cerulean wind
thanks
#help-27
queen dirge
devout snowBOT
formal bronze
How did you write this?
queen dirge
How did you write this?
ah that was supposed to be just 3/e^x
Forgot to convert it so i just put an arrow next to it
formal bronze
Oh its arrow
queen dirge
yeah
queen dirge
uhh
thought that since its - 1/e^2x
When i distribute it over the fraction
I can make it so that +1/-e^2x
formal bronze
Make what?
queen dirge
oh, so 1/ - e^2x isnt equal to - (1/e^2x)?
8 / - 4 = - 2 , - 8/4 = - 2 so i thought..l
<@&286206848099549185>
abstract moss
@queen dirge if you mean $$\frac{1}{-e^{2x}}=-(frac{1}{e^{2x}}) $$ then you are right it is true..
woven radishBOT
ideal_37
abstract moss
I don't really know how to proceed to I just bashed lopithols rule on all limit problems :/
Lol
marsh wharf
Could someone explain why 17 is incorrect? There is a point at 0 so why does it not exist?
devout snowBOT
Could someone explain why 17 is incorrect? There is a point at 0 so why does it ...
@marsh wharf Has your question been resolved?
restive river
Fundamental limit rule: $\$ $lim_{x\rightarrow a} f(x)=L \Leftrightarrow lim_{x\rightarrow a^{+}}=lim_{x\rightarrow a^{-}}=L$
woven radishBOT
Danty ⛧
restive river
Translated, the limit of a function f(x) is a number L if and only if the side limits of the function exist and are equal to L
See, looking at the graph of the function, the limit when x tends to 0 from the right is zero
Although
The limit of the function when x approaches zero from the left explodes to infinity
Therefore, the lateral limits are different
Therefore, the limit of the function when x tends to zero is not Exist
$lim_{x\rightarrow 0^{+}}f(x)=0 \
lim_{x\rightarrow 0^{-}}f(x) = \infty\
lim_{x\rightarrow 0}f(x) \nexists$
woven radishBOT
Danty ⛧
marsh wharf
Therefore, the lateral limits are different
So basically if the limits from each side are different then the limit does not exist?
tender cobalt
- use
\liminstead to get the limits to look right - use
\tosince its shorter than\rightarrow - the proper way to write "doesnt exist" is just DNE
restive river
So basically if the limits from each side are different then the limit does not ...
That's right
restive river
* use `\lim` instead to get the limits to look right
* use `\to` since its short...
Oh, Thanks
marsh wharf
$lim_{x\rightarrow 0^{+}}f(x)=0 \\
lim_{x\rightarrow 0^{-}}f(x) = \infty\\
lim_{...
Could we also just look at the symbols under the limit notation as well?
Like since x->0 doesn’t specify whether is it approaching left or right could we just say it DNE
restive river
The natural limit process (when there is no "+" or "-" specified) means that we are approaching the values of x from both sides simultaneously
Therefore, it is important that the lateral limits exist and are equal
For example, if we want to calculate the limit of the function|x|/x when x tends to zero
$\lim_{ x \to 0} \frac{|x|}{x}$
woven radishBOT
Danty ⛧
restive river
Can you tell if this limit exists just by looking at this function?
marsh wharf
I cannot
restive river
Ok
First we must analyze the Function
See that we have |x| which is the absolute value of x, that is, it will always be positive
And in the denominator we only have x, which can have both positive and negative values
Are you Understanding ?
marsh wharf
Mhm I understand so far
restive river
Ok
Continuing
Knowing this, we now analyze where the values of x are approaching through the limiting process, in this case to zero
We then calculate the lateral limits of each side
Since the function |x|/x is a simple b function, we can do this in our head
First we calculate the lateral limit on the left, that is, $\lim_{x \to 0^{-}} \frac{|x|}{x}$
woven radishBOT
Danty ⛧
restive river
In this case, the values of x are all negative
However, |x| is always positive
Then we have the case that $\frac{-x}{x}=-1}$
woven radishBOT
Danty ⛧
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
woven radishBOT
Danty ⛧
restive river
Do you understand?
