#help-27

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patent marsh
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anything else?

obsidian shuttle
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no, thanks

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how do i close the room?

patent marsh
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.close

obsidian shuttle
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.close

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restive river
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Need help 4b hints

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restive river
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wooden axle
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limit tends to 1/2

(x^2-1/4)tanΟ€x

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keen mantle
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hey

wooden axle
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Couldn't solve it by L'Hospital

keen mantle
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where did the pic go

lyric hornet
woven radishBOT
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MrFancy

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@wooden axle Has your question been resolved?

wooden axle
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Ohh got it

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junior geyser
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This is my homework I am in 10th grade - I have to give a term for the maximal possible volume of this rectanglular prism. The blue squares show the parts that have to be cut out in order to be able to fold the rest of the rectangle up in a proper manner to form a body with volume. The sides of the given squares are all the same length, x

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red turret
junior geyser
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junior geyser
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shy moth
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shy moth
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is B.del not same as del.B ?

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same with A

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a,b being vector fields

narrow plank
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Nope, B dot del is an operator

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del dot B -> div B

shy moth
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ahhh

shy moth
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A

narrow plank
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In the first term, the vector field A

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Correct

shy moth
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alr πŸ‘

narrow plank
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I wish I could explain to you how long it took me to understand that lmao

shy moth
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Lmao

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i been suffering for 6 hours to understand this bro

narrow plank
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It's weird man

shy moth
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this whole shit

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😒

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now i think i got it

narrow plank
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Yup - I remember that

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(Not all the identities) but i remember learning it

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lol

shy moth
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i dont think i dare to ask for proof

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if it took that much just to understand the result

narrow plank
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I have a great vector calc textbook i learned from

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Probably my favorite textbook of all time

shy moth
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ooh

narrow plank
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Very readable - PC Matthews - Vector Calculus

shy moth
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roger

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lemme try to find it in our library

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thank you

narrow plank
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πŸ‘

shy moth
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urban schooner
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I need help with finding the volume of a simplified model of a water bottle that consists of 3 shapes, in python.

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What I have done so far

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urban schooner
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And this is the task I'm doing:

The figure shows a simplified model of a water bottle. Note that all three shapes have the same radius, but the height may be different in the cylinder and the cone.

Create a program that calculates the volume of such a bottle. Adjust the values ​​so that your bottle contains 0.5 liters. Print a suitable text showing the total volume together with the volume of each of the shapes. Round the answer so that you only show two decimal places.

The volume formulas for the three shapes are:

Cone 𝑉=Ο€π‘Ÿ2β„Ž3

Cylinder 𝑉=Ο€π‘Ÿ2h

Sphere 𝑉=43Ο€π‘Ÿ3

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This is the print of the python code. I have reached my desired answer, but I really feel my method was wrong

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<@&286206848099549185>

restive river
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yep?

urban schooner
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Hi, you can see the problem that I posted?

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I don't know if you do python math, if not then I'm sorry for having wasted your time.

urban schooner
vague obsidian
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where is the question

urban schooner
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underneath that question there is a picture and under the picture is the task/problem

urban schooner
tardy wave
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Are you getting an error or is the math coming up with a wrong answer?

urban schooner
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I got no error, It's just I think the way I got to my answer is wrong, You can see the print of the code here.

urban schooner
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I give up, it's hopefully right

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gusty verge
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gusty verge
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Hey, how do I find the function expressions for a circle like this?

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so it's -1 +/- sqrt something i know

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i actually found it by accident but i don't know why it's correct

sonic smelt
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Are you familiar with the equation of a circle in general?

gusty verge
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so the equation for the circle is (x-2)^2+(y+1)^2=16

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yes

sonic smelt
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Ah I misread your message

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There is no function R -> R whose graph is a full circle

gusty verge
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I rewrite it as x^2-4x+4+y^2+2y+1-16=0

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there are two functions

sonic smelt
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Sure, but you can't combine them

gusty verge
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one for the upper half and one for the downer

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the task is to find the two functions

sonic smelt
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And btw it's better to keep the expressions factored there

gusty verge
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hold on

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i rewrite that again as 16-x^2+4x-4=y^2+2y+1

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and boom badabing

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12+4x-x^2 is the answer almost

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but i don't know why

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to be precise, the two functions are -1 plus or minus sqrt(12+4x-x^2)=y

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but i don't understand how that is true when 2y and 1 are still left there...

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do you have any clue?

sonic smelt
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The 2y "disappears" when you factor y^2 + 2y + 1 as (y + 1)^2

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And then take the square root of both sides

gusty verge
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hmmm

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ohhh i get it know

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thank you a lot

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good evening

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austere void
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im trying to convert from kilopond to newton, teacher told us:
1 kp = 9.8 N
1 N = 0.102 kp
and I have 9800 N
google and chatgpt told me that i should divide 9800 by 9.8, but I don't get why

gilded agate
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To convert from N to kp you multiply by 0.102

austere void
gilded agate
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1N=0.102kp
9800N=?kp

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Cross multiplication

austere void
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ohhhhhh ok thnx a lot!

