#help-27
1 messages · Page 94 of 1
I mean sure i can say that sin(90+x) = cosx
But
When it comes to the cos(90+x) its
OUUH
Right cos(90+x) = -sinx cause the cos value of the top left side is negative
Am i making sense?
Yes
It's at the left of the origin 0
it's then < 0
for sine, below x-axis and below zero
then < 0
Riggttt
I have one more problem..(its trig related)
Can i ask you?
Or you thinks just too exhausting for today?
@craggy escarp
Sin(270+x)
Why is it -cosine
By the same logic shouldn’t it be positive cosine since the value of cos is positive on the 4th quadrant
Assuming green is sin and blue cos?
y-axis is ALWAYS sine
x-axis is ALWAYS cosine
Well yeah, if you're looking at it that way
So thats a no?
the green segments are sine, true
i was looking in a different way
the blue segments are cosine
No no I didn’t say
the horizontal is always cosine
okay
Right!
Are we sure?
And the cosine for the 270+x is this righy?
yess
Oe the one on the x axis
both
Oshh
Wiatt
They look like.. idk maybe triangles in different orientations
So like…
Hmmzz
yes right
with cosine being adjacent to the angle
and sine being opposite
that's SOHCAH
Yess
270° anti-clockwise
Thats why i for some reason my Brian said rotated lol
OH MY FRIGGING gosh
I finally understand this sheiße
Oki
cos(x-90) = ?
just draw x and x-90
Cos-(90-x)
and look at x-90's cosine
Leave it as x-90
What's the problem!
Just do it the same way
draw x and (x-90)
look at cosine of (x-90)
X - 90 you say?
yes
Rotate x by 90° clockwise
Hmm
- is counter clockwise
Well i kinda said that here
the - is clockwise
This??
So like we can get the values at the normal quadrants but we just multiply the answer with negative ?
Sorryb
never mind, never mind
Whattt
Little advanced 😥
Right!
Haha
cos(270-x)
Waitt
Oh no waiy
Yess its
-cosx
Sorry
Took a little longer cause I didn’t see the x was negative
Am I correct vvv
Ohh crapp
Check again
😝
Lol look at this
I solved for sin
Instead of cos
And the minus i forgot to add
😋
Maybe you were not yet taught the notion of negative angles
All you meet for now are positive angles
Counter Clockwise
correct
WOAH
😃
No way
Haha
You’re lying lmao
No, it actually is correct
Wut!
Omg oki
Well done!
Be friends?
Good luck, I will see you around
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4x^2+7x+2=0
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Take the common terms and simplify
I couldn’t factor out
the solution isnt rational, so factoring doesnt work
use the quadratic formula instead
use quadratic formula
Appy a, b and c on formula
Doesn't factor
What you mean
Do you know how quadratic formula works?
Akira
This what I mean
Ah I figured
I use pq formula
If I use pq formula I will have 7/4 which is bothersome
Wdym by pq?
Yeah
Oh I see
I can’t use abc-formula
Well honestly quadratic formula is easier
Never heard of this before
Do you still need help? or done

The only reason I didn’t do pq formula at first is 7/4
Does the question asking you to solve it by pq formula or quadratic
It just says solve the solution
I see
I suggest you using the quadratic formula because this formula you are using doesn't makes sense at all
Is quadric formula abc formula?
Have you read this
Why can't you use that wdym
Oh that's the point
But do you know how to use Wolfram
It tells to use quadratic
,w calc 4x^2+7x+2=0
see
I won’t learn like that
Well you just learned it
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(\left|z_1\right| = 15) and (\theta_1 = 209^\circ). Express (z_1) in rectangular form as (z_1 = a + bi), where (a) and (b) are rounded to the nearest thousandth.
$(\left|z_1\right| = 15) and (\theta_1 = 209^\circ). Express (z_1) in rectangular form as (z_1 = a + bi), where (a) and (b) are rounded to the nearest thousandth.$
TangentLINE
Can somebody please help
Now, since (\theta_1 = 209^\circ), we subtract it from (360^\circ) and it equals (151^\circ). We are already given that (\left|z_1\right| = 15). Putting these two together, we have (15\left(\cos(151^\circ) + i\sin(151^\circ))). We then distribute the (15) and we will have our answer.
