#help-27

1 messages · Page 99 of 1

robust dust
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addition can be viewed as a function that takes a vector and returns a scalar (the sum of its components)

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so you can compose it with another function that takes a scalar argument

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it's just super weird looking because + is written infix

supple knot
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yea i'm mostly guessing at what alex wants

restive river
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It's basically what desync said

supple knot
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@restive river can you clarify what you mean

restive river
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But what would be better notation

robust dust
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define a new function g:R^n->R

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by (x1,x2,...xn) -> x1+x2+...+xn

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so you can consistently write everything in function notation

placid rover
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mindreaders the lot of u

supple knot
robust dust
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you can also kind of mix fold notation in and write +/(x1,x2,...xn)

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but this is uncommon

placid rover
restive river
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Second question

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Firstly

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This is a proper definition for what a matrix is right:

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$M : \Z_{[1, m]} \by \Z_{[1, n]} \to \R$ where
[
M(i, j) = M_{ij}
]

woven radishBOT
supple knot
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no

placid rover
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lex get some better notation

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theres also no such thing as 'proper'

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Z_[a, b] is absolutely cursed

robust dust
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if you wish to view a matrix as a function I guess that works? but your Z restriction is cursed

supple knot
restive river
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Hmmmmmm

wicked turtle
placid rover
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compact is not the only issue

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[n] is rather overloaded

wicked turtle
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well if it's not, then just write {1,2,...,m} x {1,2,...,n}

placid rover
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I would not say it is standard

wicked turtle
placid rover
#

{1, ..., m}

wicked turtle
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that's why i said standardish, haha, at least i've seen it from multiple authors

placid rover
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I would need quite a bit of context to clock what you meant

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if u write me f : [m] x [n] -> R

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i dont think most ppl would be able to tell

wicked turtle
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agree, anyone using that should say, "where [m] means..." when they first introduce it, otherwise it's gonna be cryptic

robust dust
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where [m] means {m,m+1,m+2,...} lipbite

placid rover
woven radishBOT
placid rover
# woven radish

tbh if ur going down this route u might as well take the set defn of numbers

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0 = {}
n = {0, 1, ..., n-1}

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then we have M : m x n -> R
monke

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opaque terrace
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opaque terrace
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just learned discontinutiy stuff and i'm struggling

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i think it's 1,5 and 7

wicked turtle
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can you describe how you would remove the discontinuity at 5?

opaque terrace
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Honestly I don't know

placid rover
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a removable discontinuity is an x value where you redefine the function

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so that the new function is continuous at that point

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f(5) = 3.5 right now for example.

You could redefine it to be f(5) = 10 say. But you have to choose something to make the new function continuous at 5

opaque terrace
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Oh ok

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So thinking that, it woiuld just be 1 and 7 then I think

placid rover
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yes.

wicked turtle
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the discontinuity at x=5 is called a "step discontinuity" or "jump discontinuity", and those are never removable

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just fyi

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solemn ginkgo
#

alr my math teacher ain't answering so lemme copy my email and send it

"Alright, for the homework thing I found on google classroom. I need to solve 8 divided by 8/9. I used a calculator and it was 9, but I am still super confused on how this works.. What I think is 8/1 divided by 8/9. 8 divided by 8 is 1, 1 divided by 9 is 1/9.. How do I turn 1/1/9 into 9??
Also..
-4/5 + 1/2 = -3/10. How? Thought it'd be -5/7."

solemn ginkgo
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idk how to work the bot still

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someone teach me how to work that equation bot and ill like make the equations easier to understand

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,help

woven radishBOT
#

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

robust dust
#

dividing by a fraction is the same as multiplying by its reciprocal (the fraction "turned upside down")

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so 1/(1/9) = 1 * (9/1) = 9

solemn ginkgo
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ohh yeah

robust dust
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also brackets

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(1/1)/9 is not the same as 1/(1/9)

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for future reference

solemn ginkgo
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so then 1/8 ÷ 8/9 that makes life easier lmao

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what abt the second one?

solemn ginkgo
robust dust
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you can't add fractions like that

solemn ginkgo
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(it's been all summer I'm so confused LMAO)

robust dust
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you've just added the numerator and denominator

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if you do that to 1/2 + 1/2 you would get 2/4

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which is 1/2, and is clearly wrong

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you need to have the same denominator on both fractions

solemn ginkgo
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ah yea now I remember

robust dust
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when you see 4/5, it's 4 * one fifth, and 1/2 is 1 * one half

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they're not the same thing, so you can't add them directly

solemn ginkgo
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so the lcd is 10

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i think

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-8/10 + 5/10

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ohhh

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now i see

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thank u! sorry I'm dumb 😭💀

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tyty :]

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robust dust
#

no worries -- nothing to be sorry for, we're all learning here 🙂

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iron pond
#

Well I was watching a video about equations with radicals because like everything in maths I find them hard to do and saw the guy do this equation which is fine but I don't really understand the last part, 0= x(x-4) and then puts as a result x = 0 and x=4 without so much as an explanation, it blew my mind, could anyone explain why he did that?

jaunty mantle
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If I tell you a*b = 0

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What can you tell me about a and/or b

iron pond
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What...?

