#help-27

1 messages · Page 94 of 1

edgy thicket
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How does this idea help with the signs tho?

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I mean sure i can say that sin(90+x) = cosx

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But

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When it comes to the cos(90+x) its

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OUUH

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Right cos(90+x) = -sinx cause the cos value of the top left side is negative

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Am i making sense?

craggy escarp
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Yes

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It's at the left of the origin 0

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it's then < 0

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for sine, below x-axis and below zero

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then < 0

edgy thicket
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Riggttt

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I have one more problem..(its trig related)

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Can i ask you?

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Or you thinks just too exhausting for today?

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@craggy escarp

craggy escarp
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Ask

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Sure

edgy thicket
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Sin(270+x)

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Why is it -cosine

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By the same logic shouldn’t it be positive cosine since the value of cos is positive on the 4th quadrant

craggy escarp
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Look at the sine of 270+x

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it's below zero

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So, it is negative

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y-axis

edgy thicket
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Assuming green is sin and blue cos?

craggy escarp
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y-axis is ALWAYS sine

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x-axis is ALWAYS cosine

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Well yeah, if you're looking at it that way

edgy thicket
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So thats a no?

craggy escarp
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the green segments are sine, true

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i was looking in a different way

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the blue segments are cosine

edgy thicket
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I marked the yellow as sin

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Is this correct?

craggy escarp
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for x, yes

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but for 270+x, no

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that is its cosine

edgy thicket
craggy escarp
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you do not reverse

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the vertical is always sine

edgy thicket
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You dont reverse

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I know that sorey

craggy escarp
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the horizontal is always cosine

edgy thicket
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No wait

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Ill mark the sin for the 270+x

craggy escarp
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okay

edgy thicket
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This???

craggy escarp
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Right!

edgy thicket
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Are we sure?

craggy escarp
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yes, it's the y-component

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Look at its length

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it is the same as the cosine of x

edgy thicket
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And the cosine for the 270+x is this righy?

craggy escarp
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yess

edgy thicket
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Oe the one on the x axis

craggy escarp
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both

edgy thicket
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Oshh

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Wiatt

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They look like.. idk maybe triangles in different orientations

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So like…

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Hmmzz

craggy escarp
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yes right

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with cosine being adjacent to the angle

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and sine being opposite

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that's SOHCAH

edgy thicket
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Um.. if we marked the vertices

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Would this be a correct way of writing them?

craggy escarp
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Yes, you could say 😛

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It looks as if we rotated the first triangle

edgy thicket
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Yess

craggy escarp
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270° anti-clockwise

edgy thicket
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Thats why i for some reason my Brian said rotated lol

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OH MY FRIGGING gosh

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I finally understand this sheiße

craggy escarp
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Nice to hear that!

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I'll give you another and tell me

edgy thicket
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Oki

craggy escarp
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cos(x-90) = ?

edgy thicket
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Um.. nope cant do the other way around

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Unless

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Ahh

craggy escarp
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just draw x and x-90

edgy thicket
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Cos-(90-x)

craggy escarp
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and look at x-90's cosine

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Leave it as x-90

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What's the problem!

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Just do it the same way

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draw x and (x-90)

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look at cosine of (x-90)

edgy thicket
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X - 90 you say?

craggy escarp
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yes

edgy thicket
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How can I subtract 90 degrees from an acute angle?

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Like waaa?

craggy escarp
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Rotate x by 90° clockwise

edgy thicket
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Hmm

craggy escarp
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  • is counter clockwise
edgy thicket
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Well i kinda said that here

craggy escarp
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the - is clockwise

edgy thicket
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So like we can get the values at the normal quadrants but we just multiply the answer with negative ?

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Sorryb

craggy escarp
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never mind, never mind

edgy thicket
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Whattt

craggy escarp
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maybe my understanding is a little advanced

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i'll give you another

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cos(180-x)

edgy thicket
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Little advanced 😥

edgy thicket
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-cosx

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Am I correct?

craggy escarp
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Right

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cos(180+x) = ?

edgy thicket
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Irsssss

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-cosx again

craggy escarp
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Right!

edgy thicket
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Haha

craggy escarp
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cos(270-x)

edgy thicket
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Waitt

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Oh no waiy

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Yess its

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-cosx

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Sorry

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Took a little longer cause I didn’t see the x was negative

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Am I correct vvv

craggy escarp
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you're right about the minus

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But it's actually -sin(x)

edgy thicket
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Ohh crapp

craggy escarp
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Check again

edgy thicket
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I see it now

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Noo

craggy escarp
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😝

edgy thicket
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Lol look at this

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I solved for sin

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Instead of cos

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And the minus i forgot to add

craggy escarp
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i see!

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it's okay, well done

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you got the hang of it

edgy thicket
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Jesus youre like my teacher now

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Lol

craggy escarp
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😋

edgy thicket
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Okay um i would like to solve the x-90 one

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Hold on

craggy escarp
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Maybe you were not yet taught the notion of negative angles

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All you meet for now are positive angles

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Counter Clockwise

edgy thicket
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Would the answer be: sinx

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Positive sin x

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@craggy escarp

craggy escarp
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For what question?

