help-27

[manic condor]

You messed up a sign.

[scenic goblet]

where?

[woven radish]

Enemagneto

[manic condor]

When there's a negative sign in front of the bracket, upon opening the bracket, sign of every term inside the bracket flips.

[manic condor]

$1 - \left(1- \frac{3}{x}\right) = 1 - 1 + \frac{3}{x} = \frac{3}{x}$

[woven radish]

Enemagneto

[manic condor]

Now, you have $1-r = \frac{3}{x}$

[woven radish]

Enemagneto

[manic condor]

Putting in the formula,

[scenic goblet]

so the denominator is 3/x

[manic condor]

$$75 = \frac{x}{\frac{3}{x}}$$
$$75= \frac{x \times x}{3}$$
$$ 75 = \frac{x^2}{3}$$
$$ 75 \times 3 = x^2$$
$$ x^2 = 225$$
$$ x = \pm15$$

[woven radish]

Enemagneto

[manic condor]

x would be positive because sum is positive.

Now, i have to go. Good luck.

[scenic goblet]

love you

thank oyi

[devout snow]

@scenic goblet Has your question been resolved?

Channel closed

Closed by @scenic goblet

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rugged storm]

what the heck is an absolute value of a vector?

[rugged storm]

I can't find the process in my textbook

[drifting hearth]

pythagorean of it’s rectangular form

[pseudo basin]

length

[drifting hearth]

the magnitude of the vector

[rugged storm]

oh

thanks

that worked 👍

[devout snow]

@rugged storm Has your question been resolved?

Channel closed

Closed by @rugged storm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lusty wing]

Elsa deposited $122,000. into a bank. After one year, she was able to withdraw $126,270.

What was the interest rate (in %) on Elsa's savings account?

[rugged storm]

4,270 is the amount of interest she accrued, which is 3.5% of the money she deposited. Thus the interest rate is 3.5%.

[lusty wing]

It isn’t 3.38%?

[winter patrol]

how are you getting 3.38%?

[rugged storm]

126123.6 would be her total dollar amount then.

[lusty wing]

Nvm I did 126270 instead of 122000

[rugged storm]

ah

[lusty wing]

Anyways I got it

Thx for leading my way.

.close

[devout snow]

Channel closed

Closed by @lusty wing

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[paper mango]

Hi. I need to solve the following task without using a calculator. I am supposed to rank the numbers in ascending order;

[paper mango]

It's 1.33 by the way

[glossy star]

what’s 1.33?

The fourth one?

[pseudo basin]

the problem number

[glossy star]

oh lol

[drifting hearth]

does lg refer to log base 10

[paper mango]

yes

[pseudo basin]

right

so you can work some of these out exactly

do you see which ones and how

[glossy star]

you should just convert everything to 10^x

[paper mango]

I'm struggling with the two last ones

[pseudo basin]

do you know that roots are fractional exponents

$\sqrt[n]{x} = x^{1/n}$

[woven radish]

Ann

[glossy star]

If you look at the expression inside the ln for the last one, it’s basically asking the question “what number do you raise 10 to to get 10^e”

[paper mango]

I sort of got that, but I don't understand how I'm supposed to work that out in my head. I think the purpose of these tasks are to just get the basic of it, and so far I've only had to use a calculator when directly stated in the problem.

[pseudo basin]

??

[glossy star]

The manipulations should be very possible mentally with a little practice

[pseudo basin]

in your head?

[pseudo basin]

this problem has an icon next to it that looks like a hand holding a pen

doesn't that mean you should do it on paper?

[glossy star]

Which message is this responding to?

[paper mango]

I do it on paper, but there shouldn't be any advanced math. I might be wrong and I need to actually work on this for a while, but I thought the problem should be easier to work out.

I'm talking about the final one here.

[pseudo basin]

$\ln(\lg(10^e))$?

[woven radish]

Ann

[glossy star]

Well that’s just the definition of a logarithm

consider the expression inside the ln first

[paper mango]

Yes Ann

[pseudo basin]

just work it out from the outside in. first work out lg(10^e) then take ln of that

[paper mango]

lg 10^e should be e, right?

[pseudo basin]

of course

[paper mango]

so the answer is 1?

[pseudo basin]

yup

[paper mango]

I looks so much more complicated. Thank you.

Quick question about the third one. lg e. I know the answer, but is this something I just have to remember? I suppose using lg and e together is rare, but is there an easy way to get to the number 0.4343 without using a calculator?

[pseudo basin]

lg(e)? no

you could easily see that it's between 0 and 1 though because e is between 1 and 10

maybe also see it's between lg(2) and lg(3) but that only helps if you remember both their values

[paper mango]

Ok. Thank you!

[devout snow]

@paper mango Has your question been resolved?

Channel closed

Closed by @paper mango

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rugged storm]

can't figure out what I did wrong

[keen oxide]

20-1+4 = 15 ?!?!?!?!?!

[rugged storm]

oh shoot youre right

calculator mistake lmao

[rugged storm]

yep that was it lol thanks

.close

[devout snow]

Channel closed

Closed by @rugged storm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[molten lake]

So I can't figure out what I'm doing wrong on a problem trying to calculate the prediction interval for my sample data: 4, 11, 3, 12, 17, 7, 16

I keep getting 10 +- 14.49 which doesn't make sense because that would put the lower end of my interval as -4.49

[tall knoll]

That's fine

If you're assuming the data comes from a normal population, then you have to accept that negative realizations are possible (since the normal distribution has positive density for all real numbers)

It really just means that the normal assumption is a bad one, but computationally convenient

[molten lake]

Ok, thank you. Can I interpret this to mean that if I were to take future samples, 95% of them would contain a value within this interval?

