help-27

[devout snow]

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[terse bolt]

Im solving a series differential equation, how would I check my answer?

[devout snow]

@terse bolt Has your question been resolved?

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[jaunty orbit]

Hello help in French please

[sullen island]

jsuis là

[jaunty orbit]

Question ; rappeler la structure d’espace vectoriel réel de M2 (R) et montrer qu’il est de dimensions fini.

[jaunty orbit]

Ah mon sauveur 😂

[jaunty orbit]

Faut qu’on m’explique ça vrm Mmdrr

[sullen island]

rappeler la structure d’espace vectoriel réel de M2 (R)

1. c'est quoi les objets dans M2 (R)
2. c'est quoi l'addition et la multiplication par un scalaire avec M2 (R)

@jaunty orbit

[jaunty orbit]

Jsuis la jsuis la

J’essayais de comprendre l’exercice mmdrr

M2(R) c’était quoi déjà ..

C’est la matrice carré ?

[sullen island]

t'as ça dans ton cours ou pas ?

[jaunty orbit]

Attend

[sullen island]

ça serait bizarre qu'on te l'aie jamais montré s'ils te disent "Rappeler la structure..."

[jaunty orbit]

Et je te jure son cours a elle il ressemble a rien

[sullen island]

ah shit

[jaunty orbit]

Rappel moi la structure stp 😂

[sullen island]

$\mathcal M _2(\mathbb R)$ c'est les matrices carrées $2\times 2$

[woven radish]

aPlatypus

[jaunty orbit]

C’est ça la structure du coup ?

M3(R) serait donc un 3*3

[sullen island]

oui

[sullen island]

faut spécifier les opérations aussi si tu veux être réglo

[jaunty orbit]

Pour répondre à la question je dois dire quoi

[jaunty orbit]

C’est à dire ?

[sullen island]

ça veut dire quoi ajouter deux matrices ?

[jaunty orbit]

Addition

[sullen island]

ça veut dire quoi multiplier une matrice par un nombre ?

[jaunty orbit]

C’est le produit de la matrice par un nombre 🤷🏻‍♀️

[sullen island]

oui mais comment tu le calcules hehe

[jaunty orbit]

Je multiplie tout les coefficients de la matrice par ce nombre non ?

[sullen island]

oui voilà

[jaunty orbit]

Okay ça nous emmène où ces raisonnement du coup ?

[sullen island]

et pour l'addition de deux matrices ?

il y a pas de raisonnement là

[jaunty orbit]

Bah on additionne les coefficients des deux matrices ensemble et ça nous donne une nouvelle matrice ?

[sullen island]

c'est juste définir les objets sur lesquels tu travailles

[jaunty orbit]

Hmm ok ça roule

[sullen island]

yup

bon ok

maintenant dimension finie

[jaunty orbit]

Qu’est ce que c’est Bahaha

[sullen island]

c'est quoi la dimension d'un espace vectoriel ?

[jaunty orbit]

R

Jsp mmmdrr

C’est R^n

Non ?

[sullen island]

c'est ta prof qui fait R on dirait

ok j'dec

[jaunty orbit]

Jpppp mais je te jure

[sullen island]

R^n sa dimension c'est n oui

dim(E) c'est le nombre de paramètres qu'il faut pour décrire tous les éléments de E, pour le dire intuitivement
(E c'est un espace vectoriel)

[jaunty orbit]

D’accord et dimensions finie c’est quoi

[sullen island]

que tu peux le décrire avec un nombre fini de paramètres

par exemple R^n (n c'est un entier positif) c'est un espace de dimension finie

dim(R^n) = n, t'as besoin de n paramètres

il y a des espaces vectoriels qui sont pas de dimension finie (sinon on se casserait pas le cul à avoir cette notion lol)

[jaunty orbit]

Mmmdrr je vous je vois

*je vois

[sullen island]

mais bon là c'était juste pour donner une idée de ce que c'est la dimension (l'idée qu'on se fait un peu tous, on dit bien 2D, 3D, etc.. dans la vie de tous les jours)

[jaunty orbit]

Oui

[sullen island]

et j'ai pas tellement envie de te faire un cours sur la dimension, les bases, les familles indépendantes, génératrices, tout le tralala, maintenant tout de suite

donc je vais te suggérer une bonne série de vidéos vu que ta prof sait pas trop faire son taf

[jaunty orbit]

Oui je vois c’est pour ça je pense je vais voir des vidéos sur les dimensions parce que là jsuis perdu

Mmmdrr oui on a pensé à la mm chose

T’as des vidéo à me suggérer

Mais des trucs vraiment compréhensible

[sullen island]

https://www.youtube.com/playlist?list=PLE8WtfrsTAimNyRsaB2kLZqKvykuliUAr

ce gars il fait des vidéos très bien

[jaunty orbit]

Je vais voir mercii

[devout snow]

@jaunty orbit Has your question been resolved?