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Sorry, I don't really understand what you're trying to ask

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What a? What b?

jaunty mantle
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Some arbitrary a and b

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But I tell you

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When I multiply them I get 0

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What can you tell me about this a and b I picked

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iron pond
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Am I supposed to tell you what number they are?

jaunty mantle
#

Yes

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0 is very special

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If I have a number a

iron pond
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Well one of them has to be 0

jaunty mantle
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Exactly

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So if x(x-4) = 0

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Then one of them has to be 0

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So either x is 0 itself

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Or x is 4 which gives 4(4-4) = 4*0 = 0

iron pond
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Oh!

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Now I get it

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You had me extremely confused there for a second

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Thanks, though

#

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west tinsel
#

hi

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west tinsel
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z^2 = i

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using this formula, but my result is 1 and i?

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which is not correct

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1 * e^i(0+p * pi)

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wicked turtle
west tinsel
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for arg(w) = a/|w|

wicked turtle
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what specifc numbers

west tinsel
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a = 0, |w| = 1

wicked turtle
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why is arg(w) = a/|w|, that doesn't sound right

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arg(w) is the angle, and the angle of i is pi/2, not 0

west tinsel
wicked turtle
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a/|w| would be the cosine of the arg

west tinsel
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ya i figured it out now

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west tinsel
#

i needed to take cos(v) = 0

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which is pi/2

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worn python
#

Can someone help me with grade 8 math?

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worn python
worn python
timid whale
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do you know

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the properties

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of a transversal

worn python
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No 😓

strange arch
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but you are familiar with properties for angles

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e.g. the angles G & E form a "semicircle" or rather, their sum must be 180°

worn python
strange arch
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hm I currently can't visualize stuff as I'm travelling, but you do know that a full circle has 360° degrees right

strange arch
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if you split the circle into two equally sized semicircles using a diagonal that cuts through the circle, the two angles on both sides must have 180° each

strange arch
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since you just split the 360° in 2

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now if you look at the first task, G & E & F & H together form a circle if you draw the angles into the image

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meaning their sum must be 360°

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if that becomes clear to you, all further steps become easier too

worn python
strange arch
#

applying the same principle as I mentioned above, we now "cut" the circle of GEFH into two with a diagonal, where on the upper side are GE and on the lower side HF

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since each side must have 180°, G+E = 180° and H+F = 180°

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I know there are two diagonals cutting them in the image, just consider the one going up from left to right for now

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which is the one that cuts GEFH into GE & FH

strange arch
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that was the important step

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because now you know G+E = 180°

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and you're already given G = 72° in Task 1.

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therefore E = 180°-72° = 108°

worn python
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Oh 😭

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Tysm

strange arch
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you'd say G and E are supplementary

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because of the above explanation

worn python
strange arch
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now, try continuing with 2. and so on and mention whenever you're stuck

worn python
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So H is also 72°?

strange arch
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nop

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look at only G & H for instance

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both of them together form another semicircle on a diagonal

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meaning their sum is 180°

worn python
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Ohh

strange arch
#

likewise H&F together form a semicircle

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E&F do as well

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mint cove
#

Is the current through each resistor the same as the current through the battery, I’m new to this stuff so I’m just a little confused

red turret
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In a series connection, the current stays same while in a parallel connection, potential difference (voltage) remains same.

mint cove
red turret
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this is a series connection

mint cove
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idk what the means

mint cove
red turret
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well, there is only one path for the current, so it cant change.

mint cove
#

alright, thank you

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restive river
#

Good evening, I need help understanding this evaluation of function

static oracle
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basically you just substitute the given value into the place of x

restive river
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No no

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I was confuse of like

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The x is value

static oracle
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what

restive river
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Like X = 2x+4

static oracle
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yea that's given right

restive river
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Ye

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I was confuse on how

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To solve it that way

static oracle
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just think of it as a number

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substitute it and continue solving

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you should end up at the ans then

restive river
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So if there's like X^2

It should be (2x+4) (2x+4)

static oracle
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yes

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doubled

restive river
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So it's like 2+2

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Wait x

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2x2 is 4
While 2x4 is 8

(2x^2+8x+8x+16)

static oracle
restive river
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I'm solving it on paper

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Ignoring the pic atm

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restive river
#

No.

restive river
#

2nd*

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The X is X+6

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The one I got confuse is

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How I can solve it

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long pasture
#

although i dont like such notations, i think it's just finding
f(x+6)

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which you replace all the x's in the original f(x) into (x+6)

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and simplify

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cunning perch
#

hi I just had a question

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cunning perch
#

when drawing a box and whisker plot, do u need to add the outliers as well

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when I searched it online, it said yes, but it didn't show the outliers within the lines so i was confused

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the max and min lines I mean

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cunning perch
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heavy tinsel
#

I'm trying to understand the relationship between expected wait time and probability. For example, let's say that person A is taking turns rolling a d6, and person B is taking turns rolling a d4. Players want to wager a fair amount for who will roll a 1 first. We know that person A's expected wait time is 6 turns, and person B's expected wait time is 4 turns. But I'm not sure how to get from that to determine what is the probability that person B sees a 1 before person A does

paper latch
#

what happens if they both roll a 1

heavy tinsel
#

Then they would continue rolling until one has a 1 and the other doesn't

winter torrent
#

in that case it's simple enough, there are 24 possibilities; in how many of them does A win? in how many of them does B win?