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cos(x-90) = ?

edgy thicket
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Yea😭

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I have a feeling that im incorrect now

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But just say the answer

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🙏

craggy escarp
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correct

edgy thicket
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WOAH

craggy escarp
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😃

edgy thicket
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No way

craggy escarp
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Haha

edgy thicket
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You’re lying lmao

craggy escarp
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No, it actually is correct

edgy thicket
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Ayy

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Yk what i did?

craggy escarp
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Wut!

edgy thicket
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Dis

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My brain is too simple

craggy escarp
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I cannot analyze that right now sadly

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I gotta disconnect now now

edgy thicket
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Omg oki

craggy escarp
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Well done!

edgy thicket
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Be friends?

craggy escarp
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Good luck, I will see you around

edgy thicket
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okay

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Bye

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Whatt

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Wait no what

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Bro got thanos snapped

devout snowBOT
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@edgy thicket Has your question been resolved?

devout snowBOT
#
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grim mountain
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4x^2+7x+2=0

devout snowBOT
grim mountain
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4x^2-x+8x+2=0

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X(4x-1) +8x+2=0

near stone
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!status

devout snowBOT
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
grim mountain
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X(4x-1) +2(4x+1)=0

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Stuck here

near stone
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Take the common terms and simplify

grim mountain
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I couldn’t factor out

restive river
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the solution isnt rational, so factoring doesnt work

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use the quadratic formula instead

near stone
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use quadratic formula

grim mountain
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I know but I don’t have the same 4x-1

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Or 4x+1

near stone
near stone
grim mountain
near stone
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Do you know how quadratic formula works?

grim mountain
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Yeah

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A^2+b^2= a+b)(a-b)

near stone
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No not that

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,tex .quadratic formula

woven radishBOT
near stone
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This what I mean

grim mountain
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Ah I figured

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I use pq formula

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If I use pq formula I will have 7/4 which is bothersome

near stone
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Wdym by pq?

grim mountain
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I’ll make a sketch out of it

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One moment

near stone
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I live in Canada and never heard something like this

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Is this what you used?

grim mountain
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Yeah

near stone
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Oh I see

grim mountain
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I can’t use abc-formula

near stone
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Well honestly quadratic formula is easier

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Never heard of this before

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Do you still need help? or done

grim mountain
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The only reason I didn’t do pq formula at first is 7/4

near stone
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Does the question asking you to solve it by pq formula or quadratic

grim mountain
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It just says solve the solution

near stone
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I see

grim mountain
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Can I simply square root 1/2

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It was a x^0.5 right?

near stone
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I suggest you using the quadratic formula because this formula you are using doesn't makes sense at all

grim mountain
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Is quadric formula abc formula?

near stone
grim mountain
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I can’t use that

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If I use that formula I’ll fail tests

near stone
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Why can't you use that wdym

grim mountain
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Against school teachings

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We use pq formula

near stone
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Oh that's the point

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But do you know how to use Wolfram

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It tells to use quadratic

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,w calc 4x^2+7x+2=0

woven radishBOT
near stone
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see

grim mountain
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I won’t learn like that

near stone
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Well you just learned it

grim mountain
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Can I simplify square root 1/2?

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.close

devout snowBOT
#
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naive basin
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(\left|z_1\right| = 15) and (\theta_1 = 209^\circ). Express (z_1) in rectangular form as (z_1 = a + bi), where (a) and (b) are rounded to the nearest thousandth.

naive basin
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$(\left|z_1\right| = 15) and (\theta_1 = 209^\circ). Express (z_1) in rectangular form as (z_1 = a + bi), where (a) and (b) are rounded to the nearest thousandth.$

woven radishBOT
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TangentLINE

naive basin
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Can somebody please help

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Now, since (\theta_1 = 209^\circ), we subtract it from (360^\circ) and it equals (151^\circ). We are already given that (\left|z_1\right| = 15). Putting these two together, we have (15\left(\cos(151^\circ) + i\sin(151^\circ))). We then distribute the (15) and we will have our answer.

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$(\left|z_1\right| = 15) and (\theta_1 = 209^\circ). Express (z_1) in rectangular form as (z_1 = a + bi), where (a) and (b) are rounded to the nearest thousandth.$

woven radishBOT
#

TangentLINE

naive basin
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$Now, since (\theta_1 = 209^\circ), we subtract it from (360^\circ) and it equals (151^\circ). We are already given that (\left|z_1\right| = 15). Putting these two together, we have (15\left(\cos(151^\circ) + i\sin(151^\circ))). We then distribute the (15) and we will have our answer.$

woven radishBOT
#

TangentLINE
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

naive basin
#

.close

devout snowBOT
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short stag
#

Help me please. Using double and triple integrals.

devout snowBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
short stag
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1

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Please, help me.

