#help-27
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Integratiom by parts
Okas
Speaking of integrals I think I have an easy one
Please send me
If I can't solve then I am quickdoomed
I haven't done definite ones yet
a is 200
Im stuck at indefinite lol
I have a problem I want to ask about
Integrating temperature over depth for depth
am I in the right place or is this for practice
You are asking a noob high schooler
So this is a bad place
Bye bye
The worst
Maybe
Make a new channel, and you close your lchannel before leaving
Sorry about that
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Is this true
no, the right hand side is equal to x^x
The left???
what?
yes
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youre welcome
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Is my work correct?
c) C = {xₙ | xₙ = n • 3, n ∊ {9, 10, 11, 12, 13}
d) D = {xₙ | xₙ = 2 • n, n ∊ {-1, 1}
And can someone help me find the description for:
E = {8, 27, 64, 125, 216}
u could simplify the first one to be { 3n | n ∈ Z and 9<=n<=13}
i think D is better represented as { x : x∈R and x^2=4 }
elements of E are perfect cubes
are these different options or is mine completely false?
different options
urs are correct
what does that mean?
but u could simplify them
yk what perfect squares are?
oh okay okay, i just started with maths so i don’t wanna confuse myself too much
uh not in mathematical terms 🙂
numbers like 1, 4, 9, 25, 36 etc etc
their square roots are integers
similiarly for perfect cubes
take 8 for example
222 = 2^3 = 8
the cube root of 8 is an integer
similiarly for 27
333 = 27
for both of these, their cube roots are integers
that is to say (possibly a little reductively) they arent fractions or decimals
the thing is for 27 and 125 u cant use 2
@lusty sigil Has your question been resolved?
u dont
27 is the cube of 3
125 is the cube of 5
@lusty sigil Has your question been resolved?
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Can someone help with the problem in yellow?
I'm utterly lost and don't know what should I do
Haven't tried anything yet
I see, there's several ways you can start with this, the first step is to calculate the resultant first
you already defined Bx = 10, By = 0, Ax = 10, Ay = 10 which is great
ohhh
Hee gave the question
Yep
do you know how to get the resultants from the component vectors (Ax Bx)?
ohh yeahh that's the final step though
that's the vector length
And second?
to find the resultant vector you add the component vectors together
so
(A+B) = (Ax + Bx, Ay + By)
Is this for the first for second sorry I'm confused
First right?
Is it another method?
You there?
you find resultant x and resultant y first, then you do r = whole root a^2 + b^2
Could you give 2?
hmmm let me think, it's been a while since i did this sorry 😭
no problem!
@carmine cedar
i redrew the components like these and then you have a triangle like this
and then you can use trigonometry to find theta
Wait lemme understand
sure suree
oh no problem, because we're trying to find theta for the y axis
it's from the question, it's asking the resultant and the y axis right?
ahhh it's okayy
OH
yeahhhh
@carmine cedar Has your question been resolved?
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If i want to calculate |AUBUC|, how would i the easiest accomplish this?
If i sum the toal of A B and C i get 180 however... that means i need to subtract red green and pink, right?
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OH wow nel!! I missed you! How are you?
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I'm fine, did you not have any more questions?
✅
Actually i did find another question i had
$D = {6q : q \in Z}$ and $A={2m : m \in Z}$ is the following true? \
$\overline{D} \subseteq \overline{A}$
My assumption was that it's true?
Use ${$
SWR
Hmm i did but i'm not sure why it removes them
\ {
ooh
\{
Merineth
There we go
I don't think it is
Is $A\subseteq D$?
SWR
No other way around
D is a subset of A
It's asking if it's true or false, but i'm not sure why it results in false?
continue
You mean complement of D is a subset of complement of A, which is true if and only if A is a subset of D, which is what I asked if A was a subset of D
$\overline{D} = {1,2,3,4,5,7,8,9,10,11,13...} \
\overline{A} = {1,3,5,7,9...}$
Merineth
And it's asking "Does D have every element that A have
oooh which is not true
missing 2 4
Other way around (with complements)
oh really O.O
It's asking whether A' (complement) has every element that D' has
Which as SWR said is equivalent to asking whether D (not complement) has every element that A has
I was under the assumption that $D \subseteq A$ meant D is a subset of A, meaning D has every element which A has
Merineth
If a subset had every element of the superset and then more, it wouldn't be contained in the superset
The superset has some elements of the universe, and the subset has some elements of the superset, and no more
If $A = {1,2,3,4}$ and $B = {1,2}$ then $B \subseteq A$ ?
