help-27

[marsh coral]

Wait

[surreal night]

so whenever we something as x^2+2ax, we know that we can complete it with (x+a)^2-some constant

[marsh coral]

So (x + a)^2 = x * x + a * a?

[surreal night]

no, (x+a)^2=(x+a)(x+a)=x*(x+a)+a*(x+a)=x*x+x*a+a*x+a*a=x^2+2ax+a^2

[marsh coral]

Oh multiplied by

[surreal night]

$(x+a)^2=(x+a)(x+a)=x*(x+a)+a*(x+a)=xx+xa+ax+aa=x^2+2ax+a^2$

[woven radish]

Flappie

[surreal night]

so, whenever we see something like x^2+8x

we can complete it by (x+4)^2

• some constant

[surreal night]

*for compensation

[marsh coral]

✅

[surreal night]

so, in your question we have 3x^2+6x

how can we complete the square

[marsh coral]

Is it always 4 (before I solve)

[surreal night]

no, its not

for that example x^2+8x its 4

[marsh coral]

Oh ok js making sure

[surreal night]

because 4=8/2

8=2a

4=a

[marsh coral]

Oh wait

So you grouped the x terms then simplified?

[surreal night]

im not sure what you mean by simplified

i completed the square

let me give you another example

x^2+5x+25/4

how would you complete the square here

dont worry about being right or wrong

[marsh coral]

Umm

Lemme get paper

[surreal night]

look at 5x

take the 5

[marsh coral]

Would it be

[surreal night]

and divide it by 2

(x+5/2)^2

is completing the square

do you see that connection?

[marsh coral]

(x + 5/2) ^ 2

Yeah I was getting there I js type slow

[surreal night]

np

[marsh coral]

Yeah

[surreal night]

alright great

[marsh coral]

Wait so basically

You have like say

[surreal night]

x^2+bx can be completed by just taking b/2

[marsh coral]

x^2 + 12x + c

You would divide the 12x by some number?

How would I know what number to divide by

[surreal night]

divide 12 by 2

[marsh coral]

Oh so it’s always divided by 2?

[surreal night]

yes

for completing the square

[marsh coral]

Got it

[surreal night]

yes

[marsh coral]

I get it now

[surreal night]

great

so lets look at your function again

3x^2+6x-17

[marsh coral]

So y = 3x^2 + 6x - 17

Finding the square ewould be

[surreal night]

so, we first need to do something to this before we can complete the square

in our previous examples, we've had x^2

but here we have 3x^2

[marsh coral]

Divide the 3x by 3?

[surreal night]

kind of

i would factorise it

3x^2+6x=3(x^2+2x)

[marsh coral]

Oh yeah I did that on my paper

[surreal night]

now inside the brackets we have x^2

which is what we want

so, complete the square with x^2+2x

[marsh coral]

With the distribution or just that

[surreal night]

completeing the square just like we did before

[marsh coral]

K so

[surreal night]

x^2+2x=(x+?)^2+?

[marsh coral]

(x + 2x/2) ^ 2

Oh wait lemme put the divided by 2 I think I solved it

Like that?

[surreal night]

where did you get the -17 from?

we are onyl looking at x^2+2x

[marsh coral]

Oh

Mb

[surreal night]

(x+1)^2=x^2+2x+1, right?

[marsh coral]

So this (x + 2x/2) ^ 2

[surreal night]

simplify your 2x/2 please

also, its not 2x/2

its 2/2

[marsh coral]

Oh

[surreal night]

only take the factor

[marsh coral]

So just 2

[surreal night]

2/2

[marsh coral]

Wait no

1 ^ 2 is 1

So just one

[surreal night]

expand (x+1)^2

[marsh coral]

This is the part that I find confusing

Because I would think that (x + 1) ^ 2 would be (x + 1)(x + 1)

But idk if that’s right

[surreal night]

thats right

[marsh coral]

Oh nvm

[surreal night]

but expand it further

so there are no brackets

[marsh coral]

x^2 + 1

[surreal night]

no

$(x+1)^2=x^2+2x+1$

[woven radish]

Flappie

[surreal night]

do you understand this?

[marsh coral]

Yes

[surreal night]

so, then do you also follow that $x^2+2x=(x+1)^2-1$?

[woven radish]

Flappie

[marsh coral]

Oh they r equal

Lemme go back up

[surreal night]

we moved the 1 to the other side

this is how we have completed the square

[marsh coral]

Which one

[surreal night]

we turned x^2+2x into something squared + some constant

[marsh coral]

We moved the the 1 in the parentheses?

[surreal night]

what?

[marsh coral]

😭 (I’m sorry this must be so annoying)

[surreal night]

its alright

i am out of time though

dinner is ready

[marsh coral]

Ok

I’ll just try to rewatch the videos

[marsh coral]

For this are both ?’s the same number?

I got (x + 2x/2) ^ 2 - 8 —> 2x^2 - 8

<@&286206848099549185>

Is this right?

[cinder wyvern]

2x^2-8

@marsh coral

thats right

[marsh coral]

Ok

Ty

Now I need the next steps

Now I plug it back in?

So y = 2x^2 - 8 - 17 ?

