#help-27

1 messages · Page 105 of 1

feral sun
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its just all that stuff confused me

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and also what is this?

dire forge
woven radishBOT
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propERICly_embedded

feral sun
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yes

dire forge
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This is very similar

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It's just saying "take the union of all the B_is"

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where i ranges over all the elements of I

feral sun
dire forge
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So if (I = {1,2,3}), then
[\bigcup_{i\in I}B_i = B_1 \cup B_2 \cup B_3]

woven radishBOT
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propERICly_embedded

dire forge
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so the union of B_i where i ranges over I

feral sun
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ohhhhhhhhhh

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wow

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thank you

dire forge
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the advantage of the notation on the left hand side is that I can be infinite!

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whereas if I is infinite, we can't use the notation on the right hand side

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it only works for finitely many sets in the union

dire forge
feral sun
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ok i think ive got it all but i just want to know, when they put something like i belongs to I or i belongs to all natural numbers under an intersection or union or a summation like you showed me, is it just trying to show that there is an infinite amount of like possibilities?

dire forge
feral sun
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ok so its just like an example

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as in, i wouldnt see this in an actual problem

dire forge
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yup yup, it doesn't have to be the natural numbers N, it can really be any set that you're taking the union over

feral sun
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so if it said like i belongs to all natural numbers in the proposition, would it be all natural numbers as well as whats in A?

dire forge
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i has nothing to do with A

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i ranges over I

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but if you chose I to be the set N of all natural numbers, then you would get one set for each natural number so B1, B2, B3, B4, ... (infinitely many sets B_i)

feral sun
dire forge
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the important thing is that for each i in I, you have one set B_i

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and you take the union of all the B_i's as i ranges over everything in I

feral sun
#

so you mean that i refers to anything in I?

dire forge
woven radishBOT
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propERICly_embedded

dire forge
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we call i a "dummy variable" since it's just a notational convenience to express the sum

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similarly i in this proposition is a dummy variable so we can give each of the sets B_i different names

feral sun
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i see

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so is the use of “dummy variables” only in stuff like propositions and theorems?

timber pebble
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you could call it i or j or k or anything you like

feral sun
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or would i come across this in a problem

timber pebble
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i can see getting this problem in a basic proofs class

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prove that the thing you posted is true

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so sure

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in math you see dummy variables all the time

feral sun
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oh ok

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well then i think thats all for now im too tired for more math but thank you both lots for the help

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vital hearth
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Hi, I need help factoring out the numerator to where i can get an x-1 on both the top and bottom to find be able to find the limit.

vital hearth
chrome granite
vital hearth
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yes i do. but when i try to factor by forcing the (x-1) on one of the sides i dont get a number that adds up on the other. unless im just missing something entirely

winter torrent
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you can tell if x-1 is a factor of the top

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by evaluating at x=1

vital hearth
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oh i think i see what i did wrong.

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so i assumed that since the bottom equaled 0 i had to start factoring the top, but since it all equals to 2/0 rather than 0/0 that would mean DNE?

winter torrent
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yeah

vital hearth
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awesome thanks so much, i completely over looked that rule

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wooden axle
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wooden axle
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I did not understand the question properly hence no idea to solve in which direction.

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<@&286206848099549185>

empty flame
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hey arjunn how are you

wooden axle
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Ohh i got it

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Solved

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Dot product solution

empty flame
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ohhh ok

wooden axle
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Btw Hello

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It's been a long time to talk with you

empty flame
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hello

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yea its been a while

wooden axle
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How are you doing?

empty flame
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how are you doing in these days

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i am fine hbu

wooden axle
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Ahh I am reading, learning each day

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Random stuffs

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Some graduated topics and some high schools topics

empty flame
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ohhh

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what topics

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are they all math

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wooden axle
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If three points are given in 3d what will be the shortest way to find in what ratio second point is dividing if they are collinear?

wooden axle
grizzled yew
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Distance formula is easy

pseudo basin
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find distances AB and BC and divide one by the other

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it takes a total of:

  • 6 subtractions
  • 4 additions
  • 6 multiplications
  • 1 division
  • 2 square root extractions
dire forge
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damn, you actually counted lol

pseudo basin
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yes i did

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specifically because arjunn is so concerned with speed

dire forge
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you could also divide just the change in one of the coordinates, if you know they're colinear

pseudo basin
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you could, yeah.

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i assume myself not to.

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but if you trust that, then it's only 2 subtractions and 1 division.

