help-27

[teal sierra]

!occupied

[devout snow]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

@grave tusk Has your question been resolved?

[grave tusk]

.close

[devout snow]

Channel closed

Closed by @grave tusk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[willow quartz]

Can anyone help with this?

[willow quartz]

im pretty sure im supposed to use the washer method?

[devout snow]

@willow quartz Has your question been resolved?

[willow quartz]

@fervent swallow Can I get some help?

[devout snow]

@willow quartz Has your question been resolved?

[willow quartz]

oh well

.close

[devout snow]

Channel closed

Closed by @willow quartz

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pale terrace]

yo

[safe fractal]

ey

[sullen island]

ay

[scenic herald]

Oi

[astral lotus]

sup

[vapid nest]

yo

[devout snow]

@pale terrace Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[weak python]

does anyone know how to do this? its trig

[frosty cradle]

you can multiply by the conjugate of the denominator

[devout snow]

@weak python Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[devout snow]

@restive river Has your question been resolved?

[devout snow]

@restive river Has your question been resolved?

[deft wadi]

yuhh

wassup my man

lemme take a look

first of all u here?

[devout snow]

@restive river Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz pendant]

If I'm doing an equation and I got -1.96 and the textbook answer is -1.97 am I wrong

[solid hull]

Depends on what type of question

If it involves rounding to significant figures etc then it can usually be fine (teacher dependent in my experience)

[quartz pendant]

Number 15

[frosty cradle]

,calc 0.11 / -3 - 1.93

[woven radish]

Result:

-1.9666666666667

[frosty cradle]

should round down to -1.97

[quartz pendant]

Okay

Thank you how do you close this channel?

[frosty cradle]

type .close

[quartz pendant]

.close

[frosty cradle]

without backticks

[quartz pendant]

. Close

Sorry

[frosty cradle]

no space, lowercase

[quartz pendant]

.close

[devout snow]

Channel closed

Closed by @quartz pendant

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vernal cave]

So my understanding of problems like this is that you have to do something like this:

$\pi\int_a^b{R(x)^2-r(x)^2dx}$

[woven radish]

Eyesonjune

[vernal cave]

However, this problem introduces an extra y-bound, whereas the example video my prof gave used an x-bound

Which made me automatically assume the right bound of the integral was the intercept of y=1 and x^4

(which is just 1, 1)

R(x) is a function of the distance from the axis of rotation to the origin, which should just be 5 here

making R(x)^2 = 25

[misty crest]

when you rotate about a vertical axis your functions need to be in terms of y

not x

[vernal cave]

isn't that a horizontal axis

[misty crest]

no

[vernal cave]

Should I solve for y first then

[misty crest]

because think about drawing a cross sectional rectangle

it’ll have a differential height dy

and the distance from the axis of rotation will be a horizontal distance

which will be x

and you will have x as a function of y

[vernal cave]

So how would I do this then

[misty crest]

solve for x

[vernal cave]

integrate from 0 to 3

[misty crest]

in terms of y

[vernal cave]

would it be like this

[misty crest]

oh wait

sorry

they wanted to rotate about y=5

my fault

ok so scratch that sorry

yes y=x^4

so

what’s the distance to the axis of rotation

for the outer radius

[vernal cave]

5?

I had to get a new problem because I tried to answer it again and it was wrong

Similar tho

So just say 2 then

[misty crest]

well the outer radius would be from y=5 to y=1

[vernal cave]

why

let me show you the video example rq

[misty crest]

because that whole region is being revolved

[vernal cave]

Are you saying that they want me to integrate the region above f(x) and below y=1

So it's effectively int1-f(x)

[misty crest]

for this problem?

[vernal cave]

yes

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by c.knief

[vernal cave]

I assumed they were only giving the y-bound so that I could get an x-bound from the intercept

[misty crest]

so to rotate about y=2 the radius from y=2 to y=x^4 is 2-x^4

does this make sense

[vernal cave]

yes

but what about the y bound in between

[misty crest]

thats where the other radius comes in

which is the distance from y=1 to 2

[vernal cave]

So my initial suspicion was that we could do this via a double subtraction

Was that correct

[misty crest]

by double subtraction do you mean using the R^2-r^2?

[vernal cave]

$\pi\int_0^1{2^2-(2-1)^2-(2-x^4)^2dx}$

[woven radish]

Eyesonjune

[vernal cave]

$\pi\int_0^1{3-(2-x^4)^2dx}$

[woven radish]

Eyesonjune

[misty crest]

i think you have the outer radius confused

why do you have 2^2 -(2-1)^2

[vernal cave]

Well I figure we want to exclude the region between 2 and 1, plus the region represented by the integral of f(x)

Actually this would be more like

$\pi\int_0^1{3-(x^4)^2dx}$

[woven radish]

Eyesonjune

[vernal cave]

in that case

Do you understand what I am getting at at least

[misty crest]

why exclude the region

between 2 and 1

that’s your outer radius

[vernal cave]

Because it's not part of the region you're trying to find the volume of?

