#help-27

1 messages · Page 83 of 1

quaint ice
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After graphing it is very clear

dark dawn
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seems a bit overpowered

quaint ice
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Definitely generous given its functions

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Thanks for the help

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potent marlin
#

Hey i need help with this

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potent marlin
#

How did we get x=0 and x= 4/3

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This is from a yt video but she didnt explain it just wrote it

lofty niche
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we have -3x^2+4x=0. firstly we factor out -x. this means that just one of the factors needs to be zero (see zero-product property). this means either -x=0 or 3x-4=0. therefore x=0 or x=4/3

potent marlin
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Ohh we just solve it

lofty niche
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yeah they are just solving h'(x)=0

potent marlin
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Ok thx

muted lintel
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can anyone help

potent marlin
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"Watch video"

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Haha jk

muted lintel
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i triedd

potent marlin
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Bcaed

muted lintel
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it’s says it wrong

potent marlin
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This isnt even preschool lol

muted lintel
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I’m british

potent marlin
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Well than i dont know the answe sorry

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Or email your prof

muted lintel
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its okk

lofty niche
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# potent marlin Bcaed

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

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sturdy mirage
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sturdy mirage
#

This is the question I'm on.

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The video explanation says that I can rewrite the two (1-lambdas) as (lambda+1) and (2-lambda), but I'm not entirely sure how he reached that conclusion.

restive river
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factor out -1 from (1-lambda)

sturdy mirage
restive river
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they factored (1-lambda)^2 -4

sturdy mirage
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Where did the -4 come from?

restive river
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expand both lines

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you will see that they are equal

sturdy mirage
restive river
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oh wait I missed that

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hold up

sturdy mirage
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How is it a typo?

restive river
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it should be 4(0 - (2-lambda))

sturdy mirage
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Ah

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Yeah that makes sense

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The person that does these videos is not very good at them.

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They just kind of assume you know every single thing they are talking about and don't actually explain what they're doing.

restive river
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hm, that sucks ig

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maybe you could try khan academy for examples

sturdy mirage
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I have had to

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So if I was to apply that to my actual question

sturdy mirage
restive river
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,w char poly [[3,11,16],[0,4,0],[1,1,3]]

restive river
sturdy mirage
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And then I expand, add the others, then synthetic division

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?

restive river
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that works

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or you could factor out (4-lambda) and get the roots by factoring

sturdy mirage
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Fair enough

sturdy mirage
restive river
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it shouldn't

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,w eigenvalues [[3,11,16],[0,4,0],[1,1,3]]

sturdy mirage
restive river
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(lambda - 4) = -(4-lambda)

sturdy mirage
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Ah.

sturdy mirage
# restive river

It also said I need to use the Gauss Jordan elimination method, which just looks like matrices stuff?

restive river
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yeah, use row operations

sturdy mirage
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So I need to get it to 1 0 0, 0 1 0, 0 0 1?

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Am I allowed to have fractions?

restive river
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for what?

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what matrix are you working on now?

sturdy mirage
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The first eigenvalue

restive river
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so you want to find the kernel of A-lambda I

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fractions are fine, but can get messy

restive river
sturdy mirage
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Do I do row operations until I only have 1s?

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Or until the bottom row is 0?

restive river
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yes

sturdy mirage
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The book doesn't really tell me how to at all.

restive river
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you want to row reduce it until you can take the kernel of it

sturdy mirage
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uh

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Yeah google had nothing for me on what a "kernel" is

sturdy mirage
restive river
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null space

sturdy mirage
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So a bunch of 0s in the last row, or the last column?

restive river
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yeah

sturdy mirage
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It has been 8 years since I took Linear Algebra now

sturdy mirage
# restive river yeah

How would you personally eliminate this one? The book is so insanely bad at describing how to do this (it does not at all), that I have zero idea where to even start.

restive river
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use a combination of these row operations

sturdy mirage
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Oh never mind

restive river
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yes, you can do that

sturdy mirage
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Or is it better to make it 1 0 4, 0 1 0, 0 0 0

restive river
sturdy mirage
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Cool

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To get the eigenvector, do I plug in -1 for k1 or k3?

restive river
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huh?

sturdy mirage
restive river
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yeah

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but what do you mean by substitute -1

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we have $\begin{bmatrix}1&0&4\0&1&0\0&0&0\end{bmatrix}\begin{bmatrix}x\y\z\end{bmatrix}=\begin{bmatrix}0\0\0\end{bmatrix}$

woven radishBOT
restive river
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write the solution in terms of the free variable z

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jolly swan
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what are intersection?

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jolly swan
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Are two lines that cross but include the Cartesian plane?

