#help-27
1 messages · Page 131 of 1
If I were doing homework (in undergrad) and wanted to use pi in this way, would I need to specify it or is it obvious/irrelevant? I guess it only really matters when you actually care about the numbers.
If you use pi to mean 360º, people will assume you made a mistake
Just write "2pi" every time you want to do that instead
Or use another letter, and specify at the beginning that it's equal to 2pi
I mean it's all just symbols there's no problem with doing anything as long as your assumptions are consistent with the actual circle.
I could define my own constant 10*circumference/radius, and call it WKSODKGM. nobody would care, it's just like assigning a value to variable.
Just make sure to not use already used symbols
And mention, if you're defining something which is not conventional
At the start of your homework problem or whatever
Will do. From the wikipedia article, I really like the pi symbol with 3 legs. I assume it's not common though.
If that helps you at all
Yeah, all of this helps.
But just as clarification to the pi = 3.14 (diameter:circumference). When we're working with radians and degrees, pi becomes a half turn. Does pi stop representing the ratio of a diameter to its circumference in the case of unit circles?
I think tau (τ) is the most popular alternative nowadays
No, the diameter of a unit circle is 2
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! What the hell am I doing here?
@restive river Has your question been resolved?
We first factor out the leading coefficient from the first two terms
So in a quadratic equation $y = ax^2 + bx + c$
USS-Enterprise
We get $y = a \cdot (x^2 + \frac{b}{a}x) + c$
USS-Enterprise
Then you take half of b/a, square that and add it inside the parantheses, then substract what you get times a from the whole thing
So the expression remains equalivalent to the previous. If we add 2 inside the parantheses and a = 3, then after distributing a through the parantheses we have 6, but we also have to substract 2 times a (3) from the whole thing so it is equivalent to the previous expression
After you do that you are in the form of $a^2 \pm 2ab + b^2$
USS-Enterprise
(inside the parantheses)
@restive river Has your question been resolved?
@restive river Has your question been resolved?
@restive river Has your question been resolved?
@restive river Has your question been resolved?
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could someone please explain what this problem means by find polynomial s(n)
Find s(1), s(2), s(3)
And then find a pattern for general s(n)
then from that i create a polynomial?
oh is this like a recursion defintion or something?
oh ok
It could be recursion, but that's irrelevant
ic ic
so i just need to find the first few values using the formula of the summand
then find the pattern
and build a polynomial
then prove by induction
that my polynomial works for any value of n
.close
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Ik all the circle theorems and stuff
but i dont really understand the question i think
bc if the angle in segment FJ is 84
cant you just do 180-84
and get the degree of HKJ
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can you do this without manually changing the denominator
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How can I prove that an affine transformation of a polyhedron is still a polyhedron? For instance, in attempting to demonstrate that both A(P) and $A^{-1}(Q)$ are polyhedra, I tried to show that the mapping between them preserves the inequality constraints. However, I encountered difficulties in doing so, even when following the provided hint
toitenlanhat
@rough talon Has your question been resolved?
<@&286206848099549185>
the hint means that you can always write a polyhedron as A(x,y)<b.
do you know Fourier-motzkin?
that is the original statement of the hint
thanks but how can I prove the statement with the hint
and also how to apply it to prove the preimage of a polyhedron is also a polyhedron
if P is a polyhedron that write it as (x,w) that Px+Qw<c for some w in R^m. when you transform x into Ax you just need to show still exist some w which satisfy P(Ax)+Qw<c
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can someone verify that my power series representation is correct?
@unkempt grotto Has your question been resolved?
,w power series 1/(8+x^3)
@unkempt grotto Has your question been resolved?