Merineth
Ye
All of B's elements are also in A. That has the opposite meaning as "B has every element that A has"
Just remember that a subset is smaller than its superset, hence the prefixes
Every element in D is not in A
Meaning it's False?
Would that be the right thought process?
Okay nice
Yeah this is a good way to remember it
FInished my discrete math for today c:
tsym 
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let x be the population 4 years ago
x times 1.1 times 1.1 times 1.1 times 1.1 = 50000 (because its growing at 10 percent per year)
equivalently x*(1.1)^4 = 50000
let 50,000 be 100% search how much is 10% is equal to then remove 50,000 from that number *4
10% will be 5000
@uneven nacelle Has your question been resolved?
So 50,000(1-10/100)4
Is it right?
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Hi
Suppose a box on a frictionless ramp is being pulled by a rope with a tension of 350 N
making an angle of 50° to the horizontal ground. If the angle of incline of the ramp is 20°, and the box is pulled 5 m, determine the amount of work done. Hint: Draw a diagram and use vectors to represent the situation.
I need help making the diagram
Start by drawing a floor, ramp and box then add the rope
This is what I have done
But i dont know how to make a diagram and adding rope and stuff
The incline of the ramp is 20° not 50°
Then where do i write 50
50° is the angle between the rope and floor
Can you show me on a piece of paper or something how to make a diagram i am a visual learner
Please
I don’t have paper on me
First, redraw what you have but with 20° angle on the ramp
Now you are told the box is being pulled by a rope, so draw a rope attached to the box at roughly a 50° angle to the floor
I dont have anything to measure 50 angle
The rope will be pulling the box up, so it will be attached to the right side of the box
It doesn’t have to be exactly 50°, a diagram is just there to help you visualise roughly what is happening
Opposite of what i did right?
Yeah
What?
Where does 30 degree go?
Let me get my phone so I can draw on your diagram
I know my calculations are right just the diagram is troubling me
i was pinged here
Idk who did that
The box is pulled parallel to the slope of the ramp. The angle between the rope and the direction the box is pulled is then 30°
The 350N is the tension on the rope, not the weight of the box
Then what is the weight of the box
The angle of the ramp is still 20° yeah
You aren’t given the weight
Based on the question you gave
The 50° is the angle the rope makes with the ground, what you have is a bit ambiguous
But it is the same as yours
I extended the line down of the rope to try to make it clear, though i will admit it is still a bit unclear
Ok the line near the 30 degree is 350 N right
This diagram shows what the angles would be for each component
Yeah that would be the rope
Ok can you check my calculations are right i think i got the diagram
Where did the cos 0 come from?
Idk
but it doesnt mean anything since it equals 1
I can remove it
Ok final look at my diagram
Diagram looks good
thank you
Pretty weird you did this without drawing a diagram first
can i add you as friend i really need your help on maths
Don’t see that very often
I’m not as active as I used to be so no point really
You’ll get help much faster asking on the help channels here
Sure
Add the following vectors using trigonometry (i.e., cosine and sine laws).
a. 7 m/s [N30°E] and 2 m/s [S17°E].
The N30°E notation is the angle from north on the direction East
And for trig, we want the angle from +ve x going counter clockwise
Let me draw the first one as an ex
60
Yeah, now use trig to decompose the vector into a sum of its x and y components
So what would the coefficient of the x component be?
7cos30
Not 30
60
Ok and then what is the next part
Now do the same for the y component
2sin17
I mean the y component of the 7N30°E vector
Also my teacher wants me to do it in cosine and sine not componenets
Add the following vectors using trigonometry (i.e., cosine and sine laws).
a. 7 m/s [N30°E] and 2 m/s [S17°E].
I mean the question just says using trigonometry, which you are
But he doesnt want components for this question he gave another question with components
What should i do?
ok
What do you get once you add the components of both vectors
So what is the resulting vector in ax + by form when you add those components to the other
do i need to calculate what 2sin17 is for that
Idk how to calculate resulting vecor in ax+by form
You can just leave the terms as they are
would it be 7x+2y
The x component would be the sum of the other 2 x components , same with the y
x component = 7sin30 + 2sin17
So you have
(7sin30 + 2sin17)x + (7cos30 + 2cos17)y
Oh
Yeah
This would be the components of the purple vector here
ok what next
Now we convert to magnitude direction form
Start with magnitude, how would you calculate it?
square root of x2 + y2
From direction meaning tan
Yeah, so what would the equation look like
I have to calculate the magnitude i will find it out in a minute
63 degree i found
Magnitude is 8.9
Equation will look like 8.9 m/s [N 63 E]
Looking at this diagram, specifically the purple vector, does 63 degrees make sense?
no
You sure?
