#help-27
1 messages · Page 64 of 1
Okay.
Dubleyou
I know we got x^4 because x^2 *x^2
notice, that this is just the identity (a+b)^2
yes
so we can rewrite this as,$y'^2=(x^2)^2-2x^2\frac{1}{4x^2}+(\frac{1}{4x^2})^2$
Dubleyou
all good?
I understand the (x^2)^2 but how did we get -2x^21/4x^2+(1/4x^2)^2...?
can you expand (a+b)^2 ?
what is it?
$(a+b)^2=(a+b)*(a+b) = a(a+b) +b(a+b) = a^2 + ba+ba +b^2 = a^2+2ab+b^2$
Dubleyou
When foiling I get this:
when you foil, you have to use every terms
ie multiply x^2 with other twos also -1/4x^2 with other twos
it seems like you have only used x^2 with all others
my bad
looks correct
but the multiplication sign is wrong
you have put paranthesis around (-1/4x^2 * x^2)
that should be subtracted from x^4 not multiplied
got it
So like this
$x^4 -\frac{1}{4x^2}x^2 -\frac{1}{4x^2}x^2 + \frac{1}{4x^2} * \frac{1}{4x^2}$
yes, simply this
I'm confused on your simplification above
oh
got it
Dubleyou
the simplification will be $x^4 -\frac{2}{4x^2} + (\frac{1}{4x^2} )^2= x^4 -\frac{1}{2x^2} + (\frac{1}{4x^2} )^2$
Dubleyou
Okay hold on...let me understand.
which is same as this step above
So these x^2’s cancel out?
no no
they get factored out
they are of same sign
think x^2 as some number and think
they are numbers when plugged in indeed
does -2 -2 gets cancels out ?
if $-23 + -26$
no it gets -4
Dubleyou
can you cancel -2 ?
nope, but can you factor out -2 ?
the whole point of factoring is to make it look as multiplication
Okay how are you factoring x^2 out here..I'm not seeing it.
can you try factoring -2 from the above?
this will help you see factoring x, for sure
-2*3+(-2) times 6 = 2 times 2 times 3..?
you can factor $-23 + -26 = -2(3+6)$
Dubleyou
i'm not sure how you got that
I see.
This is know as distributive property
recall that
we usually factor out the gcf this way
ok
so notice in the other problem, when x is plugged it looks similar to one we just did
can you try it now?
I just don't see how the pair of x^2's dissapear and turn into -2/4x^2...
We leave x^4 the way it is, compute -1/4x^2-1/4x^2 and get -2/4x^2, and we combine 1/4x^2*1/4x^2 into (1/4x^2)^2...?
let's see
we are trying to simplify the middle two terms right?
what is gcf of them or what's the common to both terms ?
You're talking about these two terms, right?:
can you instantly cancel the x^2 from numerator
x^2 is common to both terms..
what is -1/4 -1/4 ?
-1/2..
what is exactly the middle term
-1/4x^2^x^2
Dubleyou
we multiply the x^2 by the 1, and we get -x^2/4x^2...the x^2's in the numerator and denominator cancel out, and we get -1/4..?
yes indeed
Since this applies to both terms in the middle..we add them up and get -1/4-1/4 = -1/2..
Yeah...I'm rusty.
people usually struggle in pre-calculus in calculus class
calculus concepts are intuitive but pre-calculus takes the fun away
But how do we get -1/2x^2...I get the -1/2 and how the x^2's cancel in numerator and denominator but how did the x^2 spawn randomly in the denominator?
this step?
yes
Do both middle terms not simplify to -1/4?
ok
this is correct one
so we can rewrite this as,$y'^2=(x^2)^2-2x^2\frac{1}{4x^2}+(\frac{1}{4x^2})^2$
Dubleyou
so we can rewrite this as,$y'^2=x^4-\frac{1}{2}+(\frac{1}{4x^2})^2$
Dubleyou
now add 1 to it
$y'^2+1=x^4-\frac{1}{2}+(\frac{1}{4x^2})^2+1=x^4+\frac{1}{2}+(\frac{1}{4x^2})^2$
Dubleyou
By adding one, aren't we just distributing the 1 to each term? so x^4 * 1, -1/2 * 1, and 1/4x^2 * 1..?
