#help-27
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do you know the sigma notation for sums? like for example
[\sum_{i \in \bN}\frac{1}{n^2}]
propERICly_embedded
yes
This is very similar
It's just saying "take the union of all the B_is"
where i ranges over all the elements of I
doesnt this mean , the sum of 1/n^2 where i belongs to all natural numbers?
So if (I = {1,2,3}), then
[\bigcup_{i\in I}B_i = B_1 \cup B_2 \cup B_3]
propERICly_embedded
so the union of B_i where i ranges over I
the advantage of the notation on the left hand side is that I can be infinite!
whereas if I is infinite, we can't use the notation on the right hand side
it only works for finitely many sets in the union
no problem!
ok i think ive got it all but i just want to know, when they put something like i belongs to I or i belongs to all natural numbers under an intersection or union or a summation like you showed me, is it just trying to show that there is an infinite amount of like possibilities?
yup, just like how in the sum example I gave, i can be 1, 2, 3, etc, ranging over all the natural numbers
yup yup, it doesn't have to be the natural numbers N, it can really be any set that you're taking the union over
so if it said like i belongs to all natural numbers in the proposition, would it be all natural numbers as well as whats in A?
i has nothing to do with A
i ranges over I
but if you chose I to be the set N of all natural numbers, then you would get one set for each natural number so B1, B2, B3, B4, ... (infinitely many sets B_i)
what do you mean by it can be any set that youre taking the union over?
like I could be N, but it could also be the set R of real numbers, or the set {1, 2, 3, 4}, or really just any set you want
the important thing is that for each i in I, you have one set B_i
and you take the union of all the B_i's as i ranges over everything in I
so you mean that i refers to anything in I?
it's just like how in
[\sum_{i=1}^5 \frac1{n^2}]
(i) goes over all of the different elements in the set ({1,2,3,4,5}), so (i=1), (i=2), etc.
propERICly_embedded
we call i a "dummy variable" since it's just a notational convenience to express the sum
similarly i in this proposition is a dummy variable so we can give each of the sets B_i different names
i see
so is the use of “dummy variables” only in stuff like propositions and theorems?
its called dummy because it doesn't effect the result, it's not present
you could call it i or j or k or anything you like
or would i come across this in a problem
i can see getting this problem in a basic proofs class
prove that the thing you posted is true
so sure
in math you see dummy variables all the time
oh ok
well then i think thats all for now im too tired for more math but thank you both lots for the help
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Hi, I need help factoring out the numerator to where i can get an x-1 on both the top and bottom to find be able to find the limit.
Do you know how to factor a quadratic?
yes i do. but when i try to factor by forcing the (x-1) on one of the sides i dont get a number that adds up on the other. unless im just missing something entirely
oh i think i see what i did wrong.
so i assumed that since the bottom equaled 0 i had to start factoring the top, but since it all equals to 2/0 rather than 0/0 that would mean DNE?
yeah
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I did not understand the question properly hence no idea to solve in which direction.
<@&286206848099549185>
hey arjunn how are you
ohhh ok
How are you doing?
Ahh I am reading, learning each day
Random stuffs
Some graduated topics and some high schools topics
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If three points are given in 3d what will be the shortest way to find in what ratio second point is dividing if they are collinear?
Distance formula is easy
find distances AB and BC and divide one by the other
it takes a total of:
- 6 subtractions
- 4 additions
- 6 multiplications
- 1 division
- 2 square root extractions
damn, you actually counted lol
you could also divide just the change in one of the coordinates, if you know they're colinear
you could, yeah.
i assume myself not to.
but if you trust that, then it's only 2 subtractions and 1 division.
which is about six times quicker at the expense of reduced certainty.
U a real one for that
@wooden axle
Yes i am
What are these 6,4,6?
that is how many times you will have to do each operation.
i counted it up for you.
it is not relevant for your work.
divide distance AB by distance BC.
i mentioned two things, then the words "one" and "the other" refer to those same things in the same sentence.
i guess you are also learning some English on top of the math.
√56/√126
I got this
AB/BC
Let me simplify
√28/63
What next should I have to do with this?