[tall knoll]

That sounds like the right interpretation

[molten lake]

Thanks

.close

[devout snow]

Channel closed

Closed by @molten lake

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kind cedar]

the basis for W is (1,1,0),(0,0,1)

and the orthonormal basis would be

(1/root(2), 1/root(2),0),(0,0,1)

right?

so the projection would be

,rccw

[kind cedar]

something like this

right?

so idk what they have done here

why did they multiply it by 1/2 here

[winter torrent]

the thing on the outside should be of unit length

[kind cedar]

and why did they not take the orthonormal basis?

[winter torrent]

they are using the orthonormal basis

[kind cedar]

how?

they are just using (1,1,0)

[winter torrent]

no they're not

[winter torrent]

yeah that's where the 1/2 came from

you have $v_1 = \frac{(1,1,0)}{\sqrt2}$

[woven radish]

hayley!

[winter torrent]

and we want $\langle v_1, (1,2,3)\rangle v_1$

[woven radish]

hayley!

[kind cedar]

isnt that what i did here?

o wait

nahhh i messed up

[winter torrent]

see how the two v1's each contribute 1/root2

together that's 1/2

[kind cedar]

right

i kinda omitted the root2 part on the second V_1

thx that makes sense now

.close

[devout snow]

Channel closed

Closed by @kind cedar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse slate]

Do I just find the values to multiply matrix E and C together to get matrix A?

<@&286206848099549185>

[grand reef]

recall

what are the three types of elementary matrices?

or, rather, tell me what the elementary matrices do

[obtuse slate]

swap, add, and something else

[grand reef]

right

they can permute rows,

add rows

or multiply rows by a scalar

[obtuse slate]

it looks like row 3 changes and the others stay the same

[grand reef]

so now consider how we can get from matrix A to matrix C only using these operations

right

row 3 changes

and row 3 has to have changed by those operations

[obtuse slate]

im a little confused on how to write it

[grand reef]

tell me what's happened in terms of elementary matrix operations to get from A to C

[obtuse slate]

looks like they add/subtract

9 to -11, -6 tp -16, and -2 to 3

[grand reef]

could you be specific please?

[obtuse slate]

subtract 20, subtract 10, add 5

[grand reef]

okay

so the new row 3

is equal to the old row 3 - 5row 2

right

?

[obtuse slate]

wait what

[grand reef]

row3 of C = row3 of A- 5(row 2 of A)

[obtuse slate]

how did u get that?

[grand reef]

just by looking at the matrices

sorry we're going from C to A

so eitherway

row 3 of A = row 3 of C + 5(row 2 of C)

[obtuse slate]

so the new one gets -16?

[grand reef]

I don't know what you mean by that question

[obtuse slate]

this gets -16 from C row 3?

[grand reef]

think of each row as a vector

a "row vector"

then $\begin{bmatrix} -11 & -16 & -2 \end{bmatrix} + 5 \begin{bmatrix} 4 & 2 & 1 \end{bmatrix} = \begin{bmatrix} 9 & -6 & 3 \end{bmatrix}$

[woven radish]

swifteeee

[grand reef]

the first row vector is exactly row 3 of c

the second row vector is exactly row 1 of c

and the last row vector is exactly row 3 of a

and we've only done "elementary matrix operations"

so, adding rows and scaling rows in this case

I was calling row 1, row 2 earlier so i do apologise

[obtuse slate]

is that the last one C Row 3 = A row 3 + 5(A row 2)

[grand reef]

no

A row 3 = C Row 3 + 5(C row 1)

[obtuse slate]

so we use row 1 and add/multiply it to find row 3 of A?

[grand reef]

there are three types of elementary matrices

these three represent 1) swapping rows around, 2) scaling a row or 3) adding/subtracting rows from each other

so if we understand how the matrices are related through these three operations

and how the three operations are operated to the matrices

then we will understand how the matrices are related via elementary matrices

[obtuse slate]

how could i write the elemtary matrices?

[grand reef]

here's my main advice, because we're not getting anywhere

what level of education are you in Arisu?

[obtuse slate]

college

[grand reef]

and this is a first linear algebra course im guessing right?

[obtuse slate]

yea. its introduction

[grand reef]

okay

go to the course textbook

and reread and thoroughly understand the section on elementary matrices and Row reduction

if there's any line of the textbook you don't understand, you need to ask or think about why it is

you need to thoroughly understand everything in a math course, else you won't get anywhere

if there's no course textbook, i have some readings for you

[obtuse slate]

ok. what are they?

[grand reef]

Chapter 1 of Algebra by Michael Artin (from 1.1 to 1.3)

and a better reading

is from 2.1 to 2.4 of Strang's book "An Introduction to Linear Algebra"

[obtuse slate]

okay. i'll give it a read

.close

[devout snow]

Channel closed

Closed by @obtuse slate

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

Hi can someone explain this working I don’t understand

[restive river]

I don’t get the second part

[devout snow]

@restive river Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith prawn]

distributive property

[honest turtle]

just use it

what are you struggling with

[wraith prawn]

yeah but i dont know what to do here

[honest turtle]

you said it yourself

[wraith prawn]

no i mean theres a fraction in this equation

[honest turtle]

a(b-c) = ab-ac

[lilac mango]

that doesnt make anything different

[honest turtle]

same thing

[wraith prawn]

so then its just -0.75?