Oh...I thought we were distributing, nevermind..
I thought it was 1 * (y')^2...
when adding 1 to $23+64$ do we distribute ?
Dubleyou
Okay, so we do x^4+1/2+(1/4x^2)^2+1...which is effectively adding 1/2 to 1 and we get x^4+3/2+1/16x^4...
Well you had that here...did you not intend to add 1/2+1 in the last expression?
you get: x^4+1/2+1/16x^4...
I had -1/2 as middle term, adding +1 makes it 1/2
Did you mean to add another 1 after that?
after this step
Did you mean to have that circled 1 there?
$y'^2+1=x^4-\frac{1}{2}+(\frac{1}{4x^2})^2+1=x^4+\frac{1}{2}+(\frac{1}{4x^2})^2$
Dubleyou
okay yeah I'm following then
My bad, I can see how bad a typo hurts
You have to recognize this as (a+b)^2
Got it
which will get your to your disred expression
So the final expression should get us to the original expression I circled above that was red?
yes
How can we tell this intuitively though?
well, intuition in algebra comes from practice
so it requires consistent handwork
Surely there's a verification step or something that you use to prove that the expression can be derived from the circled one??
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I don’t know if I’m doing this right and if I’m going towards the right direction
I'm not sure how to simplify the yellow part
you can't really
Are there any steps to continue simplifying?
I entered it in but it's showing up as incorrect for me, so I'm thinking I might have gone wrong with my other steps in simplfying
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a curve C is defined by the equation x^2+xy^2-y^3=1. use implicit differentiation to compute the slope of the line tangent to the curve at the point (1,0)
Please don't occupy multiple help channels.
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but nobody came
well, maybe it's because you said you dont know if you're doing right, but you didn't post anything so that none of us can check
lets see
I dont have to simplify the answer
looks good, except with those (
wdym
ah, so it should be 2x[cos(x)-x^2(sin(x))]
ahh
glad that helps!
is it fine if i use f(x) to solve even though it is a d/dx problem
well, if you wanna use f(x), you'll just have to define it
just write something like
f(x)="that expression"
ok
btw, if you just wanna check your answer (and not steps) you can just use Wolframalpha
do you have a link for that ir is it an app
,w differentiate (x^5-4x^2+2)/(x^3+x)
seems correct
just Google Wolframalpha or
www.wolframalpha.com
so it doesnt show the steps if i got it incorrect
okay, next question
yeah
do you know what is implicit differentiation?
does it have something to do with seperating the equation in 2 halves
nah
here's an article for implicit differentiation
Math explained in easy language, plus puzzles, games, quizzes, videos and worksheets. For K-12 kids, teachers and parents.
okay
first denominator is a little cleaner tho
This is the original question I asked btw
Should the dy/dx be in parentheses
All good
So I just have to simplify this?
im just getting 2 as an answer
2x+y²+2xy(dy/dx)-3y²(dy/dx)=0
2xy(dy/dx)-3y²(dy/dx)=-2x-y²
(2xy-3y²)(dy/dx)=-2x-y²
dy/dx=(-2x-y²)/(2xy-3y²)
the weird thing here is that
2xy-3y²=0 at (x,y)=(1,0)
hm
looks like the slop is vertical, which is tends to infinity
recall
when you plug in (1,0)
we get
1/0
which tends to infinity
yeah
and when slope tends to infinity, the slope is vertical
how are you geting a slope of 1,0
im getting -2
how did you get -2?
my work is here
im plugging in 1 for x and 0 for y
i know. i mean do you have a photo that i can correct it?
numerator is -2, but look carefully at the denominator
is there anythign wrong with my work
nothing wrong up till here
but for the last step
the denominator is 0-0 which is 0
yeah, so im getting -2/0
lol my mind is messing something up
can you show what I should do for the last step
but im confused how you got 1,0 and i didnt
(1,0) from the question itself
ah I see, so you also got -2/0
would it be positive or negative infinity?
very good question
it's depends on which side you are measuring
so, just infinity will do
ah
yea... that's why i say it's weird
alright, I have 2 more questions
question is: suppose T(h) is the temperatire in degrees fahrenheit "h" hours after midnight on july 1, 2023.
what are the units if T'(h)?