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$\int_{ }^{ }e^{\left(3x-2\right)}dx$ need help evaluating this
water beam
do i use exponent laws or something
and then do
e^3x/e^2?
i know i can u-sub it but
do i have to do something else first
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i keep getting 53
but its not even the option
s
am i ryt
and is this jus wrong
😀
you're right
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Hey so in the book theres a worder question that goes: "A number x is equal to its own square minus 42. Find two possible values for x." and im wondering how to do this i think they mean this type of formula but im not sure, much appreciated.
try just interpret it as its stated
"a number x is equal" x=
"to its own square" x=x^2
"minus 42" x=x^2-42
which does get to this form, but the a is unnecessary
hmm ok
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COMBINATORICS:
On two sides of a regular playing cube you write 0, on two sides 2, on two sides 4. We roll it 5 times
1)How many combination you can make
2)How many combination are there, where the sum is 10
the first is $3^5$, it was not hard
Daniel
in the second, i wrote up the numbers needed to be rolled for 10
4+4+2+0+0 (y possibilities)
4+2+2+2+0 (x possibilities)
2+2+2+2+2 (1)
i wouldn't go for 3^5
i don't know how can i calc the first two
for each number u can roll its a 1/3 chance
okay
u sure
but thats for only 1 of the sums that make 10
okay, hear me out
im never sure i just think
i need every possible ways, i can roll 10 with rollin the dice five times
so roll1+roll2+...+roll5 = 10
why 5 times
You're treating 00222 and 20202 as seperate cases by doing this
In short you're permuting them as well
They aren't yeah
I'm saying your first answer is incorrect as well
So did this person
Hungary advanced level survey
let me translate
Since there are three different types of
numbers (0; 2; 4), the ordered five rolls
5^3 = 243.
számötös means you roll the dice 5 times, and the 5 number you get is the számötös
5^3 is not 243
4+2+2+2+0 has 3 repeats, so you divide by 3!
yes
every permutation of 4 2 2 2 0(out of 120) appears 6 times, so you divide by 6, and there's 20 different permutations that correspond to 4+2+2+2+0
that's how it works yeah
@steel marlin Has your question been resolved?
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Hi
hi?
Approximate the derivative of F at the point X zero using the slope of the tangent line at the point P(x0/f(x0)). Thats the task. So the slope is just one? What would it look like if I wrote it down in limes?
It actually seems lile P(0.5/0.5)
from x_0
maybe you can help
i dont know what 'lim' means
limes
whats that
then here the c and L both would be 0.5
yes
But didn't you know the Limes beforehand?
no
Its popular
i have seen it in a few questions but those questions are from future chapters which i have not been taught
Me too but I decided to go forward because the school do like boring stuff
cant find it
What
the questions
ah
in my country the students drop from school to study for entrance exams
Where are you from
india
I see
the difference in stuff they teach in school and the level of entrance exam is high
i see
which country are u from
germany
oh
jep
whats that
ohh
what does the symbol after the exponential mean
imma ask this in help
okey 👍
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In an equilateral triangle ABC there is a point P in its inner region, if the angle of PAC= x, the angle of PCA=2x and the angle of CBP=3x, what is the value of x?
@celest ivy Has your question been resolved?
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✅
!status
how much is x+2x+3x?
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
I dont think that is the graph
I'm at 2
I did this btw
here's the letters
yeah but PAC is not the same as PCA or ACP so you cant say the 3x is at CPA
right
I just don't know if I did it right there or if there is something I'm missing
yes, that is what is in the picture
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A triangle has a base length of 2x cm and a height of (x-3) cm. If its area is 18 cm^2, calculate its height and base length. I got x=-3 and x=6. The correct answer tho is x=3 and x=12
why would the rhs be 20
area = bh/2
ik
what are you talking about
i got the same answer
maybe its misprint
wdym by next question
wolfram alpha says x=4 -or+ sqrt{26}
theres 2 questions thats pretty much the same
could u show the question
the one we just did was 2x(x-3)=18 and the other one is 2x(x-8)=20
alright 1 sec
q 5 and 6
.rotate
here for q 5
whats the answer for 6 given in book
20 and 2
howwwwww
lol
i mean my answers are one is halved and another is the wrong sign
u sure
yep
whats the answer for 7 thats given
6 and 5
its my own math book
maybe we should have a 3rd opinion
also the book is manufactured by cambridge
u should search for online solutions and check from there
are u multiplying the area by 2 or not
what
no why
its a triangle if any thing
but we dont care about area only about length and base
oh you mean
...
nope
doesent work
yeah got no clue
@restive river Has your question been resolved?
