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idk how to solve this
its this one
Danny
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yes
Ru, can I have you consider something?
yes
Let $y=\arccot(x)$
PajamaMamaLlama
then $\cot(y)=x$, right?
PajamaMamaLlama
uhh yes
now if you square both sides, what do you get?
both sides would be squared?
$\cot^{2}(y)=x^2$
PajamaMamaLlama
ok yeah pretty simply 
but now I wish to use the identity $\csc^2\theta=1+\cot^2\theta$
PajamaMamaLlama
what can I do to both sides of this equation
to use this identity?
wait wdym to use it
so I have cot^2 right?
yes
but I want to get csc^2
do you mean add a 1
PajamaMamaLlama
yeah
Lmao this is what happens whne you dont wanna draw right triangles π π π
what happens if I take the reciprocal of both sides?
the algebra simplifies nicely anyways :)
sin^2(y)
yeah i can see where you are going
and
yep $\sin^2(y)=\frac{1}{x^2+1}$
PajamaMamaLlama
now how can we isolate sin?
square root
PajamaMamaLlama
now, what did we defined y to be?
^
1/sqrt of x^2 + 1?
not quite, that's sin(y)
oh
^^
PajamaMamaLlama
now look at your problem and see how easy it is now :)
what was the way he was talking about?
the other way is you draw a right traignel and solve for the missing side
and sin is defined as opposite / hypotenuse
Cauchy said it best: "As for methods I have sought to give them all the rigour that one requires in geometry, so as never to have recourse to the reasons drawn from the generality of algebra."
well im not gonna pretend like im even 1/1000th a mathematician as cauchy ;P
same
but just a good quote
also for this do i just plug in -7/6 for x
@lyric hornet

your way seemed hard to remember thats why i asked danny about the triangle
thats just an identity right
i got -6, now what do i do?
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Can someone help me 2.a I know for the bottom is x-1 because vertical asymptote is at 1 but how we figure out the top?
So far I figured out blank/x-1
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<@&286206848099549185>
@raven moth Has your question been resolved?
@raven moth Has your question been resolved?
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Im just having trouble with 1 thing
How do i tell if its a reflection off x axis
or reflection off y axis again
if you negate f(x) or y, then it will reflect off of the X axis and
if you negate x, then it will reflect off of the Y axis
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could someone help me understand the logic of this
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Working through my first problem set in Basic Mathematics by Serge Lang and he asks us to prove some equalities via commutativity and associativity. I'm doing this on my own, so I don't have a teacher to ask for correct answers.
Is my way of thinking about this (and way of writing it) correct? I've never written a proof, so I'm unsure exactly what I'm supposed to show.
Problem 1).
Commutativity tells us that x + y = y + x
Associativity tells us that (x + y) + z = (x + z) + y
By commutativity, (a + b) + (c + d) = (b + a) + (d + c)
By associativity, (a + d) + (b + c)
Therefore, (a + b) + (c + d) = (a + d) + (b + c)
Remember, this is Basic Mathematics, so we don't have set theory or any other proof methods.
@gilded coyote Has your question been resolved?
Okay, thank you π
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@late terrace Has your question been resolved?
how?
yea i have
wdym value?
so cos 60
and root3/2
right?
@restive river the angle would be 60
pie on 3?
oh ok
how is pi 180 if the radius is 1 tho
wait nvm got confused
so u mean multiples ?
well pi/3 angle would be at 60 degrees at 1/2 and root3/2
oh u mean the one in the 4th quadrant?
ah yea the one at 300 degree right
is that what u mean
ah really?
@restive river here
i see
yea sure
yea
hm
ah
rotation or expand/
?
so moving the circle?
oh is it pi
or 2pi
ohk hm
ah ye
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so 2pi right
so it means the circle can be moved in any angle at a unit of 2pi
right i understand
now how would i get the values?