[devout snow]

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[storm igloo]

how do i get started/what formula am i supposed to use (find x)

[pseudo basin]

do you know the formula for the area of a trapezoid

[storm igloo]

oh

thanks

.close

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[shut vapor]

Hi I was wondering if I could get help with this, i've already got the derivative but I don't know where to go from here

[cold bough]

write down the derivative you get

[shut vapor]

I end up getting:
mx^m-1(1-x)^n+x[n(1-x)^n-1(-1)]

[cold bough]

$mx^{m-1}(1-x)^n-nx^m(1-x)^{n-1}$

[shut vapor]

Something like this

yeah

the x following the plus is to the power of M

i mistexted it

[woven radish]

everg

[cold bough]

ok so...

you have to check that there is a zero in [0,1]

[shut vapor]

yeah, which to do that I would be able to set the derivative function = to zero right?

[cold bough]

yes in that point

f'(0)=?

[shut vapor]

All i get at those points turns out to be my endpoints 0 and 1

unless I managed to do it wrong

[cold bough]

assume m>=n

$mx^{m-1}(1-x)^n-nx^m(1-x)^{n-1}=x^{m-1}(1-x)^{n-1}(m(1-x)-nx)$

right?

[woven radish]

everg

[cold bough]

$m(1-x)-nx=m-(n+m)x=\iff 0<x=\frac{m}{n+m}<1$ here's your zero 😉

[woven radish]

everg

[shut vapor]

WAIT WHAAA

okay

[cold bough]

gg

[shut vapor]

the only part im confused on is how you manage to change the form of the equation

er how it looks h

[shut vapor]

here

[cold bough]

I group the big common part x^k(1-x)^h

[shut vapor]

okay

[cold bough]

it was useless because it had root only in 0 and 1....but we searched a root inside this interval

so i group it and study what i get

oss: there is only one zero

inside

[shut vapor]

mmm

i kind of get it

[cold bough]

because you are a good student 😉

[shut vapor]

W teacher though for real

tysm!!

[cold bough]

gg

[shut vapor]

.close

[devout snow]

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[devout snow]

@restive river Has your question been resolved?

[devout snow]

@restive river Has your question been resolved?

[devout snow]

@restive river Has your question been resolved?

[devout snow]

@restive river Has your question been resolved?

[glass hatch]

what is calculatus

cactus

[timid oar]

try this

[devout snow]

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[trim kraken]

ayo

[trim kraken]

how to do this

[pseudo basin]

kirchoff law shit

[trim kraken]

bro what

[pseudo basin]

or simplify series/parallel connections

[trim kraken]

it doesnt apply

[pseudo basin]

also don't call me bro.

[trim kraken]

for this

mb

what do i call u

[pseudo basin]

i have a name (Ann)

that should work just fine

[trim kraken]

mb ann

[pseudo basin]

anyway what are you talking about with kirchoff's laws being inapplicable

i mean ok w/e like it's probably overkill here

simplify series/parallel connections

[trim kraken]

it workds

ye

so i simplify the two 2 and the 4 on the right

i get 2 in total

[pseudo basin]

6th and 7th resistors become a single 4 Ω, and the 2nd and 3rd become a single 12 Ω, for a start.

[pseudo basin]

you get 2Ω resistance between the two rightmost nodes*

[trim kraken]

yep

10 is in series so i think u add 10 and 2

[pseudo basin]

itll be a lot better to actually draw the entire circuit at each simplification stage

but yes R4 is in series with the entire right part of the thing

[trim kraken]

so is r1 no?

[pseudo basin]

no

[trim kraken]

then what is r1

[pseudo basin]

it's in series with a bigger parallel connection

[trim kraken]

are r2and r3 in series

[pseudo basin]

sure they are

[trim kraken]

ok

so

so then u add 4 to 12?

[pseudo basin]

no

again

you are trying to reason through it blind

this will not do

you have to draw the circuit at each stage of simplification

[trim kraken]

k

i got it thx bro

.close

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[trim kraken]

.closed

[devout snow]

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[marsh bone]

$$n^{n^{n^n}} \equiv n^{n^n} \pmod{9}$$

[woven radish]

arjun the learner

[frozen aurora]

solve for n?

[pseudo basin]

!status

[devout snow]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[marsh bone]

1

[marsh bone]

Yes

[pseudo basin]

consider three cases:

• n divisible by 9
• n = 3 or 6 mod 9
• n coprime to 9

actually wait you might want to handle the case n = 1 mod 9 separately

(it is trivial though)

[marsh bone]

Suppose i took n=18

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[deft hearth]

hi may i know how to do this

[devout snow]

@deft hearth Has your question been resolved?

[devout snow]

@deft hearth Has your question been resolved?

[visual hazel]

@deft hearth spm maths?

[deft hearth]

yess

[visual hazel]

damn i took that exam almost 2 years ago, good memories that is

anyways lemme see

[deft hearth]

2021 candidate?

thx

[visual hazel]

yea

[deft hearth]

oh

this question is from mrsm 2021 btw

[visual hazel]

i see

[deft hearth]

maybe uve done this b4

[visual hazel]

ok so do you see the small triangle on the right of the square

[deft hearth]

yes

[visual hazel]

since its an equilateral triangle, one of the angle is 60 degs

[deft hearth]

ooh

ya

i can use trig?

