help-27

[hollow pollen]

$f(x) = \frac{1}{2}\ln(\frac{1+x}{1-x})$

[ashen ledge]

its 1/2 times the whole ln thing

[woven radish]

heavy

[hollow pollen]

yeah you can just drop the 1/2 then

[ashen ledge]

ohhh yeah ur right

ive found that f(-x) = f(x), f is an increasing function and that x= 1 and x=-1 are asymptotes of x

im not sure how to solve that question with a and b though

[hollow pollen]

recall that $\ln (\frac{1}{x}) = - \ln (x)$

[woven radish]

heavy

[hollow pollen]

its just about solving an equation really

[ashen ledge]

yeah but it has 2 terms

a and b

and its in terms of f() of something

hello?😭

im really sorry but ima have to tag <@&286206848099549185>

[restive river]

Case 1
f(a^2 + b^2) =0 and f(a-b+1/2) =0

ln(x)=0 if x=1

in this way solve

Case 2
f(a^2 + b^2) =-f(a-b+1/2)

ln(x)=-ln(1/x)

in both cases u get 2 equation

so u can easily solve them to get a valid answer

[restive river]

u get 2 equation in both cases so u should be able to solve

[ashen ledge]

But the first case is wrong

cause then a=b=0 and f(1/2) isn’t 0

[restive river]

they maybe

you have to eliminate the answer that are not valid

these are just 2 possibility which may or may not be correct

try case 2

[ashen ledge]

yeah i am rn @

I have

(1 + a^2 + b^2)/(1-a^2-b^2) = (-a+b+1/2)/(a-b+3/2))

[restive river]

that's a bit weird

let me try

[ashen ledge]

did you find anything?

[restive river]

Nope

[ashen ledge]

frick

[restive river]

i will let u know if i figure something out

[ashen ledge]

okay thank you for your time

<@&286206848099549185>

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[limpid zenith]

Use integration by substitution

Try u=ln(X)

@restive river

It should be u=ln(X)

du/dx= 1/x

So dx= x du

Then plug it into the intregral

So x cancels out

And u get integral of (ln(ln(X)) times ln(X))

As u= ln(X)

And then do integration by parts

Np 🙂

U too

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[nova idol]

@paper palm

!status

[devout snow]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

@paper palm Has your question been resolved?

[paper palm]

1

i dont know where to begin

i got that if the average was 13 then the total age of all of them is 130

[nova idol]

yep

and so they add 2 more and the averge goes to 14

what does that mean

what is the new sum

[paper palm]

if it increased by 1 year and 2 people then its 14*12

[nova idol]

yep

[paper palm]

168

[nova idol]

yep

[paper palm]

so 38 difference

[nova idol]

yep

[paper palm]

so the average is 19

[nova idol]

yep

you got it!

[paper palm]

oh i didnt need help then

[nova idol]

lol

[paper palm]

tysm tho

[nova idol]

np

[paper palm]

.close

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[mild basin]

Is this going to require the inner chain rule 3x?

1 outer function,
3 inner functions?

[honest meadow]

work outside to inside so yes there will be 2 chain rules

1 for the argument of ln, 1 for the rational function

[devout snow]

@mild basin Has your question been resolved?

[mild basin]

Oh OK, we don’t call the “rational” ( does that mean the root: power rule ) a chain after ln?

[honest meadow]

when ur doing derivative of ln

d/dx ln(u)=u'/u

in this case u=x+√(1+x^2)

so u' will make u take the derivative of the root, which is the 2nd chain rule

first being derivative of the argument in the ln

@mild basin

[weak cove]

you shouldn't have to think or plan beforehand how many chain rules something has, the idea behind the name of the chain rule is that it is just like a chain ⛓️ of derivatives. Start with the outside, ln( ) is a composite function so you will apply the chain rule to its inner part. x+sqrt(1+x^2) well, the derivative of x is one but the derivative of the sqrt(1+x^2) will require the chain rule again because it is a composite function yet again.

You should just be analyzing each function at each step individually

I see ln( composition )

I do chain rule

I now see sqrt( composition )

I do chain rule

but probably no need to like gameplan it all out

technically there are even three chain rules

the last composite function is (x^2) of which the derivative of 2x * d/dx of x which is 1 ( that is the reason this final step is ignored)

but you can see how you wouldn't like first view a question like that and be like oohh this is how many times... yk?

[mild basin]

Thanks y’all I will study this

.close

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[compact ravine]

.open

Yo I’m acc so confused

[compact ravine]

The first image I sent was the example my teacher showed us

And Photomath is giving me the same as we’re but in different places

[mild torrent]

A number divided by 4 and then subtracted 2018 from the result is 56. The number is:......

[compact ravine]

Bro what

😐

No one’s laughing

Ur not funny kys

[winter patrol]

the work copied down is dodge

last line is incorrect / wrong

[compact ravine]

Can u explain to me why that’s the answer

Is it where the numbers outside the brackets go last?

Wait so is the first image right or wrong

[winter patrol]

just to make it clear the $\red{4a-5a(2a-1)}$ that was written down is wrong and not the same as $(2a-1)(4a-5)$

[woven radish]

ℝamonov

[winter patrol]

ugh, the first step there upon closer inspection is also wrong

[compact ravine]

That’s the exact example my teacher told us to write down

[winter patrol]

send it back to them and/or maybe you didn't copy it down correctly

[compact ravine]

Can you explain why the 2a - 1 would go first instead?

