#help-27

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@restive river Has your question been resolved?

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urban aurora
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In this proof for proving the supremum, why can we say that M > 0?
Like what if epsilon is like 100, then M would be less than 0

supple knot
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bring up the error and ask your teacher to correct it if you haven't been taught the convention

urban aurora
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Fair enough thanks

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cold sand
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Please

devout snowBOT
cold sand
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help with derivatives

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im so lost.

twin thunder
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first combine the x's in individual terms if there is any square root

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like write x*sqrt(x) as x^(3/2)

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then use power rule

cold sand
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why tho

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see i cant remember the rules we learned

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like its just not clicking

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do you have any yt vids you recommend?

twin thunder
eager nova
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Just be careful on where u raise to the third power

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U gotta do outside the sqrt

cold sand
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im so lost

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im cooked

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F on my exam tmr

eager nova
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$x\sqrt{x} = (\sqrt{x})^3$

woven radishBOT
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Samuel

eager nova
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Only be careful to write the 3 outside because inside is not always true

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$x\sqrt{x} \neq \sqrt{x^3}$

woven radishBOT
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Samuel

cold sand
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the 5x sqrt x?

twin thunder
eager nova
twin thunder
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oh nvm you did mention it is not true for every case

cold sand
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So, if i am solving the first problem, whats the first step i should take?

twin thunder
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sry i did not notice

cold sand
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do i take the derivative of both 3x^5 and -5xsqrtx?

twin thunder
cold sand
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but which part is that for lmao

twin thunder
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the square root part

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only that term

cold sand
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okay what happens to the 5?

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Where does the ^3 come from?

twin thunder
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it remains as the coefficients

cold sand
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oh brother i am cooked

twin thunder
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ok calm down

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what is the power of x?

cold sand
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isnt it 1

twin thunder
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yeah

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and what is the power of sqare root of x?

cold sand
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2

twin thunder
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square ROOT

cold sand
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uh i got no clue

twin thunder
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1/2

cold sand
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oh right

twin thunder
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so now we can write x√x as x^1 * x^(1/2)

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clear?

cold sand
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?

cold sand
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Woops wrong orient

mystic scarab
woven radishBOT
cold sand
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thats pretty fkn dope ngl

mystic scarab
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Yes, $x\cdot\sqrt{x} = x^1 \cdot x^{\frac{1}{2}} = x^{1 + \frac{1}{2}} = x^{\frac{3}{2}}$

woven radishBOT
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Alberto Z.

cold sand
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ok this might be a dumb question but how does 1+1/2 become 3/2

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when u add fractions doesn't the denominator need to be the same?

mystic scarab
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Yes, you can write 1 as 2/2

cold sand
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ohh i see

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okay

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makes sense

mystic scarab
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I would highly recommend you to revise (very) basic stuff on fractions operation before studying derivatives (and later integrals)...

cold sand
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i have an exam tmr on derivatives

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lmao

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i hate college

cold sand
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I know 3 * 5x^4 = 15x^4

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im confused on how he gets 15x^4

mystic scarab
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What's 3*5?

cold sand
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its 15

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but where is the 3 and the 5 coming from

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3 is the coefficient right?

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and 5 is the power

mystic scarab
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Yes

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You should revise this: $$\frac{d}{dx} \left(x^a\right) = a\cdot x^{a-1}$$

woven radishBOT
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Alberto Z.

cold sand
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i give up

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how does he make it seem so easy

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like in class i feel like i understand

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when i actually practice i cant

mystic scarab
cold sand
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do you have any vids for me to watch?

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that show similar problem sets?

mystic scarab
cold sand
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lol that was much easier than i thought

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makes more sense now

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would this be over dx?

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wait nvm my professor has 5 * 3/2x^3/2-1

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pure blaze
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hi, im a little new to writing pde solvers, and i was just wondering if it's common to have loads of oscillation when solving the advection equation using crank-nicolson + gauss-seidel. i've read that cn should be unconditionally stable for advection, but for large enough time step or fine enough special discretization my simulation blows up. are there better schemes for advection, or is a smaller time step/ more diffusion the best solutions?

supple knot
pure blaze
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mb, i just joined and dont know the question asking proccess yet

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ty!