heavy tinsel
#

The actual problem I'm trying to solve is this: Player A is flipping coins until he gets sequence TTH, and B is flipping until he gets TTT. I've calculated that A's wait time is 4 flips, and B's wait time is 6 flips. I'm not sure if this would be the same answer as the above question (I thought it would be simpler to ask that one)

heavy tinsel
winter torrent
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the only possibilities that matter are the ones where either A or B win

paper latch
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before TT occurs, no one could have won

winter torrent
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are they the same coin or different coins

paper latch
#

o wait yeah sorry

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important distinction

heavy tinsel
paper latch
#

ignore what i said then

heavy tinsel
winter torrent
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ooh TTH has a strong advantage here i think

heavy tinsel
#

yes, TTH has a big advantage

paper latch
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Solution to the dice problem

heavy tinsel
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(sorry in meeting looking at this in a min)

paper latch
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basically even if u dont use that exact thing, i would just recommend drawing a tree diagram

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which may be recursive

heavy tinsel
#

right

winter torrent
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the diagram for the coins is much more involved bearlain

heavy tinsel
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yeah I'm a bit stuck haha

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for wait time it wasn't too bad

winter torrent
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actually ttt has one advantage which is that they're more likely to win ties

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this is like a Markov chain problem or something, there are so many states (13 or so)

heavy tinsel
#

this is harder than I thought it was going to be

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I was trying to come up with a good brainteaser for a smart friend

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steel sage
#

Given two square matrices of the same size D and N, D is diagonal and N is nilpotent. Do we have det(D+N)=det(D)?

steel sage
#

Someone gave me a counterexample

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So not true

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vernal lotus
#

need help with a few problems

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vernal lotus
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<@&286206848099549185>

restive river
#

what

#

???

vernal lotus
restive river
#

ye

#

lemme see

vernal lotus
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restive river
#

idk

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im too stoopid

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low walrus
#

$\int_{2}^{5/2}(\sqrt{4x-x^2}+2)\sqrt{(\frac{4-2x}{\sqrt{4x-x^2}})^2 + 1}dx$

I'm thinking there has to be a faster way to solve this monstrosity of an integral but I can't seem to find it. I honestly don't even know how to approach this so help would be appreciated lol

woven radishBOT
#

NepDep

rapid merlin
#

I think what comes to mind first is to take
$$u = \sqrt{4x - x^{2}}$$

woven radishBOT
#

Sherif Player

rapid merlin
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But I have no idea if it would help

low walrus
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yeah, where would du go

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maybe expanding the square might lead to a solution

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but nothing stuck out to me when i did that

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ill just do it a second time and see whats there

rapid merlin
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$$du = \frac{4-2x}{2 \sqrt{ 4x - x^{2}}} dx$$

low walrus
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yeah i found nothing when i expanded the square

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maybe i set up the integral wrong to begin with?

woven radishBOT
#

Sherif Player

rapid merlin
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Doesn't work very well

low walrus
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This is the original problem, i need to find the surface area of the solid of revolution

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im thinking if i set up the integral wrong this might be an easier question in disguise

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i shouldve used y rather than x

prisma snow
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lemme try

rapid merlin
#

So you say we should have takin the integration with respect to y not x?

low walrus
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well not really

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i was taking integration with respect to y but i wrote it as x because im dumb

rapid merlin
#

As it is around y-axis

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$$Y^{2} - 4Y + 4 = 4 - X^{2}$$
$$X^{2} = 4Y - Y^{2}$$
$$X = \sqrt{4Y - Y^{2}}$$
So we want to take the integration of that one

woven radishBOT
#

Sherif Player

prisma snow
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ok i got it

low walrus
#

oh

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oh my god im an idiot lol

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i was integrating the wrong function

prisma snow
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do you want working

low walrus
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i was just taking the one i saw and thought it was in terms of y for some reason

prisma snow
#

here it is if you are interested:

low walrus
#

so the derivative of that would be 4-2y(4y-y^2)^-1/2

prisma snow
#

oops wait

low walrus
#

wow youre fast

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but the answer key said the answer was 2pi

prisma snow
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yeah i forgot to square too

low walrus
#

this is so helpful

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thx

prisma snow
#

nws

low walrus
#

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pastel pasture
#

$\int e^{\cos x} \left ( \frac{x\sin^3 x + \cos x}{\sin^3 x} \right ) , \dd x$

woven radishBOT
stark shuttle
#

That looks ugly

pastel pasture
#

Oh boy it sure does

#

The worst part is I don't even know where to begin

#

There's no clue in this structure

stark shuttle
#

My guess is to simplify and IBP?

#

"I think"

pastel pasture
#

perhaps but what does simplify entail

stark shuttle
#

Maybe changing the sin^3?