$(\left|z_1\right| = 15) and (\theta_1 = 209^\circ). Express (z_1) in rectangular form as (z_1 = a + bi), where (a) and (b) are rounded to the nearest thousandth.$
TangentLINE
$Now, since (\theta_1 = 209^\circ), we subtract it from (360^\circ) and it equals (151^\circ). We are already given that (\left|z_1\right| = 15). Putting these two together, we have (15\left(\cos(151^\circ) + i\sin(151^\circ))). We then distribute the (15) and we will have our answer.$
TangentLINE
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
.close
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Help me please. Using double and triple integrals.
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Can you find the boundary constraints on the solid?
@short stag Has your question been resolved?
I tried converting it to cylindrical and for theta, I have 0 to 2pi. For the r, I tried finding the intersection point of the two surfaces and I arrived at z=sqrt(9-x²). So for r, i have 0 to sqrt(9-x²).
Please help me.
Hi
I don't know how to solve it. Huhu
did you sketch the shape
we have symmetry here so we can just cut the shape 3 times and just get the volume of this slice and multiply by 8, see if this helps
Hi, I can't really get it. Huhu
Don't understand how we cut it?
I barely understand it. Sorry.
it's alright
Start with sketching the body
that's always where you want to start when doing work like this
making solving much easier
Getting this problem right is my only chance to pass this course. But I am so dumbfounded right now.
you can draw it in 2D and make your brain fill the gaps
it's okay, im guiding through it, it isn't a hard problem. Just work with me
Please, I don't want to fail this course.🥹
well have you understood what i said before :p
That's my problem right now. I am stuck looking at the graph.
can you show me the graph you have
Im just looking at here. huhu, im sorry
But, would it be helpful if I convert the equations to polar coordinates?
oh you meant the one i sent okay
let's work it out in Cartesian coordinates now and worry about polar later
we have this shape right? we can cut it in half and get the volume of the other half
and to get the full volume we multiply by 2
got me?
I see. Im following.
same idea here, we cut at xoy then zoy plane (both ways work)
and since we cut 2 times we should multiply by 4
and with the 2 from the previous cut, we should multiply the same section by 8
reminder we can do all this since we have symmetry
Wait, im getting lost.
Yes yes. So that's why it should be multiplied by 4. Knowing we have a symmetry.
yes, should be enough to get the volume of one of these quadrants then multiply by 8 to get the volume of the entire body
so good so far?
Yes yes. But how do I get the volume of one quadrant?🥲
first we choose Which axis we want to work on first
y axis seems the easiest
oops
i meant square root
sorry another blunder
The given is 18.
lemma delete all this
yah sorry
Ok ok
now we can choose to either work on x or z plane
ah actually before that
we need to separate the body at where the cone and sphere intersect
How do we do that?🥲
x^2 + y^2 + z^2 - 18 = x^2 - y^2 + z^2
and fortunately for us stuff cancel out nicely here
and we can calculate the value of y
correct
OMG. Ok ok.
Ok. I see.
if we project the shape onto the xoy plane
we get a section of a circle with radius 3sqrt(2)
after projection we have x^2 + y^2 = 18
and we solve for x
It's 3, right?
hmm?
Oh wait.
we are trying to get x in terms of y
x = sqrt(18-y²)
yah correct
now to late step, bounds of z
here comes the importance of splitting the integral at y = 3
cause z doesnt follow the same rule all across xoy
Ohh
from 0 to 3 we have z defined by the cone and from 3 to 3sqrt(2) we have it defined by the sphere
actually i made a mistake
a big one
x is also not the same
x will have 2 forms too
like z from 0 to 3 x defined by the cone, from 3 to 3sqrt(2) defined by the sphere
so
x^2 - y^2 = 0 for 0 to 3
x^2 + y^2 = 18 from 3 to 3sqrt(2)
Is this for x?
yes
yah sorry, big mistake on my part
got it tho?