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spiral dagger
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why is the answer v15?

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spiral dagger
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doesnt the v15-v15 cancel one another out?

patent marsh
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factor out a sqrt(15) and you'll see why

patent marsh
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for example, you wou'dnt say that 2x - x = 0

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youd say it's x

spiral dagger
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wait nvm

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thanks for the help

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primal relic
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primal relic
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im really confused on how to even start i worked out AB for some reason lool but i probably did that wrong too

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mehn math makes no sense

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no way some people find chem harder

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this is utter TRASH

supple knot
primal relic
sand dove
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Since OA and OB are perpendicular, what can you say about the triangle OAB ?

primal relic
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oh

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it s a right angled triangle?

sand dove
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Yes!

primal relic
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LMAO

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ok

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so

sand dove
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And the right angle is on which point?

primal relic
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uh is it the origin?

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origin o

sand dove
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Yes on point O

primal relic
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yeee

sand dove
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So right triangle in O, what's the formula for the area?

primal relic
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1/2 base x height

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or the othe rone

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1/2 ab sin c

primal relic
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bc its right angled tri

sand dove
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Both are correct

primal relic
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yee

sand dove
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But the height in this case is?

primal relic
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can it be both oa and ob?

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like it doesnt matter whgich?

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oh is it

sand dove
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Well you can choose

primal relic
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oh

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okay OB

sand dove
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But if for example OA is the base, then the height is?

primal relic
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OB

sand dove
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Yep

primal relic
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so i just need to follow through w the formula now but the thing is how do i like

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because its got a vector form

sand dove
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How do you find the length using vector form?

primal relic
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ob - oa?

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nt sure

sand dove
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Be careful as we want the length of both

primal relic
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look at the x value for one and y for the oither and times them ?

sand dove
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The formula for area, as mentionned is 1/2 Γ— length(OB)Γ—length(OA)

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How do I find the length of OB for example ?

primal relic
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oa + ab?

sand dove
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No this wouldn't be getting us anywhere

primal relic
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blobcry sorry

sand dove
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So...

primal relic
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oh

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wait

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is it

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the magnitude

sand dove
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Maybe you're more familiar with the notation ||OB||

primal relic
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OH

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ye

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the magnitude

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so you do

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x^2 + y^2 and square root

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of both

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added

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toigether

sand dove
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Except there are 3 coordinates

primal relic
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so all 3 squared added and then root of it

sand dove
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Exactly

primal relic
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ahh

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do that for both ? ob and oa and thats the length of each

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and then times them and divide by 2

sand dove
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Yes

primal relic
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AHH

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THANK YOU

sand dove
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πŸ‘

primal relic
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aight lemme try rq

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and if i mess something up like an idiot

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ill be back

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.

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YOOOOOOOOOOOOOO I DID IT

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THANK YOU SO MUCH

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mann how do i get better at maths like you

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i keep getting bs and cs in my exams and now im in my second level of a levels

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well ty for the help have a great day !!

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neat plaza
#

How would you write a direct proof by cases of this claim. I have been stuck on it for hours, I have asked for help previously but still not sure how to move forward.

neat plaza
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I know it depends on the signs of x and y

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So I was thinking case 1: where signs of x and y are the same, and case 2: where signs of x and y are different.

neon aspen
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do you know the triange inequality?

neat plaza
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I know of it from other people but no not in detail

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I don't know the proof of it either

neon aspen
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yes you can split it into cases

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this problem becomes quite easy with the triangle inequality tho

neat plaza
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I have been told that but I don't want to use something that wasn't taught

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I am also required to use a set list of reasons for each statement so I don't think I could reason that lol

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I am told to split this into cases though, with each case being 4-6 rows in length

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#

@neat plaza Has your question been resolved?

neat plaza
#

<@&286206848099549185>

devout snowBOT
#

@neat plaza Has your question been resolved?

neon aspen
#

Damn u got classes in discord?

neat plaza
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yeah

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i got 2 classes in discord

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idk why though

restive river
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I quit helping

neat plaza
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man my head hurts

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its my only assignment for the next week

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and i dont know what i am doing

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@neon aspenany help?

neon aspen
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No

neat plaza
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ok

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<@&286206848099549185> Need help