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Help
I solved it to this but get tan 270s and I can’t solve it from there
,rotate
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@heavy sail Has your question been resolved?
cot[(3π/2)-x]=tanx
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use the definition of logarithm
yes
multiply both sides by (t-1) to start
you should get t = (t-1)e^2, and so t = e^2t - e^2
now bring everything which involves t on one side, and the constant on the other side
missed a negative
yes
dont forget the negative
answer should be t = -e^2/(1-e^2)
or t = e^2/(e^2-1) both are equivalent
Factored out the negative on the denominator
just multiply top and bottom by -1
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It looks nicely, you know how to deal with LaTeX well haha
thanks 😭
is it correct?
im learning latex still
started last month
seems so
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I don’t get why they’ve found DetB1 like that
Expanded it across the last column
Wow i would have not seen that thanks
But why have they used the last column
Does it have to be done that way
I thought u can pick any row or column with a zero and expand it across that
Assumedly they thought it would be less pain, you can pick any row or column that you'd like, though I guess the second column would have been alright as well
Ah i see, so whatever method u choose it’ll give the same determinant?
It would, if you do all the steps right (of course as per above, some are more error prone than others!)
All good 
.close
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In an equilateral triangle ABC there is a point P in its inner region, if the angle of PAC= x, the angle of PCA=2x and the angle of CBP=3x, what is the value of x?
just got it, is it 6? can someone confirm it
can you show your work
sorry if you don't understand quite well, but by an inscribable quadrilateral you can equal 30-x with 4x so you get 5x equals 30, and thus equals 6, but I don't know if there is something I'm missing because there is no option for 6 in the problem
you think so?
ya
if so, there is another method to solve it?
can you show me, cause it took me a while to solve it with congruence
you know the ABC is equilateral
so as you said
if you add a point P
all forming triangles are congruent
you can
No you cant
because the triangle is equilateral
The triangle is equlateral
yes
But the point is in its region
anywhere
not in the barycenter exactly
true
and there are angles that are 3x, 2x and x that make the point P be in a place inside the triangle
thus not making it necessarily the barycenter
assuming that is the barycenter would make pointless giving the angles
well, that is what I think
don't worry, I thought about that too while solving the problem lol
i think i got it
is there another way?
the question didnt say: there is a point anywhere in its inner region
the question said: there is a point in its inner region
lets assume the first state first
as it's more generalized
if it's anywhere, the points would not be congruent
yeah, that is true
if P is in the center, all angles would be equally distributed
well, that is if it were :/
yeah, but could not be the case also because PAC, PCA and CBP are declared different in the question
yeah, that is also said in the question
so, based on this, we already know that not all the positions matches the criteria
ig
if we move P to A, then angles PAC and PCA would increase
meaning it cant be, because x cant increase inverselly to PCB,
it would be PAC ^^^ PCA ^^ PCB ^
and the problem is the other way around
but it doesnt matter
what matter is
its just another point of view, yes
there is a point, a unique solution, that matches the question
its not anywhere
so the calculus have to be made based on the angles
not on the point
yeah, because the problem says the angles are in A B and C, not in the point itself
the only condition where it is true is when P is the incenter
why?
because all the angles will intersect at P
which means that they turn into 'external angles', that sum into 360
x + 2x + 3x = 360
x = 60
and if P is not the incenter
um
PAC would be greater than 60 degrees
and x would increase
desistabilizing
the thing
P wouldn't be the incenter
because there arent any bisectors there
the incenter is the meeting point of the bisectors of the angles in the triangle
yes
which P isn't
why
no its not
because if you say that it could be the incenter
by just saying so that is inside the triangle
then it could be the circumcenter
or other points that are known
it cant be
Lets just keep the problem as a rule and just don't assume anything, because if we assume then we don't have a real proof (by demonstration) that something is something if the problem doesn't say so
here I did the graph a bit better
but you agree that the incenter works?
just you dont think its the only solution?
it lacks proof
in this aspect i kinda agree
Incenter wont work because if x equals 60, and 3x equals 180, meaning it cant be inside the triangle
,rotate
see 3x there?
it cant be 60 :/
(sorry btw, I couldn't graph 3x according to 2x, 3x is a bit smaller, but you get the point)
but the angles arent inside the triangle
they are external angles
you cant say that these angles are outside if the problem itself says that they are inside
that would be contradictory to the problem statement
which is:
yeah 😅
now i'm doing with paper and pen instead of eyeballing it
it's way harder than i thought
you already did the calc for all the P angles didnt you?