I am not sure about this tbh
👍
Ok so final answer is 8.9 m/s [N 27 E]
Yeah
Thank you
no one helped me like you did in this server i would appreciate if you accepted my friend request but it is okay
Also, always draw a diagram for these questions
Diagram are the toughest thing to do for me
Because the inverse tan function will sometimes give you an angle that results in the wrong quadrant
So you would have to adjust by adding/subtracting 180°
Ok i have only 2 questions to do i will try them and then come back if needed
And its easiest to see when that is necessary if you draw a diagram
Sure, ping me if you get stuck
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Sorry for my paint skills, question is not in English so I had to do it like that.
I have no idea where should I start or what should I do
First, Find what A and B converge to. That will make life easier.
not very used to "converging" but I guess I have to learn it for being able to solve this question right?
You don't "need" it
you could also write both in summation notation and compare them
If you write them both in series notation, that will help
like that?
Yeah
I unfortunately have no idea how can I compare them :/
Well, there's 2 differences between the summations
Try to address one of them at a time
the initial value of n and the functions are different
Increases the value of A by 1?
Oh
Looks good
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I solved the assignment
It's to find the increment to the function from start point x=3
$f\left(3\right)=\frac{1}{13\left(3\right)}+13\left(3\right)=\frac{1}{39}+39=\frac{1}{39}+\frac{39\cdot39}{1\cdot39}=\frac{1+1521}{39}=\frac{1522}{39}$
DisplayName
so its easier to screenshot instead of just copy-pasting the same math
True
I found out that now, especially when you pointed it out also
But on the other hand, it may help that people can copy the latex code too
no it doesnt
they cant do that from a screenshot
this is too long and specific to be usable
ok, look away from latex, and look at the screenshot
you still havent said what the problem was
It's to find the increment to the function from start point x=3
that is not english
use a machine translator and try again
are you simplifying $\frac{f(3+h)-f(3)}h$?
mtt
I apologize that my english is not the greatest, especially when it comes to mathematical terms. our danish terms are sometimes quite different. machine translations doesn't help much unfortunately.
$\Delta f$
DisplayName
are you simplifying $f(3+h)-f(3)$?
mtt
yes or no
you shouldve said so
additionally
showing work does not display this adequately
especially from work like yours, its customary that it doesnt show the problem at all
you need to explicitly state the problem
like this
instead of this
with that out of the way, a lot of this work can be condensed for a few reasons
Nothing is shown in this message
yes, because it is a statement of the problem, which I asked for
also
did you notice I was replying to a different message?
No nothing is shown. You say "like this", but there is nothing shown
I know youre not new to discord: the reply on here is a standard way of referring to a previous message
so in this case, its a shorthand for saying: "like this"
Ok it didnt show that. Only now that you pasted the screenshot of it is it shown
are you viewing discord through IRC?
