help-27

[rapid jewel]

wait is it cuz when differentiating w/ respect to x, everything that doesn’t have x=0

[restive river]

differentiating a constant, 'a' with respect to any variable gives 0

[restive river]

yes.

[rapid jewel]

oh okay

[restive river]

but more importantly that 'a' is a constant

[rapid jewel]

okay i think i get it now, thanks!

.close

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[restive river]

Pls anyone help me get an answer and explain how you get it.

[restive river]

@restive river

[pastel pasture]

!nosols

[devout snow]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[restive river]

TQ @restive river

[restive river]

its literally a detailed explanation.

but okay i get your point

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[restive river]

Yes

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[proper violet]

3

[rich summit]

Since it says that there are fast cars that aren't red, some fast cars are a different colour from red

[soft raven]

What exactly do you need help with

[hybrid snow]

The existence of non-red fast cars does not imply the nonexistence of red fast cars

For example if I said that there are fast runners that are not 6 feet or above tall

That doesn't imply that there are no fast runners that are 6 feet or above; that would be silly

[devout snow]

@proper violet Has your question been resolved?

[proper violet]

so the c is telling that there are no red cars

@hybrid snow

[hybrid snow]

It's saying that all fast cars are not red which implies that all red cars are not fast

I like to treat logic problems like reading comprehension for an SAT test

[devout snow]

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[young crane]

Anyone know how to solve c

[devout snow]

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@young crane Has your question been resolved?

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[tacit crow]

Hi can someone help me pls

[silk hill]

Do you know how find the equation of line given two points

[tacit crow]

y-y1=m(x-x1)

Ohh wait I’ve got it now

I realised I forgot to substitute the y value into the equation

.close

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[winged imp]

can someone help me Solve for Vi

[devout snow]

Please don't occupy multiple help channels.

[winged imp]

<@&286206848099549185> Please i really need help

[loud mirage]

@winged imp Hi! what you need. What does Vf and Vi mean in your studies?

[winged imp]

yah

Can you help me how Should i start with first step?

[sage burrow]

Answering questions would be a good start: "What does Vf and Vi mean in your studies?"

[winged imp]

Idk i just started sorry

[sage burrow]

a little bit context would be fine. just dropping a formula makes it really impossible to help (for me). maybe someone else understand what you need.

[winged imp]

should i try?

?

Nvm maybe i got it

.close

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[lethal iris]

Can anyone help me with this question??

[lethal iris]

p value?

[devout snow]

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[lethal iris]

<@&286206848099549185>

[wooden zodiac]

no

#❓how-to-get-help

[devout snow]

@lethal iris Has your question been resolved?

[lethal iris]

<@&286206848099549185>

[wooden zodiac]

...............

Someone close this channel

[sage burrow]

why? elaina has asked something, the channel was closed by timeout and she has reopened it (without using the reopen command).

[sage burrow]

and this was the question.

[wooden zodiac]

ohh didnt see

[devout snow]

@lethal iris Has your question been resolved?

[hybrid snow]

You didn't even post a fucking question

Are you trolling or?

[sage burrow]

@hybrid snow read this.

[hybrid snow]

Ngl I'd just repost it

[sage burrow]

yes, would have been better, of course.

[devout snow]

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[restive river]

hm...

[devout snow]

@drowsy jewel Has your question been resolved?

[drowsy jewel]

<@&286206848099549185>

[devout snow]

@drowsy jewel Has your question been resolved?

[devout snow]

@drowsy jewel Has your question been resolved?

[valid galleon]

is this a test?

[devout snow]

@drowsy jewel Has your question been resolved?

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[viscid dove]

Anyone free to help me solve this?

[west palm]

what to find

[jagged kestrel]

constant a presumably
such that the system is consistent

[proper rampart]

system of equations

with 3 variables

[west palm]

just find it

or should use matrix

[devout snow]

@viscid dove Has your question been resolved?

[viscid dove]

Yes

.close

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[vital flicker]

Can someone help me with a math lesson i dont understand?

[main relic]

sure

send it out

[vital flicker]

Equations reduced to Quadratic Equation, im 9th grade btw

[main relic]

ok sure

what are you struggling with?

[vital flicker]

Almost everything with it... can you like explain almost everything? if its okay

[main relic]

i need a lil bit more specific stuff

[vital flicker]

how does this help forum work? via chat?

