Yep
do you mean how long the curve is starting at t=0
Randomly and idk how can i solve it
How can u find distance from distance
Yep
thats called "arc length" and you can google it for a formula
I gotta inform you that this left me more confused than I started, I was thinking you came up with something that is different from arc length
youre taking an integral from 0 to t of how long the curve is
or from 0 to t of the length of the curve
"its point" does not describe this
youre not listening here
Im back from google it
I want to find the length of this thing
Yeah
what formula did you get from google?
This
thats unfortunate, google this instead
https://www.google.com/search?q=arc+length+of+curve+formula
...this google search isnt good either
Oh hell nah i search arc length integral and found this
I never know integral can be use like this
this formula is for finding how long a curve y = f(x) is from x=a to x=b
for example:
now if you zoom in on a small part, you get what is essentially a line
we can find how long a line is with pythagorean theorem
the blue length is dx
the green length is dy
and the length of the red bit (hypotenuse) is ds
so dx^2 + dy^2 = ds^2
so 1 + dy^2 / dx^2 = ds^2 / dx^2
so 1 + (dy/dx)^2 = (ds/dx)^2
so sqrt((1 + (dy/dx)^2) = ds/dx
so sqrt(1 + (dy/dx)^2) dx = ds
so ∫ sqrt(1 + (dy/dx)^2) dx = ∫ ds
now "∫ ds" would represent adding up all the ds parts together
since each ds represents a red bit of the curve,
adding up all the ds represents the total length of the curve
so the arc length is integral sqrt(1 + (dy/dx)^2) dx
in this case, the arc length is $\int_{-2}^2\sqrt{1+(2x)^2}\dd{x}$
mtt
(y = x^2 so dy/dx = 2x)
often the integrals you get cannot be simplified, this as it is is your 'best answer'
the integral is about 9.294
so the red curve is 9.294 units long
yep thats correct
Damn that's so scary
the good news is that after you simplify the derivatives, you dont have to do the integral
you leave the computer to find the length for you
I wanna ask something integral can be use to find the length and area under curve so can it do something more?
the integral simplifies to this
this is not a possible integral, some nonsense is involved to "solve" it
you would get this
or this
didnt realize the integral can be solved, whoops
the other one with the x^2 can also be solved too
It look a lot better
Wow tysm
I wonder how did we get hyperbolic trig here
But ill search it myself
Thx bro
np
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type .close or .solved
.solved
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how do you find the partial derivative of P respect to V
the answer gives this but doesnt differentiating both sides by dV make the right side 0
since nRT can be treated as a constant
but nRT is in the answer
i managed to get the second part but i cant get the first one
?
icannotdoanymorecauchy
@simple vessel u can express P as this, no?
oh i did it implicitly
lemme try
ok i got it
then why doesnt implicit work or am i doing smth wrong
lets see
d/dV (V-nb) = 1
blud
the answer is correct
but u forgot to rearrange it
to remove P
let me show ya
icannotdoanymorecauchy
yea i know
and substitute this
the rest is easy for u
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Whats the magic trick to this one? how does the given info help? I can rewrite it but not in any helpful way thus far
how can you rewrite it
@fervent ore
Sorry i have to step away i will reopen and ask for help soon when im back so sorry
Do i do .close?
@fervent ore Has your question been resolved?
ok back now sorry
i can rewrite ln(2)^-1 approx= 1.443 as 1/1.443 approx= ln(2). I can rewrite in the summation 2^(-k) as -k * ln(2)
Those are two things i can rewrite, is there some trick to set 2^-k equal to e^-1000, log both then get k alone and solve for k
if i round i get that to 1000 * 1.443 = 1443 and because we will keep adding numbers the equality wont hold but they are so small that increasing it to 1444 should make it right?
Is this a proper way of solving it?
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I have a question on Claire'ts theorem , as the function 1/ (x-y) is discontinuous
what does the thm state again
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Can someone help me answer this question
nah
lmk when it gets to $30
If you get all of the remaining 7 points in that question I'll give you $20
And if you help me with another one $30
Final offer and only if the answers right I think this is a tricky question
I was already wrong for #2 and #3
so you need b, c, and d
^ I can vouch
Is this even the right channel for finance?
Starting to wonder whether this request is a bit different than typical math
I think that people here could help you
But giving you answers is not what we do here
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
It’s a rule of this server my friend
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could someone explain what is actually happening in this proof i dont understand the n+1 or the 1/2
Any real number that's less than M0 should not be an upper bound, so they chose to subtract 1/2 from M0
The n + 1 is basically taking the n you found from here, you know that adding 1 to any natural number gives you a natural number, but then you know both that (n + 1) is a natural number, and that it's greater than M0, the supposed upper bound of the naturals
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can some1 explain this? I understand substituting and i've done u substitution problems before but i don't understand how they even get to the 1st step?
Maybe they're doing something completely diff idk.
