#help-27

1 messages · Page 152 of 1

calm sky
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erm

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what is RHS?

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Im at grade 7

vast wing
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do you know about least common multiple?

calm sky
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no

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i dont think so

past scaffold
past scaffold
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I mean adding them ?

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Like whats 1/2+1/4 ?

calm sky
past scaffold
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Try bringing all the x terms to the right hand side

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So that constant terms are in one side
And the variable terms are in another side

calm sky
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so( 1/4+1/6+1/2 )x X +5?

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5 22/24x

past scaffold
calm sky
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yes

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i alr did that but i dont understand why the result is 60

past scaffold
calm sky
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yes

past scaffold
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Now move 22X/24 to the right hand side so that only 5 is on the left side of the equal to sign

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Whats the new expression now

calm sky
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5 = X + 22/24X?

past scaffold
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No

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Take it like 1+3=4
1=4**-**3

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Now think again

calm sky
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so: 5 = x - 22/24X?

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its wrong right?

past scaffold
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No

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Its correct

calm sky
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YAY

past scaffold
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Now 5 =x (1-22/24)
Do u get it

calm sky
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so then 5= 2/24 x

past scaffold
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Yep

calm sky
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btw

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ur muslim right?

past scaffold
calm sky
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ok Allah hafiz

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thanks

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im muslim too

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lol

past scaffold
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Oh

devout snowBOT
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placid rover
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I typed out a question in #help-28. I need it to unlock to access it again, so just recycling channels. Sorry for the spam & ignore

placid rover
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stuck field
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They rewrote z = r^25 * e^(25i theta)

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Can you write it in polar form?

devout snowBOT
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@quiet glade Has your question been resolved?

plush vault
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Hey

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Can I help

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What way

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You have to write it in polar form

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It is simple

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You expand it ??

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By polar form you can do that in 3 steps just

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Ya then

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I think polar form is much helpful you should try it

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May I explain it

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random glade
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random glade
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Any formula that could help me with this?

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up

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lapis flint
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I'm struggling understanding division. It's a magical operation that I use all of the time without really understanding its usefulness. I've been using this example to understand multiplication:

For every 1 group, there are 4 flowers. The ratio from flowers to groups is: 4:1

If multiplication is the process of repeatedly adding a number to itself, then:

4 flowers * 3 groups = for every 1 group, add 4 flowers (until there are 3 groups)

3 groups can be broken down into individual units: 1 group + 1 group + 1 group. So, this is a process of iteration.

likewise, when we divide 12 flowers by 3 groups ( 12 / 3 = 4) . What exactly is going on here?

12 flowers / 3 groups = for every 1 group, do what??

thin tapir
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Division is intrinsically a more complicated thing than multiplication

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It is the inverse process

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If every group has 7 flowers and there are 6 groups, there are 7*6=42 flowers in total
And if there are 42 flowers in total and there are 6 groups, each group must have 42/6=7 flowers

lapis flint
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is there a concrete or iterative process to get 7 flowers

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I get long division

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but when you add units it gets confusing

eager nova
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Imagine your example, 12 flowers and 3 groups.

thin tapir
eager nova
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Give 1 flower to group 1, another flower to group 2, and another flower to group 3

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You have one flower to each group, so now you have 9 flowers

thin tapir
eager nova
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You repeat this loop while you have flowers

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Every time you finish the loop, you count as one iteration

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When you are done with the flowers, the number of iterations is the answer

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You can do it just by adding 1 by 1

lapis flint
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I can think of the phrase "divide by" or the division symbol as allocating 1 unit of the divisor to each group

thin tapir
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Yes

eager nova
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Every operation can be done with addition

lapis flint
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By operation you mean the other arithmetic operators?

eager nova
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Subtraction, multiplication, power, logarithms, etc..

stuck field
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Subtraction*

lapis flint
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How do you do subtraction with addition

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unless you mean by making an algebra problem out of it?

