help-27

[woven radish]

Renz

[midnight grove]

the x on the right cancels

,,-\frac{1}{2}x-x=-2

[woven radish]

Renz

[midnight grove]

whats $-\frac{1}{2}x-x$ equal to

[woven radish]

Renz

[midnight grove]

if you are confused with fractions, we can easily convert -1/2 to -0.5

[fast fossil]

-2

?

-2x

[midnight grove]

,,-0.5x-x=-2

[woven radish]

Renz

[midnight grove]

not exactly

whats $-0.5x$ minus 1x

[woven radish]

Renz

[fast fossil]

-1.5k

x*

[midnight grove]

yea

its -1.5x

[fast fossil]

oh

[midnight grove]

,,-1.5x=-2

[fast fossil]

-1 1/2

[woven radish]

Renz

[midnight grove]

now, how do we isolate x

x is being multiplied to -1.5

how can we undo that

[fast fossil]

(x1)

(-1)

on each side

?

i forgot

[midnight grove]

since x is being multiplied to -1.5

we divide both sides by -1.5

to undo that multiplication

[fast fossil]

ok

[midnight grove]

,,\frac{-1.5x}{-1.5}=\frac{-2}{-1.5}

[woven radish]

Renz

[midnight grove]

now what do you think happens on the left

wow i got helpful role

[fast fossil]

you are very helpful rn

school starts soon

positive 1.5x

?

[midnight grove]

nah

there is -1.5 on the numerator

and a -1.5 on the denominator

meaning, they get cancelled

[fast fossil]

so X

?

[midnight grove]

so it becomes

,,x=\frac{-2}{-1.5}

[woven radish]

Renz

[midnight grove]

what is that equal to

[fast fossil]

uh

1..........

1.3 something

[midnight grove]

yea

its 1.333333333 repeating

or you can say

,,x=\frac{4}{3}

[woven radish]

Renz

[midnight grove]

4/3 is just 1.333333...

[fast fossil]

ok

wait so is that e

[midnight grove]

not yet

[fast fossil]

o...

[midnight grove]

thats the x-value of our intersection

[fast fossil]

i have to leave for school now

tho

[midnight grove]

to find the y-value

just choose an equation here

,,y=-\frac{1}{2}x+4\y=x+2

[woven radish]

Renz

[midnight grove]

substitute x=4/3

and get the value of y

that will be the y-value

[fast fossil]

alright

and for f what do i do before i go

[midnight grove]

alright

so in e, you found the x and y-value

get the first equation, and substitute the values of x and y

they must be equal to each other

and then, get the second equation, substitute the same x and y values

[fast fossil]

wait so for y value

its 6/3

[midnight grove]

and show that they are equal

[midnight grove]

not exactly

[fast fossil]

y = 4/3x + 2

[midnight grove]

alright we have y=x+2 right

,,y=x+2

[woven radish]

Renz

[midnight grove]

and we know that x is 1.33333

we sub that in

,,y=1.33333+2

[woven radish]

Renz

[midnight grove]

what will y be

[fast fossil]

3

3.3

[midnight grove]

the answer will be 3.33333 repeating

[fast fossil]

mb

[midnight grove]

yea

or in fraction form, 10/3

so your values are

[fast fossil]

Ok

[midnight grove]

x=4/3
y=10/3

or

x=1.33333...
y=3.33333...

meaning, (1.333,3.333) is the point of intersection

[midnight grove]

the coords of this intersection will be this

[devout snow]

@fast fossil Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusky wing]

I know I need to get it to have the bottom left corner triangle with row operations

But idk how to work around the B

Do I have to swap rows or how do I solve?

[dusky wing]

Phrased this poorly

I know I need RREF

Couldn't think of the acronym

[fossil locust]

Can you find a way to get v2 from a linear combination of v1 and v3?

The numbers are convenient

[dusky wing]

Huh?

Honestly I've never done a problem like this before

[fossil locust]

So a linear combination of v1 and v3 could be something like 2 * v1 + (-1) * v3

[unkempt narwhal]

No need for RREF. Observe that the first, second and fourth entries of v_1, v_2 and v_3 (we call them c_1, c_2, c_3) satisfy c_1+c_2-c_3 = 0

[fossil locust]

!nosols

[devout snow]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[dusky wing]

I had that written out

[fossil locust]

Well I mean that's not the full justification but yes

[dusky wing]

But I can't figure out how to work with it

[unkempt narwhal]

This is a cheap trick

[fossil locust]

Cool, so to justify it, you would need to solve a(-1) + b(1) = -2
and a(1) + b(2) = -1

From the first and second rows

[dusky wing]

Wait if c1v1+c2v2+c3v3=0 how are we doing c1v1+c2v2=c3?