[visual hazel]

yep

[deft hearth]

dang i didnt see that

[visual hazel]

you know the opposite side is 4m

so using trig you can know the hypotenuse and the adjacent side

and the left and right triangles are equal to each other

so you basically know the whole bottom length

Since its equilateral, just multiply that bottom length by 3

[deft hearth]

wait isnt that equal to 1

bc it says perimeter =4

[visual hazel]

oh yeah mb

[deft hearth]

but still icant find the answer

the ans is a

oh i forgot to multiply by 3

thx

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[visual nest]

How do I do this?

[visual nest]

please ping me if you can help me, thankyou!

[sand dove]

is there a link between $0.\dot{7}$ and $0.0\dot{7}$? Maybe a factor between them?

[woven radish]

rafilou2003

[visual nest]

hmm

they both only have 7 recurring?

[sand dove]

yes, but one starts one decimal later...

so maybe 0.7 repeating = ... * 0.07 repeating?

[visual nest]

wait so 0.7 repeating = 7/9 so 0.07 should be

7/90?

[sand dove]

yes

[visual nest]

ok perfect thanks, can I have help with one more. Please?

Thanks a lot @sand dove

[sand dove]

$0.4\dot{7} = ...+...$

[woven radish]

rafilou2003

[visual nest]

0.4 + 0.7 recurring

[visual nest]

am i right?

<@&286206848099549185> :/

[boreal pier]

Hi

So what was 0.07777777

As a fraction

@visual nest

[visual nest]

its 7/90

[boreal pier]

Yes

Now we can agree that 0.47777 =0.4 + 0.077777

Right

?

[visual nest]

yes

[boreal pier]

Now rewrite that using this

[visual nest]

4/90?

[boreal pier]

Close

Here

:

0.47777 = 0.4 + 0.0777777

0.07777 = 7/90

So

0.47777 = 0.4 + 7/90

Does that make sense?

[visual nest]

I dont really understand.

sorry 😐

[boreal pier]

That’s alright

Do u see how 0.47777 = 0.4+7/90

We are just plugging 7/90 for 0.0777

Since they are the same

[visual nest]

yes

[boreal pier]

Great

Now what is 0.4 as a fraction

[visual nest]

4/9

[boreal pier]

Not out of nine

Close

[visual nest]

4/10

[boreal pier]

Yep

So

Now using the earlier equation

Plug in 4/10 for 0.4 since they are the same

If 0.47777=0.4+7/90

And 4/10 = 0.4

What can u plug in for 0.4

[visual nest]

its 0.32222 + 7/90 = 0.4?

[boreal pier]

Basically take 0.4777 = 0.4 + 7/90

But replace 0.4 with 4/10

Because they are the same thing

[visual nest]

yes

[boreal pier]

So you would agree that it would be:

0.477777 = 4/10 + 7/90

Right?

[visual nest]

yeah

[boreal pier]

Now

All we need to add 4/10 + 7/90

Right?

[visual nest]

I urgently have to go tommoroww in like 8 hours or so ill look at the messages sorry

[boreal pier]

Ur fine

Just remember to add 4/10 + 7/90

If u need help

Look up a video abt adding fractions

[visual nest]

thanks a lot ill check it out latr i hve to go urgently thanks

ok

[boreal pier]

🙂

Ok

[visual nest]

thanks a lot

[boreal pier]

Ur welcome

[devout snow]

@visual nest Has your question been resolved?

[devout snow]

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[candid moat]

how do i solve a question like this?

[lavish nimbus]

Solve the integral first.

[candid moat]

how

[jade oak]

I do not think that is solvable with elementary functions

[candid moat]

so yh looked it up but no idea what an erf is

[jade oak]

You should use ftoc

[candid moat]

ah alr

ill try

[jade oak]

It is just a function defined by that integral

[candid moat]

yeah still not too sure

these are my multiple choices

[jade oak]

Ok so you know what ftoc is right

[candid moat]

this right

[jade oak]

That is the “2nd” one I mean the first

$\frac{d}{dx}\int_a^xf(t)dt=f(x)$

[woven radish]

Cure Miracle

[candid moat]

yep did it

thank you

.close

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[normal phoenix]

hello

[normal phoenix]

need help with this question

there are two equal glasses that contain water. in of the glasses there is a rock. the height of the waater in both of the glasses is equal

what will happen if you will add an equal glass of water to each one of them

will the first glass be taller or the second or they will both stay the same height?

[topaz axle]

it will stay equal

just imagine all the water sinks

[normal phoenix]

isnt the rock gonna have some kinda impact on that?

[topaz axle]

the rock doesn't care how much water is below

it would do the same thing, the top part has to look the same

[normal phoenix]

i see

thanks

.close

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[young crane]

What is the reason for changing the subject?

[winter torrent]

you need them to be y = (stuff with x) to do the washer/disk method like that

because y describes the radius of the disk

[young crane]

If the values/bounds were y values would I have to do so?

[winter torrent]

yeah the important part is that you're revolving around the x axis

[young crane]

What if it revolves around y?

