#help-27

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versed vault
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SinC/14

barren frigate
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okok

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ioh

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oh

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i watched so many videos on this still didnt understand

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i been stuck on this assignment for 2 weeks I keep quitting

versed vault
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do u understand what the ambigous case is conceptly

barren frigate
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conceptly uhh

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like defining it?

versed vault
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I would watch a yt video on it

barren frigate
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I came here because i didnt understand

versed vault
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but for this problem

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u have ur ratio

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which u said was this

barren frigate
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ambigous case is when we arent given the info to sovle the triangle

versed vault
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....

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no

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we are

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its just you can get 2 diffirent triangles for the given triangle

barren frigate
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that what my teacher taught us

barren frigate
versed vault
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... doesnt matter

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its the same exact thing

barren frigate
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😨

versed vault
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now solve for angle C

barren frigate
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how tho

versed vault
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cross mutiply the 14

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you want to isolate sinC

barren frigate
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14* the value of sin?

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sin39/10

versed vault
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14sin(39)/10

barren frigate
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okok that makes sense

versed vault
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So that gets you what

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sinC=?

barren frigate
# versed vault

I knew the formula but didnt understand it looked like this

barren frigate
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lemme calculatye

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50.4803633161 is what i got

versed vault
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uh thats wrong

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are u radians?

barren frigate
versed vault
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not 10 deg

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...

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its just 10

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10 is a length

barren frigate
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šŸ’€ oh yeah

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0.88104854747

versed vault
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ye

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So

barren frigate
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now wdym by sinc_

versed vault
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sinC=0.88104854747

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now do sin inverse

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to find theta

barren frigate
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oh now we have anfgle by -1

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whats theta in this

versed vault
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angle C

barren frigate
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its gonna be the straight 90 degree line?

versed vault
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...

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No

barren frigate
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;-;

versed vault
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Just put it in ur calc

barren frigate
versed vault
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so

barren frigate
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so C is 62 degree?

versed vault
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you know know that there is two possible values for AC

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Because

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The side opposite the given angle is smaller than the side ajacent to the given angle.

barren frigate
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how this leading me to that

versed vault
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because a<c in this case

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and ambig case

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here let me send a notes exampke

barren frigate
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our adjacent is

versed vault
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Reference this

barren frigate
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wh

barren frigate
barren frigate
versed vault
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You don’t have to

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But it would help

barren frigate
versed vault
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But do you see why it’s two?

barren frigate
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trying to

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what is our adjacent

versed vault
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Basically given the opposite side of the given angle is smaller than the the side

barren frigate
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beside Angle A

versed vault
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Our adjacent could be either side b or c

barren frigate
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ok so

versed vault
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I never learned the height method

barren frigate
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but what if height is small

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and we only checked a<c

versed vault
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Height doesn’t affect law of sines

barren frigate
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WQHART

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DAYUM

versed vault
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Your teacher may give you the height

versed vault
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For this example, you don’t need the height at all

barren frigate
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good point

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ok I get it

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are u free for more quesdtions or did I suck up ur brain cells

versed vault
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Sure I can help

barren frigate
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ok wait let me put this explanation together

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Find Angle C= 14sin(39deg)/10
arcsin(0.88104854747) = 61.7 = 62 Degrees
Explanation: The side opposite the given angle is smaller than the side adjacent to the given angle.

versed vault
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Well not that’s just the case i

barren frigate
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wott

versed vault
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Because the side opposite of the given angle is smaller

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If we get a theta value that is possible, then there is two triangles in that case

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If theta is equal to 90 there is one triangle

barren frigate
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what is theta

versed vault
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If you plug into your calc, and you get an error you have zero triangles

barren frigate
versed vault
versed vault
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Measure of angle C

versed vault
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Sometimes you plug it into your calc and it will say error

barren frigate
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theres times we dont get it?

versed vault
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Yes

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There’s times where there is no triangle

barren frigate
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is that our fault or thats a real thing

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ohh

versed vault
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Real thing

barren frigate
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so what do i add to my explanation

versed vault
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I mean I don’t know how your teacher teaches it

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And she may not understand the explanation but

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I would say ā€œBecause the opposite side of the given angle is less than the side adjacent of the given angle and a theta value for angle C is possible then there must be two trianglesā€

barren frigate
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is there another word we can use than theta

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cause theta we didnt use it for this from what i remember

versed vault
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Just say measure of angle C

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Theta is just a way of expressing an unknown angle

barren frigate
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can i say

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the unknown angle (which is c)

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wait no

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thats stupid

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alr

versed vault
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Theta is this

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Īø

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You probs have seen it

barren frigate
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yes

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Im gonna go shower

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ill make a new question later and ping u and if ur free u can respond if ur not its fine

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Thank u for the help Propus

versed vault
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Anytime

devout snowBOT
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devout snowBOT
cedar ginkgo
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sorry ignore that image^^

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the answer say that this graph has a pos skew

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cedar ginkgo
#

.close

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dapper barn
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Where do I go solving this from here?

devout snowBOT
dapper barn
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Any help is appreciated

quaint fulcrum
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u have any notes on how to do it?

dapper barn
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Nope

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First time solving a problem like this

quaint fulcrum
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same :(

supple knot
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,rotate

woven radishBOT
dapper barn
devout snowBOT
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@dapper barn Has your question been resolved?

dapper barn
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How do I solve thi@s?