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isn't the objective to isolate the variable by continuously doing the inverse operation

eager nova
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To represent the subtraction with an addition, you take the opposite of the number

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Of example if you want to subtract 5 to 8

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You add to 8 the opposite of 5, which is -5

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So you would have 8 + opp(5)

lapis flint
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what about with multiplication

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decimals?

eager nova
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If you can put in a fraction, it’s like normal multiplication

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For example 2/3 times 3/4

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You know how to multiply 2 and 3 with addition

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2+2+2

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And also the denominator

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If it’s impossible to write with one single fraction

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You will need to use infinite sums of fractions

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To get an approximation

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But every number with decimals that is not irrational can be written in fraction form

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That way you can multiply by using additions

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leaden plover
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$\newline U(y) = U_osin(cy) \newline
-\frac{dU(y)}{dy}=cU_ocos(cy)$

woven radishBOT
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Cewkins

leaden plover
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@stuck field Sorry for the ping but again i am not entirely sure, again the original function is sin(cy) ignoring the constant U_o, shouldnt we use the chain rule here? otherwise how is the answer cUcos(cy)?

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@leaden plover Has your question been resolved?

stuck field
stuck field
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I'm not sure what is it that's confusing you, truth be told.
You've written something, that's what you think should be correct, or is it something that's given to you and you think it's incorrect? Or what?
As you've written, that statement is incorrect.
-dU/dy is not U_0 * c * cos(cy)

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(if the channel closes, then don't ping me after you reopen it or open another)

leaden plover
leaden plover
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leaden plover
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I am literally sending messages here what

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stuck field
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stuck field
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What you've written is not.

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You're making this unnecessarily complicated.

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Just find dU/dy first

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Then put a - afterwards.

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That's all you want to do.

leaden plover
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Okay that makes sense now thanks

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Sorry for the pings

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.close

stuck field
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It's my channel.

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.close

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leaden plover
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Right

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main terrace
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/Zaharik

devout snowBOT
main terrace
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draw the parallelogram ABCD in the figure; O is the intersection point of its diagonals. The point K is outside the plane of the parallelogram. KA=KC and KB=KD. Prove that KO is perpendicular to (ABCD).

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Can you help me?

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ok)

valid iron
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i might die in like 2 minutes , so...--

main terrace
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I hope it's clear?

valid iron
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yeah

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just making sure can you point out where k is

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nvm i think you understood the asignment

main terrace
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nd here's the question: how to prove that OK is parallel to the plane?

valid iron
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Ak parrallel to the paralllogram plane?

main terrace
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K is the lower point

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ups

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OK

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sorry

valid iron
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,,

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the question simply asks you to proof ko being perpendicular to the plane no?

main terrace
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yes

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I even turned to the neural network, she was talking about some vertical angles there

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Angle AOK= angle COK as vertical

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аnd based on this, therefore, that OK is perpendicular to this plane

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are you here?

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?

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ау

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Is there anyone here?

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аууу

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people

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<@&286206848099549185>

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ayyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

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<@&268886789983436800>

wooden veldt
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please dont ping mods for math help

main terrace
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ok

main terrace
wooden veldt
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wait patiently

main terrace
wooden veldt
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catshrug i dont control how long it takes

wooden veldt
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? no i dont control who helps you

main terrace
wooden veldt
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not sure what you mean by that

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at this point i recommend closing this channel and opening a fresh one

wooden veldt
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do .close here and open a new one the same way you opened this one

main terrace
#

.close

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cinder juniper
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i have done this

devout snowBOT
cinder juniper
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but the answer sheet says its negative sign in the parenthesis at the end instead of a minus

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i dont see why

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@cinder juniper Has your question been resolved?

cinder juniper
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<@&286206848099549185>

limber granite
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yes?

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charred pike
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hi

devout snowBOT
sinful crown
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.claim

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fak

charred pike
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so I get that sin(pi-x) = sinx

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but i want to know if there are similar rules for tan and cos?

smoky nimbus
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I'm assuming you mean these

charred pike
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yeah

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oh

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cool

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thanks

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@smoky nimbus but it works for all 0 theta right?

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like any angle?

crystal drift
charred pike
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what

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@crystal drift what do you mean "in the domain of tangent"

crystal drift
woven radishBOT
crystal drift
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because $\tan \frac {\pi} 2$ doesnt exist

woven radishBOT
charred pike
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don't you just mean anny angle between two line sthat is 90 degrees?

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@crystal drift

crystal drift
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basically

charred pike
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and the coterminal angles to theta = pi is 0=90 degree and 0=270 degree

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and x should not be those values

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because tan 90 or tan270 dont exist

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@crystal drift correct?

crystal drift
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👍

charred pike
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cool

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thank you.