Now we do the same for the lateral limit on the right
$\lim_{x \to 0^{+}} \frac{|x|}{x}$
woven radishBOT
Danty ⛧
restive river
However, this time, x will always be positive
So |x|=x
Therefore
$\lim_{x \to 0^{-}} \frac{|x|}{x}=1$
woven radishBOT
Danty ⛧
restive river
See that the lateral limits were different
This means that the limit of |x|/x does not exist when x tends to
We can see this from the graph
marsh wharf
Ah I see I see
restive river
,w graph of |x|/x
woven radishBOT
restive river
Look
marsh wharf
Ohh okay that makes sense
restive river
See that when we take values of x from the left of the function (negative values) the function has a value of -1
And when we do the same to the right (positive values) the function has value 1
marsh wharf
Mhm I see
marsh wharf
**Danty ⛧**
Just like here and the one above it
restive river
Just like here and the one above it
That's right
But I forgot to change the limit sign there haha srry
restive river
Anytime
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hidden dragon
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hidden dragon
Find the instant at which velocity of stone makes an angle of 45° with +ve x axis.
The initial speed is u
And u is perpendicular to the x axis
The x axis in this case is the incline
I tried doing tanα= Vy/Vx => Vy=Vx => but I'm not getting desirable answer
restive river
the tangent slope should be 0
restive river
the highest point
hidden dragon
Or highest point from ground
restive river
you said the x axis was the incline
hidden dragon
Yeah
restive river
restive river
nice
hidden dragon
But I have a confusion regarding this
What if it had asked the instant at which angle is 45 degree with respect to negative x axis
Would it be somewhere after highest point from x axis
restive river
yes
hidden dragon
How would we calculate that?
restive river
(ds_y/dt)/(ds_x/dt) would give you the slope for every t
restive river
wait
hidden dragon
Ok
hidden dragon
Yeah
restive river
but the previous one was the vertex
hidden dragon
Yeah
I studied that initial speef and final speed of landing of landing are same
Dunno about angle of projection and landing
restive river
youre basically trying to find where the slope becomes -infinity on a quadratic
hidden dragon
But with respect to x axis it will make slope of - tan45
And not slope of infinity
restive river
(ds_y/dt)/(ds_x/dt) would give you the slope for every t
this is based on setting the x axis as the ground
restive river
nice
hidden dragon
Can we use vx=ax * t and vy= u + ay * t and do tan 45= vy/vx?
In that case there is no ds_x and ds_y
restive river
Can we use vx=ax * t and vy= u + ay * t and do tan 45= vy/vx?
the second one?
Or in general
hidden dragon
General
restive river
you can do that
restive river
nice
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hearty nexus
is $x^4+x^2y^2+y^4$ a difference of squares?
devout snowBOT
is $x^4+x^2y^2+y^4$ a difference of squares?
woven radishBOT
rynite
tall knoll
There's no difference at all, so no
tall knoll
Sum of squares? Well you are summing squares, so sure
hearty nexus
Sum of squares? Well you are summing squares, so sure
ah, so this could be factored to (x^4+x^2y^2+y^4)(x^4-x^2y^2+y^4)?
eager lodge
notice that x^4+2x^2y^2+y^4 can be factored
hearty nexus
ah the 4's should be 2
tall knoll
That would still not be correct
hearty nexus
and x^2y^2 -> xy
hearty nexus
(x^2+xy+y^2)(x^2-xy+y^2)
hearty nexus
eager lodge
bruh
it's completely different from what you asked but ok
you can't simplify x^2+xy+y^2 further
hearty nexus
I started with
(x^2)y^3 - (y^2)^3 to make it a difference of cubes
then factored to
(x^2-y^2)(x^4+x^2y^2+y^4)
good so far?
