#help-27
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okok
ioh
oh
i watched so many videos on this still didnt understand
i been stuck on this assignment for 2 weeks I keep quitting
do u understand what the ambigous case is conceptly
I would watch a yt video on it
I came here because i didnt understand
ambigous case is when we arent given the info to sovle the triangle
....
no
we are
its just you can get 2 diffirent triangles for the given triangle
that what my teacher taught us
opposite
šØ
now solve for angle C
how tho
14sin(39)/10
okok that makes sense
I knew the formula but didnt understand it looked like this
now wdym by sinc_
angle C
its gonna be the straight 90 degree line?
;-;
Just put it in ur calc
so
so C is 62 degree?
you know know that there is two possible values for AC
Because
The side opposite the given angle is smaller than the side ajacent to the given angle.
I do not know bro
how this leading me to that
side a is smaller to our adjacent
our adjacent is
wh
14?
you want me to study this?
uihhh
But do you see why itās two?
Basically given the opposite side of the given angle is smaller than the the side
beside Angle A
Our adjacent could be either side b or c
I never learned the height method
Height doesnāt affect law of sines
Your teacher may give you the height
I mean it does but
For this example, you donāt need the height at all
she never does
good point
ok I get it
are u free for more quesdtions or did I suck up ur brain cells
Sure I can help
ok wait let me put this explanation together
Find Angle C= 14sin(39deg)/10
arcsin(0.88104854747) = 61.7 = 62 Degrees
Explanation: The side opposite the given angle is smaller than the side adjacent to the given angle.
Well not thatās just the case i
wott
Because the side opposite of the given angle is smaller
If we get a theta value that is possible, then there is two triangles in that case
If theta is equal to 90 there is one triangle
what is theta
If you plug into your calc, and you get an error you have zero triangles
which is 10cm
C
wdym that is possible
Measure of angle C
Like if we get a value for theta in our calc
Sometimes you plug it into your calc and it will say error
theres times we dont get it?
Real thing
then we choose cant be calculated in that situation?
so what do i add to my explanation
I mean I donāt know how your teacher teaches it
And she may not understand the explanation but
I would say āBecause the opposite side of the given angle is less than the side adjacent of the given angle and a theta value for angle C is possible then there must be two trianglesā
is there another word we can use than theta
cause theta we didnt use it for this from what i remember
yes
Im gonna go shower
ill make a new question later and ping u and if ur free u can respond if ur not its fine
Thank u for the help Propus
Anytime
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Where do I go solving this from here?
Any help is appreciated
u have any notes on how to do it?
same :(
,rotate
Have any ideas?
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Hello everyone!
Kate has some 10% vinegar. How much water does she need to add to it in order to get 3 kg of 6% vinegar?
I am doing this type of question for the first time and with no clue on the process (btw my working is shown in picture 2). Is there a way of optimizing it?
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Given, $\frac{5xu}{2} + u = v$, such that $u = \sin^2(\frac{\pi x}{2})$ and $v = \cos(\pi x)$
I know it has an integral solution at x=2 (from graphing)
atleast I think so
let me confirm
wait nvm
well yes ofc
i wrote u and v cus it would get big and messy
one sec I need to modify the equation
ItzKraken
you bsure?
what I'd try as a first step is covert sin^2(pix/2) into cos
how does that help
wait thats cos^2 of pi/2(x-1) no
that definitely does
what after this?
$\sin^{2}\left(\frac{\pi x}{2}\right)=\frac{1+\cos\left(\pi x\right)}{2}$
B-eard
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did you get it?
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Simplify 5x^2x3m^6
and now I wait
is this $5x^2 \times 3m^6$?
jan Niku
or $5x^2x3m^6$?
jan Niku
yes
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
stop giving solutions
so, you gotta combine everything you can combine
is it 5x^2 times 3m^6 or 5x^2x3m^6
combining works like this: numbers go with numbers, letters can go with like letters, and onwards
so numbers go with numbers, m goes with m, x goes with x
the first one
alright so this one
so all you can do is combine numbers
yes
$5 \times x^2 \times 3 \times m^6$
jan Niku
so we'll bring the powers down?
