#help-27
1 messages · Page 196 of 1
@feral cairn Has your question been resolved?
<@&286206848099549185> ?
@feral cairn Has your question been resolved?
@feral cairn Has your question been resolved?
@feral cairn Has your question been resolved?
@feral cairn Has your question been resolved?
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can someone please help me with this
Maïcha's parents want to make a rainwater collector in the shape shown opposite. The apothem of the cone, the height of the cylinder and the radius of the sphere will be 60 cm, 2.5 m and 30 cm respectively.
It will be made of aluminum foil. The area of an aluminum sheet is 1.6 m², and each sheet sells for $32 (tax included).
What will be the total area of the reclaimer, how many full sheets will they need to buy and what will the project cost?
thats the translation
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@fossil steppe Has your question been resolved?
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Wondering how to solve a recurrence relation like this
@vestal lance Has your question been resolved?
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I still need help with this problem.
@feral cairn Has your question been resolved?
I'm not sure if it should be general, like one specific r or for every v it can be a different r...
r should be greater than 0 and for any ||L(v)|| = r* ||v||. And r must be independent from v.
Yeah got it
Wait why do u think r must be independent from v?
It says so in the task
@feral cairn Has your question been resolved?
@feral cairn Has your question been resolved?
<@&286206848099549185> ?
@feral cairn Has your question been resolved?
I now have like an idea for the proof, but I'm not sure if this is the right approach and if I'm allowed to say that A just can be these 2 cases or if I'm supposed to use the other attributes L has cause it's conformal that are written in the task...
@feral cairn Has your question been resolved?
@feral cairn Has your question been resolved?
i'll post it here again for ease of access:
Let A be a real 2 × 2 matrix and L : R^2 → R^2 : v→ A * v the corresponding linear mapping. We call L conformal if L is injective and
for all v, w ∈ R^2 with v, w != 0 it holds that (Screenshot)
L is conformal. Show that |L(v)| = r*|v| if r> 0 and not depends on v ∈ R^2.
Tip: First consider the basis vectors e1 = (1,0) and e2 = (0,1) and the vector e1+e2
How do you know it can just be one of these two cases?
Googled what conformal matrices can be cause I had no good approach without this.
It's a bit tricky! I think it's dangerous to start going into matrix components too quickly, there's some abstract things you can do first to get intuition for the question
For example, entering e1 and e2 gives you that L(e1) and L(e2) are orthogonal. So the map maps orthogonal sets of vectors to orthogonal sets of vectors. Entering e1+e2 into v and w and using linearity of L and the scalar product gives you |L(e1)|^2 + |L(e2)|^2 = |L(e1 + e2)|^2, so a pythagorean theorem. That's also kinda cool
Still struggling how to get the exact thing we want tho!
With entering you mean apply in the <L(v)L(w)> / <||L(v)||||L(w)|| = <v>*<w>...?
Ye
v = e1 and w = e2
And then play around with the equation until interesting stuff comes out
Don't know if I made a mistake here and I didn't quite get how you should go from |L(E1+E2)| to |L(E1)|^2+|L(E2)|^2..
$\langle e_1 + e_2 , e_1 + e_2\rangle = 2$, right?
Lartomato
Oh true
Also not sure why the $\langle L(e_1 + e_2), L(e_1 + e_2)\rangle$ in the enumerator on the left disappears
Lartomato
I thought because of the equality that this has to be the same as 1 or now 2. But I think that's wrong...
Nah, we don't know much about what the value of that is. But we can decompose it with linearity and see what happens
Is this correct?
That is correct, but then you just get 1 = 1 on both sides of the equation and haven't gained any information
What means decompose with linearity?
L(e1 + e2) = L(e1) + L(e2)
That's how fancy math people talk about that step hehe
Also $\langle a + b, c \rangle = \langle a, c\rangle + \langle b ,c \rangle$
Lartomato
That means I can calculate the numerator left =2
Why's $\langle L(e1), L(e1) \rangle = 1$?
Lartomato
I thought the scalar product of the same vector is always 1. But I see that was also a wrong assumption xD
Nope, it's actually $\langle v, v \rangle = |v|^2$. So it's only 1 if the length of the vector is 1 🙂
Lartomato
but that happens often enough so i understand why you'd think that
Yeah I had something in mind with normalized vectors.
I don't really have an idea for the next step. But if I get somehow a result with this for r, then this r is the solution for the complete task?
My recommendation is to stay away from matrix entries as long as possible
They're only gonna make your equations more complicated
What is the value of |e1 + e2|^2?
Ok. I thought maybe sth cancels.
- I know the right side is 1 but I thought cause of the task I shouldn't get rid of it.
But now that we found out that |L(e1)|^2 + |L(e2)|^2 = |L(e1 + e2)|^2 i struggle with the next step. From |L(e1+e2)| = r*|e1+e2| I can get r=(|L(e1)|^2 * |L(e2)|^2)/2 but I still don't see how that helps to generalize it to all vectors and r is still dependant on v as the two is only possible because |e1+e2|^2 = 2
I get that the proof for |L(e1)|^2 + |L(e2)|^2 = |L(e1 + e2)|^2 can be adapted to |L(v)|^2 with v=xe1 +ye2 which makes it possible to generalize r for all vectors but it's still dependant on v isn't it
<@&286206848099549185>
hi
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Yeah, the equation $|L(v)|^2 + |L(w)|^2 = |L(v +w)|^2$ then can be adapted to hold for any orthogonal vectors $v,w$. The final step is inserting $v = e1 - e2$ and $v = e1 + e2$; the right-hand side becomes $4 |L(e1)|^2$, the l.h.s becomes, using that L(e1) and L(e2) are orthogonal, $2 |L(e1)|^2 + 2 |L(e2)|^2$
Hence you get that L(e1) and L(e2) have the same length. But by linearity this implies that all vectors of length 1 are mapped to vectors of the same length r = |L(e1)|
@feral cairn sorry that i left you hanging afterwards, above is a proof sketch
Lartomato
Wondering if there's a slicker proof. But damn this was kinda fun
Thank you
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i havent done trig in forever
how is it "easily" 3π/2 radians
i know that this is the transformation matrix for a rotation counterclockwise
and the representation matrix T can be found by multiplying this matrix and the reflection transformation matrix
so you know that pi/2 is a quarter turn right
yea
1
counterclock wise
hmmm
hmmm
but
but?
ok wait nvm
i need to take a break
i made it harder than it needed to be 😭
thank you tho

