#help-27

1 messages · Page 68 of 1

trail apex
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i dont

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oh yes i do sorry nvm

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@stuck field

stuck field
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Then you should know a geometric progression has something called common ratio.

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Aware?

trail apex
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yes

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same number is used to multiply right

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?

stuck field
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Yes.

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2,4,8...
2 is the common ratio.

trail apex
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ah yes i see

stuck field
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Alright.

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So in this question, you would form two equations.

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And you have two variables also.

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One is this very common ratio.

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And the other one is the first term.

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So let us assume the first term is a and the common ratio is r.

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Alright?

trail apex
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is there any chance u could show me on paper

stuck field
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I could write it down for you.

trail apex
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that would be great thanks

stuck field
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But not on paper.

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I'll use LaTeX it should be fine?

trail apex
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yes

stuck field
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Alright. Before I write anything.

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Can you write "nth" term in a geometric progression?

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You said you can.

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Earlier.

trail apex
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yes

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2,4,8,16 would be 2x2^n-1 right

stuck field
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Yes.

trail apex
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which is just 2^n

stuck field
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Yes.

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Now, can you do it for general values.

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For example, the first term being a and the common ratio being r

trail apex
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nope dont thnk so

woven radishBOT
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What the hell am I doing here?

stuck field
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Isn't this essentially what you did too? When you wrote it earlier.

trail apex
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oh right yes

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i do i just didnt know it was in that form

stuck field
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It's fine.

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Now you know.

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Now in your question.

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You have been given the value of this expression

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At n = 4 and n = 6

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Right

trail apex
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yes

stuck field
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So, if you put say n = 4

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You'd have

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$a \cdot r^3 = \frac{5\sqrt{2}}{4}$

woven radishBOT
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What the hell am I doing here?

stuck field
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Yes?

trail apex
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whered u get r3 from?

stuck field
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n being 4

trail apex
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oh yes

stuck field
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n-1 would be 3

trail apex
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u subtract from 1

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yes sorry

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right waht next

stuck field
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Now you do the same for 6.

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Can you write what the equation is going to be?

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It's exactly like this.

trail apex
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a . r ^5 = 5 root 2 / 8

stuck field
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Yes.

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Now, well.

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You have two equations and two variables.

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Can you solve them?

trail apex
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r2 = 4?

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idk rlly

stuck field
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well.

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You could divide the two equations.

trail apex
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quite confused

stuck field
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We're dividing the equation you wrote by the one I wrote.\
$\frac{ar^5}{ar^3} = \frac{5 \sqrt{2}}{8} \div \frac{5 \sqrt{2}}{4}$

trail apex
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right

stuck field
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Wrong.

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Lol. I wrote wrong, wait.

woven radishBOT
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What the hell am I doing here?

stuck field
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Right now, look carefully.

trail apex
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40 root 2 over 20 root 2

stuck field
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That one was wrong...

trail apex
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oh 20 root 2 over 40 root 2

stuck field
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Yep.

trail apex
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so its root 2 / 2 root 2

stuck field
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Which is just 1/2

trail apex
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ye

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whats next?

stuck field
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r^2 = 1/2

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That's all.

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You now have r.

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Use the value of r in one of the above-mentioned equations to get a.

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And be sure to mention all this in your work, because apparently they want that. And you need a. So figure that out.

trail apex
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wait im confused

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how do i use the value sorry

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@stuck field

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where do i sub it into

stuck field
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First

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r = ?

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You tell me.

trail apex
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1/2

stuck field
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No?

trail apex
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oh 2

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sorry wrong way around

stuck field
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No?

trail apex
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oops

stuck field
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r is neither 2 nor 1/2

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r^2 = 1/2

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This is what you had.

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How do you get from here to r = 2?

trail apex
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sorry

stuck field
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No, don't be sorry. I'm not scolding you or anything. Just asking.

trail apex
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i thought r meant like common ratio or something like that

stuck field
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it is that.

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I'm just saying, r^2 = 1/2

trail apex
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right ok

stuck field
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well

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We're only considering the postive solution.

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$r^2 = \f{1}{2}$\
$\sqrt{r^2} = \sqrt{\frac{1}{2}}$

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Oops

woven radishBOT
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What the hell am I doing here?

trail apex
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oh i see

stuck field
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So what's r?

trail apex
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root 1 over 2

stuck field
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root 1 is just 1.
So 1/root2

trail apex
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so do i now do 5 root 2 over 4 divided by 1/root 2 cubed?

stuck field
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Yes.