I got degrees fahrenheit per hour
part b is where they are asking is T'(8) likeley greater or less than 0?
hmmm T(h) is not given, right?
nope, but part c asks if T(8) is greater or less than 0
it looks like a geography question lol
yeah lol
i guess I can't help with that
it really depends on the general knowledge of the place you are living in
okay, i got a different question
Man this is a long homework packet lol
@long pasture
good question
like if you have
f(x)=x²
then df(x)/dx=2x
you can change it to t
like
f(t)=t²
and df(t)/dt=2t
it really depends on which variable you are differentiating with respect to
like for example, how would I find the derivative of this one since it has d/dt
you can't
what
if you don't know if x and t have relationship
ahh, so its a no solution?
let's say if you know x(t) = t²+t+1 something like that, you can find it
but if you don't, you can't tell anything from that
and usually, it's just a typo
oh
teachers do have typos lol
you mean i should solve it with d/dx in case its a typo
yep
that's the best way i guess, or you can just report the question the your teacher
yeah
and usually your teacher will just say, yea it's a typo and you'll have to calculate it
@zenith stump Has your question been resolved?
thanks man, I really appreciate the help!
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wait would BE and BC be equla
show the full problem
I actually don't know, sry
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since PQ is always required, so let it equal one speak called U, so find how many ways you can permute 4 speakers
but
4!
oh
it dont say
very true
yeah I don't think it means P is immediately before Q
that would be too simple
P(4!) + 3P(3!) would be the first two terms
so for each possibility either p goes before q or q goes before p
you can derive something from that
oh, like 5! divided by 2
yeah
P(4!) + 3P(3!) + Permute(3,2)P(2!) + Permute(3,3)P(1!)
what is P?
where Permute(n,k) = n!/(n-k)!
it's just the P speaker
4! + 3(3!) + (3!)(2!) + (3!)
24 + 18 + 12 + 6 = 60
which equals 5!/2
yeah that's the right answer
i was just enumerating the 4 possible positions the P speaker could be
I gotcha now
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Start by factoring by the (1/5) and after that you will have 10*(1/5), which is equal to 2
Maybe I misunderstood something, sorry but I can't help you
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Will z limit start from 0?
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can somebody explain the math here?
It's completing the square method
??
They factored a 1/2 out the square root
wait how
Do lcm
elaborate
(2x-1)/2
mhm
Which is squared
mhm
no, i'm writing
This is it
nope, i have to do this now
Ok then did u write
this exponent is confusing me
It squares 1/2
doesn't it expand x-1/2??
The two of the denominator
Do cross multiplication first then square
Step by step
isn't (x-1/2)^2 the same as (x-1/2)(x-1/2)?
i can't see the cross multiplication with this fraction
Ok what's an odder way of writing THIS
How do u subtract simple fraction s
What's 1-0.5
I wonder what school makes people learn calculus before making them learn fractions
yeah the communication was just not clicking for me
years of forgetting basic math does that
Answer!!!
There's 2 in denominator
Yess
WHAT
WHY
because that made more sense to me in that moment
Dude look
Everything is good here OK?
mhm
NOW SQUARE THE FRIKIN FRACTION
isn't that what the bloody exponent is supposed to do
Teh ' ^2'
@frank dew
Good
Now theres another ROoT
Quite the opposite
Lololol the jonas aden track was good tho
sqrt of 1/4 is 1/2
Yeassir!
Mission accomplished
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ty for bearing w me btw
No sir apparently I'm a differently abled person in my education system
damn
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that graph doesnt even make sense, how does x^2 + y^2 = 1 have a coordinate at (0,2)
Yea im confused as well,need to convert it into polar coordinates,or was that just a printing mistake and we should just ignore the two?
Could be a typo. If the book has a new edition check that online or think of something which seems reasonable in the context to fix the typo.
Maybe it was meant to be x^2 + y^2 = 4.