Yes yes
alright
for z we have
from 0 to 3 x^2-y^2+z^2=0
from 3 to 3sqrt(2) x^2+y^2+z^2=18
and we solve for z
is z = sqrt(9-x²)?
👍
now write the integral
polar coordinates going to be much easier
actually we will use spherical*
Gosh, how do i start writing it?
OMG, im lost. Haha
we said y is from 0 to 3sqrt(2) with a cut at 3
[ \int_{0}^{3\sqrt{2}} [ \int_{D_{xz}} ,dxdz ] ,dy ]
alihsaas
Ok, im following.
and since x is different from 0 to 3 and 3 to 3sqrt(2) it becomes:
[ \int_{0}^{3} [ \int_{D_{xz}} ,dxdz ] ,dy + \int_{3}^{3\sqrt{2}} [ \int_{D_{xz}} ,dxdz ] ,dy ]
alihsaas
continue from here
OMG, im lost. Im not sure if im doing it right.
show me what you did
just a moment, phone gonna die
Ok ok
ok the problem is you can swiped the bounds of x and z
you can't do that with the equations you go
like in the first integral
you used x before we defined x
How do I do that?
see what we did
Yes
OMG, spherical.😭 Let's go.
spherical is R Theta Phi
ill define Theta as the angle between Z axis and M and phi the angle betwen x axis and projection
so phi is the polar angle
Ok ok
can you tell me what R is here
the interval it belongs to
also lets work on the same slice
Wait, it's hard for me.
0 to 3 and 3 to 3√2 is the interval which R belongs to of not?🥲
How do i determin phi?
can you tell me what Beta is here
Does beta represent phi?
you haven't told me what beta is
Sorry. I can'r figure it out.
equation of cone is x^2 - y^2 + z^2 = 0 right?
and since we are looking at the projection on xoy
z is zero
Yes
so we get x = y
Ok ok
and beta here is tanBeta = x/y
solving for Beta
tan^-1 (x/y) = tan^1 (1) = pi/4
i mean /4
Oh, wow. Amazing. Sorry, i was too dumb.
now we can deduce phi
0 to pi/4?
why 0
Because we started at the origin? Im not sure. Sorry, huhu.
going from 0 to pi/4 means going like this, the correct idea is pi/4 to pi/2
while it should give the same answer, better write correctly
Ok ok
now write the integral
Is this correct?
So what I wrote is incorrect?
just need to change the sin
rest should be correct
and don't forget to multiply by 8
they took theta as the polar angle in your image
we took phi as the polar angle here
Oh i see
sorry for the confusion but that's how I usually work
No problem.
so i have consistent naming between spherical and polar
How do I solve it using double integrals?
this is a volume, you have to use triple
But our professor asked us to solve it using both methods. Huhu
ah actually right
basically what we did originally using Cartesian coordinates
but instead of the integral of z we put the function
How I do that?
originally we got z in terms of x and y right?
Yes
for both domains
from 0 to 3 and 3 to 3✓2
just replace the integral dz with them
they are our functions
I dont follow. Huhu, sorry.
alihsaas
to calculate the area a curve
[ \int_{a}^{b} \int_{y_1(x)}^{y_2(x)} f(x, y) dydx ]
alihsaas
Can you help me do it?
did you try writing it
Oh i see.
cause cone is x^2 - y^2 + z^2 = 0
and don't forget to multiply by 8
cause this is volume of section
My problem now is how to integrate the function with respect to x and y.
Can we transform it into polar?
yah sure same thing as spherical but no theta
and we take x = r cos phi
y = r sin phi
@short stag Has your question been resolved?
@short stag any problem?
Hi, just finished solving. But I have another problem. Huhu
You were really a great help to me, @coral crescent thank you so much!🥹
you're welcome anytime
Here's another problem
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i have f(x, y) = x²y² / (x² + y²) and i wanna calculate $D_1f(x,y)$
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hey i just wanted to know if i’m trippin or did i get the right answers for these
!show
Show your work, and if possible, explain where you are stuck.
