#help-27
1 messages · Page 99 of 1
so you can compose it with another function that takes a scalar argument
it's just super weird looking because + is written infix
yea i'm mostly guessing at what alex wants
It's basically what desync said
@restive river can you clarify what you mean
Just wanted to verify this. But I think it makes sense noe
But what would be better notation
define a new function g:R^n->R
by (x1,x2,...xn) -> x1+x2+...+xn
so you can consistently write everything in function notation
mindreaders the lot of u
u jelly
you can also kind of mix fold notation in and write +/(x1,x2,...xn)
but this is uncommon

Second question
Firstly
This is a proper definition for what a matrix is right:
$M : \Z_{[1, m]} \by \Z_{[1, n]} \to \R$ where
[
M(i, j) = M_{ij}
]
no
lex get some better notation
theres also no such thing as 'proper'
Z_[a, b] is absolutely cursed
if you wish to view a matrix as a function I guess that works? but your Z restriction is cursed
Hmmmmmm
i've seen worse, but it isn't great..
the only somewhat standardish and compact notation i've seen for the first n positive integers is [n]
well if it's not, then just write {1,2,...,m} x {1,2,...,n}
I would not say it is standard
of course
{1, ..., m}
that's why i said standardish, haha, at least i've seen it from multiple authors
I would need quite a bit of context to clock what you meant
if u write me f : [m] x [n] -> R
i dont think most ppl would be able to tell
agree, anyone using that should say, "where [m] means..." when they first introduce it, otherwise it's gonna be cryptic
where [m] means {m,m+1,m+2,...} 
rather than think about this though, it is better to first define R^n
tbh if ur going down this route u might as well take the set defn of numbers
0 = {}
n = {0, 1, ..., n-1}
then we have M : m x n -> R

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can you describe how you would remove the discontinuity at 5?
Honestly I don't know
a removable discontinuity is an x value where you redefine the function
so that the new function is continuous at that point
f(5) = 3.5 right now for example.
You could redefine it to be f(5) = 10 say. But you have to choose something to make the new function continuous at 5
yes.
the discontinuity at x=5 is called a "step discontinuity" or "jump discontinuity", and those are never removable
just fyi
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alr my math teacher ain't answering so lemme copy my email and send it
"Alright, for the homework thing I found on google classroom. I need to solve 8 divided by 8/9. I used a calculator and it was 9, but I am still super confused on how this works.. What I think is 8/1 divided by 8/9. 8 divided by 8 is 1, 1 divided by 9 is 1/9.. How do I turn 1/1/9 into 9??
Also..
-4/5 + 1/2 = -3/10. How? Thought it'd be -5/7."
idk how to work the bot still
someone teach me how to work that equation bot and ill like make the equations easier to understand
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dividing by a fraction is the same as multiplying by its reciprocal (the fraction "turned upside down")
so 1/(1/9) = 1 * (9/1) = 9
ohh yeah
(ty)
you can't add fractions like that
(it's been all summer I'm so confused LMAO)
you've just added the numerator and denominator
if you do that to 1/2 + 1/2 you would get 2/4
which is 1/2, and is clearly wrong
you need to have the same denominator on both fractions
ah yea now I remember
when you see 4/5, it's 4 * one fifth, and 1/2 is 1 * one half
they're not the same thing, so you can't add them directly
so the lcd is 10
i think
-8/10 + 5/10
ohhh
now i see
thank u! sorry I'm dumb 😭💀
tyty :]
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Well I was watching a video about equations with radicals because like everything in maths I find them hard to do and saw the guy do this equation which is fine but I don't really understand the last part, 0= x(x-4) and then puts as a result x = 0 and x=4 without so much as an explanation, it blew my mind, could anyone explain why he did that?
Some arbitrary a and b
But I tell you
When I multiply them I get 0
What can you tell me about this a and b I picked
@iron pond Has your question been resolved?
I don't know
Am I supposed to tell you what number they are?
