#help-27

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devout snowBOT
#

@sinful mango Has your question been resolved?

sinful mango
#

nah not yet

hidden hinge
#

First find the volume of the cylinder, since you know the mass, $Density = \frac{Mass}{Volume}$ You can rearrange and solve for volume from mass and density.

woven radishBOT
sinful mango
#

Ok

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visual brook
devout snowBOT
visual brook
#

how did they get the interval for tan(t+ pie/4)

supple knot
visual brook
supple knot
visual brook
supple knot
#

Depends on the initial condition

visual brook
#

their initial conditions

supple knot
visual brook
supple knot
#

Read this

visual brook
supple knot
#

pi / 2

visual brook
#

like isnt it -pie/2 to pie/2 is the range

supple knot
#

Discontinuities refer to domain of functions, not range

supple knot
visual brook
supple knot
#

I don't know what "more depending" is referring to

visual brook
supple knot
#

Correct

visual brook
visual brook
#

for y = tan(t)

supple knot
visual brook
supple knot
visual brook
#

discontinuity is at pie/2 + npie

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for y(0) = 0 , that means n is 0

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so domain is from (-pie/2 to pie/2)

visual brook
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@visual brook Has your question been resolved?

visual brook
# supple knot ?

nvm forget everytihng i said, but i got (-pie/4 to positive 3pie/4

#

because everyting shifts because of t+ pie/4

visual brook
# supple knot ?

ok so how does y = tan(t+ pie/4) shift to the left of the normal function tan(t)

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i thought since its being added it would shift to the right

supple knot
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No

visual brook
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but yea my answers were flipped because of that

visual brook
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how does that help us if partial derivative or the function itself isnt continuous

supple knot
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What does this have to do with tangent function

visual brook
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oh nothing

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i figured that out

#

this is another ques

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brazen halo
#

Need help with b, to sketch a graph but dont know where to start.

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jade oak
brazen halo
jade oak
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Yeah

brazen halo
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Is the form right?

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I mean the line?

jade oak
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Yeah

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This interval is 2pi wide. There is a condition saying f(x)=f(x+2pi)

You can think about how to sketch the other parts by placing two fingers on the points at -pi and pi. By the earlier condition as you move your fingers, they will be at the same vertical height, so as one finger follows along the graph of the interval you drew, the other finger will be sketching in the intervals you havent drawn

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Keep them the same horizontal distance apart so the condition x vs x+2pi is met

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It may be obvious though without having to do this if you just think about it for a bit

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@brazen halo Has your question been resolved?

brazen halo
#

Hold on, still thinking this.

jade oak
#

Another way of thinking of this is that f(x)=f(x+a) is the definition of being periodic (it is also given in text the function is periodic) with period a. In this case a=2pi, and you already have an interval of 2pi, so you just need to copy that interval

brazen halo
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So something like this?

jade oak
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Yeah

brazen halo
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huh.

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so, can you explain why and how what I drew is the answer?

jade oak
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Take any point, move 2pi to the right, the output value is the same. The f(x)=x^2/pi is also obviously satisfied

brazen halo
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So from here, The f(x)=x^2/pi, that function is the form of the quadratic function between -pi and pi?

jade oak
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Yeah

brazen halo
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Another question is, what is the maximum height?

jade oak
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visually u can see it happens at -pi, which you can plug into the equation

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Also happens at other places but -pi is part of the “base case” interval.

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So you can directly plug it into x^2/pi

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@brazen halo Has your question been resolved?

brazen halo
#

Still processing and trying to understand this. Pls bear with me.

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Discussing it with a friend. I think I will leave this convo open for the night.

wheat pawn
#

About the question of your maximum height.
If you want to do it analytically, you need to obtain the derivative of your function in the interval.
Then you need to check if there's any value of x that makes that derivative equal to zero.
The maximum value is either one of those, or one of the endpoints of the interval.

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stray cave
devout snowBOT
stray cave
#

Hi need help on this question. I got 3 as my answer

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am i supposeed to do (2^(4)-41)/(22^(2)-32+2) or (2^(4)-44)/(22^(2)-32+2)

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so its either 0 or 3

plush vault
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🤔

thick iris
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It's been a long time since I did limits, but I believe you have to plug in (-2) in t's place and then reduce

stray cave
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?

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i got 3/4 if i just plugged in -2

long sundial
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Yea

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The limit is really easy in this example because nothing becomes 0 when putting -2 in

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Sometimes this will happen and we'll need to use some special tricks first and then put in the limit

stray cave
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so whats the answer?