[violet wind]

the integrand is pi*R^2

in that instance R would be |x|

so pi*x^2

[young crane]

So when it revolves around y it will be pi*y^2

Around x is pi*x^2

[violet wind]

No

Think about what the radius is when it revolves around the y-axis

[young crane]

the radius is just the function no?

[violet wind]

Nope

The function just tells you what region you're integrating over

you want to "add up" the contribution from every point (x,y) in your region

[devout snow]

@young crane Has your question been resolved?

[young crane]

So around x it will be pi*y^2?

Is this correct? Calculating the area under a curve using the trapezium rule

[devout snow]

@young crane Has your question been resolved?

[young crane]

.close

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[restive river]

you can take the integrla by rewriting sin^5x in terms of a trig identity

do you know what trig identities are?

can you think of a way

to transform

sin^5x

so that

you can u substitution later

and simplify the equation enough

to integrate?

let me know

if you need a little push

nah you dont need that here

use this

sin^5x

take one sin out

sin^4x

sin^4x = (1-cos^2x)^2

so then your equation is

integral of (1-cos^2x)^2 sinx cos^4x dx

and you u sub this

have you never done a problem like this before?

have you learned u subbing?

u substitition

okay

well when you u sub

you usually have to derive it for du and then

you can see what it can cancel out from the equation

for example

if you let u = cosx here

trty

its asking you for coeffients because it wants you to integrate

this is easy

if you'll just take the time to try it

lmk if you get stuck

❤️

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✅

[devout snow]

@tacit agate Has your question been resolved?

[devout snow]

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[mellow mountain]

How does the square root 5 go to 25

[minor timber]

,rotate

[mellow mountain]

h

<@&286206848099549185>

[restive river]

It goed to the 4th root of 25

Because (sqrt(5))^4=(5^(1/2))4=5^2=25

So sqrt(5)=4th root of 25

[mellow mountain]

Oh

Thanks

.close

[devout snow]

Channel closed

Closed by @mellow mountain

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• Show your work, and if possible, explain where you are stuck.
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[random ice]

How can i finish this

[random ice]

Or did i do a mistake somewhere?

I have to use log at the end

Since i cant use a calculator

[modest dagger]

That's 1^x/6^x at the end?

[random ice]

Yes

[modest dagger]

Well a^x/b^x=(a/b)^x is one route

Another is that 1^x is just 1

[random ice]

So (1/6)^x at the right?

[modest dagger]

Yep

[random ice]

And then?

[modest dagger]

This

[random ice]

Yeah but i am not finished yet, am I ?

[modest dagger]

What else do you think you need to do?

You mean after taking the log?

[random ice]

I have the solution from my teacher but I didnt understand

She had like from 1/4 = (1/6)^x

To 4=6^x

[modest dagger]

Oh yeah, that's another way

To do that, multiply both sides by 6^x and 4

Then simplify

Both work

[random ice]

Can you show it in like a $$

[modest dagger]

Yeah

I'll just write it

[random ice]

Thank you

[modest dagger]

Oops accidentally sent a meme lol

This is the first part

[random ice]

Yeah

And the 2nd

[random ice]

Thats complicated

[modest dagger]

But notice another thing you can do is just to take log of both sides at the start of here

[random ice]

How would that look like

[modest dagger]

If you do that you'll get some ugly logs of fractions

[random ice]

Yeah ok then nvm

[modest dagger]

If you do this you do more work up front but get nicer logs at the end.

[random ice]

Yes thats what we have to do

[modest dagger]

Either way after simplifying your answer at the end you'll get the same thing.

[random ice]

We have to use log or lg

[modest dagger]

What is lg to you?

Natural log?

[random ice]

log10 (...)

That 10 is small under the log

[modest dagger]

Ah well it doesn't matter which log you choose much either.

There's a property of logs that let you write any log in terms of any other.

[modest dagger]

Makes sense lg is log base 10

[random ice]

Our teacher explained that log10 is used so much that they used just lg

Just used*

[modest dagger]

Sometimes this changes based on classes and regions. It's kind of a conventions type thing.

[random ice]

Ah ok

[modest dagger]

In computer science often lg means log base 2 lol

[random ice]

Didnt know that

[modest dagger]

Best to just ask when in doubt. But here ur fine your course does lg for log base 10.

[random ice]

Yeah 👍

Wait i have one more question

[modest dagger]

You have this $log_b(a^x)=xlog_b(a)$ no matter what base $b$ you pick.

[woven radish]

DootDooter

[modest dagger]

So to finish out your q you can do whatever log you like unless the question says to use a specific one.

Fwiw I did not check your work for errors.

[random ice]

Why is it x = log base 4 (6)

[modest dagger]

But since your prof got the same thing it seems you did things right.

[random ice]

And not log base 6 (4)

[modest dagger]

I don't know what you mean?

[random ice]

Yeah i think its ok

4 = 6^x right

[modest dagger]

Yeah

[random ice]

So how would you write that in log

x = log ???

[modest dagger]

So your solution says $x=log_{4}(6)$?

