#help-27

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outer oasis
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idk how to solve this

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bitter bough
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lets start with the inside function

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what does inverse cot mean?

outer oasis
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angle where cotangent is

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^

bitter bough
outer oasis
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yeah

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i dont know how to get the the angle of a number that isnt on unit circle

bitter bough
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we can rewrite it

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$\cot(\Theta)=-7/6$

woven radishBOT
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Danny
Compile Error! Click the errors reaction for more information.
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outer oasis
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yes

lyric hornet
outer oasis
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yes

lyric hornet
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Let $y=\arccot(x)$

woven radishBOT
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PajamaMamaLlama

lyric hornet
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then $\cot(y)=x$, right?

woven radishBOT
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PajamaMamaLlama

outer oasis
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uhh yes

lyric hornet
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now if you square both sides, what do you get?

outer oasis
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both sides would be squared?

lyric hornet
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$\cot^{2}(y)=x^2$

woven radishBOT
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PajamaMamaLlama

lyric hornet
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ok yeah pretty simply helper_laugh

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but now I wish to use the identity $\csc^2\theta=1+\cot^2\theta$

woven radishBOT
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PajamaMamaLlama

lyric hornet
lyric hornet
outer oasis
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wait wdym to use it

lyric hornet
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so I have cot^2 right?

outer oasis
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yes

lyric hornet
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but I want to get csc^2

lyric hornet
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to use csc^2=cot^2+1?

outer oasis
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do you mean add a 1

lyric hornet
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so now $\csc^2(y)=x^2+1$, right?

woven radishBOT
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PajamaMamaLlama

outer oasis
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yeah

bitter bough
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Lmao this is what happens whne you dont wanna draw right triangles πŸ˜‚ πŸ˜‚ πŸ˜‚

lyric hornet
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what happens if I take the reciprocal of both sides?

lyric hornet
outer oasis
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sin^2(y)

bitter bough
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yeah i can see where you are going

outer oasis
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and

lyric hornet
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yep $\sin^2(y)=\frac{1}{x^2+1}$

woven radishBOT
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PajamaMamaLlama

lyric hornet
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now how can we isolate sin?

outer oasis
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square root

lyric hornet
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yep!

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$\sin(y)=\frac{1}{\sqrt{x^2+1}}$

woven radishBOT
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PajamaMamaLlama

lyric hornet
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now, what did we defined y to be?

lyric hornet
outer oasis
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1/sqrt of x^2 + 1?

lyric hornet
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not quite, that's sin(y)

outer oasis
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oh

lyric hornet
outer oasis
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arccot

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(x)

lyric hornet
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precisely!

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now we have the identity

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$\sin(\arccot(x))=\frac{1}{\sqrt{x^2+1}}$

woven radishBOT
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PajamaMamaLlama

lyric hornet
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now look at your problem and see how easy it is now :)

outer oasis
bitter bough
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the other way is you draw a right traignel and solve for the missing side

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and sin is defined as opposite / hypotenuse

lyric hornet
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Cauchy said it best: "As for methods I have sought to give them all the rigour that one requires in geometry, so as never to have recourse to the reasons drawn from the generality of algebra."

bitter bough
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well im not gonna pretend like im even 1/1000th a mathematician as cauchy ;P

lyric hornet
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same kekw but just a good quote

outer oasis
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@lyric hornet

lyric hornet
outer oasis
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your way seemed hard to remember thats why i asked danny about the triangle

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thats just an identity right

outer oasis
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raven moth
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Can someone help me 2.a I know for the bottom is x-1 because vertical asymptote is at 1 but how we figure out the top?

raven moth
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So far I figured out blank/x-1

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raven moth
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<@&286206848099549185>

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vast violet
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Hi

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vast violet
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Im just having trouble with 1 thing

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How do i tell if its a reflection off x axis

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or reflection off y axis again

normal badge
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if you negate f(x) or y, then it will reflect off of the X axis and
if you negate x, then it will reflect off of the Y axis

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limpid citrus
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could someone help me understand the logic of this

limpid citrus
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.close

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gilded coyote
#

Working through my first problem set in Basic Mathematics by Serge Lang and he asks us to prove some equalities via commutativity and associativity. I'm doing this on my own, so I don't have a teacher to ask for correct answers.

Is my way of thinking about this (and way of writing it) correct? I've never written a proof, so I'm unsure exactly what I'm supposed to show.

Problem 1).

Commutativity tells us that x + y = y + x
Associativity tells us that (x + y) + z = (x + z) + y

By commutativity, (a + b) + (c + d) = (b + a) + (d + c)
By associativity, (a + d) + (b + c)

Therefore, (a + b) + (c + d) = (a + d) + (b + c)

Remember, this is Basic Mathematics, so we don't have set theory or any other proof methods.