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ok it was 3/4

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wooden veldt
#

You must also check the points where the function is not differentiable

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Yeah so look for points where the function itself is defined, but the derivative is not defined

winter patrol
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there is a min

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consider the above

wooden veldt
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The min can either occur at places where the derivative is zero, or places where the derivative is undefined

winter patrol
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considering a combination of range,domain,the above

wooden veldt
winter patrol
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yes. the common way to find local min/max would be to first find the location of stationary points from f'(x) = 0

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but as mentioned those aren't the only places local mins/max may occur

wooden veldt
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Yes, but that is exactly "checking the points where the derivative is undefined"

winter patrol
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or here, its also a boundary location

wooden veldt
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Yes but that might be hard to do depending on the function

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That's what derivatives are a tool for

winter patrol
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or places where the derivative is undefined

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when will
$$f'(x) = \frac{x}{\sqrt{x^2-4}}$$
be undefined

woven radishBOT
#

ℝαμΩℕωⅤ

winter patrol
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and are there values there where $f(x)$ is defined

woven radishBOT
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ℝαμΩℕωⅤ

winter patrol
#

not quite

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you're including stuff outside of

between 2 and -2

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to be more specific are there values between
-2 and 2 inclusive where
f(x) is defined

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what about 2 and -2

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is f(x) defined at -2 and 2?

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that's how you'd use the derivative here to determine locations of other extrema

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on from the range of the sqrt function, you've identified that there will be mins at these locations

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calm maple
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calm maple
#

check if correctly mathematically written

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@calm maple Has your question been resolved?

calm maple
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<@&286206848099549185>

calm maple
#

😕

calm maple
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<@&286206848099549185>

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please

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grizzled harness
#

Two trains leave Toronto heading towards Ottawa.
Train A travels at a constant speed of 80 km/h.
Train B travels at a constant speed of 60 km/h.
However, Train B has already covered 30 km by the time Train A departs.
Determine when Train A will overtake Train B using equation(s).

grizzled harness
#

How can I do this?

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grizzled harness
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mighty copper
#

can someone please check if my prove is right

mighty copper
#

we had to prove its converging using monotonic convergent theorem

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its dicreasing because denominator is bigger than the numerator. will that reasoning work?

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to prove its bounded this is what i did:

1/(2n+1)! > 0
multipliying both sides by 2n-1 !
(2n-1)!/(2n+1)! > 0

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since its bounded and dicreasing its convergant

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to find its limit di di like

(2n-1)* (2n-2)...1/(2n+1) * (2n)*(2n-1)...1
1/(2n+1)(2n)
taking limits we get 1/infinity which is 0

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so is my proof and working right?

alpine inlet
#

seems good to me

mighty copper
#

ln(1+1/n) = an
taking its derivative we get -1/(n^2+n) which is always negative which means the function is dicreasing.

1+1/n > 1
ln(1+1/n) > ln(1)
ln(1+1/n)>0
which means its lower bound is 0 and its uppber bound is at a_1. so its bounded and monotone hence converging

alpine inlet
#

ye seems good

mighty copper
#

thankyou

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bright juniper
#

a trapezoids bases are 4 and 12 i got a line that is parallel to the bases and it crosses the touching parts of the diagnals find the lenght of that line

hollow sparrow
#

hi

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holy hmm

bright juniper
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Hi

lunar oar
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the diagonal lines would cross in the center

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so the horizontal line will be the line that is the average of both bases (in length)

bright juniper
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Wrong

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We don’t know the trapezoids legs and no one says that the diagnal lines would cross in the center

lunar oar
#

true

bright juniper
#

<@&286206848099549185>

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neon fable
devout snowBOT
neon fable
#

no idea where to even start

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or how to isolate e as a variable

uncut crow
#

what a weird choice of variable name

restive river
#

I thought that e was supposed to be the nepper number

uncut crow
#

this whole problem is weird af honestly

restive river
#

doesn't that just end with e = e?

sand dove
#

it does

alpine inlet
#

First of all, the limit in there is e. Dunno if you'd have to prove that but it's a commonly known fact.

#

so, it's also e^1 and log_b(e^1)=1 can only hold if b=e

neon fable
uncut crow
#

i think the question is poorly framed… whatever it’s supposed to be

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neon fable
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visual brook
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Please don't occupy multiple help channels.

visual brook
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close

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@visual brook Has your question been resolved?

supple knot
#

.close

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quasi acorn
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quasi acorn
#

Need help on this question

long sundial
#

What have you tried?

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restive lark
devout snowBOT
restive lark
#

this is where i got substituting the polar form of z, but now im not sure what to do witht he d^2/dt^2

#

later the problem says:
"Note that z depends on time, meaning that both r and θ do, too. Use the product
rule to compute the second derivative with respect to time", but will i need to compute it if the equation is already second derivative = something?

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does this mean that i evaluate the second derivative of the polar form of z first at the step i am currently on?

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this is the whole problem

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am i overthinking it and have already completed step 1, and am ready for step 2?