[misty crest]

well it is no

you’re finding the volume when rotating the region bounded between x^4 y=2 and y=1

about y=2

[vernal cave]

are you saying we want to find this region?

[misty crest]

why didn’t you shade the left part

[vernal cave]

I thought we were doing this

[misty crest]

was that on purpose

ok yea

that

nevermind

[vernal cave]

Yes I think they want it to be for x >= 0 though they did not specify

[misty crest]

the outer radius

is the other one

2-x^4

but

you shouldn’t have

2^2

-…

it should just be R^2-r^2

where R=(2-x^4)

[vernal cave]

Is the inner radius the R

[misty crest]

and r=(2-1)

[vernal cave]

And the r is the outer radius

[misty crest]

inner radius is r

[vernal cave]

I don't get it

What region are we trying to find

[vernal cave]

Is it this one

[misty crest]

the one you shaded

[vernal cave]

Or this one

[vernal cave]

There are two

[misty crest]

here

[vernal cave]

Ok then

So let me try and explain my reasoning here and you can correct me when I mess up

The shaded region, ignoring the rotation about the axis, can be represented as such

$\int_0^1{1-x^4dx}$

[woven radish]

Eyesonjune

[misty crest]

oh btw

[vernal cave]

The region underneath that can be represented by

[misty crest]

make sure you include the left part

not just the part on the right

[vernal cave]

$\int_0^1{x^4dx}$

[misty crest]

it’s the entire region under y=1

[woven radish]

Eyesonjune

[misty crest]

but above x^4

not 0 to 1

[vernal cave]

I don't think it is for this problem as previously stated

[misty crest]

-1 to 1

[vernal cave]

I know it doesn't say but I think it's supposed to be from 0 to 1

[misty crest]

does it say x>0?

why do you think that

[vernal cave]

The example video given for this problem just infers x>=0

[misty crest]

that was a different problem

[vernal cave]

If it's not the case you can say I told you so

[vernal cave]

yes but they're supposed to be almost identical

[misty crest]

because it was bounded by the vertical line and the x axis

they’re not

[vernal cave]

Every other problem in this set has been x>=0

I think it's just a poorly-written problem

[misty crest]

the region bounded by y=1 and y=x^4 is the whole area

[vernal cave]

But anyway let's just say 0 to 1 and if it's wrong we can try doubling it later

it should just be a double at any point in the calculation because it is symmetrical

[vernal cave]

I get 3 tries per problem

So we have a little bit of leeway

[vernal cave]

So back to this

[misty crest]

mhm

[vernal cave]

We must exclude the area between 1 and 2, plus the area under the x^4 curve

[misty crest]

the integral from 0 to 1 of x^4 will give area under the curve not above it

[vernal cave]

That's what I said

[vernal cave]

^

[vernal cave]

^

We need the underneath region to exclude it from the volume

[misty crest]

no but the shaded is just top function - bottom function inside the integral from 0 to 1

it already subtracts it off

[vernal cave]

That's what I said

The top function is y=1

So it's 1-f(x)

[vernal cave]

as seen here

[misty crest]

ok

[vernal cave]

but this is helpful

So yeah I get what you mean

that being said I think we could get this one of two ways

The way I was thinking was to figure out the volume of a cylinder with a radius 2

Then subtract the volume of a cylinder with radius 1

Then subtract the volume of a cylinder with radius intx^4

That may not work tho

[misty crest]

ok but why are you getting cylinders with radius 2

to find the volume you use the washer method

it’s not a cylinder

[vernal cave]

A washer is just a cylinder with parts cut out lol

This might not be the right method but you do see what I'm getting at at least right

[misty crest]

yes but i think you’re thinking of it differently

[vernal cave]

Yes

Anyway

Let's do washer method

Can you explain where we go now that we know the function to use in the area integral is 1-x^4

[misty crest]

so the washer method is essentially just the disc method which i assume you’re familiar with and the premise of it is the find the volume of a solid rotated about the axis of rotation then to subtract off some inner radius now from the graph you can tell the outer radius would be the distance from y=2 to y=x^4 which we can label R and it will be R= 2-x^4 now if we found the volume of that it would be a disc but notice there is space between the axis of rotation and the curve y=x^4 for the bounded region so there would be a hole which is the volume found from revolving the inner radius about the axis of rotation where the inner radius is r=(2-1) now we just subtract the volume generated by the inner radius from what it would be had x^4 not been bounded to that region thus we get integral (R^2-r^2)

does this make sense

[vernal cave]

Sorry can you add punctuation I am having a hard time reading that

Not trying to be snarky just legit am a little braindead today

It's kinda late

[misty crest]

💀

which part is confusing

in short

[vernal cave]

the whole thing is one sentence

[misty crest]

subtract the volume generated by the inner radius from the volume generated by the outer radius

[vernal cave]

In the video it shows R as the outer radius and r as the inner

[misty crest]

which is what i used as well

R=(2-x^4)

[misty crest]

x^4 is farther from the axis of rotation

[vernal cave]

wdym

[misty crest]

like

[vernal cave]