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weak cove
#

Are you asking what the intersection of two lines is?

weak cove
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It is the point where they cross eachother (if they do)

jolly swan
weak cove
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there is only 1 line in that image

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but the point you have selected

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you could say that is where the line 'intercepts' the y-axis

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or also you could say that is where the line 'intercepts' the x-axis

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But, you don't have two lines in that

jolly swan
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zenith stump
#

can someone check if i did this correctly

zenith stump
#

here is my work:

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<@&286206848099549185>

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sturdy mirage
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This is the problem I am on and the solution I have come up with.

sturdy mirage
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I know the solution is incomplete and that I need to solve for the 3 constants, I'm just not entirely sure how.

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This is the matrix I have, I'm just not sure how to do row reductions on it to get constant values.

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crisp fossil
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first of all, x(0), so t=0

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so all your e^rt become 1

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then you get a normal matrice [-3, 1, 3][0, -4, 0][1, 3, 1] times [c1, c2, c3] = [1, 4, 0] which is trivial to solve

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@sturdy mirage ty for doing all the work bc I do not remember how to do systems of differential equations, but I can scoop up the glory for this problem regardless :D /j

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sturdy mirage
crisp fossil
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Trivial as in this is a simple system of equations, it’s poor notation on my part

sturdy mirage
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Do I still do the row reduction?

frosty cradle
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yes, unless you wanted to invert the matrix and multiply that by [1, 4, 0]

sturdy mirage
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Ignore the e's

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slate bramble
#

How do I find the range to the double integral in the uv-plane?

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@slate bramble Has your question been resolved?

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@slate bramble Has your question been resolved?

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slate bramble
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deep vortex
#

Given that [\lambda \mapsto \Bigl(\frac b a_1 - \frac{a_2\lambda}{a_1}, \lambda\Bigr),] my book says that when plugging in $\lambda = a_1$, we get $(-a_2, a_1)$.

deep vortex
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warped tartan
#

I need help for letter b

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rancid verge
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By AAS rule

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Angle LMN = Angle TUV (35)
Angle LNM = Angle TVU (100)
LN = TV (7)

warped tartan
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Ohhhh

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I see

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Tqq

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warped tartan
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.reopen

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warped tartan
#

@rancid verge sorry continue your sentence..

rancid verge
#

What?

warped tartan
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.close

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hardy ruin
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hardy ruin
#

i need help

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w this

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#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
winter patrol
#

do you know the relation between slopes of perpendicular lines?

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wdym by "it"

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gradient of what

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you really need to be specific here

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no

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wrong phrasing / words omitted results in the wrong result

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there are two lines here

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the product of gradients of two perpendicular lines
(excluding horizontal/vertical)
is -1

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yeh, as horizontal lines have a gradient of 0, slope of vertical is undefined, so that property doesn't apply there

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to find the slope of the perpendicular line,
you can take the negative reciprocal of the given line

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slope is pretty much same as gradient

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yes

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that can be simplified though

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yes

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well now you have the slope/gradient and a point

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and there's a formula that pretty much tells how to get the equation of a line from that

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the point-slope/gradient formula

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no

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look up point slope formula

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actually seeing as you're given the y-intercept
you can just use
slope/gradient intercept form directly

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yeh

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rapid mauve
#

There is a question with a total of 9 points. The Mean score was 4.48 with a standard deviation of 3.19.

I calculated that at least 7.8% of students got 9/9. I also calculated that at least 4.3% of students got at or below -1/9 as a score, and that at least 4.1% of students got 10/9. Even though neither of those makes sense

How can I correctly calculate how many students got 9/9 if the score can only go from 0 to 9?

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hasty moat
#

screw probability

supple knot
hasty moat
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yeah im gonna help the dude chill

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some light banter first

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@rapid mauve

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you alive?

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muted stump
#

I wanna learn fraction decomposition integration, got a few basics down. I am solving a few of my past papers and I wanna learn how to integrate sqrts since there are a few of those in my papers

rapid mauve
hasty moat
hasty moat
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make sure the denominator is represented as a series of linear factors

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so (x-1)(x+2).....

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Javaman open a new channel

rapid mauve
muted stump
hasty moat
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and once you've done that, you can write each term seperately

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actually this might be easier to explain

muted stump
hasty moat
#

$\frac{A}{(x+1)} + \frac{B}{(x+2)}$

muted stump
#

yeah i understand that

woven radishBOT
hasty moat
#

yeah

muted stump
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but my question is

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how do u do it with square roots

hasty moat
#

provide an example?

muted stump
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like

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∫ (3x + 6)/sqrt(4x + 12) dx

hasty moat
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so for that you wouldn't use fractional decomposition

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you'd use trig substitution

muted stump
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hold up

hasty moat
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what

muted stump
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before u continue

