#help-27

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unreal pollen
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where did I go wrong

main gull
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You didn't need to do this

unreal pollen
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oh.

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so what does Q do exactly then

main gull
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Yes cos is negative in Q2, but the range of arccos is [0, 180]

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If you plotted this, that means the angle would have been in Q4, meaning x is positive and r is positive, for cos

unreal pollen
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oh which is outside of the range of cos

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so the answer is just 143?

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it's between 0-180 degrees

main gull
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Should be, because 143 is in Q2, and -0.7986 would be -x and +r

unreal pollen
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let me try

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🎊 it is

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thank you

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dry rover
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hello, dumb question but how exaclty do i find the accumulation points of sequences like cos(n*pi/3)?

dry rover
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what are the subequences?

magic thicket
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Turns out this one is periodic

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The accumulation points of a periodic sequence are pretty trivial

dry rover
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hmm

dry rover
magic thicket
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There's no reason to look at n mod 2 in particular

dry rover
magic thicket
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cos is not a sequence

dry rover
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yes indeed

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autumn sparrow
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is there any algebraic way to solve this? (curious)

mighty knoll
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not sure. I got until this algebraicly:
$tanx = (secx)^{log_{4}3}$

woven radishBOT
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imTyp0

mighty knoll
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to be frank, for big problems like these, yes I'd try algebraicly for a little bit, but when you see it won't work, just use newton's method or something like that to find your x values

flat rain
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4^(tan x) = 3^(sec x)

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I'd ln both sides

mighty knoll
flat rain
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moving log4 and log3 to opposite sides

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wait hold on

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am being stupid

mighty knoll
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am being confused

flat rain
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sorry ignore what I just said

mighty knoll
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Alright?

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cursive condor
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hello

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cursive condor
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are number 15 and 16 correct?

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someone help pls

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theres a similar one there

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sooo i kinda just tried to do the same

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@cursive condor Has your question been resolved?

cursive condor
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<@&286206848099549185>

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i did all of them. i need to know what i did wrong on them though.

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or just know which ones are wrong.

cursive condor
obsidian oak
cursive condor
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no im at home

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and teacher

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gave no asnwer key

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lmfao

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im guessing theyre all right

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cuz i did use all my resources

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rich marsh
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rich marsh
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How do I do this?

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rich marsh
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Yes

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manic timber
#

For part a i got

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manic timber
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alpha/beta = -b/a

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is that correct?

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and how do i do b

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drifting barn
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I need to find the area of each of these 3 triangles ( it in French)

dry rover
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tu sais calculer la norme entre deux points d'un plan?

drifting barn
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Le premier triangle j’ai compris comment le faire mais le deuxième je suis vraiment perdu

drifting barn
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Oui

dry rover
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et tu sais comment trouver l'équation de la perpendiculaire à une droite en utilisant un points de la perpendiculaire?

drifting barn
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Comme 2/5 -> 5/2 -> -5/2 = -2,5 ?

dry rover
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oui

drifting barn
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Mais après je sais pas quoi faire

dry rover
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tu trouves quoi comme equation de la droite (BC)?

drifting barn
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Je sais que la pente est de -2,5

dry rover
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oui

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maintenant le reste

drifting barn
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L’abscisse et l’ordonner du point (C)

dry rover
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oe tu dois trouver l'ordonnée à l'origine

drifting barn
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Du point B ?

dry rover
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genre tu fais quoi maintenant que t'as la pente

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tu dois trouver l'équation de la doite perpendiculaire à (AB) passant par C

drifting barn
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Je ne sait pas comment le faire

dry rover
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@drifting barn

drifting barn
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J’ai eu -0,02 pour le B

dry rover
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comment?

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c'est pas ca normalement

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tu remplaces x et y par 13 et 0.5

drifting barn
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(1) -2,5 x13=32,5
(2) 0,5 diviser par 32,5
(3) =0,02

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Ah lsf

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B =33

dry rover
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oui

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du coup là t'as l'equation de la droite

drifting barn
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Oui

dry rover
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donc il reste plus qu'à trouver les coordonnées de B

drifting barn
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Oui

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Mais la ducoup je fait comment puisque que j’ai ni le x et ni le y de B

dry rover
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tu dois cherche le point d'intersection de la droite (AB) et (BC), faut résoudre un systeme

drifting barn
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Est ce que la formule est x1+x2 divisée par 2?