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<@&286206848099549185> i am very lost on this problem

devout snowBOT
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@restive lark Has your question been resolved?

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@restive lark Has your question been resolved?

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@restive lark Has your question been resolved?

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@restive lark Has your question been resolved?

wicked edge
# restive lark

I think it wants you to write the first as youve written, or to apply linearity to “simplify a bit”,
for the product rule, it wants you to apply this to the rcostheta and irsintheta because theta and r are functions of t,

#

The next two should follow readily

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supple anchor
devout snowBOT
supple anchor
#

Hi I genuinely don’t know how to do 3

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How do I start

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Do I split the x squared -1 into linear?

winter patrol
#

quotient remainder form

distant harbor
#

Use the definition of division

supple anchor
#

How do I do that when I don’t know px

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Or qx

winter patrol
#

leave P(x) and Q(x) as P(x) and Q(x)

distant harbor
#

p(x) = q(x)*(x²-1)+(3x-4)

supple anchor
#

Also I have to do this by only using the form

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Oh ok

#

I get it now

#

Ty

#

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lost stream
#

hello

devout snowBOT
lost stream
#

please help me with this electric field

#

i really dont know how to solve it

stuck field
#

What's your question again?

lost stream
#

this onee. This is a physics question under electric fields and its asking me to prove that the equation is equal to 4.9

stuck field
#

I saw the image the first time.

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If your talking about 2. Then do note there's a diagram for 2. Which you've tried to hide.

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And a lot of other details as well, please state the problem.

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!original

devout snowBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

lost stream
#

hold on let me take a picture again

stuck field
#

Thank you!

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Now asinine

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This question talks about some previous question.

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I wonder what that's about?

lost stream
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we talked about the component method

stuck field
#

Alright seems useless anyway.

stuck field
lost stream
#

im really confused as to how to approach this because I have only simply tried putting in the components into the equation but always comes down to not being able to cancel the radicals

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i found

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a clearer image sorry

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and that the charges are 12n/c

stuck field
#

Both q_1 and q_2?

lost stream
#

yes

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positive to positive, negative to negative

stuck field
#

Charges are in coloumb

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Not N/c

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N/c is electric field.

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Sus

lost stream
#

oh my bad

stuck field
#

Anyways

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You know E_c, and you need E_1 and E_2?

lost stream
#

yes

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but i already have

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E1 and E2

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and Ec ? I just dont get how to prove it

stuck field
#

Oh.

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Well, if you know how components work

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E_1 would be E_c cos(alpha)

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Do you see that?

lost stream
#

yes ive done that

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thats the x value

stuck field
#

Same for y.

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That's it, I believe?

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Or you want to see how exactly this E_c cos(alpha) comes from?

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It's to do with vector addition

lost stream
#

Its just that my prof doesnt want us to use the component method but rather like what you said, vector addition

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i dont know how to separate the terms

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because technically i only have to add 2 vectors right

stuck field
#

Or you can find E_1 based on the fact E_1 is the electric field due to q_1

lost stream
stuck field
#

You know E_1 + E_2 is E_c

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(Vector)

lost stream
#

yes but i have tried

stuck field
#

What have you tried?

lost stream
#

i thought i got it but the radicals

stuck field
#

yeah you will.

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You'd round them probably.

lost stream
#

how?

stuck field
#

Do you know what it means to round off something?

lost stream
#

yes

stuck field
#

Then that's what you'd do.

lost stream
#

okay okay ill try it again

#

thank you!

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midnight bear
#

can someone please help me with part c?

devout snowBOT
midnight bear
#

its my first course on real analysis, and I'm having trouble finding which direction to proceed with doing part c

#

I figure we need to show that each side is less than or equal to the other

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so I showed that $\sup(A+B) \leq s+t$

woven radishBOT
#

goobybalooby

midnight bear
#

but I have no clue how to proceed from there. In a round a bout way, I used part (a) to prove the above inequality, so I'm assuming that proving the inequality facing the opposite direction likely involves what was proved in part (b), but I just dont see what they are getting at

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@midnight bear Has your question been resolved?

midnight bear
#

Wait where did that commenter go?

empty flame
#

i wrote something and then realized that i wrote something stupid

#

so i deleted it

midnight bear
#

Oh okay lol

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sacred thorn
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sacred thorn
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sacred tiger
#

7 part c i need a bit of help understanding what im supposed to do

sacred tiger
#

I might need help with some key concepts because I wasn't able to attend the lecture for this and it wasnt recorded

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iron sun
#

What have you tried so far? And how did you do solve a) and b)? @sacred tiger

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frail furnace
#

in a group of five men and four women, there are three pairs of male & female business partners and three teachers, where no teacher is in a business partnership. One man and one woman are selected at random. Find the probability that they are : EACH IN A BUSINESS PARTNERSHIP BUT NOT WITH EACHOTHER.