I don't think you have dropped enough information for me to do even you are fluent in English
√4/9 which is 2:3 that's it
I guess people were active just for fun here. To find some funny moments in each channel
No problem. Have fun
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hii, is C a proper subset of A if
C={ 2} and A={1, {2}, √2}? it is, right?
is every element of C, also an element of A?
it should be C= {{2}} to make it proper?
that would be a proper subset of A yes
A proper subset of a set A is a subset of A that is not equal to A.
your original C is not even a subset
Yes
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Can someone help me don't know where to start
@vestal notch Has your question been resolved?
questions are cut off,
also seems like clear explanations of the answers are given
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am lost
Tangent is pi periodic
im not sure what that means
$\tan(\pi+\theta)=\tan\theta$
MrFancy
ohhh right so its the same, and 2pi + theta is also the same no?

$\ldots=\tan(2\pi+\theta)=\tan(\pi+\theta)=\tan\theta$
MrFancy
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@open portal
Sorry for my ugly hand writing
I used the elimination method
Did i do anything wrong
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For this type of question
why are the answers always 1 term
like this
Shouldnt it be sqrt(z) = sqrt(|z|)cis(x/2) or sqrt(z) = sqrt(|z|)cis(x/2 + pi)
I can think of 1 explanation, however i don't know if it is right:
the argument being x/2 shows that for any real values substituted for 'theta,' or x in my case, both roots undergo this division of 2. In summary, the angle shown that is divided by 2 represents the all of the angles from all of the roots.
Please ping btw
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Covert 1 to log
10?
Now use the addition rule
ohh
log(3/2)+log(10)=??
Yep

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$z^{3}=-1+i$, $z=\sqrt[3]{-1+i}$
HqppyFeet
hmmm.. haven't done this type of cube root before... I know that one of the cube roots of -1 is -1, but... -1 + i? That's a different thing... can someone give me a hint as to what to do?
first you want to find one root
yup
so you need to find a complex number (a+ib) so that (a+ib)^3 = -1+i
where a,b are real
wihch you can hopefully just do algebraically
actually converting it to polar coordinates might be easier
sry
polar coordinates will make this substantially easier
i was thinking that xD
i was like... am i really going to do a+ib)^3
not an analyst :)
xD anyway, yeah i am familiar with z = r(cis(x))
instead of writing it like that
I found the modulus and argument. 2 and -pi/4 respectively
write it as $z = re^{i\theta}$
hayley!
uh -pi/4 isn't right for the angle
yeah both ways work, i tend to use cis but yeah
writing it with the exponential makes it clearer how to take the root
but cis is easier to write in text so
and neither is 2 right for the radius
hm-? $arg(-1+i) = tan^{-1}\frac{1}{-1}=-45\circ$
HqppyFeet
-45 degrees in rad is -pi/4. what did i do wrong?
ok this is why blindly applying arctan is bad
consider what -1 + i looks like on the complex plane
yeah
woops
ok im getting a bit confused as to when i can use arctan here--- simply copied a text book, apologies
my recommendation? until you're very comfortable with it, just draw a quick sketch
so what angle should you actually have?
135, or 3pi/4, right?
👍
and the modulus is sqrt(2) i realized
yeah
well nice, with e^(ix), argument, and modulus, I can simply do (re^(ix))^(1/3) and adding 2pi after each answer will give me the three roots. aight this sounds good
hmm
careful with that 2pi
Yeah.
r^(1/3) * cis(pi/4) for first root.
r^(1/3) * cis(3pi/4) for second root.
r^(1/3) * cis(5pi/4) for third root.
Is this correct?
cis(pi/4) was acquired through cis(3pi/4)^(1/3), then applying de Mouivre's theorem, => cis(3pi/12) => cis(pi/4)
(I hope my thinking is correct lol, this feels like familiar territory)
nvm, found out that r^(1/3) is 2^(1/6)
wait a minute, answer sheet says " $2^{\frac{1}{6}}(cos(\theta)+isin(\theta))$ where $\theta = \frac{\pi}{4}$, $\frac{11\pi}{12}$, $\frac{19\pi}{12}$ "
HqppyFeet
bruh what... do they add 2pi into theta before the (1/3) exponent is applied in cis(3pi/4)^(1/3)?
Sure looks like it
cos(3pi/4), so that cos(3pi/4 + 8pi/4).... mhm
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How do i do this
Show your work, and if possible, explain where you are stuck.