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austere void
#

From the top of a 30m building we drop a body of mass 50g that reaches the ground at a speed of 20m/s. What is the energy that has been dissipated by friction with the air?
I've tried:
Initial Em = Initial K (kinetic energy) + Initial U (potential energy)
Initial Em = (1/2)mV^2+mgh
and as at the beggining velocity = 0; Initial Em = mgh
Final Em = Final K + Final U
Final Em = (1/2)mV^2+mgh
and as at the end the height is 0; Final Em = (1/2)mV^2
and I got; Initial Em = 14700 | Final Em = 10000
and as Final Em = Initial Em + friction; 10000 = 14700 + friction; friction = -4700
but i think negative friction isn't a thing, and on top of that the solution book says that E = 4.715 J
(excuse my english, I'm spanish)

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limpid shale
#

JUST CONFIRMING

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limpid shale
#

THE ANSWER KEY IS WTONG RIGHT

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instructions were just to β€œsolve each inequality”

wicked turtle
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why do you say it's wrong?

limpid shale
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bc thats what photomath is saying

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and i got the answer photomath got

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^^this is exactly waht i got

storm storm
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thats just the same thing

wooden veldt
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Look at the part of the answer key to the right of what you circled

storm storm
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its just a different way of writing it

limpid shale
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why does it say or instead of and?

storm storm
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or is like the union

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it could be in either

wicked turtle
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"union" means "or"

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you can't simultaneously be in (-infinity,1] and in [2,3]

limpid shale
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but didnt union mean that both interval are correct

storm storm
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u combines the intervals

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so x can be in either

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this one or that one

limpid shale
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so they jus randomly chose to write out "or" instead of the union sign? even tho they mean the same thing.?😭

storm storm
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its just different notation

wicked turtle
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you use "U" with sets, and "or" with expressions

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you wouldn't say {x | x <= 1 U 2 <= x <= 3}

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you could however say:
{x | x <= 1} U {x | 2 <= x <= 3}

limpid shale
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o but in the answer key it said "or" in interval notation

wicked turtle
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oh yea i see

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yea that's a bit nonstandard for them to write it like that

limpid shale
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got itt so usually U is for interval notation and or is for set notation

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tysm :))

wicked turtle
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people will most likely know what you mean either way

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just don't say "and" when you mean "or" 😁

limpid shale
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will we ever use "and"?

wicked turtle
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yes

limpid shale
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how would "and" look in interval notation?

wicked turtle
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here's an example

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if x is in [2,4] and in [3,5], then x is in [3,4]

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because that's set of numbers that are in both intervals

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and = intersection

limpid shale
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OHHH

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LIKE THE DOMAIN THING COMPOSITE FUNCTION BS

wicked turtle
#

yea

limpid shale
#

YEAAA thanks :D

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math hurts

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adios!

#

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noble siren
#

I have used the inclusion exclusion method [ P(A or B) = P(A) + P(B) - P(A +B) ]
I cannot figure out how to rearrange for P(B) for the life of me.

noble siren
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P(A) is the theory test, P(B) is the practical test

jagged hornet
#

You have P(A). You have P(A or B) - P(A+B). Let x = P(B).

What is P(A + B) in terms of x? Solve for x.

noble siren
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ahh

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explain in a bit more detail please i'm still kind of lost

jagged hornet
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Which part are you lost on? What I said you already have? Or on solving P(A + B) in terms of x?

noble siren
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to answer the question i think its 0.75 + B right

jagged hornet
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No

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Do you know what it means for two events to be independent?

noble siren
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i believe its when they don't occur at the same time and have different probabilities?

jagged hornet
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P(A + B) is the probability of both A and B happening.

noble siren
#

alr i understand that

jagged hornet
jagged hornet
noble siren
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no i dont think so

jagged hornet
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Like how rolling a 6 and heads would be 1/6 * 1/2.

noble siren
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oh so they multiply

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OHHH

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alr i get a mistake i made

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i added both probabilities when im meant to multiply

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adding shouldnt work because it can add to more than one i think

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i still dont get how im meant to find P(B) tho

jagged hornet
#

Yup. Adding them gives you the P(A) + P(B) part of the equation. But you have to multiply to find P(A +B)

noble siren
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the expression A + B doesnt mean the literal chances added, it means the chance of both of them coming true

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yeah i misunderstood that alot lol

jagged hornet
#

I'm sure you know how to solve those.

noble siren
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correct me if im wrong, 0.47 = 0.75 + x - (0.75*x)

jagged hornet
#

You got it

noble siren
#

i can probably make x the subject from there

jagged hornet
#

just solve for x and you're done

noble siren
#

ill put my working here rq

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0.75 * x = 0.75 + x - 0.47

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oh

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if i divide by 0.75 and take away x i get 0

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πŸ’€

jagged hornet
#

P(A or B) - P(A + B) = .47
not P(A or B) = .47
that's why you got a negative probability

#

You have to fix that bit

noble siren
#

ngl i feel like i over complicated this cuz its GCSE content

noble siren
jagged hornet
# noble siren if i divide by 0.75 and take away x i get 0

That wouldn't happen, because when you divide by .75 on one side you also have to divide by .75 on the other. However, solving that version of the equation would give you a negative probability. πŸ˜…

If you get confused, my suggestion would be to clear denominators on x. For example, multiplying by 4 would have given 3x = 3 + 4x - 1.88 with the wrong version of the equation.

jagged hornet
#

So you have to subtract one more P(A+B) from both sides of your inclusion-exclusion formula to get values you know.

noble siren
#

ill draw out a probability tree so i can visualize it rq

#

the notations make it 10x harder.