Yes I did
but if x equals 6, then there is no option for 6 in the problem
like, a)20 b)15 c)12 d)4 e)8
got something?
i got the 15 but i'm pretty sure it's wrong
i'll remake
because i tried with another inner triangle and the results didnt match
I also tried 15, but the lower ones seem to be more matching than higher than 10
but even so, there is no other way getting around those numbers
I have it on paper here
its printed
so, there is no way I got it wrong lol
why it doesnt work
why though?
if you don't have it could you describe it please
welp
because the P would be in the edge of the A-B
and theres no way PAC
would be 20 degrees
yeah, the graph would be almost absurd
i'm just doing like you
i'm getting the values for a, inv a, b, inv b, c, inv c
all ps
but im treating the P as y
so when we sum up to 180
i finish with ax+by=?
and i do a system
i tried doing P'
and other stuff
but i dont see
where it applies
to this problem
it justs seems so simple
but it doesnt work
yes, it seems so
but it's so complex when you try to
what about trying to draw equilateral triangles so you can get congruence?
like you did with these triangles?
yes
at the end, we need to use what the problem says, and it says abc is equilateral
so we can put 60-x, 60-2x and 60-3x at the other side of the angle so it sums 60
i dont know, an idea that came to mind
i have to sleep i have exams tomorrow
but cant you use law of sines?
and discover the angles based of the arcsin?
Nope, it has nothing to do with areas
but the lengths of the side are the same
and it doesn't seem to have anything to do with known triangles like 37/53
it'd be 1/sinA = 1/sinB = 1/sinC
even so
wait
I think we could use that
but at the end we would end up getting 6 again I think
cause
wait
yeah
it would end up getting 6 again
6 again?
yes
I remember doing it with a friend last time
with trigonometry and we got root5 something
and a known triangle
but it ended up being 6 again
yeah we got 18/72
sin3x equals (squared root5-1)/4
are you sure this d is 60?
let me see
because u can law of sines with 2x
and equalize it
no wait you can?
i think you cant
yes im pretty sure it is 60
I don't think you can
i forgor the big slicing line right there
ok so
this is the original graph
I found my pen somewhere so I drew this
if we fill angles
we get this am I right
yes
ok
so here
I drew a parallel to AC
like this
by those 2 lines I say that is parallel
and I make it equal to 2x
so both sides are equal too
get it?
well, I guess we could call it a day and see if someone else tries, I don't want to interfere if you are sleepy and your exams are tomorrow too
just finish your train of thought
ok
here we get a congruence by 60-2x
You can see the line and the dot are with 60-2x
so the third angle must be 3x by congruence
thus making the triangle inside an isoceles
bro this is turning into art fr
what is this
I'm going to explain
We draw an equilateral by the angle A
we know that the angle A has a 60-2x
so after we drawn an equilaterall over there, we can say there is an angle 2x because if we add 2x with 60-2x we get 60
the 3 sides are equal, due to congruence
so we draw again a triangle AEB congruent to APC
so we can say that the angle at EAB is 2x and EBA equals x
with that we can now work with something
now here
We drew a line at EP
Why?, so we can say that the triangle EPA has a circumcenter (I know it doesn't seem so) and it's the point F
why is it on f already
i forgor D
anyways
EFP is an isoceles
so we have two angles that are equal, I called them beta
oh and
the angle at APF is x, why? because FP is parallel to AC
so x goes to FPA too
but where are you in the grind
most of the problems are like these so, I'm worried if I got it wrong
ok here, I erased F because it just wouldn't be readable
I called y the angle at EFP
we have y that equals 120+2x
and the angle at BPF equals 6x-60
because of the equilateral triangle ABC
so if we sum the angles EBP and EFP we see that
wait I forgot a step
I say to sum those angles because
EBPF is a quadrilateral
so, by adding those angles, we have that 120+2x plus 60-2x
equals 180
surprise, it is complementary, so EBPF is inscriptible
Now we need to find beta
so we can do beta=4x
its just homework, he just wants the graph and some basic questions lol
what is the graph
in my country we just send it checklisted and it's good enough for them
we find beta by using the y we found before, 120+2x plus 2beta equals 180 and we find that beta equals 30-x
wow, really?