It's closer

[misty crest]

no

y=2 is the axis of rotation

[vernal cave]

oh wait I see what you mean

[misty crest]

if it’s the region bounded by y=1

y=1 is closer

to y=2

than x^4 is

[vernal cave]

Can you write the resulting integral out in latex just so I can verify that I understand this correctly

[misty crest]

cant but i cant write it with wolfram alpha ig lol

[vernal cave]

is it

[misty crest]

,w integrate (2-x^4)^2-(2-1)^2

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by c.knief

[vernal cave]

ok

Let me try that

[misty crest]

and include your bounds of course

which are from -1 to 1

but you can do 0 to 1 first

if you don’t think so

[vernal cave]

you were right it was -1 to 1

[misty crest]

if it said bounded by y=1 and x^4 there is no reason to believe yea

because that part is also bounded by y=1 and x^4

[vernal cave]

ok

thanks

.close

[devout snow]

Channel closed

Closed by @vernal cave

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal laurel]

Mickey!

[royal laurel]

Mickey Mickey

[restive river]

what is your question?

[royal laurel]

If a function is twice differentiable

Does it means the degree of the function bigger than 2

Mickey

[teal perch]

Not really

[royal laurel]

Can f be a constant

[teal perch]

Yes

[royal laurel]

Why

Why

[teal perch]

Twice differentiable just means that second derivative exists

[misty crest]

it doesn’t have to be a polynomial

could be any other function

[teal perch]

e^x is a C^infinity class function

It is not a polynomial

But it is infinitely differentiable

[royal laurel]

I see

.close

[devout snow]

Channel closed

Closed by @royal laurel

Use .reopen if this was a mistake.

[royal laurel]

Thank you apple

And chief

[teal perch]

np.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid osprey]

there are a deck of cards from ace, 2, 3, ...., 10, adam and bob are playing a game where they lay out 4 cards and their goal is to add, subtract, multiply, divide them in order to get 24, and ace can be either 1 or 11, so like for example, if you get 2,4,5,10, you can do 2×5+4+10=24, is it true that in any 4 cards that are drawn out, you can get 24?

now my understanding of maths is not that strong, and this is just a game made bt my friends and i just wanna break it for fun

[solid osprey]

not sure where to begin with this

[vital glade]

i don't think so

actually nvm, i forgot to consider the case where ace can also be 11

[fluid venture]

idk how you would solve that mathematically but like if you pulled 4 9s i dont think thats possible

or 4 10s

[solid osprey]

you can only get one of each

like its not possible to get 2234

[vital glade]

ok so

if u have a 2, ace, a one, and a 4

where is ace is not 11

[solid osprey]

ace is one

[fluid venture]

it would be hard with big numbers

[vital glade]

your only dealing with one suit?

[fluid venture]

7 8 9 10 would be tough

idk if thats possible

[solid osprey]

yeah ig

[vital glade]

ok what i meant to say is

if u have a 2, an ace, a 3, and a 4

then i don't think there is any possible combination of +,-,/,x that can give you 24

[solid osprey]

1×2×3×4

[fluid venture]

nvm 7 8 9 10 is possible lol i think honestly since 24 has so many factors it might be possible for almost every combo

[vital glade]

oh yea mb nvm

im a certified idiot

but i find this question interesting

[fluid venture]

you would probably need a supercomputer to solve it

[vital glade]

and i have no background knowledge in combinatorics whatsoever

[solid osprey]

it is?

on uea

[fluid venture]

9/(10-7) x 8

[solid osprey]

aww0

[fluid venture]

i mean idk im only in calc maybe if ur in some crazy graduate math theres a way to prove it

[solid osprey]

im literally in 8th grade

[ripe hollow]

Is there a combination with 11,10,2,3 to get 24?

I found no such pattern for now

[solid osprey]

why use 11?

2×10+1+3

[ripe hollow]

oh I'm sorry I think I misread

it seems a bit difficult then

[ripe hollow]

I wonder if we take the numbers which aren't the factor of 24 , will they fulfill the pattern?

Like 1,5,7,9 for example

[devout snow]

@solid osprey Has your question been resolved?

[solid osprey]

hm

(9-5)(7-1)

[vital glade]

have you tried

7, 8, 9, and 11?

[solid osprey]

8×(9-7+1)

[restive river]

I don’t play cards so I’m useless here :(

[solid osprey]

this isnt really a cards question

its more like trying to piece numbers from (1/11) to 10 to make 24 somehow

[devout snow]

@solid osprey Has your question been resolved?

[astral copper]

yo

hello

[astral copper]

i will be able to help if you respond

[solid osprey]

hi

sorry my discord isnt working on pc for some reason

[astral copper]

that happens

[astral copper]

no same card/number twice right?

all unique

[solid osprey]

yes

[astral copper]

have you found 1 4 6 7

[solid osprey]

hold on

[astral copper]

wait 1 can be 11 too

[solid osprey]

also that doeaent work??

(7x4-4)×1

wait nvm

[astral copper]

we can use same number twice?