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which is about six times quicker at the expense of reduced certainty.

pseudo basin
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@wooden axle

wooden axle
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Yes i am

pseudo basin
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that is how many times you will have to do each operation.

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i counted it up for you.

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it is not relevant for your work.

wooden axle
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What should I do after AB BC

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You wrote divide one by other...what does it mean?

pseudo basin
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divide distance AB by distance BC.

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i mentioned two things, then the words "one" and "the other" refer to those same things in the same sentence.

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i guess you are also learning some English on top of the math.

wooden axle
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√56/√126

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I got this

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AB/BC

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Let me simplify

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√28/63

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What next should I have to do with this?

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I don't think you have dropped enough information for me to do even you are fluent in English

wooden axle
wooden axle
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No problem. Have fun
.close

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chrome badger
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hii, is C a proper subset of A if
C={ 2} and A={1, {2}, √2}? it is, right?

wooden veldt
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is every element of C, also an element of A?

wooden axle
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It's not proper

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Read the definition of it. Let me drop it

chrome badger
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it should be C= {{2}} to make it proper?

wooden veldt
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that would be a proper subset of A yes

wooden axle
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A proper subset of a set A is a subset of A that is not equal to A.

wooden veldt
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your original C is not even a subset

wooden axle
chrome badger
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thank uuu

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vestal notch
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vestal notch
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Can someone help me don't know where to start

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winter patrol
#

questions are cut off,
also seems like clear explanations of the answers are given

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gilded wigeon
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gilded wigeon
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am lost

weak cove
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Tangent is pi periodic

gilded wigeon
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im not sure what that means

lyric hornet
woven radishBOT
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MrFancy

gilded wigeon
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ohhh right so its the same, and 2pi + theta is also the same no?

lyric hornet
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$\ldots=\tan(2\pi+\theta)=\tan(\pi+\theta)=\tan\theta$

woven radishBOT
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MrFancy

gilded wigeon
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thank you sm mrfancy

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lyric hornet
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restive river
devout snowBOT
open portal
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multiply?

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x∈R and y∈R?

restive river
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I never tried multiplying

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😅😅

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Thought i might had to do something else

open portal
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try

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if u multiply it look easy

restive river
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@open portal

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Sorry for my ugly hand writing

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I used the elimination method

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Did i do anything wrong

open portal
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ok

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wait

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looks good

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coarse crow
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For this type of question

devout snowBOT
coarse crow
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why are the answers always 1 term

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like this

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Shouldnt it be sqrt(z) = sqrt(|z|)cis(x/2) or sqrt(z) = sqrt(|z|)cis(x/2 + pi)

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I can think of 1 explanation, however i don't know if it is right:

the argument being x/2 shows that for any real values substituted for 'theta,' or x in my case, both roots undergo this division of 2. In summary, the angle shown that is divided by 2 represents the all of the angles from all of the roots.

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Please ping btw

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copper hatch
devout snowBOT
copper hatch
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Answer sheet states y - x + 1

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Wouldnt that be Log3/2 + 1?

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2.5?

grizzled yew
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Covert 1 to log

copper hatch
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I don't know what you mean by that?

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as in log_x(X)

grizzled yew
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1=log_10(x)

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What’s x

copper hatch
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10?

grizzled yew
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Now use the addition rule

copper hatch
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ohh

grizzled yew
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log(3/2)+log(10)=??

copper hatch
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3/2 × 10

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= 15

grizzled yew
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Yep

copper hatch
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Gotcha

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Alright that makes sense

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cheers

grizzled yew
copper hatch
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untold crow
#

$z^{3}=-1+i$, $z=\sqrt[3]{-1+i}$

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woven radishBOT
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HqppyFeet

untold crow
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hmmm.. haven't done this type of cube root before... I know that one of the cube roots of -1 is -1, but... -1 + i? That's a different thing... can someone give me a hint as to what to do?

round lava
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first you want to find one root

untold crow
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yup

round lava
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so you need to find a complex number (a+ib) so that (a+ib)^3 = -1+i

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where a,b are real

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wihch you can hopefully just do algebraically

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actually converting it to polar coordinates might be easier

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sry

winter torrent
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polar coordinates will make this substantially easier

untold crow
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i was thinking that xD

round lava
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yeah irealised

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lol

untold crow
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i was like... am i really going to do a+ib)^3

round lava
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not an analyst :)

untold crow
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xD anyway, yeah i am familiar with z = r(cis(x))

winter torrent
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instead of writing it like that

untold crow
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I found the modulus and argument. 2 and -pi/4 respectively

winter torrent
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write it as $z = re^{i\theta}$

woven radishBOT
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hayley!

