#help-27
1 messages · Page 83 of 1
seems a bit overpowered
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Hey i need help with this
How did we get x=0 and x= 4/3
This is from a yt video but she didnt explain it just wrote it
we have -3x^2+4x=0. firstly we factor out -x. this means that just one of the factors needs to be zero (see zero-product property). this means either -x=0 or 3x-4=0. therefore x=0 or x=4/3
Ohh we just solve it
yeah they are just solving h'(x)=0
Ok thx
can anyone help
i triedd
Bcaed
it’s says it wrong
This isnt even preschool lol
I’m british
its okk
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
@potent marlin Has your question been resolved?
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This is the question I'm on.
The video explanation says that I can rewrite the two (1-lambdas) as (lambda+1) and (2-lambda), but I'm not entirely sure how he reached that conclusion.
factor out -1 from (1-lambda)
Where did the 3 come from though?
they factored (1-lambda)^2 -4
Where did the -4 come from?
So the 0 multiplier in the middle doesn't actually 0 it?
its a typo
How is it a typo?
it should be 4(0 - (2-lambda))
Ah
Yeah that makes sense
The person that does these videos is not very good at them.
They just kind of assume you know every single thing they are talking about and don't actually explain what they're doing.
It would look like this ?
,w char poly [[3,11,16],[0,4,0],[1,1,3]]
yes
Fair enough
So it gives me complex roots?
Ah.
It also said I need to use the Gauss Jordan elimination method, which just looks like matrices stuff?
yeah, use row operations
The first eigenvalue
so you want to find the kernel of A-lambda I
fractions are fine, but can get messy
no, it will never be invertible since lambda is an eigenvalue
What am I supposed to do with this then?
Do I do row operations until I only have 1s?
Or until the bottom row is 0?
yes
The book doesn't really tell me how to at all.
you want to row reduce it until you can take the kernel of it
What is a kernel?
null space
So a bunch of 0s in the last row, or the last column?
yeah
It has been 8 years since I took Linear Algebra now
How would you personally eliminate this one? The book is so insanely bad at describing how to do this (it does not at all), that I have zero idea where to even start.
Would putting the 0 5 0 at the bottom be the best?
Oh never mind
yes, you can do that
I got the matrix to 1 1 4, 0 1 0, 0 0 0. Is that an acceptable form?
Or is it better to make it 1 0 4, 0 1 0, 0 0 0
this makes it easier
huh?
It's asking me for the 3 eigenvectors, associated with each eigenvalue
yeah
but what do you mean by substitute -1
we have $\begin{bmatrix}1&0&4\0&1&0\0&0&0\end{bmatrix}\begin{bmatrix}x\y\z\end{bmatrix}=\begin{bmatrix}0\0\0\end{bmatrix}$
Toby
write the solution in terms of the free variable z
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what are intersection?
Are two lines that cross but include the Cartesian plane?
@jolly swan Has your question been resolved?
Are you asking what the intersection of two lines is?
yes
It is the point where they cross eachother (if they do)
this is a intercept?
there is only 1 line in that image
but the point you have selected
you could say that is where the line 'intercepts' the y-axis
or also you could say that is where the line 'intercepts' the x-axis
But, you don't have two lines in that
How do I calculate the angle of two lines?
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can someone check if i did this correctly
@zenith stump Has your question been resolved?
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This is the problem I am on and the solution I have come up with.
I know the solution is incomplete and that I need to solve for the 3 constants, I'm just not entirely sure how.
This is the matrix I have, I'm just not sure how to do row reductions on it to get constant values.
@sturdy mirage Has your question been resolved?
first of all, x(0), so t=0
so all your e^rt become 1
then you get a normal matrice [-3, 1, 3][0, -4, 0][1, 3, 1] times [c1, c2, c3] = [1, 4, 0] which is trivial to solve
@sturdy mirage ty for doing all the work bc I do not remember how to do systems of differential equations, but I can scoop up the glory for this problem regardless :D /j
@sturdy mirage Has your question been resolved?
Trivial as in only the trivial solution?
Trivial as in this is a simple system of equations, it’s poor notation on my part
It's the first problem of the chapter, I would hope it's a little easy lol
Do I still do the row reduction?
yes, unless you wanted to invert the matrix and multiply that by [1, 4, 0]
I got this
Ignore the e's
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@sturdy mirage Has your question been resolved?
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How do I find the range to the double integral in the uv-plane?