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long pasture
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late terrace
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late terrace
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so what does this question mean? i dont understand

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it should be simple

devout snowBOT
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@late terrace Has your question been resolved?

late terrace
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how?

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yea i have

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wdym value?

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so cos 60

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and root3/2

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right?

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@restive river the angle would be 60

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pie on 3?

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oh ok

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how is pi 180 if the radius is 1 tho

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wait nvm got confused

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so u mean multiples ?

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well pi/3 angle would be at 60 degrees at 1/2 and root3/2

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oh u mean the one in the 4th quadrant?

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ah yea the one at 300 degree right

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is that what u mean

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ah really?

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@restive river here

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i see

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yea sure

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yea

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hm

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ah

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rotation or expand/

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?

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so moving the circle?

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oh is it pi

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or 2pi

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ohk hm

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ah ye

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late terrace
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so 2pi right

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so it means the circle can be moved in any angle at a unit of 2pi

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right i understand

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now how would i get the values?

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late terrace
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ah yeo

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yep

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wdym k ?

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yea ok

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yea

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so it would be between 4 pi

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and -4pi

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oh hm

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why not -pi

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-4pi

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oh shoot

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u right

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yea

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so 0 and 4pi okay

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and goes in intervals of pi/3 + 2pi

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well first one is pi/3 + 2pi

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oh shoot pi/3

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how do i know if the vvalues are between 0 and 4 tho?

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i mean less than 4

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oh wait 4pi

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that makes sese

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alright so

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pi/3, pi/3+2pi, pi/3 + 4

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why pi/4?

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for that equation

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ohh okay that makes sese

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so 4pi - pi/3+4 should be negative

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let me do the math brb

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@restive river i got a differenet answer when i minus them

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and ye i changed to 4pi

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@restive river can u show me how to minus it? or do i have to convert to degree

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how is it 4pi -(pi/3 +4pi) not 4pi-pi/3+4pi

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why ?

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(5+3)-10

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oh wait i see

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how ? ur subtracting from after 3+5

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alright

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so okay 4pi - ( pi/3+4pi)

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alright let me do it

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so i got 12pi-13pi/3

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which is then -pi/23

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so correct

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sorry i mea that the value u said is correct

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how ? sorry i mean (12pi-13pi)/3 , which means the value i get is -pi/3, which then means the value is negative so no solotion

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right?

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really? a faster way? sure

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sure show

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ohhhh

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so can i do that with any given restriction tho?

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isnt that wrong tho? cause ur saying that a will always be -a

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-pi/3?

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okay

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so yea now i know that the third value is negative

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yea 2 values

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what?

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hm?

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so -pi/3 + 2pi

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for k = 1

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so then 5pi/3?

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how? by subtracting that with 4pi?

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so then i get 7pi/3

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yea

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what does this mean?

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its greater

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5pi/3 is greater

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than 4pi

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cause wait

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so if 4pi is smaller or bigger than 5pi/3, so i minus 4pi by 5pi/3

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so then it becomes (12pi-5pi)/3 which is 7pi/3

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its a postitive so then 4pi is greater @restive river ?

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is that it

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yea

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oh shoot then sorry but yea i worked it out

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try what?

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okay

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u mean -pi/3 is greater or smaller than 4pi? or the equation

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which one

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ok

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4pi-11pi/3

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which then is 12pi-11pi on 3

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pi/3

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@restive river

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wait so the answer is postive

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its greater if the answer is postive

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so ye 4pi is greater

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done

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so we have pi/3 + 2pi

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pi/3 +4pi

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really oh shoot

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too much writing i cant see

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well isnt it pi/3

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and then pi/3 + 2pi

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whats the other two we found

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and 5pi/3

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and -pi/3 + 4pi @restive river

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wait but how did u get the other two values again? ik how to check but how did we get 5pi/3 and -pi/3 @restive river

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yep

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yep

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did we do 0 tho i thought only 1 and 2

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4pi + pi/3 =12pi+pi on 3 = 13pi/3 which meas its positive

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and if its positive it means its in between 4pi @restive river

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is that wrong

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i got 4pi + pi/3 cause 4pi - - pi/3 = 4pi+pi/3

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restive river
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restive river
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Shouldn’t there be a costheta also multiplying with cosec square?

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I highlighted it

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The expression they want us to prove

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<@&286206848099549185>

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Is there a mistake or am I wrong?