fair storm
$x^6 - y^6 = (x^3 + y^3)(x^3 - y^3) = (x+y)(x-y)(x^2 - xy + y^2)(x^2 + xy + y^2)$
woven radishBOT
Roman_Garland
hearty nexus
I know the answer, I'm asking about the steps
fair storm
What did I show you?
eager lodge
(x^2-y^2)(x^4+x^2y^2+y^4)
it's a bit harder with this approach since it's harder to factorize x^4+x^2y^2+y^4
hearty nexus
ah
hearty nexus
**Roman\_Garland**
actually this makes sense to me thanks @fair storm
fair storm
No problem.
hearty nexus
.close
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snow vessel
Can anyone help me with how to process this?
devout snowBOT
Can anyone help me with how to process this?
snow vessel
Or even where to start? I assume I combine all the terms such as
xy + x(y+1) + y(x+1) = 1/9 + 7/9 + 5/18
devout snowBOT
snow vessel
Can.. you elaborate? I'm not sure sure what you mean..
quiet veldt
yes 35/18
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@snow vessel Has your question been resolved?
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inner ibex
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devout snowBOT
@inner ibex Has your question been resolved?
upbeat cairn
Yes
upbeat cairn
how is cbd = cde
That's because of the property angle in the alternative segment
inner ibex
That's because of the property angle in the alternative segment
i thought
no?
those were supposed to be equal
upbeat cairn
inner ibex
oh wait
upbeat cairn
no?
Nah, remember that the angle on tangent stick to one side of the triangle in the circle
upbeat cairn
Sorry sorry!
inner ibex
its ok we can hope that question
is not in my test
do u know why i did substitution adn i got it wrong
inner ibex
wait b+y is not 180
upbeat cairn
BRUH
upbeat cairn
LOL
inner ibex
I GOT CONFUSED OK
IM STRESSED MY TEST IS TMR
wait 1 MORE QUESTION OK
1 MORE
JUST 1 MORE
upbeat cairn
Ok
soft umbra
inner ibex
in here i solved it using 2 ways*
upbeat cairn
Your formula seems correct
upbeat cairn
I don't get
inner ibex
so do i be like let x be width and y be height
idk how to explain it
its just like making a formula......
OK
so say we have no values for height or width
how would we make the formula for it?
upbeat cairn
Wdym width and height, they don't belong to a circle
inner ibex
wiodth and height to the segment
make a formula finding the radius of a circle when given width and height of a segment
upbeat cairn
Wait
upbeat cairn
Bruhhh
inner ibex
make a formula for the radius
inner ibex
yas
upbeat cairn
Sqrt(r^2-(w/2)^2)+h=r
Like this?
Bruh but you shouldnt recite it, math is not about memorizing
inner ibex
how do i understand it
inner ibex
Bruh but you shouldnt recite it, math is not about memorizing
yes i agre
upbeat cairn
I have to draw one
inner ibex
ye spls
upbeat cairn
soft umbra
Impeccable circle
upbeat cairn
That's a part of the pyth thm
inner ibex
That's a part of the pyth thm
we only have 1 value for pythag
upbeat cairn
we only have 1 value for pythag
You said we have the w
The width
The length of chord
inner ibex
Ye
Its ok i think i can just write this in my notes
Bc for the calc section i get notes
Wait
what if the question is in non calc
umm
inner ibex
You said we have the w
yes we do but then we only have r/2 right
inner ibex
oh u are right
upbeat cairn
inner ibex
now its w/2
upbeat cairn
Nahhhhh
inner ibex
omg
inner ibex
huh..
upbeat cairn
Radius are the same
upbeat cairn
Yes
upbeat cairn
Idk
inner ibex
Sqrt(r^2-(w/2)^2)+h=r
we finding how u got dis
upbeat cairn
Oh
inner ibex
ya
upbeat cairn
w is the length of chord
inner ibex
mhm
inner ibex
wat..