#

ima go sleep πŸ’€

#

too late i cant understand it

#

.close

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lofty sinew
#

quick question for proving limits using epsilon delta definition,
im doing limt x->4 (x+2) the limit is obviously 6
and when i go to find |x-c| in f(x)-L it just goes to |x-4|=delta
is it then ok to make delta=epsilon?

lofty sinew
#

real ones rise up answer this

#

guys this problem just is NOT solving itself

#

<@&286206848099549185>

#

thoughts on this

pine rock
#

what

lofty sinew
#

ill write it out rq

pine rock
#

provide definition for a delta epsilon of a function

lofty sinew
#

sorry my mouse is a little fucking broken

pine rock
#

for any e>0 there is a d>0 : |x-4|<d => |f(x)-6| < e

lofty sinew
#

yeahy eah no i get how to prove it using epsilon delta definition

#

my only question is that normally you choose delta to equal (lets just say in this case) epsilon/3, saying that we found 3delta previously

#

it makes sense to choose that in that case

#

so 3delta = 3(epsilon/3) = epsilon

#

but in the case of my problem i had to choose detla = epsilon, then say right after that delta < epsilon

#

i just find that kinda silly yknow

pine rock
#

well, |x-4| <d => |x-4|<e if e=d

#

so we found d for any e where stuff holds

#

so why not

lofty sinew
#

ok then theres really no issue then

#

idk i just thought that the end statements in that strach work were just mildly invalidating each other

#

ig i was just confusing myself

#

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solar prism
#

Could someone double check my work on this integral?

neat solstice
#

,rotate

woven radishBOT
neat solstice
#

dv=e^-x is kinda cursed

#

you probably mean dv/dx

devout snowBOT
#

@solar prism Has your question been resolved?

solar prism
neat solstice
#

hmm

#

not really

#

i see what yyou mean though

#

with dv=e^-x we have an infinitesimal value set equal to a non infinitesimal value

#

in 99 out of 100 cases that is a bad idea

#

and that 1 case hasnt crossed my path yet

#

we have an integral over fg' and can rewrite it to
fg-int(f'g) where int is the integral
so e^-x is not dv, but dv/dx or v'

#

but the result looks good as far as i can tell

solar prism
#

Ok thanks

#

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summer dome
#

Can someone please help me with question 20?

delicate wolf
#

by using slope formula

#

y2-y1 / x2 - x1

#

we can see that the slope of the line is -2

#

since we're given the endpoint and the midpoint

#

we gotta find the left one the starting point

#

to get from mid point to end point the x value changed by 1 so we know that to get from mid to first point we also gotta change x value by 1

#

to get form mid to h x incerasedd by 1

#

so mid to g would be decreased by 1

#

and since slope is negative

#

increasing x by one would increase y by 2

summer dome
#

How should I start it then with y2-y1/x2-x1?

delicate wolf
#

sorry discord makes like math notation hard

#

when i say like y2 and x2 i mean like the x and y values of your second point

#

so if we say point 1 is H and point 2 is M

#

x1 is -3, y1 is 7, x2 is -2 and y2 is 5

#

so 5 - 7 / -2 - (-3)

#

5 - 7 = -2

#

-2 - (-3) = 1

#

-2/1 = -2

#

sorry i have no idea of how we did this

#

this was just my idea of how I'd do it without remembering like any special method

summer dome
#

What do I do after I get -2

#

<@&286206848099549185>

dapper nest
#

yes

#

@summer dome

#

what is your promblem

summer dome
#

Can I have help with 20

dapper nest
#

20?

summer dome
#

Question 20

dapper nest
#

but after 19 there is 21

#

not 20

summer dome
dapper nest
#

oh

half pawn
#

wait

pine rock
#

(-1,3)

summer dome
#

?

#

How do I do it

half pawn
#

@summer dome

summer dome
#

Is the key wrong?

#

I just wanna make sure before doing it

devout snowBOT
#

@summer dome Has your question been resolved?