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I can't seem to understand what I'm doing wrong for this question
I have my mean, and with the same data I am attempting to calculate s.d. , but it doesn't seem to be the right answer. could someone help please, thanks.
btw I know all the formulas etc. but I can't understand why I'm getting this wrong
.close
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yo i need help classifying angles
adjacent angles mean they're beside each other, sharing a common side and a vertex. While vertical angles, are usually opposite each other
while still sharing a vertex but not a side, because they are the result of two lines crossing each other
wait so number 2 would be M and L?
you usually name angles using the three letters
oh
with the middle letter being the vertex
so M, L, P
and for 11 -14
acute angles are angles under 90 degrees
obtuse angles are those over 90 but less than 180
right angles are 90 degrees and obviously straight angles are 180
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Linear algebra
length of vector u = 2, length of vector v = sqrt(3)
We know that the dot product dot(u,v) = 1
What is the length of the vector 2u-v?
I got this far but I'm not sure how to proceed
use the formula for ||a+b||^2
how do i calculate dot([2u-v],[2u-v], I don't think I have it in my material
@edgy sparrow Has your question been resolved?
Is this the correct answer?
yes
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Can someone check my work?
It's ,rotate
ok thx
Looks right
I think you should try to not convert into degrees though, try to think abt it only in radians. It can be kinda tough at first but overall makes it easier once you get it down. Not really a big deal but just something that helped me
Ok
I tend to turn them into degrees. Nothing wrong with that, since I just memorize 30-60-90 and 45-45-90 theorems
Mood
Degrees are easier than radians when it comes to triangles
But it's all preference
However, when adding angles to numbers algebraically, you need to convert to radians
Yea nothing wrong with it I just find it easier to stay in rad rather than make mistakes when converting from degrees to rad
I go back and forth too but I think when first learning it, you kinda limiting yourself if you can only understand rad if you convert to degrees
Looks right
ok
WAIT NO
that’s wrong
would they be negative ?
like that picture ?
or positive
the long 1 is not negative
I think
yes
I think right
but which one do I pick for the opposite
-1 or 1
how do I know what to pick
Final answer
@umbral heath Has your question been resolved?
Okay react to the bot first
Which?
This one
ok
So it's a 45° triangle
its best to just get used to radians
when you use trig in calculus
you can only use radians
yep
You drew it well
Correct
ok
ok but I did the radian and degree
?
what do u mean by radian
Show
i mean, its best if you can get to the point where you can completely think in radians
and not have to rely on degrees
the top half is in radians right ??? Or am I not doing radian I’m comfused
The angle inside the tan is in radians
yes
What doctor means is that you write the 30° as π/6 and the 60° as π/3
And not ever depend on degrees
But that depends on your preference of course
Yeah you do them as (π/6)(π/3)(π/2) and (π/4)(π/4)(π/2)
ok yea we’re not there yet
this is just the beginning of trigonometry
ok so netx question
,rotate
163 = ab^0 +13 is good
Then the next step everything died
Hmm
I’ll show u when I’m done
No like the 149 is not correct
I KNOW
Okay
,rotate
so far so good ?
Yeah
Wait you got b = 0.8?
Yeah
yes
SEE
Sketching?
ya
Okay
Oki
P is for period
Okay
,rotate
IDK how to scale
but that’s my road
I have to go pick up my brother I’ll be back in 10-15 min
Okay sure
Are u kiddi mg me
all these mom and dads come here 30 min early
and I can’t get a spot
@umbral heath Has your question been resolved?
Your y-axis scale works just fine
Well considering how repeated the angles will be, you will need to expand it a bit
WAIT I GOT IT
so
it would be
pi/4
3pi/4
5pi/4
right ??
and then 7pi/4
bcuz if we can do pi/2, pi, 3pi/2, 2pi we can do same with that one
awh
why*
Bcuz
isn’t my starting point pi/4
btw I’m not arguing with u I just want to understand
no idk
Okay
what do that get u
First you identified b right?
Yep
ISNT TO FIND THE PERIOD 2pi/4 which would be pi/2
Yep
then
An entire period goes through 4 stages though.
oh ok
So to get each stage, you need to have the angle for it
So in this case you will divide π/2 by 4
Which gives π/8
and u divided by 4 bcuz it go thru 4 stages?
Yep
ok thx
scaling done
now
my teacher say
to find the starting point and the ending point
how do I find the starting point tho bcuz pi/4 isn’t in the thing u know
Idk
Plug in?
plug in what
Well 4*0 equals 0 in the end
You got 1 right?