noticed you stopped typing, lets move on
@viral hornet you now need to state which principles youre going to retain in condensing the work
so far theres a calculator-heavy solution that cheats the problem which your work shows youd rather not do
I stopped because I got really turned off by you condescending attitude and I was thinking about how or what to say to you in a way that didn't make it sound like I was piss sour salty about it
you need to sound true
you dont need to sound polite
this is not a professional setting
whats more important is that we're communicating openly
Okay mtt I think you should step away
I don't think you're making the situation better
I can take a look at the problem
thank you
Is this your solution? It looks good to me besides the "h=9" part; I'm not sure where that came from
h=9 was a control test to check if the value was equal
ah okay
So, you can save some time if you don't simplify fully in the beginning
Like for example when you calculate (f(3)), you simplify it all the way down to (\frac{1522}{39})
biased_estimatERIC
I know the final conclucions and result is correct. But the calculation steps I took I feel maybe I took complicated unnecessary steps
But you can actually save some time if you leave it as (\frac1{39} + 39)
biased_estimatERIC
or even
ok yes
[f(3) = \frac1{13(3)} + 39]
biased_estimatERIC
And then when you go to calculate f(3+h)
you can similarly leave some stuff unsimplified to get
[f(3+h) = \frac1{13(3+h)} + 39 + 13h]
biased_estimatERIC
and then when you subtract them, certain things cancel
like you can just cancel out the 39s
and then you can factor out the 1/13
so it'll look like
[\begin{split}f(3+h)-f(3) &= \left(\frac1{13(3+h)} + 39 + 13h\right) - \left(\frac1{13(3)} + 39\right)\
&= \frac1{13}\left(\frac1{3+h} - \frac13\right) + 13h\end{split}]
so a key idea is when I see 39 and 13 to recognize that 3*13=39
biased_estimatERIC
I would say the key idea is to think ahead a step and notice when things will cancel out
if they'll cancel out, you don't need to simplify them right away
Yes that makes sense
like for example the 39s in this example cancel out, so you don't need to add 39 plus the fraction, which saves a lot of time
you never really have to work with large numbers at all for this question
(like the thing we ended up with here, every number is at most 13, so we never do any messy calculations)
and then simplifying the fraction is rather easy too
so I guess another key idea is, factoring stuff out like the 1/13 in this example often helps too
you get
[\frac1{13}\left(\frac{-h}{3(3+h)}\right) + 13h]
biased_estimatERIC
and from there, you can simplify the denominator: 13 * 3 * (3+h) is the same as 39 * (3 + h), which is 117 + 39h
right, I need some practice with this then, to get a better understanding factoring out and cancelling out
and then the annoying thing is that their answer choices aren't fully simplified, so you have to multiply the numerator and denominator still both by 13 I think to match one of their answer choices, but that should finish the question
I think that's some great help for me to practice on now, thanks a lot for the help!
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How to find this sum
let's see if we can do some magic here
Also I don't mind if you give me some identity even though I don't understand the whole story. Something similar to
Gamma(z)Gamma(1-z)=pi csc(piz) or something like that for example
are you familiar with formal power series manipulations?
Give an example
I also like to point out this sum came from an integral
trust the process
I understand this, it's a geo series
then:
f(x^3) = Sum x^(3n) = 1/(1-x^3)
x f(x^3) = Sum x^(3n+1) = x/(1-x^3)
now we have 3n+1 in the power
by taking the integral we should be able to get 3n+2 in the denominator
,w integral of x/(1-x^3)
This is where it comes from but since I want to evaluate the integral I have to evaluate the series
@sage pawn Has your question been resolved?
can't you evaluate the integral directly using partial fractions? or is this explicitly not allowed
I can but Wanted to see if it was possible to find the series as if I didn't mention it came from an integral
and one way to find the series is to... write the series as an easier integral
I could be wrong but there has to be some other way
@sage pawn Has your question been resolved?
@sage pawn Has your question been resolved?
hi
@sage pawn Has your question been resolved?
@sage pawn Has your question been resolved?
just timeout already
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anyone can guide me through this question
,w pi*1/6^2
try to cover up this square with the least amount of circles (of radius 1/6) as possible
do i need to calculate the whole circle
wdym?
oof
you don't have to redo the whole filling
just put more circles
over the areas unfilled
yeah, and the objective is to draw circles (that can overlap)
such that
every point of the square
do we still apply the pigeonhole formula
is at least in one of those circles
we can't right now, you haven't filled the whole square yet
well x = ?
that's the issue
x is the number of circles you need
from this
you "drew" 9 circles
now find the areas that aren't covered by the circles
and see how many circles it takes to patch them up
got it the edges right?
the edges of what
in the box we put the circle
and there is area havent fill up
which is the 4 edges
the 4 edges of a small box of side 1/3 yes
now just recall
that we want to use as few circles as possible
so be mindful about where you place the next ones
oh we don't care about the area that's filled a lot
we just want it to be filled
100%
plus it doesn't matter to count the area
since circles will overlap
etc...
hmmmm
i got 0.2146018366 for the remainder + 1/4pi which is the total of 9 circles = 1 unit
so i didnt have any correct answer yet from what i given right?
am i almost there
ok what you need to do
stop calculating the area
and just draw circles
to fill the whole 1*1 square
?
is one circle enough
the circle should be exactly as in this drawing
circles of radius 1/6
9 circles
i'll let this slide
does it fill every point of the square?
look at places like this
with circles?
yeah it's like this drawing
2.46 circles
just put a circle over it
how are you gonna put a not whole amount of circles
we need another 2.46 cirles to filled up

its kinda hard
@sand dove like this?
yep you did it
how many circles did you use in total?