You replace x by x+h in f, subtract it with f(x), then divide the whole result by h
If you tend h to 0, you unfortunately don't get the derivative, so there is a mistake somewhere for sure
Now it's for you to find it. Look back at your computations
There should be something wrong
oh okay
I don't get it, I think I do (x+h)^2 and -5(x+h) +6 which gives me x^2+h^2-5x-5h+6 and then subtract by f(x) which makes it h^2-5h over h
(x+h)^2 isn't x^2 + h^2
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Which one
i dont understand d h and j
they’re right
there is a hollow circle at -3 on the graph of h
that means -3 isn’t in the domain of h
so h(-3) doesn’t exist
can you see why h(2) also doesn’t exist?
ohh
there is a circle there too
and doesnt exist in domain
what about h(1) theres a jump here
Then you have to look for the solid circle
you mean h(0)?
you have to see if the circles are hollow or solid
hollow circles
are we looking at the same graph
I don’t see 2 hollow circles at the same y coordinate on the graph
yes
like IF
there were on h(0)
two hollow circles except one filled and one hollow
then the answer should be DNE
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in geometric its multiplied here in the question
1 4 9 16
+3 +5 +7
+2 +2
so i assume its arithmetic
damnn how tho
ur right
First, do not use chatgpt for math
why
Because chatgpt is garbage at math
Yes it is
it's not meant to do math. gpt4 may be better than the free version but it was not intended to do math problems
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Bad riemann
How do you know it's arithmetic or geometric? What if it's neither?
Do you know the definitions of arithmetic and geometric?
yes?????????????????????
Okay so is the sequence arithmetic? What do you think
what's not fixed?
the difference in terms
Could be
How could you check?
equation
what equation?
can you write out what equation you mean?
intracatholic
Yup, how can we check if this sequence satisfies that equation?
Try it out
what about the ratio? ratio of what?
of two terms
what can you say about the ratio for this sequence?
it aint the same for every consective term
yup, what ratios do you get?
right so the important thing is 4/1 and 9/4 are not the same
so is the sequence geometric?
it quadratic
that's true, but is it geometric?
nuh uh
exactly
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why is n^2 = -0 (for n ≠ 0) on the sedenion multiplication table
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I was just about to do this
bro is mad
we are not entitled to help you.
STOP FUCKING SPAMMING
bro thinks we are paid to help
!community
Hi lmao yes
Hi
!volunteer
if we dont want to help you, we wont lol
!volunteers
Helpers are just people volunteering their time to help you. Be polite.
Go google
Thank you
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<@&268886789983436800>
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@valid fern
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he thinks he will get help like that lol
Beo gone mad
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dont feed him
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What a degen
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I need help in math
what just happening
Please refer to #❓how-to-get-help
😂😂
aight bye dude
Thanks
dude
10 year old mindset
already banned
He came Into my help box spamming his shit to lol
same lol
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I wanna be greeennn
look for the roles
I mean yeah have to help MORE 🙆
Why doesn't the bot detect this convo as a new question?🤔
the channel's not open yet

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given f(x) I am supposed to determine if f is a pdf. Now I know that it is but I dont understand why it satisfies the condition that the integral from -inf to inf of f(x)dx = 1.
In my books solution it says because the sum from 0 to inf of 2^(-x) = 1. But how does this explain this ?
thats what's in my book regarding that exercise
I understand that convergence and I have already seen it before. I just dont understand why that is the explanation to why said criteria is satisfied
oh lol sorry I thouhgt you graphed the sum
i graphed the actual function
whose integral is composed of rectangles of width 1
so its integral is the sum
ohhhhh
now I understand
but like
no wait
I am just a bit confused because I feel like in order to solve this I had to be familiar with that exact function to know how it behaves
but in my book they just taught to take the integral
and I wouldve done something like this (one second)
I am sorry I dont understand that
$2^{-\ceil{x}}$
Ann
Well notice that your function is in terms of k not and x @ionic swift
Its 2^(-k)
And ceiling of x gives k, thats why
hows that different from saying
f(x) = 2^(-x) for x in N ?
I dont understand that
oh so
When input to 2^(ceil[x])
because in general x would be in R ?
oh damn
right
now I understand
big thanks to both of you
I did nothing but you're welcome
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Hi, I'm trying to solve this linear congruence, I watch a bunch of videos and I still don't understand the final step :c
This is what I did, I don't know how to continuous, I find the value of s which solve this equation 1 = 1993 * s + 990 * t, where 1993 is the result of 9965/5 (5 = gcd(9965,4950)), and 990 is the result of 4950/5
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<@&286206848099549185>
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Hello I need help with solving this equation , but I can't understand how to start
u can start by getting both the terms on the same denominator
what do you mean by that
try to get the denominator of 3/x to 5x
I get it
like how u add fractions
np
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what, is there another way to do it
nono, ur method is fine
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np
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Could u help me with this please
Hey did you try it out?