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i wanna do this WITHOUT trig sub

hasty moat
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why

muted stump
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because my curriculum didnt teach trig sub and might cut marks for it

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if i apply it

hasty moat
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you'll be fine i doubt they'd dock you for using the correct method lol

muted stump
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nah nah, u dont understand, my math teachers are different

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can u show me a method without trig sub or no

final laurel
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you can use a u-sub

hasty moat
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well maybe

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nah f** that

muted stump
hasty moat
#

multiply by $\frac{\sqrt{4x+12}}{\sqrt{4x+12}}$

woven radishBOT
hasty moat
#

do that

final laurel
#

weird curriculum ig

hasty moat
#

multiplying by that will get rid of the square root on the denominator

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will make it possible to integrate without stuff you haven't learned yet

muted stump
hasty moat
#

highschool student explaining to college students about Gcse 0 levels sully

hasty moat
#

you cannot do the question you've provided with partial fractions

muted stump
#

like for example
they give u the equation y = xsqrt(4x + 12), and u need to differentiate it
u get dy/dx = 6(x + 2)/sqrt(4x + 12).
and then they tell u to integrate what i just said above
ig u just multiply by 2 and the outside integral by 1/2
and boom ur done

muted stump
hasty moat
#

but it is very weird to be doing partial fractions and to not have done u-sub yet

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usually you learn u-sub in calc 1 intro to derivatives

muted stump
#

yeah GCSE O lvl syllabus for calc is different than american calculus courses

hasty moat
#

yeah and i'm not american

muted stump
#

ok

#

alright then, im done. cya guys

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cold granite
#

I need help with my physics hw

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cold granite
#

im literally genuinely confused

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I understand nothing

supple knot
cold granite
#

oh

pastel pasture
cold granite
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the following questions

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And when I say I understand nothing i mean im clueless

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🙏

pastel pasture
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What would the dimensions of tension be?

cold granite
#

.

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I have no idea 💀

pastel pasture
#

Do you understand what tension is

cold granite
#

uhh

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i havent learned anything this entire unit

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I have 0 knowledge on waves

pastel pasture
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What quantity is it

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I see

cold granite
#

Scalar?

pastel pasture
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Well uh

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I was expecting "force" as an answer

cold granite
#

💀oh

pastel pasture
#

In any case, I think you should revise the basics

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Maybe read on what a wave is and stuff

cold granite
#

😟

#

alr

pastel pasture
#

The standing wave thing is gonna be impossible without it

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Or the chaps at the phsyics server can help you

cold granite
#

alr thx 🙏

#

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balmy wasp
#

Guys I'm pretty confused as to why I must use the sine rule when I can just use the normal tan

balmy wasp
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fleet surge
#

Noob

#

/Joke

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rough hatch
#

how do i get this anwser

devout snowBOT
rough hatch
#

its for unit circle

rare mantle
#

tan(theta) = sin(theta) / cos(theta)

supple knot
rough hatch
supple knot
#

,tex .unit circle

woven radishBOT
#

riemann

supple knot
#

find $\sin(150^\circ)$ and $\cos(150^\circ)$

woven radishBOT
#

riemann

rough hatch
#

?

supple knot
#

yup

rough hatch
#

so how do make it so i dont get a decimal on calc

supple knot
#

google your calculator model

rough hatch
#

ok

supple knot
#

not every calculator is capable of it

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pastel pasture
#

Why does computing derivatives with logarithms over functions that can be negative work?

pastel pasture
#

And does it always work?

lusty sapphire
#

wdym

pastel pasture
#

$$y = \sin x$$
$$\ln y = \ln \sin x$$
$$y' \frac 1y = \cot x$$
$$y' = \cos x$$

woven radishBOT
#

NEONPerseus

pastel pasture
#

Like sine isn't always positive but it seems to work?

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Same thing can be done for x^3

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Despite being negative over certain intervals, you get the derivative alright with no domain restrictions

supple knot
#

the method would only yield the correct answer in that domain

pastel pasture
#

But it's still cos x fair and square

supple knot
#

that's completely independent of doing the logarithmic derivative

lusty sapphire
#

I see

supple knot
#

using this method, y' = cos(x) doesn't have to be defined for all x

#

it just happens so

pastel pasture
#

Is there a function where this fails

lusty sapphire
#

You can use complex log

#

$\text{Log }{z}=\ln{|z|}+i\text{Arg }z$

woven radishBOT
pastel pasture
#

$$\ln z = \ln |z| + i\arg (z) + 2n\pi$$
$$n \in \mathbb Z$$

#

But nothing for real valued functions?