[jaunty mantle]

Yes

[wraith prawn]

oh alright

[jaunty mantle]

But in math we kinda just leave fractions as fractions

[glossy star]

they're basically unrolling the cone

[jaunty mantle]

We don’t particularly care whether it’s a whole number or fraction or whatnot

[wraith prawn]

then how do i distribute it only as a fraction

[glossy star]

and saying that the two diametrically opposite points have half of the 180 degree, aka 90 degrees

[wraith prawn]

idk how

well if i unfraction it

-0.75

then maybe i would know

[glossy star]

-3/4 * 12 = -36/4 = -9

[lilac mango]

just think of 12 as 12/1

if that makes it easier for you to understand when multiplying fractions

[wraith prawn]

i think i got it

wait can i solve and and see if i got it right

[lilac mango]

sure

[wraith prawn]

= -9 - 12D

[lilac mango]

close

[wraith prawn]

where did i get wrong

[lilac mango]

remember that your multiplying -3/4 by **-**16d

its a double negative

[wraith prawn]

shoot

[lilac mango]

yup

[wraith prawn]

= -9 - -12D

[lilac mango]

which becomes..

[wraith prawn]

a positive?

[lilac mango]

yup

[wraith prawn]

so -12D becomes 12D

hello?

afk?

[lilac mango]

sorry yep

im here

yep thats it

[wraith prawn]

no its fine

[lilac mango]

the double negative turns it positive

[wraith prawn]

but didnt i say it up here?

[lilac mango]

but thats the negative not positive

[wraith prawn]

oh wait

so replace it with a plus sign?

[lilac mango]

yep

[wraith prawn]

=-9 + 12D

final answer

[lilac mango]

perfect

[wraith prawn]

ty

[lilac mango]

you can rewrite it as 12d - 9 if it looks cleaner to you

but doesnt matter

[wraith prawn]

its good

alr peace

.close

[devout snow]

Channel closed

Closed by @wraith prawn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith prawn]

need help distributing this

[winter patrol]

you've done 3 similar examples already, try attempting this without our aid

[wraith prawn]

but how can i go 2 / 3 * 12?

i knew the other one since it was -0.75

[dark dawn]

Do you know how to multiply two fractions together

[wraith prawn]

example?

[dark dawn]

2/3 * 12/1

[wraith prawn]

oh

let me see

8?

[dark dawn]

Yes

[wraith prawn]

wow much simpler than said

[dapper quail]

(sorry for interrupting this channel) omg what irrational number is your about me

[wraith prawn]

ima try and solve it

[winter patrol]

(you knew this was something you shouldn't be doing, that stuff can go places like #chill #discussion)

[wraith prawn]

= 8 - 10?

[dark dawn]

Forgetting something on the 10

[wraith prawn]

wait

yeah mb

noticed

-10D

= 8 - 10D

final answer

correct?

[dark dawn]

https://tenor.com/view/well-done-jeremiah-johnson-good-gif-25626389

[wraith prawn]

https://tenor.com/view/yippee-happy-celebration-joy-confetti-gif-25557730

[dark dawn]

(d to be super specific , not D)

[wraith prawn]

oh

alright

ty

[dark dawn]

https://tenor.com/view/cat-cat-jumping-cat-excited-excited-dance-gif-19354605

[wraith prawn]

https://tenor.com/view/frog-frog-laughing-gif-25708743

ima close now

peace

.close

[devout snow]

Channel closed

Closed by @wraith prawn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[raven cape]

Could someone please explain why the complex numer shown above in polar form is 81cis180° and not -81cis180°?

[winter torrent]

well, because it's at a radius of 81 and an angle of 180º

[raven cape]

Oh I see, so the modulus is always postive then right?

[winter torrent]

yeah

[final storm]

yes, u cant have a negative length

[raven cape]

Oh ok thanks👍

.close

[devout snow]

Channel closed

Closed by @raven cape

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[west tinsel]

yoyo

[west tinsel]

State the largest possible interval J... on which the restriction of h becomes injective

heres h

[restive river]

find minimum

h'(x) = 0, then find x1, then you need to calculate h(x1) = y1

J = [y1, + infinity)

but R >= 0, be careful

with y1

J is the domain?

because it's saying injective, so it must be

otherwise it would be surjective

[west tinsel]

J is a subsset of R >_ 0

[restive river]

yea but it's the domain or codomain of h(x)?

[west tinsel]

neither

J is a interval

[restive river]

idk bruh

[meager sequoia]

If you're restricting h to the interval J then J is the domain of the restriction

[west tinsel]

alright

[meager sequoia]

but yes, the advice here works because it's a quadratic. so you can be sure it's strictly increasing after the minimum point

[west tinsel]

okay, thanks

I think I got it now

.close

[devout snow]

Channel closed

Closed by @west tinsel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cunning perch]

hi

[cunning perch]

How do you find the sum of a geometric series

That has u1 128

Common ratio of 1/2

And the last term is 1/512

[wheat pawn]

Well, there's 2 obvious ways.
Either compute all the the terms from the first to the last and add them
Or use the formula that you should have been given and explained

[cunning perch]

Right the formula

[granite tulip]

You may need to understand how to divide, add, substract, and multiply fractions, do you?