[random ice]

Yeah

[woven radish]

DootDooter

[random ice]

Yes

[modest dagger]

I think they might have meant 6

[random ice]

Isnt it $x=log_{6}(4)$

[woven radish]

corazon

[modest dagger]

Pretty sure they meant thay

It's because of this

b here is the base

This property doesn't work if the base and the argument don't match.

Let me write out something

[random ice]

Like isnt it line that

Like

The number thats ^ anything is the base at log

[modest dagger]

You have a problem like the top equation

You're going to log both sides with some log with base c

[random ice]

Too complicated for me lol

[modest dagger]

If c=b then the denominator is just 1

If not then the denominator might not be 1

[modest dagger]

Ah shoot

[random ice]

But thats how it should be right?

[random ice]

We didnt do something like that yet

[modest dagger]

You're doing something like that now lol

[random ice]

Oh

[modest dagger]

Yes this is right but idk what you mean by the number that can be anything

[random ice]

I just mean that a²=b that always the thing with the ² is the base

I cant explain

[modest dagger]

You can pick any base you like, but this specific property applies when the base and the input to the log are the same

Like log_2(5) is not 1 but log_2(2) is 1 for example.

log_6(100000000) is not 1 but log_6(6) is 1

See what I mean?

[random ice]

Lets use this example

It cant be x=log_b (a) right?

Its only x=log_a (b)

[modest dagger]

No this is always true

[random ice]

How is that possible

[modest dagger]

No matter what base you pick you can always apply the log to both sides (so long as the numbers on either side are positive).

Here one sec

[random ice]

So both are correct?

[modest dagger]

All I'm saying is something like this.

If you have an equation, and the values on either side are positive you can take the log of both sides using any base you like

But what you CAN'T do is say log_b(c)=1 unless you know for sure that b=c

This is why I'm saying I think your solution has a typo.

[random ice]

Is this true?

[random ice]

Yeah but a≠b

Like 4=6^x
4≠6

[modest dagger]

Not sure off the top of my head.

[modest dagger]

You see this equation? Take the log of both sides.

Try it with both base 4 and base 6

Solve both for x

In one of them you'll have log_6(6)=1

In the other you'll have log_4(4)=1

In both cases you can still solve for x

[random ice]

Yes but thats not what i meant

I mean this one mom

[modest dagger]

?

[random ice]

Moment

[modest dagger]

I don't know what you're asking.

I'm telling you that I think your solution has an error BECAUSE of the thing I'm pointing out to you.

[random ice]

This cant be right or what do you say

[random ice]

Which one has an error the one above or the bottom one

[random ice]

.

[random ice]

If we have 4=6^x

[modest dagger]

If you do what I'm asking you to do you can check the correct answer in base 6 and base 4

[modest dagger]

.

[modest dagger]

For what it's worth this should usually be false

They are reciprocal of each other by change of base

https://www.chilimath.com/wp-content/uploads/2020/04/the-change-of-base-formula.gif

This is the change of base formula for logs

If you swap the b and the x you flip the fraction here

[modest dagger]

Show your work

[random ice]

Wdym

I put it in the calculator

[modest dagger]

Okay

This doesn't really require a calculator at all.

[modest dagger]

Do this

On paper or some other writing device, by hand

[random ice]

How do i take the log of both sides

Or wdym by take the log of both sides

[modest dagger]

Not sure exactly how to explain that. It's the same idea as adding a number to both sides or multiplying a number on both sides. But in this case you are plugging each side into the log

Since your two numbers on either side of the equal sign are actually equal, then your two log expressions will also be equal.

Like, if you know a=b, then log(a)=log(b)

Going from a=b to log(a)=log(b) is often referred to as "taking the log of both sides" for the equation a=b.

[random ice]

Ah ok i understand

What base do i use if i take log of both sides

[modest dagger]

Do it once with base 6 and once with base 4

[random ice]

You mean like this right

[modest dagger]

Yeah

Oh shit wait

No

Once with each log.

[random ice]

The x has to go ?

[modest dagger]

So, like apply log base 6 to both sides first.

We'll just do base 4 after we sort out base 6

[random ice]

Oh 1 moment

This?

[modest dagger]

Yeah, the bases have to match to apply a log on both sides. For ex 2=2 but log_2(2) and log_2(3) are different numbers.

[modest dagger]

Perfect

Now you say how to bring the x down in front of the log?

[random ice]

X = log_6 (6)

No

[random ice]

Wait yes is that right?

[modest dagger]

In general for any base you can do log_c(a^b)=b log_c(a)

Meaning if you have a single number to a power in the log you can pull out the power and put it in front of the log as multiplication

[random ice]

Ah so xlog_6(6)

[modest dagger]

Yeah you see that equals log_6(4) by your equation right?

[random ice]

Yes

[modest dagger]

Do you know that log_6(6)=1?

[random ice]

Yes

6¹=6

[modest dagger]

Yes perfect. So then you see your equation simplifies to x=log_6(4)

?

[random ice]

Thats what my teacher wrote as the solution

[modest dagger]

Okay, we're not at that yet.

[random ice]

Log_4(6)

[modest dagger]

Your teacher wrote something different.