[main relic]

yes just ask away here

[vital flicker]

okay wait

[main relic]

when you're done just type ".close" to close the channel

[vital flicker]

x-6√x + 8 = 0, for example

[main relic]

do you know how regular quadratic equations work?

like x^2 - 2x + 1 = 0

[vital flicker]

yeah, i know how to solve for roots on regural quadratic equations

[main relic]

nice, so this is exactly the same, except the "x" is now "sqrt(x)"

i dont know how to type in latex

$sqrt(x)$

crap

$root(x)$

ok forget about it

[main relic]

do you see this

(√x)^2 - 6(√x) + 8 = 0

[vital flicker]

in my school book, it says i need to substitute x for p^2

[main relic]

it's the same idea

[winter patrol]

\sqrt{stuff}

[main relic]

nice thanks

[main relic]

btw how about fractions

[winter patrol]

\frac{numerator}{denom}

[main relic]

$(\sqrt{x})^2-6(\sqrt{x})+8=0$

[woven radish]

candies

[main relic]

perfect

[vital flicker]

ahh i see, can i ask about another lesson?

[main relic]

sure

[vital flicker]

Its word problems involving quadratic equation, for example, "The sum of two numbers is 7 and the product is -60. What are the numbers?

Where do i start with that problem?

[main relic]

wanna set the 2 numbers as x and y?

yes you do want to

[main relic]

ok so now you have x and y try changing this to 2 algebraic equations

[vital flicker]

okay, but im not sure how...

[main relic]

ok its ok

so firstly

the sum of the two numbers is 7

that means $x+y=7$

[woven radish]

candies

[vital flicker]

okay

[main relic]

can you try to change "the product is -60" into a algebraic equation?

[vital flicker]

should i change it into a quadratic equation?

[main relic]

no

just an equation is fine

[vital flicker]

hmmm..

i dont know

[main relic]

alright

so their product is -60

therefore $xy=-60$

[woven radish]

candies

[vital flicker]

ahhhh okay

[main relic]

now, lets switch this up such that x is the subjec t

do you know how?

making x the subject means x is by itself on the left side and everything else is on the right side

[vital flicker]

so your gonna put y on the right side?

[main relic]

yes

so what did you get

[vital flicker]

x = -60/y
???

[main relic]

now im referring to the other equation

[main relic]

this one

the one that goes x+y=7

[vital flicker]

x =7y

or x=7/y

[main relic]

?

check twice

$x+y=7$

[woven radish]

candies

[vital flicker]

x = 7 - y

[main relic]

nice perfect

now you know whenever you see a x, you can change that to (7-y) cuz theyre the same thing

[main relic]

theres a x here, try changing that to 7-y

thats where the quadratic lies

[vital flicker]

y = 7 - x?

[main relic]

no, as in, subsitiute x = 7-y inside xy = -60

change the x in xy = -60 to 7-y

(because x=7-y)

[vital flicker]

i dont know, can you teach me?

[main relic]

ok sure

so we can change xy = -60 to

$(7-y)y=60$

[woven radish]

candies

[main relic]

because of this

now just expand the expression, and solve it like a normal quadratic

[vital flicker]

ahh i see

Thanks a lot! i learned a lot!

can you give me an example so i can solve by myself?

.close

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[molten crater]

Hey, can anyone talk me through this question as I don’t understand

[silk hill]

Have you learnt similarity of triangles

[devout snow]

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@molten crater Has your question been resolved?

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[mighty edge]

How do I show that if the upper and lower integrals are the same, then it is the unique number between the lower and upper sums

[wicked turtle]

what is "it"

[mighty edge]

the upper/lower integral

[candid viper]

it should be 0

[west palm]

yes

[mighty edge]

how do you show the integrals are 0?

[wicked turtle]

every lower sum is <= the lower integral, yes?

and every upper sum is >= the upper integral

[mighty edge]

yea

[wicked turtle]

so if the upper and lower integrals are the same, say equal to some number C, then those two inequalities mean that
every lower sum <= C <= every upper sum

agree?

[mighty edge]

yep

[wicked turtle]

and there can't be some other number D with this property, because if D is larger than C, then there's some upper sum smaller than D

by definition of the upper integral

and similarly D can't be less than C

it really just comes down to the definitions of upper and lower integral...

[mighty edge]

ohhhh okok

i was thinking abt that but i couldnt actually state it

its too late for me rn

[wicked turtle]

nw

you'll still want to make it more formal than what i wrote

but that's a sketch

[mighty edge]

yea thats all i need tysm

.close

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[lapis crescent]

I found the general term then I got stuck

[silk hill]

Can you send your working

[west palm]

use binomial

[lapis crescent]

do I expand until there is 2 same coefficients

[silk hill]

expand the next term Tr+2 which will give you 19C r+1(2)^18-r*(3x)^r+1
and then equate the coeffcients

[devout snow]

@lapis crescent Has your question been resolved?