Not quite
uhm
you want to group everything thats similar together
i cant really focus with multiple ppl here.
sorry theres stuff happening in the background
do you get what I mean by similar things go together @restive river ?
bro, can you please like..get out?
yh
sorry elio
okay, i think were good
do you get what I mean about similar things go together?
x goes with x, numbers go with numbers
naur
naur?
no
oh
yea, exactly
oh ok
you put the numbers together, the x's together, and the m's together
but youre still not quite done
$5 \times 3 \times x^2 \times m^6$
jan Niku
jan Niku
and youre done. you can check youre done by making sure that everything is grouped together
theres only one term of numbers
only one term of x's
and only one term of m's
yea
o
i guess its important to note its customary to write numbers first
some ppl consider it wrong if you put the number somewhere else
but you have it first so, just saying
thank youuuu!!

dont be suprised to see me back
math isnt rlly my stronghold
didnt think id be back so fast
p=k+m/m
make m the subject of the formula

its easier to help ppl if you make a new channel for each question
oh srry abt that
i just saw so many other channels thats why
lemme make a new one
.close
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I solved this absolute value problem using sets. Is there a more efficient way? No chance I'm solving every absolute value problem like this ā ļø
Solve for t then in the result of t put its value in x
You'll avoid a bunch of calculation
This is what i got for the first condition, is this even correct?
Looks very different from the one without the sub
The one i did without sub gets the correct answer
Comparison
Or did i mess the sub so badly?
@tropic marlin Has your question been resolved?
nope, if ab > 0, that means that a, b are both positive
or both negative
they can't be both negative as |t| + 4 is always positive
so when solving $\left|\frac{x}{x+1} \right| > 2$ then
south
you should get $x \in \left(-2, -\frac{2}{3}\right)$
that matches up with the answer to the original inequality on Desmos
asymptote is at x = -1, and y = x/(x + 1) it approaches +infinity from the left and -infinity from the right
so $\frac{x}{x+1} = 2 \implies x = -2$
and $\frac{x}{x + 1} = -2 \implies x = -\frac{2}{3}$
south
@tropic marlin Has your question been resolved?
So even the splution without the sub is wrong?
Where did i go wrong with the one without sub?
OH I PUT -2/3 AFTER -1
Thanks so much for the help
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Translation: Replace the different loads with an equivalent resultant and effective torque acting at point A
I don't know how to do this
@spark current Has your question been resolved?
<@&286206848099549185>
Womp womp
holy shit
do u know how to do this
@spark current Has your question been resolved?
@spark current still in need?
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Can somane help me with interval notation with the ā of an interval Exemple: [ -ā, 2]
On the internet the say other things
The green is ecual to a closed [ and the red is ]?
I'm not sure what you mean by green and red
but
the brackets mean whether or not you include that endpoint
the interval [-5,9] is all the numbers between -5 and 9 inclusive
aka
-5<=x<=9
and (-5,9) is not inclusive
-5<x<9
How do you write it with a [ with the symbol of ā
Yeah. I understand why you are confused
Just do it with the filled and non-filled circles
So filled means that the end-point is included and non-filled means itās not
You Can also see a mathematical reprƦsentation to the left side of my picture
Representation
You understand what this means, right?
Ow is see now but how is it with the ā and when is it filled then?
See the two last
No I dont think so, you canāt confine a point to infinity
So its always open?
Thats why we just write x greater-than-or-equal-to. a
I get it now
Good. You just need to work with it a little to understand it. No need to rush yourself, because you can't get everything at once š
thx bdw
@copper plinth Has your question been resolved?
yes
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Let's say I am given a 3x3 matrix, A. I have to find the diagolised matrix and the permutation matrix such that A = PDP^-1. Now I can easily find the eigenvalues and eigenvectors, and the diagnolised matrix, and I also know how to find the permutation matrix. My problem is, in which order do I write the eigenvectors such that it will be a permutation matrix. Lets say I have eigenvalues 1, -1, 2 and I find the eigenvectors now in which order do I write it, sorry if my question doesn't make sense
are you sure that permutation matrix is the correct word you are looking for?
not just invertible matrix P?