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supple knot
pure blaze
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fsfs

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ashen leaf
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I have a parameterization of a hyperbola and I need to rewrite this in some form that is recognizable as a hyperbola [i presume this would be X_n = acosh(alpha)-bcosh(beta)] but im not entirely sure how to go about it.

ashen leaf
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patent birch
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I need help in these two questions

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patent birch
patent birch
woven radishBOT
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LicensedDumbass

patent birch
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For the second one, I got 0 idea considering this homework is about induction and not combinatorics

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I tried normal induction but that doesn't seem to go anywhere

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@patent birch Has your question been resolved?

patent birch
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<@&286206848099549185>

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raw timber
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Using the distance formula, if I get sq rt( (300^2) + (160^2) )

raw timber
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Instead of actually doing 300x300 and 160x160, cant i just do 300+160 because im finding the root of them anyway

solid hull
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since they aren't equivalent

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think about a case like sqrt(2^2+2^2)

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that would be sqrt(4+4)=sqrt(8)

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if you square rooted both though

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it would be sqrt(2+2)=sqrt(4)=2

misty crest
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$\sqrt{a^2 + b^2} \neq a + b$

woven radishBOT
raw timber
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got it, thanks all

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sorry if that was a dumb question i havent done math in a year lol

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violet canyon
devout snowBOT
violet canyon
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is it asking me to write the answer as x=4, x=-4 or x=4,-4

misty crest
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maybe try "how to enter you answer"

violet canyon
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funny

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it dosent tell

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it just showes how to punch in numbers

versed vault
uncut crow
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i would guess
x=4, x=-4
or
x=4,x=-4

violet canyon
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okay thanks

uncut crow
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not sure if anyone could know though 🤷🏻‍♀️

violet canyon
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if its wrong imma email cause they gotta be more clear

upper schooner
violet canyon
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how would i find order pairs

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would it just be from graphinh

versed vault
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4 points

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you could plug in 1, 2, 3,4

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probs easiest to find x ints and y int

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and just one random

violet canyon
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plug that in for x

misty crest
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you plug anything in for x

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pick easy ones

edgy roost
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Just find some arbitrary values for x

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x = 0 is a good one

versed vault
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find x ints and find y int

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and then just plug in something like 1

edgy roost
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x = 1 , x = -1 are also some good ones

versed vault
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x ints and y ints are going to be the easiest

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then you just need one more

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and it can be any number besides x=7/2

violet canyon
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so it could be (0,15/7)

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oh nvm thats the y interxcempt

versed vault
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yes thats an ordered pair

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y intercept is an ordered pair

opaque haven
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any point (x,y) that satisfies the function is an ordered pair

violet canyon
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(1,9/5)

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okay

versed vault
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yes

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now find easy points

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for x intercept

violet canyon
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so i couldnt use those?

versed vault
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ye thats right

violet canyon
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okay thank u

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lucid swift
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im a bit confused on d) here, checking my old notes it should be 2^8 but i don't remember why

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@lucid swift Has your question been resolved?

supple knot
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d should depend on n

lucid swift
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mint kettle
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applied linear alg, supposed to determine only by examination whether the set is linearly dependent or independent

mint kettle
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just not really sure what im missing

misty crest
acoustic leaf
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if we have a set of vectors {v1, v2, v3} then k1v1 + k2v2 + k3v3 = 0 must mean that all 3 coefficients k1, k2, and k3 if they are linearly independent

mint kettle
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ohhh because theres the 0 vector it can just be 0(3, 5, -1) + 1(0, 0, 0) + 0(-6, 5, 4) right

acoustic leaf
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yes

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that means every set with the 0 vector is automatically linearly dependent

mint kettle
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that's right okay, silly question haha but thank you

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raw fog
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yo

devout snowBOT
raw fog
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i j want to know how my professor went from 9+c=15-c

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to 2c=6

timid valley
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Ah

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Add c to both sides

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9+c+c = 15-c+c

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The c and the -c cancel out

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Then you subtract 9 from both sides

raw fog
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so c+c after will j convert to 2c

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right

timid valley
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Yessir

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So you get 9 + 2c = 15

raw fog
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mmmmmmmm

timid valley
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To solve for c, you wanna keep 2c on its own

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I'm sure you know how to cook next

raw fog
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fs gng

timid valley
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Bet

raw fog
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thanks gng

timid valley
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Anytime

raw fog
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hope ya night or day goes well gng

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#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

fresh mason
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if x = -1, then the denominator will be 0

snow raptor
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if you plug in a certain value of x

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the denominator/numerator goes zero

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find that value

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It says denominator must not equal zero

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x+1 ≠0

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x ≠ -1

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I gave you a hint for the second one

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no

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show your work

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show what you have done

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yea but they need x≠ smth

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that was for the first question

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bro

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!nososl

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!nosol

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.nosol

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fuckj

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this server has no solution policy