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.close
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Given that [\lambda \mapsto \Bigl(\frac b a_1 - \frac{a_2\lambda}{a_1}, \lambda\Bigr),] my book says that when plugging in $\lambda = a_1$, we get $(-a_2, a_1)$.
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(Posted this in #linear-algebra)
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I need help for letter b
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.reopen
✅
@rancid verge sorry continue your sentence..
What?
.close
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@hardy ruin Has your question been resolved?
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
do you know the relation between slopes of perpendicular lines?
wdym by "it"
gradient of what
you really need to be specific here
no
wrong phrasing / words omitted results in the wrong result
there are two lines here
the product of gradients of two perpendicular lines
(excluding horizontal/vertical)
is -1
yeh, as horizontal lines have a gradient of 0, slope of vertical is undefined, so that property doesn't apply there
to find the slope of the perpendicular line,
you can take the negative reciprocal of the given line
slope is pretty much same as gradient
yes
that can be simplified though
yes
well now you have the slope/gradient and a point
and there's a formula that pretty much tells how to get the equation of a line from that
the point-slope/gradient formula
no
look up point slope formula
actually seeing as you're given the y-intercept
you can just use
slope/gradient intercept form directly
yeh
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There is a question with a total of 9 points. The Mean score was 4.48 with a standard deviation of 3.19.
I calculated that at least 7.8% of students got 9/9. I also calculated that at least 4.3% of students got at or below -1/9 as a score, and that at least 4.1% of students got 10/9. Even though neither of those makes sense
How can I correctly calculate how many students got 9/9 if the score can only go from 0 to 9?
@rapid mauve Has your question been resolved?
screw probability
don't interrupt help channels
yeah im gonna help the dude chill
some light banter first
@rapid mauve
you alive?
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I wanna learn fraction decomposition integration, got a few basics down. I am solving a few of my past papers and I wanna learn how to integrate sqrts since there are a few of those in my papers
I am really confused by your response.
not gonna explain it if you already got it and the channel was dead
for fractional decomposition
Need help ^
make sure the denominator is represented as a series of linear factors
so (x-1)(x+2).....
Javaman open a new channel
“Screw probability” is just an unusual response, but anyways I will ask in another channel
mhm
and once you've done that, you can write each term seperately
actually this might be easier to explain
im still not clear enough with ur explanation sir
$\frac{A}{(x+1)} + \frac{B}{(x+2)}$
yeah i understand that
Zouni
yeah
provide an example?
hold up
what
why
you'll be fine i doubt they'd dock you for using the correct method lol
nah nah, u dont understand, my math teachers are different
can u show me a method without trig sub or no
you can use a u-sub
eh, we didnt get to that part yet
multiply by $\frac{\sqrt{4x+12}}{\sqrt{4x+12}}$
Zouni
do that
you're doing partial frac but haven't done u sub yet?
weird curriculum ig
lmao true
multiplying by that will get rid of the square root on the denominator
will make it possible to integrate without stuff you haven't learned yet
OK LET ME EXPLAIN THIS NICELY
I am doing GCSE O lvls, where they make u do a few steps so that u can easily substitute an easy part into the complex part of the integral to easily integrate it, BUT I WANNA LEARN how to do it the hard way
highschool student explaining to college students about Gcse 0 levels 
okay...
you cannot do the question you've provided with partial fractions
like for example
they give u the equation y = xsqrt(4x + 12), and u need to differentiate it
u get dy/dx = 6(x + 2)/sqrt(4x + 12).
and then they tell u to integrate what i just said above
ig u just multiply by 2 and the outside integral by 1/2
and boom ur done
sorry i thought u might not know, this server might be filled with mostly americans
damn
alright
lmao
but it is very weird to be doing partial fractions and to not have done u-sub yet
usually you learn u-sub in calc 1 intro to derivatives
yeah GCSE O lvl syllabus for calc is different than american calculus courses
yeah and i'm not american
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I need help with my physics hw
#old-network for physics server
oh
What is it?
the following questions
And when I say I understand nothing i mean im clueless
🙏
What would the dimensions of tension be?
Do you understand what tension is
Scalar?
💀oh
In any case, I think you should revise the basics
Maybe read on what a wave is and stuff
The standing wave thing is gonna be impossible without it
Or the chaps at the phsyics server can help you
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Guys I'm pretty confused as to why I must use the sine rule when I can just use the normal tan
@balmy wasp Has your question been resolved?
@balmy wasp Has your question been resolved?