#

And technically that doesn't need to be the principal argument

#

Right

lusty sapphire
woven radishBOT
#

NEONPerseus

lusty sapphire
pastel pasture
#

True

#

Alright I guess thanks

#

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ancient gull
#

I need some help

devout snowBOT
ancient gull
#

I need help with this worksheet

#

and how area =base x hight

#

here I showed how I think you do it

#

that is number one

dense nymph
#

Imagine it on a number line

#

You start from -8

#

How many numbers would it take to get to 0

ancient gull
#

8

dense nymph
#

Yeah

#

In the first question you are adding 12

#

It takes 8 to reach zero

#

And then you have 4 numbers left

#

So what would your final number be

ancient gull
#

4

#

i think

dense nymph
#

Yeah nice

ancient gull
#

thank you

dense nymph
#

Np

ancient gull
#

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supple knot
#

"decreasing" means the slope is negative

#

Where in this image is the slope negative

#

Show the formula for this

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#

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umbral trench
#

So I am currently trying to implement an Animation in my app. Basically I have a value that is clamped from 0 to infinity, and should become very "slow" at around 30-40. I want to interpolate it like the curve shown in this picture. Its very important that the angle at the start of the function is 45 degrees, because the value is the value of a swipe gesture by the user and its used to swipe a widget. so the widget should move in the speed of the users finger in the beginning, and then slowly the speed should decrease until its eventually near 0. Any Idead?

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umbral trench
#

wait, i think i found the solution

#

its f(x)=1-ℯ^(-x)

#

should be

#

yeah I will try if it works well

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naive estuary
#

hmmm you might want to ask your teacher...

wooden sequoia
#

Can someone help me with an incline plane question?

long fog
#

Is that a -4?

viscid talon
#

yeah?

#

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dusk sand
#

hi. Algebra problem. To solve for x , why cant u multiply the denominator (without the x) to the LHS?

dusk sand
#

is it bc youd still have 1/x left over?

long fog
dusk sand
#

@long fog im srs

long fog
#

Idk who srs is

winter patrol
#

you can do valid manipulation, whether it helps you is a different story

#

why cant u multiply the denominator (without the x)
wdym by without the x

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proper violet
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finite inlet
#

Hey, quick question

devout snowBOT
finite inlet
#

[ \lim_{x \rightarrow 0} |x|^2 \cdot f(x) ]

woven radishBOT
#

madmike

finite inlet
#

Is the result always going to be 0 no matter which function f is?

#

f: R -> R

pseudo basin
#

not if f(x) = {1/x^3 for x ≠ 0, 69 at x=0} it isn't.

finite inlet
#

oh

#

well I have this function and need to show that it is continuous in x=0

woven radishBOT
#

madmike

finite inlet
#

and then I wanted to do sandwich

#

but I can't find a function that is <= |g(x)|

#

[
|g(x)| = |x \cdot f(x)| = |x| \cdot |f(x)|
\ \text{ and then } \ 0 \leq |x| \cdot |f(x)| \leq \ ?
]

woven radishBOT
#

madmike

finite inlet
#

I thought maybe ? := |x|^2 * f(x)

pseudo basin
finite inlet
#

but as you said that is not going to work

pseudo basin
#

beyond it being a function from R to R, that is

finite inlet
#

f: R \ {0} -> R is limited (restricted?)

#

up and down

#

what's the english word

#

so I guess I could choose some y that is > f(x) for all x

pseudo basin
#

can you find the german word and its definition

finite inlet
#

beschränkt

pseudo basin
#

okay yeah that means bounded

finite inlet
#

ahh okay ty

pseudo basin
#

so you know there exists a constant M such that |f(x)| ≤ M

#

that's exactly what you need for your sandwich

#

the bread, if you will

finite inlet
#

l0l

#

I can just choose some generic M?

#

nice

pseudo basin
#

wdym generic

finite inlet
#

uhhh without actually giving a number

#

I guess that would be impossible

#

sorry brain fart

#

can I use 0 for the bottom bread though?

#

I think not?

#

Because x * f(x) could be less than 0 in some x

#

right?

#

yeah

#

ty

#

.close

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grand meadow
#

how would i solve a logarithmic inequality that has a logarithm as the argument?

balmy wasp
#

give example

grand meadow
#

for example:

pseudo basin
#

10^(both sides) turns this into log_10(x) < 10^(1/2)

balmy wasp
#

i thik change whatever in the brackets into x aybe/

grand meadow
#

i'll have x >0 and x>10^sqrt10, right?

grand meadow
low holly
#

can we have x = 1/10?

grand meadow
#

wouldn't i have x>0 and x>10^sqrt10? why x=1/10?

low holly
#

also if x>10^sqrt10, then x > 0 is redundant

#

x < y implies 10^x < 10^y, i.e. the direction of the inequality is preserved when raising 10 to power of each side

final storm
#

log_10(x) < sqrt10

low holly
final storm
#

sry not greater

low holly
#

yeah...

final storm
#

mb

low holly
#

that's the part they have wrong

final storm
#

ye, my lazy ass didnt scroll up to read the question again

grand meadow
#

where would i get x=1/10?

low holly
#

(assuming you have fixed the mistake x>10^sqrt10 to x<10^sqrt10)

grand meadow
low holly
#

but does x = 1/10 satisfy the inequality?