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if you don't understand its always gonna be a problem

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but the answer is not 1

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just equate the algebraic expression you get to zero

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in both numerator and denominator

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no

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nobody used chat gpt for math

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for the second one

twin stump
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You have enough time to solve this before midnight without asking for someone else to give you the answers

twin stump
snow raptor
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thats the division problem

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yea bc I don't know how to type in latex

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(x+5) or (4x+20) ≠0

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buddy

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I was talking about x≠ part

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calm down

twin stump
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how did you get the x neq 1

snow raptor
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I told him its wrong

twin stump
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oh

snow raptor
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hmm

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then just sleep

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like wake up at 6 am or smth

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ahh

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wdym

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bruh

snow raptor
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yea

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yep

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huh

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I'm talking about part A

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no, bc you get 0/0 at a certain value of x

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find that value of x

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its negative

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no

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show your work

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jagged flare
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vast drift
jagged flare
#

I don't want to torture myself...

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Pls help ༎ຶ⁠‿⁠༎ຶ

vast drift
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it doesnt look too bad

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i think 10 minutes of suffering will be enough 🫠

dense lynx
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subtract columns 2, 3 from 1

jagged flare
#

Okayy lemme see

jagged flare
dense lynx
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should be fairly normal process

jagged flare
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Isn't normal😭🙏🏻

dense lynx
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notice u have column with (c - a) and 0 and (a - c)

jagged flare
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Yeah and I took them common too

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After that I'm left with

dense lynx
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ye

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now do row operations

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ur choices are limited so do what feels natural

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keep in mind the statement u are trying to prove, knowing the answer is (a + b + c)(a - c)^2 should be a hint

jagged flare
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What's do you suggest?

dense lynx
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i am saying think on the problem lol

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take at most 5 min and see

jagged flare
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Okayy

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I'll be right back

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Yeahh brooo got itt

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Thank youu soooo muchhh

dense lynx
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o nice

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yw 👍

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chrome nymph
#

Is it right that we can get extraneous or missing solutions only when applying not injective functions? Because on the Internet I see that they need to be invertible, i.e. bijective, for that not to happen but I fail to see how them being surjective(an extra condition for bijectiveness) is related to the issue

wheat pawn
#

can you provide an example?

chrome nymph
# wheat pawn can you provide an example?

such as applying f(x) = x^2 to both sides of an equation. It is not injective because more than 1 initial value leads to 1 result, e.g. -2 and 2 to 4. So by doing this we might introduce extraneous solutions

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@chrome nymph Has your question been resolved?

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@chrome nymph Has your question been resolved?

serene lance
#

It's the missing solutions part

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@chrome nymph Has your question been resolved?

chrome nymph
#

Okay I reviewed the topic and so far have not found any functions other than division which when applied to whole equations introduce missing solutions

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Can you think of any?

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#

@chrome nymph Has your question been resolved?

crude wasp
#

doesn't have to be surjective

chrome nymph
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Thanks for help

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lost crag
#

null means the x's that are true for system Ax=0

why is the picture true?

lost crag
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as in
AAx=0

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oh

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i see it

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AAx=0 => A0_v=0 => 0=0

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yes?

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0_v is the zero vector

acoustic leaf
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the implication is not in the correct order there

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but that's the general idea

lost crag
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i mean if x_1 is true for Ax=0 then it's in null(A), therefore also:

A^2x_1=0 => AAx_1=0 => A*0=0 => 0=0 => True

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there x_1 in null(A^2)

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yes?

acoustic leaf
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yes

lost crag
#

ty

#

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violet yacht
#

this is a question about multiplying polynomials; i understand how to do them but in this particular question
[(8m+1)+9b]^2, the answer is 64m^2+16m+1+144mb+18b+81b^2. the math program i use for my algebra class shows me a walkthrough, so here is a screenshot of exactly where i am getting stuck.
i do not understand where the 16m is coming from. it has me square the first term (8m+1)^2, which to my understanding would just be 64m^2+1

real socket
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(a+b)^2 = a^2 + b^2 +2ab

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!!!!

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Not a^2 + b^2

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16m comes from 2ab : 2(8m)(1) = 16m

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@violet yacht

violet yacht
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yeah but in the screenshot you can see they havent solved that section yet

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they still have 2(8m+1)(9b) which is the 2ab

real socket
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Its already present in above eq also

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look clearly again

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First eq also has 2(8m+1)(9b)

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They're seperate stuff!