[lapis crescent]

thank you

[devout snow]

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[winged cedar]

When being given descriptions of normal distributions like so:

X~N(Mu,Sigma^2)

am i supposed to always just use sigma to make my normal pdf and cdf calculations, instead of sigma^2?

[winged cedar]

.close

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[tight ridge]

I need help with problem 6d in order to further simplify it

[devout snow]

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[gilded ether]

Im stuck here i dont know what to do next

[gilded ether]

I am factoring

[main gull]

Factor v^2 - 4

Difference of squares

[gilded ether]

How do i factor them

[main gull]

I told you how

Difference of squares

[gilded ether]

I dont know how to do that

[main gull]

You should look it up as it is a very common form of a quadratic

[devout snow]

@gilded ether Has your question been resolved?

[fallow pendant]

which book should I buy for IOQM that teaches concepts from the scratch?

[devout snow]

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[proper violet]

Calculate the value of the current intensity I flowing in a conductor where the drift velocity of the charge carriers (electrons) is vd =2∙10^-4 m/s and the circular section is S=5 mm^2. [Assume that the carrier density is equal to n = 5∙10^28 m^-3 ].

(a) I=2A
(b) I=16A
(c) I=8A
(d) I=0.8A
(e) I=0.08A

[jaunty mantle]

@proper violet it’s right here

[devout snow]

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[proper violet]

.close

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[leaden peak]

A ship has a speed in calm waters of 65 km h−1 and it’s travelling on a
bearing of 300◦
The wind is blowing at a speed of 10 km h−1 from thesouth-east.
Take unit vectors i to point east and j to point north. Express the original velocity b of the ship relative to the water and the
velocity w of the wind in component form, giving the numerical values
in km h−1 to two decimal places.

[devout snow]

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[devout snow]

Please don't occupy multiple help channels.

[jaunty mantle]

.close

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[proper violet]

An ideal gas slowly increases its volume by 3 m3 from its initial value, while being held at a constant pressure of 200 kPa. During the transformation it absorbs a heat equal to 300 kJ, what is its final internal energy, if the initial one was equal to 900 kJ?

(a) 600kJ
(b) 300kJ
(c) 1500kJ
(d) 900kJ
(e) 1200kJ

[topaz axle]

i would say it's 1200 and the other numebrs don't matter

ok that's wrong

[proper violet]

the answer says a

I wonder how this can be solved

[topaz axle]

you subtract work done by the expansion from the input heat

work is PΔV

[proper violet]

do you mean absorbed heat by expansion

[proper violet]

okay p is constant so

600 kpa

*m^3

then..

300- 600 = -300

[topaz axle]

so 300 − 600 is −300

900 − 300 = 600

[proper violet]

initial internal + internal ?

[topaz axle]

much confusion with all the signs

clearly you;re just doing initial + heat − work

[proper violet]

is there like some other way to solve without formulas

[topaz axle]

it's like, you have a syringe with gas under pressure, and you pull it. The gas does work, helping you pull, it loses that much energy, and the heat adds to it

clearly pressure × volume is work, because (pressure × area) × length is force × distance

so i don't think there's a simple way, the formulas are pretty simple already

[devout snow]

@proper violet Has your question been resolved?

[devout snow]

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[lapis granite]

hello

[gusty sparrow]

,tex .original

[woven radish]

Talent Unlimited

[naive estuary]

hi

[lapis granite]

I need some help on this question

@naive estuary

please

[main gull]

Post a screenshot or picture

No one is going to download an image off a server on the internet

[naive estuary]

hmmm how to turn off the auto download?

[lapis granite]

sorry for sending it as a image to download

i have now sent it as a screenshot

[naive estuary]

sin3x/sinx = 2 cos2x +1

cos3x/cosx = 2 cos2x -1

= 8 cos^2 x -4

@lapis granite

[lapis granite]

is that the solution

@naive estuary

[naive estuary]

yeah

[lapis granite]

Its that simple

[naive estuary]

yes

[lapis granite]

can you help me on this question too please

[naive estuary]

sure

[lapis granite]

@naive estuary

sorry for the ping are you still there

[naive estuary]

///i hate proving trigonometry... gimme a sec

[naive estuary]

cotx - tanx = (cos^2 x - sin^2 x)/(sinx cosx)
= cos2x / (sinx cosx) = 2 cos2x/sin2x = 2 cot(2x)

[lapis granite]

hey (ᗜ ˰ ᗜ) I was wondering, it seems that you have gave me a pretty brief solution to these questions

Is there any more steps that will help me understand better for the two questions I have requested from you

@naive estuary

if possible

@naive estuary are you still there

[devout snow]

@lapis granite Has your question been resolved?