#

What does Wolfram say?

pastel pasture
#

the one on top or bottom

#

,w integrate (e^(cos x))(xsin^3 x + cos x)/(sin^3 x)

woven radishBOT
pastel pasture
#

💀

sinful gust
#

,w integrate (e^(cos x))(xsin^3 x + cos x)/(sin^3 x) dx

#

rip

#

oh wait

#

this isnt that bad

#

nvm

#

it is

sinful gust
#

part of a solution to a DE?

hybrid snow
#

,w integrate (e^(cos x))(xsin(x)^3+ cos x)/(sin(x)^3)

woven radishBOT
hybrid snow
#

Bro

red turret
#

where you got this from?

#

btw not sure, but the denominator is sin^2x lol

#

crosscheck if possible

#

and this question will use this (if it really is sin^2(x))

pastel pasture
#

Bro why is everyone so interested in the origin of the question lmao

#

In any case, it is the cube of sine

woven radishBOT
#

Dyssrupt

sinful gust
red turret
pastel pasture
pastel pasture
#

No mine definitely says cube

red turret
#

hmm

pastel pasture
#

meh I'll figure something out

#

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#
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restive river
devout snowBOT
restive river
#

For c I'm guessing you can't have both can you?

stark shuttle
#

Uhhh

pseudo basin
#

why can't you have both

#

a person may hold a passport and a VRC at once, can they not?

#

they need only present one at the checkpoint, but they can give either one...

young crane
#

What country?

#

Never entered a country w a voter’s card

restive river
young crane
#

If I leave the country won’t I return w a passport?

winter patrol
#

noones saying you don't unless you lost it for some reason

restive river
winter patrol
#

in the scenario its just saying that you don't technically need one

restive river
#

I think the word "need" is what's making me hesitant

robust dust
#

you don't need both, is not the same as you can't have both

robust dust
#

which is what you've said

wicked turtle
#

you need to have at least one of them

#

they're not saying you must have only one of them

#

contrast with the "soup or salad" example

robust dust
#

exclusive or would be them telling you that you can't enter if you do have both

winter patrol
#

or an item costs
1 euro or
2 usd

#

can't hurt to have more money

young crane
winter patrol
#

noones saying it isn't

wicked turtle
#

i bet you'll spend some time in an interview room being grilled if you try to enter even your own country without a passport

#

they'll want to know where you've been, at least

#

(unless you're in a passport-free zone like the EU)

#

(d) seems like possibly a trick question, your institution wants you to publish and they may or may not care if you also perish as long as you publish 😁

pseudo basin
winter patrol
#

(there are potential issues if they aren't your own though)

young crane
#

Not where I live

winter torrent
devout snowBOT
#

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fervent patio
#

I wanted to find the best u such that
log_2(x+1) is best aproximated by x+u(range 0-1).
I calculated the integral of the difference and set it equal to 0 to minimize the difference (https://www.wolframalpha.com/input?i2d=true&i=Integrate[Divide[ln\(40)x%2B1\(41)%2Cln\(40)2\(41)]-\(40)x%2Bm\(41)%2C{x%2C0%2C1}]%3D0) and the answer came out to be around u≈0.057305.

A different source said that it was 0.043.
Where did I go wrong?

Wolfram|Alpha brings expert-level knowledge and capabilities to the broadest possible range of people—spanning all professions and education levels.

stone stump
#

difference? absolute difference? absolute difference squared?

#

there are quite a few different options of what "approximates best" means

fervent patio
#

Uh

fervent patio
#

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restive river
#

"We will have a future, provided that people believe in science"

restive river
#

In if...then form then this is just "if people believe in science then we will have a future", correct?

fallen saffron
#

yeah seems correct

restive river
#

Ok ty

#

. close

#

. Close

#

. close

#

. close

#

. close

#

Bruh

#

.close

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#
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pseudo basin
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#
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dusty valley
dusty valley
#

Will I draw the 2 triangles as overlapping or as literally next to each other, not overlapping?

#

This is a ghost town....I'm frightened....

#

Hello, Hello, Hello?

pseudo basin
pseudo basin
dusty valley
#

I know, I'm learning

pseudo basin
#

i can show you a better diagram if you're okay with that.

dusty valley
#

Yes, of course, thank you.

pseudo basin
#

it has the drawback of only really working with angles between 0 and 90°

#

but it is very visual

dusty valley
#

Well, I guess it's a first step. I'm just going through the Khan Academy and this is on the menu.

pseudo basin
#

tell me if you need me to label stuff on the diagram.

dusty valley
#

Ah, so the first thing I see is that my assumptions of the angle having to be drawn always horizontal/vertical are wrong. It can be drawn literally at any angle.

pseudo basin
#

of course.

#

an angle's still an angle no matter how you spin it.

#

anyway i copied this from a tutoring session whiteboard so just tell me and i will put point names on it.

dusty valley
#

Okay, that helps tremendously so far. I need to remember that the triangle spins

pseudo basin
#

most anything in geometry spins

dusty valley
#

Okay but can this be drawn and visualized on the unit circle also. I just noticed this is a free standing triangle. I only see 1 point that is in bold and I'm not sure it's on the perimter of any circle.

pseudo basin
#

visualizing this on the unit circle requires some vector shit.