[cinder wyvern]

just tell me what was your steps before this answer

[marsh coral]

Lemme scroll up and copy paste it

[cinder wyvern]

waiting

[marsh coral]

Consider the parabola y = 3x^2 + 6x - 17:
a) Write the equation for the axis of symmetry
b) Find the coordinates of the vertex of the graph of the parabola
c) Identify the vertex as a maximum or minimum
d) Graph the parabola

I am not very good at parabolas so I am kinda lost. But I did try using a perfect square.

Is the question

[restive river]

ok first what's the vertex?

[marsh coral]

I haven’t got there yet

[restive river]

remember axis of symmetry is just "x = the x coordinate of the vertex"

[marsh coral]

Waitttt

[cinder wyvern]

i can answer all questions on the paper just a sec

[restive river]

!noans

[devout snow]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[restive river]

ok chidu the first step is to find the vertex

[marsh coral]

Oh wait

I’m so so sorry

I mixed up the problems

[restive river]

it's ok

[marsh coral]

My first step was factorizing 3x^2 + 6x and I got 3(x^2 + 2x)

[restive river]

bro you don't need to factor it yet

just find the vertex

[marsh coral]

I was listening to the other guy

[cinder wyvern]

oh ok

[marsh coral]

Ok I’ll just restart

[restive river]

wait

wait

did you answer any of them yet

[marsh coral]

No

I first had to learn how to do perfect squares

[cinder wyvern]

if u want to get first answer

you will need to get vertex

[restive river]

the vertex lets you do a, b, and c

[marsh coral]

ok so

[cinder wyvern]

and it will be (-1,-20)

[restive river]

BRUH

DON'T GIVE THE ANSWER

[marsh coral]

why are you giving me answers ._.

but where did that come from?

[restive river]

calculate it

[cinder wyvern]

i will explain sorry

[restive river]

yk the formula for vertex?

[cinder wyvern]

do you know -b/2a

[marsh coral]

now i do

[restive river]

yeah

the x coord is -b/2a

then plug that into the equation to get the y coord

this will give you b!

[cinder wyvern]

and the y coord will be f(-b/2a)

[restive river]

bruh

[marsh coral]

my brain is malfunctioning

[restive river]

no garuntee he knows what that means, functions were introduced after quadratics for me

[cinder wyvern]

huh

[marsh coral]

i dont know what it means (i came from a behind school and then i got into a rigorous school and the curriculum jumped up)

[restive river]

dw

[marsh coral]

i took a placement test and got put in Algebra 2 and i am lost in basically every concept it has

[restive river]

ok so what's the vertex

[restive river]

ahh

happens a lot

ok i can help you with this stuff

[cinder wyvern]

you just know vertex formules

[cinder wyvern]

damn

[marsh coral]

no

i didn't even know that

[restive river]

see?

[cinder wyvern]

its okey dw easy a lot

[restive river]

not everyone is cracked at math bruh

[marsh coral]

real

[restive river]

ok so

[marsh coral]

so lemme reprocesses this

wait

[cinder wyvern]

first u need to know the equation

[marsh coral]

so im starting with

y = 3x² + 6x - 17

how do i implement that into the vertex formula

[cinder wyvern]

ax^2+bx+c this is our equation right?

[marsh coral]

can u like pop out its kinda confusing having 2 people tell me 2 different things and the other guy was here first

oh wait no he wasn

[cinder wyvern]

thats right i will go

[restive river]

ok so

[marsh coral]

but i find his instructions more clear

[marsh coral]

listening

[restive river]

the general form of any quadratic equation is ax^2 + bx + c

[marsh coral]

define a and b

[restive river]

what's your equation again

[marsh coral]

oh wait

nvm

[cinder wyvern]

i'm glad if I could help you a little if I could

[marsh coral]

👍

y = 3x² + 6x - 17 so a = 3 and b = 6

[restive river]

yesss

ok so whats -b/(2a)

[marsh coral]

-6/(2*3) is -1

[restive river]

good good

now evaluate the equation for x = -1

[marsh coral]

brutha what 😭

oh nvm

y = 3 * -1² + -6 - 17 so 3 * 1 + -6 + -17 = -20

[restive river]

yes

so your vertex is (-1, 20) right

[marsh coral]

ohhhhh

i got it

and then -20 is y

so (-1, -20)

[restive river]

yes

this is the answer to b!

[marsh coral]

so that would be the answer to b

[restive river]

ok now we're gonna do a

it's really simple

[marsh coral]

kk

[restive river]

the axis of symetry is the equation of the vertical line that cuts it in half

it's just "x = the x coordinate of the vertex"

[marsh coral]

so -1

[restive river]

yes

a is "x = -1"

perfect now c

[marsh coral]

mhm

what is max and min

[restive river]

gonna mark this rq

[marsh coral]

for parabolas

[restive river]

ok

if a is positive the vertex is the mininum point of the quadratic equation right

the y coordinate of the vertex is the smallest value that can be outputted

(note that in algebra 2 this becomes false)

[restive river]

but this is only true if a is positive

if a is negative then it's the maximum value right

[marsh coral]

wouldn't it just be minimum then since a = 3 and 3 is a positive number

[restive river]

yes

good job

is this summer hw btw?

[marsh coral]

yes

[restive river]

ok

and you're taking algebra 2 next year?

[marsh coral]

gotta answer 25 algebra 2 math questions and read 2 books before school year starts (i just got into the school and they already making me do this)

[restive river]

did you skip geometry?

[marsh coral]

this coming school year yeah

[restive river]

did you skip algebra 1?