[cunning perch]

One second let me try it and I'll tell you

[cunning perch]

Yes

[wooden veldt]

your only missing information here is how many terms there are

[granite tulip]

Thats great then

[wooden veldt]

try and figure that out

[cunning perch]

Right yeah that's what I was confused about

I could put it in a calculator and count how many times I divide by 2

but what's the mathematical way

For finding it

[wooden veldt]

128^(what) = 1/512 basically

[wooden veldt]

but also just doing this in your head is fine here since there arent that many terms

wait typo

[cunning perch]

Yeah but I'd just like to know the mathematical way in case I get a huge number

in a test

[wooden veldt]

128*(1/2)^(what) = 1/512

you want to know how many times you have to times 128 by 1/2 to get to 1/512

[wooden veldt]

this equation encodes that

[cunning perch]

ohhh right

[cunning perch]

Because of the formula?

ar^n-1

Is that what u used

[wooden veldt]

no i just wrote what this is saying, but in an equation

how many times do we have to times 128 by 1/2 to get to 1/512

$128\cdot \left(\frac12\right)^{\text{what we are looking for}} = \frac{1}{512}$

[woven radish]

ΣΑCu

[devout snow]

@cunning perch Has your question been resolved?

[cunning perch]

So 128x(1/2)^n=1/512

how would I actually solve that

[cunning perch]

like what would be my next step algebraically

I'm not too good with exponents and algebra ahaha

[wooden veldt]

do you know logarithms?

[cunning perch]

it wasn't really taught to us yet in school

but from my understanding g

Would it be

[wooden veldt]

okay honestly if you havent been taught logs i would just do this manually

[cunning perch]

log(128)1/512=n

[cunning perch]

How?

[wooden veldt]

keep dividing 128 by 2 until you get to 1/512

[cunning perch]

yeah I got 16

16 times

is that correct?

[wooden veldt]

thats right, but 16 isnt quite the number of terms, do you see why

[cunning perch]

is it because it counts the final term as well?

And the first

So would it be 18?

[wooden veldt]

not 18

we have 128 -> 64 -> 32 -> 16 etc

each arrow is timesing by 1/2

so if there are 16 arrows, how many numbers are there

[cunning perch]

Oh

17

[wooden veldt]

yep!

[cunning perch]

ah ok

Now I would substitute 17

As n

In the equation

To find the sum

[wooden veldt]

yes

[cunning perch]

One second let me try

[cunning perch]

\frac{131071}{512}

oh

how do you work the command

$\frac{131071}{512}

[wooden veldt]

surround it with $

[cunning perch]

$\frac{131071}{512}$

[woven radish]

jonnyboy

[cunning perch]

is that the answer

[wooden veldt]

,w sum from n=0 to 16 128*(1/2)^n

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by icaird

[wooden veldt]

yup

[cunning perch]

oh ok

thank you so much

[wooden veldt]

you're welcome!

[cunning perch]

have a nice day

.close

[devout snow]

Channel closed

Closed by @cunning perch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil bloom]

for b) does multiplying by i mean that the real bit becomes imaginary and the imaginary bit becomes real but with the sign switched

[silver fjord]

recall the problem from earlier. multiplication by i is a rotation by 90 degrees

but yes, component wise that's what will happen

[tranquil bloom]

i thought a rotation of 90 degrees only applied if it was i^n

[silver fjord]

multiplication by i is i^1

sorry i mean 180deg

(-1)^1/2 for 90 deg

[tranquil bloom]

wait what it should be 90

since i^0 = 1 and i^1 = i which is 90 degrees clockwise?

anticlockwise

oops

[silver fjord]

i'm confusing myself haha

[left robin]

when we multiply complex numbers, their lengths get multiplicated and their angles gets summed
therefore multiplying by i is like a rotation of 90° counter clockwise

[tranquil bloom]

so does i(a+ib) = a 90 degree anticlockwise rotation of a+ib which the same magnitude

[left robin]

we can see this when we look at their representation with the number e:
i = 1*e^i(pi/2)

[silver fjord]

she's not supposed to know euler stuff yet I think

[left robin]

yes

[tranquil bloom]

i know that pi/2 and 3pi/2 is like purley imaginary but thats it

[left robin]

"e" makes complex numbers so much nicer haha

[silver fjord]

it does

[left robin]

$a\cdot e^{i\varphi}$

[woven radish]

Martin

[left robin]

here a is the length or "norm" or distance from the origin

and phi is the angle

we can use this representation to understand why multiplication of complex numbers is so nice

but that kinda means we have to know why this representation works...

[tranquil bloom]

not really got to do with the question but is this form related to e^ipi

[silver fjord]

Yes!

[left robin]

here we have a length of 1 and an angle of pi which is 180°

so e^ipi is pretty much a 1 rotated by 180°

which makes it negataive

[tranquil bloom]

oh and = -1

[silver fjord]

$e^{i\pi} = -1$

[woven radish]

TooManyCooks

[tranquil bloom]

thats why e^ipi +1 = 0

[left robin]

that way, we see that e^ipi=e^-ipi

[silver fjord]

almost

[tranquil bloom]

alright thanks

.close

[devout snow]

Channel closed

Closed by @tranquil bloom

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[main osprey]

So the book showed me an example of a logarithmic property were they just switched a - with a positive??