Uhh I don't think so
that said, the order of them doesnt matter
Really?
the order in which you put the eigenvectors is the same order as the eigenvalues in the diagonal
So it doesn't matter which order I follow
permutation matrices only have a single 1 in each row or column
It will still spit out the same shit?
Idk if it's a permutation matrix but it's mostly determined by P
?
I said that three messages ago
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Iāve shown that this has a critical point at (0,0,0) and now Iām trying to see if its a saddle/min/max point
Hessian at that point has negative diagonals and determinant = 0 so i concluded negative semi definite but
Not really sure where to go from there
You can just do the double derivative test to see for maxima etc right?
they did do that
using the hessian
Oh
It seems like i need to rearrange the original function? Like complete the square?
@lofty monolith Has your question been resolved?
Changed the form into x^4 + y^4 - (x+y)^2 and subbed in y=x
To get 2x^4-4x^2 which is maximised at x=0
Idk if thatās right or if i am on the right track
<@&286206848099549185>
I think its most likely a saddle point but dont really understand how to show it
hmm maybe also try y = -x? you'll see it's a minimum there
Is that enough to show its saddle
I think so? Iām not completely certain
@lofty monolith Has your question been resolved?
@lofty monolith Has your question been resolved?
Yes
@lofty monolith Has your question been resolved?
<@&286206848099549185>
Hey
Can u quickly sum up what you tried to do?
Used hessian, diagonals and determinant of hessian = 0 to conclude negative semi definite
Then did this
Hey, Hessian = 0 means that the second derivative test is inconclusive. You have checked that the function is maximized at (0,0) along the line y=x. You will see that it is minimized at (0,0) along the line y=-x, so it's a saddle point.
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I am stuck and donāt know what to do
@south rampart Has your question been resolved?
<@&286206848099549185>
y=-3(x+2)4 ?
where is your ^2 and also missing +, right. remember this is a polynomial of max power 2
your intui about it being a -x^2 is good, it's cc down
y=-3(x+2)^2+4?
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would this one be right
oh
First with opposite, what side = 30?
idk why i was thinjing sah cah toa
Hey I'm kind of stupid
30 is the opposite lmao
o
Wouldn't make since cause sah and cah would be the same lol
SOH-CAH-TOA
use pythagorean theorem to find hypotenuse then deduce the values
of the ratios
So you see the opposite is 30, so kjnow you have 30/Hypotenuse
Then yeah use the pythagorean theorem to find the hypotenuse like they said
Alright, I'll go over them all rq
Opposite is the side opposite from your angle, easy enough, if you need the visualization draw a line out from your angle and it shoudl touch the opposite side
Easiest one to spot is the hypotenuse
It is
A. The longest side
B. Opposite to the 90 degree angle
Then you have the adjacent
The other line that forms your angle besides the hypotenuse, the one adjacent to it
So on this triangle
GOing straight out from your angle, we got 30, your opposite
The hypotenuse is the long one opposite from the right angle, which we do not know yet
And finally you have the side adjacent to your angle, 16
Oh
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can someone help me with this question. I don't know how to start it
@thorny lintel Has your question been resolved?
<@&286206848099549185>
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
So it is regular. Know what that means?
was I supposed to know this term in grade 11 ššš
It's simple. It just means it is exactly as you'd want it to be.
Everything is equal that should be equal.
All the sides are the same length. All the like angles are the same.
How many side does it have?
6
So everything is the same. If we can work out one thing we can use symmetry to work out all the rest.
Try mentally dividing it up into 10 triangles, all the same. Then if we sus out one we have them all
They have drawn one line for you.
do I need to use SOH CAH TOA rn or no?
sorry about that my wifi was being wonk
ok I drew it
what now?
Do you have lines to the middle of each side and to the points of the pentagon?
ye
So, they gave us one side of the triangle, if we can work out the angle in the middle we can use that TOA thing to work out the outside edge.