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Look properly

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@violet yacht

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@violet yacht

violet yacht
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alright

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real socket
#

@violet yacht

real socket
violet yacht
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yeah cause they havent solved that section yet so there shouldn't be a 16m just yet, but okay

restive river
#

why don't you solve all of it ?

#

just use(a+b)² where (8m+1) is a and 9b is b

#

solve you'll get what you are looking for

#

@violet yacht

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restive river
#

How do you find E(X+Y | Z)

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crude wasp
#

could u give an example?

crude wasp
#

but then like u'll have to find the conditional prob. density of X given Z

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sacred isle
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Did I reach the correct answer? If I did not tell me which process was incorrect

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robust drift
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robust drift
#

Could someone help w number 2

#

Idk how to find a

supple knot
#

did you do the volume integral

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placid narwhal
#

Can $p$ of form $4k + 1$ divide $2^n + 1$ for odd $n$.

woven radishBOT
#

Pluton

placid narwhal
#

I dont see a clear contradiction yet it seems like it cant

#

As it seems that $4 \mid ord_p (2)$

woven radishBOT
#

Pluton

placid narwhal
#

Ok it can but it doesnt for first few n

restive river
#

just prove by induction lol

placid narwhal
#

n = 45

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tranquil cairn
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tranquil cairn
#

I am a bit confused by what he means by Event M being the event he has six fingers on his right hand and the probability P(M|R). Isn't that probability just 1 since we know he has six fingers?

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tranquil cairn
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<@&286206848099549185>

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tranquil cairn
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<@&286206848099549185>

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restive river
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probability can't be 1 cause he's not a criminal yet

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inner ibex
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inner ibex
#

Is there any way of differentiating this without expanding

#

The brackets

lethal pollen
cold bone
#

or logarithmic differentiation

inner ibex
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desert copper
#

Hello… We are dealing with moments and center of mass in Calculus right now. Does anyone have any clue why I got the moments wrong, but the center of mass correct? From my understanding, the only difference is that the center of mass is the moment over the sum of the masses. But evidently this is wrong.

desert copper
#

sorry for the bad screenshot by the way. No discord on my other device

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desert copper
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<@&286206848099549185> Sorry for ping. It's been 15 minutes, and i'm pretty sure this is what I'm supposed to do

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frigid zodiac
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trim marsh
#

The extrema

frigid zodiac
trim marsh
#

So x=-2

#

The vertices

frigid zodiac
#

oh right, I can create the equations by vertices

trim marsh
#

I mean you clearly see f(-2) + g(-2) = 0

#

-2 + 2 = 0

frigid zodiac
#

.close

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frigid zodiac
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.reopen

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frigid zodiac
trim marsh
#

Look at the output values for x=-2

#

Cant you see they are symmetrical

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thorn timber
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thorn timber
#

How does one prove this identity?

#

nvm I got it

#

.close

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wild badge
#

Hello, I would like to know if the is is considered as an RREF

wild badge
uncut crow
#

hi waves

wild badge
mystic scarab
wild badge
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Thanks! Foxy_Heart

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upper schooner
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little gate
#

I have this function which tell us the position at the time

little gate
#

How can i find the function that tell the distance form 0 to t?

tender cobalt
#

can you be more specific on distance

little gate
#

Like integral of 0 to t but it's point idk how to solve it

tame jackal
#

?

tender cobalt
#

sounds like you should post the original question

little gate
#

I dont have the original question

tender cobalt
#

thats a shame

little gate
#

My brain question me

tender cobalt
#

your brain is coming up with this question?

little gate
#

Yep

tender cobalt
#

do you mean how long the curve is starting at t=0

little gate
#

Randomly and idk how can i solve it

tame jackal
#

How can u find distance from distance

tender cobalt
#

thats called "arc length" and you can google it for a formula

little gate
#

Oh

#

My bad maybe im not good at english

tender cobalt
#

youre taking an integral from 0 to t of how long the curve is

#

or from 0 to t of the length of the curve

#

"its point" does not describe this

little gate
#

The problem is

#

This is how it look like

tender cobalt
#

youre not listening here

little gate
#

Im back from google it

little gate
tender cobalt
#

yes you said that

#

are you listening to me?

little gate
#

Yeah

tender cobalt
#

what formula did you get from google?

little gate
tender cobalt
#

...this google search isnt good either

little gate
#

Oh hell nah i search arc length integral and found this

#

I never know integral can be use like this

tender cobalt
#

yes very mindblowing

#

you want to see why that is?

little gate
#

Yeo

#

Yep

tender cobalt
#

for example:

#

now if you zoom in on a small part, you get what is essentially a line

#

we can find how long a line is with pythagorean theorem

#

the blue length is dx
the green length is dy

#

and the length of the red bit (hypotenuse) is ds

#

so dx^2 + dy^2 = ds^2

#

so 1 + dy^2 / dx^2 = ds^2 / dx^2

#

so 1 + (dy/dx)^2 = (ds/dx)^2

#

so sqrt((1 + (dy/dx)^2) = ds/dx

#

so sqrt(1 + (dy/dx)^2) dx = ds

#

so ∫ sqrt(1 + (dy/dx)^2) dx = ∫ ds

#

now "∫ ds" would represent adding up all the ds parts together

tender cobalt
#

adding up all the ds represents the total length of the curve

#

so the arc length is integral sqrt(1 + (dy/dx)^2) dx

#

in this case, the arc length is $\int_{-2}^2\sqrt{1+(2x)^2}\dd{x}$

woven radishBOT
tender cobalt
#

(y = x^2 so dy/dx = 2x)

tender cobalt
#

the integral is about 9.294

#

so the red curve is 9.294 units long

little gate
#

Sorry its too long to screenshot

#

But i got this after using that method

tender cobalt
#

yep thats correct

little gate
#

Damn that's so scary

tender cobalt
#

the good news is that after you simplify the derivatives, you dont have to do the integral

#

you leave the computer to find the length for you

little gate
#

I wanna ask something integral can be use to find the length and area under curve so can it do something more?

tender cobalt
#

it can be meant for other things

#

oh also

tender cobalt
#

this is not a possible integral, some nonsense is involved to "solve" it

#

you would get this

#

or this

#

didnt realize the integral can be solved, whoops
the other one with the x^2 can also be solved too

little gate
tender cobalt
#

until it didnt when it was simplified, yea

#

I like how short it is

little gate
#

Wow tysm

#

I wonder how did we get hyperbolic trig here

#

But ill search it myself

#

Thx bro

tender cobalt
#

np

little gate
#

How to close this?

tender cobalt
#

type .close or .solved

little gate
#

.solved

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simple vessel
#

how do you find the partial derivative of P respect to V

simple vessel
#

the answer gives this but doesnt differentiating both sides by dV make the right side 0

#

since nRT can be treated as a constant

#

but nRT is in the answer

#

i managed to get the second part but i cant get the first one

restive river
#

?

woven radishBOT
#

icannotdoanymorecauchy

restive river
#

@simple vessel u can express P as this, no?

simple vessel
#

oh i did it implicitly

#

lemme try

#

ok i got it

#

then why doesnt implicit work or am i doing smth wrong

restive river
#

lets see

simple vessel
#

partially differentiate both sides by V no

restive river
#

how did u move from here to here?

simple vessel
#

d/dV (V-nb) = 1

restive river
#

aight

#

gimme a moment

simple vessel
#

aight

#

i tried implicit for the second part and it works fine

restive river
#

blud

#

the answer is correct

#

but u forgot to rearrange it

#

to remove P

#

let me show ya

simple vessel
#

oh

#

so you have to make p the subj either way

woven radishBOT
#

icannotdoanymorecauchy

simple vessel
#

yea i know

restive river
#

the rest is easy for u

simple vessel
#

but i saw that nRT wouldnt be in the partial derivative

#

my bad

#

.close

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fervent ore
#

Whats the magic trick to this one? how does the given info help? I can rewrite it but not in any helpful way thus far

restive river
#

@fervent ore

fervent ore
#

Sorry i have to step away i will reopen and ask for help soon when im back so sorry

#

Do i do .close?

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#

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fervent ore
#

ok back now sorry

#

i can rewrite ln(2)^-1 approx= 1.443 as 1/1.443 approx= ln(2). I can rewrite in the summation 2^(-k) as -k * ln(2)

fervent ore
#

if i round i get that to 1000 * 1.443 = 1443 and because we will keep adding numbers the equality wont hold but they are so small that increasing it to 1444 should make it right?

#

Is this a proper way of solving it?