25
and how many points are we considering in the square?
3
no in total
51
so using the pigeonhole formula
51/25
2.04
so ur saying in any possibilliteis
in 24 pigeonholes theres 2 pigeons in each hole
and any remainder holes theres 3 pigeons
we don't know about the other ones
we just know
there's one pigeonhole
with at least 3
since 51/25 is 2 + some non zero remainder
damn the question is quite tricky
i thought we have to calculate
and all but instead how you shown me is kinda easy
@sand dove thanks alot btw
@severe compass Has your question been resolved?
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which is the cardinality of a perfect set compared to the cardinality of R ?
if i have understood correctly they have the same cardinality with continuum hypothesis but what if we dont take continuum hypothesis? which one is bigger ?
if continuum hypothesis is taken to be false, then since a perfect set is a SUBSET of R, it's gonna be smaller
that is if you find a perfect set that's not the cardinality of R
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hey guys, would like some help with a very simple doubt
a. value of vehicle = 116,000
b. down payment = 10,000
c. each installment = 4,270
d. loan period = 3 years
e. the installment is paid monthly
Question. to find the annual rate of interest
would like help in 2 doubts here
- i think we first exclude 10,000 then calculate for the interest, aka the principal is 116000-10000=106000. so am i correct?
- pls guide me in solving it to the exact interest amount if possible
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lmao did close it by mistake
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$$L\left(x\right)\ =\ f\left(a\right)\ +\ f'\left(a\right)\left(x-a\right)$$
Thyroxine
$$\tan\left(46\right)\ =\ \tan\left(45\right)\ +\ \sec^{2}\left(45\right)\left(46-45\right)$$
can someone tell me what i am doing wrong here, my final answer comes down to 3
but thats very far off from 1
the answer should be very close to 1
i used 45 for my choice of centre because tan 45 = 1
Thyroxine
@ebon rose Has your question been resolved?
<@&286206848099549185>
sup lil homie
oh
this one
well my lil homie
this only works
if u got in radians
not degrees
use pi/4 instead of 45
or thats wat i studied lmao
just try it out
its called the SI unit of angles ig
@ebon rose
Ah i used radians and got a better answer thank you!
i thought if i just kept it all in degrees it would work but ig not
yeah cool
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can you please take a look at my work and answer and let me know if it is correct?
,w d/dx x^2(1-x^2)^4
Yep looks good
but my answer has postive 2x
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can someone please asist with this question?
Do you know what that notation means?
integrate the second derivative multiple times to find the original function and then evaluate it at t=1?
kheerii
Where n is a natural number
is f^(5)(1)= -12?
Sounds about right
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Can someone help with this question ? I don’t understand it at all
first find the limits of then x = -1 and when x = 1 (right hand side)
right hand side for -1 is approximately 2.1 or 2.2?
And for when x=1 it’s approximately 0.9?
Which is 2?
Yep
Just 1
Its technically 0.9 repeated forever
Yes which is just 1
And using summation you can prove that 0.9 repeated equals 1 so yeah
then just substitute those into the equation and solve
mhm
But there is no -3 in the options
uh 2 - (3/2)*1 but yeah
I think you wrote it wrong
2 isnt multiplied by 3/2
yep
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help i don''t understand what im doing wrong i know the exterior angles of a triangle is 360 but ??? if a+b+c = 180 is the inside angles of the triangle then 360-a is not the exterior angle? then 360-a+360-b+360-c=1080-a-b-c = extrerior angles but then that equals 900??????????
can you understand the definition of an exterior angle first
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I think I'm pretty close. My idea is to find an expression relating x and b
b is the side opposite to point B btw
I have triangle BOM which has 4x as a side length but I can't do much that without an angle
power of a point
First I've heard of that but the concept seems simple enough. I'll have a deeper look. Thanks!
Alright, that was a very helpful hint. Thanks
@rose rock Has your question been resolved?
Just noticed my mistake
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For this question can I just find the lim along 2 different paths
y = x and y = -x and show that both of them arent equal to each other so thats why the limit DNE so its not cont at (0, 0)
or is there more to it
no that's it
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did I do this right, the question was A man walked 440 m [50.0° N of E] and then 580 m [5.0° S of W]. The entire trip took 150.0 min. whats his displacment.