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jaunty bobcat
#

what would be the quickest way to find the first zero of a polynomial to do synthetic division after doing the p over q chart

fervent birch
#

show problem

jaunty bobcat
#

its a in general question but i can give an example

#

hold on

#

Number 12

boreal herald
#

quadratic equation

jaunty bobcat
#

no bruh

#

heres the key wait

boreal herald
#

lol why not

weak cove
#

they all are of degree 4

#

so the quadratic equation does not apply

boreal herald
#

oh nvm

#

i see

#

yeah

#

my fault

jaunty bobcat
#

Like it says trial and error

#

But what would be the fast west way after doing the p over q chart to find the first zero

weak cove
#

ah I see

jaunty bobcat
#

Cause there are so many and I can’t just plug them in cause they are fractions

boreal herald
#

do you not see a pattern

weak cove
#

your question is basically, given a polynomial that is of degree >=3, how can you get those first roots so you can then use them for the polynomial long division?

boreal herald
#

2x-1=0

#

solve

jaunty bobcat
#

but yes

boreal herald
#

you're asking how to solve for the zeros instead of guessing and checking?

#

are you asking about that part or the synthetic division part

jaunty bobcat
boreal herald
#

smoke you already solved for your zeros you shouldnt need to guess and check

jaunty bobcat
boreal herald
#

you have it written (2x-1)(3x-2)(3x+1)

boreal herald
#

anything times 0 is zero

jaunty bobcat
#

i want to know how to avoid the trial and eror part

#

cause i can solve it it will just take forever if i dont guess the right zero to do synthetic to

boreal herald
#

so you are supposed to decide on your own what to divide the polynomial by

#

and you want to know how you're supposed to come up with what you're dividing by

#

instead of guessing?

jaunty bobcat
#

i know what i have to divide by because of the p over q chart, but there are so many to guesss and check

#

is there a way to use logic to narrow down some of the options for trial and error

boreal herald
#

im not familiar with a p over q chart and im not sure why youd be guessing and checking anything

jaunty bobcat
#

@weak cove can u help me

boreal herald
#

thats what trial and error is

#

lol

jaunty bobcat
boreal herald
#

oh okay you're asking how you arise to using (2x-1)(3x-2)(3x+1)

jaunty bobcat
#

i guess it is guessing and checking in a way but i want to avoid the guessing

jaunty bobcat
#

im simply asking how to avoid the trial and error part for all zeroes and maybe naroow somd down

#

<@&286206848099549185>

#

pls

#

help me

eager lodge
#

ok

#

notice that polynomials are continuous

jaunty bobcat
#

continuos as in?

eager lodge
#

the graph is connected

#

a connected curve

jaunty bobcat
#

yes

eager lodge
#

so if f(a) is negative and f(b) is positive, you know there must be a root between a and b

boreal herald
#

wouldnt the potential rational zeroes you could use be found using +- factors of the constant form/factors of the leading coefficient

#

nah nvm

jaunty bobcat
#

can you explain to me how to narrow down some of the p over q chartt zeroes i found

#

instead of trial and error all of them until i find one

boreal herald
#

he just kind of did

#

if you plug in f(a) and get a positive and plug in f(b) and get a negative then you know that a zero must occur between those two variables

jaunty bobcat
#

hold on

#

let me think about that for a second

#

so if the zeroes were 1, 1/2, and 2 and i plugged in 1 and got + and plugged in 2 and got - i would know its 1/2?

boreal herald
#

so if you plug in for example 1 into that quadratic and the answer is 2 and then you plug in -1 and the answer is -2 then you know that there lies a zero between 2 and negative 2

#

no

#

you would just know that a zero lies between those two numbers

#

somewhere between them

jaunty bobcat
#

explain it to me in contet of this problem

#

with these zeroes

boreal herald
#

but tbh i havent done synthetic in like 9 years and idk any short cuts other than just using educated guesses or more complex methods of math

eager lodge
#

makes 0 sense

jaunty bobcat
#

mb im trying to understand over text what u are meaning

boreal herald
jaunty bobcat
#

ive never heard of what u explained

#

is there a video that would explain this?

boreal herald
#

what he said is not a method of truly finding the zeros it just helps your guesses become more educated

#

and closer

eager lodge
#

it called mean value theorem I think

boreal herald
eager lodge
#

They asked for it though

boreal herald
#

well hes asking for a short cut

jaunty bobcat
#

yeah i searched it up its too complicated

boreal herald
#

but there isnt really one it will just become easier the more you do the problems youll pick up on patterns

eager lodge
#

basically imagine a line and two points, where one is above and one is below the line

#

horizontal line btw

jaunty bobcat
#

tangent thing

eager lodge
#

try to connect the points without touching the line

boreal herald
#

you have your equation g(x) = 18x^3+3x^2-7x-2 you plug in g(1) and you get 12 you plug in g(0) and you get -2

#

so that means that the graph crossed through the x axis and a zero occured between the values of 1 and 0

#

now you have a closer guess

jaunty bobcat
#

so then i try plugging in zeroes between 0 and 1?