#

(you should see a problem)

grand meadow
#

wait in the system of inequalities i'll have x<0 and x<10^sqrt10 so the answer should be x<10^sqrt10. idk where to plug in x=1/10

low holly
#

how did you get x < 0

grand meadow
#

honestly im following this, and since it says that i should write A>0 i wrote x<0

low holly
grand meadow
low holly
woven radishBOT
#

tushar

low holly
#

the logarithm of 0 or any negative number is undefined

#

the domain of the log function is the positive real numbers

grand meadow
#

the options to the question are : A) x<10 B)x<10^sqrt10 C)every real value of x D)1<x<10 E)1<x<10^sqrt10

low holly
#

yes

#

one of them is correct

#

you can repeatedly use the following property to derive one of the constraints: x < y implies 10^x < 10^y

#

so from log_10(log_10(x)) < 1/2 you get log_10(x) < sqrt(10) and hence x < 10^sqrt(10), as you have found

#

but this is not all, you also have the domain constraints of the log function

#

for the inner log to be defined, you must have x > 0

#

however there are tighter restrictions on x that must be placed, which you can see if you try to evaluate the left-hand side of the inequality when x = 1/10

#

in this case, the outer log becomes undefined, because you get log_10(-1)

#

thus you must also make sure that the output of the inner log is positive

#

this is as much guidance that i can give without outright solving the problem for you

devout snowBOT
#

@grand meadow Has your question been resolved?

pliant sierra
#

Please, help me 😦 <@&286206848099549185>

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#

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crisp cliff
crisp cliff
#

Starting with Step 1, I don't understand this...Wouldn't the t values just be the same? What's the point of this?

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#

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winged wagon
#

i understand how to do it i just need to know how to break the fraction into two

winged wagon
#

i got an idea on how but i feel like there is a better way

#

the 5pi/12 to pi/4 and pi/3 how can i get there with any equation

#

is there like a proccess i can use with any equation

scarlet sequoia
#

but

#

pi/4 + pi/3 isn't 5pi/12

winged wagon
#

no sin(pi/4+pi/3) the same as sin5pi/12

#

how you solve it

scarlet sequoia
#

it comes from sin(pi - x) = sin(x)

#

where x = 5pi/12

#

it follows sin(7pi/12) = sin(5pi/12)

winged wagon
#

kinda lost me there

#

ngl

#

well yeah 7pi/12 is pi/4 + pi/3

scarlet sequoia
#

yes

winged wagon
#

but how do you get to

#

7pi/12

scarlet sequoia
#

do you mean how pi/4 + pi/3 is 7pi/12 or what

#

or how should you know to split it into them

winged wagon
#

no how you looking at 5pi/12 you can use the numbers for 7pi/12

#

the sin(pi-x)

scarlet sequoia
#

It's an identity

woven radishBOT
winged wagon
#

OH

#

i see it

#

it makes sense

scarlet sequoia
#

generally

#

doing questions like this one

#

you should focus on how you can express given number as sum (difference) of pi/6, pi/4 or pi/3

#

because for them values of trig functions are well known

winged wagon
#

hmm okay

scarlet sequoia
#

might be also pi, pi/2 etc.

winged wagon
#

so try to stay with the numbers we already know and use

scarlet sequoia
#

e.g. sin(pi/12) is not "obvious"

winged wagon
#

is it

#

4pi/3-3pi/4

#

i remember that one

scarlet sequoia
#

that's 7pi/12, but in this case it seems harder than pi/4 + pi/3

#

but might be used

#

then some trig identites are required

winged wagon
#

.close

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wary hound
#

Is this right?

devout snowBOT
final storm
#

yes

wary hound
final storm
#

14 * 2

wary hound
#

And when you multiply 0.5 by -2 it should be -1 not 2

final storm
#

multiplied by 2 on both sides

wary hound
#

Oh

wary hound
final storm
#

but there is a fraction?

wary hound
#

No I mean for example

final storm
#

i dont understand what you mean

wary hound
final storm
#

no, you multiply by 2 to get rid of the fraction because it looks nicer

#

but you dont have to multiply if you dont want to

#

y - 14 = 0.5x - 1

#

y = 0.5x + 13

#

just having your answer in this form is fine too

wary hound
final storm
#

it'd be the same

#

multiplying by 2 for both sides would give 2y = x + 26

#

-x + 2y = 26

#

x - 2y = -26

wary hound
#

Oh now I get it

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ripe portal
#

In this exercise, i know that when a>3 the limit=inf and when a<3 the limit=0 but what happens when a=3, indetermination?