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ah yeo
yep
wdym k ?
yea ok
yea
so it would be between 4 pi
and -4pi
oh hm
why not -pi
-4pi
oh shoot
u right
yea
so 0 and 4pi okay
and goes in intervals of pi/3 + 2pi
well first one is pi/3 + 2pi
oh shoot pi/3
how do i know if the vvalues are between 0 and 4 tho?
i mean less than 4
oh wait 4pi
that makes sese
alright so
pi/3, pi/3+2pi, pi/3 + 4
why pi/4?
for that equation
ohh okay that makes sese
so 4pi - pi/3+4 should be negative
let me do the math brb
@restive river i got a differenet answer when i minus them
and ye i changed to 4pi
@restive river can u show me how to minus it? or do i have to convert to degree
how is it 4pi -(pi/3 +4pi) not 4pi-pi/3+4pi
why ?
(5+3)-10
oh wait i see
how ? ur subtracting from after 3+5
alright
so okay 4pi - ( pi/3+4pi)
alright let me do it
so i got 12pi-13pi/3
which is then -pi/23
so correct
sorry i mea that the value u said is correct
how ? sorry i mean (12pi-13pi)/3 , which means the value i get is -pi/3, which then means the value is negative so no solotion
right?
really? a faster way? sure
sure show
ohhhh
so can i do that with any given restriction tho?
isnt that wrong tho? cause ur saying that a will always be -a
-pi/3?
okay
so yea now i know that the third value is negative
yea 2 values
what?
hm?
so -pi/3 + 2pi
for k = 1
so then 5pi/3?
how? by subtracting that with 4pi?
so then i get 7pi/3
yea
what does this mean?
its greater
5pi/3 is greater
than 4pi
cause wait
so if 4pi is smaller or bigger than 5pi/3, so i minus 4pi by 5pi/3
so then it becomes (12pi-5pi)/3 which is 7pi/3
its a postitive so then 4pi is greater @restive river ?
is that it
yea
oh shoot then sorry but yea i worked it out
try what?
okay
u mean -pi/3 is greater or smaller than 4pi? or the equation
which one
ok
4pi-11pi/3
which then is 12pi-11pi on 3
pi/3
@restive river
wait so the answer is postive
its greater if the answer is postive
so ye 4pi is greater
done
so we have pi/3 + 2pi
pi/3 +4pi
really oh shoot
too much writing i cant see
well isnt it pi/3
and then pi/3 + 2pi
whats the other two we found
and 5pi/3
and -pi/3 + 4pi @restive river
wait but how did u get the other two values again? ik how to check but how did we get 5pi/3 and -pi/3 @restive river
yep
yep
did we do 0 tho i thought only 1 and 2
4pi + pi/3 =12pi+pi on 3 = 13pi/3 which meas its positive
and if its positive it means its in between 4pi @restive river
is that wrong
i got 4pi + pi/3 cause 4pi - - pi/3 = 4pi+pi/3
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Shouldnβt there be a costheta also multiplying with cosec square?
I highlighted it
The expression they want us to prove
<@&286206848099549185>
Is there a mistake or am I wrong?
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trying to do mathematical induction but Iβm stuck now
use the inductive hypothesis
I was going to substitute but with the < idk if I can do that
I canβt figure out what to put <=
the circled and the underlined
is this right?
@glacial aurora Has your question been resolved?
<@&286206848099549185> Can you verify if this math induction is correct?
Opps handwriting lol
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why does arg(z1+z2) = pi/2
z1+z2 is just 2i
^
it goes in the same direction as i doesn't it @safe crest
but 2i = pi
?
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Is the final answer square root 53? What did i do wrong?
<@&286206848099549185>
Forgot to divide by 3 factorial there
@trail oyster
Also have to sub x= 1/50 into the actual binomials/ equations on the lhs and then rearrange for sqroot 53
@trail oyster Has your question been resolved?
Lemme try it
At the end you then have sqroot53 / 7 = 1.02
So you multiply both sides by 7 to get what sqroot53 approximately equals to
Like this?
Alrightt thank youu so much!!