<@&286206848099549185>
i believe you’re adding the wrong components together
looks you added the y and x the components rather than both the x’s
oh alr
wouldnt sin(5)-580 be the y component though?
<@&286206848099549185>
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did i mess something up in trying to prove the least squares regression equation
heres the expected result
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<@&286206848099549185>
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Tf is this lol
tried deriving it for myself but fell 1 foot short from the result i wanted
Oh
Wat is regression??
I heard it somewhere
In python
Is it like opposite of progression? U go backwards?
Exactly
Underfitting superfitting
These I studied in AI
I wish there's an option to ping Helpers role using and command
Like Helpers AND Undergraduate Math
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@zinc pewter Has your question been resolved?
It's just rotated. The origin is here and the axes are outside the box to prevent writing them on the actual shape
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d
I think you should post original question
As people that help you may not be here now
Someone else might help you now
0.675
thnx
@hollow oriole Has your question been resolved?
P of email given picnic= P of email and picnic/ P of picnic
(135% * 3/4) / 1/2
The table above shows the distribution of preferred activity, in percent, for each response type used.
For the survey, the number of email responses was as thrice the number of phone responses. If a person who preferred a dinner dance is selected at random, what is the probability that the person responded by phone?
Phone Email
Dinner dance 65% 45%
Football 15% 45%
game
Picnic 15% 3%
pool
Party 5% 7%
Total 100% 100%
P of email given picnic= P of email and picnic/ P of picnic
P of email given picnic= (135% * 3/4) / (2/4) = 2.025
Phone Email Total
Dinner dance 65 135 200
Total 100 300 400
135*3=
405/200=2.025
It works 🎉🎉🎊
tysmm .close
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What do I do next?
Here notice that $\frac{7t-3}{9-t^2}=\frac{7t-3}{(3+t)(3-t)}$
Ciceròn
yea?
where's arcsin coming from
@mental wagon Has your question been resolved?
but you don't have a square root there
then what do i do
use the top most formula from here?
,w integrate (5t^2 -3t +18)/(t(9-t^2))
,w definite integral of (5t^2 -3t +18)/(t(9-t^2)) from t=1 to t=2
yeh, that's the end result of factorising/decomp/log integral
If the term hyperbolic doesn't ring a bell then I'd do what Ciceron suggested
ive never done hyperbolic sub
so i got no ide abt it
That's alright. Just trying decomposing this
<@&268886789983436800>
Did I do anything illegal
not you
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@polar chasm
Okay, so how did you get D?
i multiplied them with scalers ane tried to match it like for option a first element is 2 so i multiplied by -3 to third vector and add it with second so it gives
2-3+3
First element is matched but all others are different
yeah, but what if there were some other scalars, that would match them all?
you need to prove that though
and this is insufficient, this only shows that it doesnt work when the scalars are 1, 1 and -3
to actually prove that it's impossible (or find scalars for which it is possible), try setting up equation like this:
c1 * x + c2 * y + c3 * z = A
now if you can solve for c1, c2 and c3, then you have found your scalars
otherwise, if there is no solution, it must be impossible
btw this equation can be written either as a linear system, or in a matrix.
To write it in matrix, let the columns be x, y, z and the augmented column will be A
to write it as system of equations without vectors (with just 1D variables), we can focus on the individual entries of vectors x, y, z
for example first entries must match. So we get
c1 * x1 + c2 * y1 + c3 * z1 = A1
Since we know the first entries of x, y, z and A, we can actually simplify that.
2*c1 + 3*c2 + (-1)*c3 = 2
and we can get the other equations from other entries
e.g. with the 2nd entries we would get
1*c1 + (-1)*c2 + 0*c3 = 3
or we can simply write it in a matrix
MæthIsAlwaysRight
I hope I transcribed it correctly, the columns should be x, y, z and the last one is A
looks right
@spring oak Are you here? I'll have to go soon, so i'll just leave this here for you to read. I hope you can solve it with that
solutions to this will be the scalars btw
if there are no solutions, then A is not in the span of x, y, z
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<@&268886789983436800>
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1259137319714291786
(there was a 1 + 1 question, OP deleted it)
OK
I DRINK RADLER
GERMAN BEER
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this might be the hardest question in the century i can't solve this for hours...
what have you tried?