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This*

dapper barn
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Hello?

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??????????

dapper barn
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.close

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main oasis
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Hello everyone!
Kate has some 10% vinegar. How much water does she need to add to it in order to get 3 kg of 6% vinegar?
I am doing this type of question for the first time and with no clue on the process (btw my working is shown in picture 2). Is there a way of optimizing it?

devout snowBOT
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@main oasis Has your question been resolved?

main oasis
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<@&286206848099549185>

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main oasis
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: /

devout snowBOT
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finite briar
#

Given, $\frac{5xu}{2} + u = v$, such that $u = \sin^2(\frac{\pi x}{2})$ and $v = \cos(\pi x)$

finite briar
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I know it has an integral solution at x=2 (from graphing)

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atleast I think so

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let me confirm

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wait nvm

rugged sparrow
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what for do you need to solve?

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x?

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u?

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v?

finite briar
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well yes ofc

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i wrote u and v cus it would get big and messy

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one sec I need to modify the equation

woven radishBOT
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ItzKraken

finite briar
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this should have a solution at x=2

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wait it doesnt does it

rugged sparrow
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you bsure?

finite briar
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Me doing something wrong

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wait

rugged sparrow
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what I'd try as a first step is covert sin^2(pix/2) into cos

finite briar
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wait thats cos^2 of pi/2(x-1) no

rugged sparrow
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that definitely does

finite briar
rugged sparrow
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$\sin^{2}\left(\frac{\pi x}{2}\right)=\frac{1+\cos\left(\pi x\right)}{2}$

woven radishBOT
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B-eard

finite briar
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nvm

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.close

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rugged sparrow
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did you get it?

devout snowBOT
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restive river
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Simplify 5x^2x3m^6

devout snowBOT
restive river
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and now I wait

timber pebble
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is this $5x^2 \times 3m^6$?

woven radishBOT
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jan Niku

timber pebble
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or $5x^2x3m^6$?

woven radishBOT
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jan Niku

restive river
timber pebble
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!nosols

devout snowBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

restive river
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uhm

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i still dont understand

upbeat violet
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stop giving solutions

timber pebble
upbeat violet
timber pebble
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combining works like this: numbers go with numbers, letters can go with like letters, and onwards

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so numbers go with numbers, m goes with m, x goes with x

restive river
upbeat violet
timber pebble
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so all you can do is combine numbers

restive river
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yes

timber pebble
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$5 \times x^2 \times 3 \times m^6$

woven radishBOT
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jan Niku

restive river
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so we'll bring the powers down?

timber pebble
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Not quite

restive river
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uhm

timber pebble
restive river
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i cant really focus with multiple ppl here.

timber pebble
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do you get what I mean by similar things go together @restive river ?

restive river
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bro, can you please like..get out?

timber pebble
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maybe we should just wait a minute or two here

timber pebble
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sorry elio

restive river
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cuz i have an exam on tuesday

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paper 2 with no calculator

timber pebble
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okay, i think were good

restive river
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thanks

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yh

timber pebble
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x goes with x, numbers go with numbers

restive river
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naur

timber pebble
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naur?

restive river
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no

timber pebble
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oh

restive river
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so like hold on

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5 time 3 times x^2 times m^6?

timber pebble
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yea, exactly

restive river
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oh ok

timber pebble
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you put the numbers together, the x's together, and the m's together

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but youre still not quite done

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$5 \times 3 \times x^2 \times m^6$

woven radishBOT
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jan Niku

timber pebble
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we can still simplify this a little more

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(what is 5 x 3?)

restive river
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hmm

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15

timber pebble
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yea

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$15 \times x^2 \times m^6$

woven radishBOT
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jan Niku

timber pebble
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and youre done. you can check youre done by making sure that everything is grouped together

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theres only one term of numbers

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only one term of x's

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and only one term of m's

restive river
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so that is: 15x^2m^6

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?

timber pebble
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yea

restive river
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o

timber pebble
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i guess its important to note its customary to write numbers first

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some ppl consider it wrong if you put the number somewhere else

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but you have it first so, just saying

restive river
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thank youuuu!!

timber pebble
restive river
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dont be suprised to see me back

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math isnt rlly my stronghold

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didnt think id be back so fast

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p=k+m/m

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make m the subject of the formula

timber pebble
restive river
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oh srry abt that

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i just saw so many other channels thats why

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lemme make a new one

timber pebble
#

.close

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tropic marlin
#

I solved this absolute value problem using sets. Is there a more efficient way? No chance I'm solving every absolute value problem like this ā˜ ļø

tropic marlin
vagrant steeple
#

assume x/x+1 = t

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Its the easiest i can think of

tropic marlin
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hold on

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Same thing?

vagrant steeple
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Solve for t then in the result of t put its value in x

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You'll avoid a bunch of calculation

tropic marlin
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This is what i got for the first condition, is this even correct?