So for North I used 90Cos36deg
and for West I used 90Sin36deg @supple knot
<@&286206848099549185>
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Let $\mathrm{P}_{i\in I}\mathcal{A}_i={f\mid \mathrm{Dom}(f)=I\land \forall i(f_i\in \mathcal{A}_i)}$ be the "direct product" of an indexed family of sets with domain $I$ and let $\mathrm{Pr}_i={f_i\mid f \text{is a function}\land i\in\mathrm{Dom}(f)}$ be the i-th projection function. On my set theory book it's written that there is a strict geometric relation between the direct product and the i-th projection... does anyone know what is it supposed to be?
.lasur
@fleet ermine Has your question been resolved?
do they define what a "strict geometric relation" is?
@fleet ermine Has your question been resolved?
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yeah they say "the direct product of a is an I-dimensional space; the elements f of the direct product of a are I-tuples, where the i-th coordinate is f_i, i\in I. It is natural to consider the operation of projection of the i-th coordinate A_i". But I don't understand what does it mean
btw that was in the appendix
which part are you confused with?
maybe the pictures here help https://en.wikipedia.org/wiki/Cartesian_product
@fleet ermine Has your question been resolved?
what does he mean when it says "the projection"?
sorry for the notation, he means to use the capital pi notation for the cardinal product
ohhhh the notation threw me off a bit. thank you
the book is pretty old so the notation is kinda weird
yeah, I agree. haven't seen that notation before
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At question 5C, are they asking for a specific number, or can I replace the second order derivitative with the notation f''? I ask because they ask for an expression and the second order derivative isn't very concise
yes very confusing
yea
I know of the rror formula
I wondered how I should fill it in according to the question
show your form of the formula then
Should I leave f''(s) be
,rotate
That is one way to do it
there are 3 variables here but you're treating s the same
Also, would you agree with using 0,04 as the maximum bound?
calculate $f''(s)$
rie.mann
rie.mann
Should I find the maximum value of f'' then?
errr, those all should be less than or equal signs
yes on the interval [a, x] or [a, x]
Yea
So I need the third order derivative as well
Is there no easier way @supple knot ?
The question doesn't give a lot of points
Also, the book never went into picking the correct value of s
points for what?
For getting the answer correct
oh is that a test
it's a practice test, but it's very similar to the real one
what does "lot of points mean"
i don't know how you get around calculating the second derivative since it explicitly tells you to use it
Yeah no that's fine
But how do you calculate the maximum of the second derivative or do you even need to
Like the book doesn't get into picking an s at all
They just assert the correct s during the examples
yea in that example, sqrt(x) is monotone increasing so it's the right endpoint
but exp(x^2 - sin(x)) is less obvious, to me at least
Same
,w plot exp(x^2 - sin(x)) for 0 < x < 0.1
Wouldn't you need to plot the derivative?
maybe just observe that sin(x) ~ x ? so x^2 << x for that range
d/dx(exp(x^2 - sin(x))) = e^(x^2 - sin(x)) (2 x - cos(x))
and then this is the second order derivative: d/dx(e^(x^2 - sin(x)) (2 x - cos(x))) = e^(x^2 - sin(x)) (4 x^2 + sin(x) + cos^2(x) - 4 x cos(x) + 2)
nah don't do that
x^2 - sin(x) is approx -sin(x) for small x and -sin(x) is approx -x
so exp(x^2 - sin(x)) is approx 1-x
the function exp(...) is decreasing so you use the same logic here
How does that help me with: e^(x^2 - sin(x)) (4 x^2 + sin(x) + cos^2(x) - 4 x cos(x) + 2)
you don't need to differentiate at all
exp(x^2 - sin(x)) is decreasing
go back and read everything i said from here
But why does it matter whether or not f is decreasing? Isn't the important question whether f'' decreases? It is the only way to figure the maximum value for f'', right?
did you not understand this example with square root being monotone increasing
Nope
I assumed you confused sqrt with the second derivative of sqrt
Sorry, should've mentioned it at the time
no
Then I don't see how sqrt(x) is relevant when calculating the maximum value of the second order derivative
then i guess there's no easy way for you
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when something is proportional then that means
var 1 = const. x var 2
in this case:
y = const. x x
so y=mx+b?
