#help-27
1 messages · Page 91 of 1
You didn't need to do this
Yes cos is negative in Q2, but the range of arccos is [0, 180]
If you plotted this, that means the angle would have been in Q4, meaning x is positive and r is positive, for cos
oh which is outside of the range of cos
so the answer is just 143?
it's between 0-180 degrees
Should be, because 143 is in Q2, and -0.7986 would be -x and +r
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hello, dumb question but how exaclty do i find the accumulation points of sequences like cos(n*pi/3)?
what are the subequences?
Turns out this one is periodic
The accumulation points of a periodic sequence are pretty trivial
hmm
for example if i take every even and odd numbers of n; that wouldn't be enough right?
Solve this more general question. Then use it to trivialize your exercise
There's no reason to look at n mod 2 in particular
well, so in general, every value between -1 and 1 would be an accumulation point for cos
cos is not a sequence
yes indeed
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is there any algebraic way to solve this? (curious)
not sure. I got until this algebraicly:
$tanx = (secx)^{log_{4}3}$
imTyp0
to be frank, for big problems like these, yes I'd try algebraicly for a little bit, but when you see it won't work, just use newton's method or something like that to find your x values
how did you get that?
am being confused
sorry ignore what I just said
Alright?
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i'll try that
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hello
are number 15 and 16 correct?
someone help pls
theres a similar one there
sooo i kinda just tried to do the same
@cursive condor Has your question been resolved?
<@&286206848099549185>
i did all of them. i need to know what i did wrong on them though.
or just know which ones are wrong.
formulas used from right there
aint you got teacher to do that
no im at home
and teacher
gave no asnwer key
lmfao
im guessing theyre all right
cuz i did use all my resources
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@rich marsh Has your question been resolved?
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For part a i got
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I need to find the area of each of these 3 triangles ( it in French)
tu sais calculer la norme entre deux points d'un plan?
Le premier triangle j’ai compris comment le faire mais le deuxième je suis vraiment perdu
Calculer la distance entre 2 point?
Oui
et tu sais comment trouver l'équation de la perpendiculaire à une droite en utilisant un points de la perpendiculaire?
Comme 2/5 -> 5/2 -> -5/2 = -2,5 ?
oui
Mais après je sais pas quoi faire
tu trouves quoi comme equation de la droite (BC)?
Je sais que la pente est de -2,5
L’abscisse et l’ordonner du point (C)
oe tu dois trouver l'ordonnée à l'origine
Du point B ?
genre tu fais quoi maintenant que t'as la pente
tu dois trouver l'équation de la doite perpendiculaire à (AB) passant par C
Je ne sait pas comment le faire
l'equation de la droite perpendiculaire c'est y = -2.5x + b; tu sais que les coordonnées de C vérifient cette equation, maintenant il faut trouver b
@drifting barn
J’ai eu -0,02 pour le B
Oui
donc il reste plus qu'à trouver les coordonnées de B
tu dois cherche le point d'intersection de la droite (AB) et (BC), faut résoudre un systeme
Non
@dry rover you could do your problem without the inequality tbh
@drifting barn
I already deleted my post but what do you mean by that then?
rewrite as x^a/e^bx
exponential function has faster growth rate so it’ll be 1/infinity
=0
That’s already another theorem, that’s actually what we’re asked to prove
maybe squeeze theorem then if you have to use the inequality
Yes so I would need to use another function to bound it
Y=2/5(0,4)x +4
Y=-2.5x+33
Ok
Maintenant remplace le Y dans la première expression par le Y de la deuxième expression
yeah your limit is x approaches infinity from the right so you don’t need the left side bound
I mean don’t squeeze theorem require an upper and lower bound to work?
it’s requires a lower and upper bound to determine if the limit exists like lim as x-> inf of lower bound = x-> inf of upper bound for the limit to exist but your question only asks for the upper bound
They’re asking for the limit, I would need 2 functions to approach to same value(which is 0) for it to work
Quesque tu veux dire par remplace
Ahhhh
J’ai compris
no your picture shows lim x-> inf+
or was it postiive infinity
- inf
X=10.8?
10 ou 10,8?