Well one of them has to be 0
Exactly
So if x(x-4) = 0
Then one of them has to be 0
So either x is 0 itself
Or x is 4 which gives 4(4-4) = 4*0 = 0
Oh!
Now I get it
You had me extremely confused there for a second
Thanks, though
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hi
z^2 = i
using this formula, but my result is 1 and i?
which is not correct
1 * e^i(0+p * pi)
@west tinsel Has your question been resolved?
what did you use for |w| and arg(w)?
for |w| = sqrt(a^2+b^2)
for arg(w) = a/|w|
what specifc numbers
a = 0, |w| = 1
why is arg(w) = a/|w|, that doesn't sound right
arg(w) is the angle, and the angle of i is pi/2, not 0
really?
a/|w| would be the cosine of the arg
ya i figured it out now
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Can someone help me with grade 8 math?
I really can't understand this 😭
No 😓
but you are familiar with properties for angles
e.g. the angles G & E form a "semicircle" or rather, their sum must be 180°
I don't know the basics at all 😭
hm I currently can't visualize stuff as I'm travelling, but you do know that a full circle has 360° degrees right
Yes
if you split the circle into two equally sized semicircles using a diagonal that cuts through the circle, the two angles on both sides must have 180° each
Oh
since you just split the 360° in 2
now if you look at the first task, G & E & F & H together form a circle if you draw the angles into the image
meaning their sum must be 360°
if that becomes clear to you, all further steps become easier too
I'm starting to understand 😅
applying the same principle as I mentioned above, we now "cut" the circle of GEFH into two with a diagonal, where on the upper side are GE and on the lower side HF
since each side must have 180°, G+E = 180° and H+F = 180°
I know there are two diagonals cutting them in the image, just consider the one going up from left to right for now
which is the one that cuts GEFH into GE & FH
Ok 😅
that was the important step
because now you know G+E = 180°
and you're already given G = 72° in Task 1.
therefore E = 180°-72° = 108°
Oh
now, try continuing with 2. and so on and mention whenever you're stuck
So H is also 72°?
nop
look at only G & H for instance
both of them together form another semicircle on a diagonal
meaning their sum is 180°
Ohh
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Is the current through each resistor the same as the current through the battery, I’m new to this stuff so I’m just a little confused
In a series connection, the current stays same while in a parallel connection, potential difference (voltage) remains same.
so voltage is the same but current is different at each of the points?
this is a series connection
idk what the means
I think I get it now, since it has to go through each of the resistors it slows it down for the entire series and as such the current is constant throughout, right?
well, there is only one path for the current, so it cant change.
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Good evening, I need help understanding this evaluation of function
basically you just substitute the given value into the place of x
what
Like X = 2x+4
yea that's given right
just think of it as a number
substitute it and continue solving
you should end up at the ans then
So if there's like X^2
It should be (2x+4) (2x+4)
you solving this?
@restive river Has your question been resolved?
No.
So in the 2ns image
2nd*
The X is X+6
The one I got confuse is
How I can solve it
@restive river Has your question been resolved?
although i dont like such notations, i think it's just finding
f(x+6)
which you replace all the x's in the original f(x) into (x+6)
and simplify
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hi I just had a question
when drawing a box and whisker plot, do u need to add the outliers as well
when I searched it online, it said yes, but it didn't show the outliers within the lines so i was confused
the max and min lines I mean
@cunning perch Has your question been resolved?
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I'm trying to understand the relationship between expected wait time and probability. For example, let's say that person A is taking turns rolling a d6, and person B is taking turns rolling a d4. Players want to wager a fair amount for who will roll a 1 first. We know that person A's expected wait time is 6 turns, and person B's expected wait time is 4 turns. But I'm not sure how to get from that to determine what is the probability that person B sees a 1 before person A does
what happens if they both roll a 1
Then they would continue rolling until one has a 1 and the other doesn't
in that case it's simple enough, there are 24 possibilities; in how many of them does A win? in how many of them does B win?