without the b
basically: if you multiply the left side by 5
ok
then the right side also has to be multiplied by 5
and as const. is a constant
you would need 5x to fulfill it
ahh i see
in other words:
y = const. x x
<=>
5y = const. x 5x
what you mentioned previously, is what you would need in cases where you would want to display this as a graph
for example: time distance diagrams from physics
but in your case that's not needed
A good every day example would be the cost of apples:
f.e. 1 kg of apples costs 1 €
Then if y = price, and the apple weight x you would get:
y = 1 €/kg * xkg
maybe this makes it easier to grasp
because obviously if you pay more you can take more apples
and if you take more apples then you need to pay more
therefore the price and the weight of the apples is directly proportional
👍
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Pls help
With the b part only
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help
laplace
@vale bear Has your question been resolved?
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yeah you're right
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So
note the balls touch the top and bottom of the cylinder
so you in fact CAN find the height
I don’t think you can get the height of a sphere from the volume
which height? the height of a ball is given. the container is exctly 3 balls "high". which height do you think is unknown?
The cylinder
it is 3 balls high
bro
I need the balls height
it is given
and what is the diameter of a ball?
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How is probability in de tomain 2<x<=3 calculated? Why does inserting x=2 has to result in 0?
Are you asking why F(2) = 0?
Rather what is implied after that: 'thus 0 = 1/4*2^2 - 2 + C1 = -1 + C1'
Is it equal to 0, because it comes right after the 0 of x <= 2?
can you solve for $C_1$ in the equation $0 = -1 + C_1$
rie.mann
Oh- I'm sorry, I only just noticed the text up there
so now you know why is it 0?
Honestly no, would you mind elaborating?
do you know how to read f(x) as a piecewise function
it's exactly the same for F(x) for x<= 2
f(x)=0 for every value of x below or equal to 2
and 2 is below or equal than 2?
Correct
so F(2) is
I understand, but I fail to fathom the implication after that
.
Where does this come from?
F(x) is right continuous
do you know what continuity at a point means?
using limits, say
because you're solving for unknowns
using continuity lets you solve for unknowns
these are the two unknowns
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Is (a•b) : (c•d) = (a:c) • (b:d) ?
yes
yay
$\frac{a \cdot b}{c \cdot d} = \frac{a}{c} \cdot \frac{b}{d}$
redstoneplayz09
Right
Me dumb
I can’t imagine things in different manners
I mean that was so simple
Thanks 🙏
@lucid night Has your question been resolved?
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@kind cedar Has your question been resolved?
Okay, I think a good strategy to approach this is first trying to count in how many ways can you draw three tickets such that they form a 1-progression
Solve simpler individual problems, and then with that in mind try to solve the bigger one
After that, try doing the same for 2-progressions
See if there is a pattern you can exploit
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Is it possible to integrate this $\int{\frac{1}{dx}}$
Bring Back Beatrix
i dont know if that is defined anywhere, but not as far as i know
dx is a very small thing, so 1/dx is very large
and the sense of integration is to add up lots of very small things
so here, we would add up lots of very large things which is why i would think this would diverge to +- infinity
so its inifinity
what if you add a term on the denominator to compensate it example $\int{\frac{1}{x^2 dx}}$
Bring Back Beatrix
it is important to note that i am not saying that it is like that
i am just outputting my intuition here
alright
i would assume that the x^2 wouldnt change anything
It's still gonna be big
yeah just want some insight here
yep i think its just some undefined term
well i guess you can define it yourself if you have context
after all, in some cases stuff like 1/0 is defined
if it makes sense in some context, then why not define it there
but in this case, i would say it would just be infinity usually
instead of undefined
I think that $\int{\frac{f(x)}{dx}}$ is just the slope of the diagonal of the dArea of a function
Bring Back Beatrix
so since as it dx get smaller and smaller, its approaching 90 degree and the slope becomes undefined
you can define it as whatever you want. but the notation is not defined. the dx in "normal" integrals is notation, it isnt actually some small thing
you could think of dx as an abstract notation or you could treat it as some geometric entity
Do you actually have a definition
you can think of stuff however you want. without a proper definition its still just a bunch of meaningless symbols
All these integral and derivative are just somehow derived from the concept of limits, and all rules of inetgration are from limits so i think the notation and definition are just "formality"
"just"
Yes formality is how you give definitions
If you don't want to do that, then you're just admitting you don't know what your symbols mean
its like 1+1, you could give whatever formality you want, but intuition in its sense is well understood
Awful analogy
those symbols are defined. that definition just checks out with our intuition (because that is how we chose the definition)
the collection of symbols you wrote down is not defined
i understand the symbols not in a rigid strict definition most "mathematicians" like to think about, i just understand it by intuition
i probalby have
You don't have any questions then?