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.close

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crystal drift
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np

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severe otter
#

Calculus 2

devout snowBOT
severe otter
#

Does this look familiar to anyone? Apparently A is supposed to be 51 and C is supposed to be 22, so I was super close. Reworking it rn...

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Ohh yes okay

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ahh yep ok nvm got it

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.close

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brave pilot
#

Could someone help me find my mistake?

devout snowBOT
toxic magnet
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In the second step, 7*5 = 35

mossy bloom
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your -25*sqrt(21) is wrong

toxic magnet
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not -25

mossy bloom
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^

brave pilot
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OH

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OKAY

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I missed that over 80 times when I rechecked AAAHHH

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TYSMMM

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!!!

mossy bloom
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ahaha happens goodluck!:)

brave pilot
#

.close

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errant wyvern
#

In number 4 im not sure how to even start, the only info i have gathered is one side equals two which is already given

dense lynx
errant wyvern
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i found that angle P3=108 and P1 and P5 = 36

dense lynx
errant wyvern
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oh crap

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i read it wrong

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so P3=120 and P1 and P5=30

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i was thinking of a 30-60-90 like this

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but i dont know if thats the way

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i still have no idea on how to start

dense lynx
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it helps to know the 15-75-90 triangle relation

errant wyvern
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sorry i kept searching the internet and i couldnt get a precise answer

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i think its somehting about cos15 and then the 75 angle being sin(15)

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im not sure how to plug that it in since cos15 is an irrational number i think

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#

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@errant wyvern Has your question been resolved?

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smoky gyro
#

Not sure if I set the diagram up correctly

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brave atlas
#

99y + 198y + 204 = 0

step by step solution please

misty crest
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combine like terms

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we have two y terms here

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99y and 198y

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so add them together

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u get 297y

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so 297y +204=0

brave atlas
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No sorry

misty crest
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subtract 204 from both sides

brave atlas
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I meant

misty crest
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y^2?

brave atlas
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99y^2 + 198y + 204 = 0

misty crest
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ok so use quadratic formula

brave atlas
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Yep

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Can you show me

misty crest
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a=99

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b=198

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c=204

woven radishBOT
#

Juke | ping me if no response

winter brook
#

that's the quadratic formula btw

brave atlas
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What is next?

winter brook
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plug in a, b, and c

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then just solve

brave atlas
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So we have 2 solutions?

brave atlas
winter brook
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,w solve 99y^2 + 198y + 204 = 0

winter brook
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u should have gotten these

brave atlas
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What does it mean?

winter brook
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it means that this equation will equal 0 when the y is equal to either one of those

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in this case, they have to be imaginary. bc imagine this eqn is in terms of x and u graph it, it never crosses the x-axis, so it doesn't have real roots

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but there are imaginary ones

winter brook
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do u know what imaginary numbers are yet?

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@brave atlas

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stable salmon
devout snowBOT
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@stable salmon Has your question been resolved?

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@stable salmon Has your question been resolved?

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zenith vortex
#

Hi

devout snowBOT
zenith vortex
#

I want some help in making a choice

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So, I'm going to buy a CAS, either mathematica or maple

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but i cant decide which one

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some people praise one while completely denying the other is good

winter torrent
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isn't maple mostly for engineers?

zenith vortex
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heck both mathematica and maple has a comparison site where they boast about themselves

zenith vortex
devout snowBOT
#

@zenith vortex Has your question been resolved?

zenith vortex
#

<@&286206848099549185> has anyone tried any one of them?

devout snowBOT
#

@zenith vortex Has your question been resolved?

iron gazelle
#

Hey

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Ill suggest to use maple

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as it is convenient and easier to understand and would give smooth performance

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uncut crow
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upper grail
#

Hi

devout snowBOT
upper grail
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So basically why must 2 be added before the piXr^2

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When I’m asked to divide abcd by the circles

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The areas of abcd by area of circles

safe knoll
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are u saying why its 2 pi r^2 and now pi r^2 ?

upper grail
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I’m asking why the 2 is necessary before the formula of area

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When we say pi is r

safe knoll
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area of circle = pi r^2
the shape u have has 2 circles so the total area of the circles would be
area of first circle + second circle
pi r^2 + pi r^2
2(pi r^2)

upper grail
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I confused myself

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How do I go about to get the area of the rectangle