I just learned integration by parts and that doesnt seem applicable here either?
multiply and divide by 3
it creates the 1/3 outside
then we find du in the numerator exactly
wait so dx = 1/3 * du * 1/(x^2 + 5) so when we sub dx with du we get 1 in the nominator and a 1/3 outside?
u = x^3 +15x+ 8
then du = 3x^2 + 15
say num = x^2 +5 is the numerato
so 3 num = du
yeah and then we divide over like you said to get dx expressed with du right?
and (1/3) (3 num) = num
to get du for the sub, yea
i mean i guess really we uant a dx here too
ok cool and the middle step is that just rewriting it as u^-(4/3) which gives
yeah prob
do i have to memorize the power rule for integrals in the next step?
yes
its not too crazy hopefully
just work out a derivative
youll obtain the rule backwards
how would one do that?
take the deriv of x^n
yea
the integral will be one higher so you divide by n+1 and you will remove -1 from the xponent so you also have n+1 there
you want that power that comes down to get eated
so we figure to start with x^n/n
this gives x^(n-1) as deriv
now reverse the action
makes sense

my brain has been kinda exploding with rules these days for an upcoming test, so many new things, polynomial division, taylor polynomial formula, rules for when raising constant to X and differentiating/integrating, integrating by parts formula, geometric series infinite/finite, lagrange multiplier, implicit differentiation, quotient rule, Rational root theorem
but i guess thats part of learning this, assembling a toolbox of all of em. sadly no formula sheet is allowed but that will just make practice harder 🙂
just dont leave urself hanging i always feel like
if you really dont think you understand or believe something then try to convince yourself
then you can develop intuition to replace rote memory
thats my opinion at least
yes
thx for the support, have yourself a lovely rest of ur night or whatever time it is for you ❤️
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if each edge of the cube increases by 2 cm, the volume will increase by 98 cm'3. what is the length of the edge of the cube
Please don't occupy multiple help channels.
@runic thicket Has your question been resolved?
let the side lenght of each side be x.
So volume = x^3
now AQT (x+2)^3 = x^3 + 98
,w (x+2)^3 = x^3 + 98
so x = 3
what is aqt
hey man how does the x+2 and x3 98 whatever get -5 and 3 i really need to know because i need the full process of the problem
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am i correct im so bamboozled LOL is it talking about the dotted line cuz if its talking about the actual angle in the red angle thats obv not 330
it has to be A none of them would be 330 if its talking about inside the red lines
it is talking about the dotted line
how many radians make up a full rotation?
2pi
so then how many rotations would 3pi radians result in?
answer A

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where does the 2 come from?
aint the x^2 isolated within cos
chain rule
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Is it safe to assume that this is the line integral of f(z) on a piecewise smooth curve gamma?
beause the only way I can think of showing this
is by parametrizing gamma and then using the fact we can factor c out of a real valued integral I believe
Is there an easier way to go about these rather than parametrizing gamma and getting real valued functions and then applying laws on on the real valued functions and then converting it back to gamma?
This isn't a complex analysis course so she isn't expecting a rigorous proof
for example if gamma isn't assumed to be piece-wise smooth how would I go about this?
yeah im getting stuck from using my original plan
@vivid estuary Has your question been resolved?
this is the way to go imo
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Okay so, I’m wrong? 😢
My work is on the right picture
Don’t take me step-by-step, just write it out step-by-step if possible.
you should be right i think
I believe I used the right formula
The numbers I got seem a little bit over what I should be getting, if I’m siding with it being wrong.
yeah but you rounded it properly so it's still right...try asking your teacher abt it
Alright bet
I have another one, I’m not sure if I’m doing it correctly.
Here I got SinB=0.6, what do I do afterwards?
I was looking for angle B
Nvm nvm
I remember now, oops.
I was supposed to use Sin^-1
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claim
yeah I think I am getting somewhere
but I got stuck on the last line
the first part is a(integral of f(z) on gamma)
the second part with the b i’m not sure
somehow I need to get (a + ib)(integral of f(z) on gamma)
Im assuming the second part can be represented as bi(integral of f(z) on gamma) somehow
and then I'd be able to factor out a + ib
WAIT I SEE IT
factor out an i on the second part
you get -1/i
let -1 = i^2
you get i
and then it becomes bi(integral f(z))
ok I believe I got it
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Given a conical frustum with known the "cross-sectional area" (or idk how its called -> see picture; aka area from the trapezoid) is it possible to get the volume of the conical frustum without knowing other values?
A conical frustum is a frustum created by slicing the top off a cone (with the cut made parallel to the base). For a right circular cone, let s be the slant height and R_1 and R_2 the base and top radii. Then s=sqrt((R_1-R_2)^2+h^2). (1) The surface area, not including the top and bottom circles, is A = pi(R_1+R_2)s (2) = pi(R_1+R_2)sq...
if you know r, R, and h it is possible to find the volume
if you only know the area of the yellow trapezium then it isn't
okay, thank you
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✅
Is it also not possible if you know h, ((r + R) / 2) and the "cross-sectional area"
well the cross sectional area is h * (r + R)/2
I'm pretty sure you need 3 independent pieces of information
where you can't say find the "cross-sectional area" from the other 2 pieces of information
okay thank you. I am trying to proof the "keplersche Fassregel" so Simpsonsrule but rotating. But there is only known y0, y1, y2, x2, x0.