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.close

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glacial aurora
#

trying to do mathematical induction but I’m stuck now

sweet estuary
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use the inductive hypothesis

glacial aurora
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if = and if < ?

sweet estuary
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you can chain inequalities

glacial aurora
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I was going to substitute but with the < idk if I can do that

sweet estuary
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just keep it as <=

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there's no need for strict inequalities here

glacial aurora
sweet estuary
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the circled and the underlined

glacial aurora
sweet estuary
glacial aurora
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and the last operation is right?

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@sweet estuary

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@glacial aurora Has your question been resolved?

glacial aurora
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<@&286206848099549185> Can you verify if this math induction is correct?

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safe crest
devout snowBOT
safe crest
#

why does arg(z1+z2) = pi/2

sullen island
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z1+z2 is just 2i

pseudo basin
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^

sullen island
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it goes in the same direction as i doesn't it @safe crest

safe crest
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but 2i = pi

sullen island
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?

safe crest
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i = cis(pi/2)

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the arguement for i is pi/2

sullen island
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yeah, 2i = 2cis(pi/2)

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same argument

safe crest
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oh so the arguement doesnt chang

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i see

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thank you

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trail oyster
#

Is the final answer square root 53? What did i do wrong?

trail oyster
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<@&286206848099549185>

tranquil iron
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Forgot to divide by 3 factorial there

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@trail oyster

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Also have to sub x= 1/50 into the actual binomials/ equations on the lhs and then rearrange for sqroot 53

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@trail oyster Has your question been resolved?

trail oyster
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I still got 1.02

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@tranquil iron

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<@&286206848099549185>

tranquil iron
#

Lemme try it

tranquil iron
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So you multiply both sides by 7 to get what sqroot53 approximately equals to

trail oyster
#

Like this?

tranquil iron
#

πŸ‘πŸ‘πŸ‘

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Answer is to 4 d.p though so it should be smth like 7.1364

trail oyster
#

Alrightt thank youu so much!!

tranquil iron
#

No worries and to check your work you could check what sqroot of 53 is in your calc and it should be a similar value ish

trail oyster
#

πŸ‘

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restive river
#

$x$ describes the outcomes of a red die,$y$ a blue one. Can the sample Space be written as [
\set{(x,y) \in (\Z^+)^2 \where x \le 6, y \le 6}
]

woven radishBOT
restive river
#

okay I know the notation is wild but I'm trying to experiment with how you can describe stuff xd

pale bolt
#

I think you cant do $(\bZ^+)^2$

woven radishBOT
supple knot
#

$\N \times \N$

woven radishBOT
#

riemann

pale bolt
#

either that, or split x,y to each by in Z

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why does \Z work for you guys but not for me πŸ€”

restive river
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I wanted to use that but I just don't like using N anymore since it can be ambiguous on whether it includes 0 or not

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in some cases

pale bolt
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$\bN^+ \times \bN^+$

woven radishBOT
winter torrent
#

ambiguity breeds creativity and math is all about creativity if you think about it

pale bolt
#

regardless I've never seen the squared notation and I suspect its wrong

restive river
#

fair enough

restive river
woven radishBOT
restive river
#

it's the same principle

supple knot
#

The + and the 2 just makes it look ugly

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Just go with N and if someone asks "isn't 0 in N" tell them to fuck off not according to these sources: <your favorite books here>

restive river
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lmfao okay

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thanks everyone

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restive river
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.reopen

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βœ…

restive river
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wait question

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my book writes it as [
S = \set{(x,y) \where 1\le x, y\le 6}
]
but can you 1) assume that $x$ and $y$ are both integers from that, and 2) write the inequality like thay

woven radishBOT
pale bolt
#
  1. probably not by default, but if its about dice then I suppose you can assume
  2. yes
restive river
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why yes for 2)

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how can you differentiate between that and saying "x is greater or equal to 1, and y is lesser or equal to 6"

sonic smelt
#

For 2 I would say yes as well

pale bolt
woven radishBOT
pale bolt
#

I didnt even consider that alternate meaning when I read that

restive river
#

I mean, I did. That was the first thing I saw which made me confused for a second, but I guess your way makes it less ambiguous

pale bolt
#

you could explicitly write out the inequality for both x and y if you were so inclined, but this one is clear in general

restive river
#

I see ok

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ty

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dapper gyro
#

Could I get a run through on how to do these questions?

prime hollow
#

No, I think you should explain how far you have come or ask something more specific.

dapper gyro
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Well looking at it, im confused on how to find point P

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Ive found the dy/dx

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But confused on where to go from here

prime hollow
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You need to solve x^5-x^3=0

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YOu don't need the derivative for the first step

dapper gyro
#

Would it be 1?

prime hollow
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Yeah.

dapper gyro
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(1,0)

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Ah ok

prime hollow
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Right

dapper gyro
#

then use the derivative to find the tangent?

prime hollow
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You got it

dapper gyro
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ohhh ok

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Alr cheers

#

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thorny sinew
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thorny sinew
#

easy, this is undefined right?