No worries and to check your work you could check what sqroot of 53 is in your calc and it should be a similar value ish
π
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$x$ describes the outcomes of a red die,$y$ a blue one. Can the sample Space be written as [
\set{(x,y) \in (\Z^+)^2 \where x \le 6, y \le 6}
]
okay I know the notation is wild but I'm trying to experiment with how you can describe stuff 
I think you cant do $(\bZ^+)^2$
$\N \times \N$
riemann
either that, or split x,y to each by in Z
why does \Z work for you guys but not for me π€
I wanted to use that but I just don't like using N anymore since it can be ambiguous on whether it includes 0 or not
in some cases
$\bN^+ \times \bN^+$
ambiguity breeds creativity and math is all about creativity if you think about it
regardless I've never seen the squared notation and I suspect its wrong
fair enough
isn't it just similar to $\R^2$
it's the same principle
The + and the 2 just makes it look ugly
Just go with N and if someone asks "isn't 0 in N" tell them to fuck off not according to these sources: <your favorite books here>
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β
wait question
my book writes it as [
S = \set{(x,y) \where 1\le x, y\le 6}
]
but can you 1) assume that $x$ and $y$ are both integers from that, and 2) write the inequality like thay
why yes for 2)
how can you differentiate between that and saying "x is greater or equal to 1, and y is lesser or equal to 6"
you would write it the other way if you wanted that
$x \geq 1, y \leq 6$
I didnt even consider that alternate meaning when I read that
I mean, I did. That was the first thing I saw which made me confused for a second, but I guess your way makes it less ambiguous
you could explicitly write out the inequality for both x and y if you were so inclined, but this one is clear in general
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Could I get a run through on how to do these questions?
No, I think you should explain how far you have come or ask something more specific.
Well looking at it, im confused on how to find point P
Ive found the dy/dx
But confused on where to go from here
Would it be 1?
Yeah.
Right
then use the derivative to find the tangent?
You got it
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i'm confused about this
in the solution they can compute the value of e^1.3
it's just an approximation i guess and i could put say 4 or 5 if i have no better idea?
i mean what if i can't compute it?
how do i pick the max value?
@stark shale Has your question been resolved?
@stark shale Has your question been resolved?
how could i estimate e^1.3 without being able to evaluate it?
@stark shale Has your question been resolved?
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Why does it say a^2 even?
We assume when we express sqrt(2) as a/b, a and b are relatively prime integers
(Whoever wrote that sol should have written that explicitly)
So if b is an integer, so is b^2
Usually you have to specify that HCF(a,b) = 1
You definitely do
The whole idea of the proof is to force GCF(a,b)=2, which contradicts the assumption that a/b is simplified, a,b relatively prime, or GCF(a,b)=1, which are all basically equivalent
@dark tundra sorry I'm not following. If a/b = 1/3, then a^2 isn't even, right?
It still is
in the context of our proof, a^2=2b^2=2k for some integer k, which is the definition of even
@dark tundra ooohhh, I think I get it now. thx
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@restive river Has your question been resolved?
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not sure i entirely understand what im supposed to do here
if anyone could help me out that would be great
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help! this problem has been killing me.
i've been attempting to get the right answer for hours, and nothing's worked.
what did u try
i tried to FOIL this first: (3x-4)^2 (5x+1)
this is on ALEKS, which is what my homework is on. u can have multiple attempts @ different problems, and on those previous problems, i tried FOILing the others, but nothing worked.
there's more questions later that i also need urgent help on cuz this homework assignment is due @ midnight, and i've been struggling w/ it since i got home from school.
ur ignoring the last condition...
hold up. lemme test something rq.
this is correct besides ur constant value which u arent solving for
see this comment
i saw it. that's why i said i was testing something.
ok
it turns out that FOILing it won't give me a constant of -48.
im still kinda lost tho cuz idk what to do.
ik that i have to foil it cuz from my other attempts, it's gonna be in standard form.
u want to solve for some k s.t. f(x) = k(3x-4)^2 (5x+1) and f(0) = -48
what's k s.t.?
some k such that
im still lost.
oh oki.
so that u satisify ur last condition
so, what ur saying is that i should foil it first and then put -k at the end?
just to solve it?
like this?: (9x^2-24x+16)(5x+1)-k (i foiled the part w/ the multiplicity of 2.)
bro what
u have
k(3x-4)^2 (5x+1)
right?
plug in x=0 and find a k so that it equals -48
yea.