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That's a, which is what you needed.

trail apex
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yes thank you

stuck field
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You're welcome.

trail apex
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.clos

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.close

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timid sonnet
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question

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timid sonnet
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a train has a length of 220m

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at 09 30 the train crossed a bridge of length 1400m

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Calculate the time in seconds that the train took completely cross the bridge

ancient furnace
pseudo basin
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new channel opened

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pseudo basin
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jagged orbit
#

I'm struggling pretty horribly trying to understand trigonometric identities and how to factor them.

(√2sinx + 1) (√2sinx -1) + (sinx) (sinx) (sinx) (sinx) is as far as i'm getting and I'm just unsure of the steps for factoring a problem like this.

woven radishBOT
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Xetrov

south shard
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^ if you make that substitution it looks like an easily factorable quadratic

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devout snowBOT
jaunty mantle
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Do you know how to plot straight lines on a graph

nova idol
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youre not finding the slope

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youre just setting the two equations equal to find their intersection point

jaunty mantle
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Plot the 2 lines first

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When you draw a function on a graph

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every point on that line contains pairs of numbers that fit (x, f(x))

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By drawing 2 system of equations

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The point at which they intersect has the values where (x, f(x)) satisfies both equations

jaunty mantle
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Try substitute in y= 0

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Solve for x

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So for the first equation y=-x-2

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If y=0, x=-2

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So the point (-2, 0) is in the function

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Do the same for x=0

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We choose 0 because it more often than not makes it easier to solve

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We just need 2 points then we can draw a straight line through them

devout snowBOT
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@restive river Has your question been resolved?

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@restive river Has your question been resolved?

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tight estuary
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is it possible to plot functions in terms of y into a t-84?

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light fractal
#

this might help

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tranquil hare
#

OKAY so the question is regarding finding profit and marginal profit for a company based on a model

tranquil hare
light fractal
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what is "monthly demand" defined as?

tranquil hare
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demand is a piece used to find revenue right?

light fractal
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is demand how many people purchase the product?

tranquil hare
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its the economic term for how much people want to purchase the product

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err

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how many units of the product will be sold based on consumers willing the purchase

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but anyways

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So I start by creating a model for profit
which would be R = x((60000-x)/20000) to get revenue and then
P = x((60000-x)/20000) * (50000+.56x) right?

light fractal
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profit = revenue - expenses so why are you multiplying?

tranquil hare
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....Oh damn I didn't even notice LOL

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so changing the sign to -,

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I'd do P(20001) - P(20000) right?

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or could/should I simplify it first?

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...

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@dry robin

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Uhhhh??

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@tranquil hare Has your question been resolved?

tranquil hare
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.close

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pine phoenix
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how would i even figure this out

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pine phoenix
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.close

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cloud thicket
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cloud thicket
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Im confused with proofs

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I tried HL it didn't work and even though sss works where all sides are equivalent it said it wasn't congruent

pulsar hinge
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k so idr this stuff tbh

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but

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i reccomend

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zooming the pic in

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kinda unclear

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for those that can help

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prolly be easier to for clear pic

cloud thicket
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is this fine?

pulsar hinge
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yea that stuff is clear

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sorry i cant help

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but for those that can

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this is better

cloud thicket
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?

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should i start over from the beginning?

pulsar hinge
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no no what i mean is i dont remeber this stuff

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if orgot it

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but

cloud thicket
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oh

pulsar hinge
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yea

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someone who does

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they will help

cloud thicket
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ok

pulsar hinge
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last time i did somethign like that and no one told me and i got the assignment late

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so i thought itd be better to let you know

cloud thicket
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ok

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do I end the session?

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or wait?

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.close

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weary canopy
#

.ask Can someone tell me if I’m doing these 2 problems correct please

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weary canopy
#

#27 and 28

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#

@weary canopy Has your question been resolved?

jolly merlin
#

,rotate

woven radishBOT
jolly merlin
#

@weary canopy

burnt breach
#

Having trouble with this. I know it’s not B or C so it’s gotta be A or D, but I can’t figure them out

jolly merlin
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jovial mauve
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jovial mauve
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I tried to use python to solve this.

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I couldn't find where I'm going wrong

pseudo basin
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what are the symptoms of your wrongness?

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oh, may you perhaps have incorrectly normalized the second column?