[marsh coral]

i never even took algebra 1 i just got put in algebra 2 based on my performance

[restive river]

ok do you know how to graph a quadratic equation?

[restive river]

bruh school system is bad

[marsh coral]

ngl it might lowkey just be because i have good luck

[restive river]

lol

was it iready?

[marsh coral]

i solved on all the questions ik how to do and then just guessed

no

it was a google form with 50 questions

[restive river]

oh

how many answers each?

[marsh coral]

the placements were Algebra 1, Algebra 2 and AP Algebra 2

some were exact answers and some were 4 mca's

[restive river]

does your school have geometry?

[marsh coral]

the one im leaving or the one im going to

[restive river]

ok back to the question at hand

[marsh coral]

yeah

[restive river]

do you know how to graph a quadratic?

also feel free to dm me about these other problems, i can help you understand the concepts

[marsh coral]

ok ty!

and uhhhhh

khan academy can teach me

in like 4 minutes

[restive river]

yeah but if you ever need help with understanding the concepts

[restive river]

?

[marsh coral]

i mean unless u wanna walk me through it

do i need graph paper?

[restive river]

i will do that

[restive river]

probably a good idea

was it provided?

[marsh coral]

nope im writing on my personal notebook

[restive river]

ok

[marsh coral]

but i can get a sheet of graph paper

and attach it to my note book

[restive river]

yeah do that

[marsh coral]

cuz im tired of doing this bs of drawing the most crooked handdrawn graphs

[restive river]

then make a 20x20 box and add the x and y axis and make the marks and all that

or 10x10

[marsh coral]

does the scale have to be 1?

[restive river]

just make sure it's even

[restive river]

i generally do increments of 1

but for this problem

[marsh coral]

ok

[restive river]

do increments of 2 on a 20x20 box

[marsh coral]

ima ask my mom for graph paper

brb

[restive river]

actually do increments of 4 every other square

because it makes the numbers easier to read

[marsh coral]

hold on ima just send a picture

oh wait nvm

i get it

ima ask for graph paper tho

[marsh coral]

its labeled now

[restive river]

ok

now put the vertex on it

[marsh coral]

y'know pondering on it now i really had enough space to do a 1 scale-

the graph big as hell

[restive river]

yeah

[marsh coral]

ima change it to a 1 scale

and label it every other one

[restive river]

ok

[marsh coral]

ok

its labeled by 1

now graph the vertex

[restive river]

nice

now put the vertex

then the hard part which is solving it

[marsh coral]

crap

UGHHHHH

i forgot to put negatives 😭

[restive river]

3x^2 + 6x - 17 right

[marsh coral]

yes

[restive river]

lol

[marsh coral]

hold on lemme fricking redraw this whole a- graph again

and rip this paper off

[surreal night]

still on this?

[restive river]

yes

why did you have him solve it

apparently

[marsh coral]

ight im done labelling the points

[restive river]

nicee

ok

now solving the equation

well it's not factorable

[marsh coral]

ok i plotted the vertex

[restive river]

ok this is called the quadratic formula

x = $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

[woven radish]

speedydelete

[marsh coral]

is there something missing here?

[restive river]

yes this is fr

i fixed it

[marsh coral]

does that sign to the right of -b mean plus or minus

[restive river]

yes

this finds x where ax^2 + bx + c = 0

always

i can show you why it works if you want

[surreal night]

question c asks about the vertex, so it would be easiest to rewrite it as vertex form, which you can do by completing the square

[restive river]

oh right

ok so

[marsh coral]

thats where me and him left off last

[restive river]

we're not gonna use that formula

so the vertex is (-1, 20)

[marsh coral]

i got (x + x)^2 + -8

[restive river]

now any vertex is of the form (h, k)

now here's another magic thing

if (h, k) is the vertex of the quadratic equation, then you can rewrite it as

a(x - h)^2 + k

where a is the original value of a

[marsh coral]

what is h

[restive river]

the vertex is (h, k)

so h = -1 and k = 20

[marsh coral]

oh ight

so

3(x + 1)² + 20

[restive river]

yes

3(x + 1)² + 20 = 0

solve this

[marsh coral]

thats a zero?

oh im tweaking

[restive river]

you're solving the equation

also which problem is this in the 25 problem sheet

[marsh coral]

how do you expand (x + 1)²

[marsh coral]

its problem number 11

i was able to solve the first 10 on my own

[restive river]

ok

[restive river]

what do you currently have

[marsh coral]

i was trying to solve it but my brother is nagging on my shoulder correcting my work so i have nothing cuz he keeps on saying its wrong

3(x + 1)² + 20 = 0

but i have a question

in 3(x + 1)² do you distribute 3 or do the exponent first

[surreal night]

PEMDAS

[marsh coral]

right...

so (3x + 3)² ?

[restive river]

no

no

so you have 3(x + 1)^2 = -20 right

divide both sides by 3

[marsh coral]

no

[restive river]

you get (x + 1)^2 = -20/3

[marsh coral]

wait im confused

[restive river]

you don't distribute the 3 lol

[marsh coral]

is the equation 3(x + 1) ^2 = -20 or 3(x + 1)² + 20 = 0

[restive river]

it doesn't matter they mean the same thing

[marsh coral]

but ik what to do now

ok

im gonna solve the first one

[restive river]

yeah

divide both sides by 3

[marsh coral]

3(x + 1) ^2 = -20
/3 /3
(x + 1)² = -20/3
x² + 1 = -20/3
-3/3 -3/3
x² = -23/3
sq root sq root
x = 1.59861051 i

[restive river]

yk what complex numbers are?

thats wrong lol

(x + 1)^2 = x^2 + 2x + 1 not x^2 + 1

ok so

you have (x + 1)^2 = -20/3 right

so then

you take the square root of both sides!