I'm trying to show you why I think it's not right

For later I think I can do a bot command

[random ice]

So she made a mistake right?

[modest dagger]

,w log_4(6)

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dootdooter

[random ice]

Thats what i am saying aswell

[modest dagger]

,w log_6(4)

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dootdooter

[modest dagger]

You see that these are different numbers?

[random ice]

Yes

[random ice]

.

[modest dagger]

Okay, but there is a second way we can check our work too.

[random ice]

Because imo she did

[modest dagger]

Yeah and we can double check that our work is correct.

Try the same process but take the log base 4 this time

[random ice]

Yes finally i got my validation

[modest dagger]

Yeah yeah but you need to be able to show this yourself.

What if she does not believe you? :p

[modest dagger]

Do this

[random ice]

Ok

[modest dagger]

Yes good

[random ice]

So 1 =xlog_4(6)

[modest dagger]

Perfect yeah, now you can solve this for x.

x=1/log_4(6) yeah?

[random ice]

I dont have to solve x btw

[modest dagger]

Wdym?

[random ice]

Since we arent allowed to use calculatoe in the exam we dont have to solve x

Calculator

[modest dagger]

Hmm well this is till a good way to double check at least

[modest dagger]

Okay so u see how she got the reciprocol of this?

,w 1/log_4(6)

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dootdooter

[random ice]

Whats reciprocol

[modest dagger]

This matches our answer

[modest dagger]

If you have a number like d, the reciprocal of d is 1/d.

[random ice]

Ah ok

[modest dagger]

But it doesn't match he answer

Which makes sense because hers is the reciprocal of ours.

[random ice]

Yeah thank you very much for your help i really appreciate it

[modest dagger]

No problem

[random ice]

,close

[modest dagger]

.close

[devout snow]

Channel closed

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[dry sentinel]

If I have the following afirmation A=BX being A, B and X matrix of order n, if I do some permutation to the following matrix (A|B) and then I set the new matrix as (P|Q), would P=QX?

[dry sentinel]

maybe that's so clear idk how to express it better

[devout snow]

@dry sentinel Has your question been resolved?

[devout snow]

@dry sentinel Has your question been resolved?

Channel closed

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[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[vale magnet]

yo is anyone good wit logs

[lusty sapphire]

[vale magnet]

ive go this question

i got x=exp(a/b x (2ln3/ln7))

shits wrong i know it

<@&286206848099549185>

[supple knot]

!show

[devout snow]

Show your work, and if possible, explain where you are stuck.

[vale magnet]

alr

bascially i tried to expand a and b

to see if i coulld be able to cancel anything out and make it into a quadratic

and then solve it then

but it just put me back to square 1 if that makes sense

i jit confused on how any of this works

[supple knot]

Yes that does seem like going in circles

[vale magnet]

right?

plus bro i cant use a calculator so exact solutions which make it harder

[supple knot]

Try just changing the base 9 to be base 7

[vale magnet]

how

[supple knot]

9^s = 7^t

Solve for t

s=a/b, just leave it as a/b and don't substitute yet

[vale magnet]

yeah i did that

wait

yeah nah still fuckin confused

[supple knot]

About this?

[vale magnet]

yeah

[supple knot]

have you learned logs of bases other than e

[vale magnet]

yeah

we just learnt the basics

[supple knot]

Apply logs to both sides

[vale magnet]

nat logs is something we just got introduced to

[supple knot]

And choose a base that makes it convenient to solve for t

[vale magnet]

log 7

t = log 7 (9^s)

is what ur tryna say right

[supple knot]

Right. Then go back to here

Use 9^s = 7^(log_e(x)),

[vale magnet]

log_e(x) = Log 7 (9^s)

log e (x) = slog7(9)

like what this

[supple knot]

Looks good so far

Keep solving for x

[vale magnet]

lnx = ( s x 2log7(3)

x = exp(s x 2log7(3))

this should be right i think

wait

yeah nah that should be the answer

[devout snow]

@vale magnet Has your question been resolved?

[devout snow]

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[potent whale]

how does it go to 25

[earnest stirrup]

they used lhopital rule here

[potent whale]

ohhh okay

.close

[devout snow]

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[plain turtle]

hi can someone help me do my homework im really confused and i need to turn it in soon

[lusty sapphire]

!status

[devout snow]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[plain turtle]

1

[lusty sapphire]

Start with problem 1. Any ideas how to solve it?

any guesses or intuitions?

[plain turtle]

no idk anything abt this topic i havent been to school

[lusty sapphire]

Congruent polygons means they are the same size and shape

This means the sides TC and TK have the same length

[plain turtle]

congruent?

[lusty sapphire]

Definition of congruent means two shapes that are the same.

[plain turtle]

ohh

so how would i solve it?

[hybrid pond]

what question are u stuck on?

if it's #1 note that tc is congruent to tk

[lusty sapphire]

You're given TC=8x-11 and TK=3x+24 and TC=TK

[lusty sapphire]

Try solving for x

[devout snow]

@plain turtle Has your question been resolved?