The actual problem I'm trying to solve is this: Player A is flipping coins until he gets sequence TTH, and B is flipping until he gets TTT. I've calculated that A's wait time is 4 flips, and B's wait time is 6 flips. I'm not sure if this would be the same answer as the above question (I thought it would be simpler to ask that one)
but there are an infinite number of possibilities. A and B could roll 3s for a thousand turns, for example
yep, and they'll be right back where they started
the only possibilities that matter are the ones where either A or B win
the original question is easier; consider playing until TT occurs
before TT occurs, no one could have won
are they the same coin or different coins
they each have their own coin
ignore what i said then
That does make sense. I think I understand for the dice question.
ooh TTH has a strong advantage here i think
yes, TTH has a big advantage
Solution to the dice problem
(sorry in meeting looking at this in a min)
basically even if u dont use that exact thing, i would just recommend drawing a tree diagram
which may be recursive
right
the diagram for the coins is much more involved 
actually ttt has one advantage which is that they're more likely to win ties
this is like a Markov chain problem or something, there are so many states (13 or so)
this is harder than I thought it was going to be
I was trying to come up with a good brainteaser for a smart friend
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Given two square matrices of the same size D and N, D is diagonal and N is nilpotent. Do we have det(D+N)=det(D)?
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need help with a few problems
@vernal lotus Has your question been resolved?
<@&286206848099549185>
can yu help me
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$\int_{2}^{5/2}(\sqrt{4x-x^2}+2)\sqrt{(\frac{4-2x}{\sqrt{4x-x^2}})^2 + 1}dx$
I'm thinking there has to be a faster way to solve this monstrosity of an integral but I can't seem to find it. I honestly don't even know how to approach this so help would be appreciated lol
NepDep
I think what comes to mind first is to take
$$u = \sqrt{4x - x^{2}}$$
Sherif Player
But I have no idea if it would help
yeah, where would du go
maybe expanding the square might lead to a solution
but nothing stuck out to me when i did that
ill just do it a second time and see whats there
$$du = \frac{4-2x}{2 \sqrt{ 4x - x^{2}}} dx$$
yeah i found nothing when i expanded the square
maybe i set up the integral wrong to begin with?
Sherif Player
Doesn't work very well
This is the original problem, i need to find the surface area of the solid of revolution
im thinking if i set up the integral wrong this might be an easier question in disguise
i shouldve used y rather than x
lemme try
So you say we should have takin the integration with respect to y not x?
well not really
i was taking integration with respect to y but i wrote it as x because im dumb
As it is around y-axis
$$Y^{2} - 4Y + 4 = 4 - X^{2}$$
$$X^{2} = 4Y - Y^{2}$$
$$X = \sqrt{4Y - Y^{2}}$$
So we want to take the integration of that one
Sherif Player
ok i got it
do you want working
i was just taking the one i saw and thought it was in terms of y for some reason
here it is if you are interested:
so the derivative of that would be 4-2y(4y-y^2)^-1/2
nws
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$\int e^{\cos x} \left ( \frac{x\sin^3 x + \cos x}{\sin^3 x} \right ) , \dd x$
NEON
That looks ugly
Oh boy it sure does
The worst part is I don't even know where to begin
There's no clue in this structure
perhaps but what does simplify entail
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💀
,w integrate (e^(cos x))(xsin^3 x + cos x)/(sin^3 x) dx
rip
oh wait
this isnt that bad
nvm
it is
,w integrate (e^(cos x))(xsin(x)^3+ cos x)/(sin(x)^3)
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Bro
ayoo
where you got this from?
btw not sure, but the denominator is sin^2x lol
crosscheck if possible
and this question will use this (if it really is sin^2(x))
Bro why is everyone so interested in the origin of the question lmao
In any case, it is the cube of sine
Dyssrupt
that tells whether it might even be solvable in many cases
oh
this is why
We have more robotic integration
hmm
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For c I'm guessing you can't have both can you?