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Looks very different from the one without the sub

restive river
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there are no solutions for x then

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empty set

tropic marlin
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The one i did without sub gets the correct answer

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Comparison

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Or did i mess the sub so badly?

devout snowBOT
#

@tropic marlin Has your question been resolved?

fossil locust
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or both negative

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they can't be both negative as |t| + 4 is always positive

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so when solving $\left|\frac{x}{x+1} \right| > 2$ then

woven radishBOT
fossil locust
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you should get $x \in \left(-2, -\frac{2}{3}\right)$

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that matches up with the answer to the original inequality on Desmos

fossil locust
# woven radish **south**

asymptote is at x = -1, and y = x/(x + 1) it approaches +infinity from the left and -infinity from the right

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so $\frac{x}{x+1} = 2 \implies x = -2$

woven radishBOT
fossil locust
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and $\frac{x}{x + 1} = -2 \implies x = -\frac{2}{3}$

woven radishBOT
devout snowBOT
#

@tropic marlin Has your question been resolved?

tropic marlin
#

So even the splution without the sub is wrong?

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Where did i go wrong with the one without sub?

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OH I PUT -2/3 AFTER -1

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Thanks so much for the help

devout snowBOT
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spark current
devout snowBOT
spark current
#

Translation: Replace the different loads with an equivalent resultant and effective torque acting at point A

#

I don't know how to do this

devout snowBOT
#

@spark current Has your question been resolved?

spark current
#

<@&286206848099549185>

spark current
#

<@&286206848099549185>

#

<@&286206848099549185>

plush pulsar
#

Womp womp

spark current
#

holy shit

spark current
devout snowBOT
#

@spark current Has your question been resolved?

spark current
#

fucking no

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<@&286206848099549185>

hoary elbow
#

@spark current still in need?

devout snowBOT
#

@spark current Has your question been resolved?

devout snowBOT
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copper plinth
#

Can somane help me with interval notation with the āˆž of an interval Exemple: [ -āˆž, 2]

copper plinth
#

On the internet the say other things

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The green is ecual to a closed [ and the red is ]?

potent nebula
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I'm not sure what you mean by green and red

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but

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the brackets mean whether or not you include that endpoint

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the interval [-5,9] is all the numbers between -5 and 9 inclusive

aka

-5<=x<=9

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and (-5,9) is not inclusive

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-5<x<9

copper plinth
#

How do you write it with a [ with the symbol of āˆž

amber oriole
copper plinth
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I am dutch šŸ˜‰

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This is another picture

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i learned it like that

amber oriole
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Yeah. I understand why you are confused

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Just do it with the filled and non-filled circles

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So filled means that the end-point is included and non-filled means it’s not

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You Can also see a mathematical reprƦsentation to the left side of my picture

#

Representation

amber oriole
copper plinth
#

Ow is see now but how is it with the āˆž and when is it filled then?

amber oriole
copper plinth
#

So its open?

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Can it be closed?

amber oriole
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No I dont think so, you can’t confine a point to infinity

copper plinth
#

So its always open?

amber oriole
#

Thats why we just write x greater-than-or-equal-to. a

copper plinth
#

I get it now

amber oriole
#

Good. You just need to work with it a little to understand it. No need to rush yourself, because you can't get everything at once šŸ™‚

copper plinth
#

thx bdw

devout snowBOT
#

@copper plinth Has your question been resolved?

copper plinth
#

yes

devout snowBOT
#
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muted stump
#

Let's say I am given a 3x3 matrix, A. I have to find the diagolised matrix and the permutation matrix such that A = PDP^-1. Now I can easily find the eigenvalues and eigenvectors, and the diagnolised matrix, and I also know how to find the permutation matrix. My problem is, in which order do I write the eigenvectors such that it will be a permutation matrix. Lets say I have eigenvalues 1, -1, 2 and I find the eigenvectors now in which order do I write it, sorry if my question doesn't make sense

stone stump
#

are you sure that permutation matrix is the correct word you are looking for?

#

not just invertible matrix P?

muted stump
#

Uhh I don't think so

stone stump
#

that said, the order of them doesnt matter

muted stump
#

Really?

stone stump
#

the order in which you put the eigenvectors is the same order as the eigenvalues in the diagonal

muted stump
#

So it doesn't matter which order I follow

stone stump
#

permutation matrices only have a single 1 in each row or column

muted stump
#

It will still spit out the same shit?

muted stump
stone stump
#

I said that three messages ago

muted stump
#

Ok

#

That's all I needed to know

#

Thank you 😊

devout snowBOT
#

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lofty monolith
#

I’ve shown that this has a critical point at (0,0,0) and now I’m trying to see if its a saddle/min/max point

lofty monolith
#

Hessian at that point has negative diagonals and determinant = 0 so i concluded negative semi definite but

#

Not really sure where to go from there

hasty saffron
#

You can just do the double derivative test to see for maxima etc right?