mild comet
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Can you find the boundary constraints on the solid?

devout snowBOT
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@short stag Has your question been resolved?

short stag
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Please help me.

neat ember
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Hi

short stag
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I don't know how to solve it. Huhu

coral crescent
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we have symmetry here so we can just cut the shape 3 times and just get the volume of this slice and multiply by 8, see if this helps

short stag
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Hi, I can't really get it. Huhu

coral crescent
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Don't understand how we cut it?

short stag
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I barely understand it. Sorry.

coral crescent
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it's alright

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Start with sketching the body

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that's always where you want to start when doing work like this

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making solving much easier

short stag
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Getting this problem right is my only chance to pass this course. But I am so dumbfounded right now.

coral crescent
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you can draw it in 2D and make your brain fill the gaps

coral crescent
short stag
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Please, I don't want to fail this course.🥹

coral crescent
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well have you understood what i said before :p

short stag
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That's my problem right now. I am stuck looking at the graph.

coral crescent
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can you show me the graph you have

short stag
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But, would it be helpful if I convert the equations to polar coordinates?

coral crescent
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oh you meant the one i sent okay

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let's work it out in Cartesian coordinates now and worry about polar later

short stag
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Okay.x

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I really don't understand how I can cut it. Im so sorry.

coral crescent
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we have this shape right? we can cut it in half and get the volume of the other half

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and to get the full volume we multiply by 2

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got me?

short stag
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I see. Im following.

coral crescent
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and since we cut 2 times we should multiply by 4

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and with the 2 from the previous cut, we should multiply the same section by 8

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reminder we can do all this since we have symmetry

short stag
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Wait, im getting lost.

coral crescent
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cut at xoy and cut at zoy plane

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we get these 4 "quadrants" right?

short stag
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Yes yes. So that's why it should be multiplied by 4. Knowing we have a symmetry.

coral crescent
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yes, should be enough to get the volume of one of these quadrants then multiply by 8 to get the volume of the entire body

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so good so far?

short stag
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Yes yes. But how do I get the volume of one quadrant?🥲

coral crescent
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first we choose Which axis we want to work on first

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y axis seems the easiest

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oops

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i meant square root

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sorry another blunder

short stag
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The given is 18.

coral crescent
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lemma delete all this

coral crescent
short stag
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It's alright. You are a great help already.

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So the radius is 3√2?

coral crescent
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yah ok from 0 to sqrt(18)

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so yah 3sqrt2

short stag
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Ok ok

coral crescent
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now we can choose to either work on x or z plane

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ah actually before that

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we need to separate the body at where the cone and sphere intersect

short stag
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How do we do that?🥲

coral crescent
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x^2 + y^2 + z^2 - 18 = x^2 - y^2 + z^2

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and fortunately for us stuff cancel out nicely here

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and we can calculate the value of y

short stag
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y = 3?

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+-3

coral crescent
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correct

short stag
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OMG. Ok ok.

coral crescent
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+3 is enough cause we cut the body

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ok now we can work on x

short stag
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Ok. I see.

coral crescent
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if we project the shape onto the xoy plane

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we get a section of a circle with radius 3sqrt(2)

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after projection we have x^2 + y^2 = 18

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and we solve for x

short stag
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It's 3, right?

coral crescent
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hmm?

short stag
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Oh wait.

coral crescent
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we are trying to get x in terms of y

short stag
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x = sqrt(18-y²)

coral crescent
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yah correct

short stag
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I used the value of y we got. HAHA, my bad.

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Ok ok

coral crescent
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now to late step, bounds of z

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here comes the importance of splitting the integral at y = 3

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cause z doesnt follow the same rule all across xoy

short stag
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Ohh

coral crescent
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from 0 to 3 we have z defined by the cone and from 3 to 3sqrt(2) we have it defined by the sphere

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actually i made a mistake

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a big one

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x is also not the same

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x will have 2 forms too

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like z from 0 to 3 x defined by the cone, from 3 to 3sqrt(2) defined by the sphere

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so
x^2 - y^2 = 0 for 0 to 3
x^2 + y^2 = 18 from 3 to 3sqrt(2)

coral crescent
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yes

short stag
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OMG, it's getting complicated for me.🥲

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Anyway, let's continue. Hehe

coral crescent
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yah sorry, big mistake on my part

coral crescent
short stag
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Yes yes

coral crescent
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alright

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for z we have
from 0 to 3 x^2-y^2+z^2=0
from 3 to 3sqrt(2) x^2+y^2+z^2=18

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and we solve for z

short stag
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is z = sqrt(9-x²)?

coral crescent
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where did the y go

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y is still variable

short stag
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Wait

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z = sqrt(y²-x²), for 0 to 3
z = sqrt(18 - x² - y²), for 3 to 3√2

coral crescent
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👍

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now write the integral

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polar coordinates going to be much easier

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actually we will use spherical*

short stag
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Gosh, how do i start writing it?