10,8
comment tu as trouvé ca
6-33=-27
-27 diviser par -2,5
remet les étapes un peu pour voir
6=-2,5x +33
-27/-2,5=-2,5x/-2,5
10.8
comment t'as eu ce 6? Refais les étapes:
-2.5x+33=2/5x +4
pars de là
Tu ma dit de remplacer le y
J’ai crue que tu voulais dire que le y du AB je le met dans le BC
oui c ca
-2.5x+33=2/5x +4
8
oui
Alors la il faut trouver la distance?
oui maintenant t'as les coordonnées de chaque point et tu fais ton calcule d'aire habituel
Est ce que l’aire totale est de 39,64?
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Hi
Could you help me w 31
are you able to set up the integral
This is my work so far
is this what you asked on general? 😄
Yes, I forgot to write tan^2(x) in second line
Yes, it was, only tan^2(x) * sec^2(x) left
I see, I thought you asked $\int tan^2 sec^2 d[tansec]$
elyaguaro
God I hope I will never have to
try using an identity
Converting to sin-cos?
you can make that integral purely in terms of tan or sec
remember that tan^2x = sec^2x - 1
Is there a general rule for integration of other trigonometric functions like this?
this is correct
idk
not familiar with these rules
yw
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Why is 16b 3
when $\theta$ is small, $cos\theta$ tends to 1 and $tan\theta$ tends to 0
Basically they are asking you what $\frac{7+2cos2\theta}{tan2\theta+3} $ equals when $\theta = 0$
^ @prisma frost
Ah ok
Thanks for the help
Also if you don’t mind
For 18 would this my right or wrong?
I did difference of 2 squares
Then I just used the trig equations
there wont be theta nymore
question 18 says "when theta is small"
you're already using theta in cosine function
the output wont have it back
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Could someone help with b?
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
2
where did you stuck ?
I don't want to upload a pic of my rough work cause it's really messy, but I tried to show that the piecewise function is continuous on the intervals (0, 1/2) and (1/2, 1) using the delta-epsilon definition
I'm not sure how to proceed
Oh bro
function in these intervals is just linear
its obvious its continious
I think I also need to prove the limits at the endpoints of the intervals?
I know but I have to prove it haha
😂😂
okay so to prove a linear equation is continious just prove that the left and right limits are equal to each other and the value of function in that point
Right, so I just need to prove the right hand limit for x = 0, both limits for x = 1/2 and the left hand limit for x = 1?
And also show the function is continuous on the open interval
no no
look
we have a f(x) = ax+b
Mhm
show that for every t right and left limit are equal to f(t)
How about x = 1/2? Since it's included in both intervals
so you have to calculate right an and left limit seperately
and in this function they will be equal
Yes, so would I also do that for x = 1/2 in addition to the endpoints?
yeah
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hello, for this one can i just use the dot product formula and solve for cos(theta) ?
cos(θ) = (u*v)/(|u| |v|) this one
solve for theta, not cos(theta)
but yes use that formula
note that its asking for the obtuse angle so make sure your angle is obtuse
that looks good
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help
Do you realise how negative exponents work?
What the hell am I doing here?
i think they're referring to the case of the limit of x approacing 0 from the opposite side to 0+
Thank you. I have a poor understanding of mathematics
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I mean if you read what I said, then it connects to what they're asking well.
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May I get a grip within this problem?
I'm stuck within this, it's been a while I've done this math, but this is all within Quadrilaterals, is there a formula for thus?
u need help solving the issue ?
Where are you getting 180 from
Wait, I think I understand it now.
AT = 21
Meaning it must be the same within CT
Knowing it's the same length
by what property do you know its the same
Uhh,
usually you would just set 21=2x+13 and do some algebra from there, but yes the answer is 4
thats the problem with the question, it doesnt explicitly say that the shape is a parallogram
but your suppose to assume it is otherwise theres no way to solve it. For a paralellogram, the diagonals bisect each other, so AT=CT
Right right
Yeah, isn't Quad = 4 sides, right?
yes but for the shape above, its not true that the diagonals bisect each other
That's true.
so you won't be able to say that AT=CT for the shape i sent there
Right
but clearly the question is talking about a parallelogram and not just any quadrilateral otherwise it would be unsolvable, just something to keep in mind
Within this, I don't clearly understand what it is telling me.
Right right, thank you.
what part don't you understand, the question itself or how to get there
the angle ABC is a right-angle because question told us the shape is rectangle right
try drawing in that right-angle and flipping the page upsidedown and stare at it for abit
Right, use "Rectangle ABCD"
Hmm, I don't get it much, lol.