#

if you're ok with that, i can try making one.

dusty valley
#

Well, it's worth a shot. I'm a beginner but I'll look at it. Thank You.

pseudo basin
#

be warned i'm going to take some time with this

dusty valley
#

No problem, I'm here for a few years, so please take your time. I'm not going anywhere.

devout snowBOT
#

@dusty valley Has your question been resolved?

pseudo basin
#

here

#

i said it was vector bullshit and it is vector bullshit, mostly some mildly annoying vector algebra.

#

also i forgot to color-code them in steps III and IV, oops.

#

@dusty valley

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floral blaze
#

all these are vectors:
AF=AB+AC; CE=2AB; BD=1/3BC
There are two questions. no1 is answered, and am stuck in no2 :
express AE as a function of AB and AC
I Answered till here:
AE=AC+CE
=2AB+AC
Is it finished or do i have to calculate it

floral blaze
#

$AF→=AB→+AC→; CE→=2AB→; BD→=1/3BC→
Express AE→ as a function of AB→ and AC→$

woven radishBOT
#

Minds&Moves

floral blaze
#

Someone told me that it's solved

#

but we're looking for AB+AC not 2AB+AC

supple knot
#

did you draw a picture

floral blaze
#

no

#

so is it solved orrr?

devout snowBOT
#

@floral blaze Has your question been resolved?

floral blaze
#

<@&286206848099549185>

#

<@&286206848099549185>

ancient ravine
#

!15min

devout snowBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

floral blaze
#

Its passed 15 minutes!!

ancient ravine
#

You ping the helpers two times in one minute

floral blaze
#

oh.. cuz they said feel free to ping helpers

floral blaze
#

ok

#

so? helps?

floral blaze
#

<@&286206848099549185>

devout snowBOT
#

@floral blaze Has your question been resolved?

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#
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forest lily
devout snowBOT
forest lily
#

is

#

(450)/(4* pi *r^2) = dr/dt

#

correct

#

.close

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#
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weak cape
#

Simplify. Rationalize all denominators. Assume that all the variables are positive.

weak cape
#

I tried to solve this question but I got -(90-42sqrt3)/269.. how to solve it?

sonic smelt
#

Doesn't seem right, could you show your work?

sacred spade
#

Yeah not what I'm getting either

sand dove
#

In those cases, always multiply by the conjugate, I assume it's what you've done but there might be a miscalculation somewhere

devout snowBOT
#

@weak cape Has your question been resolved?

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autumn osprey
#

Hi, I'm trying to learn Basic Calculus and I have a quiz by next week. I am having a hard time following the "Introduction to Limits" since I have skipped the majority of algebra itself. I am having a hard time understanding it.

I cannot explain it in a concise manner but I have this image, I do not have any work because I am just studying it and have no idea what the solution is because of my lack of knowledge in Algebra.

This is just the first image, there are a ton more that get progressively difficult. This is not homework, this came from a presentation sent by our teacher to study at home.

I have tried to search videos like Khan's Academy's explanation but they use f(x) without the "lim" and it's driving me crazy on what's right.

autumn osprey
#

<@&286206848099549185>

sacred spade
#

Gotcha

#

So do you want it just explained or?

autumn osprey
#

I want to know how to solve it including its actual solution, I have a hard time understanding its whole concept because of my lack of Algebra knowledge. My teacher said that algebra is going to play a huge part in this and that this topic is required and mandatory to learn to be able to understand and progress our calculus course.

#

I have a lot more images coming up with longer equations, I've tried searching for videos about it but they are confusing.

sacred spade
#

Mmm

#

Alrighty

autumn osprey
sacred spade
#

So, what it's saying is, as x approaches some number C

#

what does f(x) approach?

#

Or, view f(x) as y

autumn osprey
#

L?

sacred spade
#

Correct

#

As y approaches some number, being the limit L

autumn osprey
#

It's also confusing because the equations differ.

autumn osprey
#

So how do I solve it? Is there any formula procedure to follow?

sacred spade
#

So, for any y= a constant value

#

Like, 1, 0, e, or 1835

#

What would y equal if x = 0?

autumn osprey
#

If 0 is constant, will the answer be 0 as well?

sacred spade
#

What would y equal if x=0?

autumn osprey
#

Sorry, I am having a hard time solving this, I do not know but is it still 0? I am sorry for being this difficult.

sacred spade
#

I'm asking what would y equal when x=0 for the equation y=0 (a horizontal line)

autumn osprey
#

Sorry, I still don't get it. Can you teach me while I take notes?

sacred spade
#

Gotcha

autumn osprey
#

I just don't have any knowledge of mathematics, I skipped a lot of math courses and I regret doing it resulting in me not knowing anything from graphs to probability even fractions. This feel like a Level 100 boss in a game in easy mode.

sacred spade
#

Ooooh

#

okay

#

Lets start with the most basic equation then

#

y=x.

autumn osprey
#

I basically have the intellect of an elementary student in math, only in math.

autumn osprey
#

I wrote it down.

sacred spade
#

so, what does x equal if y = 1?