[astral copper]

i wasnt able to 5 2 9 7 too

[solid osprey]

no

im stupid lol

[astral copper]

(7-4+1)*6

[solid osprey]

so is that a no?

o

[astral copper]

but i tried all permute with this couldnt find

cpp code couldnt find a solution too

[solid osprey]

alrighty then

.close

[devout snow]

Channel closed

Closed by @solid osprey

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis seal]

can somebody please help

[lapis seal]

What's wrong with this?

[devout snow]

@lapis seal Has your question been resolved?

[restive river]

not 3!

i think it meant one color

or more

[lapis seal]

i interpreted 3! as the number of permutations of the "blocks"

[restive river]

doesnt have to be 3 blocks

[low coyote]

You have to do some inclusion-exclusion because these events:

B = black balls form a single block
R = red balls form a single block
W = white balls form a single block

can happen at the same time or not and in different positions

[lapis seal]

but there are 3 colors, so 3 blocks... why not?

[restive river]

you could make 1 block and randomize others

[lapis seal]

mmm okay

[low coyote]

This is not allowed BBBRWRWRWWW

[restive river]

what

why

[lapis seal]

oh okay

[restive river]

black balls form a block

[lapis seal]

so 3! is when we ONLY have blocks

we want to find when we have a block of black balls, and red and white balls are random

etc

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lapis seal]

.reopen

[devout snow]

✅

[lapis seal]

i have a question, how do i find in how many ways i can place for example a black block and a red block in the same row

@restive river

[restive river]

i would count 1 block 2 block 3 block

make sure its only 1 block

when ur counting

[lapis seal]

I did this so far

Now I have to find in how many ways I can place 2 blocks while the rest of the balls are random

And then finally subtract 3! as before

Correct?

[restive river]

probably

[lapis seal]

10 * 9! / 4! 5! for instance is the number of ways we can place the black block while the red and white balls are random

I think

No wait that's not correct

Yes it is

Lol I'm tripping

Kinda confusing

I think I got it

[restive river]

hm

you counted cases that has 2,3 blocks with that i think

[restive river]

i might have to think abt this one

[lapis seal]

Damn youre right

I overcounted

this is the solution, the first part is correct, the binomial coefficient part is wrong

[low coyote]

As I see it, you have to use inclusion-exclusion bc when you count setting one block you are overcounting when two and three blocks happens and so on

That's why in the solution you have + - + -

[lapis seal]

yeah thats what i tried to do

7C2 + 6C2 + 5C2 = 46 but should be 92

so we have to multiply it by 2 but why?

OKAY GOT IT FINALLY

@restive river in case you wanted to see how its done

@low coyote @restive river thanks very much for the help to both! 🙂

.close

[devout snow]

Channel closed

Closed by @lapis seal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fleet garnet]

A sheet of metal measuring 8 meters by 10 meters has four squares, each of side x, cut from each corner. The four sides are then folded along the dotted lines to make an open box. What is the maximum possible volume of this box

[fleet garnet]

So what i did first was (10-2x)(8-2x)x = V

and that equals 80x-36x^2+4x^3

now differentiate to find the maximum area and set differentiated equation to 0

80x^2-72x+12x^2 = 0

now rearrange

12x^2-72x+80 = 0

simplify:

3x^2-18x+20 = 0

but when i put it into a calculator, and put the equation into the normal equation, the answer is wrong

[fossil locust]

,w d/dx (10-2x)(8-2x)x = 0

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by sooouth.

[thin tapir]

It is a quadratic equation, be careful with which solution you chose

[fleet garnet]

oh alright alright

thanks

[thin tapir]

x can't be greater than 4, because the sheet is only 10 times 8

[fleet garnet]

yeah

[thin tapir]

So x = 3+sqrt(7/3) > 3+1 is impossible

[fleet garnet]

oh ok ok

thanks

.close

[devout snow]

Channel closed

Closed by @fleet garnet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lunar maple]

don't know where to start. would be great if someone could help me get started

[harsh bluff]

Make a function for any such rectangle that can fit there

[fossil locust]

You should choose D to have x-coordinate say p

Then AD = 2p by symmetry

And CD = f(p)

So can you take the derivative and set the area to 0 from here?

[lunar maple]

oh right. yep I've got it thank you lol

.close

[devout snow]

Channel closed

Closed by @lunar maple

Use .reopen if this was a mistake.

[fossil locust]

no worries

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rugged copper]

How exactly to prove f(x) is increasing if x>0

[safe fractal]

if f'(x) is positive the function is increasing

is f'(x) positive for every x>0 ?

[rugged copper]

Well how to prove that

[safe fractal]

solve e^x > 0

or rather

f'(x) > 0

[rugged copper]

Well if x>0 then obviously e^x>0

[safe fractal]

how is it obvious?

solve it

[rugged copper]

It is an exponential function

[safe fractal]

yeah I guess that's enough

so f'(x) is > 0 for every x>0

therefore f(x) is increasing

[rugged copper]

Ok

[safe fractal]

for x>0

[rugged copper]

Thanks

.close

[devout snow]

Channel closed

Closed by @rugged copper

Use .reopen if this was a mistake.

[exotic dagger]

why shouldn't an explanation for why 1/x + lnx is positive for x>0 be given as well?