#

.CLOSE

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stark shale
#

i'm confused about this

devout snowBOT
stark shale
#

in the solution they can compute the value of e^1.3

#

it's just an approximation i guess and i could put say 4 or 5 if i have no better idea?

#

i mean what if i can't compute it?

#

how do i pick the max value?

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@stark shale Has your question been resolved?

stark shale
#

how could i estimate e^1.3 without being able to evaluate it?

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restive river
#

Why does it say a^2 even?

devout snowBOT
dark tundra
#

(Whoever wrote that sol should have written that explicitly)

#

So if b is an integer, so is b^2

signal crag
#

Usually you have to specify that HCF(a,b) = 1

dark tundra
#

You definitely do

#

The whole idea of the proof is to force GCF(a,b)=2, which contradicts the assumption that a/b is simplified, a,b relatively prime, or GCF(a,b)=1, which are all basically equivalent

restive river
#

@dark tundra sorry I'm not following. If a/b = 1/3, then a^2 isn't even, right?

dark tundra
#

It still is

#

in the context of our proof, a^2=2b^2=2k for some integer k, which is the definition of even

restive river
#

@dark tundra ooohhh, I think I get it now. thx

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vernal anvil
devout snowBOT
vernal anvil
#

not sure i entirely understand what im supposed to do here

#

if anyone could help me out that would be great

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sharp quiver
#

help! this problem has been killing me.

devout snowBOT
sharp quiver
#

i've been attempting to get the right answer for hours, and nothing's worked.

restive river
#

what did u try

sharp quiver
#

i tried to FOIL this first: (3x-4)^2 (5x+1)

#

this is on ALEKS, which is what my homework is on. u can have multiple attempts @ different problems, and on those previous problems, i tried FOILing the others, but nothing worked.

#

there's more questions later that i also need urgent help on cuz this homework assignment is due @ midnight, and i've been struggling w/ it since i got home from school.

restive river
#

ur ignoring the last condition...

sharp quiver
#

hold up. lemme test something rq.

restive river
restive river
sharp quiver
restive river
#

ok

sharp quiver
#

it turns out that FOILing it won't give me a constant of -48.

#

im still kinda lost tho cuz idk what to do.

#

ik that i have to foil it cuz from my other attempts, it's gonna be in standard form.

restive river
#

u want to solve for some k s.t. f(x) = k(3x-4)^2 (5x+1) and f(0) = -48

restive river
#

some k such that

sharp quiver
#

im still lost.

restive river
#

plug in x=0

#

solve for a k so that u get -48

sharp quiver
#

ight, but where's k supposed to be?

#

or what's k even supposed to be?

restive river
#

i havent solved it idk?

#

k is just a constant

sharp quiver
#

oh oki.

restive river
#

so that u satisify ur last condition

sharp quiver
#

so, what ur saying is that i should foil it first and then put -k at the end?

#

just to solve it?

#

like this?: (9x^2-24x+16)(5x+1)-k (i foiled the part w/ the multiplicity of 2.)

restive river
#

bro what

#

u have

#

k(3x-4)^2 (5x+1)

#

right?

#

plug in x=0 and find a k so that it equals -48

sharp quiver
#

OHHHHHH

#

hold up. i think i got it. lemme check.

#

cuz this shit's been killing me, and i still have more questions that r just as confusing.

#

just for the sake of knowledge, should i put a minus between (3x-4)^2 and (5x+1)?

#

cuz if u look back @ the question, one of the zeros is -1/5

restive river
#

wat

#

??

#

its -1/5 so u made it 5x+1?

sharp quiver
#

yea.

sharp quiver
#

since the minus will distribute itself into (5x+1)

restive river
#

(3x-4)^2 - (5x+1) ???

#

i think im misunderstanding u or smthing

#

what equation do u mean

sharp quiver
#

which would turn the overall equation into (3x-4)^2(-5x-1)

restive river
#

so like (3x-4)^2(-1)(5x+1)

#

or

#

(3x-4)^2 - (5x+1)

sharp quiver
restive river
#

no that doesnt make any sense

#

thats like a completely different equation?

sharp quiver
#

.close

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lusty moth
#

I am unsure what to do with this problem, it's a linear expression problem

graceful cosmos
#

Consider factoring that polynomial, with the understanding that x+3 is a factor

lusty moth
#

What do you mean?