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the norm of [2; 1; -2] is not sqrt(5).

jovial mauve
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After changing the norm to sqrt(9), this was the output

pseudo basin
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columnwise normalization feels like something you could have done programmatically, by the way.

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if you're using python anyway...

jovial mauve
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It is given that BB^{T} is an identity matrix

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(in the answer)

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Are there any other mistakes I've made?

pseudo basin
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do you ask because you are second-guessing yourself or because you are getting a wrong-answer popup in your face

jovial mauve
# jovial mauve

This was the output and it's not the answer I'm supposed to get.

pseudo basin
#

that's because the answer is a set of four binary choices, i would think.

jovial mauve
pseudo basin
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you are presented with four checkboxes

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presumably, the choice of ticking or not ticking each of those boxes would constitute the answer to the problem.

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and that is a different beast than the matrix numpy outputs for you.

jovial mauve
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Yes, it's a Multiple Select question (MSQ)

pseudo basin
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cool, that gave us zero new info.

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i'm saying that there is nothing strange about your output not being the answer.

jovial mauve
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It is given in the answer key that BB^{T} is the identity matrix

jovial mauve
pseudo basin
#

yes

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can you tell me what the value of the (2, 1) entry of your matrix is

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or at least its order of magnitude

jovial mauve
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-1.00636560 * 10^{-16}

pseudo basin
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x for multiplication grumble grumble

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but yes, it is something on the order of 10^-16.

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that should strike you as familiar if you know anything about how numbers are usually stored in computers.

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if it does not, then say so.

vast rain
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you could also use sympy or similar symbolic thing and not deal with stuff like this

pseudo basin
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i think there is value in at least knowing about stuff like this.

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but i shan't say a word until hazysleet tells me he knows it or doesn't but wants to.

vast rain
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I mean yeah definitely, like this is basic mathematical understanding / debugging skills

pseudo basin
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but do you want to know?

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maybe you wish to remain ignorant.

jovial mauve
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No, I wanna know

vast rain
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do you know what the e-16 means

jovial mauve
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Yes

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It's 10^{-16}

vast rain
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so how big is the number in that slot?

jovial mauve
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It's very small

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of order 10^{-16}

vast rain
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so what can you say about the output that you gave?

jovial mauve
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The numbers with e-16 and e-17 are very close to zero

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But, why is it like this?

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Is this how python works with numbers

vast rain
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do you think a computer can store an infinite number of decimal digits?

jovial mauve
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No.

vast rain
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so what would you expect

jovial mauve
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Store it up to certain significant digits

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?

vast rain
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okay so suppose it does that

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why do you expect the output to be exactly the identity then?

pseudo basin
#

spoilers at the end: ||a double-precision floating point number can store about 16 or 17 decimal digits' worth of significant figures||

jovial mauve
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I understand

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This problem was to be solved using hands

vast rain
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you can also use sympy which doesn't store the numbers themselves if it's inexact

jovial mauve
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But, I pulled out python and learnt something today

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Hmm

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torpid ocean
#

I'm confused about proeprty 6 proof

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why is it that gcd(b,c) <= gcd(a,b)

stone stump
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gcd(b,c) is a common divisor of a and b

torpid ocean
#

yes it is

stone stump
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so it has to be <= the greatest common divisor

torpid ocean
#

how

stone stump
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by definition of what greatest means

torpid ocean
#

sure

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but what about c = a- qb

stone stump
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same thing just rearranged

torpid ocean
#

why is it now gcd(a,b) <= gcd(b,c);

stone stump
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gcd(a,b) is a common divisor of b and c

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so it has to be <= their greatest common divisor

torpid ocean
#

hmm okay thanks

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fleet gorge
#

Find k every value for which p(-1;2x;x²) and q(5;k;k) vectors make acute angle for any x value

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fleet gorge
#

<@&286206848099549185>

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fleet gorge
#

This is so bs

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.close

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lost gazelle
#

can anyone tell me why is this wrong? my teacher said finding the solution is tricky, and it could be more than one answer

topaz beacon
#

What is the above tree diagram?

left robin
#

i think they talk about problem 3

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@lost gazelle Has your question been resolved?

lost gazelle
#

yes

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problem 3

stone stump
#

B can play so that A cannot win. maybe they mean that? otherwise not sure what your teacher means

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tall knoll
#

h = 32000/x^2 no? That's the first thing I see that may cause issues

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Second, using product rule seems unnecessarily complicated for the 2nd term

#

I'd say so

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tulip crown
#

Can someone help me please?