[devout snow]

@plain turtle Has your question been resolved?

[devout snow]

Channel closed

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• Show your work, and if possible, explain where you are stuck.
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[bleak jungle]

<@&286206848099549185>

[stray jetty]

…

It says 2+5 is 14 right？

[bleak jungle]

Yes

[stray jetty]

ok

[bleak jungle]

It's 14

[stray jetty]

and ur solving it for something？

[bleak jungle]

For 1 ? 10 = something

[devout snow]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[stray jetty]

no like

are u solving this problem of the week for fun or what

[smoky nimbus]

Also you need to open your own channel, please read #❓how-to-get-help

[smoky nimbus]

Because of this

And it wasn't your channel to begin with

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[plush roost]

I am taking intermediate mathematics at my Community College. I haven't done math in about 4 years, currently 21. I am confused on how the process is to achieve this answer.

I am stuck on how the equation goes from "6(3/4)" or any other of the 3 pictures to "5/2" or "3/2"

[spare zealot]

It looks like in all three cases y is given to be equal to something, but the pictures don't seem to show that

[plush roost]

oh this is a system of equation

mb

[spare zealot]

6y turns into 6(3/4) in the first, which suggest to me that y is at some point given to be equal to 3/4

[plush roost]

so I already solve for y in all those pics, I just took a snap of what the software was telling me

[spare zealot]

Not really a system unless you're working with the same values of x and y, which you're not

These are just substituting a given value of y (or what you solved for y previously) and then solving for x

[plush roost]

correct

[spare zealot]

So it could be systems by substitution but it's only the substitution part of that problem

In the first picture, the 6 is likely distributed to the fraction and then subtracted from both sides to obtain -x

[plush roost]

right but how lol, I asked a lot of my friends and they all explain me it differently but I never get it

like 6(3/4)

goes to 3/2

[spare zealot]

Let's start with $-x + 6(\frac{3}{4}) = 3$

[woven radish]

M. Frost

[spare zealot]

Do you recall what happens when we multiply a fraction by a number?

[plush roost]

the number/1?

so like 6/1?

[spare zealot]

Not quite

Let's convert the fraction to a decimal and see if it'll be more intuitive

$\frac{3}{4} = 0.75$

[woven radish]

M. Frost

[plush roost]

with decimals I am more familiar

for some reason

[spare zealot]

What's 6 * 0.75?

[plush roost]

4.5

[spare zealot]

Correct

Now multiplying a number to a fraction is similar: you just want to multiply the nominator of the fraction by the number

so $6(\frac{3}{4}) = \frac{6 \cdot 3}{4} = \frac{18}{4}$

[woven radish]

M. Frost

[plush roost]

i understand that

[spare zealot]

Which is 9/2, or 4.5

[plush roost]

ok, so.... 9/2 converts to 3/2 how

[spare zealot]

So now we have $-x + \frac{9}{2} = \frac{3}{2}$

[woven radish]

M. Frost

[plush roost]

bc i saw this on google when i searched the same problem

[spare zealot]

How might you change this to get x on its own?

[plush roost]

-9/2

so 3/2-9/2

LCD = 2

3x9?

[spare zealot]

Yup, what is 3/2-9/2?

[plush roost]

-27/2

[spare zealot]

The denominators are the same, so we don't need to multiply anything

[plush roost]

oh

lol

[spare zealot]

We're simply subtracting one from the other

[plush roost]

oh

[spare zealot]

It's essentially like doing 3-9

[plush roost]

-6

so when denominators are the same we just subtract the numerators/

[spare zealot]

Yes

[plush roost]

or add depending the case

[spare zealot]

Same denominators means that you can add and subtract just the numerators without problems

[plush roost]

so -6/2

[spare zealot]

When the denominators are different is when you need to change them up

-6/2 can be simplified

[plush roost]

I saw that the 3 changed to a 3/2, is that because we have the 2 as the lcd?

Im used to multiplying the lcd which is 2 to other terms but that would give me completely something else

the amount of different tasks is immense in math im sorry lol just trying sponge this up lol

[spare zealot]

Oh you could do that, then you're left with whole numbers

I may have mixed you up

But you'd need to multiply the -x by the same LCD

$-x + \frac{9}{2} = \frac{3}{2}$

[woven radish]

M. Frost

[plush roost]

thing is, when i multiply the 6 it becomes 24 then i divide by 4 which brings me back to 6 again lol

[spare zealot]

If you multiply by LCD you can get $-2x + 9 = 3$

[woven radish]

M. Frost

[plush roost]

so multipying by the term dont do nothing

oh

ok further down

[spare zealot]

Once you subtract you get $-2x = -6$

[woven radish]

M. Frost

[spare zealot]

This however does not end up meaning that x = 3/2 so I have no idea where your calculator got 3/2

[plush roost]

it was actually pearson

idk either

anyways, heres a problem that I am currently on, I will do it first and then stop when i need help ->

x cancels out, 2y+2y=4y 0+3 = 3
4y=3
y= 3/4

Input y for any equation
-x +2(3/4) = 0
-x + 6/4 = 0
-x + 3/2 = 0
-x = 0 - 3/2

i assume a 0 + any fraction just equals the fraction?

or - equals negative

[spare zealot]

Yup

[plush roost]

heres a method one of my friends showed me but I have no idea how he got the result prior.

but thats a separate so lets finish the first one

[spare zealot]

For any number x, 0+x=x

[plush roost]

so basically its 3/2

so
x = 3/2
now we need Y
input x
3/2 + 2y = 3
subtract 3/2 from both sides
2y = 3 - 3/2
convert with LCD
2y = 3/2 - 3/2
??