I noticed within the A, there is a square
do this and see if you have a right-angled triangle
Isn't that anything important, like an angle?
a right-angled triangle that you know the value of two sides
that means right-angled
Ohh, I see it
and have you solved a question like this before involving a right-angled triangle and where you know two of its sides and now have to find the last?
Hmm, maybe a while ago, but not now
pythagoras's theorem right?
try that
Okay okay
I'm confused, because within it being squared
There is no number that squares up to 36
34*
But there is one for 16
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what are you talking about
I meant 34
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any tips?
what’s the box for
it's a mistake
just plug in 0
2*sin0/2?
yes
I have poor mathematical knowledge, what next
what is sin(0)
sin(0) = 0
okay then your answer is 0
but there is sin 0/2
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thanx
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hi
for which value of a, b and c is f(x) differentiable at 1?
So first I was trying to find for which value of (a, b, c) it is continuous; and the limite of f(x) approaches 1< is -3; so c should be -3
but then after that, I found -pi for the limit of the rate of change when approaches 1<
why is it different?
you speak french ?
oui
okok
pourquoi est-ce que la fonction et sa dérivée devraient valoir la même chose ?
ah oui c vrai
même si je prends juste un gentil x^2 ça marche pas
enfin bon sinon
t'as encore a et b à trouver
donc probablement deux équations à trouver reliant a et b
on résout et on a gagné
quelles conditions doivent être ok sur la partie >1 pour que f soit dérivable ?
il faut que la limite du taux d'accroissement en 1 soit egale à -pi
je ne sais pas?
il faut que la limite de cette partie soit égale à -3 quand x tend vers 1
oui voilà si ta fonction est pas continue, osef qu'elle soit dérivable
donc dabord je cherche la continuité
et la limite à gauche de 1 c'est -3, et f(1)=-3; et donc 1+a+b=-3:
a+b=-4
c=-3
maintenant derivée:
la limite du taux d'accroissement de la premiere partie quand x tend vers 1 est -pi
et dans la derniere partie c'est a+2
donc a+2=-pi
a=-2-pi
donc b=-4+2+pi
b=6+pi
conditions: a=2-pi, b=6+pi, c=-3
@sullen island
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how did they convert ( omega / i ) to highlighted part?
1/i=-i
i don't understand how i^-1 is -i?
Multiply it by i/i
to remove i from the denominator
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I knew that the far left triangle is a Pythagorean triple and so is the one next to it
So now what?
<@&286206848099549185>
12^2+a^2 = 15^2
a = 9
if theres a 30-degree angle in a right triangle, that means the side that corresponds to it is 1/2 of the hypotenuse
gl
Sorry I’m trying to find AB
Length AB
@cobalt cipher
Please refer to the first picture
look at the next message i sent after that
oh, i thought that was a, i couldnt read what you had written
yes
Oh wow I didn’t know this rule
yes
yeah it is a key rule to know if you want to solve these problems
Okay I see
I know that the 90 degree angle will have the largest corresponding side
And 30 degree will have the smallest
And that two sides of a right triangle when added together must be greater than the hypotenuse side
That’s pretty much all I know
And then Pythagorean theorem
i mean, always bigger angles correspond to bigger sides, and always the sum of either two triangle sides must be greater than the third
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,tex .original
Toby
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0/0 is not an answer, it is only an indication that more work needs to be done
in this case it is possible to reason why the limit is 0
why
"why" as in "why is it possible to reason?" or as in "so why is the limit 0?"
why is it possible to reason
a line of reasoning exists, that's why.
i mean ok its a bit asinine of me to ask that
easier to just show you what it is
x^4 + 2y^4 ≤ 2x^4 + 2y^4 = 2(x^4 + y^4) ≤ 2(x^4 + 2x^2y^2 + y^4) = 2(x^2+y^2)^2
so your function is squeezed by 2(x^2+y^2) and 0
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i wish that translation made sense, like at all
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<@&286206848099549185>
What grade u on?
why
@onyx basin you have find partial g with to variable s at (1,\sqrt(2))
similarly for variable t
Apply multivariable chain rule
$\frac{\partial g}{\partial s}= \frac{\partial f}{\partial x} \frac{\partial x}{\partial s}$
$\frac{\partial g}{\partial s}= \frac{\partial f}{\partial x} \frac{\partial x}{\partial s} + \frac{\partial f}{\partial y} \frac{\partial y}{\partial s}$
.doc
Computing this and evaluating at (1,sqrt(2)) will give you answer for q1.
woo this is first time in my life seeing these type of questions...