Uhhh
why can't you have both
a person may hold a passport and a VRC at once, can they not?
they need only present one at the checkpoint, but they can give either one...
you can enter your own country with a voter's card
If I leave the country won’t I return w a passport?
noones saying you don't unless you lost it for some reason
But you don't need both of them do you? 
in the scenario its just saying that you don't technically need one
I think the word "need" is what's making me hesitant
you don't need both, is not the same as you can't have both
its inclusive or
which is what you've said
you need to have at least one of them
they're not saying you must have only one of them
contrast with the "soup or salad" example
exclusive or would be them telling you that you can't enter if you do have both
Losing a passport serious issue!!
noones saying it isn't
i bet you'll spend some time in an interview room being grilled if you try to enter even your own country without a passport
they'll want to know where you've been, at least
(unless you're in a passport-free zone like the EU)
(d) seems like possibly a trick question, your institution wants you to publish and they may or may not care if you also perish as long as you publish 😁
you don't need both but you aren't forbidden from entry with both
(there are potential issues if they aren't your own though)
Not where I live
Jorji is that you
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I wanted to find the best u such that
log_2(x+1) is best aproximated by x+u(range 0-1).
I calculated the integral of the difference and set it equal to 0 to minimize the difference (https://www.wolframalpha.com/input?i2d=true&i=Integrate[Divide[ln\(40)x%2B1\(41)%2Cln\(40)2\(41)]-\(40)x%2Bm\(41)%2C{x%2C0%2C1}]%3D0) and the answer came out to be around u≈0.057305.
A different source said that it was 0.043.
Where did I go wrong?
difference? absolute difference? absolute difference squared?
there are quite a few different options of what "approximates best" means
Uh
It was to minimize the |average difference |
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"We will have a future, provided that people believe in science"
In if...then form then this is just "if people believe in science then we will have a future", correct?
yeah seems correct
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quintuple coose
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I need help understanding angle addition identities. I'm working on sin(A+B) = cos(A)sin(B) + sin(A)cos(B). I'm not sure how to draw the 2 triangles on the unit circle. This is what I have tried in Whiteboard:
https://wbd.ms/share/v2/aHR0cHM6Ly93aGl0ZWJvYXJkLm1pY3Jvc29mdC5jb20vYXBpL3YxLjAvd2hpdGVib2FyZHMvcmVkZWVtLzAxYWMwODI1YWVhMDQ4ZTk4OWU2NmUyN2Y2NzJkZDY1X0JCQTcxNzYyLTEyRTAtNDJFMS1CMzI0LTVCMTMxRjQyNEUzRF81Y2IzYWI3Mi03YTBiLTRiNTQtODFiMS00MTMwMmE5YzA4OTQ=
Will I draw the 2 triangles as overlapping or as literally next to each other, not overlapping?
This is a ghost town....I'm frightened....
Hello, Hello, Hello?
it has been ten minutes.
after getting through microsoft's login bullshit, i can say: this is somewhat of a poor diagram.
I know, I'm learning
i can show you a better diagram if you're okay with that.
Yes, of course, thank you.
it has the drawback of only really working with angles between 0 and 90°
but it is very visual
Well, I guess it's a first step. I'm just going through the Khan Academy and this is on the menu.
Ah, so the first thing I see is that my assumptions of the angle having to be drawn always horizontal/vertical are wrong. It can be drawn literally at any angle.
of course.
an angle's still an angle no matter how you spin it.
anyway i copied this from a tutoring session whiteboard so just tell me and i will put point names on it.
Okay, that helps tremendously so far. I need to remember that the triangle spins
most anything in geometry spins
Okay but can this be drawn and visualized on the unit circle also. I just noticed this is a free standing triangle. I only see 1 point that is in bold and I'm not sure it's on the perimter of any circle.
visualizing this on the unit circle requires some vector shit.
if you're ok with that, i can try making one.
Well, it's worth a shot. I'm a beginner but I'll look at it. Thank You.
be warned i'm going to take some time with this
No problem, I'm here for a few years, so please take your time. I'm not going anywhere.