[fossil locust]

The reason we can write one vector in terms of the other is that if p (v1) + q (v3) = v2, then p (v1) + (-1) v2 + q (v3) = 0

So there exist constants a, b, c not all zero such that a (v1) + b (v2) + c (v3) = 0

[woven radish]

themadchessplayer
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[dusky wing]

Can't do determinant

Non square matrix

[unkempt narwhal]

We are just taking first 3 entries of each vector

[dusky wing]

I'm still confused how the B factors in

[fossil locust]

Yeah a property of the determinant is that the determinant is 0 if and only if the rows are linearly dependent

Or the columns are linearly dependent

[fossil locust]

So here b = -1

(and p and q are not zero)

[dusky wing]

So if I drop the last row and take the determinant that will show me?

[fossil locust]

So we've found constants that are not all zero

[fossil locust]

Yes, that's another way of doing this problem

[dusky wing]

Ok let me try that really quick

So I just want to make sure I justify it correctly

I can drop the last row because if the properties of the determinant state that if the columns have the determinant 0 they are linearly dependent

I think there's some sort of disconnect here and I can't figure it out

@fossil locust I am confused by how I can either justify the determinant or use the other method

The other method seems easier but I cant seem to grasp exactly what you are saying

[fossil locust]

This

Well there's a proof for what I said

[fossil locust]

Oh wait this has to do with that the rank of v1, v2, v3 is at most 3

Where we think of the rank as the dimension of the column space, so how many linearly independent column vectors there are

But then the dimension of the column space is the same as the dimension of the row space (that's a theorem)

So the dimension of the column space is at most 3, and hence the dimension of the row space is at most 3

So the 4th row doesn't tell you any new information

As in, you only need 3 rows and you can ignore any other row

[dusky wing]

Ohhhhh

That makes so much more sense

After taking the determinant I got 6-3B

Should I just set that =0

And solve

[fossil locust]

Yes

[dusky wing]

That gives B=2

Which is the final answer?

[dusky wing]

Does that seem right?

Because earlier you said B=-1

[fossil locust]

I said that v2 = v3 - v1

So beta = -(-2) - 0 = 2

[dusky wing]

Ohhhhh

[fossil locust]

That's correct

[dusky wing]

I am on wayyyy too little sleep for this lol

Thank you man

I appreciate it

[fossil locust]

Hold on

[devout snow]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[dusky wing]

Oh?

[fossil locust]

Wait pls don't delete the original message

I think it's v2 = v3 - v1 instead

[dusky wing]

Wait huh?

I still got B=2 after taking the determinant

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal laurel]

https://www.youtube.com/watch?v=kYB8IZa5AuE&list=PLZHQObOWTQDPD3MizzM2xVFitgF8hE_ab&index=3&t=199s

at 6:05, does it counts as a voice crack

[royal laurel]

I would like to confirm that is a voice crack.

[mighty knoll]

Not the 3b1b voice crack 😭

[sour crypt]

bomboclaaat

[wicked turtle]

man makes slightly odd noise with his mouth, someone opens a doubt channel about it

[quaint citrus]

gs has achieved status similar to certain figures in the hierarchy

namely terence tao and troposphere

his Sirness is unquestionable

[devout snow]

@royal laurel Has your question been resolved?

[fossil locust]

At 3:22

Some linear transformations are simple to think about. (...) Others are a little trickier to describe with words.
It's the way that Grant puts emphasis on words by using a creaky high voice

Not all the time but at certain moments

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

Let g(x) = ax^3 - 3x, if x =< 1 and bx^2 + 2 if x > 1. Find numbers a and b that make the function g differentiable at 1

[fossil locust]

It has to be continuous first at x = 1

[restive river]

Yes

g(1) = a-3

[fossil locust]

Yep

[restive river]

I did lim(x->1-)

And found the limit as 3a-3 after factoring

[fossil locust]

The other thing you need is the derivatives to be the same from both the left and the right

[restive river]

exactly

[fossil locust]

In other words, the derivative function must also be continuous at x = 1

Yeah ok

So what are the 2 equations you get?

[restive river]

and now that I found 3a-3, I know that lim(x->1+) = 3a-3

[fossil locust]

Yeah so you need the limits from the right yes

You need to use the information in bx^2 + 2, x > 1

[restive river]

So I have:

lim(x->1+) (bx^2 + 5 - a)/(x-1) = 3a-3. Since x is not 1, then I have
bx^2 + 5 - a = 3ax - 3x - 3a + 3. Since x -> 1:
b + 5 - a = 3a - 3 - 3a + 3 ->
a - b = 5

[fossil locust]

More simply, a - 3 = b + 2

[restive river]

Oh wait, I made a mistake

yea, now I have a-b = 5

[fossil locust]

Okok

[fossil locust]

But yeah do you see where this comes from?

You can get this directly

[restive river]

hmm, let me think for a sec

how did u get that?

is there a shortcut?