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@tulip crown Has your question been resolved?

tulip crown
#

<@&286206848099549185>

#

arctg(x) is arctan(x)

tulip crown
#

<@&286206848099549185>

supple knot
#

,rotate

woven radishBOT
supple knot
#

what inequalities do you know

tulip crown
#

I dont know how to solve it

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I found that the function x*arctan(x) -ln(x^2-1) is increasing

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But i don t know how to continue

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@supple knot if you know some inequality that might help please tell me

supple knot
tulip crown
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+1

supple knot
tulip crown
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Sorry

supple knot
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f(x) <= g(x) implies int f(x) <= int g(x)

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maybe 0<=f(x) is also needed but you have that in this case

tulip crown
#

Well i dont know how to show that f(sqrt(2) )>0

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How

supple knot
tulip crown
#

The domain neede for the integral ,[sqrt(2),sqrt(3)]

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Nedeed*

supple knot
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then yea you're done?

tulip crown
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Why?

supple knot
tulip crown
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I know that

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But why is it bigger than 0

supple knot
#

what's p

tulip crown
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0

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Sorry

supple knot
#

for your problem i mean

tulip crown
#

x*arctanx and ln(x^2+1)

supple knot
#

reversed, but yea

tulip crown
#

I need to show that the function h , where h(x)= x*arctanx-ln(x^2+1) is bigger than 0

supple knot
#

no you don't

supple knot
tulip crown
#

Well that doesen t solve my problem

supple knot
#

yes it does

supple knot
supple knot
supple knot
tulip crown
#

If h is bigger than 0 that means x*arctanx>ln(x^2+1) thus int of f(x) > int g(x)

#

f(x)=x*arctan(x)

supple knot
supple knot
supple knot
supple knot
tulip crown
#

I dont understand

#

Lets start again

supple knot
tulip crown
#

Yes

supple knot
supple knot
tulip crown
#

let f(x) be x* arctanx and g(x) be ln(x^2+1)

#

So the function h =f-g

tulip crown
#

What no

supple knot
tulip crown
#

Why nope

supple knot
tulip crown
#

You asked me to write what g and f are

supple knot
#

reversed means you had them swapped

tulip crown
#

K

#

So h is g-f

supple knot
#

you don't need h at all

#

stop using h

tulip crown
#

And how do you plan to solve it

supple knot
#

you're just confusing yourself by inventing a new function

supple knot
supple knot
tulip crown
#

How do you show that f(x)<g(x)

supple knot
#

you said you already did that

supple knot
tulip crown
#

I did not

tulip crown
supple knot
tulip crown
#

I proved that g-f is increasing

supple knot
supple knot
tulip crown
#

Well it is clear to me that you dont know what increasing means

#

It doesent mean that g-f is bigger than 0

supple knot
supple knot
tulip crown
#

Yes, and mai question was how do i prove that -f(sqrt(2))+g(sqrt(2)) is bigger than 0

tulip crown
#

There f was h

supple knot
#

...

supple knot
tulip crown
#

Because you firstly reffered to x*arctanx-ln(x^2+1) as f(x)

supple knot
#

they're the SAME f(x)

tulip crown
#

Ok

#

So can you help me with showing that h(srtq(2)) >0

supple knot
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restive river
devout snowBOT
restive river
#

y

#

ion get it

keen nacelle
#

which part

restive river
#

entire thing

restive river
#

i was gonna say

#

it's bias because

#

relative frq isn't the same for all

keen nacelle
#

so you can work out the relative frequencies right?

keen nacelle
restive river
keen nacelle
#

it says an unbiased dice would have 50 for each

keen nacelle
#

300/6 sides

#

is 50

restive river
#

hol

#

y

#

also

keen nacelle
restive river
#

mind explaining

restive river
restive river
#

precalc

keen nacelle
#

went a lot harder very quickly lmaoo

restive river
#

i got sent this

#

idk what this is

restive river
keen nacelle
#

idk calculus

#

but i can try from what ive heard

lilac frost
keen nacelle
#

i thibk

restive river
keen nacelle
#

what is it

#

@restive river

restive river
#

no clue

#

help

devout snowBOT
#

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@restive river Has your question been resolved?

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smoky gyro
#

can you tell if a quadratic function function is even or odd by looking at its power, for example x^2 - 9x + 7 is even?

supple knot
#

are there any odd quadratic functions?