Yea I've been unable to do it tho
Well your goal is to make T alone on the left hand side
I've tried by first expanding the bracket but idk how to get it on its own
I suggest you treat the question like an onion
You start by peeling the first layer
Which right now looks to be the r multiplied by the squared brackets
How do you get rid of a number being multiplied?
Divide it by itself?
Yep and to keep the equation from changing, what do you do to the right side when you divide the left side by r?
Wouldn't it just be r^2 x r at the bottom of the right side then
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do i take sq root of it
difference of perfect squares
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Can someone help me prove this
This is logic
Blue is what needs to be proven
I can only use basic propertiws
Is that true?
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3x3
What's your question?
3+3+3
What's 3x3
unsure
6 right
,w 3 * 3
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How do i find the limit of (x approaching 0) for the equation: (x-1)/((x^2)(x+5)) ? I know the answer is negative infinity and got to the equation "((1/x) - (1/x^2))/(x+5)" but am not sure where to go from there.
$\frac{x-1}{x^3+5x^2}$
binibini
1 s
ok can u get me another person ToT
binibini
@lofty obsidian
left side -infinity , right side 1/5
but i m not sure solution
ok thank u
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@visual basin Has your question been resolved?
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I don't understand what I'm supposed to do here
what
Use linearization (using the tangent line at x = 0)
i dont know what that is
You don't know what a tangent line is?
"linearization"
I legit defined it for you
Find the equation of the tangent line at x=0
Start with that
Let that line be L(x)
Then F(7) ≈ L(7)
Do you know about Taylor polynomials because that will give us better approximations
im honestly kinda confused on the first method you gave, can you like explain that
Do you know what a tangent line is
yes
,tex \linearization
Umbraleviathan
x0 is where the line is tangent to
now ive explained it already so im just gonna run in circles again
L(x) is your tangent line. Linearization is using L(x) to approximate values around x0
so F(7) is approx L(7)
@reef carbon Has your question been resolved?
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I don’t know what I’m doing at this point
Try and graph both the functions.
?
….
Is that just a rule?
I’ve had like nine of this stuff in the resources my prof gave me
None*
Yeah I haven’t even seen that before so I gotta watch a whole video on it
How do I do this?
I know that it wants me to find the Y value but why is there two?
The video connected to it isn’t even close to the problem
Like for the first one I just get -4 and -2
I legit tried bullshitting but can I get an explanation on why it flip and flops between the two expressions?
Oh shit I’m stupid
It’s the damn rule in the right
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Why is a double integral on a region D in the first quadrant which its value is negative is not possible
@shadow quest Has your question been resolved?
@shadow quest Has your question been resolved?
@shadow quest Has your question been resolved?
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so on the left i found the vertical asymptote and on the right i tried to "verify my conclusion using appropriate limit statements"
i wanted to know if its verified correctly and what does equation form mean
if anyone could help .-.
wait thats wrong 1 moment
im so confused
its not 0 its 1.5/0
which is undefined
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How can I check if function is piecewise smooth on an interval without going on Desmos to look at the graph?
piecewise smooth?
I think he means smooth on intervals that cover the entire domain.
Possibly also contininous.
In order for f(x) to be piecewise smooth on an interval, it needs to be piecewise continuous.
so continuous and differentialable
Yes
If I was given a function, how can I decide if it's piecewise smooth or not without looking at the graph?
@formal pecan this?
make sure your functions that make up the piecewise are continuous and differentiable and check where they merge
almost no piecewise functions are differentiable though
often smooth also refers to infinitely often differentiable.
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$\lim_{x \to \infty} \bigl(\frac{3x^2-6x}{4x-8} \bigr)$
R(icky)
How do I approach this
Isn't It infini since x squared to the infine will always grow bigger than 4x because it's derivate is superior to (4x)' so it's bigger growing infinity over a smaller one which leads to infinity ?
you know l'hopital's rule?
Of course you'll need to simplify and put all I said in evidence but just by being logic It seems good
I get $\frac{3}{\frac{4}{x}}$
R(icky)
Yeah wrong application(I think)
So if I sub in $\infty$ I will still get $\infty$
R(icky)
Yeah
Thanks
consider the limit intuitively like Chetrit implied - since the numerator has an x^2 term, it will grow faster than the denominator, and ultimately the function will approach infinity
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Do you guys have any tips on how to determine if an equation is a function or not without graphing it?
generally if you can put it into y = (stuff about x) form without branches like ± then it's a function
@bold cypress Has your question been resolved?
if the same value of X can have more than one value of Y, it isnt
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https://math.stackexchange.com/questions/1106170/proving-that-there-is-an-irrational-number-between-any-two-unequal-rational-numb Can someone explain to me how the irrational number is constructed in this proof.