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restive river
#

I have a question on Claire'ts theorem , as the function 1/ (x-y) is discontinuous

restive river
#

At x=y

#

So why the partial differentions f xy = f yx

distant perch
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deep marlin
#

Can someone help me answer this question

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misty crest
#

nah

deep marlin
#

I'll e-transfer $10 for correct answers

#

I'm stuck

#

$15

#

😭

distant perch
#

lmk when it gets to $30

misty crest
#

29 and you got a deal

#

🤝🏻

#

💀

olive snow
deep marlin
#

If you get all of the remaining 7 points in that question I'll give you $20

#

And if you help me with another one $30

#

Final offer and only if the answers right I think this is a tricky question

#

I was already wrong for #2 and #3

misty crest
#

so you need b, c, and d

young plover
#

I’ll help you for 40$

#

But I’m a really good teacher so it’s worth the fee

distant perch
#

^ I can vouch

young plover
#

Just ask chef he’ll vouch

#

Lmao

deep marlin
#

I don't need a teacher I just need the answers

#

40 is too much

young plover
#

Okay 👌

#

I’ll find my next client then good day sir

deep marlin
#

Is this even the right channel for finance?

#

Starting to wonder whether this request is a bit different than typical math

young plover
#

I think that people here could help you

#

But giving you answers is not what we do here

#

!nosols

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#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

young plover
#

It’s a rule of this server my friend

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patent wind
#

could someone explain what is actually happening in this proof i dont understand the n+1 or the 1/2

upper schooner
#

Any real number that's less than M0 should not be an upper bound, so they chose to subtract 1/2 from M0

#

The n + 1 is basically taking the n you found from here, you know that adding 1 to any natural number gives you a natural number, but then you know both that (n + 1) is a natural number, and that it's greater than M0, the supposed upper bound of the naturals

patent wind
#

ah right

#

thanks

#

.close

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fervent ore
#

can some1 explain this? I understand substituting and i've done u substitution problems before but i don't understand how they even get to the 1st step?

fervent ore
#

Maybe they're doing something completely diff idk.

#

I just learned integration by parts and that doesnt seem applicable here either?

timber pebble
#

it creates the 1/3 outside

#

then we find du in the numerator exactly

fervent ore
timber pebble
#

u = x^3 +15x+ 8

#

then du = 3x^2 + 15

#

say num = x^2 +5 is the numerato

#

so 3 num = du

fervent ore
#

yeah and then we divide over like you said to get dx expressed with du right?

timber pebble
#

and (1/3) (3 num) = num

timber pebble
timber pebble
fervent ore
#

ok cool and the middle step is that just rewriting it as u^-(4/3) which gives

fervent ore
fervent ore
timber pebble
#

yes

fervent ore
#

is that the easiest way or?

#

ok

timber pebble
#

its not too crazy hopefully

#

just work out a derivative

#

youll obtain the rule backwards

fervent ore
#

how would one do that?

timber pebble
#

take the deriv of x^n

fervent ore
#

n * x^n-1

#

and then?

#

oh i kinda see it

timber pebble
#

yea

fervent ore
#

the integral will be one higher so you divide by n+1 and you will remove -1 from the xponent so you also have n+1 there

timber pebble
#

you want that power that comes down to get eated

#

so we figure to start with x^n/n

#

this gives x^(n-1) as deriv

#

now reverse the action

fervent ore
#

makes sense

timber pebble
#

whats integral of x^(n-1)

#

but we already know

fervent ore
#

yeah

#

ty this helped

timber pebble
fervent ore
#

my brain has been kinda exploding with rules these days for an upcoming test, so many new things, polynomial division, taylor polynomial formula, rules for when raising constant to X and differentiating/integrating, integrating by parts formula, geometric series infinite/finite, lagrange multiplier, implicit differentiation, quotient rule, Rational root theorem

#

but i guess thats part of learning this, assembling a toolbox of all of em. sadly no formula sheet is allowed but that will just make practice harder 🙂

timber pebble
#

if you really dont think you understand or believe something then try to convince yourself

#

then you can develop intuition to replace rote memory

#

thats my opinion at least

fervent ore
#

That makes total sense

#

it will come to me soon enough 🙂

timber pebble
#

yes

fervent ore
#

thx for the support, have yourself a lovely rest of ur night or whatever time it is for you ❤️

#

.close

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runic thicket
#

if each edge of the cube increases by 2 cm, the volume will increase by 98 cm'3. what is the length of the edge of the cube

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restive river
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,w (x+2)^3 = x^3 + 98

woven radishBOT
restive river
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so x = 3

runic thicket
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what is aqt

runic thicket
# restive river so x = 3

hey man how does the x+2 and x3 98 whatever get -5 and 3 i really need to know because i need the full process of the problem

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restive river
#

am i correct im so bamboozled LOL is it talking about the dotted line cuz if its talking about the actual angle in the red angle thats obv not 330

restive river
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it has to be A none of them would be 330 if its talking about inside the red lines

tall knoll
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it is talking about the dotted line

restive river
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got it so im good

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i have one other question

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how would i do this

tall knoll
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how many radians make up a full rotation?

restive river
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2pi

tall knoll
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so then how many rotations would 3pi radians result in?

restive river
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answer A

tall knoll
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that's not what i asked

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but yes

restive river
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1 and a half

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yaya

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ty first week and i havent taken trig since hs

tall knoll
restive river
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.close

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bitter vigil
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where does the 2 come from?