#

(plug in 1 for y)

autumn osprey
#

Should I pull up a graph?

sacred spade
#

Sure.

autumn osprey
sacred spade
#

it's a graphing feature that would help us quite a bit

autumn osprey
sacred spade
#

Now, put in y=x

autumn osprey
sacred spade
#

Now, on this graph

#

We have the x axis (the darker horizontal line)

#

and the y axis (the darker, vertical line)

autumn osprey
#

Yes, I'm listening and taking notes.

sacred spade
#

Basically, we want to find where on the x axis it equals 1

#

and, where on the red line that x=1

#

For this specific line, we can see that x =1 at where y=1

#

and vice versa

#

okay that was really badly explained

#

If you need a better one lemme know before continuing

autumn osprey
sacred spade
#

Okay okay lets back track

#

Basically, on the graph, the line examines exactly where the y value is equal to the x value

#

For example, when we trace where y is equal to 1, then the x value is equal to 1.

autumn osprey
#

Yes.

sacred spade
#

So, by tracing the line, what is the value of y when x equals 2?

autumn osprey
sacred spade
#

Okay so I'm going to have you make that line, and now put y=x on top of it.

#

Where these two lines cross, that is the solution for y.

autumn osprey
#

Is this right?

sacred spade
#

Not quite.

#

This is what you should have.

autumn osprey
#

Oh, sorry I didn't know Desmos could do that.

sacred spade
#

No problem.

#

Basically, this means that, when x is equal to 2, then y is equal to 2

autumn osprey
#

Sorry for being difficult, I didn't know I was this bad in Algebra. I'm going to try and understand this one in my time. Will this be essential in Limits?

sacred spade
#

for the equation, y=x

sacred spade
#

And it will be quite needed

autumn osprey
#

Holy damn... I am hopeless.

sacred spade
#

not quite.

#

now word problems, you probably don't need to go over

#

But as long as you learn all of the different equations, as well as most of trig you should be fine

#

Now, that's a hell of a task

#

quite literally condensing all of grade school math into a small timeframe

#

But, I believe it is possible to do

#

Understanding the graph and the linear equation is one part of it.

autumn osprey
#

The problem is I do not have a simple guideline as to where to start. Like.

  1. Learn Addition
  2. Learn Subtraction
  3. Learn Multiplication
  4. Learn Division
#

I'm trying to be on the right track, chronological order may be the right term? Like in movies, it gets progressive as it goes on like it gets harder as it goes on.

#

Like movies, you will not know the plot of what you're watching if you are watching part 4 before part 3.

#

Is there a proper way on what I should learn to prepare me for basic calculus?

#

I may be able to study everything before tomorrow.

sacred spade
#
  1. Learn the coordinate plane
  2. Learn linear equations (What is slope? what are the different forms of the linear equation? what is m? what is b?)
  3. Learn quadratic equations (What is a vertex? how do you know if it is a max/min? what are roots/solutions/zeros? how do you factor? Quadratic Equation? How do you find domain/range?)
  4. learn higher order polynomial equations (what are even/odd polynomials? What is synthetic division? How do you use p/q to factor? What is domain restriction?)
  5. Learn Rational functions, root functions, logarithmic, and e (What are they, how do they shift? What is e used for?)
  6. Learn Trig (what is soh cah toa? sin, cos, trig, and their opposites? How do you shift them? What is csc, sec, and cot? what is the inverses?)
  7. bring it all together in calculus.
#

Here's a basic guide for equations

#

These go through the different levels of algebra, like the basics in pre-alg, then alg 1 with linear equations and quadratic equations, then geometry with triangles and trig, then alg 2 with higher order polynomials as well as rational functions, roots, and logarithms. and finally, the rest of trig.

#

I'm going to be honest, I don't believe someone can do this in a day

#

But, it's possible.

#

And I have high hopes for you

#

I can vc to help you learn

autumn osprey
#

I'll study these things first personally then maybe ask for help again here. I am going to dig up some notes I may have written in the past grades and see if it may help in this current situation.

sacred spade
#

but the real goats are khan academy

autumn osprey
sacred spade
#

not starting at calc

autumn osprey
#

I'm going to try it again.

sacred spade
#

but definitely starting at lower grade levels

autumn osprey
#

I'll study these before I reach college, or else I may need to change my engineer course to something more timid like architecture.

sacred spade
#

architecture requires a vast knowledge of physics, of which is calc based.

#

unless you are the designer, which requires less of it

#

but it does require less calc than engineering, that is true

#

I do believe that you can perservere, and I'm here for it

autumn osprey
#

Thank you, I have taken notes for the steps you've recommended. I will be closing this channel now. Not everyone had the patience to withstand my illiteracy in Mathematics. Thank you for setting me on the right track again, at least this time I know where to actually start. Thank you again.

#

.close

devout snowBOT
#
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timber kite
#

how do i solve this and whats the answer?

devout snowBOT
lapis flint
#

!show

devout snowBOT
#

Show your work, and if possible, explain where you are stuck.

timber kite
#

i dont now how to start it

#

do i take the inverse tangent of -12/5 and subtract it with the inverse cosine of 3/5?

winter patrol
#

you shouldn't be using any inverse functions for this question

#

it's also supposed to be a non-calculator question

#

draw reference triangles, apply pythag and based on the location of the angles
determine
sin(A), cos(A), sin(B)

timber kite
#

like thatv

#

i have this

#

is 33/65 right?

devout snowBOT
#

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restive river
devout snowBOT
restive river
#

why is this not good now?