boreal herald
#

i mean you could

#

thats one way lol

eager lodge
#

choosing midpoints would be efficient

jaunty bobcat
#

so that narrows it down to zeroes bet ween 1 and 2 though right

boreal herald
#

yes

jaunty bobcat
boreal herald
#

well it shows that a zero FOR SURE exists between 1 and 0

#

but you still need to find where it occurs

jaunty bobcat
eager lodge
#

say you know it's between 0 and 1

jaunty bobcat
eager lodge
#

and you check 0.9999

jaunty bobcat
jaunty bobcat
boreal herald
#

yeah

eager lodge
#

that doesn't really help

jaunty bobcat
#

wait what

eager lodge
#

0.999 is too close to 1

jaunty bobcat
#

oh

eager lodge
#

so their values would be close

jaunty bobcat
#

so midpoint

#

OHHH

boreal herald
#

bisection method

jaunty bobcat
#

ok thats what u meant

#

but like a mental midpoint

#

dont actually have to do the whole thing

eager lodge
#

mental?

boreal herald
#

actually

#

forget this picture

#

bad

#

bad

#

i forgot chat gpt against rules

jaunty bobcat
#

like be like "oh 0=12, 1=-2" so its closer to 1 than 0

boreal herald
#

it makes so much more sense once you take calculus i hated synthetic division

#

well you cant really assume that because its not a linear equation

jaunty bobcat
boreal herald
#

but if you know its between 0 and 2 for example then trying 1 would be a good start

jaunty bobcat
#

so just guess between that

boreal herald
#

and see how the value changes

#

yeah

jaunty bobcat
#

yay ok

#

i will try a sample probnlem

#

and let u guys know

boreal herald
#

if you wanna learn basic power rule

#

from calculus

#

you could find all your zeros like that πŸ˜„

jaunty bobcat
#

whoa

#

should i search that up

#

wait

boreal herald
#

i mean no because your professor will still probably not give you credit for your answers unless you use synthetic division

boreal herald
#

and using power rule would find your zeros without using synthetic division at all

jaunty bobcat
#

ill look into it later i guess then

boreal herald
#

you could use it to maybe double check your work if you have extra time to do some extra learning

#

but if you're crunching for an exam rn i wouldnt bother

#

just watch khan academy in that case

boreal herald
#

you and me both

jaunty bobcat
jaunty bobcat
boreal herald
#

about to be 1 am

#

have an actuary science exam at 10 am

#

which isnt really science its just math

jaunty bobcat
#

thats like college stuff

#

damn

#

its almost 12 am for me so hopefully only another hour and a half

#

gotta wake up at 6

boreal herald
#

yeah im a senior in college tryna just get my mathematics minor

jaunty bobcat
#

cool which college?

boreal herald
#

if you need any help with other topics lmk i can maybe give u some short cuts but synthetic is pretty out of my mind at this age

#

UNC

jaunty bobcat
#

chapel hill?

boreal herald
#

yessir

jaunty bobcat
#

aye w thats a great college

jaunty bobcat
#

ill solve sample problem with the new trick and post it here in a minute

boreal herald
#

yeah tbh still not really sure i understood your question or helped at all but you tryig to work one out would probably help

jaunty bobcat
#

alr it worked

#

it helped a bit i think

#

hopefully teacher doesnt throw a long ass question at me i should be fine

#

these texas teachers are crazy though

#

thanks

#

.close

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#
Channel closed

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Use .reopen if this was a mistake.

jaunty bobcat
#

.reopen

devout snowBOT
#

βœ…

jaunty bobcat
#

.close

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vestal lance
#

Why is lhs = rhs?

devout snowBOT
vestal lance
#

Shouldn’t the max value attained in lhs be different because of the squared norm?

wicked turtle
#

note that x/||x|| is a unit vector, and so is x^T/||x||

vestal lance
#

Ok, thinking through this

vestal lance
#

Thanks

#

.close

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gaunt wing
devout snowBOT
gaunt wing
#

Can someone please tell me what I’m doing wrong?

#

<@&286206848099549185>

devout snowBOT
#

@gaunt wing Has your question been resolved?

dapper nest
#

yes

#

@gaunt wing

devout snowBOT
#

@gaunt wing Has your question been resolved?

gaunt wing
#

hi

dapper nest
#

yes

restive river
# gaunt wing

can you write it a bit clearly? its almost unreadable

devout snowBOT
#

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slender stone
#

what's up with the last sentence?

devout snowBOT
slender stone
#

for power rule, i can imagine that one limit exists and another doesn't, but "all limits involved exist" also applies to the rest of the rules

manic condor
#

Well, for root rule - if n is even, f(x) has to be non-negative. Right?

slender stone
#

yup that makes sense

#

so the last sentence is just for the seventh rule?

zenith jacinth
slender stone
#

what's not a rule?