[lapis granite]

@naive estuary

.close

[devout snow]

Channel closed

Closed by @lapis granite

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[shut drum]

Help

[shut drum]

Heloo

Hello

[orchid glade]

hi

!status

[devout snow]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[shut drum]

?

[shut drum]

?

.1

[orchid glade]

so u al least have a basic understanding of rates

[shut drum]

Yea

[orchid glade]

like loss or profit amount from rate and principal

[shut drum]

Yea

[orchid glade]

ok

so our shop keeper wants to have a tag price

suppose it reads Rx

[shut drum]

Y ea

Huh

Rx

Oh

[orchid glade]

R x

[shut drum]

Yeah

[orchid glade]

rand x

[shut drum]

Oh ok

Ok

Yea

[orchid glade]

now he gives the customer a discount of

20%

[shut drum]

20%

So 48

[orchid glade]

at how much he sells?

[shut drum]

R

[orchid glade]

no

[shut drum]

but why

A discount of 20%

[orchid glade]

20% discount from marked price that is x

[shut drum]

Ok

[orchid glade]

not from what he bought

[shut drum]

What's a marked price?

[orchid glade]

if he sells for 48 he;d make loss

[shut drum]

Yea

[orchid glade]

we want a profit even after we give out a discount

how confindent are u in lagebra

algebra

[shut drum]

but discount means to make it cheaper

7/10

[orchid glade]

yes it does

suppose the marked price is

x

[shut drum]

And it's says 20% discount

Ok

[orchid glade]

now if u give 2

0% off

in how much u sel

[shut drum]

Yea

Yea

[orchid glade]

x-20% of x

that is 100x/100 -20x/100

=80x/100

or 0.8x

[shut drum]

Yes

[orchid glade]

u kept. a marked price of x

but how u are gonna sell for 0.8 r

ok?

but even after selling at this price you want a profit of 20%

@shut drum

[shut drum]

Yes

[orchid glade]

what price u need to sell for that

u bought it at R60

[shut drum]

96

Yes

[orchid glade]

of so 0.8x had to be equal to how much

[shut drum]

48

[orchid glade]

huh?

listen to me for. asec and dont forget to think

[shut drum]

Ok

[orchid glade]

after discount of 20% u dicided to sell at 0.8x

[shut drum]

What do you mean 0,8

[orchid glade]

x could be anything

[shut drum]

Ok

[orchid glade]

8/10=0.8

8 divided by 10

[shut drum]

No

Oh

0.8

[orchid glade]

ofc

[orchid glade]

so u want a profit of 20%

anyhow

at what price will you have to sell to get that

[shut drum]

20% of 60 = 12

72

[orchid glade]

correct

so you have told your customer that ypu will sell for 8/10 * marked price

and you want to sell for

72*

how much should the marked price be?

in other words

[shut drum]

Why 8/10

[orchid glade]

0.8x=72

since x is the marked price

when u sell at 0.8x

[shut drum]

Ohh

90

[orchid glade]

the customer thinks he's getting a 20% discount

poor fellow

[shut drum]

Is 90 correct

?

[orchid glade]

it is

[shut drum]

Can you help me with another question

[orchid glade]

[orchid glade]

ok whats the formula for speed

[shut drum]

I learnt this yesterday

Wait let me think

D/t

[orchid glade]

nice

[shut drum]

What do I do with that

[orchid glade]

but doubt its useful here

[shut drum]

Oi

[orchid glade]

do u get what the question says

coz i have 0 idea

[shut drum]

Wut

[orchid glade]

never even seen an elevator in my life

[shut drum]

What grade r u in

[orchid glade]

u?