coral crescent
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start with y

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what did we say about y

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by start by y i mean outermost integral

short stag
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OMG, im lost. Haha

coral crescent
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we said y is from 0 to 3sqrt(2) with a cut at 3

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[ \int_{0}^{3\sqrt{2}} [ \int_{D_{xz}} ,dxdz ] ,dy ]

woven radishBOT
#

alihsaas

short stag
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Ok, im following.

coral crescent
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and since x is different from 0 to 3 and 3 to 3sqrt(2) it becomes:

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[ \int_{0}^{3} [ \int_{D_{xz}} ,dxdz ] ,dy + \int_{3}^{3\sqrt{2}} [ \int_{D_{xz}} ,dxdz ] ,dy ]

woven radishBOT
#

alihsaas

coral crescent
#

continue from here

short stag
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OMG, im lost. Im not sure if im doing it right.

coral crescent
#

show me what you did

short stag
coral crescent
#

just a moment, phone gonna die

short stag
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Ok ok

coral crescent
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ok the problem is you can swiped the bounds of x and z

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you can't do that with the equations you go

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like in the first integral

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you used x before we defined x

short stag
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How do I do that?

coral crescent
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see what we did

short stag
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Yes

coral crescent
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and the volume is 8 * this expression

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now to spherical

short stag
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OMG, spherical.😭 Let's go.

coral crescent
#

spherical is R Theta Phi
ill define Theta as the angle between Z axis and M and phi the angle betwen x axis and projection

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so phi is the polar angle

short stag
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Ok ok

coral crescent
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can you tell me what R is here

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the interval it belongs to

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also lets work on the same slice

short stag
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Wait, it's hard for me.

short stag
coral crescent
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we wont have to cut the interval in spherical coordinates

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so R is 0 to 3✓2

short stag
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Ok ok

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Then theta is 0 to 2pi, correct?

coral crescent
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yah correct

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phi remains

short stag
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How do i determin phi?

coral crescent
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can you tell me what Beta is here

short stag
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Does beta represent phi?

coral crescent
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phi is pi/2 - Beta

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cause phi is polar angle

short stag
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Oh, I see.

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So from 0 to pi/2?

coral crescent
#

you haven't told me what beta is

short stag
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Sorry. I can'r figure it out.

coral crescent
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equation of cone is x^2 - y^2 + z^2 = 0 right?

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and since we are looking at the projection on xoy

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z is zero

short stag
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Yes

coral crescent
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so we get x = y

short stag
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Ok ok

coral crescent
#

and beta here is tanBeta = x/y

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solving for Beta

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tan^-1 (x/y) = tan^1 (1) = pi/4

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i mean /4

short stag
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Oh, wow. Amazing. Sorry, i was too dumb.

coral crescent
#

now we can deduce phi

short stag
#

0 to pi/4?

coral crescent
#

why 0

short stag
#

Because we started at the origin? Im not sure. Sorry, huhu.

coral crescent
#

going from 0 to pi/4 means going like this, the correct idea is pi/4 to pi/2

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while it should give the same answer, better write correctly

short stag
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Ok ok

coral crescent
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now write the integral

short stag
#

Is this correct?

coral crescent
#

phi is the polar angle remember

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the Jacobian should be rho^2 sin theta

short stag
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So what I wrote is incorrect?

coral crescent
#

just need to change the sin

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rest should be correct

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and don't forget to multiply by 8

short stag
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it gives rho^2 sin phi

coral crescent
#

they took theta as the polar angle in your image

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we took phi as the polar angle here

short stag
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Oh i see

coral crescent
#

sorry for the confusion but that's how I usually work

short stag
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No problem.

coral crescent
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so i have consistent naming between spherical and polar

short stag
#

How do I solve it using double integrals?

coral crescent
#

this is a volume, you have to use triple

short stag
#

But our professor asked us to solve it using both methods. Huhu

coral crescent
#

ah actually right

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basically what we did originally using Cartesian coordinates

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but instead of the integral of z we put the function

short stag
#

How I do that?

coral crescent
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originally we got z in terms of x and y right?

short stag
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Yes

coral crescent
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for both domains

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from 0 to 3 and 3 to 3✓2

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just replace the integral dz with them

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they are our functions

short stag
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I dont follow. Huhu, sorry.

coral crescent
#

back in coordinate plane we used to do

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[ \int_{a}^{b} f(x) dx ]

woven radishBOT
#

alihsaas

coral crescent
#

to calculate the area a curve

#

[ \int_{a}^{b} \int_{y_1(x)}^{y_2(x)} f(x, y) dydx ]

woven radishBOT
#

alihsaas

coral crescent
#

here we do this

#

to calculate the volume under a surface

short stag
#

Can you help me do it?

coral crescent
short stag
#

Is this right?

coral crescent
#

👍

#

should be sqrt( y^2 - x^2 ) tho

short stag
#

Oh i see.

coral crescent
#

cause cone is x^2 - y^2 + z^2 = 0

#

and don't forget to multiply by 8

#

cause this is volume of section

short stag
#

My problem now is how to integrate the function with respect to x and y.

coral crescent
#

stsrt from innermost and assume the other is constant

#

normal integration

short stag
#

Can we transform it into polar?

coral crescent
#

yah sure same thing as spherical but no theta

#

and we take x = r cos phi

#

y = r sin phi

devout snowBOT
#

@short stag Has your question been resolved?

coral crescent
#

@short stag any problem?

short stag
#

Hi, just finished solving. But I have another problem. Huhu

#

You were really a great help to me, @coral crescent thank you so much!🥹

short stag
#

Here's another problem

coral crescent
#

mmm alright

#

started working on it?