[safe fractal]

hm?

Oh I didn't even see that

[exotic dagger]

like to answer part a, the reasoning is that f'(x) > 0, but 1/x + lnx isn't obviously positive right, since lnx tends to negative infinity at 0

[safe fractal]

I just looked at their final line and saw the e^x

lol

[safe fractal]

yeah you gotta check that too

the full function, not just e^x

I didn't see your writing properly

but yeah the full f'(x) > 0

[rugged copper]

lnx is logrithm function

1/x is also postive if x>0

[safe fractal]

is ln(x) always positive though?

[rugged copper]

wait

lnx can be negetive

[safe fractal]

best to just solve the full thing e^x * (1/x + ln(x)) > 0

I just missread your writing

[rugged copper]

e^(-1/x)>x

[safe fractal]

Nah don't solve it like that

[rugged copper]

oh wait I can just double d

[safe fractal]

Since you know e^x is always positive it breaks down to

1/x + ln(x) > 0

[exotic dagger]

should it be the other way round, x > e^(-1/x)?

[safe fractal]

Oh nvm you did the e thing

[rugged copper]

well the equation will be undefine if x<0 or x=0

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[night burrow]

Checking to see if my answers are correct

[restive river]

is this a test?

[night burrow]

No its practice

[restive river]

ok

so

is there any info above the table

because i'm not sure what it's trying to say

[night burrow]

Sorry

[restive river]

so

no

your answers are not correct

and we know this because

if we add up your probabilities, we get 4/5+3/5+2/5+1/5+0/5=2

it has to be 1

because

only one thing can happen

and

there is not a 0 chance we roll heads 0 times

@night burrow

[night burrow]

Hmmm

Okay so how would I be able to solve this?

[restive river]

so

we can make a tree of the possible outcomes

[night burrow]

Okay

[restive river]

and label each bottom value with the number of heads

then count

[night burrow]

Like this?

[restive river]

sorta

with one start

and heads and tails

[night burrow]

I forgot to add 0

Okay so

For each coin there’s two outcomes right

[restive river]

yes

and there are 4 flips

so you should have 16 numbers at the bottom

[devout snow]

@night burrow Has your question been resolved?

Channel closed

Closed by @night burrow

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jaunty seal]

hey

[jaunty seal]

I don’t understand why we make 3 the numerator here?

Exercise 3

<@&286206848099549185>

[fickle spruce]

What fucking sum is that

I think it's pretty long sum

[jaunty seal]

What do you mean

Last point that we wrote where it’s r equals a square root of whatever, it’s 3v over pie etc

why is 3 a numerator

This is what i did before i realised it was wrong

,rccw

[stable cloak]

Technically it's correct

[jaunty seal]

like 100% orr

cuz the teacher wrote 3v over πh

[stable cloak]

If you simplify it you will the same one lol

[jaunty seal]

and i wrote v over 1/3πh

[jaunty seal]

how can i simplify it further?

[stable cloak]

A/(B/C)

[jaunty seal]

i don’t get it

[stable cloak]

Which will be A x C/B

[jaunty seal]

what are A C and B in my exercises?

exercise

[stable cloak]

Uhhh basically they are division rules

[woven radish]

faiyrose

[jaunty seal]

i’m so confused, is what i did right?

[jaunty seal]

Why isn’t V part of the fraction

but the other dude said if i simplified it i’ll get the same answer, in my exams i always have to simplify things i’m confused on how i can simplify my answer further

[stable cloak]

Like they are division laws lmao

I can't really explain them through text

Try to google it

[jaunty seal]

you mean like the powers and stuff?

like to the power of half is a square root

so it would be r= square root of V/0.33333πh

[stable cloak]

No 😭😭

[stable cloak]

These ones

Yep

[jaunty seal]

ohh so should i change the 1/3 to 3 to the power of -1

i’m so confused

can you change the answer to what you mean and show me please

[woven radish]

faiyrose

[jaunty seal]

yeah i get that but like should i have not divided V by 1/3πh at point 2?

ohh

so long story short if i keep it the same would i lose marks if it told me to simplify it as much as i can?

okay thank you for your help

.close

[devout snow]

Channel closed

Closed by @jaunty seal

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet wind]

what

[restive river]

Please send the photo of the question

Well it makes no sense

And 2 times smaller what?

[devout snow]

Channel closed

Closed by @tardy sable

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[north aurora]

why doesn’t my prof keep sqrt2, I got Cos(Theta) = sqrt2/2 (once simplified)

<@&286206848099549185> #very-easy-solve

[restive river]

wait 15m

please

[north aurora]

original problem: sec^2(theta) = 2

[north aurora]

you’re correct. sorry about that.