#

are you sure the question isn't about even or not even?

smoky gyro
#

I just want to know how to determine if a quadratic function is odd or even

#

I know x^3 is odd and x^4 even and x^1 is odd

#

I want to know if that sort of rule applies to when there’s other variables in the function

weak cove
#

those are polynomial functions

#

quadratics are either even, or if they are adjusted off of the origin (like it would be if you say subtract 9x) then they are neither even nor odd

#

but they are never odd

#

for polynomials without any sort of adjustment it depends on the power of x, so is x is raised to an even power it is even, and if to an odd power it is odd

#

and quadratics specifically are polynomials of degree 2, meaning they are raised to an even power of 2

weak cove
#

so if they aren't adjusted off the origin they will be even

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jolly swan
#

How i know if a interval is continous

devout snowBOT
scarlet sequoia
#

you mean function is continuous on the interval?

jolly swan
#

yea

#

for example sqrt 4-x^2 on [-2,2]

#

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uneven bloom
#

could someone walk me through this problem?
For the following exercises, eliminate the parameter t to rewrite the parametric equation as a Cartesian equation.

hybrid snow
#

!status

devout snowBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
uneven bloom
#

1

hybrid snow
#

Recall that $e^{-2t} = (e^{-t})^2$. This means that $x = (e^{-t})^2$. Isolate $e^{-t}$ in terms of $x$.

woven radishBOT
#

Umbraleviathan

hybrid snow
#

@supple knot starting to think it's a bit hard to read or nah?

uneven bloom
#

im still confused, could i do this in terms of ln?

hybrid snow
#

I wouldn't

#

There's a much easier way

#

Im showing you the easier way

uneven bloom
#

ok

#

so it turns into $sqrt(x)=\frac{1}{e^{t}}$?

woven radishBOT
#

Astassa

hybrid snow
#

Yeah but I would just keep it as $\sqrt{x} = e^{-t}$

woven radishBOT
#

Umbraleviathan

hybrid snow
#

Because $y = 2e^{-t}$

woven radishBOT
#

Umbraleviathan

hybrid snow
#

So you just replace e^-t

uneven bloom
#

ok

#

so the answer is $y=2\sqrt{x}$?

hybrid snow
#

Yeah

woven radishBOT
#

Astassa

uneven bloom
#

alright thank you!

#

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hollow pollen
#

how would one go about c

devout snowBOT
hollow pollen
#

it is clear that 3SAT is in NP

#

is there an easy way to write any SAT into a 3SAT?

#

i think i know how to deal with an even number of literals per clause

#

but then

#

how do you deal with odd numbers of literals

#

suppose you have 4 literals

#

x1 or x2 or x3 or x4

#

is it valid to write y1 = x3 or x4

#

and then write

#

x1 or x2 or y1 = x1 or x2 or x3 or x4

#

yes

#

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pseudo jacinth
#

I have a lot of potatoes, oil, and rice at home, but I would like to eat sushi. What to do? My Japanese neighbour will surely give me wasabi if I bring her both beef and fries. With potatoes and oil, I can make fries as well as potato salad (as much as required, of both). For sushi, I need fish and rice and wasabi. My other neighbor (who just turned veggie) will certainly give me fish and beef if I get him some rice and potato salad.So in the end, will I be able to have my sushi? Please answer this question using resolution.

pseudo jacinth
#

discrete math problem

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#

@pseudo jacinth Has your question been resolved?

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#

@pseudo jacinth Has your question been resolved?

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#

@pseudo jacinth Has your question been resolved?

vast rain
#

what have you tried

#

this seems like an application of some everyday logic

#

maybe you have to formalize it but you should at least be able to answer the question with a yes/no

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jaunty dagger
devout snowBOT
jaunty dagger
#

how would i split this up to use partial fractions?

graceful cosmos
#

A/x + (Bx+C)/(x² + 2x + 5)

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hexed ocean
#

how do you do 21a?