#

sketch?

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#

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maiden zinc
#

i have f(x, y) = x²y² / (x² + y²) and i wanna calculate $D_1f(x,y)$

woven radishBOT
maiden zinc
#

(x,y) != 0

#

i don't know how to do that

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junior stratus
#

hey i just wanted to know if i’m trippin or did i get the right answers for these

devout snowBOT
junior stratus
#

So for North I used 90Cos36deg
and for West I used 90Sin36deg @supple knot

#

<@&286206848099549185>

supple knot
#

Try using that

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scenic ether
#

.reopen

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#

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fleet ermine
#

Let $\mathrm{P}_{i\in I}\mathcal{A}_i={f\mid \mathrm{Dom}(f)=I\land \forall i(f_i\in \mathcal{A}_i)}$ be the "direct product" of an indexed family of sets with domain $I$ and let $\mathrm{Pr}_i={f_i\mid f \text{is a function}\land i\in\mathrm{Dom}(f)}$ be the i-th projection function. On my set theory book it's written that there is a strict geometric relation between the direct product and the i-th projection... does anyone know what is it supposed to be?

woven radishBOT
#

.lasur

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grand siren
#

do they define what a "strict geometric relation" is?

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fleet ermine
# grand siren do they define what a "strict geometric relation" *is*?

yeah they say "the direct product of a is an I-dimensional space; the elements f of the direct product of a are I-tuples, where the i-th coordinate is f_i, i\in I. It is natural to consider the operation of projection of the i-th coordinate A_i". But I don't understand what does it mean

fleet ermine
#

btw that was in the appendix

restive river
#

which part are you confused with?

devout snowBOT
#

@fleet ermine Has your question been resolved?

fleet ermine
#

sorry for the notation, he means to use the capital pi notation for the cardinal product

restive river
#

so basically, the i-th projection maps to the i-th coordinate

fleet ermine
#

ohhhh the notation threw me off a bit. thank you

#

the book is pretty old so the notation is kinda weird

restive river
#

yeah, I agree. haven't seen that notation before

fleet ermine
#

thank you tho, you were verty helpful

#

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untold ether
#

At question 5C, are they asking for a specific number, or can I replace the second order derivitative with the notation f''? I ask because they ask for an expression and the second order derivative isn't very concise

untold ether
#

And also they say "using f(2)"

supple knot
#

yes very confusing

untold ether
#

yea

untold ether
#

I know of the rror formula

supple knot
untold ether
#

I wondered how I should fill it in according to the question

supple knot
#

show your form of the formula then

untold ether
#

Should I leave f''(s) be

supple knot
#

,rotate

untold ether
#

wrong one

#

,rotate

woven radishBOT
untold ether
#

That is one way to do it

supple knot
# supple knot

there are 3 variables here but you're treating s the same

untold ether
#

Also, would you agree with using 0,04 as the maximum bound?

supple knot
#

calculate $f''(s)$

woven radishBOT
#

rie.mann

supple knot
#

``between" means either $a < s < x$ or $x < s < a$

woven radishBOT
#

rie.mann

untold ether
#

Okay

#

That might be the confusion then

untold ether
supple knot
#

errr, those all should be less than or equal signs

untold ether
#

Oh

#

But should I go for the maximum value?

supple knot
untold ether
#

Yea

#

So I need the third order derivative as well

#

Is there no easier way @supple knot ?

#

The question doesn't give a lot of points

#

Also, the book never went into picking the correct value of s

supple knot
untold ether
supple knot
#

oh is that a test

untold ether
#

it's a practice test, but it's very similar to the real one

supple knot
#

what does "lot of points mean"

untold ether
#

0.5 out of 10

#

the next question gives 1 full point :

supple knot
#

i don't know how you get around calculating the second derivative since it explicitly tells you to use it

untold ether
#

Yeah no that's fine

#

But how do you calculate the maximum of the second derivative or do you even need to

#

Like the book doesn't get into picking an s at all

#

They just assert the correct s during the examples

supple knot
#

yea in that example, sqrt(x) is monotone increasing so it's the right endpoint

#

but exp(x^2 - sin(x)) is less obvious, to me at least

untold ether
#

Same

supple knot
#

,w plot exp(x^2 - sin(x)) for 0 < x < 0.1

untold ether
#

Wouldn't you need to plot the derivative?

supple knot
#

hmmCat maybe just observe that sin(x) ~ x ? so x^2 << x for that range

untold ether
#

d/dx(exp(x^2 - sin(x))) = e^(x^2 - sin(x)) (2 x - cos(x))

#

and then this is the second order derivative: d/dx(e^(x^2 - sin(x)) (2 x - cos(x))) = e^(x^2 - sin(x)) (4 x^2 + sin(x) + cos^2(x) - 4 x cos(x) + 2)

supple knot
#

nah don't do that

supple knot
#

so exp(x^2 - sin(x)) is approx 1-x

untold ether
#

How does that get me to an error bound?