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Pour le point d’intersection

dry rover
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non

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tu sais résoudre un systeme?

drifting barn
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Non

dry rover
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Ah

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Écris les deux équations

neat night
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@dry rover you could do your problem without the inequality tbh

dry rover
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@drifting barn

dry rover
neat night
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rewrite as x^a/e^bx

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exponential function has faster growth rate so it’ll be 1/infinity

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=0

dry rover
neat night
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maybe squeeze theorem then if you have to use the inequality

dry rover
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Yes so I would need to use another function to bound it

drifting barn
neat night
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well you’re given the bound

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prob just have to do some algebra

dry rover
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Only one bound with that inequality tho?

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I’ll think about it

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Thanks

dry rover
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Maintenant remplace le Y dans la première expression par le Y de la deuxième expression

neat night
dry rover
neat night
dry rover
drifting barn
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Ahhhh

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J’ai compris

neat night
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or was it postiive infinity

dry rover
dry rover
drifting barn
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X=10.8?

dry rover
drifting barn
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10,8

dry rover
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comment tu as trouvé ca

drifting barn
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6-33=-27
-27 diviser par -2,5

dry rover
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remet les étapes un peu pour voir

drifting barn
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6=-2,5x +33
-27/-2,5=-2,5x/-2,5
10.8

neat night
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well the lower bound is 0

dry rover
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-2.5x+33=2/5x +4

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pars de là

drifting barn
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Tu ma dit de remplacer le y

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J’ai crue que tu voulais dire que le y du AB je le met dans le BC

dry rover
dry rover
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-2.5x+33=2/5x +4

drifting barn
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Ah

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Ok

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Alors le x est 10?

dry rover
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oui

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et y?

drifting barn
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8

dry rover
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oui

drifting barn
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Alors la il faut trouver la distance?

dry rover
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oui maintenant t'as les coordonnées de chaque point et tu fais ton calcule d'aire habituel

drifting barn
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Est ce que l’aire totale est de 39,64?

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@drifting barn Has your question been resolved?

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shut fable
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Hi

devout snowBOT
shut fable
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Could you help me w 31

restive river
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are you able to set up the integral

shut fable
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This is my work so far

restive river
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you can probably do a substitution

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wait no

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hmm

inner oyster
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is this what you asked on general? 😄

shut fable
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Yes, I forgot to write tan^2(x) in second line

shut fable
inner oyster
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I see, I thought you asked $\int tan^2 sec^2 d[tansec]$

woven radishBOT
#

elyaguaro

shut fable
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God I hope I will never have to

restive river
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try using an identity

shut fable
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Converting to sin-cos?

restive river
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you can make that integral purely in terms of tan or sec

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remember that tan^2x = sec^2x - 1

shut fable
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Righttt

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I think that's tan^3(x)/3

shut fable
restive river
restive river
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not familiar with these rules

shut fable
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Alright

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Thank you

restive river
#

yw

shut fable
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prisma frost
#

Why is 16b 3

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restive river
civic ore
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Basically they are asking you what $\frac{7+2cos2\theta}{tan2\theta+3} $ equals when $\theta = 0$

woven radishBOT
#

physicsIsThicc

civic ore
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^ @prisma frost

prisma frost
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Ah ok

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Thanks for the help

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Also if you don’t mind

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For 18 would this my right or wrong?

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I did difference of 2 squares

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Then I just used the trig equations

restive river
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question 18 says "when theta is small"

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you're already using theta in cosine function

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the output wont have it back

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crimson kiln
#

Could someone help with b?

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snow oasis
devout snowBOT
# crimson kiln Could someone help with b?
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
snow oasis
crimson kiln
# snow oasis where did you stuck ?

I don't want to upload a pic of my rough work cause it's really messy, but I tried to show that the piecewise function is continuous on the intervals (0, 1/2) and (1/2, 1) using the delta-epsilon definition

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I'm not sure how to proceed

snow oasis
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function in these intervals is just linear

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its obvious its continious

crimson kiln
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I think I also need to prove the limits at the endpoints of the intervals?

crimson kiln
snow oasis
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okay so to prove a linear equation is continious just prove that the left and right limits are equal to each other and the value of function in that point

crimson kiln
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And also show the function is continuous on the open interval

snow oasis
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look

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we have a f(x) = ax+b

crimson kiln
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Mhm

snow oasis
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show that for every t right and left limit are equal to f(t)

crimson kiln
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How about x = 1/2? Since it's included in both intervals

snow oasis
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and in this function they will be equal

crimson kiln
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Yes, so would I also do that for x = 1/2 in addition to the endpoints?

crimson kiln
#

.close

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snow oasis
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opal elm
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opal elm
#

hello, for this one can i just use the dot product formula and solve for cos(theta) ?