[fossil locust]

Yes, just sub x = 1 into bx^2 + 2

[restive river]

Oh yeah, it makes sense

[fossil locust]

bx^2 + 2 may not be defined at x = 1

[restive river]

yeahh

to find the limit u just need to plug

[fossil locust]

But its limit certainly exists for x = 1+

[restive river]

the x into it

[fossil locust]

Yeah

That's it

[restive river]

i missed that

and now what am I supposed to do? we have a-b = 5

I don't think we can do anything else

we just need any a, b numbers such that a-b = 5

[fossil locust]

You need to do the same thing for the derivatives of ax^3 - 3x and bx^2 + 2

[restive river]

oh, so we have:
3ax^2 - 3 = 2bx + 2. Since x = 1 ->
3a - 3 = 2b + 2
3a - 2b = 5
a - b = 5 -> b = 2a
then a = -5 and b = -10
they have to be continous, true

[fossil locust]

Yeah that's it, so once you have a - b = 5 and 3a - 3 = 2b + 2 you should be fine

Yep that's correct by subbing those values in

[restive river]

appreciate the help south

[fossil locust]

No worries

[restive river]

.close

[devout snow]

Channel closed

Closed by @broken perch

Use .reopen if this was a mistake.

[restive river]

.reopen

[devout snow]

✅

[restive river]

A tangent line to the hyperbole yx = c is traced in a point B.
a) Show that the midpoint of the segment of this tangent line by the coordinate axes is P
R: y = c/x. Let P(x, c/x) and the line be bx + d
dy/dx = -c.x^(-2) = b.

-c/x + d = c/x -> x = 2c/d. Now we know that P's coordinates are (2c/d, d/2)

-c/x + d = 0 -> x = c/d. (c/d, 0) and (0, d). And now the midpoint is (2c/d, d/2). Proved

could you take a quick look @fossil locust? I thought it would be faster instead of opening another help

[fossil locust]

I'm busy rn, pls ask someone else

[restive river]

.close

[devout snow]

Channel closed

Closed by @broken perch

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime tinsel]

i need help with sum simultaneous equations elimination method

[prime tinsel]

3x + 2y = 25
2x + y = 16

i forgot how do it over break

[lost laurel]

elimate x or y first

for instance, multiply the second expression by 2

[winter patrol]

*equation

[devout snow]

@prime tinsel Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[empty barn]

f : R → R is defined with f (x) = x2 + 4x + 4 how to be sure that function is injective or surjective 100%?

[empty barn]

i usually just try x = (from -5 to 5) and then see if this is right with all values for x: f (x1) = f (x2) and x1 = x2

[late rose]

hey

[empty barn]

or there is 2 values for x with same f (x1) = f (x2)

[late rose]

you can use graphical approach

[empty barn]

how?

[late rose]

for example

lets say you wanna check

one-one

you draw a horizontal line, if its cuts at more than 1 point

then its not one-one

[empty barn]

ok i understand

[late rose]

and for onto

check the minimum value of the function

[spring solstice]

you can also use desmos for a graphical calculator ( no offense )

[late rose]

I kinda prefer not using desmos most of the time, cuz in exams they dont provide you with desmos

for explanation purposes yeah

from the graph you can see that the function is never negative

[empty barn]

and what do i need to do with minimum value?

[late rose]

im talking in general*

because for onto function

co-domain has to be equal to the range right

[empty barn]

yea

[late rose]

here the co-domain is all real numbers

but the range does not include negative numbers

therefore its not onto

[empty barn]

ok i will try to use that

thank you

[late rose]

have a nice day

[devout snow]

@empty barn Has your question been resolved?

Channel closed

Closed by @empty barn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[errant turtle]

I roughly know that e^z is a good starting point, but I can't quite figure out how to organize it. Can anyone help me with this? Thank you very much.

[errant turtle]

I try to solve the equation like this, but i stuck here

[devout snow]

@errant turtle Has your question been resolved?

[errant turtle]

<@&286206848099549185>

[devout snow]

@errant turtle Has your question been resolved?

[devout snow]

@errant turtle Has your question been resolved?

[errant turtle]

I give up

.close

[devout snow]

Channel closed

Closed by @errant turtle

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[paper musk]

Let's say I have a function 2xy = 10
If I do implicit differentiation w.r.t x on this equation as follows:
d(2xy)/dx = d(10)/dx
2x(dy/dx) + 2(dx/dx)y = 0 (By product rule)
2x(dy/dx) + 2y = 0
dy/dx = -y/x (By rearranging)
We get that dy/dx = -y/x
Considering that dy/dx means the change in y with respect to x that means that the "sensitivity" of change in y w.r.t x at a given point also depends on y itself. How does that make any sense? How am I supposed to interpret this?

[paper musk]

If we look at the equation dy/dx = -y/x we can say that y is less sensitive to change with higher values of x as it is in the denominator. So with higher values of "x", "y" should increase or decrease slowly. But what is the point of the y in the numerator? In the graph of 2xy = 10 we can see that y has only one value for a given value of x, So shouldn't this relationship be simply knocked down to depending on x? is what I have been thinking

[sterile geyser]

if u rlly dont want f(x,y), u can rearrange 2xy=10 to isolate y and input that into y'=-y/x

generally tho, y' can depend on the original function, thats where differential equations come from

like y'=ky means the rate of change of y is proportional to itself

[paper musk]

Hmmm, I see. So something like:
y' = -y/x = -5/x^2 (as y = 5/x from 2xy = 10)

But would this be valid? 2xy = 10 as y = 5/x is not defined on 0?