glacial wyvern
#

Wolfram Alpha says that it diverges to infinity but I have no idea why

ripe portal
#

in my solutions too

glacial wyvern
#

how did you attempt to tackle it?

lusty sapphire
#

Show that the log of the limit still diverges

#

That's my guess anyway

glacial wyvern
#

that's smart

#

yeah Wolfram says that the log also diverges

ripe portal
#

so what can i do, apply the log?

glacial wyvern
#

yeah and then take out the x^3 and then simplify it a bit and then use l'hopital (nvm I have actually no clue if that would work lmao)

ripe portal
#

so it is an indetermination right?

#

and what do you mean by diverge?

glacial wyvern
#

diverge = does not converge to a value

ripe portal
#

so it's inf

#

or -inf

low holly
#

,w lim x to infinity ((3x^2+4)/(3x^2+2))^(x^3)

glacial wyvern
#

it diverges to positive infinity

ripe portal
#

but it's a indetermination no?

glacial wyvern
#

The limit is indeterminate yes

ripe portal
#

and to solve it, i applied the ln, taking out the x^3 and then the result is (x^3)ln(0) ?

low holly
#

$$\lim_{x \to \infty} \left(\frac{3x^2+4}{3x^2+2}\right)^{x^3} = \mathrm{exp}\left(\lim_{x\to\infty} \frac{\ln\left(\frac{3x^2+4}{3x^2+2}\right)}{1/x^3}\right)$$

woven radishBOT
#

tushar

ripe portal
#

i don't know doing by this way

#

i show you how i do it

#

i think that is what you write

#

but could u explain me the step of dividing x^3?

woven radishBOT
#

tushar
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

ripe portal
#

is the method that i used changing the e for A

low holly
#

essentially equivalent

ripe portal
#

but then, how can i solve the intedermination 0*inf?

low holly
#

rewriting $f(x)^{g(x)}$ as $e^{\ln(f(x)^{g(x)})} = e^{g(x)\ln(f(x))}$

woven radishBOT
#

tushar

low holly
#

then since e^x is continuous, we can pass the limit into the exponent

woven radishBOT
#

tushar
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

low holly
#

formally, you would be arguing: assume that the limit in question exists. then this limit must also exist, which you seek to contradict

ripe portal
#

okey, now i see it clearly

#

and then, i transform my 0*inf in a 0/0 indetermination right?

low holly
#

0 * infinity is just 0 / 0 when you bring the infinity to the denominator

ripe portal
#

which by l'hopital is easy to solve

low holly
#

to get 0/0

low holly
ripe portal
#

okey thanks

#

.close

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late gull
#

Solve this (D^4+D^2+1)y=e^-(x/2)cos(sqrt3/2 *x) how to solve?

late gull
#

D=d/dx

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brazen spire
devout snowBOT
brazen spire
#

Is this correct

#

<@&286206848099549185>

#

Also do I need to find extra points

#

Hello

#

<@&286206848099549185>

devout snowBOT
#

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carmine swallow
#

Is my answer correct?

devout snowBOT
carmine swallow
devout snowBOT
#

@carmine swallow Has your question been resolved?

carmine swallow
#

<@&286206848099549185>

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carmine swallow
#

.close

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maiden tree
#

how do you graph E

devout snowBOT
maiden tree
#

im clueless

#

can someone just provide a quick solution to this

lusty sapphire
#

Maybe it's a typo. Or maybe it's -2

maiden tree
#

yeah

#

it's (-2, 2, 0)

devout snowBOT
#

@maiden tree Has your question been resolved?

devout snowBOT
#

@maiden tree Has your question been resolved?

maiden tree
#

As well

#

how do you do this question

#

<@&286206848099549185>

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@maiden tree Has your question been resolved?

umbral raft
#

draw it

#

thats what i would do

#

(-13,-5)?

waxen harness
#

@maiden tree are you here?

maiden tree
#

yea

last imp
waxen harness
#

Mid point of SQ would be M ( -6-3/2 , 1-4/2) so M (-4.5,-1.5) then take R (x,y) and x+4 = -9 , y+2= -3. So x = -13, y = -5.

#

Hope this helps.

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mossy gale
#

I'm struggling with questions like these. What chapters should I learn before I have strong basics of these

pastel pasture
#

You really only need to know about complex numbers for these ones

mossy gale
#

Where can I find more sums about summation

#

That sigma

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distant shore
#

Hello Could I please have some help with this question

distant shore
quaint citrus
#

If 1 # = 18, then how much is ##?

