#help-27
1 messages · Page 68 of 1
Then you should know a geometric progression has something called common ratio.
Aware?
ah yes i see
Alright.
So in this question, you would form two equations.
And you have two variables also.
One is this very common ratio.
And the other one is the first term.
So let us assume the first term is a and the common ratio is r.
Alright?
is there any chance u could show me on paper
I could write it down for you.
that would be great thanks
yes
Alright. Before I write anything.
Can you write "nth" term in a geometric progression?
You said you can.
Earlier.
Yes.
which is just 2^n
Yes.
Now, can you do it for general values.
For example, the first term being a and the common ratio being r
nope dont thnk so
What the hell am I doing here?
Isn't this essentially what you did too? When you wrote it earlier.
It's fine.
Now you know.
Now in your question.
You have been given the value of this expression
At n = 4 and n = 6
Right
yes
What the hell am I doing here?
Yes?
whered u get r3 from?
n being 4
oh yes
n-1 would be 3
Now you do the same for 6.
Can you write what the equation is going to be?
It's exactly like this.
a . r ^5 = 5 root 2 / 8
quite confused
We're dividing the equation you wrote by the one I wrote.\
$\frac{ar^5}{ar^3} = \frac{5 \sqrt{2}}{8} \div \frac{5 \sqrt{2}}{4}$
right
What the hell am I doing here?
Right now, look carefully.
40 root 2 over 20 root 2
That one was wrong...
oh 20 root 2 over 40 root 2
Yep.
so its root 2 / 2 root 2
Which is just 1/2
r^2 = 1/2
That's all.
You now have r.
Use the value of r in one of the above-mentioned equations to get a.
And be sure to mention all this in your work, because apparently they want that. And you need a. So figure that out.
wait im confused
how do i use the value sorry
@stuck field
where do i sub it into
1/2
No?
No?
oops
r is neither 2 nor 1/2
r^2 = 1/2
This is what you had.
How do you get from here to r = 2?
sorry
No, don't be sorry. I'm not scolding you or anything. Just asking.
i thought r meant like common ratio or something like that
right ok
well
We're only considering the postive solution.
$r^2 = \f{1}{2}$\
$\sqrt{r^2} = \sqrt{\frac{1}{2}}$
Oops
What the hell am I doing here?
oh i see
So what's r?
root 1 over 2
root 1 is just 1.
So 1/root2
so do i now do 5 root 2 over 4 divided by 1/root 2 cubed?
yes thank you
You're welcome.
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question
a train has a length of 220m
at 09 30 the train crossed a bridge of length 1400m
Calculate the time in seconds that the train took completely cross the bridge
Does it give velocity?
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I'm struggling pretty horribly trying to understand trigonometric identities and how to factor them.
(√2sinx + 1) (√2sinx -1) + (sinx) (sinx) (sinx) (sinx) is as far as i'm getting and I'm just unsure of the steps for factoring a problem like this.
set $z = \sin^2(x)$
Xetrov
^ if you make that substitution it looks like an easily factorable quadratic
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Do you know how to plot straight lines on a graph
youre not finding the slope
youre just setting the two equations equal to find their intersection point
Plot the 2 lines first
When you draw a function on a graph
every point on that line contains pairs of numbers that fit (x, f(x))
By drawing 2 system of equations
The point at which they intersect has the values where (x, f(x)) satisfies both equations
So no
Try substitute in y= 0
Solve for x
So for the first equation y=-x-2
If y=0, x=-2
So the point (-2, 0) is in the function
Do the same for x=0
We choose 0 because it more often than not makes it easier to solve
We just need 2 points then we can draw a straight line through them
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is it possible to plot functions in terms of y into a t-84?
@tight estuary Has your question been resolved?
this might help
In this video, learn how to add the X= feature to your TI-84 Plus CE Graphing Calculator. By enabling this feature, you will be able to graph vertical lines on your calculator.
Use this information to help you be more confident using your calculator!
💡 Check out this calculator tutorial video: https://youtu.be/mIkAPkQzlQQ
🔥 DON'T FORGET to ch...
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OKAY so the question is regarding finding profit and marginal profit for a company based on a model
what is "monthly demand" defined as?
demand is a piece used to find revenue right?
is demand how many people purchase the product?
its the economic term for how much people want to purchase the product
err
how many units of the product will be sold based on consumers willing the purchase
but anyways
So I start by creating a model for profit
which would be R = x((60000-x)/20000) to get revenue and then
P = x((60000-x)/20000) * (50000+.56x) right?
profit = revenue - expenses so why are you multiplying?