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The remaining

safe knoll
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u know the value of AD which is 4r

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and AD = BC = 4r

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AB = DC = 2r

upper grail
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So is it 4r x 2r

safe knoll
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yeah thats the area of the whole rectangle

upper grail
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So 8r - the circles area

safe knoll
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what are u to find?

upper grail
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The area of the places not covered by the circles

safe knoll
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ah ok

safe knoll
upper grail
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Why is 8r in the power if 2

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Am I asking dumb questions

#

I forgot everything

safe knoll
#

$$4r \cdot 2r = 8r^{2}$$

woven radishBOT
#

JustToPro

upper grail
#

Ah

safe knoll
#

i mean thats basic algebra

upper grail
#

Forgot about that

#

Yeah

#

So that - 2(pi r^2)

safe knoll
#

yeah

#

if u want , u could factor out the 2r^2 term

#

$8r^{2} - 2(\pi r^2) = 2r^2(4-\pi)$

woven radishBOT
#

JustToPro

upper grail
#

I think I need to sleep

#

Thanks for the help

safe knoll
#

np

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restive river
#

(opening for a separate question independent of my other occupied help channel)

devout snowBOT
#

Please don't occupy multiple help channels.

restive river
#

Let $n$ be odd, $n\ge 3$. Show that the edges of the complete graph $K_n$ cannot be partitioned into blocks such that each block consists of the edges of a Hamiltonian graph

woven radishBOT
restive river
#

So a Hamiltonian path has n -1 edges

#

the total number of edges of K_n should be n choose 2

#

so the number of paths is n/2, which isnt an integer for odd n's

#

so this cannot be partitioned

#

is my logic fine?

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restive river
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orchid basin
devout snowBOT
orchid basin
#

This was incorrect, why?

#

Given a video with these formulas

zinc flint
#

ur r is wrong

#

u did - instead of +

orchid basin
#

oh good catch

orchid basin
#

ty

#

Idk about B tho, that one seems pretty cut and dry and idk how they got their ans

acoustic leaf
#

if your point is in quadrants 2-3 (i.e. the x is negative) you have to add π = 180° to the given angle from arctan (since it can only give angles in quadrants 1 & 4)

orchid basin
#

I did tan^-1 (-4/-1) and tan^-1 (| -4/-1 |) and both marked wrong

orchid basin
#

like would I do
(-1, -4) (given coordinates)

arctan(-4/-1) + 2pi

acoustic leaf
#

just arctan(-4/-1) + π. the angle is exactly opposite what it should be so adding a half-rotation flips it over

orchid basin
#

gotcha gotcha

#

thank you!

#

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odd abyss
#

$a\nmid n$ and $a\mid2n \implies 2\mid a$ for any integers $a,n.$

woven radishBOT
#

BeeReallyYum

odd abyss
#

I know this is true, but how to prove it?

jovial stump
#

How would you rewrite those definitions?

odd abyss
#

$2n=aq$ and $n\neq ak$

woven radishBOT
#

BeeReallyYum

odd abyss
#

but I think I just found a way with Gauss's Lemma

jovial stump
#

Nice

odd abyss
#

thanks anyway

jovial stump
#

Np gl

odd abyss
#

if you don't mind

jovial stump
#

Sure!

#

One sec lol

odd abyss
#

ok lol

jovial stump
#

I'm thinking that you need to prove n is odd and a is even I'd need more time for a specific answer

odd abyss
#

ok it's fine

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thanks!

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oblique rover
devout snowBOT
oblique rover
#

Where should i plug rv+sw to show that this is linear transformation?

sand dove
#

Having trouble reading the upper coordinate of f((x y z))

oblique rover
#

Sorry it’s f((x,y,z)^T)->(x+y+1,x-y)^T

oblique rover
sand dove
#

What should f(0 0 0) be?

oblique rover
#

(1,0)

sand dove
#

Yes, is f a linear transformation?

oblique rover
#

hm

oblique rover
sand dove
#

Yes

#

f(the zero vector) is predefined when f is linear

oblique rover
#

ou yes you are right never noticed this

#

nice that eases thing up a lot

#

but using my method how could i do that?

sand dove
#

You have to write rf(v) + sf(w) on another side

#

And compare

stone stump
#

well you could for example set v=(x,y,z) and w=(a,b,c). then what is rv+sw?

oblique rover
#

but for example when we have transformation $f:P_4(x,\mathbb{R}) \rightarrow \mathbb{R},f(p(x))=p(3)$ this condition with zero does not hold does it? and it is linear transformation

woven radishBOT
#

Slowaq

stone stump
#

the zero polynomial evaluated at 3 is zero

oblique rover
#

wait how do you write out this zero polynomial?

stone stump
#

0

oblique rover
#

ah

#

so it is polynomial of first degree?