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why chebyshev and not kolmogorov
kolmogorov was easily low S tier
idk if i'd say the same about chebyshev
because chebyshev's norm is the infinite pee norm
m8of48...
laila at home ...
wtf
this is above my pay grade

pee norm
are you familiar with Lp norms
and the max norm
no
ic
i havent taken any pure math classes
are you familiar with what a norm is
we just started martingales tho so thats pretty cool
its the length of a vector right? or something like that
time to beat the casino 
why is your name pee norm
ways to measure a vector but ye
i am explaining right now!
you are not
i am in the process of explaning right now!
.reopen
✅
Lp norms is $\left(\sum_{n} |a_n|^p\right)^{1/p}$
chebyshev's infinite pee norm
if p = 2 it's the standard euclidean norm
whats a_n
the elements of the vector
now why is your name pee norm and not p norm
$(4^p + 6^p + 7^p)^{1/p}$
chebyshev's infinite pee norm
yes got it
ye
so then
take lim p to infinity
and it turns out this norm is the same thing as the maximum norm, $max(|a_1|, |a_2|,\ldots)$
chebyshev's infinite pee norm
Sir how would one prove this ?
so whats the maximum norm of this
it's very hard you wouldn't understand
7^p?
My ma'am just said this to me... how could she
it's max(4,6,7) = 7
@weak cove 
ah ok
Hello
this channel
This looks like a lovely group here
sakatayaksha
We are looking to solve $\mg{(4, 6, 7)}_{\infty}$
Ultimate Chad
that's my name don't wear it out
and the proof is pretty simple but im lazy to type it
no that's @stuck field
sir there's nothing to solve
Wow this actually was p simple
pee simple
so whats the importance of this and chebyshev discovered it?
pee norm
Glad that I could clear the doubt.
🔠 ?
maximum norm is chebyshev's norm
does my sir mean frobenius norm restricted to the rows?
I prefer the L2 norm
i prefer the taxicab norm
o i c
and idk the history whether chebyshev found the two coincided
pee
oh ok so pee
sorry Sir
thank you
that wouldn't make sense
FIsh def do
you look very handsome in your pic
slayla 
My ma'am complimented the gigachad with extremely large pectoral muscles"
:SCcog:
Not even my sir @weak cove has pectoral muscles as large as this gigachad..
my pectoral muscles are that big
um
look away
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
is this allowed to be here?
if u say so
we know what we are doing
ohk
please dont report us to the mods through modmail
mb
We served in the war of the sleeping force
lmao
⚔️ down with lust
i gotchu
She can not afford another strike
she sold me fetanyal
another
lmao
⚔️ the lusty mods shall be demolished
@oak widget Please ban all of these misbehaviors, specifically @rustic jetty
thats crazy
my ma'am slayla has been banished from the mathcord before?
yes
Oh shit its joever for you sir. Any last words/
Multiple times
noooooooooooooooooooooooooooooooooo
no only once actually
revoked of green multiple times
Okay apology accepted.
i havent done anything lusty
I shall soon join you
Have a nice day sir
Good. One of us
Do you have a doubt still?
i actually don't know if my green got revoked manually when i got banned or my helpful status reset when i got banned
oops
wrong reply
ma'am
all my other roles were gone when i joined back
how do you get helpful anyway
By being helpful
how helpful is helpful?
Very
i just meme alot and got it
nice
maybe if you meme as much as i did
lmao
Lies he ABCD
You need to clear an incredible amount of doubts
you have to ABCDEFGH
Like our kingly sir @weak cove
for awhile
The leader of the doubtclearers and the bringer of destruction to the lusty mods
i will bring destruction to sakatayaksha
Our ma'am is wrought with betrayal...
What shall be done?
Why would you want to destroy @stuck field
he teaches at my school
he is my school
i'm sorry for your loss
lmfao
wait actually
yes
He is indeed.
Please don't doxx my sirs image.
without his permission
is this real ☠️
doesn't matter
you should be ashamed
My maam is right
your ma'am is always right