....Oh damn I didn't even notice LOL
so changing the sign to -,
I'd do P(20001) - P(20000) right?
or could/should I simplify it first?
...
@dry robin
Uhhhh??
@tranquil hare Has your question been resolved?
@tranquil hare Has your question been resolved?
.close
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how would i even figure this out
.close
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Im confused with proofs
I tried HL it didn't work and even though sss works where all sides are equivalent it said it wasn't congruent
k so idr this stuff tbh
but
i reccomend
zooming the pic in
kinda unclear
for those that can help
prolly be easier to for clear pic
yea that stuff is clear
sorry i cant help
but for those that can
this is better
oh
ok
last time i did somethign like that and no one told me and i got the assignment late
so i thought itd be better to let you know
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#27 and 28
@weary canopy Has your question been resolved?
,rotate
Having trouble with this. I know it’s not B or C so it’s gotta be A or D, but I can’t figure them out
Please create a separate help channel #❓how-to-get-help
28 is also wrong, try writing cos(theta) first
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what are the symptoms of your wrongness?
oh, may you perhaps have incorrectly normalized the second column?
the norm of [2; 1; -2] is not sqrt(5).
columnwise normalization feels like something you could have done programmatically, by the way.
if you're using python anyway...
It is given that BB^{T} is an identity matrix
(in the answer)
Are there any other mistakes I've made?

do you ask because you are second-guessing yourself or because you are getting a wrong-answer popup in your face
This was the output and it's not the answer I'm supposed to get.
that's because the answer is a set of four binary choices, i would think.

you are presented with four checkboxes
presumably, the choice of ticking or not ticking each of those boxes would constitute the answer to the problem.
and that is a different beast than the matrix numpy outputs for you.
Yes, it's a Multiple Select question (MSQ)
cool, that gave us zero new info.
i'm saying that there is nothing strange about your output not being the answer.
It is given in the answer key that BB^{T} is the identity matrix
However this was what I got.
yes
can you tell me what the value of the (2, 1) entry of your matrix is
or at least its order of magnitude
-1.00636560 * 10^{-16}
x for multiplication grumble grumble
but yes, it is something on the order of 10^-16.
that should strike you as familiar if you know anything about how numbers are usually stored in computers.
if it does not, then say so.
you could also use sympy or similar symbolic thing and not deal with stuff like this
i think there is value in at least knowing about stuff like this.
but i shan't say a word until hazysleet tells me he knows it or doesn't but wants to.
I mean yeah definitely, like this is basic mathematical understanding / debugging skills
I don't know.
No, I wanna know
do you know what the e-16 means
so how big is the number in that slot?
so what can you say about the output that you gave?
The numbers with e-16 and e-17 are very close to zero
But, why is it like this?
Is this how python works with numbers

do you think a computer can store an infinite number of decimal digits?
No.
so what would you expect
okay so suppose it does that
why do you expect the output to be exactly the identity then?
spoilers at the end: ||a double-precision floating point number can store about 16 or 17 decimal digits' worth of significant figures||
you can also use sympy which doesn't store the numbers themselves if it's inexact
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gcd(b,c) is a common divisor of a and b
yes it is
so it has to be <= the greatest common divisor
how
by definition of what greatest means
same thing just rearranged
why is it now gcd(a,b) <= gcd(b,c);
gcd(a,b) is a common divisor of b and c
so it has to be <= their greatest common divisor
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Find k every value for which p(-1;2x;x²) and q(5;k;k) vectors make acute angle for any x value
@fleet gorge Has your question been resolved?
<@&286206848099549185>
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can anyone tell me why is this wrong? my teacher said finding the solution is tricky, and it could be more than one answer
What is the above tree diagram?
i think they talk about problem 3
@lost gazelle Has your question been resolved?
B can play so that A cannot win. maybe they mean that? otherwise not sure what your teacher means
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h = 32000/x^2 no? That's the first thing I see that may cause issues
Second, using product rule seems unnecessarily complicated for the 2nd term
I'd say so
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Can someone help me please?
@tulip crown Has your question been resolved?
<@&286206848099549185>
,rotate
what inequalities do you know
I dont know how to solve it
I found that the function x*arctan(x) -ln(x^2-1) is increasing
But i don t know how to continue
@supple knot if you know some inequality that might help please tell me
x^2-1 or x^2 + 1?
+1
if you did this on the right interval, then you're done?