#

.close

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atomic trench
devout snowBOT
atomic trench
#

what is third quadrant

pine rock
#

where x and y are negative

atomic trench
#

Thanks I will try it then send my working

#

a<-12c

#

so if c=1 then a should equal -13

#

Would this be correct

#

b<-4/5 so that means b can equal negative one

restive river
#

Well it wouldn't necessarily equal something. You could say that a < -12, so it could be -13 but also smaller

atomic trench
#

yes

#

I chose that particular soloution

#

I think it works

#

a=-13, b=-1, c=1

pine rock
#

u can just do a=0, b=0, c<0

atomic trench
#

true

#

.close

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wooden axle
devout snowBOT
wooden axle
#

x^2-3x+2<x^2+x+2

mystic scarab
#

No

#

What is 0 β€’ (xΒ² + x + 2)?

wooden axle
#

Ohh

#

x^2-3x+2<0

#

Done

mystic scarab
#

Awesome πŸ‘

wooden axle
#

2,1 roots

#

Let me check it

#

Option A

#

1.5 satisfied

mystic scarab
#

Yes option A is indeed correct

wooden axle
#

.close

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#
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dire hinge
devout snowBOT
dire hinge
#

explain someone pls

rugged sparrow
#

1cm^3=1ml

dire hinge
#

?

dire hinge
dire hinge
rugged sparrow
#

"1 centimeters cubed is equal to 1 mililiters"

dire hinge
#

but isn't a centimeter larger than a millilitre

rugged sparrow
dire hinge
red turret
#

centimeter is larger than a milimeter

#

dont compare it with litre

rugged sparrow
dire hinge
#

what is the conversion factor?

rugged sparrow
#

1 cm^3 = 1 ml

dire hinge
#

wbt others

rugged sparrow
#

conversion factor =1

dire hinge
#

is this the only factor?

rugged sparrow
#

like wdym?

dire hinge
#

like what would 1ml^3 equal to?

rugged sparrow
#

we can use the basis that 1 cm^3= 1 ml to derive relation in other units
1 cm=(1/100)m
1 cm^3 =(1/100)^3 m^3
1 cm^3=(1/1000000) m^3
thus, 1 m^3=1000000 ml= 1000 L

rugged sparrow
#

a cube has its volume as s^3. So, if the side is 2 cm, then the VOLUME is 8 cm^3

#

Now can you imagine that we measure side length in mL?

#

WE CAN'T

dire hinge
#

then how does the conversion factor come up?

#

how does 1cm cubed= 1mL

rugged sparrow
#

well, consider a cube of side length 1 cm.
It would occupy 1 mL space of volume
but its volume is also given by s^3 which is 1 cm^3

#

thus 1 cm^3= 1 ml

#

in general, this is the only relation that you pretty much need to remember

dire hinge
#

oh I see

#

so back to this

#

how would we do this?

rugged sparrow
#

did you get that we can write 2000 cm^3 as 2000 mL?

dire hinge
#

ohhh

#

because they equal

#

and 2000mL=2 tones right?

rugged sparrow
#

no

#

1 L = 1000 mL

dire hinge
#

yes

rugged sparrow
#

2000 mL = 2*1000 mL

dire hinge
#

so how many mL in a ton?

rugged sparrow
#

mL and ton are not related

dire hinge
#

yes ok

#

so what is the answer?

#

alright yes I get it now ty

#

.close

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rapid spire
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quick horizon
#

hi

devout snowBOT
devout snowBOT
rapid merlin
quick horizon
#

BECAUSE I never understand algebra basics

eager lodge
#

there's always youtube

red turret
#

since they have no question regarding maths, closing this.

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cosmic lake
devout snowBOT
cosmic lake
#

someone please help

#

d and e in the first row

#

and the question is

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"find the maximum and minimum values of the following"

rocky iris
#

,rccw

woven radishBOT
devout snowBOT
#

Show your work, and if possible, explain where you are stuck.

restive river
#

1-3cos(theta) is biggest where cos(theta) is smallest

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And vice versa

cosmic lake
#

idk what to do when the square is involved tho

agile tide
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do u know sin^2 graph?

cosmic lake
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and when it becomes a fraction

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no

restive river
#

Well x^2 will be maximum when the magnitude of X is maximum

agile tide
#

at least for e, the rationale should be the bigger the denominator, the smaller the overall frac

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and smaller denom = bigger fraction

cosmic lake
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how would i f ind Max and min tho?

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answer says max=1 and min =1/3

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makes no sense tho

agile tide
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for e?

cosmic lake
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yep

agile tide
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what's the biggest possible value for cosx

#

whats the smallest possible value for cosx

cosmic lake
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1?