What rule lets them get away with this?

[minor timber]

can u send more clear image cant see it properly of monitor

[main osprey]

They literally just put a positive here out of no where

[silver fjord]

They factored it out, no?

[main osprey]

Oh you mean they put it in another set of parentheses? So the negative would expand it back out?

[silver fjord]

ln x - ln(x+4) - ln(x-4) = ln x - [ ln(x+4) + ln(x-4) ] = ln x - ln (x+4)(x-4)

[main osprey]

I see it now

Thanks!

.close

[devout snow]

Channel closed

Closed by @main osprey

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silver peak]

Decide the square of 5a-3?

[ionic narwhal]

(5a - 3) ^ 2 = 25a² + 9 - 30a²

9 - 5a²

[silver peak]

Okay, thank you. But when you have (5a-3) (5a-3), which one do you like count? Bcs we did it in class in our head but I don’t remember how again

[ionic narwhal]

Oh

[ionic narwhal]

Simply it

(5a - 3)(5a - 3) = 25a² + 9

[red turret]

wrong

[silver peak]

The one in the middle. In the equation (5a-3) (5a-3), is it then 5a5a - 3x5a + 33??

[ionic narwhal]

(a - b)² = a² + b² - 2ab

[red turret]

yeah

where did -30a^2 pop out from

[ionic narwhal]

How is it worng?

Oh

I realise

Srry😞

[silver peak]

.

[ionic narwhal]

What?

[silver peak]

Pls 😭😭

5a • 5a - 3 • 5a + 3 • 3?

[ionic narwhal]

No

(5a)² - 2×5a×3 + 3²

Go as per the formula

Now in this equation
A = 5a
B = 3

Now just put the values

Actually there's a easier way

(5a - 3)(5a - 3) =
5a(5a - 3) -3(5a - 3)

[silver peak]

But the square sentence for (5a -3)^2 = (5a-3) (5a-3)

The formula is a^2 - 2ab + b^2

So 5a • 5a = 25a^2 - 15a + 9??

[ionic narwhal]

5a × 5a = 25a²

[silver peak]

Yes

[ionic narwhal]

How did the -15a + 9 came?

[silver peak]

2ab = -3•5a = -15a

B^2 = -3•-3 = 9

[ionic narwhal]

We do not take negative values in a formula

Just use the number
The sign is already given

2ab = 2 × 5a × 3

[silver peak]

Ohh you have to multiply it with 2 first?

[ionic narwhal]

Yea

[silver peak]

So then 2•5a = 10a

10a•3= 30a

Mkmk, thank you! 🫶

[ionic narwhal]

Yup

[silver peak]

.close

[devout snow]

Channel closed

Closed by @silver peak

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proud perch]

this is a fraction

it means "8 divided by d"

[devout snow]

Channel closed

Closed by @sharp reef

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[idle kestrel]

What does integral 1 dx mean

[idle kestrel]

What does the d stand for in dx/dy

[restive river]

d/dy(anything) would mean taking the derivative in terms of y

[stone stump]

the d is notation

[restive river]

You are integrating 1 in terms of x

[idle kestrel]

What does that mean

Ik what integrating

So what does it mean by in terms of x

[stone stump]

shouldnt your question be "what is integration" instead of asking about a specific integral?

[idle kestrel]

Ik what integration is

[stone stump]

then what exactly is your question

integration is something you do with respect to a variable

the dx says that the variable is x

[idle kestrel]

What the dx means so what does it mean by in terms of x

So d means in " terms of"?

[restive river]

The dx js to specify which variable you are working on

In case when there are many different ones

The bottom one in d(whatever)/d(whatever) is what you look for

[stone stump]

for example $\int xy dx = \frac12 x^2y$ and $\int xy dy = \frac12 x y^2$

[woven radish]

Denascite

[stone stump]

in the first you are integrating the x and in the second the y

[idle kestrel]

So integral of one dx will just be x?

[stone stump]

yes

[devout snow]

@idle kestrel Has your question been resolved?

Channel closed

Closed by @idle kestrel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vagrant spire]

This is more of a problem in translation. There's a theorem in Chinese called "垂径定理", which basically states any diameter perpendicular to a chord in a circle bisects it and the two arcs formed by it. I've hit it up in google translate, though nothing came out of it. There is that in Wikipedia, though there's only the Chinese page and the source was incorrect.
Wikipedia page: https://zh.wikipedia.org/zh-hans/垂径定理

[supple knot]

What is your math question then

[vagrant spire]

Trying to find the English translation of this theorem

(if there is)

[supple knot]

https://translate.google.com/

[vagrant spire]

look

[vagrant spire]

ˆ

[supple knot]

https://www.bing.com/translator

Bing has better Chinese translation sometimes

[dire forge]

I've never heard a name for this theorem

[vagrant spire]

hmm

[vagrant spire]

thx

found it

[dire forge]

what was it?

[vagrant spire]

Perpendicular diameter theorem

very straight forward

[dire forge]

haha, never heard of that

[vagrant spire]

probably a rarely used one

[dire forge]

I would just call it by its content: "a diameter perpendicular to a chord bisects the chord"

there doesn't seem to be any search results for "perpendicular diameter theorem"

[vagrant spire]

.closed

.solved

[dire forge]

.close

[devout snow]

Channel closed

Closed by @dire forge

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[red turret]

I literally have no idea. Also can't use integration, just pure limits.