#

in notebook says -1/3 not -2

wooden veldt
#

Can you provide the question

restive river
#

why is this not good?

#

I looked in the notebook and I have two different results

#

does not match -2

#

x/3 is x here 1?

wooden veldt
#

Just a picture of the statement of the question from where ever you're reading it from

restive river
#

or regular x

wooden veldt
#

Because we do not know what you're doing without the question

restive river
#

is the solution I pictured good?

#

last example

#

3*e

wooden veldt
#

Without knowing what the question is how could I possibly answer that

restive river
#

hyh

#

Derivative

wooden veldt
#

Of? This is alot easier if you just send a picture of the question

restive river
#

I already have a solution, but I'm styding

wooden veldt
#

So you never took the derivative of -5/3

restive river
#

i guess no

wooden veldt
#

And the derivative of -5/3 is?

restive river
#

0?

#

but why is the derivative of (-1/3-5/3)

#

huh

#

someone else

#

how to the dervative of e pow(x+2)?

#

<@&286206848099549185>

#

brb have to eat

robust dust
#

just do chain rule on e^x and x+2

devout snowBOT
#

@restive river Has your question been resolved?

sacred spade
devout snowBOT
#
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tender wind
#

e^-x where x is = 0

devout snowBOT
tender wind
#

gives what

#

E^-0 is still 1 right

quaint citrus
#

$e^{-0} = \frac {1}{e^0} = \frac 11 = 1$

woven radishBOT
#

Stephen

quaint citrus
#

Or just

#

$e^{-0} = e^0 = 1$

woven radishBOT
#

Stephen

strange arch
tender wind
#

alr

#

ty

#

sin (1) is 0 right

#

nvm

quaint citrus
#

Other way around

tender wind
#

huh

quaint citrus
#

Sin(0) = 0

tender wind
#

Ohh

#

yes

#

sorry

#

.close

devout snowBOT
#
Channel closed

Closed by @tender wind

Use .reopen if this was a mistake.

tender wind
#

.reopen

devout snowBOT
#

tender wind
#

when i differentiate e^-x

#

it gives e^-x still right

#

with *-1

quaint citrus
#

Right

tender wind
#

e^-x and this stays the same

#

it doesnt go back to e^x

quaint citrus
#

So e^-x * -1

tender wind
#

got it

quaint citrus
#

It doesn’t go back

#

Maybe I shoulda said “yes”

#

But u get it

tender wind
#

kk

#

so

#

1+1 over 1

#

2

strange arch
tender wind
strange arch
#

if you get 0, 1, 2, π or e then the answer must clearly be correct

tender wind
#

wait really

strange arch
#

:D

#

no

quaint citrus
#

Lol it’s a joke

tender wind
#

ah

#

i thought it was a trick

strange arch
#

it was meant as a joke like the ones who make questions are lazy

quaint citrus
#

Unless ur a uni teacher and wanna trick ur kids

tender wind
#

hahaha

quaint citrus
#

A dastardly action indeed

prisma snow
#

reminds me of a time where we had to simplify a tan equation and the result was 1 + 1 💀

quaint citrus
#

Lol

tender wind
#

in this lim should i transform it into -tan x over cos x

tender wind
#

how do i evaluate this

#

-sin x / cos^2 (x)

main gull
main gull
strange arch
#

@tender wind

devout snowBOT
#

@tender wind Has your question been resolved?

#
Channel closed

Closed by @tender wind

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

plush light
devout snowBOT
robust dust
#

!status

devout snowBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
plush light
#

3

#

So basically I thought in order to solve this problem you would have to take the derivatives of both of x(t) and y(t) and see what value of t both of the derivatives result in 0

robust dust
#

so what did you get

plush light
#

the derivative of x(t) is 3t^2 - 6t

#

the derivative of y(t) = 12 - 6t

#

so t has to be 0 or 2

#

but it has to be 2 because it has to satisfy y(t) too

green kelp
#

Yea

robust dust
#

all good so far

plush light
#

so now we just plug 2 back into x(t) and y(t)

ripe mason
#

could not agree more

green kelp
#

Bro solved it by himself

restive river
#

lmao

plush light
#

what

#

no

#

i got it wrong though

restive river
#

what did u get

plush light
#

x(2) = 8 - 12

#

-4

restive river
#

ye

plush light
#

12

restive river
#

ye

#

so A?

green kelp
plush light
#

oh

restive river
#

lmao

plush light
#

bruh

#

thanks guys

restive river
#

no problem

plush light
#

.close

devout snowBOT
#
Channel closed

Closed by @plush light

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tawny summit
#

HELLO

devout snowBOT
tawny summit
#

?!