inner ibex
yeh
upbeat cairn
But in your case, the radius=w/2
inner ibex
ye
inner ibex
ye
inner ibex
ye
upbeat cairn
Yes
inner ibex
ya
inner ibex
r-w/2 = OD ^2
upbeat cairn
Bruh
upbeat cairn
Sqrt is √
upbeat cairn
r^2-(w/2)^2 ≠ (r+ w/2)^2
upbeat cairn
Yes
inner ibex
ok isee
upbeat cairn
Just like a^2-b^2 ≠ a-b
inner ibex
ye
upbeat cairn
I mean sqrt
inner ibex
and then just + h
upbeat cairn
Yup
upbeat cairn
And it will be the radius
inner ibex
jk i hate it so much i want to dorp out and never see it again in my life
upbeat cairn
Lmaoo
inner ibex
good night :p unless u see me herer again
upbeat cairn
upbeat cairn
I'm not
inner ibex
.close
devout snowBOT
upbeat cairn
Hey
inner ibex
nope
upbeat cairn
Bye!
inner ibex
ur m,ean
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Available help channel!
hard knot
devout snowBOT
hard knot
uhhh so bascically
I know you can use the double angle formula but is there a way to simplify it?
devout snowBOT
@hard knot Has your question been resolved?
wicked turtle
do you know about complex exponentials?
hard knot
no
wicked turtle
ok, how about telescoping sums?
hard knot
On the side of that,
How dis make sense?
near trout
-
On the side of that,
How dis make sense?
do you know angle sum and angle difference formulae
devout snowBOT
@hard knot Has your question been resolved?
hard knot
do you know angle sum and angle difference formulae
No?
If it’s like drawing related I just use logic
near trout
No?
If it’s like drawing related I just use logic
look up angle sum and angle difference formulae for like sin and cos
you can't do this without them
wild siren
this is a geometric figure to calculate sin 15 without using angle sum formula
oh but the problem requires the formula
sorry nvm
devout snowBOT
@hard knot Has your question been resolved?
somber harbor
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somber harbor
i got the integral but when i plug in inf i get an infinity and a 0
does this mean that it converges
cobalt schooner
is it solved yet ?
supple knot
i got the integral but when i plug in inf i get an infinity and a 0
show your integral
devout snowBOT
@somber harbor Has your question been resolved?
bitter mantle
I need help with reducing this to be vx/vo
devout snowBOT
I need help with reducing this to be vx/vo
supple knot
you need to separate what's given vs. what you manipulated
supple knot
is that just the same image?
supple knot
I need help with reducing this to be vx/vo
is your question to find vx/v0 or v0/vx?
supple knot
both look fine here starting from your 2nd line
bitter mantle
is your question to find vx/v0 or v0/vx?
Needs to be vo /vx
I am checking for also vx/vin
wooden kraken
i always hated circuits
bitter mantle
It simple algebra
bitter mantle
@supple knot is it good then
supple knot
i was really bad at olympiad circuits
!redir
devout snowBOT
i was really bad at olympiad circuits
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
supple knot
both look fine here starting from your 2nd line
again, looks fine from the 2nd line. anything before that could have a mistake
bitter mantle
Okay. As thank you for that and also the vin/vx
Is this good then
I used my ti89 for trying to solve this
@supple knot
supple knot
no idea this is a math server not EE server
#old-network for EE or physics if you want that checked
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Available help channel!
frail sun
How should I start this problem?
devout snowBOT
How should I start this problem?
twin thunder
use the chain rule
frail sun
I'm at
woven radishBOT
Someone
devout snowBOT
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Available help channel!
light needle
devout snowBOT
light needle
I'm doing a one way anova test right now and I have the f statistic and I think i got the p value?
What do i do with the f statistic of 34.33504?