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hi
im strugglng with this
heres my work
i got the point (2,-1,-1) from using r = 1 in L3
i got the point (-3,-10,2) from L2 standard equation
used them to get the vector <-5,-9,6>
cross producted that from the vector from l3 standard equation
got thhe normal vector -12,-4,-4
divided the magnitude of that by the magnitude of l3 standard equation vector
got sqrt(176)/sqrt(6)
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Hello, I don't understand why the second method is correct and the first one is incorrect
the first one counts the same group multiple times
How?
Using combinations, I first choose 1 random boy (6 possibilities) then a random girl (4 possibilities) and a random from the rest
8 possibilities
e.g. "first male, 6th male and first female"
this method would count that, and then count it again
2 times total
why would it count it again?
why does the first double count and the second doesn't?
you first choose random boy (6th one) then random girl (first one), then random person (1st boy)
you first choose random boy (1st one) then random girl (first one), then random person (6th boy)
the second one just doesn't do it
I see
And how should I think so my mind knows that I will double count if I do the first method?
🤷
How do you know that you will double count?
Btw, if it double counts, wouldn't it mean that half of the results would be correct? But that's not true since 192/2 =!= 96
192/2 = 96
yeah, so it doesn't double count everything neatly
oh it does
perhaps think about why 6C1 * 5C1 =/= 6C2
because you can not pick "2" from a set of "6" by selecting one and then selecting two. thats counting (1,5) and (5,1) as two instead of one
you meant selecting one and then selecting another one?
yes. thats the incorrect way to go about it. no?
the first one would be true if the leftover (8) set was disjoint from the first two, it is not!
what do you mean disjoint? +?
no intersection
How do I write that?
two sets are said to be disjoint sets if they have no element in common
huh?
im just trying to explain the why first one is wrong and second is right
no problem
1 second I'm thinking
Ok I understand this. And I understood and I know that 6C1 * 5C1 =/= 6C2 but I don't really understand why.
why is 6C1 * 5C1 =!= 6C2?
well
6C1 is selecting one from a set of 6. 5C1 is selecting 1 from a set of 5.
multiply together, you get 6 * 5 = 30
Yes
I know that it's not equal, I'm not seeking the calculations for why is it not the same, I am seeking what is not the same in the logic
Maybe I spoke too early sorry you're still typing
the first is for when you have two sets you need one element each from. the second is for when you have one set you need two from
Ok and since I end up needing to select 1 from a set that has both I can't do the first way
we can see that there is double counting involved in the first. because 6C1 * 5C1 counts (1,2) and (2,1) differently. we dont want that
yes. you need either 2 from M and 1 from F
OR 2 from F and 1 from M
that (1,2) (2,1) syntax makes me confused
I don't get that
I get it but at the same time not
i have a set {1,2,3,4,5,6}
You are saying it first selects 1 and then selects 2 and 5C1 does the second one
how many 2-combinations can i make from this set?
6C2
=15
but what if i use 6C1 * 5C1
lets say the first term 6C1 selects 1
and then 5C1 selects 2
so we get the combination (1,2)
next, 6C1 selects 2 and 5C1 selects 1
so we get the combination (2,1)
IT COUNTS THESE AS TWO DIFFERENT COMBINATIONS (THEY ARE NOT)
this is why we say we are "DOUBLE COUNTING"
Okaaay I got that, and in the second way (6C1 * 4C2) + (6C2 * 4C1) I don't have the problem you're pointing here because I am choosing 1 boy from a set of only boys, then 2 girl from a set of only girls plus the other way around
2 boys and 1 girl
yes
Hmmmm and is there a way to rewrite the first method?? Using arrays or factorials I don't know
Or dividing and having an explanation for that division without it being because I am double counting
the first approach just wont work here without division (and that looks ugly)
lmfao
Okii thank you a lottt utrebstoooooo
np
How do I close this?
.close
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Hi, I need help for this question,
Also
I got x = pi/2 + pi(n), n in Z
Would it be correct? If so, why?
They're both equal
but what proof are they refering to
The expression ig
I think they meant to say "which values is the identity valid"?
ah
Yeah
Which, it's an identity right?