wise plank
#

using the hessian

hasty saffron
#

Oh

lofty monolith
#

It seems like i need to rearrange the original function? Like complete the square?

devout snowBOT
#

@lofty monolith Has your question been resolved?

lofty monolith
#

Changed the form into x^4 + y^4 - (x+y)^2 and subbed in y=x

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To get 2x^4-4x^2 which is maximised at x=0

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Idk if that’s right or if i am on the right track

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<@&286206848099549185>

lofty monolith
wise plank
lofty monolith
#

Is that enough to show its saddle

wise plank
#

I think so? I’m not completely certain

devout snowBOT
#

@lofty monolith Has your question been resolved?

devout snowBOT
#

@lofty monolith Has your question been resolved?

spark current
devout snowBOT
#

@lofty monolith Has your question been resolved?

lofty monolith
#

<@&286206848099549185>

hoary elbow
#

Can u quickly sum up what you tried to do?

hoary elbow
#

Just ping me you do

lofty monolith
#

Used hessian, diagonals and determinant of hessian = 0 to conclude negative semi definite

lofty monolith
worldly field
#

Hey, Hessian = 0 means that the second derivative test is inconclusive. You have checked that the function is maximized at (0,0) along the line y=x. You will see that it is minimized at (0,0) along the line y=-x, so it's a saddle point.

lofty monolith
#

Thank you so much

#

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south rampart
#

I am stuck and don’t know what to do

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@south rampart Has your question been resolved?

south rampart
#

<@&286206848099549185>

frail moss
south rampart
#

y=-3(x+2)4 ?

frail moss
#

where is your ^2 and also missing +, right. remember this is a polynomial of max power 2

#

your intui about it being a -x^2 is good, it's cc down

south rampart
#

y=-3(x+2)^2+4?

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vast violet
#

]

devout snowBOT
vast violet
#

would this one be right

restive river
#

Remember sine = Opposite/Hypotenuse

vast violet
#

oh

restive river
#

First with opposite, what side = 30?

vast violet
#

idk why i was thinjing sah cah toa

restive river
#

Hey I'm kind of stupid

restive river
vast violet
#

o

restive river
#

SOH-CAH-TOA

turbid zealot
#

use pythagorean theorem to find hypotenuse then deduce the values

vast violet
#

ohhh

#

SOH

turbid zealot
#

of the ratios

vast violet
#

not sah

#

lOl

restive river
#

So you see the opposite is 30, so kjnow you have 30/Hypotenuse

#

Then yeah use the pythagorean theorem to find the hypotenuse like they said

vast violet
#

waitttttt

#

so what is 16

restive river
#

Opposite is the side opposite from your angle, easy enough, if you need the visualization draw a line out from your angle and it shoudl touch the opposite side

#

Easiest one to spot is the hypotenuse

#

It is
A. The longest side
B. Opposite to the 90 degree angle

#

Then you have the adjacent

#

The other line that forms your angle besides the hypotenuse, the one adjacent to it

#

So on this triangle

#

GOing straight out from your angle, we got 30, your opposite

#

The hypotenuse is the long one opposite from the right angle, which we do not know yet

#

And finally you have the side adjacent to your angle, 16

vast violet
#

Oh

devout snowBOT
#

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thorny lintel
#

can someone help me with this question. I don't know how to start it

devout snowBOT
#

@thorny lintel Has your question been resolved?

thorny lintel
#

<@&286206848099549185>

devout snowBOT
# thorny lintel can someone help me with this question. I don't know how to start it
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
forest rapids
#

So it is regular. Know what that means?

thorny lintel
#

eh

#

regular?

forest rapids
#

Yep

#

Given a regular ...

thorny lintel
#

was I supposed to know this term in grade 11 😭😭😭

forest rapids
#

It's simple. It just means it is exactly as you'd want it to be.
Everything is equal that should be equal.

#

All the sides are the same length. All the like angles are the same.

#

How many side does it have?

thorny lintel
#

6

forest rapids
#

Really?

#

I must have mis-counted.

thorny lintel
#

oh 5

#

im tired

#

and blind

forest rapids
#

So everything is the same. If we can work out one thing we can use symmetry to work out all the rest.

#

Try mentally dividing it up into 10 triangles, all the same. Then if we sus out one we have them all

#

They have drawn one line for you.

thorny lintel
#

do I need to use SOH CAH TOA rn or no?

#

sorry about that my wifi was being wonk

#

ok I drew it

#

what now?

forest rapids
#

Yes, but not just yet.

#

Where are the lines? describe it

thorny lintel
#

um...

#

the height?

forest rapids
#

Do you have lines to the middle of each side and to the points of the pentagon?

thorny lintel
#

ye

forest rapids
#

So, they gave us one side of the triangle, if we can work out the angle in the middle we can use that TOA thing to work out the outside edge.

#

Can we work out the angle in the middle?

thorny lintel
#

i think?

forest rapids
#

.... suspense....