I'm just wondering why for the men it's 3/5 (im assuming this means 3 businessmen out of 5 men) but for women its 2/4

frail furnace
#

wait

#

yeah i meant 2/4

stuck field
#

What do you think it should be?

frail furnace
#

but how do u get 2/4

#

is it not supposed to be 3/4??

#

my thought process on this is 3/5 x (3-1)/4

#

idk how they got 2

stuck field
#

because 2 is infact 3-1?

frail furnace
#

why did they choose to minus it from the women though

#

and not the men

#

thats what im stuck on

rustic jetty
stuck field
#

It's the same either way.

frail furnace
stuck field
frail furnace
#

💀

#

im stupid

#

my fault

#

thank you though

#

😭

#

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mystic jetty
#

Can i solve thus with pythagreom (idfk how to spell it) theory

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winter patrol
#

not in the way you want,
no

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winter patrol
#

pythag doesn't apply as you don't have a right triangle

mystic jetty
#

i forgot abt that

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muted blaze
#

hi i just want a pair of second eyes

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muted blaze
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muted blaze
#

Im thinking the correct solve is an application of a balanced force

#

im thinking if its balanced, it will just maintain equilibrium/the velocity it already has

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formal bronze
#

Indeed.

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muted blaze
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.close

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restive river
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restive river
#

I'm asked to prove this identity

#

tried working on the left side, but to no avail

#

the right side however

#

I know there's a way to seperate that fraction into two things

#

but I'm kinda slow rn

#

multiply cos(x)

#

on both sides

#

you know, I did try that

#

give me a sec

#

should work

#

okay I see where you're going with this

plush vault
restive river
#

but i'm still a tad bit confused

restive river
plush vault
#

Then multiply with 1-sinx up and down

restive river
#

$\frac{cos^2x}{cosx-sinxcosx}$

woven radishBOT
plush vault
restive river
plush vault
#

No in LHS

restive river
#

lhs being secx+tanx right?

plush vault
#

Ya

#

Then
(1+sinx)/cosx

#

Now multiply

midnight hinge
#

thoughts on this method

restive river
#

$\frac{1-sinx}{cosx-cosxsinx}+\frac{sinx-sin^2x}{cosx-sinxcosx}$

woven radishBOT
restive river
#

$\frac{1-sinx+sinx-sin^2x}{cosx-cosxsinx}$

woven radishBOT
restive river
#

$\frac{1-sin^2x}{cosx-cosxsinx}$

woven radishBOT
plush vault
#

This is so simple how you making so complicated

restive river
#

$\frac{cos^2x}{cosx-cosxsinx}$

woven radishBOT
plush vault
#

Ya that's right

#

Go on

restive river
#

$\frac{cosxcosx}{cosx-cosxsinx}$

woven radishBOT
plush vault
#

You really fast

restive river
#

wait this looks

#

very familiar

#

to if we multiplied RHS

#

by cosx

plush vault
#

Yeah 😅

restive river
#

on both sides

#

okay i see i see

plush vault
#

Just take common in demonitor and cut one cosx in numeroter

restive river
#

$\frac{cosxcosx}{cosx-cosxsinx}=\frac{cosxcosx}{cosx-cosxsinx}$

woven radishBOT
plush vault
#

Ok ya that also

#

Good job

restive river
#

$\frac{cosx(cosx)}{cosx(1-sinx)}$

woven radishBOT
plush vault
#

Thank you

midnight hinge
#

nice ig

restive river
#

$\frac{cosx}{1-sinx}$

plush vault
#

It's so satisfying when you got a answer

woven radishBOT
restive river
#

yep

#

especially with trig identities

#

you know you got it right when you get it right

#

this method is pretty clever though

#

but it seems almost predicted

#

that guy must've done the whole thing in his head

#

😭

midnight hinge
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uncut mulch
#

hey i need help with this one

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uncut mulch
#

need to Calculate a determinant of this matrix

sand dove
#

hint: you can start from last row and subtract the previous row.

#

and then find a pattern...

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uncut mulch
#

@sand dove hey if you know how to solve that cant you go on call with me and help me, this type of question im gonna have on exam, i know if i practice it well it could be easy

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clear cloak
#

A rectangular piece of cardboard measuring 25 inches by 47 inches is to be made into a box with an open top by cutting equal size squares from each corner and folding up the sides. Let x represent the length of a side of each such square. For what value of x will the volume be a maximum? If necessary, round to 2 decimal places.

clear cloak
#

I know that I need to find the volume

#

which is V= (47-2x)(25-2x)x

#

which is 1175x-144x^2+4x^3

#

but i got 0 idea what else to do after this step since i dont have a cal

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clear cloak
#

.reopem

#

.reopen

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supple knot
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vivid ermine
#

can someone help me with this?