[winter patrol]

that part should just be 2a not -2a

[winter patrol]

the order in the final product doesn't matter,
pq = qp

what you do need to ensure that your expression properly represents the correct things being multiplied

$$(2a-1)(4a-5) = (4a-5) (2a-1)$$
getting either is fine

[woven radish]

ℝamonov

[compact ravine]

Oh ok

Thanks

[winter patrol]

which the teacher / your notes did not achieve

[compact ravine]

Bro what can u speak English

[winter patrol]

wdym

[compact ravine]

Like the placement of the stuff is different

[winter patrol]

the order in the final product doesn't matter,
pq = qp

[compact ravine]

Ok

[winter patrol]

(5m^2+t)(t-2) is equivalent to (t-2)(5m^2+t)

what does matter is that you should have a plus sign (coloured in blue) between those terms
and write your ts more cursive so they don't get misread as + signs

[compact ravine]

Ok

[devout snow]

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[flat breach]

.open

i'm unable to solve this question
13th (eclipse)

[topaz axle]

because the larger diameter is sqrt(2) times larger, you can draw this around a square

hax

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[keen prairie]

Hi sorry i asked this question before, but i keep getting stuck on j. Does anyone mind walking me through the solution? 😅😅

[keen prairie]

<@&286206848099549185>

[devout snow]

@keen prairie Has your question been resolved?

[keen prairie]

<@&286206848099549185>

wait sorry what

[wicked siren]

ok hold on

[devout snow]

@keen prairie Has your question been resolved?

[keen prairie]

<@&286206848099549185>

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@keen prairie Has your question been resolved?

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@keen prairie Has your question been resolved?

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[true tangle]

Quick question

[true tangle]

Where did that negative came from?

[scarlet sequoia]

notice that in order to cancel out x - 16 and 16 - x

you have to do 16 - x = -(x-16) or same trick but in the numerator

[true tangle]

Ohh yeah

[woven radish]

Modus

[true tangle]

That sign is tricky

Thankss

.close

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[humble cedar]

I got to this point but idk how to get A

Would appreciate any help pls thanks

[stone stump]

where does A send the vectors (1,0,0), (0,1,0) and (0,0,1)

from that you can read off the columns of A

[humble cedar]

ohh right

thanks

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[valid axle]

Assume that the function f(x) is defined on the entire real line and that $(f(x))^2 ≤ x^4 + x^6$ for all x.

[woven radish]

afeAlway

[valid axle]

(a) Determine whether f must be continuous at the point x = 0.

[woven radish]

afeAlway

[valid axle]

In what world is this true? |f(0)| ≤ 0 <=> |f(0)| = 0?

[sonic smelt]

Absolute values are generally can't be negative, right?

[valid axle]

yes

[sonic smelt]

And a <= b means a < b or a = b

So, here

[valid axle]

I get it now

[sonic smelt]

Alright

[valid axle]

since it can't be less than 0, the only way the inequality will hold is if f(0)=0 right?

[valid axle]

a quick question, can you do the opposite? $f(x) = |\sqrt{x^4 + x^6}|$ ?

[woven radish]

afeAlway

[sonic smelt]

No

[devout snow]

@valid axle Has your question been resolved?

[valid axle]

i mean y

[sonic smelt]

f(x) could be zero

Or -|sqrt(x^4 + x^6)|

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@valid axle Has your question been resolved?

[devout snow]

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[somber shore]

hi

[somber shore]

here is the question

I tried everyway but that is the only thing i found

[urban hornet]

What do you have to find

[somber shore]

(tanx-sinx)/(sinx-cosx)

i just wrote the main part of the solution. after this part we find sinx and cos x and just replace it

is this correct? is there any other solution?

[urban hornet]

You can go with the rhs itself, simplify it

[somber shore]

what do you mean? could you explain more

[urban hornet]

Use dividendo and componenedo

[somber shore]

oh i got it

pretty smart move

how can i get better at trigonometry and trigonometric identities?

[urban hornet]

Practice and learn all the formulae

[somber shore]

do you have any set of questions that can be helpful?

[urban hornet]

Solve books of trigonometry. I am not from your country, so I don't know what type of question there are. I, solve cengage. But it is a pretty hard book

[somber shore]

alr

thank you so much

.close

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[abstract prism]

claim

[abstract prism]

how do I express cos(7pi/20) as a cofunction of a complementary angle?

.close

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[timber pebble]

I'm working on b

I know that you have to in some way set it up as an optimization problem but its not really clear to me how to do that

I think I have to take partials somewhere?

I mean clearly

[stone stump]

set up the function that you want to minimize

probably norm(s-c1-c2cos^2)^2

[timber pebble]

okay

so we are here

@stone stump is it like this?