Sorry
f(x) <= g(x) implies int f(x) <= int g(x)
maybe 0<=f(x) is also needed but you have that in this case
what domain did you prove this for
then yea you're done?
Why?
unless you need to prove this
what's p
what's f and g here?
for your problem i mean
x*arctanx and ln(x^2+1)
reversed, but yea
I need to show that the function h , where h(x)= x*arctanx-ln(x^2+1) is bigger than 0
no you don't
you need to show log(x^2 + 1) >= 0
Well that doesen t solve my problem
yes it does
type explicitly what f(x)=? and g(x)=? equals
these are your two options
to plug into this
If h is bigger than 0 that means x*arctanx>ln(x^2+1) thus int of f(x) > int g(x)
f(x)=x*arctan(x)
nope
.
following this
this eliminates the need for your h(x) altogether
are you SURE you understand this?
Yes
rearrange this and express this function in terms of f(x) and g(x)
again noting this
no
What no
do you understand what this means?
Why nope
.
You asked me to write what g and f are
And how do you plan to solve it
you're just confusing yourself by inventing a new function
this is all you need
and the one after
How do you show that f(x)<g(x)
you said you already did that
you're just proving the integral inequality aren't you?
I did not
I did not

I proved that g-f is increasing
this
implies this
Well it is clear to me that you dont know what increasing means
It doesent mean that g-f is bigger than 0
yes you also need a domain. which you already said you found
which is why i asked it early on
Yes, and mai question was how do i prove that -f(sqrt(2))+g(sqrt(2)) is bigger than 0
where did you ask this
...
where did you define f here?
Because you firstly reffered to x*arctanx-ln(x^2+1) as f(x)
where
idk do i even know what increasing is?
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]
which part
entire thing
how do ik if it's bias or not
i was gonna say
it's bias because
relative frq isn't the same for all
so you can work out the relative frequencies right?
yes
somewhat
it says an unbiased dice would have 50 for each
o
relative freq is just freq/300 here
i gte that\
went a lot harder very quickly lmaoo
yuh
no
@restive river Has your question been resolved?
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can you tell if a quadratic function function is even or odd by looking at its power, for example x^2 - 9x + 7 is even?
are there any odd quadratic functions?
are you sure the question isn't about even or not even?
Well I just came up with it at the top of my head
I just want to know how to determine if a quadratic function is odd or even
I know x^3 is odd and x^4 even and x^1 is odd
I want to know if that sort of rule applies to when there’s other variables in the function
those are polynomial functions
quadratics are either even, or if they are adjusted off of the origin (like it would be if you say subtract 9x) then they are neither even nor odd
but they are never odd
for polynomials without any sort of adjustment it depends on the power of x, so is x is raised to an even power it is even, and if to an odd power it is odd
and quadratics specifically are polynomials of degree 2, meaning they are raised to an even power of 2
so if they aren't adjusted off the origin they will be even
@smoky gyro Has your question been resolved?
Oh okay
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How i know if a interval is continous
you mean function is continuous on the interval?
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could someone walk me through this problem?
For the following exercises, eliminate the parameter t to rewrite the parametric equation as a Cartesian equation.
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
Recall that $e^{-2t} = (e^{-t})^2$. This means that $x = (e^{-t})^2$. Isolate $e^{-t}$ in terms of $x$.
Umbraleviathan
@supple knot starting to think it's a bit hard to read or nah?
im still confused, could i do this in terms of ln?
Astassa
Yeah but I would just keep it as $\sqrt{x} = e^{-t}$
Umbraleviathan
Because $y = 2e^{-t}$
Umbraleviathan
So you just replace e^-t
i think it's fine!
Yeah
Astassa
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how would one go about c
it is clear that 3SAT is in NP
is there an easy way to write any SAT into a 3SAT?
i think i know how to deal with an even number of literals per clause
but then
how do you deal with odd numbers of literals
suppose you have 4 literals
x1 or x2 or x3 or x4
is it valid to write y1 = x3 or x4
and then write
x1 or x2 or y1 = x1 or x2 or x3 or x4
yes
.close
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I have a lot of potatoes, oil, and rice at home, but I would like to eat sushi. What to do? My Japanese neighbour will surely give me wasabi if I bring her both beef and fries. With potatoes and oil, I can make fries as well as potato salad (as much as required, of both). For sushi, I need fish and rice and wasabi. My other neighbor (who just turned veggie) will certainly give me fish and beef if I get him some rice and potato salad.So in the end, will I be able to have my sushi? Please answer this question using resolution.
discrete math problem
@pseudo jacinth Has your question been resolved?