[shut drum]

You've never seen an escalator in your life

8

[orchid glade]

well there arent any around this part of the world

i could help if i understood the question that is

[shut drum]

https://tenor.com/view/escalator-plank-gif-11413618

This

[orchid glade]

cool

ok ok

i got it

imagine instead of a "escalator"

a conveyer be;t

belt

they essentially do the sam ething

move at a constant rate

@shut drum

[shut drum]

Ya

[orchid glade]

bruh i keep on thinking u left teh caht

ok

u walk with a constant speed x

[shut drum]

Ya

[orchid glade]

and the conveyer does so with its own constant speed y

in one case the net speed is x-y

[shut drum]

What is a net speed

[orchid glade]

while in the other case the net speed is x+y

well its like how much is the actual speed

u move with spped x

[shut drum]

Ok

[orchid glade]

but if the belt moves in the opposite direction with speed y

[shut drum]

Ya

[orchid glade]

there an actual speed of x-y'which we call the net speed

[shut drum]

Ok

[orchid glade]

so u have the times for these two cases as well

and a distance constant d to be covered in each case

s=d/t

x+y=d/36

x-y=d/72

[shut drum]

Ya

[orchid glade]

add those two together

[shut drum]

108

[orchid glade]

y cancels out

[shut drum]

108

[orchid glade]

u are left with 2x = d/36+d/72

[shut drum]

Ok

2d/108

[orchid glade]

ok now

[shut drum]

d/72

[orchid glade]

ok how abt this

dont add rn

take the first equation in terms of d

then replace d in the other equation

work it out and send a photo

[shut drum]

I'm confused

[orchid glade]

ur a 8th grader comeon

express in terms of d

then substitute

[shut drum]

Wdym

[orchid glade]

im in no mood to write it out its midnight

[orchid glade]

well the answer is 54

[shut drum]

Wrong

[orchid glade]

i got no clue how to help u so

[shut drum]

I have the memo

[orchid glade]

ping a helper

[shut drum]

.close

[orchid glade]

might be'

[devout snow]

Channel closed

Closed by @shut drum

Use .reopen if this was a mistake.

[orchid glade]

im clueless

[devout snow]

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[severe zenith]

Exercise 2: (7.5 marks)
Consider the figure opposite with
IJ = 6.8cm
JH = 3.2cm
HK=2.4cm and JK=4cm.

1. Show that the lines (IK) and (JH) are perpendicular.

[severe zenith]

I want help to figure out how do I find out if something is perpendicular?

There’s also 2 questions later but I wanna figure this out first

[devout snow]

@severe zenith Has your question been resolved?

[devout snow]

@severe zenith Has your question been resolved?

[rough tapir]

you can show that those two lines are perpendicular by proving that the pythagorean theorem holds true for atleast one of the smaller triangles pictured

the only triangle you have all 3 lengths for is JHK, so you'll need to use that one

@severe zenith

[severe zenith]

Oh alright that makes sense, thank you

If you’re on can I show you the other two questions?

For 2 they want me to show how IH = 6

Nvm I found out they

They

Thatt

.close

[devout snow]

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[tawdry burrow]

uh

[tawdry burrow]

i have no idea what to do, tmrw is my algebra EOC 9th grade

and i have used brainly for this whole year

any tips

[supple knot]

ask #discussion

help channels are for specific problems

[tawdry burrow]

i dont have access

[arctic field]

,iamnot dying

[woven radish]

No roles to add or remove, nothing to do.

May 8, 2023, 9:11 PM

[arctic field]

^ do this

[restive river]

.iamnot dying

,iamnot dying

[woven radish]

You don't have the selfroles studying!, do you want to add them? (y(es)/n(o))
(Tip: use ,iam to add roles without this prompt.)

Session timed out waiting for user response.

May 8, 2023, 9:16 PM

[devout snow]

@tawdry burrow Has your question been resolved?

[devout snow]

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[keen thunder]

.

[devout snow]

Channel closed

Closed due to the original message being deleted

[jolly swan]

.close

[devout snow]

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[digital egret]

can someone explain why its negative

[supple knot]

https://www.khanacademy.org/test-prep/mcat/physical-processes/work-and-energy-mcat/a/work-can-be-negative

[devout snow]

@digital egret Has your question been resolved?

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[modest helm]

.close

[devout snow]

Channel closed

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[patent marsh]

did you figure it out?

[modest helm]

yes

[patent marsh]

coolio

[devout snow]

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[dim shadow]

How 2 pronounce

[dim shadow]

Anyone know how to pronounce an integral sign in a word

[pseudo basin]

you don't

it's definitely something you should ask whoever came up with this (frankly ridiculous) name

[dim shadow]

Unfortunately got no clue who dod that

[pseudo basin]

we can't help you either then

[devout snow]

@dim shadow Has your question been resolved?

[devout snow]

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[warped ore]

(x^2/49)+(y^2/19)=1

[warped ore]

How do I graph this, finding the center and vertices/ellipses?

[long pasture]

usually i would
sub x=0 for y-intercept
sub y=0 for x-intercept

and
(x-h)²/a²+(y-k)²/b²=1
(h,k) will be the center

[devout snow]

@warped ore Has your question been resolved?