winter torrent
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uh -pi/4 isn't right for the angle

untold crow
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yeah both ways work, i tend to use cis but yeah

winter torrent
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but cis is easier to write in text so

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and neither is 2 right for the radius

untold crow
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hm-? $arg(-1+i) = tan^{-1}\frac{1}{-1}=-45\circ$

woven radishBOT
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HqppyFeet

untold crow
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-45 degrees in rad is -pi/4. what did i do wrong?

winter torrent
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ok this is why blindly applying arctan is bad

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consider what -1 + i looks like on the complex plane

untold crow
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🫠

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well in argand diagram? oh yeah it would be in the second quadrant.

winter torrent
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yeah

untold crow
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woops

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ok im getting a bit confused as to when i can use arctan here--- simply copied a text book, apologies

winter torrent
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my recommendation? until you're very comfortable with it, just draw a quick sketch

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so what angle should you actually have?

untold crow
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135, or 3pi/4, right?

round lava
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👍

untold crow
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and the modulus is sqrt(2) i realized

winter torrent
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yeah

untold crow
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well nice, with e^(ix), argument, and modulus, I can simply do (re^(ix))^(1/3) and adding 2pi after each answer will give me the three roots. aight this sounds good

untold crow
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Yeah.
r^(1/3) * cis(pi/4) for first root.
r^(1/3) * cis(3pi/4) for second root.
r^(1/3) * cis(5pi/4) for third root.
Is this correct?

winter torrent
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seems right

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wait

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yeah

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wait

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sorry

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3pi / 4 * 3 = 9pi / 4 = pi/4

untold crow
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cis(pi/4) was acquired through cis(3pi/4)^(1/3), then applying de Mouivre's theorem, => cis(3pi/12) => cis(pi/4)

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(I hope my thinking is correct lol, this feels like familiar territory)

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nvm, found out that r^(1/3) is 2^(1/6)

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wait a minute, answer sheet says " $2^{\frac{1}{6}}(cos(\theta)+isin(\theta))$ where $\theta = \frac{\pi}{4}$, $\frac{11\pi}{12}$, $\frac{19\pi}{12}$ "

woven radishBOT
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HqppyFeet

untold crow
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bruh what... do they add 2pi into theta before the (1/3) exponent is applied in cis(3pi/4)^(1/3)?

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Sure looks like it

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cos(3pi/4), so that cos(3pi/4 + 8pi/4).... mhm

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narrow jolt
#

How do i do this

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jaunty musk
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You replace x by x+h in f, subtract it with f(x), then divide the whole result by h

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If you tend h to 0, you unfortunately don't get the derivative, so there is a mistake somewhere for sure

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Now it's for you to find it. Look back at your computations

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There should be something wrong

narrow jolt
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oh okay

jaunty musk
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Look closely at your h terms in the numerator

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Me goofed you didn't see anything

narrow jolt
#

I don't get it, I think I do (x+h)^2 and -5(x+h) +6 which gives me x^2+h^2-5x-5h+6 and then subtract by f(x) which makes it h^2-5h over h

winter patrol
#

(x+h)^2 isn't x^2 + h^2

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ripe finch
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ripe finch
#

Guys reap quick is this correct

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Real*

chrome granite
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Which one

ripe finch
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i dont understand d h and j

chrome granite
ripe finch
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but can u explain

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bz these are my classmates answers

chrome granite
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there is a hollow circle at -3 on the graph of h

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that means -3 isn’t in the domain of h

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so h(-3) doesn’t exist

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can you see why h(2) also doesn’t exist?

ripe finch
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ohh

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there is a circle there too

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and doesnt exist in domain

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what about h(1) theres a jump here

chrome granite
chrome granite
ripe finch
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yes sorry

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also if there are two circles there it means it wouldn't exist

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then*

chrome granite
ripe finch
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hollow circles

chrome granite
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I don’t see 2 hollow circles at the same y coordinate on the graph

ripe finch
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yes

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like IF

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there were on h(0)

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two hollow circles except one filled and one hollow

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then the answer should be DNE

chrome granite
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yes

ripe finch
#

thx my dude

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restive river
devout snowBOT
restive river
#

Need help on number 11

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Don't know if its arithmetic or geometric