in these questions i usually try the answers to see which work because we dumb
ya
30-x equals 4x so x equals 6
and that is why I say that there is no option for x in my paper sheet
that would be really helpful for me lol
you could write an article about this and expect a counterarticle
our education aint that good either lol
so it sums up
but it's really impressive bro
u know a lot of stuff
it isn't like that
In our school teachers like to hand us these problems
so I just got worried because there wasn't option
anyways, I think it's ok the procedure right?
Not really though
in my high school there was these challenge problems but it wasnt nearly like that
just involved some researching and applying some formulas
this is good
omg
so, I need to finish for tomorrow and I was just worried about this and coulnd't go for other problems lol
if i were you i'd leave it as it is
it's not right but it shows you have the knowledge
it's better to solve the rest
Well, I guess I'll do so, but I think you are right in something, it's kind of overcomplicated
yes it most definitely is
and i gotta sleep lol
maybe it's different because Im at school
don't worry, its just something that bothered me and maybe doing the procedure again made me a bit more confident about it
its just the world
i was supposed to study the same thing when i was at school
instead i learnt not even the basics from them
only in the first year of undergrad i realized and had to catch up
I'm at south america so, I need to practice like this for the exams to be approved and sent into uni, not having money is a problem
me too lmao
it really seems like a struggle
where are you from
Peru
brazil
not too far huh
yea
Im really trying to get into first places though, so maybe a bit more effort will do
here is the same, but the exams is 'easy'
basic questions
it's just exhausting
good luck for you!!!!
most of the problems at the exam for the uni (to be inside the uni and accepted) are like that one
so i need to familiarize with them
i almost went to argentina from these first places
i got first 2x from an astrophysics comp from brazil
it's really worth to put effort into these
opens a lot of doors
must be like that
the uni i'm at today is possible because of this
that seems like a great achievement
I'm at the last grade of school so, I don't have too much time to practice these subjects
I wasted too much time before
it's mostly heavy practice
brazilians here spend as much as 5 years just studying to get into med
here it's almost 8-10 years depending on the uni
heavy lifting everywhere innit
just like that, even so, if you want to get into med you need first places (national uni)
and to compete with almost 4000 people prepared
is tough
really seems to be
anyways, I'm not going to med, I'm going to engineering
which one?
systems or informatic
cool
really demanded career
wow, similar to pure maths?
in the beginning yes
but as you progress
it starts being mostly applications of the math
in the computer
its called numerical analysis in fancy terms
but it's just basicaly coding math
i'd really like to enter in computational physics
but i didnt pass :(
well, it seems like subjects and careers there are similar to here
although we don't have computational mathemathics
it must have been lol
but by now I'm just doing this to enter to the uni
I don't know why, but they needed to separate the entrance exams (to be accepted into uni) in 3
really? what a mess, I think that one exam could do the thing and 2 is more than enough
eh specifically here i think it's better
because the education here is a mess
and the exam is 180 questions that divided in 2 that 10% can do well
seems like a good idea there
0.1% well enough to enter in public uni
do you already have specialized high school?