@pseudo jacinth Has your question been resolved?
@pseudo jacinth Has your question been resolved?
what have you tried
this seems like an application of some everyday logic
maybe you have to formalize it but you should at least be able to answer the question with a yes/no
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how would i split this up to use partial fractions?
A/x + (Bx+C)/(x² + 2x + 5)
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how do you do 21a?
have you tried drawing it out
I can't really draw it out if i don't know any points
i wouldve done $A = \frac{1}{2}| (A_2 - A_1) \cross (A_3 - A_1)|$
doctor99268
what is A1 A2 A3
the question litearlly tells you
@hexed ocean they are coordinates
vector coordinates
@hexed ocean how much of vectors have you learnt
let me see
oh i havent learnt crap about them
we went over them for a few weeks
but thats it
then you wont know how to use my method
:(
whats that
to put it simply, the cross product between 2 vectors, gives another vector that is perpendicular to both of them
ah ok
and the magnitude of that vector is the area of the parralelogram made by the 2 vectors
and since the triangle area is half that area
its why i did 1/2
you can achieve the same area though
if you just draw everything out
but for me i find that very long
I can probably do it with distance formulas and what not
but idfk what they mean by making trapeziums
and dropping perpendiculars
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@hexed ocean
this is what they mean
find the area of the triangle
by findin the area of the total rectangle
and minusing it from the areas that arent the triangle
youll get the right answer by doing this
honestly though, you should learn what cross product is, itll be advanced for you, but it makes vectors alot easier
like, if two vectors are collinear
the cross product between them is 0
doing the cross product itself is just something you memorise
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Hello i wanna check this result but wolfarmalpha is not responding ,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi = n!/k^(n+1)/m
whats the integral meant to be
,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi
This ^^
too many constants bro
wtf is the original problem lol
Isn’t that similar to gamma function?
Its not a problem its just a general result that is mentioned in our book
Ann
@restive river is it this result
In the power those n+1/m are together
ok then you misplaced your parentheses
and it's meant to be $$\int_0^{+\infty} x^n e^{-kx^m} \dd{x} \overset?= \frac{n!}{k^{(n+1)/m}}$$
Ann
i am highly sus of it tho
But why it is not responding to this input?

for n=0, k=1, m=2 it gives 1 as the value of the integral
and yet
,w int[0,infty] exp(-x^2) dx
what, exp(-x^2)?
No
Oh can you please share?
For this
ok then out with it
I do know how to calculate using u sub but it will take ages
,rccw
x=alpha?
,w integrate x²e^(-alphax⁴) dx from 0 to infi
Uh its a question that i solved which involves this result
So just to verify
Itbwas this precisely
Uh
So the numerator should be (-1/4)!
If it was ((1-n)/m)! Then it would have made sense
But i am really not sure
,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi where n=1,k=1,m=827
,w ((1-n)/m)!/(m(k^((n+1)/m))), where n=1,k=1,m=827
,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi where n=1,k=1,m=8
,w ((1-n)/m)!/(m(k^((n+1)/m))), where n=1,k=1,m=8
,w calc gamma(2/827)/827
,w (1/((k ^ ((n + 1)/m) * (m))) * ((n - m + 1)/m)!), m=2, n=2, k=1
,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi where m=2, n=2, k=1
,w Gamma symbol capital
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i have a problem
i want to put in {7 <= y <= 10} but it doesnt let me
whenever i put it in, the line on the graph disappears immediately
i want the line to show just from y = 7 to y = 10
i put it in a blank one
it still disappears
does it show you a ⚠️ symbol
yes
what does it say if you click on that
oh
it only works for x and y
because i put z in there
is there any way to fix?
or do i just change back to x as variable
... you didn't tell me what it says when you click on the warning symbol
ah yeah
i was just trynna make it smth diff, not x
but ig i have to make it x
ty
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can someone explain steps pls
For the first fraction, multiply $(x^{2}+5x+4)$ to the numerator and denominator
RomeNunt
first one as in (2x-5)/(x^2+5x+4)?
Sorry do u mind explaining a little more in depth
it's not making sense to me
Could you vc, it's hard to explain with text
nah, vc private
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what do they mean by a function f from [1,5] to [1,7]
domain = [1,5] and [1,7] is the codomain
ohhhh
so pi should lie in its co-domain?
yeah
yw :)
is it just me or are all true?
yeah
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How I find the volume of the body limited by this equation in cylindrical coordinates?