[sterile geyser]

it would be valid

y'=-y/x is also not defined at x=0

[paper musk]

Oh yeah, that makes sense

[paper musk]

if lets say we had an equation where it was defined at 0. Would then substituting an equation into it which is not defined at 0 be an "illegal move"?

Welp, nevermind, I'm going to sleep so I should close this one

.close

[devout snow]

Channel closed

Closed by @paper musk

Use .reopen if this was a mistake.

[sterile geyser]

that generally wont happen if u work ur way consistently

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[queen holly]

I am trying to understand eqn 20.5, apparently it follows from a markov assumption that z_t is only dependent on z_t-1

[queen holly]

I guess I'm more so trying to prove 20.5

x can be interpreted as z_0

I can provide more context if necessary

This is probably a better picture

<@&286206848099549185>

[gilded monolith]

<@&286206848099549185>

[devout snow]

@queen holly Has your question been resolved?

[devout snow]

@queen holly Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[balmy stag]

I have no idea how to go about this. I think it's mean value theorum but I'm not sure. Could someone help?

[tall knoll]

not mean value theorem, but definitely one of the other theorems you've been introduced to

[balmy stag]

It's rolles then

but I have 0 clue how to do that lmao

[tall knoll]

well what is rolle's theorem?

actually you probably can use mvt but let's stick with rolle's

[balmy stag]

Honestly I couldn't explain it

[tall knoll]

that's a problem

[balmy stag]

I just know it's when f'(c) = 0

something related to that yeah

[balmy stag]

I agree

[tall knoll]

you should probably look at the statement of rolle's theorem again

[balmy stag]

Its when f(a) = f(b)

so there has to be a point where f'(c) = 0

is it just because v(4) and v(10) both equal each other

so its guaranteed that there is a value such that a(c) = 0

[tall knoll]

indeed

[balmy stag]

because its continuous

are all velocity functions continuous

also how would I phrase the answer to this then

[tall knoll]

velocity functions do tend to be continuous indeed

i don't want to think about the physics implications if they weren't

[balmy stag]

Yeah

Thanks

.close

[devout snow]

Channel closed

Closed by @balmy stag

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hazy drift]

how would i find this limit

$\lim_{x\to0} (1+x)^{1/x}$

[woven radish]

notnick

[sand dove]

$a^b = e^{b\ln(a)}$

[woven radish]

rafilou2003

[hazy drift]

how does that help me find this limit, as i still am stuck

[devout snow]

@hazy drift Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pallid oasis]

Why is the reference angle 60 and not 120 or 240?

[winter patrol]

reference angles aka related acute angles are acute

[pallid oasis]

Why is 60 related to -300 though

[winter patrol]

that's the acute angle between the terminal side and the x-axis

which are how those reference angles are defined

[pallid oasis]

Ah ok so it has to be the reflected side of the x-axis?

[winter patrol]

no

no reflection needed

[pallid oasis]

No ik i meant like

When i look at -300 and look across the x-axis it would be 60

Well no it seems it would be -60 but im just confused

[winter patrol]

since its negative, you'd go anticlockwise

[pallid oasis]

Ohh ok

I see

[winter patrol]

that angle would be 60°

-300° is also coterminal with 60° which happens to be acute

[pallid oasis]

And the - coterminal would be -360?

Or wait

-420?

No

-720?

Wait ok

So the positive coterminal is 60 and the negative is -660

.close

[devout snow]

Channel closed

Closed by @pallid oasis

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal venture]

im not sure what to do

[vapid nest]

don't you gotta do like $s_n - s_{n-1}$

or sm

[woven radish]

nosqldb

[vapid nest]

or am I tripping

[formal venture]

Thats what i was told

but like

im not sure what that means

lol

[vapid nest]

think about it like this

ur like a cookie dealer this summer

and you note down all the sum of the profits

after each order

if you forget the most recent purchase, you just subtract ur current sum with the last sum you wrote down

[formal venture]

im not confused on the topic

im confused on what the answer is expecting

[vapid nest]

algebra

[formal venture]

womp

I meant like

[vapid nest]

$\frac{n-6}{n-7}-\frac{\left(n-1\right)-6}{\left(n-1\right)-7}$

[formal venture]

I guess im nto understanding the topic

[woven radish]

nosqldb

[vapid nest]

sm like that

but simplify

[formal venture]

Not sure why that'd be the answer but okay

thank you

[vapid nest]

what

[formal venture]

im not understanding it at all is all

[vapid nest]

^

$a_n = s_n - s_{n-1}$

do you get from this point?