#

@distant shore

distant shore
#

the answer is 36

quaint citrus
#

Right and then what would half of a hashtag be worth?

#

If one hashtag is 18, what’s half of it?

distant shore
#

27

whole lake
distant shore
#

used a calculator

#

and now it gives me a very different answer

wise marsh
#

Ex.

If () = 4, then () () () = 3 * () = 3 * 4 = 12
Which means half () = ( = ½ * 4 = 4/2 = 2
() ( = 4 + 2 = 6

distant shore
#

.close

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loud spindle
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loud spindle
#

An i on the correct step

#

I don't know what to do after that assuming I did everything correctly till that point

#

$e^xsec(x)=0$

woven radishBOT
#

ilikecats

loud spindle
#

$Tan^-1(1)=\pi/4$

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#

@loud spindle Has your question been resolved?

supple knot
#

,rotate

woven radishBOT
loud spindle
#

I tried it another way
I got pi/4

#

I don't know how to solve the questions after this?
Because that's not within the interval

#

I think

#

I mean 3pi/4

#

I miss wrote

#

No idk

#

They are both values for tan^-1 (1)= pi/4,3pi/4
Idk

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restive river
#

how do I take notes in maths

devout snowBOT
restive river
#

I seem to remember really well using questions

#

But I would like advice from someone more experienced

#

And generally how to approach questions and worked examples

#

I just try to solve a question till I get it

#

But I find that very slow and ineffective is there a better way

#

If so I would really appreciate any advice

karmic quarry
#

For me, I usually like to look at a couple examples to see if there's a certain pattern or pattern of steps when it comes to specific kind of questions before I approach a problem by myself. I also like to reason why they needed to do that step in the problem to get the end result.

karmic quarry
karmic quarry
restive river
#

I suck at highschool maths so badly tbh

#

Also what about focus and effort

#

I cant seem to completely focus on the problem and that leads me to skip or forget a step

karmic quarry
#

have you tried like marking the problem with a star to indicate that you have to go back and try again?

#

or like mark it with a question mark to ask a teacher

karmic quarry
restive river
karmic quarry
#

ah i see

restive river
#

I tried improving my basics

#

And got a bit better

#

But still suck

#

Any advice on atleast scoring a C

#

Anything would really help

karmic quarry
#

while you still can use your school's math resources to get in-person help, they can help narrow down where you are getting stuck

#

when working through a problem when you get stuck try to solve the problem through other methods for 5-8 minutes, if that can't seem to get through, look up the problem, and work it through the problem with them, and try to understand why they did that step or method

restive river
#

Ok i will try to fix my basics completely in six hours

#

Then i will try to cover all the main topics

karmic quarry
#

most math follow a set of pattern and reasoning, so knowing that can help with problems

#

half of the battle is understanding why and how

restive river
#

If its ok could u talk to me in dms about improving and feedback

karmic quarry
#

it's hard to explain

#

it just kind of clicks

#

i know it's not the greatest thing to say, but it will eventually happen

#

just be patient with yourself, practice a lot, it will eventually click

restive river
#

How much should spent on one problem

#

Rn im doing basic algerba

karmic quarry
#

for me i personally if i get stuck and spend more than 7 minutes trying to figure it out, i usually stop and either look at my notes to see if it helps or look up a step by step answer guide to see how they got there

restive river
#

Cuz thats something i learned recently too

karmic quarry
#

yeah

restive river
#

Close.

#

.close

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bright gulch
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bright gulch
#

How do you know the components of a vector field?

#

How did you get <-y+z, -x+z, x+y>?

supple knot
#

Use the definition of the gradient

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rich helm
#

been trying to figure out this problem with trig and i'm confused on if ur supposed to subtract 20 from 90 because it's a depressing angle and input 70 in the calculator or use 20.

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rich helm
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.close

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obtuse pulsar
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obtuse pulsar
#

how do i solve this?

#

any specific formula?

winter patrol
#

area of rectangles

#

drawing a sketch helps

obtuse pulsar
#

what are the points?

#

(2,5) (4,1) (5,5) ?

#

.close

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finite briar
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finite briar
#

Isnt the answer just infinity?

pseudo basin
#

how so

finite briar
#

well its asking 'maximum'

#

and there is no 'maximum integer'

pseudo basin
#

you have a constraint

#

sqrt(x-5) + sqrt(y-3) = sqrt(x+y)

finite briar
#

like obtaining x in terms of y

#

i got $x=\frac{3y+8}{y-5}$

woven radishBOT
#

ItzKraken2

finite briar
#

but idk how to proceed from here

pseudo basin
#

i want to verify this before we proceed

finite briar
#

Okay 👍

pseudo basin
#

,w sqrt(x-5) + sqrt(y-3) = sqrt(x+y) isolate x

pseudo basin
#

!nosols

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#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

pseudo basin
#

so it sounds like you have fucked up your arithmetic somewhere

pseudo basin
#

but in any case now you want to maximize y(5y+1)/(y-3) for y ∈ {4, 5, ...}

finite briar
pseudo basin
#

have you never done optimization problems before

pseudo basin
#

💀

#

then how are you expected to do this somewhat nontrivial one

#

actually hang on

proud perch
#

you don't need calculus

pseudo basin
#

... this looks weird to me

#

oh wait hold up

#

x must be an integer

proud perch
#

just some algebra and intuition

pseudo basin
#

so theres only so many values y can take given that

finite briar
#

Huh..