devout snowBOT
cursive totem
#

have you tried drawing it out

hexed ocean
#

I can't really draw it out if i don't know any points

fathom thicket
woven radishBOT
#

doctor99268

hexed ocean
fathom thicket
#

the question litearlly tells you

hexed ocean
#

they're just points

#

how do you subtract points

fathom thicket
#

@hexed ocean they are coordinates

#

vector coordinates

#

@hexed ocean how much of vectors have you learnt

hexed ocean
#

let me see

#

oh i havent learnt crap about them

#

we went over them for a few weeks

#

but thats it

fathom thicket
#

then you wont know how to use my method

hexed ocean
#

:(

fathom thicket
#

thats not a multiplication symbol,

#

thats the cross product symbol

hexed ocean
#

whats that

fathom thicket
#

to put it simply, the cross product between 2 vectors, gives another vector that is perpendicular to both of them

hexed ocean
#

ah ok

fathom thicket
#

and the magnitude of that vector is the area of the parralelogram made by the 2 vectors

#

and since the triangle area is half that area

#

its why i did 1/2

#

you can achieve the same area though

#

if you just draw everything out

#

but for me i find that very long

hexed ocean
#

I can probably do it with distance formulas and what not

#

but idfk what they mean by making trapeziums

#

and dropping perpendiculars

#

.close

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#
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fathom thicket
#

.reopen

devout snowBOT
#

fathom thicket
#

@hexed ocean

#

this is what they mean

#

find the area of the triangle

#

by findin the area of the total rectangle

#

and minusing it from the areas that arent the triangle

#

youll get the right answer by doing this

hexed ocean
#

Ohhhhh

#

I see it now

#

Tysm

fathom thicket
#

honestly though, you should learn what cross product is, itll be advanced for you, but it makes vectors alot easier

#

like, if two vectors are collinear

#

the cross product between them is 0

#

doing the cross product itself is just something you memorise

hexed ocean
#

Alr 👍🏿

#

.close

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restive river
#

Hello i wanna check this result but wolfarmalpha is not responding ,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi = n!/k^(n+1)/m

restive river
#

whats the integral meant to be

#

,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi

woven radishBOT
restive river
#

too many constants bro

#

wtf is the original problem lol

vale dew
restive river
pseudo basin
#

$\int_0^{+\infty} x^n e^{-kx^m} \dd{x} = \frac{n!}{k^{n+1}/m}$

#

this?

woven radishBOT
pseudo basin
#

@restive river is it this result

restive river
pseudo basin
#

ok then you misplaced your parentheses

#

and it's meant to be $$\int_0^{+\infty} x^n e^{-kx^m} \dd{x} \overset?= \frac{n!}{k^{(n+1)/m}}$$

woven radishBOT
pseudo basin
#

i am highly sus of it tho

restive river
pseudo basin
#

no idea

#

but your book is feeding you lies

restive river
pseudo basin
#

for n=0, k=1, m=2 it gives 1 as the value of the integral

#

and yet

#

,w int[0,infty] exp(-x^2) dx

restive river
#

Books lie too

vale dew
#

Umm

#

I got a different result

#

For that integral

pseudo basin
#

what, exp(-x^2)?

vale dew
#

No

restive river
vale dew
pseudo basin
#

ok then out with it

restive river
#

I do know how to calculate using u sub but it will take ages

vale dew
restive river
#

I see

#

Hmm

#

When 2=n, x=alpha and m=4

pseudo basin
#

,rccw

woven radishBOT
pseudo basin
restive river
#

,w integrate x²e^(-alphax⁴) dx from 0 to infi

pseudo basin
#

it's k that is alpha

#

the renaming was kind of pointless

restive river
#

So just to verify

#

Itbwas this precisely

woven radishBOT
restive river
restive river
restive river
#

Gamma t+1 = t!

restive river
#

If it was ((1-n)/m)! Then it would have made sense

#

But i am really not sure

#

,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi where n=1,k=1,m=827

woven radishBOT
restive river
#

,w ((1-n)/m)!/(m(k^((n+1)/m))), where n=1,k=1,m=827

woven radishBOT
restive river
#

,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi where n=1,k=1,m=8

#

,w ((1-n)/m)!/(m(k^((n+1)/m))), where n=1,k=1,m=8

#

,w calc gamma(2/827)/827

restive river
#

,w (1/((k ^ ((n + 1)/m) * (m))) * ((n - m + 1)/m)!), m=2, n=2, k=1

#

,w integration of x ^ n * e ^ (- k * x ^ m) dx 0 to infi where m=2, n=2, k=1

restive river
#

,w Gamma symbol capital

woven radishBOT
devout snowBOT
#

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sonic ravine
devout snowBOT
sonic ravine
#

i have a problem

#

i want to put in {7 <= y <= 10} but it doesnt let me

#

whenever i put it in, the line on the graph disappears immediately

#

i want the line to show just from y = 7 to y = 10

pseudo basin
#

can you graph 7<=y<=10 as its own thing

#

er, wait.

sonic ravine
#

it still disappears

pseudo basin
#

does it show you a ⚠️ symbol

sonic ravine
#

yes

pseudo basin
#

what does it say if you click on that

sonic ravine
#

oh

#

it only works for x and y

#

because i put z in there

#

is there any way to fix?