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bitter vigil
#

aint the x^2 isolated within cos

supple knot
bitter vigil
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im dumb

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didn't see the product rule

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vivid estuary
#

Is it safe to assume that this is the line integral of f(z) on a piecewise smooth curve gamma?

vivid estuary
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beause the only way I can think of showing this

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is by parametrizing gamma and then using the fact we can factor c out of a real valued integral I believe

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Is there an easier way to go about these rather than parametrizing gamma and getting real valued functions and then applying laws on on the real valued functions and then converting it back to gamma?

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This isn't a complex analysis course so she isn't expecting a rigorous proof

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for example if gamma isn't assumed to be piece-wise smooth how would I go about this?

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yeah im getting stuck from using my original plan

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jolly orchid
#

Okay so, I’m wrong? 😢

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jolly orchid
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My work is on the right picture

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Don’t take me step-by-step, just write it out step-by-step if possible.

lilac patio
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you should be right i think

jolly orchid
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I believe I used the right formula

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The numbers I got seem a little bit over what I should be getting, if I’m siding with it being wrong.

lilac patio
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yeah but you rounded it properly so it's still right...try asking your teacher abt it

jolly orchid
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Alright bet

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I have another one, I’m not sure if I’m doing it correctly.

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Here I got SinB=0.6, what do I do afterwards?

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I was looking for angle B

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Nvm nvm

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I remember now, oops.

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I was supposed to use Sin^-1

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vivid estuary
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claim

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vivid estuary
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but I got stuck on the last line

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the first part is a(integral of f(z) on gamma)

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the second part with the b i’m not sure

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somehow I need to get (a + ib)(integral of f(z) on gamma)

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Im assuming the second part can be represented as bi(integral of f(z) on gamma) somehow

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and then I'd be able to factor out a + ib

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WAIT I SEE IT

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factor out an i on the second part

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you get -1/i

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let -1 = i^2

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you get i

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and then it becomes bi(integral f(z))

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ok I believe I got it

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viral oxide
#

Given a conical frustum with known the "cross-sectional area" (or idk how its called -> see picture; aka area from the trapezoid) is it possible to get the volume of the conical frustum without knowing other values?

fossil locust
# viral oxide Given a conical frustum with known the "cross-sectional area" (or idk how its ca...

A conical frustum is a frustum created by slicing the top off a cone (with the cut made parallel to the base). For a right circular cone, let s be the slant height and R_1 and R_2 the base and top radii. Then s=sqrt((R_1-R_2)^2+h^2). (1) The surface area, not including the top and bottom circles, is A = pi(R_1+R_2)s (2) = pi(R_1+R_2)sq...

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if you know r, R, and h it is possible to find the volume

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if you only know the area of the yellow trapezium then it isn't

viral oxide
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okay, thank you

fossil locust
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no worries!

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viral oxide
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.reopen

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viral oxide
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Is it also not possible if you know h, ((r + R) / 2) and the "cross-sectional area"

fossil locust
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I'm pretty sure you need 3 independent pieces of information

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where you can't say find the "cross-sectional area" from the other 2 pieces of information

viral oxide
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okay thank you. I am trying to proof the "keplersche Fassregel" so Simpsonsrule but rotating. But there is only known y0, y1, y2, x2, x0.
I made: A_trapezoid = y_1 * (x_2 - x_0) and A_parallelogram = 0,5 * (y_0 + y_2) * (x_2 - x_0) - A_trapezoid
But now I am struggeling with getting the volumina

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viral oxide
#

<@&286206848099549185>

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@viral oxide Has your question been resolved?

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@viral oxide Has your question been resolved?

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@viral oxide Has your question been resolved?