[red turret]

no binomial.

[mellow panther]

Use the fact that $\sum_{r=1}^{\infty} r^n = \frac{r^{n+1}}{n+1}$

[woven radish]

numbily

[mellow panther]

It's not actually equal but it is the same order as that

[red turret]

how is that derived?

[mellow panther]

Approximate infinite sum by integral

[red turret]

but no integral

[mellow panther]

Wdym no integral?

[red turret]

I cant use integration in this

[mellow panther]

You just have to use the approximation, the integral is one way of deriving the approximation

[red turret]

can you show me some other way of deriving this?

i think i've seen this somewhere, but cant remember

[mellow panther]

I don't really know, I had a similar question that I missed in the exam and then someone I think the server owner Mniip told me this

[red turret]

oh np, thanks, maybe I'll wait here.

[mellow panther]

Tag helpers if it's been long

[red turret]

most of them are offline rn

<@&286206848099549185> ironic

[minor timber]

tf is that

[livid geyser]

uhh only thing I have to say is you probably meant to put something like say arbitrary variablr k representing a finit e integer on top of the summand and on the RHS k instead of r, cus you can't approximate the infinite sum, it's just divergent 🙃. Also r is a variable bound to the sum so it wouldn't make sense for it to be free on RHS

speaking to numbily I mean

[astral sierra]

Find the local maxima and inflection points for the function
fx=|x-2|+|x-4|

[devout snow]

Please read #❓how-to-get-help

[livid geyser]

bruh

Channel's taken

[devout snow]

@red turret Has your question been resolved?

[red turret]

<@&286206848099549185>

imma just shift this to #calculus

.close

[devout snow]

Channel closed

Closed by @red turret

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viscid wagon]

,rotate

[viscid wagon]

can the minimum value be negative?

[low coyote]

Yes

It could be

[viscid wagon]

4x^2 + 3y^2 + 4x - 12y + 41 can be re-written as (2x+1)^2 + 3(y-2)^2 +28 ?

[low coyote]

Yes

[viscid wagon]

so because they're squares, it doesn't matter if it's negative or not, we just need to find the value closest to zero

if y is 2, 3(y-2)^2 will be 0

but if x is 0 or -1, (2x+1)^2 will be 1

so i'm assuming that's not the answer because there's only 1 answer

@low coyote is the minimum value of z 29?

<@&286206848099549185>

[prime skiff]

Shouldn't it be 28 then?

[viscid wagon]

why 28

i forgot about decimals 💀

is (x, y) = (-0.5, 2) ?

<@&286206848099549185>

[prime skiff]

Yea put those values the squared values become 0 and hence the answer is 28

[viscid wagon]

.close

[devout snow]

Channel closed

Closed by @viscid wagon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[orchid pike]

To factor a quadratic into a perfect square

[orchid pike]

I.e, (x-1)^2

Wherein both things are the same (-1)

Does your leading coefficient need to be 1?

like x^2 + 2x + 3 or smth

(Random, maybe not factorable)

For example in completing the square - turning the quadratic standard form into vertex form

You divide middle coefficient by 2, then you plug positive and negative of that number in between. Then the first three terms create a perfect square

But what if its not 1 leading coefficient

[unique kelp]

you could theoretically still solve it as is

but usually you're gonna have a better time just dividing by the x^2 coefficient

[orchid pike]

What do you mean

You mean factoring it out

[unique kelp]

yeah factoring it out

and then you can just get rid of it if the other side of your equation is a 0

by dividing each side

[orchid pike]

I have -2x^2 -2x + 5 how would I go about doing this. I can’t factor
Would I still do -2/2 = -1
-2x^2 -2x -1 5 + 1?

[unique kelp]

you can factor it out

just divide each term by -2

[orchid pike]

but the 5

Ok

[unique kelp]

so you get -2 * (x^2 + x - 5/2)

in some cases you can get kinda messy fractions in which case maybe the quadratic equation is easier? idk

[orchid pike]

Whats wrong with leaving the leading coefficient

Would it not lead to a perfect square?

Does this technique still work

[unique kelp]

hmm

the technique I remember for completing the square doesn't account for the leading coefficient, so it wouldn't work

you could probably modify the technique slightly and get something that works

[orchid pike]

-2x^2 -2x -1

a * c = 2. Factors of 2 that add up to b are -1
-2x^2 -1x -1x -1

I assume this wouldn’t work

?

You would normally do factor by grouping here

Would it give u perfect square

[unique kelp]

I'm not sure what you mean

[unique kelp]

what would you think the solution to this is?

[orchid pike]

Idk, -1(2x^2 + 2x + 1)

If I don’t factor the 2 off the start

[unique kelp]

that's halfway to a solution

I kinda need to go now though sorry

[devout snow]

@orchid pike Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winter crag]

how to start?

[pseudo basin]

write the integrand as $\frac{\ln(\tan(x))}{\tan(x)} \cdot \frac{1}{\cos^2(x)}$

[woven radish]

Ann

[winter crag]

wait

still having problem

any substitution?

oh wait

nvm

i am getting

1/2 ln^2(tanX)

@pseudo basin

[pseudo basin]

sounds about right

[winter crag]

so how can i get form here

to A,C,D

and especially the cot how is possible?

shouldn't it be 1/cot?