[woven radish]

nosqldb

[formal venture]

We didn't learn partial sums anything like that

so its not making sense at all

Thats something new to me

[vapid nest]

read my example tho

aight fine I'll give you another example

tell me something you like to do over the wekeend

[formal venture]

your example confuses me

uh

Lets make the example paying for gas

[vapid nest]

aight ur a gas attendant

let's say you are attending customers and you get a % of the total profits in the day

so you keep a note of the sum of gas prices at a certain point

so a civic pulls up, they spend $30 on gas so you note down $30 on ur paper

a bmw pulls up, they spend $60 on gas so you note down $30 + $60 on ur paper

[kindred agate]

The partial sum is the sum of the first N terms. If you want to get the Nth term, you take the partial sum up to N and subtract what it was before you added the Nth term

[vapid nest]

this is the same idea of a partial summer

now say you put on ur headphones

and you attend a customer and you note down the "current" sum

[kindred agate]

Partial sum up to 5 is a1+a2+a3+a4+a5. If you want a5, you subtract all the terms except a5

[vapid nest]

and your supervisor asks about how much they spent on gass

[kindred agate]

Thats a1+a2+a3+a4

[vapid nest]

you would take the current sum (let's say it's $120) and subtract by the previously noted sum

[kindred agate]

Which is partial sum up to 4

[vapid nest]

so $120 - $90 = $30 (cost of that car)

same idea

[formal venture]

So youre subtracting the partial sum up to N from a1 basically?

[kindred agate]

You are subtracting partial sum up to N by the sum of the terms except N

1+2+3 - (1+2) = 3

[formal venture]

Thats honestly gibbeirsh to me, and I'm not sbure why

[kindred agate]

For example

You want a_n and you have the sum of the terms until n

So you have like a1+a2+a3 when n is 3

What do you subtract to get a3

[formal venture]

a1+s

a2

bc if its like

1+2+3 it equals 6, but if i wanna get to a3, id subtract 1+2

[kindred agate]

Yes

[formal venture]

and if n is 3

[kindred agate]

And what is 1+2

[formal venture]

n-1 is 2, and then n-1 again is 1

[kindred agate]

In terms of partial sum

[formal venture]

3

[kindred agate]

Yes but like

In terms of partial sums

Of the sequence 1,2,3…

What is 1+2

Its the partial sum of the first…

[formal venture]

not following

partial sum of the first plus the partial sum of the second

[kindred agate]

The partial sum UP TO 2

1+2 is the partial sum of 1,2,3,… up to 2

1+2+3 is the partial sum UP TO 3

so when you subtract 1+2+3 - (1+2) you are doing partial sum up to 3 minus partial sum up to 2

s_n -s_(n-1)

[formal venture]

ah

[devout snow]

@formal venture Has your question been resolved?

Channel closed

Closed by @formal venture

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pallid oasis]

Anyone able to help im not really sure what to look up

I know the first one only because its on the unit circle

[tall knoll]

are you allowed a calculator?

[pallid oasis]

Yes

[tall knoll]

well then it's really just plugging and chugging

[pallid oasis]

Yea ig im just not sure what to do lol

[tall knoll]

how did you do a

[pallid oasis]

I have a unit circle with it preprinted

Already told me the coordinates of 45 degrees

Which im allowed to use

[tall knoll]

can i see this print?

[pallid oasis]

Oh wait

Im thinking wrong about this i think

[tall knoll]

perhaps

[pallid oasis]

Jeez i cant find any videos giving the same examples though

I thought i should originally have passing points given for each

But yea idk

[tall knoll]

idk what i was expecting but that printout isn't as helpful as I'd have liked

[pallid oasis]

Yea sorry thats all im allowed

[tall knoll]

anyway here's how you can visually approach this problem

take any of those points, and draw a line either up or down so that it hits the x-axis

actually nvm let me just draw it

[pallid oasis]

Well i should be making a triangle

Right

[tall knoll]

right

,rccw

[tall knoll]

pretend the circle is drawn better

now since you're working with the unit circle, what is h?

[pallid oasis]

Which part

Pi/4 or the coordinate

[tall knoll]

in my drawing

[pallid oasis]

Oh

The terminal sode

Side

[tall knoll]

yes but what is it?

[pallid oasis]

Of the angle

[tall knoll]

it's the same value for all possible drawings

[pallid oasis]

45

Oh

Uh

[tall knoll]

how long is h

[pallid oasis]

1

[tall knoll]

1

so you know the angle (it's given), and you're looking at a right triangle where you know the hypotenuse

what tools sound like they'd be helpful with extracting the values of x and y?

[pallid oasis]

Cos tan sin

Alr

[tall knoll]

i'm on board with two of those

one of them sounds pretty unhelpful for this task

[pallid oasis]

No yea i just named the main 3

Cos and sin

[tall knoll]

better

[pallid oasis]

I got .71 for both

[tall knoll]

for which?

[pallid oasis]

X and Y

[tall knoll]

question b?

[pallid oasis]

No a

[tall knoll]

ah ok

then yes

[pallid oasis]

I can do b though

[pallid oasis]

Thats not final though right?

[tall knoll]

is it not?