penix?
wait a minute
i really thought you were just going to make a penis joke
that would be lusty behavior
and sir is anything but lusty
⚔️
ew college football
NOO
oh
any football that isn't nfl i can't watch
they went bears and falcons so I guess u wont be watching them anytime soon
its only playing it or watching superbowl thats acceptable
any football that isn't taylor swift i can't watch
rip
isnt this from her fortnite song
You are right sir
My sir has never played Fortnite festival 🤣🤣🤣
hi
never even played fortnite

what 4k
.
⁉️⁉️⁉️⁉️⁉️
also what did u think about her fortnite song
what did i miss
My sir is embarassed
what got deleted
whole album is meh except i can do it with a broken heart
i don't wanna hear her sing 15 gloomy songs about her 15 exes
good thing i can play the music i like and not have to be forced to listen to someone else's preferences
just like how i can go to the supermarket and buy the foods i personally like to eat
this is the only music I like
and the clothes i like to wear
frosst chill it was a minion music joke
huh im not mad at all

:majjnow:
did u used to play despicable me phone game
i was just saying that oh wow people have different preferences and that's okay 
lmfaoooo now i know what you know you from
well still not exactly
yesway
how is this still open
it was .reopened
Closed by @weak cove
Use .reopen if this was a mistake.
rip
🔠
you play rs right
⚔️
what's rs?
it's just the best massive multiplayer online role playing game in the world
don't worry about it

spoken like a millenial
did we know each other?!
is it older than wizard 101
idts, i'd remember you better if we did
i must have just seen your name around somewhere
yep

:ratjam:
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in the equation 8x^2-40x+199+(-1008/x+5)=y
Find all integer solutions of the proposal in which x and y are negative integers.
where is y?
you're gonna regret this