[pseudo basin]

$\ln^2(1/\cot(x)) = [-\ln(\cot(x))]^2$

[woven radish]

Ann

[winter crag]

ohk

got it

ohk

i got it @pseudo basin

thanks ma'am

you help me to escape the problem as always

🫡

.close

[devout snow]

Channel closed

Closed by @winter crag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plush frigate]

since i'm looking for COE and the middle line starts, or O on the center of the protractor, how can i tell if i'm using the outer or inner scale?

[safe knoll]

use any

u get same answer

but if u are using out side scale , use it till the end of question

dont swap in the middle from outer to inner , use the same scale for the entire questions

[plush frigate]

right so

i can put 140 degrees and it'll be completely valid?

[safe knoll]

no

[plush frigate]

since E is on the 140 angle

[safe knoll]

coe isnt touching with the straight line

[safe knoll]

u need to find coe , but what u found is aoe

cuz for coe u dont need to have the angle aoc in ur answer , u only need coe

[plush frigate]

what if i tried 40 then?

would that be different?

[winged rivet]

find the function and domain

[safe knoll]

!help

[devout snow]

Please read #❓how-to-get-help

[safe knoll]

u are not getting my point

[plush frigate]

yeah i'm not understanding

[safe knoll]

in the diagram , look at the angle u need to find (COE)

[plush frigate]

yeah i know that

[winged rivet]

!help

[devout snow]

Please read #❓how-to-get-help

[safe knoll]

what do u see?

this is the angle COE that u need to find

[safe knoll]

and previously u measured angle e, over here

do u see any difference in these both angles?

[plush frigate]

yeah i see 140 is bigger

so the angle i'm looking for is a smaller number?

[safe knoll]

yes , how much bigger tho

[plush frigate]

i'm still a bit confused though, what am i suppose to be looking at to find that angle that i need?

i normally look at the last letter of the given angle

[safe knoll]

yes thats when the angle is on the straight line AOB

cuz at that point angle starts from 0

[plush frigate]

yeah

and then if it goes left to right, i'd be looking at an outer or inner scale

[safe knoll]

now , answer my question
how much bigger is angle AOE then COE

[plush frigate]

that would be hard to answer because i dont know what COE is

[safe knoll]

obviously thats when u use common sense , and u will see if the angle is either inner scale or outer scale

[safe knoll]

i have marked it already with a ?

[plush frigate]

but since this is inbetween, what type would i be looking at?

[safe knoll]

just answer my question and ill tell u

[plush frigate]

40 degrees?

is that COE

[safe knoll]

yes

[plush frigate]

so im looking at the INNER SCALE then

[safe knoll]

so that means
aoc + coe = aoe

correct?

[safe knoll]

as i said before , u can use any scale , just use that same scale for the entire question and dont swap

[safe knoll]

@plush frigate .

[plush frigate]

right ok that makes sense

[plush frigate]

yeahj

[safe knoll]

and u know how to find angles that start from 0

so just take coe as "X" and find the other angles , but then in a equation and u get ur answer

[plush frigate]

right ok

i gotchu

[safe knoll]

in this question
AOC = 25 degree
AOE = 140 degree
aoc + coe = aoe
25 + x = 140
x = 115
COE = 115

now find DOE , so that i can check if u understood the question or no?

[plush frigate]

ok hold on

DOE = 20?

[safe knoll]

no?

u are close , u didnt measure BOD properly

[plush frigate]

bod is 60

[safe knoll]

no its between 60 and 70

[plush frigate]

65

my bad

i forgot

[safe knoll]

yeah , be careful

[plush frigate]

ok so BOD = 65

[safe knoll]

and doe =?

[plush frigate]

DOE = 110?

doe has to be either 115 or 110

im guessing 115

[safe knoll]

um

how?

[safe knoll]

also in angles some times use ur eyes , looking at DOE u can see that it can not possibly be equal to 115

[plush frigate]

i used bod to find DOE

no?

[safe knoll]

i have no clue how u are getting 115

[safe knoll]

here u almost got the correct answer (DOE is 25 btw)

and now u completely deflated away

[plush frigate]

OH OK

SO what i was doing was

i used BOD to find DOE

since the D angle was at 65, i used that and counted all the way to E

which was around 115

but i see what i did wrong

i was suppose to use D, count the distance on how many it took to get to E

and i got 25

[safe knoll]

yes

or u could just count to e (from b) and then d (from b) and subtract

[plush frigate]

eh counting from d to e is easier for me lol

[safe knoll]

its preference ig

good luck btw (u can .close here to close the channel)

[plush frigate]

so i have

[safe knoll]

if u have no more questions

[plush frigate]

AOC = 25 degree
AOE = 140 degree
aoc + coe = aoe
25 + x = 140
x = 115
COE = 115
DOE = 25

what do i do with this now

[safe knoll]

uh

[plush frigate]

wait nvm sorry

[safe knoll]

coe was ur questions and doe was a test question from me

[plush frigate]

i got the answer

yeah lol mb

.close

[devout snow]

Channel closed

Closed by @plush frigate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

let f(x)=1 when x is rational, and let f(x)=0 when x is irrational

[restive river]

what is the shortest period of f(x)?

.close

[devout snow]

Channel closed

Closed by @midnight spindle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[normal quartz]

what does this mean?

[topaz axle]

pick an x, and find the y

pick a different y and find the x

[normal quartz]

thanks

[devout snow]

@normal quartz Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dawn perch]

Translation "We are going to build the structure in the picture using wooden sticks. The structure should take the form of a three-sided prism, with its base being a right-angled isosceles triangle. The volume of the prism should be 126 cm³. Determine the minimum length of wooden sticks required to construct the framework."