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cos(θ) = (u*v)/(|u| |v|) this one

restive river
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solve for theta, not cos(theta)

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but yes use that formula

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note that its asking for the obtuse angle so make sure your angle is obtuse

opal elm
#

yeye

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so is it something like this

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1m

restive river
#

that looks good

opal elm
#

alright

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ty bro

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.close

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restive river
devout snowBOT
restive river
#

how do I work now that I have 0-

stuck field
#

Do you realise how negative exponents work?

woven radishBOT
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What the hell am I doing here?

restive river
#

i think they're referring to the case of the limit of x approacing 0 from the opposite side to 0+

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Thank you. I have a poor understanding of mathematics

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stuck field
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sharp wing
#

May I get a grip within this problem?

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sharp wing
#

I'm stuck within this, it's been a while I've done this math, but this is all within Quadrilaterals, is there a formula for thus?

flat talon
#

u need help solving the issue ?

sharp wing
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Yes, yes I do.

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Wait, I'm dumb.

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LMAO

flat talon
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C+A=180

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so 21+2x+13=180

untold pivot
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Where are you getting 180 from

sharp wing
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Wait, I think I understand it now.

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AT = 21

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Meaning it must be the same within CT

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Knowing it's the same length

untold pivot
sharp wing
#

So, 2(4) = 8

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8+13 = 21

sharp wing
untold pivot
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usually you would just set 21=2x+13 and do some algebra from there, but yes the answer is 4

sharp wing
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Aren't these lines "parallel"?

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So, it would be the same with all the sides, right?

untold pivot
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thats the problem with the question, it doesnt explicitly say that the shape is a parallogram

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but your suppose to assume it is otherwise theres no way to solve it. For a paralellogram, the diagonals bisect each other, so AT=CT

sharp wing
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Well, I put in the beginning that all the

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Shapes are Quadrilaterals

untold pivot
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^this is a quadrilateral too

sharp wing
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Yeah, isn't Quad = 4 sides, right?

untold pivot
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yes but for the shape above, its not true that the diagonals bisect each other

sharp wing
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That's true.

untold pivot
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so you won't be able to say that AT=CT for the shape i sent there

sharp wing
#

Right

untold pivot
#

but clearly the question is talking about a parallelogram and not just any quadrilateral otherwise it would be unsolvable, just something to keep in mind

sharp wing
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Within this, I don't clearly understand what it is telling me.

untold pivot
sharp wing
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How to get there, because like

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BC = X

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AC = 34

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AB = 16

untold pivot
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the angle ABC is a right-angle because question told us the shape is rectangle right

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try drawing in that right-angle and flipping the page upsidedown and stare at it for abit

sharp wing
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Right, use "Rectangle ABCD"

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Hmm, I don't get it much, lol.

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I noticed within the A, there is a square

untold pivot
sharp wing
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Isn't that anything important, like an angle?

untold pivot
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a right-angled triangle that you know the value of two sides

untold pivot
sharp wing
untold pivot
#

and have you solved a question like this before involving a right-angled triangle and where you know two of its sides and now have to find the last?

sharp wing
untold pivot
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pythagoras's theorem right?

sharp wing
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Ohh

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That's been a while yeah

untold pivot
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try that

sharp wing
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Okay okay

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I'm confused, because within it being squared

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There is no number that squares up to 36

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34*

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But there is one for 16

devout snowBOT
#

@sharp wing Has your question been resolved?

devout snowBOT
#

@sharp wing Has your question been resolved?

neat night
sharp wing
#

I meant 34

devout snowBOT
#

@sharp wing Has your question been resolved?

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restive river
#

any tips?

devout snowBOT
neat night
#

what’s the box for

restive river
#

it's a mistake

neat night
#

just plug in 0

restive river
#

2*sin0/2?

neat night
#

yes

restive river
#

I have poor mathematical knowledge, what next

neat night
#

what is sin(0)

restive river
#

1

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okey but there is sin 0/ 2

neat night
#

okay so your answer is 0

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what

restive river
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sin(0) = 0

neat night
#

okay then your answer is 0

restive river
#

but there is sin 0/2

neat night
#

okay and?

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what is 0/2….

restive river
#

.close

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restive river
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dry rover
#

hi

devout snowBOT
dry rover
#

for which value of a, b and c is f(x) differentiable at 1?