I thought that I just compared the 2.64 to whatever significance level?
so in this case i thought it would've been just 2.64 > 0.05, therefore dont reject Ho
devout snowBOT
@light needle Has your question been resolved?
light needle
<@&286206848099549185>
light needle
<@&286206848099549185> please 😭
devout snowBOT
@light needle Has your question been resolved?
wooden kraken
ew stats
devout snowBOT
@light needle Has your question been resolved?
hollow vortex
I don't understand why i'm wrong, this is my exact work typed out below a screenshot of the original question, i wrote "given C = 37... find..."
devout snowBOT
I don't understand why i'm wrong, this is my exact work typed out below a screen...
solar goblet
pretty sure youre correct
bright phoenix
If the numbers work out your right
restive river
MINE
restive river
R={N, Z, Q} ok so, in the set of real numbers, we got, Natural numbers, Integers (Z), and Rational numbers (Q) but like..what bout the Irrational numbers
tardy mulch
irrational numbers are real numbers
restive river
so are integers but they are still represented in the setr
restive river
BUT THEY SHOULDVE ADDED 'I'
devout snowBOT
BUT THEY SHOULDVE ADDED 'I'
lusty sapphire
BUT THEY SHOULDVE ADDED 'I'
Irrational numbers are sometimes denoted as $\mathbb{J}$ (at least it was for me). They're literally just the real numbers that are not rational. So you can define $\mathbb{J}=\bR\setminus\bQ$
woven radishBOT
SWR
lusty sapphire
.close
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restive river
Hi can someone please help me with a vector question
devout snowBOT
Hi can someone please help me with a vector question
restive river
I’m not understanding how my answer is wrong for 10
I used component method exactly how I was taught and the answer in the back of the book is like 5 N off and a couple degrees off. Is it possible I did something wrong?
I’m sorry I don’t have that much time <@&286206848099549185>
supple knot
I’m sorry I don’t have that much time <@&286206848099549185>
why not
devout snowBOT
@restive river Has your question been resolved?
restive river
Because I have to sleep soon lmao
And bc normally when I ask questions on here no one ends up answering
<@&286206848099549185>
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restive river
.close
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Available help channel!
snow tundra
i need help
devout snowBOT
i need help
uneven imp
anyone can help me with these?
devout snowBOT
anyone can help me with these?
uneven imp
i have to find the equation for the line that goes through P and intercepts b = -3
and the perpendicular line to the last one that goes through x=10
wooden wraith
What have you tried? @uneven imp
devout snowBOT
@uneven imp Has your question been resolved?
uneven imp
What have you tried? <@1119004091822125076>
so far nothing, idk where or how to start so im doing other problems, u.u
uneven imp
like y-y1 = m(x-x1)
yes i know that form, can i apply it here?
am i not missing some info?
wooden wraith
Nope, you've got everything you need
(x1,y1) can be any point on the line
and m is the slope. To find the slope, you need two points, but another was given as well
You're told the line intersects the y-axis at b=-3, which is the point (0,-3)
and of course you're given (-1,2)
wooden wraith
awesome 👍 let me know and I can check your answer if you want
uneven imp
awesome 👍 let me know and I can check your answer if you want
im kinda getting it but
do i have to take in account if they have a minus in front ?
like the -2 and the -1
oh wiat
wooden wraith
everything here looks good so far
uneven imp
now i got it, its y= -5x-3
wooden wraith
yep
uneven imp
it says it cuts the y axis in x=10
wooden wraith
Okay yeah so (0,10), that's on the x-axis
there is a relationship between the slopes of perpendicular lines. do you know it?
uneven imp
oh right
wooden wraith
Since your first line has a slope of -5
The slopes of perpendicular lines always have a product of -1
wooden wraith
or are you all good
I think we're good. there are lots of help channels right now so feel free to jump in wherever someone asks a question you are comfortable answering
uneven imp
The slopes of perpendicular lines always have a product of -1
wait wait
is that a form ? or just like a rule
wooden wraith
you could express it as a formula if you want
it's always true
If $m_1$ and $m_2$ are the slopes of two perpendicular lines, then $m_1m_2=-1$
woven radishBOT
tatpoj
uneven imp
m1 would be the slope i already have
uneven imp
lol its ok
uneven imp
-5 * 1/5 = -1
yes i get that
wooden wraith
I kinda gave away the answer but I think you got it anyway
wooden wraith
no, use the same form as before
y-y1 = m(x-x1)
The slope m of this line is 1/5
and you know a point on the line
wooden wraith
yep looks good 👍
uneven imp
thanks very much
devout snowBOT
@uneven imp Has your question been resolved?