#

.close

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limpid citrus
#

I am doing the projectile question at the bottom and I am kind of stumped

limpid citrus
#

Wouldn't the position vector for i have a t in it?

#

because the answer abstains the t in (25sqrt2)/2

#

ping me if you have answer

devout snowBOT
#

@limpid citrus Has your question been resolved?

limpid citrus
#

<@&286206848099549185>

wicked turtle
limpid citrus
#

are you sure?

wicked turtle
#

yes

#

think about a vertical line in the x-y plane

limpid citrus
wicked turtle
#

every point on the line has the same x value

#

oh i didn't see the first screenshot, just the second one and your question about t

#

let me check the first

limpid citrus
#

this is the type of quetion that is like: "state accleration"

#

now find velocity

wicked turtle
#

yea that should have a t in it of course

limpid citrus
#

now find displacement

#

thats what I thought

#

the answers abstained the t and I was thinking it was a typo

wicked turtle
#

the velocity won't have a t in the i component

#

because the horizontal velocity will be constant

limpid citrus
#

yes indeed

#

alright thank you for the help bungo

wicked turtle
#

sure cheers

limpid citrus
#

.close

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zinc whale
devout snowBOT
zinc whale
#

can someone explain to me why 1/2 and 1 were used in this interval

#

and how did they come up with this #?

#

oh wait nvm I see it

#

.close

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crude sonnet
#

are these two the same

devout snowBOT
pseudo basin
#

no, $\bmqty{1 & 0 \ 0 & 3}^{35} \neq \bmqty{1 & 0 \ 0 & 3}^{35 \cdot 35}$

woven radishBOT
#

AnnGhost

crude sonnet
pseudo basin
#

i don't know what you want to hear tbh

#

you raise the matrix [1 0; 0 3] to the 35th power and you call the result A

#

and then you ask whether A and A^35 are the same thing

#

which no they are not

crude sonnet
#

well im unsure how you solve something like this since multiplying it by itself 3 times isnt it

#

the 2s somehow become 16 instead of 8
2x2x2

#

in the answer the 2s become 16 and the 3 becomes 27 which i understand since 3x3x3

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@crude sonnet Has your question been resolved?

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@crude sonnet Has your question been resolved?

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@crude sonnet Has your question been resolved?

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restive river
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restive river
#

is this correct?

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#

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stuck ether
devout snowBOT
stuck ether
#

how do I solve this??

quaint citrus
#

Use FV of annuity formula

stuck ether
#

but when I use it the answer is lower than 4k

quaint citrus
#

Show work

stuck ether
#

wait

quaint citrus
#

,rcw

woven radishBOT
stuck ether
#

see what I mean

#

its lower than 4k

quaint citrus
#

Hmm

stuck ether
#

Im kind of confused because in the problem theres the word end and beginning at the same time

#

<@&286206848099549185>

stuck ether
#

<@&286206848099549185> ?

plucky sapphire
#

the beginning of january means that the entire month of january should be counted

#

and the end of april means that the entire month must be counted as well

#

so the total time is 4 months

stuck ether
#

so what formula do I use?

plucky sapphire
stuck ether
#

yess I already get that

plucky sapphire
#

just use the compound interest formula and keeping the number of months to be 4

stuck ether
plucky sapphire
# woven radish

yes but since it is compounded monthly the time is not 4/12

#

it is only 4

#

i would have been 4/12 if it was compounded yearly

stuck ether
#

ahh okey let me try that

#

its to large

plucky sapphire
#

yep

stuck ether
#

is it really 50931.21??

plucky sapphire
#

probably

#

wait what

#

no

stuck ether
plucky sapphire
#

yep

#

wait

#

the answer is 1125.51

stuck ether
#

what??

#

why is it lower than 4k??

plucky sapphire
#

it is meant to be lower than 4k

#

why would it be higher?

#

ohhhhh

#

nvm

#

sorry

#

my fault

stuck ether
#

hmm this problem is kind of tricky

plucky sapphire
#

yep

plucky sapphire
#

if you used the right values

stuck ether
#

is 16060.1 the answer

#

or 4015.025

#

hmm I still not sure to my answer

devout snowBOT
#

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keen falcon
#

A person tried by a three-judge panel is declared guilty if at least two judges cast votes
of guilty (i.e. a majority verdict).
Suppose that when the defendant is in fact guilty, each judge will independently vote
guilty with probability 0.85, whereas when the defendant is in fact not guilty (i.e.
innocent), this probability drops to 0.25.
1
If 70% of defendants are guilty, compute the conditional probability that judge number
3 votes guilty given that:
(a) judges 1 and 2 vote guilty

devout snowBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
keen falcon
#

step number 2

devout snowBOT
#

@keen falcon Has your question been resolved?

keen falcon
#

.close

devout snowBOT
#
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brazen void
#

Divide( 2x^3+54) by (xβˆ’3) using long polynomial division

brazen void
#

im stuck idk where to begin at all

wild creek
#

did you try to read your course material about long division?