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solved

ripe finch
#

in geometric its multiplied here in the question

1 4 9 16
+3 +5 +7
+2 +2

so i assume its arithmetic

restive river
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wrong

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i asked chat gpt

ripe finch
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damnn how tho

restive river
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dunno

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oh wait

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its because arithmetic is only fixed

ripe finch
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ur right

main gull
restive river
main gull
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Because chatgpt is garbage at math

restive river
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no its not

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when is the last time you used chat gpt

main gull
silver fjord
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it's not meant to do math. gpt4 may be better than the free version but it was not intended to do math problems

supple knot
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dire forge
#

.reopen

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main gull
dire forge
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ChatGPT is unreliable at math, yeah

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But anyways

dire forge
#

Do you know the definitions of arithmetic and geometric?

restive river
dire forge
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Okay so is the sequence arithmetic? What do you think

restive river
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noooooooooooooooooooooo

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its not fixed

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its 1,4,9,16

dire forge
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what's not fixed?

restive river
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the difference in terms

dire forge
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Yeah exactly

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Is the sequence geometric then?

restive river
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Could be

dire forge
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How could you check?

restive river
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equation

dire forge
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what equation?

restive river
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geometric

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equation

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qtin

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eqtin

dire forge
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can you write out what equation you mean?

restive river
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ya

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$a_n=a_1*r^{n-1}$

woven radishBOT
#

intracatholic

dire forge
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Yup, how can we check if this sequence satisfies that equation?

restive river
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1,4,9,16

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we plug

dire forge
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Try it out

restive river
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ok

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1 goes in the place of a_1

dire forge
#

right

#

what next?

restive river
#

ratio

#

right

dire forge
#

what about the ratio? ratio of what?

restive river
#

of two terms

dire forge
#

what can you say about the ratio for this sequence?

restive river
#

it aint the same for every consective term

dire forge
#

yup, what ratios do you get?

restive river
#

4/1

#

is 4

#

4/9

#

is

#

9/4 is

#

somet

#

and 16/9

#

is somt

dire forge
#

right so the important thing is 4/1 and 9/4 are not the same

#

so is the sequence geometric?

restive river
#

it quadratic

dire forge
#

that's true, but is it geometric?

restive river
#

nuh uh

dire forge
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frozen dune
#

why is n^2 = -0 (for n ≠ 0) on the sedenion multiplication table

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devout snowBOT
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@misty spoke Has your question been resolved?

red turret
#

dont ping the helpers multiple times.

#

you can, but dont spam ping

#

sigh

finite briar
#

.close

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red turret
#

bruhhh

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#

red turret
#

<@&268886789983436800> deal with this

#

being too impatient

finite briar
zenith jacinth
#

bro is mad

red turret
#

we are not entitled to help you.

finite briar
#

STOP FUCKING SPAMMING

zenith jacinth
#

bro thinks we are paid to help

finite briar
#

!community

restive river
true dew
#

Hi

finite briar
#

!volunteer

zenith jacinth
#

if we dont want to help you, we wont lol

red turret
#

!volunteers

devout snowBOT
#

Helpers are just people volunteering their time to help you. Be polite.

restive river
#

Go google

finite briar
red turret
#

sorry mods

#

.close

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mystic scarab
#

<@&268886789983436800>

devout snowBOT
#

restive river
#

@valid fern

red turret
#

.close

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#

zenith jacinth
#

he thinks he will get help like that lol

restive river
#

Beo gone mad

mystic scarab
#

.close

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#
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red turret
#

dont feed him

restive river
#

.close

west ridge
#

What a degen

devout snowBOT
#

true dew
#

I need help in math

zenith jacinth
buoyant furnace
#

what just happening

karmic abyss
restive river
#

😂😂

zenith jacinth
#

aight bye dude

true dew
buoyant furnace
#

dude

restive river
#

10 year old mindset

red turret
#

already banned

restive river
#

Banned from thy hearts

#

Wow, so impatient

west ridge
#

He came Into my help box spamming his shit to lol

buoyant furnace
#

same lol

red turret
#

.close

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#
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restive river
zenith jacinth
restive river
#

I mean yeah have to help MORE 🙆

red turret
restive river
#

Why doesn't the bot detect this convo as a new question?🤔

red turret
#

the channel's not open yet

restive river
#

Oh

#

I've seen you alot, you go "sigh . close"

red turret
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ionic swift
#

given f(x) I am supposed to determine if f is a pdf. Now I know that it is but I dont understand why it satisfies the condition that the integral from -inf to inf of f(x)dx = 1.
In my books solution it says because the sum from 0 to inf of 2^(-x) = 1. But how does this explain this ?