#

or do i just change back to x as variable

pseudo basin
#

... you didn't tell me what it says when you click on the warning symbol

sonic ravine
#

ah yeah

#

i was just trynna make it smth diff, not x

#

but ig i have to make it x

#

ty

#

.close

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wraith dirge
#

can someone explain steps pls

devout snowBOT
wild aspen
#

For the first fraction, multiply $(x^{2}+5x+4)$ to the numerator and denominator

woven radishBOT
#

RomeNunt

wild aspen
#

Then expand

#

Then subtract or add the terms in the numerator

wraith dirge
#

first one as in (2x-5)/(x^2+5x+4)?

wraith dirge
#

it's not making sense to me

wild aspen
#

Could you vc, it's hard to explain with text

wraith dirge
#

sure

#

Is there a vc in this discord?

wild aspen
#

nah, vc private

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kind cedar
devout snowBOT
kind cedar
#

what do they mean by a function f from [1,5] to [1,7]

restive river
#

domain = [1,5] and [1,7] is the codomain

kind cedar
#

so pi should lie in its co-domain?

restive river
#

yeah

kind cedar
#

i see

#

thx!

restive river
#

yw :)

kind cedar
restive river
#

yeah

kind cedar
#

thx!

#

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peak bear
#

How I find the volume of the body limited by this equation in cylindrical coordinates?

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#

@peak bear Has your question been resolved?

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@peak bear Has your question been resolved?

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@peak bear Has your question been resolved?

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restive river
#

For elimination you need the same x or y, in this case none are the same

#

So you can find the lcm and then multiply to get the same number

#

For x it would be the least common multiple of 250 and 1, which is 250 so you multiply the bottom equation by 250

#

For y it would be the least common multiple of 150 and 1, which is 150 so you multiply the bottom equation by 150

#

Yeah true, the top equation can be simplified to 5x - 3y = 43 but it’s not needed

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mild ore
#

Hi can someone help me? I have to prove that the only null Lagrangians are the total derivatives?

mild ore
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The converse is easy to enough to prove

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To be precise I am only interested in the case for a Lagrangian with up to second order derivatives

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I tried this but

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Got stuck with this pde

flat mulch
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is this a right triangle

mild ore
# mild ore

This was after proving that a null lagrnagian must be a of the form g(x,y,')y"+h(x,y,y')

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@mild ore Has your question been resolved?

mild ore
#

<@&286206848099549185>

weary holly
solemn ginkgo
weary holly
#

I thought he asked the rest

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visual lark
visual lark
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this is what I have so far

austere hollow
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I think you might be going the wrong way using the tan fucntion

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and having a cosx as the denominator

visual lark
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I checked It should work since cosx is not = 0

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although I do not see any other way atm

austere hollow
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I'd suggest you try to use the fact that cos(a-b)=cosacosb+sinasinb

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you know that indentity ?

visual lark
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yes

austere hollow
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aight lemme give you a hint

visual lark
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although I need 2 cos functions

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and I have only 1

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how can i covert the sin to cos

austere hollow
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you agreed so far?

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agree*

visual lark
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yes

austere hollow
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using the identity I told you aboce

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above

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and now you can solve knowing that x is in 0 2pi

visual lark
austere hollow
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you know 1/2 = cos(pi/3)

visual lark
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yes

austere hollow
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same for the sqrt(3)/2 and the sin

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and same for the other side

visual lark
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aaaaaaaaaaa

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aaaa

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Now everything makes sense

austere hollow
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yeaa

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those are remarquable values

visual lark
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although I do not know how I would think of this on my own (;

austere hollow
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for the trig functions

visual lark
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yup

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although why would the tan way not work?

austere hollow
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yea no problem it'll come with time

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I mean I haven't fully thought about, it might work

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juste seems pretty sketchy

visual lark
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sketchy how?