-1008/x+5 or -1008/(x+5)?
-1008/x+5
just to confirm, $\frac{-1008}{x} + 5$?
slayla
!occupied
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
no, sorry i miss, -1008/(X+5)
ok
I'm a bit confused typing math on the keyboard
yea issok
that's a common mistake people make here so that's why i asked about it lol
so what you want to know is... for which values of x is 8x^2-40x+199 - 1008/(x+5) a negative integer
yea but
every x that makes 8x^2-40x+199 - 1008/(x+5) a negative integer gives a solution to the equation
well every negative integer value of x
yes
just factorize -1008 and find the values of x so that 1008/x+5 is a integer
1008 is 2.2.2.2.63
now permutate all the possible factors
then find x+5 = negetive(of these factos)
oh right
isn't y negative if x is negative?
no
also im stupid i thought 63 was prime bruh
for all x negative, y is not negative
is not true
i just woke up 😭
for example when x is -1, y is -5
okay so 8x^2-40x+199
always gives positive output
we just need to find the interval where 8x^2-40x+199 is less than 1008/x+5
Won't this create a huge inequality?
yeah...
Did you arrive at something? I tried here and found something absurd
8x^2-40x+199 > 149 for any x
then we can say something like
for x < -10, -1008/(x+5) > -100
so 8x^2-40x+199 + -1008/(x+5) > 0
how you get it?
u just did 8x^2-40x+199-1008/(x+5)<0?
well my point was that for x < -10, 8x^2-40x+199 + -1008/(x+5) is positive so there are no solutions in that case
then there is just x with 0 < x < -10 to worry about
and you can just check manually for each one to see if 8x^2-40x+199-1008/(x+5) < 0
So the only solutions for negative x and y are for x between 1 and 9? since x can be at this value because (x+5) is a multiple of 1008?
maybe? hard for me to understand what you're asking exactly
i mean if you got 8x^2-40x+199 > 149 you'll also need 1008/x+5 > 149
compare maybe the values of x where the values are attained
the uniques divisors of 1008 between 0 to -10 is -1, -2, -3... -9
x = approx 1.7
this is the case when x < -10 (and also for other x)
wait nvm that
i think we are on a different page
my point was that when x < -10, there are no solutions
How do I prove this for nonsense?
how you get it?
No, i just tried to put in geogebra to find
can you send? plz
its gibberish
random nonsense
what i wanted to tell was
i got: if x<1.7 then 1008/x+5 > 149
and also if x<-5 then the difference in the main equation chances to sum
-1008/x+5 will just add then
so answer between this range
and you needed negetive answers
so
-1 -2 -3 -4
let me do something a little better. if x <= -6 we have:
- 8x^2-40x+199 is positive (because 8x^2-40x >= 0 and 199 is positive)
- -1008/(x+5) is positive because -1008 and x+5 are both negative
so 8x^2-40x+199 -1008/(x+5) is positive
so there are no solutions outside of {-1,-2,-3,-4} (-5 is not a solution because division by 0)
yeah
ooooooooooo
and you can check that those are all solutions
💯
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https://cdn.discordapp.com/attachments/976967307953860609/1233249529571315803/image.png?ex=662c68a0&is=662b1720&hm=6b7874811d9943e0902725e0b891dbda7db1d292f12c8d486f0c7d75fa385999& I'm wondering what the correct approach/setup is for this problem because I cannot figure it out
you get rates of change by just taking the derivative of the formula you're given (with respect to t, need chain rule for e^h(t))
then you'll have dP/dt and dh/dt, where dh/dt is sin40 of the speed since you just want height and the speed is diagonal
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help
how can i get help?
post q
what's that?
post ur question
where?
here
xdxdxd
So all the ones above the one were currently in
discord in white mode
its fire isnt it
nah, i was asking not about math help (in this serever)
how can I get that people help me in mathematics , it seems redundant , but the question is not about this server , but how to get help
?
I have failed , like , 6 years in a row to get help
and we continue
here we go again
have you ever realised that when is 23:41 at the clock happens that 23 is prime , 41 is prime and 2341 is prime
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is there a way to find or approximte a sine angle
mclaurin series is one way
using series expansion of sinx
alright ty
ima check it out
Your calculator uses CORDIC
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Series are better to learn about tho
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Hi
common factors can be cancelled given that they're not 0
It doesnt matter where?
same factor on the numerator and denominator
Because there’s another (p+2) on the left side
well only one of each will get cancelled
since there's only one factor of (p+2) on top
the effective denominator will be the product of the individual denominators
So if it’s in another fraction I can’t cancel it?
It has to be in the same fraction numerator and denominator ?
if its separeated by addition, no
ℝαμΩℕωⅤ
way overcomplicating it
It’s how they taught us
who?
just take out 2 common from (2p+4)
Teacher
what is the point of all that multiplication and division
either you have a bad teacher or you're misremembering/misapplying what they said
you're still left with the original eq
Would that be for all equations?
Or just this one
for all, with the way you're doing it
you're not being asked to add/subteract fractions
there's no point in getting a common denominator for each idnvidual fraction being multiplied
multipylying and dividing then cancelling the same factors accounts to nothing
if you really want to first combine everything into a single fraction, just apply what i had typed above directly
and factorise the numerator and denominator separately if possible
then cancel common factors that appear
But I can’t cancel out bc the bottom ones are tied to their variables
wdym
yes, however refer to
and factorise the numerator and denominator separately if possible
Not sure how to?
Would that be p+2 p+2
no
2
yes, so factor that out
Leaves p+2?
wdym
yes, 2p + 4 factorises to 2(p+2)
() around the p+3
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Hey
nuh uh
do you know what calculus is
Yeah
and thats your answer
Tysm
Wait but 9.8 is negative
How do I ignore that
And is 4 the negative one or 14 for the numerator
yes
now take negative sign
because that'd make the top negative and bottom is negative so it'd be positive overall
i meant ignore the + sign one as
(i forgot to put - sign)
yes
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can someone check this for me
sorry its so messy if u need me to tell u what smth says i can
it’s right
you have to simplify this right
yh
yeah this right
ight ty
@tight wave Has your question been resolved?
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uh guys i need help with making a base or layout for our research introduction, its basic statistical research
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help
!status
is this a test?
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1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
q 37 and 38 and 39
ok
so 2W+L=56
yes write it as w=2/3 * L
yes
then you can substitute your value for w into here
close it's 2(2/3 L) +L=56
so it then becomes 4/3 L +L=56
VS
yes?
ok can you send the question again
.
.
F and NF
ok
wait
ok
yes
there are 2400 more non fiction books than fiction books
ok got it
@restive river
the way i'd start is from here
i'd say NF=F+2400
yes
now you have to find the second equation you'd subsitute NF into
what
mb
same as this just rearranged
im not sure sorry
can you realign it to make a rectangle
yes
so AB * BD = 98
yes
make your life easier so rearrange this to make it AB= .5BD
yes
subbstitute now
.5xBD=98
yeah
now
okok
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So firstly, does part b basically confirm that part a is possible?
And secondly, for part b. I can think of computing the cross ratio of the points and cross ratio of the projection points.
To my understanding, we can find the distance between $x_1$ to $x_2$ and $x_2$ to $x_3$, and we wish to find the distance between $x_3$ and $x_4$. However, the cross ratio needs 4 values to compute. Also, how would we compute the cross ratio of the projected points? I don't think we were given anything in the question. Thank you.
WhoTao
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I still need help w this one
question makes no sense
why are they giving you the condition of if x=? find:
when the equation you have to find the value of doesn't have an x
this was mentioned yesterday already
Yes
taking the expression at face value and trying to evaluate directly doesn't give any of the options
and neither does the bottom fraction lol tf
there's probably a typo or typesetting issue
the original intended problem is irrecoverable
so just skip and move on
If u want i can send u some examples
I think the circle is supposed to be an operation
Yes
,w \frac{2*1+1+(-2+1)}{(2 * 6/7 + 1) - (2 * 5/7 + 1)}
yeah it is
very unusual notation
maybe you have to take the values circled in blue and make them equal to x?
Emmmh idk
sorry I don't speak enough spanish to understand this 😅
I'm gonna use square brackets instead of that circle thing
I thought it was just decoration so I ignored them
[7x-3] = 2x+1
if we want [4], them we can let x = 1
that gives us [7(1)-3]=[4]=2(1)+1=3
rinse and repeat for the other 3
Heres what i tried yesterday
yeah but that gives you 0 in the numerator
if you put the equation = 4, and then -10, you'll get 1 & -1
idk this is very confusing