@dusty valley Has your question been resolved?
here
i said it was vector bullshit and it is vector bullshit, mostly some mildly annoying vector algebra.
also i forgot to color-code them in steps III and IV, oops.
@dusty valley
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all these are vectors:
AF=AB+AC; CE=2AB; BD=1/3BC
There are two questions. no1 is answered, and am stuck in no2 :
express AE as a function of AB and AC
I Answered till here:
AE=AC+CE
=2AB+AC
Is it finished or do i have to calculate it
$AF→=AB→+AC→; CE→=2AB→; BD→=1/3BC→
Express AE→ as a function of AB→ and AC→$
Minds&Moves
did you draw a picture
@floral blaze Has your question been resolved?
!15min
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
Its passed 15 minutes!!
!!
You ping the helpers two times in one minute
oh.. cuz they said feel free to ping helpers
Read it
<@&286206848099549185>
@floral blaze Has your question been resolved?
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Simplify. Rationalize all denominators. Assume that all the variables are positive.
I tried to solve this question but I got -(90-42sqrt3)/269.. how to solve it?
Doesn't seem right, could you show your work?
Yeah not what I'm getting either
In those cases, always multiply by the conjugate, I assume it's what you've done but there might be a miscalculation somewhere
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Hi, I'm trying to learn Basic Calculus and I have a quiz by next week. I am having a hard time following the "Introduction to Limits" since I have skipped the majority of algebra itself. I am having a hard time understanding it.
I cannot explain it in a concise manner but I have this image, I do not have any work because I am just studying it and have no idea what the solution is because of my lack of knowledge in Algebra.
This is just the first image, there are a ton more that get progressively difficult. This is not homework, this came from a presentation sent by our teacher to study at home.
I have tried to search videos like Khan's Academy's explanation but they use f(x) without the "lim" and it's driving me crazy on what's right.
I want to know how to solve it including its actual solution, I have a hard time understanding its whole concept because of my lack of Algebra knowledge. My teacher said that algebra is going to play a huge part in this and that this topic is required and mandatory to learn to be able to understand and progress our calculus course.
I have a lot more images coming up with longer equations, I've tried searching for videos about it but they are confusing.
I do not even know how and when I should consider a limit a constant.
So, what it's saying is, as x approaches some number C
what does f(x) approach?
Or, view f(x) as y
L?
It's also confusing because the equations differ.
Yes, L would be the answer right?
So how do I solve it? Is there any formula procedure to follow?
So, for any y= a constant value
Like, 1, 0, e, or 1835
What would y equal if x = 0?
If 0 is constant, will the answer be 0 as well?
Well okay lets say we are given the equation y=0
What would y equal if x=0?
Sorry, I am having a hard time solving this, I do not know but is it still 0? I am sorry for being this difficult.
We're basically moving away from the limits for now
I'm asking what would y equal when x=0 for the equation y=0 (a horizontal line)
Sorry, I still don't get it. Can you teach me while I take notes?
Gotcha
I just don't have any knowledge of mathematics, I skipped a lot of math courses and I regret doing it resulting in me not knowing anything from graphs to probability even fractions. This feel like a Level 100 boss in a game in easy mode.
I basically have the intellect of an elementary student in math, only in math.
Should I pull up a graph?
Sure.
Actually, pull up desmos.com
it's a graphing feature that would help us quite a bit
Now, put in y=x
Now, on this graph
We have the x axis (the darker horizontal line)
and the y axis (the darker, vertical line)
Yes, I'm listening and taking notes.
Basically, we want to find where on the x axis it equals 1
and, where on the red line that x=1
For this specific line, we can see that x =1 at where y=1
and vice versa
okay that was really badly explained
If you need a better one lemme know before continuing
Okay okay lets back track
Basically, on the graph, the line examines exactly where the y value is equal to the x value
For example, when we trace where y is equal to 1, then the x value is equal to 1.
Yes.
So, by tracing the line, what is the value of y when x equals 2?
Okay so I'm going to have you make that line, and now put y=x on top of it.
Where these two lines cross, that is the solution for y.