[stone stump]

that error depends on theta. you probably dont want that

so more likely something like int (s-c1-c2cos)^2 dtheta

[timber pebble]

are you saying take another derivative

sorry i realize these are dumb questions

the error will depend on theta if we do it this way, right?

i mean theres no getting around it, there are thetas and phis in the form of S_b so you cant have it not depend on them

[stone stump]

they arent very explicit in the question but they very likely want the best approximation of s in the L^2 norm

[timber pebble]

I can post what the teacher said

the way he wrote it is not making sense to me though

[stone stump]

ok so you only want to evaluate it at certain points

theta_i

[timber pebble]

thats what it seems like

but we have no data

[stone stump]

$\sum_i (s(\theta_i) - (c_1+c_2 \cos^2(\theta_i)))^2$ something like that

[timber pebble]

how would you decide on the thetas

[woven radish]

Denascite

[timber pebble]

or do you just do like a hundred thousand

[stone stump]

yeah that's what surprises me a bit

[timber pebble]

im not sure he understands what im asking

[stone stump]

if we do the L^2 norm then we get "all" thetas

[timber pebble]

so id take his answer with a grain of salt

[stone stump]

$\int (s(\theta)-(c_1+c_2\cos^2(\theta)))^2 d\theta$

[woven radish]

Denascite

[timber pebble]

oh man we have another integral on top

i mean

how are you even going to set this to 0

the goal is finding c1 and c2 right

so at some point you have to take a partial of this fucked up nested thing

[stone stump]

$E(c_1, c_2) = \int_{-\pi/2}^{\pi/2} (s(\theta)-(c_1+c_2\cos^2(\theta)))^2 d\theta$

[timber pebble]

wrt c1 and c2

[woven radish]

Denascite

[stone stump]

this would be the error function

which you could differentiate etc

[timber pebble]

its not going to lead to something that is like

manipulable by hand

[stone stump]

well its gonna be a bit messy

[timber pebble]

the prof says we should do this by hand

i mean we cant evaluate the integral

which if you do it this way youll eventually have to do

by integral i mean s_beta

[stone stump]

well by hand you cant do line of best fit anyway

[timber pebble]

idk what you mean haha

[stone stump]

just way too much work

to do by hand

[timber pebble]

no i mean

its not possible to evaluate that integral

[stone stump]

we are gonna let matlab do the math stuff in the end either way

[timber pebble]

sure

i mean i can use matlab for all of this

i just dont understand the problem at all so im not sure how id code it

itd be better if i can do stuff thats by hand by hand

idk maybe ill ask chat gpt and guess through it lol

[stone stump]

dont ask chatgpt

[timber pebble]

@stone stump big picture, youre saying

im not sure what to do

big picture

we define an error function, which given a c1 and a c2, will tell us how "far" we are from the original solution

[stone stump]

yes

[timber pebble]

we take derivatives of the error function with respect to each parameter we have control over, and find minimums

and thats it

[stone stump]

yes

yes

[timber pebble]

thank u for the 3 yes

[stone stump]

in theory. in practice we of course would have to calculate all the values which would be messy

[timber pebble]

so then you must just use a linspace?

idk how youd do this without a computer

[stone stump]

so the problem here is mostly with the question "which error function do we use"

[timber pebble]

its just where to introduce it

well he gave one rnight

right

then the question is what thetas

lol

[stone stump]

yes

probably just use linspace with 1k points or something

[timber pebble]

okay

so then

[stone stump]

whatever you used previously do plot s(theta) in the first place

[timber pebble]

error function by hand

derivatives by hand

minimums by compute

i think i understand

but wait

you said these were wrong?

last question i promise lol

[stone stump]

you would need to sum those up over all theta_i

[timber pebble]

oh, thats what you mean by theta dependency

[stone stump]

$E(c_1, c_2) = \sum_i (s(\theta_i)-c_1-c_2\cos^2(\theta_i)))^2$

[timber pebble]

okay

[woven radish]

Denascite

[timber pebble]

I'm gonna leave this open so i can reference it but i think thats good enough i can approach it

thank you @stone stump 🙇‍♂️

[stone stump]

youre welcome

[devout snow]

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[topaz beacon]

Do you know modular arithmetic?

[paper palm]

maybe but i dont know the name

[topaz beacon]

Ok well anyway, i want you to list like the last digit of the first 3^n for 1<=n<=10

You should see a pattern

[paper palm]

3 9 7 1 3 9 7 1

oh yeah

[topaz beacon]

Figure out the remainder of 2011 when divided by 4

[paper palm]

1

[topaz beacon]

Note thats 3^n has a last digit of 3 when n has a remainder of 1 when divided by 4, last digit of 9 when n has a remainder of 2, 7 when it has a remainder of 3, and 1 when it has no remainder

[paper palm]

oh yeah

[topaz beacon]

So whats the remainder of 2011 when divided by 4

[paper palm]

1

[topaz beacon]

U sure?

[paper palm]

it has a remainder of 1 right

[devout snow]

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[woven crystal]

if i have a variable that tells me the average cost of a product over the last 7 days, and i have another data which is the latest cost in the last 24 hours, could i update the average cost? I want it to be the average of the recent 7 data points basically.
i dont think i can because i need to know the oldest price which i dont have
is there a way to make a close estimate for it?

[devout snow]

@woven crystal Has your question been resolved?

[odd palm]

If I think I understand what you are saying, you have this sort of set up?

So the day average is not included in the last weeks average?