You'd need the notion of a measure for that proof
Do you really want to go that far for that?
wdym by notion of measure?
@restive river Has your question been resolved?
whats notion of meausre mean
Which part exactly don't you understand
how they constructed the irrational number
They explained that in detail
Which sentence or equation exactly don't you understand
dont know how they came to this conclusion
That's a number by construction
Do you know the axioms of real numbers
no
Use completeness axiom to construct sqrt(2) then s follows
did they have to divide by 2 here
Why do you think they did that
What happens if there's no 2 in the denominator
its not in between
Also for proof by contradiction, do I still have to do it in an arbitrary way
or is an example okay
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hi i am stuck
Like sure the addinf part i know
3x-38 there
But the when the = sign is there idk
😭
what are you trying to do and what is your original problem
honestly id multiply everything by x^2-4 for me personally that seems easier
Uhh, make the denominator x²-4 for every case and just focus on the above part
you get (x+9)(x+2)=3(x-2)+44 right
Yup
ye I did it the same way let me ping op @vast violet
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how do i solve this?
i know that it involves force times sin of the angle
for horizontal force
but im not sure how to proceed
isnt w=Tv
You have the force
you have the angle
how do you calculate F_y?
btw I answers your previous thread but you ignored it
i got on a bus home
didnt have service
im not sure thats what im confused on
You can get the vertical force by multiplying the force with sin(angle)
is horizontal force force multiplied by cos(angle) then?
what do i do with vertical force now tho
if you divide that with gravity you can get the mass
u mean the weight?
weight sorry
how do i get gravity tho
add a () on numerator
its not right tho
is there anything we could have missed?
in the process
like a diff way to calculate gravity maybe
yea
Its been a serious long time I did physics
but yea I think so lol
since we just calculated one side
still not working lol
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Would this be correct?
I thought it was positive 6 but it was wrong
we dont help in quizzes
It isn't a quiz there is multiple attempts
Are you aware of the general form of the equation of a circle centred at a point (h,k) with radius r?
State it
r^2
Oh so it would be negative cuz of the formula
Wdym?
"it" what?
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I'm starting to graph sin and cos functions and instead of help with the specific question I'd appreciate it if someone could go more into depth of how I find the numbers to graph onto the graph
it was phrased a little confusing and was super exhausted when it was gone over
What kind of transformations do you see?
You dont need to know that besides the transformations and the period of the sine function
Translations even perhaps
3pi/2 i believe is shifting it to the left 3pi/2
Yes
Well wait, lemme explain why that's the answer
The period (the length of the interval which repeats forever) of the sine function is 2pi
so you can say that sin(x) = sin(x +- 2npi) where n is an integer
Thus you can use that identity to say that sin(x + 3pi/2) = sin(x - pi/2) which is that the graph D represents
i dont understand how we go from sin(x) = sin(x +- 2npi) to sin(x + 3pi/2) = sin(x - pi/2) could u elaborate on that
it just looks like u removed n from the 2nd equation and only changed the left
@rancid dune Has your question been resolved?
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Pedro Henrique has low grades in Portuguese. The last test of the year will have 56 questions. To be approved and move on to the following year, Pedro Henrique's performance in this test must be, at least,
8/5
. What is the smallest number of questions he must get right on this test to pass?
Please don't occupy multiple help channels.
how do i solve this?
he needs to get 8 out of every 5 questions correct?
It's his minimum performance
can I see the question?
ok so they wrote 5/8 and you wrote 8/5
Ah, sorry, I tried to translate the question
You do not need to close your previous channel if no one helps you
Helpers are just people volunteering their time to help you. Be polite.
the other one didn't close?
Yes it did, you deleted your message there which made it close
so he needs to get 5 8ths of the questions correct, yes?
can you write that out mathematically?
5/8 mathematically?
5 8ths of 56
I don't know how to do this mathematically
generally when we say some fraction of some number it means the fraction and the number multiplied together
for example, 1 half of 4 = (1/2)*4 = 2
then it would be: 56/1*5/8
yeah
56/1*5/8=280/8=35?
looks good!
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Closed by @rancid dune
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For which t values in [0,2pi) does this guy converge in C?
@grizzled roost Has your question been resolved?
<@&286206848099549185>
Did you try ratio test