OHHHHHH
hold up. i think i got it. lemme check.
cuz this shit's been killing me, and i still have more questions that r just as confusing.
just for the sake of knowledge, should i put a minus between (3x-4)^2 and (5x+1)?
cuz if u look back @ the question, one of the zeros is -1/5
yea.
wat does this mean then
im saying should i put a minus between it so that it's easier to calculate.
since the minus will distribute itself into (5x+1)
(3x-4)^2 - (5x+1) ???
i think im misunderstanding u or smthing
what equation do u mean
im saying when i write (3x-4)^2 and (5x+1), should i put a minus sign between them so that it distributes itself into (5x+1) and causes it to turn into -5x-1
which would turn the overall equation into (3x-4)^2(-5x-1)
like this.
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I am unsure what to do with this problem, it's a linear expression problem
Consider factoring that polynomial, with the understanding that x+3 is a factor
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I am doing the projectile question at the bottom and I am kind of stumped
Wouldn't the position vector for i have a t in it?
because the answer abstains the t in (25sqrt2)/2
ping me if you have answer
@limpid citrus Has your question been resolved?
<@&286206848099549185>
not necessarily.. there would be no t for the i component if the particle is always moving vertically
because the question here doesn't state it being in constant motion or such
every point on the line has the same x value
oh i didn't see the first screenshot, just the second one and your question about t
let me check the first
yea that should have a t in it of course
now find displacement
thats what I thought
the answers abstained the t and I was thinking it was a typo
the velocity won't have a t in the i component
because the horizontal velocity will be constant
sure cheers
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can someone explain to me why 1/2 and 1 were used in this interval
and how did they come up with this #?
oh wait nvm I see it
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are these two the same
no, $\bmqty{1 & 0 \ 0 & 3}^{35} \neq \bmqty{1 & 0 \ 0 & 3}^{35 \cdot 35}$
AnnGhost
what's the first example called since the second is raising to the power of dont know what its called in english
i don't know what you want to hear tbh
you raise the matrix [1 0; 0 3] to the 35th power and you call the result A
and then you ask whether A and A^35 are the same thing
which no they are not
well im unsure how you solve something like this since multiplying it by itself 3 times isnt it
the 2s somehow become 16 instead of 8
2x2x2
in the answer the 2s become 16 and the 3 becomes 27 which i understand since 3x3x3
@crude sonnet Has your question been resolved?
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@crude sonnet Has your question been resolved?
@crude sonnet Has your question been resolved?
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is this correct?
@restive river Has your question been resolved?
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how do I solve this??
Use FV of annuity formula
but when I use it the answer is lower than 4k
Show work
,rcw
Hmm
Im kind of confused because in the problem theres the word end and beginning at the same time
<@&286206848099549185>
the beginning of january means that the entire month of january should be counted
and the end of april means that the entire month must be counted as well
so the total time is 4 months
so what formula do I use?
here
yess I already get that
just use the compound interest formula and keeping the number of months to be 4
like this?
yes but since it is compounded monthly the time is not 4/12
it is only 4
i would have been 4/12 if it was compounded yearly
yep
is it really 50931.21??
the value is to big
it is meant to be lower than 4k
why would it be higher?
ohhhhh
nvm
sorry
my fault
hmm this problem is kind of tricky
yep
can you check your caqlculations again
if you used the right values
is there a wrong value??
is 16060.1 the answer
or 4015.025
hmm I still not sure to my answer
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A person tried by a three-judge panel is declared guilty if at least two judges cast votes
of guilty (i.e. a majority verdict).
Suppose that when the defendant is in fact guilty, each judge will independently vote
guilty with probability 0.85, whereas when the defendant is in fact not guilty (i.e.
innocent), this probability drops to 0.25.
1
If 70% of defendants are guilty, compute the conditional probability that judge number
3 votes guilty given that:
(a) judges 1 and 2 vote guilty
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
step number 2
@keen falcon Has your question been resolved?