.close

[devout snow]

Channel closed

Closed by @north aurora

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[low marlin]

Does anybody here know linear programming i have 2 things that i do not understand frist is

1. how to set up linear programming
   2)How to make this green bridge on pic 2

1. Set a linear programming problem that corresponds to the given task:
   Bakery Mica needs to make four types of pastries, salty rolls, sweet rolls, salty pretzels and mini pizzas for the celebration. The table shows the time needed to prepare and bake 1 kg of each type of pastry. Mica works 8 hours in one day, and has 5 days at her disposal. He plans to use 3 hours for the preparation of the pastries, and - for the baking - of the planned time.
   Mica should deliver at least 30 kg of pastries, so that there are at least twice as many savory rolls as sweet, and at least as many mini pizzas as there are pretzels.
   If 1 kg of salty rolls costs 300 dinars, sweet rolls 500 dinars, pretzels 350 dinars and mini pizza 600 dinars, which production plan gives the maximum profit?

[devout snow]

@low marlin Has your question been resolved?

[low marlin]

<@&286206848099549185>
anybody know how to get that green line(bridge here)
this is question

i know how to come to here but i dont know how to put that green line

[devout snow]

@low marlin Has your question been resolved?

[low marlin]

.cole

.close

[devout snow]

Channel closed

Closed by @low marlin

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tiny breach]

is this correct

[safe fractal]

Hmm... are you sure about t2?

What are the 2 legal strings you found

?

[tiny breach]

vv or w*w

[safe fractal]

what about "xx"

is that legal?

[tiny breach]

can

[safe fractal]

right so there's not 2, there's more

what about "yy"

[tiny breach]

yupp

but zz can?

[safe fractal]

no

because "zz" is not an elementary string

all string must be combinations of

the given elementary strings

[tiny breach]

okay so it is 4 for t2

then t3 should be 1 for zzz

@safe fractal

[safe fractal]

are you sure?

t2 looks fine

but t3

is "vvv" legal?

what about "vww"

"wwv"

etc

[tiny breach]

as in t2 = 4 right not 2

[tiny breach]

how ?

[tiny breach]

yes

[tiny breach]

also can

so for t3 vww, vxx, vyy

and zzz

so then 4 for t3

[safe fractal]

are you sure?

There more

"vvv" is also legal

why wouldn't it?

[tiny breach]

how ? can u pls explain

because v is only 1

[safe fractal]

yes but you can copy it

[tiny breach]

oh so u can do 3 times because its 1

[safe fractal]

you can have multiples

[tiny breach]

yes ok

so t3 = 5

[safe fractal]

how?

think more

try to write out all possibilities

[tiny breach]

because v is the only single one rest is pair

[safe fractal]

hmmm

is "vyy" legal?

[tiny breach]

hmm is vww = wwv?

[safe fractal]

no

or at least I don't think so

[tiny breach]

if thats taken into consideration then

[safe fractal]

order should matter here

because they're different strings

[tiny breach]

so

wwv,xxv,yyv

so t3 = 8?

[safe fractal]

"vvv" "vww" "wwv" "vyy" "yyv" "vxx" "xxv" "zzz"

ye

you should be starting to notice a pattern by now

[tiny breach]

yupp

what about the rest

[safe fractal]

well

the next question asks you for the general case

so did you figure out the pattern for the general case?

try calculating t4, t5 etc

[tiny breach]

yeah got it

thank you so much

.close

[devout snow]

Channel closed

Closed by @tiny breach

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sick leaf]

How to do Q11 and 12?

[sick leaf]

For 11 I got (5)(4)(4)(3)(3)(2)(2)(1)(1)/(2!)^2 but that's wrong

And 12 I have the formula

(7C2)(4C1) in mind?

[radiant dune]

For 11, permute the consonants first and then insert your vowels into the gaps

[sick leaf]

Yeah that's what I did

We got 5 consonants and 4 vowels

(5)(4)(4)(3)(3)(2)(2)(1)(1) is the end result

And then 2!^2 is because there're 2 E and 2N

But then it's not correct

[radiant dune]

there should also be a 6c4

multiplied to that

because you want to choose

out of the 6 gaps

which ones you want to put the vowels in

[sick leaf]

But don't we only have 4 gaps only?

That is correct though

[radiant dune]

no

[sick leaf]

Cause I got something like this

[radiant dune]

you're probably missing the start one

and the end one

youre only counting the in between ones

[radiant dune]

refer this

[sick leaf]

Wasn't C1 and C5 the start and end one?

Nvm I though there were 9 letters instead of 10

[radiant dune]

for 12,
choose which 2 get correctly answered, then for the remaining 6 you have 3 ways for each question

so 7c2 * (4c3)^6

[sick leaf]

Gimme a sec while I get these tidied up lol

[sick leaf]

Yeah that's near to what I got as well but the answer says 5103 instead of 86016

Oh wait

Nope not this either

[radiant dune]

im pretty sure it should be 86016 only

[sick leaf]

Yeah that's why I am confused also

[radiant dune]

what resource are you using

[sick leaf]

I grabbed some conclusion papers based on the Australian CSSA exams

[devout snow]

@sick leaf Has your question been resolved?

Channel closed

Closed by @sick leaf

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral latch]

If 3b = 2 mod 5, and 2b = 3 mod 5, can i do additive rule and say that 3b - 2b = 2 - 3 mod 5 --> b = -1 mod 5?