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So first I was trying to find for which value of (a, b, c) it is continuous; and the limite of f(x) approaches 1< is -3; so c should be -3

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but then after that, I found -pi for the limit of the rate of change when approaches 1<

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why is it different?

sullen island
#

you speak french ?

dry rover
#

oui

sullen island
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okok

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pourquoi est-ce que la fonction et sa dérivée devraient valoir la même chose ?

dry rover
#

ah oui c vrai

sullen island
#

même si je prends juste un gentil x^2 ça marche pas

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enfin bon sinon

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t'as encore a et b à trouver

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donc probablement deux équations à trouver reliant a et b

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on résout et on a gagné

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quelles conditions doivent être ok sur la partie >1 pour que f soit dérivable ?

dry rover
sullen island
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oui

#

il y a un autre truc aussi

dry rover
#

je ne sais pas?

#

il faut que la limite de cette partie soit égale à -3 quand x tend vers 1

sullen island
#

oui voilà si ta fonction est pas continue, osef qu'elle soit dérivable

dry rover
#

donc dabord je cherche la continuité

#

et la limite à gauche de 1 c'est -3, et f(1)=-3; et donc 1+a+b=-3:

#

a+b=-4

#

c=-3

#

maintenant derivée:

#

la limite du taux d'accroissement de la premiere partie quand x tend vers 1 est -pi

#

et dans la derniere partie c'est a+2

#

donc a+2=-pi

#

a=-2-pi

#

donc b=-4+2+pi

#

b=6+pi

#

conditions: a=2-pi, b=6+pi, c=-3

#

@sullen island

sullen island
#

re @dry rover

#

enfin c'est b=pi-2

#

mais sinon oui ça me va

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#

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dry rover
#

merci

#

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restive river
#

how did they convert ( omega / i ) to highlighted part?

stone stump
#

1/i=-i

restive river
#

it is not inverse?

#

not i^-1?

stone stump
#

i*(-i)=-i^2=-(-1)=1

#

it is the inverse

#

which just happens to be -i

restive river
#

i don't understand how i^-1 is -i?

rugged sparrow
#

to remove i from the denominator

restive river
#

aah

#

got it

#

👍

#

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pearl trellis
devout snowBOT
pearl trellis
#

I knew that the far left triangle is a Pythagorean triple and so is the one next to it

#

So now what?

#

<@&286206848099549185>

cobalt cipher
#

12^2+a^2 = 15^2

#

a = 9

#

if theres a 30-degree angle in a right triangle, that means the side that corresponds to it is 1/2 of the hypotenuse

#

gl

pearl trellis
#

Sorry I’m trying to find AB

#

Length AB

#

@cobalt cipher

#

Please refer to the first picture

cobalt cipher
#

yes

#

i gave you more than a pointer

pearl trellis
#

I knew that length was 9

#

I put 9 there as you can you in the second pic

cobalt cipher
#

look at the next message i sent after that

pearl trellis
#

So hypotenuse is 30

#

For the bigger triangle

cobalt cipher
cobalt cipher
pearl trellis
#

Okay and then 30-5 is 25-9=16

#

So 16

#

Would be the the length of AB

pearl trellis
cobalt cipher
#

yeah it is a key rule to know if you want to solve these problems

pearl trellis
#

Are there other rules for 45 45 90

#

Or 30 60 90

cobalt cipher
#

there are a few

#

most are with 30 degree ones

pearl trellis
#

Okay I see

#

I know that the 90 degree angle will have the largest corresponding side

#

And 30 degree will have the smallest

#

And that two sides of a right triangle when added together must be greater than the hypotenuse side

#

That’s pretty much all I know

#

And then Pythagorean theorem

cobalt cipher
#

i mean, always bigger angles correspond to bigger sides, and always the sum of either two triangle sides must be greater than the third

pearl trellis
#

Alright!

#

Anyways thank you

#

.close

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reef carbon
devout snowBOT
reef carbon
#

not really sure how to simplify

surreal frigate
#

you can get rid of the 2s

#

doesn't go further

restive river
#

,tex .original

woven radishBOT
reef carbon
#

.close

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onyx basin
devout snowBOT
onyx basin
#

Shouldn't this be an indetermination

#

0/0

pseudo basin
#

0/0 is not an answer, it is only an indication that more work needs to be done

#

in this case it is possible to reason why the limit is 0

onyx basin
#

why

pseudo basin
#

"why" as in "why is it possible to reason?" or as in "so why is the limit 0?"

onyx basin
#

why is it possible to reason

pseudo basin
#

a line of reasoning exists, that's why.