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edgy ridge
#

for this question we've got: a triangle formed by A and B and C; I is the middle point of [BC]. we need to prove that vec(AB)^2 - vec(AC)^2 = -4 vec(AI)*vec(IB)

in this case vec(AB) means a vector from a going to b

alpine inlet
#

I assume you mean the length of the vector before squaring it

edgy ridge
alpine inlet
#

I mean vec(AB)^2

edgy ridge
#

here is how my attempt went

edgy ridge
alpine inlet
#

idk, squaring a vector doesnt make sense

edgy ridge
#

so vec(u)^2 is vec(u) dot product vec(u)

alpine inlet
#

okay

edgy ridge
#

but my solution is a bit different from the solution

alpine inlet
#

in your first step, why should AB be the same as AI + IB?

alpine inlet
#

"a triangle formed by A and B and C; I is the middle point of [BC]"
I don't see this to be the same problem setup

edgy ridge
#

one sec

alpine inlet
#

okay now I get it lol, was still thinking of vector lengths

edgy ridge
#

Yeah it still works that way

edgy ridge
#

my main problem is with these two

#

since I is the center of BC we can do vec(IC)=-vec(IB)

alpine inlet
#

good observation

#

I think that is key

edgy ridge
#

which gets us close but the sign inverted

#

we get the following:

#

2 * vec(AI) * vec(IB) + 2 * (vec(AI)*vec(IB)

#

note that I filled the + in between the two sides because I changed IC to IB

#

the result is 4 * vec(AI) * vec(IB)

#

but the solution the exercise wants me to find is *vec(AB)^2 - vec(AC)^2 = -4 vec(AI)vec(IB) notice the minus sign

#

so it's either:

the solution is wrong
or I made a mistake somewhere

alpine inlet
#

from what I can tell you're correct

edgy ridge
#

and we haven't yet dealt with

alpine inlet
#

Does that not cancel out?

edgy ridge
#

hmmm

alpine inlet
#

IB = -IC

edgy ridge
#

doesn't the square affect anything?

#

oh

#

I guess if we think of them as lengths

#

then they cancel out

#

yeah so the answer is correct except for that minus sign

#

I'll ask my professor about it tomorrow

alpine inlet
#

maybe he intentionally gave you this so you don't use chatgpt to cheat, cuz chatgpt would imagine a wrong proof

edgy ridge
#

well I'll mark this as solved for now

#

thanks for the help!

alpine inlet
#

welcome 😄

edgy ridge
#

:)

#

.close

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brazen halo
#

Im trying to brush up my math skills. Need some explanation on this question.
When I move everything from the right side to the left side, becoming
-2x^2+5x+1=0
The roots are
x=0.1861 x=2.6861

When I move from left to right side, becoming
0 = 2x^2 - 5x - 1
or by switching sides
x^2+4x-1 = 9x - x^2
then becoming
2x^2 - 5x - 1 = 0
The roots are
x=2.6861 x=-0.1861

I put the equation on Symbolab and the latter is correct. Why do we have to switch sides?

patent marsh
#

the roots are the same, they're just reflections of one another

#
-2x^2 + 5x + 1 (moved over to left side)
2x^2 - 5x - 1 (moved over to right side)

I think you had an arithmetic error

brazen halo
#

Ay yes sorry, the first part i forgot to put negative.
x=-0.1861 x=2.6861

#

The part where they are reflection of each other I understand. '

#

Does that mean all 4 x answers are correct?

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brazen halo
#

Just need this question answered.

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@brazen halo Has your question been resolved?

brazen halo
#

ill just close it.

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bold cypress
#

How will I find the highest frequency when there are 2 in this grouped data?

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ivory quail
#

in e^x =5, why does x(1) = log5?

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vestal dirge
#

do you know what e^x and log(x) are?

ivory quail
#

I'm aware of logarithims idk what the meaning of e^x is

vestal dirge
#

do you know what a function is?

eager nova
#

Do you know what is e?

wicked turtle
#

what do you mean by x(1), do you just mean x?

vestal dirge
woven radishBOT
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grand lynx
#

i need help with the answers here
my gf is doing these and i honestly have no clue what the answer is

grand lynx
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tender cobalt
#

that was quick

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whole grove
#

for this question:

we have 5 beers, 4 ciders, and 3 sodas

you want to get 8 drinks to go. What this means is that the order of the drinks no
longer matters - we only care about how many of each drink you have.

question: How many ways can you order 8 drinks if you order at least 2 of B1 and at least 1 of
C1?

how would i approach a q like this

inland seal
#

So you already have 2 beers and 1 cider, you just need to pick 5 more drinks

#

There are 3 beers, 3 ciders and 3 sodas left to pick from

#

In how many ways can you pick 5 drinks from those?

whole grove
#

does it matter if its B_1 or B_2

#

it says two of B_1

inland seal
#

I don't know what's B_1 or B_2

whole grove
#

like 5 beers

inland seal
#

im assuming all drinks of the same type are the same?

whole grove
#

so B_1, b_2

#

etc.