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snow vessel
Can any give input on this question? Simplifying doesn't give anything workable.
supple knot
Can any give input on this question? Simplifying doesn't give anything workable.
show what you tried
snow vessel
Uhh, factoring it out gave me something like:
x^4-6x^3+6x^2+2x-16=0
I'm not sure what to do now since it's not a "normal" quadratic
I also tried separating the quadratics
pastel pasture
$x^4 -6x^3 + 6x^2 + 2x - 16$
woven radishBOT
NEON
pastel pasture
hmm
supple knot
v i e t a
snow vessel
(x-1)(x-2) and the last quadraic, which became (x-2)(x-4)
pastel pasture
,w expand (x - 2)^4
woven radishBOT
long pasture
factorize further from start
snow vessel
Like (x-1)(x-2) (x-4)(x+1) - (x-2)(x-4)?
pastel pasture
$(x^2 + 4)(x + 2)(x - 2) -2x(3x^2 - 3x + 2)$
woven radishBOT
NEON
long trout
Like (x-1)(x-2) (x-4)(x+1) - (x-2)(x-4)?
now u can factor the (x-2)(x-4) out
pastel pasture
i dont know what im doing ignore me
snow vessel
now u can factor the (x-2)(x-4) out
Can you explain this part?
long trout
because both polynomials (x-1)(x-2)(x-4)(x+1) and (x-2)(x-4) share a common factor of (x-2)(x-4) we can factor them out
snow vessel
Oh, something like ((x-2)(x-4))(x-1)(x+1)-1)?
long trout
yes
long pasture
((x-2)(x-4))((x-1)(x+1)-1)
long trout
((x-2)(x-4))((x-1)(x+1)-1)
oh it should be this
long trout
Oh, something like ((x-2)(x-4))(x-1)(x+1)-1)?
be careful when using brackets
snow vessel
((x-2)(x-4))(x^2-2)=0 and x would equal.. +2, +4, and something?
snow vessel
radical(2)?
long trout
yes
snow vessel
Is that all the answers? Or am I missing something still?
long pasture
±
snow vessel
Ah, +- radical (2)?
long trout
yeah, dont forgot that +-
long pasture
±√2 😁
snow vessel
So then it would have 4 total answers, 2, 4, and ±√2
Interesting.. I never though to factor out an entire quadratic..
Very cool. Thanks for all the help!
devout snowBOT
Very cool. Thanks for all the help!
If you are done with this channel, please mark your problem as solved by typing .close
long pasture
Cheers!
devout snowBOT
@snow vessel Has your question been resolved?
hard knot
look up angle sum and angle difference formulae for like sin and cos
Thank you I will check it out! sry for ping, just wanted to say thanks :3
brisk patio
In the triangle ABC, straight on B it tracez the height BH, next the medium points M of BC, and N of BH, so AM=2AN, calculate the angle of C (I need help to solve it, I have tried everything)
devout snowBOT
In the triangle ABC, straight on B it tracez the height BH, next the medium poin...
@brisk patio Has your question been resolved?
halcyon yew
Help
halcyon yew
Plz
I have a math test in a few hours
Im gna fail
This is one of the review questions
<@&286206848099549185> srry for ping but this is rlly urgent
I just dont get it
I cant fail this
Plzzzzzz
fair storm
Have you visited those websites?
fair storm
What is x in yours?
halcyon yew
Time elapsed
fair storm
Let me ask you a question
halcyon yew
Ok
fair storm
why is it x/5?
halcyon yew
x/5 because number of hours that has passed to complete it in x hours
X= time in hours that goes by
cedar yarrow
You realise that x/3 > x/5
fair storm
cedar yarrow
Subtract greater - smaller
halcyon yew
You realise that x/3 > x/5
O
I thought it would be Matt (takes longer) - Together (shorter time)
But ig not??