#

i mean ok its a bit asinine of me to ask that

#

easier to just show you what it is

#

x^4 + 2y^4 ≤ 2x^4 + 2y^4 = 2(x^4 + y^4) ≤ 2(x^4 + 2x^2y^2 + y^4) = 2(x^2+y^2)^2

#

so your function is squeezed by 2(x^2+y^2) and 0

onyx basin
#

Are you talking about something like this?

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#

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onyx basin
devout snowBOT
onyx basin
#

I translated it

#

I'm lost here

#

differential*

restive river
#

i wish that translation made sense, like at all

onyx basin
#

exercise doesn't make sense

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#

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#

@onyx basin Has your question been resolved?

onyx basin
#

<@&286206848099549185>

unique bone
onyx basin
arctic temple
#

@onyx basin you have find partial g with to variable s at (1,\sqrt(2))

#

similarly for variable t

#

Apply multivariable chain rule

#

$\frac{\partial g}{\partial s}= \frac{\partial f}{\partial x} \frac{\partial x}{\partial s}$

#

$\frac{\partial g}{\partial s}= \frac{\partial f}{\partial x} \frac{\partial x}{\partial s} + \frac{\partial f}{\partial y} \frac{\partial y}{\partial s}$

woven radishBOT
arctic temple
#

Computing this and evaluating at (1,sqrt(2)) will give you answer for q1.

languid tangle
#

woo this is first time in my life seeing these type of questions...

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#

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restive river
#

hi

devout snowBOT
restive river
#

im strugglng with this

#

heres my work

#

i got the point (2,-1,-1) from using r = 1 in L3

#

i got the point (-3,-10,2) from L2 standard equation

#

used them to get the vector <-5,-9,6>

#

cross producted that from the vector from l3 standard equation

#

got thhe normal vector -12,-4,-4

#

divided the magnitude of that by the magnitude of l3 standard equation vector

#

got sqrt(176)/sqrt(6)

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#

@restive river Has your question been resolved?

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#

@restive river Has your question been resolved?

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#

@restive river Has your question been resolved?

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@restive river Has your question been resolved?

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dreamy wave
devout snowBOT
dreamy wave
#

Hello, I don't understand why the second method is correct and the first one is incorrect

topaz axle
#

the first one counts the same group multiple times

dreamy wave
#

How?
Using combinations, I first choose 1 random boy (6 possibilities) then a random girl (4 possibilities) and a random from the rest

#

8 possibilities

topaz axle
#

e.g. "first male, 6th male and first female"

#

this method would count that, and then count it again

#

2 times total

dreamy wave
#

why would it count it again?

topaz axle
#

it has to

#

the way it works has to count it twice

dreamy wave
#

why does the first double count and the second doesn't?

topaz axle
#

you first choose random boy (6th one) then random girl (first one), then random person (1st boy)
you first choose random boy (1st one) then random girl (first one), then random person (6th boy)

#

the second one just doesn't do it

dreamy wave
#

I see

#

And how should I think so my mind knows that I will double count if I do the first method?

topaz axle
#

🤷

dreamy wave
#

How do you know that you will double count?

#

Btw, if it double counts, wouldn't it mean that half of the results would be correct? But that's not true since 192/2 =!= 96

low fossil
#

192/2 = 96

topaz axle
#

yeah, so it doesn't double count everything neatly

dreamy wave
#

oh yeah you are right

#

My bad

topaz axle
#

oh it does

low fossil
#

because you can not pick "2" from a set of "6" by selecting one and then selecting two. thats counting (1,5) and (5,1) as two instead of one

dreamy wave
low fossil
#

yes. thats the incorrect way to go about it. no?

low fossil
# dreamy wave

the first one would be true if the leftover (8) set was disjoint from the first two, it is not!

dreamy wave
low fossil
#

no intersection

dreamy wave
#

How do I write that?

low fossil
#

two sets are said to be disjoint sets if they have no element in common

low fossil
dreamy wave
#

Oh I understand

#

Sorry I don't have a good vocabulary

low fossil
#

im just trying to explain the why first one is wrong and second is right

low fossil
dreamy wave
#

1 second I'm thinking

dreamy wave
low fossil
#

why is 6C1 * 5C1 =!= 6C2?

#

well

#

6C1 is selecting one from a set of 6. 5C1 is selecting 1 from a set of 5.