#

up to b_5

inland seal
#

so the beers are different?

whole grove
#

• 5 different types of craft beer, B1, B2, B3, B4, B5,
• 4 different types of cider, C1, C2, C3, C4, and
• 3 different types of soda, S1, S2, S3

#

yes

inland seal
#

And how many of each type?

#

Do we have?

whole grove
#

5 beer, 4 cider, 3 sodas

#

like above

inland seal
#

But 5 what

#

This doesn't tell us how many of each

inland seal
#

Yeah

#

What if all of our beers are of type B4?

#

We don't know how many

#

Also sorry I gtg, my food is ready

#

Maybe someone else can take over

whole grove
#

.close

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tender cobalt
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bright pawn
#

Hey guys. How do you graph a rectangle?

devout snowBOT
restive river
bright pawn
#

I want to graph a rectangle on Desmos.

#

Not a circle.

#

Not an elipse.

#

But a rectangle.

#

Also, I want the lines to be connected, so I can actually see it. So not just four points.

inland seal
#

One way is to make a table

restive river
inland seal
#

Type "table"

woven radishBOT
restive river
#

and modify your values if you want to from there

inland seal
#

Press and hold left click on the colored icon, and mark the options "lines"

bright pawn
#

Oh, I see.

#

Perfect, thank you.

#

.close

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sand jetty
#

.close

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halcyon yew
#

Your car is stuck in the snow. Desperate to leave the school’s parking lot, you ask your friend to help you push your car. Your friend does not want to help so they say, “Any force I apply to your car will be met with an equal force, creating a net force of zero; there will be no movement due of Newton’s Third Law.” What is your argument to prove your friend wrong?

halcyon yew
#

I dont get this

wicked turtle
#

that equal force acts on you, not on the car

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halcyon yew
#

O ok that makes sense

#

How about 1a

#

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quick radish
devout snowBOT
quick radish
#

Can anyone explain the underlined integration step?

supple knot
#

you can work backwards by just adding the 3 underlined terms using a common denominator

quick radish
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stark shuttle
#

Hello

devout snowBOT
stark shuttle
#

$\left[1:::::2\right]\left[3:::::4\right]=\left[1:::::2\right]\left[3:::::4\right]^T$

woven radishBOT
#

LE SSERAFIM

stark shuttle
#

Why does both equal 11

topaz beacon
#

the first one equal [3, 8]

elfin atlas
#

You can't multiply the first two matrices, 1×2 and 1×2

stark shuttle
#

Did I input something wrong in the calculator?

elfin atlas
#

😂😂😂 lmao
Since when are two 1×2 matrices multiplicable

stark shuttle
#

I'm so confused

topaz beacon
#

thats because those are vectors

#

thats a dot product

stark shuttle
topaz beacon
#

(v1, v2) dot (w1, w2) = v1w1 +v2w2

stark shuttle
topaz beacon
#

thats just a matrix product then

topaz beacon
# stark shuttle

notice that your calculator assumed that when you meant to multiply, it assume dot prod

stark shuttle
topaz beacon
#

yes they are

stark shuttle
#

Ohh I see

#

Thank you!

#

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gloomy valve
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gloomy valve
#

Can someone help pls

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#

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gloomy valve
#

<@&286206848099549185>

wicked turtle
#

show what this "constant sum" property is?

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tender grail
#

help

devout snowBOT
tender grail
#

i got this but its marking it wrong

#

is there any other way to rewite that?

wicked turtle
#

is it some software doing the grading?

#

maybe it wants a decimal approximation

#

or maybe something stupid like ln(a/b) instead of ln(a) - ln(b)

#

your answer is right

tender grail
wicked turtle
#

hmm

#

only a couple of things i can think of

#

maybe try ln((2 - sin(2)) / (1 - sin(1)))

#

or maybe log instead of ln

tender grail
#

Ill try that

#

tried log too, doesn't work

wicked turtle
#

ah bummer

#

software just seems wrong then

#

,w integrate (1 - cos(t)) / (t - sin(t)) from t = 1 to t = 2

tender grail
#

right then thanks

woven radishBOT
wicked turtle
#

ah why isn't it showing it here

#

i'll paste

#

matches yours

tender grail
#

yeah just doesn't work tho

wicked turtle
#

yea sorry, no idea, do you have an instructor you can ask

tender grail
#

yeah ill ask them tmr

#

thank you tho

wicked turtle
#

sure, gl, hope it works out

tender grail
#

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brisk star
#

Matrix square roots are expensive to compute, so is there a faster way to get from F to the eigen values of U?