[woven crystal]

i dont think day averegae is the same thing

its just the price on that day

[odd palm]

Ok

Is the day you have the price for included in your seven day average?

[woven crystal]

its not

[odd palm]

Okay cool

So, if you have the average value for the week i.e the last 7 days

Then one rough assumption is that the price on each day of that week was the average, if that makes sense?

[woven crystal]

well sure, but that seems really drastic

[odd palm]

If all the data you have is the week average and the next days average, I dont think you can calculate the new average without that assumption

[woven crystal]

could we take the average of the new value and the weekly average?

[odd palm]

Well what I was going to suggest was doing (6*(Week average) + (day average))/7

[woven crystal]

ah because then its like subtracting the oldest price

[odd palm]

yeah exactly

[woven crystal]

are there any alternative assumptions we could do?

[odd palm]

I'm just thinking about that

[frail galleon]

Help pls

[odd palm]

Hey BadBarbie, its best to open a new channel for this post #❓how-to-get-help message

A slightly more nuanced assumption could be to do something clever if we assume the price moves smoothly

So like if the day price is a lot higher than the week average, we can imagine the actual week values to start lower than the average and build up to approach closer to the day average

And then you could use that assumption to do something clever

Which could just be to give more weight to the day average

Like (5*(week average) + 2*(day average))/7

[woven crystal]

isnt that giving less weight to the day average?

[odd palm]

I think thats more as the prev one was (6(week average) + (day average))/7 right?

[woven crystal]

ohh i see

ill keep playing around with it, thank u

[woven crystal]

okay so i was thinking we know sum = 7*average

and you said something like if the day price is a lot higher than the weekly average then the values build up to approach closer to that day average

so could we artificially create terms of the sum

like sum = something big + something smaller + something smaller than that + ... + smallest

[devout snow]

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[alpine heron]

From a point P due south of a vertical tower, the angle of elevation of the top of the tower is 20°, from a point Q due east of the tower the angle of elevation is 35°, the distance from P to Q is 40 metres use pythag to calculate the heigh of ghe tower

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[weary ledge]

hi, I'm struggling with this problem; how would I find the zeros of f''(x)?

[weary ledge]

I tried factor theorem, didn't get anywhere with that

[nova idol]

why not use the cubic formula

[weary ledge]

I don't think I've been introduced to that

[nova idol]

the zeros arent nice

so either you use a calculator or you messed up taking the derivative

[weary ledge]

the only other thing I could think of was a graphing calculator

[nova idol]

well yeah

[weary ledge]

I double-checked the derivative, I'm pretty sure it's correct

I'll use Desmos then, I just wanted to see if there was something I was doing wrong

[nova idol]

yeah so those are the zeros in the photo i sent

sometimes you just cant factor it and have to use a calculator

[weary ledge]

I see

damn :/

well, thanks for the help

[nova idol]

np

[weary ledge]

.close

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[wispy geyser]

am i right with A?

[nova idol]

;-;

youre just asking for answers which is not the point of this server

[blissful cloak]

i dont believe he is asking for the answer, only if he is right

[wispy geyser]

i solved it bra

[wispy geyser]

YES

[blissful cloak]

if he is right, then say he is right

[wispy geyser]

W MANS

this what im tryna say bro

[blissful cloak]

if he is wrong, explain why he is wrong

[elfin bridge]

kefir r u good at probability

[wispy geyser]

open a question gang

[elfin bridge]

i did xd

[nova idol]

thats asking for the answer...

someone else needs to solve it and tell him if he's wrong or right

and idealy tell him the correct answer

[nova idol]

what kind

[wispy geyser]

NOT HERE THREN BRO

[blissful cloak]

we dont tell him the correct answer if he is wrong, we tell him that its wrong, then ask for him to show work so we can show him where he went wrong

[blissful cloak]

#❓how-to-get-help

[elfin bridge]

mb

[nova idol]

ideally yes but a lot of helpers will actually tell them the correct answer

[elfin bridge]

look at help 26 kefir

[blissful cloak]

ur good 🙂

[nova idol]

or outt will just ask them for the correct asnwer

[blissful cloak]

then we remind those helpers to not give out the answers

[nova idol]

well yeah

[wispy geyser]

can you help?

[blissful cloak]

maybe, let me work it out first

[wispy geyser]

tysm man

[nova idol]

I feel like this is a waste of time

if they found a solution

they probably know at least some of it

[wispy geyser]

im in a tough situation rn i got to get 6 assignments completed today

[nova idol]

they only need help if they get it wrong

if they are right the helper's time is wasted

and whos' fault is that

[wispy geyser]

omg what is bro chattin bout

😭

[blissful cloak]

if you see it as a waste of time then leave it to another who will help

[nova idol]

im saying for any helper it can be a waste

[elfin bridge]

Bro just help me then please

[nova idol]

so people shouldnt ask those type of questions

[elfin bridge]

leave them

to do there thing

[nova idol]

bro I volunteer

please stop begging

[elfin bridge]

ok

fine

it jusr dosent seem like ur wanted in this channel

[blissful cloak]

vort, ping helpers role in your own channel if it has been 15 min

[wispy geyser]

heres the question again

[elfin bridge]

i did lol

[blissful cloak]

ping it every 15 min, create a help forum, or post your question in the appropriate channel

@wispy geyser could you tell me the reasoning behind your answer?