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how do i get this anwser
its for unit circle
tan(theta) = sin(theta) / cos(theta)
are you given the unit circle?
yea
,tex .unit circle
riemann
then it's just this
find $\sin(150^\circ)$ and $\cos(150^\circ)$
riemann
yup
so how do make it so i dont get a decimal on calc
google your calculator model
ok
not every calculator is capable of it
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Why does computing derivatives with logarithms over functions that can be negative work?
And does it always work?
$$y = \sin x$$
$$\ln y = \ln \sin x$$
$$y' \frac 1y = \cot x$$
$$y' = \cos x$$
NEONPerseus
Like sine isn't always positive but it seems to work?
Same thing can be done for x^3
Despite being negative over certain intervals, you get the derivative alright with no domain restrictions
taking the log already assumes domain restrictions
the method would only yield the correct answer in that domain
that's completely independent of doing the logarithmic derivative
I see
using this method, y' = cos(x) doesn't have to be defined for all x
it just happens so
Is there a function where this fails
SWR
$$\ln z = \ln |z| + i\arg (z) + 2n\pi$$
$$n \in \mathbb Z$$
But nothing for real valued functions?
And technically that doesn't need to be the principal argument
Right
Technically, log(sin(x)) will not be defined for sin(x)<=0 if you stick to the reals
NEONPerseus
I guess
I'm sticking to principal log. Plus, the 2npi would disappear once you do derivative
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I need some help
I need help with this worksheet
and how area =base x hight
here I showed how I think you do it
that is number one
Imagine it on a number line
You start from -8
How many numbers would it take to get to 0
8
Yeah
In the first question you are adding 12
It takes 8 to reach zero
And then you have 4 numbers left
So what would your final number be
Yeah nice
thank you
Np
.close
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"decreasing" means the slope is negative
Where in this image is the slope negative
Show the formula for this
@mighty acorn Has your question been resolved?
@mighty acorn Has your question been resolved?
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So I am currently trying to implement an Animation in my app. Basically I have a value that is clamped from 0 to infinity, and should become very "slow" at around 30-40. I want to interpolate it like the curve shown in this picture. Its very important that the angle at the start of the function is 45 degrees, because the value is the value of a swipe gesture by the user and its used to swipe a widget. so the widget should move in the speed of the users finger in the beginning, and then slowly the speed should decrease until its eventually near 0. Any Idead?
@umbral trench Has your question been resolved?
wait, i think i found the solution
its f(x)=1-ℯ^(-x)
should be
yeah I will try if it works well
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hmmm you might want to ask your teacher...
Can someone help me with an incline plane question?
Is that a -4?
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hi. Algebra problem. To solve for x , why cant u multiply the denominator (without the x) to the LHS?
is it bc youd still have 1/x left over?

Idk who srs is
you can do valid manipulation, whether it helps you is a different story
why cant u multiply the denominator (without the x)
wdym by without the x
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Hey, quick question
[ \lim_{x \rightarrow 0} |x|^2 \cdot f(x) ]
madmike
not if f(x) = {1/x^3 for x ≠ 0, 69 at x=0} it isn't.
madmike
and then I wanted to do sandwich
but I can't find a function that is <= |g(x)|
[
|g(x)| = |x \cdot f(x)| = |x| \cdot |f(x)|
\ \text{ and then } \ 0 \leq |x| \cdot |f(x)| \leq \ ?
]
madmike
I thought maybe ? := |x|^2 * f(x)
is anything known about f(x)?
but as you said that is not going to work
beyond it being a function from R to R, that is
f: R \ {0} -> R is limited (restricted?)
up and down
what's the english word
so I guess I could choose some y that is > f(x) for all x
can you find the german word and its definition
okay yeah that means bounded
ahh okay ty
so you know there exists a constant M such that |f(x)| ≤ M
that's exactly what you need for your sandwich
the bread, if you will
wdym generic
uhhh without actually giving a number
I guess that would be impossible
sorry brain fart
can I use 0 for the bottom bread though?
I think not?