brisk star
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thick wadi
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thick wadi
#

Need help with B

#

Hello

#

<@&286206848099549185>

#

<@&286206848099549185>

#

Helloooo

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thick wadi
#

@loud jolt

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<@&286206848099549185>

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white lava
#

what do they mean by restrictions right here?

lost laurel
#

values that x can't take I think

white lava
lost laurel
#

is the function defined at 1 and -1?

white lava
#

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raven stream
devout snowBOT
white lava
#

what

hollow hollow
#

Equal

white lava
raven stream
white lava
#

you can just get rid of the denominators

#

they equal

#

you can do x^2 + 2x-1 = 2

#

i think

elfin atlas
#

but make sure that you write x!={-1,1}

white lava
#

like i dont understand

elfin atlas
#

x/(x-1) at x=1 is 1/0
1/(x+1) at x=-1 is 1/0
both are not defined so

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frigid jetty
#

well

#

maybe 1/2(7x+10)?

#

so did you get answer

#

both ig

#

do you have an answer sheet

#

or whatever

#

yeah

#

we did inverse

#

damn

#

we have to multiply left side

#

not right

#

by1/2

#

yeah

#

what you got

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weary hedge
# devout snow

I don't understand how the numerator was factored. I don't get the factoring common terms

  • 10 - 5, shouldn't it be still 5√ 3?
woven radishBOT
#

Civil Service Pigeon

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#

@weary hedge Has your question been resolved?

weary hedge
#

I don't get it just because when the common term is 5,
10 = 2
5 = 1
isn't it? I am pondering on how it was really factored.

#

or is it valid that i just cancel out the two fives in the numerator with the 5 in the denominator?

lunar harbor
#

Yeah 5 is a common factor, so you cancel it

weary hedge
#

.close

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fluid flax
#

In the mathematical models used to describe the evolution of a disease, the average number of new infections that each infected person causes in the population is called RO. When this number is less than 1, each infected individual transmits the disease to, on average, less than one person and the disease tends to disappear. Conversely, if RO is greater than 1, the disease spreads and an epidemic occurs. When an effective vaccine against the disease is discovered, the epidemic can be controlled by vaccinating only a proportion p of the population. This is known as herd immunity. Indeed, once a proportion p E(0,1) of the population has been vaccinated, the new RO, which is called effective and denoted by Re, is the product of the original RO by the proportion of individuals who are not vaccinated , 1-p. And control of the epidemic is achieved if Re is less than 1.
c) Express, in general, the minimum population threshold that needs to be vaccinated as a function of the RO value of a disease Sketch this function for RO values between 1 and 20.

fluid flax
#

I don't understand why the statement says that if R0 exceeds 1 there is an epidemic and if it is lower the disease disappears. And in question c) it says that R0 has to vary between the values 1 and 20.

#

<@&286206848099549185>

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spring pollen
#

,tex d/dx sin \sqrt {cos x ^3}

devout snowBOT
woven radishBOT
#

LeAbhi

d/dx sin  \sqrt {cos x ^3}
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.49 d/dx sin  \sqrt {
                      cos x ^3}
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.

LaTeX Font Info:    Trying to load font information for OT1+lmr on input line 4
9.
(/usr/local/texlive/2023/texmf-dist/tex/latex/lm/ot1lmr.fd```
obsidian elbow
#

Do you know and understand the chain rule?

devout snowBOT
#

@spring pollen Has your question been resolved?

spring pollen
#

just dont know how does root derivative work

bold drum
#

a square root can be expressed as ^1/2 right

#

and you just apply the power rule

spring pollen
#

ohh

bold drum
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coral wraith
#

how would i do this problem?

devout snowBOT
coral wraith
#

there must be an easier way than what im thinking

dense lynx
#

sounds like a job for “Newton’s Sums”

would recommend reading about it if you don’t know what it is

devout snowBOT
#

@coral wraith Has your question been resolved?

coral wraith
#

I’ll use them though

red viper
#

if you don't know Newton's sums, you can use this: $$x^{n+1}+y^{n+1}=(x+y)(x^n+y^n)-xy(x^{n-1}+y^{n-1})$$

woven radishBOT
#

Alisia

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#

@coral wraith Has your question been resolved?

coral wraith
#

Thanks

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#

@coral wraith Has your question been resolved?

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#

@coral wraith Has your question been resolved?

coral wraith
#

anyone?

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<@&286206848099549185>

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.close

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coral wraith
#

.reopen

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#

coral wraith
weak salmon
#

Hmm. At least you can formulate that (x-r)(x-s) = 0 ; that might get you somewhere.