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Divide( 2x^3+54) by (xβ3) using long polynomial division
im stuck idk where to begin at all
my teach havent teach it yet
how are you supposed to do something you havent learned
idk bro she said practice at home
idk even know where to put the 0's here
im actually mentally block
This video tutorial explains how to perform long division of polynomials with remainder and with missing terms. It's explains how to do long division easily and it provides the step by step process to get it done. Basically, there are 3 steps that you have to repeat. 1. Divide 2. Multiply 3. Subtract This video contains plenty of ex...
the internet is wide
what zeros?
if you tried something
pls show
and show which zero you are talking about
this 0
cant see in you photo
but those $0x^3$ and $0x$ are there so that the guy shows you that the coefficient for these powers of x is 0
Benjamin
but you dont need it
wait what
thought we supposed to use 0x to fill out the missing number
naw im actually trippin
answer supposed to be like this i just need to know the solution
i need the solution lol thats why im here
need help on how to solve this cuz my teacher just gave an assign and dip out
,w long division (2x^3 +54) by (x-3)
so pls take a better photo
of your working out
i cant see
or explain clearly what you dont understand
im not in your head
i cant know
heres the questions alr solved the 1 and 2 im just stuck at 3
ok
lemme take a photo of 1 and 2 wait a min
my handwriting is kinda bad imo just adjust lol
yeah so re do it i think you know how to subtract
ok wait the mental block is not mental blocking anymore
lemme try to solve it
i think i got it?
tried to copied on what i did in no2
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Shoot is someone here i need help with long and synthetic division
I have an equation labeled (3x^3-x+1+7x^2) Γ· (3x+1)
I seem to get stuck when i finally get the partial quotient and solve it against the -x
can you show me your work?
Ah theres even the synthetic one that had a remainder of 29
I know
I dont even know if the long one is correct
Theres more that went even worse than this
im sorry you have to do that?
yes always
the dividend is 3x^3+7x^2-x+1
then divide that by 3x+1
the rest should be simple
not kne hlaf
you need to equate it with 0
3x+1 =0
and solve for x
which is -1/3
that's what you use for synthetic division
Everyone in the comments said divide everything by 2 just so long as the x is remaining and you're left with a number after equals
Oh thanks
I'm not sure what that means but I can say you don't always need to divide by 2
Just so long as whatever number is with x divide it with the same number to remove that number so x remains
Also whats 4 divided by 3x now
in 3x+1 it's 3 not 2
?
y e a
getting it?
Wait im already lagging just wait a bit
Also w a t
show me when it's done
I cant just leave it there
Im gonna try again
yep
you dont have a 3x squared?
Ye a
wait wait
F u ck first thing midnight wrong thing alredy
relax
just try again
doing long division rn right
Yeah so im left with a whole seven afterwards
Unless, x^2 times 1 leads to it becoming 2x somewhere
in the 2nd step you need to multiply by 2x
Damn
why don't you watch a tutorial on yt?
I tried
I didnt get anything
It just made me even more confused
Damn it i didnt even know how the venn diagram thing worked since i kept getting a negative answer where im not supposed to
Wait is it even possible to get an x-x in the answer
now you're doing venn diagrams?
Well this ended up devolving again theres too many of them already
A while back but for now since this is the one question i can clear this for now
Whoops
Welp sorry about that
Worse question to ask
why
somehow in college
IM PRETTY SURE U LEARN THIS AT 7TH GRADE
and yes i did learn about this but somehow i forgot
wtf
ah
you know what
first focus
seeing your work
Okay i know its bad and im also wondering how the fuck im here
makes me think you're not into it at all
M e s s y
F
yea
due some time soon
oh
you still have time?
if then I suggest go do smth else to lighten your brain
for a bit
Oh i have a lot
the last one on the right is on the right track tho
What last one theres too many of them since i didnt even know what x^2 times one is
Thank god i just started to doubt about that
never question math
Hold on let me check what went right
How do u get rid of the one -x
And the rest of them
Unless since theres no way just slap it on top
your dms open?