like u can choose your subjects and stuff
they will add this thing too
Yes, I'm at one
but I don't choose my subjects
they choose it for me depending on the public uni I go
In my country this is the only uni that has prestige enough to be called the uni every engineer needs to go to be a "real engineer" and is the only one that does this with the exams
in brazil they will allow you to substitute subjects that you dont like to more in depth ones
the dumbs will get more dumber
because you can substitute like high school math for like
arts
wtf is this
i mean not entirely substitute
but 50% of it
gone for something useless
bullshit country
Lol, it seems similar here
Public schools are something really different to a private one
They have religion, arts, dancing, and these subjects that don't really add something to your academic knowledge
here you can do well enough if you go to a public uni, a private one hmmmmmmmmmmmmmm it's tougher
but there's one public uni that if you enter
your life is like
DONE
you can rest
usp yeah?
yep
it's on another level
but it's like
insane to enter there
on 180 you have to get 160 right minimum to get in a competent course
and there are impossible questions
In here it's completely the opposite lmao
woah, here our final result is by 180 too but you need at least 90 to enter to a career and 145 to enter to a decent one
same to here more or less
maybe 90 is a stretch
100
but its more or less the same
well, that is UNI (its called UNI the uni lmao) other unis are different, they just have 100 questions and you just enter if you do 50% or more
are the questions hard?
like this aberration you showed me
due to the exam being 3 hours, and 3 exams being separated into 100 40 and 40 questions
first one being general knowledge (Mathematical reasoning, reading, history, etc) and the other 2 being maths and science
3 hours for 40 questions
it says by itself how hard each one is
for the whole 180?
no
splitted in 2 days
first day 90 questions + essay
but these 90 questions
are language and social
the texts are HUGE
and you have 2m30s to answer
2nd day
science and math
more 5 hours
3min question
the questions are not hard
but they are long
like
compare these 5 products
and tell which one is the more profitable
2 you can discard
but the other 3 you have to make a lot of calc
and its 2% margin
at max
they must be to choose an option right?
its just tiddiest
yes
its not hard, we dumb
i just wish we had a little bit more difficult questions
and a little bit more time to answer
because this doesnt select the more intelligent
it selects the one who did more of this shit
so they have a preference for social and reading subjects like literature and others?
not preference
by faaaaar you gain the most points out of math and essay
the way i put it
they have a preference over quantity
over difficulty
the more questions you can pull off
before burning out
the better
woah, here they do more difficult questions that each time are new ones, I think that one time it came about universal gravitation
for perspective, the exam of the first day this year had 20 pages
plus a essay
that u had to manage to do in 5 hours
30 lines
demonstrating the earth's gravitation and with that calculating how long will an object fall on another planet with x gravitation relative to the earth's one, i dont remember quite well
must be tough to be 5 hours into something constantly
what a nightmare
by now Im studying at school and an "academy" they call it here, you prepare yourself there so you can do well in the exam
that's cool
i prefer this over what we have in there
the physics question we use the same formulas
but like
we have to just plug it there
but the numbers are like
7,14
5,6
3,46
these type of numbers
and u have to nail it
in under 3min
its really stressful
thank god ours has rounded numbers
only pi here is rounded
lmao
tbh, in our exam, the hardest subject is just geometry
i really felt it
that is why I put some effort into it
yeah lol
no joke, there are questions harder than the one I showed
And they expect you to do that in less than 5 min
omg
math here is kinda weird
mostly is kinda fine
like
automatic mode
repeat
but from nothing there is an impossible question
about recursion
or idk planification of 4d objects
its like that
woah, even I haven't seen that ever in the exams
these insanely hard questions are generally about logic
so they dont need you do understand the topic
they want that you figure it out
but i'll not figure this bullshit in 3min
fuck you
true
in exams you are rushing with time, there is basically no time to loose at even the easiest question
yes
i made it 2 times, i get insanely frustrated because i feel there is like a clock in my head
like speedrunning
specially in math
and i feel the time is going to end at any moment
i dont like these
timing questions while doing calculations is just a mess
i dont time it, i generally feel that i wasted a bunch of time yk?
like when you got stuck doing multis thinking
yes
this stresses me out so much
20 seconds feel like 1 min
the more seconds pass the more you feel like you are wasting
right now Im doing this school and the preparation so I hope this helps me with the speed
do you ever feel like you have your day full?