#

Even more useful: the r and s have the form of a-z and a+z. Now your problem looks like (a-z)^10 + (a+z)^10, where probably quite many coefficients disappear if you carefully start expanding that.

#

Hmm, what you get is 5 terms, all having an even number of z's there (odd ones cancel each other out), so your square roots disappear. I think it's manageable expansion -wise.

dense lynx
#

if you know how to find the sum of the roots and the product of the roots using vieta's, then consider the case where n = 1, and you can work up until n = 9

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pulsar relic
#

so i did this work, but i dont know what the question is trying to ask of me for c? like are they trying to ask me when y = 0 x = 5?

also is my other work right?

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#

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pulsar relic
#

for how many things i should say

#

idk

weak cove
#

I mean is this a test/exam?

pulsar relic
#

no not a test / exam at 5:31am 😬

weak cove
#

The world doesn't share a universal timezone :p

pulsar relic
#

kms if i had an exam at 5:31am 😭

opal cloak
pulsar relic
#

or is it trying to allude that f(x) has its roots there....

opal cloak
#

dont worry about x and y values

opal cloak
#

maybe make a line at x=5

pulsar relic
#

oh! then...when f'(x)=0, f(x) = 0

opal cloak
pulsar relic
#

why does this magic happen lol

#

oh

#

ahhhhhh

#

its f(x)'s axis of symmetry?

opal cloak
#

yeah that is true, but more specifically its when f(x) has a turning point

pulsar relic
#

ohhh.........hmmm

#

is turning point at f'(x) a key concept?

#

and by turning point we mean when f(x) goes from negative slope to positive slope?

opal cloak
#

yeah, at that exact point f(x) will have no slope

#

well not no slope but rather its just a flat line

pulsar relic
#

does this concept pop up more the further into calculus courses?

opal cloak
#

yeah it will

pulsar relic
#

what is the usefulness of it? if you can say it in words to help me know the importants better

#

is it like..when setting the derivative of a function to 0 we will find turning points for functions of higher degree which have many

pulsar relic
#

x^3 would have 2 turning points and we can find two points

#

ahhhhhhhhh

opal cloak
pulsar relic
#

oh yeah, but sometimes when

#

the thing with the quadratic formula is postivie

opal cloak
#

yeah

pulsar relic
#

discriminate? omg theres so much math

opal cloak
#

discriminant, but lcose

#

close*

pulsar relic
#

😄 ill take it

pulsar relic
opal cloak
#

point of symmetry

pulsar relic
#

ty

#

/close

#

.close

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#
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zealous gull
#

.reopen

#

Soo... my question was closed for inactivity, sorry about that... How did they get from the first line to the second using the formulas down? X,A are matrices, x,u,v_k,a are vectors

devout snowBOT
#

@zealous gull Has your question been resolved?

zealous gull
#

umm

#

we can do something else with the trace

#

x^T A x = Tr(Axx^T)
so
we can replace the trace with
(v_k-u)^T A^-1 (v_k-u)

#

and then we can derive using (d/dx) {x^Ta}=a

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thorn bramble
#

In year $N$, the $300^\text{th}$ day of the year is a Tuesday. In year $N+1$, the $200^\text{th}$ day is also a Tuesday. On what day of the week did the $100^\text{th}$ of year $N-1$ occur?

woven radishBOT
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terse leaf
#

Why do we have trigonometry, but don't have tetragonometry? 🧐

lost laurel
#

what would tetragonmetry even be? The study of the relationship between the sides of a quadrilateral and its angles?

terse leaf
#

The exact same thing as for triangle, but for quadrilateral, right

winter torrent
#

triangles are very rigid

#

quadrilaterals aren't

dense lynx
#

🤔 every quadrilateral is a composition of two triangles if that helps

terse leaf
#

So last two messages want to say triangles are more fundamental for geometry that even gained own trigonometry topic

restive river
#

trigonometry wasnt really made for triangles it was made for circles

terse leaf
restive river
#

study some history you would get it how it got from circles to triangles

terse leaf
#

Triangles were used to calculate chords? I suppose

#

Anyway, I got answers clarifying my vision for geometry so thanks for responses

#

.close

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supple knot
#

Do you know the y-intercept of your equation

#

Yes. Now which option has that y-intercept

#

Depends on the lines

#

Just learn to plot 2x+3

#

Depends on the imaginary 2 lines you're making up

#

2 is the slope of 2x+3

#

Do you know how to plot a line of slope 2

#
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short iron
#

Does this make sense for 10a? which(x,y : capital(x,y) and small(y))

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flat raft
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I need help to prove, if $f'(x)$ is even and $f(0)=0$, then $f(x)$ is odd

woven radishBOT
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shrödinger

flat raft
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<@&286206848099549185>

vital pasture
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What proof techniques have they taught you so far?

flat raft
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Deduction

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i know proofs