[warped ore]

gotchya ill try that and some other things

[devout snow]

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[warped ore]

How do I go about graphing 25x^2 - 9y^2 = 255?

[west palm]

you mean sketch the graph or what?

[warped ore]

well

yeah but ya gotta find the vertices and focal points n stuff first

Dunno how

[west palm]

well

find x and y intercept first

[warped ore]

naw it aint like that lol

[west palm]

what do you mean

[warped ore]

I dont think

[west palm]

for me i usually find x and y intercept first

[warped ore]

like the other one's formula was ((x-h^2)/a^2)+(y-k^2/b^2)

to find a ellipses

[west palm]

then first and second derivatives

[graceful cosmos]

Can think of it in terms of graph transformations. Rewrite as:
(5x)² - (3y)² = 255
Which is a hyperbola that is compressed by 1/5 in terms of x, by 1/3 in terms of y

[warped ore]

well I got y^2 = (25x^2 - 255)/9

its a conic section

[lament cradle]

hyperbola is a conic section, Kaynex is 100% right here.

[warped ore]

gotchya so I got (5x)² - (3y)² = 255 then, what now?

and a section as in its just one part of it?

[lament cradle]

its a plane passing through it

[warped ore]

thas coo

[lament cradle]

the 2d curves are the intersections.

[warped ore]

Gotchya

So, I'm there so far but what now lol

[lament cradle]

you have to manipulate the equation into standard form

$\frac{\left(x-h\right)^{2}}{a^{2}}-\frac{\left(y-v\right)^{2}}{b^{2}}=1$

[woven radish]

b0ngl0rd

[warped ore]

ahah aight one sec then

oh wait thats my question tho

a^2 and b^2, I only know of one number for the denominator

i'd assume its 9, but what is it 1.5-1.5?

[devout snow]

@warped ore Has your question been resolved?

[devout snow]

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[restive river]

How can I determine whether this converges?

[restive river]

$\displaystyle\sum\limits_{n=1}^{+\infty} \dfrac{n+\sqrt{n}}{n^3+n}$

[woven radish]

CWolf

[graceful cosmos]

It's "kind of like" Σ n/n³, which converges

You can make that rigorous with the limit comparison test

Compare it with 1/n²

[restive river]

Okay that puts me in the right direction thanks 😄

.close

[devout snow]

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[devout snow]

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[primal tusk]

so

i want to simpify that

however instead of + i want to simply it as a multiplication

(2g/3h)x(5/2h)

everything i look up to do it show it differently

so im just double checking the correct way to do it

[stark anvil]

$\frac{5G}{3h^2}$

[woven radish]

ColdTee

[devout snow]

@primal tusk Has your question been resolved?

[primal tusk]

completly forgot about this question lol

how does it become 3h^2?

[kind void]

$\frac{2G}{3h} \times \frac{5}{2h}$ ?

[woven radish]

totalminer

[kind void]

For fractions you can just multiply everything, example $\frac{2}{3} \times \frac{4}{5} = \frac{2 \times 4}{3 \times 5} = \frac{8}{15}$

[woven radish]

totalminer

[kind void]

@primal tusk Does this answer your question?

[primal tusk]

eh

kinda

how did it bevome 3h^2

[primal tusk]

that shows something completly different than

[stark anvil]

It's either that or $\frac{10G}{6h^2}$

[woven radish]

ColdTee

[stark anvil]

$\frac{5 \times 2G}{3h \times 2h}$

[woven radish]

ColdTee

[primal tusk]

yea that makes much more sense

ok thats p simple

ty

.close

[devout snow]

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[devout snow]

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[minor basalt]

how do they get that?

[minor basalt]

theres this lemma, but they havent even used it there?

i keep getting 0

[devout snow]

@minor basalt Has your question been resolved?

[minor basalt]

.close

[devout snow]

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[foggy geyser]

idk where to start

[valid galleon]

start with the triangle on the outer side

get the other angle

[foggy geyser]

the one that has #1 at the top?

[valid galleon]

u know what screw what I said

[foggy geyser]

oh

[valid galleon]

u know the cyclic quadrilateral rules

?

[foggy geyser]

uh

probablt not

[valid galleon]

it basically says

any quadrilateral inscribed

in a circle

the opposite angles of the quadrilateral is equal to 180

[foggy geyser]

omg

[valid galleon]

so

u have 50 and 100

use the linear pair

[foggy geyser]

would it be 80

[valid galleon]

..

[foggy geyser]

oh

[valid galleon]

ok yea

the whole thing?

or the angle u found?