#

or that would be p_1(3)?

stone stump
#

first degree would mean it has an x in it

#

depending on definition the zero polynomial either has degree 0 or degree -infty

oblique rover
#

o no i meant 0th degree

#

well but isnt x^0=1 thus p(3) isnt 1?

stone stump
#

huh?

#

the zero polynomial is constant zero

oblique rover
#

hm so then 1 is what degree polynomial?

stone stump
#

still degree 0

oblique rover
#

flonshed now i am confused

#

so zero degree polynomial is either 1 or 0?

stone stump
#

there is no unique zero degree polynomial

#

there are lots of polynomials with degree 0

oblique rover
#

is it like zero degree polynomial is equal to some constant? P(x)=c?

stone stump
#

yes

oblique rover
#

alright now it makes sense

sand dove
#

Zero degree polynomials are P(x) = c with c not zero

oblique rover
stone stump
#

its still the polynomial that is constant zero

#

its zero everywhere

#

no matter what you plug in

oblique rover
#

but why did he write c ≠ 0?

stone stump
#

like I said before, depending on defintion the zero polynomial has degree -infty. not degree zero

oblique rover
#

here when i plug zero matrix its determinant is zero but this isnt linear transformation how come?

stone stump
#

but that doesnt change that it is also a constant polynomial

oblique rover
#

ah alight i think i get it now

stone stump
#

well mapping zero to zero is a very mild requirement

#

not everything that satisfies it is linear

#

f(x)=x^17-x also maps zero to zero

#

but its not linear

oblique rover
#

yes i figured

#

it seems its good requirement for quick first elimination

#

alright i think thats all thx for help

#

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mighty copper
#

assuming you publish a video on youtube , 30 days before your video got 300 views and 60 likes. find the probability of getting 4 like tomorrow

mighty copper
#

This is what I did:
P kf getting a like when you get a view is 60/300

#

So p of getting 4 likes would be 4 power of thay

#

But my ta said it's like n=10, p =0.2 and x =4 so just use binomial

#

But I am still not able to convince myself so can someone please explain

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finite tartan
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finite tartan
#

May I please have help with both questions

vast wing
#

we know that AB = BC, so ABC is an isosceles triangle

#

and BC = 4y + 1

#

4y + 1 + 4y + 1 + 2y - 5 + 5y + 1 = 178 (perimeter)

#

15y - 2 = 178

#

15y = 180

#

y = 12

#

,w 19^2 + 61^2 = x^2

woven radishBOT
finite tartan
#

.close

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untold arch
#

hi i need complex analysis help

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untold arch
#

dont know what to do

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wooden zodiac
#

n?

wraith horizon
#

there...is no n

wooden zodiac
#

I have no idea what any of these are

#

What's a What's l

#

n is mymber of terms then

#

You start from r=3 not =0

#

r=0 would be 31 terms btw

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snow forge
#

when writing the cos, sin, etc for a coterminal angle that is negative, do i write is as the negative or where the angle is on the unit circle

ex:

do i write

sin -pi/2 =
or
sin 3pi/2

fresh elbow
snow forge
#

wdym the domain it's just the

#

regular unit circle

winter torrent
#

!original

devout snowBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

fresh elbow
#

Regular unit circle I would use 3pi/2 but -pi/2 isn’t wrong either

snow forge
winter torrent
#

they asked for -30º so you should say -30º

snow forge
#

okay

#

thanks!

#

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tepid shadow
#

can anyone help me with this graph theory proof?