#

Do all the triangles share apoint in the middle?

thorny lintel
#

yess

forest rapids
#

So all the way round is 360 degrees

#

And there are ten the same

thorny lintel
forest rapids
#

Yep - looking good.

#

so 10 angles, all the same, make up 360 degrees.

thorny lintel
#

yuh

forest rapids
#

... each one is ....?

thorny lintel
#

90 degrees

forest rapids
#

10 * 90 does not equal 360

#

😦

thorny lintel
#

😭

forest rapids
#

Divide by 10 is not difficult when one is not tired.

#

360/10 = ?

thorny lintel
#

divide what by 10? 360?

#

oh

#

36

forest rapids
#

yep

#

So now you have an angle 36 degrees and an adjacent edge 4.5 andTOA to work out the "O" edge

thorny lintel
#

wait which angle is the one that's 36 degrees?

forest rapids
#

all those ones in the middle.

thorny lintel
#

oh ok

forest rapids
#

ten of them get all the way round.

#

so 10 * angle = 360 degrees

thorny lintel
#

ok

#

now do we use SOH CAH TOA

forest rapids
#

And adjacent edge is 4.5cm - and yes TOA

#

What does TOA look like again?

thorny lintel
#

Tan theta: op/adj

forest rapids
#

Sweet

thorny lintel
#

idk how to do the theta symbol

forest rapids
#

$\theta$

woven radishBOT
#

G. Spark

thorny lintel
#

oh

#

idk how to use these commands to complicated

forest rapids
#

Me neither.

#

Don't need them.

#

so $tan(\theta) = Opposite/adjacent$

woven radishBOT
#

G. Spark

thorny lintel
#

ok

#

wrote that down

#

what goes into theta?

#

the 90 or 36?

forest rapids
#

you have worked out the angle

#

Which edge do you want? The angle opposite that.
Would suggest the first question is perimeter, so work out the outside edge first.

#

$tan(\theta) = Opp/Adj$

woven radishBOT
#

G. Spark

forest rapids
#

$tan(36) = Opp/4.5$

thorny lintel
#

is 0.16 right?

#

feels too small

woven radishBOT
#

G. Spark

forest rapids
#

What did you do with the 4.5?

thorny lintel
#

i did

#

$opp = tan36/4.5$

woven radishBOT
forest rapids
#

$tan(36) = Opp/4.5$

woven radishBOT
#

G. Spark

thorny lintel
#

i think i did it the wrong way

forest rapids
#

So how do we getthat 4.5 to go to the other side?

#

multiple both side by 4.5

#

The right-hand one cancels and the left -side gets a 4.5

thorny lintel
#

i got 2.6

forest rapids
#

$4.5*tan(36)$ = ?
Is your calculator working in degrees?

thorny lintel
#

... I think I cleared it earlier hold on-

#

3.6

woven radishBOT
#

G. Spark

thorny lintel
#

ok now I got 3.6

#

so do I just multiply by 5 to get the perimeter?

forest rapids
#

I don't get 3.6
But this gives you the opposite side to the angle. Check which part of the pentagon that is.

thorny lintel
#

oh sorry 3.3

#

😭

#

my eyes ain't working

forest rapids
#

Great - on a roll

#

So pick the triangle we are using. Find the "opposite side to the angle".

#

And work out how many of them make up the perimeter.

thorny lintel
#

can't I just find perimeter for the pentagon now?

forest rapids
#

Yes

thorny lintel
#

I could just do 3.3 x 5

forest rapids
#

not 5

#

check which side length we worked out again.

thorny lintel
#

it's a pentagon

#

it has 5 sides

forest rapids
#

yep

#

And what did we work out?

#

How many triangles were there?

thorny lintel
#

10

forest rapids
#

yep

thorny lintel
forest rapids
#

So that's 10 of them?

#

Looks alittle small.

thorny lintel
#

oh no thats the number I got from doing 3.3 x 5

forest rapids
#

Look at the triangle - we worked out the length of one side of one triangle. There are ten of them round the pentagon.

thorny lintel
#

you want me to do 3.3 x 10 or something?

forest rapids
#

Ideally, you'd understand what side we just calculated & see what is right.

thorny lintel
#

yea the opposite

forest rapids
#

Which is half a pentgon side.

#

One triangle only.

#

ten triangles to get all the way round.

forest rapids
#

Should I send an image?

thorny lintel
#

sure

forest rapids
#

Is this what we are looking at?

thorny lintel
#

yea

forest rapids
#

So there are ten bits, all length about 3.2cm.

thorny lintel
#

yuh

forest rapids
#

Is that good?
Is the next part, the area?

thorny lintel
#

yea

forest rapids
#

Any idea of the area of a triangle? Or have you got that one sorted?

thorny lintel
#

one sec-

#

area I got 7.4 cm^2

#

do i multiply by 10 again?

forest rapids
#

Maybe best to not round until the end. But looks right.

thorny lintel
#

yea

forest rapids
#

HOw many triangle areas are there in the whole?

#

Multiply by that number.

thorny lintel
#

yea

#

i did it and rounded it

#

i got

#

73.6

forest rapids
#

Looks good.