Can we work out the angle in the middle?
i think?
yess
yuh
... each one is ....?
90 degrees
š
yep
So now you have an angle 36 degrees and an adjacent edge 4.5 andTOA to work out the "O" edge
wait which angle is the one that's 36 degrees?
all those ones in the middle.
oh ok
Tan theta: op/adj
Sweet
idk how to do the theta symbol
$\theta$
G. Spark
G. Spark
you have worked out the angle
Which edge do you want? The angle opposite that.
Would suggest the first question is perimeter, so work out the outside edge first.
$tan(\theta) = Opp/Adj$
G. Spark
$tan(36) = Opp/4.5$
G. Spark
What did you do with the 4.5?
Suri
$tan(36) = Opp/4.5$
G. Spark
i think i did it the wrong way
So how do we getthat 4.5 to go to the other side?
multiple both side by 4.5
The right-hand one cancels and the left -side gets a 4.5
i got 2.6
$4.5*tan(36)$ = ?
Is your calculator working in degrees?
G. Spark
I don't get 3.6
But this gives you the opposite side to the angle. Check which part of the pentagon that is.
Great - on a roll
So pick the triangle we are using. Find the "opposite side to the angle".
And work out how many of them make up the perimeter.
can't I just find perimeter for the pentagon now?
Yes
I could just do 3.3 x 5
10
yep
i got 16.5
oh no thats the number I got from doing 3.3 x 5
Look at the triangle - we worked out the length of one side of one triangle. There are ten of them round the pentagon.
you want me to do 3.3 x 10 or something?
Ideally, you'd understand what side we just calculated & see what is right.
yea the opposite
Which is half a pentgon side.
One triangle only.
ten triangles to get all the way round.
Should I send an image?
sure
Is this what we are looking at?
yea
So there are ten bits, all length about 3.2cm.
yuh
Is that good?
Is the next part, the area?
yea
Any idea of the area of a triangle? Or have you got that one sorted?
Maybe best to not round until the end. But looks right.
yea
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you havent done anything wrong
your substitution just wasnt that helpful
do I need to use another sub?
u=e^x makes it look somehwat like partial frac
alright
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odokawa
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reaction for more information.
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odokawa
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hello im trying to solve a integral for 1/(1+2x^2)dx from my point of view i need to u-substitute 2x but i get stuck when trying to solve this. would appreciate any help!
is it (2x)^2
I think you let u = sqrt(2)x
^
how sqrt(2)x im confused
$u=\sqrt{2} x$
LordFelix
there you go
oh im so stupid, well i got it now. thanks for the help all of you!
i think i can solve it from here
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i know it is not ideal, but i took the positive x axis along the incline
would [
N = w_y + T_y \
T_x = w_x
]
be correct?
I'm not familiar with your notation
w_y the y-component of the weight force and T tension I assume?
yes
and when you say you took the positive x-axis along the incline
you mean your frame of reference is like this
messy visual I guess
the positive x axis like the opposite of what you have but it doesn't matter
anyways like
wait
$\degrees$
ok
cries in $^\circ$
Desync

anyways so [
N = w\m\cos{35\degrees} + T\m\sin{35\degrees}
]
if my trig wasnt wrong?
yes
I'm used to just using gravity as negative y š
having to do coordinate conversions
š
i struggle with this too its annoying š
but anyways, we want to find N but we dont know T and w
so hmmge
I usually find that setting your x-axis parallel to the plane is only helpful if you have tension forces along the plane
but there aren't too many forces in this problem so I guess it doesn't really matter either way
i just did it here because i want to practice more verstaile cases rather than sticking to one thing i guess
but i totally get you yeah
yeah, sure
that choice would have been much better
you have w because you have the mass of the ball
so you can figure out T from that as well
yeah, give it in terms of m
oh ic ok
this makes like easier
[
N = w\m\cos\theta + T\m\sin\theta \
T\m\cos\theta = w\m\sin\theta \Implies T = w\m\tan\theta
]
(writing theta instead of 35 for simplicity for now)
so
[
N = mg\p{\m\cos\theta + \m\sin\theta\m \tan\theta}
]
hopefully?
looks good
,w 9.81(cos(35180/pi) + sin(35180/pi)tan(35*180/pi)
hmm
that's a bit off
how did you get this?