[spare zealot]

Not quite

You can't divide that 3 by 2 without also doing so with everything else in the equation

[plush roost]

so here I would multiply by the lcd

[spare zealot]

So if you turn 3 into 3/2, you also need to divide 2y by 2 and -3/2 by 2

[plush roost]

correct

ok

[spare zealot]

Yeah you could multiply everything by 2 to get rid of the fraction

[plush roost]

ok..
3+4y=6
-3
4y=6-3
4y=3
y=3/4

am i dumb

lol

am I just checking myself rn

[patent marsh]

Not dumb, just learning 🙂

[plush roost]

ty

[spare zealot]

Yeah nobody's dumb in math, we're all just constantly learning new things

[plush roost]

so y= 3/4 x = 3/2

[spare zealot]

,w 3/2 + 2y = 3

[woven radish]

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Requested by lexitorius

[plush roost]

hey look at this

long time no see

[spare zealot]

Looks good to me

[plush roost]

however this was really easy matter of fact

let me go back to one of the problems I had rough time in'

[spare zealot]

Fractions take some getting used to but once you get them down they're pretty easygoing

I prefer them over decimals at this point

[plush roost]

-x + 10(5/4) = 10
10(5)/4 = 50/4
-x + 50/4 = 10
Multiply each term by the LCD
-4x + 50 = 40
subtract 50
-4x = 10
divide by -4
x = -10/4 or -5/2
x = -5/2

how did the picture show me a positive and i got a negative

$-x+18(5/4)=20

aww i cant run that cmd

-x+18(5/4)=20
18(5)/4 = 90/4 -> 45/2
-x + 45/2 = 20
Multiply the LCD
-2x + 45 = 20
-2x = 20 - 45
-2x = -25
x = -25/2
opp i did something wrong

ooo did not multiply the 20 by 2

-2x = 40 - 45
-2x = -5
x = 5/2

LETS GO BBABY

[plush roost]

however I am still confused on the negative there, when in the image it shows a positive

ohhhhhhhh 40-50 = -10 not 10
-4x = -10
x = -10/-4 or 5/2

im genius today

https://tenor.com/view/math-math-meme-einstein-albert-einstein-big-brain-gif-16179237059548673624

im legit just solving my own problems rn

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[pastel veldt]

could anyone mind help walking me through how to do this so i can do the rest ?

[dense jay]

something isnt a function if a single x value corresponds to 2 distinct f(x) values

eg, circle equations arent functions

[pastel veldt]

hm okay

what do you mean 2 distinct F(x) values?

are you talking about the second and third box?

[dense jay]

im speaking generally, if you have a function f(x)
if you input some x and you can get two distinct values back, then that isnt a function

[pastel veldt]

oh i see

[dense jay]

2 distinct values means 2 values that arent the same

[pastel veldt]

so if you put something in x and it comes with 1 value then its a function?

[dense jay]

if only one value corresponds to each x, then yeah

[pastel veldt]

ah ok

so i need to find a value in x ?

so am i right with the X = 0 ?

[dense jay]

another one i missed, it must be defined for every element in its domain

so yeah youre on the right path

[pastel veldt]

okay

so how do i find f() is it the value of 1/x?

[dense jay]

youre looking at x=0

so youre looking at f(0)

which is?

[pastel veldt]

0

[dense jay]

is it?

[pastel veldt]

im not sure... wive been very behind in my class lol

[dense jay]

dw

can you divide by 0?

[pastel veldt]

well no

because itll just be zero

[dense jay]

nono

dividing by 0 doesnt give 0

its undefined

eg

[pastel veldt]

oh

[dense jay]

,calc 5/0

[woven radish]

Result:

Infinity

[dense jay]

well, yeah

undefined

[pastel veldt]

ah i see

okay

so whenever 0 is on the bottom itll be undefined?

[dense jay]

yes

[pastel veldt]

ah okay that makes a bit more sense

so its asking me to put in numbers to make it not be a function correct?

so like with this one i would want x to be something thatll not be a function when sqr?

[misty escarp]

yeah I guess they're asking when it's undefined

[misty escarp]

if with this question they're working within the real numbers when x is less than 0 it would be undefined

[pastel veldt]

so x = 0 with this one too because you cant sqrt 0?

[misty escarp]

you can do sqrt 0

[pastel veldt]

oh

[misty escarp]

0*0 = 0 lol

but less than 0 would be undefined

[pastel veldt]

ah lol fair enough

ah

[misty escarp]

does it say they're working in real numbers?

[pastel veldt]

Why is f not a function from R to R if