[pallid oasis]

Well why is it converted to be like sqrt2/2

Also will it work the same if i convert rad to degrees and then solve

[tall knoll]

sqrt(2)/2 is the exact form, but the question asks you for decimals

[pallid oasis]

Yea ur right but if i were to need exact form how would i go about that

[tall knoll]

if they're not on the printout, you'll have to do extra work to get them

[pallid oasis]

Yea its fine for now thank you

[tall knoll]

if you've been taught some trig identities (like sin(a+b) and all them) then you can arrive at the answer

but it's not necessary for this problem i don't think

[pallid oasis]

For b was it -.81

And -.59

Oh wait

234 degrees is has a length of (0,-1) right?

Or is it (-1,0)

Ok it’d be (0,-1)

[tall knoll]

it has a length of 1

well ok 234 degrees doesn't have a length of anything

[pallid oasis]

Yea u know what i mean though

[pallid oasis]

Even if its in Q3?

[tall knoll]

you're working with the unit circle, every line drawn from the origin to the circle has length 1 by definition

regardless of the angle you're forming

[pallid oasis]

Then whats the point of the negative coordinates

[tall knoll]

i don't see how the two are related

[pallid oasis]

This quarter is where 234 degrees would be and the length becomes negative

Is what im asking

Does the x and y coordinate value on the bottom there and left have nothing to do with it?

Otherwise i just guessed the length was 1 lol

[tall knoll]

length is never negative

[pallid oasis]

So the length of that line is always 1?

[tall knoll]

yes

[pallid oasis]

Interesting

I do have another question though

Why when i do trig for sin does it equal 13

Oh wait

Whoops

Im not sure why i have such a hard time with csc sec and cot

Any guidance to the right direction lol

[devout snow]

@pallid oasis Has your question been resolved?

[pallid oasis]

.close

[devout snow]

Channel closed

Closed by @pallid oasis

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid rain]

if someone could help me figure out what side a semi ellipse goes on that would be much appreciated 👍

[livid rain]

I've solved these two problems but I can't figure out why in question one it has a y-range from [0, 4]

same with question two, why does it have a range of [-10, 0]

aka how do I figure it out

[regal moat]

choose a random x value, subs it in

You should get a y value in return

So if the y > 0; u know the semi ellipse is on the positive side

[livid rain]

ok thank you

.close

[devout snow]

Channel closed

Closed by @livid rain

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limpid sorrel]

can anyone help explain how part a and b has been solved

[regal moat]

So

cos(x) can only go from -1 to 1

Then 8 * cos(x) can go from -8 to 8

4+ 8*cos(x) can go from -4 to 12

So v must be in between those value; thus -4 < v < 12

[devout snow]

@limpid sorrel Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mossy yacht]

(4/sqrt243)^5

[distant harbor]

What?

[vapid nest]

let's think about this

[soft umbra]

!status

[devout snow]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[midnight grove]

how can you rewrite fractional exponents

[mossy yacht]

^5sqrt243^4?

[midnight grove]

yea thats right

wait actually nvm

theres a shorter way

do you know what you can do with 243

[mossy yacht]

Teach me

[midnight grove]

what do you notice with the number 243

ill give you a hint

it can be expressed as a power

[mossy yacht]

It an whole number

[midnight grove]

try to find a way to express 243 as a power

for example,

81 can be expressed as 9²

125 can be expressed as 5³

or even 64 can be expressed as 2⁶

ill give another hint

try to find the prime factorization of 243

what do you think can divide 243

[mossy yacht]

6

[midnight grove]

thats not right

,w 243/6

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by reenziee

[midnight grove]

it gives a decimal

the quotient should be a whole number

[mossy yacht]

9

?

9*27

[midnight grove]

yea

thats right

but you can still expand 9

what numbers, when you multiply them gives you 9

except for 1 and 9

[mossy yacht]

3

oo

??

[midnight grove]

#❓how-to-get-help

please open a new channel

this channel is already taken

[midnight grove]

yes, 9 is basically 3x3

so what we do is, we rewrite 243 like this:

,,243=9\cdot 27

[woven radish]

Renz

[midnight grove]

rewrite 9 into 3x3

,,243 = 3327

[mossy yacht]

3^5

[woven radish]

Renz

[midnight grove]

yea you got it

replace 243 with 3^5 in the question

we get

,,(3^5)^\frac{4}{5}

[woven radish]

Renz

[midnight grove]

now we have a power of a power

what do we do to the exponents we are raising a power to a power

[mossy yacht]

multiple?

[midnight grove]

yea

correct

so whats 5 * 4/5

[mossy yacht]

4

[midnight grove]

now

,,3^4

[woven radish]

Renz

[midnight grove]

whats that

[mossy yacht]

243?

33=9 * 3=273

[midnight grove]

its not 243

[midnight grove]

whats 27*3

[mossy yacht]

81

[midnight grove]

ye

then the answer to the question should be 81

[mossy yacht]

yea now it make sense, I was struggling to think factor of 243
Thank you Renz

.close

[devout snow]

Channel closed

Closed by @mossy yacht

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry jolt]

Is this proposition correct?