#

ANYONE HERE

#

<@&286206848099549185>

devout snowBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

tawny summit
#

i need help with algebratic equations

#

PLEASE

#

I SAW U DUDE

#

YES

lyric hornet
#

Be patient, post your question, and if you're respectful someone will help

tawny summit
#

sorry

#

its my first time

#

can u help me

#

pleas

#

E

quaint citrus
#

Post ur question homes

tawny summit
#

is that me

#

okay

#

i dont have like a paper

#

but i was wondering

#

wait wait

#

Do u know what algebraitic equations is

#

because im not sure on how to do it

quaint citrus
#

Hmm

#

I think I know what ur referring to

#

But send a problem so I can see what ur having trouble with

tawny summit
quaint citrus
#

Alright

tawny summit
#

how do i do it

quaint citrus
#

So what’s troubling u with this

tawny summit
#

the formula

#

what do i do first

#

how do i solve it

quaint citrus
#

There’s no actual formula to these

#

But essentially, u wanna get all the terms with an x on one side, and all the terms without an x to the other side

tawny summit
#

the only one with an x is 2x

quaint citrus
#

Good

#

But there’s also a term without an x on the left side

#

How would u move it to the right

tawny summit
#

i have no idea

#

but are u talking about the 7

#

-7

#

hello

#

uh

#

SORRY IF IM DUMB

quaint citrus
#

No, the -3

tawny summit
#

oh thats easy

#

-3 turns into +3

#

since uhm

#

You are basically doing the equation backwards

#

so its 2x + 3

quaint citrus
#

Wdym by turns into

tawny summit
#

what about the 7

quaint citrus
#

No

tawny summit
#

?

tawny summit
quaint citrus
#

No

tawny summit
#

oh

quaint citrus
#

Maybe it would be more helpful if u watched a video on this concept first, maybe this one could help: https://youtu.be/q3g68vcMXxM?feature=shared

#MathIsSimple #Grade 7 #Expressions #Equations
Solving Two-Step Equations | Expressions & Equations | Grade 7

Like to learn more math problems from Middle School to Algebra on Math is Simple!, SUBSCRIBE! https://www.youtube.com/channel/UCDiq57azrogGN7gFa2LJC7A

Visit the Math is Simple! website: www.mathissimple.com

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▶ Play video
tawny summit
#

subsitutes

quaint citrus
#

To at least get a foundation

tawny summit
#

kay

#

This guy boring

#

Boom

#

easy dub

#

i found out

#

okay

#

MY BAD

#

so

#

negative 3 becomes positive 3

quaint citrus
#

Don’t say becomes

tawny summit
#

lets pretend there is a mirror line

quaint citrus
#

It doesn’t make sense

tawny summit
#

so it happens on both sides

#

what shall i say

#

Substitute

#

?

quaint citrus
#

The opposite operation

#

So currently it’s minus 3 on the left

#

So we add 3 to both sides

tawny summit
#

yeah

#

OH

#

that makes sense

#

okay

#

PRETEND THERE IS A MIRROR LINE OKAY

quaint citrus
#

Ok

tawny summit
#

so now its like 2x+10

#

so now

#

we need to find out what x is

#

so x X 2 = ?

#

5

#

5 X 2 = 10

#

X= 5

#

ez dub

#

come on

#

dab me up

quaint citrus
#

No

tawny summit
#

WHAT

#

its not right ?

quaint citrus
#

What’s -7 + 3

tawny summit
#

uh

#

-10

#

Where u come from

#

this dude helped me out

#

and i did it

#

nO

#

HOW

#

I WATCHED THE VIDEO

#

Is it 10

#

7

#

My bad

#

haha

#

SOEELING MISTKWE

#

4

#

my bad bro

#

my keyboard

#

HENSN,SHSHHAIO

#

WHY IM I SO DUMB

#

STUPID MATHS

#

im in the dark

#

okay

#

wait

#

Where did the other dude go

#

THAT WAS MY GUY

quaint citrus
#

-7 + 3

tawny summit
#

my GuY

quaint citrus
#

Same as 3-7

tawny summit
#

EZ

#

-4

#

ahem

#

I CANT DELETE IT

#

WHAT

#

uh

#

helllo

#

i NEED HELP MY GUY

#

please bro

#

u a smart dude

quaint citrus
#

Homey

#

Why u use calculator

#

What’s the point

tawny summit
#

i didnt

#

i worked it out before

#

The other guys help

#

helped me work it out

#

just wrote it down to check

quaint citrus
#

Ok so now what do we have now

tawny summit
#

lets see

#

-5

#

X=-5

quaint citrus
#

Show how u got that

tawny summit
#

okay

#

so

#

is it right

#

OKAY

quaint citrus
#

No

tawny summit
#

MIRROR LINE

#

HEHM,AKJ

#

HOW

#

STUPID MATHS

quaint citrus
#

What happened after u added -7 + 3

#

What did u so from there

tawny summit
#

i did 3+-7

#

then it becomes positive

#

10

#

2 x x = 5

quaint citrus
#

What is 3 + -7

tawny summit
#

hold up

#

im gonna use everything i have

quaint citrus
#

How do u keep getting 10 lol

tawny summit
#

10

#

look at this my dude

#

i do 3+7

quaint citrus
#

That’s not what we’re doing tho

tawny summit
#

since a positive and a negative converts into a positive

quaint citrus
#

It’s 3 + -7