[marsh coral]

i did

oh wait

you take the sq root of both sides in that state?

[restive river]

now you have $x + 1 =\pm\sqrt{\frac{-20}{3}}$

[woven radish]

speedydelete

[marsh coral]

ohhhhhhhhhh

you know that makes a lot more sense

[restive river]

you do the plus minus because squaring produces the same output

can you solve it now

[marsh coral]

i can solve it now but i just need one more thing to know

can u use plus/minus in another example?

[restive river]

sqrt(-20/3) = sqrt(-20)/sqrt(3) = sqrt(-20)sqrt(3)/3 = sqrt(-60)/3 = sqrt(60)i/3

uh sure

yk what absolute values are

[marsh coral]

yes

oh so just that

[restive river]

yess

[restive river]

do you get this too?

[marsh coral]

the av value and the non av value

[restive river]

yes

[marsh coral]

lost me after the 2nd = sign

waot wait

nvm

hold on

[restive river]

$x = \pm \ |x|$

[marsh coral]

when it says sqrt(-20)sqrt(3)/3 wouldn´t you multiply it by 3

[woven radish]

speedydelete

[marsh coral]

instead of divide by 3

[restive river]

no no no

for some reason

well ik the reason

[marsh coral]

why are we double dividing?

[restive river]

teachers won't give you credit if there are square root signs at the bottom of fractions

[marsh coral]

🤦

[restive river]

so i multiplied both sides of the fraction by sqrt(3) to remove it

[marsh coral]

wait so

hold on

so what im understanding

sqrt(-20/3) = sqrt of them individualy and those become two separate parts so when u seperate the 3 from -20 it becomes its own thing so dividing it cancels it?

oh wait

yeah i get the equation now

[restive river]

yeah

i'm just simplifying it

[marsh coral]

ye ye ye

so now what do i do with it

[restive river]

simple

so you have

$x + 1 = \frac{\sqrt{60}i}{3}$

[woven radish]

speedydelete

[restive river]

so now just subtract 1

actually that's not in simplest form

60 = 4*15 right

so sqrt(60) = sqrt(4)*sqrt(15)

[marsh coral]

oh ok

yes

[restive river]

use exact solutions unless the problem demands numerical ones

your answer is

[marsh coral]

ight

[restive river]

$x = \pm \frac{2\sqrt{15}i}{3} - 1$

[woven radish]

speedydelete

[restive river]

good job

lol

now you can't mark those points on the graph of course

[marsh coral]

this the last step holy

3 hour math problem 😭

[restive river]

so just evaluate the function for different points

-2, -3, ...

and 0, 1, ...

[marsh coral]

plug in random x values?

[restive river]

and mark those

then connect the dots

you're done then!

[marsh coral]

i gotta plug in random x values?

[restive river]

again dm me if you want to understand concepts i will answer much faster than this place generally

[restive river]

just do integer values

[marsh coral]

so 1 2 3?

[restive river]

vertex is -1 right

and 0

and -2, -3, ...

[marsh coral]

-1, 0, -2, and -3?

substitute those in for x and solve the equations then label it?

on the graph?

ight ty

i wanna leave the channel open tho so i can look back

[restive river]

just remember it's help-27 and scroll up

!dond

!done

[devout snow]

If you are done with this channel, please mark your problem as solved by typing .close

[restive river]

i gtg

[marsh coral]

ight bye

[surreal night]

you got it?

[marsh coral]

yup yup

ty

.close

[devout snow]

Channel closed

Closed by @marsh coral

Use .reopen if this was a mistake.

[surreal night]

nice

[marsh coral]

i got it i dont need anymore help im just looking back at the channel to find one last hting

i think me and you are both over this 💀

[surreal night]

im chillin

[marsh coral]

ight

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dim halo]

is the following true? if Pr(~A) > Pr(~B), then Pr(A) < Pr(B)

[dense lynx]

Pr(A) + Pr(~A) = 1

[dim halo]

I know, but I'm trying to figure out the proof

The formal derivation

[devout snow]

@dim halo Has your question been resolved?

[devout snow]

@dim halo Has your question been resolved?

[safe jasper]

that’s pretty much exactly what you need for the proof

P(~A) = 1-P(A), so your P(~A) > P(~B) turns into 1-P(A) > 1 - P(B)

very straightforward to get your conclusion from the hypothesis

[devout snow]

@dim halo Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ashen mortar]

Im confused what it wants.

[devout snow]

@ashen mortar Has your question been resolved?