#

Am I not to use lagrange?

supple knot
# untold ether

the function exp(...) is decreasing so you use the same logic here

untold ether
#

How does that help me with: e^(x^2 - sin(x)) (4 x^2 + sin(x) + cos^2(x) - 4 x cos(x) + 2)

supple knot
#

you don't need to differentiate at all

supple knot
supple knot
untold ether
supple knot
# untold ether

did you not understand this example with square root being monotone increasing

untold ether
#

Nope

#

I assumed you confused sqrt with the second derivative of sqrt

#

Sorry, should've mentioned it at the time

supple knot
#

no

untold ether
# supple knot no

Then I don't see how sqrt(x) is relevant when calculating the maximum value of the second order derivative

supple knot
untold ether
#

.close

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restive river
devout snowBOT
restive river
#

Help i dont understand this

#

Hey

#

hi

glacial lagoon
#

when something is proportional then that means
var 1 = const. x var 2

#

in this case:
y = const. x x

glacial lagoon
#

without the b

restive river
#

^

#

delete and go to the category called math help (available)

glacial lagoon
#

basically: if you multiply the left side by 5

restive river
#

ok

glacial lagoon
#

then the right side also has to be multiplied by 5

#

and as const. is a constant

#

you would need 5x to fulfill it

restive river
#

ahh i see

glacial lagoon
#

in other words:

y = const. x x
<=>
5y = const. x 5x

glacial lagoon
# restive river so y=mx+b?

what you mentioned previously, is what you would need in cases where you would want to display this as a graph

#

for example: time distance diagrams from physics

#

but in your case that's not needed

restive river
#

ok

#

hold on

#

its

#

C

glacial lagoon
#

A good every day example would be the cost of apples:

f.e. 1 kg of apples costs 1 €

Then if y = price, and the apple weight x you would get:

y = 1 €/kg * xkg

#

maybe this makes it easier to grasp

#

because obviously if you pay more you can take more apples

#

and if you take more apples then you need to pay more

#

therefore the price and the weight of the apples is directly proportional

restive river
#

ahhh i see

#

yeah that makes sense

glacial lagoon
#

👍

restive river
#

.close

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quaint oracle
#

Pls help

devout snowBOT
quaint oracle
#

With the b part only

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vale bear
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vale bear
#

laplace

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#

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wooden axle
devout snowBOT
wooden axle
#

I guess all options wrong

#

A is matched but sign problem

pseudo basin
#

,w det {{a,b,c},{b+c,c+a,a+b},{a^2,b^2,c^2}}

pseudo basin
#

yeah you're right

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restive river
#

So

devout snowBOT
restive river
#

How do I solve without knowing the height

pseudo basin
#

note the balls touch the top and bottom of the cylinder

#

so you in fact CAN find the height

restive river
#

I don’t think you can get the height of a sphere from the volume

sage burrow
restive river
#

The cylinder

sage burrow
#

it is 3 balls high

restive river
#

I need the balls height

sage burrow
#

it is given

restive river
#

All I’m given is the diameter?

#

Oh wait

sage burrow
#

and what is the diameter of a ball?

restive river
#

Height is 12•3

#

36

#

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dark kelp
#

How is probability in de tomain 2<x<=3 calculated? Why does inserting x=2 has to result in 0?

dark kelp
#

Rather what is implied after that: 'thus 0 = 1/4*2^2 - 2 + C1 = -1 + C1'

#

Is it equal to 0, because it comes right after the 0 of x <= 2?

hollow mantle
#

can you show what's up there?

supple knot
woven radishBOT
#

rie.mann

dark kelp
#

Oh- I'm sorry, I only just noticed the text up there

hollow mantle
#

so now you know why is it 0?

dark kelp
#

Honestly no, would you mind elaborating?

supple knot
#

do you know how to read f(x) as a piecewise function

#

it's exactly the same for F(x) for x<= 2

dark kelp
#

f(x)=0 for every value of x below or equal to 2

hollow mantle
#

and 2 is below or equal than 2?

dark kelp
#

Correct

hollow mantle
#

so F(2) is

dark kelp
#

I understand, but I fail to fathom the implication after that

supple knot
dark kelp
#

Where does this come from?

supple knot
#

F(x) is right continuous

#

do you know what continuity at a point means?