[thin inlet]

what is -1 mod 5

but yes

[devout snow]

@floral latch Has your question been resolved?

[floral latch]

-1 mod 5 is a thing, no?

[floral latch]

oh okay thanks

[devout snow]

Channel closed

Closed by @floral latch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell glacier]

Could I get a hint for 5.4 please?
This is what I have atm
Thanks!

Wolfram says this goes to exp(t^2 / 2)
but I'm not quite sure how to calculate this limit

it may have to do with thr taylor series of e?

actually that's exact what it is...

.close

[devout snow]

Channel closed

Closed by @shell glacier

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tawdry torrent]

do you know about inverse of a function?

[devout snow]

@jolly dawn Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime agate]

Hello, please I am looking to find the anti-derivative of 3sin(2x) and I struggle a lot with it

[prime agate]

the rules that I actually have doesn't allow me to, is there a way I can do it ?

(ping me please)

[topaz axle]

the last one says 2sin(2x)

if i'm not mistaken

@prime agate

[devout snow]

@prime agate Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twin wasp]

.reopen

I have to find the length of PR, i already calculated all of the other sides but is just dont now where to start now when i want to find PR. Can someone help me?

[twin wasp]

It is an folded sheet of paper with al sides 8 cm

[restive river]

! status

[devout snow]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[twin wasp]

its a perfect squere so the corners are 90 degrees

[gaunt galleon]

form the vectors AP and AR, then take AP - AR and calculate the magnitude

[twin wasp]

wait can you give some more explenation i dont really understan it sry

[gaunt galleon]

you familiar with vectors?

[twin wasp]

no

[gaunt galleon]

ok so you choose the origin of your coordinate system to be A.

then AP would be (0, -3)

and AR would be (8, -7)

[twin wasp]

ill take a look

Like this i think and then i know how to calculate

Ill be back in 3 mins

I this correct?

[devout snow]

@twin wasp Has your question been resolved?

Channel closed

Closed by @twin wasp

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble mortar]

is it the same thing with different ways?

[stable wraith]

both uses gaussian elimination to solve a sustem of equations yes

[nimble mortar]

in the second photo operations isn't random? I asked because i watched the first video and there is logic how to calculate

[stable wraith]

operations arent random no, you try to get a reduced form on the matrix in both cases

[nimble mortar]

but i can get the same result with different ways no?

i mean different operations

[ornate vector]

there are a lot of ways to do it

[stable wraith]

yes, does not matter in wich order you do them or how you get it, as long as the operations are legal

[ornate vector]

you need to be careful with it

[nimble mortar]

so that means operations are random to reduce as "low" as possible

[ornate vector]

yes

you need to stair it

[nimble mortar]

yes and i think the first method is the safest and fastest way to get results at the first try

[ornate vector]

gauss is pretty easy

[nimble mortar]

but @stable wraith told me both of them are gauss

[ornate vector]

yes

both of them are gauss

[nimble mortar]

i will clarify

both of them are the same with different ways?

[ornate vector]

with a different order

[nimble mortar]

ok thank you guys

i will close it

.close

[devout snow]

Channel closed

Closed by @nimble mortar

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limpid ridge]

Given are 2 vector space basis R^3: B = B={(1,2,1),(0,1,−1),(1,0,4)}, C= C={(1,1,1),(0,1,1),(0,0,1)}
Calculate the transition matrix P(B->C).
Calculate the coordinates of the vector v_C in the C basis given its coordinates v_B = (5, 1, -2) in the basis B

[teal perch]

What have you tried?

@limpid ridge

[limpid ridge]

nothing, rly, i don't get it

[teal perch]

Do the coordinate transformation matrix first.

Ok. Do you know what the question is asking?

[limpid ridge]

yea

[teal perch]

What are your thoughts?

[limpid ridge]

but bcuz i just learned it

i was absent on the prev lesson

[teal perch]

Ok. What is the transition matrix, from your perspective?

[limpid ridge]

it expresses the vector of a given matrix using another one

[teal perch]

I will denote the the basis for B as $\beta$ and the basis for C as $\gamma$

[woven radish]

Applejakop

[teal perch]

For the sake of helping to guide you through this.

[teal perch]

Kinda. But not quite. It helps us move from one basis to another.

Which is why we call it "transition".

[limpid ridge]

basis as i recall is a set b such that a vector space can be written as a unique linear combination of the elemnts of that basis

[teal perch]

Actually, it is that every element in the vector space can be written as a unique...

The latter part is right

If the the basis has enough basis vectors to span the whole vector space then your statement would be true.

Which I do believe it is the case here.

[limpid ridge]

could you rewrite that sentence

i don't udnerstand ur correction

[teal perch]

But we usually say that every element/vector in the vector space could be represented as a unique linear combination of the basis vectors.

Rather similar to your original definition.

Right, let's get into the question then.

[limpid ridge]

and the definition of a basis is a set that consists of these vectors

yes

[teal perch]

Yeah, and if it spans the whole vector space then it would be a spanning set of that space.

But let's get into the first part.

[limpid ridge]

ok

[teal perch]

We do know that it is from B to C, right?