Because x * f(x) could be less than 0 in some x
right?
yeah
ty
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how would i solve a logarithmic inequality that has a logarithm as the argument?
give example
for example:
10^(both sides) turns this into log_10(x) < 10^(1/2)
i thik change whatever in the brackets into x aybe/
i'll have x >0 and x>10^sqrt10, right?
and the answer to this inequality would be x<10^sqrt10?
just this, or also x > 0?
can we have x = 1/10?
wouldn't i have x>0 and x>10^sqrt10? why x=1/10?
how are you getting x>10^sqrt10?
also if x>10^sqrt10, then x > 0 is redundant
x < y implies 10^x < 10^y, i.e. the direction of the inequality is preserved when raising 10 to power of each side
x > 10^sqrt10 seems correct
log_10(x) < sqrt10
how? the left-hand side is increasing to infinity
sry not greater
yeah...
mb
that's the part they have wrong
ye, my lazy ass didnt scroll up to read the question again
where would i get x=1/10?
i'm asking you to consider what happens when x = 1/10 since you seem to include that in your solutions
(assuming you have fixed the mistake x>10^sqrt10 to x<10^sqrt10)
i thought the answer to the inequality is x<10^sqrt10, is this wrong?
well you pointed out that we must have x > 0 otherwise the inner logarithm is undefined
but does x = 1/10 satisfy the inequality?
(you should see a problem)
wait in the system of inequalities i'll have x<0 and x<10^sqrt10 so the answer should be x<10^sqrt10. idk where to plug in x=1/10
how did you get x < 0
honestly im following this, and since it says that i should write A>0 i wrote x<0
why would you write x < 0 if A > 0?
because here it's <
no
tushar
the logarithm of 0 or any negative number is undefined
the domain of the log function is the positive real numbers
the options to the question are : A) x<10 B)x<10^sqrt10 C)every real value of x D)1<x<10 E)1<x<10^sqrt10
yes
one of them is correct
you can repeatedly use the following property to derive one of the constraints: x < y implies 10^x < 10^y
so from log_10(log_10(x)) < 1/2 you get log_10(x) < sqrt(10) and hence x < 10^sqrt(10), as you have found
but this is not all, you also have the domain constraints of the log function
for the inner log to be defined, you must have x > 0
however there are tighter restrictions on x that must be placed, which you can see if you try to evaluate the left-hand side of the inequality when x = 1/10
in this case, the outer log becomes undefined, because you get log_10(-1)
thus you must also make sure that the output of the inner log is positive
this is as much guidance that i can give without outright solving the problem for you
@grand meadow Has your question been resolved?
Please, help me 😦 <@&286206848099549185>
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Can I get help understanding the 5 steps mentioned in this video about recursive models? (Time stamp is at that part)
https://youtu.be/ynu0cpyVrto?list=PLhpOtgf9GbnRruVksD0qfd0obHUzJSc4f&t=425
In this video, we discuss a more complicated recursive model and how to go about finding an explicit solution to the model.
Starting with Step 1, I don't understand this...Wouldn't the t values just be the same? What's the point of this?
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i understand how to do it i just need to know how to break the fraction into two
i got an idea on how but i feel like there is a better way
the 5pi/12 to pi/4 and pi/3 how can i get there with any equation
is there like a proccess i can use with any equation
it comes from sin(pi - x) = sin(x)
where x = 5pi/12
it follows sin(7pi/12) = sin(5pi/12)
yes
do you mean how pi/4 + pi/3 is 7pi/12 or what
or how should you know to split it into them
It's an identity
Modus
generally
doing questions like this one
you should focus on how you can express given number as sum (difference) of pi/6, pi/4 or pi/3
because for them values of trig functions are well known
hmm okay
might be also pi, pi/2 etc.
so try to stay with the numbers we already know and use
e.g. sin(pi/12) is not "obvious"
yeah
that's 7pi/12, but in this case it seems harder than pi/4 + pi/3
but might be used
then some trig identites are required
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Is this right?
yes
But how did they get 28
14 * 2
And when you multiply 0.5 by -2 it should be -1 not 2
multiplied by 2 on both sides
Oh
But you only do that if there was a fraction right?
but there is a fraction?
No I mean for example
i dont understand what you mean
Let's say it was 2 instead of 1/2 for example
You still multiply both sides?
no, you multiply by 2 to get rid of the fraction because it looks nicer
but you dont have to multiply if you dont want to
y - 14 = 0.5x - 1
y = 0.5x + 13
just having your answer in this form is fine too
But would the outcome still be the same even tho the answer is completely different?
it'd be the same
multiplying by 2 for both sides would give 2y = x + 26
-x + 2y = 26
x - 2y = -26
Oh now I get it
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In this exercise, i know that when a>3 the limit=inf and when a<3 the limit=0 but what happens when a=3, indetermination?
Wolfram Alpha says that it diverges to infinity but I have no idea why
in my solutions too
how did you attempt to tackle it?
so what can i do, apply the log?
yeah and then take out the x^3 and then simplify it a bit and then use l'hopital (nvm I have actually no clue if that would work lmao)
diverge = does not converge to a value
,w lim x to infinity ((3x^2+4)/(3x^2+2))^(x^3)
it diverges to positive infinity
but it's a indetermination no?