ionic swift
#

thats what's in my book regarding that exercise

pseudo basin
#

one moment

ionic swift
#

I understand that convergence and I have already seen it before. I just dont understand why that is the explanation to why said criteria is satisfied

pseudo basin
#

i graphed your function

#

and even had desmos shade the area under it

ionic swift
#

oh lol sorry I thouhgt you graphed the sum

pseudo basin
#

i graphed the actual function

#

whose integral is composed of rectangles of width 1

#

so its integral is the sum

ionic swift
#

ohhhhh

#

now I understand

#

but like

#

no wait

#

I am just a bit confused because I feel like in order to solve this I had to be familiar with that exact function to know how it behaves

#

but in my book they just taught to take the integral

#

and I wouldve done something like this (one second)

pseudo basin
#

your function isn't 2^-x

#

it's 2^-ceil(x) essentially

ionic swift
pseudo basin
#

$2^{-\ceil{x}}$

woven radishBOT
ionic swift
#

why the ceil ?

#

where does that come from

vernal monolith
#

Well notice that your function is in terms of k not and x @ionic swift

#

Its 2^(-k)

#

And ceiling of x gives k, thats why

ionic swift
ionic swift
vernal monolith
#

Well for example if x=1/2

#

x would get rounded to 1

ionic swift
#

oh so

vernal monolith
#

When input to 2^(ceil[x])

ionic swift
#

because in general x would be in R ?

#

oh damn

#

right

#

now I understand

#

big thanks to both of you

vernal monolith
#

I did nothing but you're welcome

ionic swift
#

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heady coral
#

Hi, I'm trying to solve this linear congruence, I watch a bunch of videos and I still don't understand the final step :c
This is what I did, I don't know how to continuous, I find the value of s which solve this equation 1 = 1993 * s + 990 * t, where 1993 is the result of 9965/5 (5 = gcd(9965,4950)), and 990 is the result of 4950/5

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heady coral
#

<@&286206848099549185>

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fluid laurel
devout snowBOT
fluid laurel
#

Hello I need help with solving this equation , but I can't understand how to start

heady current
#

u can start by getting both the terms on the same denominator

fluid laurel
#

what do you mean by that

heady current
#

try to get the denominator of 3/x to 5x

fluid laurel
#

I get it

heady current
#

like how u add fractions

fluid laurel
#

I worked with it, but it is still wrong, i don't know where I went wrong

heady current
#

u dont need to get the denominator to 5x²

#

find the lcm

#

get it to 5x

fluid laurel
#

I found it, I wrote 6 instead of 16

#

thanks for helping

#

@heady current ++

heady current
#

np

fluid laurel
#

.close

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fluid laurel
#

.reopen

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#

fluid laurel
heady current
fluid laurel
#

Thanks for helping out,

#

.close

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heady current
#

np

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frozen dirge
devout snowBOT
frozen dirge
#

Could u help me with this please

warped relic
#

Hey did you try it out?

frozen dirge
#

Yea I've been unable to do it tho

warped relic
#

Well your goal is to make T alone on the left hand side

frozen dirge
#

I've tried by first expanding the bracket but idk how to get it on its own

warped relic
#

I suggest you treat the question like an onion

#

You start by peeling the first layer

#

Which right now looks to be the r multiplied by the squared brackets

#

How do you get rid of a number being multiplied?

frozen dirge
#

Divide it by itself?

warped relic
#

Yep and to keep the equation from changing, what do you do to the right side when you divide the left side by r?

frozen dirge
#

Wouldn't it just be r^2 x r at the bottom of the right side then

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vast violet
#

How to factor that 9x^2-25

devout snowBOT
vast violet
#

do i take sq root of it

winter torrent
#

difference of perfect squares

vast violet
#

Oh

#

Oops

#

So (3x+5)(3x-5)?

#

perfect thnx

#

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silent briar
#

Can someone help me prove this

devout snowBOT
silent briar
#

This is logic

#

Blue is what needs to be proven

#

I can only use basic propertiws

#

Is that true?