i thinks it good for now
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Prove that $||A_n||_2$ tends to infinity when\
$A=\begin{pmatrix}
1&1&1&\cdots &1\
1&2&2&\cdots &2\
1&2&3&\cdots &3\
\vdots &\vdots &\vdots &\ddots &\vdots\
1&2&3&\cdots & n\
\end{pmatrix}$
Huh, not sure why latex doesn't like that
I tried to find some eigenvalue that depends on n, but I couldn't
casiel368
How about using the definition and x the all ones vector
So the l2 norm of x is sqrt(n) (for x= all ones vector )
and the l2 norm of Ax is at least n (because the sum of each row is at least n)
So ||A||_2 is at least sqrt(n)
@grizzled roost
yw
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f(x)=ln(sin(x)^sin(x) + 1) where 0<x<pi/2 how to find the range?
<@&286206848099549185>
Hi.
hello
this question
Can you text the problem again?
f(x)=ln(sin(x)^sin(x) + 1) where 0<x<pi/2 how to find the range?
k
To find the minimum and maximum, there are two things that you should do. First, calculate the derivative and evaluate when it is equal to zero. The second thing you will need to do is evaluate the end points of the interval. Whichever values are the largest and smallest will determine the interval of the range.
how to calculate the derivative?
If you never heard of it, you probably have to do it a different way
okay, tell me the other way to do it.
,w plot sin(x)^sin(x) for 0 < x < pi/2
,w min sin(x)^sin(x) on [0, pi/2]
Yea I'm not sure how
Do you know how to calculate a derivative or just not how to calculate this particular derivative?
is this the derivative?
@tame palm @supple knot
,wolf derivative ln( (sin(x))^(sin(x)) + 1)
Wait is it sin(x)^sin(x) or sin(x^sin(x))?
latter
Ugh, that looks ugly. 😖
this is not the question
its x^sin(x)
For the record that's not what you wrote originally
i don't know how to use LaTeX, otherwise i would have used it
Do you know what a^b means
what
$a^b$
rie.mann
bro
With a=b=sin(x)
wait i will send the picture
ultravioletvoodoo
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Is is (sin(x))^(sin(x)) or sin(x^(sin(x)))?
latter 😅
I would first simpifly th eproblem using logarithm rules.
I hate it when books don't use parentheses. 😛
how to simplify this?
Hmm, nevermind. I had my rules mixed up.
doesn't look like you can use log rules here
you do know how to calculate a derivative right?
is this correct @rigid shadow
,wolf derivative ln(sin( x^(sin(x))) + 1)
Yup, still an ugly derivative.
very bad chain rule derivative
ya
Can you post the entire question? I feel like there is something missing.
No, post the entire question as it is written.
ok
No, if that's it, then no.
okay
Then it's just this
The logarithm is monotonic so you just need to find the min and max of the argument
why should we evaluate the derivative at 0?
you could find the range without differentiating
how?
Bring Back Beatrix
what do you think the highest value it could have
1
it would be $log(1+1)$
Bring Back Beatrix
Bring Back Beatrix
and this one is at max when x is $\frac{\pi}{2}$
Bring Back Beatrix
oh right
but pi/2 isn't included, so ln 2 should also not be included in the range?
sorry
yes
and for the minimum value?
Bring Back Beatrix
do you think its the minimum value
look at this one $x^{sin(x)}$
Bring Back Beatrix
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✅
you know by doing this we can bump our question
what do you think is the minimum value of this $x^{sin(x)}$
Bring Back Beatrix
no
0?