[wispy geyser]

The product of the slopes of successive sides is -1 and the lines are said to be perpendicular to one another, so each sides are orthogonal and perpendicular to one another.

[blissful cloak]

are you saying in the question, its given that the lines are perpendicular? of so that is not the case

it shouldn't be given, were seeing who is checking if the lines are perpendicular in the right way

so, who would you say is going about it the right way, carla or jonah, and why?

[wispy geyser]

i mean i think its carla

[blissful cloak]

why do you think it is carla?

im not saying you are wrong, im simply asking why do you think its carla

[devout snow]

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[north light]

Hello!

having trouble with #39

Im not sure what im doing wrong as I keep on getting the wrong answer

some insight would be appreciated

[quaint citrus]

Try drawing it in Q1

[north light]

they want us to use

pythagorean identities

[devout snow]

@north light Has your question been resolved?

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[green walrus]

https://dpaste.com/G5C59WWEH#wrap

[green walrus]

Mathematically, what would be your formulaic pattern for this problem?

The logic I came up with isn't correct for all cases.

Namely, my logic is to iterate through the array and decrement the larger element in a pair where the hunger level difference is the greatest in the array

but this logic fails for an example like this -> [1, 5, 4, 1]

my logic would output:

541
531

but the actual correct answer is:

541
441

[still pulsar]

why not make another var to compare the largest Hn and allocate N to it? so a priority thing

[green walrus]

I have three variables currently:

highest, highestDiff, and diff

[still pulsar]

compare i and i+1

[green walrus]

you're comfortable in JS?

just in case you are, here's my current attempt:

https://dpaste.com/7QY4BFCWJ

my other attempts are not good though:

first attempt:
https://dpaste.com/562WD2AM9
this passed 4 of 10 checks
second attempt:
https://dpaste.com/8QVPGEK7V

been working on this for over 23 hours

so, I'm ready to move on already

[nova idol]

@green walrusisnt this just programming

is it cp

there are a bunch of servers for that

[green walrus]

I'm interested in the math logic here

i only shared my code since Rain seemed to be comfortable in JS

[nova idol]

its not really math

I also do JS

this is like basic compeititve programming

[still pulsar]

make it so you assign the i-th item and replace it with the next largest i, then take one away from N and add 1 to the new i term.
Then loop that until N = 0

[green walrus]

oh, you don't have to give me the answer directly

I was hoping more for guidance

[nova idol]

oh lol

[green walrus]

so I can understand the code better

[nova idol]

i was gonna give you the answer

its hard to explain because there arent many steps

[green walrus]

i want guidance so it hopefully doesn't take me over 20 hours next time

[nova idol]

its just a programming thing

you're looping from 1 to N

but youre not resetting i when you find the max hunger pair

[green walrus]

wait, can you ask me like an interview style?

so, I can realize my mistake(s)

and get that "aha!" moment

[nova idol]

this is straight up cp lol

okay so

the first run

you find index 0 and index 1

which is 1 and 5 right

so you subtract from 5

[green walrus]

no, I'll do the walkthrough

[nova idol]

oh

[green walrus]

you can just ask me probing questions to ensure I understand the logic and what the code is doing

my code works, but my logic is not correct for all cases

that's why I came here to get an opinion from people really good in math

[green walrus]

#help-27 message

[vast rain]

I wonder if you can solve this in a greedy fashion

like compute the median of the array

[nova idol]

wait what

[vast rain]

and then decrement/increment the value of the element farthest away from the median

[nova idol]

greedy seems like overkill

theres no time constraint

[vast rain]

????

[nova idol]

arent you just keeping track of the max hunger diff

and the two indexes of that

and then decrementing the larger one at the end of the loop

[green walrus]

yes, that is what I'm currently

[nova idol]

okay so

just loop through that as many times as you need

from index 0 to n-1

like n times if you want

[vast rain]

oh yeah you're just feeding hunger, not getting sandwiches from people

[green walrus]

but again, please don't give me the solution directly, if possible

i won't learn that way

[vast rain]

wait this is super easy, just sort the array and decrement from the back

[nova idol]

the order matters

[vast rain]

isn't the whole idea here to feed the most hungry people

[nova idol]

its pretty simple though

but you still want to print out the people in the original order

can we go on a voice call

is that possible on this server

[green walrus]

yes, sadly I realized this after working on it for the first 19 hours

see my first really long attempt

[nova idol]

alright so

can you walk me through your code

[vast rain]

why tf doesthe order matter

the problem doesn't change depending on the order of the people

[nova idol]

cause they want to know which index got less hungry

arent you outputting which people in what order

[green walrus]

but hunger ratios do change depending on the order

[nova idol]

can you send the original problem

[vast rain]

aren't they just asking for the largest difference in hungers

[nova idol]

no

they want you to output the impact after as well

oh i just realized you're also a CS major

willow are you a CS major too?