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supple knot
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delicate phoenix
#

3x3

devout snowBOT
sonic smelt
#

What's your question?

open portal
delicate phoenix
#

What's 3x3

dense jay
#

unsure

delicate phoenix
#

6 right

sonic smelt
#

,w 3 * 3

sonic smelt
#

.close

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lofty obsidian
#

How do i find the limit of (x approaching 0) for the equation: (x-1)/((x^2)(x+5)) ? I know the answer is negative infinity and got to the equation "((1/x) - (1/x^2))/(x+5)" but am not sure where to go from there.

open portal
#

$\frac{x-1}{x^3+5x^2}$

woven radishBOT
#

binibini

open portal
#

1 s

lofty obsidian
#

ok tysm

#

hello, are you there?

open portal
#

for now

#

i dont know

lofty obsidian
#

ok can u get me another person ToT

open portal
#

<@&286206848099549185>

#

x-1/x^2 * 1/x+5

#

$\frac{x-1}{x^2} * \frac{1}{x+5}$

woven radishBOT
#

binibini

open portal
#

left side -infinity , right side 1/5

#

but i m not sure solution

lofty obsidian
#

ok thank u

devout snowBOT
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lofty obsidian
#

.close

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visual basin
devout snowBOT
visual basin
#

what does deltax = x

#

means

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visual basin
#

.close

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reef carbon
#

I don't understand what I'm supposed to do here

hybrid snow
#

Use differentials

#

Or linearization

reef carbon
#

what

hybrid snow
#

Use linearization (using the tangent line at x = 0)

reef carbon
#

i dont know what that is

hybrid snow
#

You don't know what a tangent line is?

reef carbon
#

"linearization"

hybrid snow
reef carbon
#

okay well im still confused

#

do you want to elaborate

hybrid snow
#

Find the equation of the tangent line at x=0

#

Start with that

#

Let that line be L(x)

#

Then F(7) ≈ L(7)

supple pasture
#

Do you know about Taylor polynomials because that will give us better approximations

hybrid snow
#

I mean theres multiple ways

#

Taylor

#

Euler's

#

Easiest to do is linearization

reef carbon
#

im honestly kinda confused on the first method you gave, can you like explain that

hybrid snow
#

Do you know what a tangent line is

reef carbon
#

yes

hybrid snow
#

,tex \linearization

woven radishBOT
#

Umbraleviathan

hybrid snow
#

x0 is where the line is tangent to

#

now ive explained it already so im just gonna run in circles again

#

L(x) is your tangent line. Linearization is using L(x) to approximate values around x0

#

so F(7) is approx L(7)

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#

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cyan axle
#

I don’t know what I’m doing at this point

devout snowBOT
cyan axle
#

This is the new one can I get some help with it

#

This is the answer I came up with

candid timber
#

Try and graph both the functions.

cyan axle
#

?

crude valley
#

vertical shift isnt inside the sqrt function

#

thats only for horizontal

cyan axle
#

….

cyan axle
#

I’ve had like nine of this stuff in the resources my prof gave me

#

None*

crude valley
#

yeah kinda like this 1s

#

like this

#

but it goes for any graph

cyan axle
#

Yeah I haven’t even seen that before so I gotta watch a whole video on it

#

How do I do this?

#

I know that it wants me to find the Y value but why is there two?

#

The video connected to it isn’t even close to the problem

#

Like for the first one I just get -4 and -2

#

I legit tried bullshitting but can I get an explanation on why it flip and flops between the two expressions?

#

Oh shit I’m stupid

#

It’s the damn rule in the right

#

.close

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#
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shadow quest
#

Why is a double integral on a region D in the first quadrant which its value is negative is not possible

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#

@shadow quest Has your question been resolved?

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@shadow quest Has your question been resolved?

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#

@shadow quest Has your question been resolved?

shadow quest
#

/close

#

.c;pse

#

.close

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nova basin
devout snowBOT
nova basin
#

so on the left i found the vertical asymptote and on the right i tried to "verify my conclusion using appropriate limit statements"

#

i wanted to know if its verified correctly and what does equation form mean

#

if anyone could help .-.

#

wait thats wrong 1 moment

#

im so confused

#

its not 0 its 1.5/0

#

which is undefined

#

.close

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formal pecan
#

How can I check if function is piecewise smooth on an interval without going on Desmos to look at the graph?

midnight bane
#

piecewise smooth?

stark shuttle
#

I've never heard of that too

#

You mean continuous?

storm crater
#

I think he means smooth on intervals that cover the entire domain.