∀x ∈ R, ∃y ∈ R, [(x - 4y) ≠ 5] -> (3xy <= 0)

Can someone help me with this? I have no idea how to do this one the right way

[green grove]

my initial idea is to represent y in terms of a product of x

(x - 4y) ≠ 5 pretty much excludes the case of y = -x when x=1 and probably theres some kind of patter nto it

but doesnt exclude the case of $y = -\frac x2$

[woven radish]

Xerunox

[eternal tapir]

two cases

x = 5 or x != 5

in the latter, there's a very obvious y value that satisfies it

[green grove]

i imagined it would be more of a case of x < 0, x > 0 and x = 0

[eternal tapir]

you can do it like that

but you're probably overthinking it

[green grove]

maybe

[eternal tapir]

hint it's extremely super duper obvious

[wintry jolt]

uhhhh

[eternal tapir]

when is 3xy = 0

[wintry jolt]

y = 0???

[eternal tapir]

yes

[wintry jolt]

what

is that really it

[eternal tapir]

if x is not 5, use y = 0

if x is 5

then what

[green grove]

for all cases x != 5

so just find any case for x = 5

[wintry jolt]

oh

aight

[green grove]

hint

you dont need to solve for it

[wintry jolt]

wait

can i just

put it as y = -1

[green grove]

yep

[wintry jolt]

when x = 5

oh my god bro

[green grove]

any negative number works

[wintry jolt]

these proposition questions get out of hand sometimes man

[green grove]

i feel your pain it feels like it wouldnt be so obvious

[wintry jolt]

im so used to picking y=something related to x

aight thx yall

.close

[devout snow]

Channel closed

Closed by @wintry jolt

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland moth]

I simplified the numerator and denominator by taking n²common

Got [∏rx/n+1 ÷ ∏ (rx/n)²+1]^x/n

then took log both sides

after which I am stuck

[inland moth]

And btw it's a multiple correct question where one or more than one option can be correct

<@&286206848099549185> anyone?

[devout snow]

@inland moth Has your question been resolved?

[devout snow]

@inland moth Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fervent ledge]

what is domain of a function

[fervent ledge]

my teachers only teach me that put x=1,2,3,0,-1,-2,-3

if the values are real then domain belongs to real numbers

but what rlly is domain

[polar bolt]

https://en.m.wikipedia.org/wiki/Domain_of_a_function

[devout snow]

@fervent ledge Has your question been resolved?

[fervent ledge]

.close

[devout snow]

Channel closed

Closed by @fervent ledge

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stuck trellis]

15r^2 −16r−20=−5

[midnight grove]

are you solving for r

[twilit comet]

solve for r?

quadratic formula

[stuck trellis]

Yes

[woven radish]

ren

[twilit comet]

@stuck trellis ^^

[stuck trellis]

I understand the formula,

[twilit comet]

alr

so what's the issue

[stuck trellis]

Sooo you start out doing +5?

[oblique mirage]

To use the quadratic formula just make sure to move the -5 in your equation to the other side so that the equation is set equal to 0

[twilit comet]

yes

[twilit comet]

exactly

[stuck trellis]

Ahh gotcha

[twilit comet]

just one extra step lmao

[stuck trellis]

Alright, one step

[twilit comet]

mhm

[oblique mirage]

Then identify a b and c

[stuck trellis]

Ooops no I meant one second,

[twilit comet]

alr

take ur time

no rush

[stuck trellis]

A,b,c, oki

Now plug into formula?

[twilit comet]

soooo

what'd you get

[stuck trellis]

-20+5 is not 25? Is it?

[twilit comet]

...?

how is -20 + 5 = 25?

[stuck trellis]

-15?

[twilit comet]

yes

where'd you get 25 from...?

[stuck trellis]

I messed up I Thought it was addition

[twilit comet]

alr

what'd you plug into the formula?

[oblique mirage]

Ok so what is your a your b and your c?

[twilit comet]

show your work

[stuck trellis]

Sending image in one sec

[twilit comet]

alr

[twilit comet]

okay first of all

that handwriting is REALLY large and sort of incomphrensible

secondly

[stuck trellis]

….. sorry

What esle?

[twilit comet]

you need to divide in the quadratic formula

[oblique mirage]

Its fine

[twilit comet]

where's that

[oblique mirage]

So

[twilit comet]

?

[stuck trellis]

I know. I haven’t gotten that far yet

[twilit comet]

ah

alr

[stuck trellis]

You wanted to see my woke

[twilit comet]

lmk when u get there

[stuck trellis]

*work

[twilit comet]

is alr

[stuck trellis]

So I sent it this far

[twilit comet]

np np

just ping me when u get there

[stuck trellis]

?

[oblique mirage]

Nvm it was a 2a I read it as 20

[stuck trellis]

Oh ok

[oblique mirage]

So your variables look correct. So plug them into the formula.

Don’t solve just yet let’s work through it together

[stuck trellis]

1156?