[devout snow]

@ashen mortar Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[faint gorge]

,,G = \big { \vec{x} \in \mathbb{R} : : : x^2+y^2=(2(2-z))^2, 0\leq z \leq 1 \big }

[woven radish]

𝔸dωn𝓲²s

[faint gorge]

My question is this

I have first to give context

Basically this is a frustum of a cone

and I need to find a parametrization for the "lateral surface area"

the blue

and I first used cylinder coordinates

to describe the whole surface

,,K : \begin{pmatrix} r \cos\theta \ r\sin\theta \ z \end{pmatrix} = \begin{pmatrix} r \cos\theta \ r\sin\theta \ 2-\frac{r}{2} \end{pmatrix} \quad \theta \in [0, 2\pi], : r \in (0, 2(2-z)]

[woven radish]

𝔸dωn𝓲²s

[faint gorge]

acshually

yea so to continue

The "lateral surface" in the solution is $$\vec{x}_L = \begin{pmatrix} 2(2-z) \cos\theta \ 2(2-z) \sin\theta \ z \end{pmatrix} \quad \theta \in [0, 2\pi], : z \in [0,1]$$ but I wanted to ask if my parametrization is also fine

$$\vec{x}_L = \begin{pmatrix} r \cos\theta \ r \sin\theta \ 2- \frac{r}{2} \end{pmatrix} \quad \theta \in [0, 2\pi], : r \in [2,4]$$

[nova glen]

hmm i have a feeling this is a lot simpler

r = (2(2-z))^2, right? for example whats wrong with fixing z, getting the circumference of the circle and then integrating over z

[faint gorge]

I found my mistake

I need to plug in the bounds of z

for r

[woven radish]

𝔸dωn𝓲²s

[faint gorge]

yay

[faint gorge]

nothing wrong

i just want to explore things for the exam

that's how i tend to get a better understanding

it's because

when I use polar coordinates i am used to theta and r but now theta and z is a new thing

Like what I mean is $\vec{x}_L(\theta, r)$ is more familiar than $\vec{x}_L(\theta, z)$.

[woven radish]

𝔸dωn𝓲²s

[faint gorge]

thanks

no problem

.solved

[devout snow]

Channel closed

Closed by @faint gorge

Use .reopen if this was a mistake.

[nova glen]

ah okay i see

you were trying to parameterize, not just compute it

mbmb

glad you figured it out

[faint gorge]

yea

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid estuary]

we only need 3 points to find the area right, does it matter which 3?

[vivid estuary]

imagining a parrallelogram if I choose the furthest points away from each other and another point would the cross product of that still be the area?

[soft nest]

Yeah I think so, just remember your right hand rule stuff

Ah you probably want ad in that case right?

[violet wind]

so let's call the other side AD

AC is AB + AD

[soft nest]

Ab and bc should work though

[violet wind]

AB × AC
= AB × (AB + AD)
= AB × AB + AB × AD
= 0 + AB × AD
= AB × AD

So it does not matter which 3

You can also draw the parallelogram associated and see that the area they share is half of both of them

[vivid estuary]

oh ok thank you

.close

[devout snow]

Channel closed

Closed by @vivid estuary

Use .reopen if this was a mistake.

[violet wind]

np

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lusty sapphire]

screenshots please

[glossy owl]

I'm not sure if those are blurry, here's them indivudally

[devout snow]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[faint zinc]

Reopening for you @glossy owl #help-27 message

[glossy owl]

thank you, my bad

[faint zinc]

Major problems:

Problem 2 you prove something completely wrong.

Minor quibbles:

Problem 1 part 1, you have a latex typo, /in should be \in

Problem 2 you have a ~ x and bx but you probably mean b ~ x as well.

I've only gone through problem 2 so far

[glossy owl]

I have the quibbles fixed no worries, these are screenshots before the read through on typos.

[faint zinc]

In 2, you are supposed to prove [a] cap [b] = {} OR [a] = [b]

Instead you say [a] cap [b] = {} implies [a] = [b], which is almost the opposite

[glossy owl]

Okay, I'll work on that.

[faint zinc]

Anyway, I'm going to close this, reopen this channel after if you can

.close

[devout snow]

Channel closed

Closed by @faint zinc

Use .reopen if this was a mistake.

[faint zinc]

@glossy owl ^

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glossy owl]

.reopen

.reopen

/reopen

[glossy owl]

If someone could check over these proof for Analysis I I would really appreciate it.

I redid 2

[storm gyro]

This solution for 2 suffices, with some weird phrasing in places but still perfectly clear.

For 1), i don't quite know if you've already shown something in class that makes this make sense but it seems like you assume in the => direction that being bijective implies being invertible (line 4 of the proof) which is kinda what you're trying to prove here in the first place

I haven't read through all of 4 and checked the specific math but the idea is right. i assume you have a LaTeX typo in the second to last line though where it says p \in s_{?3}

5. is great, aside from a \in typo early on

[glossy owl]

I fixed all the typos, no worries. For 1) what would I change?

Do I just take out the invertible and try to prove it later on>

[storm gyro]

Up to the blue line is okay, you've defined g in the right way, but the way you show that its the inverse is a bit unclear. For f(g(y))=y for y in Y, g(y):=x s.t. f(x)=y by your definition which you've explained well enough, but you also should show that g(f(x))=x for x in X, for which you can say: let f(x)=y, so that g(f(x))=g(y)=x

Both of these things are basically just "it falls out of the definition" but you really need to explicitly state that f(g(y))=y and g(f(x))=x and why it follows from your definition of the function.

The thing after the blue line just doesn't really make sense, I think its supposed to be like a concluding statement for your proof, but it reads as another step. After showing the two things I said above, you are done.

[glossy owl]

Okay, sounds good. Thank you

.close

[devout snow]

Channel closed

Closed by @glossy owl

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[devout snow]

@inner bough Has your question been resolved?