Yea
I don't think I'm allowed to send ans here so
I dont know hwo this place works either ill be honest
yea
.close
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Sorry for my bad English I'm french , so the thing is that when I frame(Encadre in my language) I have impossible things like 20,9<-2x+3y<20,7 But how can 20,7 be > yo 20,9 what did I've done wrong
-4 < x < -3 donc 6 < -2x < 8
12,9 < 3y < 14,7
donc tu sommes tes deux inΓ©galitΓ©s et t'as
18,9 < -2x+3y < 22,7
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Linda thought of a natural number and then added a 5 to the left and an 8 to the right in the number representation. This increased the number Linda thought of by 518215.
Find the number Linda thought of and explain why it is uniquely determined.
i dont know what to do next
i have
5ABCD8
-518215
but my teacher asked me why i did ABCD and not ABCDE (i have to explain why although it is correct
)
and i dont know how to subtract a number from a letter
<@&286206848099549185>
try to abstract yourself away from digits for a sec. let x be the number you are looking for. how do we represent the transformation described in the problem
@daring nebula Has your question been resolved?
so what do u suggest i do? do you mean x - 518215? if im understanding it correctly
what's D?
forget about digits for now
adding 5 to the front of $x$ and adding 8 to the end is the same as $5\cdot10^{k+1}+x\cdot10+8$ where $k$ is the number of digits in $x$
now, you get that the increase from x to that number above is 518215
so 5*10^(k+1) + x*10 + 8 = x + 518215
ohh
and you can easily figure out what k is equal to from this
artemetra
sorry i still dont quite understand could u help me out a bit more? super sorry if im being annoying
understanding what
^
how to solve for k
cause i got something
questionable
!show
Show your work, and if possible, explain where you are stuck.
this was the original question
and for k i got
k=log(-9x/5 + 518215/5) -1
show howyou got your answer
note the original restriction on k
it must be a positive integer, so no need for logs
so here you are adding 5*10^(k+1) to (x with 8 in front) and that results in an increase from (x) to 518215
notice that 5*10^(k+1) and 518215 have same leading digits. does that help anyhow?
i got 2023
mhm
but i dont know
correct
IT IS!?@?!?
yep
TGANK YOU SO MUCH
no problem haha
was that the number she thought of then??
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A train and a dog parallel to each other from the same points at same time start running at 216kmph and 21.6 kmph respectively. if the length of train is 180 m , find in how much time will the train surpass the dog completely.
plz solve this one
for the dog to be behind the train it would have to be exactly 180m behind the train, correct?
could it be 3.33....s?
1 minute I'll type it
Train speed = 216 kmph => 60 m/s
Dog speed = 21.6 kmph => 6m/s
Using the forula to measure distance traveled:
X0 + V0*t + A0*t*t/2 = d
we can say that the starting acceleration (A0) = 0, so that is no longer part of the equation
so The distance traveled by the train:
Starting distance X0 = 0
=> d = V0*t <=> d = 60m/s * t
For the dog, who has a starting position of 180m relative to the train
=> d = 180m + 6m/s * t
now we calculate when they pass eachother:
180m + 6m/s*t = 60m/s*t
=> calculate for t => t = 3.33..s
yea?
yea i'm lookin
thanks
been a while since i've done trigonometry
can this question be done without using relative velocity?
I am a school grader so relative velocity out of my concept
I see
i tried doing it myself but my teacher said that my ans is wrong
i am sharing my answer , plz look into it
uhm i gues you could also say that the train is going 54 kmph faster than the dog, so you just have to calculate the time in which you have travelled 180m whilst going at 54m/s
i can find the angle but not sin(xΒ΅)
Are there any formulas that you can come up with then solving trigonometry algebra?
wait for 2 mins
could sin be 9/15?
ok
brother i guess sinΞ = 3/5
i tried for error and trial method
i guess thats correct ans
yea that is right
thanks
I made an error
ye
it's b
how?
i'm writing it down
ok
hahaha it's just experience
can you help with physics numericals too
i mean whats your age that you have gained so much exprience?
sure