The limit is indeterminate yes
and to solve it, i applied the ln, taking out the x^3 and then the result is (x^3)ln(0) ?
$$\lim_{x \to \infty} \left(\frac{3x^2+4}{3x^2+2}\right)^{x^3} = \mathrm{exp}\left(\lim_{x\to\infty} \frac{\ln\left(\frac{3x^2+4}{3x^2+2}\right)}{1/x^3}\right)$$
tushar
i don't know doing by this way
i show you how i do it
i think that is what you write
but could u explain me the step of dividing x^3?
tushar
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is the method that i used changing the e for A
essentially equivalent
but then, how can i solve the intedermination 0*inf?
rewriting $f(x)^{g(x)}$ as $e^{\ln(f(x)^{g(x)})} = e^{g(x)\ln(f(x))}$
tushar
then since e^x is continuous, we can pass the limit into the exponent
tushar
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formally, you would be arguing: assume that the limit in question exists. then this limit must also exist, which you seek to contradict
okey, now i see it clearly
and then, i transform my 0*inf in a 0/0 indetermination right?
0 * infinity is just 0 / 0 when you bring the infinity to the denominator
which by l'hopital is easy to solve
just dividing by 1/x^3 instead of multiplying by x^3
to get 0/0
yes
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Solve this (D^4+D^2+1)y=e^-(x/2)cos(sqrt3/2 *x) how to solve?
D=d/dx
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Is this correct
<@&286206848099549185>
Also do I need to find extra points
Hello
<@&286206848099549185>
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Is my answer correct?
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<@&286206848099549185>
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how do you graph E
Maybe it's a typo. Or maybe it's -2
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@maiden tree are you here?
yea
Find the midpoint of PQ and use the coordinate of the midpoint and coordinates of S to find the coordinates of R that are inline
This is quite simple. Property of parallelogram is that the diagonals bisect each other. Using this, we can apply midpoint formula to find the point of intersection and then point R as well. Should I do it on paper?
Mid point of SQ would be M ( -6-3/2 , 1-4/2) so M (-4.5,-1.5) then take R (x,y) and x+4 = -9 , y+2= -3. So x = -13, y = -5.
Hope this helps.
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I'm struggling with questions like these. What chapters should I learn before I have strong basics of these
You really only need to know about complex numbers for these ones
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Hello Could I please have some help with this question
the answer is 36
Right and then what would half of a hashtag be worth?
If one hashtag is 18, what’s half of it?
27
how did you get 27
Ex.
If () = 4, then () () () = 3 * () = 3 * 4 = 12
Which means half () = ( = ½ * 4 = 4/2 = 2
() ( = 4 + 2 = 6
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An i on the correct step
I don't know what to do after that assuming I did everything correctly till that point
$e^xsec(x)=0$
ilikecats
$Tan^-1(1)=\pi/4$
@loud spindle Has your question been resolved?
,rotate
I tried it another way
I got pi/4
I don't know how to solve the questions after this?
Because that's not within the interval
I think
I mean 3pi/4
I miss wrote
No idk
They are both values for tan^-1 (1)= pi/4,3pi/4
Idk
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how do I take notes in maths
I seem to remember really well using questions
But I would like advice from someone more experienced
And generally how to approach questions and worked examples
I just try to solve a question till I get it
But I find that very slow and ineffective is there a better way
If so I would really appreciate any advice
For me, I usually like to look at a couple examples to see if there's a certain pattern or pattern of steps when it comes to specific kind of questions before I approach a problem by myself. I also like to reason why they needed to do that step in the problem to get the end result.
honestly, sometimes this is just a thing that you have to do. A lot of getting good in math is working through problems, and just overall practicing
maybe like when taking notes or working through problems question why that step is needed.