#

on polynomials

brazen void
#

my teach havent teach it yet

wild creek
#

how are you supposed to do something you havent learned

brazen void
#

idk bro she said practice at home

#

idk even know where to put the 0's here

#

im actually mentally block

wild creek
#

the internet is wide

brazen void
#

alr watched that

#

it didnt describe where to put the 0's

wild creek
#

what zeros?

#

if you tried something

#

pls show

#

and show which zero you are talking about

brazen void
#

this 0

wild creek
#

0x^3?

#

and 0x?

brazen void
#

0x

#

like the no2

wild creek
#

cant see in you photo

#

but those $0x^3$ and $0x$ are there so that the guy shows you that the coefficient for these powers of x is 0

woven radishBOT
#

Benjamin

wild creek
#

but you dont need it

brazen void
#

wait what

#

thought we supposed to use 0x to fill out the missing number

#

naw im actually trippin

#

answer supposed to be like this i just need to know the solution

wild creek
#

wolfram alpha exists if you just want answers

#

you dont need this discord

brazen void
#

i need the solution lol thats why im here

#

need help on how to solve this cuz my teacher just gave an assign and dip out

wild creek
#

,w long division (2x^3 +54) by (x-3)

wild creek
#

2x^2 +6x +18

#

remainder is 108

#

now if you want to learn i can help you

brazen void
#

yes

#

pls

#

i think u can do better than my math teach

wild creek
#

so pls take a better photo

#

of your working out

#

i cant see

#

or explain clearly what you dont understand

#

im not in your head

#

i cant know

brazen void
#

heres the questions alr solved the 1 and 2 im just stuck at 3

wild creek
#

ok

brazen void
#

lemme take a photo of 1 and 2 wait a min

#

my handwriting is kinda bad imo just adjust lol

wild creek
#

once you are here

#

you only need to subtract

#

right?

brazen void
#

yes

#
  1. Divide 2. Multiply 3. Subtract
#

mb for late reply was trying to solve it

wild creek
#

yeah so re do it i think you know how to subtract

brazen void
#

ok wait the mental block is not mental blocking anymore

#

lemme try to solve it

#

i think i got it?

#

tried to copied on what i did in no2

wild creek
#

ok

#

nice

brazen void
#

thanks alot dude

#

.close

devout snowBOT
#
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velvet python
#

Shoot is someone here i need help with long and synthetic division

velvet python
#

I have an equation labeled (3x^3-x+1+7x^2) Γ· (3x+1)

#

I seem to get stuck when i finally get the partial quotient and solve it against the -x

static oracle
#

can you show me your work?

velvet python
#

Oh its going wrong alright hahahahaha

#

fuck wait

static oracle
#

yep

#

hopefully I'll figure out where you went wrong

velvet python
#

Ah theres even the synthetic one that had a remainder of 29

static oracle
#

wait let me try synthetic

#

you're not supposed to have a remainder

velvet python
velvet python
#

I dont even know if the long one is correct

static oracle
#

um rearrange the equation first

#

in the order of decreasing exponents

velvet python
#

Theres more that went even worse than this

velvet python
static oracle
#

the dividend is 3x^3+7x^2-x+1

#

then divide that by 3x+1

#

the rest should be simple

velvet python
#

How did you even get the synthetic version of 3x+1

#

How did mine turn to one half

static oracle
#

not kne hlaf

#

you need to equate it with 0

#

3x+1 =0

#

and solve for x

#

which is -1/3

#

that's what you use for synthetic division

velvet python
#

Everyone in the comments said divide everything by 2 just so long as the x is remaining and you're left with a number after equals

velvet python
static oracle
velvet python
#

Just so long as whatever number is with x divide it with the same number to remove that number so x remains

#

Also whats 4 divided by 3x now

static oracle
#

I'm pretty sure you don't need to divide 4 by 3x

#

in this one

velvet python
static oracle
#

getting it?

velvet python
#

Wait im already lagging just wait a bit

velvet python
static oracle
#

show me when it's done

velvet python
#

I cant just leave it there

static oracle
#

I tried and there was no remainder

#

there was no 4 at all

velvet python
#

Im gonna try again

static oracle
#

yep

velvet python
#

you dont have a 3x squared?