I made: A_trapezoid = y_1 * (x_2 - x_0) and A_parallelogram = 0,5 * (y_0 + y_2) * (x_2 - x_0) - A_trapezoid
But now I am struggeling with getting the volumina
@viral oxide Has your question been resolved?
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@viral oxide Has your question been resolved?
@viral oxide Has your question been resolved?
@viral oxide Has your question been resolved?
@viral oxide Has your question been resolved?
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Scope is highschool math if that matters
Consider the Bernstein polynomial $B_{n,k}(t)$ of degree n and order k that is defined by $B_{n,k}(t)= ^{n}C_{k} t^{k}(1-t)^{n-k}
part (1) Find the sum of all $B_{n,k}$ where k varies on [0,n] (i got = 1)
part2) (where im stuck)
Dootud
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
part2 asks
Show that for $r \leq k \leq n$, $\frac{^{k}C_{r}}{^{n}C_{r}}B_{n,k}(t) = ^{n-r}C_{k-r}t^{k}(1-t)^{n-k}$
Dootud
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Hi guys. Can someone verify my answer to correct value? i think there is mismatch in my calculations
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Someone help me I don’t know how I’m supposed to calculate either rates
HELP
MY FRIENDS THING
Anyways…
I need help with calculating for both rates I have no idea how to do it when it should be something so simple😭
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@scenic pike Has your question been resolved?
@scenic pike Has your question been resolved?
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What's the answer to 2(-2)+1/-2+1? is it (3) or (-3.5)? i used calculator but it said (-3.5) but i tried solving it manually and i keep getting (3)...
f(-2) = 2(-2) + 1/(-2)+1
f(-2) = -4 + 1 / -1
f(-2) = -3 / -1
f(-2) = 3
is it 1/(-2+1) or 1/-2 + 1
1/-2 + 1
can u show the f(x) ? :)
cuz 1/-2 + 1 and 1/(-2+1) are 2 different things
2x + 1 / x + 1
with any brackets or just like that?
i'm supposed to graph a rational function but i can't seem to point it correctly without table of values
just as it is
$$\frac{2x+1}{x+1}?$$
JustToPro
yess
write it as (2x+1)/(x+1) next time
what ur trying to type is read as
$$2x + \frac{1}{x} + 1$$
JustToPro
probably how the calculator read it as well , so thats why 3.5
OHH no wonder i'm overthinking, thanks so much !
i will close now, thx for ur help i gotta watch my syntax now
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for 10. are the numbers 16,8,0,0? just need someone to check
@deep gale Has your question been resolved?
<@&286206848099549185>
I'm assuming they want the common ratio of the GP to not be 0
yes
there has to be another solution, ok let me try
a, a + d, a + 2d, (a + 2d)^2/(a + d)
,w a + (a + 2d)^2 / (a + d) = 16, a + d + a + 2d = 8
ah so if you choose a = -2, d = 4 instead
you get -2, 2, 6, 18
which must be the intended solution
I suspect you divided something in the quadratic instead of factoring properly
okay so your attempt that ends with $16r - a_1 r^4 + 16r^2 - a_1 r^5 = 8$ is the most promising I think
higher's secret twin brother
then you haven't used the fact that the 1st, 2nd, 3rd terms are in AP
so what would my 2 equations be?
AH the problem is that you've misunderstood the question
the first three are in AP and the last three are in GP
so you can't say that $a_1 + a_1 r^3 = 16$
higher's secret twin brother
if you don't mind going along with this method
cause the last 3 terms are in GP
you know the common ratio is (a + 2d)/(a + d)
so the 4th term has to be (a + 2d)/(a + d) * (a + 2d)
so from (a + d) + (a + 2d) = 8 you can replace a with (8 - 3d)/2 for example
now sub that into a + (a + 2d)^2 / (a + d) = 16
yep!
now multiply everything by 4 - 3/2 d + d = 4 - d/2
and it's a quadratic
@deep gale
yes, that's what i'm doing rn
i was trying to solve for another problem while you were gone and got stuck again
okok
careful
(a + b)^2 is not a^2 + b^2
so instead of doing that, expand $(4 + d/2)^2$
wait i messed up already?
oh yeah and you also didn't multiply by 4 - 3/2 d + d on the right
for some reason you just multiplied by 4 - 3/2 d
hold on
nono but i multiplied 16 to 4-3/2 d to it
oh wait that's correct sorry
this is the other issue then
and i got 64-24d
you should be multiplying 16 by 4- d/2
why 4 - d/2 and not 4 - 3/2 d