I suck at highschool maths so badly tbh
Also what about focus and effort
I cant seem to completely focus on the problem and that leads me to skip or forget a step
have you tried like marking the problem with a star to indicate that you have to go back and try again?
or like mark it with a question mark to ask a teacher
i mean it's okay to struggle. you wouldn't learn anything if you were able to breeze through
I dont think i can do that cuz my o level gce exam is on 9 may
ah i see
I tried improving my basics
And got a bit better
But still suck
Any advice on atleast scoring a C
Anything would really help
while you still can use your school's math resources to get in-person help, they can help narrow down where you are getting stuck
when working through a problem when you get stuck try to solve the problem through other methods for 5-8 minutes, if that can't seem to get through, look up the problem, and work it through the problem with them, and try to understand why they did that step or method
Ok i will try to fix my basics completely in six hours
Then i will try to cover all the main topics
most math follow a set of pattern and reasoning, so knowing that can help with problems
half of the battle is understanding why and how
If its ok could u talk to me in dms about improving and feedback
So how can i know that
it's hard to explain
it just kind of clicks
i know it's not the greatest thing to say, but it will eventually happen
just be patient with yourself, practice a lot, it will eventually click
for me i personally if i get stuck and spend more than 7 minutes trying to figure it out, i usually stop and either look at my notes to see if it helps or look up a step by step answer guide to see how they got there
Is explaining a given example step by step a good way to gain understanding
Cuz thats something i learned recently too
yeah
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M
How do you know the components of a vector field?
How did you get <-y+z, -x+z, x+y>?
Use the definition of the gradient
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been trying to figure out this problem with trig and i'm confused on if ur supposed to subtract 20 from 90 because it's a depressing angle and input 70 in the calculator or use 20.
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Isnt the answer just infinity?
how so
right...well i tried solving the constraints
like obtaining x in terms of y
i got $x=\frac{3y+8}{y-5}$
ItzKraken2
but idk how to proceed from here
i want to verify this before we proceed
Okay 👍
,w sqrt(x-5) + sqrt(y-3) = sqrt(x+y) isolate x
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
so it sounds like you have fucked up your arithmetic somewhere
lemme see
but in any case now you want to maximize y(5y+1)/(y-3) for y ∈ {4, 5, ...}
but how can u maximize..? i mean doesnt this have infinitely many values?
have you never done optimization problems before
nope
you don't need calculus
just some algebra and intuition
so theres only so many values y can take given that
1 sec
i actually did the whole squaring thing
$x+y-8+2\sqrt{xy+8-5x-3y} = x+ y$
ItzKraken2
$2\sqrt{xy+8-5x-3y} = 8$
let's rewrite that, it's better to leave it factored
ItzKraken2
mmm okay 👍
$$2\sqrt{(x-5)(y-3)} + x + y - 8 = x + y$$
Mr. Gamer
now get the square root by itself on one side
ItzKraken2
we square again?
divide by 2 first
ItzKraken2
which gives $(x-5)(y-3)=16$, upon squaring
ItzKraken2
right?
yep, now here's where the geometric intuition comes into play
nah nvm you just have to test the cases
Sooo i do that by looking at factors of 16, find x and y, then xy, then compare?
yes
Okay lemme do that real quick
(1,16), (2,8), (4,4), (8,2), (16,1)
it's not symmetric so you have to include both factor pairs
K
i got xy = 128
x=6, y = 18
from (1,16)
as the maximum
how can y be 18
yes...
then its 114...
there you go
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Max/Min f(x,y) = x^2 + y^2 under the constraint x^2+xy+y^2 = 3
I have a quick question regarding the task above. If we solve this with the lagrange-method we get multiple candidates for the optimization problem. But if I simply solve the constraint for x^2 and then insert it in the original equation I get completely different solutions. Why does that not work?
<@&286206848099549185>
Helperbros I need your help
@mortal depot Has your question been resolved?
<@&286206848099549185>
@mortal depot Has your question been resolved?
<@&286206848099549185>
When I solve x^2+xy+y^2=3 for x I get a solution for x that depends only on y. If I insert it into the original equation and maximize it I get the correct solutions. (although this is quite annoying to do)
When I solve x^2 + xy + y^2 = 3 for x^2 I get a solution for x that depends on x and y. If I insert it into the original equation and maximize it I get wrong solutions.
From a purely theoretical standpoint, why is the second approach invalid?
I am aware that solving via lagrange is much easier, simply curious.
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@mortal depot Has your question been resolved?
rip
@mortal depot Has your question been resolved?
As long as the extrema exist at points where x^2 + xy + y^2 = 3 define a function x in terms of y or y in terms of x you should be fine to use your approach.
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could someone guide me on how to write a quadratic polynomial in standard form
Q=x^t(SDS^t)x+Px+c
@fossil garden Has your question been resolved?
That doesn't look quadratic

Q is a quadratic polynomial here not a quadratic form
@supple knot
or am i missing something
P=[p_1 .. p_n]
and x\in R^n
nvm i did it
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i don’t know how to solve this 
why is this part 0?