[vast rain]

it specifically asks for the final minimized difference

[nova idol]

so why is willow returning three values

and twice

[green walrus]

i'm trying

[nova idol]

like trying to get into the major or trying to stay in the major

[vast rain]

this literally amounts to feeding the most hungry people

[green walrus]

trying to stay in it

[nova idol]

okay

can you send the original problem

[vast rain]

but you make sure that you never overfeed, as in you never feed past the minimum of the array

so if you sort the array in ascending order

just feed the end

[green walrus]

my first attempt yields this output for the array [2,1,0,4,1,0]:

[nova idol]

oh the first value is the number of sanwhiches

[green walrus]

110210

but this is incorrect

why?

initial list:         2,1,0,4,1,0
sandwich allocation: -0,0,0,3,0,0
final hunger levels:  2,1,0,1,1,0
pairwise differences:  1,1,1,0,1
total difference: 4

[nova idol]

you cant though

[vast rain]

why can you not

[nova idol]

cause the pairs matter

[green walrus]

that's why order matters

[vast rain]

no they don't

the order doesn't matter

it's saying the maximum difference across ALL pairs

[vast rain]

how many sandwiches do you have again?

[nova idol]

what

oh youre right

[vast rain]

Your goal is to minimize the hunger difference between each pair of people in the array using the sandwiches you have available.

[nova idol]

i read pair of people as in like adjacent

yeah then just sort lol

[nova idol]

and I'm guessing so did willow

[green walrus]

for this problem, 4

[nova idol]

are you making sure the first value isnt the number of sandwiches

you have to ignore that

and the pairwise isnt like that now

its every possible pair

[vast rain]

so for example, if you have 4 sandwiches

you sort it as 0, 0, 1, 2, 4

feed 2 sandwiches to the back

now you have 0, 0, 1, 2, 2

feed two more to each of the elements in the back

0, 0, 1, 1, 1

min difference is now 1

[nova idol]

doesnt mean that always works

[green walrus]

and what's your total difference with this method??

[nova idol]

willow is looking for intuition right

[nova idol]

doesnt matter

only looking for max difference

[nova idol]

max*

[green walrus]

I'm just checking to ensure his/her method is accurate

[vast rain]

max difference is 1

[nova idol]

wait no it is total

the total is the output

@vast rainoml

[green walrus]

or wait, I mean total difference

[vast rain]

oh wait you want the total difference

[nova idol]

Another example: if arr is [4, 5, 2, 3, 1, 0] then you can distribute the sandwiches in the following order: [3, 0, 1, 0, 0] which makes all the hunger levels the following: [2, 2, 2, 1, 0]. The differences between each pair of people is now: 0, 0, 1, 1

[vast rain]

I think the algorithm still works

[nova idol]

it IS in order

its in adjcent pairs

[green walrus]

yes

[nova idol]

look at the differences

its 0, 0, 1, 1

4 values in 5 people

its not all possible pairs

this problem is written so badly

two CS majors getting it wrong multiple times

[green walrus]

original prompt:

https://dpaste.com/BR4F4DDFL#wrap

[vast rain]

0, 0, 1, 1 and so your program should return the final minimized difference of 2.

it's not adjacent pairs

[green walrus]

then, that is incorrect then

the answer is 4

not 2

[nova idol]

looks like it to me

[vast rain]

oh wait it is adjacent pairs

[nova idol]

lol

@green walrusyou should do better worded problems

use leetcode

[green walrus]

yes, please

[green walrus]

not me, it's my teacher

[nova idol]

so we are trying to minimize the sum of the array of adjacent differences

what kind of class are you in

[nova idol]

can we agree on this

[green walrus]

i think so

that sounds correct

[green walrus]

#help-27 message

we want to allocate the sandwiches that yield the least minimal difference

[vast rain]

so then this is probably just iterating through each adjacent pair and only decrementing an element if it is greater than both of its neighbours

[green walrus]

my logic is incorrect as indicated above

the answer should be 3

[nova idol]

so greedy right

[green walrus]

not 4

[nova idol]

what if no value is greater than both its neighbors

i gtg but I think saccharine can figure this out

[green walrus]

ty

[vast rain]

then decreasing it won't help much

yeah greedy I think

[nova idol]

right cause it makes one better and one worse

so once you cant find any more n > n-1 and n+1 you stop

[green walrus]

so, let's analyze why my logic fails and intuitive tips that I should be aware of

let's try 541

with 1 sandwich

when I saw this array fail my logic, I thought:

maybe I will have to check the entire array for a cumultative minimal difference

but then, that seems to increase the time complexity dramatically

[devout snow]

@green walrus Has your question been resolved?

[devout snow]

@green walrus Has your question been resolved?

[devout snow]

@green walrus Has your question been resolved?

[nova idol]

@green walrus just join a cp discord

They’ll be able to help you

I’m kinda rusty on cp and it looks like sacc is busy

[green walrus]

again, I'm not looking for code

but rather the math pattern present here

[nova idol]

willow trust me

I did cp for months

[green walrus]

i think this is algebra

[nova idol]

Its not about the math

You don’t learn this in math

This is purely cs

Almost every beginner problem is like this

People who do cp can easily and coherently explain it to you

[devout snow]

@green walrus Has your question been resolved?

[wanton aspen]

Hello

I read your question but havent seen the discussion

But basically, every time you give a sandwich, you reduce the total difference by -2, -1, 0, 1, or 2. You have to greedily choose the reduction in difference

Also I assumed adjacent pairs because thats what the solution seems to consider

[pseudo basin]

ain't much to say from a purely-mathematical-not-coding standpoint here.