#

Solved. Remember to tell the bot to close the chat.

thorny lintel
#

ok thank you for your help

#

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viscid plover
devout snowBOT
viscid plover
#

I feel like I’m doing something wrong

#

can someone confirm?

dense jay
#

you havent done anything wrong
your substitution just wasnt that helpful

viscid plover
#

do I need to use another sub?

dense jay
#

hmm

#

actually

#

it could work

viscid plover
#

u=e^x makes it look somehwat like partial frac

dense jay
#

yeah thats what i was thinking

#

that would probably work out

#

give it a go

viscid plover
#

alright

devout snowBOT
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@viscid plover Has your question been resolved?

viscid plover
#

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woven radishBOT
#

odokawa
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

#

odokawa
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lost echo
#

.reopen

#

.reopen

lime zinc
#

hello im trying to solve a integral for 1/(1+2x^2)dx from my point of view i need to u-substitute 2x but i get stuck when trying to solve this. would appreciate any help!

valid iron
#

is it (2x)^2

lime zinc
eager lodge
#

I think you let u = sqrt(2)x

warm lantern
#

^

lime zinc
#

how sqrt(2)x im confused

eager lodge
#

we want to turn it to 1/(1+u^2)

#

so 2x^2=u^2

#

u=sqrt(2)x

wheat pawn
#

$u=\sqrt{2} x$

woven radishBOT
#

LordFelix

wheat pawn
#

there you go

lime zinc
#

oh im so stupid, well i got it now. thanks for the help all of you!

#

i think i can solve it from here

devout snowBOT
#

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restive river
#

i know it is not ideal, but i took the positive x axis along the incline

restive river
#

would [
N = w_y + T_y \
T_x = w_x
]
be correct?

woven radishBOT
robust dust
#

I'm not familiar with your notation

#

w_y the y-component of the weight force and T tension I assume?

restive river
#

yes

robust dust
#

and when you say you took the positive x-axis along the incline

restive river
robust dust
#

you mean your frame of reference is like this

restive river
#

messy visual I guess

robust dust
#

right yeah

#

yeah, those look right then

restive river
#

the positive x axis like the opposite of what you have but it doesn't matter

#

anyways like

#

wait

#

$\degrees$

woven radishBOT
restive river
#

ok

robust dust
#

cries in $^\circ$

woven radishBOT
#

Desync

restive river
#

anyways so [
N = w\m\cos{35\degrees} + T\m\sin{35\degrees}
]
if my trig wasnt wrong?

woven radishBOT
robust dust
#

yes

#

I'm used to just using gravity as negative y 😭

#

having to do coordinate conversions

restive river
#

😭

#

i struggle with this too its annoying šŸ˜”

#

but anyways, we want to find N but we dont know T and w

#

so hmmge

robust dust
#

I usually find that setting your x-axis parallel to the plane is only helpful if you have tension forces along the plane

#

but there aren't too many forces in this problem so I guess it doesn't really matter either way

restive river
#

i just did it here because i want to practice more verstaile cases rather than sticking to one thing i guess

#

but i totally get you yeah

robust dust
#

yeah, sure

restive river
#

that choice would have been much better

robust dust
#

you have w because you have the mass of the ball

#

so you can figure out T from that as well

restive river
#

do i?

#

it just says m

robust dust
#

yeah, give it in terms of m

restive river
#

oh ic ok

#

this makes like easier

#

[
N = w\m\cos\theta + T\m\sin\theta \
T\m\cos\theta = w\m\sin\theta \Implies T = w\m\tan\theta
]

woven radishBOT
restive river
#

(writing theta instead of 35 for simplicity for now)

#

so

#

[
N = mg\p{\m\cos\theta + \m\sin\theta\m \tan\theta}
]

woven radishBOT
restive river
#

hopefully?

robust dust
#

looks good

restive river
#

,w 9.81(cos(35180/pi) + sin(35180/pi)tan(35*180/pi)

robust dust
#

hmm

restive river
#

hmmge the answer is given as 1.22mg

#

okay thats fine

#

,w 18.6/9.81

robust dust
#

that's a bit off

restive river
#

yeah

#

something is wrong

robust dust
restive river
restive river
robust dust
#

bracketing perhaps?

restive river
#

oh wdym

robust dust
#

was checking the wolfram input

#

see if there was some bracketing stuff going on

restive river
#

seems fine

#

here is what they did btw

robust dust
#

ah wait, weight and tension are perpendicular

#

so Tx = wx doesn't work I think it's relative to the plane not to gravity, ignore that

restive river
#

wait i just did it on my physical calculator

#

cos(theta) + tan(theta)sin(theta) does return 1.22

#

why is WA drugged out then

#

anyways for c)

#

[
T =w\m\tan\theta
]
should do the trick me think

woven radishBOT
robust dust
#

I closed my diagram already 😭

#

did you take the normal into account?

restive river
#

wait for what-

robust dust
#

the normal is pulling away from the string, and it's not in motion so tension will be some component of weight and some component of normal, won't it?