[foggy geyser]

oh wait wait

would it b 30

like the small space

[valid galleon]

yea

anyway 50 +30 is 80

so let the first angle be a variable

equate it now

tell me if u got an answer

hold up

there's two angles?

on the top?

does angle no 1 take the whole thing

[foggy geyser]

i think 1 is only the left side

[valid galleon]

hmmm

[foggy geyser]

wait 1 + the unnamed is 90 right cos its connected to a semicircle rigjt

[valid galleon]

which one

[foggy geyser]

the

hold on

[valid galleon]

HOLD UP I GOT IT

[foggy geyser]

OKAY!!

[valid galleon]

ok did u equate the two angles

what was top most angles

[foggy geyser]

i dont understand what that means

[valid galleon]

the

like

u found the bottom angle as 80 right

[foggy geyser]

yes..

i think

[valid galleon]

I told you that opposite angles of a quadrilateral inscribed in a circle is 180 degs

[foggy geyser]

yes

[valid galleon]

so what is the top most angle of the quadrilateral

[foggy geyser]

ok so

[valid galleon]

are u stuck?

[foggy geyser]

yeah..

[valid galleon]

I told you this rule right

so basically

[foggy geyser]

is it 90

[valid galleon]

take the top most angle as x

[valid galleon]

nope

x + 80 = 180

u understood?

x = 100

that our top most angle

[foggy geyser]

ok wait just making sure u mean this angle

[valid galleon]

yes

the entire thing is 100

degs

[foggy geyser]

okay

[valid galleon]

did u understand?

how its 100

[foggy geyser]

WAITR

I UNDERSTAND

[foggy geyser]

I UNDERSTAND THIS

[valid galleon]

good

now

see the triangle on the outer side

and the triangle of the right hand side of the quadrilateral

join them

u see

130 and 35 degs

equate them to find the smaller angle

of the top most thing

and subtract 100 from the smaller angle

that is your first angle

[foggy geyser]

wait wiat

ur talkong abo it finding this angle the one with the question mark

?

lh wist

wait

[valid galleon]

no

[foggy geyser]

no thay doesnt make sense

nvm i know what youre talking about

[valid galleon]

the smaller angle of the top most

[foggy geyser]

yes okay

[valid galleon]

angle of the quadr

[foggy geyser]

YES OKAY WIAT

[valid galleon]

there's a joined tri

[foggy geyser]

ok so

[valid galleon]

gtg

dm me

I say later

[foggy geyser]

130 + 35 = 165 and then 180-165 = the unknown angle?

and then 100 - 15

so 1 = 85

and 2 = 15 because 15 and 2 have the same arc

[devout snow]

@foggy geyser Has your question been resolved?

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[pure vessel]

hi

[devout snow]

Please don't occupy multiple help channels.

[pure vessel]

if 3sinx - 4sin power 3 x -k = 0 such that 0<k<1
what is the value of x
can i neglect k since its too small to affect the angle x

[pastel pasture]

This is math not physics

In any case does $3\sin x - 4\sin^3 x$ look familiar

[woven radish]

NEONPerseus

[pure vessel]

sin 3 x

[twin wedge]

t = sinx

-1<=t<=1

?

wdym x

[polar chasm]

solving depressed cubic is hard

[twin wedge]

huh?

-4t³+3t

[polar chasm]

-k=0

solve this in terms of t

[twin wedge]

nonono

-4t³+3t = k

draw -4t³+3t

[polar chasm]

huh, okay

[twin wedge]

now use -1<=t<=1

[polar chasm]

With this, sin(3x)-k=0

[twin wedge]

and find if it intersects

[polar chasm]

Using what method?

[pure vessel]

but with such small value of x will there be any effect on angle x

[polar chasm]

Yes, there will be huge effect

[pure vessel]

ohh

[polar chasm]

https://www.desmos.com/calculator/7c7g72mcmo

check the roots

[pure vessel]

thnx

[polar chasm]

In this case substituting would work, but it would be painful work. To find the intersection, you would have to use formula for depressed cubics. Which is like quadratic formula on steroids.

Lots of painful work, modifying it to sin(3x)-k=0 is much easier

[twin wedge]

no its not

-4t³+3t=k

now you can draw -4t³+3t

[polar chasm]

wdym by draw

[twin wedge]

find the minima and maxima

[pastel pasture]

So now you have $\sin 3x = k$

[woven radish]

NEONPerseus

[pastel pasture]

Do you know the general solution for $\sin \theta = \sin \phi$

[woven radish]

NEONPerseus

[pure vessel]

Buy wait

[polar chasm]

||I guess you arent aware of the fact that there are infinitely many solutions that vary depending on value of k. I guess that helpee wants general solution for x given k||

[pure vessel]

I am in Grade 11 basics...And i haven't been taught that 3sin x -4sin³x = sin3x

Can u solve this then ?