[limpid ridge]

yes

B={(1,2,1),(0,1,−1),(1,0,4)}, C={(1,1,1),(0,1,1),(0,0,1)}

[teal perch]

Let's denote the transition matrix as $[T]_B^C$

[woven radish]

Applejakop

[teal perch]

Do you know how we are going to find this matrix?

[limpid ridge]

no

[teal perch]

Also, did the question give us the specific transformations?

Like, T(a vector in B)=some vector

Otherwise we couldn't really calculate it.

[limpid ridge]

that's the entier question

[teal perch]

That's strange. Normally we would have the T given to us.

[limpid ridge]

Calculate the transition matrix P(B->C).

you have to calculate it

[teal perch]

Oh sorry

I misread the question

I thought it was T

There was no T.

Lol

Ok. Let's denote the matrix as $[P]_B^C$

[woven radish]

Applejakop

[teal perch]

Any thoughts on how to move on from here?

[limpid ridge]

no

as i had said i was absent on the prev lesson

do you think you could show me the solution to this or another such question and help me solve a next one

like i'd solve the next one based on ur solution

[teal perch]

It's quite technical, I would say.

A hint would be first, write each vector in C as a linear combination of the vectors in B. Note down its coefficients.

I will do one for you.

Let's do the first basis vector in C.

[limpid ridge]

ok

[teal perch]

Which is (1,1,1)

[teal perch]

Could you find the coefficients of this vector as a linear combination of the basis vectors of B?

So, find the coefficients $\alpha,\beta,\gamma$ in the equation $(1,1,1)=\alpha(1,2,1)+\beta(0,1,-1)+\gamma(1,0,4)$

[woven radish]

Applejakop

[limpid ridge]

ok

[teal perch]

When you finish solving ping me.

@limpid ridge Have you found the coefficients?

[limpid ridge]

yes

alpha = 2
beta = -3
gamma = -1

[teal perch]

Lemme check real quick

[limpid ridge]

i have to go to in ~30min so let's do it really fastp lz

[teal perch]

Right

Then you would agree that $[\vec{b_1}]_C$=(2,-3,-1)?

[woven radish]

Applejakop

[limpid ridge]

yes

[teal perch]

That is the first column of the transition matrix

Do the same for the other two

COLUMN

Not row

[limpid ridge]

https://www.emathhelp.net/en/calculators/linear-algebra/transition-matrix-calculator/?a=[[1%2C2%2C1]%2C[0%2C1%2C-1]%2C[1%2C0%2C4]]&b=[[1%2C1%2C1]%2C[0%2C1%2C1]%2C[0%2C0%2C1]]

[teal perch]

Um you wrote the wrong basis

[limpid ridge]

wrong how

oh

i wrote columns as rows

[teal perch]

You use these as basis vectors

[limpid ridge]

yea\

and i wrote them as rows in that program

instead of as columins

[limpid ridge]

.

[teal perch]

No that's the resulting matrix

Not the basis

Omg

[limpid ridge]

ok rewrite it plz while i solve the 2nd column

to make sure i get the correct result

[teal perch]

Wait

Am I doing something wrong

I am 100% sure the logic is right though

lemme check

WAIT

@limpid ridge

I misread again

Sorr

Sorry

It sohuld be basis vectors of B in C

So just solve for alpha beta and gamma such that the linear combinatinos of the basis vectors of C is the veectors in B.

Do the same for each of the vectors in B

[limpid ridge]

so all of the above is rwong

???

[limpid ridge]

this was a waste of time?

[teal perch]

Um if you think the whole thing was a waste of time you could use a calculator instead of asking here

I am a human and I do make mistakes

[limpid ridge]

okay

so what do i do now

[limpid ridge]

what do i set as what

please be fast

i have to go soon

i want to solve this question beofre then

[teal perch]

.

[limpid ridge]

so the reverse?

@teal perch hi?

previously i was solving alpha beta gamma such that the linear combinations of the basis vectors of B is the vector in C, yes?

meaning i should now write
(1, 2, 1) = a(1, 1, 1) + b (0, 1, 1) + c(0, 0 1)?

[teal perch]

yes

[limpid ridge]

are u sre

i found a similar problem online

[teal perch]

um if you wanna rely on online calculators

please do so

[limpid ridge]

this is from B to B'

[teal perch]

Welll then trust online resources instead of binge asking here

[limpid ridge]

why didy ou changey our mind

about how we have to do it

[teal perch]

I didn't.

[limpid ridge]

based on the above our previous approach was corerct

[teal perch]

Then do it the way you like.

[limpid ridge]

what did you misread

[teal perch]

It pisses me off when I have to answer questions of someone who doesn't really have manners

Good luck

[limpid ridge]

i'm sorry

i'll do better

i'm an esl so sorry for being impolite

wasn't my intention

[teal perch]

As I said, resort to online resources to your liking

[limpid ridge]

could you please clarify what i should do

i value your perspective

you're moer intelligent than me

i'd like to udnerstand this before i have to go

[teal perch]

Alternatively use augmentation

@limpid ridge