Yep
You got sin(0), which should equal 0
Wait wait
The -2 is multiplied by the sin(0)
And sin(0) is the same as 0
So -2 multiplied by 0
=0
Nooooo I didn't mean it to be disappointing

Problem was because of the sin(0) thingy
Anyways we found the starting point of your graph
NONWE DIDNT
Put a point at x=π/4 and y=1
Hmm
So like here's where I don't understand the "endpoint"
Yepp
that was so confusing
Can I tell you some corrections to make or are you aware of them?
what is it
Mood. Me with my first sine wave graphing exercise.
Okay so that 4 under the 2π. You can keep it as 4 by erasing the 2 next to π or you change the 4 to an 8
Also I think you know that the lines should behave more like waves
so basically pi/2
No it's π/4
You can keep the 4 by just erasing the 2
Or you change it to 8 without erasing the 2
Also I think it will be easier for you rn to check with a graphing calculator
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having a hard time with this question
where did you get stuck?
I've substituted u in and taken 2 out of the integral leaving 2 /int_{1}^{2} 1/u^2 dx
but I don't think that's right
and I'm not sure what is
can you take a pic of what you did?
Not at the moment, my roommate is sleeping. But I can type it lol
<@&286206848099549185>
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How would I solve this?
look up disks and shells by organic chemistry teacher
Well I have some work done but I'm getting the wrong answer.
idk how to do it myself, I just know thats how youre supposed to do it
you gotta wait 15 min to ping helpers, so not on here no
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angle SVT = angle TWU
yknow why?
@woven raft
@woven raft
i am going to close this forum
yes
I am
@woven raft
I am siting down
angle svt = angle vtw because of alternate angles
Usually i ask for a photo
but i will take ur word for it
and angle vtw = angle twu because of alternate angles again!
r u following?
please confirm
yea
not relly
SV
∥
TW
. Prove that △STV≅△TUW.
thats what it wants not sure how this proves it
yea
we need more stuff to be equal!
vst = wtu by correpsonding angles
thats two angles!
ahh ok
VS = WT
so we have two angles
AAS
im going next
hope this solves it!
sorry
does that symbol
that u hv there
mean similarity or congruency
if its simialrity we are done
cos we have two angles and its equiangular
@woven raft
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Hi
I'm given a triangular based pyramid Smth like this:
Is it possible to find all three slant height of the pyramid
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I have been recently pondering about probability.
Let's consider a toy example of a gacha game where you want to get a particular roll. I always thought that the probability of getting what you want in the next three rolls does not depend on the past. Lets assume that you stop rolling as soon as you get the "item".
Going over my probability notes I was thinking about the case where we want to calculate the proability of a machine to break down in the next time instant, given that it has already lived for a time t.
P(t < X < t+ dt | X >t) = P(t < X <t+ dt and x >t)/P(x>t) = P(t < X <t+ dt)/P(x>t).
Wouldn't it be possible to consider the gacha game where X is, instead of the life expectancy, the number of rolls needed to get the item? And would the calculation be different from the above and why?
I believe the core of the issue is when we say that P(t < X <t+ dt and x >t) = P(t < X <t+ dt).
but even so, why wouldn't this hold for the toy example of the gacha game?
TL DR, if X is an independent variable why is P(y < X < z and X > y) = P(y < X < z)P(X > y) and not simply = P(y<X<z)?
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okay you got a bet with these rules:
50/50 chance to win, double money on win
if you got 2000€ and you bet 1000€ does that give you more than 50% chance to success? if you lose you can retry to win with another 1000€
My friend argued that since you basically got two tries it has to be more than 50% chance
Okay thanks
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Linear algebra
I have to prove that polarization identity exists for all {u, v = R}
I'm not really sure if I follow, isn't this proof enough?
@edgy sparrow Has your question been resolved?
@edgy sparrow Has your question been resolved?
yes that is enough
.close
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Hey! Can anyone help me with this problem?
let f(x) = 1/2ln((1+x)/(1-x)) for every xE(-1,1). Find a,bER such that f(a^2 + b^2) + f(a-b+1/2) = 0