#

multiply together, you get 6 * 5 = 30

dreamy wave
#

Yes

low fossil
#

6C2 is selecting two from 6

#

6C2 = 15

dreamy wave
#

I know that it's not equal, I'm not seeking the calculations for why is it not the same, I am seeking what is not the same in the logic

#

Maybe I spoke too early sorry you're still typing

low fossil
#

the first is for when you have two sets you need one element each from. the second is for when you have one set you need two from

dreamy wave
low fossil
#

we can see that there is double counting involved in the first. because 6C1 * 5C1 counts (1,2) and (2,1) differently. we dont want that

#

yes. you need either 2 from M and 1 from F

#

OR 2 from F and 1 from M

dreamy wave
#

I don't get that

#

I get it but at the same time not

low fossil
#

i have a set {1,2,3,4,5,6}

dreamy wave
#

You are saying it first selects 1 and then selects 2 and 5C1 does the second one

low fossil
#

6C2

#

=15

#

but what if i use 6C1 * 5C1

#

lets say the first term 6C1 selects 1

#

and then 5C1 selects 2

#

so we get the combination (1,2)

#

next, 6C1 selects 2 and 5C1 selects 1

#

so we get the combination (2,1)

#

IT COUNTS THESE AS TWO DIFFERENT COMBINATIONS (THEY ARE NOT)

#

this is why we say we are "DOUBLE COUNTING"

dreamy wave
#

Okaaay I got that, and in the second way (6C1 * 4C2) + (6C2 * 4C1) I don't have the problem you're pointing here because I am choosing 1 boy from a set of only boys, then 2 girl from a set of only girls plus the other way around

#

2 boys and 1 girl

low fossil
#

yes

dreamy wave
#

Or dividing and having an explanation for that division without it being because I am double counting

low fossil
#

the first approach just wont work here without division (and that looks ugly)

dreamy wave
#

I saw that adsjklahdas

low fossil
#

lmfao

dreamy wave
#

Okii thank you a lottt utrebstoooooo

low fossil
#

np

dreamy wave
#

How do I close this?

low fossil
#

.close

dreamy wave
#

.clsoe

#

.close

devout snowBOT
#
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summer ocean
#

Hi, I need help for this question,
Also
I got x = pi/2 + pi(n), n in Z
Would it be correct? If so, why?

magic pine
#

what is "the proof"

#

@summer ocean

summer ocean
magic pine
#

but what proof are they refering to

summer ocean
#

The expression ig

graceful cosmos
#

I think they meant to say "which values is the identity valid"?

magic pine
#

ah

summer ocean
#

Yeah

graceful cosmos
#

Which, it's an identity right?

#

Other than some values which cause problems

#

I think you've correctly pointed out where the identity isn't valid

magic pine
graceful cosmos
#

Sorry, yep I lied

#

Right at you

summer ocean
#

Cos is at the bottom

#

Wait..

#

Sinx is at the denom of cotx

#

So its undefined at x = pi(n)

#

Right?

magic pine
#

yes

summer ocean
#

So would it look like this:

x = pi(n), n in Z?

magic pine
#

what is the question asking you to find

summer ocean
#

For which values of x is it valid

magic pine
#

and what did you find

summer ocean
#

Invalid interval

jaunty mantle
#

Give them a set

magic pine
jaunty mantle
#

^^

magic pine
#

can you use that to give the values where it is valid?

summer ocean
#

Isn't it just all real numbers outside of that range?

#

so x in Z?

magic pine
summer ocean
magic pine
#

what kind of ways have you been taught to show a domain?

#

intervals? sets? equalities?

summer ocean
#

Intervals and sets

magic pine
#

i suggest you try writing this as a set

#

do you know about set builder notation?

summer ocean
#

D: { x/= pi + pi(n), x e Z}

magic pine
#

what about x = 2pi?

#

or x = 3pi? or x = -pi?

summer ocean
#

Is it correct now?

magic pine
#

no

#

it's close

#

why did you change x to x in Z

summer ocean
#

To include negative numbers

magic pine
#

ok let's take a step back

#

we want to take all real numbers

summer ocean
#

Yeah

magic pine
#

except pi * n for any integer n

summer ocean
#

Yes

magic pine
#

the set you built

#

which i'm going to write in the more standard order

#

is

#

${ x \in \mathbb{Z} | x\ne n\pi}$

woven radishBOT
#

maximo

magic pine
#

is 1/2 in this set?

summer ocean
#

No

magic pine
#

you are right

#

why is it not in the set

summer ocean
#

It's not undefined then?

magic pine
#

what do you mean

summer ocean
#

U mean pi/2?