halcyon yew
Imma watch it rn brb
Okay just watched it
So I understand those types
But this question I had is like a little different
Cause we have together
fair storm
so 1/3 = 1/5 + 1/x
halcyon yew
Also my teacher did x/5 + 1= x/3 (idk how got that)
fair storm
$\frac{1}{3} = \frac{1}{5}+ \frac{1}{x}$\
$\frac{1}{3} \cdot x = (\frac{1}{5}+ \frac{1}{x}) \cdot x$
woven radishBOT
Roman_Garland
fair storm
Do you understand now?
halcyon yew
I think so what confused me is why I couldnt do x/5 (larger time) - x/3 (smaller time)= 1
If u could clear that up for me that would be awesome
Only thing
fair storm
1/t so if t get larger the value 1/t get smaller
halcyon yew
Are u able to adapt ur answer to my equation
So x/x
Jus so i understand more easily
Sorry
fair storm
$\frac{1}{3} = \frac{1}{5}+ \frac{1}{x}$\
$\frac{1}{3} \cdot x = (\frac{1}{5}+ \frac{1}{x}) \cdot x$\
$\therefore \frac{x}{3} = \frac{x}{5}+ 1$
woven radishBOT
Roman_Garland
fair storm
Like this?
halcyon yew
Yes thx
But what I wondering is why I couldnt do x/5 (larger time) - x/3 (smaller time)= 1
fair storm
What does "(larger time)" mean
halcyon yew
Takes longer to do the task
fair storm
No it's smaller time. x/5 is smaller time.
halcyon yew
But 5h is more than 3h
fair storm
yes but if you compare 1/5 with 1/3, 1/3 > 1/5
halcyon yew
So its that simple? I was just wondering if there is another explanation to it
fair storm
So do you want another explanation or do you understand?
halcyon yew
Another would be nice just so I remember
fair storm
So you want another explanation on why 1/5 is less than 1/3?
fair storm
No problem.
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near lily
Help if a pipe can empty a swimming pool 20hrs and another pipe can fill the pool in 32 hours would it be -x/20 +x/32
@fair storm
Pls help
<@&286206848099549185>
Pls
I’m gonna fail
<@&286206848099549185> pls I’m gonna fail anyone
halcyon yew
Plz help with this
Answer his first plz
@near lily
We are gna fail our test
Its in a few hours
near lily
@fervent swallow
<@&286206848099549185>
Help if a pipe can empty a swimming pool 20hrs and another pipe can fill the pool in 32 hours would it be -x/20 +x/32
@woven radish
Help
<@&286206848099549185>
Pls man pls
lucid stump
Man............... I want to help you but I don't want to give you wrong answer...........
What course is this...
lucid stump
Did you try to ask, google gemini, / chatgpt, desperate times comes to desperate measures., also post your question on the help forum as well, there, people can see you in two places.
near lily
Yeah ChatGPT said yes but then it proceeded to give me a random equations that actually shouldn’t work
Thank you for at least trying to help and not ignoring like some people
lucid stump
Gemini is better, than chatgpt at this, also what about the help forum did you post the question there too? This will make you twice as likely to get a response, seriously. Also I prefer you to use AI tutors for math equations, and those are free.
Ohhhhhhhhh I'm sorry to hear that you feel that way, I don't think they want to ignore, as much as they are just unfamiliar with it.
Sorry I just want to help you even if I can't directly help at the moment.
The answer is 60 Km by the way.
I just solved it bro
Do you want to know how I got it?
near lily
Ok thanks you so much I just posted on forum I’ll try Gemini
lucid stump
I already did gemini and it showed me the right way to do it I believe, it makes a lot of sense.
Let x be the truck's usual speed.
The time it takes to drive the route at the usual speed is
x
270
hours. Driving 6 km/h faster means driving at a speed of x+6 km/h, and so it takes
x+6
270
hours to drive the route at the faster speed.