i subbed in T = wtan(theta) in the first equation
bracketing perhaps?
oh wdym
ah wait, weight and tension are perpendicular
so Tx = wx doesn't work I think it's relative to the plane not to gravity, ignore that
wait i just did it on my physical calculator
cos(theta) + tan(theta)sin(theta) does return 1.22
why is WA drugged out then

anyways for c)
[
T =w\m\tan\theta
]
should do the trick me think
wait for what-
the normal is pulling away from the string, and it's not in motion so tension will be some component of weight and some component of normal, won't it?
oh yeah but my choice of coordinates makes us able to completley iggnore the normal for this me think
because like the x axis is the incline
so we can only consider T_x = w_x
ah right, sure
yeah its correct
woohoo
okay great
thanks a lot
but i just have like
a conceptual question if u dont mind
its okay. I am sure this is like highschool level for most i guess
um actually i guess its okay dw about it i think i answered my q
LOL
thanks a bunch
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Let $V = \mathbb{R}^{2 \times 2}$ and consider the basis
[
B = \begin{bmatrix}
1 & 0 \
0 & 0
\end{bmatrix},
\begin{bmatrix}
0 & 1 \
0 & 0
\end{bmatrix},
\begin{bmatrix}
0 & 0 \
1 & 0
\end{bmatrix},
\begin{bmatrix}
0 & 0 \
0 & 1
\end{bmatrix}.
]
For the matrix $A =
\begin{bmatrix}
1 & 2 \
-1 & -1
\end{bmatrix}$, define the mapping $f : V \to V$ by $f(X) = AX + XA$. Find the matrix $[f]_B^B$ and determine the kernel and image of the mapping $f$.
Slowaq
why to find matrix $[f]_B^B$ i have to do this?
Slowaq
@oblique rover Has your question been resolved?
i dont have any altenative way i just dont understand how to get $[f]_B^B$
Slowaq
well what does a transformation matrix mean ?
how do you define it ? what are the entries ?
you should have a definition of what a transformation matrix is somewhere
if you don't get what's going on in this definition we can talk about it
well if we have two vector spaces $W,V$ over field $\mathbb{F}$ then $f:V \rightarrow W$ is linear transformation, $B=(v_1,...,v_n)$ is basis of $V$, $C=(w_1,...,w_n)$ is basis of $W$. Then this is representation of linear transformation $f$ with respect to basis $B,C$
Slowaq
ok
so each column of that matrix is the image of a basis vector in B written in basis C (that's what [f(v)]^C means)
and what I mean by written in basis $C$ is that $[v]^C$ tells you how much $w_1, w_2, \cdots, w_n$ you have in the vector $v$
aPlatypus
i.e. to be very explicit, if you have $v=k_1w_1 + k_2w_2 + \cdots + k_nw_n$ then $$[v]^C = \begin{bmatrix} k_1Ā \ k_2 \ \vdots \ k_n \end{bmatrix}$$
aPlatypus
why tf is my k_1 not aligned ffs
xdd doesnt matter
and the k1, ..., kn are unique cause C is a basis (fortunately)
it's not like you can get two representations for the same vector given a basis
right
so what they're doing in your solution is strictly applying the definition you gave
looking at the image of each basis vector of B
getting the coefficients of these images in basis B (that's easy)
and writing that in the expected format of a transformation matrix
@oblique rover
and what do you mean by image of a basis vector in B? xd
yes yes im here i am trying to understand it xd
cuz i think i get it only this makes me unsure
f(v_i) with v_i is a vector in basis B
I'm just using fancy/overloaded words
@oblique rover
last questuon what do you mean by with?
explaining what v_i is in f(v_i)
ahh alright i understand the whole thing now
thank you very much my man you are a saviour
but how do i find this
when
basis are
i want to find how much -1,0,1 in in $\begin{pmatrix}1&0&0\0&1&0\0&0&1 \end{pmatrix}$?