I have something down, and I think its on the right track, but I am using almost no mathematical language

tepid shadow
#

What I have right now:
proof by contradiction: Assume that no such j > 3 exists. This means that for every vertex Vj with j > 3 for which {v2, vj} E E(G) we also have {V3, Vj} E E(G). Now consider the degree of V2 & V3. The problem statement says that deg(V2) > deg(v3), but if every neighbor of v2 (except possibly V1) is also a neighbor of v3, then v3 would have at least as many neighbors as v2, which contradicts our assumption that deg(v2) > deg(v3), thus there must exist j > 3 such that {v3, vj} is not in E(G)

#

I guess there is some mathematical language in there, but is it enough? (forgive me, for I know not what I am doing)

worthy raft
#

I think that's pretty good, one thing you could maybe do is note that because {v1,v2} not in E(G) and {v1,v3} in E(G) that the degree of v3 is bigger than deg(v2) if there's no neighbours j > 3

#

And I think you're using a fine amount of math language

tepid shadow
#

okay, cool! Thank you @worthy raft I really appreciate it!

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covert geyser
#

a question on the degree and order of a differential eqn

covert geyser
#

but for the following

#

i figure the order is 3

#

but for degree do i have to choose to classify the t or y?

#

i understnad the rule of homogeneity

#

but im not sure how to tie that in with linear/nonlinear degree

crisp niche
covert geyser
#

so then

#

im gessing non linear

#

but the order is still 3

crisp niche
#

is linear in respect to y

#

y = y ( t)

covert geyser
#

ok

crisp niche
#

but coefficients are not constants, be ware of it

covert geyser
#

got it

crisp niche
#

cos is "ugly" element here 🙂

covert geyser
#

so then for the example above

#

3rd order non linear

crisp niche
#

no

#

cos refers to t

#

not to y

#

right ?

covert geyser
#

so it IS linear?

crisp niche
#

yes

#

third order, linear

covert geyser
#

so wait

#

referring back to the definition

crisp niche
#

yes

#

it is yours

#

n = 3

covert geyser
#

and for example this question

#

its 4th order

#

linear

crisp niche
#

yes

#

n = 4

#

linear

covert geyser
#

ok

#

and this one

#

second order

crisp niche
#

no

covert geyser
#

non linear

#

ok

#

i think i got it

crisp niche
#

it i snon -linear

#

bbecasue

#

sinus eats y 🙂

#

\inside

covert geyser
#

combines t and y as its input

crisp niche
#

yes

covert geyser
#

perfect

crisp niche
#

smiles

covert geyser
#

haha

#

thanks boss 👍

crisp niche
#

yvw

covert geyser
#

.close

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woven tundra
#

I need help on number 7 and 9

devout snowBOT
#

Please don't occupy multiple help channels.

woven tundra
#

tsa

light fox
#

do you know how to find the surface area of each of the faces of the shape?

woven tundra
#

not really

#

been trying to watch videos on it

light fox
#

the area of a triangle is (base length times height) / 2

#

the the area of a rectangle is the base length times height

#

once you find the area of every side you add them together to get the surface area

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spring hemlock
#

hello i need help with a proof
P1 = (x1, y1) and P2 = (x2, y2) such that y > 0 and x1 < x2. C is a circle that contains the points P1 and P2, and is tangent to the x-axis at the point (x3, 0). Prove that the condition x1< x3< x2 cannot always be fulfilled for a circle C given any two points (x1, y1) and (x2, y2).
I need some intuition as to where to start

hidden bobcat
#

i would think youd have to find a way to construct x3 to break the condition

#

you can use geogebra to get some intuition

spring hemlock
#

how would i use geogebra

hidden bobcat
#

i will make one for you

spring hemlock
#

alright

hidden bobcat
#

here is one counter example

#

see if you can construct a nicer one

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#

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spring hemlock
#

Alright thanks

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deep wing
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deep wing
#

Noob question but I wanted to confirm I did this correct?

torpid rampart
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smoky gyro
#

I’m a little confused on what I have to do for part B

restive river
#

take I = (10⁸)Io
and the value of Io is already provided

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grave dune
#

hi im back, for this i did the vector SR x vector RQ and then took the magnitude but it isn't coming out as correct

grave dune
#

to find the vector SR i did <3-2, 3-0, 0-0>=<1,3,0> and for RQ <1-3, 2-3, 2-0>=<-2,-1,2>

#

for SR x RQ i got 6i -2j +5k

tender cobalt
#

you should do (SR x RQ) / 2

grave dune
#

ohhhh 1/2 youre right lol

#

it worked

#

important step that is

#

thanks lol

#

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tender cobalt
#

np

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honest oasis
#

can someone help me on part C

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honest oasis
#

<@&286206848099549185>

woeful laurel
#

Hello sir

#

I am at your service

#

What do you need help with?