restive river
#

oh yeah but my choice of coordinates makes us able to completley iggnore the normal for this me think

#

because like the x axis is the incline

#

so we can only consider T_x = w_x

robust dust
#

ah right, sure

restive river
#

yeah its correct

#

woohoo

#

okay great

#

thanks a lot

#

but i just have like

#

a conceptual question if u dont mind

robust dust
#

sure

#

but last time I did mechanics was in my A-levels years ago

restive river
#

its okay. I am sure this is like highschool level for most i guess

#

um actually i guess its okay dw about it i think i answered my q

#

LOL

#

thanks a bunch

#

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oblique rover
#

Let $V = \mathbb{R}^{2 \times 2}$ and consider the basis
[
B = \begin{bmatrix}
1 & 0 \
0 & 0
\end{bmatrix},
\begin{bmatrix}
0 & 1 \
0 & 0
\end{bmatrix},
\begin{bmatrix}
0 & 0 \
1 & 0
\end{bmatrix},
\begin{bmatrix}
0 & 0 \
0 & 1
\end{bmatrix}.
]

For the matrix $A =
\begin{bmatrix}
1 & 2 \
-1 & -1
\end{bmatrix}$, define the mapping $f : V \to V$ by $f(X) = AX + XA$. Find the matrix $[f]_B^B$ and determine the kernel and image of the mapping $f$.

woven radishBOT
#

Slowaq

oblique rover
#

why to find matrix $[f]_B^B$ i have to do this?

woven radishBOT
#

Slowaq

oblique rover
devout snowBOT
#

@oblique rover Has your question been resolved?

sullen island
#

what do you mean why ?

#

what's your alternative way ?

oblique rover
#

i dont have any altenative way i just dont understand how to get $[f]_B^B$

woven radishBOT
#

Slowaq

sullen island
#

well what does a transformation matrix mean ?

#

how do you define it ? what are the entries ?

#

you should have a definition of what a transformation matrix is somewhere

#

if you don't get what's going on in this definition we can talk about it

oblique rover
#

well if we have two vector spaces $W,V$ over field $\mathbb{F}$ then $f:V \rightarrow W$ is linear transformation, $B=(v_1,...,v_n)$ is basis of $V$, $C=(w_1,...,w_n)$ is basis of $W$. Then this is representation of linear transformation $f$ with respect to basis $B,C$

woven radishBOT
#

Slowaq

oblique rover
#

could you please explain this formula a little bit more?

sullen island
#

ok

#

so each column of that matrix is the image of a basis vector in B written in basis C (that's what [f(v)]^C means)

#

and what I mean by written in basis $C$ is that $[v]^C$ tells you how much $w_1, w_2, \cdots, w_n$ you have in the vector $v$

woven radishBOT
#

aPlatypus

sullen island
#

i.e. to be very explicit, if you have $v=k_1w_1 + k_2w_2 + \cdots + k_nw_n$ then $$[v]^C = \begin{bmatrix} k_1Ā \ k_2 \ \vdots \ k_n \end{bmatrix}$$

woven radishBOT
#

aPlatypus

sullen island
#

why tf is my k_1 not aligned ffs

oblique rover
sullen island
#

and the k1, ..., kn are unique cause C is a basis (fortunately)

#

it's not like you can get two representations for the same vector given a basis

#

right

#

so what they're doing in your solution is strictly applying the definition you gave

#

looking at the image of each basis vector of B

#

getting the coefficients of these images in basis B (that's easy)

#

and writing that in the expected format of a transformation matrix

#

@oblique rover

oblique rover
oblique rover
oblique rover
sullen island
#

I'm just using fancy/overloaded words

#

@oblique rover

oblique rover
#

ah alright i think i get it now

#

buuut xd

oblique rover
sullen island
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explaining what v_i is in f(v_i)

oblique rover
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ahh alright i understand the whole thing now

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thank you very much my man you are a saviour

oblique rover
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but how do i find this

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basis are

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i want to find how much -1,0,1 in in $\begin{pmatrix}1&0&0\0&1&0\0&0&1 \end{pmatrix}$?

woven radishBOT
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Slowaq

oblique rover
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@sullen island

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$P^3(x,\mathbb{R})$ is polynomial with maximum degree being 3 if i am not mistaken

woven radishBOT
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Slowaq

devout snowBOT
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@oblique rover Has your question been resolved?

sullen island
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f(1) means, take the polynomial p(x)=1, and compute (p(-1), p(0), p(1)), that's the result

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@oblique rover

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f(1) = (1, 1, 1), cause p(x) = 1 always evaluates to 1 no matter the input

oblique rover
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ah alright got it thx

devout snowBOT
#

@oblique rover Has your question been resolved?

devout snowBOT
#
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#
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fading leaf
#

During student council elections, you had to vote for 2 of the 3 candidates. After the results were counted, the votes were the following:

  • Student A - 236 votes
  • Student B - 184 votes
  • Student C - 152 votes
    How many people voted in total? (Assuming each person picked 2 candidates)
    How many people voted for Student A and Student C simultaneously?
neat solstice
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say 10 people vote for 2 candidates each
then we will get 20 votes in total right?