Is this right?
Oh, sorry I didn't know Desmos could do that.
Sorry for being difficult, I didn't know I was this bad in Algebra. I'm going to try and understand this one in my time. Will this be essential in Limits?
for the equation, y=x
Well... calculus requires the knowledge of everything before it
And it will be quite needed
Holy damn... I am hopeless.
not quite.
now word problems, you probably don't need to go over
But as long as you learn all of the different equations, as well as most of trig you should be fine
Now, that's a hell of a task
quite literally condensing all of grade school math into a small timeframe
But, I believe it is possible to do
Understanding the graph and the linear equation is one part of it.
The problem is I do not have a simple guideline as to where to start. Like.
- Learn Addition
- Learn Subtraction
- Learn Multiplication
- Learn Division
I'm trying to be on the right track, chronological order may be the right term? Like in movies, it gets progressive as it goes on like it gets harder as it goes on.
Like movies, you will not know the plot of what you're watching if you are watching part 4 before part 3.
Is there a proper way on what I should learn to prepare me for basic calculus?
I may be able to study everything before tomorrow.
- Learn the coordinate plane
- Learn linear equations (What is slope? what are the different forms of the linear equation? what is m? what is b?)
- Learn quadratic equations (What is a vertex? how do you know if it is a max/min? what are roots/solutions/zeros? how do you factor? Quadratic Equation? How do you find domain/range?)
- learn higher order polynomial equations (what are even/odd polynomials? What is synthetic division? How do you use p/q to factor? What is domain restriction?)
- Learn Rational functions, root functions, logarithmic, and e (What are they, how do they shift? What is e used for?)
- Learn Trig (what is soh cah toa? sin, cos, trig, and their opposites? How do you shift them? What is csc, sec, and cot? what is the inverses?)
- bring it all together in calculus.
Here's a basic guide for equations
These go through the different levels of algebra, like the basics in pre-alg, then alg 1 with linear equations and quadratic equations, then geometry with triangles and trig, then alg 2 with higher order polynomials as well as rational functions, roots, and logarithms. and finally, the rest of trig.
I'm going to be honest, I don't believe someone can do this in a day
But, it's possible.
And I have high hopes for you
I can vc to help you learn
I'll study these things first personally then maybe ask for help again here. I am going to dig up some notes I may have written in the past grades and see if it may help in this current situation.
but the real goats are khan academy
Yes, it's been recommended by many.
not starting at calc
I'm going to try it again.
but definitely starting at lower grade levels
I'll study these before I reach college, or else I may need to change my engineer course to something more timid like architecture.
architecture requires a vast knowledge of physics, of which is calc based.
unless you are the designer, which requires less of it
but it does require less calc than engineering, that is true
I do believe that you can perservere, and I'm here for it
Thank you, I have taken notes for the steps you've recommended. I will be closing this channel now. Not everyone had the patience to withstand my illiteracy in Mathematics. Thank you for setting me on the right track again, at least this time I know where to actually start. Thank you again.
.close
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how do i solve this and whats the answer?
!show
Show your work, and if possible, explain where you are stuck.
i dont now how to start it
do i take the inverse tangent of -12/5 and subtract it with the inverse cosine of 3/5?
you shouldn't be using any inverse functions for this question
it's also supposed to be a non-calculator question
draw reference triangles, apply pythag and based on the location of the angles
determine
sin(A), cos(A), sin(B)
@timber kite Has your question been resolved?
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Can you provide the question
why is this not good?
I looked in the notebook and I have two different results
does not match -2
x/3 is x here 1?
Just a picture of the statement of the question from where ever you're reading it from
or regular x
Because we do not know what you're doing without the question
Without knowing what the question is how could I possibly answer that
Of? This is alot easier if you just send a picture of the question
So you never took the derivative of -5/3
i guess no
And the derivative of -5/3 is?
0?
but why is the derivative of (-1/3-5/3)
huh
someone else
how to the dervative of e pow(x+2)?