honest oasis
#

ive got 1/2 a for part a

#

a+b for part b

#

but i dont understand part C

round cedar
#

Take 8 common

#

Then inside it becomes 1+8/x so taking LCM it becomes x+8/x

woeful laurel
honest oasis
#

oh i think i see it now

#

the log8

#

goes to 3

#

x+8

#

b

round cedar
#

3 + b-a

honest oasis
#

yews

#

thank you

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#

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young crane
#

How do I solve this system of equations

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#

@young crane Has your question been resolved?

young crane
#

<@&286206848099549185>

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swift falcon
#

i need help doing this worksheet

#

from question 1, i have no idea what im doing

heavy current
swift falcon
#

no clue literally

#

i only know sin

#

cosine and tangent

heavy current
#

Presumably you’ve seen this??

swift falcon
#

oh yeah, just at the end of my physics class

#

very confusing but sure ok

heavy current
#

in any case, Snell’s Law gives the relationship between the refractive indices of two media and the incident/refracted angles

#

Now you just have to identify what your variables are

#

And then you can solve for the unknown one

swift falcon
#

ok

#

wait but like

#

is n1 multiplied by sin of 1? or is sin1 like a variable of the first number

#

i don't really get it

#

would the equation be 1.5(sin45) = n2(sin65)

#

just simple algebra?

heavy current
#

theta_1 is a variable, namely the incident angle

heavy current
swift falcon
#

but theta is the angle, so

#

ok

#

thanks

#

lemme solve real quick and get back to you

#

ok

#

so

#

i got n2 = 1.544

swift falcon
heavy current
swift falcon
#

well i did

#

and i got to hte point of 0.5 = 1.523(sin())

#

and so Im thinking, right

#

if i divide 0.5

#

by 1.523

#

do i just get sin (1.523)?

#

sorry no

#

sin(0.322)?

heavy current
#

I don’t follow what you’re doing

swift falcon
#

ill send a pic

heavy current
#

kk

swift falcon
#

what i basically have

#

is

#

$0.5 = 1.523 (sin())$

woven radishBOT
#

GMDennis

swift falcon
#

can i divide each side by 1.523?

#

to then get sin(0.328)?

heavy current
swift falcon
#

$0.5/1.523 = 1.523/1.523$

woven radishBOT
#

GMDennis

swift falcon
#

listen just look at the pic

heavy current
#

no but how are you getting sin(0.328)?

swift falcon
#

right ok im really sorry we need to step back, i was under the delusion that the sin of 30 was 0.5, it's 0.988

heavy current
#

you were correct the first time

swift falcon
#

OH ok

#

sorry my Ti-84 was in radian mode, not degree

heavy current
swift falcon
#

but what do i do with that?

#

is that simply my final answer?

heavy current
#

use the arcsin on both sides of the equation

swift falcon
#

but it isn't, we still need to find theta 2

#

ok

#

i got 19.147 degrees

#

is that correct?

heavy current
#

looks fine to me

swift falcon
#

so I have to apply arcsin to both sides, so sin^-1(0.328) = 19.147

#

while the sin(theta_2) cancels out

#

ok

#

wow, this is insane

#

im in 10th grade and never would have dreamt of doing this kind of math

#

in pHYSICS class

#

WOAH

#

WOAH

#

2?

heavy current
swift falcon
#

listen

#

how do i do number 2

#

it has like exponents and shit

#

terrifying

heavy current
swift falcon
#

yeah but

heavy current
swift falcon
#

it doesn't make sense compared to the others

swift falcon
heavy current
#

it is not

#

it is a “slowed” speed of light

#

i presume you were taught that the speed of light is c = 3.0*10^8 m/s?

swift falcon
#

well

#

yeah

#

basically

heavy current
#

To calculate the refractive index of a material, we are essentially asking about how much it slows light

swift falcon
#

teacher didn't want to go into the bs of 299------------ so he just said 300000000 m/s

heavy current
#

The question says you have a slowed speed of 2.7*10^8 m/s

heavy current
swift falcon
#

so do we just divide 270000000/300000000?

heavy current
swift falcon
#

anyway yeah so

swift falcon
heavy current
swift falcon
#

huh

#

# why

heavy current
#

If a refractice index has value of 1.5, that means that light moves 1.5x slower in it

swift falcon
#

i got like 1.111111111111111111

#

what units would i stick at the end of it tho

heavy current
swift falcon
#

ok yeah i get it, but what unit at the end of 1.111

heavy current
#

So they cancel out

swift falcon
#

so

#

final answer is just 1.111?

heavy current
#

I mean you can write that yeah

swift falcon
#

k

#

so the next one is about light travelling throw a liquid

#

im thinking it's water, but im starting to doubt that real quick

#

yeah it's wrong

#

is it crown glass? Sure as seems to me like it

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#

@swift falcon Has your question been resolved?