static oracle
#

nop

velvet python
#

Ye a

static oracle
#

wait wait

velvet python
#

F u ck first thing midnight wrong thing alredy

static oracle
#

you already have 3 in your divisor so you don't need 3 anymore

#

just x^2

static oracle
#

just try again

#

doing long division rn right

velvet python
#

Yeah so im left with a whole seven afterwards

#

Unless, x^2 times 1 leads to it becoming 2x somewhere

static oracle
#

in the 2nd step you need to multiply by 2x

velvet python
#

Damn

static oracle
#

why don't you watch a tutorial on yt?

velvet python
#

I tried

#

I didnt get anything

#

It just made me even more confused

#

Damn it i didnt even know how the venn diagram thing worked since i kept getting a negative answer where im not supposed to

#

Wait is it even possible to get an x-x in the answer

static oracle
velvet python
#

Well this ended up devolving again theres too many of them already

velvet python
#

Whoops

#

Welp sorry about that

static oracle
#

hm?

#

what grade are you in btw

velvet python
#

Worse question to ask

static oracle
#

why

velvet python
#

somehow in college

#

IM PRETTY SURE U LEARN THIS AT 7TH GRADE

#

and yes i did learn about this but somehow i forgot

static oracle
#

ah

#

you know what

#

first focus

#

seeing your work

velvet python
static oracle
#

makes me think you're not into it at all

velvet python
static oracle
#

no no

#

at some places you forgot to copy down the x

velvet python
#

F

static oracle
#

that's what's been wrong

#

is it like a hw?

velvet python
#

yea

static oracle
#

due some time soon

#

oh

#

you still have time?

#

if then I suggest go do smth else to lighten your brain

#

for a bit

velvet python
static oracle
velvet python
#

What last one theres too many of them since i didnt even know what x^2 times one is

static oracle
#

x^2 times 1 is x^2

#

anything times 1 is that same anything

velvet python
#

Thank god i just started to doubt about that

static oracle
#

never question math

velvet python
#

Hold on let me check what went right

static oracle
#

hm

#

got it?

velvet python
#

How do u get rid of the one -x

#

And the rest of them

#

Unless since theres no way just slap it on top

static oracle
#

your dms open?

velvet python
#

Yea

static oracle
#

I don't think I'm allowed to send ans here so

velvet python
#

I dont know hwo this place works either ill be honest

static oracle
#

yea

velvet python
#

Ha

#

So thats what happened how did i get stuck

static oracle
#

no you need to copy the -Γ—

#

in the 2nd step

velvet python
#

.close

devout snowBOT
#
Channel closed

Closed by @velvet python

Use .reopen if this was a mistake.

velvet python
#

Its fine now

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

karmic garden
#

Sorry for my bad English I'm french , so the thing is that when I frame(Encadre in my language) I have impossible things like 20,9<-2x+3y<20,7 But how can 20,7 be > yo 20,9 what did I've done wrong

dapper tiger
#

-4 < x < -3 donc 6 < -2x < 8
12,9 < 3y < 14,7
donc tu sommes tes deux inΓ©galitΓ©s et t'as
18,9 < -2x+3y < 22,7

karmic garden
#

Ah on inverse directement merci !

#

.close

devout snowBOT
#
Channel closed

Closed by @karmic garden

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

daring nebula
#

Linda thought of a natural number and then added a 5 to the left and an 8 to the right in the number representation. This increased the number Linda thought of by 518215.

Find the number Linda thought of and explain why it is uniquely determined.

daring nebula
#

i dont know what to do next

#

i have
5ABCD8
-518215

#

but my teacher asked me why i did ABCD and not ABCDE (i have to explain why although it is correct wyipee_sob)

#

and i dont know how to subtract a number from a letter

#

<@&286206848099549185>

frozen aurora
#

try to abstract yourself away from digits for a sec. let x be the number you are looking for. how do we represent the transformation described in the problem

devout snowBOT
#

@daring nebula Has your question been resolved?

daring nebula
frozen aurora
#

not really

#

notice that adding 8 to the end is the same as doing ||x*10 + 8||

daring nebula
#

OH

#

so D=10 or 100?

frozen aurora
#

what's D?

daring nebula
#

i mean like in 5ABCD8

#

the F

#

D*

frozen aurora
#

adding 5 to the front of $x$ and adding 8 to the end is the same as $5\cdot10^{k+1}+x\cdot10+8$ where $k$ is the number of digits in $x$