#

is there like any method?

#

to find this?

proud perch
#

sure

#

take the original equation

#

square both sides

#

what does that give you?

finite briar
#

i actually did the whole squaring thing

#

$x+y-8+2\sqrt{xy+8-5x-3y} = x+ y$

woven radishBOT
#

ItzKraken2

finite briar
#

$2\sqrt{xy+8-5x-3y} = 8$

proud perch
#

let's rewrite that, it's better to leave it factored

woven radishBOT
#

ItzKraken2

finite briar
proud perch
#

$$2\sqrt{(x-5)(y-3)} + x + y - 8 = x + y$$

woven radishBOT
#

Mr. Gamer

proud perch
#

now get the square root by itself on one side

finite briar
#

okay

#

$$2\sqrt{(x-5)(y-3)} = 8$$

woven radishBOT
#

ItzKraken2

finite briar
#

we square again?

proud perch
#

divide by 2 first

finite briar
#

Okay

#

$$\sqrt{(x-5)(y-3)} = 4$$

woven radishBOT
#

ItzKraken2

finite briar
#

which gives $(x-5)(y-3)=16$, upon squaring

woven radishBOT
#

ItzKraken2

finite briar
#

right?

proud perch
#

yep, now here's where the geometric intuition comes into play

finite briar
#

wdym by 'geometric intuition'

#

like theres no geometry here

#

is there?

proud perch
#

nah nvm you just have to test the cases

finite briar
#

Sooo i do that by looking at factors of 16, find x and y, then xy, then compare?

proud perch
#

yes

finite briar
#

Okay lemme do that real quick

proud perch
#

(1,16), (2,8), (4,4), (8,2), (16,1)

#

it's not symmetric so you have to include both factor pairs

finite briar
#

i got xy = 128

#

x=6, y = 18

#

from (1,16)

#

as the maximum

proud perch
#

how can y be 18

finite briar
#

its 19

#

16+3 is 19 right

proud perch
#

yes...

finite briar
#

then its 114...

proud perch
#

there you go

finite briar
#

yeah thats correct

#

tysm!

#

.close

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mortal depot
#

Max/Min f(x,y) = x^2 + y^2 under the constraint x^2+xy+y^2 = 3

I have a quick question regarding the task above. If we solve this with the lagrange-method we get multiple candidates for the optimization problem. But if I simply solve the constraint for x^2 and then insert it in the original equation I get completely different solutions. Why does that not work?

mortal depot
#

<@&286206848099549185>
Helperbros I need your help

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mortal depot
#

<@&286206848099549185>

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#

@mortal depot Has your question been resolved?

mortal depot
#

<@&286206848099549185>

#

When I solve x^2+xy+y^2=3 for x I get a solution for x that depends only on y. If I insert it into the original equation and maximize it I get the correct solutions. (although this is quite annoying to do)

When I solve x^2 + xy + y^2 = 3 for x^2 I get a solution for x that depends on x and y. If I insert it into the original equation and maximize it I get wrong solutions.

From a purely theoretical standpoint, why is the second approach invalid?

I am aware that solving via lagrange is much easier, simply curious.

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@mortal depot Has your question been resolved?

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#

@mortal depot Has your question been resolved?

soft raven
#

Hi

#

I will help you

#

wait what

#

actually no sorry i dont know

mortal depot
#

rip

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#

@mortal depot Has your question been resolved?

analog trellis
#

As long as the extrema exist at points where x^2 + xy + y^2 = 3 define a function x in terms of y or y in terms of x you should be fine to use your approach.

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fossil garden
#

could someone guide me on how to write a quadratic polynomial in standard form

fossil garden
#

Q=x^t(SDS^t)x+Px+c

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#

@fossil garden Has your question been resolved?

supple knot
fossil garden
#

Q is a quadratic polynomial here not a quadratic form

#

@supple knot

#

or am i missing something

fossil garden
#

and x\in R^n

#

nvm i did it

#

.close

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rapid jewel
#

i don’t know how to solve this bleakkekw

restive river
#

@rapid jewel

rapid jewel
#

why is this part 0?