<@&286206848099549185>
brb have to eat
just do chain rule on e^x and x+2
@restive river Has your question been resolved?
To better answer this, you multiply the derivative of e^(x+2) times the derivative of x+2, which is the chain rule
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e^-x where x is = 0
$e^{-0} = \frac {1}{e^0} = \frac 11 = 1$
Stephen
Stephen
Use l'hop.
Other way around
huh
Sin(0) = 0
Closed by @tender wind
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.reopen
✅
Right
So e^-x * -1
got it
No
It doesn’t go back
Maybe I shoulda said “yes”
But u get it
:o what a neat number

if you get 0, 1, 2, π or e then the answer must clearly be correct
wait really
Lol it’s a joke
it was meant as a joke like the ones who make questions are lazy
Unless ur a uni teacher and wanna trick ur kids
hahaha
A dastardly action indeed
reminds me of a time where we had to simplify a tan equation and the result was 1 + 1 💀
Lol
in this lim should i transform it into -tan x over cos x
My bad, I might have gotten confused when I said this
This works
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!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
3
So basically I thought in order to solve this problem you would have to take the derivatives of both of x(t) and y(t) and see what value of t both of the derivatives result in 0
so what did you get
the derivative of x(t) is 3t^2 - 6t
the derivative of y(t) = 12 - 6t
so t has to be 0 or 2
but it has to be 2 because it has to satisfy y(t) too
Yea
all good so far
so now we just plug 2 back into x(t) and y(t)
could not agree more
Bro solved it by himself
lmao
what did u get
ye
12

oh
lmao
no problem
.close
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HELLO
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
Be patient, post your question, and if you're respectful someone will help
Post ur question homes
is that me
okay
i dont have like a paper
but i was wondering
wait wait
Do u know what algebraitic equations is
because im not sure on how to do it
Hmm
I think I know what ur referring to
But send a problem so I can see what ur having trouble with
Alright
how do i do it
So what’s troubling u with this
There’s no actual formula to these
But essentially, u wanna get all the terms with an x on one side, and all the terms without an x to the other side
the only one with an x is 2x
Good
But there’s also a term without an x on the left side
How would u move it to the right
No, the -3
oh thats easy
-3 turns into +3
since uhm
You are basically doing the equation backwards
so its 2x + 3
Wdym by turns into
what about the 7
No
?
Is it right
No
oh
Maybe it would be more helpful if u watched a video on this concept first, maybe this one could help: https://youtu.be/q3g68vcMXxM?feature=shared
#MathIsSimple #Grade 7 #Expressions #Equations
Solving Two-Step Equations | Expressions & Equations | Grade 7
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subsitutes
To at least get a foundation
kay
This guy boring
Boom
easy dub
i found out
okay
MY BAD
so
negative 3 becomes positive 3
Don’t say becomes
lets pretend there is a mirror line
It doesn’t make sense
The opposite operation
So currently it’s minus 3 on the left
So we add 3 to both sides
Ok
so now its like 2x+10
so now
we need to find out what x is
so x X 2 = ?
5
5 X 2 = 10
X= 5
ez dub
come on
dab me up
No
What’s -7 + 3
uh
-10
Where u come from
this dude helped me out
and i did it
nO
HOW
I WATCHED THE VIDEO
Is it 10
7
My bad
haha
SOEELING MISTKWE
4
my bad bro
my keyboard
HENSN,SHSHHAIO
WHY IM I SO DUMB
STUPID MATHS
im in the dark
okay
wait
Where did the other dude go
THAT WAS MY GUY
-7 + 3
my GuY
Same as 3-7
EZ
-4
ahem
I CANT DELETE IT
WHAT
uh
helllo
i NEED HELP MY GUY
please bro
u a smart dude
i didnt
i worked it out before
The other guys help
helped me work it out
just wrote it down to check
Ok so now what do we have now
Show how u got that
No
What is 3 + -7
How do u keep getting 10 lol
That’s not what we’re doing tho
since a positive and a negative converts into a positive
It’s 3 + -7