[devout snow]

@inner bough Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

Hi probably a dumb question but i need a sanity check lol

[restive river]

“x is a function of y. When plotted in the xy-coordinate plane, the function g(y) intersects the y-axis twice.” We want to roughly show that the number of intersection point between g(y) + 1 is in {0,1,2} and thus can’t be uniquely determined. “

Some tutor posted this solution, isn’t this just wrong?

It’s not even a function in (y) to begin with, no?

lol

[wise storm]

the tutor flipped the x and y axes so it would look like a function in x you're used to dealing with

[restive river]

Ohh, I didn’t realize that

Well is that the optimal way to do it?

What would you have done?

[wise storm]

yeah that's what I was thinking to do before you posted the picture

I'd say it looks good and makes sense to me, if you have any other doubts I can try to help on this

[restive river]

It makes sense to me now, I think i didn’t notice his new definition of a coordinate system, but hmm wait

what if i was working in x-y instead of y-x

is that just a 90 degree clockwise rotation of the parabola?

it got me thinking how + 1 translates there

[wise storm]

not quite, it'll actually look like a reflection through the diagonal line y=x

https://www.desmos.com/calculator/hrhi0qwr1w

maybe this helps to see

[restive river]

So basically you’re tryna plot an “inverse function” of sorts?

[wise storm]

yeah sort of, except it won't be an inverse usually speaking

[restive river]

right cuz the original function isn’t objective?

bijective*

[wise storm]

like you can see how it doesn't pass the vertical line test (or horiztonal line test if you're looking at it the other way)

yeah

[restive river]

okay okay i see, but wait how does the “+1” translate in the side way version of the parabola?

it isn’t clear to me the +1 pushes it to the right

well if u swap the x and ys then it becomes intuition but otherwise no

g(y) is a sideway parabola so g(y) + 1 is a sideway parabola shifted 1 unit to the right?

oh + 1 means move 1 unit in the direction of positive x?

[wise storm]

yeah the +1 is moving it up cause now it's x=g(y), so now that we've swapped the axes in the picture it looks like y=g(x)

and so +1 is doing y=g(x)+1

[wise storm]

exactly

[restive river]

ah cool, final thing which probably has to do with the phrase of the question but:

“x is a function of y” and how exactly does that line alongside the last one translate to x = g(x) + 1

[uncut crow]

hi kiz

[restive river]

hii wait

sharp?

ohh you’re layla! hi hi

[uncut crow]

no that’s my bf

[wise storm]

it won't be x=g(x)+1

[restive river]

sorry i mean x = g(y) + 1

[restive river]

[wise storm]

when we flip the x and y axes in the picture, it's the exact same thing as if we switch the variables y = g(x) +1

idk if that's sort of the thing you're thinking about or something else

[restive river]

well uh i was thinking about something like:

“x is a function of y…the function g(y) + 1” -> how does that translate to like x = g(y) + 1

so normally you have that y is a function of x

and this is just the “opposite”

so instead of y = g(x) + 1 you have x = g(y) + 1?

[wise storm]

x is a function of y means we can pick any value of y and plug it in to get a value of x out

for instance x = y^2 you could pick y = 2 and get x=4 out

or put in y=-3 and get x=9 out

you can't necessarily do the same the reverse way, since if I give you x=4 you can't tell me if that came from y=2 or y=-2, so in this example y is not a function of x

[restive river]

sure okay makes sense, cuz the sideways parabola isn’t even a function

okay okay thanks

[wise storm]

yup you got it

you're welcome

[devout snow]

@restive river Has your question been resolved?

Channel closed

Closed by @frozen fossil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[true crag]

Hello there!

[true crag]

I just had a question with this problem

This is what I did and I was wondering if I messed up anywhere

[neon acorn]

sorry, what is the problem?

[true crag]

I was wondering if my work was correct

[true crag]

Here ^

[neon acorn]

no like what are you trying to prove

the screenshot you sent doesn't have a prompt

[true crag]

Oops I thought I sent it to you

[neon acorn]

ah ok, gotcha

[neon acorn]

yeah this looks good

[true crag]

Thank you very much

I was worried I got it wrong somehow

Have a nice day

.close

[devout snow]

Channel closed

Closed by @true crag

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fading plover]

Susan is writing a novel that will be 950-pages long when finished. She can write 10 pages per day on weekdays and 20 pages per day on weekends. I am trying to find the least number of days it would take her.
Here is my calculation. I got 72 as my answer, however the correct answer is 73. I am not quite sure where I went wrong there

[fading plover]

Oh 950, not 920. Lol

I'm getting 74 now rounded up instead of 73. Am I doing anything incorrectly?

[topaz axle]

this works if you must start on monday

you should calculate it as if you need to write 910 pages

or maybe that won't work still

73 is correct

[fading plover]

So I cannot do it as a single algebraic expression?

[topaz axle]

i don't think so

[fading plover]

Aha, that's good to know. So I can at least avoid making the mistake in the future. I am guessing the better way is to compute it only a weekly basis and see where it breaks off

Thank you 🙂

.close

[devout snow]

Channel closed

Closed by @fading plover

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

Is there a way where we don't use inequalities

[frigid jetty]

Why not

[iron sun]

You’ll have to use monotonicity for integrals one way or another

[restive river]

Can we solve the integration ?