magic pine
#

no

#

i mean 1/2

summer ocean
#

Oh

magic pine
#

is 1/2 in the set we wrote above?

summer ocean
#

Not sure

magic pine
#

do you know what that set notation is saying

summer ocean
#

Z is saying all positive and negative numbers

magic pine
#

no

#

all positive and negative integers (and 0)

summer ocean
#

Oh

#

So R would include them?

magic pine
#

R is every real number

#

positive, negative, 0, integer, rational, irrational

summer ocean
#

Ohh

#

I see

magic pine
#

so we don't want x in Z

#

we want x in R

#

${ x \in \mathbb{R} | x\ne n\pi}$

woven radishBOT
#

maximo

magic pine
#

now it's almost there

#

the last thing to ask

#

what is n?

summer ocean
#

The number of times it dies a pi turn

#

Does*

magic pine
#

let me ask a different question

#

what values should n be allowed to be

summer ocean
#

Integers

magic pine
#

yes

#

so we add that to the set

#

${ x \in \mathbb{R} | x\ne n\pi , n\in\mathbb{Z}}$

woven radishBOT
#

maximo

summer ocean
#

Oh

#

I see

#

Thx then

devout snowBOT
#

@summer ocean Has your question been resolved?

devout snowBOT
#
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cyan fossil
#

how is this

devout snowBOT
cyan fossil
#

i tried all ways i always get either 10 or 12 or -8 new answer everytime

devout snowBOT
#

Show your work, and if possible, explain where you are stuck.

verbal meadow
#

Uhm yea u substitute those...

#

Thats it ryt

cyan fossil
#

I multiply first then do dot product?

verbal meadow
#

Yea mult->add/subtr

#

Then dot pdt

cyan fossil
#

I got -8

#

i was adding 1 - (-9) = -8

#

.close

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#
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dense sail
#

in a inequality, lets say x < y , if i apply a strictly increasing function, does the inequality stay the same? what about a strictly decreasing function?
striictly increasing -> 1st derivative is always positive
strictly decreasing -> 1st derivative is always negative

feral agate
#

inequality sign flips in second case, stays the same for first case

dense sail
#

thanks sir

devout snowBOT
#

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jaunty seal
#

i feel like this is a dumb question but how do we solve this without using a calculator

jaunty seal
#

$14^2-14 x 11$

woven radishBOT
#

𝖈𝖆𝖘𝖍𝖞𝖈𝖔𝖎𝖓𝖘

jaunty seal
#

-14 times 11 but it’s showing it as the value x

#

i did 14(14-1x11)

#

but apparently that’s wrong

#

we have to do 14(14-11) but why is that

#

<@&286206848099549185>

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# jaunty seal <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

jaunty seal
#

Dude are u even gonna help

boreal pier
#

hello

jaunty seal
#

yo

boreal pier
#

did u memorize ur squares

jaunty seal
#

i guess but i already know this and there’s more complex things in my revision sheet it’s just that this is the only thing confusing me

boreal pier
#

i see

jaunty seal
#

i’ve been dealing with squares for 3 years

#

ye

boreal pier
#

nice

#

whats 14 squared

jaunty seal
#

196

boreal pier
#

niiice

jaunty seal
#

ohh u meant like the timetable thing

boreal pier
#

its fine

#

whats 14 x 11

jaunty seal
#

I don’t have those at the top of my head rn but ik how to solve it

jaunty seal
boreal pier
#

now subtract them

jaunty seal
#

42

#

Yo

boreal pier
#

thats ur answer

jaunty seal
#

wait whyd we do that

#

oh wait

#

hang on

#

14 squared cuz it says 14^2,

boreal pier
#

yep

jaunty seal
#

and then we multiply 14 by 11 and subtract them because it’s negative 14

boreal pier
#

yeo

#

p

jaunty seal
#

yo i never thought of that

#

lemme show u what we did in class

boreal pier
#

yea

jaunty seal
#

which is absolutely confusing

boreal pier
#

ok

jaunty seal
boreal pier
#

do you know about pemdas

jaunty seal
#

i don’t get why we did this

#

yes

boreal pier
#

ok

#

that should help

#

you dont need to factor

jaunty seal
#

uhh

#

wdym

boreal pier
#

what u did above was called factoring

jaunty seal
#

oh

#

can u tell me how to factor such equations in case it asks me in the exam if u don’t mind

boreal pier
#

sure

jaunty seal
#

yay thanks

boreal pier
#

do u know distibutive property

jaunty seal
#

nope

boreal pier
#

ok

jaunty seal
#

i think i may know it if u show it to me

#

but we probably have a different name for it

boreal pier
#

so when u have a number in fron tof a parenthesis

#

like this:

jaunty seal
#

yeah

#

it’s multiplying

boreal pier
#

2(2+3)

jaunty seal
#

that’s 10

boreal pier
#

then you can multply 2 by each term in the parenthesis

#

like this

#

2 x 2 + 2 x 3

#

make sense?