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let's say the votes are: 3,7,10 so total votes are 20. we can deduce that 10 people voted

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we can do the same here

fading leaf
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So (152+184+236) / 2

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Right?

neat solstice
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šŸ‘

fading leaf
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Awesome.

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What about the 2nd part, that seems more tricky to me.

neat solstice
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hmm

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indeed, tricky

fading leaf
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this is 9th grade math by the way

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why do they make this so hard.

neat solstice
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ahhhhhh

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i got it

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we have to make one implication

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someone cant vote for A twice for example

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if someone votes for A and C. that means they did not vote for B right?

fading leaf
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Right.

neat solstice
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so the number of people voting for A and C at the same time
is the same number of people not voting for B

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the number of people not voting B is the number of votes minus the number of people voting B

fading leaf
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388

neat solstice
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correct

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but not the end result

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that is the number of votes

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now we want to get the number of people

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and we already know how to do that šŸ™‚

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number of people = Votes/2

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so 388/2

fading leaf
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194

neat solstice
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šŸ‘

fading leaf
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Wait, but, how could 194 people vote for a and c simultaneously

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If c only has a total of 152 votes

neat solstice
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oh true

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hmm

fading leaf
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Any maybe someone voted c and b as well

neat solstice
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ah i think i got it now

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Here, I fixed my statement:

so the number of people voting for A and C at the same time
is the same number of people not voting for B
the number of people not voting B is the number of voters minus the number of people voting B

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B got 184 votes

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so 184 people voted for B

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286 people voted

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so 286-184 people did not vote for B and thus voted for A and C

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that makes 102

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sry for the confusion before

fading leaf
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No problem.

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Are you sure its correct?

neat solstice
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pretty sure, yes

fading leaf
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because for some reason, this question really makes you doubt your confidence lol

neat solstice
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primarily, it makes me realise it's late haha

fading leaf
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yes, I see now.

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Alright.

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I guess I’ll close it now. Thanks for the help, you made my evening way more nicer.

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.close

devout snowBOT
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Channel closed

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neat solstice
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that is nice to hear šŸ™‚

fading leaf
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Cheers!

devout snowBOT
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dusty dust
devout snowBOT
dusty dust
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anyone understand

wraith horizon
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sure, what's the problem

dusty dust
wraith horizon
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!status

devout snowBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
dusty dust
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so i understand the lesson in general but i don’t understand this question cuz of the 4x^2 one

wraith horizon
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ah okay

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so you can factor the 4x^2 thing and one of those factors should cancel out with the top to make it cleaner

dusty dust
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I’d like to combine the top then combine the bottom
Normally when i find something like 4x^2 i usually do Mode 5,3 on my calculator yet i can’t do it this time due to the 4

wraith horizon
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you can at least make it 4(stuff)?

dusty dust
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or i don’t think it does

dusty dust
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so it could be

wraith horizon
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that at least gets rid of some things

dusty dust
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-2 and +1

wraith horizon
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yep

dusty dust
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gets rid of x+1

wraith horizon
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looks like it gets rid of a lot of things, that's nice

dusty dust
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and then it’s 4/ 2x (4)(x-2)

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now what could we do?

wraith horizon
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well I'm seeing at least 1 common factor on top and bottom šŸ˜›

dusty dust
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OH LOL

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okay so we can get rid of the 4’s

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aaaand so it’ll be
1/2x(x-2)

wraith horizon
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looking good

dusty dust
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wooohooooo it’s rit

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thank uuu šŸ™

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how to end ticket i forgor

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/end

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/close

wraith horizon
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.close

dusty dust
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.close

wraith horizon
#

oop I can't do it

devout snowBOT
#
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dusty dust
devout snowBOT
wraith horizon
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sure, go for it

dusty dust
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what if i got smth to factorize that doesn’t have a least common factor, something like 3x^2+8x+7?

wraith horizon
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you can try to factorise it by hand

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or if you're really stuck, reach for the quadratic formula

dusty dust
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oh so there’s no way to do it using a calculator?

wraith horizon
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not...easily

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(ax +b)(cx + d) = acx^2 + (bc+ad)x + bd
ac = 3
bc+ad = 8
bd=7

obv. b d are 7 and 1, and a c are 3 and 1 which means...uhh...yeah I don't think this has real solutions because you can't get that middle bit to work

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if you have x^2 + bx + c it's a boatload easier to hand-factorise

smoky nimbus
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You can check if it's factorable over reals using the discriminant first

wraith horizon
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duh, of course

dusty dust
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this was my teacher’s method but i don’t understand why it doesn’t work and gives me the same answer as my calc

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there’s supposed to be a 4 in front of the two parentheses

dusty dust
wraith horizon
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quadratic formula I guess

dusty dust
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alright thank youu

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i’m assuming the way my teacher taught it isn’t very conventional 😭

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closing ticket now tysm for help :D

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.close

devout snowBOT
#
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