[iron sun]

Oh welp yeah if you want lmao

But that’s not needed, you’ll find that the inequality way is a lot friendlier

[restive river]

yes,but its hard to reccognize that this can be solved that way

that's the reason

[iron sun]

I see, well I guess option d) is really the only one you’d have to check separately

The other three options can be done swiftly-ish if you did it the inequality way, i.e using monotonicity arguments

[restive river]

monotonicity arguments?

[iron sun]

You kept using the word inequality, what’s that process? Since that’s what I’m referring to read my comment again

[restive river]

This is what they(solution) did
For x ranging between pi/4 and pi/2
sinx > cosx

[iron sun]

Yes

[restive river]

And from here on they started building the function inside the integrations

[iron sun]

Yup

This is the simplest way

[restive river]

Is there an intuitive way ?

[iron sun]

For understanding the inequalities?

[restive river]

no,for solving this question

[iron sun]

I guess you could just draw the graphs of the integrands

[restive river]

oh my

[iron sun]

Lmao understating the inequalities would be solving the question

I’m telling you, that’s the most direct and easy way of going about this

[restive river]

Okay

Thank you

[iron sun]

I could help you understand the inequalities, that’s the key here

[restive river]

I am good with ineequalities,its just not the method i prefer to use while solving because i tend to make a lot of silly mistakes

[lost laurel]

try graphing the two functions and visually comparing the areas

[restive river]

1Graphing is way worse, i am more comfortable with inequalities than graphs

[wise storm]

since they're exponentials they're all positive, and you can compare the functions directly since one is the reciprocal of the other

[restive river]

Okay

[iron sun]

You should start investing more time to get used to them, it’s really useful

[restive river]

Okay,i will

Thanks everyone!

.close

[devout snow]

Channel closed

Closed by @hot vortex

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet wind]

that can't be an actual question

I don't think this can be "solved"

[devout snow]

@restive river Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tight saffron]

Hii! Can someone explain this question to me?

[lost laurel]

do you know of any theorm that relates the angle subtended by an arc at the centre of a circle to that subtended at the vertex

[tight saffron]

Umm no I don’t think so 🤔 (English is not my native language maybe I understood your question wrong)

[lost laurel]

one minute

The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.

[tight saffron]

Ooh!

[lost laurel]

so what is angle AOC

[tight saffron]

So I have to multiply it by two?

And that’s 116?

[lost laurel]

yes!

now for the next question

do you know what the sum of opposite angles of a cyclic quadrilateral is

[tight saffron]

Nope sadly no

[lost laurel]

do you know what a cylic quadrilateral is

[tight saffron]

I don’t even know what a cyclic quadrilateral is?

[tight saffron]

Oh no

[lost laurel]

,w cyclic quadrilateral

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by physicsrocks

[lost laurel]

basically a quadrilateral inscribed in a circle

[tight saffron]

Ooh!

[lost laurel]

the opposite angles add up to 180deg

so here B+D=180

[tight saffron]

So when B is 58 then D is 122

[lost laurel]

I think so too

[tight saffron]

Ok thank you so much!!

[lost laurel]

👍

[devout snow]

@tight saffron Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall stirrup]

sorry for bad image quality

[silver schooner]

cant see mate

[tall stirrup]

i got determinant to be p^3 + q^3 + r^3 -3prq = 0

[silver schooner]

ahh classic

[tall stirrup]

i factorised

and don't know where to go

[silver schooner]

a^3 + b^3 + c^3 = 3abc

then a + b + c = 0

its an identity or whatever u wanna call it

[tall stirrup]

yes, but these are moduli so it can't be true

[silver schooner]

oof complex?

oh wait

then they all just zero?

[arctic field]

theres another factor

[tall stirrup]

no

[arctic field]

(p - q)^2 + (q - r)^2 + (r - p)^2 = 0

[tall stirrup]

i got 1/2((p - q)^2 + (q - r)^2 + (r - p)^2) = 0

so what next?

[arctic field]

so p = q = r

[tall stirrup]

how?

[arctic field]

p q r are real

[tall stirrup]

how to write it i mean

[arctic field]

sum of real squares = 0 forces all squares = 0

[silver schooner]

sum of squares = 0 means the numbers r 0

[arctic field]

[tall stirrup]

ok nice

so |u| = |v| = |w|

arg(w) - arg(v) = ???

what should i do next

[arctic field]

its just geometry at this point

[tall stirrup]

u, v and w lies on a circle

[woven radish]

Pro_Hecker

[tall stirrup]

$w = xe^{i\theta_1}; v =xe^{i\theta_2}; u=xe^{i\theta_3}$

[woven radish]

Pro_Hecker

[tall stirrup]

so what next?

i can't get any further

[arctic field]

its a geometry problem

the inscribed angle theorem

[tall stirrup]

oh so option (a)?

[arctic field]

yes

[tall stirrup]

thanks
.close

.close

[devout snow]

Channel closed

Closed by @tall stirrup

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen rivet]

multiplying a vector with a unit vector will just change its direction?

[keen rivet]

or rather

what happens if you multiply a vector with a unit vector

[pastel pasture]

"multiplying"

dot or cross

[keen rivet]

oh

dot

oh you again

hi

[pastel pasture]

Hello

Dotting with a unit vector doesn't really do much I mean

After you do it it's a scalar so there's no talk of direction

[keen rivet]

ohh right

[worthy girder]

dotting with the nth unit vector just gets you the nth component of your vector as a scalar

for instance, (1,2,3)^T . (0,1,0)^T = 2

[keen rivet]

wait how many unit vectors are there

[worthy girder]

ie. dot product with e_2 gives the 2nd component, etc

[keen rivet]

3?