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For elimination you need the same x or y, in this case none are the same
So you can find the lcm and then multiply to get the same number
For x it would be the least common multiple of 250 and 1, which is 250 so you multiply the bottom equation by 250
For y it would be the least common multiple of 150 and 1, which is 150 so you multiply the bottom equation by 150
Yeah true, the top equation can be simplified to 5x - 3y = 43 but it’s not needed
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Hi can someone help me? I have to prove that the only null Lagrangians are the total derivatives?
The converse is easy to enough to prove
To be precise I am only interested in the case for a Lagrangian with up to second order derivatives
I tried this but
Got stuck with this pde
is this a right triangle
This was after proving that a null lagrnagian must be a of the form g(x,y,')y"+h(x,y,y')
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No
MDC is a right triangle
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can someone help me solve this equation? https://gyazo.com/ce5e4d058964d2d8e614db66c5fd81f3
I think you might be going the wrong way using the tan fucntion
and having a cosx as the denominator
I checked It should work since cosx is not = 0
although I do not see any other way atm
I'd suggest you try to use the fact that cos(a-b)=cosacosb+sinasinb
you know that indentity ?
yes
aight lemme give you a hint
yes
using the identity I told you aboce
above
and now you can solve knowing that x is in 0 2pi
although how did you get this?
you know 1/2 = cos(pi/3)
yes
although I do not know how I would think of this on my own (;
for the trig functions
yea no problem it'll come with time
I mean I haven't fully thought about, it might work
juste seems pretty sketchy
yea yea it's allowed cause 0 pi and 2pi arent solutions
but we don't really knoiw how to solve these kinds of equations
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Need help with understanding spectral decomposition. I understand that it is supposed to be a way to express a matrix as a sum of spectral matricies and eigenvalues like $$A=\lambda_1 v_1 v^T + \lambda_2 v_2 v^T ...$$ but when I attempted to find the SD of $$A =\begin{pmatrix} 4 & 1 \ 1 & 4\end{pmatrix}$$, I ended up getting the original matrix times 2.
$$\lambda_1=5, v_1 = \begin{pmatrix} 1 \ 1\end{pmatrix} \lambda_2=3, v_2 = \begin{pmatrix} -1 \ 1 \end{pmatrix}$$
$$5 \begin{pmatrix} 1 & 1 \ 1 & 1 \end{pmatrix}+3 \begin{pmatrix} 1 & -1 \ -1 & 1 \end{pmatrix} = \begin{pmatrix} 8 & 2 \ 2 & 8 \end{pmatrix}$$
plz halp :3
Giga5
do I have to normalize the eigenvectors first?
yes
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hello, I am stuck in solving this task, we are not allowed to use L'hopital's rule I need to expand the fraction with something, I tried both the upper and lower part but I can't finish it. (Btw solution is -1)
you probably want to rationalise the denominator
I tried to do the difference of squares above, but the lower part of the fraction is constantly tending to zero
difference of squares how?
,rotate
well you have to multiply it out and simplify
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,rotate
oh i missed it the first time. you rationalized the numerator instead of the denominator
should be sqrt(1+x) +1 instead
Okey, now this ugly part is up, it needs another rationalization, but how? This is a new topic to me i am really sorry if i am a bit boring😅
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Hey guys can you please check if I did this question correctly?
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<@&286206848099549185>
Come on guys I spent 9 hours thinking about this question 😩
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What is the problem?
<@&286206848099549185>
<@&286206848099549185>
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is the following statement correct?
If the enlargement factor is F, then the pressure on the bottom face of the cuboid is = pressure * F.
you are using the letter F to refer to two different things are you not
so it means that is the enlargemnt factor is 25 then force in the eqaution of pressure is also 25
at least thats what i thinl
thats the qeustion that i was asked
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benevo
but how
V is volume
n is moles (quantity of gas)
R is a constant
T is the temp. of the room```
because the gas is in a sealed vessel n cannot change, and T is ignored as it assumed that the gas will reach the same room temp after some time as in the initial conditions.
and because r is a constant it can be ignored
so we have the simplified formula for gas pressure change with volume change
$PV=C$
benevo
where C simply remains constant
P is the pressure of the gas, to find force you multiply the pressure by the area it is exerted upon to get a force measurement.
$Pressure * Area = Force$
benevo
does this all make since so far?
ya
can you finish the problem with the information I have provided?
ya i think so
respond to my last message if that changes, good luck. :)
ok, thanks a bunch
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@jade falcon Has your question been resolved?
i need help
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