[green walrus]

I think the problem boils down to algebra

[pseudo basin]

if it's anything the problem boils down to, it's an optimization problem

you have your parameters $N, h_1, h_2, \dots, h_n$ and decision variables $s_i$ (representing the amount of sandwiches given to person $i$) and your goal is to minimize $$\sum_{k=1}^{n-1} |(h_i - s_i) - (h_{i+1} - s_{i+1})|$$ under the constraint $$\sum_{k=1}^n s_k \leq N.$$

[woven radish]

Ann

[devout snow]

@green walrus Has your question been resolved?

[nova idol]

@green walrus have you asked in a cp server yet

This is not a math question

Its an everyday cp question

[green walrus]

Hmm.

With this formula, how would you proceed?

[nova idol]

@green walrusare you even reading my messages

[green walrus]

https://qr.ae/prSX0R

https://qr.ae/prS78U

[nova idol]

dude

its computer science

its the skills you learn in computer science

optimization in this scenario is cs

not math

why wont you just ask in a cs server

I've done like hundreds of these problems

its cs

if you tried to use pure math for every example (even if you could) it would take forever

and they would not hire you as an intern

[lavish venture]

Help me learn for my studies

[nova idol]

not here

#❓how-to-get-help

[prisma canopy]

this no longer works.

[wanton aspen]

Not sure what exactly you're asking. It is a mathematics problem that you solve algorithmically with the help of a computer. There's no equating of formulas and cancelling out of variables if that's what you mean by "algebra".

[green walrus]

https://dpaste.com/AZPHBSA3T#wrap

sorry about the link expiration

[wanton aspen]

what's your question? this channel has been open for like 1.5 days

[glad cobalt]

link doesn't work

oh wait I didn't see your recent comment

maybe edit your original post

[glad cobalt]

when they say "pair" of people I'm assuming they mean adjacent people?

otherwise there would be n choose 2 pairs instead of n-1 pairs

[devout snow]

@green walrus Has your question been resolved?

[nova idol]

Yes

[nova idol]

They want a pure math solution

Which as multiple people have told them already is not possible

[green walrus]

Just wanted to get more input

but i'll go ahead and close at this point

ty

.close

[devout snow]

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[prisma cargo]

Don’t know any concept here

Need you peeps help now

[crimson tiger]

assume x/1 = (y-2)/2 = (z+3)/3 = a

so x/1 = a => x=a

(y-2)/2=a => y=2a+2

similarly find z

[prisma cargo]

In simple finding the vector eqn

[crimson tiger]

so you'll get a general point on the first line in terms of a

[prisma cargo]

Right?

[crimson tiger]

yeah kinda

now if u assume the 2nd line as b, find a general point in terms of b

[prisma cargo]

Can you write it like
On paper
😅

[crimson tiger]

for the 2nd line, equate it to b and find values of x, y and z

once u get that, equate the x and the y to find a and b

substitute a and b in the value of z. If both give the same value of z, the lines intersect

and you automatically get the point of intersection

[prisma cargo]

Thanks mate

I got it now

Thanks for your help

[crimson tiger]

ur welcome

[prisma cargo]

.close

[devout snow]

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[devout snow]

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[kindred sedge]

Hi I need help why is this undefined

[kindred sedge]

Should I factor first or is this answer okay?

[restive river]

0/0 is not undefined, necessarily

0/0 is an indeterminate form

Notice that we have $\lim_{x \to x_0} \frac{x^2 - b^2}{x - b}$

[woven radish]

Nika

[kindred sedge]

Yeahh

Do I factor?

[restive river]

Yes.

[kindred sedge]

Okayy thank youu

.close

[devout snow]

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[neat kelp]

is 1-sin^2(x) = (1-sinx)(1+sinx)

[neat kelp]

and so lim as x->0 (1-sin^2(x)) would be [lim as x->0 (1-sinx) times lim as x->0 (1+sinx)]?

or like thats another way of writing the lim

[devout snow]

@neat kelp Has your question been resolved?

[neat kelp]

.close

[devout snow]

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[patent wolf]

i am new to integration, in a case such as this, why didnt we use the substitution method?

[patent wolf]

i know it wouldnt have worked, but the problem looks like a problem that requires substitution method or "reverse chain rule"

[devout snow]

@patent wolf Has your question been resolved?

[patent wolf]

@dry robin

[upper schooner]

Well because there's no real need to do a substitution, as you can do it "by recognition"

Some "reverse chain rule" situations you can visually spot

[patent wolf]

i see, thanks

.close

[devout snow]

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[kindred sedge]

I tried multiplying the numerator to the fraction with -3 turning positive

Is that the correct way or is there a better way

Btw the denominator is x-7

[exotic stump]

you can't outright multiply by that, you need to multiply by the equivalent of 1

which is that over itself

or $\frac{\sqrt{x+2}+3}{\sqrt{x+2}+3}$

[woven radish]

a disappointing son

[exotic stump]

(which is equal to 1)

[kindred sedge]

Ohhh

I see isee

Is this called rationalization

[exotic stump]

yes

[kindred sedge]

Is rationalizing possible with numerators?