Being half an hour late is equivalent to being
2
1
of an hour behind schedule. Since the driver arrives on time despite starting late, we have the following equation:
x+6
270
x
270
−
2
1
Multiplying both sides of the equation by 2x(x+6) gives:
540=270x−x
2
−6x
which can be rewritten as:
x
2
−276x+540=0
This factors as:
(x−210)(x−6)=0
So, the possible values of x are 6 and 210. Since the usual speed must be positive, the truck's usual speed is
60
km/h.
It doesn't print well here, but GEMINI gives you the right answer.
GEMINI all the way!!!!!!!!!
I did my best to help you out, I felt bad no one was doing anything, but the answer is 60 km/h
near lily
Ok thank you so much
lucid stump
Yep no problem, I thought you were ignoring this message!!
lol
This is printed wierd, do it there on gemini and you will understand it much better, also KEY TIP, there are many places to post problems like these other than discord, so you have multiple ways to get your response answered.
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restive river
show through the chain rule that the two equations at the bottom of question (2a) are true, which is easy
what is hard for me, is question (2b), where we are supposed to use our answer from (a) and the chain rule to show that the two new equations are true
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sage aspen
$\text{prove} \ \forall x >0 ,x-\frac{x^3}{6}\leq sinx\leq x$
devout snowBOT
$\text{prove} \ \forall x >0 ,x-\frac{x^3}{6}\leq sinx\leq x$
winter patrol
please stop abusing helper pings, pretty sure you've been informed of this before
sage aspen
oh sorry
sage aspen
please stop abusing helper pings, pretty sure you've been informed of this befor...
can u help here
winter patrol
maybe later if noone else does
sage aspen
i really need the solution i would appreciate it so much if you help me
woven radishBOT
brahim3579
sage aspen
$\text{prove} \ \forall x >0 ,x-\frac{x^3}{6}\leq sinx\leq x$
woven radishBOT
brahim3579
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Available help channel!
hollow edge
Can anyone help me with part (iii), I’ll send my working so far
devout snowBOT
Can anyone help me with part (iii), I’ll send my working so far
hollow edge
wait I’ve just realised how messy my working looks I’ll rewrite it a bit neater
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hollow edge
that’s parts 1 and 2 i’ve realised i’m not fully sure what part 2 is looking for
craggy lake
hi
tired portal
You know what maclaurin expansion is?
hollow edge
yes
and i could brute force my way to the fifth derivative but i think the questions trying to lead me to some general term
like how (1-x^2) d2y /dx^2 = dy/dx
tall tangle
hi
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green steeple
I need help with logic, specifically with deductive systems and natural deduction. Idk if anyone here can help me with this, but im struggling lmao. I just want someone to explain the theory to me, the rules and stuff. Thanks in advance :D
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I need help with logic, specifically with deductive systems and natural deductio...
green steeple
<@&286206848099549185>
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graceful cosmos
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soft umbra
wdym by planar representation? Could you elaborate?
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severe crystal
could someone help me with this one
devout snowBOT
could someone help me with this one
severe crystal
i have defined a function g(z) = [f(z)(z-w) + f(z)(z-a)]/(z-a) for some large a.
The plan was to apply cauchy's formula to g, separate the resulting integral(s) into those with integrands f(z)/(z-a) and f(z)/(z-w) and then take a->inf
and if it would help, I have also constructed the following curves for the case where |w| < 1
supple knot
!occupied
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supple knot
<@&268886789983436800>
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severe crystal
<@&286206848099549185>
west sparrow
I can help with this question
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severe crystal
I can help with this question
any ideas?
severe crystal
.close
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honest thorn
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honest thorn
Idk how to do 21-24
I think I just don't really understand the question
Idk what that N symbol means
late orbit
honest thorn
What about the n though
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honest thorn
.close
dusky bone
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dusky bone
hi does anyone know what i should do here
ripe mason
if thats all youve got i would guess
tardy mulch
its asking for the gradient at the point x=-1
ripe mason
perhaps draw a tangent?
dusky bone
draw a tangent line?
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