I know I can express the volume of it as $\frac{x^2h}{2}=126$ but I can't figure out how to express $h$ in terms of $x$ if that makes sense

[woven radish]

Dex

[devout snow]

@dawn perch Has your question been resolved?

[devout snow]

@dawn perch Has your question been resolved?

[dawn perch]

<@&286206848099549185>

[devout snow]

@dawn perch Has your question been resolved?

[dawn perch]

.close

[devout snow]

Channel closed

Closed by @dawn perch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grizzled roost]

Find all holomorphic functions $f: \mathbb{C} \rightarrow \mathbb{C}$ such that $f'(0) = 1$ and $f(x + iy) = e^x f(iy)$ for all $x, y \in \mathbb{R}$

[woven radish]

Casiel368

[grizzled roost]

I know I have to use cauchy-riemann at some point, but it doesn't reveal much information

[devout snow]

@grizzled roost Has your question been resolved?

[grizzled roost]

This is all I came up with

[devout snow]

@grizzled roost Has your question been resolved?

[grizzled roost]

<@&286206848099549185>

[grizzled roost]

<@&286206848099549185>

[still yarrow]

what class is this?

@grizzled roost

[grizzled roost]

Complex analysis

[still yarrow]

yeah too complex for me as well

goodluck

[devout snow]

@grizzled roost Has your question been resolved?

[devout snow]

@grizzled roost Has your question been resolved?

[sweet zinc]

what you trying to solve?

[grizzled roost]

This

[supple knot]

Did you solve the ODEs from the CR equations

[devout snow]

@grizzled roost Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[south rampart]

I don’t understand how to solve these.

[slender wigeon]

why not

use third eqn

[south rampart]

I don’t know what equastions to use and I don’t know what it’s using for

[slender wigeon]

u know initial vel

[south rampart]

These are the equations I can use

[slender wigeon]

also u know the final velocity

[slender wigeon]

go for bottom rightmost eqn

[south rampart]

One second

[south rampart]

How

It doesn’t tell me

Would it be 0?

[slender wigeon]

yea 0

its slows down...till 0...till then heights increasing

[south rampart]

But why is it because it doesn’t tell us?

[slender wigeon]

gravity pulling down

[south rampart]

Ok

[slender wigeon]

ball going up

vel decreasing

[lavish nimbus]

Try to have your known values up, like:
v_0 = 15 m/s
v_f = 0 m/s
a = -9.81 m/s^2

[slender wigeon]

hes asking why vf is 0

[south rampart]

How did u get -9.8

What I am confused now

[lavish nimbus]

Our positive direction is upwoards.

[slender wigeon]

sign convention

[south rampart]

I don’t understand

[slender wigeon]

or forget it..its just 9.8

alr?

[lavish nimbus]

Any force that will stay against the direction, will have a negative force.

[slender wigeon]

verfied experimentally

or mathematically

[lavish nimbus]

A easy question, why would the ball fall down?

[south rampart]

So any question that is about gravity and stuff we remember the number -9.8

[south rampart]

Gravity

[lavish nimbus]

Is the gravity a positive or negative force to the ball?

[south rampart]

Negative because it pulls it down

[lavish nimbus]

That's right, then you have a=-g

Since your ball is going up.

[south rampart]

So a = -9.8?

[lavish nimbus]

m/s^2

[south rampart]

Ok

But what equation do I use to find what is the max height it will reach

[slender wigeon]

r u allowed to go with 10

insttead of 9.8

aproximation

[south rampart]

Idk

[slender wigeon]

then use 10

its easy

[lavish nimbus]

Use this. These are all the known values.

Try to find a formula that you can substitute in to find the distance.

[south rampart]

Ok

One second

Vf=Vo+at ?

[lavish nimbus]

What are you going to find?

[south rampart]

That finds us the time I think

[lavish nimbus]

It does, but is it what the question asks?

[south rampart]

The maximum height that it will reach

So basically max height

[lavish nimbus]

Alright, what measure does the height have?

[south rampart]

H?

Oh feet

[lavish nimbus]

Like velocity have m/s

[south rampart]

So height is velocity

But we have that

[lavish nimbus]

So you're 180 m/s tall? It seems a bit akward.

[south rampart]

Since we have velocity already we should find v^2 then

[lavish nimbus]

Yep, but we are using m/s, which means we are going to use meters.

[south rampart]

Bro bro 💀

Still stuck

7a

This person was helping me tho

[lavish nimbus]

Take over if you want to.

[south rampart]

Yes

Yes

Yes

Som about gravity having to pull it down

[slender wigeon]

try a = vdv/dx

[south rampart]

Idk what that is

[slender wigeon]

boom youre free to forget signs

nvm

bruh...yea third eqn

[south rampart]

Are you saying a = deltav/t

Yes

[slender wigeon]

f vector = m times vector a

you pull something...it accelerates that thing near to u

[south rampart]

Yes

Why that equation tho out of all of them

[slender wigeon]

coz its got displacement

and both velocities

the knows parameters

we know nothing about time

[south rampart]

Oh we don’t now time that’s why we use that one

[slender wigeon]

all of the others contain time

[south rampart]

Yea ur right I just noticed that

One second ima answer it

Gotta write it