#

using limits, say

dark kelp
#

I do

#

But why choose x=2 and y=0

supple knot
#

because you're solving for unknowns

#

using continuity lets you solve for unknowns

#

these are the two unknowns

dark kelp
#

Do you maybe have an article that relates to this topic?

#

nevermind

#

.close

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#
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lucid night
#

Is (a•b) : (c•d) = (a:c) • (b:d) ?

devout snowBOT
inland seal
#

yes

lucid night
#

yay

inland seal
#

$\frac{a \cdot b}{c \cdot d} = \frac{a}{c} \cdot \frac{b}{d}$

woven radishBOT
#

redstoneplayz09

lucid night
#

Right

#

Me dumb

#

I can’t imagine things in different manners

#

I mean that was so simple

inland seal
#

no worries, thats how math is

#

we all miss simple things

lucid night
#

Thanks 🙏

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#

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kind cedar
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#

@kind cedar Has your question been resolved?

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@kind cedar Has your question been resolved?

grizzled roost
#

Okay, I think a good strategy to approach this is first trying to count in how many ways can you draw three tickets such that they form a 1-progression

#

Solve simpler individual problems, and then with that in mind try to solve the bigger one

#

After that, try doing the same for 2-progressions

#

See if there is a pattern you can exploit

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distant cypress
#

Is it possible to integrate this $\int{\frac{1}{dx}}$

woven radishBOT
#

Bring Back Beatrix

left robin
#

i dont know if that is defined anywhere, but not as far as i know

#

dx is a very small thing, so 1/dx is very large

#

and the sense of integration is to add up lots of very small things

#

so here, we would add up lots of very large things which is why i would think this would diverge to +- infinity

distant cypress
#

so its inifinity

#

what if you add a term on the denominator to compensate it example $\int{\frac{1}{x^2 dx}}$

woven radishBOT
#

Bring Back Beatrix

left robin
#

it is important to note that i am not saying that it is like that
i am just outputting my intuition here

distant cypress
#

alright

left robin
#

i would assume that the x^2 wouldnt change anything

hybrid snow
#

It's still gonna be big

distant cypress
#

yeah just want some insight here

hybrid snow
#

If dx is real small

#

Then x^2 is gonna do jackshit against dx

distant cypress
#

yep i think its just some undefined term

left robin
#

well i guess you can define it yourself if you have context
after all, in some cases stuff like 1/0 is defined

#

if it makes sense in some context, then why not define it there
but in this case, i would say it would just be infinity usually

#

instead of undefined

distant cypress
#

I think that $\int{\frac{f(x)}{dx}}$ is just the slope of the diagonal of the dArea of a function

woven radishBOT
#

Bring Back Beatrix

distant cypress
#

so since as it dx get smaller and smaller, its approaching 90 degree and the slope becomes undefined

stone stump
#

you can define it as whatever you want. but the notation is not defined. the dx in "normal" integrals is notation, it isnt actually some small thing

distant cypress
#

you could think of dx as an abstract notation or you could treat it as some geometric entity

supple knot
stone stump
#

you can think of stuff however you want. without a proper definition its still just a bunch of meaningless symbols

distant cypress
#

All these integral and derivative are just somehow derived from the concept of limits, and all rules of inetgration are from limits so i think the notation and definition are just "formality"

stone stump
#

"just"

supple knot
#

Yes formality is how you give definitions

#

If you don't want to do that, then you're just admitting you don't know what your symbols mean

distant cypress
#

its like 1+1, you could give whatever formality you want, but intuition in its sense is well understood

supple knot
#

Awful analogy

stone stump
#

those symbols are defined. that definition just checks out with our intuition (because that is how we chose the definition)

#

the collection of symbols you wrote down is not defined

distant cypress
#

i understand the symbols not in a rigid strict definition most "mathematicians" like to think about, i just understand it by intuition

supple knot
#

Good for you

#

If you have your intuition great

distant cypress
#

i probalby have

supple knot
#

You don't have any questions then?

distant cypress
#

i thinks it good for now

supple knot
#

.close

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#
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distant cypress
#

.close

devout snowBOT
#
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grizzled roost
#

Prove that $||A_n||_2$ tends to infinity when\
$A=\begin{pmatrix}
1&1&1&\cdots &1\
1&2&2&\cdots &2\
1&2&3&\cdots &3\
\vdots &\vdots &\vdots &\ddots &\vdots\
1&2&3&\cdots & n\
\end{pmatrix}$

grizzled roost
#

Huh, not sure why latex doesn't like that

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I tried to find some eigenvalue that depends on n, but I couldn't

woven radishBOT
#

casiel368

small quartz
#

How about using the definition and x the all ones vector

distant harbor
#

What does that mean

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||

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And the _2

small quartz
#

So the l2 norm of x is sqrt(n) (for x= all ones vector )

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and the l2 norm of Ax is at least n (because the sum of each row is at least n)

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So ||A||_2 is at least sqrt(n)

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@grizzled roost

grizzled roost
#

Oh my

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It was so simple

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Thank you

small quartz
#

yw

grizzled roost
#

I was so centered in spectral radius

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.close

devout snowBOT
#
Channel closed

Closed by @grizzled roost

Use .reopen if this was a mistake.