Slowaq
@sullen island
$P^3(x,\mathbb{R})$ is polynomial with maximum degree being 3 if i am not mistaken
Slowaq
@oblique rover Has your question been resolved?
f(1) means, take the polynomial p(x)=1, and compute (p(-1), p(0), p(1)), that's the result
@oblique rover
f(1) = (1, 1, 1), cause p(x) = 1 always evaluates to 1 no matter the input
ah alright got it thx
@oblique rover Has your question been resolved?
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During student council elections, you had to vote for 2 of the 3 candidates. After the results were counted, the votes were the following:
- Student A - 236 votes
- Student B - 184 votes
- Student C - 152 votes
How many people voted in total? (Assuming each person picked 2 candidates)
How many people voted for Student A and Student C simultaneously?
say 10 people vote for 2 candidates each
then we will get 20 votes in total right?
let's say the votes are: 3,7,10 so total votes are 20. we can deduce that 10 people voted
we can do the same here
š
ahhhhhh
i got it
we have to make one implication
someone cant vote for A twice for example
if someone votes for A and C. that means they did not vote for B right?
Right.
so the number of people voting for A and C at the same time
is the same number of people not voting for B
the number of people not voting B is the number of votes minus the number of people voting B
388
correct
but not the end result
that is the number of votes
now we want to get the number of people
and we already know how to do that š
number of people = Votes/2
so 388/2
194
š
Wait, but, how could 194 people vote for a and c simultaneously
If c only has a total of 152 votes
Any maybe someone voted c and b as well
ah i think i got it now
Here, I fixed my statement:
so the number of people voting for A and C at the same time
is the same number of people not voting for B
the number of people not voting B is the number of voters minus the number of people voting B
B got 184 votes
so 184 people voted for B
286 people voted
so 286-184 people did not vote for B and thus voted for A and C
that makes 102
sry for the confusion before
pretty sure, yes
because for some reason, this question really makes you doubt your confidence lol
primarily, it makes me realise it's late haha
yes, I see now.
Alright.
I guess Iāll close it now. Thanks for the help, you made my evening way more nicer.
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that is nice to hear š
Cheers!
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anyone understand
sure, what's the problem
dis
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
so i understand the lesson in general but i donāt understand this question cuz of the 4x^2 one
2
ah okay
so you can factor the 4x^2 thing and one of those factors should cancel out with the top to make it cleaner
Iād like to combine the top then combine the bottom
Normally when i find something like 4x^2 i usually do Mode 5,3 on my calculator yet i canāt do it this time due to the 4
Doesnāt work
you can at least make it 4(stuff)?
or i donāt think it does
that at least gets rid of some things
-2 and +1
yep
gets rid of x+1
looks like it gets rid of a lot of things, that's nice
well I'm seeing at least 1 common factor on top and bottom š
looking good
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oop I can't do it
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hey could i ask another question š
sure, go for it
what if i got smth to factorize that doesnāt have a least common factor, something like 3x^2+8x+7?
you can try to factorise it by hand
or if you're really stuck, reach for the quadratic formula
oh so thereās no way to do it using a calculator?
not...easily
(ax +b)(cx + d) = acx^2 + (bc+ad)x + bd
ac = 3
bc+ad = 8
bd=7
obv. b d are 7 and 1, and a c are 3 and 1 which means...uhh...yeah I don't think this has real solutions because you can't get that middle bit to work
if you have x^2 + bx + c it's a boatload easier to hand-factorise
You can check if it's factorable over reals using the discriminant first
duh, of course
this was my teacherās method but i donāt understand why it doesnāt work and gives me the same answer as my calc
thereās supposed to be a 4 in front of the two parentheses
is there a more reliable method to factorize by hand?
quadratic formula I guess
alright thank youu
iām assuming the way my teacher taught it isnāt very conventional š
closing ticket now tysm for help :D
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