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I checked it is possible to devide by cosx

austere hollow
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yea yea it's allowed cause 0 pi and 2pi arent solutions

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but we don't really knoiw how to solve these kinds of equations

visual lark
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hmmmm yeah I guess

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alright thank you for learning me something new

austere hollow
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there are no good ways to get out of this

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no problem fam

visual lark
#

.close

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vagrant zodiac
#

Need help with understanding spectral decomposition. I understand that it is supposed to be a way to express a matrix as a sum of spectral matricies and eigenvalues like $$A=\lambda_1 v_1 v^T + \lambda_2 v_2 v^T ...$$ but when I attempted to find the SD of $$A =\begin{pmatrix} 4 & 1 \ 1 & 4\end{pmatrix}$$, I ended up getting the original matrix times 2.

$$\lambda_1=5, v_1 = \begin{pmatrix} 1 \ 1\end{pmatrix} \lambda_2=3, v_2 = \begin{pmatrix} -1 \ 1 \end{pmatrix}$$

$$5 \begin{pmatrix} 1 & 1 \ 1 & 1 \end{pmatrix}+3 \begin{pmatrix} 1 & -1 \ -1 & 1 \end{pmatrix} = \begin{pmatrix} 8 & 2 \ 2 & 8 \end{pmatrix}$$

plz halp :3

woven radishBOT
vagrant zodiac
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do I have to normalize the eigenvectors first?

torn vessel
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yes

vagrant zodiac
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zamn that was a bonehead move on my part

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thanky

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:3

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.close

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signal ginkgo
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hello, I am stuck in solving this task, we are not allowed to use L'hopital's rule I need to expand the fraction with something, I tried both the upper and lower part but I can't finish it. (Btw solution is -1)

woven radishBOT
wooden veldt
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you probably want to rationalise the denominator

signal ginkgo
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I tried to do the difference of squares above, but the lower part of the fraction is constantly tending to zero

wooden veldt
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difference of squares how?

signal ginkgo
grand siren
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,rotate

woven radishBOT
supple knot
signal ginkgo
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okey, now i got -x up, but how to make lower part just x?

devout snowBOT
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@signal ginkgo Has your question been resolved?

supple knot
#

,rotate

woven radishBOT
supple knot
#

should be sqrt(1+x) +1 instead

signal ginkgo
#

Okey, now this ugly part is up, it needs another rationalization, but how? This is a new topic to me i am really sorry if i am a bit boring😅

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gilded wharf
#

Hey guys can you please check if I did this question correctly?

gilded wharf
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@gilded wharf Has your question been resolved?

gilded wharf
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<@&286206848099549185>

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<@&286206848099549185>

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Come on guys I spent 9 hours thinking about this question 😩

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gilded wharf
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<@&286206848099549185>

gilded wharf
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<@&286206848099549185>

small nest
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What is the problem?

gilded wharf
#

Can you please check if I got this question correct ?

gilded wharf
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<@&286206848099549185>

gilded wharf
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<@&286206848099549185>

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jade falcon
#

is the following statement correct?

If the enlargement factor is F, then the pressure on the bottom face of the cuboid is = pressure * F.

jade falcon
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F is force

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in the pressure formula

pseudo basin
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you are using the letter F to refer to two different things are you not

jade falcon
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so it means that is the enlargemnt factor is 25 then force in the eqaution of pressure is also 25

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at least thats what i thinl

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thats the qeustion that i was asked

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jade falcon
#

<@&286206848099549185>

sly viper
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I assume ideal gas laws will work for this

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$PV=nRT$

woven radishBOT
#

benevo

jade falcon
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but how

sly viper
#
V is volume
n is moles (quantity of gas)
R is a constant
T is the temp. of the room```
jade falcon
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idk n and T

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its not given

sly viper
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because the gas is in a sealed vessel n cannot change, and T is ignored as it assumed that the gas will reach the same room temp after some time as in the initial conditions.

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and because r is a constant it can be ignored

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so we have the simplified formula for gas pressure change with volume change

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$PV=C$

woven radishBOT
#

benevo

sly viper
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where C simply remains constant

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P is the pressure of the gas, to find force you multiply the pressure by the area it is exerted upon to get a force measurement.

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$Pressure * Area = Force$

woven radishBOT
#

benevo

sly viper
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does this all make since so far?

jade falcon
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ya

sly viper
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can you finish the problem with the information I have provided?

jade falcon
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ya i think so

sly viper
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respond to my last message if that changes, good luck. :)

jade falcon
#

ok, thanks a bunch

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vapid flare
#

i need help

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boreal blaze
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