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vast drift
#

Scope is highschool math if that matters

Consider the Bernstein polynomial $B_{n,k}(t)$ of degree n and order k that is defined by $B_{n,k}(t)= ^{n}C_{k} t^{k}(1-t)^{n-k}

part (1) Find the sum of all $B_{n,k}$ where k varies on [0,n] (i got = 1)

part2) (where im stuck)

woven radishBOT
#

Dootud
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

vast drift
#

part2 asks
Show that for $r \leq k \leq n$, $\frac{^{k}C_{r}}{^{n}C_{r}}B_{n,k}(t) = ^{n-r}C_{k-r}t^{k}(1-t)^{n-k}$

woven radishBOT
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Dootud

vast drift
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oh wait nvm i got it

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ripe oriole
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Hi guys. Can someone verify my answer to correct value? i think there is mismatch in my calculations

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scenic pike
#

Someone help me I don’t know how I’m supposed to calculate either rates

scenic pike
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HELP

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MY FRIENDS THING

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Anyways…

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I need help with calculating for both rates I have no idea how to do it when it should be something so simple😭

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@scenic pike Has your question been resolved?

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@scenic pike Has your question been resolved?

alpine scaffold
#

Is the question solved?

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proven arch
#

What's the answer to 2(-2)+1/-2+1? is it (3) or (-3.5)? i used calculator but it said (-3.5) but i tried solving it manually and i keep getting (3)...

f(-2) = 2(-2) + 1/(-2)+1

f(-2) = -4 + 1 / -1

f(-2) = -3 / -1

f(-2) = 3

proven arch
#

1/-2 + 1

safe knoll
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cuz 1/-2 + 1 and 1/(-2+1) are 2 different things

proven arch
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2x + 1 / x + 1

safe knoll
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with any brackets or just like that?

proven arch
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i'm supposed to graph a rational function but i can't seem to point it correctly without table of values

proven arch
safe knoll
#

$$\frac{2x+1}{x+1}?$$

woven radishBOT
#

JustToPro

proven arch
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yess

safe knoll
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write it as (2x+1)/(x+1) next time

#

what ur trying to type is read as
$$2x + \frac{1}{x} + 1$$

woven radishBOT
#

JustToPro

safe knoll
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probably how the calculator read it as well , so thats why 3.5

proven arch
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OHH no wonder i'm overthinking, thanks so much !

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i will close now, thx for ur help i gotta watch my syntax now

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.close

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deep gale
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deep gale
#

for 10. are the numbers 16,8,0,0? just need someone to check

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deep gale
#

<@&286206848099549185>

fossil locust
deep gale
#

yes

fossil locust
#

there has to be another solution, ok let me try

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a, a + d, a + 2d, (a + 2d)^2/(a + d)

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,w a + (a + 2d)^2 / (a + d) = 16, a + d + a + 2d = 8

fossil locust
#

ah so if you choose a = -2, d = 4 instead

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you get -2, 2, 6, 18

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which must be the intended solution

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I suspect you divided something in the quadratic instead of factoring properly

deep gale
#

this is my solution btw, i didn't get close but i tried 😂

fossil locust
woven radishBOT
fossil locust
# woven radish

okay so your attempt that ends with $16r - a_1 r^4 + 16r^2 - a_1 r^5 = 8$ is the most promising I think

woven radishBOT
#

higher's secret twin brother

fossil locust
#

then you haven't used the fact that the 1st, 2nd, 3rd terms are in AP

deep gale
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so what would my 2 equations be?

fossil locust
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AH the problem is that you've misunderstood the question

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the first three are in AP and the last three are in GP

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so you can't say that $a_1 + a_1 r^3 = 16$

woven radishBOT
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higher's secret twin brother

deep gale
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ohhh

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what should it be then?

fossil locust
#

cause the last 3 terms are in GP
you know the common ratio is (a + 2d)/(a + d)

so the 4th term has to be (a + 2d)/(a + d) * (a + 2d)

fossil locust
#

now sub that into a + (a + 2d)^2 / (a + d) = 16

deep gale
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like this?

fossil locust
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yep!

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now multiply everything by 4 - 3/2 d + d = 4 - d/2

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and it's a quadratic

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@deep gale

deep gale
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yes, that's what i'm doing rn

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i was trying to solve for another problem while you were gone and got stuck again

fossil locust
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okok

deep gale
#

😭

fossil locust
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(a + b)^2 is not a^2 + b^2

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so instead of doing that, expand $(4 + d/2)^2$

deep gale
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wait i messed up already?

fossil locust
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oh yeah and you also didn't multiply by 4 - 3/2 d + d on the right

for some reason you just multiplied by 4 - 3/2 d

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hold on

deep gale
fossil locust
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oh wait that's correct sorry

fossil locust
deep gale
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and i got 64-24d

fossil locust
deep gale
#

why 4 - d/2 and not 4 - 3/2 d