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#

@swift falcon Has your question been resolved?

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proper terrace
devout snowBOT
#
What step are you on?
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7. None of the above
swift falcon
#

Economics is crazy

#

blud even idk

#

so after 10 years you'll have the 1500

#

idk hwo to do the equation tho

true plume
swift falcon
#

oh hell naw i aint including math into econ

proper terrace
true plume
#

I think it should be I may be wrong tho but thats the formula I used for compound interest in the past

proper terrace
#

t is time right ?

true plume
#

yeah

proper terrace
#

ok thanks

#

.close

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stiff scroll
devout snowBOT
#
What step are you on?
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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
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7. None of the above
stiff scroll
#

3

devout snowBOT
#

Show your work, and if possible, explain where you are stuck.

stiff scroll
#

Solid line going vertically down = y >(w line under) -2x + 14
Solid Line going down = x >(w line under) 5
Dotted Line = y < x + 4

#

thats what I thought ^

stiff scroll
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#

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opaque saffron
#

So ive got a question. If a wheel is travelling at the speed 21.6km/hr and has a circumfrence of 64pi cm, how long is one revoltution in seconds?

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#

Please don't occupy multiple help channels.

opaque saffron
#

.close

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oblique rover
#

How on earth can I determine truth of there statements?

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#

@oblique rover Has your question been resolved?

oblique rover
#

<@&286206848099549185>

#

<@&286206848099549185>

oblique rover
#

<@&286206848099549185>

devout snowBOT
#

@oblique rover Has your question been resolved?

oblique rover
#

Why nobody want to help me:(

restive river
#

ill help

oblique rover
restive river
oblique rover
#

yes and you?

restive river
oblique rover
#

ou thats reaaaly far away

restive river
#

from anywhere

oblique rover
#

xd

oblique rover
oblique rover
oblique rover
restive river
restive river
oblique rover
restive river
oblique rover
#

.close

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calm topaz
#

what is the definition for a function not to a have a final limit when x is approching infinity? by heine and cauchy

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brave pilot
#

How would I do this one

devout snowBOT
brave pilot
#

It does not really make any sense to me

#

Real

#

😭

jovial stump
brave pilot
#

I HAD NOTHING TO DO WITH THAT

#

I am a nice student, just studying for my finals

jovial stump
#

Nah I saw dw

hallow thunder
#

Bruv

devout snowBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

jovial stump
#

Ty

jovial stump
#

The intercept turns into -9

brave pilot
#

How would i know if the

#

Intercept is -9

#

If the graph is absolute

jovial stump
#

It looks like the graph is of 1/f(x)

jovial stump
#

Does that make sense

brave pilot
#

Input is 1/9?

jovial stump
#

The inputs are the x axis

brave pilot
#

hm

#

I see

jovial stump
#

-1/9 is an output

#

I input a 0 and got out -1/9

brave pilot
#

oh oki'=

#

I think I kind of get this

#

Thanks!!!

jovial stump
brave pilot
#

.close

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subtle kindle
#

question about my solution

devout snowBOT
subtle kindle
#

my teacher gives that this function is a concave function when x∈ (-infinity,0),(0,1/2)

#

convex when ∈ (1/2, infinity)

#

where did he get the 0 from?

#

did I do something wrong?

#

the task was to: find the inflection points of the function and the intervals of concavity and convexity

#

copied from google translate, so may not be right

#

<@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185>

devout snowBOT
#

@subtle kindle Has your question been resolved?

crisp niche
crisp niche
subtle kindle
#

oh i see

#

how would i show it on the graph?

#

like that?

crisp niche
subtle kindle
#

i see

#

well, thank you!

crisp niche
#

yvw )

subtle kindle
#

.close