#

Possibly also contininous.

formal pecan
midnight bane
#

so continuous and differentialable

formal pecan
#

Yes

#

If I was given a function, how can I decide if it's piecewise smooth or not without looking at the graph?

storm crater
midnight bane
#

make sure your functions that make up the piecewise are continuous and differentiable and check where they merge

#

almost no piecewise functions are differentiable though

storm crater
#

often smooth also refers to infinitely often differentiable.

formal pecan
#

I'll try the best I can, but thanks

#

.close

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nocturne hound
#

$\lim_{x \to \infty} \bigl(\frac{3x^2-6x}{4x-8} \bigr)$

woven radishBOT
#

R(icky)

nocturne hound
#

How do I approach this

cosmic orchid
#

Isn't It infini since x squared to the infine will always grow bigger than 4x because it's derivate is superior to (4x)' so it's bigger growing infinity over a smaller one which leads to infinity ?

dark sable
dark sable
#

lemme google

cosmic orchid
#

Of course you'll need to simplify and put all I said in evidence but just by being logic It seems good

nocturne hound
#

I get $\frac{3}{\frac{4}{x}}$

woven radishBOT
#

R(icky)

dark sable
nocturne hound
#

So if I sub in $\infty$ I will still get $\infty$

woven radishBOT
#

R(icky)

dark sable
nocturne hound
#

Thanks

slate zephyr
nocturne hound
#

.close

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bold cypress
#

Do you guys have any tips on how to determine if an equation is a function or not without graphing it?

winter torrent
#

generally if you can put it into y = (stuff about x) form without branches like ± then it's a function

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#

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wheat pawn
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restive river
#
silver fjord
#

You'd need the notion of a measure for that proof

#

Do you really want to go that far for that?

restive river
#

wdym by notion of measure?

devout snowBOT
#

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restive river
supple knot
restive river
supple knot
#

Which sentence or equation exactly don't you understand

restive river
supple knot
#

Do you know the axioms of real numbers

restive river
supple knot
#

Use completeness axiom to construct sqrt(2) then s follows

restive river
supple knot
#

What happens if there's no 2 in the denominator

restive river
#

its not in between

#

Also for proof by contradiction, do I still have to do it in an arbitrary way

#

or is an example okay

restive river
#

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vast violet
devout snowBOT
vast violet
#

hi i am stuck

#

Like sure the addinf part i know

#

3x-38 there

#

But the when the = sign is there idk

#

😭

crude valley
#

what are you trying to do and what is your original problem

vast violet
#

sry

crude valley
#

honestly id multiply everything by x^2-4 for me personally that seems easier

vast violet
#

Ok

#

Ill try that and show

#

oh

#

then i do factor with grouping?

quaint cove
#

Uhh, make the denominator x²-4 for every case and just focus on the above part

crude valley
#

you get (x+9)(x+2)=3(x-2)+44 right

quaint cove
#

Yup

crude valley
#

ye I did it the same way let me ping op @vast violet

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#

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midnight sedge
#

how do i solve this?

#

i know that it involves force times sin of the angle

#

for horizontal force

#

but im not sure how to proceed

crude valley
#

isnt w=Tv

storm grotto
#

You have the force

#

you have the angle

#

how do you calculate F_y?

#

btw I answers your previous thread but you ignored it

midnight sedge
#

didnt have service

midnight sedge
storm grotto
#

You can get the vertical force by multiplying the force with sin(angle)

midnight sedge
#

is horizontal force force multiplied by cos(angle) then?

storm grotto
#

cos yea

#

I dont think you need the F_x here tho

midnight sedge
#

what do i do with vertical force now tho

storm grotto
#

if you divide that with gravity you can get the mass

midnight sedge
#

u mean the weight?

storm grotto
#

weight sorry

midnight sedge
#

how do i get gravity tho

storm grotto
#

gravity is always 9,82 m/s^2

#

or 9,8

#

it various from countries

midnight sedge
#

uh

#

im getting a negative number

storm grotto
#

add a () on numerator

midnight sedge
#

nope

storm grotto
#

im getting 1.23

#

you are in radians mode

#

need to be in degrees mode

midnight sedge
#

is there anything we could have missed?