[worthy girder]

depends what space you're in

[keen rivet]

so it just needs to have a magnitude of 1

[worthy girder]

$\mathbb{R}^3$ has 3 dimensions

[woven radish]

Bob Goldham

[worthy girder]

the plane (R²) has 2

[keen rivet]

so in 3d its
(1, 0, 0)
(0, 1, 0)
(0, 0, 1)

[worthy girder]

in euclidean spaces, the unit vector is the vector is the vector that is 1 in one component and 0 in all others

[worthy girder]

yes

in 5d it'd be (0,0,0,0,1) (0,0,0,1,0) (0,0,1,0,0) (0,1,0,0,0) (1,0,0,0,0)

[keen rivet]

wait ill prolly just follow this question up lol

[worthy girder]

(each transposed)

since we generally consider column vectors

[keen rivet]

a= any vector
b= unit vector

what would (a.b)b look like

like its just multiplied

theres no cross or dot

[worthy girder]

scalar multiplication yeah

[restive river]

Hi

[worthy girder]

if b is the nth unit vector, this operation basically sets all components of a except the nth component to 0

while leaving the nth component unchanged

[restive river]

Hi

[worthy girder]

a=(5,10,15)^T b=(0,0,1)^T would result in (0,0,15)^T

[restive river]

Hello

[keen rivet]

wait whats T?

[worthy girder]

transponsed

[keen rivet]

ohh

right i get it now somewhat lol

thanks!!

[worthy girder]

$\begin{pmatrix}
5\
10\
15
\end{pmatrix}$

[woven radish]

Bob Goldham

[keen rivet]

.close

[devout snow]

Channel closed

Closed by @keen rivet

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet wind]

Is $\bR$ the field of fractions of any of its proper subrings?

[woven radish]

thewizardofOU

[sand dove]

isn't Q the field of fractions of itself?

[violet wind]

yes

[sand dove]

oh you're asking if R can be the field of fractions of some subring

[violet wind]

yeah

[devout snow]

@violet wind Has your question been resolved?

[faint zinc]

Suppose there exists a field F such that Quot(F) = R. Then for all r in R there exists a, b in F such that a/b = r, which implies a = br. a = br is a member of F, and b is also a member of F, therefore, r is also a member of F. But r is an arbitrary real number, so every r is in F, so F is just R.

Or am I misunderstanding the question?

[violet wind]

right, which is why i'm asking about subrings

[faint zinc]

I guess you didn't specify that F is a division ring

[violet wind]

every proper subfield would be it's own quotient field

since fields are their own quotient fields

[faint zinc]

https://math.stackexchange.com/a/1397291/25445

(Solution spoilers, obviously)

[violet wind]

!nosols

[devout snow]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[violet wind]

[faint zinc]

[violet wind]

ah well rip

.close

[devout snow]

Channel closed

Closed by @violet wind

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis seal]

So i just finished my discrete math exam

[lapis seal]

And there was a question: is 125^125 divisibile by 81?

[ocean yacht]

so do you need the answer to it?

[tall stirrup]

just factorise 125

and factorise 81

[lapis seal]

I made it become 44^125 congruent to 0 mod 81

And then got stuck

[tall stirrup]

you'll see it's not possible

[ocean yacht]

oh

well by logic yes, you can factorise 125 = 5^3

[raw knoll]

it's not possible at all since you cant divide 125 by 3

[lapis seal]

And then I wrote that 44 = 4x11 and 125=3^4, so 44^125 will be some multiple of 4 and since 4 isn't a factor of 125, then 125^125 cannot be divisible by 81

Is this wrong?

Please tell me this is correct

[raw knoll]

you could just see the factors

[lapis seal]

Its probably wrong though

[raw knoll]

5^3 vs 3^4

For a number to be divisible by the other it needs to be a multiple

but (5^3)^whatever can never be a multiple of 3^4

[lapis seal]

Yes

[raw knoll]

^

[lapis seal]

So I just added another unnecessary step

[raw knoll]

it's all 5s

[lapis seal]

The one where I make 125 become 44

[raw knoll]

yeah lol

[lapis seal]

Anyway would you mark this correct or not?

[raw knoll]

it just isn't possible from the factors alone

[raw knoll]

I'm not a teacher 💀

[lapis seal]

Lol if you had to

Is my logic correct?

(Please say yes)

[raw knoll]

I think it shouldn't be wrong but I'm not sure if that's the concept they want you to use

good luck I guess lol

[lapis seal]

Yea probably not, atleast maybe I get some points and not 0

[lapis seal]

Thanks!!

[raw knoll]

you should get marks for getting the answer at least

[lapis seal]

I hope so

Thx for the answers

.close

[devout snow]

Channel closed

Closed by @lapis seal

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ancient basin]

Can someone explain to me question 35

[surreal night]

,rotate

[winter patrol]

for f(x)/g(x) to be defined
f(x) and g(x) need to defined
and g(x) can't be 0

[ancient basin]

<@&286206848099549185>

[surreal night]

!15m

[devout snow]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[modern nimbus]

I don’t feel like doing LaTeX

(1,5) if you can’t see it

Also it’s 1:43 in my timezone and i’m tired

[winter patrol]

!nosols

[devout snow]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.