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-1

agile tide
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yeah right so plug that into the formula

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and wam bam

cosmic lake
#

ohhh

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yes

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wambam

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that is so right

agile tide
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u just wanna look for the extremities

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congrats

cosmic lake
#

πŸ‘πŸ‘πŸ‘πŸ‘

#

thank u

#

i will solve everythingelse now

#

.close

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dire mirage
#

how do I find the common ratio for this

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jolly bluff
devout snowBOT
jolly bluff
#

how do I even solve this

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I am pretty sure im supposed to rerange it

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but im confused on how

jolly bluff
#

<@&286206848099549185>

eager lodge
#

use this

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$\frac{ds}{dt}=\lim_{h\to 0}\frac{s(t+h)-s(t)}{h}$

woven radishBOT
#

WhereWolf(ping if needed)

eager lodge
#

you get this by letting a=t+h

restive river
jolly bluff
eager lodge
restive river
jolly bluff
#

I want to try and understand before I submit the answer

restive river
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sorry

#

differentiation

jolly bluff
#

oh

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Idk what that is

restive river
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so basically the huge ass formula they wrote is nothing but saying that if you differentiate the displacement equation given, u get the velocity

#

u find the velocity by differentiating the displacement and just plug in t=2 and since 4.9 is a lame number and u got the option of nearest integer, u can take 4.9~5 and plug in 3 to get the answer

jolly bluff
#

what is d supposed to be

restive river
#

read it the qn a few more times to understand it

restive river
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u know differentiation right

jolly bluff
#

no

restive river
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oww thats a problem

jolly bluff
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yes

restive river
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u gotta learn differentiation first to solve this

jolly bluff
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isnt that later in calc tho?

restive river
#

and it isnt something u can understand by me writing

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yup

jolly bluff
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bruh why tf is it on my calc hw lol

restive river
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u know limits?

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lol

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u know it?

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slice bro

jolly bluff
#

ye

restive river
jolly bluff
#

we are doin that now

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I cant even

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its asynch class

restive river
#

then i guess its not unusual to have that

jolly bluff
#

and the teacher is like fuckign 1000

restive river
#

nope

#

man this is a proper qn

jolly bluff
#

wym

restive river
#

u gotta go the tough way to solve this then

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just solve the limit

jolly bluff
#

how

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oh

restive river
#

lol

jolly bluff
#

one sec let me draw smth

#

and tell me iF i HAVE THE the right idea

restive river
#

yup u do ur thing and ill take some time to tell u the steps

#

well i got it

#

its easy the limit way as well

jolly bluff
restive river
#

yup yup yup

jolly bluff
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ok good

restive river
#

absolutely right

jolly bluff
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thx 😏

#

what do I do now tho

#

do i multiply by (3+t)/(3+t)

restive river
#

wait bro

#

smth is wrong

jolly bluff
#

damn

restive river
#

a not =3

jolly bluff
#

really

restive river
#

do as i tell u

jolly bluff
#

it says t = a

restive river
#

wait

#

just do as i tellu

jolly bluff
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ok

restive river
#

ill explain later

jolly bluff
#

ok

restive river
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first put t=a in the expression given

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ok?

jolly bluff
#

wat

restive river
#

write f(a) i mean

jolly bluff
#

ogh

restive river
#

done?

jolly bluff
#

f(a) = t

restive river
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omg

#

no man

jolly bluff
#

f(a) = f(t)

restive river
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no bro wait listen to me

jolly bluff
#

ok

restive river
#

replace t with a in the eqn and name it f(a(

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f(a)

jolly bluff
#

ok ojne sec

restive river
#

like f(a)= expression with a in place of t

#

send me a pic after u got it

jolly bluff
restive river
#

yup

jolly bluff
#

k

restive river
#

now simplify this shit

#

i mean cancel the unnecessary terms

jolly bluff
#

like 500?

restive river
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u get what i mean right?

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yup

#

u got it

#

send me a pic

#

it should be very easy from here

jolly bluff
restive river
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yup

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bro

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u screwed up

#

check this step again

#

u made a mistake

jolly bluff
#

k one sec

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oh

#

did I feorget the negative

#

I added it

restive river
#

pic?

jolly bluff
restive river
#

take 4.9 common after removing minus

jolly bluff
#

wym

restive river
#

brackets i mean

jolly bluff
restive river
#

yup

#

now do ur thing

#

cancel a-t

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up and down

jolly bluff
#

oh so its just a - t?

restive river
#

dont forget the 4.9

#

its -4.9(t+a)

#

check it again if u dont get it

jolly bluff
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where did the 4.9 come from

#

didnt it get cancelled out

restive river
#

bro

#

no it didnt check it again

#

msg me after u get it

#

dont rush take it slow

jolly bluff
#

isnt -4.9 - (-4.9) = 0?

restive river
#

yup it is and u take 4.9 common not cancel it

jolly bluff
#

oh

#

like 4.9(a^2 - t^2)

#

?

restive river
#

yup yup

#

yup

#

u got it

#

?

jolly bluff
restive river
#

yup

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now cancel the a-t

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up and down