#

now, you get that the increase from x to that number above is 518215

#

so 5*10^(k+1) + x*10 + 8 = x + 518215

daring nebula
#

ohh

frozen aurora
#

and you can easily figure out what k is equal to from this

woven radishBOT
#

artemetra

daring nebula
#

sorry i still dont quite understand could u help me out a bit more? super sorry if im being annoying

daring nebula
daring nebula
#

cause i got something

#

questionable

supple knot
devout snowBOT
daring nebula
#

and for k i got

k=log(-9x/5 + 518215/5) -1

supple knot
frozen aurora
#

it must be a positive integer, so no need for logs

frozen aurora
#

notice that 5*10^(k+1) and 518215 have same leading digits. does that help anyhow?

daring nebula
#

OH

#

I THINK I GOT IT NOW

frozen aurora
#

let's goo

#

spoiler: the value of x is very nice

daring nebula
#

i got 2023

frozen aurora
#

mhm

daring nebula
#

but i dont know

frozen aurora
#

correct

daring nebula
#

IT IS!?@?!?

frozen aurora
#

yep

daring nebula
#

TGANK YOU SO MUCH

frozen aurora
#

no problem haha

daring nebula
#

was that the number she thought of then??

frozen aurora
#

yes

#

you are done

daring nebula
#

THANK YOI

#

.close

devout snowBOT
#
Channel closed

Closed by @daring nebula

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cyan flame
#

A train and a dog parallel to each other from the same points at same time start running at 216kmph and 21.6 kmph respectively. if the length of train is 180 m , find in how much time will the train surpass the dog completely.

cyan flame
#

plz solve this one

opaque haven
#

for the dog to be behind the train it would have to be exactly 180m behind the train, correct?

cyan flame
#

wait

#

a sec plz

pulsar oracle
#

could it be 3.33....s?

cyan flame
#

ya correct

#

how?

#

plz share

pulsar oracle
#

1 minute I'll type it

cyan flame
#

okk

#

??

pulsar oracle
#
Train speed = 216 kmph => 60 m/s
Dog speed = 21.6 kmph => 6m/s

Using the forula to measure distance traveled:
X0 + V0*t + A0*t*t/2 = d

we can say that the starting acceleration (A0) = 0, so that is no longer part of the equation 

so The distance traveled by the train:
Starting distance X0 = 0
=> d = V0*t <=> d = 60m/s * t

For the dog, who has a starting position of 180m relative to the train
=> d = 180m + 6m/s * t

now we calculate when they pass eachother:

180m + 6m/s*t = 60m/s*t
=> calculate for t => t = 3.33..s
cyan flame
#

thanks very much

#

one more problem

pulsar oracle
#

yea?

cyan flame
#

hello?

pulsar oracle
#

yea i'm lookin

cyan flame
#

thanks

pulsar oracle
#

been a while since i've done trigonometry

cyan flame
#

ohh

#

no worries

#

take your time

cyan flame
#

I am a school grader so relative velocity out of my concept

pulsar oracle
#

I see

cyan flame
#

i tried doing it myself but my teacher said that my ans is wrong

#

i am sharing my answer , plz look into it

pulsar oracle
#

uhm i gues you could also say that the train is going 54 kmph faster than the dog, so you just have to calculate the time in which you have travelled 180m whilst going at 54m/s

cyan flame
#

nope

#

wait i am solving

pulsar oracle
lavish nimbus
# cyan flame

Are there any formulas that you can come up with then solving trigonometry algebra?

cyan flame
#

wait for 2 mins

pulsar oracle
#

with the t formulas you can find the angle

#

t = 1/3 => tan(x/2) = 1/3

cyan flame
#

sorry for being late...

#

plz check it once

#

are you checking?

pulsar oracle
cyan flame
#

i am not sure

#

thats why i am asking you

pulsar oracle
#

i'll send you my math

#

but imma write it down properly 1 min

cyan flame
#

ok

#

brother i guess sinΘ = 3/5

#

i tried for error and trial method

#

i guess thats correct ans

cyan flame
#

whether its correct or not

pulsar oracle
#

the method i used is quiet elaborate

pulsar oracle
cyan flame
#

thanks

pulsar oracle
cyan flame
#

brother

#

one more problem

pulsar oracle
#

ye

cyan flame
#

a sec

#

are you solving?

#

hello brp

pulsar oracle
#

it's b

cyan flame
#

how?

pulsar oracle
#

i'm writing it down

cyan flame
#

ok

pulsar oracle
cyan flame
#

thankyou very much

#

you are genius

pulsar oracle
#

hahaha it's just experience

cyan flame
#

can you help with physics numericals too

cyan flame
pulsar oracle
cyan flame
#

omg!

#

I am 15