jaunty seal
#

uh

#

yeah

boreal pier
#

also

jaunty seal
#

ye i understand it

boreal pier
#

you can do the reverse

#

do you know variables

jaunty seal
#

wdym

boreal pier
#

?

jaunty seal
#

yea

boreal pier
#

ok

#

so if you have:

#

3x+3y

#

you can do the above, but in reverse

#

3(x+y)

#

make sense?

jaunty seal
#

Yeah

#

i was just doing those actually

boreal pier
#

yep

#

this is called the distributive propertyy

jaunty seal
#

but i don’t understand why we did that, lemme show u what i did

jaunty seal
#

here’s what i did

boreal pier
#

ok

jaunty seal
#

i did 14(14 so that it’s 14 squared, then i added -1 so that it matches the equation (-14) and then i multiplied 11

boreal pier
#

yeo

#

p

#

u just used the distibutive property

#

nice job

jaunty seal
#

But it gave me a different answer

#

OH

#

WAIT IM SO DUMB

boreal pier
#

order of operation

#

s

jaunty seal
#

i forgot to use pedmas omg

#

yeahhh

boreal pier
#

yea

jaunty seal
#

-1x11

#

that’s so stupid

boreal pier
#

yep

#

no

#

common mistake

#

i see it a lot

jaunty seal
#

Dude i’ve legit been struggling over it for a whole month

boreal pier
#

wow

jaunty seal
boreal pier
#

but now u know

jaunty seal
boreal pier
#

omg really

jaunty seal
jaunty seal
boreal pier
#

great work

jaunty seal
#

thanks man 😁

boreal pier
#

np

jaunty seal
#

also thank u so much for ur help

boreal pier
#

np

#

have a nice day

#

bye

jaunty seal
#

have u good day

#

u too

#

.close

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final hatch
#

how does this make sense

devout snowBOT
final hatch
#

its from the answer key

fallen garnet
#

i need help with a question

final hatch
#

find different channel, i claimed this one

#

<@&286206848099549185> no other responses for 15 mins, but i would still like to understand this question

boreal pier
#

hello

#

i think i can help

#

so as you can see

#

wednesday has 20%

final hatch
#

20 percent of what

boreal pier
#

number of sales

final hatch
#

oh i see

boreal pier
#

yea

#

so you can say that:

final hatch
#

i thought that was the number of tickets sold

boreal pier
#

i see

#

but, now we can say that

#

0.2 * x = 30

#

where x is the total number of sales

#

make sense?

final hatch
#

yeah i understand now that i saw it was the percent of sales 💀

boreal pier
#

yea

#

so solve for x

#

to find the # of sales

final hatch
#

well the answer was already there in answer key

#

its just that i didn't know how that got there

#

until now

boreal pier
#

i see

#

so do u understand now

final hatch
#

yes

#

.close

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craggy quiver
devout snowBOT
craggy quiver
#

how do you go from the top line to the bottom line

#

the question is

supple knot
craggy quiver
#

full qustion

#

full solution

supple knot
#

(a^2) ^ (-3/2) = a^(-3)

devout snowBOT
#

@craggy quiver Has your question been resolved?

craggy quiver
#

oh i just clocked

#

thank

#

s

#

.close

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restive river
#

Does anyone know how to get from step 2 to 3 in this projection explanation? From Linear Algebra.

devout snowBOT
#

@restive river Has your question been resolved?

devout snowBOT
#

@restive river Has your question been resolved?

restive river
#

<@&286206848099549185>

restive river
#

<@&286206848099549185>

#

I dont understand where the transpose operation comes from

devout snowBOT
#

@restive river Has your question been resolved?

ancient trail
#

@restive river I'm typing up a response

restive river
#

thank you

#

I found another proof for the situation that involves angles, but I dont understand this method

ancient trail
#

ping me if u have questions

restive river
#

thank you for the help, especially step 2 clarified a lot

#

.close

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flint snow
#

Can someone turn this into a table model

devout snowBOT
flint snow