Or is it mandatory for u to know the identity for this question

[polar chasm]

Can you show us the original question?

[pure vessel]

Yeah sure

[pastel pasture]

Were you explicitly disallowed from using formulae that you aren't taught?

[pure vessel]

Nope but what if I didn't know the formula which was the case for me coz of which i didn't get the answer

[pastel pasture]

Then we suffer in silence

[pure vessel]

There are multiple ways of solving can we solve it without using that identity

[polar chasm]

Are you solving for x in terms of k?

[pastel pasture]

Maybe some long drawn out process of completing the cube

[polar chasm]

yeah, it's just depressed cubic. But still it seems like too much pain for 11th grade

[pastel pasture]

Cubics are too much pain for anyone over the age of 0 tbh unless it was designed with one integral root

[pure vessel]

It will either be A and D or B and C right

Obviously the sum of angles shld be π

[pastel pasture]

If I was you I'd put k = 1/2 or something

The values are independent of k, so there's really no point of it existing

[pure vessel]

That's y i said that i neglected k

Coz the equation is independent of k

[pastel pasture]

You can't neglect k, since it lies between 1 and 0

Neglecting it would be k = 0

[pure vessel]

Then id get sin 3 x = k

[pastel pasture]

Yes

[pure vessel]

After that wht do i do

[pastel pasture]

And you know x can either be A or B

[pure vessel]

Yeah

[twin wedge]

0<k<1

[pure vessel]

Right

[twin wedge]

if i set f(t) = -4t³+3t

f(-1) = 1

[pastel pasture]

Can you tell me the range of the angles of a triangle? @pure vessel

[twin wedge]

and you know 0<k<1

[pure vessel]

A particular angle of a triangle right

[pastel pasture]

I mean, between what values can the angle of a triangle lie

[pure vessel]

Ok

[pastel pasture]

It was a question

[pure vessel]

Is it 0<sin theta<1

[pastel pasture]

The angles of a triangle?

[pure vessel]

Haven't read about it yet...im in Grade 11 and we haven't read about range of angles

Yet

[pastel pasture]

Do you know about obtuse angled triangle, right triangles, and stuff?

[pure vessel]

That's fine

But the range depends on the type of triangle given

If it's right or obtuse or acute

[pastel pasture]

Yeah, think about the widest triangle possible, what would it's largest angle be?

[pure vessel]

178° + 1° + 1° if in integers

It can be 179.999° ?

[pastel pasture]

Are you familiar with interval notation?

[pure vessel]

Nope

[pastel pasture]

(0, 1]

Stuff like this?

[pure vessel]

Yeah

Close and open intervals

[pastel pasture]

So it would be (0°, 180°) right?

[pure vessel]

Yeahh

Oh that's wat u were asking

[pastel pasture]

Yeah I'm sorry if it was unclear

[pure vessel]

Correct

It's fine

[pastel pasture]

So can you tell me what would the range of sin x be for x in (0, π)

[pure vessel]

It would be 0

Sin 0 = 0

Sin π = 0 as well

[pastel pasture]

You would get a range of values

what is sin π/2

[pure vessel]

1

Oh

[pastel pasture]

So what would the range of sin x be?

[pure vessel]

Now I get it

[pastel pasture]

I hope you're familiar with trigonometry outside the first quadrant

[pure vessel]

Yeah

The ASTC rule

[pastel pasture]

Yes

[pure vessel]

Yeap

[pastel pasture]

Now sin 3x lies between 0 and 1 in our question

Correct?

[pure vessel]

Yes

Coz it's equal to K

[pastel pasture]

Precisely

[pure vessel]

And 0<k<1

Right

[pastel pasture]

So where would 3x vary from

[pure vessel]

0 to π/2

?

[pastel pasture]

There's also the second quadrant

[pastel pasture]

.

[pure vessel]

To π

[pastel pasture]

Perfect

[pure vessel]

Ok

[pastel pasture]

So 3x is in (0, π)

[pure vessel]

Yess

[pastel pasture]

What would the range of x be?

[pure vessel]

0 to π/3 ?

[pastel pasture]

Excellent

Now x is either A, or B

Do you think you can figure out what options are correct now?

[pure vessel]

Yess

Ohh