I fear my tchr would say that

[exotic stump]

normally you hear of rationalizing the denominator to get rid of a root in the denominator

[kindred sedge]

Yeahh

[exotic stump]

multiplying by the conjugate

would be a term to use

[honest meadow]

yes, but u mostly rationalize the denominator for other areas of math

[kindred sedge]

Is there a more basic way to do this other than rationalizing or conjugating

We haven't tackled much of it yet and I fear my tchr would question the validity of my knowledge

[exotic stump]

not one that i'm aware of

[kindred sedge]

Alrighty thanksss guys for the help

.close

[devout snow]

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[devout snow]

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[prisma cargo]

Yo

[prisma cargo]

I know I can remove one Sinx

But I face difficulty with the 3 inside

Can anyone help me here

[grim burrow]

there is a much more straight-forward approach than that

you can start by answering these two questions:
What is the derivative of cos^3(x)?
Can you integrate sin^3(x)?

[prisma cargo]

Nah
Can’t integrate sun3x

[grim burrow]

do you know the triple angle identity?

[prisma cargo]

The school text us recommending to go with the substitution method

But I can’t do that

You know anything to approach with substitution method

[grim burrow]

i need an answer for this

[prisma cargo]

No

[grim burrow]

alright, then it's time you know it.
The triple angle identity for sin(3x)=3sin(x)-4sin^3(x)
You can derive this by just using sum of angle identity and then double angle identity

[prisma cargo]

Ok

[grim burrow]

so by using this, we know that sin^3(x)=1/4 * (3sin(x)-sin(3x))

now you can integrate sin^3(x)

both 3sin(x) and sin(3x) are integrable by hand

[rugged sparrow]

It can also be written as 4cos(60-x)cosxcos(60+x)

[arctic field]

wouldn't converting sin^3(x) into sin(x) (1 - cos^2(x)) be more straightforward

[grim burrow]

well, the idea is that everything here is now doable terms by terms

but sure

and like, i have asked the first time around, the derivative of cos^3(x) is just 3sin(x)cos^2(x)

Also, if you inspect further, sin(3x)=3cos^2(x)sin(x) - sin^3(x), but this is not a very popular form of the triple angle identity.

[prisma cargo]

Ok
I got it
I have to approach with triple angle identity
And then do integrate

Thanks mate

.close

[devout snow]

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[arctic field]

triple angle is less well known than pythagorean identity

[devout snow]

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[dapper chasm]

can someone help me with this?

[rugged sparrow]

Could you provide the diagram

[rugged sparrow]

What does &lt mean?

[dapper chasm]

angle

[sick fulcrum]

<

the html decoding failed

[rugged sparrow]

The third one should be vertically opposite angles

[rugged sparrow]

What are options for the 6th?

[dapper chasm]

also the same with the 3rd one

[rugged sparrow]

So the answer of the 3rd one is the last option

[dapper chasm]

oh okii

wait wouldnt it be Definition of Congruent Angles?

instead of vertical angles?

[rugged sparrow]

Vertical angles are equal so

[dapper chasm]

okayy

[devout snow]

@dapper chasm Has your question been resolved?

[devout snow]

@dapper chasm Has your question been resolved?

[devout snow]

@dapper chasm Has your question been resolved?

[restive river]

well

if x=16

and both angles (each) 42

what is the question?

[devout snow]

@dapper chasm Has your question been resolved?

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[devout snow]

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[manic sedge]

I don't understand this

[red sierra]

did you try drawing the diagram?

[manic sedge]

I don't know what is circumcircle

So I don't know how to draw it

[feral agate]

the circumcenter is where the perpendicular bisectors of all sides intersect

[manic sedge]

Oh

[manic sedge]

That's what I have to prove

[red sierra]

no it's not

[feral agate]

no

[manic sedge]

It's not

Now I m confused

[red sierra]

the bisector of angle A and the perpendicular bisector of BC intersects on the circumcircle

[manic sedge]

Oh ok

And tell me one thing that circumcircle is the same thing as circumference?

This could be the figure?

[devout snow]

@manic sedge Has your question been resolved?

[manic sedge]

<@&286206848099549185> you would get blessings if you help me to solve this

[stone crypt]

Hi

[red sierra]

oh sorry i left

[manic sedge]

No problem

[red sierra]

holdon ill draw a quick diagram

[manic sedge]

Ok

[manic sedge]

Hi bro everything good

[rocky pine]

gimme 5 minutes

[manic sedge]

+5 minutes added to your life

[red sierra]

your diagram should look like this

red line: bisector of angle A
blue line: perpendicular bisector of BC

[manic sedge]

Ohhhh

Now I have to prove that , the intersection point of red and blue line lies on the arc BC

[red sierra]

yep

[manic sedge]

How would I do that

🥲

[red sierra]

I don't know

maybe put in on a 2d plane

[manic sedge]

[manic sedge]

💀

[red sierra]

no like

not an airplane

i mean the cartesian coordinate

let B(0,0) A(a,b) C(c,0) smth like that

[manic sedge]

I could prove that the blue line is the right angled bisector of BC

Then

[idle swift]

i think you can somehow use similarity/congruency and show that the angle subtended by same arc is equal