[stuck trellis]

Saw this last min my bad

@oblique mirage can I dm you? Bc I’m actually running outta time on my lunch shift and seems you can help me further when I have time again

[twilit comet]

again, replying to this in case u need it anytime soon

[oblique mirage]

Yea go ahead

[stuck trellis]

Thanks

[oblique mirage]

You can ping me or ren

[twilit comet]

np

[stuck trellis]

Oko

[twilit comet]

feel free to DM me

idm

[oblique mirage]

I may be busy from 12:20-2:20 EDT

[stuck trellis]

Imma stay til I have to go.soo lemme send my work again

[twilit comet]

alr

[green crypt]

Doesn't your about me have "no dm me"?

[stuck trellis]

Alright yall. In one min I gotta go. So imma go now. Thanks for your help and imma dm either of ya soon

[twilit comet]

not anymore idt

[twilit comet]

and that's only bc randoms DM me; idm if someone asks

[green crypt]

Gotcha

[oblique mirage]

Felt

[twilit comet]

?

[devout snow]

@stuck trellis Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy talon]

If an amount X of shoes was sold for 6 dollars, how many shoes are sold for 11 dollars, if there is a total of 200 shoes

that's it

so you have X sold for 6 and 200-X sold for 11

do you know how to write the equation now

What's bugging you

[twilit comet]

let's say "x" shoes were sold for 6 dollars

what is the total... price? idk
for those shoes

no no no

ONLY for the 6 dollar shoes

why ;-;

stephen

why

okay

let's say i buy "x" shoes

each shoe

costs 6 dollars

what is the total cost

mhm

very good

let's say i buy "y" shoes

each shoe costs 11 dollars

what's the total cost this time?

very good!

now we know that there are a total of 200 shoes.

so, x + y = 200, yes?

very good

and we know that the separate costs are 6x and 11y

the TOTAL cost is 1600

doesn't matter, y is basically 200-x (rearrange; you'll see)

[devout snow]

Channel closed

Closed by @barren lake

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland moth]

<@&286206848099549185>

[devout snow]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[twilit comet]

dude

don't ping is in ur original message

WAIT

[inland moth]

oops

[bright pumice]

oh hey

did you solve your prev integral

[inland moth]

yes I did

thanks for helping

[inland moth]

Nvm i got this question

[devout snow]

@inland moth Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

Hello ,
i need help with this
" What is the equation of a circle whose center is on the line 5x-2y=-21, and is tangent to both coordinate axes? "

[winter patrol]

what have you tried

[thin fern]

If it's tangent to both axes, what does that say about where the center of the circle must lie?

[restive river]

No thing i dont know how to start

[winter patrol]

also is this the full question as there will be two solutions

[restive river]

here

[restive river]

Yeah

[thin fern]

What does that mean

Give something that will help you toward a solution

[winter patrol]

draw a few circles tangent to both axes, in different quadrants (preferably on grid paper)
tell us what you recognise about the coordinates of the centres

[restive river]

center is equidistant from both axes

[winter patrol]

what do you see when you look at the coordinates of those points

[restive river]

equals r

[winter patrol]

no

the coodinates themselves

look at the first circle you drew

what are the x and y coordinates

[restive river]

equal ?

[winter patrol]

what about one of the circles in a different quadrant

[restive river]

same but different signs

[winter patrol]

yes

so from that, the centres would lie on either
y=x
or y=-x

and to find the centres, find where these lines intersect with the given line

[restive river]

How can we determine the quadrant in which a given line lies?

or just use both

x=y
x=-y

[winter patrol]

consider both cases

hence why i asked whether there was more info at the start

[restive river]

either (-7,-7) or ( -3,3 )

[winter patrol]

yes

[restive river]

and r is | h | = |k| so its 7

[golden flower]

If i were u id graph the line

Idk

[restive river]

so
eq's are (x+7)^2+(y+7)^2=49
and
(x+3)^2 +(y-3) ^2 = 49 ?

[winter patrol]

wrong r^2 value for the second equation

[restive river]

oh yes

(x+3)^2 +(y-3) ^2 = 9

[winter patrol]

yes

[restive river]

But the center of the yellow circle does not lie on the given line

[golden flower]

it does

[winter patrol]

you didn't enter the equation properly

swapped the signs around

[restive river]

oh my bad

thank you

.close

[devout snow]

Channel closed

Closed by @tawny tinsel

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

Hello! I'm having a difficult time understanding this concept. Some help would be really appreciated.

[pure flower]

The concept as in?

[restive river]

Unions, I think that's what it's called, the u sign

So A is 12, and B is 13, the deck in total is 52 cards

What's N then

[pure flower]

Yes

[restive river]

[pure flower]

N is the number of elements in a set

[restive river]

So, this would be 2 elements? (Face cards and diamonds)

[pure flower]

no like

How many diamonds are also face cards?

[restive river]

Oh

3

[pure flower]

yeah

so $n(A \cup B)=3$

ah damit

what was the symbol

there we go

[woven radish]

Percy

[pure flower]

WAIT

FUCK

I JUST DID AN INTERSECTION

NVM IM SORRY

[restive river]

Lol, it's alright

[pure flower]

im tired

anyway