are we just ignoring this
But if i do that theyll will be 3(?
They all*
I only calculated this one
I’m saying the other three are the same process
So writing it out for all 4 is fairly pointless
So
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,rotate
Can somebody give me a starting point
Try finding RM in terms of x
is r the midpoint of bp
Yeah
That's not given, but since BUMP is a square, U and M are each the same height above B and P respectively
which means they are placed symmetrically along the circle
and R is the center of the circle, so B and P must be equidistant from R
Okay so should i try to find SA
If you can, but I'm not sure if that's possible without finding the whole square first
Im not sure how to prove it but i think that ST is 2x
Not quite
Okay
Think about what you have so far, why do you think RM is important?
Yeah, how do you know?
Because BR = RP and BU=MP
Ahh that's true, but I was going for something else
What were u going fort
Think about the circle
Yes
Okay
All the radii of a circle are the same
So yes RM is the same as RU
But its also the same as RT
And from there I think you can find the area of the large square
Should be 5x^2 I think
forgot to type the exponernt
Yep that's right
I got 1:5 for my final answer
Yep 👍
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Can someone explain to me how i'd do this problem?
Not cheating on a test by the way, this is a screenshot from my preparation class. 👍
Can you explain it to me like i'm 5?

or 8 I just do not understand this in complex terms / do not understand what those equations mean
There are formulas made by a guy called vietta that help in this exact scenario
But the way they teach them in school sucks
Because it’s treated like rote memorization
You can derive them easily
Do you agree with this
i have no idea what it means nor do i understand it how can i agree with it
I’m just saying every quadratic can be written in factored form
Instead of ax^2+bx+c=0
r1 and r2 are the solutions
The roots
Now expand the left hand side
Get rid of the parenthesis and foil
See what you get
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Thanks!
I'll use that, much appreciated!
.close
.close
sobs
@heady plinth Can you close it?
It’s closed