#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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restive river
#

f(x)=ln(sin(x)^sin(x) + 1) where 0<x<pi/2 how to find the range?

restive river
#

<@&286206848099549185>

deft marsh
#

Hi.

restive river
#

hello

deft marsh
#

What do you need help with?

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Hello.

deft marsh
#

Can you text the problem again?

restive river
#

f(x)=ln(sin(x)^sin(x) + 1) where 0<x<pi/2 how to find the range?

deft marsh
#

I’m sorry, but I don’t know how to solve it.

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I haven’t learned it yet.

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I’m sorry.

restive river
#

k

tame palm
#

To find the minimum and maximum, there are two things that you should do. First, calculate the derivative and evaluate when it is equal to zero. The second thing you will need to do is evaluate the end points of the interval. Whichever values are the largest and smallest will determine the interval of the range.

restive river
supple knot
restive river
supple knot
#

,w plot sin(x)^sin(x) for 0 < x < pi/2

supple knot
#

,w min sin(x)^sin(x) on [0, pi/2]

supple knot
#

Yea I'm not sure how

tame palm
restive river
#

@tame palm @supple knot

tame palm
#

,wolf derivative ln( (sin(x))^(sin(x)) + 1)

wooden veldt
#

Wait is it sin(x)^sin(x) or sin(x^sin(x))?

restive river
tame palm
#

Ugh, that looks ugly. 😖

restive river
#

its x^sin(x)

wooden veldt
#

For the record that's not what you wrote originally

restive river
#

i don't know how to use LaTeX, otherwise i would have used it

supple knot
#

Do you know what a^b means

restive river
supple knot
#

$a^b$

woven radishBOT
#

rie.mann

restive river
#

bro

supple knot
#

Where a=x and b=sin(x)

restive river
#

wait i will send the picture

rigid shadow
#

$\ln{(\sin{x^\sin{x}}+1)}$

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is that right

restive river
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no

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its ln(sin(x^sin(x))+1)

woven radishBOT
#

ultravioletvoodoo
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

restive river
#

yes that's correct

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@supple knot @tame palm

tame palm
#

Is is (sin(x))^(sin(x)) or sin(x^(sin(x)))?

restive river
tame palm
#

I would first simpifly th eproblem using logarithm rules.

tame palm
restive river
tame palm
#

Hmm, nevermind. I had my rules mixed up.

rigid shadow
#

doesn't look like you can use log rules here

rigid shadow
restive river
tame palm
#

,wolf derivative ln(sin( x^(sin(x))) + 1)

tame palm
#

Yup, still an ugly derivative.

rigid shadow
#

very bad chain rule derivative

restive river
#

ya

tame palm
#

Can you post the entire question? I feel like there is something missing.

restive river
#

f(x)=whatever i sent

tame palm
#

No, post the entire question as it is written.

restive river
#

ok

tame palm
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Is that part above the question also part of the question?

restive river
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no

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from find range..

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thats the question

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should i send it again?

tame palm
#

No, if that's it, then no.

restive river
#

okay

supple knot
#

The logarithm is monotonic so you just need to find the min and max of the argument

restive river
#

why should we evaluate the derivative at 0?

rigid shadow
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it's to find the min and max

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the difference between those two is the range

distant cypress
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you could find the range without differentiating

distant cypress
#

especially this one $sin(x^{sin(x)})$

woven radishBOT
#

Bring Back Beatrix

distant cypress
#

what do you think the highest value it could have

distant cypress
#

thats right

#

so

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plug it to log

restive river
#

0

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?

distant cypress
#

it would be $log(1+1)$

woven radishBOT
#

Bring Back Beatrix

restive river
#

oh

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but the domain is restricted

distant cypress
#

yes

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but you see one of the end point is $\frac{\pi}{2}$

woven radishBOT
#

Bring Back Beatrix

distant cypress
woven radishBOT
#

Bring Back Beatrix

restive river
#

oh right

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but pi/2 isn't included, so ln 2 should also not be included in the range?

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sorry

distant cypress
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yes

restive river
#

and for the minimum value?

distant cypress
#

it will be $R<\ln(2)$

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for minimum the same process

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what do you think

restive river
#

if i put 0, its ln(sin1+1)

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@distant cypress

woven radishBOT
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Bring Back Beatrix

distant cypress
#

look at this one $x^{sin(x)}$

woven radishBOT
#

Bring Back Beatrix

restive river
#

.close

devout snowBOT
#
Channel closed

Closed by @rigid zodiac

Use .reopen if this was a mistake.

restive river
#

.reopen

devout snowBOT
#

restive river
#

you know by doing this we can bump our question

distant cypress
#

what do you think is the minimum value of this $x^{sin(x)}$

woven radishBOT
#

Bring Back Beatrix

restive river
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x

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sorry

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1

distant cypress
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no

restive river
#

0?