Other than some values which cause problems
I think you've correctly pointed out where the identity isn't valid
||they did so for tan^2 + 1 = sec^2||
Cos is at the bottom
Wait..
Sinx is at the denom of cotx
So its undefined at x = pi(n)
Right?
yes
So would it look like this:
x = pi(n), n in Z?
what is the question asking you to find
For which values of x is it valid
and what did you find
Invalid interval
Give them a set
this accurately depicts the values for which the identity is not valid
^^
can you use that to give the values where it is valid?
no
How would I show it then?
what kind of ways have you been taught to show a domain?
intervals? sets? equalities?
Intervals and sets
D: { x/= pi + pi(n), x e Z}
Is it correct now?
To include negative numbers
Yeah
except pi * n for any integer n
Yes
the set you built
which i'm going to write in the more standard order
is
${ x \in \mathbb{Z} | x\ne n\pi}$
maximo
is 1/2 in this set?
No
It's not undefined then?
what do you mean
U mean pi/2?
Oh
is 1/2 in the set we wrote above?
Not sure
do you know what that set notation is saying
Z is saying all positive and negative numbers
maximo
Integers
maximo
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how is this
i tried all ways i always get either 10 or 12 or -8 new answer everytime
Show your work, and if possible, explain where you are stuck.
I multiply first then do dot product?
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in a inequality, lets say x < y , if i apply a strictly increasing function, does the inequality stay the same? what about a strictly decreasing function?
striictly increasing -> 1st derivative is always positive
strictly decreasing -> 1st derivative is always negative
inequality sign flips in second case, stays the same for first case
thanks sir
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i feel like this is a dumb question but how do we solve this without using a calculator
$14^2-14 x 11$
𝖈𝖆𝖘𝖍𝖞𝖈𝖔𝖎𝖓𝖘
-14 times 11 but it’s showing it as the value x
i did 14(14-1x11)
but apparently that’s wrong
we have to do 14(14-11) but why is that
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Dude are u even gonna help
hello
yo
did u memorize ur squares
i guess but i already know this and there’s more complex things in my revision sheet it’s just that this is the only thing confusing me
i see
196
niiice
ohh u meant like the timetable thing
I don’t have those at the top of my head rn but ik how to solve it
154
now subtract them
thats ur answer
yep
and then we multiply 14 by 11 and subtract them because it’s negative 14
yea
which is absolutely confusing
ok
do you know about pemdas
what u did above was called factoring
oh
can u tell me how to factor such equations in case it asks me in the exam if u don’t mind
sure
yay thanks
do u know distibutive property
nope
ok
i think i may know it if u show it to me
but we probably have a different name for it
2(2+3)
that’s 10
then you can multply 2 by each term in the parenthesis
like this
2 x 2 + 2 x 3
make sense?
also
ye i understand it
wdym
?
yea
ok
so if you have:
3x+3y
you can do the above, but in reverse
3(x+y)
make sense?
but i don’t understand why we did that, lemme show u what i did
ok
i did 14(14 so that it’s 14 squared, then i added -1 so that it matches the equation (-14) and then i multiplied 11
yea
Dude i’ve legit been struggling over it for a whole month
wow
Thanks for understanding
but now u know
Yeah even the teacher gave up
omg really
yesss 💪
yes LMAOOO
great work
thanks man 😁
np
also thank u so much for ur help
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how does this make sense
its from the answer key
i need help with a question
find different channel, i claimed this one
<@&286206848099549185> no other responses for 15 mins, but i would still like to understand this question
20 percent of what
number of sales
oh i see
i thought that was the number of tickets sold
i see
but, now we can say that
0.2 * x = 30
where x is the total number of sales
make sense?
yeah i understand now that i saw it was the percent of sales 💀
well the answer was already there in answer key
its just that i didn't know how that got there
until now
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Show the full context
They just canceled the square with the 3/2 in the exponent
(a^2) ^ (-3/2) = a^(-3)
@craggy quiver Has your question been resolved?
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Does anyone know how to get from step 2 to 3 in this projection explanation? From Linear Algebra.
@restive river Has your question been resolved?
@restive river Has your question been resolved?
<@&286206848099549185>
@restive river Has your question been resolved?
@restive river I'm typing up a response
thank you
I found another proof for the situation that involves angles, but I dont understand this method
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Can someone turn this into a table model