#

in the process

#

like a diff way to calculate gravity maybe

storm grotto
#

well you have 2 sides

#

did you add it twice?

midnight sedge
#

wait wha

#

so multiply the 1.23 by 2?

storm grotto
#

yea

#

Its been a serious long time I did physics

#

but yea I think so lol

#

since we just calculated one side

midnight sedge
#

still not working lol

storm grotto
#

hmm

#

yea im not sure anymore

midnight sedge
#

.close

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#
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pine patrol
#

Would this be correct?

devout snowBOT
pine patrol
#

I thought it was positive 6 but it was wrong

near stone
#

we dont help in quizzes

pine patrol
#

It isn't a quiz there is multiple attempts

livid carbon
pine patrol
#

No

#

Actually ya

#

I kinda know it we just learned it today

livid carbon
#

State it

pine patrol
#

(x-h)^2+(y-k)^2

#

=r

#

Is that it?

livid carbon
#

r^2

pine patrol
#

Oh so it would be negative cuz of the formula

livid carbon
#

Wdym?

pine patrol
#

Isn't the formula y-k

#

So it wouldn't be positive

livid carbon
#

"it" what?

pine patrol
#

The y part of the center point

#

I thought it was positive 6

#

But is it -6

livid carbon
#

Yeah

#

k = -6 (in this case)

pine patrol
#

Ok thanks

#

Have a nice day

#

.close

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#
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rancid dune
devout snowBOT
rancid dune
#

I'm starting to graph sin and cos functions and instead of help with the specific question I'd appreciate it if someone could go more into depth of how I find the numbers to graph onto the graph

#

it was phrased a little confusing and was super exhausted when it was gone over

stark shuttle
#

What kind of transformations do you see?

autumn sparrow
#

You dont need to know that besides the transformations and the period of the sine function

stark shuttle
#

Translations even perhaps

rancid dune
#

3pi/2 i believe is shifting it to the left 3pi/2

autumn sparrow
#

Yes

stark shuttle
#

Nice

#

Well done

#

What graph reflects on what you said?

rancid dune
#

A i believe

#

nop that wrong wrong lul

#

i guess D

stark shuttle
#

Yes

#

Good job

#

You didn't fall for the trap

autumn sparrow
#

Well wait, lemme explain why that's the answer

rancid dune
#

i did fall for the trap

#

i only knew cause it told me it was wrong lul

autumn sparrow
#

The period (the length of the interval which repeats forever) of the sine function is 2pi

#

so you can say that sin(x) = sin(x +- 2npi) where n is an integer

#

Thus you can use that identity to say that sin(x + 3pi/2) = sin(x - pi/2) which is that the graph D represents

rancid dune
#

i dont understand how we go from sin(x) = sin(x +- 2npi) to sin(x + 3pi/2) = sin(x - pi/2) could u elaborate on that

#

it just looks like u removed n from the 2nd equation and only changed the left

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#

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rancid dune
#

.close

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hexed solar
#

Pedro Henrique has low grades in Portuguese. The last test of the year will have 56 questions. To be approved and move on to the following year, Pedro Henrique's performance in this test must be, at least,
8/5

. What is the smallest number of questions he must get right on this test to pass?

devout snowBOT
#

Please don't occupy multiple help channels.

hexed solar
#

how do i solve this?

unique kelp
#

he needs to get 8 out of every 5 questions correct?

hexed solar
hexed solar
unique kelp
#

can I see the question?

hexed solar
unique kelp
#

ok so they wrote 5/8 and you wrote 8/5

hexed solar
#

Ah, sorry, I tried to translate the question

main gull
devout snowBOT
#

Helpers are just people volunteering their time to help you. Be polite.

hexed solar
main gull
#

Yes it did, you deleted your message there which made it close

unique kelp
unique kelp
#

can you write that out mathematically?

hexed solar
#

5/8 mathematically?

unique kelp
#

5 8ths of 56

hexed solar
unique kelp
#

generally when we say some fraction of some number it means the fraction and the number multiplied together

#

for example, 1 half of 4 = (1/2)*4 = 2

hexed solar
#

then it would be: 56/1*5/8

unique kelp
#

yeah

hexed solar
#

56/1*5/8=280/8=35?

unique kelp
#

looks good!

hexed solar
#

thx

#

.close

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#
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rancid dune
devout snowBOT
rancid dune
#

how does pi/2 come out of this?

#

nvm

#

.close

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grizzled roost
#

For which t values in [0,2pi) does this guy converge in C?

devout snowBOT
#

@grizzled roost Has your question been resolved?

grizzled roost
#

<@&286206848099549185>

supple knot
#

Did you try ratio test

grizzled roost
#

It goes to 1, right?

#

So yeah, that didn't work

supple knot
#

I guess you can write it in terms of the real and imaginary parts

#

Then find when both series converge

grizzled roost
#

That looks annoying but I guess it works

#

How do I manage the n being inside the sine/cosine along with the t

#

I can eyeball a few cases but I should conclude something for every t